E-PORTFOLIO LENGKESHINY

JABATAN TENAGA MANUSIA

4. Food court
Area = 354.082 ft² x 85

= 30096.97 BTU/hr

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JABATAN TENAGA MANUSIA

5. Office
Area = 105.272 ft² x 50
= 5263.60 BTU/hr

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JABATAN TENAGA MANUSIA

6. Surau
Area = 121.063 ft² x 85
= 10290.355 BTU/hr

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1. Sale
Area = 10504.050 ft² x 50

= 525202.5 BTU/hr

2. Shop1
Area = 349.453 ft² x 50
= 17472.65 BTU/hr

3. Shop2
Area = 986.090 ft² x 50
= 49304.50 Btu/hr

4. Food court
Area = 354.082 ft² x 85

= 30096.97 BTU/hr

5. Office
Area = 105.272 ft² x 50
= 5263.60 BTU/hr

6. Surau
Area = 121.063 ft² x 85
= 10290.355 BTU/hr

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Kategori kawasan p

Kategori A = sepanjang wakt
Kategori B = pada masa terte
Kategori C = operasi 24 jam d

penyaman udara

tu pejabat
entu shj semasa terdapat aktiviti
dan perlu unit tunggu sedia

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1. Sale
Area = 10504.050 ft² x 50
A = 525202.5 BTU/hr

2. Shop1
Area = 349.453 ft² x 50
A = 17472.65 BTU/hr

3. Shop2
Area = 986.090 ft² x 50
A = 49304.50 Btu/hr

4. Food court
Area = 354.082 ft² x 85

= 30096.97 BTU/hr
A
5. Office
Area = 105.272 ft² x 50
A = 5263.60 BTU/hr

6. Surau
Area = 121.063 ft² x 85
B = 10290.355 BTU/hr

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÷9000 1. Sale
Area = 10504.050 ft² x 50

= 525202.5 BTU/hr
= 58.36 Hp = 59 Hp

2. Shop1
Area = 349.453 ft² x 50
= 17472.65 BTU/hr
= 1.94 Hp = 2 Hp

3. Shop2
Area = 986.090 ft² x 50
= 49304.50 Btu/hr
= 5.5 Hp

4. Food court
Area = 354.082 ft² x 85

= 30096.97 BTU/hr
= 3.34 Hp = 3.5 Hp
5. Office
Area = 105.272 ft² x 50
= 5263.60 BTU/hr

= 0.6 Hp = 1 Hp
6. Surau

Area = 121.063 ft² x 85
= 10290.355 BTU/hr
= 1.2 Hp = 1.5 Hp

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Soalan :
Kirakan beban haba pendingina
menggunakan kaedah rule of th

10 m

11 m

an kelas dalam rajah di bawah
humb.

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Q (rule of thumb)
= A x GTH
= 10 x 11 x 10.764 x 60
= 71042.4 BTU/hr
= 7.9 Hp
= 8 Hp

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JABATAN TENAG

KEMENTERIAN SUM

THANK

GA MANUSIA

MBER MANUSIA

K YOU

www.jtm.gov.my

JABATAN TENA

KEMENTERIAN SUM

AGA MANUSIA

MBER MANUSIA

Diploma Teknologi
Penyejukbekuan dan Penyamanan

Udara (L05)

L05-34-31
HVACR Architecture Drawing

and Cooling Load

INSTRUCTOR : SHARIFFAH SYAHIDAH BINTI S AMIR

www.jtm.gov.my

JABATAN TENAGA MANUSIA

RUMUS ASAS
BEBAN
PENDIN

S PENGIRAAN
N HABA
NGINAN

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JABATAN TENAGA MANUSIA

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JABATAN TENAGA MANUSIA

PRINSIP PENG
DALAM B

GALIRAN HABA
BANGUNAN

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JABATAN TENAGA MANUSIA Proses pengaliran dan pertukaran haba

Panas Sejuk

Pengalir haba
Rintangan terhadap pengaliran haba (he

R-value Semakin rintangan

R-value p

a

Penebat haba
eat resistance)(rintangan terma)
n terhadap pengaliran haba
penebat yang baik

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JABATAN TENAGA MANUSIA

R-value (Rintang

⮚ merujuk kepada rintangan t
atau pemasangan kompone

⮚ Unit - m2 K/W

gan terma)

termal (haba) pada setiap bahagian
en bangunan

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JABATAN TENAGA MANUSIA R-value (Rintanga

• RT = Ro + b1/K1 + b2/K2 +…

Dimana

Ro : Rintangan lapisan udara b
Ri : Rintangan lapisan udara b
K : Konduktiviti terma bagi ses
b : Ketebalan bagi sesuatu ba

Unit = (m2 º K/W)

an terma)

……+ bn/Kn + Ri

bagi permukaan luar (m2 º K/W)
bagi permukaan dalam (m2 º K/W)
suatu bahan (W/m º K)
ahan (m)

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JABATAN TENAGA MANUSIA Rintangan Lapisan Udara Per

⮚Dipengaruhi oleh halaju angin

⮚Berbeza bagi rintangan lapisan u
dalam (Ri)

⮚Ro : Rintangan lapisan udara bag

⮚Ri : Rintangan lapisan udara bag

rmukaan
udara permukaan luar (Ro) dan permukaan
gi permukaan luar (m2 ° K/W) - moving air
gi permukaan dalam (m2 °K/W) - still air

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Surface Film Resistances for wall

Type of
A. Surface FSilmurRfaescisetances for walls.

1. Inside surface (Ri)
a) High Emissivity
b) Low Emissivity

2. Outside surface (Ro) High Emissivity.

B. Surface Film Resistances for Roofs.
1. Inside Surface (Ri)

a) High Emissivity
(i) Flat Roof
(ii) Sloped roof 22½
(iii) Sloped roof 45°

b) Low Emissivity
i) Flat Roof
(ii) Sloped roof 22½
(iii) Sloped roof 45°

2) Outside surface (Ro) High Emissivity.
Flat or sloped

& roof (Ri ,Ro).

Thermal Resistance
m2 oK/W

0.120
0.299
0.044

0.162
½° 0.148
° 0.133

0.801
½° 0.595
° 0.391

0.055

K-value (KonduktJABATANTENAGAMANUSIA

⮚ Ditakrifkan sebagai kuantiti h
bahan apabila perbezaan suh
bertentangan.

⮚ Unit - (W / m ° K)

tiviti terma)

haba yang dipindahkan melalui luas unit
hu wujud di antara permukaan yang

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JABATAN TENAGA MANUSIA

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JABATAN TENAGA MANUSIA U-value / Faktor

⮚Kuantiti haba yang mengalir m
bangunan dalam satu masa dis
dikedua-dua permukaan.

⮚Pekali pemindahan haba bert
dan menaikan perbezaan suhu

⮚U = 1 / RT (W/m2 °K)

⮚RT meningkat = U menurun

U

melalui sesuatu luas permukaan bagi
sebabkan perbezaan suhu udara

tindak pada keluasan 1 meter persegi
1°K

penebat yang baik

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JABATAN TENAGA MANUSIA Langkah-Langkah Pengiraan Fa

Langkah 1
Mengenalpasti bahan binaan u
lapisan udara (Ro & Ri)

Langkah 2
Dapatkan nilai ketebalan bahan

Langkah 3
Kirakan nilai rintangan terma R

Langkah 4
Kirakan nilau U faktor

aktor U
untuk mendapatkan k-value dan rintangan
n daripada lukisan arkitek
RT

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JABATAN TENAGA MANUSIA Contoh 1

Ro = 0.044 (m2 º K/W)

30 mm concrete Ri
block K = 1.154
W/m2°K 75 mm co
plaster K =
W/m2°K

i = 0.107 (m2 º K/W)
oncrete
= 1.442

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Contoh 1

Ro = 0.044 (m2 º K/W)

30 mm concrete 75 mm
block K = 1.154 plaste
W/m2 °K W/m2

RT = Ro + b1/K1 + b2/K2 + Ri
= 0.044 + 0.03/1.154 + 0.075/1.442 + 0.107
= 0.229 (m2 º K/W)

U = 1/RT
= 1/0.229
= 4.367 (W/m2 ºK)

Ri = 0.107 (m2 º K/W)

m concrete
er K = 1.442

°K

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