430 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES STEP 4 MCQ CONCEPT TEST WRITTEN cÖkœ 01. 10C ZvcgvÎvi 5kg cvwb‡K 100C ZvcgvÎvi cvwb‡Z DbœxZ Ki‡Z G›Uªvwci cwieZ©bÑ A. 5978.86 JK–1 B. 6978 JK–1 C. 5798.76 JK–1 D. 6000 JK–1 02. = 5 3 Gi Rb¨ †KvbwU mwVK? A. Cp = 5 3 R B. CV = 5 3 R C. CV = 3 2 R D. CV = 2R 03. †Kvb wm‡÷‡gi Dci evwn¨K ej Øviv 500 J KvR m¤úv`b Kivq wm‡÷g n‡Z 300 J Zvc kw³ †ewi‡q †Mj| wm‡÷‡gi AšÍt¯’ kw³i cwieZ©b KZ? A. – 800 J B. – 200 J C. + 200 J D. + 800J 04. †Kv‡bv Kv‡b©v Bwćbi `ÿZv 75% Ges ZvcMÖvn‡Ki ZvcgvÎv 67%C| Zvc Dr‡mi ZvcgvÎv KZ n‡e?] A. 85C B. 840C C. 1087C D. 1360C 05. 0.01 kg cvwb‡K 0C †_‡K 10C G DËß Kiv n‡jv| G›Uªwc cwieZ©b n‡jv A. 3.5 JK1 B. 4.5 JK1 C. 2.5 JK1 D. 1.5 JK1 06. ¯^vfvweK Pv‡c 100m3 AvqZ‡bi GKwU M¨v‡m 5103 J Zvc w`‡j M¨v‡mi AvqZb 100.2m3 nq| H M¨v‡mi K…Z Kv‡Ri cwigvb n‡e - A. 20265J B. 105 J C. 30520J D. 9800J 07. GKwU Zvc BwÄb Drm †_‡K 600k ZvcgvÎvq 2.56106 j Zvckw³ MÖnb K‡i ZvcMÖvn‡K 5.12105 Zvckw³ eR©b K‡i| Bwćbi `¶Zv wbY©q Ki| A. 60% B. 80% C. 70% D. 75% 08. 1270C I 270C ZvcgvÎvi g‡a¨ Kg©iZ GKwU Zvc Bwćbi me©vwaK Kg©`¶Zv KZ? A. 60% B. 40% C. 450% D. 25% 09. GKwU Zvc Bwćbi Kg©`¶Zv 40%| BwÄbwU Zvi M„wnZ Zv‡ci KZ Ask eR©b Ki‡e? A. 40% B. 60% C. 80% D. 100% 10. GKwU Kv‡bv©wU BwÄb 800K I 400K ZvcgvÎvq †h `¶Zvi KvR K‡i, wVK mg `¶Zvq KvR K‡i T I 900K Zvc gvÎvq| ZvcgvÎv T Gi gvb KZ? A. 900K B. 450 C. 1800K D. 500K 11. GKwU wØ cigvby wewkó M¨v‡mi †¶‡Î Cp Cv njA. 1.67 B. 1.4 C. 1.33 D. 1.11 12. DòZvwgwZK ag© m¤úbœ e¯‘i D`vnibA. •KwkK b‡j iw¶Z cvi` B. cøvwUbvg Zvi C. ZvchyM‡ji cwievnx Zvi D. mK‡jB 13. ¯^vfvweK Pv‡c 100 m3 AvqZ‡bi GKwU M¨v‡m 5x103 J Zvc w`‡j M¨v‡mi AvqZb 60.2 m3 nq Z‡e H M¨v‡mi K…Z KvR n‡eA. 20260 J B. 199000 J C. 22384 J D. 25380 J 14. GKwU Kv‡b©v BwÄb hLb 270C DòZvi ZvcMÖvn‡K _v‡K ZLb Kg©`¶Zv 50%| G‡K 60% `¶ Ki‡Z n‡j Gi D³ ZvcgvÎvi wK cwieZ©b Avb‡Z n‡e| A. 600K B. 300K C. 240K D. †KvbwUB bq 15. ‡Kvb ZvcgvÎvq †Kjwfb I dv‡ibnvBU †¯‥‡j GKB cvV cvIqv hvq? A. 574.25F B. 273.16K C. 374.25F D. 375F 16. m‡gvò cÖwµqvq †h †f․Z ivwkwU w¯’i _v‡K Zv‡K wK e‡j? A. GbUªwc B. AšÍ¯’kw³ C. Pvc D. AvqZb 17. cvwbi AvqZb 0.1% msKzwPZ Kivi Rb¨ KZ Pvc cÖ‡qvM Ki‡Z n‡e, cvwbi AvqZb ¸bvsK = 2100 M Pa (1MPa= 106 pascall) A. 2.1106 Pa B. 2.1108 Pa C. 2.1105 Pa D. 2.1104 Pa 18. 35% Kg©`¶Zvwewkó GKwU Zvcxq BwÄb cÖwZ c~Y©Pµ †k‡l Drm †_‡K M„nxZ Zv‡ci kZKiv KZfvM eR©b K‡i? A. 35 B. 45 C. 50 D. 65 19. GKwU Kv‡b©vi BwÄb (Carnot engine) 327o I 27o ZvcgvÎvq KvR K‡i| Gi Kg©`¶Zv (efficiency) KZ ? A. 50% B. 0% C. 100% D. 92% 20. 100 wgUvi DuPz GKwU RjcÖcvZ n‡Z cvwb wb‡P cwZZ nq| Dc‡ii I wb‡Pi cvwbi ZvcgvÎvi cv_©K¨ n‡eA. 0.822C B. 0.234C C. 1.220C D. 0.880C OMR SHEET 01. A B C D 06. A B C D 11. A B C D 02. A B C D 07. A B C D 12. A B C D 03. A B C D 08. A B C D 13. A B C D 04. A B C D 09. A B C D 14. A B C D 05. A B C D 10. A B C D 15. A B C D WRITTEN PART 21. `ywU K…ò e¯‘ A I B Gi cÖwZ GKK †¶Îdj †_‡K cÖwZ †m‡K‡Û wbM©Z Zvc kw³i AbycvZ 16:1. A Gi ZvcgvÎv 2000 K, Ab¨wUi ZvcgvÎv KZ? DËi:....................................................................................... 22. GKwU w¯’i AvqZb M¨vm _v‡g©vwgUvi 0 0CGes 1000C ZvcgvÎvq h_vµ‡g 100cm I 135cm cvi` Pvc cÖ`k©b K‡i| †Kvb Zi‡j H _v‡g©vwgUvi 120cm cvi` Pvc cÖ`k©b Ki‡j H Zi‡ji ZvcgvÎv KZ?| DËi:....................................................................................... 23. GKwU BwÄb 4200J Zvc MÖnb K‡i 3200J Zvc eR©b K‡i| BwÄbwU Øviv Drcvw`Z Kv‡Ri cwigvb KZ? DËi:....................................................................................... 24. 3kg cvwb‡K 100C ZvcgvÎvi ev‡®ú cwiYZ Ki‡Z GbUªwci cwieZ©b KZ n‡e? DËi:....................................................................................... 25. C ZvcgvÎvi 1kg cvwb‡K 100C ZvcgvÎvi ev‡®ú cwiYZ Ki‡Z KZ GbUªwc cwieZ©b nq? DËi:....................................................................................... 26. 2kg f‡ii GKwU e¯‘ 3m D”PZv n‡Z c‡o Zv‡c iƒcvšÍwiZ n‡j Zv‡ci cwigvY KZ n‡e? DËi:....................................................................................... 27. GKwU Kv‡b©vi BwÄb 230° C I 27° C ZvcgvÎvq KvR Ki‡Q| Gi Kg©`¶Zv KZ? DËi:....................................................................................... 28. 10C ZvcgvÎvq 2 kg eid‡K 0C ZvcgvÎvq cvwb‡Z cwiYZ Ki‡Z cÖ‡qvRbxq Zv‡ci cÖ‡qvRb n‡eDËi:....................................................................................... 29. ¯^vfvweK ZvcgvÎv I Pv‡c wKQz cwigvb M¨vm‡K nVvr msKzwPZ K‡i Zvi AvqZb GK Z…Zxqvsk Kiv nj| PzovšÍ ZvcgvÎv n‡eDËi:....................................................................................... 30. 27C ZvcgvÎvq †Kvb wbw`©ó cwigvb M¨vm nVvr cÖmvwiZ n‡q wظb AvqZb jvf Ki‡j| PzovšÍ ZvcgvÎv KZ? [ = 1.40] DËi:.......................................................................................
ASPECT PHYSICS wØZxq cÎ ZvcMwZwe`¨v 431 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES MCQ ANSWER ANALYSIS WRITTEN cÖkœ bs DËi e¨vL¨v 01 C dS = ms 373K 283K dT T = 5 4200 ln (373 + 283) = 5798.76 JK –1 02 C Cv = R –1 = R 5 3 – 1 = 3 2 R 03 C dQ = – 300 J.dW = – 500 J ; dU – dQ – dW = + 200 J 04 C = 1 – T2 T1 T2 T1 = 1 – ; T1 = T2 1 – = 340 1 – 75% = 340 0.25 = 1360K = 1087C 05 D S = 283 273 ms = dT T ; = 0.01 4200 {ln(283) – ln(273)} = 1.5JK–1 06 A W = P V= 1.01325105 (100.2 – 100) = 20265J 07 B 100% 1 1 2 Q Q Q 100% 2.56 10 2.56 10 0.512 10 6 6 6 = 80% 08 D 100% 1 1 2 T T T 100% 400 127 27 100% 400 100 25% 09 B = 1 – Q2 Q1 0.4 = 1 – Q2 Q1 Q2 Q1 = 0.6 Q2 = 0.6 Q1 Q2 = 60% Q1 A_©vr M„nxZ Zv‡ci 60% eR©b Ki‡e| 10 C T = cÖv_wgK ZvcgvÎv؇qi AbycvZ wØZxq †¶‡Îi ZvcgvÎv ev, 900 400 800 T ev, T=1800K 11 B GK cigvYyK M¨v‡mi †¶‡Î: = 1.66 (He, Ar) ; wØ-cigvYyK M¨v‡mi †¶‡Î: = 1.4(O2, N2, X2) 12 A DòZvwgwZK ag© m¤úbœ e¯‘i D`vnib n‡jv- •KwkK b‡j iw¶Z cvi`| 13 B W = P v = 5103 (100 –60.2)= 5 103 39.8 = 199000J 14 D T = DT (1 – 1)(1 – 2) = 0.10 300 (1–0.5)(1–0.6) = 150K 15 A x 273 5 = x 32 9 9x 9 273 = 5x 5 32 4x = 9 273 5 32 x = 574.25F 16 B m‡gv cÖwµqvq ZvcgvÎv I AšÍt¯’ kw³ w¯’i _v‡K| 17 A P2 = 2100106 0.001 =2.1106 Pa 18 D eR©b K‡i = 100 – 35 = 65 19 A 100% 600 327 27 100% 600 300 = 50% 20 B w¯’wZ kw³ Zvc kw³‡Z iƒcvšÍwiZ n‡j, = 428 h = 428 100 = 0.234K= 0.234C 21 4 B 4 A B A T T E E 1000K 2 2000 T T 2000 1 16 4 B B 4 22 x = 100 100 0 0 x x x x p 100 57.14 C 135 100 120 100 23 w = Q1 – Q2 = 4200 – 3200= 1000J = 100 × 108 (1J = 107 erg] 24 G›Uªwci cwieZ©b, dS = dQ T = 1.81 10 J/ k 373 3 2.26 10 T mL 4 6 v 25 dS = T dQ 2260000/373 = 6.05×103 J/K Note: eZ©gv‡b 2.26×106 J/K Gi cwie‡Z© 2.268×106 J/K aiv nq| 26 Q = mgh = 29.8 3 = 58.8J= 58.8 4.2 = 14.01 cal 27 = 1 – ‡QvU gvb eo gvb 100 %= 100% 230 273 27 273 1 = 40.35% = 40% 28 Q = m(S + lf) = 2(2100 10 + 3.36 105 ) = 71400 J 29 T1 V1 -1 = T2 V2 -1 T2 -1 2 1 V V ×T1 = 1 2 2 V 3V × T1 = (3)1.4-1 ×273 =423.65K T2 = 150C 30 T1V1 -1 = T2V2 -1 T2= V1 V2 1 T1= V V 2 300=227.35k T2= – 45.600C w
432 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES SURVEY TABLE Kx coe? †Kb coe? †Kv_v n‡Z coe? KZUzKz coe? TOPICS MAGNETIC DECISION [hv co‡e] MAKING DECISION [†h Kvi‡Y co‡e] VVI For This Year DU JU RU CU GST Engr. HSC Written MCQ THEORY CONCEPT-01 Zwor Gi mvaviY welqvw` 10% 20% 10% 15% 20% - 20% - CONCEPT-02 Kzj‡¤^i m~Î 60% 65% 70% 60% 65% 10% 50% CONCEPT-03 Zwor‡ÿÎ, Zwor‡ÿ‡Îi cÖvej¨ I Zwor d¬v· 80% 75% 70% 75% 70% 90% 90% CONCEPT-04 Zwor wefe I mgwefe Zj 30% 25% 20% 70% 35% 70% 60% CONCEPT-05 Zwor w؇giæ 75% 50% 30% 40% 40% 30% 70% CONCEPT-06 aviK I aviKZ¡ 30% 50% 60% 70% 70% 80% 70% CONCEPT-07 MvD‡mi m~Î 20% 10% 10% 5% 10% 15% 40% MvwYwZK cÖ‡qvM CONCEPT-01 Kzj‡¤^i m~Î msµvšÍ MvwYwZK cÖ‡qvM 70% 75% 65% 70% 80% 35% 60% CONCEPT-02 Zwor‡ÿ‡Îi cÖvej¨ msµvšÍ 60% 65% 70% 70% 75% 75% 80% CONCEPT-03 Zwor wefe wbY©q msµvšÍ MvwYwZK cÖ‡qvM 75% 70% 70% 75% 80% 90% 80% CONCEPT-04 Pv‡R©i ZjgvwÎK NbZ¡ msµvšÍ 60% 65% 60% 70% 70% 80% 70% CONCEPT-05 Zwor w؇giæ 30% 35% 40% 30% 40% 55% 40% CONCEPT-06 aviK I avi‡Ki mgevq msµvšÍ 75% 70% 65% 70% 80% 40% 60% CONCEPT-07 avi‡Ki mwÂZ kw³ 80% 75% 70% 75% 80% 90% 70% DU. = Dhaka University, JU. = Jahangirnagar University, RU. = Rajshahi University, CU = Chittagong University, GST = General, Science & Technology, Engr. = Engineering. STEP 1 mvRv‡bv me Z_¨ THEORY fwZ© †ivMxi c_¨ Concept 1 Zwor Gi mvaviY welqvw` ✅ w¯’i ev MwZkxj Pv‡R©i cÖfve‡K Zwor ejv nq| ✅ Zwo‡Zi DrcwË: Zwor kãwU‡K MÖxK kã Electron n‡Z MÖnY Kiv n‡q‡Q| Electron k‡ãi A_© †mv‡jgvbx cv_i ev A¨v¤^vi (Amber) Lªxóc~e© 600 A‡ã MÖxK `vk©wbK †_wjm A¨v¤^vi‡K †ikgx Kvco Øviv N‡l Pv‡R©i ev Avav‡bi Aw¯ÍZ¡ cÖ_g †`Lvb| A¨v¤^vi n‡”Q cvBb Mv‡Qi AvVv| 1600 Lªxóv‡ã weª‡U‡bi ivbx GwjRv‡e_ Gi M„n wPwKrmK W. wMjevU© A‡bK e¯‘‡ZB Nl©‡Yi d‡j Pv‡R©i Aw¯ÍZ¡ Lyu‡R cvb| ✅ mecÖ_g ch©‡eÿY: †_wjm ✅ we¯ÍvwiZ AbymÜvb: W. DBwjqvg wMjevU© ✅ wMÖK `vk©wbK †_wjm (Thales: 640-548 B.C) me©cÖ_g ch©‡eÿY K‡ib †h †mv‡jgvbx cv_i ev cvBb Mv‡Qi k³ AvVv w`‡q †ikgx Kvco‡K Nl‡j G¸‡jv †QvU †QvU KvM‡Ri UzKiv‡K AvKl©Y K‡i| DBwjqvg wMjevU© (William Gilbert: 1540-1603) G m¤^‡Ü we¯ÍvwiZ AbymÜvb K‡ib Ges A‡bK c`v‡_©i g‡a¨ GB ag© ev ¸Yv¸Y jÿ¨ K‡ib| W. wMjevU© cieZ©x‡Z jÿ¨ K‡ib †h, Nl©‡Yi d‡j cÖ‡Z¨K e¯‘ Ab¨ e¯‘‡K Kg-‡ewk AvKl©Y K‡i Ges GB ag©B ZwoZvwnZKiY (Electrification) bv‡g cwiwPZ| ✅ A¨v¤^vi Gi MÖxK bvg Electron, hv †_‡KB Electricity ev Zwor cÖevn Gi DrcwË n‡q‡Q| ✅ Zwo‡Zi cÖKvi‡f`: Zwor `yB cÖKvi: h_v (1) w¯’i Zwor I (2) Pj Zwor| ✅ w¯’i Zwor: Zwor ev PvR© hLb †Kvb e¯‘‡Z Ave× _v‡K ZLb Zv‡K w¯’i Zwor e‡j| ✅ Pj Zwor: hLb PvR© cwievnxi ga¨ w`‡q AbeiZ Pj‡Z _v‡K ZLb Zv‡K Pj Zwor e‡j| ✅ gva¨g: gva¨g wZb cÖKvi, h_v: (1) cwievnx, (2) Aa©cwievnx I (3) AšÍiK| cwievnx: hvi g‡a¨ Zwor mn‡R PjvPj Ki‡Z cv‡i| cwievnx‡Z cÖPzi cwigv‡Y gy³ B‡jKUªb _v‡K| D`v: Zvgv, iƒcv, mKj avZz, gvbe‡`n, GwmW, gvwU, GwmW wgwkÖZ cvwb, A¤ø, ÿvi, cvi` BZ¨vw`| Aa©cwievnx: cwievnx Ges AšÍi‡Ki gvSvgvwS GK ai‡bi c`v_© Av‡Q hvi Zwor cwievwnZv cwievnx c`v‡_©i †P‡q A‡bK Kg; wKš‘ AšÍi‡Ki †P‡q †ewk| G¸jv‡K ejv nq Aa©cwievnx| †hgb: Rv‡g©wbqvg, wmwjKb, Kve©b, K¨vWwgqvg mvjdvBW, M¨vwjqvg Av‡m©bvBW BZ¨vw`| AšÍiK: hvi g‡a¨ Zwor PjvPj Ki‡Z cv‡i bv| Acwievnx‡Z †Kvb gy³ B‡jKUªb _v‡K bv| D`v: KuvP, cøvw÷K, wmivwgK, †ikg, ivevi, B‡evbvBU, Aå, †cv‡m©wjb, †gvg, MÜK, ïKbv KvV, ckg BZ¨vw`| w¯’iZwor ELECTROSTATICS wØZxq cÎ 02 Aa¨vq c„ôv 432
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 433 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ✅ cwievnx, Aa©cwievnx I Acwievnxi D`vniY mn‡R g‡b ivLvi Dcvq: Kwe e‡j‡Qbcwievnx Aa© cwievnx Acwievnx gv gv cv cv Gm av°v †Zvgvi cik Avgvq Kv`vq Rvg©vb wkíxiv dzmKv Avbvq D`vniYt KvP, †ikg, ievi, B‡evbvBU, Aå, †cv‡m©wjb, †gvg, MÜK, ïKbv KvV, iRb, KvMR gv gv cv cv Gm av °v ‡Zvgvi cik Avgvq Kv`vq Rvg©vb wkíxiv gvbe‡` n gvwU cvwb cvi` GwmW avZz ¶vi D`vniYt Zzjv cv_i A¨vj‡Kvnj †K‡ivwmb Rv‡g©wbqvg wmwjKb ✅ Nl©‡Y Pv‡R©i m„wó nq| hw`I Zwor Avavb m„wó ev Drcbœ nq, GUv ejv cÖK…Zc‡ÿ mwVK bq| ZwoZvwnZKi‡Yi mgq ZwoZvavb Drcbœ nq bv; †KejgvÎ wKQz msL¨K B‡jKUªb GK c`v_© n‡Z Ab¨ c`v‡_© ¯’vbvšÍwiZ nq| ✅ bx‡Pi ZvwjKvfz³ e¯‘¸‡jvi †h †Kvb `ywU‡K Nl©Y Ki‡j ZvwjKvq 1g D‡jøwLZ e¯‘wU abvZ¥K I c‡i DwjøwLZ e¯‘wU FYvZ¥K Pv‡R© PvwR©Z n‡e| (1) ckg (2) d¬v‡bj (3) Mvjv (4) KvP (5) KvMR (6) †ikg (7) Zzjv (8) KvV (9) avZe c`v_© (10) ivevi (11) MÜK (12) B‡evbvBU ✅ K‡qKwU c`v‡_©i wØZvwoZ/ civ‣e`y¨wZK aªæeK/ WvBB‡jKwUªK aªæeK: c`v_© WvBB‡jKwUªK aªæeK c`v_© WvBB‡jKwUªK aªæeK c`v_© WvBB‡jKwUªK aªæeK cvwb 20.0/80.0/78 †gv‡g †fRv‡bv KvMR 2.7 k~b¨¯’vb 1.00 Aå 7.0 cvB‡i· KuvP 4.5 UvB‡Uwbqvg WvBA·vBW 100 KuvP 5.10 cwjw_b 2.3 †cvi‡mwjb 6.5 KvMR 3.5 B‡evbvBU 2.8 A¨v¤^vi 2.7 evqy 1.05/1.0005/1.00054 g‡b ivL‡Z n‡e: civ‣e`y¨wZK aªæe‡Ki gvb me©`vB 1 Gi †P‡q †ewk nq| GwU GKK wenxb| REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. oo Gi GKK wb‡gœi †KvbwUi GK‡Ki mgvb? [DU: 2014-15] A. (velocity)2 B. (velocity)1/2 C. 1/velocity D. 1/(velocity)2 Ans D STEP 02 ANALYSIS OF JU QUESTION 01. abvZ¥K Pv‡R© PvwR©Z GKwU †ejyb GKwU gvwU‡Z Muv_v avZe `‡Ûi mv‡_ ¯úk© Ki‡j, †ejy‡bi PvR©- [JU-A, Set-A. 19-20] A. K‡g hv‡e B. GKB _vK‡e C. k~b¨ n‡e D. †KvbwUB bq f~wg Pv‡R©i mvMi n‡jI G‡Z Zwor wefe k~b¨| ZvB †h †Kv‡bv PvwR©Z e¯‘ f~wg‡Z mshy³ n‡j mKj PvR© f~wg‡Z P‡j hvq Ges PvwR©Z e¯‘i PvR© k~b¨ n‡q hvq| 02. KuvP`Û‡K ckgx Kvco Øviv Nl‡j KuvP`‡Û Drcbœ PvR©- [JU: 2013-14] A. †b‡MwUf B. cwRwUf C. cwRwUf I †b‡MwUf D. †Kvb PvR© Drcbœ nq bv Ans B 03. Zwor AšÍiK †KvbwU? [JU: 13-14] A. dmdivm B. gvwU C. †gvg D. gvbe‡`n Ans C 04. †Kvb †MvjKxq cwievnxi e¨vmva© r Ges Gi Dci mylgfv‡e Aew¯’Z Pv‡R©i cwigvY Q n‡j, Pv‡R©i Zj-NbZ¡ n‡e- [JU: 2011-12] A. = 1 4Q r 2 B. = Q 4r 2 C. = 4r 2 Q D. = 1 4 Qr2 Ans B 05. `ywU cwievnx‡Z wecixZgyLx Zwor cÖevn ci¯úi‡K [JU: 2010 -11] A. weKl©Y K‡i B. AvKl©Y K‡i C. †Kvb ej wµqv K‡i bv D. †KvbwUB bq Ans A 06. PvR© cwievnxi †Kv_vq Ae¯’vb K‡i? [JU: 2010-11, MAT: 2002-03] A. wfZ‡ii c„‡ô B. †K‡›`ª C. Dfq c„‡ô D. evB‡ii c„‡ô Ans D 07 cwievn‡Ki c„‡ôi †Kvb we›`yi Pviw`‡K cÖwZ GKK †¶Îd‡ji Dci Avav‡bi cwigvY‡K H we›`yi- [JU: 2009-10] A. Zwor cÖvej¨ B. Avavb NbZ¡ C. Zwor ej‡iLv D. †KvbwUB bq Ans B 08. c„w_exi wef‡ei gvb- [JU: 2009-10; RU: 2017-18] A. 100 V B. 220 V C. 1.5 V D. 0 V Ans D 09. GKwU wew”Qbœ abvZ¥K we›`y Pv‡R©i ej‡iLv- [JU: 2009-10] A. AšÍgy©Lx B. ewngy©Lx C. `Û Pz¤^‡Ki ej‡iLvi gZ D. †Kvb ej‡iLv †bB Ans D STEP 03 ANALYSIS OF RU QUESTION 01. GK Kzj¤^ Pv‡R© KZ¸‡jv B‡jKUª‡bi PvR© _vK‡e? [RU: 2017-18] A. GKwU B‡jKUª‡bi B. 6.25×1018 B‡jKUª‡bi C. 1.6×1019 B‡jKUª‡bi D. 6.25×10–19 B‡jKUª‡bi 1 Kzj¤^ Pv‡R© 6.25×1018 msL¨K B‡jKUª‡bi PvR© i‡q‡Q| 02. Zwor ej‡iLvi ag© †KvbwU? [RU: 2010-11] A. ej†iLv¸‡jv me©`v Uvb Kiv w¯’wZ¯’vcK myZvi b¨vq •`N¨© eivei cÖmvwiZ n‡Z †Póv K‡i| B. ej†iLv¸‡jv ci¯úi‡K cv‡ki w`‡K AvKl©Y K‡i| C. ej‡iLv¸‡jv me©`v PvwR©Z cwievnxi c„‡ôi mv‡_ mgvšÍivj fv‡e _v‡K D. `ywU ej‡iLv ci¯úi‡K †Q` K‡i bv| Ans D 03. wb‡¤œi †KvbwU mwVK bq? [RU: 2009-10] A. c„w_ex GKwU Zwor cwievnK B. c„w_ex abvZ¥Kfv‡e AvwnZ e¯‘‡K wb¯ÍwiZ K‡i C. c„w_ex FYvZ¥Kfv‡e AvwnZ e¯‘‡K wb¯ÍwiZ K‡i D. c„w_ex Zwor AcwievnK Ans D STEP 04 ANALYSIS OF DU-7 Clg QUESTION 01. k~b¨¯’v‡bi †f`b †hvM¨Zvi (0) GKK †KvbwU? [DU. 7Clg-A: 20-21] A. C –2Nm–2 B. C 2N –1m –2 C. C 2N –2m –1 D. CN–1m –2 S B info 0 = 8.854 10–12 C 2N –1m –2 STEP 05 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. GKwU ej b‡j KZ msL¨K ej †iLv _v‡K? [JnU: 2015-16] A. 1 B. 2 C. D. 2 Ans A 02. w¯’i Pv‡R©i Dci †P․¤^K ej- [JnU: 2015-16] A. k~b¨ B. AZ¨šÍ †ekx C. AZ¨šÍ Kg D. †KvbwUB bq Ans A 03. B‡jKUªb †fvë (eV) wK‡mi GKK? [JnU: 2013-14] A. Avavb B. ZxeªZv C. KvR D. cÖevn Ans C 04. Pv‡R©i ZjgvwÎK Nb‡Z¡i GKK- [JnU: 2011-12] A. Cm-1 B. Cm-2 C. Cm-3 D. C2m -2 Ans B
434 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES KU 01. B‡j±ª‡bi PvR© KZ? [KU: 2014-15] A. 1.6 × 10-19 C B. 1.9 × 10-19 C C. 1.96 × 10-16 C D. 9.1 × 10-31C Ans A 02. AšÍixY cwievnxi †h †Kvb As‡k PvR© cÖ`vb Ki‡j Dnviv cwievnxi me©Î Qwo‡q c‡o Ges GB PvR© †Kej- [KU: 2004-05] A. cwievnxi wfZ‡ii c„‡ô Ae¯’vb K‡i B. cwievnxi g‡a¨ †Kvb we›`y‡Z Ae¯’vb K‡i C. cwievnxi evB‡ii c„‡ô Ae¯’vb K‡i D. cwievnxi g‡a¨ †Kvb †iLvq Ae¯’vb K‡i Ans C IU 01. AvwnZ e¯‘i †Kv_vq me‡P‡q †ekx Avavb _v‡K-[IU: 2016–17, JUST: 2014–15] A. †K‡›`ª B. AeZj Z‡j C. mgZj Z‡j D. DËj Z‡j PvR© †Mvj‡Ki c„‡ô Ae¯’vb K‡i| wfZ‡i PvR© bvB ZvB †Mvj‡Ki wfZ‡i Zwor cÖvej¨ k~b¨| 02. B‡j±‡bi MwZkw³ AbyhvqxÑ [IU: 2014 - 15] A. E = eV B. V = eE C. E = ½ mv2 D. E = v/e Ans A 03. wbDUª‡bi PvR©- [IU: 2012-13] A. abvZ¡K B. FbvZ¡K C. wbi‡c¶ D. †KvbwU bq Ans C 04. e¨vmva© hZ †QvU nq PvwR©Z Zj NbZ¡ ZZ- [IU: 2011-12] A. n«vm cvq B. AcwiewZ©Z _vK‡e C. cÖ_‡g n«vm c‡i e„w× cvq D. e„w× cvq Ans D 05. B‡evbvBU `Û‡K d¬v‡bj w`‡q Nl‡j B‡evbvBU `‡Û [IU: 2006-07] A. †Kvb PvR© Drcbœ nq bv B. cwRwUf PvR© Drcbœ nq C. †b‡MwUf PvR© Drcbœ nq D. Dfq PvR© Drcbœ nq Ans C PART B Analysis of Science & Technology Question MBSTU 01. Zwor ej‡iLvi AeZviYv K‡ib †K? [MBSTU: 2015-16] A. †jbR B. d¨viv‡W C. wbDUb D. AvBb÷vBb Ans B HSTU 01. †Kvb ai‡bi Zi‡ji ga¨w`‡q Zwor cÖevwnZ n‡j Zi‡ji †Kvb cwieZ©b nq bv? [HSTU: 2015-16] A. cvi` B. cvwb C. ¶viK D. GwmW †gkv‡bv cvwb Ans A PSTU 01. we`y¨‡Zi †¶‡Î abPvR© I FYPvR© †K bvgKiY K‡ib? [PbSTU: 2013-14] A. Kzj¤^ B. d¨viv‡W C. †eÄvwgb d«v¼wjb D. Ing Ans C 02. we`¨yrex¶Y h‡š¿i mvnv‡h¨ †KvbwU Rvbv hvq bv? [PbSTU: 2013-14] A. Pv‡R©i cwigvc B. Pv‡R©i Aw¯ÍZ¡ C. Pv‡R©i cÖK„wZ D. Pv‡R©i cÖ‡ek¨Zv Ans B STEP 06 ANALYSIS OF ENGINEERING & BUTex QUESTION BUET 01. GKwU PvwR©Z e¯‘‡K AwMœ wkLvi Dc‡i a‡i ivL‡j Zv APvwR©Z nq| KviY [BUET: 2011-12] A. AwMœ wkLvi DËß M¨vm AvqwbZ nq e‡j B. DËß Kiv n‡j e¯‘wU cwievnx‡Z iƒcvšÍwiZ nq e‡j C. e¯‘wU AwMœ wkLvi wecix‡Z PvwR©Z nq e‡j D. DËß M¨vmwU e¯‘wU‡K AvNvZ K‡i Ges PvR© AcmviY K‡i e‡j Ans D 02. GKwU Møvm iW wm‡éi Kvco Øviv Nl©b Kiv n‡j Møvm i‡W †h ai‡bi we`y¨r Drcbœ n‡e Zv n‡jv- [CUET: 2009-10] A. FbvZ¡K B. abvZ¡K C. FbvZ¡K Ges abvZ¡K DfqB D. None Ans B STEP 07 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. Avavb msµvšÍ wb‡Pi †Kvb Z_¨wU mwVK bq? [MAT: 2008-09] A. Nl©‡bi d‡j PvR© m„wó nq B. e = 1.6 10-19c C. B‡j±ª‡bi NvUwZ n‡”Q abvZ¡K PvR© D. Q = ±ne Ans A 02. †KvbwU Zwor ej‡iLvi ag© bq [MAT: 2006-07] A. ej‡iLv abvZ¡K cwievn‡Ki c„‡ôi mv‡_ j¤^fv‡e cÖ‡ek K‡i| B. Zwor ej‡iLv ¸‡jv abvZ¡K Avavb †_‡K †ei n‡q FYvZ¡K Avav‡b †kl nq C. `ywU ej‡iLv KL‡bv ci¯úi‡K †Q` K‡i bv D. Zwor ej‡iLv †Lvjv eµvKvi Ans A 03. †h †Kvb c`v_©‡K KqwU Dcv‡q PvwR©Z Kiv hvq ? [MAT: 2004-05] A. 1 wU B. 2 wU C. 3 wU D. 4 wU Ans C 04. MÖxK `vk©wbK †_wjm KZ mv‡j we`y¨r cÖ_g j¶ K‡ib? [MAT: 2003-04] A. 600 Lªxóc~e©vã B. 650 L„xóc~e©vã C. 700 L„xóc~ev©ã D. 750 L„xóc~ev©ã Ans A 05. wb‡Pi †KvbwUi Dci Avweó PvR© wbf©i K‡i bv? [MAT: 2003-04] A. Av‡ekx Pv‡R©i cwigvb B. Avweó e¯‘i †¶Îdj C. Avweó e¯‘i cÖK…wZ D. Avweó e¯‘i Ávb Ans D 06. Zwor ev Avavb m¤ú‡K© wb‡Pi †KvbwU mwVK bq? [MAT: 2001-12] A. †Kvb wWwm g~j ms‡hv‡Mi `ywU Zv‡ii †KvbwU aYvZ¡K ev Zwor we‡køl‡Yi mvn‡h¨ wbb©q Kiv B. †Kvb KzÛjx‡Z cÖevngvÎv GK GKK n‡j, H KzÛjxi mv‡_ RwoZ †gvU d¬v· msL¨vMZ fv‡e Gi Av‡ek ¸Yv‡¼i mgvb C. GKwU Zwor ex¶Y h‡š¿ Avavb hw` nq FYvZ¥K Ges cix¶Yxq e¯‘i Avavb hw` abvZ¥K nq, cvZ؇qi duvK e„w× cv‡e| D. Amgfv‡e DËß †Kvb cwievnx‡Z Zwor Pvjbv Ki‡j cwievn‡Ki †Kv_vI Zv‡ci D™¢e Ges †Kv_vI Zv‡ci †kvlY nq G‡K e‡j †cjwkqvi wµqv Ans C DAT 01. Pv‡R©i SI GKK KZ? [DAT. 2020-21] A. †fvë B. d¨viv‡W C. Ing D. Kzj¤^ S.I. c×wZ‡Z Pv‡R©i GKK Kzj¤^| STEP 08 ANALYSIS OF HSC BOARD QUESTION 01. 1 B‡jKUªb †fvë (1 eV) n‡jv- [Xv. †ev. 2017] A. 1.6 109 J B. 1.6 109 J C. 1.6 1019 J D. 1.6 1019 J S C info 1eV = 1.6 10–19 C 1V = 1.6 10–19J 02. wb‡Pi †KvbwU AšÍiK? [P. †ev. 2016] A. †jvnv B. wmivwgK C. wemgv_ D. wmwjKb Ans B 03. wb‡Pi †Kvb kw³ Ab¨ kw³‡Z mn‡R iæcvšÍwiZ n‡Z Pvq bv? [P. †ev. 2016] A. Zvc B. Av‡jv C. kã D. Zwor Ans A 04. me‡P‡q †ewk Avavb _v‡K AvwnZ e¯‘i- [w`. †ev. 2016] A. †K‡›`ª B. AeZj Z‡j C. mgZj Z‡j D. DËj Z‡j Ans D 05. Av‡cwÿK †f`b‡hvM¨Zv me‡P‡q †ewk- [w`. †ev. 2016] A. A‡åi B. G‡evbvB‡Ui C. Kv‡Pi D. cwjw_‡bi Ans A 06. wb‡Pi †KvbwU PvR© cÖev‡ni nvi cwigv‡ci GKK? [h. †ev. 2016-17] A. Kzj¤^ B. †fvë C. A¨vw¤úqvi D. wm‡gÝ Ans C 07. Avav‡bi †Kvqv›Uvqb Abymv‡i †Kv‡bv e¯‘‡Z wb‡Pi †Kvb PvR©wU _vKv m¤¢e? [B‡jKUª‡bi PvR© 1.6 10–19 C] [Kz. †ev. 2017] A. 4.6 10–19C B. 3.2 10–19CC. 6.2 1019C D. 9.4 1019C S B info Q = ne †hLv‡b, n = 1, 2, 3, 4, 5 BZ¨vw` n‡j (B) Ackb mwVK|
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 435 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 2 Kzj‡¤^i m~Î ✅ Kzj‡¤^i m~Î: divmx weÁvbx ÒPvj©m AMvw÷b wW Kzj¤^Ó 1785 mv‡j ÒwecixZ eM©xq m~ÎÓ bv‡g GKwU m~Î cÖKvk K‡ib, hv 1787 mv‡j Kzj‡¤^i m~Î wn‡m‡e AvZ¥cÖKvk K‡i| Ò‡Kvb GKwU wbw`©ó gva¨‡g `ywU we›`y Pv‡R©i g‡a¨ wµqvkxj AvKl©Y ev weKl©Y e‡ji gvb PvR© `ywUi ¸Yd‡ji mgvbycvwZK, PvR© `ywUi ga¨eZ©x `~i‡Z¡i e‡M©i e¨¯ÍvbycvwZK Ges G ej PvR© `ywUi ms‡hvRK †iLv eivei wµqv K‡i| GB m~Îvbymv‡i, F q1q2 r 2 Gm.AvB (S.I) ev Gg. †K Gm. (M.K.S) c×wZ‡Z K = 1 4 †jLv hvq| (Epsilon) n‡jv PvR© `ywU †h gva¨‡g Aew¯’Z H gva¨‡gi †f`b‡hvM¨Zv ev ms‡ÿ‡c †f`¨Zv (Permitivity) F = 1 4 q1q2 r 2 k~b¨ ev evqy gva¨‡gi g‡a¨ Kzj‡¤^i m~Î wb¤œiƒc: F0 = F = 1 40 q1q2 r 2 0= 8.854 10–12 Kzj¤^2 /(wbDUb-wgUvi) 2 c 2 N.m2 Ges 1 40 = 9 109 wbDUb-wgUvi2 /Kzj¤^2 [* gva¨‡gi †h a‡g©i Rb¨ `yÕwU Pv‡R©i ga¨eZ©x AvKl©Y ev weKl©Y e‡ji A_©vr •e`y¨wZK †ÿ‡Îi cwieZ©b N‡U Zv‡KB †f`¨Zv ev cviwgwUwfwU (Permittivity) e‡j| AZGe, mgxKiY (3) n‡Z cvB, F0 = 9 109q1q2 r 2 ✅ we›`yPvR©: †h mKj ZwoZvwnZ e¯‘i AvKvi Zv‡`i AšÍeZ©x `~i‡Z¡i Zzjbvq bMb¨, Zv‡`i‡K we›`yPvR© e‡j| ✅ mgag©x Avavb ci®úi‡K weKl©Y K‡i Ges wecixZ ag©x Avavb ci®úi‡K AvKl©Y K‡i| ✅ `ywU Pv‡R©i ga¨Kvi AvKl©Y I weKl©Y e‡ji gvb 3wU k‡Z©i Dci wbf©i K‡i| PvR©`ywUi cwigvY PvR©`ywUi ga¨eZ©x `~iZ¡ PvR©`ywUi ga¨eZ©x gva¨g ✅ Pv‡R©i Ae¯’vb me©`vB e¯‘i evB‡ii c„‡ô| ✅ Pv‡R©i GKK: S.I. c×wZ‡Z Kzj¤^| 1 C = 1 A1 S ✅ `ywU mggv‡bi PvR© k~b¨ gva¨‡g 1 m `~‡i Ae¯’vb K‡i ci¯ú‡ii Dci 9 109N ej cÖ‡qvM Ki‡j, H PvR© `ywUi cÖ‡Z¨K‡K GK Kzj¤^ e‡j| A_ev, cwievnxi ga¨ w`‡q| 1 A cÖevn 1 S a‡i Pj‡j, †h cwigvY Avavb cÖevwnZ nq, Zv‡K GK Kzj¤^ e‡j| ✅ Kzj‡¤^i m~Î †KejgvÎ we›`y Pv‡R©i Rb¨ cÖ‡hvR¨| ✅ Kzj‡¤^i m~Î mivmwi cÖ‡qvM K‡i `ywU ZwoZvwnZ we¯Í…Z e¯‘i cvi¯úwiK ej wbY©q Kiv hvq bv| ✅ F Gi gvb abvZ¥K ivwk n‡j ej weKl©Y g~jK| ✅ Kzj‡¤^i m~‡Îi mxgve×Zv: ïaygvÎ w¯’i Pv‡R©i †ÿ‡Î cÖ‡hvR¨; MwZkxj Pv‡R©i †ÿ‡Î GB m~Î cÖ‡qvM Kiv hvq bv| Ave× Pv‡R©i †ÿ‡Î Kzj‡¤^i m~Î cÖ‡hvR¨ bq| * we›`y Pv‡R©i †ÿ‡Î cÖ‡hvR¨| *** †hme e¯‘i †ÿ‡Î Kzj‡¤^i m~Î cÖ‡hvR¨ bq Zv g‡b ivLvi mnR Dcvq: Awb evmv †_‡K Av‡jvi †e‡M MwZkxj n‡jv| Awb ev mv †_‡K Av‡jvi †e‡M MwZkxj n‡jv AwbqwgZ AvK…wZi PvwR©Z e¯‘ eo PvwR©Z e¯‘ m`„k PvR© web¨vm hLb PvwR©Z KYvmg~‡ni †eM Av‡jvi †e‡Mi KvQvKvwQ nq MwZkxj PvR© REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF JU QUESTION 01. `ywU we›`y PvR© ci¯úi‡K †h e‡j AvKl©Y ev weKl©Y K‡i Zv PvR©Ø‡qi- [JU: 2013-14] A. †hvMd‡ji e¨¯ÍvbycvwZK B. e‡M©i mgvbycvwZK C. †hvMd‡ji mgvbycvwZK D. †KvbwUB bq Fq1q2 02. aªæe msL¨v 0 Gi gvb- [JU: 2010-11] A. 8.85410–12 C 2N –1m –2 B. 5.85410–12C 2Nm C. 8.85410–12C 2Nm D. 5.8510–12 C 2N –1m –1 Ans A STEP 02 ANALYSIS OF CU QUESTION 01. 1 40 Gi gvb KZ? [CU: 2015-16] A. 9.0109Nm~2C 2 B. 9.0109NmC–2 C. 9.0109Nm2C –2 D. 8.510–12Nm2C –2 E. 8.51012NmC–1 Ans C 02. k~b¨ gva¨‡g Kzj‡¤^i m~Î †f±‡ii mvnv‡h¨ wb¤œiƒ‡c cÖKvk Kiv hvq- [CU: 2008-09;Xv. †ev. 2015] A. F = 1 40 Q1Q2 r 2 B. F = 1 40 X Q 1Q 2 r 2 C. F = 1 40 Q1Q2 r 3 r D. F = 1 4 Q1Q2 r 2 r Ans C STEP 03 ANALYSIS OF GST QUESTION PART A Analysis of General University Question CoU 01. k~b¨¯’v‡b Av‡cw¶K †f`b †hvM¨Zvi gvb- [CoU: 2013-14] A. 1.005 B. 1.0000 C. 1.0005 D. 2.3 Ans A A B F q1 r q2
436 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES IU 01. †f`b‡hvM¨Zvi GKK- [IU: 2012-13] A. Kzj¤^2 /wbDUb-wgUvi B. d¨vivW/wgUvi C. Kzj¤^/wbDUb D. d¨vivW/wgUvi2 Ans B PART B Analysis of Science & Technology Question BSMRSTU 01. `yBwU PvR© q1 Ges q2 ci¯úi †_‡K r `~i‡Z¡ _vK‡j wµqvkxj ej hw` F nq Zvn‡j Dfq PvR©‡K wظY Ges `~iZ¡ A‡a©K Ki‡j wµqvkxj e‡ji gvb n‡e- [BSMRSTU-B, 19-20] A. F B. 4F C. 8F D. 16F F = 9 109 Q1Q2 d 2 F2 = 2 2 1 2 2 F1 = 16F1 NSTU 01. Kzj‡¤^i m~ÎwU †KvbwUi †ÿ‡Î cÖ‡hvR¨? [NSTU-A, 19-20] A. e„nr PvR© B. ÿz`ª PvR© C. we›`y PvR© D. †h †Kvb PvR© Kzj‡¤^i m~Î ïaygvÎ we›`y Pv‡R©i †ÿ‡Î cÖ‡hvR¨| AvwnZ ev PvwR©Z e¯‘i AvKvi hLb LyeB †QvU nq, ZLb H ewR©Z e¯‘i PvR©‡K we›`y PvR© e‡j| STEP 04 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. `ywU Avav‡bi ga¨eZx© `~iZ¡ wZb¸Y Kiv n‡j, Z‡e ej KZ ¸Y n‡e? [MAT: 2016-17] A. 1 9 B. 9 C. 1 3 D. 3 Ans A 02. Kyj‡¤^i m~Îvbymv‡i †Kvb&wU mwVK bq? `ywU we›`y PvR© ci¯úi‡K †h e‡j AvKl©Y K‡i Zv PvR©Ø‡qi- [MAT: 2013-14] A. ¸Yd‡ji mgvbycvwZK B. ga¨eZ©x `~i‡Z¡i e‡M©i e¨¯ÍvbycvwZK C. ms‡hvM mij‡iLv eivei wµqv K‡i D. ga¨eZ©x `~i‡Z¡i e‡M©i A‡a©‡Ki e¨¯ÍvbycvwZK Ans D STEP 05 ANALYSIS OF HSC BOARD QUESTION 01. wb‡Pi †Kvb mgxKiYwU fzj? [Xv. †ev. 2017] A. E = hf B. I = Is + Ig C. F = 1 40 q1q2 d D. C = Q V Ans C 02. ci‣e`y¨wZK aªæe‡Ki GKK †KvbwU? [iv. †ev. 2017] A. C 2N –1m –2 B. C 2N –2m –1 C. GKK wenxb D. CN–1m –2 Ans C 03. Zwor †f`bv‡hvM¨Zvi GKK †KvbwU? [e. †ev. 2015; P. †ev. 2016; CU. 19-20] A. C 2N –1m –2 B. Nm2C –2 C. C 2N –2m –2 D. Nm2C –2 Ans A 04. Kzj‡¤^i m~‡Î mgvbycvwZK aªæe‡Ki gvb KZ? [wm. †ev. 2015] A. 1 C B. 9 109 Nm2C 2 C. 8.854 1012 CN1m 2 D. 2 107 N Ans B Concept 3 Zwor‡ÿÎ, Zwor‡ÿ‡Îi cÖvej¨ I Zwor d¬v· ✅ †¶Î ZË¡: gvB‡Kj d¨viv‡W `ywU PvwR©Z e¯‘i cvi¯úwiK wµqv e¨vL¨vi Rb¨ Zwor †¶‡Îi avibv Dc¯’vcb K‡ib| ✅ `ywU PvwR©Z e¯‘i ga¨eZ©x `~iZ¡ Amxg n‡jB, †Kej cvi¯úwiK Zwor e‡ji gvb k~b¨ n‡Z cv‡i| ✅ e¯‘i IRb I Zwor ej mgvb n‡j e¯‘ w¯’i _vK‡e| ✅ Zwor ej mgxKiY: F = qE ◈ q = Pv‡R©i gvb; E = Zwor‡ÿÎ| ◈ GKK: wbDUb ◈ Zwor e‡ji DcwicvZb bxwZ: cÖ‡Z¨KwU Pv‡R©i Rb¨ e‡ji wbY©xZ †f±i †hvMdj = Pv‡R©i Dci wµqvkxj bxU ej| ✅ Zwor †¶Î: †Kvb GKwU PvwR©Z e¯‘i Pviw`‡K †h AÂje¨vcx Zvi cÖfve we¯Ívi K‡i, Zv‡K H PvwR©Z e¯‘i Zwor †¶Î e‡j| GKK: wbDUb/Kzj¤^ (NC –1 ) A_ev †fvë/wgUvi (Vm –1 ) Zwor †¶Î GKwU †f±i ivwk| AZ¨šÍ ¶z`ª gv‡bi KvíwbK PvR©, hv Ab¨ †Kvb Pv‡R©i Dci ej cÖ‡qvM K‡i bv, Zv‡K ciL PvR© e‡j| MvwYwZK fv‡e •e`y¨wZK †¶Î Amxg, wKš‘ ev¯Í‡e, wbw`©ó mxgv ch©šÍ AvKl©Y ev weKl©Y ej wµqv K‡i| Zwor †¶‡Îi gvb I w`K me©Î mgvb nB‡j, Zv‡K mylg Zwor †¶Î e‡j| ✅ Zwor cÖvej¨: •e`y¨wZK †ÿ‡Îi †Kvb we›`y‡Z cÖwZ GKK abvZ¥K Pv‡R©i Dci †h ej wµqv K‡i Zv‡K H we›`yi Zwor cÖvej¨ e‡j| Zwor cÖvej¨ †f±i ivwk| ✅ Zwor d¬v·: Zj/c„‡ôi ga¨ w`‡q hZ¸‡jv Zwor ej‡iLv AwZµg K‡i, ZvB Zwor d¬v·| GwU GKwU †¯‥jvi ivwk| cÖKvk: E = E. A = EA cos [E= Zwor cÖvej¨, A = †ÿÎdj] Zwor †¶Î I Z‡ji Awfj¤^ mgvšÍiv‡j Zwor d¬v· me©vwaK| KviY, = 0 Zwor †¶Î I Z‡ji Awfj¤^ mg‡Kv‡Y Zwor d¬v· k~b¨| KviY, = 90 Zwor cÖvej¨: Zwor †¶‡Îi †Kvb we›`y‡Z GKK abvZ¥K ¯’vcb Ki‡j GwU †h ej Abyfe K‡i Zv‡K H †¶‡Îi H we›`y‡Z cÖvej¨ e‡j| Zwor cÖve‡j¨i ivwkgvjv : E = 9 109 q r 2 [q= †h Pv‡R©i Rb¨ cÖvej¨ m„wó nq|] GKK: Vm–1 A_ev NC–1 , E= – dV dr ✅ ¸iæZ¡ c~Y© Z_¨: Zwor cÖvej¨ wecixZ eM©xq m~Î †g‡b P‡j| ciL PvR© GZB ¶z`ª †h, GUv Zwor †¶Î‡K cÖfvweZ K‡i bv| eis ciL Pv‡R©i Av‡k cv‡ki GK ev GKvwaK PvR©B Zwor †¶‡Îi Drm| cÖvej¨ 5.5710–11NC –1 n‡j, GKwU B‡jKUªb Zvi IR‡bi mgvb ej Abyfe K‡i| F F E +q E (K) (L) –q
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 437 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. •e`y¨wZK d¬v· Gi GKK- [DU: 2016-17] A. Newton-meter2 /Coulomb B. Newton-meter/ Coulomb C. Newton/ Coulomb D.Newton/ meter2 Ans A 02. r `~i‡Z¡ ivLv `ywU ¶z`ª KYvi g‡a¨ ci¯úi ga¨vKl©xq AvKl©Y F, KYv `yBwUi gvSLv‡b GKwU fvix †jvnvi cvZ ivLv n‡j GLb Zv‡`i g‡a¨ ci¯úi AvKl©Y ej KZ ? [DU: 2013-14] A. 0 B. F C. F/2 D. F/4 Ans B 03. GK Kzj¤^ gv‡bi `ywU abvZ¡K Avavb 1cm. `~i‡Z¡ Aew¯’Z| hw` G‡`i GKwU abvZ¡K Avavb mwi‡q GK Kzj¤^ gv‡bi FYvZ¡K Avavb emv‡bv nq Z‡e Avavb `ywUi ga¨Kvi e‡ji gvb- [DU: 2005-06] A. k~b¨ B. Av‡Mi †P‡q Kg C. Av‡Mi †P‡q †ewk D. Av‡Mi mgvb Ans D STEP 02 ANALYSIS OF JU QUESTION 01. wb‡Pi †Kvb mgxKiYwU fzj? [JU-H, Set-1. 19-20] A. 1 σ QA B. r q 4π 1 E 0 C. 2 1 2 r q q 4π 1 F D. Q = CV Avgiv Rvwb Zwor cÖvej¨, E = 1 40 q r 2 02. GKwU FYvZ¥K PvR© c„ôvi evg †_‡K Wvb w`‡K ¯’vwcZ GKwU Zwor †ÿ‡Î ¯’vcb Ki‡j, Pv‡R©i Dci cÖ`Ë e‡ji w`K- [JU-A, Set-D. 19-20] A. evg †_‡K Wvb B. Wvb †_‡K evg C. c„ôvi †fZi †_‡K evB‡i D. †KvbwUB bq hw` PvR© abvZ¥K nq Zvn‡j Zwor ej, Zwor‡ÿ‡Îi mv‡_ GKB w`‡K wµqviZ nq| hw` PvR© FYvZ¥K nq Zvn‡j Zwor ej, Zwor‡ÿ‡Îi mv‡_ wecixZ w`‡K wµqviZ nq| 03. E cÖvej¨ wewkó mylg Zwor †¶‡Î A we›`y n‡Z B we›`y‡Z Avb‡Z bx‡Pi †KvbwU cÖ‡hvR¨- [JU: 2016–17] A. cÖvej¨ Ges miY mggyLx B. cÖvej¨ Ges miY wecixZgyLx C. cÖvej¨ mi‡Yi e¨¯ÍvbycvwZK D. †KvbwUB bq Ans B 04. mylg Zwor †¶‡Îi gvb I w`KÑ [JU: 2011-12] A. me©Î Amgvb B. me©Î mgvb C. gvb mgvb wKš‘ w`K wfbœ D. †KvbwUB bq Ans B 05. +q PvR© n‡Z r `~‡ii †Kvb we›`y‡Z Zwor †¶‡Îi cÖvej¨ KZ? [JU: 2011-12] A. E = 1 40 q r 2 B. E = 1 40 r 2 q C. E = 1 4r q 0 D. E = 1 40 q 2 r Ans A 06. Zwor cÖve‡j¨i- [JU: 2009-10] A. gvb Av‡Q w`K †bB B. w`K Av‡Q gvb †bB C. gvb I w`K DfqB Av‡Q D. Aw¯ÍZ¡ †bB Ans C 07. m f‡ii GKwU cvwbi †duvUv GKwU gvÎ B‡jKUªb Øviv PvwR©Z nq| Bnv‡K SzjšÍ Ae¯’vq a‡i ivL‡Z cÖ‡qvRbxq Zwor †¶‡Îi cwigvY KZ? [JU: 2009-10] A. mg B. mg e C. mge D. em g Ans B STEP 03 ANALYSIS OF RU QUESTION 01. wb‡Pi †Kvb mgxKiYwU wefe cv_©K¨ I cÖve‡j¨i g‡a¨ m¤úK© ¯’vcb K‡i? [RU: 2017-18] A. F = qoE B. V=1/4E0.q/r C. E = v/d D. V = w/q Ans C STEP 04 ANALYSIS OF CU QUESTION 01. GKwU PvwR©Z Lvwj, †Mvj‡Ki Af¨šÍ‡i •e`y¨wZK ZxeªZv KZ? [CU-A, Set-2. 19-20] A. Eo B. /Eo C. Eo /2 D. k~Y¨ PvwR©Z †Mvj‡Ki Af¨šÍ‡i •e`y¨wZK ZxeªZv/cÖvej¨ k~b¨ KviY wefe me©Î mgb/aªæe _v‡K| 02. Zwor cÖve‡j¨i GKK wK? [CU: 2015-16] A. Nm B. JC C. NC–1 D. V E .N–1C Ans C 03. k~b¨¯’v‡bi †f`¨Zv KZ ? [CU: 2012-13] A. 8.8541012C 2N 1m 2 B. 8.8541016C 2N 1m 2 C. 8.8541010C 2N 1m 2 D. 8.85410x C 2N 1m 2 E. 8.854101 C 2N 1m 2 Ans A 04. GKwU wbw`©ó cwigvY PvR© q †K wKiƒc `yÕwU As‡k fvM Ki‡j Dnviv GKwU wbw`©ó e¨eav‡b †_‡K me‡P‡q †ewk e‡j weKl©Y Ki‡e? [CU: 2006-07] A. 2 q , 2 q B. 4 3q , 4 q C. 5 2q , 5 q D. 3 2q , 3 q E. 6 5q , 6 q Ans A STEP 05 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. 1 e.m.u (Electromagnetic Unit) = KZ A¨vw¤úqvi? [IU-D, 19-20] A. 10A B. 1/10A C. 1/100A D. 1/1000A 1 e.m.u (Electromagnetic Unit) = 10 Coloumb Avgiv Rvwb, I = q t 1 e.m.u = 10A IU 01. Point Charge- Gi Rb¨ r- `~i‡Z¡ q Pv‡R©i Rb¨ †fv‡ëR- [IU: 2015-16] A. V=4q/0r B. V=q/20r C. V=q/40r D. V=r/40q Ans C PART B Analysis of Science & Technology Question SUST 01. Zwo”PvjK ej (electromotive force)-Gi GKK †KvbwU? [SUST:2018-19] A. N B. Nm C C. V C D. J E. J s Ans B 02. GKwU eM©‡¶‡Îi Pvi †KvYvq PviwU abvZ¡K mgvb PvR© q ivLv n‡q‡Q, Zvn‡j e‡M©i †K‡›`ª- [SUST: 2005-06] A. Zwor cÖvej¨ Ges wefe k~b¨ gvb wewkó B. Zwor cÖvej¨ k~b¨ Ges wefe abvZ¡K gvb wewkó C. Zwor cÖvej¨ abvZ¡K Ges wefe k~b¨ gvb wewkó D. Zwor cÖvej¨ Ges wefe abvZ¡K gvb wewkó Ans B 03. `ywU mgvšÍivj cv‡Zi g‡a¨ Zwor †¶‡Îi cªvej¨ mylg| GKwU cvZ n‡Z Ab¨wUi `~iZ¡ evovi mv‡_ wefe cv‡ki †Kvb †jLwPÎ Abyhvqx cweewZ©Z n‡e? [SUST: 2014-15] A. v d B. d v C. d v D. d v V = Ed MBSTU 01. `ywU PvwR©Z e¯‘ ci¯ú‡ii mv‡_ mshy³ Ki‡j Pv‡R©i cÖevn †Kvbw`‡K n‡e Zv †Kvb wel‡qi Dci wbf©i K‡i? [MBSTU-C, Set-2 19-20, IU. 15-16] A. Pv‡R©i cwigvY B. Zwor †ÿÎ C. Zwor cÖvej¨ D. Zwor wefe Zwor wefe wbY©q K‡i Pv‡R©i cÖev‡ni w`K| 02. GKwU mgvšÍivj cvZ avi‡Ki `yB †cø‡Ui gv‡S WvB-B‡jKwUªK c`v_© XzKv‡j Zvi mwÂZ kw³ cuvP¸Y e„w× cvq| H c`v‡_©i WvB-B‡jKwUªK aªæe‡Ki gvb KZ? [MBSTU-C, Set-2 19-20] A. 0.04 B. 0.2 C. 5 D. 25 U K ,K = WvBB‡jKwUªK aªæeK K = 5 03. Zwor †¶‡Îi †Kv‡bv we›`y‡Z cÖvej¨ E n‡j H we›`y‡Z ¯’vwcZ q Avavb †h F ej jvf Ki‡e Zv n‡e- [MBSTU: 2014-15] A. qE B. q E C. E q D. q2E Ans A
438 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES STEP 06 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. cÖ‡ek¨Zvi GKK †KvbwU- [MAT: 2004-05] A. C2 /N-m 2 B. C/N-m 2 C. C2 /N2 -m D. C/N2 -m Ans A STEP 07 ANALYSIS OF HSC BOARD QUESTION 01. Zwor †ÿ‡Îi gvb wbY©q Kiv hvqÑ [iv. †ev. 2015, KU. 18-19] i. Kzj‡¤^i m~Î †_‡Kii. A¨vw¤úqv‡ii m~Î †_‡K iii. MvD‡mi m~Î †_‡K wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans B 02. Zwor‡ÿ‡Îi w`K wbY©‡q e¨eüZ nqÑ [w`. †ev. 2017] A. we›`y PvR© B. cig PvR© C. e×PvR© D. gy³PvR© Ans B 03. GKwU PvwR©Z mgZj cwievnxi mwbœK‡U Zwor cÖve‡j¨i gvb †KvbwU? [Kz. †ev. 2017] A. E = 20 B. E = 0 C. E = 2 0 D. E = 3 20 Ans A 04. Zwor cÖvej¨ I `~i‡Z¡i ga¨Kvi m¤úK©m~PK †jLwPÎ †KvbwU? [wm. †ev. 2016] A. B. C. D. E d E E E d d d Ans D 05. GKwU PvwR©Z e¯‘‡K c„w_exi mv‡_ hy³ Ki‡j e¯‘wU‡K Pv‡R©i cwigvYÑ [e. †ev. 2015] A. e„w× cv‡e B. n«vm cv‡e C. AcwiewZ©Z _vK‡e D. k~b¨ n‡e Ans D Concept 4 Zwor wefe I mgwefe Zj ✅ Zwor wefe: Amxg †_‡K GKwU abvZ¡K Avavb‡K Zwor †¶‡Î Avb‡Z †h KvR Ki‡Z nq| GKK: †fvë ev Ryj/Kzj¤^| cÖKvk: V = W Q = KvR PvR© | GwU †¯‥jvi ivwk| mgxKiY: V = 1 4o Q r ✅ wefe cv_©K¨/wefe •elg¨/wefevšÍi: `ywU we›`yi g‡a¨ wef‡ei e¨eavb‡K wefe cv_©K¨ e‡j| A_ev †Kvb we›`y†_‡K Aci we›`y‡Z GKwU Avavb Avb‡Z hZ KvR Ki‡Z nq Zv‡K wefe cv_©K¨ e‡j| [hw` E aªæeK nq] cÖKvk: V = Ed, GwU †¯‥jvi ivwk| ✅ mgwefe Zj: †h Z‡ji mKj we›`y‡Z wef‡ei gvb mgvb, †mUvB mgwefe Zj| A_©vr wefecv_©K¨ ev wef‡ei cwieZ©b, V = 0 mgwefe Z‡ji •ewkó¨: ZwoZvwnZ cwievnxi Zj me©`v mgwefe Zj| GB Z‡ji Dci Zwor Avavb¸wj w¯’i _v‡K| Zwor ej‡iLv mgwefe Zj‡K mg‡Kv‡Y †Q` K‡i| mgwefe Z‡ji Dci †Kv‡bv Zwor Avavb‡K GK we›`y n‡Z Aci we›`y‡Z ¯’vbvšÍwiZ Ki‡Z †Kv‡bv KvR nq bv †Kv‡bv e¯‘i Zj ev AvqZb mgwefe m¤úbœ n‡Z cv‡i| Avevi k~b¨ †`k¯’ (inspace) †Kvb Zj ev AvqZb I mgwefe m¤úbœ n‡Z cv‡i| mgwefe Zj KLbB ci¯úi‡K †Q` K‡i bv, ïay mg‡Kv‡Y †Q` K‡i| REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF JU QUESTION 01. Zwor wef‡ei gvÎv mgxKiY †KvbwU? [JU-H, Set-1. 19-20] A. [ML2T –3 I –1 ] B. [ML2T –2 I –2 ] C. [MLT–3 I –2 ] D. [ML–2T 2 I –2 ] V = W q = W It gvÎv = [ML2T 3 I 1 ] 02. c„w_exi Zwor wefe wb‡Pi †KvbwU? [JU: 2014-15] A. abvZ¥K B. FYvZ¥K C. AFYvZ¥K D. †KvbwUB bq c„w_exi wefe k~b¨ aiv nq| 03. †Mvj‡Ki c„‡ô wefe, V = ? [JU: 2011-12] A. Q 20rr B. Q 40rr C. 20rr Q D. 20rr Q Ans B 04. +q PvR© n‡Z r `~‡ii †Kvb we›`y‡Z Zwor wef‡ei ivwkgvjv †KvbwU? [JU: 2011-12] A. V = 1 40 q 2 r B. V = 1 40 q r C. V = 1 40 q r 2 D. V = 1 40 r q Ans B STEP 02 ANALYSIS OF RU QUESTION 01. Avavb I wef‡ei ¸Yd‡ji GKK wK? [RU: 2016–17, wm. †ev. 2015] A. Ryj B. †fvë C. d¨vivW D. †nbwi PvR© ¯’vbvšÍ‡ii K…ZKvR, W=VQ STEP 03 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. `ywU PvwR©Z mshy³ e¯‘i g‡a¨ PvR© cÖevwnZ n‡Z _v‡K hZ¶Y bv Zv‡`i- [KU: 2004-05] A. PvR© mgvb nq B. wefe mgvb nq C. aviKZ¡ mgvb nq D. mwÂZ kw³ mgvb nq Ans B IU 01. mylg †MvjvKvi †Lvj‡Ki wfZ‡i Aew¯’Z mKj we›`y‡ZÑ [IU: 2014-15] A. fi k~b¨ nq B. wefe k~b¨ nq C. cªvej¨ k~b¨ nq D. †KvbwUB bq Ans C 02. Amxg †_‡K cÖwZ Kzj¤^ abvZ¡K PvR©‡K Zwor †¶‡Îi †Kvb we›`y‡Z Avb‡Z GK Ryj KvR m¤úbœ nq Z‡e H we›`yi wefe- [IU: 2012-13] A. GK A¨vw¤^qvi B. GK B‡jKUªb-‡fvë C. GK †fvë D. GK IqvU Ans C mgwefe Zj Zwor ej‡iLv q +q
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 439 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES PART B Analysis of Science & Technology Question SUST 01. mgwefe Zj Ges Zwor cÖvej¨ ci®ú‡iiÑ [SUST: 2007-08] A. mgvšÍivj B. wecixZgyLx C. j¤^ D. †KvbwUB bq Ans C STEP 04 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. c„w_exi wefe KZ aiv nq? [MAT: 2017-18, BRUR. 12-13, w`.‡ev. 2017] A. 100 V B. 0 V C. 10 V D. 1 MV Ans B STEP 05 ANALYSIS OF HSC BOARD QUESTION 01. mgwefe Z‡ji †h †Kv‡bv `ywU we›`yi wefe cv_©K¨Ñ [Xv. †ev. 2016] A. k~Y¨ B. Amxg C. GK †fvë D. `yB †fvë Ans A 02. PvwR©Z duvcv †Mvj‡Ki †K›`ª n‡Z `~iZ¡ e„w×i mv‡_ wef‡ei cwieZ©b †Kvb †jLwPÎ cÖ‡hvR¨? [P. †ev. 2017] A. B. C. D. O R V V V V R R R O O O Ans B 03. wb‡Pi †KvbwU †fv‡ëi mgZzj¨? [P. †ev. 2016] A. JA–1 s –1 B. JA–1 s C. JAs–1 D. JAs S A info IV = I JC–1 = J (Amp.s)–1 = JA–1 s –1 04. GKwU PvwR©Z †MvjvKvi cwievnxiÑ [h. †ev. 2017] i. Af¨šÍ‡i cÖvej¨ k~b¨ ii. Af¨šÍ‡i wefe k~b¨ iii. c„‡ôi mKj we›`yi wefe mgvb wb‡Pi †KvbwU mwVK? Ans B A. i I ii B. i I iii C. ii I iii D. i, ii I iii 05. B O A C wP‡Î †Kvb `yB we›`yi wefe mgvb? [h. †ev. 2016] A. A Ges B B. B Ges C C. O Ges B D. O Ges A Ans D wb‡Pi DÏxc‡Ki Av‡jv‡K 06 I 07 bs cÖ‡kœi DËi `vI : +1C PvR©wewkó 10cm e¨vmv‡a©i GKwU avZe duvcv †MvjK, B †K AvKl©Y Ki‡Q| 06. A †MvjKwUi ZjgvwÎK NbZ¡ KZ? [wm. †ev. 2016] A. 7.96 C/m2 B. 7.96 C/Cm2 C. 31.83 C/m2 D. 31.83 C/cm2 S A info = Q A = 1 4(0.10) 2 = 7.96 C/m2 07. B †MvjKwU‡KÑ [wm. †ev. 2016] i. PvR©nxb n‡Z n‡e ii. abvZ¥K Pv‡R© PvwR©Z n‡Z nq iii. FYvZ¥K Pv‡R© PvwR©Z n‡Z nq wb‡Pi †KvbwU mwVK? Ans A A. i I ii B. ii I iii C. i I ii D. i, ii I iii Concept 5 Zwor w؇giæ ✅ Zwor w؇giæ: `ywU mgcwigvY wKš‘ wecixZag©x we›`y PvR© ci®ú‡ii Lye KvQvKvwQ _vK‡j w؇giæ MwVZ nq| w؇giæ åvgK, p = q 2l, GwU †f±i ivwk| hvi w`K (–ve) PvR© †_‡K (+ve) Pv‡R©i w`‡K| ✅ w؇giæ N~Y©‡b K…ZKvR, W = pE (cos1 – cos2) p = w؇giæ åvgK; E = Zwor‡ÿ‡Îi cÖvej¨, 1 = cÖve‡j¨i mv‡_ w؇giæi Avw` Ae¯’vb; 2 = cÖve‡j¨i mv‡_ w؇giæi †kl Ae¯’vb ✅ Zwor w؇giæi Rb¨ Zwor cÖvej¨, E = 1 4o P r 3 (1+3cos2 ) hLb = 0° A_©vr we›`ywU hw` w؇giæi A‡¶ Aew¯’Z nq, †m‡¶‡Î, E = 1 4o 2P r 3 hLb = 90° A_©vr we›`ywU A‡¶i Dci Awfj¤^ nq, †m‡¶‡Î, E = 1 4o P r 3 ✅ Zwor wØ †giæi Rb¨ Zwor wefe V = 1 4o Pcos r 2 hLb = 0° A_©vr we›`ywU A‡¶ Ae¯’vb K‡i †m‡¶‡Î vp = 1 4o . P r 2 hLb = 90° A_©vr we›`ywU A‡¶i Dci Awfj¤^ nq, †m‡¶‡Î vp = 0 ✅ Zwor wØ-‡giæ A‡¶i Dci †Kvb we›`y‡Z wefe, v = 1 4o p r 2 –l 2 ✅ Zwor wØ-‡giæi j¤^ wØLÛK †iLv eivei †Kvb abvZ¡K PvR©‡K miv‡j †Kvb KvR m¤úv`b Ki‡Z nq bv| ✅ ¯’vqx Zwor wØ-‡giæi D`vniY: cvwb (H2O), †K¬v‡ivdig (CHCl3) I A¨v‡gvwbqv (NH3) REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. GKwU Zwor w؇cv‡ji Rb¨ Zwor‡¶Î, `~iZ¡ r Gi mv‡_ wKfv‡e cwiewZ©Z nq? [DU: 2014 -15, JUST. 19-20] A. r–1 B. r–2 C. r D. r–3 S D info Zwor w؇cv‡ji Rb¨ Zwor‡¶Î, E = 1 40 P r 3 [P= dipole moment] E 1 r 3 STEP 02 ANALYSIS OF GST QUESTION IU 01. †Kvb PvR©‡K †P․¤^K‡¶‡Î ivL‡j H PvR©wU †P․¤^K ej Abyfe Ki‡e hLb- [IU: 2012-13] A. PvR©wU w¯’i _vK‡e B. PvR©wU MwZkxj n‡e C. PvR©wUi †e‡Mi Dcvsk _vK‡e bv D. †KvbwU bq Ans B E Er E E rd d O q q wPÎ: Zwor w؇giæ
440 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 6 aviK I aviKZ¡ ✅ Zwor aviKZ¡: †Kvb cwievnxi Zwor wefe GK-GKK e„w× Ki‡Z Gi g‡a¨ †h cwigvY PvR© cÖ`vb Ki‡Z nq, Zv‡K H cwievnxi aviKZ¡ e‡j| ✅ mgxKiY: C=Q/V; GKK aviK‡Z¡i GKK d¨viv‡W ✅ †MvjKxq cwievnxi aviKZ¡: C=4 0 Kr ev, C=4 r [ = 0K] ✅ aviK: cwievnx‡Z PvR© mwÂZ ivLvi hvwš¿K cÖwµqv‡K aviK e‡j| ✅ avi‡Ki aviKZ¡ = AšÍixZ cv‡Zi PvR© `yB cv‡Zi g‡a¨ wefe cv_©K¨ mgvšÍivj cvZ avi‡Ki aviKZ¡: d A C 0 ev, d K A C 0 ✅ cwievnxi aviKZ¡ wbf©i K‡i hvi Dci: PvR©MÖ¯’ cwievnxi Kv‡Q PvR©k~b¨ cwievnx, C ev‡o PvR©MÖ¯’ cwievnxi Kv‡Q PvR©hy³ cwievnx, C K‡g PvR©MÖ¯’ cwievnxi Kv‡Q wecixZ PvR©hy³ cwievnx, C ev‡o ✅ mgvšÍivj aviK, †Mvjxq aviK cÖf„wZ aviK mPivPi e¨eüZ nq| ✅ avi‡Ki aviKZ¡ wbf©i K‡i- avi‡Ki cv‡Zi †¶Îd‡ji Dci cvZ؇qi ga¨eZ©x `~i‡Z¡i Dci cvZ؇qi ga¨eZ©x gva¨‡gi ci‣e`y¨wZK aªæe‡Ki Dci ***aviKZ¡ g‡b ivLvi mnR Dcvq: aviKZ¡ †h †h wel‡qi Dci wbf©i K‡i `yt Lx ‡mv gv gva¨‡g `~iZ¡ (cvZ؇qi ga¨eZ©x) ‡ÿÎdj (cwievnxi) mvwbœa¨ (f~-mshy³ cwievnxi) cwievnxi Pvicvk^©¯’ ✅ civ‣e`y¨wZK aªæeK ev Zwor gva¨gvsK ev Av‡cw¶K †f`¨Zv: K ev r = 0 = F0 Fr = k~b¨ ev evqygva¨‡g ej Ab¨ gva¨‡g ej , r = C C0 = AšÍiK c`v_© c~Y© avi‡Ki aviKZ¡ k~b¨ gva¨g c~Y© avi‡Ki aviKZ¡ *** WvB B‡jKwUªK c`v‡_©i D`vniY g‡b ivLvi mnR Dcvq: Gevi Avwg iweev‡i •Zj gvL‡ev| Gevi Avwg iweevi •Zj gvL‡ev B‡evbvBU A¨v¤^vi ivevi •Zj †gvg ✅ avi‡Ki w¯’wZ ev mwÂZ kw³ ev wefe kw³ (potential energy) Ep = 1 2 QV = 1 2 CV2 = 1 2 Q 2 C ✅ avi‡Ki mgevq ev web¨vm- †kªYx ev wmwiR mgevq : 1 Cs = 1 C1 + 1 C2 + 1 C3 + ....... + 1 Cn mgvšÍivj mgevq: Cp = C1+C2+C3+....... + Cn [Note: aviK n‡”Q †iv‡ai D‡ëv A_©vr, †iv‡ai †ÿ‡Î †kÖYx mgevq n‡j avi‡Ki †ÿ‡Î mgvšÍivj n‡e|] ✅ †kªYx mgev‡q Zzj¨ aviKZ¡ n«vm cvq Ges mgvšÍivj mgev‡q Zzj¨ aviKZ¡ e„w× cvq| ✅ GK bR‡i avi‡Ki e¨envi (use of capacitor at a glance): ‡UwjMÖvd, †Uwj‡dv‡b Ges †eZvi MÖvnK h‡š¿ wUDwbs Gi Kv‡R aviK e¨eüZ nq| •e`y¨wZK cvLv‡K †Rv‡i Nyivevi Rb¨ aviK e¨eüZ nq| weea©K h‡š¿ Kvcwjs Gi Kv‡R aviK e¨envi Kiv nq| •e`y¨wZK eZ©bx‡Z PvwR©s Ges wWmPvwR©s Gi Kv‡R e¨eüZ nq| ‣e`y¨wZK eZ©bx‡Z wWwm eøwKs, wn‡m‡e e¨eüZ nq| wdëvi mvwK©‡U aviK e¨envi Kiv nq| ¯ú›`‡K aviK e¨envi Kiv nq PvR© mwÂZ Ki‡Z Ges •e`y¨wZK bvbv Kv‡R aviK e¨envi Kiv nq| d¬vk d‡UvMÖvdx‡Z Kw¤úDUvi wK‡ev‡W© REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. GKwU mgvšÍivj cvZ aviK‡K PvwR©Z Kivi d‡j GwUi cvZ `yBwUi g‡a¨ wefe cv_©K¨ nq V| aviKwUi mwÂZ kw³ wظY Kivi Rb¨ wefe cv_©K¨ KZ n‡e? [DU: 2013-14] A. 1 4 V B. 1 2 V C. 2 V D. 2V S C info E = 1 2 CV2 EαV2 [GKwU avi‡Ki Rb¨ C w¯’i] V E ; V2 = E2 E1 V1 = 2 V 02. mgvb cÖ¯’‡”Q` A wewkó `ywU mgvšÍivj †cø‡Ui g‡a¨i e¯‘i civ‣e`y¨wZK aªæeK k I Df‡qi ga¨Kvi `~iZ¡ d n‡j †cøU `ywUi aviKZ¡ KZ?[DU: 2001-02] A. ( k)A/d B. (k/)A/d C. KA/d D. None S C info Avgiv Rvwb, mgvšÍivj cvZ avi‡Ki †¶‡Î, C = d A C = d 0 kA [ = 0 k] 03. GKwU mgvšÍivj cvZ aviK‡Z¡i cvZ؇qi ga¨eZx© ¯’vb evqy (k=1) Gi cwie‡Z© k=20 WvB B‡jKwUªK aªæe‡Ki c`v_© Øviv c~iY Kiv nj, wKš‘ cv‡Z GKB Avavb ivLv n‡j- [DU: 2003-04] A. ïay wefe cv_©K¨ (cvZ؇qi) cwiewZ©Z n‡e B. ïay aviKZ¡ cwiewZ©Z n‡e C. DfqB cwiewZ©Z n‡e D. aviKZ¡ I wefe cv_©K¨ GKB _vK‡e Ans C 04. wb‡Pi †KvbwU avi‡Ki kw³i mgxKiY bq? [DU: 2000-01] A. 1 2 CV2 B. 1 2 QV C. Q 2 2C D. Q 2C2 Ans D STEP 02 ANALYSIS OF JU QUESTION 01. avi‡Ki g‡a¨ †Kvb civ‣e`y¨wZK c`v_© cÖ‡ek Kiv‡j Gi aviKZ¡Ñ [JU-A, Set-G. 20-21] A. e„w× cvq B. n«vm cvq C. AcwiewZ©Z _v‡K D. †Kv‡bvwUB bq S A info C = 40kr C k
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 441 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 02. avi‡Ki †ÿ‡Î †KvbwU mwVK? [JU-A, Set-B. 20-21] A. W = 1 2 VC2 B. W = 1 2 CI2 C. W = 1 2 Q C D. W = 1 2 V 2C S D info W = 1 2 CV2 = 1 2 QV = 1 2 Q 2 C . 03. avi‡Ki aviK‡Z¡i GKK †KvbwU- [JU: 2015-16, RU. 07-08] A. d¨vivW B. †fvë C. †nbwi D. Ryj Ans A 04. †MvjvKvi avi‡Ki aviKZ¡ Zvi e¨vmv‡a©i [JU: 2010-11] A. e¨¯ÍvbycvwZK B. e‡M©i e¨v¯ÍvbycvwZK C. mgvbycvwZK D. eM©g~‡ji mgvbycvwZK Avgiv Rvwb, C = 40 r ; C r ,aviKZ¡ e¨vmv‡a©i mgvbycvwZK| 05. †KvbwU fzj? [JU: 2009-10] A. C = V Q B. = Q A C. E = F Q D. V = W q0 Ans A 06. wb‡Pi †KvbwU avi‡Ki w¯’wZ kw³i mgxKiY bq?[JU: 2009-10, PSTU. 19-20] A. 1 2 Q 2 C B. 1 2 Q/C2 C. 1 2 CV2 D. 1 2 QV Ans B STEP 03 ANALYSIS OF RU QUESTION 01. K‡qKwU 3 pF aviK w`‡q 1 pF aviKZ¡ †c‡Z n‡j- [RU: 2013-14] A. †kÖYx‡Z jvMv‡Z n‡e B. mgvšÍiv‡j jvMv‡Z n‡e C. cvIqv m¤¢e bq D. GKwU 1 †iv‡ai mgvšÍiv‡j Ans A 02. mgvšÍivj avi‡Ki aviKZ¡ e„w×i Rb¨ [RU: 2010-2011] A. cvZ؇qi †¶Îdj n«vm Kiv †h‡Z cv‡i B. cvZ؇qi †iva e„w× Kiv †h‡Z cv‡i C. cvZ؇qi ga¨eZx© `~iZ¡ e„w× Kiv †h‡Z cv‡i D. Dc‡ii †KvbwUB Kvh©Ki bq Ans D 03. †KvbwU mZ¨ bq? [RU: 2009-10] A. †Mvj‡Ki aviKZ¡ Gi e¨vmva© e„w×i mv‡_ e„w× cvq B. GKwU aviK‡K AvwnZ Ki‡Z cÖ‡qvRbxq †gvU Kv‡Ri cwigvY aviKZ¡ e„w×i mv‡_ n«vm cvq C. cwievn‡Ki MwZc‡_i Pvwiw`‡K †P․¤^K †¶Î m„wó nq D. B‡jKUª‡bi MwZc‡_i Pvwiw`‡K †P․¤^K †¶Î m„wó nq Ans B 04. †KvbwU‡K B‡jKUª‡bi Avavi wnmv‡e MY¨ Kiv nq- [RU: 2009-10] A. evqy B. cvwb C. gvwU D. MÖvdvBU Ans C STEP 04 ANALYSIS OF CU QUESTION 01. GKwU Amxg cvZj kx‡Ui PvwR©Z cwievnxi wbKU we›`y‡Z •e`y¨wZK †¶‡Îi cwigvY KZ? [CU-A, Set-2. 19-20] A. o B. o C. 2o D. o o 2 mivmwi m~Î| 02. Avgiv hw` c„w_ex‡K 6400 km e¨vmva© wewkó GKwU cwievnx †MvjK we‡ePbv Kwi Z‡e Gi aviKZ¡ †Kvb µ‡gi n‡e? [CU-A, Set-2. 19-20] A. mF B. F C. F D. kF aviKZ¡, C = 40R = 1 9 × 109 × 6400 × 103 = 0.711mF STEP 05 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. †Kvb Zwor cwievnxi aviKZ¡ wK‡mi Dci wbf©i K‡i bv? [KU: 2015-16] A. cwievnxi †¶Îdj B. cwievnxi Pvicvk¦©¯’ gva¨g C. cwievnxi NbZ¡ D. cvZ؇qi ga¨eZ©x `~iZ¡ C = 0kA d 02. wb‡Pi †Kvb& mgxKiY mwVK bq? [KU: 2003-04] A. C = 0A d B. E = 1 40k q1q2 d 2 C. C = QV D. U = 1 2 CV2 Ans C IU 01. mgvb aviK‡Z¡i 3wU avi‡Ki mgvšÍivj mgevq Zv‡`i †kªYx mgev‡qi mgZzj aviK‡Z¡i KZ ¸Y ? [IU: 2010-11] A. 9 ¸Y B. 3 ¸Y C. 27 ¸Y D. 1 3 ¸b Ans A BRUR 01. GKwU mgvšÍivj cvZ avi‡Ki cvZ؇qi ga¨Kvi `~iZ¡ wظY Kivi d‡j avi‡Ki mwÂZ kw³i Kx cwieZ©b nq? [BRRU-F, Set-2, 19-20] A. wظY B. AcwiewZ©Z C. A‡a©K D. 4 ¸Y e„w× C = oA d ; C 1 d C2 = d1 d2 × C1 = 1 2 C. 02. WvB-B‡jw±«K wµqv n‡jv- [BRUR: 2015-16] A. aviKZ¡ evov‡bv B. cvZ `ywUi ga¨eZ©x `~iZ¡ e„w× Kiv C. wµqvkxj †fv‡ë‡Ri gvb Kgv‡bv D. aviKZ¡ Kgv‡bv Ans A PART B Analysis of Science & Technology Question HSTU 01. K¨vcvwmU‡ii g‡a¨ WvB B‡jKwUªK c`v‡_©i KvR wK? [HSTU: 2015-16] A. C evov‡bv B. C Kgv‡bv C. T evov‡bv D. DËi †bB Ans A STEP 06 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. Kg RvqMvq †ewk Zwor m‡qi Rb¨ wb‡Pi †Kvb aviKwU e¨eüZ nq? [MAT: 2018-19] A. AåaviK B. wmivwgK aviK Ans C C. cwieZ©bxq evqy aviK D. B‡jK‡UªvjvBwUK aviK 02. wb‡Pi †KvbwU k~b¨ ¯’v‡bi Rb¨ cÖ‡hvR¨? mgvb aviK‡Z¡i 4wU avi‡Ki mgvšÍivj mgev‡qi _vKvKvjxb Zzj¨ aviKZ¡, †kªYxe× mgev‡q _vKvKvjxb Zzj¨ aviK‡Z¡i.........¸Y [MAT: 2009-10] A. 1 2 B. 1 3 C. 1 16 D. 2 3 Ans C STEP 07 ANALYSIS OF HSC BOARD QUESTION 01. aviKmg~n‡K GKB Dr‡mi mv‡_ mgvšÍiv‡j hy³ Ki‡jÑ [wm. †ev. 2017] i. cÖ‡Z¨K avi‡Ki `yÕcv‡Zi wefe cv_©K¨ e„w× cvq ii. cÖ‡Z¨K avi‡Ki `yÕcv‡Z Avavb n«vm cvq iii. Zzj¨ avi‡Ki mwÃZ kw³ AcwiewZ©Z _v‡K wb‡Pi †KvbwU mwVK? A. i I ii B. ii I iii C. i I iii D. i, ii I iii Ans Blank 02. avi‡Ki cvZ؇qi ga¨eZ©x `~iZ¡ e„w× Ki‡j aviKZ¡Ñ [wm. †ev. 2016] i. e„w× cv‡e ii. n«vm cv‡e iii. AcwiewZ©Z _vK‡e wb‡Pi †KvbwU mwVK? Ans B A. i B. ii C. iii D. i, ii I iii 03. †MvjvKvi cwievnxi aviKZ¡ ebvg e¨vmva© †jL-wP‡Îi †MÖwW‡q›U (bwZ) n‡e- [e. †ev. 2016] A. 1 40 B. 40 C. 0 D. 0 d c = q v = 0 c ∮ E ─ . ds ─ ∮ E . dr ─ = 0 = 4r 2 . E rE = 40r dc dr = 40
442 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES wb‡Pi DÏxc‡Ki Av‡jv‡K wb‡Pi `ywU cÖ‡kœi DËi `vI: d e¨v‡mi GB †MvjKwUi aviKZ¡ C| Gi †K›`ª O Ges A c„‡ôi Dci GKwU we›`y| †MvjKwUi PvR© q| O A 04. †MvjKwUi aviKZ¡ KZ? [e. †ev. 2017] A. 1 40d B. 1 20d C. 20d D. 40d C = 40r = 40 d 2 = 20d 05. D‡jøwLZ DÏxc‡Ki †ÿ‡ÎÑ [e. †ev. 2017] i. O we›`y‡Z wefe q 20d ii. O we›`y‡Z cÖvej¨ k~Y¨ iii. A we›`y‡Z wefe q 20d wb‡Pi †KvbwU mwVK? A. i I ii B. ii I iii C. i I iii D. i, ii I iii Ans D Concept 7 MvD‡mi m~Î ✅ MvD‡mi m~Î: m~‡Îi Avwe®‥viK I mvj: Kvj© †d«WwiL MvDm, 1835 mv‡j| MvD‡mi m~Î c`v_© weÁv‡bi 4wU †g․wjK m~‡Îi GKwU| m~Î: ÒGKwU w¯’i Zwor †¶‡Îi †Kvb e× Z‡ji Dci, †gvU Awfj¤^ Av‡ek ev d¬v·, H Zj Øviv †ewóZ †gvU Pv‡R©i 1 0 ¸Y| MvwYwZK cÖKvk: 0 0 E.d S = q hw`, q = 0 nq Z‡e Zwor d¬v· = 0 Ed S = 0 [GLv‡b 0 wPýwU Ave× Z‡ji Rb¨ mgvKjb wb‡`©kK] ✅ MvD‡mi m~‡Îi e¨envi: mylgfv‡e PvwR©Z †Mvj‡Ki Rb¨ Zwor cÖvej¨ wbY©‡qi †ÿ‡Î| †Mvj‡Ki Af¨šÍ‡i †Kvb we›`y‡Z Zwor cÖvej¨ wbY©‡qi †ÿ‡Î| mylgfv‡e PvwR©Z mgZj cv‡Zi wbK‡U †Kv‡bv we›`y‡Z Zwor cÖvej¨ wbY©‡q| `ywU mgvšÍivj PvwR©Z cv‡Zi Rb¨ Zwor-cÖvej¨ wbY©‡q| GKwU `xN© mylgfv‡e PvwR©Z miæ Zv‡ii •iwLK PvR© eȇbi Rb¨ Zwor cÖvej¨ wbY‡©q| REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF GST QUESTION SUST 01. GKwU MvDmxq Zj Øviv GKwU Zwor w؇giæ Ave× _vK‡j ZjwUi ga¨ w`‡q AwZµvšÍ †gvU Zwor d¬v· E n‡e- [SUST: 2018-19] A. abvZ¥K B. Amxg C. FYvZ¥K D. Awb‡Y©q E. k~b¨ Zwor w؇giæi abvZ¥K Avavb n‡Z wbM©Z ej‡iLv FYvZ¥K Avav‡b AvMZ ej‡iLvi mgvb nIqvq net ej †iLv k~b¨| MBSTU 01. = E .d s GwU Kvi m~Î? [MBSTU: 2015-16] A. Kzj‡¤^i m~Î B. d¨viv‡Wi m~Î C. A¨vw¤úqv‡ii m~Î D. MvD‡mi m~Î Ans D STEP 2 mg„× †ewmK MvwYwZK cÖ Ö‡qvM (MATH) kU©KvU †UKwbK Concept 1 Kzj‡¤^i m~Î msµvšÍ MvwYwZK cÖ‡qvM FORMULA 01.Zwor ej, F = 1 40 q 1 q 2 r 2 = 9109 q 1 q 2 r 2 ; 1 40 = 9109 02. E = F q F = qE = mg Model Example01 `ywU mgvb Pv‡R©i ga¨eZx© `~iZ¡ A‡a©K Kiv n‡j Ges PvR© `ywUi gvb Kwg‡q A‡a©K Kiv n‡j e‡ji gvbGeneral Rules [Written] 3 in 1 Shortcut Tricks & Tips [MCQ] Kzj‡¤^i m~Îvbymv‡i, 2 1 2 o r q q 4 1 F F 2 1 2 r q q F F F r r q q q q F 2 2 2 2 1 1 2 2 1 2 1 F 2 1 2 r q q F 1 2 1 2 1 2 2 F 1 CONCEPTUAL MATH MEx 01 nvB‡Wªv‡Rb cigvYyi †cÖvUb I B‡jKUª‡bi g‡a¨ •e`y¨wZK ej 8.110–8 N n‡j, KYv `ywUi g‡a¨ `~iZ¡ KZ? ej, F = 1 40 q1q2 r 2 r = 1 40 q1q2 F = 9 109 (1.6 10–19) 2 8.1 10–8 = 53 10–12 m MEx 02 †jvnvi wbDwK¬qv‡m `ywU †cÖvU‡bi g‡a¨ wµqvkxj Zwor ej KZ n‡e hw` Zv‡`i g‡a¨ `~iZ¡ 4 10–15m nq? F= Cq1q2 d2 = 9 109 (1.6 10–19) 2 (4 10–15) 2 = 9 × 109 × 1.6 × 16 × 10–39 16 × 10–30 = 9 ×1.6 = 14.4N MEx 03 k~b¨ gva¨‡g `yBwU B‡jKUª‡bi ga¨Kvi Kzj¤^ ej FE Ges gnvKl© ej FG Gi AbycvZ n‡e2 2 2 2 4 0 1 r m G r q F F G E 2 11 31 9 19 2 6.67 10 9.1 10 9 10 (1.6 10 ) = 4.21042 [K¨vjKz‡jk‡bi Rb¨ ïay 10 Gi cvIqvi wn‡me Ki‡jB n‡e]
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 443 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES MEx 04 evqy‡Z GK Kzj‡¤^i `ywU Avavb ci®úi †_‡K 1km e¨veav‡b Aew¯’Z n‡j G‡`i ga¨Kvi ej KZ n‡e? F = 9 109 q1q2 r 2 = 9 109 1 1 (1 103 ) 2 = 9 103N. MEx 05 FYvZ¥K Zwo‡Z PvwR©Z 0.1 gm IR‡bi GKwU wc_-ej 2 †mw›UwgUvi Dc‡i ivLv GKwU abvZ¥K Pv‡R© PvwR©Z e¯‘i AvKl©Y k~‡b¨ w¯’i Av‡Q| wc_ e‡ji PvR© –6.6710–9 C n‡j e¯‘i PvR© KZ? awi, e¯‘i PvR©, q F = 1 40 q1 q2 d 2 – (mg) = 1 40 q1 q2 d 2 [AvKl©Y e‡j F = (–) ve n‡e|] [–(0.1 10–3 ) 9.8] = 9 109 q (–6.67 10–9 ) (0.02) 2 e¯‘i PvR©, q = + 6.53 10–9C MEx 06 `ywU Avav‡bi ga¨eZ©x `~iZ¡ wظb Kiv n‡j ej KZ n‡e? F2 = d1 d2 2 F1 = 1 2 2 F1 = 1 4 F1 NOW START PRACTICE 01. GKwU †Uwjwfkb wUD‡ei †Kvb GK we›`y‡Z 1.610-19 C Pv‡R©i GKwU B‡j±ª‡bi Dci 810-14 N ej Abyfe nq| H we›`y‡Z •e`¨ywZK †¶‡Îi ZxeªZv KZ? 02. GKwU B‡jKUªb‡K 105 NC–1 Zwor‡ÿ‡Î ¯’vcb Ki‡j B‡jKUª‡bi Dci wµqvkxj ej KZ? 03. nvB‡Wªv‡Rb cigvYyi cÖ_g K¶c‡_i e¨vmva© 0.5310–10 m H K¶c‡_ B‡jKUª‡bi †eM KZ n‡j wbDwK¬qv‡mi AvKl©‡Y GwU wbDwK¬qv‡mi Dci G‡m co‡e bv? 04. 1Å e¨eav‡b Aew¯’Z `ywU gy³ B‡jKUª‡bi ga¨eZx© Kzj¤^ ej wbY©q Ki? (1Å=10–10m) NOW PRACTICE SOLVE : 01. N C q F F qE E 5 10 / 1.6 10 8 10 5 19 14 02. F = qE = 1.6× 10–19 × 105 = 1.6 × 10–14 N 03. Fe = mv2 r = 1 40 e 2 r 2 ; v = 1 40 e 2 m = 9 109 (1.6 10–19) 2 0.53 10–10 9.1 10–31 = 2.18 106ms–1 04. q1 = q2 = (1.610–19)C ej, 2.3 10 N 10 1.6 10 9 10 d q q 4 1 F 8 2 10 19 9 2 1 2 0 REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. `yBwU mgvšÍivj Zv‡ii g‡a¨ GKB gv‡bi Zwor cÖevwnZ nq Ges Zvi `yBwU cÖwZ GKK •`‡N©¨ F ej Øviv G‡K Aci‡K weKl©Y K‡i| hw` cÖevwnZ Zwor wظY Ges Zvi؇qi g‡a¨ `~iZ¡‡K wZb ¸Y Kiv nq Z‡e cÖwZ GKK •`‡N©¨ e‡ji gvb n‡e- [DU. 2018-19] A. 2F 3 B. 4F 3 C. 2F 9 D. 4F 9 F L = 0I1I2 d F I1I2 d F2 = 2 2 3 F = 4 3 F 02. `ywU mgvb Pv‡R©i ga¨eZx© `~iZ¡ A‡a©K Kiv n‡j Ges PvR© `ywUi gvb Kwg‡q A‡a©K Kiv n‡j e‡ji gvb- [DU. 2017-18] A. A‡a©K n‡e B. wظY n‡e C. AcwiewZ©Z _vK‡e D. Pvi¸Y n‡e Kzj‡¤^i m~Îvbymv‡i, F = 1 40 q1q2 r 2 F q1q2 r 2 F = q1 q2 q2 q1 r r 2 F = 1 2 1 2 2 2 F = F 03. k~b¨ gva¨‡g `yBwU B‡jKUª‡bi ga¨Kvi Kzj¤^ ej FE Ges gnvKl© ej FG Gi AbycvZ n‡e- [DU. 2016–17] A. 4.21062 B. 4.21052 C. 4.21042 D. 4.21032 FE FG = 1 40 q 2 r 2 G m 2 r 2 = 9 109 (1.6 10–19) 2 6.67 10–11 (9.1 10–31) 2 = 4.21042 04. hw` 5A Zwor 3 N›Uv a‡i GKwU evwZi ga¨ w`‡q cÖevwnZ nq Zvn‡j H evwZi ga¨ w`‡q cÖevwnZ Pv‡R©i gvb- [DU. 2015-16] A. 3.6104C B. 5.4104C C. 1.4103C D. 3.6106C Q = it = 5×3×60×60 = 5.4×104C 05. 5.0 cm e¨vmv‡a©i GKwU cwievnx †Mvj‡Ki PvR© 4.0C. †K›`ª †_‡K 4.0cm `~i‡Z¡ wefe KZ? [DU. 2001-02] A. 0V B. 3.5105 V C. 6.0105 V D. 7.2105 V †Mvj‡Ki †K‡›`ª wefe, c„‡ô wefe ev Af¨šÍ‡i †h †Kvb we›`y‡Z wefe GKB K_v| 4 cm `~i‡Z¡ wefe 5 cm `~i‡Z¡ wefe , V= 1 40 . r q = 9109 0.05 4 106 = 7.2 105 V 06. GKwU †Uwjwfkb wUD‡ei †Kvb GK we›`y‡Z 1.610-19 Coulomb Pv‡R©i GKwU B‡j±ª‡bi Dci 810-14 Newton ej Abyfe nq| H we›`y‡Z •e`y¨wZK †¶‡Îi ZxeªZv KZ? [DU. 2000-01] A. 2.5105 N/C B. 25.610-33 N/C C. 5105 N/C D. 12.810-33 N/C N C Q F F E Q E 5 10 / 1.6 10 8 10 . 5 19 14 STEP 02 ANALYSIS OF JU QUESTION 01. evqy‡Z 1 Kzj‡¤^i `yBwU PvR©‡K 1m `~i‡Z¡ ¯’vcb Ki‡j weKl©Y e‡ji gvb n‡e- [JU-A, Set-C. 20-21] A. 8 × 109N B. 9 × 109N C. 1.6 × 109N D. †KvbwUB bq S B info Avgiv Rvwb, F = C q1q2 d 2 = 9 109 1 1 1 2 = 9 × 109N
444 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 02. Avav‡bi †Kvqv›Uvqb Abymv‡i †Kvb e¯‘‡Z wb‡Pi †Kvb PvR©wU _vKv m¤¢e? [JU. 2018-19] A. 9.4 1019C B. 4.6 10–19C C. 6.2 10–19C D. 3.2 10–19C Q = ne A_©vr, n = c~Y©msL¨v| 1.6 × 1019 × 2 = 3.2 × 10 19 03. 2 m e¨v‡mi GKwU †MvjvK…wZ cwievnxi c„‡ô 3109C PvR© †`qv n‡jv| †Mvj‡Ki †K›`ª †_‡K 0.80 m `~‡i †Kvb& we›`yi wefe I cÖvej¨ n‡e- [JU. 12-13] A. 20V I 20 N/C B. 27V I 27 N/C C. 27V I 0 N/C D. 0V I 0N/C `~iZ¡ d=0.8 m, v = 9 109 3 10–9 1 = 27v, cÖvej¨ E = 0 04. 3.2510-29 Pv‡R©i GKwU cøvw÷‡Ki ej †Kvb ¯’v‡b 2.6104 volt/m cÖve‡j¨i GKwU mylg •e`y¨wZK †¶‡Î SzjšÍ Ae¯’vq ivLv nj| D³ ¯’v‡b AwfKl© Z¡i‡Yi gvb 10ms-2 n‡j ejwUi fi- [JU. 2011-12] A. 8.39810-16kg B. 1.20510-15kg C. 102051015Kg D. ‡KvbwUB bq F=EQ ev, mg=EQ m = EQ g = 2.6 104 3.25 10–29 10 = 8.45 10-26 STEP 03 ANALYSIS OF RU QUESTION 01. Zwor †¶‡Îi cÖvej¨ KZ n‡j Puv‡` Aew¯’Z GKwU †cÖvUb Zvi IR‡bi mgvb ej Abyfe Ki‡e? [RU. 2017-18] A. 1.7×10–8 wbDUb/Kzj¤^ B. 1.7×10–7 wbDUb/Kzj¤^ C. 1.7×108 wbDUb/Kzj¤^ D. †KvbwUB bq •e`y¨wZK cÖve‡j¨i gvb, E = F q = mg q = 1.6 10–27 (9.8/6) 1.6 10–19 = 1.63×10-8 wbDUb/Kzj¤^ 02. 4.0 cm e¨vmv‡a©i †Kvb GKwU PvwR©Z †Mvj‡Ki Pv‡R©i Zj NbZ¡ 2.5 GKK| H †Mvj‡K KZ PvR© mÂwiZ wQj| [RU. 2015–16, BUET: 2007-08] A. 402.4 GKK PvR© B. 502.4 GKK PvR© C. 204.4 GKK PvR© D. 205.4 GKK = Q A ev, Q = A = 4r 2 =2.54(4)2 = 502.4 03. †Kvb eM©‡¶‡Îi †K․wbK we›`y‡Z h_vµ‡g 3, -6 Ge 7 Kzj¤^ PvR© ¯’vcb Kiv Av‡Q| PZz_© †K․wbK we›`y‡Z KZ PvR© ¯’vcb Ki‡j H eM©‡¶‡Îi †K‡›`ª wef‡ei gvb k~b¨ n‡e? [RU. 2011-12] A. -6 Kzj¤^ B. -4 Kzj¤^ C. 5 Kzj¤^ D. 6 Kzj¤^ 1g PvR© Q1=3 Kzj¤^; 2q PvR© Q2=-6 Kzj¤^; 3q PvR© Q3=7Kzj¤^ PZy_© †K․wbK we›`y‡Z PvR© = –(Q1+Q2+Q3)= -(3-6+7) = -4 Kzj¤^ 04. mgfv‡e AvwnZ `ywU wc_ej evqy‡Z 2.0mm e¨eav‡b ivL‡j ci¯úi‡K 4×10-5Ne‡j weKl©Y K‡i| cÖ‡Z¨K wc_ e‡ji Avav‡bi gvb KZ? [RU. 09-10] A. 8.6×10-10C B. 5.22×10-10C C. 1.33×10-10C D. 2.55×10-10C F = 9×109 q q (2 10–3 ) 2 ev, 4×10-5 = 9×109 q 2 (2 10–3 ) 2 ev, q = 1.33×10-10C STEP 04 ANALYSIS OF CU QUESTION 01. Avqib wbDwK¬qv‡mi `y‡Uv †cÖvUb 4 × 10 –15m `~i‡Z¡ Ae¯’vb Ki‡j Zv‡`i g‡a¨ •e`y¨wZK ej KZ n‡e? [CU-A, Set-1. 20-21] A. 7.2 N B. 14.4 N C. 1.44 N D. 144.0 N S B info F = 1 40 q1q2 d 2 = 9 109 (1.60 10–19) 2 (4 10–15) 2 = 14.4N 02. GKwU Kzj¤^ Avav‡bi Rb¨ KZ¸‡jv B‡j±ª‡bi cÖ‡qvRb? [CU-A, Set-2. 20-21, CoU. 16-17 ] A. 6.02 × 1023 B. 1.6×1019 C. 6.24 × 1018 D. 9 × 1016 S C info B‡jKUªb msL¨v = 1 1.6×10-19 = 6.25× 1018 03. `ywU Avav‡bi ga¨eZ©x `~iZ¡ A‡a©K n‡j, Avavb؇qi g‡a¨ wµqvkxj ej wK n‡e? [CU. 2015-16, CoU. 15-16] A. wظY n«vm cvq B. Pvi¸Y n«vm cvq C. wظY e„w× cvq D. Pvi¸Y e„w× cvq E. ‡Kv‡bvwUB bq F2 F1 = d1 d2 2 ev, F2 F1 = 2 1 2 ev, F2 = 4F 04. 2F aviKZ¡ wewkó GKwU aviK‡K 40V e¨vUwii mv‡_ mshy³ Ki‡j Zv‡Z mwÂZ Avavb- [CU. 2014–15] A. 2.010-6 C B. 2.010-5 C C. 1.610–3 D. 8.010-5 C E. 8.010-4 C Ep = 1 2 cv2 = 1 2 2 10–6 (40)2 = 1.610–3 05. GKwU wbw`©ó cwigvb PvR© q †K wKiƒc `ywU As‡k fvM Ki‡j Dnviv GKwU wbw`©ó e¨eav‡b †_‡K me‡P‡q †ekx e‡j weKl©Y Ki‡eÑ [CU. 2006-07] A. q 2 . q 2 B. q 4 . 3q 4 C. q 5 . 2q 5 D. q 3 . 2q 3 E. q 6 . 5q 6 q 2 . q 2 STEP 05 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. c„w_exi e¨vmva© 6400 km n‡j, c„w_exi aviKZ¡ wbY©q Ki| [JnU. 2008-09] A. 6400 F B. 3200 F C. 2200 F D. 711 F †Mvj‡Ki †¶‡Î, C = 40 711.11 F 9 10 6400 1000 R 9 02. nvBWª‡Rb cigvbyi †cÖvUb I B‡jKUª‡bi g‡a¨ •e`y¨wZK ej 8.110–8 N n‡j Kbv `ywUi g‡a¨ `~iZ¡ KZ? [JnU. 2008-09] A. 4310–11 m B. 5310–12m C. 63110–10 m D. 5310–13 m F = 9 109 Q1Q2 d 2 ev, d = 9 109 Q1 Q2 F = 9 109 (1.6 10–19) 8.1 10–8 = 5.33 10–11 = 53 10–12 03. 104 N/C Zwor †¶‡Î GKwU B‡jKUª‡bi Dci ej KZ? [JnU. 2006-07] A. 9.110-31N B. 1.610-23N C. 1.610-19N D. 1.610-15N F=EQ = 104 1.610-19 =1.610-15 N KU 01. `ywU we›`yi g‡a¨ wefe cv_©K¨ 322kV| G‡`i GK we›`y †_‡K Aci we›`y‡Z 9C PvR© ¯’vbvšÍi Ki‡j K…Z Kv‡Ri cwigvb KZ? [KU. 2012-13] A. 5.898 J B. 4.898 J C. 3.898 J D. 2.898 J W = Q.v = 322103 910-6 = 2.898j 02. `ywU mgvb I mgagx© we›`y PvR© evqy ev k~b¨ gva¨‡g ci¯úi n‡Z 1 m `~i‡Z¡ ¯’vcb Ki‡j hw` G‡`i g‡a¨ wµqvkxj weKl©Y ej 9109 wbDUb nq Z‡e cÖ‡Z¨KwU Pv‡R©i gvb- [KU. 2004-05] A. 2C B. 1C C. 3C D. 4C awi, q1= q2 = q 2 2 0 d q 4 1 F PvR©, q 4 d F 4 (1) 9 10 1C 2 9 0 2 0
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 445 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES CoU 01. hw` 1 Coulomb gv‡bi `ywU Avavb evZv‡m ci¯ú‡ii mv‡_ 1 metre `~iZ¡ †i‡L Ae¯’vb K‡i, Z‡e Zv‡`i ga¨eZx© ej KZ? [CoU. 2017-18] A. 9 109 N B. 8.851012 N C. 1.6 1019 N D. 2.2 N F = 1 40 q1q2 r 2 = 9109 q1q2 r 2 = 9 109 1 1 1 2 = 9 109 N PART B Analysis of Science & Technology Question SUST 01. ‡Kvb Zwor †¶‡Îi cÖvej¨ KZ n‡j †mLv‡b GKwU B‡jKUªb Zvi IR‡bi mgvb ej Abyfe Ki‡e? [SUST: 2012-13, KU: 2015-16] A.5.5710-11NC-1 B. 4.6710-12NC-1 C. 6.5110-12NC-1 D. 5.5710-11NC-2 E. 5.5710-10NC-2 F = E E = F Q = mg Q = 9.1 10–31 9.8 1.6 10–19 = 5.5710-11NC-2 02. GKwU mij †iLvq q Ges 4q PvR© n‡Z 1m `~i‡Z¡ ivLv Av‡Q| GB mij †iLvq †Kvb we›`y‡Z Zwor cÖvej¨ k~b¨| [SUST: 2011-12] A. Q PvR© n‡Z 1m `~‡i, -4Q PvR© n‡Z 2m `~‡i B. Q PvR© n‡Z 1 3 m `~‡i Ges -4Q PvR© n‡Z 2 3 `~‡i C. Q PvR© n‡Z 4m `~‡i Ges -4Q PvR© n‡Z 1m `~‡i D. Q PvR© n‡Z 4m `~‡i Ges -4Q PvR© n‡Z 1m `~‡i E. Q PvR© n‡Z 2 3 `~‡i Ges -4Q PvR© n‡Z 1 3 m `~‡i awi, Q PvR© n‡Z x m `~‡i cÖvej¨ k~b¨ 3 1 1 2 1 1 4 1 4 1 1 Q Q x -4Q PvR© n‡Z m 3 2 3 1 1 `~‡i cªvej¨ k~b¨| 03. `ywU Pv‡R©i †fZi ej 10-3 N| PvR© `ywU wظb `~i‡Z¡ mwi‡q wb‡j †gvU ej n‡eÑ [SUST: 2005-06] A. mgvbB _vK‡e B. A‡a©K n‡e C. wظb n‡e D. Pvifv‡Mi GK fvM n‡e 1 2 2 . 1 F x F 2 1 . 2 1 F 1 . 4 1 F = Pvifv‡Mi GK fvM| 04. nvB‡Wªv‡Rb cigvYy‡Z B‡jKUªb I †cÖvU‡bi ga¨eZx© `~iZ¡ 5.310-11m. n‡j Zv‡`i ga¨Kvi Mo B‡jK‡Uªv÷¨vwUK e‡ji cwigvbÑ [SUST: 2004-05] A. 4.110-8 N B. 0 C. 5.010-11 N D. 8.210-8 N Ans D MBSTU 01. hw` `ywU Avav‡bi ga¨eZ©x `~iZ¡ wZb¸Y Kiv nq Zvn‡j ej KZ¸Y n‡e? [MBSTU-C, Set-2 19-20, P. ‡ev. 2016] A. 1 9 B. 9 C. 1 3 D. 3 F 1 r 2 F2 = 1 (3) 2 F1 = 1 9 F1 02. k~b¨ gva¨‡g Aew¯’Z `yBwU Pv‡R©i ga¨eZ©x AvKl©Y ej 10N| PvR© `y‡Uvi ga¨eZ©x ¯’v‡b 2.5 gv‡bi GKwU WvB B‡jKwUªK ¯’vcb Kiv n‡j, PvR© `yBwUi g‡a¨ AvKl©b ej n‡e: [MBSTU: 2014-15] A. 4N B. 2.5N C. 10N D. 25N AvKl©b ej F2 = 2.510 = 25N BSMRSTU 01. `ywU + 2C Ges + 6C we›`y PvR© 12N e‡j weKl©Y K‡i| hw` cÖwZwU PvR©‡K –4C PvR© cÖ`vb Kiv nq, ZLb ej n‡e- [BSMRSTU: 2014-15, BUET: 2007-08] A. 4N weKl©Y B. 4N AvKl©Y C. 8N weKl©Y D. 8N AvKl©Y 2 6 ( 2) (2) 1 2 F F ev, 12 4 12 2 F F2 = – 4N AvKl©Y ej DU Technology 01. k~b¨ gva¨‡g 1C gv‡bi `ywU PvR©‡K 1 m `~iZ¡ ¯’vcb Ki‡j weKl©Y e‡ji gvb n‡e? [DU-Tech. 2020-21] A. 11 × 109N B. 9 × 1011N C. 9 × 109N D. 11 × 1011N S C info weKl©Y e‡ji gvb, F = 9 109 1 1 1 2 = 9 109N [q1 = q2 = 1C] STEP 06 ANALYSIS OF HSC BOARD QUESTION +4C Avavbwewkó `ywU †MvjK 0.01 m `~‡i ivLv n‡q‡Q| Ic‡ii Z‡_¨i Av‡jv‡K 01 bs I 02 bs cÖ‡kœi DËi `vI| [iv. †ev. 2015] 01. PvR© `ywUi ga¨eZx© e‡ji gvb KZ? A. 1.44 105 N B. 1.44 1015 N C. 1.82 1011 N D. 1.90 1011 N S B info F = 1 40 . q1.q2 d 2 = 9 109 4 4 (0.01) 2 = 1.44 1015 N 02. +4C Pv‡R©i cwie‡Z©- 4C PvR© ¯’vcb Kiv n‡j Avavb؇qi ga¨Kvi w¯’i Zwor e‡ji gvbA. k~b¨ n‡e B. c~‡e©i mgvb n‡e C. †ewk n‡e D. Kg n‡e S B info F = 1 40 . q1 q2 d 2 = 9 109 (–4) (–4) (0.01) 2 = 1.44 1015 N hv c~‡e©i mgvb| 03. `ywU Pv‡R©i ga¨eZx© `~iZ¡ 1 3 ¸Y Ki‡j, G‡`i ga¨Kvi e‡ji cwieZ©b KZ ¸Y n‡e? [P. †ev. 2016] A. 9 B. 3 C. 1 3 D. 1 9 S A info F1 = C q1.q2 d 2 Ges F2 = C q1 q2 d 3 2 = 9F1 04. evqy‡Z –4C I 5C gv‡bi `ywU Pv‡R©i ga¨eZ©x `~iZ¡ Amxg| G‡`i g‡a¨ wµqvkxj ej n‡jvÑ [w`. †ev. 2017] A. – 0.1 N B. – 0.2 N C. – 0.3N D. 0 N S D info F = 1 40 . q1q2 r 2 ; wKš‘ r = n‡j F = 0 nq| wb‡Pi DÏxc‡Ki Av‡jv‡K cÖ‡kœi DËi `vI: [Kz. †ev. 2015] A B q = +2c q = 2c A I B Awfbœ †MvjK؇qi Avavb h_vµ‡g q1 I q2| 05. A †MvjK KZwU B‡jKUªb nvwi‡q‡Q? A. 1.6 1019 B. 3.2 1019 C. 6.24 1018 D. 1.25 1019 S D info 1C = 1 1.6 10–19 wU B‡jKUªb 2C = 2 1.6 10–19 wU = 1.25 1019 wU 06. ci¯úi †_‡K 1 m `~i‡Z¡ Aew¯’Z cÖwZ 1A Zwor cÖevnevnx Zv‡ii cÖwZ 1 m •`‡N©¨ †h ej wµqv K‡i Zvi gvb- [e. †ev. 2016] A. 2 107 N B. 4 107 N C. 2 107 N D. 4 107 N Ans A
446 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 2 Zwor‡ÿ‡Îi cÖvej¨ msµvšÍ FORMULA 01. Zwor cÖvej¨, E = 1 40 q r 2 = 9 109 q r 2 = 9 109 K q r 2 02. E= q F = q mg = d V 03. PvR©Øq wecixZ ag©x n‡j ga¨we›`y‡Z cÖvej¨, 2 1 2 1 9 1 9 10 q q r E (r1 = ga¨we›`yi `~iZ¡) ASPECT SPECIAL: q1 PvR© n‡Z x wgUvi `~‡i cÖvej¨ mgvb ev k~b¨ n‡j, x = 1 2 q q 1 d x q1 d q2 Model Example01 `ywU ¶z`ª †MvjK A Ges B-†Z h_vµ‡g 9C Ges 16 C PvR© cÖ`vb Kiv nj| hw` e¯‘ `ywUi ga¨eZx© `~iZ¡ 0.28 m nq, Z‡e Zv‡`i ms‡hvRK mij‡iLvi †Kvb& we›`y‡Z Dfq Pv‡R©i Rb¨ cÖve‡j¨i gvb mgvb n‡e? General Rules [Written] 3 in 1 Shortcut Tricks & Tips [MCQ] g‡bKwi, 9C PvR© n‡Z x `~i‡Z¡ C we›`y‡Z Dfq Pv‡R©i cÖve‡j¨i gvb mgvb n‡e| x d= 0.28m A C B 9C Pv‡R©i `iæb C we›`y‡Z cÖvej¨, EA = 1 40 . q r 2 = 9 109 9 x 2 16C Pv‡R©i `iæY C we›`y‡Z cÖvej¨, EB = 1 40 . q r 2 = 9 109 16 (0.28 – x) 2 kZ©g‡Z, EA = EB 9 109 9 x 2 = 9 109 16 (0.28 – x) 2 9 x 2 = 16 (0.28 – x) 2 (0.28 – x) 2 x 2 = 16 9 0.28 – x x = 4 3 0.84 – 3x = 4x 7x = 0.84 x = 0.12 9c PvR© n‡Z 0.12m `~‡i Dfq Pv‡R©i cÖve‡j¨i gvb mgvb n‡e ev fvimvg¨ we›`y •Zwi n‡e| x = d 1 + q2 q1 = 0.28 1 + 16 9 = 0.12 m CONCEPTUAL MATH MEx 01 ci®úi †_‡K 1.20m `~‡i Aew¯’Z 30 10–6C Ges – 60 10–6C Gi `ywU Avav‡bi ms‡hvM †iLvi wVK ga¨¯’‡j Zwor cÖvej¨ KZ n‡e? E = 1 40 q1 + q2 (d/2) 2 (wecixZ PvR©) = 1 40 (30 + 60) 10–6 (1.20/2) 2 = 2.25 10–6NC–1 (e„nËi Avav‡bi w`‡K) MEx 02 `yBwU PvR© h_vµ‡g 60C Ges +60C ci¯úi n‡Z 0.12 m `~i‡Z¡ Aew¯’Z| PvR© `ywUi ms‡hvRb †iLvi wVK ga¨we›`y‡Z cÖvej¨ n‡e? ( ) 1 9 10 2 1 2 1 9 q q r E (PvR©Øq wecixZ agx© e‡j) ev, E N 14 2 9 (60 60) 3 10 (.06) 1 910 NOW START PRACTICE 01. q Ges 4q Avavb 1m `~i‡Z¡ ivLv Av‡Q| ms‡hvM †iLvq q Avavb †_‡K KZ `~‡i Zwor cÖvej¨ k~b¨ n‡e? 02. GKwU we›`y PvR© n‡Z 1m `~i‡Z¡ Zwor‡¶‡Îi cÖve‡j¨i gvb E n‡j, 2m `~i‡Z¡ Zwor‡¶‡Îi cÖve‡j¨i gvb KZ? 03. GKwU we›`y PvR© 610–9C †_‡K KZ `~‡i •e`y¨wZK †¶‡Îi gvb 5N/C n‡e? 04. A¶Ø‡qi g~j we›`y‡Z 30C GKwU PvR© ivLv nj| x=5m we›`y‡Z •e`y¨wZK cÖve‡j¨i gvb wbY©q Ki? 05. `ywU wcZ‡ji e‡ji e¨vm h_vµ‡g 0.03m Ges 0.06m| ej `ywU‡Z h_vµ‡g 2.5×10–9C Ges 5×10–9C PvR© †`qv n‡jv| G‡`i Pv‡R©i ZjgvwÎK Nb‡Z¡i Zzjbv Ki| 06. GKwU mylg Zwor‡¶Î 50 †mwg e¨eav‡b Aew¯’Z `ywU we›`yi wefe cv_©K¨ 200 †fvë, Zwor‡¶‡Îi cÖvej¨ n‡e07. GKwU †MvjKxq Z‡ji †¶Îdj 10 m2 | D³ Z‡j 600 C PvR© cÖ`vb Kiv n‡j Pv‡R©i Zj NbZ¡ wbY©q Ki| NOW PRACTICE SOLVE : 01. awi, q PvR© n‡Z x `~‡i Zwor cÖvej¨ k~b¨ n‡e; x = d 1 + q2 q1 = 1 1 + 4q q = 1 3 m 02. Zwor‡¶Î, E = 1 40 q r 2 E 1 r 2 ; E2 = r1 r2 2 E1 = 1 2 2 E = E 4 03. •e`y¨wZK cÖve‡j¨i gvb, E = 1 40 q r 2 ; r = 1 40 q E = 9 109 6 10–9 5 = 3.28 m
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 447 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 04. •e`y¨wZK cÖve‡j¨i gvb, E = 1 40 q r 2 = 9 109 30 10–6 5 2 = 10.8 103 N/C 05. 2 1 = 2 2 1 2 1 2 Q (r ) Q (r ) = 9 2 9 2 5 10 (0.03) 2.5 10 (0.06) = 1 2 1 : 2 =2:1 06. •e`y¨wZK cÖve‡j¨i gvb, E = 1 400 0.5 200 Vm d V 07. Pv‡R©i Zj NbZ¡, 60 10 600 A q C/m2 REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. GKwU we›`y PvR© n‡Z 2m `yi‡Z¡ Zwor‡¶‡Îi cÖve‡j¨i gvb E n‡j, 1m `yi‡Z¡ Zwor‡¶‡Îi cÖve‡j¨i gvb KZ? [DU. 2015-16] A. E B. 2E C. 4E D. E/2 E 1 r 2 E2 E1 = r1 r2 2 = 2 1 2 ev, E2 = 4E 02. mgvšÍivj `ywU avZe cv‡Zi ga¨Kvi `~iZ¡ d Ges wefe cv_©K¨ V| hw` Q Avav‡bi GKwU we›`y PvR© cvZ `ywUi wVK ga¨eZx© we›`y‡Z ivLv nq Z‡e PvR©wUi Dci wµqvkxj w¯’i Zwor e‡ji gvb KZ? [DU: 2014-15] A. 2VQ / d B. VQ/d C. VQ/2d D. dQ/V Zwor‡¶Î, E = F Q = V d F = VQ d 03. `yBwU abvZ¡K we›`y PvR© q1 I q2. d `~i‡Z¡ Ae¯’vb Ki‡Q| q1 q2 = 16 n‡j q1 n‡Z KZ `~i‡Z¡ Zwor †¶Î cÖve‡j¨i gvb mgvb n‡e| [DU. 2007-08] A. d 2 B. 4 5 d C. 1 16 d D. 2 d q1 n‡Z x `~i‡Z¡ cÖvej¨Øq mgvb n‡j, x = d 1 + q2 q1 ev, x = d 1 + 1 16 = d 1 + 1 4 = 4d 5 04. `yBwU PvR© h_vµ‡g-60c Ges +60c ci¯úi n‡Z 0.12m `~i‡Z¡ Aew¯’Z| PvR© `ywUi ms‡hvRb †iLvi wVK ga¨we›`y‡Z cÖvej¨ n‡e? [DU.003-04] A. 31 14 N B. 3.51 15 N C. 2.51016 N D. 41015 N E = 9 109 1 r1 2 (Q1 + Q2) (PvR©Øq wecixZ agx© e‡j) ev, E = 9 109 1 (0.06) 2 (60 + 60) = 3 1014 N STEP 02 ANALYSIS OF JU QUESTION 01. 0.002Kg f‡ii GKwU †kvjvi ej 10–4 Kzj¤^ Pv‡R© PvwR©Z| ejwU‡K w¯’i ivL‡Z n‡j KZ Zwor †¶‡Îi cÖ‡qvRb n‡e? [JU. 2017-18; BRUR. 2015-16] A. 4 10 0.002 9.8 B. 9.8 0.002 104 C. 0.002 104 D. 0.00210–4 •e`y¨wZK cÖve‡j¨i gvb, q mg q F E = 4 10 0.002 9.8 02. 0.50m e¨vmv‡a©i GKwU †Mvj‡K 20C PvR© †`qv Av‡Q| †Mvj‡Ki †K‡›`ª •e`y¨wZK cÖve‡j¨i gvb- [JU. 2017-18] A. 0 B. 3.61011 C. 2.811011 D. †KvbwUB bq †K›`ª n‡Z c„ô ch©šÍ †h‡Kvb we›`yi cÖve‡j¨i gvb k~b¨| PvR© _vK‡j Zwor †¶Î cÖvej¨ m„wó nq| PvR© †Mvj‡Ki c„‡ô Ae¯’vb K‡i| wfZ‡i PvR© bvB ZvB †Mvj‡Ki wfZ‡i Zwor cÖvej¨ k~b¨| O E = 2 o (r h) q 4 1 r E = 0 h 03. ci¯úi †_‡K 10cm `~‡i Aew¯’Z 210–9C I 210-9C Gi `ywU Pv‡R©i ms‡hvM †iLvi wVK ga¨we›`y‡Z cÖvej¨ n‡e- [JU. 2015–16] A. 200NC–1 B. 180NC–1 C. 0 NC–1 D. 400NC–1 E = 9 109 1 r1 2 (2 10–9 – 2 10–9 ) = 0 04. GKwU 0.30 m e¨vm wewkó avZe †Mvj‡K 1C PvR© mwÂZ Av‡Q| †K‡›`ª •e`y¨wZK †¶‡Îi gvb KZ ? [JU. 2012-13] A. 0 NC–1 B. 25 NC–1 C. 100 NC –1 D. 250 NC–1 †K‡›`ª †Kvb •e`y¨wZK †¶Î _v‡K bv| 05. 4 10–9C gv‡bi `ywU we›`y PvR© ci¯úi n‡Z 12m `~‡i Aew¯’Z| G‡`i ms‡hvM †iLvi ga¨we›`y‡Z Zwor cÖve‡j¨i gvb n‡e- [JU. 2012-13] A. 1N/C B. 2N/C C.0N/C D. 4N/C E = 9 109 r1 2 (Q1 – Q2) = 9 109 6 2 (4 10–9 – 4 10–9 ) r1 = d 2 = 6 = 0 STEP 03 ANALYSIS OF RU QUESTION 01. 3 cm `y‡i Aew¯’Z `ywU 5 C Pv‡R©i g‡a¨ GKB mij †iLvq Z…Zxq GKwU 10 C PvR© emv‡bv nj| cÖ_g PvR© n‡Z KZ `~i‡Z¡ Z…Zxq PvR© emv‡j Dnvi Dci jwä ej ïb¨ n‡e? [RU. 2016–17] A. 1cm B. 2cm C. 3cm D. †KvbwUB bq Zwor cÖvej¨ k~b¨ n‡j, Z…Zxq PvR© Gi Dci jwä ej k~b¨ n‡e| awi, cÖ_g PvR© n‡Z x `~‡i Zwor cÖvej¨ k~b¨ n‡e| x = d 1 + q2 q1 = 3cm 1 + 5 5 = 3cm 2 = 1.5 cm 02. GKwU we`y¨r Zwor wefe, v = –5x + 3y + 15z n‡j H we›`y‡Z Zwor cÖvej¨ KZ? [RU. 2015-16] A. 4 GKK B. 5 GKK C. 6 GKK D. 7 GKK E = – dV ds ; Ex = – dVx dx = 5, Ey = dVy dy = – 3, Ez = – dVz dz = – 15 ; E = – i Ex–j Ey–k Ez=5i +3j + 15 k ; |E| = 5 2 + 32 + 15 = 7 GKK 03. `yBwU avZzi cvZ GKwU 9v e¨vUvixi `yB cÖv‡šÍ hy³ Av‡Q| cvZ `ywU 10cm `~i‡Z¡ Ae¯’vb Ki‡j, cvZ `ywUi ga¨eZ©x †Kvb we›`y‡Z •e`y¨wZK cÖve‡j¨i gvb KZ n‡e? [RU. 2013-14] A. k~b¨ n‡e B. 90NC–1 C. 9.0NC–1 D. ‡KvbwUB bq E = 1 d (v1 v2) = 0 04. 4 F Ges 8 F `ywU aviK‡K 100V e¨vUvixi mv‡_ mgvšÍiv‡j hy³ Kiv nj| GK N›Uv ci aviK `ywU‡Z h_vµ‡g KZ Kzj¤^ PvR© Rgv n‡e? [RU. 2012-13] A. 410–6 I 810–6 B. 410–4 I 810–4 C. 3210–2 I 810–2 D. 1210–4 I 810–4 q1 = c = Q.v = 4 10–6 100 = 4 10–4 q2 = c2 = v = 8 10–6 100 = 8 10–4 05. 0.75g f‡ii GKwU ¶z`ª ej 8C abvZ¥K Avavb enb K‡i| ejwU‡K GKwU myZvi mvnv‡h¨ wb¤œgyLx Zwor‡¶‡Î Szwj‡q †`Iqv nj| Zwor‡¶‡Îi cÖvej¨ 600 NC1 n‡j myZvi Dci Uvb wbY©q Ki- [RU. 2012-13] A. 8.28103N B. 4.8103 N C. 7.35103N D. 12.15103N T = 0.7510–3 9.8+810–6 600 = 12.15 × 10–3N
448 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 06. GKwU mgvšÍivj cv‡Z avi‡Ki cvZ؇qi ga¨eZ©x `~iZ¡ A‡a©K n«vm I cvZ؇qi †¶Îdj wظb e„w× Ki‡j avi‡Ki aviKZ¡ KZ¸b e„w× cv‡e- [RU. 2011-12] A. wظb B. wZb¸b C. Pvi¸b D. k~b¨¸b C1 C2 = A2 A1 d1 d2 = 2 1 2 1 = 4 07. evZv‡m 100 C PvR© n‡Z 1m `~‡i †Kvb we›`y‡Z •e`y¨wZK cÖvej¨ KZ? [RU. 2010-11, HSTU. 15-16] 9 1 . 9 10 A Nc 11 1 . 9 11 B Nc 12 1 . 9 10 C Nc D. ‡KvbwUB bq E = 9 109 Q d 2 = 9 109 100 1 = 9 1011 NC–1 08. KZ cÖve‡j¨i •e`y¨wZK †¶‡Îi g‡a¨ GKwU B‡j±ªb ¯’vcb Ki‡j B‡j±«bwU Zvi IR‡bi mgvb ej Abyfe Ki‡e? [RU. 09-10,08-09, 07-08] A. 1.611011 N/C B. 5.121010 N/C C. 9.811011 N/C D. 5.571011 N/C •e`y¨wZK cÖve‡j¨i gvb, E = F q = mg q = 9.1 10–31 9.8 1.6 10–19 = 5.57 10–11 NC–1 09. 1.510-9 Kzj¤^ Pv‡R©i GKwU ¶z`ª †MvjK‡K evqy‡Z ¯’vcb Kiv nj| †MvjK n‡Z 0.12 m `~‡i †Kvb we›`y‡Z Zwor cÖvej¨ NC~1 GK‡K KZ n‡e? [RU. 2007-08] A. 937.5 B. 389.5 C. 739.5 D. 795.5 •e`y¨wZK cÖve‡j¨i gvb, E = 1 40 . q r 2 = 9 109 1.5 10–9 0.122 = 937.5 NC–1 10. 10 10-8 C Ges –5 10-8 C PvR© wewkó `ywU ¶z`ªvKvq †Mvj‡Ki ga¨eZ©x `~iZ¡ 10 cm| Avavb `ywUi wVK ga¨we›`y‡Z Zwor cÖvej¨ KZ n‡e? [RU. 06-07] A. 5.4105 NC-1 B. 5.4105 NC C. –5.4104 NC-1 D. –5.4104 NC ga¨we›`y‡Z cÖvej¨, 2 1 0 1 2 (q r/ 2 1 4 1 E E E q ) 2 = 9 109 1 0.052 15 10–8 =5.4105 NC–1 STEP 04 ANALYSIS OF CU QUESTION 01. GKwU mylg Zwor †¶‡Î 25cm e¨eav‡b Aew¯’Z `yÕwU we›`yi wefe cv_©K¨ 150V| Zwor †¶‡Îi cÖvej¨ KZ? [CU. 2012-13] A. 600 Vm1 B. 60Vm1 C. 600Vm D. 60Vm E. 600Vcm1 E = v D = 150 0.25 = 600 Vm1 02. 25 wgUvi e¨eav‡b Aew¯’Z GKwU mylg Zwor †¶‡Îi `yB we›`yi wefe cv_©K¨ 150 †fvë Zwor †¶‡Îi cÖvej¨ KZ? [CU. 2011-12] A. 6 v/m B. 60/m C. 650 v/m D. 3 v/m E. 69 v/m V = ED ev, E = v D = 150 25 = 6 vm–1 STEP 05 ANALYSIS OF DU-7 Clg QUESTION 01. wecixZag©x Pv‡R© PvwjZ `ywU Dj¤^, mgvšÍivj Ges Acwievnx cv‡Zi (ZjgvwÎK NbZ¡ ) ga¨eZ©x †Kv‡bv ¯’v‡b Zwor cÖvej¨ KZ? [DU. 7Clg-A: 20-21] A. 2 0 B. 0 C. 20 D. 0 S B info + E1 E2 – + – E2 E1 + – + – E = E1 + E2 = 20 + 20 = 0 STEP 06 ANALYSIS OF GST QUESTION PART A Analysis of General University Question IU 01. 2×10-9C PvR© †_‡K 0.10m `~i‡Z¡ •e`y¨wZK cÖvev‡j¨i gvb KZ?[IU. 2006-07] A. 1800C B. 18000 N/CC. 1800 N/C D. 1800 N/C2 E = 9×109 q r 2 = 9×109 2 10–9 (0.1) 2 = 1800 N/C BRUR 01. 10 GKK PvR© wewkó GKwU ¶z`ª †MvjK evqy‡Z ¯’vcb Kiv n‡q‡Q| Dnvi †K›`ª n‡Z 15cm `~‡i †Kvb we›`y‡Z •e`y¨wZK cÖvej¨ KZ? [BRUR. 2012-13] A. 0.044 dyne/GKK PvR© B. 15 dyne/GKK PvR© C. 150 WvBb/GKK PvR© D. 1.5 WvBb/GKK PvR© E = q r 2 = 10 (15) 2 = 0.044 dyne/GKK PvR© 02. GKwU B‡jKUª‡bi w¯’i Ae¯’v n‡Z 2400 volt m-1 cÖve‡j¨i Zwor †¶‡Îi ga¨ w`‡q Pj‡j Z¡iY KZ? [BRUR. 2012-13] A. 4×1013ms-2 B. 4.22×1014ms-2 C. 5×1013ms-2 D. 14×1012ms-2 ac = F me = EQ me = 2400 1.6 10–19 9.1 10–31 = 4.22×1014 ms-2 PART B Analysis of Science & Technology Question SUST 01. (3i ˆ + 4j ˆ ) NC–1 •e`y¨wZK †ÿ‡Î GKwU KYvi Z¡i‡Yi gvb KZ m.s–2 ? [SUST-B, 19-20] A. 2.2 × 106 B. 1.2 × 108 C. 2.4 × 106 D. 2.4 × 108 E. 1.2 × 106 a = F m F = qE ; E = (3 i + 4 j) E = 3 2 + 42 = 5NC1 a = F m = 2 1.6 1019 5 6.6 1027 ms2 = 2.4 108 ms2 02. †Kv‡bv ¯’v‡b f~-c„‡ôi wbK‡U DaŸ©gywL Zwor cÖve‡j¨i gvb 4.9×105 N.C–1 | H ¯’v‡b 1g f‡ii GKwU e¯‘‡K k~‡b¨ w¯’i ivL‡Z n‡j Gi Avavb KZ C n‡Z n‡e? [SUST-A, 19-20] A. 2 × 10 –7 B. 2 × 10–6 C. 2 × 10–8 D. 4 × 10–7 E. 6 × 10–10 F = qE = mg qE = mg q = mg E = 1 103 9.8 4.9 105 c = 2 108 C 03. A we›`y Ges Zvi †_‡K 1m `~‡i B we›`y‡Z 2q Ges – q Avavb ivLv n‡j †Kvb we›`y‡Z Zwor cÖvej¨ k~b¨ n‡e| [SUST: 2008-09] AB †iLvq A Ges B we›`y †_‡K h_vµ‡g A. 2+ 2m , 1+ 2m B. 2 – 2m , 1 – 2m C. 1+ 2m , 2m D. 1 – 2m , – 2m A we›`y‡Z PvR© = 2q and B we›`y‡Z PvR© = –q A we›`y †_‡K `~iZ¡ = 1 1 + q 2q = 1 1 + 1 2 = 2 2 + 1 04. PviwU GKB gv‡bi (q=210-6 ) Zwor PvR© GKwU eM©‡¶‡Îi (cÖwZwU evûi •`N©¨ 0.2 m) Pvi †Kvbvq ¯’vcb Kiv nj Gi †K›`ªwe›`y‡Z •e`y¨wZK cÖvej¨Ñ [SUST: 2008-09] A. 15105 NC-1 B. 0 NC-1 C. 18105 NC-1 D. 11105 NC-1 †K‡›`ª ev †¶‡Îi wfZ‡ii cÖvej¨ k~b¨|
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 449 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 05. GKwU †cÖvUb‡K k~‡b¨ fvmgvb ivL‡Z n‡j Zv‡K KZUzKy Zwor †¶‡Îi cÖve‡j¨i gv‡S ivL‡Z n‡e? [SUST: 2007-08] A. 1.010-7N/C B. 1.6710-27N/C C. 9.110-31N/C D. ‡KvbwUB bq Ans A 06. 104 V/m Zwor †¶‡Î GKwU B‡j±ª‡bi Z¡iY KZ m/s2 ? [SUST: 2014-15] A. 1.761016 B. 1.761015 C. 1.761014 D. 1.7610-15 E. 1.7610-16 F = ma QE = ma a = QE m = 1.6 10–19 104 9.1 10–31 = 1.761015 JUST 01. Zwor wefe 5 10 9 0 v x x , GLv‡b x `~iZ¡ wb‡`©k K‡i| x= 1m n‡j Zwor †¶‡Îi gvb KZ? [JUST: 2014-15] A. -20v/m B. -10v/m C. -15v/m D. 1v/m E. 2v/m v = 5x0 +10x – 9 ev, E = – dv dx = – d dx(10x) = – 10 NSTU 01. 1.610–9C Pv‡R© PvwR©Z GKwU ¶z`ª †MvjK‡K evqy‡Z ¯’vcb Kiv n‡jv| PvwR©Z †Mvj‡Ki †K›`ª n‡Z 0.15m `~‡i †Kvb we›`y‡Z •e`y¨wZK cÖvej¨ wbY©q Ki| [NSTU: 2014–15] A. 550NC–1 B. 640NC–1 C. 185NC–1 D. 825NC–1 640 0.15 1.6 10 9 10 2 9 9 E NC–1 STEP 07 ANALYSIS OF ENGINEERING & BUTex QUESTION KUET 01. 1.6 10–6C Ges 2.8 10–6C Pv‡R©i `ywU we›`yPvR© ci¯úi n‡Z 12cm `~‡i Aew¯’Z| 1.6 10 –6C †_‡K ms‡hvM mij‡iLvi †Kvb we›`y‡Z Zwor †ÿ‡Îi cÖvej¨k~Y¨ n‡e? [KUET:2018-19] A. 4.37m B. 0.21m C.0.068m D. 5.17cm E. 7.2cm q1 x 2 = q2 (12 – x) 2 = 12 – x x = 2.8 10–6 1.6 10–6 x = 5.166cm STEP 08 ANALYSIS OF HSC BOARD QUESTION 01. 4.0 104Vm–1 m~lg †ÿÎ cÖvej¨wewkó we`y¨r †ÿ‡Î GKwU †cÖvUb Gi Ici wµqvkxj ej KZ n‡e? [P. †ev. 2016] A. 0.4 10–23N B. 6.4 10–15N C. 4.6 1015N D. 6.4 1023N F = qE = 1.6 10–19C 4.0 104 vm–1 = 6.4 10–15N 02. mylg Zwor †ÿ‡Îi GKwU we›`y‡Z †cÖvU‡bi Dci cÖhy³ e‡ji gvb 4.8 10–19N| H we›`y‡Z Zwor †ÿ‡Îi cÖvej¨Ñ [P. †ev. 2016] A. 7.7 10–38NC–1 e‡ji wecixZ B. 7.7 10–38NC–1 e‡ji w`‡K C. 3.0 NC–1 e‡ji wecix‡Z D. 3.0 NC–1 e‡ji w`‡K E = F q = 4.8 10–19N 1.6 10–19C = 3 NC–1 03. evqy‡Z GKwU mgvšÍivj cvZ avi‡Ki cÖwZ cv‡Z Pv‡R©i ZjgvwÎK NbZ¡ 8.854 1012 Cm2 | avi‡Ki Af¨šÍ‡i K = 5 civ‣e`y¨wZK aªæeKhy³ c`v_© cÖ‡ek Kiv‡bv n‡j Zwor cÖvej¨ n‡e- [w`. †ev. 2017] A. 0.02 NC1 B. 0.02 NC1 C. 0.5 NC1 D. 1.0 NC1 E = k0 = 8.854 10–12 cm–2 5 8.854 10–12 C 2N –1m –2 = 0.02 NC1 DÏxc‡Ki Av‡jv‡K 04 I 05 bs cÖ‡kœi DËi `vI : mylgfv‡e PvwR©Z GKwU †Mvj‡Ki †gvU PvR© Ges e¨vm h_vµ‡g 24C Ges 0.08 wgUvi| 04. †Mvj‡Ki †K›`ª †_‡K 0.04 wgUvi `~i‡Z¡i †Kv‡bv we›`yi cÖvej¨ KZ wbDUªb/Kzj¤^? [gv. †ev. 2017] A. 2.7 1012 B. 5.4 1012 C. 3.38 1013 D. 1.35 1014 E = 9 109 24 (0.04) 2 = 1.35 1014 NC–1 05. †MvjKwUi †K›`ª †_‡K 0.03 wgUvi `~‡ii †Kv‡bv we›`y‡ZÑ [gv. †ev. 2017] i. wefe 5.4 1012 V ii. cÖvej¨ 2.4 1014 NC–1 iii. cÖve‡j¨i gvb k~b¨ wb‡Pi †KvbwU mwVK? A. i I ii B. ii I iii C. i I iii D. i, ii I iii Ans C Concept 3 Zwor wefe wbY©q msµvšÍ MvwYwZK cÖ‡qvM FORMULA 01. Zwor wefe, V = 1 40 q r = 9 109 q r 02. jwä wefe, V= V1 + V2 + ..... = 9 109 q1 r1 + q2 r2 + ............... 03. eM©‡ÿ‡Îi †K‡›`ª wefe, V= 4 0 1 × r/ 2 1 ×(q 1 +q 2 +q 3 +q 4 ) [e„‡Ëi †K›`ª n‡Z c„ô ch©šÍ †h †Kv‡bv we›`yi wefe c„‡ôi wef‡ei mgvb] 04. V = Ed Model Example01 †Kv‡bv eM©‡ÿ‡Îi wZbwU †K․wYK we›`y‡Z h_vµ‡g + 6 10–9C, – 12 10–9C Ges 14 10–9C Avavb ¯’vcb Kiv n‡jv| PZz_© †K․wYK we›`y‡Z KZ Avavb ¯’vcb Ki‡j eM©‡ÿ‡Îi †K‡›`ª Zwor wefe k~b¨ n‡e? General Rules [Written] 3 in 1 Shortcut Tricks & Tips [MCQ] awi, eM©‡ÿÎwUi (wPÎ Abyhvqx) †K․wYK we›`y¸‡jv †_‡K †K‡›`ªi `~iZ¡ a Ges PZz_© we›`yi PvR© q| Avgiv Rvwb, eM©‡ÿ‡Îi †K‡›`ª wefe = †K›`ª n‡Z Pvi †K․wYK we›`y‡Z wef‡ei mgwó A_©vr, V1 + V2+ V3 + V4 = 0 0 = 1 40 6 10–9 a – 12 10–9 a + 14 10–9 a + q a 6 10–9 – 12 10–9 + 14 10–9 + q = 0 8 10–12+ q = 0 q = – 8 10–12C q4 q1 q2 a q3 q1 + q2 + q3 + q4 = 0 q4 = – (q1 + q2 + q3) = – (6 10–9 – 12 10–9 + 14 10–9 ) = –8 10–12C
450 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES CONCEPTUAL MATH MEx 01 evqy‡Z GKwU eM©‡¶‡Îi Pvi †KvYvq h_vµ‡g 210–9C, 310–9C, 410–9C Ges 510–9C PvR© ¯’vcb Kiv n‡jv| eM©‡¶‡Îi evûi •`N©¨ 0.8m n‡j eM©‡¶‡Îi †K‡›`ª wefe KZ? r = AB 2 = 0.8 2 = 0.4 2 m V0 = VA + VB + CC + VD = 1 40 1 r (q1 + q2 + q3 + q4) †K‡›`ª wefe, V0 = (9 109 ) 1 0.4 2 (2+3 +4+5)10–9 =222.74 V r A B D C O 0.8 0.8 r r r r 0.8 0.8 MEx 02 GKwU mgevû wÎfz‡Ri wZb †KvYvq cÖ‡Z¨KwU +6nC gv‡bi wZbwU PvR© ivLv nj| wÎfz‡Ri cÖ‡Z¨KwU evûi •`N©¨ 12m| wÎfzRwUi f‚wgi ga¨we›`y‡Z wefe wbY©q Ki? awi, BD = CD = 6m ; AD = AC2 – CD2 = 122 – 6 2 = 6 3 m; VD = VA + VB + VC = q 40 1 AD + 1 BD + 1 CD VD = (9 109 ) (6 10–9 ) 1 6 3 + 1 6 + 1 6 = 23.2V A C B D MEx 03 PviwU GKB gv‡bi (q=210–6C) Zwor PvR© GKwU eM©‡¶‡Îi (cÖwZ evûi •`N©¨ 0.2 m) Pvi †KvYvq ¯’vcb Kiv n‡j Gi †K›`ªwe›`y‡Z •e`y¨wZK wefe KZ n‡e? eM©‡¶‡Î KY© = 2 evûi •`N©¨ = 2 0.2 r = 1 2 ( 2 0.2) = 0.1414 VA = 1 40 . 1 2 .4q = 9 109 1 (0.1414) 4 210–6 =5.091105V r q q q q A 0.2 0.2 r r r r 0.2 0.2 MEx 04 GKwU eM©‡¶‡Îi †K‡›`ª q Ges eM©‡¶‡Îi wZbwU †KvYvq h_vµ‡g 5, 8 Ges 5C Avavb ivLv n‡q‡Q| PZz_© †KvYvq KZ Avavb ivLv n‡j †K‡›`ªi wefe k~b¨ n‡e? PZz_© †K․wYK we›`y‡Z PvR©, q4 = (q1 + q2 + q3) = (5+8+5) = 18C NOW START PRACTICE 01. 20 †fv‡ëi GKwU e¨vUvixi GK cÖvšÍ n‡Z Ab¨ cÖv‡šÍ 10 Kzj¤^ PvR©‡K cwievwnZ Ki‡Z KZ KvR Ki‡Z n‡e? 02. †Kvb avZe wbDwK¬qv‡mi PvR© q=810–18C wbDwK¬qvm †_‡K 10–12m `~‡i †Kvb we›`y‡Z Zwor wefe wbY©q Ki? 03. +2C Ges +5C gv‡bi `ywU Pv‡R©i ga¨Kvi `~iZ¡ 6m| G‡`i ms‡hvM †iLvi ga¨we›`y‡Z wefe KZ? 04. 0.02m evû •`‡N©¨i GKwU eM©‡¶‡Îi wZb †KvYvq h_vµ‡g +410–9 C, 410–9C Ges +410–9 C Gi wZbwU PvR© ivLv nj| Aci †K․wYK we›`y‡Z •e`y¨wZK wefe wbY©q Ki? 05. 2 2 evûwewkó GKwU eM©‡ÿ‡Îi cÖwZwU †Kvbvq 2 × 10–9 C PvR© ¯’vcb Kiv n‡jv| eM©‡ÿ‡Îi †K‡›`ªi wefe KZ? NOW PRACTICE SOLVE : 01. PvR© ¯’vbvšÍ‡ii K…ZKvR, W = qV = 1020 = 200J Ans. 02. Zwor wefe, V = 1 40 q r = 9 109 8 10–18 10–12 = 72 103 Volt 03. ga¨we›`y‡Z wefe, V = V1 + V2 = 1 40 1 r/2 (q1 + q2) = 9109 1 3 (2+5)10–6 =21000V=21 kV 04. awi, qA= 410–9C, qB = –410–9C Gis qC =410–9C BD = 2AB = 0.02 2m ; VD = VA +VB+VC = 1 40 qA AD + qB BD + qC CD VD = 9 109 4 10–9 0.02 + –4 10–9 0.02 2 + 4 10–9 0.02 = 2327.2V A B D C 05. V = 9 × 109 × 4 × 2 × 10–9 2 2 2 = 36 Volt
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 451 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. hw` Zwor †ÿ‡Îi cÖvej¨ + x Aÿ eivei wµqv K‡i Ges Gi gvb E = cx2 nq, †hLv‡b, c = aªæeK, Z‡e Zwor wefe V = ? [DU: 2018-19] A. –2cx B. 2cx C. –c x 3 3 D. cx3 3 E = – dv dx; dV = –Edx = –cx2 dx = –c x 3 3 + K 02. 5.0 cm.e¨vmv‡a©i GKwU cwievnx †Mvj‡Ki PvR© 4.0 C| †K›`ª †_‡K 4.0cm. `~i‡Z¡ wefe KZ? [DU. 2001-02] A. 6.0105 V B. 0 V C. 3.5105 V D. 7.2105 V V = 9 109 Q r (r > d) V = 9 109 4 10–6 0.05 = 7.2 105 volt 03. GKwU 1.0 m evû wewkó eM©‡¶‡Îi cÖwZwU †KvYvq 10nC Avavb ¯’vcb Kiv n‡jv| eM©‡¶‡Îi †K‡›`ªi wefe KZ? [DU. 2000-01] A. 255V B. 510V C. 358V D. 123V r = 1 2 1 2 + 12 = 1 2 ; V0 = 1 40 4q r = 9 109 4 10 10–9 1 2 = 510V 04. hw` a e¨vmva© wewkó `yÕwU cwievnx †MvjK‡K hv‡`i GKwU‡Z +Q Avavb Av‡Q, Ab¨wU‡Z †Kvb Avavb †bB, ci®úi ms¯ú‡k© Avbv nq, Zvn‡j P~ovšÍ wefe KZ? [DU. 2000-01] A. 1 80 Q a B. 1 40 Q a C. 1 20 Q a D. None ms¯ú‡k©i ci cÖwZwU‡Z Avavb = Q 2 V = 1 40 Q 2 a 1 80 Q a STEP 02 ANALYSIS OF JU QUESTION 01. GKwU cwievn‡Ki aviKZ¡ 40 F n‡j G‡Z KZ PvR© cÖ`vb Ki‡j Gi wefe 8V n‡e? [JU-A, Set-C. 20-21, NSTU. 14-15] A. 280 C B. 300 C C. 320 C D. †KvbwUB bq S C info Avgiv Rvwb, Q = V C = 8 40 = 320C 02. 10cm e¨vmv‡a©i GKwU †Mvj‡Ki c„‡ô 10C gv‡bi GKwU PvR© ¯’vcb Ki‡j Gi c„‡ô Zwor wef‡ei gvb KZ n‡e? [JU-A, Set-E. 20-21, JU. 18-19, 15-16] A. 7 1011V B. 8 1011V C. 9 1011V D. †KvbwUB bq S C info Zwor wefe, V = C q r = 9 109 10 0.1 = 9 1011V 03. 1.34 105Nc1 cÖve‡j¨i GKwU Zwor‡ÿ‡Î 15.8cm e¨eav‡b Aew¯’Z `ywU we›`yi wefe cv_©K¨ KZ? [JU. 2018-19] A. 2.12 104V B. 2.12 10–4V C. 1.12 104V D. 1.12 10–4V v = Ed = 1.34 105 15.8 10–2 = 2.12 104V 04. 110–9C Pv‡R© PvwR©Z 100cm e¨vmv‡a©i GKwU †MvjK‡K evqy‡Z ¯’vcb Kiv n‡jv| †Mvj‡Ki †K›`ª †_‡K 0.1 cm `~‡i †Kvb we›`y‡Z Zwor cÖevj¨ I wefe h_vµ‡g- [JU. 2015–16] A. 9NC–1 I 9V B. 0 NC–1 I 9V C. 10 NC–1 I 9V D. †KvbwUB bq ‡Mvjv‡Ki e¨vmva©, r 100cm , `~iZ¡ d 0.1com [r > d] cÖvej¨ E = 0; wefe v = 9 109 Q r = 9 109 1 10–9 1 = 9v 05. GKwU †gvUi Mvwoi e¨vUvixi `yB cÖv‡šÍi wefe cv_©K¨ 12 V| 2.5 C Avavb‡K e¨vUvixi FYvZ¥K cÖvšÍ †_‡K abvZ¥K cÖv‡šÍ ¯’vbvšÍ‡ii Rb¨ m¤úbœ Kv‡Ri cwigvY- [JU. 2011-12] A. 25 J B. 28 J C. 30 J D. 32 J PvR© ¯’vbvšÍ‡ii K…ZKvR, W = q V =12 2.5 = 30 J 06. †Kvb we›`yi wefe 20V| Amxg `~iZ¡ n‡Z 5 C PvR©‡K D³ we›`y‡Z Avb‡Z Kv‡Ri cwigvY KZ n‡e? [JU. 2011-12, RU. 07-08] A. 4 J B. 100 J C. 15 J D. 25 J PvR© ¯’vbvšÍ‡ii K…ZKvR, W = q V =205= 100 J STEP 03 ANALYSIS OF RU QUESTION 01. Zwor‡ÿ‡Îi cÖve‡j¨i mgxKiY E(x) = ax2 n‡j, Zwor wef‡ei ivwkÑ[RU. Sinovac, Set-1. 20-21] A. 2ax B. ax3 3 + b C. ax3 3 D. ax3 3 b S B info E = – dV x – dV = ax 2 dx – V = ax3 3 + b V = – ax3 3 + b 02. 18 cm e¨vmva©wewkó GKwU duvcv †MvjKxq cwievnx‡Z Pv‡R©i cwigvb 10-2 C| †Mvj‡Ki c„ôZ‡j wefe KZ? [RU. 2016–17] A. 0 V B. 50 V C. 200 V D. 500 V †Mvj‡Ki c„ôZ‡j wefe, v = 1 40 q r = 9109 10–2 10–6 0.18 = 500Volt 03. 0.2 m e¨v‡mi GKwU †MvjvK…wZ cwievnxi c„‡ô 33.310–9 C PvR© †`qv nj| †Mvj‡Ki †K›`ª 0.5 m n‡Z `~‡i Zwor wefe KZ? [RU. 2008-09] A. 590.1 V B. 579.2 V C. 559.3 V D. 599.4 V †Mvj‡Ki †K›`ª †_‡K 0.50 m `~‡i, V = 1 40 q r = 9 109 33.3 10–9 0.5 = 599.4Volt STEP 04 ANALYSIS OF CU QUESTION 01. 1C Avavb‡K GKwU Zwor †¶‡Îi `ywU we›`y‡Z wb‡Z 1J KvR Ki‡Z n‡j, H we›`y؇qi ga¨eZ©x wefe cv_©K¨- [CU. 2014–15] A. 1.0100 V B. 1.0101 V C. 1.0102 V D. 1.0103 V E. 1.010-19 V PvR© ¯’vbvšÍ‡ii K…ZKvR, W = Vq; V= W q = 1 1 = 1 Volt 02. GKwU eM©‡¶‡Îi wZbwU †K․wbK we›`y‡Z 2 10 , 9 c 4 10 , 9 c c 9 8 10 PvR© ¯’vcb Kiv nj| Gi PZz_© †K․wbK we›`y‡Z KZ PvR© ¯’vcb Ki‡j †K‡›`ª wefe k~b¨ n‡e? [CU. 2010-11] A. 7 10–9C B. –14 10–9C C. 10 10–9C D. 12 12–9C E. –8 10–9C Q4 = –(Q1+Q2+ Q3) = – (2 + 4 + 8) 10–19 = –1410–9 STEP 05 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. A B C D eM©‡¶‡Îi A we›`y‡Z 6 Kzj¤^, B we›`y‡Z 8 Kzj¤^ I C we›`y‡Z -2 Kzj¤^ PvR© _vK‡j D we›`y‡Z KZ PvR© ¯’vcb Kiv n‡j †K‡›`ª wef‡ei gvb k~b¨ n‡e? [JnU. 2010-11] A.16 C B. 12 C C. -12 C D. -16 C S C info q4 = – (Q1 + Q2 + Q3) = – (6 + 8 – 2) = – 12C
452 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 02. `yÕwU avZe †Mvj‡Ki e¨vm h_vµ‡g 6 cm. Ges 10 cm| †MvjK `yÕwU‡K GKwU Zvi w`‡q hy³ K‡i 6.410-6 c PvR© cÖ`vb Kiv nj| †MvjK `yÕwUi mvavib wefe KZ? [JnU. 2007-08] A. 6.410-6 v B. 0.8106 v C. 0.910-6 v D. 0.7106 v V = q C1 + C2 = q 40r1 + 40r2 = 40 1 q r1 + r2 0.03 0.05 6.4 10 9 10 6 9 = 0.7106V CoU 01. 2 m e¨v‡mi GKwU †MvjvK…wZ cwievnxi c„‡ô 3109C PvR© †`qv n‡jv| †Mvj‡Ki †K›`ª †_‡K 0.80 m `~‡i †Kvb& we›`yi wefe I cÖvej¨ n‡e- [CoU. 12-13] A. 20V I 20 N/C B. 27V I 27 N/C C. 27V I 0 N/C D. 0V I 0N/C [†K›`ª n‡Z c„ô ch©šÍ †h‡Kvb we›`yi cÖve‡j¨i gvb k~b¨| e„‡Ëi †K›`ª n‡Z c„ô ch©šÍ †h‡Kvb we›`yi wefe, c„‡ôi wef‡ei mgvb|] e„‡Ëi †K›`ª †_‡K 0.80 m `~‡i, V = 1 40 q r = 9 109 3 10–9 1 = 27V 02. 12 Kzj¤^ PvR©‡K GK ¯’vb n‡Z Ab¨ ¯’v‡b Avb‡Z KZ KvR Ki‡Z n‡e hw` wefe cv_©K¨ 500v nq| [CoU. 2008-09, 10-11] A. 6×106 erg B. 6×1010erg C. 6×108 erg D. 6×105 erg W = qv = 12×500 = 6×103 J = 6×10 10erg IU 01. GKwU eM©‡¶‡Îi wZbwU †K․wYK we›`y‡Z h_vµ‡g 5C, 10C, –20C Avavb ¯’vwcZ| PZz_© †K․wYK we›`y‡Z KZ Avavb ¯’vcb Ki‡j eM©‡¶ÎwUi †K›`ª Zwor wefe ïb¨ n‡e? [IU. 2016–17] A. –5C B. –10C C. +5C D. +10C [†K‡›`ª wefe k~b¨] PZz_© †K․wYK we›`y‡Z PvR©, q4 = (q1 + q2 + q3) = (5 +10–20) = +5C BRUR 01. †Kvb GKwU •e`y¨wZK †¶‡Îi GKwU we›`y‡Z wef‡ei gvb 30V| Amxg †_‡K H we›`y‡Z 2C PvR© Avb‡Z Kv‡Ri cwigvY- [BRUR.14–15] A. 20J B. 60J C. 50J D. 120J KvR, w = Qv = 302 = 60j PART B Analysis of Science & Technology Question SUST 01. k~b¨ gva¨‡g q gv‡bi `yBwU abvZ¥K we›`y Avavb‡K r `~i‡Z¡ ivLv n‡jv| Zv‡`i ms‡hvM †iLvi ga¨we›`y‡Z Zwor cÖvej¨ I Zwor wefe h_vµ‡g- [SUST-B, 19-20] A. 2q/0r 2 , q/0r B. 0, 2q/0r C. q/0r 2 , 0 D. 2q/0r 2 , 0 E. 0, q/0r S E info Zwor wefe, V = 1 40 2q r 2 = q 0r Ges Zwor cÖvej¨, E = 1 40 r 2 2 (q – q) = 0 02. 0.5m evûwewkó GKwU mgevû wÎf~‡Ri wZb kxl©we›`y‡Z wZbwU Avavb q1 = +210–8C, q2 = –310–8C Ges q3 = +410–8C ¯’vcb Ki‡j wÎfy‡Ri †K‡›`ª wefe KZ V n‡e? [SUST: 2015-16] A. 835.3 B. 5.5.3 C. 935.3 D. 965.3 E. 980.3 mgevû wÎf~‡R a sin A = 2R ev, 0.5 sin 60 = 2R ev, R = 0.29m V = R 9 910 (210–8 –310–8 +410–8 ) V = 0.29 9 109 (210–8 –310–8 +410–8 )= 934 03. cv‡k¦©i wP‡Î •e`y¨wZK mgwefe Zj¸‡jvi g‡a¨ wefe cv_©K¨ 0.33V Ges Zj¸‡jv 11cm e¨eav‡b i‡q‡Q| Zwor‡¶Î cÖvej¨ KZ Vm~1 ? [SUST: 2015-16] A. 0.03 B. 0.11 C. 0.30 D. 0.33 E. 3.00 V = ED ev, E = V D = 4 0.33 4 0.11 = 3 04. GKwU mylg Zwor †¶‡Î 50 cm. e¨eav‡b Aew¯’Z `ywU we›`yi wefe cv_©K¨ 200 v. n‡j Zwor †¶‡Îi cÖvej¨Ñ [SUST: 2007-08; MBSTU: 2013-14] A. 200 Vm-1 B. 400 Vm-1 C. 100 Vm-1 D. 50 Vm-1 V = ED ev, E = V D = 200 0.50 = 400 Vm-1 JUST 01. GKwU avi‡Ki aviKZ¡ 5F| G‡Z 1000 C PvR© cÖ`vb Ki‡j wefe KZ n‡e? [JUST: 2015-16] A. 150 V B. 200 V C. 250 V D. 300 V C = Q V ev, V = Q C = 1000 5 = 200V 02. 0.02m e¨vmva© wewkó 64 wU †Mvjv‡Ki †duvUv‡K GKwÎZ K‡i GKwU eo †dvUvq cwiYZ Kiv nj| hw` cÖwZ †duvUvq 1C PvR© we`¨gvb _v‡K Z‡e eo †duvUvi wefi KZ? [JUST: 2014–15] A. 8.9×10-10 V B. 7.19×1012 V C. 9.2×1010 V D. 10.7×1012 V E. 8.9×1010 V Nr3 = R3 , 64 (.02)3 = R3 R = 0.08m c = 40 R = 4 3.1416 8.85 10–12 0.08 = 8.9 10–12 V = q c = 64 8.9 10–12 = 7.19 × 1012 V BSMRSTU 01. †Kvb wbtm½ PvR© n‡Z 10cm `~‡i 100V wefe m„wó n‡j G PvR©wUi cwigvY KZ? [BSMRSTU-B, 19-20] A. 0.11 10–10C B. 1.1 10–10C C. 0.11 10–9C D. 1.1 10–9C Zwor wefe, V = 9 109 Q r 100 = 9 109 Q 0.1 Q = 100 0.1 9 109 = 10 9109 = 1.11 10–9 C PSTU 01. GKwU †MvjvKvi cwievnxi e¨vmva© 0.5 m Ges Zv‡Z 10 C PvR© †`Iqv Av‡Q| †Mvj‡Ki †K›`ª n‡Z 0.1m `~i‡Z¡ ‣e`y¨wZK wef‡ei gvb KZ n‡e? [PSTU: 2013-14] A. 9×109V B. 1.8×1011V C. 9×1011 V D. 3.6×1011V volt r Q v 9 9 11 1.8 10 0.5 10 910 910 STEP 06 ANALYSIS OF ENGINEERING & BUTex QUESTION BUET 01. a evû wewkó GKwU eM©‡¶‡Îi †K․wYK we›`y A, B, C I D †Z h_vµ‡g PviwU PvR© +q, +q, -q I –q ¯’vcb Kiv nj| Dnvi †K›`ª O we›`y‡Z •e`y¨wZK wef‡ei gvb n‡e- [BUET: 2013-14] A. 1 40 q a B. 1 40 2q a C. 1 40 4q a D. 0 (zero) P‡R© ¸‡jvi †hvMdj = (q + q – q – q ) = 0 02. eRªcv‡Zi mgq 30C PvR© 1.0108 v wefe cv_©‡K¨i g‡a¨ 2.010-2 s mg‡q wb:mwiZ nq| H eRªwbbv‡`i mv‡_ Aegy³ kw³i cwigvb n‡jv [BUET: 2012-13] A. 1.51011j B. 3.0109 j C. 6.0107 j D. 3.3106 j W = QV = 301.0108 = 3109 j
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 453 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 03. GKwU eRª †g‡Ni `ywU As‡ki wefe cv_©K¨ hw` 108 v nq, Z‡e 20C PvR©‡K AwZµ‡gi d‡j wK cwigvb kw³ cwiZ¨³ n‡e- [BUET: 2011-12] A. 1.251028j B. 3.21010j C. 2109 j D. 3.210-10j W = QV = 20108 = 2109 j 04. GK †dvUv †Zj‡K 400v wefe cv_©K¨ Øiv w¯’i ivLv nq| GKB cwigvb Avavbhy³ wظb e¨vmva© wewkó Av‡iKwU †dvUv‡K w¯’ive¯’vq ivL‡Z wefe cv_©‡K¨i cÖ‡qvRb n‡e- [BUET: 2007-08] A. 800v B. 1600v C. 3200v D. 400v V2 = 400(2)2 = 1600v 05. 910-12.cm e¨vmv‡a©i GKwU cigvYyi wbDwK¬qv‡mi (z = 50) c„‡ô Zwor wef‡ei gvb [BUET: 2005-06] A. 9v B.60v C. 9105 v D.8105 v 14 19 9 9 9 10 50 1.6 10 9 10 9 10 r Q v =8105 V STEP 07 ANALYSIS OF HSC BOARD QUESTION 01. 10C O 12C –15C wP‡Î eM©‡ÿ‡Îi 4_© †K․wYK we›`y‡Z KZ PvR© ¯’vcb Ki‡j †K‡›`ª wefe k~b¨ n‡e? [Xv. †ev. 2017] A. –7C B. –3C C. 5C D. 7C awi, AO = BO = CO = DO 10C O 12C –15C A D B C 1 40 q1 AO + q2 BO + q3 CO + q4 DO = 0 q1 + q2 + q3 + q4 = 0 q4 = – (q1 + q2 + q3) = – (10 + 12 – 15) = – 7C 02. N4 = ? N3 = 6C N1 = 2C N2 = –4C DÏxc‡K eM©‡ÿ‡Îi †K‡›`ª wef‡ei gvb k~b¨ n‡j N4 = KZ? [iv. †ev. 2015] A. –4C B. +4C C. +12C D. –12C V = 1 40 N r 1 40 N1 r + N2 r + N3 r + N4 r = 0 N1 + N2 + N3 + N4 = 0 2 – 4 + 6 + N4 = 0 N4 = – 4C 03. †Kv‡bv †Mvj‡Ki c„‡ô 20 C gv‡bi 10wU Avavb mylgfv‡e Qwo‡q †`Iqv nq| D³ †Mvj‡Ki e¨vmva© 15 cm| †Mvj‡Ki †K›`ª n‡Z 5 cm `~‡i wefe KZ? [Kz. †ev. 2015] A. 1.2 1013V B. 3.6 1013V C. 8 1013V D. 7.2 1014V †Mvj‡Ki Af¨šÍ‡i mKj we›`yi wefe c„‡ôi wef‡ei mgvb (wKš‘ †K‡›`ª wefe k~Y¨)| †K›`ª n‡Z 5cm `~‡i wefe n‡e †K›`ª n‡Z 15cm `~‡ii wef‡ei mgvb A_©vr c„‡ôi wef‡ei mgvb| V = 1 40 q r = 9 10 9 20 10 0.15 = 1.2 1013 V Concept 4 Pv‡R©i ZjgvwÎK NbZ¡ msµvšÍ FORMULA 01. Pv‡R©i ZjgvwÎK NbZ¡ ev Avavb NbZ¡, = A Q = 2 4 r Q [A = 4r 2 (†Mvj‡Ki †ÿ‡Î) †MvjvKvi cwievnx‡Z PvR© me©`v c„‡ô _v‡K|] 02. E = 0 ✅ †MvjvKvi cwievnx: †MvjvKvi cwievnx‡Z PvR© me©`v c„‡ô _v‡K| CONCEPTUAL MATH MEx 01 `ywU †Mvj‡Ki e¨vmva© h_vµ‡g 0.01m Ges 0.02m G‡`i‡K h_vµ‡g 30C Ges 60C Pv‡R© PvwR©Z Kiv nj| †MvjK `ywUi Pv‡R©i Zj NbZ¡ Zzjbv Ki| ZjgvwÎK NbZ¡, 2 4 r q A q ; 2 r q 1 2 = q1 q2 r2 r1 2 = 30 60 0.02 0.01 2 = 2 : 1 NOW START PRACTICE 01. `yBwU †Mvj‡Ki e¨vmv‡a©i AbycvZ 1:2| Zv‡`i GKwU‡Z 40C I Ab¨wU‡Z 80C PvR© cÖ`vb Kiv n‡j| PvR© Nb‡Z¡i AbycvZ KZ n‡e? 02. GKwU †MvjKxq Z‡ji †¶Îdj 10 m2 | D³ Z‡j 600 C PvR© cÖ`vb Kiv n‡j Pv‡R©i Zj NbZ¡ wbY©q Ki| NOW PRACTICE SOLVE : 01. 1 2 = Q1 Q2 r2 r1 2 = 40 80 2 1 2 = 2 : 1 02. Pv‡R©i Zj NbZ¡, = q A = 600 10 = 60 C/m2 REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF JU QUESTION 01. `yBwU †Mvj‡Ki e¨vmva© h_vµ‡g 2cm Ges 4cm| G‡`i‡K h_vµ‡g 1000 Kzj¤^ Ges 2000 Kzj¤^ Pv‡R©i PvwR©Z Kiv n‡jv| ¶z`ª I e„nr †Mvj‡Ki Pv‡R©i Zj Nb‡Z¡i AbycvZ KZ? [JU. 2014–15] A. 2:1 B. 1:2 C. 4:1 D. 1:4 1 2 = r2 r1 2 = 4 2 2 = 4:1 STEP 02 ANALYSIS OF GST QUESTION 01. †Kvb Zj Øviv Ave×K…Z 2 GKK Pv‡R©i Rb¨ k~b¨¯’v‡b •e`y¨wZK d¬v·- [GST-A. 20-21] A. 20 B. 0 C. 1/40 D. 2/0 = q 0 = 2 0
454 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 5 Zwor w؇giæ FORMULA 01. w؇giæ åvgK, p = q 2l 02. Zwor w؇giæi Rb¨ Zwor cÖvej¨, E = 1 4o P r 3 (1+3cos2 ) hLb = 0° A_©vr we›`ywU hw` w؇giæi A‡¶ Aew¯’Z nq, †m‡¶‡Î, E = 1 4o 2P r 3 hLb = 90° A_©vr we›`ywU A‡¶i Dci Awfj¤^ nq, †m‡¶‡Î, E = 1 4o P r 3 03. Zwor wØ †giæi Rb¨ Zwor wefe V = 1 4o Pcos r 2 hLb = 0° A_©vr we›`ywU A‡¶ Ae¯’vb K‡i †m‡¶‡Î vp = 1 4o . P r 2 hLb = 90° A_©vr we›`ywU A‡¶i Dci Awfj¤^ nq, †m‡¶‡Î vp = 0 04. Zwor wØ-‡giæ A‡¶i Dci †Kvb we›`y‡Z wefe, v = 1 4o p r 2 –l 2 05. w؇giæ N~Y©‡b K…ZKvR, W = pE (cos1 – cos2) p = w؇giæ åvgK; E = nZ Zwor‡ÿ‡Îi cÖvej¨, 1 = cÖve‡j¨i mv‡_ w؇giæi Avw` Ae¯’vb; 2 = cÖve‡j¨i mv‡_ w؇giæi †kl Ae¯’vb E Er E E rd d O –q q wPÎ: Zwor w؇giæ CONCEPTUAL MATH MEx 01 1C Gi `yÕwU wecixZag©x PvR© ci¯úi 1mm `~i‡Z¡ Ae¯’vb K‡i GKwU Zwor w؇giæ MVb K‡i| w؇giæwUi ga¨we›`y †_‡K 10cm `~‡i Gi A‡ÿi Dci †Kvb we›`y‡Z Zwor cÖvej¨ wbY©q Ki| GLv‡b, Zwor w؇giæi cÖ‡Z¨KwU‡Z Pv‡R©i cwigvY, q = 1 10–6C ga¨eZ©x `~iZ¡, 2l = 1 10–3m w؇giæi †K›`ª †_‡K `~iZ¡, r = 10 10–2m w؇giæi åvgK, P = q 2l = 1 10–6 1 10–3 = 1 10–9Cm w؇giæi A‡ÿi Dci Aew¯’Z we›`yi Rb¨, E = 1 40 ; 2p r 3 = 9 109 2 10–9 (0.1) 3 = 1.8 104NC–1 [GLv‡br 1, ZvB w؇giæi cÖve‡j¨i m~Î e¨envi Kiv hv‡”Q| Zv bv n‡j D‡jøwLZ we›`y‡Z cÖ‡Z¨K Pv‡R©i Rb¨ m„ó Zwor cÖvej¨ wn‡me K‡i jw× cÖvej¨ †ei Ki‡Z nZ|] MEx 02 k~b¨ ¯’v‡b +4C Ges –4C we›`y Avavb `ywU 10–3 m e¨eav‡b †_‡K GKwU Zwor w؇giæ MVb K‡i| Gi w؇giæ åvgK KZ? Zwor w؇giæi åvgK, p = q 2l p = 4 10–6 10–3 = 4 10–9 cm Ans. NOW START PRACTICE 01. + 1C Ges –1C Avavb `ywU‡K 10 cm e¨eav‡b †i‡L GKwU Zwor w؇giæ MVb Kiv n‡jv| GB w؇giæi Aÿ eivei 15 cm `~‡ii †Kvb GKwU we›`y‡Z Zwor wefe KZ? 02. GKwU Zwor w؇cv‡ji Rb¨ Zwor‡¶Î, `~iZ¡ r Gi mv‡_ wKfv‡e cwiewZ©Z nq? NOW PRACTICE SOLVE : 01. GL‡b, P = q 2l = 1 10–6 10 10–2 = 10 10–8 cm = 10–7 cm V = 9 109 P r 2 = 9 109 10 10–8 (15 10–2 ) 2 = 4 104 V 02. Zwor w؇cv‡ji Rb¨ Zwor‡¶Î, E = 1 40 P r 3 [P= dipole moment] E 1 r 3 REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF JU QUESTION 01. + 1C Ges – 1C Avavb `ywU‡K 5cm e¨eav‡b †i‡L GKwU Zwor w؇giæ MVb Kiv n‡jv| GB w؇giæi Aÿ eivei 15 cm `y‡ii †Kv‡bv GKwU we›`y‡Z Zwor wefe wbY©q Ki| [JU-H, Set-A. 20-21] A. 6 × 104 volt B. 4 × 104 volt C. 2 × 104 volt D. 8 × 104 volt S C info Avgiv Rvwb, V = 1 40 p r 2 – l 2 [p = q 2l] V = 9 109 1 10–6 5 10–2 (15 10–2 ) 2 (2.5 10–2 ) 2 [2l = 5cm] = 2 ×104 volt
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 455 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 02. GKwU Zwor w؇giæi PvR©Ø‡qi ga¨ewZ© `~iZ¡ 310–19 m Ges Pv‡R©i cwigvb 3.210–9C| GB w؇giæ n‡Z 3cm `~‡i Gi A‡¶i j¤^ wØLÛ‡Ki Dci Zwor cÖvej¨ 3.210–15 NC–1 n‡j w؇giæi åvg‡Ki gvb- [JU. 17-18] A. 310–19 3.210–9 B. 31019 3.210–9 C. 2 9 3 10 3.2 10 4 1 D. 3.210–5 3.210–9 w؇giæi åvg‡Ki gvb, P = Pv‡R©i cwigvb (q) PvR©Ø‡qi ga¨ewZ© `~iZ¡ (2L) = 3.2 10–9 3 10–19 STEP 02 ANALYSIS OF HSC BOARD QUESTION DÏxcKwU co Ges 01 I 02 bs cÖ‡kœi DËi `vI: GKwU Zwor w؇giæi PvR©Ø‡qi ga¨eZ©x `~iZ¡ 3 10–10cm Ges w؇giæi j¤^ wØLÛ‡Ki Dci w؇giæi †K›`ª n‡Z 3cm `~‡i evqy gva¨‡g Zwor‡ÿ‡Îi cÖvej¨ 3 10–6NC–1 | 01. DÏxc‡K DwjøwLZ Zwor w؇giæi Pv‡R©i cwigvY KZ? [iv.†ev., h.†ev.2017] A. 9 10–9C B. 4.5 10–6C C. 3 10–9C D. 1.5 10–9C S C info q = Er3 9 109 21 = 3 10–6 (3 10–2 ) 3 9 109 3 10–12 = 3 10–9C 02. D‡jøwLZ Zwor wØ-†giæi †K›`ª n‡Z Aÿ eivei 3cm `~‡i evqy gva¨‡g Zwor‡ÿ‡Îi cÖvej¨ c~‡e©Kvi ZzjbvqÑ [iv. †ev., h.†ev.2017] A. wظY B. mgvb C. A‡a©K D. GK-PZz_©vsk S A info E = 9 109 4lq r 3 = 9 109 2 3 10–12 3 10–9 (3 10–2 ) 3 = 6 10–6 NC–1 03. GKwU Zwor w؇giæi PvR© `ywUi cwigvY KZ n‡e? [P. †ev. 2015] A. 2 1019C I 8 1019C B. 2 1019C I 4 1019C C. 5 1019C I 5 1019C D. 2 1019C I 7 1019C Ans C Concept 6 aviK I avi‡Ki mgevq msµvšÍ FORMULA 01. aviKZ¡, C = Q V = V It 02. K civ‣e`y¨wZK wewkó mgvšÍivj cvZ avi‡Ki aviKZ¡: d K A C 0 03. †MvjKxq cwievnxi aviKZ¡: C=4Kr 04. wmwiR/†kªYx mgev‡q Zyj¨ aviKZ¡ Cs C C C Cn 1 1 1 1 1 1 2 3 05. mgvšÍivj mgev‡q Zzj¨ aviKZ¡: Cp = C1+C2+C3 + ------ + Cn ASPECT SPECIAL: avi‡Ki msL¨v n, avi‡Ki aviKZ¡ = C, mggv‡bi n msL¨K aviK‡K mgvšÍiv‡j hy³ Ki‡j Zzj¨ aviKZ¡ Cp = n.C mggv‡bi n msL¨K aviK‡K †kªYx‡Z hy³ Ki‡j Zzj¨ aviKZ¡ Cs = n C mgvšÍiv‡j Zzj¨ aviKZ¡ †kªYx‡Z Zzj¨ aviK‡Z¡i n 2 ¸Y| A_©vr Cp:Cs = n :1 2 aviK‡Z¡i mgevq ¸‡jv ‡iv‡ai mgev‡qi Dëv Model Example01 mgvb aviK‡Z¡i `ywU avi‡Ki mgvšÍivj ms‡hvRbx‡Z _vKvKvjxb aviKZ¡, †kÖYxe× fv‡e _vKvKvjxb aviK‡Z¡i KZ ¸Y| General Rules [Written] 3 in 1 Shortcut Tricks & Tips [MCQ] 1 Cs = 1 C1 + 1 C2 1 Cs = 1 C + 1 C 1 Cs = 1 + 1 C 1 Cs = 2 C = Cs = C 2 ..................(i) Avevi, Cp = C1 + C2 Cp = C + C Cp = 2C ...................(ii) (ii) (i) ; Cp Cs = 2C C 2 = 2C 2 C Cp Cs = 4 Cp = 4Cs mgvb aviK‡Z¡i n msL¨K avi‡Ki †¶‡Î, Cp Cs = n2 = 22 = 4 ¸Y CONCEPTUAL MATH MEx 01 20F aviK‡Z¡i GKwU aviK‡K 10 mA Zwor cÖevn Øviv AvwnZ Kiv nj| avi‡Ki cvZ؇qi g‡a¨ 30V wefe cv_©K¨ Drcbœ Ki‡Z KZ mgq Zwor cÖevwnZ Ki‡Z n‡e? q =It = CV or, t = CV I = (20 10–6 ) 30 10 10–3 mgq, t = 0.06 s MEx 02 100V Gi GKwU e¨vUvixi `yB cÖv‡šÍi mv‡_ 4 F I 8 F Gi `yBwU aviK mgvšÍiv‡j hy³ Av‡Q| cÖ‡Z¨KwU avi‡Ki PvR© KZ? q1 = C1V = 4 10–6 100 = 4 10–4 C; q2 = C2V = 8 10–6 100 = 8 10–4 C MEx 03 GKwU mgvšÍivj cvZavi‡Ki cvZØq ci¯úi n‡Z 0.01m `~‡i Aew¯’Z| hw` cvZ `yÕwUi wefe cv_©K¨ 66V nq Ges cÖ‡Z¨KwU cv‡Zi Pv‡R©i cwigvY 5.8710–8C nq, Z‡e cv‡Zi †¶Îdj KZ? mgvšÍivj cv‡Zi †¶‡Î, C = 0A d = q V †¶Îdj, A = dq 0V = 0.01 5.87 10–8 8.854 10–12 66 = 1m2 MEx 04 GKwU mgvšÍivj cvZ avi‡Ki cvZ`ywU e„ËvKvi| cvZ `ywUi cÖ‡Z¨KwUi e¨vmva© 810–2 m Ges Zv‡`i ga¨eZx© `~iZ¡ 210–3 m| aviKwU‡Z 100V wefe cÖ‡qvM Ki‡j Gi `ywU cv‡Z wK cwigvY PvR© Rgv n‡e wbY©q Ki| q = CV = 0A d V = 0r 2 d V = 8.85 10–12 3.14 (8 10–2 ) 2 2 10–3 100 = 8.89 10–9 C MEx 05 GKwU mgvšÍivj cv‡Z avi‡Ki cvZ؇qi ga¨eZ©x `~iZ¡ A‡a©K n«vm I cvZ؇qi †¶Îdj wظb e„w× Ki‡j avi‡Ki aviKZ¡ KZ¸b e„w× cv‡eC2 C1 = A2 A1 × d1 d2 = 2 1 × 2 1 = 4
456 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES MEx 06 3F, 4F I 5F aviKZ¡ wewkó wZbwU aviK‡K †kÖYx mgev‡q I mgvšÍivj mgev‡q mvRv‡bvi ci Dfq mgevq‡K Avevi †kÖYx‡Z ivL‡j Zzj¨ aviKZ¡ KZ n‡e? †kÖYx mgev‡qi †¶‡Î C (C C C ) (3 4 5 ) 1.277 F 1 1 1 1 1 1 3 1 2 1 s 1 ; mgvšÍivj mgev‡qi †¶‡Î, Cp C1 C2 C3 3 4 5 12F ; Zzj¨ aviKZ¡, (C C ) 1.277 (12) 1.154 1 1 1 1 1 p 1 s F MEx 07 5FGi 5wU aviK wmwiR ms‡hv‡M hy³ Kiv n‡jv| H aviK¸‡jvi mgZzj¨ aviKZ¡ n‡jvavi‡Ki msL¨v n = 5, cÖwZwU avi‡Ki aviKZ¡ c = 5 wmwiR ms‡hv‡M Zzj¨ aviZ¡ Cs = F n C 1 5 5 NOW START PRACTICE 01. GKwU mgvšÍivj cvZ avi‡Ki cvZ `ywUi ga¨eZx© `~iZ¡ 10–3 m| GB avi‡Ki aviKZ¡ 1F n‡Z n‡j cv‡Zi †¶Îdj KZ n‡Z cv‡i? 02. c„w_exi e¨vmva© 6.38 6 10 m n‡j, c„w_exi aviKZ¡ KZ? 03. wZbwU avi‡Ki aviKZ¡ h_vµ‡g 2, 3 Ges 6F| †kÖYxe×fv‡e G‡`i ms‡hvRb Ki‡j aviKZ¡ KZ n‡e? 04. wZbwU avi‡Ki aviKZ¡ h_vµ‡g 3, 4 Ges 2F; G‡`i cÖ_g I wØZxqwU mvwi‡Z †i‡L Z…ZxqwUi mv‡_ G‡`i mgvšÍiv‡j hy³ Kiv nj| Zzj¨ aviKZ¡ wbY©q Ki? 05. mgvb aviK‡Z¡i wZbwU aviK‡K mgvšÍivj mgev‡q hy³ K‡i 30V wefe cv_©K¨ cÖ‡qvM Kiv nj| mgev‡q †gvU Pv‡R©i cwigvY 90C n‡j cÖwZwU avi‡Ki aviKZ¡ KZ? aviK¸‡jv‡K †kÖYx mgev‡q hy³ Ki‡j †gvU PvR© KZ n‡e? 06. cv‡ki Qwe‡Z †`Lv‡bv aviK¸‡jvi aviKZ¡ C n‡j †gvU aviKZ¡ KZ? 07. mgvb aviK‡Z¡i wZbwU avi‡Ki mgvšÍivj ms‡hvRbx‡Z _vKvKvjxb aviKZ¡, †kÖYxe× fv‡e _vKvKvjxb aviK‡Z¡i KZ ¸Y| NOW PRACTICE SOLVE : 01. mgvšÍivj cv‡Zi †¶‡Î, d A C 0 †¶Îdj, 8 2 1 2 3 0 1.13 10 m 8.854 10 Cd 1 10 A 02. †Mvj‡Ki †¶‡Î, C = 4 r 0 = 4 6.38 10 7.099 10 F 6 4 0 03. †kÖYx mgev‡qi †¶‡Î Zzj¨ aviKZ¡, C (C C C ) (2 3 6 ) 1 F 1 1 1 1 1 1 3 1 2 1 s 1 04. †kÖYx mgev‡q Zzj¨ aviKZ¡ = Cs ; 1 1 2 1 CS C1 C (3 -1+4 -1 ) -1 Cs 1.71F †klwU mgvšÍivj ms‡hvRbx, G‡¶‡Î Zzj¨ aviKZ¡, C C C 1.71 2 p s 3 Cp = 3.71 F 05. Cp=3C ; Cp= V q 3C = 30 90 C=1F, again, F; 3 1 n C Cs q' = CsV= 30 10 3 1 C 06. †gvU aviKZ¡ Cs C C 3C 1 1 3 1 1 ev, Cs 3C 1 1 3 1 ev, Cs 3C 1 5 ev, Cs C 5 3 07. mgvb aviK‡Z¡i n msL¨K avi‡Ki †¶‡Î, Cp Cs = n2 = 32 = 9 ¸Y REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. 5FGi 5 wU aviK wmwiR ms‡hv‡M hy³ Kiv n‡jv| H aviK¸‡jvi mgZzj¨ aviKZ¡ n‡jv- [DU. 2014-15] A. 5 F B. 4 F C. 1 F D. 10 F avi‡Ki msL¨v n = 5, cÖwZwU avi‡Ki aviKZ¡ c = 5 wmwiR ms‡hv‡M Zzj¨ aviZ¡ Cs = C n = 5 5 = 1F 02. 4F Gi 4wU aviK wmwi‡R ms‡hvM Kiv nj| Zv‡`i mgZyj¨ aviKZ¡ n‡”Q- [DU. 2010-11] A. 1 F B. 2 F C. 4 F D. 16 F †kÖYx mgev‡qi †¶‡Î, 1 1 4 1 3 1 2 1 1 ( ) Cs C C C C (4 4 4 4 ) 1F 1 1 1 1 1 03. GKwU mgvšÍivj †cøU K¨vcvwmU‡ii †cø‡Ui †¶Îdj 2m2 | †cøU `yBwUi g‡a¨ civ‣e`y¨wZK e¯‘ cÖ‡ek Kiv‡bv nj hvi Av‡cw¶K cviwgwUwfwU 6| GLb aviKZ¡ c~‡e©i Zzjbvq KZ¸b n‡e? [DU. 2004-05] A. 6 B. 1 6 C. 12 D. 3 mgvšÍivj cv‡Zi †¶‡Î, C1= 0A d , C2 = K0A d = 60A d C2 = 6C1 04. GKwU mgvšÍivj cvZ avi‡Ki cÖ‡Z¨K cv‡Zi †¶Îdj 0.01m2 | cvZ `ywUi g‡a¨ KZ cyiæ‡Z¡i Aå cvZ (k=6) cÖ‡ek Kiv‡j aviKwUi aviKZ¡ 1m e¨vmva© wewkó GKwU †MvjKxq cwievnxi aviK‡Z¡i mgvb n‡e? [DU. 2005-06] A. 510–3 m B. 4.810–3 m C. 4.710–3 m D. 4.7710–3 m 0 KA d 40 r d = KA 4r = 6 0.01 4 3.14 = 4.7710–3 m 05. `ywU mgvb aviK‡Z¡i aviK‡K cÖ_‡g †kªYx‡Z I c‡i mgvšÍiv‡j mshy³ Kiv nj| †kªYx I mgvšÍivj ms‡hv‡M Zzj¨ aviK‡Z¡i AbycvZ| [DU. 2007-08, ComU: 2009-10, HSTU: 2015-16, BSMRSTU: 2014-15] A. 1 : 1 B. 4 : 1 C. 1 : 2 D. 1 : 4 Cs : Cp=1 : n2 =1 : (2)2 = 1 : 4 06. GKwU e„ËvKvi c„ôZj wewkó mgvšÍivj cvZ avi‡Ki c„ôZ‡ji e¨vm I cvZ `ywUi g‡a¨ `~iZ¡ `ywU‡KB wظY Kiv nj| aviKwUi bZzb aviKZ¡ c~‡e©i Zzjbvq: [DU. 2009-10] A. GKB _vK‡e B. Pvi¸b n‡e C. wظb n‡e D. A‡a©K n‡e S C info C = 0A d = 0D 2 d C D 2 d ; Cnew Cold = D2 2 D1 2 d1 d2 = 4 1 1 2 wظY n‡e C C C C C C C
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 457 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 07. 1F, 2F Ges 4F aviKZ¡ wewkó wZbwU aviK‡K †kªYx mgev‡q ms‡hvM †`qv n‡jv| G‡`i mgZzj¨ aviKZ¡ n‡e- [DU. 2009-10] A. 7F B. 2.63F C. 1.75F D. 0.57 F C1 = 1F, C2 = 2F and C3 = 4F †kªYx mgev‡q G‡`i mgZyj¨ aviKZ¡: Cs= (1-1 +2-1 +4-1 ) –1 = 0.57 F 08. GKwU mgvšÍivj cvZ avi‡Ki cvZ؇qi ga¨eZx© ¯’vb evqyi (k = 1) cwie‡Z© (k = 20) WvB B‡jKwUªK aªæe‡Ki c`v_© Øviv c~iY Kiv n‡jv| wKš‘ `yB cv‡Z GKB Avavb ivLv n‡jt [DU. 2006-07] A. ïay wefe cv_©K¨ (cvZ؇qi) cwiewZ©Z n‡e B. ïay aviKZ¡ cwiewZ©Z n‡e C. DfqB cwiewZ©Z n‡e D. aviKZ¡ I wefe cv_©K¨ GKB _vK‡e k Gi gvb cwieZ©b Ki‡j WvB B‡jKwUªK c`v_© wecixZ w`‡K Zwor †¶Î cÖ‡qvM K‡i| myZivs wefe K‡g hvq| C = 0KA d E E †m‡¶‡Î, C †e‡o hvq| aviKZ¡ I wefe cv_©K¨ DfqB cwiewZ©Z n‡e| 09. K‡qKwU aviK †kªYx mgev‡q mshy³ Ki‡j- [DU: 2002-03] A. cÖ‡Z¨KwUi wefe cv_©K¨ mgvb B. cÖ‡Z¨KwUi PvR© mgvb C. jwä aviKZ¡ me¸‡jv avi‡Ki mgwói †_‡K eo D.jwä aviKZ¡ me¸‡jv avi‡Ki mgwói †_‡K †QvU Ans B 10. 2 gvB‡µv d¨vivW, 3 gvB‡µv d¨vivW Ges 4 gvB‡µv d¨vivW gv‡bi wZbwU aviK mgvšÍ ivj mgev‡q hy³| G‡`i Z‚j¨ aviKZ¡ n‡e- [DU. 2000-01] A. 1.08 F B. 0.92 F C. 4.5 F D. 9 F mgvšÍivj mgev‡q Z‚j¨ aviKZ Cp = C1 + C2 + C3 = 2 + 3 + 4 = 9 F STEP 02 ANALYSIS OF JU QUESTION 01. wZbwU avi‡Ki aviKZ¡ h_vµ‡g 1, 2 I 3F †kÖYxe× web¨v‡m Gi Zzj¨ aviKZ¡ KZ? [JU. 2014-15] A. 6 F B. 6 11 F C. 11 6 F D. 1 6 F †kÖYx mgev‡qi †¶‡Î, Cmin = Cs = (C1 –1 + C2 –1 + C3 –1 ) –1 = (1 –1 + 2 –1 + 3 –1 ) –1 = 6 11 F 02. †MvjvKvi avi‡Ki aviKZ¡ Zvi e¨vmv‡a©i [JU. 2010 -11] A. e¨¯ÍvbycvwZK B. e‡M©i e¨v¯ÍvbycvwZK C. mgvbycvwZK D. eM©g~‡ji mgvbycvwZK Avgiv Rvwb, C = 40 r; C r ,aviKZ¡ e¨vmv‡a©i mgvbycvwZK| 03. GKwU †MvjvKvi avZe cwievnxi e¨vmva© 12cm n‡j 1.2 Zwor gva¨gvsK wewkó gva¨‡g Gi aviKZ¡ KZ? [JU. 2012-13, 15-16] A. C = 16×10-12F B. C = 6×10-12F C. C = 16×10-6 F D. 0.3 C = 4rk = rk 9 109 = 0.12 1.2 9 109 = 16 × 10-12F 04. 16F I 22F aviKZ¡ wewkó `ywU aviK‡Ki †kªbx mgev‡q mvR‡j Zzj¨ aviKZ¡ KZ? [JU. 2011-12] A. 92.6F B. 9.26F C. 8.62F D. 12.98F Cs = {(16)-1 + (22)-1 } -1 = 9.26F 05. `ywU aviK‡K †kªbx mgev‡q hy³ Ki‡j Zzj¨ aviKZ¡ 2.4F GKwU avi‡Ki aviKZ¡ 4F n‡j Ab¨wUi aviKZ¡ KZ? [JU. 2011-12] A. 3F B. 4F C. 2F D. 6F 1 cs = 1 4 + 1 q ev, 1 2.4 = 1 4 + 1 q ev, q = 6F 06. `ywU aviK‡K †kªbx I mgvšÍivj mgev‡q hy³ Ki‡j aviKZ¡ h_vµ‡g 2F I 9F nq| aviK `ywUi aviKZ¡ n‡e? [JU. 2013-14] A. 2F Ges 3F B. 3F Ges 4F C. 2F Ges 9F D. 3F Ges 6F From D option, Cp = C1 + C2 = 3 + 6 = 9F 07. GKwU AšÍixZ cwievnx‡Z 10 Kzj¤^ PvR© cÖ`vb Kivq Gi wefe 2V n‡jv| cwievnxi aviKZ¡ KZ n‡e? [JU. 2014–15] A. 5F B. 1 5 F C. 20F D. 1 20 F Q = CV ev, C = Q v = 10 2 = 5F STEP 03 ANALYSIS OF RU QUESTION 01. aviK¸‡jvi cÖ‡Z¨KwUi aviKZ¡ 100F n‡j, cy‡iv m¾vi Zzj¨ aviKZ¡ KZ?\ [RU. Astrazeneca, Set-1. 20-21] A. 100F B. 700F C. 220F D. 45.45 F avi‡Ki mgevqwUi Zzj¨ aviKZ¡ = 100 + 100 5 + 100 = 220F 02. GKwU mgvšÍivj cvZ aviK n msL¨K mgZj mgvšÍivj avZe cvZ w`‡q •Zix| Gi cvZ¸‡jv mgvb `~i‡Z¡ Aew¯’Z| cvkvcvwk `ywU cv‡Zi aviKZ¡ C n‡j G‡`i mgZzj¨ aviKZ¡ KZ n‡e? [RU-C, Set-1. 19-20] A. n(n + 1)C B. (n 1)C C. C/n D. nC mggv‡bi n msL¨K aviK, ● †kÖwY mgev‡q hy³ _vK‡j, Cs = C n ● mgvšÍivj mgev‡q hy³ _vK‡j, Cp = n C 03. †Kvb cwievn‡Ki wefi 1V evov‡Z hw` 1C Avav‡bi cÖ‡qvRb nq, Zvn‡j H cwievn‡Ki aviKZ¡- [RU. 2016–17] A. 1F B. 1mF C.1F D. †KvbwUB bq cwievn‡Ki aviKZ¡, C = q V = 1 1 = 1F 04. GKwU cwievn‡Ki aviKZ¡ 40 F| G‡Z KZ Avavb cÖ`vb Ki‡j Gi wefe 8 V n‡e- [RU. 2015-16] A. 5 C B. 320 C C. 160 C D. 240 C Q = CV = 40×8 =320 C 05. mgvb aviK‡Z¡i wZbwU aviK cÖ_‡g †kªYx‡Z Ges c‡i mgvšÍivj mgev‡q hy³ Kiv n‡jv| G `yÕ‡¶‡Îi Zzj¨ aviKZ¡ Gi AbycvZ KZ? [RU. 2015–16] A. 1:4 B. 1:6 C. 1:9 D. 1:12 S C info Cs :Cp = 1:n2 = 1:32 = 1:9 06. 2,3 I 6 F aviK‡Z¡i aviK †kªYxe×fv‡e mvRv‡bvi ci 10V e¨vUvwii m‡½ ms‡hvM †`qv n‡j eZ©bx‡Z Pv‡R©i cwigvb KZ n‡e ? [RU. 2014–15] A. 1.010-5C B. 2.010-5C C. 3.010-5C D. 6.010-5C S A info Cs = (2–1 + 3–1 + 6–1 ) –1 10–6 = 1 10–6 v = 10volt, C = Q/v ev, Q = CV = 10 10–6 = 10–5 07. GKwU mgvšÍivj cvZ avi‡Ki ga¨eZ©x `~iZ¡ I cvZ؇qi †¶Îdj `yB ¸Y e„w× Ki‡j aviKZ¡ wK n‡e? [RU. 2013-14] A. 2 ¸Y evo‡e B. 2 ¸Y Kg‡e C. 4 ¸Y evo‡e D. AcwiewZ©Z _vK‡e C = kA d C2 C1 = d1 A2 d2 A1 = 1 2 2 1 = 1 08. 3F I 4F Gi `yBwU aviK‡K mvwi‡Z †i‡L 3q GKwU avi‡Ki mv‡_ mgvšÍiv‡j hy³ Ki‡j Zzj¨ aviKZ¡ 3.7F nq, Z‡e 3q avi‡Ki gvb? [RU. 2009-10] A. 2.5F B. 1F C. 5F D. 2F Cs =(3-1 +4-1 ) -1 = 1.7143; C3 = 3.7-1.7143 = 1.985 = 2F STEP 04 ANALYSIS OF CU QUESTION 01. 1F aviK‡Z¡i †Kvb aviK 100V wewkwó †Kvb we`y¨r Dr‡mi mv‡_ mshy³ Ki‡j avi‡K mwÂZ Avavb KZ Kzj¤^ n‡e? [CU. 2014-15] A. 10-4 B. 10-3 C. 10-2 D. 10-1 E. None Q = CV = 1 10–6 100 = 10–4 c
458 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 02. 3F I 6F aviKZ¡ wewkó `ywU aviK‡K †kªbx mgev‡q mvRv‡j Zzj¨ aviK‡Z¡i gvb KZ? [CU. 2010-11] A. 2 F B. 3F C. 4F D. 9F E. 18F CS = (3-1 + 6–1 ) –1 = 2F 03. 6F I 12F aviK‡Z¡i `ywU aviK †kªbxe×fv‡e mshy³ Ki‡j Zzj¨ aviKZ¡ n‡e? [CU. 2004-05] A. 1 4 F B. 1F C. 4F D. 18F Cs = (6-1 +12-1 ) -1 = 4F 04. wZbwU avi‡Ki aviKZ¡ 2F, 4F Ges 8F G‡`i‡K †kªbx‡Z hy³ Ki‡j Zzj¨ aviKZ¡ n‡e? [CU. 2008-09] A. 8 7 F B. 7 8 F C. 1F D. 10F E. 14F Cs = (2-1 +4-1 +8-1 ) -1 = 8 7 STEP 05 ANALYSIS OF DU-7 Clg QUESTION 01. GKK aviK‡Z¡i `ywU aviK †kÖYxe× fv‡e mshy³ Ki‡j Zzj¨ aviKZ¡ KZ n‡e? [DU-7Clg.A.19-20] A. 2F B. 1F C. 0.5F D. 1.5F Cs = C n = 1 2 = 0.5 F STEP 06 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. wZbwU avi‡Ki aviKZ¡ h_vµ‡g 3F, 4F Ges 5F G‡`i mgvšÍivj hy³ Ki‡j Zzj¨ aviKZ¡ KZ n‡e- [JnU. 2009-10] A. 12F B. 1.2F C. 60F D. 7F mgvšÍivj Zzj¨ aviKZ¡ Cp = C1+ C2+ C3 = 3F + 4F + 5F = 12F 02. `yÕwU 2 F aviK‡K wmwi‡R mshy³ Kivi d‡j mgZzj¨ avi‡Ki aviKZ¡ n‡eÑ [JnU. 2007-08] A. 4 F B. 1 F C. 0.5 F D. 2 F Cs = C n = 2 2 = 1F 03. evqy fwZ© `ywU mgvšÍivj cvZ avi‡Ki cvZ؇qi ga¨eZx© `~iZ¡ 0.1 c.m. GB mgvšÍivj cvZ avi‡Ki aviKZ¡ 1.F n‡j cÖ‡Z¨KwU cv‡Zi †¶Îdj KZ? [JnU. 2006-07] A. 1.13108m 2 B. 2104m 2 C. 1108m 2 D. 1.131010m 2 Avgiv Rvwb, C = 0A d ev, A = C d 0 = 1 0.1 10–2 8.85 10–12 = 1.13 108 m 2 KU 01. `ywU aviK‡K mgvšÍivjfv‡e hy³ Ki‡j Z‚j¨ aviKZ¡ 5 F Ges †kÖwY‡Z hy³ Ki‡j Zzj¨ aviKZ¡ 1.2 F nq| aviK `ywUi aviKZ¡ KZ d¨viv‡W? [KU. 2017-18] A. 1; 4 B. 1; 0.2 C. 3; 2 D. 0.8; 0.4 x 2 – eo x + eo †QvU = 0; x 2 – 5x +5 1.2 = 0; x = 3F, 2F 02. GKwU mvgvšÍivj cvZ avi‡Ki cÖ‡Z¨K cv‡Zi †¶Îdj 1m2 Ges Gi gv‡S 1mm cyiæ evqyi ¯Íi _vK‡j Gi aviKZ¡ n‡e- [KU. 2010-11] A. 8.85410-10F B. 8.85410-12F C. 4.85410-9 F D. 4.85410-12F 3 12 0 10 8.854 10 1 d A C F 9 8.854 10 IU 01. mgvb aviK‡Z¡i 3 wU avi‡Ki mgvšÍivj mgev‡qi mgZyj aviKZ¡ Zv‡`i †kÖYx mgev‡qi mgZyj aviK‡Z¡i KZ ¸Y? [IU. 2010 -11] A. 9 ¸Y B. 3 ¸Y C. 27 ¸Y D. 1/9 ¸Y mgvb aviK‡Z¡i n msL¨K avi‡Ki †¶‡Î, S 2 CP n C =3 2 = 9¸Y BRUR 01. wZbwU avi‡Ki aviKZ¡ h_vµ‡g 1, 2 Ges 3F, G‡`i‡K cÖ_‡g †kÖYx‡Z I c‡i mgvšÍivj mgev‡q hy³ Kiv n‡j, G `y‡ÿ‡Îi Zzj¨ aviK‡Z¡i AbycvZ KZ? [CoU. 2018-19] A. 11: 2 B. 1 : 11 C. 2 : 11 D 3 : 11 Cs = 1 1 + 1 2 + 1 3 1 = 6 + 3 + 2 6 1 = 6 11 Cs : CP = 1 :11 PART B Analysis of Science & Technology Question SUST 01. GKwU mgvšÍivj cvZ avi‡Ki cÖ‡Z¨K cv‡Zi †¶Îdj 1.5106 mm2 Ges cvZ؇qi ga¨eZx© `~iZ¡ 2 mm| hw` wefe cv_©K¨ 60 V nq Z‡e cÖ‡Z¨K cv‡Zi PvR© KZ? (0 = 8.85410–12 F/m) [SUST:2016–17] A. 1.5610–9 B. 3.9810–7 C. 4.8210–9 D. 5.1510–9 E. 6.6410–9 mgvšÍivj cv‡Zi †¶‡Î, C = d 0 A V q ; 3 12 0 2 10 8.854 10 1.5 60 d A V q 3.9810–7C 02. wb‡Pi Qwe‡Z cÖ‡Z¨KwU aviK (Capacitor) Gi mgvb n‡j A we›`y‡Z wefe KZ? [SUST: 2011-12] A 90V A. 0V B. 30V C. 40V D. 60V E. 75V Zzj¨ aviKZ¡ = C1+C2; CP = C + C =2C Zzj¨ aviKZ¡ = 1 1 1 1 1 Cs C C = C 2C 1 1 = 2C 3 ev, 3 2C Cs A we›`y‡Z wefe VA = 2 60 3 90 03. cv‡k¦©i Qwe‡Z †`Lv‡bv Dcv‡q Amxg msL¨K aviK mvRv‡bv Av‡Q| cÖwZwU avi‡Ki gvb F n‡j †gvU aviK KZ? [SUST: 2009-10] A. 1.6 F B. 1.0 F C. 0.5 F D. 0.0 F †gvU aviKZ¡ 1.6 F 04. cv‡ki Qwe‡Z cÖ‡Z¨KwU avi‡Ki gvb F n‡j †gvU aviKZ¡ KZ? [SUST: 2007-08] F F F F F A. F 4 B. F 2 C. F D. 2 F †gvU aviKZ¡ C F F F F F 1 1 1 1 ev, C F F 2F 1 1 2 1 1 2F 1 2 1 ev, C 2F 1 4 ev, 4 2F C ev, 2 F C
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 459 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES JUST 01. hw` c1 = c2 = c nq Zvn‡j †Kvb m¤úK©wU mwVK? [JUST-C, 19-20] A. cp = 2cs B. cs = 2cp C. 4cp = cs D. cp = 4cs Cp = C1 + C2 = 2C; 1 Cs = 1 C1 + 1 C2 = 1 C + 1 C = 2 C Cp × 1 Cs = 2C × 2 C = 4 Cp = 4Cs . 02. GKwU aviK cÖwZ †m‡K‡Û Zvi A‡a©K PvR© wejyß K‡i| hw` 5 †m‡KÛ ci Zvi PvR© q nq Zvn‡j Zvi cÖv_wgK PvR© KZ wQj? [JUST-A, Set-Ka 19-20] A. 4q B. 8q C. 16q D. 32q T1/2 = 1sec = 0.693 T1/2 = 0.693 GLb N = N0e –t N0 = N e –t = q e –0.693 5 = 32q MBSTU 01. wZbwU avi‡Ki aviKZ¡ h_vµ‡g 2, 3 Ges 4F| G‡`i‡K cÖ_‡g †kªwY‡Z I c‡i mgvšÍivj mgev‡q mshy³ Kiv n‡jv| GB `yB †¶‡Îi Zzj¨ aviK‡Z¡i Zzjbv Ki| [MBSTU: 2014-15] A. 4:39 B. 3:39 C. 39:5 D. 2:40 CS = (2–1 + 3–1 + 4–1 ) –1 = 12 13 Cp = 2 + 3 + 4 = 9, Cs : Cp = 12 13 9 = 4:39 BSMRSTU 01. `ywU aviK‡K mgvšÍivj I †kÖwY‡Z hy³ Ki‡j Zzj¨ aviKZ¡ h_vµ‡g 9F I 2F nq aviK `ywUi aviKZ¡ KZ? [BSMRSTU-B, 19-20, DU-Tech. 2020-21] A. 3F I 2F B. 4F I 3F C. 5F I 2F D. 6F I 3F CP = aviK؇qi †hvMdj = 9; Cs = aviK؇qi ¸Ydj aviK؇qi †hvMdj = 2 Cp = 6 + 3 = 9; Cs = 6 3 6 + 3 = 2 NSTU 01. wZbwU avi‡Ki aviKZ¡ h_vµ‡g 3F, 2F Ges 1F| G‡`i wØZxq I Z…ZxqwU‡K †kÖwYe×fv‡e mvwR‡q cÖ_gwUi mv‡_ mgvšÍiv‡j hy³ Kiv n‡j Zzj¨ aviKZ¡ KZ? [NSTU: 2014–15] A. 5.6F B. 4.5F C. 3.67F D. 6.5F C = 3 + (2–1 + 1–1 ) –1 = 3.67 F PSTU 01. 1 pF=? [PUST: 2013-14] A. 10-9 F B. 10-15F C. 10-12F D. 10-6 F 1 pF = 10–12F STEP 07 ANALYSIS OF ENGINEERING & BUTex QUESTION BUET 01. evqyc~Y© mgvšÍivj cvZ avi‡Ki aviKZ¡ 1PF cv‡Zi ga¨eZ©x `~iZ¡ wظb K‡i cvZ `ywUi ga¨eZ©x ¯’vb m¤ú~Y©iƒ‡c †gvg civ gva¨g w`‡q c~Y© Kiv nj| d‡j aviKZ¡ 2PF nq| †gv‡gi WvBB‡jKwUªK aªæe nq- [BUET: 2008-09] A. 0.25 B. 0.50 C. 2.0 D. 4.0 cm c0 = d0 dm ev, 1 2 = k 1 2 ev, k = 4 02. mgvšÍivj cvZ avi‡Ki `yB cv‡Zi g‡a¨ WvBB‡jKwUªK Øviv c~Y© Kivq aviKZ¡ 5µF †_‡K †e‡o 60µF nq| WvBB‡jKwUªK (civ‣e`y¨wZA. aªæe‡Ki gvb n‡e- [BUET: 2013-14] A. 65 B. 55 C. 12 D. 10 C0 Cm = 1 k ev, k = Cm C0 = 60 5 = 12 KUET 01. GKwU mgvšÍivj cvZ avi‡Ki cvZ `ywU e„ËvKvq| cvZ `ywUi cÖ‡Z¨KwUi e¨vmva© 810-2m Ges Zv‡`i ga¨eZ©x `~iZ¡ 210-3 aviKwU‡Z 100v wefe cÖ‡qvM Ki‡j cvZ `ywU‡Z wK cwigvb PvR© Rgv n‡e wbY©q Ki? [KUET: 2010-11] A. 8.910-3C B. 8.910-9C C. 6.910-3C D. 9.810-6C Q = 0A D V = 3 12 2 2 2 10 8.85 10 (8 10 ) 100 = 8.8910-9 C 02. wZbwU avi‡Ki †kªbxe× web¨v‡mi †gvU aviKZ¡ 1F `yBwU avi‡Ki gvb h_vµ‡g 2, 3 F n‡j Z…ZxqwUi gvb KZ? [KUET: 2011-12, RU. 17-18] A. 7F B. 6F C. 8F D. F E. 5F 1 cs = 1 c1 + 1 c2 + 1 c3 ev, 1 1 = 1 2 + 1 3 + 1 c3 ev, C3 = 6F 03. GKwU mgvšÍivj cvZ avi‡Ki cÖwZwU cv‡Zi c„ó‡¶Îdj 1.4m2 Ges evqy gva¨‡g cvZ؇qi ga¨eZx© `~iZ¡ 3cm| Bnvi aviKZ¡ wbY©q Ki| [KUET: 2013-14, JU. 18-19] A. 4.110-6 F B. 4.13210-4 F C. 410-4 F D. 6.4210-4 F E. 4.410-6 F C = 0A d = 8.85 10–12 1.4 0.03 = 4.1310-10F = 4.1310-4 F STEP 08 ANALYSIS OF HSC BOARD QUESTION 01. C C C C X Y wP‡Îi XV Gi ga¨Kvi Zzj¨ aviKZ¡ KZ? [iv. †ev. 2016] A. C 5 B. 5 C C. 5C D. C X I Y Gi g‡a¨ C gv‡bi cuvPwU aviK †kÖwY‡Z hy³ Av‡Q| Zzj¨ aviKZ¡, 1 Cs = 1 C + 1 C + 1 C + 1 C + 1 C ; Cs = C 5 02. C3 C2 C1 C1 = C2 = C3 = 2F ms‡hvMwUi †gvU aviKZ¡ KZ? [Pv. †ev. 2015] A. 2.25F B. 2.00F C. 1.75F D. 1.33F Cp = C2 + C3 = 2 + 2 = 4F; 1 Cs = 1 C1 + 1 Cp = 1 2 + 1 4 Cs = 1.33F 03. 3F 1F 2F DÏxc‡Ki eZ©bxi Zzj¨ aviKZ¡ KZ? [P. †ev. 2017] A. 6.0 F B. 4.5 F C. 1.5 F D. 0.67 F 2F I 2F aviKØq mgvšÍiv‡j hy³, G‡`i Zzj¨ aviKZ¡, CP = (2 + 1)F = 3F| CP I 3F †kÖwY‡Z hy³ Kivq eZ©bxi Zzj¨ aviKZ¡, 1 C = 1 3 + 1 3 = 2 3 C = 3 2 F = 1.5F
460 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES wb‡Pi DÏxc‡Ki Av‡jv‡K 04 I 05 cÖ‡kœi DËi `vI: C1= 400 F C2= 600 F E=150V + – 04. eZ©bxwUi Zzj¨ aviKZ¡ KZ? [P. †ev. 2015] A. 2.4 10–10F B. 1 10–9 F C. 2.4 10–19 F D. 1 10–9 F Cp = C1 + C2 = (400 + 600) 10–12F = 1 10–9 F 05. aviK `ywU‡Z Pv‡R©i AbycvZ KZ? [P. †ev. 2015] A. 15 : 1 B. 1 : 15 C. 2 : 3 D. 16 : 36 Q1 = C1V ; Q2 = C2V Q1 : Q2 = C1 : C2 = 400 : 600 = 2 : 3 DÏxcKwU co Ges 06 I 07 bs cÖ‡kœi DËi `vI: GKwU mgvšÍivj cvZ avi‡Ki cÖ‡Z¨K cv‡Zi †ÿÎdj 1.5m2 Ges Gi gv‡S 1 mm cyiæ evqy¯Íi i‡q‡Q| 06. avi‡Ki aviKZ¡ KZ n‡e? [h. †ev. 2017] A. 3.27 10–8 F B. 1.327 10–8 F C. 0.327 10–8 F D. 1.327 108 F C = 0A d = 8.85 10–12 1.5 1 10–3 = 1.327 10–8 F 07. aviKwUi aviKZ¡ e„w×i Rb¨ cvZ `ywU‡KÑ [h. †ev. 2017] i. `~‡i miv‡Z n‡e ii. KvQvKvwQ Avb‡Z n‡e iii. eo Ki‡Z n‡e wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans C 08. 2F 2F 4F 2V Dc‡i cÖ`Ë eZ©bxi Zzj¨ aviKZ¡ KZ? [Kz. †ev. 2017] A. 2F B. 4F C. 8F D. 10F 2F I 2F aviKØq ci¯úi mgvšÍiv‡j hy³; Zzj¨aviKZ¡, CP = (2 + 2) F = 4F; hv 4F Gi mv‡_ †kÖwY‡Z hy³| eZ©bxi Zzj¨ aviKZ¡, C = (4–1 + 4–1 ) –1 = 2F wb‡Pi DÏxc‡Ki Av‡jv‡K 09 I 10 bs cÖ‡kœi DËi `vI: †ivnvb I mv`gvb 10C PvR©wewkó mgvb aviK‡Z¡i `ywU mgvšÍivj cvZ aviK wb‡q KvR KiwQj| †ivnvb Zvi avi‡Ki cvZ؇qi wefe cv_©K¨ †cj 2 Volts| wKš‘ mv`gvb Zvi avi‡Ki cvZ؇qi wefe cv_©K¨ †cj 1 Volts| †ivnv‡bi aviKwU evqyc~Y© wQj| 09. †ivnv‡bi avi‡Ki aviKZ¡ KZ? [Kz. †ev. 2016] A. 5F B. 3F C. 0.5F D. 0.3F C = Q V = 10 2 = 5F 10. mv`gvb‡K 2 volt wefe cv_©K¨ †c‡Z n‡j Zvi avi‡Ki Kx ai‡bi cwieZ©b Avb‡Z n‡e? [Kz. †ev. 2016] A. q n«vm B. †f`¨Zv e„w× C. d n«vm D. A n«vm †h‡nZz V = Q C ........... (i) Avevi, C = 0A d ........ (ii) V = Qd 0A ........ (iii) (iii) bs Abyhvqx A n«vm Ki‡j V Gi gvb e„w× cv‡e| 11. C = 2F C2 = 5F C1 = 3F C2 = 7F wPÎ Abymv‡i Cp : Cs = ? [e. †ev. 2016] A. 10 : 1 B. 7 : 1 C. 1 : 10 D. 1 : 7 Cp = C1 + C2 = 3 + 7 = 10F 1 Cs = 1 C1 + 1 C2 = 1 2 + 1 5 = 5 + 2 10 = 7 10; Cs = 10 7 Cp : Cs = 10 10 7 = 7 : 1 12. C1 C2 C3 C4 12V + – wP‡Îi cÖwZwU avi‡Ki aviKZ¡ 2F n‡j eZ©bxq Zzj¨ aviKZ¡ n‡eÑ [e. †ev. 2015] A. 0.8F B. 1.25F C. 5F D. 5F 1 Cs = 1 C2 + 1 C4 = 1 2 + 1 2 ; Cs = 1F C = C1 + Cs + C4 = 2 + 1 + 2 = 5F wb¤œwjwLZ DÏxc‡Ki Av‡jv‡K 13 bs I 14 bs cÖ‡kœi DËi `vI : [e. †ev. 2015; iv. †ev. 2015] evqy gva¨gwewkó †Kv‡bv avi‡Ki mgZj cvZ `ywUi cÖ‡Z¨‡Ki †ÿÎdj 12 cm2 Ges Zviv ci¯úi n‡Z 2 mm `~‡i Aew¯’Z| aviKwU‡K 2C Avav‡b AvwnZ Kiv n‡j cvZ؇qi wefe cv_©K¨ nq 4mV| GK QvÎ aviKwUi cÖ‡Z¨KwU cvZ‡K mgwØLwÐZ K‡i 0.5 mm e¨eavbwewkó `ywU aviK evwb‡q Zv‡`i ci¯úi †kÖwY‡Z hy³ Kij| 13. cÖ‡Z¨K avi‡Ki cvZ؇qi ga¨eZx© ¯’v‡bi cÖvej¨ KZ? A. 8 106NC1 B. 8 103NC1 C. 2 103NC1 D. 2NC1 E = V d = 4 10–3 2 10–3 = 2NC–1 14. QvÎ KZ…©K m„ó aviK mgev‡qi aviKZ¡ c~‡e©i aviKwUiA. A‡a©K B. mgvb C. wظY D. Pvi ¸Y Avw` Ae¯’vq, C = 0A d .......... (i) cvZ‡K †K‡U A‡a©K Ges `~iZ¡ 0.5mm Ki‡j d cwiewZ©Z n‡q d 4 nq| †m‡ÿ‡Î, GKwU avi‡Ki aviKZ¡, C1 = 0 A 2 d 4 = 0A 2 4 d = 2 0A d C2 = 2 0A d ; Zzj¨ aviKZ¡, 1 Cs = 1 C1 + 1 C2 ev, 1 Cs = d 20A = d 0A Cs = 0A d hv c~‡e©i aviK‡Z¡i mgvb| wb‡Pi eZ©bxwUi Av‡jv‡K 15 bs cÖ‡kœi DËi `vI: C1 E C3 C2 C2 = 100F C2 = 200F C3 = 300F E = 12Volt 15. eZ©bxi Zzj¨ aviKZ¡ KZ n‡e? [mKj †ev. 2018] A. 8.33 10–6 F B. 83.3 10–6 F C. 833.3 10–6 F D. 8333.3 10–6 F S B info CP = C2 + C2 = (200 + 300) F = 500 F CS = C1CP C1 + CP = 83.3 F
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 461 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 7 avi‡Ki mwÂZ kw³ FORMULA 01. avi‡Ki mwÂZ kw³/K…ZKvR, E = 2 1 CV2 = 2 1 C Q 2 = 2 1 QV 02. mwÂZ kw³ n ¸Y n‡j, PzovšÍ wefe, V2 = n .V1 03. wefe n ¸Y n‡j P~ovšÍ mwÂZ kw³, W2 = n2 . W1 ◈ mgvšÍivj ms‡hv‡M wefe cv_©K¨ w¯’i, †kÖwY ms‡hv‡M PvR© w¯’i CONCEPTUAL MATH MEx 01 6F aviKZ¡ wewkó GKwU 100 volt aviK‡K GKwU e¨vUvix Øviv c~Y© PvwR©Z Kiv nj| avi‡K mwÂZ kw³i cwigvb KZ? EP = 1 2 C.V2 = 1 2 × 6 × 10–6 × (100)2 = 0.03J MEx 02 GKwU avi‡Ki `yB cv‡Zi g‡a¨ wefe cv_©K¨ V Ges avi‡Ki mwÂZ kw³ U| avi‡Ki wefe cv_©K¨ e„w× K‡i 3V Kiv n‡j mwÂZ kw³ e„w× †c‡Z KZ n‡e? 2 1 2 1 2 v v U U = 2 3 v v ev, U2 = 9U NOW START PRACTICE 01. 2 F aviKZ¡ wewkó GKwU B‡jKUªwbK h‡š¿i Uvwg©bvj ؇qi g‡a¨ 2000 volt wefe cv_©K¨ cÖ‡qvM Kiv n‡j, avi‡K mwÂZ kw³i cwigvYÑ 02. GKwU mgvšÍivj cvZ avi‡Ki g‡a¨ GKwU WvBB‡jKwUªK c`v_© ¯’vcb Kivq avi‡Ki mwÂZ kw³ cuvP ¸b e„w× cvq| c`v_©wUi WvBB‡jKwUªK aªæeK KZ n‡e? 03. GKwU avi‡Ki PvR© 9.6 nC Ges Gi `yÕcÖv‡šÍi wefe cÖ‡f` 120V| aviKwUi aviKZ¡ Ges G‡Z mwÂZ kw³i cwigvY wbY©q Ki? 04. GKwU mgvšÍivj cvZ avi‡Ki cvZ؇qi wefe cv_©K¨ Zvi Avw` wefe cv_©K¨ A‡a©K n‡q †M‡j, aviKwUi mwÂZ kw³ wK cwigvY nªvm cv‡e? NOW PRACTICE SOLVE : 01. E = 1 2 CV2 = 1 2 × 2 × 10–6 × (2000)2 = 4J 02. C = 0 AK d , E = 1 2 CV2 , E C K, WvBB‡jKwUªK aªæeK K = 5 aªæeK 03. C = q V = 9.6 10–9 120 = 8 10–11 F = 80PF mwÂZ kw³ E = 1 2 CV2 = 1 2 8 10–11 1202 = 5.76 10–7 J 04. 2 1 2 1 2 2 2 1 E V V E E1 = 0.25E1 E = E2 E1 = 0.25E1 E1 = – 0.75E1= 75% n«vm REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. GKwU mgvšÍivj cvZ aviK‡K PvwR©Z Kivi ci e¨vUvwi Ly‡j †djv n‡jv| G Ae¯’vq aviKwU‡Z mwÂZ kw³i cwigvY U0| cvZ `ywUi `~iZ¡ hw` wظY Kiv nq, Z‡e avi‡K mwÂZ kw³ KZ ¸Y n‡e? [DU. 20-21] A. U0 2 B. U0 4 C. 2U0 D. 4U0 S C info U = Q 2 2C U 1 C [Pv‡R©i cwigvY Q aªæeK n‡j] C = 0A d C 1 d [ cv‡Zi †ÿÎdj A GKB _vK‡j] U d U2 U1 = d2 d1 = 2d1 d1 = 2 U2 = 2U1 = 2U0 02. GKwU avi‡Ki `yB cv‡Zi g‡a¨ wefe cv_©K¨ V Ges avi‡Ki mwÂZ kw³ X. avi‡Ki cv_©K¨ K‡i 3V Kiv n‡j mwÂZ kw³ e„w× †c‡q KZ n‡e? [DU. 2012-13] A. 3x B. 6x C. 9x D. 27x S C info 1g avi‡Ki wefe cv_©K¨© v1 = v 1g avi‡Ki mwÂZ kw³ Ep1 = x 2ev‡i, avi‡Ki wefe cv_©K¨© v2 = 3v, avi‡Ki mwÂZ kw³ Ep2 = ? Ep = 1 2 cv2 Ep2 Ep1 = v2 v1 2 ev, Ep2 x = 3v v 2 ev, Ep2 = 9x 03. GKwU wew”Qbœ mgvšÍivj cvZ avi‡Ki cvZ؇qi ga¨eZ©x `~iZ¡ wظb Kivi d‡j avi‡Ki mwÂZ kw³i wK cwieZ©b nq? [DU. 2010-11; JUST: 2014-15] A. kw³ wظY nq B. kw³i †Kvb cwieZ©b nq bv C. kw³ A‡a©K nq D. kw³ Pvi ¸Y e„w× cvq| C = 0A d Ges Ep = 1 2 CV2 Ep = 1 2 0Av2 d `~iZ¡ wظb ZvB kw³ A‡a©K n‡e| 04. GKwU mgvšÍivj cvZ aviK‡K PvwR©Z Kivi d‡j cvZ؇qi g‡a¨ wefe cv_©K¨ n‡j V| wefe cv_©K¨ KZ n‡j avi‡Ki mwÂZ kw³ wظb n‡e? [DU. 06-07, 13-14] A. 1 4 V B. 1 2 V C. 2V D. 2V E = 1 2 CV2; EαV2 [GKwU avi‡Ki Rb¨ C w¯’i] V2 = E2 E1 V1 = 2 V 05. 3F aviKZ¡ wewkó GKwU 200 volt aviK‡K GKwU e¨vUvix Øviv c~Y© PvwR©Z Kiv nj| avi‡K mwÂZ kw³i cwigvb KZ? [DU. 2000-01, IU: 2004-05] A. 0.2510-10 Ryj B. 0.06 Ryj C. 0.12 Ryj D. 0.661010 Ryj Ep = 1 2 CV2 = 1 2 3 10–6 (200)2 = 0.06 J
462 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES STEP 02 ANALYSIS OF JU QUESTION 01. GKwU wew”Qbœ mgvšÍivj cvZ avi‡Ki cvZ؇qi ga¨eZx© `~i‡Z¡i Kx cwigvY cwieZ©b Ki‡j avi‡K mwÂZ kw³ c~‡e©i kw³i wظY nq? [JU-H, Set-1. 19-20] A. wظY B. Pvi¸Y C. A‡a©K D. GK PZz_©vsk U = 1 2 CV2 ; U C; C= 0A d ; C 1 d U 1 d `~i‡Z¡i cwigvY A‡a©K Ki‡j mwÂZ kw³ c~‡e©i 2 ¸Y n‡e| 02. 1.2 μF aviKZ¡ wewkó GKwU B‡jKwUªK h‡š¿i cÖv‡šÍi g‡a¨ 2000V wefe cv_©K¨ †`qv nj, avi‡Ki mwÂZ kw³i cwigvY KZ ? [JU. 2011-12, SUST. 07-08] A.2.4 J B. 1.4 J C. 3.4 J D. 4.2 J avi‡Ki mwÂZ kw³, E = 1 2 CV2 = 1 2 1.2 10–6 (2000)2 = 2.4 J STEP 03 ANALYSIS OF RU QUESTION 01. 10F aviKZ¡ wewkó GKwU aviK‡K 200 V e¨vUvwi Øviv c~Y© PvwR©Z Kiv n‡jv| avi‡K mwÂZ kw³i cwigvY KZ? [RU. Moderna, Set-2. 20-21] A. 2 J B. 0.2 J C.0.002 J D. 0.0002 J S B info avi‡Ki mwÂZ kw³, U = 1 2 CV2 = 1 2 10 10 10–6 (200)2 = 0.2J 02. 4F I 5F Gi `ywU aviK †kÖwY‡Z mshy³| GB mgevq‡K 900V wefe cv_©‡K¨i GKwU Dr‡mi mv‡_ mshy³ Ki‡j mwÂZ kw³ n‡e- [RU. Astrazeneca, Set-1. 20-21] A. 0.9 J B. 9 J C. 90 J D. 0.009 J S A info avi‡Ki †kÖwY mgev‡qi †ÿ‡Î Cs = 1 4 + 1 5 –1 = 20 9 F aviKwUi mwÂZ kw³, U = 1 2 CsV 2 = 1 2 20 9 10–6 900 900 = 10 9 1 1000000 81 104 = 0.9J 03. 1000V e¨vUvixi `yB cÖv‡šÍ GKwU aviK hy³ Kivq avi‡K 50J kw³ mwÂZ n‡jv| avi‡K mwÂZ Pv‡R©i cwigvY KZ? [RU. 2012-13] A. 10C B. 1C C. 101C D. 102C EP = 1 2 Q.v ev, Q = 50 2 1000 = 10–1C STEP 04 ANALYSIS OF CU QUESTION 01. 1 ‡gMv B‡j±ªb †fvë (MeV) mgvb KZ? [CU. 2014–15] A. 1.610-19 JB. 1.610-15 J C. 1.610-13 J D. 1.610-11 JE) 1.61019 J 1Mev = 1.610–19106 = 1.610–13j 02. 4F Gi GKwU aviK‡K 9.0v e¨vUvwi Øviv AvwnZ Ki‡j G‡Z wK cwigvb kw³ mwÂZ n‡e? [CU. 2002-03, 2013-14; IU:2005-06; JU:2013-14, DU. 7Clg-A: 20-21] A. 1.62×10-4 j B. 3.24×10-4 j C. 1.62×10-3 j D. 3.24×10-3 j E= 1 2 cv2 = 1 2 ×4×10-6 × (9)2 = 1.62 × 10-4 STEP 05 ANALYSIS OF GST QUESTION PART A Analysis of General University Question IU 01. PvwR©Z avi‡Ki w¯’wZ kw³- [IU. 2015-16, MBSTU-A, Set-2 19-20] A. 1 2 CV2 B. 1 2 QV C. Q2 /2C D. me¸‡jv Ans D PART B Analysis of Science & Technology Question SUST 01. GKwU avi‡Ki wef‡ei cwigvY wظY Kiv n‡j Zvi †fZ‡i mwÂZ kw³i cwigvY e„w× cv‡e- [SUST: 2010-11] A. 1.4 ¸Y B. wظY C. wZb¸Y D. Pvi¸Y 2 CV 2 1 E ; EαV2 [GKwU avi‡Ki Rb¨ C w¯’i] E 4E V 2V E V V E 2 1 2 1 2 2 02. GKwU avi‡Ki wef‡ei cwigvb wظb Kiv n‡j Zvi wfZ‡i mwÂZ kw³i cwigvb e„w× cv‡e [SUST: 2010-11] A. 1.4 ¸b B. wظb C. wZb¸b D. Pvi¸b Ep = 1 2 cv2 = 1 2 Q.v = 1 2 Q 2 c Ep2 Ep1 = v2 v1 2 = 2 1 2 = 4 A_©vr, mwÂwZ kw³ e„w× = 4 1 = wZb¸Y| 03. GKwU wbw`©ó avi‡Ki mwÂZ kw³ 16 ¸Y e„w× Ki‡Z n‡j Avavb KZ¸Y e„w× Ki‡Z n‡e? [SUST: 2015-16] A. 0 B. 2 C. 4 D. 8 E. 16 Uvb, Ep = 1 2 QV Ep2 Ep1 = Q2 Q1 16 1 = Q2 Q1 ev, Q2 = 16Q MBSTU 01. GKwU avi‡Ki wef‡ei cwigvY wZb¸Y Kiv n‡j Zvi w¯’wZ kw³ KZ ¸Y e„w× cv‡e? [MBSTU: 2014-15] A. 3 ¸Y B. 6 ¸Y C. 1.5 ¸Y D. 9 ¸Y EP v 2 DU Technology 01. GKwU mgvšÍivj cvZ aviK‡K PvwR©Z Kivi d‡j cvZ؇qi g‡a¨ wefe cv_©K¨ n‡jv V1 wefe cv_©K¨ KZ n‡j avi‡Ki mwÂZ kw³ wظY n‡e? [DU-Tech. 2020-21] A. 2 v B. v 2 C. v 2 D. 2v S A info Avgiv Rvwb, avi‡Ki mwÂZkw³, U = 1 2 CV2 U2 U1 = V2 2 V1 2 = V2 2 V 2 2U1 U1 = V2 2 V 2 V2 = 2V STEP 06 ANALYSIS OF ENGINEERING & BUTex QUESTION RUET 01. 0.2F GKwU K¨vcvwmUi‡K Ggbfv‡e PvR© Kiv n‡jv †hb †cø‡Ui we`y¨r wefe 100v nq| GB mwÂZ Pv‡R©i kw³ KZ? [RUET: 2009-10] A. 0.001J B. 100J C. 10J D. 0.0001J E. 100J Ep = 1 2 cv2 = 1 1 0.210-6 (102 ) 2 = 0.001J STEP 07 ANALYSIS OF HSC BOARD QUESTION 01. avi‡K mwÂZ kw³i †ÿ‡Î †KvbwU mwVK? [Xv. †ev. 2017; e. †ev. 2018, 2017; P. †ev. 2016] A. W = 1Q 2C B. W = 1 2 CP C. W = 1 2 VC2 D. W = 1 2 CV2 Ans D 02. wb‡Pi †Kvb †jLwPÎ Øviv mgvšÍivj cvZ avi‡Ki wefe cwieZ©‡bi mv‡_ mwÃZ w¯’i •e`y¨wZK kw³i cwieZ©b mwVKfv‡e Dc¯’vcb K‡i? [iv. †ev. 2016] A. B. C. D. E V E V E V E V E = 1 2 CV2 m~Îvbymv‡i, V Gi wewfbœ gv‡bi Rb¨ E Gi gvb wbY©q K‡i MÖvd AuvK‡j (M) wPÎwU cvIqv hv‡e| 03. hLb 8 mC PvR© 12V wefe cv_©K¨ AwZµg K‡i ZLb Kx cwigvY we`y¨r kw³ iƒcvšÍwiZ nq? [P. †ev. 2016] A. 96 J B. 48 J C. 0.096 J D. 0.048 J W = Vq = 12V 8 10–3C = 0.096 J
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 463 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 04. wefe cv_©K¨ w¯’i _vK‡j GKwU Pv‡R©i avi‡Ki kw³ Zvi Pv‡R©i- [P. †ev. 2015; Kz. †ev. 2015] A. e¨¯ÍvbycvwZK B. mgvbycvwZK C. e‡M©i e¨¯ÍvbycvwZK D. eM©g~‡ji mgvbycvwZK Ans B 05. GKwU mgvšÍivj cvZ avi‡Ki cÖwZwU cv‡Zi †ÿÎdj 0.04 m2 | cvZ؇qi ga¨eZx© `~iZ¡ 0.002 m Ges wefe cv_©K¨ 60V| avi‡Ki GKK AvqZ‡b mwÂZ wefe kw³ KZ Ryj? [w`. †ev. 2015] A. 3.18 107 B. 2.52 C. 0.004 D. 251.57 S A info C = 0A d = 8.854 10–12 0.04 0.002 = 1.7708 10–10 F Avevi, E = 1 2 CV2 = 1 2 1.7708 10–10 (60)2 = 3.18 10–7 J 06. GKwU PvwR©Z avi‡Ki kw³ NbZ¡ wbY©q Kiv hv‡e wb‡Pi †Kvb mgxKi‡Yi mvnv‡h¨? [e. †ev. 2016] A. U = 1 2 QV B. U = 1 2 0E 2 C. U = 1 2 Q 2C D. U = 1 2 0V 2 Ans A SAQ Short Answer Questions WRITTEN PART BAQ Broad Answer Questions 01. nvB‡Wªv‡Rb cigvYy‡Z B‡jKUªb I †cÖvU‡bi g‡a¨ wµqvkxj ej wbY©q Ki| B‡jKUª‡bi Kÿc‡_i e¨vmva© 5.3 10–11m n‡j B‡jKUª‡bi •iwLK †eM †ei Ki| Solve Avgiv Rvwb, F = 1 40 q1q2 r 2 = 8.2 10–8N Avevi, GB AvKl©Y e‡j B‡jKUª‡bi Dci wµqvkxj †K›`ªgyLx e‡ji mgvb| GLv‡b, q1 = q2 = 1.6 10–19C me = 9.1 10–31 Kg r = 5.3 10–11m F = ? v = ? F = mv2 r ev, v = Fr m = 2.18 106ms–1 (Ans.) 02. 20 †mw›UwgUvi e¨v‡mi GKwU †Mvj‡Ki c„‡ô 10C gv‡bi `ywU PvR© ivLv n‡jv| †Mvj‡Ki †K›`ª n‡Z 8 †mw›UwgUvi Ges 12 †mw›UwgUvi `~i‡Z¡ Zwor wefe I Zwor cÖvej¨ wbY©q Ki| Solve 1g †ÿ‡Î, Avgiv Rvwb, †Mvj‡Ki Af¨šÍ‡i †h †Kvb we›`yi wefe Gi c„‡ôi wef‡ei mgvb| V1 = 1 40 q r1 = 1.8 1012V Ges †Mvj‡Ki Af¨šÍ‡i PvR© bv _vKvq cÖvej¨ k~b¨| GLv‡b, r = 20/2cm = 10cm = 0.1m q = (10 + 10)C = 20C 1g †ÿ‡Î, r1 = 8cm = 0.08m V1 = ? E1 = ? 2q †ÿ‡Î, r2 = 12cm = 0.12m V2 = ? E2 = ? 2q †ÿ‡Î, V2 = 1 40 q r2 = 1.5 1012V Ges, E2 = 1 40 q r2 2 = 1.25 1013 NC–1 03. 0.04 wgUvi e¨vmv‡a©i 64wU †MvjvK…wZ †duvUv‡K GKwÎZ K‡i GKwU eo †dvUvq cwiYZ Kiv n‡jv| cÖwZwU †duvUvq Pv‡R©i cwigvY 1C n‡j eo †dvUvi aviKZ¡ I wefe wbY©q Ki| Solve cÖkœvbymv‡i, eo †duvUvwUi AvqZb †QvU †duvUvi AvqZ‡bi 64 ¸Y n‡e| 4 3 R 3 = 64 4 3 r 3 R = 0.16m eo †duvUvi aviKZ¡, C = 40R = 17.8 10–12F eo †duvUvi wefe, V = Q/C = 3.59 1012V GLv‡b, r = 0.04m R = ? q = IC Q = 64q = 64C C = ? V = ? 04. GKwU mgvšÍivj cvZ avi‡Ki `ywU cv‡Zi ga¨eZ©x `~iZ¡ 2cm Ges `ywUi AvK…wZ e„ËvKvi| cÖwZwU cv‡Zi e¨vmva© 2cm| aviKwU‡Z 8 –6 C PvR© cÖ`vb Ki‡j cvZ `ywUi g‡a¨ wefe cv_©K¨ wbY©q Ki| cvZ `ywUi ga¨eZ©x ¯’v‡bi Zwor cÖvej¨ Ges cv‡Zi PvR© NbZ¡ wbY©q Ki| avi‡Ki mwÂZ kw³i cwigvY wbY©q Ki| Solve Avgiv Rvwb, C = 0kA d = 5.56 10–13F V = Q/C = 1.44 107V E = V/d = 72 107NC–1 cv‡Zi PvR© NbZ¡, = Q/A = 6.37 10–3Cm–2 avi‡Ki mwÂZ kw³, P.E. = QV/2 = 57.6J GLv‡b, r = 2cm = 0.02m k = 1 Q = 8 10–6C A = r 2 = 1.2566 10–3m 2 d = 2cm = 0.02m V = ? E = ? ; = ? ; P.E. = ? 05. GKwU mgvšÍivj cvZ avi‡Ki cÖwZwU cv‡Zi †ÿÎdj 200cm2 Ges evqy‡Z cvZ؇qi ga¨eZ©x `~iZ¡ 0.4cm n‡j Gi (i) aviKZ¡ wbY©q Ki| (ii) hw` aviKwU 500V •e`y¨wZK Dr‡mi mv‡_ ms‡hvM Kiv nq, Z‡e avi‡K KZ kw³ mwÂZ n‡e? Solve A = 200cm2 = 200 10–4m= 0.02m2 d = 0.4cm = 0.4 10–2m = 4 10–3m V = 500V; (i) aviKZ¡ C = 0A d = 8.8410–120.02 410–3 = 4.4310–11F (ii) U = 1 2 CV2 = 1 2 4.43 10–11 500 500 = 5.53 10–6 J 06. 12C Ges 8C `ywU we›`y PvR© ci¯úi †_‡K 10 †m.wg. `~‡i Aew¯’Z| PvR© `ywU‡K 6 †m.wg. e¨eav‡b wb‡q Avm‡Z KZUzKz KvR Ki‡Z n‡e| PvR© `ywU k~‡b¨ Aew¯’Z| Solve W = q2(v2 – v1) = 8 10–6 q1 40 1 r2 – 1 r1 = 8 10–6 12 10–6 9 1 0.06 – 1 0.1 = 5.76J (Ans.) 07. PviwU 4F Gi aviK‡K 100V e¨vUvwii mwnZ (K) mgvšÍivj ms‡hvM w`‡j wK cwigvY •e`y¨wZK kw³ mwÂZ n‡e? (L) wmwiR ms‡hvM w`‡j wK cwigvY •e`y¨wZK kw³ mwÂZ n‡e? Solve (K) Cp = (4 + 4 + 4 + 4) = 16F = 16 10–6 F mwÂZ kw³, U = 1 2 CpV 2 = 1 2 16 10–6 1002 = 8 –2 J (L) 1 Cs = 1 4 + 1 4 + 1 4 + 1 4 = 4 4 = 1 Cs = 1F = 1 10–6 F mwÂZ kw³, U = 1 2 CsV 2 = 1 2 10–6 (100)2 = 5 103 J 08. Kzj‡¤^i m~ÎwU wee„Z Ki| †jvnvi wbDwK¬qv‡m Ae¯’vbiZ `ywU †cÖvU‡bi g‡a¨ cvi¯úwiK wµqvkxj ej KZ n‡e hw` Zv‡`i g‡a¨ `~iZ¡ 4 10–15 nq? [NSTU-A, 19-20] Solve Kzj‡¤^i m~Î: wbw`©ó gva¨‡g `ywU we›`y Avav‡bi g‡a¨ wµqvkxj AvKl©Y ev weKl©Y e‡ji gvb Avavb؇qi ¸Yd‡ji mgvbycvwZK| G‡`i ga¨eZx© `~i‡Z¡i e‡M©i e¨v¯ÍvbycvwZK Ges GB ej Avavb؇qi ms‡hvRK mij‡iLv eivei wµqv K‡i| ej, F = 9 109 q1q2 r 2 = 9 109 (1.6 10–19) 2 (4 10–15) 2 = 14.4 N 09. Kcv‡ii •Zwi AjsKv‡ii Dci 0.1 mm cyiæ †mvbvi cÖ‡jc w`‡Z 0.5 A we`yr cÖevn KZ mgq a‡i Pvjbv Ki‡Z n‡e? †mvbvi NbZ¡ = 19 103 kgm–3 Ges AjsKv‡ii cÖ¯’‡”Q` = 20 cm2 , †mvbvi Zwor ivmvqwbK mgZzj = 6.38 10–7 kgC–1 | [RUET: 19-20] Solve †mvbvi cÖ‡j‡ci AvqZb V = 20 10–4 0.1 10–3 = 2 10–7 m 3 †mvbvi cÖ‡j‡ci fi m = V = 19103 2 10–7 = 3.8 10–3 kg PvR© cÖ‡qvRb, Q = 3.8 × 10–3 kg 6.38 × 10–7 kgC–1 It = 5956.11 t = 5956.11 0.5 = 11912.23 s = 3.31 hr
464 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 10. 20 †mwg e¨vmv‡a©i GKwU cwievnx †Mvj‡Ki Zj mylgfv‡e 3 gvB‡µv-Kzj¤^ Avav‡b AvwnZ| †Mvj‡Ki c„‡ô Ges †K›`ª †_‡K 30 †mwg `~‡i †Kvb we›`y‡Z Zwor cÖvej¨ wbY©q Ki| [KUET; 19-20] Solve †Mvj‡Ki c„‡ô Zwor cÖvej¨, E1 = 1 40 . q r1 2 = 9 109 3 10–6 (20 10–2 ) 2 = 6.75 105 NC–1 Avevi, †K›`ª †_‡K 30cm `~‡i Zwor cÖvej¨, E2 = 1 40 . q r2 2 = 9 109 3 10–6 (30 10–2 ) 2 = 3 105 NC–1 11. c„w_ex c„‡ôi mwbœK‡U evqyk~b¨ ¯’v‡b y A‡ÿi, y = 10m we›`y‡Z GKwU B‡jKUªb Aew¯’Z| y A‡ÿi †Kvb we›`y‡Z cÖ_g B‡jKUª‡bi mv‡c‡ÿ wØZxq B‡jKUªb ivL‡j, Zv‡`i ga¨w¯’Z w¯’iwe`y¨Zxq ej, cÖ_g B‡jKUª‡bi Dci wµqvkxj gva¨vKl©Y e‡ji fvimvg¨ iÿv Ki‡e? [g = 9.8m/sec2 ] [BUET: 2018-19] Solve Fe = Fg 1 40 q 2 a 2 = meg a 2 = 9 109 (1.6 10–19) 2 9.11 10–31 9.8 = 25.8m2 = a = 5.08m y = 10 – 5.08 = 4.92m 12. GKwU avi‡Ki cvZ؇qi ga¨eZ©x `~iZ¡ 5 mm n‡j Gi g‡a¨ ivLv 10wU B‡jKUªb enbKvix GKwU †Z‡ji †dvUvi fvimvg¨ iÿv Ki‡Z KZ wefe cÖ‡qvM Ki‡Z n‡e Zv wbY©q Ki| †`Iqv Av‡Q, †Z‡ji †dvUvi fi 3 10–16kg. [BUET; 19-20] Solve Avgiv Rvwb, mg = qE 3 10–16 9.8 = 10 1.6 10–19 E E = 1837.5 NC–1 ; V = Ed = (1837.5 5 10–3 ) V = 9.1875V 13. GKwU mgvšÍivj cvZ avi‡Ki cÖwZwU cv‡Zi †ÿÎdj 0.05m2 | cvZ؇qi ga¨eZx© gva¨g k~b¨; G‡`i g‡a¨ `~iZ¡ 0.0015m Ges wefe cv_©K¨ 5V n‡j (A) avi‡Ki aviKZ¡, (B) cvZ `ywUi g‡a¨ mwÂZ kw³ Ges (C) avi‡Ki GKK AvqZ‡bi mwÂZ kw³ wbY©q Ki| [0 = 8.85 10-12F/m] [BUET: 2018-19] Solve A.; A = 0.05m2 ; d = 0.0015m; V = 50V C = 0A d = 2.95 10–10F; B. W = 1 2 CV2 = 3.69 10-7 J C. GKK AvqZ‡b mwÂZ kw³ = W Ad = 4.92 10–3 J 14. GKwU evqyc~Y© mgvšÍivj cvZ avi‡K aviKZ¡ 8 × 10–12 F, hw` aviKwU 6 civ‣e`y¨wZK aªæeK wewkó GKwU gva¨g Øviv c~Y© K‡i cvZ؇qi ga¨eZ©x `~iZ¡ Kwg‡q A‡a©K Kiv nq, Zvn‡j aviKwUi aviKZ¡ KZ n‡e? [BUTex. 2020-21] Solve Avgiv Rvwb, aviKZ¡, C = A d = 0kA d [ = k0] k~b¨ gva¨g/evqc~Y© gva¨‡gi Rb¨, C0= 0k0A d0 = 0A d0 [ evqy gva¨‡gi Rb¨ k0 = 1] C C0 = 0kA d 0A d0 = k d0 d = 6 2 = 12 C = 12C0 = 12 8 10–12F = 9.6 10–11F C0 = 8 10–12F k0 = 1 k = 6 cvZ؇qi ga¨eZ©x Avw` `~iZ¡, d0 cvZ؇qi ga¨eZ©x eZ©gvb `~iZ¡, d = d0 2 15. GKwU mylZg Zwor †ÿ‡Î Zwor cÖvej¨ E = 5 i + 3 j + 2 k Zwor †ÿ‡Î Y-Z Z‡j ¯’vwcZ 15m2 ‡ÿÎdj wewkó GKU Z‡j Zwor d¬v· KZ n‡e? Solve Y-Z Z‡ji ga¨ w`‡q d¬v· = Z‡ji †ÿÎdj (ds) EX GLv‡b Z‡ji †ÿÎdj, ds = 15m2 cÖvej¨ E G x Dcvsk (EX) Y Z Z‡ji Dci Awfj¤^| AZGe, wb‡Y©q d¬v· ds EX = 15m2 5Vm1 = 65 Nm2C 1 65 Nm2C 1 Y 5vm1 2vm1 Y Z Zj 3vm1 X 16. †Kv‡bv Zwor †ÿ‡Îi cÖvej¨ KZ n‡j †mLv‡b GKwU B‡jKUªb Zvi IR‡bi mgvb ej Abyfe Ki‡e? Solve GLv‡b, m = B‡jKUª‡bi fi = 9.1 10–3 kg Q = B‡jKUª‡bi PvR© = 1.6 10–19 C E = Zwor cÖvej¨ = ? g = AwfKl©xq Z¡iY = 9.8 ms–2 Pv‡R©i Dci wµqvkxj ej F n‡j, E = F Q wKš‘ F = mg E = mg Q = 9.1 10–31 9.8 1.6 10–19 = 5.57 10–11 NC –1 5.57 10–11 NC –1 17. GKwU we›`y‡Z Zwor wefe V = – 5x + 3y + 30 z n‡j , H we›`y‡Z Zwor cÖvej¨ KZ? Solve Avgiv Rvwb, E = Ex i + Ey j + Ez k GLv‡b, V = – 5x + 3y + 30z Ges, Ex = dVx dx = d dx (– 5x) = 5 ev, Ey = dVy dy = d dy (3y) = 3 ev, Ez = dVz dz = – d dz ( 30z) = 30 E = E 2 x + E2 y + E2 z = 5 2 + ( 3) 2 + ( 30) 2 = 25 + 9 + 30 = 64 = 8 unit 8 GKK 18. + 1.0 10–6 C I + 2.0 10–6 C Gi `ywU PvR© ci¯úi n‡Z 10cm `~‡i Aew¯’Z| G‡`i ms‡hvM †iLvi Dci Ggb GKwU we›`y wbY©q Ki †hLv‡b cÖvej¨Ø‡qi gvb mgvb| A B q1 = 1.0 + 10-6C q2 = 2.0 10-6C x (0.10 -+ 10-6C) PvR© `ywU GKB cÖK…wZi e‡j G‡`i ms‡hvM †iLvi Af¨šÍ‡i †h‡Kv‡bv ¯’v‡b PvR© `ywUi Rb¨ Zwor cÖvej¨ mgvb n‡e| Solve aiv hvK, 1g PvR© n‡Z x `~‡i x `~‡i O we›`y‡Z cÖvej¨Ø‡qi gvb mgvb| 1g Pv‡R©i Rb¨ cÖvej¨, E1 = 1 40 . q1 x 2 .................. (i) 2g Pv‡R©i Rb¨ cÖvej¨, E2 = 1 40 . q 2 (0.10 – x) 2 .... (ii) cÖkœg‡Z, E1 = E2 Zvn‡j, q1 x 2 = q2 (0.10 – x) 2 ev, 0.10 – x x = q2 q1 ev, 0.10 x – 1 = 2.0 10–6 1.0 10–6 ev, 0.10 x = 2 + 1 x = 0.10 2.414 = 0.041m q1 PvR© n‡Z PvR©Ø‡qi ms‡hvM‡iLvi 0.041m `~‡i q2 Pv‡R©i w`‡K cÖvej¨Ø‡qi gvb mgvb|
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 465 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 19. `ywU Avavb + 5 C Ges – 5 C evqy‡Z 4cm `~‡i GKB †iLv eivei Aew¯’Z n‡q GKwU w؇giæ MVb K‡i| w؇giæi Aÿ eivie ga¨we›`y †_‡K 4cm `~‡i Zwor †ÿ‡Îi cÖvej¨ wbY©q Ki| Solve w؇giæi åvgK, p = q(2l) = 5 10–6 4 10–2m = 2 10–7m Avgiv Rvwb, E = 1 40 . 2pr (r 2 – l 2 ) 2 = 9 109 2 2 10–7 4 10–2 (16 10–4 – 4 10–4 ) 2 = 9 4 4 144 10–8 NC–1 = 108 NC–1 GLv‡b, PvR, q = 5C = 5 10–6C w؇giæ ga¨eZ©x `~iZ¡, 2l = 4 cm = 4 10–2m w؇giæi ga¨ we›`y n‡Z Av‡jvP¨ we›`yi `~iZ¡, r = 4cm = 4 10–2 m cÖvej¨, E = ? STEP 3 mKj cvV¨eB‡qi NCTB QUESTIONS ANALYSIS cÖkœ e¨vLvmn mgvavb cÖkœ 01. †Kvb we›`y‡Z Zwor †¶ÎÑ [Bm&nvK m¨vi] i. wbiwew”Qbœ, hw` IB we›`y‡Z †Kv‡bv Avavb bv _v‡K ii. wew”Qbœ, hw` IB we›`y‡Z †KejgvÎ †Kv‡bv abvZ¥K Avavb _v‡K iii. wew”Qbœ, hw` IB we›`y‡Z †Kv‡bv Avavb _v‡K wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans B 02. mylgfv‡e AvwnZ duvcv †Mvj‡Ki Rb¨ Zvi †K›`ª †_‡K `~i‡Z¡ (r>R) Zwor cÖvej¨ n‡jvÑ [Bm&nvK m¨vi] A. E r B. r 1 E C. 2 r 1 E D. E r 2 Ans C 03. wPÎ Abyhvqx mgwefe we›`y¸wj n‡jvÑ[BQ&nvK, Avwgi] A. P Ges Q B. S Ges Q C. S Ges R D. P Ges R Ans C P S R Q 04. GKwU Aa©‡MvjK mylgfv‡e abvZ¥K Avav‡b AvwnZ| Aa©‡MvjKwUi †K‡›`ª Zwor cÖvej¨ n‡jvÑ [Bm&nvK m¨vi] A. e¨v‡mi Dci j¤^ B. e¨v‡mi m‡½ mgvšÍivj C. e¨v‡mi m‡½ wZh©Kfv‡e AvbZ Ges Aa©‡Mv&jK AwfgyLx Ans A D. e¨v‡mi m‡½ wZh©Kfv‡e AvbZ Ges Aa©‡Mv&jK †_‡K evB‡ii w`‡K 05. wP‡Î GKwU Zwor †¶‡Îi ej‡iLv †`Lv‡bv n‡q‡Q| IB †¶‡Î GKwU w؇giæ ivLv n‡q‡Q| wb‡Pi †KvbwU mwVK? [Bm&nvK m¨vi] -q +q A. w؇giæwU †Kvb ej Abyfe Ki‡e bv B. w؇giæwU Wvb w`‡K GKwU ej Abyfe Ki‡e C. w؇giæwU evg w`‡K ej Abyfe Ki‡e D. w؇giæwU DËi w`‡K ej Abyfe Ki‡e Ans C wPÎwU jÿ Ki Ges 06 Ges 07 bs cÖ‡kœi DËi `vI: 2F 1F 3F 50 V 06. eZ©bxi Zzj¨ †iva KZ? [Bm&nvK m¨vi] A. 3.66 F B. 6F C. 6.67F D. 2 3 F 1 Cs = 1 2 + 1 = 3 2 Cs = 2 3 C = 3 + 2 3 = 11 3 = 3.66F 07. me¸‡jv aviK‡K mgvšÍivj mgev‡q hy³ Ki‡j Zzj¨ aviKZ¡ n‡eÑ [Bm&nvK m¨vi] A. 3.66 F B. 6F C. 10 F D. 0 F Cp = 1 + 2 + 3 = 6F 08. hw` †Kvb Z‡j E.ds 0 nq Z‡eÑ [Bm&nvK m¨vi] i. IB Z‡ji †fZ‡i Zwor †¶Î mylg ii. IB Z‡j hZ¸wj Zwor d¬v· cÖ‡ek K‡i wVK ZZ¸wjB Zwor d¬v· wbM©Z nq iii. mg¯Í Avavb¸wj Z‡ji evB‡i Aew¯’Z wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans C 09. GKwU AvwnZ avi‡K kw³ mwÂZ _v‡KÑ A. †cø‡Ui ga¨eZ©x Zwor †¶‡Î B. FYvZ¥K †cø‡U C. †cøU `ywUi cÖv‡šÍi Pvicv‡k D. abvZ¥K †cø‡U Ans A 10. Zwor †¶‡Îi †Kvb we›`yi cÖvej¨ E n‡j †mLv‡b q PvR© †h ej F Abyfe K‡i Zv wb‡Pi †KvbwU? [Zcb m¨vi] A. qE B. q E C. E q D. q2E Ans A 11. GKwU PvwR©Z e¯‘i Pviw`‡K hZ`yi Zvi cÖfve _v‡K Z‡K Kx e‡j? [Zcb m¨vi] A. Zwor cÖvej¨ B. Zwor wefe C. Zwor †¶Î D. Gi †KvbwUB bq Ans C 12. `ywU PvwR©Z e¯‘ ci¯ú‡ii mv‡_ mshy³ Ki‡j Pv‡R©i cÖevn †Kvb w`‡K n‡e Zv †Kvb wel‡qi Dci wbf©i K‡i? [Zcb m¨vi] A. Pv‡R©i cwigvY B. Zwor †¶Î C. Zwor cÖvej¨ D. Zwor wefe Ans D 13. wZbwU Z_¨ †`Iqv Av‡Q- [Zcb m¨vi] i. †Kv‡bv e¯‘‡Z †gvU Avav‡bi cwigvY B‡jKUª‡bi Avav‡bi c~Y© msL¨K ¸wYZK n‡eB| ii. `ywU Avav‡bi ga¨Kvi cvi¯úwiK e‡ji gvb Zv‡`i ga¨eZx© gva¨‡gi cÖK…wZi Dci wbf©i K‡i bv| iii. Zwor w؇giæ åvg‡Ki gvb n‡”Q w؇giæi †h‡Kv‡bv GKwU Avavb Ges G‡`i ga¨eZx© `~i‡Z¡i ¸Yd‡ji mgvb| wb‡Pi †KvbwU mwVK? A. i I ii B. ii I iii C. i I iii D. i, ii I iii 14. R e¨vmv‡a©i GKwU †MvjvK…wZ cwievnxi c„‡ô Q PvR© †`qv nj| †Mvj‡Ki †K›`ª n‡Z (R-2) GKK `~‡i †Kv‡bv we›`yi wefe-- [Zdv¾j m¨vi] A. V = 1 40 Q R B. V = 1 40 Q R – 2 C. V = 1 40 Q R 2 D. V = 1 40 Q (R– 2) 2 R Q . 4 0 1 R R 2 V
466 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 15. civ‣e`y¨wZK aªæeK nj- [Zdv¾j m¨vi] i. 0 ii. F F0 iii. C C0 wb‡Pi †KvbwU mwVK? A. i B. i I ii C. i I iii D. ii I iii Ans B 16. †K me©cÖ_g cÖgvY K‡ib †h, Nl©Y Øviv m„ó PvR© GKB cÖK…wZi bq? [Mwb m¨vi] A. †eÄvwgb d«v¼wjb B. Pvj©m wm.Gd Wz‡d C. Pvj©m Kzj¤^ D. iv`vi †dvW© Ans B 17. gvBKvi cviwgwUwfwU KZ? [Mwb m¨vi] A. 53.124×10-12C 2N -1m -2 B. 10×8.84×10-12C 2N -1m -2 C. 15C2N -1m -2 D. 81×8.845×10-12C 2N -1m -2 gvBKvi, 0 12 Eo 6 8.854 10 12 2 1M 2 53.124 10 C N m –2 wZbwU aviK C1=1F, C2=2F Ges C3=3F wb‡Pi wPÎ Abyhvqx mshy³| Dc‡ii Z_¨ †_‡K 18 I 19 bs cÖ‡kœi DËi `vI : 18. A I B Gi g‡a¨ Zzj¨ aviKZ¡Ñ [Mwb m¨vi] A. 1.5F B. 4.5F C. 6F D. 1F Cs=1+2=3, 1.5MF 6 9 3 3 3 3 C = 1.5F 19. GB eZ©bx‡Z †gvU KZ PvR© cÖevwnZ n‡j A I B we›`yi wefe cv_©K¨ 10V n‡e? [Mwb m¨vi] A. 45×10-6C B. 1.6×10-19C C. 15×10-6C D. 1×10-6C 15 10 C Q 1.5 10 10 V 10V Q CV C 1.5 10 F 6 6 6 20. wPÎvbymv‡i aviK¸‡jvi Zzj¨ aviKZ¡ KZ n‡e? [igv m¨vi] A. 1F B. 1.6F C. 2F D. 2.6F Cp = 5 + 3 = 8F 1 C = 1 8 + 1 2 = 5 8 C = 8 5 = 1.6F 21. wb‡Pi †Kvb †jLwPÎwU Zwor cÖvej¨ Ges `~i‡Z¡i m¤úK© wb‡`©k K‡i? A. E d B. E d C. InP InT D. E d E 1 d 2 wb‡Pi Z‡_¨i wfwˇZ 22-23 bs cÖ‡kœi DËi `vI : 22. hw` 0 we›`y‡Z wefe k~b¨ nq Z‡e PZz_© †K․wYK we›`y‡Z PvR© q4= KZ? [kvgmyi m¨vi] A. -8C B. +8C C. +12C D. +32C q4 = – (6+14–12) = – 8C 23. q2 I q4 PvR© `ywUi ga¨eZ©x e‡ji gvb KZ n‡e? [kvgmyi m¨vi] A. 27×10-13N B. 27×10-5N C. 27×105N D. 27×1013N F = 9109 4 32 10 ( 8)( 12) = 271013N 24. 1V Zwo”PvjK e‡ji GKwU e¨vUvwii mv‡_ GKwU aviK mshy³ Kivq hw` avi‡Ki 0.1J kw³ mwÂZ nq Z‡e avi‡K Kx cwigvY Avavb Rgv n‡e? [nvwjg m¨vi] A. 0.02C B. 0.2C C. 2C D. 20C Q = 2u v = 2 0.1 1 = 0.2 25. AšÍiK c`v_© Af¨šÍ‡i Zwor w؇giæi mij •iwLK nIqvi cÖfve‡K ejv nqÑ [nvwjg m¨vi] A. aviKZ¡ B. miY †f±i C. †cvjvivB‡Rkb D. Zwor cÖvej¨ Ans C STEP 4 MCQ CONCEPT TEST WRITTEN cÖkœ 01. mgvb aviK‡Z¡i `ywU avi‡Ki mgvšÍivj ms‡hvRbx‡Z _vKvKvjxb mgZzj¨ aviKZ¡ Zv‡`i †kÖwYe×fv‡e _vKvKvjxb mgZzj¨ aviK‡Z¡iA. 1 4 ¸Y B. 4 ¸Y C. 1 2 ¸Y D. 2 ¸Y 02. GKwU mgvšÍivj cvZ avi‡Ki aviKZ¡ 4F| cvZ `ywUi g‡a¨ GKwU AšÍiK c`v_© cÖ‡ek Kiv‡j aviKZ¡ 80F nq| AšÍiK gva¨gwUi Zwor gva¨gv¼ KZ? A. 10 B. 15 C. 20 D. 25 03. GKwU avi‡Ki `ywU cv‡Zi g‡a¨ wefe cv_©K¨ V Ges avi‡K mwÂZ kw³ U| avi‡Ki wefe cv_©K e„w× K‡i 3V Kiv n‡j, mwÂZ kw³ e„w× †c‡q KZ n‡e? A. 3U B. 6 U C. 9 U D. 27 U 04. 4μF Gi 4wU aviK †kÖwY‡Z ms‡hvM Kiv n‡jv| Zv‡`i mgZzj¨ aviKZ¡ KZ n‡e? A. 1 μF B. 2 μF C. 4 μF D. 16 μF 05. `ywU Pv‡R©i ga¨Kvi Kzj¤^ ej 10-3N . PvR© `ywU wظY `~i‡Z¡ mwi‡q wb‡j †gvU ej n‡eÑ A. wØMyY B. A‡a©K C. Pvi fv‡Mi GK fvM D. †lvj fv‡Mi GK fvM 06. GKwU mgvšÍivj cvZ aviK‡K PvwR©Z Kivi d‡j cvZ؇qi g‡a¨ wefe cv_©K¨ n‡j V| wefe cv_©K¨ KZ n‡j avi‡Ki mwÂZ kw³ wظb n‡e? A. V 4 1 B. V 2 1 C. 2V D. 2V 07. we`y¨‡Zi †¶‡Î abPvR© I FYPvR© †K bvgKiY K‡ib? A. Kzj¤^ B. d¨viv‡W C. †eÄvwgb d«v¼wjb D. Ing A C1 C3 B C2
ASPECT PHYSICS wØZxq cÎ w¯’iZwor 467 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 08. c„w_exi wef‡ei gvb KZ? A. 220v B. Amxg C. 311v D. 0 v 09. `yÕwU 2 F aviK‡K wmwi‡R mshy³ Kivi d‡j mgZzj¨ avi‡Ki aviKZ¡ n‡eÑ A. 4 F B. 1 F C. 0.5 F D. 2 F 10. Avavb I wef‡ei ¸Yd‡ji GKK wK? A. Ryj B. †fvë C. d¨vivW D. †nbwi 11. hw` a e¨vmva© wewkó `yÕwU cwievnx †MvjK‡K hv‡`i GKwU‡Z +Q Avavb Av‡Q, Ab¨wU‡Z †Kvb Avavb †bB, ci®úi ms¯ú‡k© Avbv nq, Zvn‡j P~ovšÍ wefe KZ? A. a Q 8 0 1 B. a Q 0 4 1 C. a Q 0 2 1 D. None 12. 18 cm e¨vmva©wewkó GKwU duvcv †MvjKxq cwievnx‡Z Pv‡R©i cwigvb 10-2 C| †Mvj‡Ki c„ôZ‡j wefe KZ? A. 0 V B. 50 V C. 200 V D. 500 V 13. †Kvb Zwor †¶‡Îi cÖvej¨ KZ n‡j †mLv‡b GKwU B‡jKUªb Zvi IR‡bi mgvb ej Abyfe Ki‡e? A. 5.5710–11 NC1 B. 1.610–19 NC1 C. 9.110–31 NC1 D. 9.810–10 NC1 14. GKwU avi‡K 320C PvR© cÖ`vb Ki‡j Dnvi wefe 8v nq| Dnvi aviKZ¡ KZ? A. 1 40F B. 60 F C. 40F D. 90F 15. GKwU mylg Zwor †¶‡Î 25cm e¨eav‡b Aew¯’Z `yÕwU we›`yi wefe cv_©K¨ 150V| Zwor †¶‡Îi cÖvej¨ KZ? A. 600 Vm1 B. 60Vm1 C. 600Vm D. 600Vcm1 16. eRªcv‡Zi mgq 30C PvR© 1.0108 v wefe cv_©‡K¨i g‡a¨ 2.010-2 s mg‡q wbtmwiZ nq| H eRªwbbv‡`i mv‡_ Aegy³ kw³i cwigvb n‡jvA. 1.51011J B. 3.0109 J C. 6.0107 J D. 3.3106 J 17. 0.2F GKwU K¨vcvwmUi‡K Ggbfv‡e PvR© Kiv n‡jv †hb †cø‡Ui we`y¨r wefe 100v nq| GB mwÂZ Pv‡R©i kw³ KZ? A. 0.001J B. 100J C. 10J D. 0.0001J 18. `ywU PvwR©Z e¯‘ ci¯ú‡ii mv‡_ mshy³ Ki‡i Pv‡R©i cÖevn †Kvb w`‡K n‡e Zv †Kvb wel‡qi Dci wbf©i K‡i? A. Pv‡R©i cwigvY B. Zwor †¶Î C. Zwor cÖvej¨ D. Zwor wefe 19. GKwU avi‡Ki `ywU cv‡Zi g‡a¨ wefe cv_©K¨ V Ges avi‡K mwÂZ kw³ U| avi‡Ki wefe cv_©K e„w× K‡i 3V Kiv n‡j, mwÂZ kw³ e„w× †c‡q KZ n‡e? A. 3U B. 6 U C. 9 U D. 27 U 20. cix¶K Avav‡bi gvb n‡jvÑ A. 0C B. 1C C. Gi †P‡q †ekx D. gvb B”Qvaxb OMR SHEET 07. A B C D 14. A B C D 01. A B C D 08. A B C D 15. A B C D 02. A B C D 09. A B C D 16. A B C D 03. A B C D 10. A B C D 17. A B C D 04. A B C D 11. A B C D 18. A B C D 05. A B C D 12. A B C D 19. A B C D 06. A B C D 13. A B C D 20. A B C D WRITTEN PART 21. GKwU mgvšÍivj cvZ avi‡Ki cÖwZwU cv‡Zi c„‡ôi †¶Îdj 2.0m2 Ges evqy gva¨‡g cvZ؇qi ga¨eZ©x `~iZ¡ 0.02m| aviKwUi aviKwUi aviKZ¡ KZ? DËi:....................................................................................... 22. 0.01mGes 0.03m e¨vmv‡a©i `ywU †MvjK‡K ci¯ú‡ii c„ô n‡Z 0.20m `~i‡Z¡ ivLv n‡jv| cÖ‡Z¨K †MvjK‡K 100C PvR© cÖ`vb Kiv n‡j Zv‡`i g‡a¨ KZ ej wµqv Ki‡e? DËi:....................................................................................... 23. nvB‡Wªv‡Rb cigvYyi B‡jKUªb I †cÖvU‡bi ga¨eZ©x `~iZ¡ 0.53A n‡j Zv‡`i ga¨Kvi AvKl©Y ej KZ n‡e? DËi:....................................................................................... 24. 106N/C gv‡bi GKwU mylg Zwor‡ÿ‡Î ¯’vwcZ GKwU B‡jKUª‡bi Z¡iY KZ? DËi:....................................................................................... 25. 10-6C Ges 2×10-6C gv‡bi `yBwU Avavb we›`y ci¯úi n‡Z 10cm `~‡i Aew¯’Z| Avavb `ywUi ms‡hvMKvix †iLvi †Kvb we›`y‡Z Zwor cÖvej¨ k~Y¨ n‡e? DËi:....................................................................................... 26. evZv‡m 100C PvR© n‡Z 1m `~‡i †Kvb we›`y‡Z •e`y¨wZK cÖvej¨ KZ? DËi:....................................................................................... 27. mgAvKv‡ii AvUwU cvwbi †dvUv‡K GKwÎZ Ki‡j eo †MvjvKvi †dvUv Drcv`b nq I mgcwigvY mgag©x Avavb _v‡K, ZLb eo †dvUvi wefe n‡et DËi:....................................................................................... 28. GKwU mgvšÍivj cvZ avi‡K Pv‡R©i cwigvY 25C| hw` cÖwZwU cv‡Zi Kvh©Kix †¶Îdj 5cm2 nq Zwor †¶‡Î Zwor d¬v· NbZ¡ KZ n‡e Zv wbY©q Ki| DËi:....................................................................................... 29. 20A Gi PvR© wenxb GKwU K¨vcvwmUv‡ii g‡a¨ w`‡q 4A Zwor cÖevn (wW.wm) 3 wgwj‡m‡K‡Ûi Rb¨ cÖevwnZ Kiv n‡jv| K¨vcvwmU‡ii `yB cv‡Zi wefe cv_©K¨ wbY©q Ki? DËi:....................................................................................... 30. wZbwU avi‡Ki aviKZ¡ h_vµ‡g 3F, 2F Ges 1F| G‡`i wØZxq I Z…ZxqwU‡K †kÖwYe×fv‡e mvwR‡q cÖ_gwUi mv‡_ mgvšÍiv‡j hy³ Kiv n‡j Zzj¨ aviKZ¡ KZ? DËi:....................................................................................... MCQ ANSWER ANALYSIS WRITTEN cÖkœ bs DËi e¨vL¨v 01 B Cp = C1 + C2 = 2C C = Cp 2 1 Cs = 1 C + 1 C = 2 C = 1 Cp Cp = 4Cs 02 C Ko = 80 4 = 20 03 C 2 1 2 1 2 V V U U ev, U2 = U v v 2 3 = 9U 04 A Cs = C n = 4 4 = 1F
468 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES cÖkœ bs DËi e¨vL¨v 05 C 10 N 4 1 F 4 1 F 2 1 F d d F 3 2 1 2 2 1 2 06 C 2 2 1 E CV EαV2 [GKwU avi‡Ki Rb¨ C w¯’i] V V E E V 2 1 1 2 2 07 C we`y¨‡Zi †¶‡Î abPvR© I FYPvR© †K bvgKiY K‡ib †eÄvwgb d«v¼wjb| 08 D c„w_exi wef‡ei gvb 0| 09 B mgZzj¨ avi‡Ki aviKZ¡ n‡eÑ 2 2 2 + 2 = 1 10 A PvR© ¯’vbvšÍ‡ii K…ZKvR, W=VQ 11 A ms¯ú‡k©i ci cÖwZwU‡Z Avavb 2 Q a Q F a Q F 0 8 0 1 2 4 1 12 D †Mvj‡Ki c„ôZ‡j wefe, Volt r q V 500 0.18 10 9 10 4 1 2 9 0 13 A •e`y¨wZK cÖve‡j¨i gvb, 11 1 19 31 5.57 10 NC 1.6 10 9.1 10 9.8 q mg q F E 14 C C = v q = 8 320 = 40F 15 D 1 600 0.25 150 v m D v E 16 B w = Qv = 301.0108 = 3109 j 17 D Ep = 2 2 1 cv = 2 1 0.210-6 (102 ) 2 = 0.001j 18 D 19 C 2 1 2 1 2 V V U U ev, U2 = U v v 2 3 = 9U 20 B 21 0.02 8.854 10 2 d A C 12 0 8.85 10 F 10 22 F = 9 × 109 × 2 1 2 d Q Q = 2.25 × 1015N 23 Kzj‡¤^i m~Î †_‡K Rvwb, 2 1 2 0 r q q 4 1 F 2 9 1 2 r q q 910 = 10 2 2 19 9 (0.53 10 ) 1.6 10 9 10 = 8.2 10 N 8 24 E= q ma a= m qE = 31 19 6 9.1 10 1.6 10 10 = 17 1.810 ms-2 25 x = 1 2 q q 1 d = 10 1 + 2 × 10–6 10–6 = 10 2.41 = 4.14 26 9 11 1 2 9 9 10 1 100 9 10 9 10 NC r q E 27 Rvwb, V = 1 40 q r AZGe, V1 V2 = q1 q2 r2 r1 q1 q2 3 v2 v1 = 1 8 3 8 1 = 1 8 2 = 1 4 V2 = 4V1 28 = Q A = 25C 510–4m 2 = 5 104 Cm–2 = 50 kCm–2 29 V = q c V = 3 × 10–3 × 4 20 × 10–6 V = 600V 30 CS = (2–1 +1–1 ) –1 = 3 2 Cp = 3 + 3 2 = 3.67
ASPECT PHYSICS wØZxq cÎ Pj Zwor 469 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES SURVEY TABLE Kx coe? †Kb coe? †Kv_v n‡Z coe? KZUzKz coe? TOPICS MAGNETIC DECISION [hv co‡e] MAKING DECISION [†h Kvi‡Y co‡e] VVI For This Year DU JU RU CU GST Engr. HSC Written MCQ THEORY CONCEPT-01 eZ©bxi mvaviY welqvw` 20% 30% 10% 10% 40% 5% 35% - CONCEPT-02 †iv‡ai wbf©ikxjZv 15% 20% 10% 15% 20% 55% 25% - CONCEPT-03 Ry‡ji Zvcxq wµqvi m~Î 15% 20% 20% 10% 30% - 40% CONCEPT-04 we`y¨r cÖevngvÎv Ges Zvob‡eM 16% 10% 15% 10% 15% - 35% - CONCEPT-05 Zwo”PvjK ej Ges Af¨šÍixY †iva 50% 60% 65% 60% 70% 60% 65% CONCEPT-06 wKk©‡di m~Î 60% 65% 50% 55% 60% 70% 75% CONCEPT-07 c‡UbwkIwgUvi, ûBU‡÷vb eªxR I kv›U msµvšÍ 40% 45% 50% 40% 45% - 60% CONCEPT-08 A¨vwgUvi I †fvëwgUvi msµvšÍ 15% 20% 15% 10% 20% - 70% - CONCEPT-09 Kvjvi †KvW (wm‡jev‡m bvB Z‡e cÖkœ Avm‡Z cv‡i) 20% 10% 15% 5% 10% 10% 30% - MvwYwZK cÖ‡qvM CONCEPT-01 Zwor cÖevn, Zvob †eM, cÖevn NbZ¡ msµvšÍ MvwYwZK cÖ‡qvM 65% 70% 75% 70% 70% - 30% CONCEPT-02 Av‡cw¶K †iva I †iva msµvšÍ 55% 60% 55% 60% 65% 50% 75% CONCEPT-03 In‡gi m~Î, Zwor cÖevn I wefe cv_©K¨ msµvšÍ 65% 70% 65% 60% 70% 60% 70% CONCEPT-04 we`y¨r cÖev‡n Drcbœ Zvc I •e`y¨wZK ÿgZv msµvšÍ MvwYwZK cÖ‡qvM 80% 85% 80% 70% 80% 70% 80% CONCEPT-05 we`y¨r wej msµvšÍ MvwYwZK cÖ‡qvM 40% 50% 40% 30% 50% 60% 80% CONCEPT-06 †iv‡ai mgevq Ges Zzj¨‡iva msµvšÍ MvwYwZK cÖ‡qvM 80% 70% 75% 70% 80% 85% 90% CONCEPT-07 GKK †iv‡ai ga¨ w`‡q Zwor cÖevn, wefe cv_©K¨ Ges VDR, CDR msµvšÍ MvwYwZK cÖ‡qvM 70% 74% 70% 75% 80% 90% 80% CONCEPT-08 M¨vjfv‡bvwgUvi I kv›U msµvšÍ MvwYwZK cÖ‡qvM 65% 70% 70% 75% 70% 70% - CONCEPT-09 wKk©‡di m~‡Îi cÖ‡qvM msµvšÍ MvwYwZK cÖ‡qvM 60% 65% 60% 65% 70% 80% 50% CONCEPT-10 mvwK©U msµvšÍ MvwYwZK cÖ‡qvM 90% 85% 80% 80% 90% 70% 70% DU. = Dhaka University, JU. = Jahangirnagar University, RU. = Rajshahi University, CU = Chittagong University, GST = General, Science & Technology, Engr. = Engineering. STEP 1 mvRv‡bv me Z_¨ THEORY fwZ© †ivMxi c_¨ Concept 1 eZ©bxi mvaviY welqvw` ✅ Zwor cÖevn: †Kv‡bv cwievnxi ga¨w`‡q ‡Kv‡bv wbw`©ó w`‡K gy³ Pv‡R©i cÖevn nj Zwor cÖevn| msÁv: ‡Kv‡bv cwievnxi ‡h ‡Kvb cÖ¯ ‡”Q‡`i wfZi w`‡q PvR© cÖev‡ni nvi‡K (GKK mg‡q ‡h cwigvY PvR© ev B‡jKUªb cÖevwnZ nq) we`y¨r cÖevn gvÎv ev ïay we`y¨r cÖevn e‡j| cÖKvk: Zwor/we`y¨r cÖevn gvÎv, I = PvR© cÖev‡ni nvi = cÖevwnZ PvR© e¨wqZ mgq = Q t GKK: Ampere (A) A¨vw¤úqvi: cwievnxi ‡Kv‡bv cÖ¯ ‡”Q` w`‡q Awfj¤^fv‡e 1 ‡m‡K‡Û 1 Kzj¤^ PvR© cÖevwnZ n‡j ‡h cÖevngvÎv cvIqv hvq Zv nj 1 A¨vw¤úqvi| 1A = 1Cs –1 ✅ A¨vw¤úqv‡ii AvšÍR©vwZK fv‡e M„nxZ msÁv: k~b¨¯ v‡b ci®ú‡ii ‡_‡K GK wgUvi `~‡i Aew¯ Z Amxg •`‡N©¨i `ywU mgvšÍivj cwievnxi cÖ‡Z¨KwU‡Z mgvb ‡h gvÎvi we`y¨r cÖev‡ni d‡j ci®ú‡ii g‡a¨ cÖwZ wgUvi •`‡N©¨ 210–7N ej cÖ‡qvM Ki‡e Zv‡K GK A¨vw¤úqvi ejv nq| ✅ GKwU cwievnxi wfZi w`‡q abvZ¡K PvR© †h w`‡K AMÖmi nq ‡mUvB we`y¨r cÖev‡ni AwfgyL e‡j aiv nq| ✅ ‡iva: cwievnxi ‡h a‡g©i Rb¨ Gi ga¨ w`‡q Zwor cÖevn evav cÖvß nq Zv n‡jv cwievnxi ‡iva| ✅ GKK: IÕg (ohm, ) mgxKiY: 1 = 1V 1A = 1VA –1 Pj Zwor CURRENT ELECTRICITY wØZxq cÎ 03 Aa¨vq c„ôv 469
470 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ✅ cwievwnZv: ‡iv‡ai wecixZ ivwk nj cwievwnZv (conductance) cÖKvk: G GKK: mho ev simens(s) ev (ohm)–1 mgxKiY G = 1 R ✅ mgxKiY: G = 1 R ✅ †ivavsK ev Av‡cw¶K ‡iva: wbw`©ó ZvcgvÎvq GKK ‣`N©¨ I GKK cÖ¯ ‡”Q‡`i ‡¶Îdj wewkó ‡Kv‡bv cwievnxi ‡iva‡K ‡ivavsK ev Av‡cw¶K ‡iva ejv nq| ✅ mgxKiY: R = L A ev = RA L = Rr 2 L cÖKvk: GKK: ohm – m ev – m REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF JU QUESTION 01. †h me c`v‡_©i ZvcgvÎv evo‡j †iva ev‡o Zv‡`i e‡j? [JU: 2011-12] A. AšÍiK B. Aa©cwievnx C. cwievnx D. ‡KvbwUB bq Ans C 02. Zwor cwievnxi D`vniY wn‡m‡e wb‡Pi †KvbwU mwVK bq? [JU: 2011-12] A. †jvnv, †gvg, Aå B. gvwU, ¶vi, gvbe‡`n C. †jvnv, †mvbv, MÜK D. Zvgv, †mvbv, KvV Ans D 03. eyb‡mb ‡Kvl n‡jv- [JU: 2011-12] A. GK cÖevnx B. wØ-cÖevnx C. wÎ-cÖevnx D. GKwUI bq Ans B 04. ‡KvbwU ev¯Í‡e cvIqv hvq bv? [JU: 2010-11] A. Aa©cwievnx e¯‧ B. c~Y© `„p e¯‧ C. cwievnx e¯‧ D. AwZ cwievnx e¯‧ Ans D 05. GKwU wbw`©ó ZvcgvÎvi bx‡P †h me c`v‡_©i †iva k~b¨ nq †hme c`v_©‡K ejv nq? [JU: 2009-10] A. Acwievnx B. mycwievnx C. Kzcwievnx D. AwZcwievnx Ans B STEP 02 ANALYSIS OF RU QUESTION 01. GKwU Av`k© e¨vUvwii Avf¨šÍixY †iva KZ Ing? [RU: 2017-18] A. Amxg B. - Amxg C. k~b¨ D. ‡KvbwUB bq Ans C 02. ZvcgvÎv e„wׇZ Aa©cwievnxi †iva- [RU: 2011-12, 2007-08] A. e„w× cvq B. n«vm cvq C. AcwiewZ©Z _v‡K D. †KvbwUB bq Ans B STEP 03 ANALYSIS OF CU QUESTION 01. •e`y¨wZK wnUv‡i †h avZe Zv‡ii KzÛjx e¨eüZ nq Zvi bvg wK? [CU: 2009-10; 2006-07] A. Uvs‡÷b B. gvBKv C. bvB‡µvg D. Zvgv E. †fbvwWqvg Ans C 02. `ywU wfbœ c`v‡_©i •Zix avZe Zv‡ii `yB cÖvšÍ hy³ K‡i GKwU eÜ eZ©bx •Zix K‡i ms‡hvM ¯’j `ywU‡K wfbœ ZvcgvÎvq ivL‡j GKwU Zwor PvjK kw³i D™¢e nq Ges eZ©bxi ga¨ w`‡q Zwor cÖevn Pj‡Z _v‡K| G‡K ejv nqÑ [CU: 2006-07] A. mx‡eK wµqv B. ‡cjwkqvi wµqv C. _gmb wµqv D. ZvcZwor wµqv E. d¨viv‡W wµqv Ans A 03. Zwor we‡køl‡Yi e¨envwiK cÖ‡qvM n‡”QÑ [CU: 2006-07] A. Zwor cÖ‡jcb B. B‡jK‡UªvUvBwcs C. avZz wb®‥vkb D. avZz †kvab E. me¸‡jv Ans E STEP 04 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. †Kvb we`y¨r‡Kv‡l ivmvqwbK wµqvi d‡j Zvi `yB †giæi g‡a¨ †h wefe cv_©K¨ Drcbœ nq Zv‡K wK ejv nq? [KU: 2015-16] A. wefe wefvRK B. †iva C. Zwo”PvjK ej D. †Kv‡li †kÖwY mgevq Ans A 02. wm‡gÝ wK‡mi GKK? [KU: 2012-13] A. Av‡cw¶K †iva B. cwievnxZv¼ C. aviKZ¡ D. cwievnxZv Ans D CoU 01. d¨viv‡Wi aªæe‡Ki gvb- [CoU: 2012-13] A. 10500C B. 90000C C. 96500C D. 50000C Ans C IU 01. ‡Kvb cwievnxi •`N©¨ L Ges †iva R n‡j wb‡Pi †Kvb m¤úK©wU mwVK? [IU: 2015-16] A. RL B. R1/L C. RL 2 D. R1/L2 Ans A 02. Zwor cÖev‡ni w`K †KvbwU? [IU: 2015-16] A. B‡j±ªb cÖev‡ni w`‡K B. †cÖvUb cÖev‡ni wecixZ w`‡K C. B‡j±ªb cÖev‡ni wecixZ w`‡K D. ‡cÖvUb cÖev‡ni w`‡K Ans C 03. _v‡g©vB‡jw±ªK cÖwµqvq we`y¨r Drcv`‡b cÖ‡qvRb nq- [IU: 2012-13] A. cvwbi ‡mªvZ B. UvievBb C. Zvc D. _gmb wµqv Ans C BRUR 01. †h cwigvY Avavb †Kvb ‡g․‡ji 1gm Zzj¨vsK fi gy³ K‡i Zv‡K wK ejvnq? [BRUR: 2013-14] A. wm‡gÝ B. Kzj¤^ C. A¨vw¤úqvi D. d¨viv‡W Ans D 02. ‡gvevB‡ji e¨vUvwi wK ai‡bi †Kvl w`‡q •Zix? [BRUR: 2013-14] A. cÖv_wgK ‡Kvl B. ‡g․wjK †Kvl C. ‡M․Y †Kvl D. ï®‥ †Kvl Ans C PART B Analysis of Science & Technology Question SUST 01. ZvcgvÎv evovi mv‡_ mv‡_ †Kvb&wUi we`y¨r cwievwnZv ev‡o? [SUST: 2012-13,JSTU 15-16] A. Al B. Fe C. Ag D. Si E. Cu Ans D MBSTU 01. wefe cv_©‡K¨i GKK †KvbwU? [MBSTU 13-14] A. A¨vw¤úqvi B. ‡fvë C. wm‡gÝ D. IÕg Ans B BSMRSTU 01. 1 d¨vivW A_© wK? [BSMRSTU: 2014–15] A. 1 Coul/V B. 1 Amp/V C. 1 Cal D. 1 wefe Ans A HSTU 01. ZvcgvÎv e„w× Ki‡j cwievnxi cwievwnZv wKiƒ‡c cwiewZ©Z nq? [HSTU: 2015-16] A. n«vm cvq B. e„w× cvq C. AcwiewZ©Z _v‡K D. wظY nq Ans A STEP 05 ANALYSIS OF HSC BOARD QUESTION 01. GKwU Zvi‡K †U‡b j¤^v Ki‡j- [Xv. †ev. 2021] i. Av‡cwÿK †iva e„w× cvq ii. †iva e„w× cvq iii. †iva n«vm cvq wb‡Pi †KvbwU mwVK? A. i B. ii C. i I ii D. i I iii Ans B 02. wb‡Pi †Kvb GKKwU PvR© cÖev‡ni nvi cwigv‡ci GKK? [Xv. †ev. 2015, iv. †ev. 17] A. volt B. ampere C. watt D. ohm Ans B 03. wi‡qv‡÷‡Ui cÖZxK †KvbwU? [e. †ev. 2015] A. B. C. D. Ans B
ASPECT PHYSICS wØZxq cÎ Pj Zwor 471 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 2 †iv‡ai wbf©ikxjZv ✅ avZzi g‡a¨ iæcvi †iva me‡P‡q Kg| ✅ ï¯‥ Ae¯’vq gvby‡li kix‡ii †iva 50,000 Ges wfRv Ae¯’vq 10,000 ✅ †iv‡ai wbf©ikxjZv: LATE L A T E Length Area Temperature Element ✅ †Kvb cwievnxi †iva 4wU wel‡qi Dci wbf©ikxj| •`N©¨ [R L] cÖ¯ ‡”Q‡`i †ÿÎdj [R l A ; R l r 2] ZvcgvÎv cwievnxi Dcv`vb| ✅ •e`y¨wZK wdDR : msÁv AwZwi³ Zwor cÖev‡ni Kvi‡Y hš¿cvwZ bó ev `~N©Ubv cÖwZ‡iva Kivi Rb¨ eZ©bx‡Z †kÖwY mgev‡q Kg Mjbv‡¼i †h cwievnx Zvi hy³ Kiv nq| MVb Dcv`vb wb¤œ Mjbv¼ wewkó msKi avZz e¨envi Kiv nq| mvaviYZ wZb fvM wmmv I GK fvM wU‡bi wgkÖ‡Y msKi avZz wdDR Zvi wn‡m‡e e¨envi Kiv nq| wmmv I wU‡bi wgkÖ‡Yi •Zwi Zv‡ii Mjbv¼ 300 †m. Gi Kg| Kvh©c×wZ AwZwi³ Zwor cÖevwnZ n‡j ZviwU Mig nq Ges M‡j wM‡q we`y¨r mieivn eÜ K‡i †`q| †iv‡ai Dci ZvcgvÎvi cÖfve cwievnx Aa©cwievnx aYvZ¥K (+ve) FYvZ¥K (–ve) T evo‡j, R ev‡o, I K‡g T evo‡j, R K‡g, I ev‡o cwievnx D”P ZvcgvÎvq Aa©cwievn‡Ki g‡Zv AvPiY K‡i| D”PZvcgvÎvq Aa©cwievnx cwievnxi g‡Zv AvPiY K‡i| T Kg‡j, R K‡g, I ev‡o T Kg‡j, R ev‡o, I K‡g cwievnx wb¤œ ZvcgvÎvq AwZcwievnK (Super-conductor) Gi g‡Zv AvPiY K‡i| wb¤œ ZvcgvÎvq Aa©cwievnx AšÍi‡Ki g‡Zv AvPiY K‡i| ✅ †iv‡ai ZvcgvÎv ¸YvsK ev DòZv ¸YvsK: cÖwZ wWMÖx †mjwmqvm ZvcgvÎv e„w×i Rb¨ GKK ‡iva m¤úbœ ‡Kvb cwievnxi ‡iv‡ai ‡h cwieZ©b nq Zv‡K D³ cwievnxi †iv‡ai ZvcgvÎv ¸YvsK ev DòZv ¸YvsK e‡j| ✅ GKK: (C)–1 ev K –1 ✅ g¨v½vwb‡Ri ‡iv‡ai DòZv mnM = 310–5K –1 ✅ Aa© cwievnxi ‡iv‡ai DòZv mnM = – 610–2 (°C)–1 ✅ _vwg©óvi Gi mvnv‡h¨ Lye Aí ZvcgvÎvi cwieZ©b (0.005°C) wbY©q Kiv hvq| ✅ AwZ wbgœ ZvcgvÎvq cwievnxi ‡iva cÖvq k~b¨ gvb jvf K‡i| cwievnxi G Ae¯ v‡K AwZcwievnxZv e‡j| –290°C ZvcgvÎvq cvi` AwZcwievnx wnmv‡e KvR K‡i| ✅ bvB‡µvg (wb‡Kj, ‡j․n Ges ‡µvwgqv‡gi msKi avZz) g¨v½vwbR Gi ZvcgvÎvi cwieZ©‡b ‡iv‡ai Lye Kg cwieZ©b N‡U| REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. GKwU Zvgvi Zv‡ii •`N©¨ 2m I e¨vm 5mm| hw` ZviwUi •`N©¨ wظY I e¨vm A‡a©K Kiv nq Z‡e ZviwUi Av‡cw¶K †iv‡ai Kx cwieZ©b n‡e? [DU: 2016–17] A. Av‡cw¶K †iva A‡a©K n‡e B. Av‡cw¶K †iva GKB _vK‡e C. Av‡cw¶K †iva wظY n‡e D. Av‡cw¶K †iva Pvi¸Y n‡e Av‡cw¶K †iva nq cwievnxi Dcv`v‡bi| GKB Dcv`v‡bi Av‡cw¶K †iva cwiewZ©Z nq bv| STEP 02 ANALYSIS OF JU QUESTION 01. GKwU †iv‡ai GK cÖv‡šÍ GKwU e¨vUvixi abvZ¥K cÖvšÍ jvMv‡bv i‡q‡Q| Ab¨ GKwU †iva †kÖwY ms‡hv‡M GB †iv‡ai mv‡_ jvwM‡q e¨vUvixi FYvZ¥K cÖvšÍ jvMv‡bv i‡q‡Q| †KvbUvi g‡a¨ abvZ¥K PvR© ev †nvj cÖevn n‡e? [JU-A, Set-A. 19-20] A. cÖ_g †iva B. wØZxq †iva C. Df‡qi †fZi D. †KvbwUB bq e¨vUvwi †_‡K †iv‡ai g‡a¨ abvZ¥K PvR© ev †nvj cÖevwnZ nq bv| 02. In‡gi m~Î cÖ‡hvR¨ bq- [JU. 2015-16, JKKNIU-B, Set-3, 19-20] A. Aa© cwievnx‡Z B. Gwm eZ©bx‡Z C. wWwm eZ©bx‡Z D. cwievnx‡Z Ans C 03. †iva wb‡Pi †Kvb wel‡qi Dci wbf©i K‡i bv? [JU. 2018-19] A. Dcv`vb B. ‣`N©¨ C. Zwor cÖevn D. cÖ¯ ‡”Q‡`i †ÿÎdj Ans C STEP 03 ANALYSIS OF RU QUESTION 01. ZvcgvÎv w¯’i _vK‡j †KvbwU In‡gi m~Î? [RU: 2018-19] A. I = V B. V = R C. V = I D. V = IR Ans D 02. wb‡¤œi †Kvb †¶‡Î †iv‡ai gvb AcwiewZ©Z _vK‡e? [RU: 17-18; DU: 00-01] A. Both length and cross sectional area are doubled B. Both length and radius are doubled C. Only the length is increased D. Cross sectional area is reduced Ans A 03. `ywU cix¶vq Zvgvi •Zwi `ywU Zvi A I B Gi Av‡cw¶K †iva wfbœ cvIqv †Mj, Gi A_©- [RU: 2014-15] A. A I B Gi •`N©¨ wfbœ B. A I B Gi cÖ¯ ‡”Q‡`i †¶Îdj wfbœ C. cwi¶v `ywU wfbœ ZvcgvÎvq Kiv n‡q‡Q D. †KvbwUB bq Ans D 04. In‡gi m~Î †KvbwU? [RU: 2012-13] A. V = I 2R B. I = V1 – V2 R 2 C. U = 1 2 CV 2 D. IR = (V1–V2) Ans D 05. ZvcgvÎv e„w× †c‡j Kve©‡bi †iva- [RU: 2006-07] A. e„w× cvq B. n«vm cvq C. AcwiewZ©Z _v‡K D. †KvbwU bq Ans B
472 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES STEP 04 ANALYSIS OF CU QUESTION 01. In‡gi myÎ wb‡¤œi †KvbwUi †ÿ‡Î cÖ‡hvR¨ b‡n? [CU-A, Set-1. 20-21] A. w`K cwiewZ© cÖevn eZ©bx B. cwievnx C. Aa©-cwievnx D. ZvcgvÎv cwieZ©bkxj cwievnx S D info GKwU wbw`©ó ZvcgvÎvq wbw`©ó †Kv‡bv cwievnxi ga¨ w`‡q †h Zwor cÖevn P‡j Zv cwievnxi `yB cÖv‡šÍi wefe cv_©‡K¨i mgvbycvwZK| 02. cÖwZ‡iva ÿgZvi GKK Kx? [CU-A, Set-3. 20-21] A. Ohm B. ohm-m C. Mho D. Siemen Ans A 03. Av‡cwÿK †iv‡ai GKK Kx? [CU-A, Set-3. 20-21, 15-16, 14-15] A. m B. m –1 C. m 2 D. m –2 Ans A STEP 05 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. K¶ ZvcgvÎvq bx‡Pi †KvbwUi Av‡cw¶K †iva †ekx? [KU: 2011-12] A. †jvnv B. Rvg©vb wmjfvi C. bvB‡µvg D. cvi` Ans C 02. cÖwZ wWMÖx †mw›U‡MÖW DòZv e„wׇZ GKK †iva m¤úbœ †Kvb cwievnxi †iv‡ai †h cwigvY cwieZ©b nq Zv‡K e‡j cwievnxwUi- [KU: 2001-02] A. Av‡cw¶K †iva B. Zzj¨ †iva C. †iv‡ai DòZv ¸YvsK D. †iv‡ai m~Î Ans C CoU 01. ZvcgvÎv evo‡j ‡iva e„w× cvq- [CoU: 2015-16] A. cwievn‡Ki B. Aa©cwievn‡Ki C. AšÍi‡Ki D. mevi †iva e„w× cvq Ans A IU 01. GKwU Zvi‡K `yB fv‡M fvM Ki‡j- [IU: 2015-16, e.†ev. 2021] A. ‣e`y¨wZK ¸bvejx bó n‡q hvq B. Av‡cw¶K †iva GKB _v‡K C. †iva I Av‡cwÿK †iva A‡a©K D. †iva GKB _v‡K Ans B 02. †iv‡ai wecixZ ivwk‡K ejv nq- [IU: 2010-11, Xv.†ev. 2021] A. A¨vWwgU¨vÝ B. mvm‡mcU¨vÝ C. cwievwnZvsK D. cwievwnZv Ans D 03. mvavibZ weï× cwievnxi †iva msKi avZzi †iv‡ai †P‡q- [IU: 2012-13] A. Kg B. ‡ewk C. mgvb D. m¼i avZzi †iva †bB Ans A weï× cwievnxi †iva Kg, msKi cwievnxi †iva †ekx| BRUR 01. hLb †Kvb mvwK©‡Ui ga¨ w`‡q AC cÖevwnZ nq ZLb G cÖev‡n evav cÖ`vb K‡i †KvbwU? [BRUR: 2013-14] A. ‡iva B. aviK C. Av‡ekK D. me¸‡jv Ans A PART B Analysis of Science & Technology Question JUST 01. In‡gi m~‡Î w¯’i _v‡K †KvbwU? [JSTU 15-16] A. Zwor cÖevn B. ZvcgvÎv C. wefe cv_©K¨ D. †iva E. mgq Ans B MBSTU 01. ZvcgvÎv, Dcv`vb I •`N©¨ w¯’i _vK‡j cwievnxi †iva Gi cÖ¯’‡”Q‡`i †¶Îd‡ji- [MBSTU: 2013-14] A. mgvbycvwZK B. e¨¯ÍvbycvwZK C. e‡M©i mgvbycvwZK D. e‡M©i e¨¯ÍvbycvwZK Ans B PUST 01. Kv©eb ¸ovi Dci Pvc e„w× †c‡j Gi †iva n«vm cvq GB ag© e¨eüZ nq †Kvb h‡š¿? [PUST. 13-14] A. B‡j±ªwbK Nwo B. gvB‡µv‡dvb C. Kw¤úDUvi cÖ‡mmi D. †Rbv‡iUi Ans B PSTU 01. wb‡Pi †Kvb ivwkwU cwigv‡c wgUvi eªxR e¨eüZ nq? - [PSTU: 2013-14] A. aviKZ¡ B. cÖevn C. wefe D. †iva Ans D STEP 06 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. cÖ¯’‡”Q‡`i ‡¶Îdj wظY Kiv n‡j †iva wK cwigvY n‡e? [MAT: 2014-15] A. A‡a©K B. wZb¸Y C. wظY D. Pvi¸Y R2 R1 = A1 A2 ev, R2 R1 = 1 2 ev, R2 = 1 2 R1 A‡a©K 02. †Kvb cwievnxi †iva wK‡mi Dci wbf©ikxj bv- [MAT: 2013-14] A. ZvcgvÎv B. Dcv`vb C. cÖ¯ ‡”Q‡`i †¶Îdj D. Pvc Ans D 03. †iv‡ai mgevq KZ cÖKvi? [MAT: 2003-04] A. 1 cÖKvi B. 2 cÖKvi C. 3 cÖKvi D. 4 cÖKvi Ans B 04. †iv‡ai †ejvq †Kvb Dw³wU mwVK bq? [MAT:2000-01] A. cwievn‡Ki †iva Zvi Dcv`v‡bi Dci wbf©i K‡i| B. wbw`©ó ZvcgvÎvq wbw`©ó Dcv`v‡bi cwievn‡Ki ‣`N¨© w¯ i _vK‡j cwievn‡Ki †iva Zvi cÖ¯ ‡”Q‡`i †¶Îd‡ji mgvbycv‡Z cwiewZ©Z nq C. wbw`ó© ZvcgvÎvq wbw`©ó Dcv`v‡bi cwievn‡Ki ‣`N¨© w¯ i _vK‡j cwievn‡Ki †iva Zvi cÖ¯ ‡”Q‡`i †¶Îd‡ji e¨¯Ívbycv‡Z cwiewZ©Z nq| D. wbw`©ó ZvcgvÎvq wbw`©ó Dcv`v‡bi cwievn‡Ki cÖ¯ ‡”Q‡`i †¶Îdj w¯ i _vK‡j cwievn‡Ki †iva Zvi ‣`‡N¨©i mgvbycv‡Z cwiewZ©Z nq| Ans B DAT 01. Zv‡ii †iva e„w×i Rb¨ wb‡Pi †KvbwU `vqx? [DAT: 2018-19] A. Zv‡ii •`N©¨ K‡g †M‡j B. Zv‡ii cÖ¯ ‡”Q‡`i †¶Îdj e„w× †c‡j C. Zv‡ii AvqZb e„w× †c‡j D. Zv‡ii DòZv e„w× †c‡j Ans D STEP 07 ANALYSIS OF HSC BOARD QUESTION 01. A¨vjywgwbqv‡gi DòZv mnM n‡jvÑ [Xv. †ev. 2015] A. 1.65 10–3 (C)–1 B. 3.25 10–3 (C)–1 C. 3.9 10–3 (C)–1 D. 4.5 10–3 (C)–1 Ans C 02. wb‡Pi †KvbwUi †iv‡ai DòZv mnM FYvZ¥K? [iv. †ev. 15; e. †ev. 15; Kz. †ev. 15] A. Zvgv B. wcZj C. A¨vjywgwbqvg D. wmwjKb Ans D 03. wb‡Pi †Kvb †jLwPÎwU In‡gi m~Î †g‡b P‡jÑ [P. †ev. 2021; g. †ev. 2021] A. B. C. D. l V l V l V l V Ans A 04. ZvcgvÎvq mv‡_ cwievn‡Ki †iv‡ai cwieZ©b wb‡Pi †Kvb †jLwPÎwU wb‡`©k K‡i? [P. †ev. 2017, h.†ev. 2016] A. B. C. D. O R R R R 0C O O O 0C 0C 0C Ans C 05. IÕn‡gi m~Î Abymv‡i wb‡Pi MÖv‡di Xvj †Kvb ivwk wb‡`©k K‡i? [w`. †ev. 2021] O I (Zwor cÖevn) V (wefe cv_©K¨) P A. †iva B. Av‡cwÿK †iva C. cwievwnZv D. cwievwnZvsK Ans A 06. †Kv‡bv cwievn‡Ki †ivaÑ [h. †ev. 2015] i. ZvcgvÎv evo‡j e„w× cvq ii. •`N©¨ evo‡j e„w× cvq iii. cÖ¯ ‡”Q‡`i †ÿÎdj evo‡j e„w× cvq wb‡Pi †KvbwU mwVK? Ans A A. i I ii B. ii I iii C. i I iii D. i, ii I iii 07. GKwU bjvKvi Zvgvi Zv‡ii †iva R| AvqZb mgvb †i‡L ZviwUi •`N©¨ wظY Kiv n‡j cwiewZ©Z †iva KZ? [Kz. †ev. 2015; DU. 2014-15] A. 2R B. 4R C. 8R D. R/2 R L
ASPECT PHYSICS wØZxq cÎ Pj Zwor 473 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 08. GKwU cwievnx Zv‡ii •`N©¨ wظY I cÖ¯’‡”Q‡`i †ÿÎdj A‡a©K Ki‡j Dnvi †iva n‡e? [g. †ev. 2021] A. A‡a©K B. wظY C. Pvi¸Y D. cwieZ©b n‡e bv Ans D 09. wbw`©ó wefe cv_©K¨hy³ †Kv‡bv cwievnx Zvi‡K †U‡b •`N©¨ wظY Ki‡jÑ [e. †ev. 2015] i. cÖ¯ ‡”Q` evo‡e ii. cÖevn Kg‡e iii. Drcbœ Zvc Kg‡e wb‡Pi †KvbwU mwVK? Ans C A. i I ii B. i I iii C. ii I iii D. i, ii I iii 10. †Kv‡bv Zv‡ii Av‡cwÿK †iva wbf©i K‡i hvi DciÑ [mKj †ev. 2018] i. Zv‡`i •`‡N©¨i ii. Zv‡ii ZvcgvÎv iii. Zv‡ii Dcv`v‡bi wb‡Pi †KvbwU mwVK? Ans C A. i B. ii C. ii I iii D. i, ii I iii Concept 3 Ry‡ji Zvcxq wµqvi m~Î ✅ ‡Rgm ‡cÖmKU Ryj 1841 mv‡j wZbwU m~Î cÖ`vb K‡ib| 1. we`y¨r cÖevn gvÎvi (i) m~Î: we`y¨r evnx cwievnxi ‡iva R I we`y¨r cÖevn Kvj t AcwiewZ©Z _vK‡j cwievnx‡Z we`y¨r cÖev‡ni `iæb D™¢~Z Zvc we`y¨r cÖevn gvÎvi e‡M©i mgvbycvwZK| H I 2 , hw` R Ges t w¯ i _v‡K| 2. †iv‡ai m~Î (R): we`y¨r cÖevn gvÎv I we`y¨r cÖevn Kvj AcwiewZ©Z _vK‡j cwievnx‡Z we`y¨r cÖev‡ni `iæb D™¢~Z Zvc cwievnxi †iv‡ai mgvbycvwZK| H R, hw` I Ges t w¯ i _v‡K| 3. mg‡qi m~Î: we`y¨revnx cwievnxi ‡iva Ges we`y¨r cÖevn gvÎv AcwiewZ©Z _vK‡j cwievnx‡Z we`y¨r cÖev‡ni `iæb D™¢~Z Zvc we`y¨r cÖevn Kv‡ji mgvbycvwZK| H t, hw` I Ges R w¯ i _v‡K| ✅ Ry‡ji 3wU m~Î GKÎ K‡i cvB, H I 2Rt H = I2Rt Ryj H = 0.24I2Rt K¨vjix| ✅ Zv‡ci hvwš¿K mgZzj/hvwš¿K mgZv: GKK Zvc Drcbœ Ki‡Z ‡h cwigvY KvR Ki‡Z nq ev GKK Zvc Øviv ‡h cwigvb KvR Kiv hvq Zv‡K Zv‡ci hvwš¿K mgZzj/mgZv ejv nq| cÖKvk: J gvb: 4.2J/cal ✅ K¨vjwi: GK MÖvg weï× cvwbi ZvcgvÎv GK wWwMÖ ‡mjwmqvm (1°C) e„w× Ki‡Z cÖ‡qvRbxq Zvc‡K GK K¨vjwi (1 cal) e‡j| 1 Ryj = 0.24 K¨vjwi| 1 K¨vjwi = 4.2 Ryj| ✅ Zv‡ci hvwš¿K mgZv wbY©‡qi c×wZ: 1. Ry‡ji c×wZ I 2. K¨v‡jÛvi ev evY©m Gi c×wZ| ✅ ‣e`y¨wZK kw³: ‡Kvb cwievnxi ga¨ w`‡q •e`y¨wZK PvR© ev Avavb †cÖib Ki‡Z ‡Kvb •e`y¨wZK hš¿ ev Drm‡K ‡h KvR Ki‡Z nq Zv‡K H Dr‡mi •e`y¨wZK kw³ e‡j| ✅ ‣e`y¨wZK kw³, EP = W = VQ = VIt ✅ GKK: Ryj| (1 Ryj = 1 ‡fvë 1 A¨vw¤úqvi 1 ‡m‡KÛ) ✅ ‣e`y¨wZK ¶gZv: ‡Kvb •e`y¨wZK hš¿ ev Dr‡mi KvR Kivi nvi‡K A_©vr GKK mg‡q m¤úvw`Z KvR‡K D³ h‡š¿i ¶gZv e‡j| ✅ cÖKvk: P ✅ mgxKiY: P = W t = VI = EI = I2R = V 2 R ✅ GKK: IqvU = Ryj ‡m‡KÛ = J s 1 Hp = 746 watt 1 k Wh = 3.6106 j ✅ wK‡jvIqvU N›Uv‡K ‡evW© Ae ‡UªW (B.O.T) GKK ev e¨emvwqK GKK ev mvaviYZ BDwbU (unit) ejv nq| REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. GKwU •e`y¨wZK evwZi gva¨‡g we`y¨r kw³‡K iƒcvšÍwiZ K‡i cvIqv hvq- [DU: 2002-03] A. ïay Zvckw³ B. ïay Av‡jvK kw³ C. Zvckw³ I Av‡jvK kw³ D. cvigvYweK kw³ Ans C STEP 02 ANALYSIS OF JU QUESTION 01. wbw`©ó cwievwn‡Z wbw`©ó mgq a‡i Zwor cÖevwnZ Ki‡j m„ó Zv‡ci cwigvc n‡e cÖevwnZ Zwor Gi- [JU: 2018-19] A. e‡M©i e¨¯ÍvbycvwZK B. e¨¯ÍvbycvwZK C. mgvbycvwZK D. e‡M©i mgvbycvwZK Drcbœ Zvc, H = I2Rt 02. ZvcgvÎv w¯’i _vK‡j †Kvb wbw`©ó cwievn‡Ki ga¨ w`‡q †h Zwor cÖevn P‡j Zv cwievn‡Ki `yB cÖv‡šÍi wefe cv_©‡K¨i- [JU: 2013-14, KU. 10-11] A. e¨¯ÍvbycvwZK B. e‡M©i mgvbycvwZK C. mgvbycvwZK D. ‡KvbwUB bq Ans C 03. Zvc Drcv`‡b Ry‡ji cÖ_g m~Î †KvbwU ? [JU: 2011-12] A.H i B. H i 2 C. H 2 1/i2 D. H 2 i Ans B 04. K¨vjix I Ry‡ji g‡a¨ m¤úK© nj- [JU: 2011-12, CU. 12-13] A. 1 Cal = 2.4 J B. 1 Cal = 4.2 J C. 1 J = 4.2 Cal D. 1 J = 2.4 Cal Ans B 05. Amgfv‡e DËß †Kvb cwievnx‡Z Zwor cÖevn Pvjbv Ki‡j cwievwn‡Z †Kv_vI Zv‡ci D™¢e Ges †Kv_vI Zv‡ci †kvlY nq G‡K e‡j? [JU: 2010-11, KU. 10-11, RU. 09-10] A. ‡cvjwkqvi wµqv B. _gmb wµqv C. Ry‡ji m~Î D. mx‡eK µxqv Ans B STEP 03 ANALYSIS OF CU QUESTION 01. ‡Kvb cwievnxi ga¨ w`‡q Zwor cÖev‡ni d‡j Drcbœ Zv‡ci ivwkgvjv | [CU: 2016–17] A. H = V2Rt B. H = R2Vt C. H = IRt D.H = I2Rt E.H = I2R 2 t Ans D 02. wK‡jvIqvU-NÈvi mv‡_ Ry‡ji m¤úK©- [CU: 2014-15 ] A. 1kWh= 550J B. 1kWh=746 C.1kWh=3.6×106 J D.1kWh=9.8 J E. 1kWh=3.6×105 J Ans C STEP 04 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. wb‡¤œi †Kvb evK¨wU mwVK? [JnU: 2011-12] A. Zvc cÖ‡qv‡Mi d‡j Aa©cwievnxi I cwievnxi †iva K‡g B. Zvc cÖ‡qv‡Mi d‡j Aa©cwievnxi I cwievnxi †iva ev‡o C. Zvc cÖ‡qv‡Mi d‡j Aa©cwievnxi †iva K‡g I cwievnxi †iva ev‡o D. Zvc cÖ‡qv‡Mi d‡j Aa©cwievnxi †iva ev‡o I cwievnxi †iva K‡g Ans C
474 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES KU 01. †KvbwU Ry‡ji Zvcxq wµqvi m~Î bq? [KU. 2018-19] A. HI 2 B. HR C. HI 2Rt D. HkI2Rt Ans D 02. `ywU wfbœ avZzi •Zwi GKwU Zvc we`y¨r hyM‡ji ga¨ w`‡q we`y¨r cÖevn Pvjbv Ki‡j Zvc we`y¨r hyM‡ji ms‡hvM ¯’‡j Zvc D™¢~Z ev †kvwlZ nIqv‡K e‡j- [KU: 2009-10] A. mx‡eK wµqv B. _gmb wµqv C. wbi‡c¶ D. Zvc wµqv E. ‡cjwkqvi wµqv Ans B BRUR 01. ZvcgvÎv e„w× Ki‡j cwievnxZv ev‡o- [BRUR: 2013-14] A. Rv‡g©wbqv‡gi B. ‡jvnvi C. Zvgvi D. iƒcvi Ans A PART B Analysis of Science & Technology Question PUST 01. 1 B.O.T Unit = KZ Ryj? [PUST: 2013-14] A. 56×105 B. 36×105 C. 35×105 D. 55×105 1B.O.T = 3.6106 j = 36105 HSTU 01. mx‡eK wµqvi wecixZ Zvc we`y¨r wµqv‡K wK e‡j? [HSTU: 2015-16] A. _gmb wµqv B. gvBg¨vb wµqv C. ‡cjwkqvi wµqv D. Ry‡jwig wµqv Ans C NSTU 01. †KvbwU Ry‡ji m~·K mg_©b K‡i bv? [NSTU-A, 19-20] A. H t B. H i C. H i D. H R H = i2Rt H i 2 BSFMSTU 01. Zvc MwZwe`¨vi cÖ_g m~Î Abyhvqx- [BSFMSTU-A, 19-20] A. W = J+2H B. W = JH C. J/H D. W = J2 ZvcMwZwe`¨vi 1g m~Ît hLb KvR m¤ú~Y©iƒ‡c Zv‡c ev Zvc m¤ú~Y©iƒ‡c Kv‡R iƒcvšÍwiZ nq ZLb KvR I Zvc ci¯ú‡ii mgvbycvwZK| W H W = JH; J Zv‡ci hvwš¿K mgZv| STEP 05 ANALYSIS OF ENGINEERING & BUTex QUESTION BUET 01. ‡Kvb ZvchyM‡ji Rb¨ wb‡Pi gšÍe¨¸‡jvi g‡a¨ †KvbwU mwVK bq? [BUET: 2011-12] A. ‡Kvb GKwU wbw`©ó Zvc hyMj †m‡Ui Rb¨ wbi‡c¶ ZvcgvÎv w¯ i _v‡K| B. wbi‡c¶ ZvcgvÎv kxZj ms‡hv‡Mi ZvcgvÎvi Dci wbf©i K‡i bv C. Drµg ZvcgvÎv kxZj ms‡hv‡Mi ZvcgvÎvi Dci wbf©i K‡i bv D. wbi‡c¶ ZvcgvÎvq m‡e©v”P Zvcxq Zwor PvjK kw³ (thermo e.m.f) cvIqv hvq Ans C STEP 06 ANALYSIS OF MEDICAL & DENTAL QUESTION DAT 01. Zvc‡K wb¤œ ZvcgvÎv †_‡K D”P ZvcgvÎvq cvVv‡bvi cÖwµqv‡K wK e‡j? [DAT: 2018-19] A. wngvqb B. jxb Zvc C. Zvc BwÄb D. wngvqK Ans A STEP 07 ANALYSIS OF HSC BOARD QUESTION 01. Ry‡ji Zvc Drcv`b msµvšÍ Z„Zxq m~·K wb‡Pi †Kvb †jLwPÎ w`‡q cÖKvk Kiv hvq? [Xv. †ev. 2021] A. H t B. H t C. H t D. H t S A info H i 2 Rt ; H t [i, R Constant] g~jwe›`yMvgx n‡e| 02. cv‡ki wP‡Î cÖ`wk©Z eZ©bxi †KejgvÎ †iv‡ai gvb cwieZ©‡b Zv‡Z Drcbœ Zv‡ci cwieZ©b wb‡Pi †Kvb †jLwPÎ mwVKfv‡e Dc¯’vcb K‡i?[iv. †ev. 2016] A. B. C. D. H R H R H R H R H R 03. hw` wbw`©ó cwievwn‡Z wbw`©ó mgq a‡i Zwor cÖevwnZ nq Z‡e Drcbœ Zv‡ci cwigvY n‡e, cÖevwnZ Zwo‡Zi wb‡Pi †KvbwU? [w`. †ev. 2015] A. e‡M©i e¨¯ÍvbycvwZK B. e¨¯ÍvbycvwZK C. mgvbycvwZK D. e‡M©i mgvbycvwZK Ans D H I 2 04. hw` wbw`©ó cwievn‡K wbw`©ó mgq a‡i Zwor cÖevwnZ Ki‡j m„ó Zv‡ci cwigvY n‡e cÖevwnZ Zwo‡Zi- wb‡Pi †KvbwU? [w`. †ev. 2015] A. e‡M©i e¨¯ÍvbycvwZK B. e¨¯ÍvbycvwZK C. mgvbycvwZK D. e‡M©i mgvbycvwZK Ans D 05. †Kv‡bv cixÿvq e¨eüZ GKwU cwevnxi †iva R1| Gi ga¨ w`‡q I1 gv‡bi Zwor cÖevn t mgq a‡i Pjvq H1 cwigvY Zvc Drcbœ n‡jv| G‡ÿ‡Î wb‡Pi †Kvb m~ÎwU cÖ‡hvR¨? [Kz. †ev. 2016] A. H1 = I1R1 2 t B. H1 = I1 2R1t C. H1 = I1R1t 2 D. H1 = I1 2R1 2 t Ans B 06. R ohm †ivawewkó †Kv‡bv cwievnxi ga¨ w`‡q i amp we`y¨r tmgq a‡i cÖevwnZ n‡j Drcbœ Zvc n‡e- [Kz. †ev. 2016] A. 0.24 I2Rt cal B. VI Joule C. I 2R Joule D. V R t Joule S A info H = 0.24 I2 RT 07. we`y¨r cÖev‡ni d‡j Drc‡bœi †ÿ‡Î Ry‡ji cÖevnKv‡ji m~‡Îi iƒc †KvbwU? [gv.†ev. 18] A. H I 2 B. H R C. H t D. H t 2 Ans C 08. Zv‡ci hvwš¿K mgZvi GKK n‡jv- [mKj †evW© 2018] A. K¨vjwi/MÖvg B. Ryj/K¨vjwi C. K¨vjwi/Ryj D. Ryj-K¨vjwi Ans B Concept 4 we`y¨r cÖevngvÎv Ges Zvob‡eM ✅ we`y¨r cÖevngvÎv ✅ B‡j±ªb wb¤œ wefe †_‡K D”P wef‡ei w`‡K hvq| ✅ Zwor cÖevn/Kv‡i›U D”P wefe †_‡K wb¤œ wef‡ei w`‡K hvq| I Vd wb¤œwefe D”Pwefe Vd = I nAe ✅ Zvob‡eM: B‡jKUªb cwievnxi †fZ‡i (av°v †L‡Z †L‡Z) †hB Mo‡eM AMÖmi nq, Zv‡K Zvob‡eM e‡j| I = n. A. Vd.e– GKK AvqZ‡b gy³ e – msL¨v cÖ¯ ‡”Q‡`i †ÿÎdj, A = r 2 Zvob‡eM e – Gi PvR© –1.610–19 Coulomb
ASPECT PHYSICS wØZxq cÎ Pj Zwor 475 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. wb‡Pi wgwkÖZ GKK ¸wji g‡a¨ †KvbwU IqvU Gi mgZzj¨ bq? [DU: 2013-14] A. Joul/sec B. (Amp)(Volt) C. (Amp2 )() D. 2 /Volt. IqvU Gi mgZzj¨ GKK : Joul/sec, Amp×Volt, Amp2 ×, Volt2 / STEP 02 ANALYSIS OF JU QUESTION 01. Zwor cÖev‡ni mv‡_ †P․¤^K †ÿ‡Îi m¤úK© wbY©q K‡i- [JU-A, Set-A. 19-20] A. A¨vw¤úqv‡ii m~Î B. cwievwnZvi m~Î C. †d‡ivPz¤^K D. †KvbwUB bq A¨vw¤úqv‡ii m~Î: †Kv‡bv e× c_ eivei †Kv‡bv †P․¤^K †ÿ‡Îi •iwLK mgKvjb, c_wU Øviv †ewóZ †ÿÎd‡ji †fZi w`‡q cÖevwnZ †gvU cÖevngvÎvi 0 ¸Y| 02. `ywU cwievnx‡Z wecixZgyLx Zwor cÖevn ci¯úi‡K- [JU: 2010-11, PUST: 2014–15] A. weKl©Y K‡i B. AvKl©Y K‡i C. †Kvb ej wµqv K‡i bv D. †KvbwUB bq Ans B 03. 1 A¨vw¤úqvi-N›Uv = ? [JU: 2009-10] A. 36 C B. 360 C C. 3600 C D. 360000 C Ans C STEP 03 ANALYSIS OF CU QUESTION 01. Gm.AvB. c×wZ‡Z Zwor cÖev‡ni GKK- [CU: 2014–15] A. Kzj¤^ B. ‡fvë C. A¨vw¤úqvi D. mx‡gÝ E. d¨vivW Ans C STEP 04 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. wb‡Pi †KvbwU Zwor we‡køl‡Yi e¨envwiK cÖ‡qvM bq? [KU: 2015-16] A. eøK I g‡Wj •Zwi Kiv B. g~j¨evb avZzi Dci cÖ‡jc †`qv C. Zwor cÖevn wbY©q Kiv D. avZz wb®‥vkb Kiv Ans C 02. •e`y¨wZK ev‡j¦ †h miæ avZe Zvi _v‡K Zv †Kvb c`v_© w`‡q •Zwi?[KU: 2009-10] A. Uvs‡÷b B. bvB‡µvg C.Zvgv D. cøvwUbvg Ans A IU 01. I = Anve Zwor cÖev‡ni m~Î n‡j Zwor cÖevn NbZ¡ n‡e- [IU: 2011-12] A. ni v/e B. nvi / A C nve D. ne Ans B BRUR 01. Zvob †eM I cÖevn Nb‡Z¡i m¤úK© n‡jv- [BRUR: 2012-13] A. v = j ne B. v = j ne C. v = I Ane D. v = JA ne Ans C STEP 05 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. †Kvb GK‡Ki ms‡KZ mwVK? [MAT: 2016-17] A.PvR©-W B. Zwor cÖevn- A C. wefe- C D. Zwor ivmvqwbK Zzj¨v¼- JS –1 Ans B STEP 06 ANALYSIS OF HSC BOARD QUESTION 01. cÖevn Nb‡Z¡i GKK Kx? [Xv. †ev. 2016] A. Am B. Am–1 C. Am–2 D. Am–3 Ans C 02. †Zvgvi K‡j‡R w`K cwieZ©x •e`y¨wZK mieivn jvB‡bi K¤úv¼ KZ? [Xv. †ev. 2016] A. 50 Hz B. 100 Hz C. 150 Hz D. 220 Hz Ans A 03. †Kv‡li Af¨šÍixY †iva e„w× †c‡j eZ©bxi Zwor cÖevngvÎvÑ [Kz. †ev. 2021] A. mgvbycv‡Z ev‡o B. mgvbycv‡Z K‡g C. e¨¯Ívbycv‡Z K‡g D. e¨¯Ívbycv‡Z ev‡o Ans C Concept 5 Zwo”PvjK ej Ges Af¨šÍixY †iva ✅ Zwo”PvjK ej: 1. ewn:eZ©bxi ms‡hvM wew”Qbœ Ae¯ vq ‡Kv‡li `yB cÖv‡šÍi m‡e©v”P wefe cv_©K¨‡K Zwo”PvjK ej e‡j| 2. ‡h PvwjKv kw³ eZ©bx‡Z we`y¨r cÖevn eRvq iv‡L Zv‡K Zwo”PvjK ej e‡j| 3. cÖwZ GKK Avavb‡K ‡Kvl m‡gZ ‡Kv‡bv eZ©bxi GK we›`y ‡_‡K m¤ú~Y© eZ©bx Nywi‡q Avevi H we›`y‡Z Avb‡Z †h KvR m¤úbœ nq A_©vr †Kvl †h Zwor kw³ mieivn K‡i Zv‡K H †Kv‡li Zwo”PvjK kw³ e‡j| cÖKvk: E GKK: ‡fvë (volt) = Ryj Kzj¤^ = J c mgxKiY: E = IR + Ir ev, I = E R + r ✅ Af¨šÍixb ‡iva: ‡Kv‡li Af¨šÍ‡i we`y¨r cÖevn ‡h cwigvb evav cvq Zv‡K ‡Kv‡li Af¨šÍixb ‡iva e‡j| cÖKvk: r ✅ wKQzK_v: A¨vwgUvi: †Kvb •e`y¨wZK eZ©bxi we`y¨r cÖevngvÎv mivmwi (A¨vw¤úqv‡i) cwigvc Kiv nq| †fvëwgUvi: †Kvb eZ©bxi `yB cÖv‡šÍi ev †h †Kvb As‡ki g‡a¨ wefe cv_©K¨ mivmwi (†fv‡ë) cwigvc Kiv nq| gvwëwgUvi: †Kvb eZ©bx‡Z we`y¨r cÖevngvÎv, eZ©bxi `yB cÖv‡šÍi wefe cv_©K¨ Ges †Kvb cwievnxi †iva gvcv hvq| M¨vjfv‡bvwgUvi: †Kvb cwievnxi we`y¨r cÖev‡ni Aw¯ Z¡ I cwigvc Kiv hvq| ✅ †R‡b ivLv fvj cwievnxi †iv‡ai DòZv ¸bvs‡Ki gvb abvZ¡K Ges Aa©cwievnxi †¶‡Î Zv FbvZ¡K e¨eüZ †iva‡Ki AwaKvskB Kve©b †h․M; AwZ cwievnxZv : cvi`- 2690 C ; mxmv- 2660 C; GKvwaK(cell) †Kvl wb‡q e¨vUvwi MwVZ; B‡jKUªb wbgœ wefe †_‡K D”P wef‡ei w`‡K cÖevwnZ nq; Zwor cÖevn D”P wefe n‡Z wbgœ wef‡ei w`‡K cÖevwnZ nq; ZvcgvÎv e„w× †c‡j Aa©cwievnxi †iva n«vm cvq; ï¯‥ Ae¯ vq gvby‡li kix‡ii †iva 50,000 Ges wfRv Ae¯ vq 10,000 |
476 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF JU QUESTION 01. ‡Kvb ZvchyM‡ji DËß ms‡hvM ¯’‡j ‡h we‡kl ZvcgvÎvq Zvcxq ZworPvjK kw³ m‡ev©”P nq, Zv‡K wK e‡j? [JU: 2013-14] A. wbi‡c¶ ZvcgvÎv B. Drµg ZvcgvÎv C. µvwšÍ ZvcgvÎv D. cig k~b¨ ZvcgvÎv Ans B 02. eZ©bx †Lvjv Ae¯’vq †Kv‡li `yB cÖv‡šÍi wefe cv_©K¨ H †Kv‡li ZworPvjK kw³i †P‡qÑ [JU: 2011-12, IU. 12-13] A. mgvb B. Amgvb C. †QvU D. eo Ans A 03. ZworPvjK kw³ I cÖev‡ni ga¨ m¤úK© †KvbwU? [JU: 2011-12] A. I = R r E B. I = E R r C. I = r. R E D. I = r. E R Ans A STEP 02 ANALYSIS OF CU QUESTION 01. Zwo”PvjK ej (emf) Gi aviYv †`q †K? [CU-A, Set-1. 20-21] A. Oersted B. Faraday C. Lenz D. Kirchhoff S B info ZworPvjK ej Gi aviYv †`b gvB‡Kj d¨viv‡W| STEP 03 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. Zwor PvjK kw³i •ewkó¨ bq? [MAT: 2000-01] A. eZ©bxi ‡h †Kvb As‡k Ab¨ †Kvb kw³ Zwor kw³‡Z iƒcvšÍwiZ nq †m As‡k Zwor PvjK kw³ _v‡K| B. GK GKK Avavb‡K †Kvb cwievn‡Ki GK we›`y ‡_‡K Ab¨ we›`y‡Z ¯ vbvšÍwiZ Ki‡Z †h KvR m¤úbœ nq Zv‡K H we›`y؇qi Zwor PvjK kw³ e‡j| C. Zwor PvjK kw³ ‡Kv‡li ivmvqwbK wµqvi Dci wbf©i K‡i| D. †KvbwUB bq| Ans B STEP 04 ANALYSIS OF HSC BOARD QUESTION 01. Zwo”PvjK kw³i GKK n‡jvÑ [h. †ev. 2016] A. Ryj B. †fvë C. Kzj¤^ D. A¨vw¤úqvi Ans B 02. n msL¨K E-Zwor”PvjK e‡ji †Kvl‡K †kÖwY‡Z hy³ Ki‡j cÖevn i n‡e (†Kv‡li Avf¨šÍixY †iva r I ewnteZ©bxq †iva R)| [wm. †ev. 2021] A. i = nE R + nr B. i = nE nR + r C. i = nE nR + nr D. i = nE R + r n Ans A 03. †Kv‡bv wbivcËv wdDR Gi Mv‡q 5A wdDR †jLv _vK‡j Gi A_©Ñ [g. †ev. 2021; P. †ev. 2021] i. †Kv‡bv eZ©bx‡Z hy³ Ki‡j Zv 5A ch©šÍ Zwor cÖevn mn¨ Ki‡Z cv‡i ii. 5A Gi AwaK cÖevngvÎvq wdDR M‡j eZ©bx ms‡hvM wew”Qbœ K‡i iii. wdDRwU mieivn jvB‡bi mv‡_ mgvšÍiv‡j hy³ _v‡K wb‡Pi †KvbwUmwVK? A. iI ii B. iiI iii C. iI iii D. i, iiI iii Ans A Concept 6 wKk©‡di m~Î ✅ m~‡Îi bvg m~‡Îi eY©bv m~‡Îi e¨vL¨v i. cÖ_g m~Î (Kv‡i›U m~Î ev Rvskb Dccv`¨) we`y¨r eZ©bxi †Kvb ms‡hvM we›`y‡Z wgwjZ cÖevn¸‡jvi exRMvwYwZK †hvMdj k~b¨ nq| i1 i2 i3 i4 i5 i1 – i2 –i3–i4 + i5 = 0 i = 0 ii. wØZxq m~Î (eZ©bx m~Î ev †fv‡ëR m~Î ev jyc Dccv`¨) †Kvb e× eZ©bxi AšÍM©Z †gvU we`y¨r PvjK kw³ (e.m.f) H eZ©bxi wewfbœ kvLv¸‡jvi †iva Ges Zv‡`i ga¨ w`‡q cÖevwnZ mswkøó we`y¨r cÖevngvÎvi ¸Yd‡ji exRMvwYwZK †hvMd‡ji mgvb| i2 R2 R1 E i1 i1R1 + i2 R2 = E iR = E ✅ we‡kl Z_¨ : wKk©‡di m~‡Îi e¨envi we`y¨r cÖevn I wefe cv_©K¨ wbY©q| ûBU‡÷vb eªx‡R wKk©‡di m~‡Îi e¨envi| we`y¨r †Kv‡li †kÖwY mgev‡qi †ÿ‡Î wKk©‡di m~‡Îi e¨envi (we`y¨r cÖevn I wefe cv_©K¨ wbY©q)| we`y¨r †Kv‡li mgvšÍivj mgev‡q wKk©‡di m~‡Îi cÖ‡qvM (we`y¨r cÖevn I wefe cv_©K¨ wbY©q)| wKk©‡di m~Î I IÕ†gi m~‡Îi Zzjbv IÕ†gi m~‡Îi mvnv‡h¨ mij eZ©bxi we`y¨r cÖevngvÎv I †iva wbY©q Kiv hvq| wKk©‡di m~Î w`‡q mij I RwUj Dfq‡ÿ‡Î we`y¨r cÖevngvÎv I †iva wbY©q Kiv hvq| eZ©bxi ‡Kvl I PvR© mwÂZ ev m„wó n‡Z cv‡i bv| wKk©‡di 1g m~Î PvR© msi¶‡bi GKwU Dw³| †Kvb e× eZ©bx‡Z mKj wefe cZb Ges we`y¨r PvjK e‡ji exRMvwYwZK ‡hvMdj k~b¨ nq| In‡gi m~‡Îi mvnv‡h¨ mij eZ©bxi we`y¨r cÖevn gvÎv I †iva wbY©q Kiv hvq| wKk©‡di m~Î w`‡q mij I RwUj Dfq‡¶‡Î we`y¨r cÖevn gvÎv I ‡iva wbY©q Kiv hvq|
ASPECT PHYSICS wØZxq cÎ Pj Zwor 477 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF GST QUESTION PART A Analysis of General University Question BRUR 01. wb‡Pi †KvbwU Kvk©‡di 1g m~Î †K wb‡`©k K‡i- [BRUR: 2015-16] A. IR=E B. I=0 C. I = mE mR + 1 D. I = nE R + nr Ans B PART B Analysis of Science & Technology Question PUST 01. Kvk©‡di m~θ‡jv cÖ‡hvR¨- [PUST: 2013-14] A. Gwm I wWwm Df‡qi †¶‡Î B. ïaygvÎ Gwm Gi †¶‡Î C. ïaygvÎ wWwm Gi †¶‡Î D. †KvbwU bq Ans A STEP 02 ANALYSIS OF ENGINEERING & BUTex QUESTION CUET 01. Kvk©‡di m~θ‡jv †KvbwU? [CUET: 2010-11] A. I=0 and IR=0 B. IR=0 and I=E C. I=0 and IR=E D. R=0 and I=0 Ans C STEP 03 ANALYSIS OF HSC BOARD QUESTION 01. wKk©‡di cÖ_g m~‡Î I wØZxq m~‡Î †Kvb †Kvb †f․Z ivwk msiwÿZ _v‡K? [Kz. †ev. 2015] wKk©‡di cÖ_g m~Î wKk©‡di wØZxq m~Î A. kw³ PvR© B. kw³ fi‡eM C. PvR© kw³ D. fi‡eM kw³ Ans C wb‡Pi wPÎwU jÿ Ki Ges 02 bs cÖ‡kœi DËi `vI: G D C Q A P B R S 02. V wefe cv_©K¨wewkó †Kv‡bv cwievnxi †fZi w`‡q t mgq a‡i Q cwigvY Avavb cwievwnZ cwievwnZ n‡j Zwor ÿgZv P wb‡Pi †KvbwU?[wm. †ev. 2015] A. VQt B. V Qt C. VQ D. VQ t P = VI = VQ t Concept 7 c‡UbwkIwgUvi, ûBU‡÷vb eªxR I kv›U msµvšÍ c‡UbwkIwgUvi ✅ c‡UbwkIwgUvi : †h h‡š¿i Zv‡ii •`N©¨ eivei µgvMZ wefe cZb m„wó Kiv hvq Ges hvi mvnv‡h¨ †Kvb •e`y¨wZK †Kv‡li Zwor PvjK kw³ A_ev †Kvb •e`y¨wZK eZ©bxi †h †Kvb `yB we›`yi wefe cv_©K¨ wbb©q Kiv hvq Zv‡K c‡UbwkIwgUvi e‡j| ✅ hš¿ : 1 wgUvi j¤^v 10 wU g¨v½vwbR Gi Zvi ci®úi mgvšÍiv‡j web¨¯Í _v‡K| ✅ c‡UbwkI wgUv‡ii e¨envi: `ywU †Kv‡li Zwor PvjK kw³i Zzjbv, E1 E2 = L1 L2 ‡h †Kvb †Kv‡li Zwor PvjK kw³ wbb©q| Zwor †Kv‡li Af¨šÍixb †iva wbb©q : r = L1 – L2 L2 R ûBU‡÷vb eªxR ✅ ûBU‡÷vb eªxR: PviwU ‡iva ‡kªYxe×fv‡e mw¾Z K‡i GKwU Ave× jyc •Zix Ki‡j ‡h PviwU ms‡hvM¯ j •Zix nq, Zvi †h †Kv‡bv `ywU wecixZ ms‡hvM¯ ‡ji gv‡S GKwU we`y¨r ‡Kvl Ges Aci `ywU ms‡hvM¯ ‡ji gv‡S M¨vjfv‡bvwgUvi ms‡hvM w`‡j †h eZ©bx •Zwi nq Zv‡K ûBU‡÷vb eªxR e‡j| ✅ ûBU‡÷vb eªxR bxwZ e¨envi Kiv nq- wgUvi eªxR (Metre bridge) ‡cv÷ Awdm e· (Post office box) ✅ mvg¨ve¯ vq ûBU‡÷vb eªxR Gi wfZi w`‡q †Kv‡bv we`y¨r cÖevwnZ nq bv| ZvB M¨vjfv‡bvwgUv‡i we‡¶cI _v‡K bv| G‡K wb¯ú›` Ae¯ v ejv nq| ✅ m¨vgy‡qj nv›Uvi wµw÷ 1833 mv‡j ûBU‡÷vb eªxR Avwe¯‥vi K‡ib| ✅ m¨vi Pvj©m ûBU‡÷vb 1843 mv‡j Gi DbœwZ K‡i G‡K e¨envi Dc‡hvMx K‡ib| ✅ P Q = R S A_©vr mvg¨ve¯ vq M¨vjfv‡bvwgUv‡ii Dfq cÖv‡šÍi `yB cv‡k¦© hy³ ‡iva `ywUi AbycvZ mgvb n‡e| kv›U ✅ M¨vjfv‡bvwgUvi ev m~² I my‡e`x •e`y¨wZK h‡š¿i ga¨ w`‡q hv‡Z D”PgvÎvi we`y¨r cÖevwnZ n‡Z bv cv‡i Zvi Rb¨ h‡š¿i mv‡_ mgvšÍiv‡j ¯^í gv‡bi †h †iva hy³ Kiv nq Zv‡K kv›U e‡j| ✅ kv‡›Ui ‡iva k~b¨ n‡j mKj we`y¨r cÖevn kv‡›Ui ga¨ w`‡q hv‡e| ✅ kv‡›Ui ‡iva Amxg n‡j mKj cÖevn M¨vjfv‡bvwgUv‡ii ga¨ w`‡q hv‡e| ✅ G + S S †K kv‡›Ui ¸Yb ¶gZv ev kv‡›Ui ¸bK ejv nq| ✅ S = R n – 1 ✅ kv‡›Ui e¨envi: 1. kv‡›Ui e¨envwiK cÖ‡qvM †`Lv hvq A¨vwgUv‡i| 2. M¨vjfv‡bvwgUv‡ii we`y¨r cÖevngvÎv n«vm Kiv hvq I AwZ we`y¨r cÖevnRwbZ ¶wZi nvZ ‡_‡K i¶v Kiv hvq| 3. D”P we`y¨r cÖevngvÎv cwigv‡c G‡K e¨envi Kiv nq| ✅ †cv÷ Awdm e·, wgUvi eªxR I c‡UbwkIwgUv‡i me©`vB M¨vjfv‡bvwgUvi e¨envi Kiv nq| REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF JU QUESTION 01. M¨vjfv‡bvwgUv‡ii `yB cÖv‡šÍi mv‡_ mv›U e¨envi Kiv nq †Kb?[JU: 2010-11] A. Zwor cÖevn Kgv‡bvi Rb¨ B. Zwor cÖevn wbw®…q Kivi Rb¨ C. Zwor cÖevn e„w×i Rb¨ D.k~b¨ Zwor cÖev‡ni Rb¨ M¨vjfv‡bvwgUv‡ii `yB cÖv‡šÍi mv‡_ mv›U e¨envi Kiv nq Zwor cÖevn Kgv‡bvi Rb¨| STEP 02 ANALYSIS OF RU QUESTION 01. wK wbY©‡q c‡UbwkIwgUvi e¨eüZ nq bv- [RU. 2011-12] A. †iva wbY©‡q B. cÖevngvÎv wbY©‡q C. ZworPvjK kw³ wbY©‡q D. Pv‡R©i cwigvY wbY©‡q Ans D
478 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES STEP 03 ANALYSIS OF CU QUESTION 01. †Kvb myÎ e¨envi K‡i ûBU‡÷vb weªR bxwZ cÖwZcv`b Kiv hvq? [CU-A, Set-4. 20-21, 17-18] A.Kzj‡¤^i myÎ B.Kvk©‡di myÎ C.A¨vw¤úqv‡ii myÎ D.d¨viv‡Wi myÎ Ans B 02. ûBU‡÷vb weª‡Ri mvnv‡h¨ wK cwigvc Kiv nq? [CU: 2015-16] A. cÖevn B. Zwo”PvjK kw³ C. wefe cv_©K¨ D. †iva E. Zvc Ans D 03. ‡cv÷ Awdm e‡·i mvnv‡h¨ AÁvZ †iv‡ai gvb KZ `kwgK ¯’vb ch©šÍ wVK fv‡e wbb©q Kiv hvq? [CU: 2006-07] A. cuvP B. Pvi C. `yB D. wZb E. GK Ans C STEP 04 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. c‡UbwkIwgUvi †h bxwZi Dci KvR K‡i- [KU: 2013-14] A. ûBU‡÷vb weª‡Ri bxwZ B. wefe cZb c×wZ C. wefe wefvRb c×wZ D. †iv‡ai mgevq c×wZ Ans A 02. †h h‡š¿i mvnv‡h¨ wefe cv_©K¨ I Zwor PvjK kw³ cwigvc Kiv hvq Zv‡K e‡j- [KU: 2010-11, 2007-08] A. ‡fvë wgUvi B. A¨vwgUvi C. wiI÷¨vU D. c‡UbwkIwgUvi c‡UbwkIwgUv‡ii e¨envi (i) wefe cZb, (ii) we`y¨r PvjK ej, (iii) wefe cv_©K¨ wbY©q| PART B Analysis of Science & Technology Question MBSTU 01. ûBU‡÷vb weª‡Ri fvimv‡g¨i kZ© †KvbwU? [MBSTU: 2014–15, wm.‡ev: 15] A. P R = S Q B. P R = R Q C. P Q = R S D. P Q = S R Ans C STEP 05 ANALYSIS OF ENGINEERING & BUTex QUESTION BUET 01. L •`N¨© Ges R ‡iva wewkó GKwU c‡UbwkIwgUv‡ii Zv‡ii g‡a¨ Zwor cÖev‡ni gvÎv I n‡j wef‡ei cwieZ©‡bi nvi n‡e? [BUET: 10-11] A. L IR B. IRL C. I RL D. R IL Ans D STEP 06 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. wb‡Pi †Kvb h‡š¿i mvnv‡h¨ †QvUgv‡bi †iva I we`y¨”PvjK kw³ wbY©q Kiv hvq? [MAT: 2017-18] A. A¨vwgUvi B. M¨vjfv‡bvwgUvi C. ‡cv‡UbwkIwgUvi D. wgUvieªxR Ans C 02. M¨vjfv‡bvwgUv‡ii Zwor eZ©bx‡Z kv›U e¨envi Kiv nq Kx D‡Ï‡k¨? [MAT: 2018-19] A. M¨vjfv‡bvwgUv‡ii we`y¨r cÖevn evov‡bvi Rb¨ B. M¨vjfv‡bvwgUv‡ii we`y¨r cÖevn Kgv‡bvi Rb¨ C. M¨vjfv‡bvwgUv‡ii wefe cv_©K¨ evov‡bvi Rb¨ D. M¨vjfv‡bvwgUv‡ii wefe cv_©K¨ Kgv‡bvi Rb¨ Ans B DAT 01. †cv÷ Awdm e· hš¿wU wb‡Pi †Kvb Kv‡R e¨eüZ nq? [DAT: 2008-09] A. wefe cÖv_©K¨ cwigv‡c B. ‡cv÷ Awd‡m C. ‣e`y¨wZK †iva cwigv‡c D. we`y¨r cwigv‡c Ans C STEP 07 ANALYSIS OF HSC BOARD QUESTION 01. wb‡Pi †KvbwU kv‡›Ui ÿgZv ¸YK? [w`. †ev. 2021] A. (G + S)/G B. G/(G + S) C. S/(G + S) D. (G + S)/S Ans D 02. ûBU‡÷vb weªR bxwZi wfwˇZ cwiPvwjZ nqÑ [w`. †ev. 2021] i. †cv÷ Awdm e· ii. c‡UbwkIwgUvi iii. wgUviweªR wb‡Pi †KvbwUmwVK? A. i I ii B. ii I iii C. i I iii D. i, ii I iii Ans C 03. kv›U m¤ú‡K© mwVK mZ¨ †KvbwU? [w`. †ev. 2021] A. mgvšÍivj hy³ e„nr gv‡bi †iva B. mgvšÍivj hy³ ¯^í gv‡bi †iva C. †kÖwY‡Z hy³ ¯^í gv‡bi †iva D. †kÖwY‡Z hy³ e„nr gv‡bi †iva Ans B 04. †Kv‡li EMF Zzjbv Ki‡Z e¨eüZ nq †KvbwU? [w`. †ev. 2021] A. M¨vjfv‡bvwgUvi B. c‡UbwkIwgUvi C. wgUvi weªR D. †fvëwgUvi Ans B 05. †iva gvcvi hš¿ n‡jvÑ [w`. †ev. 2016] i. wgUvi weªR ii. †cv÷ Awdm e· iii. c‡UbwkIwgUvi wb‡Pi †KvbwU mwVK? Ans D A. i I ii B. i I iii C. ii I iii D. i, ii I iii 06. mv›U e¨eüZ nq †Kvb h‡š¿? [Kz. †ev. 2021] A. A¨vwgUvi B. †fvë wgUvi C. wgUvieªxR D. †cv÷ Awdm e· Ans A 07. mv›U mivmwi e¨envi Kiv nqÑ [wm. †ev. 2016] i. A¨vwgUvi-G ii. M¨vjfv‡bvwgUvi-G iii. †fvëwgUvi-G wb‡Pi †KvbwU mwVK? Ans A A. i I ii B. i I iii C. ii I iii D. i, ii I iii 08. G = M¨vjfv‡bvwgUv‡ii †iva Ges S = mv‡›Ui †iva n‡j mv›U aªæeKn‡e- [e. †ev. 2016; Kz. †ev. 2016] A. S G + S B. G + S S C. G G + S D. G + S G Ans B Concept 8 A¨vwgUvi I †fvëwgUvi msµvšÍ A¨vwgUvi ✅ A¨vwgUvi (Ameter) : †h h‡š¿i mvnv‡h¨ †Kvb eZ©bxi we`y¨r cÖevn gvÎv mivmwi A¨vw¤úqvi GK‡K cwigvc Kiv hvq Zv‡K A¨vwgUvi e‡j| ✅ eZ©bxi cÖevn gvÎv wbb©‡qi Rb¨ A¨vwgUvi‡K eZ©bxi mv‡_ †kªYx mgev‡q hy³ Kiv nq| ✅ GKwU PjKzÛjx M¨vjfv‡bv wgUvi (G) Gi KzÛjxi mv‡_ GKwU ¯^í gv‡bi †iva S mgvšÍiv‡j mshy³ K‡i A¨vwgUvi MVb Kiv nq| ✅ A¨vwgUv‡ii cvjøv e„w× : GKwU ¯^í cvjøvi A¨vwgUvi‡K †ekx cvjøvi A¨vwgUv‡i cwibZ Ki‡Z n‡j A¨vwgUv‡ii mv‡_ mgvšÍiv‡j AZ¨šÍ ¯^í gvÎvi †iva hy³ Ki‡Z nq| r = R n – 1 †fvëwgUvi ✅ †fvëwgUvi (Voltmeter) : †h h‡š¿i mvnv‡h¨ †h †Kvb `yÕwe›`yi ga¨Kvi wefe cv_©K¨ mivmwi †fvë GK‡K cwigvc Kiv hvq, Zv‡K †fvë wgUvi e‡j| G‡K eZ©bx‡Z mgvšÍivj mgev‡q mshy³ Ki‡Z nq| ✅ †fvë wgUvi n‡”Q GKwU M¨vjfv‡bv wgUvi hvi m‡½ GKwU D”P gv‡bi †iva †kªYx mgev‡q jvMvb _v‡K| ✅ †fvëwgUv‡ii cvjøv e„w× : GKwU ¯^í cvjøvi †fvë wgUvi‡K †ekx cvjøvi †fvë wgUv‡i cwibZ Ki‡Z n‡j h‡š¿i mv‡_ †kªYx mgev‡q Ggb GKwU †iva hy³ Ki‡Z n‡e hv‡Z h‡š¿i wfZi we`y¨r cÖev‡ni †Kvb cwieZ©b bv nq| S = R(n – 1)
ASPECT PHYSICS wØZxq cÎ Pj Zwor 479 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ✅ A¨vwgUvi I †fvëwgUv‡ii cv_©K¨: 1| †Kvb eZ©bxi we`y¨r cÖevngvÎv mivmwi (A¨vw¤úqv‡i) cwigvc Kivi hš¿‡K A¨vwgUvi e‡j| 1| †Kvb eZ©bxi `yB we›`yi g‡a¨ wefe cv_©K¨ mivmwi (†fv‡ë) cwigvc Kivi hš¿‡K †fvëwgUvi e‡j| 2| A¨vwgUvi GKwU Kg †ivawewkó Pj KzÛjx M¨vjfv‡bvwgUvi| GKwU Pj KzÛjx M¨vjf‡bvwgUv‡ii mv‡_ wb¤œgv‡bi †iva mgvšÍiv‡j hy³ K‡i GwU •Zwi| 2| †fvëwgUvi GKwU D”P †iva wewkó Pj KzÛjx M¨vjfv‡bvwgUvi| GKwU Pj KzÛjx M¨vjfv‡bvwgUv‡ii mv‡_ D”Pgv‡bi †iva †kÖYx‡Z hy³ K‡i GwU •Zix| 3| †h eZ©bxi we`y¨r cÖevn gvÎv wbY©q Ki‡Z n‡e Zvi mv‡_ Zv‡K wmwiR (†kÖYx) mgev‡q hy³ Ki‡Z n‡e| 3| eZ©bxi †h `yB we›`yi g‡a¨ wefe cv_©K¨ wbY©q Ki‡Z n‡e H `yB we›`yi ga¨eZ©x As‡ki mv‡c‡ÿ G‡K mgvšÍivj mgev‡q hy³ Ki‡Z nq| h‡š¿i bvg Kx cwigvc Kiv nq GKK cÖvmw½K ¸iæZ¡c~Y© Z_¨vejx †fvëwgUvi wefe cv_©K¨ Volt (v) cvjøv e„w× S = R(n 1) †hLv‡b, R = †fvëwgUv‡ii †iva; n = v v A¨vwgUvi Zwor cÖev‡ni gvb I w`K, I Ampere (A) cvjøv e„w×: S = R n 1 ; n = I I R = A¨vwgUv‡ii Af¨šÍixY †iva IÕg wgUvi ‡iva, R Ohm(m) (i) R = L A (ii) R = R0 (1 + ) wgUvi weªR ‡iva Ges Av‡cwÿK †iva (Av. †iva) Ohm -meter (m) †cv÷ Awdm e· AwZ D”P Ges AwZKg gv‡bi †iva †cv‡UbwkIwgUvi I, V, R Zwo”PvjK ej Ges Af¨šÍixY †iva Zwo”PvjK ej, (Volt) Af¨šÍixY †iva () g~jbxwZ I w¯ i _vK‡j, V L * E = I (R + r) gvwë wgUvi •e`y¨wZK †iva, wefe cv_©K¨ I Zwor cÖevn ** AVO meter bv‡g cwiwPZ| REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF JU QUESTION 01. A¨vwgUv‡ii mv‡_ †iva hy³ _v‡K- [IU: 2012-13] A. ‡kªYx‡Z B. mgvšÍiv‡j C. wgkªfv‡e D. ‡h †Kvb fv‡e Ans B STEP 02 ANALYSIS OF RU QUESTION 01. Kcvi ‡fvëvwgUv‡ii Rb¨ ‡KvbwU wVK bq? [RU: 2015–16] A. A¨v‡bvW Zvgvi •Zix B. Zwor we‡køl¨ wnmv‡e Kcvi mvj‡d‡Ui `ªeY _v‡K C. Zwor we‡køl‡bi mgq `ªe‡Yi NbZ¡ K‡g hvq D. A¨v‡bv‡Wi fi n«vm cvq Ans A 02. †fvëwgUvi GKwU M¨vjfv‡bvwgUvi hv- [RU: 2009-10] A. wmwi‡R D”P †ivahy³ B. wmwi‡R wb¤œ †ivahy³ C. mgvšÍiv‡j wb¤œ †ivahy³ D. mgvšÍiv‡j D”P †ivahy³ Ans D 03. Zwor cÖevngvÎv cwigv‡ci Rb¨ e¨eüZ h‡š¿i bvg- [RU: 2008-09, CU. 06-07, MBSTU. 14-15] A. M¨vjfv‡bvwgUvi B. A¨vwgUvi C. †fvëwgUvi D. ‡fvëvwgUvi Ans B STEP 03 ANALYSIS OF CU QUESTION 01. wgUvi eªxR †Kvb bxwZ Abymv‡i KvR K‡i? [CU-A, Set-1. 20-21, Kz. †ev. 2016, 15] A.A¨vw¤úqv‡ii m~Î B.ûBU‡÷vb eªxR bxwZ C.dv‡g©‡Ui bxwZ D.Kvk©‡di m~Î S B info wgUvi eªxR ûBU‡÷vb eªxR Gi bxwZ AbymiY K‡i| 02. †h hš¿ w`‡q Zwor cÖevn, wefe cv_©K¨ I †iva gvcv nq Zv‡K wK e‡j? [CU: 2012-13] A. †fvëwgUvi B. gvwëwgUvi C. A¨vwgUvi D. †fvëwgUvi Ans B STEP 04 ANALYSIS OF GST QUESTION PART A Analysis of General University Question IU 01. A¨v‡fvwgUvi Gi Aci bvg? [IU: 2012-13] A. ‡fvë wgUvi B. ‡fvëwgUvi C.gvwëwgUvi D.‡KvbwUB bq Ans C BU 01. PjKzÛwj wewkó GKwU M¨vj‡fv‡bvwgUvi‡K †fvëwgUv‡i iƒcvšÍwiZ Ki‡Z n‡j Avgv‡`i wK ms‡hvM Ki‡Z n‡e- [BU: 2012-13] A. High resistance in series B. High resistance in parallel C. Low resistance in series D. Low resistance in parallel Ans B PART B Analysis of Science & Technology Question SUST 01. wKfv‡e eZ©bx‡Z A¨vwgUvi ms‡hvM Ki‡Z nq? [SUST: 2006-07, MBSTU- 14,15, PSTU. 13-14] A. mgvšÍiv‡j B. ‡kªYx‡Z C. j¤^fv‡e D. ‡KvbwUB bq Ans B 02. Zzjbvg~jKfv‡e †fvëwgUv‡ii Ges A¨vwgUv‡ii †iva h_vµ‡gÑ [SUST: 2005-06] A. †ekx-†ekx B. †ekx-Kg C. Kg-†ekx D. Kg-Kg Ans B MBSTU 01. eZ©bx ms‡hv‡Mi †¶‡Î mgvšÍiv‡j hy³ Kiv nq- [MBSTU: 2015-16)] A. ‡iva B. e¨vUvwi C. A¨vwgUvi D. ‡fvëwgUvi Ans D BSMRSTU 01. †KvbwU D”P †iva wewkó Pj KzÛjx M¨vjfv‡bvwgUvi? [BSMRSTU-B, 19-20, CU-13-14] A. †fvëwgUvi B. GwgUvi C. c‡UbwkIwgUi D. †cv÷ Awdm e· A¨vwgUvi n‡”Q GKwU D”P‡iva wewkó PjKzÛjx M¨vjfv‡bvwgUvi hv w`‡q cÖevn gvcv nq Ges †fvëwgUvi w`‡q wefe cv_©K¨ gvcv nq| PUST 01. ‣e`y¨wZK eZ©bx‡Z †fvëwgUvi I A¨vwgUvi jvMv‡Z nq h_vµ‡g- [PSTU: 14–15] A. mgvšÍivj I wmwi‡R B. wmwiR I mgvšÍivj C. wmwi‡R D. mgvšÍiv‡j Ans A ûBU‡÷vb weªR bxwZ‡Z KvR K‡i M¨vjfv‡bvwgUvi e¨eüZ nq AVO M¨vjfv‡bvwgUvi