ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 189 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ✅ abvZ¡K KvR I FYvZ¡K Kv‡Ri g‡a¨ cv_©K¨: abvZ¡K KvR/e‡ji Øviv KvR FYvZ¡K KvR/e‡ji weiæ‡× KvR 1. Gi Øviv e¯‘‡Z Z¡i‡Yi m„wó nq 2. w¯’wZ kw³ n«vm cvq 3. MwZ kw³ e„w× cvq 4. mxgv 0 0 < 900 1. Gi Øviv e¯‘‡Z g›`b m„wó nq| 2. w¯’wZ kw³ ew„× cvq 3. MwZ kw³ n«vm cvq 4. mxgv: 90° < 180° ✅ k~b¨ KvR: msÁv ej cÖ‡qv‡M hw` †Kv‡bv e¯‘i miY e‡ji j¤^ eivei nq, Z‡e H e‡ji Øviv †Kv‡bv KvR nq bv| kZ© e¯‘‡Z hw` ej cÖ‡qvM Kiv bv nq| (F = 0) ej cÖ‡qv‡M hw` e¯‘i miY bv nq| (S=0) 0 90 n‡j cos900 = 0 D`vniY fvix ev· gv_vq wb‡q `uvwo‡q _vKv †mªv‡Zi weiæ‡× muvZvi †K‡U w¯’i _vKv GKwU `wo‡Z cv_i †e‡a e„ËvKvi c‡_ Nyiv‡bv †K›`ªgyLx ej KZ…©K K…Z KvR c„w_exi AveZ©‡bi mgq m~‡h©i gnvKl© ej †Kvb KvR K‡i bv| `wo †_‡K Szjv‡bv GKwU †ejb| GKwU Luv‡R wbðj GKwU †ejb (wmwjÛvi) `woi gv_vq cv_i †eu‡a [w`‡j fv‡jv nq] GKwU e¨vM nv‡Z wb‡q mgZj c‡_ nuvU‡j e¨vMwUi IRb A_©vr AwfKl© ej †Kvb KvR K‡i bv| ✅ cwieZ©bkxj ej KZ©…K K…ZKv‡Ri D`vniY: w¯cÖs cÖmvi‡Y ev ms‡KvP‡b ev w¯’wZ¯’vcK ej Z_v w¯cÖs e‡ji K…ZKvR| W = 1 2 kx2 ev, W x 2 evwn¨K ej cÖ‡qv‡M weK…Z e¯‘i Dci K…ZKvR| AwfKl© ej/ gnvKl© ej KZ©…K K…ZKvR| ✅ w¯cÖs m¤cÖmvi‡Y K…Z KvR: F = –kx, w = 1 2 kx2 = 1 2 Fx ✅ w¯cÖs aªæeK: w¯cÖs aªæe‡Ki gvb wbf©i K‡i w¯cÖs Gi ‣`N©¨ c`v‡_©i w¯’wZ¯’vcK a‡g©i Dci ✅ GKK: w¯cÖs aªæe‡Ki GKK Nm–1 gvÎv: MT–2 ✅ GK AwfKlx©q GKK KvR = GK AwfKlx©q GKK ej GKK miY ✅ Kv‡Ri †¶‡Î AwfKlx©q GKK‡K cig GK‡K iƒcvšÍ‡ii mgq g Øviv ¸Y Ki‡Z nq Ges cig GKK‡K AwfKlx©q GK‡K iƒcvšÍ‡ii mgq g Øviv fvM Ki‡Z nq| ✅ ej I mi‡Yi ga¨eZx© †KvY 90˚ n‡j A_ev Zv‡`i gvb Avjv`v Avjv`vfv‡e k~b¨ n‡j Kv‡Ri gvb k~b¨ n‡e| ✅ aªæe ej Øviv K…Z KvR: AwfKl© e‡ji cÖfv‡e †Kvb e¯‘‡K Aí D”PZvq Dc‡i DVv‡bv ev wb‡P bvgv‡bv| D”PZv Aí n‡j AwfKl© ej aªæe| Avbyf~wgK eivei MwZkxj e¯‘i Dci AwfKl© ej KZ…©K K…Z KvR k~b¨| ✅ 1kWh = 3.6 106 J ,CGS c×wZ‡Z Kv‡Ri GKK erg, erg n‡jv Ry‡ji †P‡q †QvU GKK [l erg = 10–7 J] 1erg = 1dyne cm = 1gm cm2 s –2 ✅ AwfKlx©q Kv‡Ri D`vniY: (i) e¯‘ Dc‡i DVv‡bv (ii) e¯‘ wb‡P bvgv‡bv (iii) AvbZ Zj †e‡q e¯‘i Dc‡i DVv (iv) AvbZ Zj †e‡q e¯‘i wb‡P bvgv| ✅ gnvKl© ej Øviv K…ZKvR: W = GMm 1 ra – 1 rb ✅ AwfKl© ej Øviv KvR: W = mgh [w h] AwfKl© ej, F = GMm r 2 F 1 r 2 REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. kw³i gvÎv Kx n‡e? [DU. 17-18; JU. 09-10; SUST. 06-07] A. MLT–2 B. ML2 T –1 C. M2 LT–2 D. ML2 T –2 KvR I kw³i gvÎv : ML2 T –2 ; ÿgZvi gvÎv: = ML2 T –3 02. ej, miY I KvR Gi g‡a¨ m¤úK© n‡jv- [DU. 16-17; MBSTU. 14-15; kvgmyi m¨vi] A. W = F. S B. W = FS cos C. W = F S D. A I B DfqB W = F. S = FS cos STEP 02 ANALYSIS OF JU QUESTION 01. Mv‡Qi GKwU Av‡cj c„w_ex‡K f e‡j AvKl©Y Ki‡Q| c„w_ex Av‡cj‡K F e‡j AvKl©Y Ki‡Q| myZivsÑ [JU-A, Set-E. 20-21] A. F < f B. F >> f C. F > f D. F = f Ans D 02. c„w_ex m~‡h©i Pvwiw`‡K 24 N›Uvq GK evi N~Y©b m¤úbœ K‡i, Zvn‡j c„w_ex KZ…©K K…Z KvR KZ? c„w_exi e¨vmva© 6400 km. [JU-H, Set-1. 19-20] A. 0 J B. 86.4 KJ C. 86.4 J D. 6400 J c~‡e©i Ae¯’vq Avevi wd‡i Avm‡j K…ZKvR = 0 03. ej cÖ‡qv‡M m‡e©v”P KvR n‡e hLb ej mi‡Yi mv‡_ wµqv K‡i- [JU. 18-19] A. 45 †Kv‡Y B. 30 †Kv‡Y C. j¤^ eivei D. GKB w`‡K Ans D 04. †Kvb e¯‘i Dci GK wbDUb ej cÖ‡qv‡Mi d‡j hw` e‡ji w`‡K e‡ji cÖ‡qvM we›`yi GK wgUvi miY nq, Z‡e m¤úbœ Kv‡Ri cwigvY‡K wK e‡j- [JU. 09-10] A. GK WvBb B. GK AvM© C. GK Ryj D. †KvbwUB bq Ans C STEP 03 ANALYSIS OF RU QUESTION 01. Kv‡Ri gvb k~b¨ n‡e hw` cÖhy³ ej I mi‡Yi ga¨eZ©x †KvY nq? [RU. 17-18; IU. 11-12; CoU. 13-14; RU. 10-11; JU. 12-14; MAT. 04-05] A. 0 B. 90 C. 180 D. 360 KvR, W = FS cos = 0 n‡j W = FS Avevi, n‡j W = 0 [ cos90 = 0]
190 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 02. cÖwZ †m‡K‡Û 746 Ryj KvR Kivi ÿgZv‡K wK e‡j? [RU. 17-18] A. MwZkw³ B. Ak^ÿgZv C. wK‡jv-IqvU N›Uv D. wbDUb wgUvi 1 Ak^ ÿgZv = 746Js–1 = 746 Watt cÖwZ †m‡K‡Û 746 Ryj KvR Kivi ÿgZv‡K GK Ak^ ÿgZv e‡j| 03. GKwU e¯‘ mg`ªæwZ‡Z e„ËvKvi c‡_ Nyi‡j Gi Dci- [RU. 15-16] A. †Kvb KvR nq bv B. me©vwaK KvR nq C. †Kvb ej wµqv K‡i bv D. †eM AcwiewZ©Z _v‡K Ans A 04. †Kvb e¯‘i Dci cÖhy³ ej Øviv K…Z KvR e¯‘wUi MwZ kw³i cwieZ©‡bi- [RU. 15-16] A. †P‡q †ewk B. †P‡q Kg C. mgvb D. †Kv‡bvwUB bq KvR kw³ Dccv`¨: †Kvb e¯‘i Dci cÖhy³ ej Øviv K…Z KvR e¯‘wUi MwZ kw³i cwieZ©‡bi mgvb| STEP 04 ANALYSIS OF CU QUESTION 01. †Kvb ivwki GKK wK‡jvIqvU N›Uv (kWh)? [CU. 15-16] A. Avavb B. cÖevn C. kw³ D. ¶gZv E. Ak¦ ¶gZv Ans C 02. wK‡jvIqvU-N›Uvi mv‡_ Ry‡ji m¤úK©- [CU. -14-15; KU. 13-14] A.1 kWh = 550J B. 1 kWh = 746J C. 1 kWh = 3.6 106 J D. 1 kWh = 9.8J E. 1 kWh = 3.6 105 J Ans C 03. †KvbwU kw³ bq? [CU. 14-15] A. Zvc B. Av‡jvK C. ZvcgvÎv D. me¸‡jvB kw³ Ans C 04. cwieZx© ej Øviv K…Z Kv‡Ri mgxKiY †KvbwU? [KU. 09-10] A. w FS B. w = F. dS C. w = 1 2 kx2 – 1 2 ky2 D. w = 1 2 kx2 Ans B STEP 05 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. 1 watt mgvb KZ Lumen? [JnU. 15-16] A. 600 B. 620 C. 550 D. 621 Ans D KU 01. e‡ji gvÎv mgxKiY †KvbwU? [KU. 18-19] A. [MLT–2 ] B. [MLT–1 ] C.[ML2 T –1 ] D. [ML2 T –2 ] Ans A 02. cÖhy³ ej Ges mi‡Yi ga¨eZ©x †KvY k~b¨ n‡j K…ZKvR- [IU. 15-16] A. abvZ¥K B. FbvZ¡K C. k~b¨ D. me©wb¤œ Ans A 03. w¯cÖsÑ Gi Dci ej cÖ‡qv‡M gy³ cÖv‡šÍi x miY n‡j w¯cÖs e‡ji wecixZ K…ZKvRÑ [IU. 14-15] A. W = – 1/2 kx2 B. W = 1/2 kx2 C. W = – 1/2 k2 x D. W = 1/2 k2 x Ans B 04. Kv‡Ri cwigvY FYvZ¥K n‡e hLb cÖhy³ ej I mi‡bi g‡a¨ †Kv‡Yi gvb- [KU. 13-14] A. 45° B. 90° C. 120° D. 180° Ans CD 05. ej cÖ‡qv‡M †Kvb e¯‘i miY e‡ji j¤^ eivei n‡j Kv‡Ri cwigvY- [IU. 13-14] A. me©vwaK B. me©wbgœ C. ±1 D. 0 w = Fs cos90 = 0 06. GK †gMv B‡jKUªb †fvë mgvb- [JU. 11-12; HSTU: 14-15] A. 1.610–13 Ryj B. 1.610–34 Ryj C. 1.610–28 Ryj D. 1.610–19 Ryj Ans A 07. Kv‡Ri cwigvY me‡P‡q †ekx nq hLb cÖhy³ej I mi‡Yi g‡a¨ †Kv‡Yi gvb nq- [IU. 11-12, BU: 14-15, HSTU: 14-15; CU. 14-15] A. 45 B. 90 C. 30 D. 0 Ans D 08. cÖ‡Z¨K iƒcvšÍ‡i cÖ`Ë kw³ I cÖvß kw³- [KU. 10-11] A. mgvb nq B. mgvb nq bv C. k~b¨ nq D. mgvbycvwZK nq Ans A PART B Analysis of Science & Technology Question JUST 01. KLb me©vwaK cwigvY KvR m¤úbœ nq? [JUST-C, 19-20] A. F ||d B. F ⊥d C. F = d D. F = – d ej I mi‡Yi ga¨eZ©x †Kvb 0° n‡j Kv‡R©i cwigvb m‡e©v”P| MBSTU 01. GKwU gv‡e©j‡K myZvq ‡eu‡a e„ËvKvi c‡_ Nyiv‡j Kv‡Ri cwigvY n‡e- [MBSTU. 15-16] A. m‡e©v”P B. abvZ¥K C. FYvZ¥K D. k~b¨ Ans D 02. ‡K›`ªgyLx ej Øviv K…ZKvR- [MBSTU. 14-15; JU. 12-13] A. Amxg B. abvZ¥K C. k~b¨ D. FYvZ¥K Ans C HSTU 01. wXj Quy‡o Avg cvovi mgq wX‡ji †Kvb kw³ Avg‡K e„šÍPz¨Z K‡i? [HSTU: 15-16] A. wefe kw³ B. MwZkw³ C. ivmvqwbK kw³ D. Zvckw³ Ans B 02. 1 Ak¦¶gZv = KZ ‡gMvIqvU? [HSTU: 14-15] A. 746 10 B. 746 10–6 C. 746 10–3 D. 746 103 Ans B NSTU 01. c„w_ex c„‡ôi KvQvKvwQ Kÿc‡_ Nyi‡Z _vKv m¨v‡UjvB‡Ui MwZkw³ wظY Kiv n‡j, m¨v‡UjvB‡Ui Ae¯’v wK n‡e? [NSTU-A, 19-20] A. GwU `ªæZ AvewZ©Z nq B. GwU Av‡¯Í AvewZ©Z nq C. GwU AcwiewZ©Z _v‡K D. GwU nvwi‡q hv‡e v Ek v2 = 2v1 = 1.41v1 STEP 06 ANALYSIS OF ENGINEERING & BUTex QUESTION BUET 01. ej I kw³i gvÎv h_vµ‡g [BUET: 09-10; JU. 11-12] A. [LT–2 ] and [MLT–2 ] B. [MLT–2 ] and [ML2 T –2 ] C. [LT–2 ] and [ML2T –2 ] D. [MLT–2 ] and [ML–2 T –3 ] Ans B STEP 07 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. hw` †Kvb e¯‘ f~wgi Dc‡i †Zvjv nq †Kvb kw³i wecix‡Z KvRwU Kiv nj? [MAT. 2020-21] A. Zwor Pz¤^Kxq kw³ B. Nl©Yg~jK kw³ C. ga¨vKl©Y kw³ D. ivmvqwbK kw³ S C info GKRb †jvK gvwU †_‡K GKwU PvD‡ji e¯Ív‡K gv_vi Ici Zzj‡jv| Avevi, GKwU eB‡K †g‡S †_‡K Avjgvix‡Z Zzj‡jv| GiKg †ÿ‡Î AwfK‡l©i A_©vr gva¨vKl©Y kw³i weiæ‡× KvR Kiv nq| 02. ej Ges ¯’vbPz¨ZKi‡Yi ga¨ewZ© †KvYwU hw` 0 nq, Z‡e Kv‡Ri cwigvY n‡eÑ [MAT. 2020-21] A. AmxgZv B. m‡e©v”P C. k~b¨ D. by¨bZg S B info Kv‡Ri cwigvY me‡P‡q †ewk nq hLb cÖhy³ ej I mi‡Yi ga¨eZ©x †KvY 0 nq| W = Fs cos = Fscos0 = Fs = Wmax 03. †Kvb wbw`©ó f‡ii e¯‘i MwZkw³, Gi fi‡e‡Mi mv‡_ m¤úK© Kx? [MAT. 16-17] A. eM©g~‡ji mgvbycvwZK B. e‡M©i mgvbycvwZK C. e‡M©i e¨¯ÍvbycvwZK D. mgvbycvwZK S B info Ek = p 2 2m Ek p 2
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 191 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 04. Kv‡Ri GKK †KvbwU? [MAT. 07-08; CU. 11-12] A. wbDUb B. Ryj C. IqvU D. c¨vm‡Kj Ans B 05. 0° < 90° n‡j e‡ji Øviv K…Z KvR- [MAT. 02-03] A. FYvZ¡K n‡e B. abvZ¥K n‡e C. †Kvb KvR n‡e bv D.Dc‡ii †KvbwUB bq Ans B 06. †KvbwU mwVK? [MAT. 01-02] A. †K›`ªgyLx e‡ji †hvMvb †`Iqvi Rb¨ †ijc_ †hLv‡b ‡eu‡K †M‡Q, †mLv‡b evu‡Ki evB‡ii w`‡K GKUz DuPy Kiv nq B. wewfbœ c`v‡_©i Aby¸‡jvi g‡a¨ cvi¯úwiK AvKl©Y ej‡K mskw³ ej e‡j C. Amsi¶Ykxj ej Gi †¶‡Î GKwU e¯‘‡K †h †Kvb c‡_ Nywi‡q cybivq cÖv_wgK Ae¯’vq Avb‡j ej KZ…©K KZ KvR k~b¨ n‡e D. mvaviYZ fi †K›`ª I fvi †K›`ª GKB n‡q _v‡K Ans A,D DAT 01. ÒB‡jKUªb †fvëÓ wb‡Pi †KvbwUi GKK? [DAT. 2020-21] A. cÖvej¨ B. cÖevn C. Avavb D. KvR S D info cvigvYweK I wbDwK¬q c`v_©we`¨vq KvR I kw³i GKK Ryj QvovI B‡j±ªb †fvë e¨eüZ nq| 1eV = 1.60 10–19J [ W = Vq J] ● Kv‡Ri hvwš¿K GKK Ryj ● Kv‡Ri •e`y¨wZK GKK wK‡jvIqvU ● Kv‡Ri wbi‡cÿ GKK ● F.P.S c×wZ‡Z dzUÑcvDÛvj ● C.G.S c×wZ‡Z erg; ● S.I (Gm.AvB. c×wZ‡Z) Ryj AFMC 01. †Kvb e¯‘i Dci cÖhy³ ej I mi‡Yi ga¨eZ©x †KvY 90 n‡j KvR KZ? [AFMC. 2020-21] A. m‡e©v”P B. me©wb¤œ C. 0 j D. †Kv‡bvwUB bq S C info ej I mi‡Yi ga¨eZx© †KvY 0˚ n‡j KvR m‡e©v”P nq Ges 90˚ n‡j me©wb¤œ nq| e‡ji w`‡K KvR¸‡jv w¯’wZkw³ n«vm cvq, MwZkw³ e„w× cvq, e‡ji Øviv Kv‡Ri †ÿ‡Î 0˚ 90˚| e‡ji weiæ‡× KvR n‡j w¯’wZkw³ e„w× cvq, e‡ji weiæ‡× Kv‡Ri †ÿ‡Î 90˚ 180˚ msiÿYkxj e‡ji cÖfv‡e hw` †Kv‡bv e¯‘ e„ËvKvi c‡_ Ny‡i ZLb KvR k~b¨ nq| †K›`ªgyLxej Øviv K…ZKvR k~b¨| STEP 08 ANALYSIS OF HSC BOARD QUESTION 01. m‡e©v”P Kv‡Ri Rb¨ cÖhy³ ej I mi‡Yi ga¨eZ©x †KvYÑ [Xv.‡ev 2021] A. 0 B. 30 C. 60 D. 90 Ans A wb‡Pi DÏxcKwU co Ges cÖ‡kœi DËi `vI: †Kv‡bv e¯‘‡Z F = (3 i + 2 j – k)N gv‡bi ej 2sec wµqv Kivq e‡ji w`‡K e¯‘i †eM nq V = ( i + 2 j + k)ms–1 02. e‡ji Øviv K…ZKvR KZ? [Xv.‡ev 2021] A. 12 J B. 16 J C. 2(4 i + 4 j) J D. 1 2 (4 i – 4 j + 4 k) J s = vt = 2 i + 4 j + 2 ^ k W = F. s = 3.2 + 2.4 1.2 = 12J 03. †K›`ªgywL ej Øviv K…Z KvRÑ[Xv. †ev. 2019; iv.‡ev 2021; e.‡ev 2021; P.‡ev 2021] A. Amxg B. abvZ¥K C. k~b¨ D. FYvZ¥K Ans C 04. †KvbwU AmsiÿYkxj ej? [iv.‡ev 2021] A. Zwor ej B. mv›`ª ej C. AwfKl© ej D. w¯’wZ¯’vcK ej Ans B 05. 1 wK‡jvIqvU N›Uv mgvbÑ [iv. †ev. 2017] A. 1000J B. 3600J C. 6000J D. 3.6106 J S D info 1kwh = 1000W × 3600J = 3.6 × 106 J 06. K…ZKvR k~b¨ n‡e [iv. †ev. 2016] i. e¯‘ mg‡e‡M MwZkxj _vK‡j ii. e¯‘ mgZ¡i‡Y MwZkxj _vK‡j iii. e¯‘i Dci cÖhy³ †K›`ªgyLx ej _vK‡j wb‡Pi †KvbwU mwVK? A. i I ii B. ii I iii C. i I iii D. i, ii I iii Ans C 07. bx‡Pi †KvbwU abvZ¥K Kv‡Ri kZ©? [P.‡ev 2021; e.†ev. 2021] A. 090 B. 090 C. 090 D. 090 Ans A 08. 0 S F F I S h_vµ‡g ej I miY n‡j Gi †Kvb gv‡bi Rb¨ KvR k~b¨ nq? [P.‡ev 2021] A. 0 B. 45 C. 90 D. 180 Ans C 09. ej F I miY r DfqB †f±i ivwk n‡j G‡`i †¯‥jvi ¸Yd‡j Kx ivwk Drcbœ n‡e? [P.‡ev 2021] A. ÿgZv B. kw³ C. KvR D. UK© Ans C 10. ej I mi‡Yi ga¨eZx© †KvY KZ n‡j Kv‡Ri cwigvY m‡e©v”P nq? [w`. †ev. 2016] A. 0 B. 45 C. 90 D. 180 Ans A 11. ej aªæeK Gi gvÎv †KvbwU? [h.‡ev. 2019] A. [ML0T -2 ] B. [M2LT-1 ] C. [ML-2 ] D. [ML2T 2 ] Ans A 12. Kv‡Ri gvb k~b¨ n‡e hw` cÖhy³ ej I mi‡Yi ga¨eZ©x †KvY- [Kz.‡ev 2021] A. 90 B. 180 C. 0 D. 360 S A info w = Fs cos w = Fs cos90 [ = 90] w = 0 13. abvZ¥K Kv‡Ri †ÿ‡Î †Kv‡bv e¯‘i [Kz. †ev. 2016] A. MwZkw³ e„w× cvq, g›`b nq B. MwZkw³ n«vm cvq, g›`b nq C. MwZkw³ n«vm cvq, Z¡iY nq D. MwZkw³ e„w× cvq, Z¡iY nq Ans D 14. e‡ji weiæ‡× KvR m¤úbœ nq hLb ej I mi‡Yi ga¨eZx© †KvY Gi gvbÑ [Kz. †ev. 2016] A. 0 < 90 B. 0 < 90 C. 90 180 D. 90 < 180 Ans D 15. k~b¨ Kv‡Ri kZ© n‡jv- [Kz. †ev. 2015] A. e¯‘i Ici ej cÖ‡qv‡M Djø¤^ w`‡K miY n‡j B. e¯‘i Ici ej cÖ‡qv‡MI †Kv‡bv miY bv NU‡j C. hw` cos = 0 D. me¸‡jvB Ans D 16. CGS c×wZ‡Z Kv‡Ri GKK †KvbwU? [wm.‡ev 2021] A. Joule B. Ft-Poundal C. erg D. N.m Ans C 17. Kv‡Ri gvb me©vwaK n‡e- [wm.‡ev 2021] i. S V P V ii. S V F iii. S V F wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans A 18. ej I mi‡Yi ga¨eZx© †Kvb KZ n‡j e‡ji Øviv KvR m¤úbœ n‡e? [wm.‡ev. 2019] A. 45 B. 120 C. 180 D. 200 S A info ej Øviv KvR nIqvi kZ©: 0˚ < 90˚ 19. †Kv‡bv e¯‘i Ici wµqvkxj ej Øviv K…Z KvR wb‡Pi †Kvb ivwkwUi cwieZ©‡bi mgvb? [wm. †ev. 2017] A. ZvcgvÎv B. NbZ¡ C. MwZkw³ D. wefekw³ Ans C
192 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 20. e‡ji Øviv KvR ev abvZ¥K KvR nq hw`Ñ [wm. †ev. 2015] A. ej cÖ‡qv‡M miY k~b¨ nq B. e¯‘ mg`ªæwZ‡Z e„ËvKvi c‡_ Ny‡i C. ej I mi‡Yi ga¨eZ©x †KvY 90 nq D. ej I mi‡Yi ga¨eZ©x †KvY k~b¨ nq Ans D 21. GKwU gv‡e©j‡K myZvq †eu‡a e„ËvKvi c‡_ Nyiv‡j Kv‡Ri cwigvY n‡eÑ[wm. †ev. 2015] A. m‡e©v”P B. FYvZ¥K C. k~b¨ D. abvZ¥K Ans C 22. ej I mi‡Yi ga¨eZx© †KvY 0 n‡j, Kv‡Ri cwigvY n‡eÑ [wm. †ev. 2015] A. k~b¨ B. me©wb¤œ C. m‡e©v”P D. Amxg Ans C 23. †Kv‡bv e¯‘i Dci bxU ej k~b¨ n‡j w¯’i _vK‡e- [g.‡ev 2021] i. †eM ii. Z¡iY iii. MwZkw³ wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans B 24. 15 IqvU ÿgZv ej‡Z eySvq- [e. †ev. 2015, DAT. 2019-20] A. 1 †m‡K‡Û 15 Ryj KvR B. 3 †m‡K‡Û 5 Ryj KvR C. 5 †m‡K‡Û 3 Ryj KvR D. 15 †m‡K‡Û 1 Ryj KvR Ans A Concept 2 kw³ Ges kw³i iƒcvšÍi ✅ kw³ I Kv‡Ri gvÎv mgxKiY GKB [ML2T –2 ] ✅ kw³i cÖKvi‡f`/iƒc‡f`: 9 cÖKvi| ✅ kw³i cÖKvi‡f` g‡b ivLvi †K․kj: HELENA MSC (‡n‡jbv GgGmwm) H E L E N A M S C (Heat) Zvc kw³ (Electrical) we`y¨r kw³ (Light) Av‡jvK kw³ (Nuclear) cvigvYweK kw³ (Magnetic) ‡P․¤^K kw³ (Sound, Solar) kã kw³ I †m․i kw³ (Chemical) ivmvqwbK kw³ ✅ hvwš¿K kw³: hvwš¿K kw³i `ywU iƒc Av‡Q- 1. MwZkw³; 2. wefe kw³ ev w¯’wZkw³ ✅ w¯’wZkw³i cÖKvi‡f`: w¯’wZkw³ ev kw³i wewfbœ cÖKvi| h_v- 1. AwfKl©xq wefe kw³; 2. w¯’wZ¯’vcK/ w¯cÖs Gi wefe kw³; 3. Zwor wefe kw³ ◈ w¯’wZkw³i cÖKvi‡f` Q‡›`i gva¨‡g g‡b ivwL: Awf ZvovZvwo Avm‡Zv| Awf ZvovZvwo Avm‡Zv AwfKl©xq Zwor w¯’wZ¯’vcK ✅ MwZkw³ I w¯’wZkw³i Zzjbvg~jK cv_©K¨: MwZkw³ w¯’wZ kw³ 1. ‡e‡Mi Rb¨ e¯‘ MwZkw³ jvf K‡i 1. w¯’ive¯’vb A_ev Ae¯’v cwieZ©‡bi Rb¨ e¯‘ w¯’wZ kw³ jvf K‡i 2. MwZ kw³i mgxKiY, Ek = 1 2 mv2 = P 2 2m 2. w¯’wZ kw³i mgxKiY nj, Ep = mgh 3. †eM e„wׇZ e¯‘i MwZ kw³ e„w× cvq 3. D”PZv e„wׇZ e¯‘i w¯’wZkw³ e„w× cvq 4. †eM n«vm †c‡j e¯‘i MwZ kw³ n«vm cvq 4. D”PZv n«vm †c‡j e¯‘i w¯’wZkw³ n«vm cvq 5. w¯’i e¯‘i MwZkw³ _v‡K bv 5. MwZkxj e¯‘i w¯’wZ kw³ _vK‡ZI cv‡i ✅ cošÍ e¯‘i †¶‡Î: hZB bx‡P bvg‡e ZZB w¯’wZkw³ n«vm I MwZkw³ e„w× cvq| cošÍ e¯‘i cÖwZ we›`y‡Z w¯’wZkw³ I MwZkw³i †hvMdj mgvb| e¯‘wU gvwU ¯úk© Ki‡j w¯’wZkw³ I MwZkw³ Ges kã kw³ Zvckw³ I hvwš¿K kw³‡Z iƒcvšÍwiZ nq| ✅ mgvb fi‡eMwewkó `ywU e¯‘i g‡a¨ nvjKv e¯‘wUi MwZkw³ †ewk n‡e| ✅ mgvb MwZkw³wewkó `ywU e¯‘i g‡a¨, fvix e¯‘i fi‡eM †ekx| ✅ MwZkw³ KL‡bv FYvZ¥K n‡Z cv‡i bv| ✅ Mvwoi Bwćb 20% kw³, Nl©Y‡K cÖkwgZ Ki‡Z e¨q nq| ✅ kw³i wbZ¨Zv ev msi¶Y m~Î: kw³i m„wó ev webvk †bB| GwU †Kej GKiƒc n‡Z Ab¨ GK ev GKvwaK iƒ‡c cwiewZ©Z n‡Z cv‡i| iƒcvšÍ‡ii Av‡M I c‡i †gvU kw³i cwigvY wbw`©ó I AcwieZ©bxq| G‡K kw³i wbZ¨Zv ev msi¶Y m~Î e‡j| ✅ hvwš¿K kw³i wbZ¨Zv ev msi¶Y m~Î: †Kvb e¨e¯’vq †Kej msiÿYkxj ej wµqv Ki‡j e¨e¯’vi MwZkw³ I wefekw³i mgwó me©`v aªæe n‡e| A_©vr K + U = aªæeK| ✅ hvwš¿K kw³i wbZ¨Zv ev msi¶Y m~‡Îi D`vniY: GKwU e¯‘ hZB Dc‡i †_‡K wb‡P bvg‡e ZZB Zvi w¯’wZ kw³ n«vm cvq Ges MwZkw³ e„w× cvq| wKš‘ Zv‡`i †hvMdj me©`v w¯’i _v‡K| e¯‘wU hLb gvwU ¯úk© K‡i ZLb w¯’wZkw³ I MwZkw³ DfqB †jvc cvq Ges GB kw³ Zvckw³, hvwš¿Kkw³, kãkw³ cÖf„wZ‡Z iƒcvšÍwiZ nq| mij‡`vj‡Ki cÖv‡šÍi †eM Z_v MwZkw³ k~b¨ wKš‘ w¯’wZkw³ m‡e©v”P| Ab¨w`‡K mvg¨Ae¯’v‡b †eM ev MwZkw³ m‡e©v”P wKš‘ w¯’wZkw³ k~b¨| wKš‘ †gvU kw³ me©`v w¯’i _v‡K|
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 193 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES AmsiÿYkxj e‡ji Rb¨ GB m~Î cÖ‡hvR¨ bq: D`vniY kw³i iƒcvšÍi UvievBb Nywi‡q we`y¨r kw³ Drcbœ Kiv hvwš¿K kw³ we`y¨r kw³‡Z •e`y¨wZK evwZ we`y¨r kw³ Av‡jvK kw³‡Z •e`y¨wZK Bw¯¿‡Z ZworPvjbv K‡i Zvc Drcbœ Kiv GB Zv‡ci mvnv‡h¨ Kvco-‡Pvco Bw¯¿ Kiv we`y¨r kw³ Zvc kw³‡Z Zvc kw³ hvwš¿K kw³‡Z •e`y¨wZK cvLv we`y¨r kw³ hvwš¿K kw³‡Z KuvPv †jvnvi Dci AšÍixZ Zvgvi Zvi Rwo‡q we`y¨r Pvjbv K‡i cvZwU‡K Pz¤^‡K cwiYZ Kiv we`y¨r kw³ Pz¤^K kw³‡Z d‡Uv B‡jKwUªK †Kv‡l Av‡jv †d‡j we`y¨r cÖevn •Zwi Kiv Av‡jvK kw³ we`y¨r kw³‡Z `yB nv‡Zi Zvjy ci¯úi Nl‡j Zvc Drcbœ nq hvwš¿K kw³ Zvc kw³‡Z d‡UvMÖvwdK wd‡j¥i Dci Av‡jvK m¤úvZ K‡i Av‡jvKwPÎ •Zwi Kiv Av‡jvK kw³ ivmvqwbK kw³‡Z Jl‡ai KviLvbvq kÖe‡YvËi ev k‡ãvËi Zi‡½i mvnv‡h¨ RxevYy aŸsm Kiv Kc©yi‡K cvwb‡Z `ªexf~Z Kiv k‡ãvËi Zi½ Øviv e¯¿vw`i gqjv cwi®‥vi Kiv kã kw³ hvwš¿K kw³‡Z •e`y¨wZK N›Uv †Uwj‡dvb we`y¨r kw³ kã kw³‡Z Kqjv †cvov‡j Zvc Drcbœ nq ivmvqwbK kw³ Zvc kw³‡Z we`y¨r †Kv‡l ivmvqwbK `ª‡e¨i wewµqvi d‡j we`y¨r Drcbœ nq ivmvqwbK kw³ Zwor ev we`y¨r kw³‡Z wbDwK¬qvi wiq¨v±‡ii g‡a¨ GKwU wbDUªb Øviv fvix cigvYy‡K AvNvZ K‡i wbDwK¬q wdkb wewµqv NUv‡bv| cvigvYweK kw³ Zvc kw³‡Z REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. wb‡Pi †KvbwU f‡ii GKK bq? [DU.A 19-20] A. amu B. 2 c MeV C. MeV D. Nm–1 s 2 S C info Mev kw³i GKK f‡ii GKK bq| STEP 02 ANALYSIS OF JU QUESTION 01. AwfKlx©q wefe kw³ n‡jv- [JU. 09-10] A. 0.5mgh B. mgh C. 2mgh D. mgh2 Ans B STEP 03 ANALYSIS OF RU QUESTION 01. GKwU e¯‘‡K Lvovfv‡e Dc‡ii w`‡K Qz‡o †`Iqv n‡jv| †Kvb †jLwPÎwU f~wg n‡Z D”PZv h Gi mv‡c‡ÿ wefekw³ E wb‡`©k K‡i? [RU. Moderna, Set-2. 20-21] A. O E h B. O E h C. O E h D. O E h S A info GLv‡b, E = mgh E h e¯‘wU f‚wg †_‡K hZ Dc‡i DV‡Z _v‡K A_©vr h Gi gvb hZ evo‡Z _v‡K ZZB wefe kw³ E Gi gvb mgvbycvwZK nv‡i mij‣iwLKfv‡e e„w× †c‡Z _v‡K| 02. Rjwe`y¨r Drcv`‡bi †ÿ‡Î wb‡Pi †KvbwU e¨envi Kiv nq? [RU. 17-18] A. cvwbi wefekw³ B. cvwbi w¯’wZ kw³ C. cvwbi mv›`ªZv D. cvwbi c„ôUvb Ans AB 03. GKwU e¯‘‡K mgZj f~wgi (i) a ¯’vb n‡Z Dj¤^fv‡e b ¯’v‡b †bqv n‡jv| Gici (ii) b ¯’vb n‡Z Avbyf~wgKfv‡e c ¯’v‡b †bqv n‡jv Ges me‡k‡l (iii) c ¯’vb n‡Z Lvov wb‡Pi w`‡K H f~wgi d ¯’v‡b bvgv‡bv n‡jv | wb‡Pi †KvbwU mwVK? [RU. 14-15] A. (i)-G K…Z KvR FYvZ¥K B. (ii)-G K…Z KvR abvZ¥K C. (iii)-G K…Z KvR DfqB D. †KvbwUB bq Ans B 04. B‡jKUªb †fvë (eV) wK‡mi GKK? [RU. 11-12] A. wefe B. cÖwZmiY C. kw³ D. PvR© Ans C 05. Ryj wK‡mi GKK? [RU. 09-10; †gvK‡Q`] A. Zv‡ci B. Kv‡Ri C. kw³i D. c~‡e©i me¸wj Ans D STEP 04 ANALYSIS OF CU QUESTION 01. kw³i GKK I gvÎv n‡”Q h_vµ‡g- [CU. 07-08] A. Ryj I ML2 T –3 B. IqvU I ML2 T –3 C. Ryj I ML3 T –3 D. Ryj I ML2 T –2 E. Ryj I MLT–2 Ans D STEP 05 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. wb‡Pi †Kvb kw³ Ab¨ kw³‡Z mn‡R iæcvšÍwiZ n‡Z Pvq bv? [KU-A, Set-Ka. 19-20] A. Av‡jv B. Zvc C. Zwor D. kã Ans B 02. N~Y©vqgvb e¯‘i MwZkw³ (K.E)- [KU. 18-19] A. 1 2 I 2 B. 1 2 I C. I 2 D. 1 2 I 2 Ans A PART B Analysis of Science & Technology Question SUST 01. 50 kg f‡ii †Kv‡bv e¯‘‡K h D”PZv †_‡K †dj‡j f~wg ¯úk©Kv‡j Gi †eM 25 km.h–1 †e‡M Pjgvb 2000 kg Uªv‡Ki MwZkw³i mgvb| h Gi gvb KZ m? [SUST-A, 19-20] A. 29.5 B. 9.8 C. 98.4 D. 109.2 E. 189.6 Uªv‡Ki †ÿ‡Î, m = 2000 kg v = 25kmh1 = 25 1000 3600 ms1 = 6.944 ms1 Ek = 1 2 mv2 = 1 2 2000 (6.944) 2 = 48219.136 J Ep = Ek (f‚wg ¯úk©Kv‡j) mgh = 48219.136 h = 48219.136 50 9.8 = 98.4 m
194 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES JUST 01. wb‡Pi †KvbwU kw³i GKK bq? [JUST-B, 19-20] A. kgm2 s –1 B. kwh C. N–m D. W–S 1 kwh = 3.6×106 J, 1 N–m = 1J, 1 W–S = 1J. MBSTU 01. MwZkw³ I fi‡e‡Mi g‡a¨ m¤úK©Ñ [MBSTU-C, Set-2 19-20] A. k = p 2 2m B. k = p 2m C. k = 2p m D. k = 2p2 m Ans A BSMRSTU 01. †h h‡š¿i mvnv‡h¨ hvwš¿K kw³‡K Zwor kw³‡Z iƒcvšÍwiZ Kiv hvq Zv‡K Kx e‡j? [BSMRSTU-H, 19-20] A. †gvUi B. Wvqbv‡gv C. UªvÝdg©vi D. †KvbwUB bq Ans B DU Technology 01. 1 eV KZ Ry‡ji mgvb? [DU-Tech.19-20] A. 1.60210–10 B. 1.60210–16 C. 1.60210–19 D. 1.60210–12 1 MeV = 1.6 10–13 J STEP 06 ANALYSIS OF ENGINEERING & BUTex QUESTION BUTex 01. D‡ovRvnvR †_‡K wbwÿß †evgv gvSc‡_ †d‡U †M‡j Gi- [BUTex-12-13] A. MwZkw³ evo‡e B. †gvU kw³ evo‡e C. ‡gvU kw³ Kg‡e D. ‡gvU fi‡eM Kg‡e Ans D STEP 07 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. cvwbi †Kvb ag©‡K Kv‡R jvwM‡q cvwb †_‡K we`y¨r Drcv`b Kiv nq? [MAT. 16-17] A. mv›`ªZv B. c„ôUvb C. wefe kw³ D. w¯’wZ kw³ Ans C 02. kw³i †¶‡Î †Kvb&wU mwVK bq? [MAT. 13-14] A. ewntw¯’wZkw³ f~-c„ô n‡Z c`v‡_©i mvgwMÖK Ae¯’v‡bi Dci wbf©ikxj B. ewntw¯’wZkw³ c`v‡_©i MVb cÖK…wZi Dci wbf©ikxj C. Af¨šÍixY w¯’wZkw³ e¯‘ KYvi Ae¯’vb I MVb cÖK…wZi Dci wbf©ikxj D. Af¨šÍixY MwZkw³ e¯‘ KYvi ¯’vbvšÍ‡ii Dci wbf©ikxj Ans B 03. †KvbwU kw³i cÖKvi‡f` bq? [MAT. 12-13] A. Pz¤^K kw³ B. AvYweK kw³ C. we`y¨r kw³ D. †m․i kw³ Ans B 04. c`v_© weÁv‡bi bx‡Pi †Kvb Z_¨wU mwVK? [MAT. 10-11] A. kw³i gvÎv: ML2 T –2 B. mgh MwZkw³i mgxKiY C. ¶gZvi gvÎv 1 2 mv2 D. MwZkw³ GKwU †f±i ivwk Ans A 05. ‡Kvb Z_¨wU MwZ kw³i Rb¨ cÖ‡hvR¨ bq? [MAT. 05-06] A. m f‡ii e¯‘i †eM v n‡j e¯‘i MwZkw³ 1 2 mv2 B. MwZkw³ e¯‘i AYy cigvYyi Av‡cw¶K Ae¯’v‡bi Dci wbf©i K‡i C. e¯‘i †eM bv _vK‡j MwZkw³ _v‡K bv D. †Kvb e¯‘ MwZkxj nIqvi Rb¨ †h kw³ AR©b K‡i Ans B DAT 01. †m․i Pzjøx‡Z fvZ ivbœv Ki‡j, †Kvb kw³ Zvckw³‡Z iƒcvšÍwiZ nq? [DAT. 16-17] A. hvwš¿K kw³ B. kã kw³ C. ivmvqwbK kw³ D. Av‡jvK kw³ Ans D STEP 08 ANALYSIS OF HSC BOARD QUESTION 01. MwZkw³i gvÎv [Xv. †ev., iv. †ev., h. †ev., wm. †ev. 2016] A. [MLT2 ] B. [ML2T 2 ] C. [ML3T 1 ] D. [M1L 2T 2 ] Ans B 02. kw³ GKK- [w`.‡ev 2021] i. Ryj ii. Kgms–2 iii. B‡jKUªb †fvë wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii S B info w = FS = Nm = J = Kg m2 S –1 = ev = erg 03. w¯úªs-G mwÂZ kw³ n‡”Q- [w`. †ev. 2015] A. wefe kw³ B. hvwš¿K kw³ C. ivmvqwbK kw³ D. A I B DfqB Ans D 04. wb‡¤œi †KvbwU kw³i GKK bq? [h.‡ev. 2019] A. kW-h B. N-m C. kgms-1 D. W-s Ans C 05. kw³i gvÎv †KvbwU? [h. †ev. 2016; wm.†ev. 2017] A. [ML2T 2 ] B. [ML2T 2 ] C. [ML3 T 2 ] D. [ML2 T 2 ] Ans A 06. e¯Íyi AvKvi cwieZ©‡bi Rb¨ w¯’wZkw³ jvf K‡iÑ [Kz. †ev. 2015] i. aby‡K Zxi jvwM‡q Uvb‡j ii. avZe cvZ‡K euvKv‡j iii. ivevi‡K cÖmvwiZ Ki‡j wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i,iiIiii Ans D 07. Kv‡Ri AwfKlx©q GKK †KvbwU? [wm. †ev. 2016] A. Ryj B. AvM© C. †KwR-wgUvi D. WvBb-†mw›UwgUvi Ans C 08. msKzwPZ Ae¯’vq w¯úªs Gi †fZi †Kvb kw³ mwÂZ _v‡K? [e. †ev. 2019; mKj †evW© 2018] A. Zvc kw³ B. w¯’wZ kw³ C. MwZ kw³ D. AšÍ¯’ kw³ Ans B 09. w¯úªs‡K cÖmvwiZ Ki‡j Gi g‡a¨ †Kvb ai‡bi kw³ mwÂZ nq? [e.‡ev. 2019] A. wefe kw³ B. MwZkw³ C. ivmvqwbK kw³ D. Zvc kw³ Ans A 10. msKzwPZ Ae¯’vq w¯úªs Gi wfZi †Kvb kw³ mwÂZ _v‡K? [mKj †evW©-2018] A. †j․n †Mvj‡Ki MwZkw³ †ewk B. †Uwbm e‡ji MwZkw³ †ewk C. Df‡qi MwZkw³ mgq D. MwZkw³i Dci fi‡e‡Mi cÖfve †bB Ans C
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 195 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 3 msiÿYkxj ej I AmsiÿYkxj e‡ji cv_©K¨ I •ewkó¨ ✅ msi¶Ykxj I Amsi¶Ykxj ej Gi g‡a¨ cv_©K¨: msi¶Ykxj ej Amsi¶Ykxj ej K…Z KvR m¤ú~Y©iƒ‡c cybiæ×vi Kiv m¤¢e K…Z KvR m¤ú~Y©iƒ‡c cybiæ×vi m¤¢e bq msi¶Ykxj e‡ji wµqvq hvwš¿K kw³i wbZ¨Zv m~Î cvwjZ nq Amsi¶Ykxj e‡ji wµqvq hvwš¿K kw³i wbZ¨Zv m~Î cvwjZ nq bv e‡ji wµqvi AwfgyL e¯‘i MwZi Awfgy‡Li Dci wbf©i K‡i bv e‡ji wµqvi AwfgyL e¯‘i MwZi Awfgy‡Li Dci wbf©ikxj wdiwZ c‡_i Rb¨ Avw` I †kl MwZkw³ mgvb _v‡K wdiwZ c‡_i Rb¨ Avw` I †kl MwZkw³i g‡a¨ cv_©K¨ _v‡K K…Z Kv‡Ri MwZc_ cÖv_wgK I †kl we›`yi Dci wbf©ikxj K…ZKv‡Ri MwZc_ ïay cÖv_wgK I †kl we›`yi Dci wbf©ikxj bq msiÿYkxj ej Øviv K…ZKvR c‡_i Dci wbf©i K‡i bv AmsiÿYkxj ej Øviv K…Z KvR c‡_i Dci wbf©i K‡i – × – F = 0 nq – × – F 0 nq D`vniY: AwfKl©xq ej, •e`y¨wZK ej, Zwor ej, †P․¤^K ej, gnvKl© ej, Av`k© w¯cÖs Gi weK…wZ cÖwZ‡ivax ej| D`vniY: Nl©Y ej, mv›`ª ej, mej I `ye©j wbDwK¬q ej| ◈ AmsiÿYkxj e‡ji D`vniY: ejwU N‡l my›`i K‡iv| ejwU N‡m m`©vb©x‡K my›`ªx evbvI Nl©Y ej mej I `ye©j wbDwK¬qej mv›`ª ej ✅ msi¶Ykxj e‡ji •ewkó¨: ej ïay Ae¯’v‡bi Dci wbf©i K‡i| GKwU e¯‘‡K GK ¯’vb ‡_‡K Ab¨ ¯’v‡b ¯’vbvšÍ‡i K…ZKvR c‡_i Dci wbf©i K‡i bv| ïay e¯‘i Avw` I PzovšÍ Ae¯’v‡bi Dci wbf©i K‡i| ✅ Amsi¶Ykxj e‡ji •ewkó¨: ej ïay Ae¯’v‡bi Dci wbf©i K‡i bv GKwU e¯‘‡K GK ¯’vb ‡_‡K Av‡iK Ab¨ ¯’v‡b ¯’vbvšÍ‡i K…Z KvR c‡_i Dci wbf©i K‡i REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF RU QUESTION 01. wb‡Pi †KvbwU msi¶Ykxj e‡ji †¶‡Î AmZ¨ bq? [RU. 14-15] A. kw³i AcPq N‡U B. K…Z KvR cybiæ×vi Kiv Am¤¢e bq C. hvwš¿K kw³i msi¶Y m~Î Lv‡U bv D. †KvbwUB bq Ans B STEP 02 ANALYSIS OF GST QUESTION PART A Analysis of Science & Technology Question JUST 01. †KvbwU msi¶Ykxj e‡ji D`vniY bq? [JUST. 14-15] A. AwfKl©xq ej B. ‣e`y¨wZK ej C. Av`k© w¯cÖs Gi weK…wZ cÖwZ‡ivaKvix ej D. mv›`ªej msi¶Ykxj ej : AwfKl©xq ej/ gnvKl© ej, Zwor ej, Kzj¤^ej/ •e`y¨wZK ej, †P․¤^K ej, Av`k© w¯cÖs Gi weK…wZ cÖwZ‡ivax ej| Amsi¶Ykxj ej: Nl©b ej, mv›`ª ej| STEP 03 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. wb‡Pi †Kvb Z_¨wU mwVK? [MAT. 10-11] A. ‡Kv_v n‡Z D”PZv cwigvY Kiv n‡”Q, MwZkw³ Zvi Dci wbf©ikxj B. ¶gZv abvZ¡K I FYvZ¡K `yB iK‡gi n‡Z cv‡i C. kw³ GKiƒc †_‡K Ab¨iƒ‡c iƒcvšÍwiZ nq D. Amsi¶bkxj ej Øviv K…ZKvR m¤ú~Y©iƒ‡c cybtiæ×vi Kiv m¤¢e bq AnsCD 02. †Kvb Dw³wU mZ¨ bq? [MAT. 06-07] A. ¯^vfvweK Ae¯’v ev Ae¯’vb cwieZ©b K‡i †Kvb e¯‘‡K Ab¨ †Kvb Ae¯’v ev Ae¯’v‡b Avb‡j e¯‘ KvR Kivi †h mvg_©¨ AR©b K‡i Zv‡K wefe kw³ e‡j B. msi¶Ykxj ej Øviv K…Z KvR m¤ú~Y©iƒ‡c cybiæ×vi Kiv m¤¢e bq C. mylg †ejbvK…wZ e¯‘i AwfKl© †K›`ª Gi A‡¶i ga¨ we›`y‡Z Aew¯’Z D. Mogy³ c_ M¨v‡mi Nb‡Z¡i e¨¯ÍvbycvwZK msi¶Ykxj ej Øviv K…Z KvR m¤ú~Y©iƒ‡c cybiæ×vi Kiv m¤¢e 03. wb‡Pi †KvbwU AmZ¨ bq? A. hvwš¿K kw³i wbZ¨Zvi m~Î msi¶Ykxj e‡ji †¶‡Î N‡U B. Nl©Y ej GB e‡ji D`vniY C. msi¶Ykxj ej Øviv K…Z KvR m¤ú~Y©iƒ‡c cybiæ×vi Kiv m¤¢e D.†Kvb KYv GKwU c~Y© Pµ m¤úbœ K‡i Zvi Avw` Ae¯’v‡b wd‡i Avm‡j, msi¶Ykxj e‡ji Øviv K…Z Kv‡Ri cwigvY k~b¨ nq bv Ans AC DAT 01. †KvbwU Nl©Y ej (Frictional Force) Gi D`vniY? [DAT. 2020-21] A.msiÿYkxj kw³ B.mgwš^K kw³ C.AvVv‡jv kw³ D.A-msiÿYkxj kw³ S D info Nl©Y ej GKwU AmsiÿYkxj ej| KviY, c~Y©P‡µ †gvU K…ZKvR k~b¨ nq bv| msi¶Ykxj ej: AwfKl©xq ej, •e`y¨wZK ej, Zwor ej, †P․¤^K ej, gnvKl© ej, Av`k© w¯cÖs Gi weK…wZ cÖwZ‡ivax ej| Amsi¶Ykxj ej: Nl©Y ej, mv›`ª ej| STEP 04 ANALYSIS OF HSC BOARD QUESTION 01. AmsiÿYkxj e‡ji D`vniY †KvbwU? [iv. †ev. 2015] A. Nl©Y ej B. ‣e`y¨wZK ej C. Pz¤^K ej D. AwfKl©R ej Ans A 02. msiÿYkxj ej n‡jv- [w`. †ev. 2015] A. gnvKl© ej B. Av`k© w¯úªs ej C. mv›`ª ej D. A I B DfqB Ans D 03. AmsiÿYkxj e‡ji •ewkó¨ bq †KvbwU? [e. †ev. 2017] A. K…Z KvR k~b¨ B. c‡_i Ici wbf©i K‡i bv C. hvwš¿K kw³i wbZ¨Zvi m~Î Lv‡U bv D. K…ZKvR cybiy×vi m¤¢e Ans A 04. wb‡Pi †KvbwU AmsiÿYkxj ej? [e. †ev. 2015] A. mv›`ª ej B. Kzj¤^ ej C. †P․¤^K ej D. gnvKlx©q ej Ans A
196 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 4 ÿgZv msµvšÍ Z_¨vejx ✅ ¶gZv: †Kvb GKwU Dr‡mi KvR Kivi nvi‡K ¶gZv e‡j| ✅ GK IqvU: GK †m‡K‡Û GK Ryj KvR Kivi ¶gZv‡K GK Ryj/†m. ev GK IqvU e‡j| ¶gZvi •e`y¨wZK e¨envwiK GKK‡K IqvU (Watt) e‡j| ÔIqvUÕ ÿgZv cwigv‡ci AvšÍR©vwZK GKK| ✅ GK Ak¦ ¶gZv: cÖwZ †m‡K‡Û 746 J KvR Kivi ¶gZv‡K GK Ak¦ ¶gZv e‡j| ✅ GK †fvë wefe cv_©‡K¨ GKwU B‡jKUª‡bi AwR©Z kw³B GK B‡jKUªb †fvë| ✅ †Kvb h‡š¿i Kg©`¶Zv ej‡Z Kvh©iZ kw³ Ges cÖ`Ë †gvU kw³i AbycvZ‡K eySvq| ✅ KvR, kw³ I ¶gZv GB wZbwUB Aw`K ev †¯‥jvi ivwk|KvR I kw³i GKK Ges gvÎv mgxKiY Awfbœ| ✅ ¶gZvi GKK: IqvU| 1HP = 746 watt = 550ft.lb/s ✅ GKRb gvby‡li Mo ¶gZv: 110 watt ev, 0.147 hp ✅ gvÎv mgxKiY: ¶gZv- [ML2T –3 ] ◈ 1kw = 103w ◈ 1 wh = 3600J ◈ 1kwh = 3.6 × 106 J ✅ Kg©`¶Zv ev Kvh©¶gZv () = Kvh©Ki kw³ ‡gvU kw³ = E1–E2 E1 × 100% ZvrÿwYK ÿgZv †Kvb gyûZ©‡K wN‡i AwZ ÿz`ª mg‡qi e¨eav‡b mg‡qi mv‡_ KvR Kivi nvi‡K ZvrÿwYK ÿgZv e‡j| ZvrÿwYK ÿgZv, P = Lt t0 W t = dw dt ÿgZv, ej I †e‡Mi m¤úK© P = W t = Fs t = F s t = Fv = mgv = mgs t ÿgZv = cÖhy³ ej e¯‘i †eM †f±i wPý Abyhvqx, P = F . v AveZ© N~Y©b MwZi †ÿ‡Î ÿgZv AveZ© MwZi †ÿ‡Î Avgiv Rvwb, KvR W = UK© †K․wYK miY; w = 2n = = Fr ÿgZv, P = W t = UK© †K․wYK miY mgq ÿgZv, P = UK© †K․wYK †eM REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. ¶gZvi gvÎv mgxKiY- [DU. 09-10; JU. 09-10; CU. 13-14] A. [ML2 T –2 ] B. [ML3 T –2 ] C.[ML2 T –3 ] D. [ML2 T –1 ] Ans C STEP 02 ANALYSIS OF RU QUESTION 01. Ak^ÿgZv wK? [RU. 15-16] A. 500ft.lb/s B. 746 erg/s C. 700 erg/s D. 550ft.lb/s Ans D 02. GK Ak¦ ¶gZv mgvb KZ IqvU? [RU. 15-16; JU. 10-11, 09-10] A. 746 B. 747 C. 798 D. 749 Ans A 03. ¶gZvi hvwš¿K e¨envwiK GKK- [RU. 06-07] A. IqvU B. Ak¦¶gZv C. wK‡jvIqvU D. dzU-cvDÛ Ans B STEP 03 ANALYSIS OF CU QUESTION 01. ¶gZvi GKK- [CU. 09-10] A. wbDUb/†m‡KÛ B. wbDUb- wgUvi C. Ryj †m‡KÛ D. Ryj/†m‡KÛ E. wbDUb/†m‡KÛ Ans D STEP 04 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. †Kvb h‡š¿i Kg©`¶Zv ej‡Z wK †evSvq? [KU. 10-11] A. Kvh©Kix kw³ I cÖ`Ë †gvU kw³i mgwó B. Kvh©Kix kw³ I cÖ`Ë †gvU kw³i AšÍi C. Kvh©Kix kw³ I cÖ`Ë ‡gvU kw³i AbycvZ D. Dc‡ii †KvbwUB bq Ans C PART B Analysis of Science & Technology Question HSTU 01. GKRb gvby‡li ¶gZv KZ? [HSTU: 15-16] A. 90 watt B. 120 watt C. 110 watt D. 220 watt S C info GKRb gvby‡li ¶gZv 110watt ev, 0.147 HP STEP 05 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. c`v_©we`¨v‡Z wb‡Pi †KvbwU Power Gi GKK bq? [MAT; 19-20] A. Ak¦kw³ B. IqvU C. Ryj D. Ryj/†m‡KÛ S C info welq GKK kw³ Ryj ÿgZv Ryj/‡m‡KÛ, IqvU Ges Ak¦kw³ (Horse power)
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 197 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 02. ¶gZv I kw³i e¨vcv‡i wb‡gœi †Kvb Z_¨wU mwVK? [MAT. 11-12] A. ¶gZv abvZ¡K I FYvZ¡K `yB cÖKvi n‡Z cv‡i B. kw³ GK iƒc †_‡K Ab¨iƒ‡c iƒcvšÍwiZ nq C. Amsi¶Ykxj ej Øviv K…Z KvR m¤ú~Y©iƒ‡c cybiæ×vi Kiv m¤¢e D. †Kv_v †_‡K D”PZv cwigvc Kiv n‡”Q MwZkw³ Zvi Dci wbf©ikxj Ans B 03. GK Ak¦^¶gZv = ? [MAT: 05-06] A. 647joule/sec B. 764joule/sec C. 746joule/sec D.467joule/sec Ans C 04. Kvh©Ki kw³ cÖ`Ë †gvU kw³ = ? [MAT. 03-04] A. KvR B. Kg©`¶Zv C. kw³ D. †KvbwUB bq Ans B STEP 06 ANALYSIS OF HSC BOARD QUESTION wb‡Pi DÏxcKwU co Ges cÖ‡kœi DËi `vI: †Kv‡bv e¯‘‡Z F = (3 i + 2 j – k)N gv‡bi ej 2sec wµqv Kivq e‡ji w`‡K e¯‘i †eM nq V = ( i + 2 j + k)ms–1 01. ÿgZv KZ? [Xv.‡ev 2021] A. (4 i + 4 j)W B. (4 i – 4 j + 4 k)W C. 6W D. 8W S C info P = F. V (3 ) ^ i + 2 ^ j ^ k .( ) ^ i + 2 ^ j ^ k W = 3 + 4 1 = 6W 02. wb‡Pi †KvbwU ÿgZvi gvÎv? [gv. †ev. 2017] A. MLT–2 B. ML2L –2 C. ML2T –3 D. MLT–1 Ans C STEP 2 mg„× †ewmK MvwYwZK cÖ Ö‡qvM (MATH) kU©KvU †UKwbK Concept 1 KvR msµvšÍ MvwYwZK cÖ‡qvM FORMULA 01. KvR = e¨wqZ kw³i cwigvY = MwZkw³i cwieZ©b ev w¯’wZkw³i cwieZ©b| 02. W = F. S = FScos = 1 2 mv1 2 – 1 2 mv2 2 = mgh1 mgh2 = mg(h1 h2) = k = pt = Fvt 03. w¯úªs Gi K…ZKvR, w = 1 2 kx2 = 1 2 k (xi 2 – xf 2 ) = 1 2 Fx 04. gnvKl© ej Øviv K…ZKvR: W = GMm 1 ra – 1 rb 05. Zwor cÖev‡ni `iæY Drcbœ Zvckw³, w = H= i2Rt = ms = mlf = mlv 06. cÖZ¨qbx ej, F = –kx 07. nvZzwo Dj¤^fv‡e †c‡iK‡K AvNvZ Ki‡j, w = mg(h + x) 08. n msL¨K BU w`‡q ¯§„wZdjK •Zix Ki‡Z K…Z KvR, W = mgh n(n – 1) 2 ‡hLv‡b GKwU B‡Ui fi = m Ges GKwU B‡Ui D”PZv = h B‡Ui msL¨v = n i. W = Fs (cos1 – cos2) miY Avbyf~wgK eivei) ii. W = mgs sin Abyf~wg†Ki mv‡_ †KvY m„wó Ki‡j iii. W = mgs cos †`qv‡ji mv‡_ †KvY m„wó Ki‡j CONCEPTUAL MATH MEx 01 6N ej †Kvb wbw`©ó f‡ii e¯‘i Dci wµqv Kivq e¯‘wU e‡ji w`‡K 60° †Kvb Drcbœ K‡i 10m `~‡i m‡i †Mj| Kv‡Ri cwigvY KZ? KvR, W = FS cos = 6 × 10 cos60° = 30j MEx 02 GKwU KYvi Dci F = (10 i + 10 j + 10 k) N ej cÖ‡qvM Ki‡j KYvwUi miY nq r = (2 i + 2 j – 2 k) m| ej KZ…©K m¤úvw`Z KvR KZ n‡e? KvR W = F. r = (10 i + 10 j + 10 k)N . (2 i + 2 j – 2 k) = (10 2) + (10 2) – (10 2) = 20J MEx 03 5 kg f‡ii GKwU e¯‘‡K f~wg n‡Z Lvov Dc‡ii w`‡K 10m Dc‡i DVvb nj| m¤úvw`Z Kv‡Ri cwigvb n‡e? W = mgh ev W = 5 9.8 10 = 490 J MEx 04 10m DuPz ¯’vb n‡Z 100gm fi wewkó GKwU ej‡K †d‡j w`‡j hw` ejwU cybivq 8m DuPz ch©šÍ D‡V Z‡e wK cwigvb kw³ e¨vq nq? ( ) w mg h1 h2 = 0.10 × 9.8(10 – 8) = 0.10 × 9.8 × 2 = 1.96J NOW START PRACTICE 01. GKwU †gvU‡ii ¶gZv 16.0W| 4 wgwb‡U Gi Øviv K…Z KvR KZ? 02. 300 Nm–1 ej aªyeK m¤úbœ GKwU w¯cÖs‡K KZUzKz msKzwPZ Ki‡j 1.5 J KvR Kiv n‡e? 03. 5 kg f‡ii GKwU e¯‘‡K f~wg n‡Z Lvov Dc‡ii w`‡K 10m Dc‡i DVv‡bv nj| m¤úvw`Z Kv‡Ri cwigvY n‡e? 04. Avbyf~wg‡Ki mv‡_ 300 †Kv‡b AvbZ 10m `xN© GKwU gB †e‡q 10 ‡m‡KÛ mg‡q 20 kg f‡ii †evSvmn 80 kg f‡ii GKRb †jvK Qv‡` D‡V| †jvKwUi KvR I ¶gZv wbY©q Ki| 05. GKwU †Nvov f~wgi mv‡_ 30° †Kv‡b 120 N ej cÖ‡qv‡M GKwU e¯Ív ‡U‡b 2 ms-1 mg‡e‡M miv‡Z _v‡K| 5 wgwb‡U KZ KvR K‡i? 06. 10wU BU GKwUi Dci Avi GKwU †i‡L GKwU ¯§„wZ ¯Í¤¢ •Zix Ki‡Z m¤úvw`Z KvR KZ? cÖwZwU B‡Ui D”PZv h = 0.25m Ges B‡Ui fi = 1kg NOW PRACTICE SOLVE : 01. W = Pt = 16 × 4 × 60 = 3840J 05. W = FS Cos = 120 × 600 × Cos30° = 6.235 × 104 J (S = vt = 2 × 5 × 60 = 600 m) 02. W = 1 2 kx2 ev x = 2w k = 2 1.5 300 = 0.1m 06. W = mgh 2 n(n – 1) = 1 9.8 0.25 10 ( 10 – 1) 2 = 110.25J 03. W = mgh ev W = 5 9.8 10 = 490 J 04. KvR, W = (m1 + m2)ghsin = (20 + 80) × 9.8 × 10 × sin30 = (20 + 80) 9.8 10 0.5 = 4900 J ¶gZv, P = W t = 4900 10 = 490 W
198 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. GKwU KYvi Dci F = (10 i + 10 j + 10 k) N ej cÖ‡qvM Ki‡j KYvwUi miY nq r = (2 i + 2 j – 2 k) m| ej KZ…©K m¤úvw`Z KvR KZ n‡e? [DU. 17-18] A. 20J B. 30 J C. 10 J D. 40 J KvR W = F. r = (10 i + 10 j + 10 k)N. (2 i + 2 j – 2 k) = (10 2) + (10 2) – (10 2) = 20J 02. 1g f‡ii GKwU e¯‘‡K 0.5me¨vmv‡a©i GKwU Abyf~wgK e„ËvKvi c‡_ 2m/s mg`ªæwZ‡Z †Nviv‡bv n‡”Q| GK c~Y© N~Y©‡bi Rb¨ cÖ‡qvRbxq Kv‡Ri gvb KZ? [DU. 15-16] A. 0 J B. 1 J C. 2 J D. 4 J Ans A 03. ‡Kvb e¨vw³ 30 Xv‡ji 5m DPuy Nl©Ywenxb Zj eivei GKwU 100N eøK †U‡b Zzj‡Q| eøKwU mg`ªæwZ‡Z Pj‡j e¨w³ wK cwigvb KvR Ki‡e? [DU. 14-15] A. 250J B. 500J C. 0 D. 100J W = Fh sin = 100 5 sin30 = 250J STEP 02 ANALYSIS OF JU QUESTION 01. 2N ej †Kv‡bv wbw`©ó f‡ii e¯‘i Dci wµqv Kivq e¯‘wU e‡ji w`‡Ki mv‡_ 60 †KvY Drcbœ K‡i 5m `~‡i m‡i †Mj| Kv‡Ri cwigvY KZ? [JU-A, Set-E. 20-21] A. 2 J B. 5 J C. 10 J D. 30 J S B info W = Fscos = 2 5 cos 60 = 5J 02. Kv‡Ri gvb k~b¨ n‡e hw` cÖhy³ ej I mi‡Yi ga¨eZ©x †KvYÑ [JU-A, Set-B. 20-21] A. 0 B. 45 C. 90 D. 180 S C info W = Fs cos = Fs cos 90 = 0 [ = 90] 03. 20 kg-m †K Joule G cÖKvk Ki| [JU. 17-18] A. 199 J B. 196 J C. 200 J D. 188 J W = mgh 20 kg m = 20 9.8 1= 196 J 04. GKwU e¯‘ mij c‡_ (3, 0, 0) we›`y †_‡K (3, 3, 0) we›`y‡Z †Mj| e¯‘wUi Dci wµqvkxj ej F = 4 i – 3 j + k n‡j K…ZKvR n‡e- [JU. 15-16] A. –9 J B. –10 J C. 0 J D. †KvbwUB bq S = (3 – 3) i + (3 – 0) j + (0 – 0) k = 3 j F = 4 i – 3 j + k w = F S = (3) (–3) = – 9 J 05. GKwU jb‡ivjvi Uvbv I †Vjvi Rb¨ Abyf~wg‡Ki mv‡_ 30 †Kv‡Y 20N ej cÖ‡qvM Kiv n‡jv| Uvbvi mgq IRb †Vjv A‡cÿv Kg n‡e- [JU. 15-16] A. 20N B. 10N C. 15N D. ‡KvbwUB bq Uvbvi mgq IRb = W – Fsin30 †Vjvi mgq IRb = W + Fsin30 Uvbvi mgq Kg n‡e = (W + Fsin30) (W F sin30) = 2 F cos30 = 2 20 1 2 = 20N 06. 2200Nm1 w¯úªs aªæe‡Ki GKwU w¯úªs Gi mv‡_ mshy³ GKwU ev· †Kvb Avbyf~wgK Z‡ji Dci w`‡q PjvPj Ki‡Z cv‡i | ev·wUi Dci w¯úªs ej Øviv K…Z KvR wnmve Ki hLb ev·wU mvg¨e¯’vb xt = 0 †_‡K xt = 0.15 Ae¯’v‡b hvq? [JU. 13-14] A. –24.75J B. 24J C. –74.75J D. 22.00J W = 1 2 kx2 = 1 2 (2200) (0.15)2 = 24.75J 07. GKwU KYvi Dci F=(5 i + 3 j – 2 k)N ej cÖ‡qv‡M KYvwUi r= (3 i – 2 j – k) m miY nq| m¤úvw`Z Kv‡Ri cwigvb KZ? [JU. 09-10] A. 5J B. 2J C. 7J D. 8J S Blank info KvR, W = F. r = 15 – 6 + 2 = 11J 08. 200 N ej †Kvb wbw`©ó f‡ii e¯‘i Dci wµqv Kivq e¯‘wU e‡ji w`‡Ki mv‡_ 60˚ †KvY Drcbœ K‡i 30 m `~‡i m‡i †Mj| Kv‡Ri cwigvY KZ? [JU. 09-10] A. 3000 W B. 3000 J C. 6000 J D. 9000 J KvR, W = FS cos 60˚ = 200 30 cos 60˚ = 3000 J 09. 120 cvDÛ IR‡bi GKRb †jvK 90 cvDÛ IR‡bi GKwU e¯‘‡K Abyf–wgK †g‡Si Dci w`‡q 6 dzU `~i‡Z¡ †V‡j wb‡Z 30 cvDÛ IR‡bi Avbyf~wgK ej cÖ‡qvM K‡ib| Kv‡Ri cwigvY wbY©q Ki| [JU. 09-10] A. 2700 ft – ℓbB. 540 ft – ℓb C. 180 ft – ℓb D. 720 ft – ℓb KvR, W = Fs = 30 6 = 180 ft – ℓb STEP 03 ANALYSIS OF RU QUESTION 01. GKwU 5 wK‡jvwgUvi mPj e¯‘i mi‡Yi j¤^w`‡K 10 wbDUb I 5 wbDUb gv‡bi `ywU ej e¯‘wUi Dci wecixZ w`‡K wµqv K‡i| ej `ywU Øviv K…Z Kv‡Ri gvb KZ n‡e? [RU. 17-18] A. 50 Ryj B. 25 Ryj C. 0 Ryj D. 15 Ryj Ans C 02. 2N ej †Kvb wbw`©ó f‡ii e¯‘i Dci wµqv Kivq e¯‘wU e‡ji w`‡Ki mv‡_ 60 †KvY Drcbœ K‡i 5cm `~‡i m‡i †M‡j Kv‡Ri cwigvY KZ? [RU. 15-16] A. 5J B. 0.005J C. 10J D. 0.05J W = Fs cos = 2 5 10–2 cos60 = 0.05J 03. 100 GKK †giæ kw³ I 10 †m. wg. •`N©¨ GKwU Pz¤^K‡K †P․¤^K ga¨‡iLvi mv‡_ 60 †KvY AvbZ Ki‡Z K…Z Kv‡Ri cwigvY KZ? (H = 0.32 GKK) [RU. 15-16] A. 180 erg B. 200 erg C. 160 erg D. 140 erg K…Z KvR = 100 10 cos60 0.32 = 160 erg 04. ‡Kvb ¯’v‡b GKwU e¯‘i IRb 250N| e¯‘wUi fi KZ? [RU. 15-16] A. 250kg B. 255kg C. 25.51kg D. 525.51kg m = W g = 250 9.8 = 25.51kg 05. 10N ej cÖ‡qvM GKwU Mvox‡K 100m miv‡Z K…Z KvR KZ? ( = 60) [RU. 15-16] A. 100J B. 1900J C. 500J D. 50J W = Fscos = 10 100 cos60 = 500J 06. 2N ej †Kvb wbw`©ó f‡ii e¯‘i Dci wµqv Kivq e¯‘wU e‡ji w`‡Ki mv‡_ 60o †Kvb Drcbœ K‡i 5cm `~‡i m‡i †M‡j Kv‡Ri cwigvb KZ? [RU. 14-15] A. 5J B. 0.005J C. 10J D. 0.05J w = Fs cos = 2 0.05 cos60 = 0.05J 07. 5N ej 19.6N IR‡bi e¯‘i Dci wµqv Kivq e¯‘wU e‡ji w`‡Ki mv‡_ 60 †KvY Drcbœ K‡i 10m `~‡i †Mj| Kv‡Ri cwigvY KZ? [RU. 12-13] A. 10J B. 20J C. 25J D. 50J W = Fscos = 5 10 cos60 = 25J STEP 04 ANALYSIS OF CU QUESTION 01. †Kv‡bv e¯‘i Dci cÖhy³ ej I mi‡Yi g‡a¨ †Kv‡Yi gvb KZ n‡j Kv‡Ri cwigvY m‡ev©”P nq? [CU-A, Set-4. 20-21] A. 0 B. 45 C. 90 D. 30 S A info W = Fs cos GLv‡b, cos Gi m‡e©v”P gv‡bi Rb¨ W Gi gvb m‡e©v”P n‡e| Zvn‡j cos = 1 = cos0 A_©vr = 0| 02. †Kvb ej Øviv K…Z KvR W = F.S| F Ges S †KvbwUB k~b¨ bv n‡jI KLb K…Z KvR k~b¨ n‡e? [CU. 15-16] A. F Ges S GKB w`‡K B. F Ges S wecixZgyLx C. F Ges S ci¯ú‡ii Dci j¤^ D. F Ges S ci¯úi mgvšÍivj E. F Ges S Gi ga¨eZx© †KvY 45 n‡j| W = FS cos = FS cos90 = 0 03. 40N IR‡bi e¯‘‡K †g‡S †_‡K 2m DuPz‡Z 2s a‡i ivL‡Z Kv‡Ri cwigvY KZ? [CU. 15-16] A. 0 J B. 40 J C. 120 J D. 160 J E. 240 J †Kv‡bv e¯‘‡K †Kvb wbw`©ó Ae¯’v‡b a‡i ivL‡j miY k~b¨ nq| ZvB KvR, W = 0
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 199 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 04. 25N ej Øviv †Kvb w¯cÖs‡K †U‡b 10cm e„w× Kiv n‡jv| Gi w¯cÖs aªæeK KZ? [CU. 12-13] A. 12.5Ncm–1 B. 25Nm C. 250Nm–1 D. 250Ncm E. 2.5Nm F = kx ev, k = F x = 25 0.1 = 250Nm–1 05. 2N ej †Kvb wbw`©ó f‡ii e¯‘i Dci wµqv Kivq e¯‘wU e‡ji w`‡Ki mv‡_ 60 †KvY Drcbœ K‡i 5m `~‡i m‡i †Mj| Kv‡Ri cwigvY KZ? [CU. 12-13] A. 2.5J B. 5J C. 10J D. 15J E. 20J W = FS cos = 2 5cos60 = 5J STEP 05 ANALYSIS OF DU-7 Clg QUESTION 01. GKwU `vjv‡bi Qv‡`i mv‡_ 5m j¤^v GKwU gB Abyf~wg‡Ki mv‡_ 30 †KvY K‡i Av‡Q| 30 kg f‡ii GKwU evjK 10 kg f‡ii GKwU e¯‘ wb‡q 30 sec G Qv‡` D‡V| evjKwUi K…Z Kv‡Ri cwigvY KZ? [DU. 7Clg-A: 20-21] A. 245 J B. 490 J C. 735 J D. 980 J S D info w= F(s sin) = ej (e‡ji w`‡K miY) =Fs sin30 = mgs sin30 = 40 9.8 5sin30 = 980J 30 evj‡Ki cÖ‡qvMK…Z e‡ji w`K evj‡Ki IRb = mg 5m STEP 06 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. 1 RyjMwZ kw³i †Kvb e¯‘i MwZi wecix‡Z 1N ej cÖ‡qvM Kiv n‡j e¯w‘U KZ`~i AMÖmi n‡q †_‡g hv‡e- [JnU. 10-11] A. 1m B. 10m C. 1 10 M D. ‡KvbwUB bq W = Ek = FS ev, 1 = 1.S ev, S = 1m 02. 6N ej †Kvb wbw`©ó f‡ii e¯‘i Dci wµqv Kivq e¯‘wU e‡ji w`‡K 60 †KvY Drcbœ K‡i 10m `~‡i m‡i †Mj| Kv‡Ri cwigvb KZ? [JnU. 09-10] A. 10J B. 30J C. 6J D. 15J KvR, w = FS cos = 6 × 10 cos60° = 30J 03. 100 N ej cÖ‡qvM Kivi d‡j †Kvb e¯‘i e‡ji w`‡K 0.5m miY NU‡j Kv‡Ri cwigvY KZ n‡e? [JnU. 09-10] A. 500 J B. 50 J C. 5 J D. 0.5 J KvR, W = Fs = 1000.5 = 50 J 04. 1 kN ej cÖ‡qv‡M †Kvb e¯‘i e‡ji w`‡K miY 20 m n‡j Kv‡Ri cwigvY- [JnU. 08-09] A. 2 103 J B. 20 103 J C. 2 104 J D. 20 102 erg KvR, W = Fs = 103 20 = 20 103 J KU 01. 25 N ej †Kvb w¯cÖs‡K †U‡b 10 cm e„w× K‡i| w¯cÖs‡K 6 cm cÖmvwiZ Ki‡j KZ KvR m¤úbœ nq? [KU. 15-16, SUST. 2007-08; JUST. 2014-15] A. 0.45 J B. 0.045 J C. 0.25 J D. 2.5 J W = 1 2 F x1 (x2) 2 = 1 2 25 0.1 (0.06)2 = 0.45J 02. GKwU B‡Ui •`N©¨ 0.24m cÖ¯’ 0.12m I D”PZv 0.06m Ges fi 2kg| B‡Ui •`N©¨‡K Abyf~wgK Ae¯’vb n‡Z Djø¤^ Ae¯’v‡b ivL‡Z wK cwigvb KvR Ki‡Z n‡e? [KU. 13-14] A. 1.564J B. 1.664J C. 1.764J D. 1.864J fi‡K‡›`ªi miY = L 2 – h 2 = 1 2 (0.24 – 0.06) = 0.09 K…Z KvR = mg miY = 2 9.8 0.09 = 1.764J 03. 2N ej †Kvb wbw`©ó f‡ii e¯‘i Dci wµqv Kivq e¯‘wU e‡ji w`‡Ki mv‡_ 60 †KvY Drcbœ K‡i 5 m `~‡i m‡i †M‡j Kv‡Ri cwigvY- [KU. 09-10] A. 5J B. 13J C. 5N D. 10J KvR, W = Fs cos = 2 5 cos 60˚ = 5 J Ans. 04. GKwU †gvU‡ii ¶gZv 16.0W. 4 wgwb‡U Gi Øviv K…Z KvR KZ? [KU. 09-10] A. 64J B. 3840J C. 240J D. 960J w = Pt = 16 × 4 × 60 = 3840J BU 01. 20kg fi wewkó GKwU evjK 1.5 wgwbU 2.5kg fi wewkó GKwU †evSv wb‡q 18m DPuy evwoi Qv‡` DVj| evjKwU wK nv‡i KvR Kij? [BU: 12-13] A. 44.1Watt B. 42.4Watt C. 24.5Watt D. 44.3Watt P = (m1 + m2)gh t = (20 + 2.5) 9.8 18 1.5 60 = 44.1W PART B Analysis of Science & Technology Question SUST 01. GKwU KYvi Dci cÖhy³ ej F(x) = (6x2 + 2)N KYvwU x = 0 m Ae¯’vb †_‡K x = 2m Ae¯’v‡b m‡i †M‡j cÖhy³ ej KZ©„K K…Z KvR KZ? [SUST. 18-19] A. 16 J B. 10 J C. 24 J D. 12 J E. 20 J w = x2 x2 Fdx = 2 0 (6x2 + 2)dx = [2x3 + 2x] 2 0 = 20J 02. k w¯cÖs aªæe‡Ki GKwU w¯cÖs‡K †U‡b j¤^v Kiv nj| wØZxq GKwU w¯cÖs‡K Gi A‡a©K cwigvY j¤^v Ki‡Z wظY KvR Ki‡Z nq| wØZxq w¯cÖs Gi w¯cÖs aªæeK KZ? [SUST. 12-13] A. K B. 2k C. 4k D. 8k E. 16k w2 w1 = k2x 2 2 k1x 2 1 = 2 1 = k2 1 2 k1 2 2 k2 = 8k1 = 8k 03. GKwU 10 kg f‡ii e¯‘‡K Abyf‚wgK Z‡j 5m miv‡bv n‡jv (mij •iwLKfv‡e)| AwfKl© e‡ji Øviv K…Z Kv‡Ri cwigvY KZ? [SUST. 12-13] A.0 J B. 10 J C. 49 J D. 50 J E. 490 J W = mgh = m.g.0 = 0 04. 20 kg f‡ii GKwU evjK 10m DuPz eªxR †_‡K b`xi cvwb‡Z jvd w`‡”Q, cvwb †_‡K 5m DPz‡Z †c․Qv‡bvi ci Zvi IRb- [SUST. 10-11] A. 198N. B. 99N C. 20N D. 0 N k~‡b¨ _vKv Ae¯’vq IRb ev Pvc = 0 JUST 01. GKwU `vjv‡bi Qv‡`i mv‡_ jvMv‡bv 5 wgUvi j¤^v GKwU gB Avbyf~wg‡Ki mv‡_ 300 †KvY K‡i Av‡Q| 60 †KwR f‡ii GK e¨w³ 20 †KwR f‡ii †evSv wb‡q 10 †m‡K‡Û Qv‡` D‡Vb| Zvi ¶gZv KZ? [JUST. 14 – 15] A. 3920 W B. 3395 W C. 1960 W D. 196 W E. 296 W P = mgs Sin t = (60 + 20) 9.8 5 sin30 10 = 196 W 02. 2mm e¨vmv‡a©i GKwU e„wói †duvUv 250m D”PZv †_‡K gvwUi Dci co‡Q| e„wói †duvUvi Dci AwfKl©xq ej KZUv KvR Ki‡e? [JUST. 14-15] A. 0.0821N B. 0.0801N C. 0.0820N D. 0.0831N E. 0.0841N W = mgh = 4 3 2 100 3 103 9.8 250 = 0.0821N
200 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES MBSTU 01. 60kg f‡ii GKRb gvbyl‡K 50m D”PZvq DV‡Z KZ KvR Ki‡Z n‡e? [MBSTU. 14-15] A. 29400J B. 30000J C. 29600J D. 3000J Ep = mgh = 60 9.8 50 = 29400J 02. 1 kg fiwewkó ‡Kvb e¯‘ GKwU Rvnv‡Ri Ici n‡Z 10m wb‡P co‡jv| g = 9.8ms–2 n‡j e¯‘wUi cÖv_wgK w¯’wZkw³ n‡e- [MBSTU. 14-15] A. 9.8J B. 0.98J C. 98J D. 980J Ep = mgh = 1 9.8 10 = 98J NSTU 01. GK e¨w³ GKwU e¯‘‡K 30 †m‡K‡Û 1m D”PZvq DVvq| Aci GK e¨w³ GKB e¯‘‡K 60 †m‡K‡Û GKB D”PZvq Zzj‡Z cv‡i| Zv‡`i Kv‡Ri AbycvZ n‡eÑ [NSTU: 14-15] A. 1:2 B. 1:1 C. 2:1 D. 4:1 W1 W2 = h1 h2 = 1 : 1 PSTU 01. 5kg f‡ii GKwU e¯‘ 5m DPz ‡_‡K GKwU ‡c‡i‡Ki Dci co‡j ‡c‡iKwU gvwUi wfZ‡i 10cm Xz‡K hvq| gvwUi Mo cÖwZ‡iva ej KZ? [PSTU. 15-16] A. 2500N B. 2450N C. 1250N D. 1249N mgh = FS F = mgh s = 5 9.8 5 0.10 = 2450N DU Technology 01. 1kilowatt-hour (kWh) =? [DU-Tech. 2020-21] A. 60 J B. 3600 J C. 3600000 J D. 36000 J S C info 1Kwh = 103 Js–1 3600s = 3600000 J 02. GKwU 25N ej †Kv‡bv w¯úªs‡K †U‡b 10cm cÖmvwiZ Ki‡Z cv‡i| w¯úªswU‡K 4cm cÖmvwiZ Ki‡Z KZ KvR m¤úbœ n‡e? [DU-Tech. 2020-21] A. 0.4 J B. 0.2 J C. 0.6 J D. 0.8 J S B info W = 1 2 F x1 (x2) 2 = 1 2 25 0.1 (0.04)2 = 0.2J STEP 07 ANALYSIS OF ENGINEERING & BUTex QUESTION BUET 01. GKwU KYvi Dci F i j kN ej cÖ‡qvM Kivi d‡j KYvwUi d idy j km miY nq| dy Gi gvb KZ nj m¤úvw`Z Kv‡Ri cwigvb k~b¨ n‡e? [BUET: 12-13] A. 0 B. 5 C. 6 D. 6 w = F d = i j k idy j k 0 = 15 – 6dy + 15 6 Dy = 30 ev, dy = 5 02. 51024kg fi Ges 6.1 106m e¨vmv‡a©i wewkó GKwU MÖ‡ni c„ô n‡Z 2.0kg f‡ii GKwU e¯‘‡K gnvk~b¨ cvVv‡Z cÖ‡qvRbxq kw³i cwigvb nj- [BUET: 11-12] A. 9.0J B. 2.2 108 J C. 1.1 108 J D. 1.1 106 J kw³ E = W = GMm R = 6.67 10–11 1024 5 2 (6.1 106 ) =1.1108 J 03. f~wg †_‡K 3m D”PZv wewkó GKwU ¯’vb †_‡K 2.0kg fi wewkó GKwU Kv‡Vi UzKiv Xvjy c_ †e‡q 50J kw³ wb‡q gvwU‡Z co‡Q| †e‡q covi Rb¨ Nl©Y KZ…©K Kv‡Vi UzKivwUi Dci Kv‡Ri cwigvb cÖvq| [BUET: 09-10] A.9J B. 6J C.44J D. 18J Wk= (mgh-w) = (2 9.8 3 – 50) = 8.8 = 9J CKRuet. Combind 01. GKwU †c‡iK GKwU Avbyf~wgK Kv‡Vi Dci Lvov fv‡e ivLv Av‡Q| 1 kg f‡ii GKwU nvZzox 4 m/sec †e‡M †c‡iKwUi wb‡Pi w`‡K AvNvZ Kiv nj| †c‡iKwU hw` Kv‡Vi g‡a¨ 0.015 m cÖ‡ek K‡i, Z‡e Kv‡Vi Mo cÖwZeÜK ej †ei Ki? [CKRUET. 2020-21] A. 5413.13 N B. 523. 33 N C. 523.13N D. 453.13 N E. None of them S A info K…Z KvR = †gvU hvwš¿K kw³i cwieZ©b Fx = 1 2 mv2 + mgx F = 1 2 × 1 × 42 + (1 × 9.81 × 0.015) 0.015 N = 543 .13 N STEP 08 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. wmivR mv‡n‡ei fi 20 †KwR| wZwb 25 †mw›UwgUvi DuPz †gvU 20wU wmuwo 10 †m‡K‡Û DV‡j Zvi m¤úvw`Z ÒKv‡Ri cwigvYÓ KZ? [MAT; 19-20] A. 1080 Ryj B. 980 Ryj C. 900 Ryj D. 1000 Ryj S B info m¤úvw`Z Kv‡Ri cwigvY W = Fs = mgs = 20 9.8 0.25 20 = 980 J| 02. 500g f‡ii GKwU e¯‘‡K w¯’i Ae¯’vb †_‡K 2N ej cÖ‡qvM Kwiqv 1m `~i‡Z¡ miv‡bv n‡jv| e¯‘wUi Dci wK cwigvY KvR Kiv n‡jv? [MAT. 14-15] A. 2J B. 9.8J C. 4.9J D. 0.5J W = FS = 2 1 = 2J DAT 01. 40N IR‡bi e¯‘‡K †g‡S †_‡K 2 wgUvi DuPz‡Z 2 †m‡KÛ a‡i ivL‡Z Kv‡Ri cwigvY n‡e- [DAT; 19-20] A. 0 J B. 180 J C. 40 J D. 120 J ej cÖ‡qv‡M †Kv‡bv e¯‘i hw` miY bv N‡U A_ev e¯‘i miY e‡ji Awfgy‡Li j¤^ eivei nq Z‡e Zv‡K k~b¨KvR e‡j| 40N IR‡bi e¯‘‡K †g‡S †_‡K 2 wgUvi DuPz‡Z 2 †m‡KÛ a‡i ivL‡Z e¯‘wUi †Kv‡bv miY N‡U bv e‡j Kv‡Ri cwigvY k~b¨ nq| 02. 60kg f‡ii GK e¨w³ 6m j¤^v GKwU wmuwo †e‡q wb‡P bvgj| f~wgi mv‡_ wmuwo 30 †Kv‡Y Aew¯’Z n‡j †jvKwUi wb‡P bvg‡Z wb‡¤œ D‡jøwLZ KZ Ryj (J) KvR Ki‡Z n‡qwQj? [DAT. 07-18] 6m 30 h A. 2940 B. 5880 C. 5800 D. 2900 S Blank info W = mg h = 60 9.8 6sin30 = 1764J AFMC 01. 1 wK‡jvIqvU NÈv mgvb KZ Ryj? [AFMC. 2020-21] A. 3.6 106 J B. 3.6 105 J C. 3.6 104 J D. 3.6 103 J S A info wK‡jvIqvU-NÈv: mvaviYZ we`y¨r kw³i wnmve-wbKv‡ki mgq wK‡jvIqvU-NÈv GKKwU e¨eüZ nq| GK wK‡jvIqvU ÿgZv m¤úbœ †Kv‡bv hš¿ GK NÈv KvR Ki‡j †h kw³ e¨q nq Zv‡K GK wK‡jvIqvU NÈv e‡j| 1 kWh = 1000 Wh = 1000 Js–1 3600s 1 kWh = 3.6 106 J = 36 105 J 1kWh = 1B.O.T = 1unit = 3.6106 J [B.O.T means Board of Trade] STEP 09 ANALYSIS OF HSC BOARD QUESTION 01. †Kv‡bv KYvi Dci cÖhy³ ej F = ( i + j – 2 k)N I ej cÖ‡qv‡M S = (2 i – 3 j – k)m miY n‡jv| ej Øviv K…Z KvR KZ? [iv.‡ev 2021] A. – 3J B. 1J C. 3J D. 7J S B info w = – F . – S = ( i + j – 2 k). (2 i – 3 j – k) = 2 – 3 + 2 = 1J
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 201 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 02. 2kg f‡ii 1.5m j¤^v GKwU iW‡K kvwqZ Ae¯’v n‡Z Lvov Ki‡Z Kx cwigvY KvR Ki‡Z n‡e? [iv.‡ev 2021] A. 0J B. 14.7J C. 29.4J D. 44.1J S B info w = mg h 2 = 2×9.8×1.5 2 = 14.7J 03. ej I mi‡Yi ga¨eZx© †KvY n‡j FYvZ¥K Pv‡R©i kZ© n‡e [P. †ev. 2017] A. < 90 B. 90 < 180 C. 180 < 90 D. 90 < 90 Ans B 04. e‡ji weiy‡× KvR m¤úbœ nq hLb ej I mi‡Yi ga¨eZ©x †KvY Gi gvb-[P. †ev. 2015] A. 0 < 90 B. 0 < 90 C. 90 180 D. 90 < 180 Ans D 05. cÖwZwU KYvi Dci F = (2 i + 3 j – k)N ej cÖ‡qvM Kivq KYvwUi r = ( i + j + k)m miY N‡U| F I r Gi ga¨eZ©x †KvY KZ? [P.‡ev 2021] A. 48.19 B. 51.88 C. 81.84 D. 84.53 S B info = cos–1 F . r |F|.|r| = cos–1 4 14. 3 = 51.88˚ 06. wP‡Î F e‡ji cÖfv‡e eøKwU‡K AvbZ Nl©Ygy³ Z‡j Ic‡ii w`‡K †bqv n‡”Q| wb‡Pi †Kvb e‡ji weiæ‡× KvR n‡q‡Q? [w`.‡ev 2021] m V F V A. mg B. mgsin C. mgcos D. mgtan S B info F = mg cos (90 –) = mg sin 07. GKwU KYvi Ici F = (2i ˆ + 2j ˆ + kˆ) N ej cÖ‡qv‡M KYvwUi miY r = (6i ˆ – 3j ˆ – 2kˆ) m nq| cÖ‡qvMK…Z ej KZ…©K m¤úvw`Z Kv‡Ri cwigvY n‡e- [w`. †ev. 2017] A. 20 J B. (8i ˆ – j ˆ – kˆ) J C. 4 J D. (– 4i ˆ + 5j ˆ + 3kˆ) J S C info W = F .r = (2i ˆ + 2j ˆ + kˆ).(6i ˆ – 3j ˆ – 2kˆ) = 12 – 6 – 2 = 4 J 08. Kv‡Ri cwigvY me‡P‡q †ewk nq hLb cÖhy³ ej I mi‡Yi g‡a¨ †Kv‡Yi gvb- [w`. †ev. 2016; wm. †ev. 2015] A. 0˚ B. 45˚ C. 90˚ D. 30˚ S A info W = Fscos F I S Gi wbw`©ó gv‡bi Rb¨ KvR Gi gvb me©‡”Pv n‡e hLb cos = 1 cos = cos0˚ = 0 09. 5kg fim¤úbœ GKwU e¯‘i Dci GKwU ej F = (10 ) ^ i + 3^ j 2 ^ k N Gi wµqvq e¯‘wUi Ae¯’vb r1 = (8 ) ^ i + 7^ j 3 ^ k m †_‡K Aci GKwU Ae¯’vb r2 = (12 ) ^ i + 2^ j + 7^ k m G ¯’vbvšÍwiZn‡jv| G‡Z K…ZKvRÑ [h.‡ev. 2019] A. 2J B. 3J C. 5J D. 7J S C info W = F .r = F . (r2 – r1) = (10i ˆ + 3j ˆ – 2k ˆ ) . (4i ˆ – 5j ˆ + 10k ˆ ) = 40 – 15 – 20 = 5 J 10. ej I mi‡Yi ga¨eZx© †Kv‡Yi †Kvb gv‡bi Rb¨ e‡ji Øviv KvR m¤úbœ n‡e? [h. †ev. 2017] A. 60 B. 120 C. 180 D. 210 S A info e‡ji Øviv KvR abvZ¥K nIqvi kZ©: ˚ < 90˚ 11. F I S h_vµ‡g ej I miY n‡j Gi †Kvb gv‡bi Rb¨ KvR k~b¨ nq? [h. †ev. 2016] A. 0 B. 45 C. 90 D. 180 S C info W = F .S FScos = 0 cos = 0 = 90˚ wb‡Pi DÏxcKwU c‡ov Ges 12 I 13 bs cÖ‡kœi DËi `vI : [h. †ev. 2015] GKwU KYvi Dci F = (2 ^ i +3 ^ j ^ k )N ej cÖ‡qvM Kivq KYvwUi r = ( ^ i + ^ j + ^ k ) m miY N‡U| 12. K…Z Kv‡Ri gvb KZ? [h. †ev. 2015] A. 2 Joule B. 14 Joule C. 4 Joule D. 6 Joule S C info W = F .r = 2 + 3 – 1 = 4 J 13. F I r Gi ga¨eZx© †KvY KZ? [h. †ev. 2015] A. 22.20 B. 51.88 C. 81.84 D. 84.53 S B info = cos–1 F . r |F|.|r| = cos–1 4 14. 3 = 51.88˚ 14. e‡ji Øviv Kv‡Ri †ÿ‡ÎÑ [Kz.‡ev. 2019] A. 0 90 B. 90 180 C. 0 90 D. 90 180 Ans A wb‡Pi Z_¨ n‡Z 15 I 16 bs cÖ‡kœi DËi `vI : ÒGKwU nvZzwoi fi 1kg| GwU 10ms-1 †e‡M P‡j GKwU †c‡i‡Ki gv_vq AvNvZ Kij| G‡Z †c‡i‡Ki miY nj 2cmÓ| 15. KZÿb nvZzwowU †c‡i‡Ki ms¯ú‡k© wQj? [Kz. †ev. 2017] A. 410-3 sec B. 210-3 sec C. 110-3 sec D. 0.2510-3 sec S A info s = u + v 2 t t = 2s u + v = 2 × 0.02 10 + 0 s t = 4 × 10–3 s 16. nvZzwo Øviv m¤úvw`Z KvR KZ? [Kz. †ev. 2017] A. 100J B. 50J C. 10J D. 0.2J S B info W = Ek = 1 2 mv2 – 0 = 1 2 × 1 × 102 = 50 J 17. [Kz. †ev. 2016] A. dw = Fd r B. dw = F d r C. dw = Fdr D. dw = Fdr sin Ans A 18. GKwU KYvi Dci, F = (5 i + 3 j – 3 k)N ej cÖ‡qvM Kivi d‡j hw` KYvwUi miY r = (4 i – 3 j – 3 k)m nq Zvn‡j G‡ÿ‡Î K…ZKv‡Ri gvb wbY©q Ki| [wm.‡ev 2021] A. 20J B. 9J C. 2J D. 1J S A info w = F . S = 5 4 3 3 + 3 3 = 20J 19. Kv‡Ri gvb k~b¨ n‡e hw` cÖhy³ ej I mi‡Yi ga¨eZx© †KvY- [wm. †ev. 2016; h. †ev. 2016; iv. †ev. 2015] A. 90˚ B. 180˚ C. 0˚ D. 360˚ Ans A 20. 5kg f‡ii e¯‘‡K †U‡b Abyf~wgK eivei 5m miv‡j AwfKl©xq ej Øviv Kv‡Ri gvb KZ n‡e? [g.‡ev 2021] A. 0J B. 5J C. 25J D. 245J S D info W = mgh =59.85=245J 21. w¯’wZ¯’vcK e‡ji weiæ‡× mi‡Yi gvb wظY Ki‡j KvR e„w× cv‡e [gv. †ev. 2016] A. 100% B. 200% C. 300% D. 400% S C info W = 1 2 kx 2 W x 2 W1 W2 = x 2 1 x 2 2 W2 = x2 x1 2 × W1 = 2x1 x1 2 × W1 = 4W1 e„w× = 4 – 1 = 300%
202 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 2 kw³ msµvšÍ MvwYwZK cÖ‡qvM FORMULA 01. †h †Kvb mg‡qi MwZkw³, Ek = 1 2 mv2 ; Ek v 2 ev v Ek ; †h †Kvb mg‡qi wefekw³, Ep = mgh ; Ep h 02. Ep= mg (h1~h2) (`ywU D”PZvi †¶‡Î) Ek= 1 2 m (v1 2 ~ v2 2 ) (`ywU †e‡Mi †¶‡Î) Ges Ek = p 2 2m 03. f~wg ¯úk© Kiv gyû‡Z© Ek = Ep = mgh mgh = FS 1 2 mv2 = FS = mgh v = 2gh 04. †Kvb e¯‘‡K h D”PZv n‡Z †Q‡o w`‡j hvÎv c‡_i †Kvb we›`y‡Z, Ep = mgx, Ek = mg(h – x) Note: (i) Ek = 1 2 mv2 ; Ek m [v constant] (ii) Ek= p 2 2m; Ek 1 m [p constant] A we›`y‡Z, Ek = A; Ep = 0 B we›`y‡Z, Ek = A 2 – x 2 ; Ep = 1 2 m 2 x 2 C we›`y‡Z, Ek = 0; Ep = 1 2 m 2A 2 †gvU kw³, E = Ek + Ep = 1 2 KA2 = 1 2 m 2A 2 x = o x = A A C B P CONCEPTUAL MATH MEx 01 16 †KwRi GKwU †evgv we‡ùvwiZ n‡q 4 kg I 12kg Gi `ywU LÛ nj| 12 kg f‡ii †eM 4m/s n‡j Ab¨ UzKivwUi MwZ kw³ KZ? Ab¨ UzKivwUi MwZkw³ Ek = 1 2 .4.(12) 2 = 288J MEx 02 20 kg fi wewkó GKwU e›`yK †_‡K ¸wj Qyuo‡j ¸wj 10 ms–1 ‡e‡M wbM©Z nq| ¸wji fi 100g Ges ¸wjwU GKwU Kv‡Vi Z³vq 20 cm `yiZ¡ cÖ‡ek K‡i †_‡g †M‡j Dnvi Dci cÖhy³ evav RwbZ ej KZ? 1 2 mv2 = FS F = mv2 2S = 0.1 10 10 2 0.2 = 25N MEx 03 5 kg f‡ii GKwU cv_i‡K 50 m/s †e‡M Dc‡ii w`‡K wb‡¶c Kiv nj| 5 s ci Dnvi MwZkw³ KZ? v = u-gt = 50–9.8 5 = 1 m/sec 2 2 1 mv k E = 1 2 5 1 2 = 2.5 J MEx 04 5kg f‡ii GKwU ej‡K Dci †_‡K †Q‡o ‡`Iqv nj| gvwU‡Z ¯úk© Kivi g~û‡Z© Zvi MwZkw³ 980 J n‡j, ejwU KZ D”PZv †_‡K Qvov n‡qwQj? mgh = 980 ev, h 20m 5 9.8 980 MEx 05 200gm f‡ii GKwU e¯‘ 10m Dci †_‡K wb‡P c‡o hvq| f~-c„ô‡K ¯úk© Kivi c~e© gyû‡Z© Gi MwZkw³- f~wg ¯úk© Kivi c~e© g~û‡Z© MwZkw³, Ek = mgh = 0.2 9.8 10 = 19.6J NOW START PRACTICE 01. 5 kg f‡ii GKwU nvZzwo Øviv †`qv‡j GKwU †c‡iK‡K 2 ms–1 †e‡M AvNvZ Kivq GwU 10 cm Xz‡K †Mj| †`qv‡ji Mo evav ej wbY©q Ki| 02. 10 m DuPz ¯’vb †_‡K 100 gm fi wewkó GKwU ej‡K †d‡j w`‡j hw` ejwU cybivq 8 m DuPz ch©šÍ I‡V Z‡e wK cwigvY kw³ ¶q nq? 03. 5 kg f‡ii GKwU nvZzwo Øviv †`qv‡j GKwU †c‡iK‡K 4 ms–1 †e‡M AvNvZ Kivq GwU 25 m Xz‡K †Mj| †`qv‡ji Mo evav ej wbY©q Ki| 04. 1kg f‡ii GKwU nvZzwo Avbyf~wgK Kv‡Vi Dci Dj¤^fv‡e iw¶Z GKwU †c‡iK‡K Lvov bx‡Pi w`‡K 0.8ms–1 †e‡M AvNvZ Kivq †c‡iKwU Kv‡Vi 0.02m Xy‡K hvq| evav ej wbY©q Ki? 05. 25 gm f‡ii GKwU ey‡jU 500 m/s ‡e‡M GKwU j¶¨ e¯‘‡K AvNvZ K‡i 100 m/sec ‡e‡M †ei n‡q †Mj| e¯‘wUi wfZi w`‡q hvIqvi d‡j wK cwigvY kw³ e¨wqZ nj? NOW PRACTICE SOLVE : 01. Fs = 2 1 mv2 F = 2s mv2 F = 2 0.10 5 (2) 2 = 100 N 02. E = mg (h x) = 0.1 9.8 × (10 8) = 1.96 J 03. Fs = 1 2 mv 2 F = mv2 2s F = 5 (4) 2 2 25 = 1.6 N 04. 1 2 mv 2 = FS F = mv2 2s = 1 (0.8) 2 2 .02 = 16N 05. Ek = 1 2 m (v1 2 ~ v2 2 ) = 1 2 .025 (5002 ~ 1002 ) = 3000 J
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 203 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. 300 Nm-1 ej aªæeK m¤úbœ GKwU w¯cÖs‡K KZUzKz msKzwPZ Ki‡j 1.5 J KvR Kiv n‡e? [DU. 06-07] A. 0.1m B. 1.5m C. 3.0m D. 1.0m Ek = 1 2 kx2 ev, 1.5 = 1 2 300 x 2 ev, x = 0.1m 02. 2N/m w¯úªs aªæeK m¤úbœ GKwU Av`k© w¯úªs‡qi •`N©¨ mvg¨ve¯’v †_‡K 0.1m e„w× Ki‡j w¯úªs‡qi w¯’wZkw³i e„w× n‡e- [DU. 04-05] A. 0.1J B. 0.001J C. 1J D. 0.01J W = 1 2 kx2 = 1 2 2 (0.1)2 = 0.01J 03. 3kg f‡ii GKwU cv_i‡K 30m/s †e‡M Dc‡ii w`‡K wb‡ÿc Kiv nj| 2s ci Dnvi MwZkw³ KZ? [DU. 00-01] A. 161.62J B. 1200J C. 1000J D. 1500J v = u – gt = 30 – 9.81 2 = 10.38ms–1 Ek = 1 2 mv2 = 1 2 3 (10.38)2 = 161.62 J STEP 02 ANALYSIS OF JU QUESTION 01. 30 m D”PZv †_‡K GKwU ej‡K webv evavq co‡Z w`‡j †Kvb D”PZvq ejwUi MwZkw³ wefekw³i wظY n‡e? [JU-A, Set-G. 20-21] A. 10 m B. 15 m C. 20 m D. 30 m S A info x = h n + 1 = 30 2 + 1 = 10 m STEP 03 ANALYSIS OF RU QUESTION 01. 20 kg f‡ii GKwU KYvi †eM (4 i + 5 i + 6 k) ms1 n‡j Gi MwZkw³ KZ n‡e? [RU. Astrazeneca, Set-1. 20-21] A. 300J B. 600 J C. 770J D.1440 J S C info KYvi †e‡Mi gvb, v = 4 2 + 52 +62 = 16 + 25 +36 = 77 Ek = 1 2 mv2 = 1 2 20 77 = 770J 02. 3kg f‡ii e¯‘‡K f~c„ô †_‡K 20m D”PZvq DVv‡bv n‡jv| e¯‘wUi kw³ KZ? [RU. 12-13] A. 580 J B. 588 J C. 600 J D. 560 J e¯‘wUi kw³ = mgh = 3 9.8 20 = 588J STEP 04 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. 60 kg f‡ii R‣bK e¨w³ 20 min G 180 m DuPzP‚ovq Av‡ivnY K‡ib| Zvi wefe kw³ KZ Ryj? [KU. 17-18] A. 9.58 104 B. 10.58 104C. 12.58104 D. 15.58104 wefe kw³, U = mgh = 60 9.8 180 =10.58104 J BU 01. GKwU w¯cÖs Gi miY hLb x cm ZLb Zvi wefe kw³ U. miY KZ n‡j wefe kw³ wظb n‡e? [BU: 15-16] A. x B. 2x C. 2x D. 4x u2 u1 = x2 x1 2 (u = 1 2 kx2 ) ev, 2 1 = x2 x1 2 ev, x2 = 2x1 PART B Analysis of Science & Technology Question SUST 01. cv‡k¦©i †jLwP‡Î GKwU w¯cÖs G cÖhy³ e‡ji mv‡_ •`N©¨e„w×i cwieZ©b †`Lv‡bv n‡q‡Q| w¯cÖswUi •`N©¨e„w× 2.0 cm n‡j w¯cÖs G mwÂZ kw³i cwigvY KZ J? [SUST. 15-16] cm 4 2 0 0 2 3 4 6 N A. 0.03 B. 0.05 C. 1.50 D. 2.00 E. 2.50 F = kx1ev, k = F x1 mwÂZ kw³ Ep = 1 2 kx2 = 1 2 F. x 2 x1 = 1 2 6 (0.02) 2 0.04 = 0.03 STEP 05 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. GKwU 2 †KwR f‡ii e¯‘ 10 wgUvi D”PZv †_‡K co‡j, f~wg ¯úk© Kivi c~e© gyû‡Z© Gi MwZkw³ KZ n‡e? [MAT. 2020-21] A. 95.01 B. 74.4 J C. 19.6 J D. 39.2 J S Blank info Dc‡i _vKvKvjxb e¯‘wUi w¯’wZkw³ = f~wg ¯úk© Kivi wVK Av‡Mi gyn~‡Z© e¯‘wUi MwZkw³ = mgh = 2 10 9.8 = 196 J 02. GK Ak¦kw³ (Horse power) mgvb KZ IqvU? [MAT; 19-20] A. 746 B. 756 C. 766 D. 776 Ans A STEP 06 ANALYSIS OF HSC BOARD QUESTION 01. 100 Nm–1 w¯úªs aªæeKm¤úbœ GKwU w¯úªs‡K 2 cm cÖmvwiZ Ki‡Z •`N©¨ eivei cÖhy³ ej n‡eÑ [Xv.‡ev 2021] A. – 1N B. 0.02N C. 2N D. 200N S C info F = kx = 100 × 2 100 = 2N 02. wP‡Î m f‡ii e¯‘wU †U‡b †Q‡o w`‡j ¯ú›`‡bi K¤úv¼ n‡eÑ [Xv.†ev. 2019] A. f = 1 2 k1 k2 m B. f = 1 2 m k1 + k2 C. f = 1 2 m k1 k2 D. f = 1 2 k1 + k2 m Ans C 03. †Kv‡bv w¯úªs‡K 5N ej Øviv †U‡b 10cm cÖmvwiZ Kiv n‡j, w¯úªs aªæeK KZ n‡e? [P.‡ev. 2019] A. 0.5 Nm-1 B. 2 Nm-1 C. 50Nm-1 D. 250 Nm-1 S C info K = F x = 5 0.1 = 50 Nm–1
204 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 04. GKwU w¯úªs Gi T 2 ebvg m Gi †jLwPÎ †KvbwU? [h. †ev. 2016] A. B. C. D. Ans A wb‡Pi DÏxc‡Ki Av‡jv‡K 05 I 06bs cÖ‡kœi DËi `vI : •`N©¨ e„w× (cm) 1 B V 2 3 4 O 1 2 3 4 5 6 5 ej (N) †jLwPÎwU‡Z GKwU w¯úªs-G cÖhyw³ e‡ji mv‡_ •`N©¨ e„w×i cwieZ©b †`Lv‡bv n‡q‡Q| 05. Nm–1 GK‡K w¯úªs aªæeK KZ? [Kz.‡ev 2021] A. 2 B. 200 C. 150 D. 50 S C info A we›`y‡Z, F = kx k = F x = 3 (0.02) = 150 Nm–1 06. w¯úªswUi •`N©¨ e„w× 3cm n‡j w¯úªs-G mwÂZ kw³i cwigvY KZ?[Kz.‡ev 2021] A. 0.0675J B. 0.0576J C. 0.0275J D. 0.0375J S A info Ep = 1 2 kx2 = 1 2 × 150 × (0.03)2 = 0.0675J wb‡Pi DÏxcKwU co Ges 07 I 08 bs cÖ‡kœi DËi `vI: [Kz. †ev. 2016] GKwU w¯úªs Gi Dc‡ii cÖvšÍ AvUKv‡bv Ges Aci cÖv‡šÍ 0.25kg f‡ii GKwU †MvjK Szjv‡bv Av‡Q| †MvjKwU‡K mvg¨ve¯’v n‡Z 0.08m Dc‡i DwV‡q †Q‡o †`qv nj| w¯úªs Gi MwZi miY ebvg mgq MÖvdwU wb‡P †`qv nj: 07. †MvjKwUi m‡e©v”P Z¡i‡Yi gvb KZ? [Kz. †ev. 2016] A. 2 4 s/ms2 B. 2 s/ms2 C. 2 2 s/ms2 D. 4 2 s/ms2 S C info amax = 2A = 2 T 2 × A = 2 0.6 – 0.2 2 × 0.08= 2 2 ms–2 08. MwZkw³i m‡e©v”P Ges me©wb¤œ gvb ebvg mgqm~PK MÖvd †KvbwU? [Kz.†ev. 2016] A. B. C. D. Ans C 09. cwieZ©bkxj ej Øviv K…Z KvR n‡jvÑ [Kz. †ev. 2015] A. W = f i F.d s B. W = 32 x1 Fs (x)dx C. W = GMm 1 rb – 1 ra D. W = x 0 Fdx Ans A Concept 3 MwZkw³ Ges wefe kw³ msµvšÍ MvwYwZK cÖ‡qvM FORMULA 01. †Kv‡bv e¨e¯’vq †Kej msiÿYkxj ej wµqv Ki‡j e¨e¯’vi MwZkw³ (Ek) I wefe kw³i (EP) mgwói me©`v aªæe _v‡K| A_©vr Ek + EP = aªæeK| ASPECT SPECIAL: h D”PZv n‡Z e¯‘‡K †Q‡o ‡`qv n‡jv, x D”PZvq MwZkw³ w¯’wZkw³i n ¸Y n‡j, x = n 1 h w¯’wZkw³ MwZkw³i n ¸Y n‡j, x = n 1 nh [w¯’wZ kw³ I MwZ kw³ mgvb n‡j n = 1] B C h 30m (30 – h)m A h x h – x Ep Ek Model Example01 30m D”PZv †_‡K GKwU e¯‘‡K webv evavq co‡Z w`‡j †Kv_vq Dnvi MwZkw³ wefe kw³i wظY n‡e? General Rules [Written] 3 in 1 Shortcut Tricks & Tips [MCQ] g‡bKwi, f~wg n‡Z h Ic‡i Ges Ici n‡Z (30 – h)m wb‡P MwZkw³ wefekw³i wظY n‡e| GLv‡b, h = 30m; v0 = 0 Avgiv Rvwb, wefekw³, Ep = mgh; MwZkw³, Ek = 1 2 mv2 cÖkœg‡Z, Ek = 2Ep ............(i) v 2 = v0 2 + 2g (30 – h) v 2 = 0 + 2g(30 h) = 2g (30 h) Ek = 1 2 m 2g (30 h) = mg (30 h) mgxKiY (i) Abyhvqx, mg (30 h) = mg (30 h) 2h = 30 h, ev, h = 10m GLv‡b, x = f~wg n‡Z D”PZv h = m‡e©v”P D”PZv n = MwZkw³, wefekw³i KZ¸Y x = h n + 1 = 30 2 + 1 = 10m B C h 30m (30 – h)m A
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 205 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES NOW START PRACTICE 01. 100m D”PZv †_‡K GKwU e¯‘‡K webv evavq co‡Z w`‡j †Kv_vq Gi MwZ kw³ wefe kw³i wZb ¸Y n‡e? 02. 60m D”PZv n‡Z GKwU e¯‘‡K webv evavq co‡Z w`‡j f~wg n‡Z KZ D”PZvq wefekw³ MwZkw³i A‡a©K n‡e? NOW PRACTICE SOLVE : 01. MwZkw³ wefe kw³i wZb¸Y, A_©vr n = 3 awi, f~wg n‡Z x D”PZvq MwZkw³ wefe kw³i wZb¸Y| x = h n + 1 = 100 3 + 1 = 100 4 = 25m 02. x = nh n + 1 = 1 2 60 1 2 + 1 = 20m REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. 30m D”PZv †_‡K GKwU e¯‘‡K webv evavq co‡Z w`‡j †Kvb D”PZvq MwZkw³ wefekw³i wظY n‡e? [DU. 16-17; KU. 15-16; CUET: 10-11] A. 10m B. 15 m C. 25 m D. 28 m x = 30 2 + 1 = 10m 02. wP‡Î †`Lv‡bv c_ w`‡q GKwU 4.0N IR‡bi cv_i‡K c„w_exi AwfKlx©q †¶‡Î P we›`y †_‡K R we›`y‡Z ¯’vbvšÍwiZ Kiv nj| cv_iwUi w¯’wZ kw³ KZ e„w× †cj? [DU. 13-14; CU. 10-11] Q R P 30m 40m 50m A. 120J B. 200J C. 280J D. 1200J Ep = mgh = 4 30 = 120J 03. 16kg Gi GKwU †evgv we‡ùvwiZ n‡q 4kg I 12kg Gi `ywU LÛ nj| 12kg f‡ii †eM 4ms-1 n‡j Ab¨ UzKivwUi MwZ kw³ KZ? [DU. 11-12, JnU. 10-11] A. 96J B. 144J C. 288J D. 192J m1v1 = m2v2 ev, v1 = m2 v2 m1 = 12 4 4 = 12ms–1 Ek 1 = 1 2 m1v 2 1 = 1 2 4 (12)2 = 288J 04. 100kg f‡ii GKwU e¯‘i fi‡eM 200kgms–1 n‡j Gi MwZkw³ KZ? [DU. 08-09; RU. 16-17] A. 100j B. 300j C. 200j D. 150j MwZkw³, Ek = P 2 2m = (200) 2 2 100 = 200J 05. GKwU Mvox 36 km/hr ‡e‡M MwZkxj| cÖvq †Kvb †e‡M Pj‡j MvoxwUi MwZkw³ wظY n‡e? [DU. 02-03; JnU. 05-06; CU. 11-12] A. 7 m/s B. 20 m/s C. 54 m/s D. 14 m/s v2 = n v1 = 2 36 3.6 14 m/sec 06. 10 m DuPz ¯’vb †_‡K 100 gm fi wewkó GKwU ej‡K †d‡j w`‡j hw` ejwU cybivq 8 m DuPz ch©šÍ I‡V Z‡e wK cwigvY kw³ ¶q nq? [DU. 01-02; JU. 10-11] A. 1000J B. 98J C. 1J D. 1.96J Ep = mg (h1 h2) = 0.1x9.8 (10 8) = 1.96 J STEP 02 ANALYSIS OF JU QUESTION 01. 1J MwZkw³i GKwU e¯‘i MwZi wecix‡Z 1N ej cÖ‡qv‡M e¯‘wU KZ`yi AMÖmi n‡q †_‡g hv‡e? [JU. 16-17, JNU. 10-11] A. 1m B. 2m C. 3m D. 4m W = 1 2 mv2 = Ek = F.s s = Ek F = 1 1 = 1m 02. 50kg f‡ii GKwU †evgv f~c„ô †_‡K 1km DPz‡Z Aew¯’Z GKwU wegvb †_‡K †d‡j †`qv n‡jv| f~wg ¯úk© Kivi c~e© gyû‡Z© Gi MwZkw³ KZ? [JU. 16-17] A. 49 104 J B. 49 105 J C. 49 106 J D. 49 107 J f~wg ¯úk© Kivi c~e© gyû‡Z© MwZkw³ = m‡e©v”P D”PZvq wefekw³, mgh = 50 9.8 1000 = 49 104 J 03. MwZkxj e¯‘i †eM wظY n‡j MwZkw³ KZ n‡e? [JU. 14-15, 13-14; KU. 13-14; SUST. 07-08] A. mgvb B. A‡a©K C. wظY D. Pvi¸Y MwZkw³, Ek = 1 2 mv2 ; Ek v 2 E2 = v2 v1 2 E1 = (2)2 E1 = 4 E1 04. 20m D”PZv †_‡K GKwU e¯‘‡K webv evavq co‡Z w`‡j †Kv_vq Dnvi MwZkw³ wefe kw³i mgvb n‡e? [JU. 12-13] A. 15m B. 5m C. 10m D. 12m x = h 2 = 20 2 = 10m 05. 200gm f‡ii GKwU e¯‘ 10m Dci †_‡K wb‡P c‡o hvq| f~-c„ô‡K ¯úk© Kivi c~e© gyû‡Z© Gi MwZkw³- [JU. 11-12] A. 20.6J B. 19.6J C. 18.6J D. 17.6J c~e©gyû‡Z© MwZkw³, Ek = mgh = 0.2 9.8 10 = 19.6J 06. 64m DPz ¯’vb n‡Z 0.5kg f‡ii GKwU e¯‘i Lvov bx‡P †d‡j w`‡j f~wg ¯úk© Kivi gyû‡Z© e¯‘wU MwZ kw³ n‡e- [JU. 11-12] A. 31.36J B. 320J C. 313.6J D. 400J f~wg ¯úk© Kivi gyû‡Z© Ek = mgh = 0.5 64 9.8 = 313.6J STEP 03 ANALYSIS OF RU QUESTION 01. 60 m D”PZv †_‡K GKwU e¯‘‡K webv evavq wb‡P co‡Z †`Iqv n‡jv| †Kvb D”PZvq e¯‘wUi MwZkw³ wefekw³i cuvP¸Y n‡e? [RU. Sinovac, Set-1. 20-21] A. 10 m B. 15 m C. 12 m D. 5 m S A info Ek = 5Ep 1 2 mv2 = 5 mgh 1 2 2 g (60– h) = 5gh – h = 5h h = 10m ASPECT SPECIAL: f‚wg †_‡K D”PZv x = h n + 1 = 60 5 + 1 = 10m [GLv‡b h n‡jv †gvU D”PZv, Ges n n‡jv MwZkw³ Ges wefekw³i AbycvZ]
206 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 02. 20kg f‡ii GKwU KYvi †eM (4 j + 5 j + 6 k)ms–1 n‡j Gi MwZkw³ KZ Ryj? [RU. 18-19] A. 300 B. 600 C. 770 D. 1440 EK = 1 2 20 4 2 + 52 + 62 = 770 03. F ej cÖ‡qv‡M GKwU †Uªb S `~i‡Z¡ _v‡g| hw` Avw`‡eM wظY Kiv nq Z‡e †Kvb `~i‡Z¡ †UªbwU _vg‡e? [RU. 17-18] A. S B. 2S C. S4 D. 4S W = EK = 1 2 mv2 = mgs s v 2 A_©vr †eM wظY Ki‡j miY 4 ¸Y n‡e| 04. 1m DPz †Uwe‡ji Dci Aew¯’Z 100g f‡ii GKwU eB‡K 10cm `~‡i miv‡bv n‡j, eBwUi w¯’wZ kw³i cwieZ©b n‡e- [RU. 17-18] A. 9.8J B. 98J C. 0J D. ‡KvbwUB bq Ans C 05. w¯’i Ae¯’v †_‡K 40kg fiwewkó †Kvb e¯‘ wbw`©ó e‡ji wµqvi d‡j 2s ci 15ms1 †eM cÖvß nj| 4s ci e¯‘wUi MwZkw³ KZ n‡e? [RU. 15-16] A. 6000J B. 12000J C. 18000J D. 0J 2s ci, v = u + at 15 = 0 + a 2 7.5ms–1 4s ci, v = u + at = 0 + 7.5 4 = 30ms–1 MwZkw³, Ek = 1 2 mv 2 = 1 2 40 302 = 18000J 06. e¯‘i MwZkw³ k, fi m n‡j MwZkw³ I fi‡e‡Mi g‡a¨ m¤úK©- [RU. 17-18; MBSTU. 14-15] A. p = k 2 2m B. k = 2m pm C. k = p 2 2m D. P = 2m k 2 Ans C 07. GKwU Uªv‡Ki IRb GKwU Kv‡ii IR‡bi wظY Ges UªvKwUi Kv‡ii wظY MwZ‡Z Pj‡Q| Kv‡ii Zzjbvq Uªv‡Ki MwZkw³i Rb¨ †KvbwU mZ¨? [RU. 13-14] A. Uªv‡Ki MwZkw³ †ekx-ïay GUv ejv hvq B. Uªv‡Ki MwZkw³ Kv‡ii Zzjbvq 8 ¸Y C. Uªv‡Ki MwZkw³ Kv‡ii Zzjbvq 4 ¸Y †ekx D. Uªv‡Ki MwZkw³ Kv‡ii Zzjbvq wظY †ekx ET EC = 1 2 mtvt 2 1 2 meve 2 = 2me (2ve) 2 meve 2 = 8 ET = 8EC 08. 5kg f‡ii GKwU ej‡K Dci †_‡K †Q‡o ‡`Iqv nj| gvwU‡Z ¯úk© Kivi g~û‡Z© Zvi MwZkw³ 980 J n‡j, ejwU KZ D”PZv †_‡K Qvov n‡qwQj? [RU. 13-14] A. 20 m B. 2 m C. 20 km D. 2cm mgh = 980 ev,h = 980 5 9.8 = 20m 09. 1m DuPz †Uwe‡ji Dci Aew¯’Z 100g f‡ii GKwU eB‡K 30 cm `~‡i miv‡bv n‡jv| eBwUi w¯’wZkw³i cwieZ©b KZ? [RU. 13-14] A. 9.8 × 105 erg B.2.94 × 104 erg C.0erg D. 3 × 104 erg Ep = mgh = mg × 0 = 0 10. GKwU wmwjÛv‡ii fi 50Kg Ges e¨vmva© 0.2m| wmwjÛviwUi A‡ÿi mv‡c‡ÿ Gi RoZvi åvgK 1kgm2 | wmwjÛviwU hLb 4ms †e‡M Abyf~wgKfv‡e Mov‡Z _v‡K, ZLb Zvi †gvU MwZkw³ KZ n‡e? [RU. 12-13] A. 150J B. 300J C. 450J D. 600J e¯‘wU Abyf~wgKfv‡e Mov‡j †gvU MwZkw³ Ek = 1 2 mv2 + 1 2 I 2 = 1 2 50 4 2 + 1 2 1 4 0.2 2 = 600J STEP 04 ANALYSIS OF CU QUESTION 01. GKwU B‡jKUª‡bi fi 9.1 1031kg Ges †eM 1.0 108 m/s n‡j Gi MwZ kw³ KZ? [CU. 11-12] A. 4.55 10–15 Ryj B. 4.55 10–19 B‡jKUªb †fvë C. 2.50 10–15 Ryj D. 1.53 102 B‡jKUªb †fvë MwZ kw³, E = 1 2 mv2 = 1 2 9.1 10–31 (1 108 ) 2 = 4.55 10–15J 02. 0.5Kg f‡ii GKwU †evgv f~wg n‡Z 1km DuPz‡Z Aew¯’Z GKwU wegvb †_‡K †d‡j †`qv nj| f~wg ¯úk© Kivi c~e© gyn~‡Z© Gi MwZ kw³ KZ? [CU. 09-10] A. 4400 J B. 4800 J C. 5900 J D. 4900 J E. 4500J f~wg ¯úk© Kivi c~e© gyû‡Z© MwZkw³ = D”PZvq w¯’wZkw³ MwZkw³, EK = mgh = 0.5 9.8 1000 = 4900J STEP 05 ANALYSIS OF DU-7 Clg QUESTION 01. m Ges 2m f‡ii `ywU e¯‘i •iwLK fi‡e‡Mi AbycvZ 2:1 n‡j G‡`i MwZkw³i AbycvZ n‡eÑ [DU-7Clg.A.19-20] A. 2:1 B. 2:1 C. 4:1 D. 8:1 Ek1 Ek2 = p 2 1m2 p 2 2m1 = 2 2 .2m 1 2 .m = 8 : 1 STEP 06 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. GKwU Mvwo 10ms–1 MwZ‡Z Pj‡Q| KZ †e‡M Pj‡j MvwowUi MwZkw³ wظY n‡e? [JnU. 05-06] A.10m/s B. 40m/s C. 100m/s D. 14.1m/s v2 = mv1 ev, v2 = 2 10 = 14.1m/s KU 01. GKwU ¸wji †eM wظY Kiv n‡j Gi MwZkw³ KZ ¸Y n‡e? [KU-A, Set-Ka. 19-20] A. 0.5 B. 2 C. 3 D. 4 Ek v 2 Ek 2 = (2)2 Ek 1 = 4 Ek 1 . 02. N~Y©vqgvb e¯‘i MwZkw³ (K.E)- [KU. 18-19] A. 1 2 I 2 B. 1 2 I C. I 2 D. 1 2 I 2 Ans A CoU 01. GKB avZzi •Zix `ywU †MvjK hv‡`i GKwUi e¨vmva© Ab¨wUi wظY| †MvjK `ywU‡K Zij c`v‡_© c~Y© GKwU j¤^v Rv‡ii ga¨ w`‡q co‡Z †`qv n‡j †QvUwUi Zzjbvq eowUi Uvwg©bvj MwZ [CoU. 11-12] A. GKB n‡e B. wظY n‡e C. Pvi¸Y n‡e D. A‡a©K n‡e Ans D IU 01. w¯’ive¯’vi 6kg fiwewkó GKwU e¯‘i Dci 30N ej 10s cÖhy³ n‡j MwZkw³- [IU-D. 19-20] A. 1800 J B. 2500 J C. 3500J D. 7500J a = F m = 30 6 = 5 ms–2 v = u+at = 0+5 10 = 50 ms–1 Ek = 1 2 mv2 = 1 2 6 (50)2 = 7500 J 02. h D”PZv †_‡K GKwU e¯‘‡K webv evavq co‡Z w`‡j f‚wg n‡Z KZ D”PZvq Gi MwZkw³ wefe kw³i wظY n‡e? [IU-D, 19-20] A. h/6 B. h/3 C. 2h/3 D. 5h/6 h = h n + 1 = h 2 + 1 = h 3 03. MwZkxj e¯‘i †eM wظY n‡j MwZkw³Ñ [IU. 14-15] A. wظY B. GK PZz_©vsk C. Pvi¸Y D. AvU¸Y Ek = 1 2 mv2 , Ek v 2
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 207 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES BRUR 01. `yBwU e¯‘i g‡a¨ GKwUi IRb 2kg Ges AciwUi IRb 4kg Df‡qi fi‡eM mgvb n‡j †Kvb e¯‘wUi MwZkw³ †ekx n‡e? [BRU. 13-14] A. 4kg f‡ii e¯‘wUi B. 2kg f‡ii e¯‘wUi C. `yBwU MwZkw³ mgvb n‡e D. ‡KvbwUB bq Ans B BU 01. wb‡Pi †Kvb e¯‘i MwZkw³ †ekx? [BU. 14-15] A. fi 3M, †eM 2V B. fi 2M, †eM 3V C. fi M, †eM 4V D. fi 3M, †eM 2V From A. option Ek = 1 2 3 4 = 6 From B. option Ek = 1 2 2 (3)2 = 9 From C. option Ek = 1 2 1 (4)2 = 8 From D. option Ek = 1 2 3 4 = 6 JKKNIU 01. GKwU e¯‘i fi‡eM 200% e„w× Ki‡j MwZkw³ †Kgb cwiewZ©Z n‡e? [JKKNIU-B, Set-3, 19-20] A. 2 ¸Y e„w× cv‡e B. 4 ¸Y e„w× cv‡e C. 6 ¸Y e„w× cv‡e D. 8 ¸Y e„w× cv‡e fi‡eM 200% evov‡j bZzb fi‡eM, P2 = (100 + 200)% = 300% ev 3 ¸b, Ek2 = (3)2 Ek 1 = 9 Ek 1 MwZkw³i cwieZ©b Ek = (9Ek –Ek) = 8 Ek = 8 ¸b e„w×| PART B Analysis of Science & Technology Question SUST 01. 40km/hr †e‡M PjšÍ GKwU Mvwoi MwZkw³ 2 105 J| MvwowU 20km/hr †e‡M Pj‡j Zvi MwZkw³ KZ J n‡e? [SUST. 16-17] A. 4 10J B. 6 105 C. 3 105 D. 8 105 E. 0.5 105 1 2 mv2 = 2 105 J 1 2 m = 1620 1 2 mv2 = 1620 20 1000 3600 2 = 0.5 105 J 02. 40 km/hr ‡e‡M PjšÍ GKwU Mvwoi MwZkw³ 2.0 105 J| MvwowU hLb 20 km/hr ‡e‡M Pj‡e ZLb Zvi MwZkw³ KZ Ryj (J) n‡e? [SUST. 15-16] A. 5.0 105 B. 3.0 105 C. 1.0 105 D. 5.0 104E. 3.0 104 Ek2 Ek1 = v2 v1 2 ev, Ek2 20 40 2 2 105 = 5 104 03. GKwU e¯‘‡K wbw`©ó D”PZv †_‡K †d‡j †`Iqv nj| f~wg n‡Z 5.0m D”PZvq MwZkw³ wefekw³i 4 ¸Y n‡j KZ m D”PZv n‡Z e¯‘wU‡K †d‡j †`Iqv n‡qwQj? [SUST. 14-15] A. 15 B. 25 C. 35 D. 45 E. 55 x = h n + 1 ev, 5 = h 4 + 1 ev, h = 25m 04. 40m D”PZv †_‡K GKwU e¯‘‡K webv evavq co‡Z w`‡j †Kvb D”PZvq MwZkw³ w¯’wZkw³i wZb¸Y n‡e? [SUST. 13-14] A. 10m B. 13.33m C. 20m D. 26.66m x = h n + 1 = 40 3 + 1 = 40 4 = 10m 05. GKwU e¯‘‡K w¯’i Ae¯’vq D”P ¯’vb †_‡K Qvov n‡q‡Q| e¯‘wU hLb 10m D”PZvq †b‡g‡Q ZLb Zvi MwZkw³ †mB Ae¯’vq w¯’wZ kw³i A‡a©K| e¯‘wU KZ D”PZv n‡Z Qvov n‡q‡Q- [SUST. 09-10] A. 5m B. 10m C. 15m D. 20m x = h n +1 = h 1 2 + 1 2h = 30m h = 15 m 06. 4 kg f‡ii GKwU e¯‘‡K 15 m D”PZv †_‡K †Q‡o †`q n‡j f~-c„ô‡K ¯úk© Kivi wVK c~e© gyû‡Z© Gi MwZkw³ n‡e- [SUST. 07-08] A. 588 J B. 294 J C. 1176 J D. 566 J f~wg ¯úk© Kivi gyû‡Z© MwZkw³ = mgh = 4 9.8 15 j = 588 j 07. 1.67 x 10–27 kg fi wewkó wbDUª‡bi †eM 4.0x104 ms–1 n‡j Gi MwZkw³i cwigvY- [SUST. 07-08] A. 8.35 ev B. 8.7 ev C. 16.7 ev D. †KvbwU bq Ek = 1 2 mv2 = 1 2 1.67 10–27 (4 104 ) 2 1.6 10–19 ev= 8.35eV 08. m f‡ii GKwU e¯‘ mg‡e‡M mij •iwLKfv‡e Pjgvb| hw` e¯‘wUi †eM wظY Kiv nq Z‡e Gi MwZkw³i wK cwieZ©b n‡e? [SUST. 07-08] A. e¯‘wUi MwZkw³ c~‡e©i MwZkw³i Pvi¸b B. MwZkw³i †Kvb cwieZ©b n‡e bv C. MwZkw³ c~‡e©i Zzjbvq A‡a©K n‡e D. MwZkw³ c~‡e©i Zzjbvq wظb n‡e †eM wظb n‡j MwZkw³ n‡e; Ek2 = (n)2 = (2)2 = 4 ¸b JUST 01. h wgUvi DPz ¯’vb †_‡K GKwU e¯‘ co‡Q| †Kv_vq Zvi MwZ-kw³ w¯’wZkw³i A‡a©K n‡e? [JUST. 15-16] A. h/3 wgUvi B. 2h/3 wgUvi C.3h/2wgUvi D. h/2wgUvi E. 4h/3 wgUvi x = h n + 1 = h 1 + 0.5 = h 1.5 = 2h 3 MBSTU 01. 50 kg f‡ii GKwU e¯‘i fi‡eM 50 kgms1 n‡j Gi MwZkw³ n‡eÑ [MBSTU-A, Set-2 19-20] A. 100 J B. 25 J C. 2500 J D. 50 J Ek = P 2 2m = (50) 2 2 50 = 25 J 02. GKwU Mvwo 36 kmh1 †e‡M MwZkxj| †Kvb MwZ‡Z Pj‡j MvwowUi MwZkw³ wظY n‡e? [MBSTU-B, Set-2 19-20] A. 7 ms1 B. 20 ms1 C. 54 ms1 D. 14 ms1 v Ek v2 = Ek2 Ek1 v1 = 2 10 = 14.1 ms–1 BSMRSTU 01. m Ges 4m f‡ii `ywU MwZkxj e¯‘i MwZkw³ GKB n‡j Zv‡`i •iwLK fi‡e‡Mi AbycvZ KZ? [BSMRSTU-B, 19-20] A. 1:4 B. 1:2 C. 4:1 D. 2:1 Ek = P 2 2m P1 P2 2 = m1 m2 P1 P2 = m 4m = 1 2 P1 : P2 = 1:2 STEP 07 ANALYSIS OF ENGINEERING & BUTex QUESTION BUET 01. 80m D”PZv †_‡K hw` GKwU ej †g‡S‡Z c‡o Ges ejwUi 20% kw³ †g‡Si mv‡_ cÖwZNv‡Z n«vm cvq| Z‡e ejwU †g‡S‡Z av°v †L‡q †h D”PZvq DV‡e? [BUET. 11-12] A. 60m B. 64m C. 68m D. 72m mgh × 0.8 = mgh1 ev, h1= 0.8 × h = 0.8 × 80 = 64
208 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES CKRuet. Combind 01. 1 km D”PZv †_‡K GKwU e¯‘ †d‡j †`Iqv n‡jv| GKB mg‡q Ab¨ GKwU e¯‘‡K f~wg †_‡K 200 m/s †e‡M Lvov Dc‡ii w`‡K wb‡ÿc Kiv n‡jv| e¯‘Øq f~wg †_‡K KZ D”PZvq wgwjZ n‡e? [CKRUET. 2020-21] A. 0 m B. 122.5 m C. 200 m D. 877.5 m E. 1000m S D info x = 200t – 1 2 gt2 .......(i); h – x = 1 2 gt2 ...........(ii) (i) + (ii) h = 200t = 1000 t = 5s x = 200 × 5 – 4.9 × 52 = 877.5 m h hx x STEP 08 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. 50 kg f‡ii GKwU e¯‘i fi‡eM 50 kgms–1 n‡j Gi MwZkw³ KZ n‡e? [MAT. 17-18] A.100 J B. 25 J C. 500 J D. 50 J Ek = p 2 2m = (50) 2 2 50 = 25J STEP 09 ANALYSIS OF HSC BOARD QUESTION wb‡Pi DÏxcKwU co Ges 01 I 02bs cÖ‡kœi DËi `vI: 40m DuPz n‡Z GKwU e¯‘ f‚wg‡Z coj| (g = 9.8ms–2 ) 01. e¯‘wU f‚wg‡Z KZ †e‡M co‡e? [Xv.‡ev 2021] A. –28ms–1 B. 28ms–1 C. 392ms–1 D. 784ms–1 S B info v = 2gh = 2 × 9.8 × 40 = 28ms1 02. f‚wg n‡Z KZ D”PZvq e¯‘wUi MwZkw³ wefe kw³i wظY n‡e? [Xv.‡ev 2021] A. 13.33m B. 20m C. 26.67m D. 40m S A info x = h n + 1 = 40 2 + 1 = 13.33 03. GKwU e¯‘i •iwLK fi‡eM 50% e„w× Ki‡j MwZkw³ e„w× cvq KZ? [Xv. †ev. 2017] A. 25% B. 50% C. 125% D. 225% S C info Ek = P 2 2m , Ek P 2 Ek2 = P2 P1 2 × Ek1 [∵ P2 = P1 + 0.5 P1 = 1.5 P1] = 1.5 P1 P1 2 × Ek1 = 2.25 Ek1 Ek = (2.25 – 1) = 125% 04. cošÍ Ae¯’vq f~wg n‡Z 5m DuPz‡Z wefekw³ I MwZkw³i AbycvZ †KvbwU? [Xv. †ev. 2017] A. 1 : 2 B. 1 : 3 C. 1 : 4 D. 2 : 1 S B info Ep = mgx; Ek = mg(h – x); Ep Ek = x h – x = 5 20 – 5 = 5 15 = 1 3 GKwU e¯‘ 20m D”PZv †_‡K f~wg‡Z co‡jv| (g = 10ms2 ) 05. GKwU e¯Íy‡K Lvovfv‡e Dc‡ii w`‡K Quy‡o †`Iqv n‡jv| †Kvb MÖvdwU f~wg n‡Z D”PZv ÔhÕ Gi mv‡c‡ÿ e¯ÍywUi wefekw³ EP Gi cwieZ©b wb‡`k© K‡i? [Xv.†ev. 15] A. B. C. D. Ans C 06. 1kg I 9kg f‡ii `ywU e¯‘ mgvb MwZkw³‡Z MwZkxj| G‡`i fi‡e‡Mi AbycvZ KZ? [iv.‡ev 2021] A. 1 : 3 B. 3 : 1 C. 3 : 1 D. 1 : 9 S A info Ek = P 2 2m P m [ Ek constant] P1: P2 = 1 : 3 07. †Kv‡bv e¯‘‡K f~wg n‡Z Lvov Dc‡ii w`‡K wb‡ÿc Kivi wKQz mgq ci Avevi f~wg‡Z wd‡i G‡jv| D”PZv (h) ebvg MwZkw³ (&Ek) Gi †jLwPÎ wb‡`©k K‡i? [iv.‡ev 2021] A. B. C. D. Ek h Ek h h Ek Ek h Ans D 08. k w¯úªs aªæeKwewkó †Kv‡bv w¯úªs-Gi gy³ cÖv‡šÍi x cwigvY miY NU‡j mwÂZ wefe kw³- [iv. †ev. 2016] A. W = kx2 B. W = 1 2 kx2 C. W = kx D. W = – 1 2 kx Ans B 09. hw` MwZkw³ = K, fi = m I fi‡eM = P nq, Z‡e †Kvb m¤úK©wU mwVK? [P.‡ev 2021] A. K = 2P2 m B. K = 2P m C. K = P 2m D. K = p 2 2m Ans D 10. 200gm f‡ii GKwU e¯‘ 10m Dci †_‡K co‡j f~wg ¯úk© Kivi c~e© gyn~‡Z© G‡i MwZkw³ KZ? [P.‡ev 2021] A. 19.6J B. 39.2J C. 78.4J D. 98J S A info E = mgh = 0.2 × 9.8 × 10 = 19.6J 11. 2 kg f‡ii GKwU e¯‘i fi‡eM 2 kgms–1 n‡j MwZkw³ KZ n‡e? [P. †ev. 2017] A. 1 J B. 1.5 J C. 2 J D. 4 J S A info E = P 2 2m = 2 2 2 × 2 = 1 J 12. cošÍ Ae¯’vq f~wg n‡Z 5m DuPz‡Z wefekw³ I MwZkw³i AbycvZ †KvbwU? [P. †ev. 2017] A. 1 : 2 B. 1 : 3 C. 1 : 4 D. 2 : 1 Ans B 13. 60 m D”PZv n‡Z GKwU e¯‘‡K webv evavq co‡Z w`‡j f~wg n‡Z KZ D”PZvq wefekw³ MwZkw³i A‡a©K n‡e? [P. †ev. 2015] A. 10 m B. 20 m C. 30 m D. 40 m S B info x = 1 2 h n + 1 = 1 2 60 1 2 + 1 = 30 3 2 = 20m wb‡Pi DÏxc‡Ki Av‡jv‡K 14 I 15bs cÖ‡kœi DËi `vI : 15m DuPz GKwU Mv‡Qi Wvj n‡Z 200g f‡ii GKwU Avg wb‡Pi Kv`v gvwU‡Z c‡o 10cm M‡Z©i m„wó K‡i| [g = 9.1ms–2 ] 14. Kv`v gvwUi Mo cÖwZ‡iva ej KZ? [w`.‡ev 2021] A. 29.40N B. 292.04l C. 294.00N D. 295.96N S D info mgh = 1 2 mv2 v 2 = 2gh = 2 × 9.8 × 15.1 = 295.96 F = m. v 2 2s = 0.2 × 295.96 2×0.1 = 295.96 15. f~wg n‡Z KZ D”PZvq AvgwUi wefe kw³ Gi MwZ kw³i wظY n‡e?[w`.‡ev 2021] A. 5m B. 8m C. 10m D. 12m S B info EP = nEK n = nh n + 1 = 2×15 2+1 = 10 m 16. e¯‘i fi‡e‡M (P) ebvg MwZkw³ (E) Gi †jLwPÎ wb‡Pi †KvbwU? [w`.‡ev 2021] A. B. C. D. fi‡eM P(kgms–1 ) MwZkw³ E(J) fi‡eM P(kgms–1 ) MwZkw³ E(J) fi‡eM P(kgms–1 ) MwZkw³ E(J) fi‡eM P(kgms–1 ) MwZkw³ E(J) S D info Ek = P 2 2m Ek P 2
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 209 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 17. 20kg f‡ii GKwU w¯’i e¯‘‡K Nl©Ynxb Z‡ji Dci w`‡q 10ms-1 †e‡M MwZkxj Ki‡Z K…ZKvR KZ? [w`.‡ev. 2019] A. 200 J B. 1000 J C. 2000 J D. 4000 J S B info W = F.S = ma. v 2 – u 2 2a = 1 2 m1a (v2 – u 2 ) = 1 2 × 20 × 102 = 1000 J 18. 60 m D”PZv n‡Z GKwU e¯‘‡K webv evavq co‡Z w`‡j f~wg n‡Z KZ D”PZvq wefekw³ MwZkw³i A‡a©K n‡e? [w`. †ev. 2016; P. †ev. 2015] A. 10 m B. 20 m C. 30 m D. 40 m S B info x = nh n + 1 = 1 2 × 60 1 2 + 1 = 20 m 19. h D”PZv †_‡K GKwU e¯‘‡K webv evavq co‡Z w`‡j f~wg n‡Z KZ D”PZvq Gi MwZkw³ wefekw³i wظY n‡e? [w`. †ev. 2016] A. h 6 B. h 3 C. 2h 3 D. 5h 3 S B info x = h n + 1 = h 2 + 1 = h 3 20. †Kv‡bv e¯‘i fi‡eM I MwZkw³i cwieZ©‡bi †jLwPÎ n‡jvÑ [wm.‡ev. 2019] A. B. C. D. Ans A 21. 200 g f‡ii GKwU e¯‘ 100 m Ici †_‡K co‡j f~wg ¯úk© Kivi c~e© gyn~‡Z© Gi MwZkw³ KZ? [wm. †ev. 2015] A. 196 J B. 39.2 J C. 78.4 J D. 98 J Ans A S A info Ek = Ep = mgh = 0.2 × 9.8 × 100 = 196 J 22. MwZkxj e¯‘i †eM wظY n‡j MwZkw³ n‡e- [g.‡ev 2021] A. A‡a©K B. mgvb C. wظY D. Pvi¸Y S D info Ek = 1 2 mv2 Ek V 2 EK2 = n2 × Ek1 = 22 × EK1 EK2 = 4 EK1 23. hw` MwZkw³ = K, fi = m I fi‡eM = P nq, Z‡e †Kvb m¤úK©wU mwVK? [e.‡ev 2021] A. K = 2P2 m B. K = 2P m C. K = P 2m D. K = p 2 2m Ans D 24. 200gm f‡ii GKwU e¯‘ 10m Dci †_‡K co‡j f~wg ¯úk© Kivi c~e© gyû‡Z© Gi MwZkw³ KZ? [e.‡ev 2021] A. 19.6J B. 39.2J C. 78.4J D. 98J Ans A 25. f~wgi mv‡_ 30 †Kv‡Y AvbZ 5m `xN© GKwU Xvjyc‡_ 100gm fiwewkó GKwU e¯‘ †h MwZkw³ cÖvß n‡e [e. †ev. 2017] A. 0.49J B. 0.848J C. 1.225J D. 2.45J S D info Ek = 1 2 mv2 = 1 2 (2mgh sin) = mgh sin = 0.1 × 9.8 × 5 × sin 30˚ = 2.45 J 26. 1cm cyiæ‡Z¡i I 200gm f‡ii wgUvi †¯‥j‡K Abyf~wgK Ae¯’v †_‡K Lvov Ki‡j wefekw³ [gv. †ev. 2016] A. 19.60 J B. 1.960 J C. 1.940 J D. 0.970 J S B info Ep = mgh = 0.2 × 9.8 × 1 = 1.96 J Concept 4 fi‡eM msµvšÍ MvwYwZK cÖ‡qvM FORMULA 01. Ek = p 2 2m; E1 E2 = P1 2 P2 2 ASPECT SPECIAL: (i) Ek2 = n2 × Ek1 (ii) P2 = n × P1 [n = MwZkw³ ev fi‡e‡Mi ¸Y] Model Example01 †Kvb e¯‘i MwZkw³ 300% e„w× Kiv n‡j D³ e¯‘i fi‡eM evo‡eGeneral Rules [Written] 3 in 1 Shortcut Tricks & Tips [MCQ] Avgiv Rvwb, Ek = P 2 2m Ek2 Ek1 = P2 P1 ev, 300 + 100 100 = P2 P1 2 ev, 4 1 = P2 P1 2 ev, P2 P1 = 2 ev, P2 = 2P1, fi‡eM e„w× = 2 1=1P =100% ASPECT SPECIAL: P2 = n × P1 P2 = (100 + 300)% = 400% = 4 ¸Y = N P2 = 4 × P1 = 2P1 fi‡eM e„w× = 2 1=1P =100% CONCEPTUAL MATH MEx 01 10kg f‡ii GKwU e¯‘i MwZkw³ 80J n‡j fi‡eM wbY©q Ki| Ek = p 2 2m ev, p = 2Ek.m = 2 80 10 = 40 kg ms–1 MEx 02 100kg f‡ii GKwU e¯‘i fi‡eM 200kgms–1 n‡j Gi MwZkw³ KZ? MwZkw³, Ek = m P 2 2 2 100 200 2 = 200J MEx 03 ‣iwLK fi‡eM 60% evo‡j MwZkw³ e„w× cvqE P 2 E2 = 1 1 2 1 2 1 2 E 1.6 E 2.56E P P MwZkw³ e„w×, ΔE = 2.56–1=1.56×100% = 156% NOW START PRACTICE 01. GKwU KYvi fi‡eM P| KYvwUi MwZkw³ wZb¸b Kiv n‡j Gi bZzb fi‡eM KZ n‡e? 02. GKwU Mvox 36 km/hr †e‡M MwZkxj| cÖvq †Kvb †e‡M Pj‡j MvoxwUi MwZkw³ wظY n‡e?
210 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES NOW PRACTICE SOLVE : 01. MwZ kw³, Ek = P 2 2m Ek P 2 P E bZzb fi‡eM, P2 = E2 E1 P1 = 3 P 02. v2 = nv1 = 2 × 36 3.6 =14 m/sec REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. GKwU KYvi fi‡eM P| KYvwUi MwZkw³ wظY Kiv n‡j Gi fi‡eM KZ n‡e? [DU. 12-13; JU. 14-15] A. 2P B. 2P C. 4P D. 8P Ek = 1 2 mv2 = m 2 v 2 2m = p 2 2m Ek P 2 e‡j MwZkw³ wظY Ki‡j fi‡eM, P Ek| STEP 02 ANALYSIS OF RU QUESTION 01. •iwLK fi‡eM 60% evo‡j MwZkw³ e„w× cvq- [RU. 16-17] A. 60% B. 125% C. 156% D. 160% E = P 2 2m [GKwU KYv nIqvi Kvi‡Y Zvi fi w¯’i] E P 2 E1= P2 P1 2 E1 = 1.62 E1 = 2.56E1 MwZkw³ e„w×, ΔE = 2.56 – 1 = 1.56 × 100% = 156% STEP 03 ANALYSIS OF GST QUESTION PART A Analysis of General University Question BRUR 01. GKwU KYvi fi‡eM 10kgm/s hw` KYvwUi MwZkw³ 100J Z‡e KYvi fi- [BRUR. 12-13] A. 0.5kg B. 1.5kg C. 1kg D. None Ek = p 2 2m ev, m = p 2 2ER = (10) 2 2 100 = 0.5kg PART B Analysis of Science & Technology Question JUST 01. †Kvb e¯‘i MwZkw³ 300% e„w× Kiv n‡j D³ e¯‘i fi‡eM evo‡e- [JUST. 15-16, BUET: 08-09] A. 100% B. 150% C. 200% D. 250% E. 300% Ek = P 2 2m Ek 2 Ek 1 = P2 P1 ev, 300 + 100 100 = P2 P1 2 ev, 4 1 = P2 P1 2 ev, P2 P1 = 2 ev, P2 = 2P1, fi‡eM e„w× = 2 1=1P =100% PUST 01. GKwU nvjKv e¯‘ I GKwU fvix e¯‘i fi‡eM mgvb n‡j MwZkw³ †Kvb e¯‘i Kg? [PUST-A. 19-20] A. nvjKv e¯‘i B. fvix e¯‘i C. Df‡qiB mgvb D. †KvbwUB bq nvjKv I fvix e¯‘i fi‡eM mgvb n‡j nvjKv e¯‘i †eM †ekx Ges fvix e¯‘i †eM Kg| ZvB fvix e¯‘i MwZkw³ Kg| MwZkw³ mgvb n‡j fvix e¯‘i fi‡eM †ewk| DU Technology 01. M I 4M f‡ii `ywU MwZkxj e¯‘i MwZkw³ GKB n‡j Zv‡`i •iwLK fi‡e‡Mi AbycvZ KZ n‡e? [DU-Tech. 2020-21] A. 1:4 B. 1:2 C. 4:1 D. 1:1 S B info Ek 1 = Ek 2 p1 2 2m1 = p2 2 2m2 p1 2 p2 2 = m1 m2 = M 4M p1 p2 = 1 2 02. GKwU KYvi fi‡eM P, KYvwUi MwZkw³ wظY Kiv n‡j Gi bZzb fi‡eM KZ n‡e? [DU-Tech.19-20] A. 2 P B. 2P C. 4P D. 8P Ek P 2 P Ek P2 = 2 P STEP 04 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. GKwU e¯‘i fi‡eM wظY n‡q ‡M‡j Dnvi MwZkw³- [MAT. 14-15] A. wظY n‡e B. GKB _vK‡e C. AvU¸Y n‡e D. Pvi¸Y n‡e Ek2 Ek1 = P2 P1 2 ev, Ek2 Ek1 = 2 1 2 ev, Ek2 = 4Ek1 = Pvi¸b STEP 05 ANALYSIS OF HSC BOARD QUESTION 01. M f‡ii GKwU e¯‘i MwZkw³ E n‡j Gi fi‡eM KZ? [Xv.‡ev 2021] A. M 2E B. ( 2m).E C. 2ME D. 1 2 ME Ans C 02. m f‡ii GKwU e¯‘ E MwZkw³‡Z Pj‡Q| Gi •iwLK fi‡eM KZ? [P.†ev.2019] A. mE B. 2mE C. m E D. 2mE S B info E = P 2 2m P = E 2m P = 2m E wb‡Pi Aby‡”Q`wU co Ges 03 I 04 bs cÖ‡kœi DËi `vI : [w`. †ev. 2015] GKwU fvix e¯‘i fi Aci GKwU nvjKv e¯‘i f‡ii wظY| e¯‘i `ywUi fi‡eM mgvb| 03. nvév I fvix e¯‘i †e‡Mi AbycvZ KZ? A. 1 : 2 B. 2 : 1 C. 4 : 1 D. 1 : 4 S B info m1 = m ; m2 = 2m ; Ek = 1 2 mv2 m1 m2 = v 2 2 v 2 1 v 2 1 : v 2 2 = m2 : m1 = 2 : 1 04. nvjKv I fvix e¯‘ `ywUi MwZkw³i AbycvZ KZ? A. 2 : 1 B. 1 : 2 C. 1 : 4 D. 4 : 1 S B info Ek1 : Ek2 = m1 : m2 = 1 : 2 05. MwZkw³ I fi‡e‡Mi g‡a¨ m¤úK© †KvbwU?[Kz. †ev. 2019; wm. †ev. 2017, 2016] A. K = 2p m B. K = p 2m C. K = 2p2 m D. K = p 2 2m Ans D
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 211 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 5 ÿgZv msµvšÍ MvwYwZK cÖ‡qvM FORMULA 01. ¶gZv = KvR mgq = W t = mgh t = 1 2 mv2 t = Fs t = FV = mgv = Fscos t = mgscos t = mv2 2t 02. `¶Zv, = cÖvß ÿgZv ‡gvU ÿgZv = P P = mgh t P ev, cÖvß ¶gZv = †gvU ¶gZv Kg©`¶Zv ev Kvh©¶gZv () = Kvh©Ki kw³ ‡gvU kw³ = E1–E2 E1 × 100% 03. P = = (2 – 1) t r CONCEPTUAL MATH MEx 01 55kg f‡ii GK e¨w³ 3 †m‡K‡Û 3 wgUvi DPz GKwU wmwo †e‡q Dc‡i I‡V| H e¨w³i ¶gZv KZ? P = mgh t = 55 9.8 3 3 = 539 W MEx 02 cÖwZ †m‡KÛ 10litre cvwb 10m Dc‡i †Zvjvi Rb¨ AšÍZ KZ ÿgZvi cv¤ú `iKvi? P = W t = mgh t = 10 9.8 10 1 = 980W MEx 03 100m Mfxi GKwU Kzqv †_‡K Bwćbi mvnv‡h¨ 1 wgwbU 10 †m‡K‡Û 100 kg cvwb DVvb nq, hw` Bwćbi ¶gZv 30% bó nq| Zvn‡j Gi †gvU ¶gZv wbY©q Ki| P = t mgh P = 100 9.8 100 70 100 70 = 2000 W MEx 04 110 lb f‡ii GK e¨w³ †`․‡o 5 †m‡K‡Û 10 ft DuPz wmuwo †e‡q Dc‡i D‡V| †jvKwUi Ak¦ ¶gZv KZ? †jvKwUi Ak¦ ¶gZv, P = t mgh = 110 × 32 × 10 5 × 550 = 12.8 hp NOW START PRACTICE 01. 100m Mfxi GKwU Kzqv †_‡K Bwćbi mvnv‡h¨ cÖwZ wgwb‡U 1000 kg cvwb DVvb nq, hw` Bwćbi ¶gZv 40% bó nq| Zvn‡j Gi ¶gZv wbY©q Ki| 02. 0.250 kg f‡ii GKwU †evSv GKwU †µ‡bi mvnv‡h¨ 0.1ms–1 aªye †e‡M DVvb nj| †µ‡bi ¶gZv KZ? 03. 2000kg f‡ii GKwU BwÄb 1.5ms–1 mg‡e‡M PjvKv‡j cÖwZ kg Gi Rb¨ 1.96N ej cÖwZ‡iva Ki‡Z nq| Bwćbi ¶gZv KZ? 04. GKwU Mvwo BwÄb cÖ¯‘ZKvix †Kv¤úvbx `vex K‡i †h, Zv‡`i •Zix 1200kg f‡ii GKwU Mvwoi BwÄb m‡ev”P© 90kW ¶gZv cÖ‡qvM Ki‡Z cv‡i| MvwowU‡K w¯’ive¯’v †_‡K 30 ms–1 ‡eM w`‡Z me©wb¤œ KZ mgq jvM‡e? 05. 1000 kg fi wewkó GKwU Mvox †mvRv iv¯Ívq 10 ms–1 mgMwZ‡Z Pjv Ae¯’vq wecixZ w`‡K 400 N ej Abyfe K‡i| G Ae¯’vq MvoxwUi Bwćbi ¶gZv nj : 06. cv‡¤úi mvnv‡h¨ GKwU Ifvi †nW cvwbi U¨vs‡K 100 s mg‡q 1000 kg cvwb D‡Ëvjb Kiv hvq| U¨vs‡Ki cvwbi Mo D”PZv 20 m n‡j cv‡¤úi ¶gZv (g = 9.8 m/s2 ) NOW PRACTICE SOLVE : 01. 60%p = mgh t 746 ev p = 1000 9.8 100 60 746 0.60 = 36.49 HP 02. P = mgv = 250 9.8 0.1= 245watt 03. P = Fv = 2000 1.96 1.5 = 5.88kW. 04. P = w t ev t = w p = 1 2 m(u 2 v 2 ) p = 1200 302 2 90 103 ev t = 6 sec 05. P = Fv = 400 10 = 4000W = 4 KW 06. P = mgh t P = 1000 9.8 20 100 = 1960J = 1.96kJ
212 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. 1000 kg fi wewkó GKwU Mvox mgvšÍivj iv¯Ívq 10 ms-1 mgMwZ‡Z Pjv Ae¯’vq wecixZ w`‡K 400 N ej Abyfe K‡i| G Ae¯’vq MvoxwUi Bwćbi ¶gZv nj- [DU. 04-05] A. 4KW B. 4200W C. 4500W D. 400W P = Fv = 400 10 = 400W = 4KW 02. cv‡¤úi mvnv‡h¨ GKwU Ifvi †nW cvwbi U¨vs‡K 100 s mg‡q 1000 kg cvwb D‡Ëvjb Kiv hvq| U¨vs‡Ki cvwbi Mo D”PZv 20 m n‡j cv‡¤úi ¶gZv (g = 9.8 m/s2 ) [DU. 02-03] A. 0.98 kw B. 1.46 kw C. 1.96 kw D. 2.64 kW P = mgh t P = 1000 9.8 20 100 = 1960w = 1.96kW STEP 02 ANALYSIS OF JU QUESTION 01. GKwU cvwbc~Y© K‚‡ci MfxiZv I e¨vmva© h_vµ‡g 10 m I 2m| cv‡¤úi Ak¦ÿgZv 6.87 HP n‡j K‚cwU cvwb k~b¨ n‡e- [JU-A, Set-D. 19-20] A. 20 min B. 15 min C. 25 min D. 40 min t = W P = r 2 lgh P [cvwb c~Y© Kzqvi †ÿ‡Î h = l 2 ] t = 3.14 2 2 10 103 9.8 5 6.87 746 60 = 20 min 02. 60kg f‡ii GK‡jvK 30 wgwb‡U 600m DPzu‡Z DV‡Z cv‡i| Zvi KvR Kivi ÿgZv KZ? [JU. 18-19] A. 196 W B. 392 W C. 588 W D. 98 W KvR Kivi ÿgZv, p = mgh t = 60 9.8 600 30 60 = 196 Watt 03. 55kg f‡ii GK e¨w³ 3 †m‡K‡Û 3 meter DPz GKwU wmuwo †e‡q Dc‡i D‡V| e¨w³i ¶gZv KZ? [JU. 17-18; RU. 09-10] A. 539 W B. 639 W C. 739 W D. 839 W ¶gZv, P = mgh t = 55 9.8 3 3 = 539 watt 04. 110 lb f‡ii GK e¨w³ †`․‡o 5 †m‡K‡Û 10 ft DuPz wmuwo †e‡q Dc‡i D‡V| †jvKwUi Ak¦ ¶gZv KZ? [JU. 17-18] A. 0.6 hp B. 0.8 hp C. 0.4 hp D. 0.3ph †jvKwUi Ak¦ ¶gZv, P = mgh t = 110 10 5 550 = 0.4 hp 05. 600 kg f‡ii GKwU cv_i‡K †µ‡bi mvnv‡h¨ 0.1ms-1 †e‡M Qv‡`i Dc‡i DVv‡Z †µ‡bi ÿgZv KZ? [JU. 16-17] A. 294 W B. 550 W C. 588 W D. 600 W ¶gZv, P = Fv = mg v = 600 × 9.8 × 0.1 = 588 Watt 06. GKwU BwÄb cÖwZ NÈvq 37300 kg cvwb 18 m Dc‡i DVv‡Z cv‡i| Bwćbi ¶gZvÑ [JU. 11-12] A. 1827.7 W B. 827.7 W C. 2827.7 W D. 3827.7 W Bwćbi ¶gZv, P = mgh t = 37300 9.8 18 3600 = 1827.7 Watt 07. 270 kg f‡ii GKwU †evSv GKwU †µ‡bi mvnv‡h¨ 0.1 ms–1 aªæe †e‡M DVv‡bv n‡j †µ‡bi KZ ¶gZv e¨q nq? [JU. 11-12; MBSTU. 14-15] A. 365.6 W B. 463.6 W C. 164.5 W D. 264.6 W ¶gZv, P = Fv = mgv = 270 9.8 0.1 = 264.6 Watt 08. GKwU BwÄb cÖwZ NÈvq 37300kg cvwb 18m Dc‡i DV‡Z cv‡i| Bwćbi ¶gZv- [JU. 11-12] A.1827.7 W B. 827.7 W C. 2827.7 W D. 3827.7 W P = mgh t = 37300 9.8 18 60 60 = 1827.7W 09. GKwU †gvUi wgwb‡U 5.5 105 kg cvwb 100m Dc‡i Zzj‡Z cv‡i| †gvUiwUi `¶Zv 70% n‡j Gi ¶gZv n‡e- [JU. 10-11, 09-10] A. 17202.85H.P B. 1.720H.P C. 1759H.P D. 172H.P p = mgh t 746 H.P ev, p = 5.5 105 9.8 100 60 0.70 746 = 17202.85 H.P STEP 03 ANALYSIS OF RU QUESTION 01. cÖwZ N›Uvq 5000 gallon cvwb 36ft Dc‡i Zzj‡Z me©wb¤œ KZ Ak^ÿgZvi BwÄb jvM‡e? [RU. 17-18] A. 0.5 B. 1 C. 1.5 D. †KvbwUB bq P = mgh t = 5000 3.79 9.8 36 0.3048 3600 = 566.04W = 566.04 746 HP = 0.76HP STEP 04 ANALYSIS OF CU QUESTION 01. GKwU hš¿ 5 †m‡K‡Û 20 Ryj KvR Ki‡Z cv‡i| hš¿wUi ¶gZv KZ? [CU. 06-07] A. 4 IqvU B. 4 wbDUb/†m‡KÛ C. 4 IqvU/†m‡KÛ D. 4 wbDUb/wgUvi ¶gZv, P = w t = 20 5 = 4 Watt 02. GKwU •e`y¨wZK †gvU‡i 240V P‡j Ges Gi ¶gZv 120W. hw` †gvUiwU 40N IR‡bi GKwU e¯‘ 4 ‡m‡KÛ 8m. D”PZvq DVv‡Z cv‡i Z‡e †gvUi MvwowUi `¶Zv KZ? [CU. 03-04] A.17% B. 20% C. 255 D.67% P = F S t = 40 8 4 = 80 watt = 80 120 100% = 66.666 = 67% STEP 05 ANALYSIS OF GST QUESTION 01. GKwU `vjv‡bi Qv‡`i mv‡_ jvMv‡bv 10m GKwU gB f~wgi mv‡_ 30 †Kv‡Y AvbZ Av‡Q| 68 kg f‡ii GK e¨w³ 12 kg f‡ii wRwbmmn 19.6 s G gB †e‡q Qv‡` D‡V| H e¨w³ KZ IqvU (w) ÿgZv cÖ‡qvM K‡i‡Q? [GST-A. 20-21] A. 200 B. 300 C. 400 D. 600 S A info P = mgsin t = 68×9.8×sin30 19.6 P = 200 w
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 213 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES PART A Analysis of General University Question JnU 01. cÖwZ †m‡K‡Û 10 wjUvi cvwb 10 wgUvi Dc‡i †Zvjvi Rb¨ KZ ¶gZvq cv¤ú cÖ‡qvRb? [JnU. 10-11] A. 100W B. 980kW C. 980W D. 980J p = mgh t = 10 9.8 10 1 = 980W 02. 75kg f‡ii GK e¨w³ 30 wgwb‡U 300m DPz‡Z D‡V| Zvi KvR Kivi nvi KZ? [JnU. 08-09] A. 12.5W B. 122.5 W C. 300 W D. 245 W P = mgh t = 75 9.8 300 30 60 = 122.5 W KU 01. 100 kg f‡ii GKwU e¯‘‡K †µ‡bi mvnv‡h¨ 10 cms1 †e‡M Qv‡`i Dci DVv‡j †µ‡bi ÿgZv KZ watt? [KU-A, Set-Ka. 19-20] A. 0.98 B. 10 C. 98 D. 9800 †µ‡bi ÿgZv, P = mgv = 100 × 9.8 × 0. 1 = 98 watt. 02. GKwU Kzqv †_‡K GKwU cv‡¤úi mvnv‡h¨ cÖwZ wgwb‡U 1200 kg cvwb 1.0 m Mo D”PZvq D‡Ëvjb Kiv nq| cv¤úwUi Ak¦¶gZv KZ? [KU. 14-15] A. 2.63 H.P B. 1960 H.P C. 117600 H.P D. 120 H.P P = mgh t 746 H.P. = 1200 9.8 10 60 746 = 2.63HP 03. 7.5m j¤^v GKwU gB †`qv‡ji mv‡_ 600 †Kv‡Y †njv‡bv Av‡Q| 65kg f‡ii GK e¨w³ 12kg f‡ii GKwU †evSvmn 20s G gB †i‡L Qv‡` I‡V| cÖhy³ ¶gZv KZ? [KU. 12-13] A. 131.5W B. 135.5W C. 121.5W D. 141.5W P = (m1 + m1)gs cos t = 77 9.8 7.5 cos60 20 = 141.487 = 141.5W BU 01. 5N wµqvi d‡j GKwU e¯‘ wbw`©ó ‡e‡M e‡ji w`‡K avweZ n‡”Q| 100W ¶gZv e¨q n‡j †eM KZ? [BU: 11-12] A. 5m/s B. 100m/s C. 25m/s D. 20m/s P = Fv ev, v = P F = 100 5 = 20m/s JKKNIU 01. 100 kg f‡ii GKwU e¯‘‡K †µ‡Yi mvnv‡h¨ 10 cms–1 †e‡M Qv‡`i Ici DVv‡j †µ‡Yi ÿgZv KZ? [JKKNIU-B, Set-3, 19-20] A. 0.98 W B. 10 W C. 98 W D. 9800 W †µ‡bi ÿgZv, p = mgv = 100 × 9.8 × 0. 1 = 98 watt. PART B Analysis of Science & Technology Question SUST 01. GKRb QvÎx 15min G 120 m DuPz GKwU wUjvq Av‡ivnY Ki‡Z 65.3 W ¶gZv cÖ‡qvM Ki‡j QvÎxi fi KZ kg? [SUST. 14-15] A. 50 B. 60 C. 70 D. 80 E. 90 P = mgh t ev, m = pt gh = 65.3 15 60 9.8 120 = 49.974 = 50kg JUST 01. `vjv‡bi Qv‡`i mv‡_ jvMv‡bv 7.46 m j¤^v GKwU gB †`qv‡ji mv‡_ 60˚ †Kv‡Y Av‡Q| 60 kg f‡ii GK e¨w³ 15 kg f‡ii GKwU †evSvmn 30 sec-G gB †e‡q Qv‡` D‡V| cÖhy³ ÿgZv KZ IqvU? [JUST-A, Set-Ka 19-20] A. 54.9 B. 76.2 C. 91.4 D. 97.2 p = mgh cos t = 75 × 9.8 × 7.46 cos 60o 30 = 91.4 w 02. 75 kg f‡ii GK e¨w³ 30 wgwb‡U 300 m DuPz‡Z D‡V| Zvi KvR Kivi nvi KZ? [JUST. 15-16] A. 12.5 W B. 122.5 W C. 132.5 W D. 300 W E. 245 W P = mgh t = 75 9.8 300 30 60 = 122.5W MBSTU 01. 60 kg f‡ii GKRb †jvK cÖwZwU 15 cm DuPz 40wU wmwo 20 s G DV‡Z cv‡i| †jvKwUi Ak¦ÿgZvÑ [MBSTU-C, Set-2 19-20] A. 236 H.P. B. 176.4 watt C. 0.236 H.P. D. 0.176 watt P = W t = mgh t = 60 9.8 0.15 40 20 Watt = 176.4 W 02. GKwU cv¤ú f~wgi mv‡_ 30 †KvY K‡i 20 m j¤^v cvBc w`‡q NÈvq 36000 kg cvwb Dc‡i DVvq| cv¤úwUi ÿgZv KZ? (g = 9.8 ms2 ) [MBSTU-C, Set-2 19-20] A. 1 kW B. 2 kW C. 3 kW D. 4 kW ÿgZv, P = W t = mgh t = mg lsin30 t 1000 kW = 36000 9.8 20 sin30 3600 1000 = 0.98 kW 1 kW 03. GKwU ‡gvU‡ii ¶gZv 16W| 4wgwb‡U Gi Øviv K…Z KvR KZ? [MBSTU. 15-16] A. 3600J B. 3740J C. 3840J D. 3940J W = Pt = 16 4 60 = 3840J 04. GKwU wjdU 1000 kg fi wb‡q m‡e©v”P 0.1ms–1 ‡e‡M Dc‡i DV‡Z cv‡i| wjdwUi ¶gZv KZ? [MBSTU. 15-16] A. 980W B. 98W C. 1000W D. 100W P = mgv = 1000 9.8 0.1 = 980 W PUST 01. GK wgwb‡Ui g‡a¨ GKwU evj¦ 600THz K¤úv‡¼i GK wgwjqb †dvUb †`q| evj¦wU KZ Iqv‡Ui wQj? [PUST-A, 19-20] A. 6.63 10–19 W B. 6.63 10–15 W C. 3.98 10–19 W D. †KvbwUB bq ÿgZv, P = W t = E t = nh t = 106 6.626 10–34 600 1012 60 = 6.626 10–34 6 1019 6 W = 6.626 10–15 W NSTU 01. 50kg f‡ii GK e¨w³ 5sec G †Kvb wmwo †e‡q 20 avc Dc‡i DVj| cÖwZ av‡ci D”PZv 10cm| †jvKwU KZ ¶gZv e¨envi Kij? [NSTU: 14-15] A. 1.9×104watt B. 490 watt C. 196 watt D. None of them P = mgh t = 50 9.8 2 5 =196 Watt. (h = 20 × 10 = 200cm = 2m) PSTU 01. GKwU BwÄb †Kv‡bv KYvi Dci (2 i j– k) N ej 2 †m‡K‡Û cÖ‡qvM Kivq KYvwUi ( i j k) m miY nq| BwÄbwUi ¶gZv KZ? [PSTU. 15-16] A. 15 IqvU B. 7.5 IqvU C. 75 IqvU D. 1.5 IqvU F i j k S i j k P = W t = FS t F S P = FS t = 15 2 = 7.5W
214 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES STEP 06 ANALYSIS OF ENGINEERING & BUTex QUESTION CKRuet. Combind 01. 100 m Mfxi Kzqv †_‡K GKwU cv¤ú N›Uvq 700kg cvwb D‡Ëvjb Ki‡Z cv‡i| cv¤úwUi ÿgZv wbY©q Ki| †`Iqv Av‡Q, cv¤úwUi Kg©`ÿZv = 72% , [g = 9.8m/sec2 ] [CKRUET. 2020-21] A. 2646.6 W B. 1372 W C. 82320 W D. 1905.6 W E. None of them S A info Kvh©Kix ÿgZv, P = mgh t = 7000×9.8×100 3600 = 1905.56 W ÿgZv P n‡j, P P = 72% P 0.72 = 1905.56 0.72 = 2646.6W 02. †Kv‡bv Kzqv †_‡K 30 m Dc‡i cvwb †Zvjvi Rb¨ 5 kW Gi GwKU cv¤ú e¨envi Kiv nq| cv‡¤úi Kg©`ÿZv 90% n‡j cÖwZ wgwb‡U KZ wjUvi cvwb †Zvjv hv‡e? [g = 9.8 m/sec2 ] [CKRUET. 2020-21] A. 1000 liters B. 815 liters C. 1200 liters D. 918 liters E. 1918 liters S D info Kvh©Kix ÿgZv, P= P × = 5 × 103 × 90% = 1500W P= mgh t m = Pt gh = 4500 × 60 9.8×30 = 918.37 kg V = 918.37L KUET 01. c„w_ex c„‡ôi 20m bxP †_‡K †gvUi cv‡¤úi mvnv‡h¨ cvwb †U‡b DVv‡bv nq Ges cÖwZ wgwb‡U 600kg cvwb wbM©Z nq| hw` cvwbi evB‡i Avmvi †eM 5ms-1 nq, †gvUi cv‡¤úi ¶gZv KZ? [KUET: 12-13] A. 1.96K.W B. 2K.W C. 2.085K.W D. 125Kw E. 2.085W P = mgh + 1 2 mv 2 t = 600 9.8 20 + 1 2 (5) 2 600 60 1000 = 600(9.8 20 + 1 2 (5) 2 ) 60 1000 kW = 2.085K.W 02. 30hp ¶gZv wewkó GKwU Bwćbi `¶Zv 50%. 330 lb f‡ii GKwU e¯‘‡K f~wg †_‡K 750ft D”PZvq Zzj‡Z H Bwćbi KZ mgq jvM‡e? [KUET: 08-09] A. 20sec B. 30sec C. 29sec D. 31sec E. 28sec p= mh t 550 ev, t = mh p 550 ev, t = mh p 550 = 330 750 0.5 30 550 = 30sec 03. ‡Kvb we`y¨r †K‡›`ªi mieivnK…Z we`y¨r kw³ Øviv cÖwZ †m‡K‡Û 5 106 Joule KvR Kiv hvq| we`y¨r †K‡›`ªi ¶gZv KZ? [KUET: 05-06] A. 50M.W B. 100M.W C. 500M.W D. 5M.W P = 5 106Watt = 5M.W BUTex 01. †Kvb e¯‘i Dci F ej cÖ‡qvM Ki‡j e¯‘wU hw` V †e‡M MwZkxj nq Zvn‡j ÿgZv- [BUTex: 15-16] A. FV B. F/V C. FV/2 D. V/F P = W t = Fd t = FV 02. †µ‡bi mvnv‡h¨ 200kg f‡ii GKwU †evgv‡K 0.1ms1 †e‡M DVv‡bv n‡j †µ‡bi ÿgZv KZ? [BUTex: 15-16] A. 19.6W B. 98W C. 196W D. 200W W = Fv = mg v = (200 9.8 0.1)W = 196W 03. GKwU Rj we`y¨r †K‡›`ªi ev‡ai MfxiZv 20m| cÖwZ †m‡K‡Û KZ †KwR cvwb Aek¨B UvievBb †eø‡Wi Dci co‡j GwU 0.5MW we`y¨r Drcbœ Ki‡e? [g = 10ms2 ] [BUTex. 13-14] A. 25 102 kg B. 25 10 kg C. 25 103 kg D. 25 104 kg mgh = Pt; m = Pt gh = 2500kg 04. c„w_exi c„‡ôi 20m wbP †_‡K †gvUi cv‡¤úi mvnv‡h¨ cvwb †U‡b DVv‡bv nq Ges cÖwZ wgwb‡U 600kg cvwb wbM©Z nq| hw` cvwb evB‡i Avmvi †eM 5ms1 nq, †gvU cv‡¤úi ÿgZv KZ? [BUTex: 03-04] A. 1.96 kW B. 2 kW C. 2.085 kW D. 125 kW E. 2.085 kW awi, g = 600kg, h = 20m, v = 5m/s, g = 9.8 m/s2 , t = 60 sec P = mgh + 1 2 mv2 t = 600 9.8 20 + 1 2 600 (5) 2 60 = 2085 = 2.085kw [Avgiv GLv‡b 2 av‡c KvR Kwi cvwbi Ae¯’vb cwieZ©b Kwi Ges MwZkw³ cÖ`vb Kwi|] STEP 07 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. 15 IqvU (watt) kw³ A_©Ñ [MAT. 2020-21] A. 15 J work in 1 sec B. 5 J work in 3 sec C. 1 J work in 15 sec D. 3 J work in 5 sec S A info ÿgZv = KvR mgq = 15 J 1 sec 15 J KvR 1 sec-G n‡j 15 watt ÿgZv eySvq| 02. 74.6kg Gi GKRb †jvK cÖwZwU 25cm DPuy 20wU wmwo 10s G DV‡Z cv‡i| Zvi ¶gZv (w) wb‡gœi †KvbwU [MAT. 07-08] A. 364.54 B. 365.54 C. 366.54 D. 367.54 P = mgh t = 74.6 9.8 0.25 20 10 = 365.54 DAT 01. 100 kg f‡ii GKwU cv_i‡K †µ‡bi mvnv‡h¨ 0.1 ms–1 †e‡M Qv‡`i Ici IVv‡j †µ‡bi ÿgZv KZ? [DAT. 17-18] A. 98W B. 10W C.0.98W D.9800W P = Fv = mgv 100 9.8 0.1 = 98 W STEP 08 ANALYSIS OF HSC BOARD QUESTION 01. 100 kg f‡ii GKwU e¯‘‡K †µ‡bi mvnv‡h¨ 10 cms–1 †e‡M Qv‡`i Ici IVv‡j †µ‡bi ÿgZv KZ? [Xv. †ev. 2019 (gvb wfbœ); P. †ev. 2015] A. 0.98 W B. 10 W C. 98 W D. 9800W S C info P = FV = mg × V = 100 × 9.8 × 10 100 = 98 W 02. 250 kg f‡ii GKwU e¯‘ †µ‡bi mvnv‡h¨ 0.1 ms-1 aªæe‡e‡M Dc‡i DVv‡bv n‡jv| †µ‡bi ÿgZv KZ? [Xv.†ev. 2019] A. 24500 W B. 2500 W C. 245 W D. 24.5 W S C info P = Fv = 250 × 9.8 × 0.1 = 245 W 03. †Kv‡bv cÖwµqvq †gvU cÖ`Ë kw³ Em-Gi GKwU Ask Kvh©Ki kw³ u-†Z iƒcvšÍwiZ nq Ges evwK kw³ W AcPq nq, cÖwµqvwUi `ÿZv KZ? [Xv. †ev. 2015] A. u – W Em 100% B. W Em 100% C. u Em 100% D. u + W Em 100% Ans C
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 215 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES wb‡Pi DÏxcKwU c‡o 04 I 05 `ywU cÖ‡kœi DËi `vI : [Xv. †ev. 2015] wP‡Î Avbyf~wg‡Ki mv‡_ †Kv‡Y AvbZ GKwU Nl©Ywenxb Xv‡j GKwU m kg f‡ii e·‡K †`Lv‡bv n‡jv| e·wU‡K Xv‡ji Dc‡ii w`‡K aªye‡e‡M MwZkxj Ki‡Z Gi Dci Xv‡ji mgvšÍivj F ej cÖ‡qvM Kiv n‡jv| 04. e·wU‡K Xv‡ji Dc‡ii w`‡K ÔxÕm `~iZ¡ AwZµg Kivi Rb¨ KZ KvR Ki‡Z n‡e? A. mgx sin B. mgh cos C. mgx cos D. mgh sin Ans A 05. GLb hw` e·wU‡K ÔvÕ †e‡M MwZkxj ivLvi Rb¨ e‡ji w`‡K ÔaÕ Z¡iY m„ó Ki‡Z nq, Z‡e KZ ÿgZv cÖ‡qvM Ki‡Z n‡e? A. mgv + mav sin B. mav + mgv sin C. mav + mgv cos D. mgv + mav cos Ans B 06. †Kv‡bv hš¿ KZ…©K F aªæe ej cÖ‡qv‡M †Kv‡bv e¯‘ v aªæe †e‡M MwZkxj n‡j h‡š¿i ÿgZv KZ? [iv.‡ev 2021] A. P = Fv2 B. P = Fv C. P = F2 v D. P = F v S B info P = mgh t = FV 07. ¯^vaxb GKwU e¨vMmn 416.5 IqvU ÿgZvm¤úbœ GKwU wjd‡U f~wg †_‡K 0.5ms1 †e‡M wØZxq Zjvq DVj| e¨vMmn ¯^vax‡bi IRb n‡e [h. †ev. 2016] A. 85kg wt B. 42.5kg wt C. 83.3kg wt D. 833kg wt S A info P = Fv F = P v F = 416.5 0.5 = 833 N = 833 9.8 = 85 kg.wt 08. wewfbœ †ÿ‡Î ÿgZvi mgxKiY‡K cÖKvk Kiv hvq- [wm.‡ev 2021] i. P = Frcos t ii. P = F.V iii. P = 1 wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans A 09. 270kg f‡ii e¯‘‡K †µ‡bi mvnv‡h¨ 0.1ms1 aªye †e‡M Dc‡i DVv‡bv n‡j †µ‡bi ÿgZv [wm. †ev. 2016] A. 27W B. 264.6W C. 27HP D. 264.6HP S B info P = Fv = mgv = 270 × 9.8 × 0.1 = 264.6 W 10. GK Ak¦-ÿgZvi mgZzj¨ gvb n‡jv- [g.‡ev 2021] i. 746 Joule/sec ii. 550ft-lb/sec iii. 17710 ft-Poundal/sec wb‡Pi †KvbwU mwVK? A. i B. ii C. i I ii D. i, ii I iii S D info 1 HP = 746 Watt = 550 ft-lb/sec = 550 × 32.2 ft. Poundal/sec [∵g = 32.2 fts-2 ] = 17710 ft.Poundal/ Sec wb‡Pi DÏxc‡Ki Av‡jv‡K 11 I 12 bs cÖ‡kœi DËi `vI: [gv. †ev. 2017] P1 I P2 ÿgZvwewkó `ywU hš¿ h_vµ‡g 20 s Ges 10 s-G 10 kg f‡ii GKwU Kv‡Vi ¸wo‡K GKB mgZj †_‡K 1.5 m D”PZvq DVv‡Z cv‡i| [g = 9.8 ms–2 ] 11. P1 ÿgZvm¤úbœ h‡š¿i Kv‡Ri cwigvY KZ Ryj? A. 15 B. 30 C. 147 D. 200 S C info w = mgh = 10 × 9.8 × 1.5 = 147 J 12. †Kvb m¤úK©wU mwVK? A. P1 = P2 2 B. P1 = P2 C. P1 > P2 D. P1 > 2P2 S A info P1 = mgh t1 , P2 = mgh t2 P1 P2 = t2 t1 P1 = t2 t1 × P2 = 10 20 × P2 P1 = P2 2 13. wPÎvbyhvqx 5N IR‡bi GKwU eøK‡K 10 ‡m. G A †_‡K B †Z wb‡Z cÖhy³ ÿgZvÑ [mKj †evW©-18] A. 3W B. 4W C. 5W D. 6W S A info BC = AB2 – AC2 = 102 – 8 2 = 6 P = w t = F.S t = 5 × 6 10 = 3 W Concept 6 Kzqv msµvšÍ MvwYwZK cÖ‡qvM FORMULA 01. cvwb c~Y© Kzqv Lvwj Kivi †ÿ‡Î W = mg h = mg 2 h 02. Aa© cvwb c~Y© Kzqv Lvwj Kivi †ÿ‡Î W = mg 4 3h 03. K…ZKvR, W = mg h = r 2 h g h ; cvwbi NbZ¡ = v m ; m = v = r 2 h, GLv‡b, h cÖK…Z D”PZv, hv h bq 3h/4 h/2 h/4 h/2 h/4 h=0 h=h h = 2 h + h/4 = 3h/4 h = cvwb k~b¨ D”PZv + cvwb c~Y©D”PZv 2 CONCEPTUAL MATH MEx 01 †Kvb Kyqvi MfxiZv 20m n‡j H K~qv Aa© c~Y© Ae¯’vq Lvwj Ki‡Z K…ZKvR KZ? (cvwbi fi 600kg) W = mg 3h 4 = 600 9.8 3 20 4 = 88200J. NOW START PRACTICE 01. c„w_ex c„ô †_‡K 1.5km Dc‡i wKQz cwigvY †gN Av‡Q H †gN e„wó iƒ‡c †b‡g G‡m f~-c„‡ô 1 106m 2 ¯’v‡b 1cm MfxiZvi cvwb m„wó K‡i| D³ cvwb‡K †g‡N cwiYZ Ki‡Z KZ KvR Ki‡Z n‡qwQj? 02. 10 m MfxiZv wewkó A‡a©K c~Y© Kzqvi m¤ú~Y© cvwb Zzj‡Z K…ZKv‡Ri cwigvY wbY©q Ki? (m¤ú–Y© cvwbi fi, m = 1600 kg ; g = 10 m/s2 )
216 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES NOW PRACTICE SOLVE : 01. W = mgh ( v)gh ( A l)gh 1000 106 .01 9.8 1.5 103 14.7 1010J. 02. cvwb Zzj‡Z K…ZKvR,W = mg 3h 4 = 3 4 mgh = 3 4 1600 10 10 = 1.2 105 J REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. GKwU cvwbc~Y© K~qvi MfxiZv 12m Ges e¨vm 1.8m| GKwU cv¤ú 24 wgwb‡U KyqvwU‡K cvwbk~b¨ Ki‡Z cv‡i| cvwbi NbZ¡ 100 kg/m3 n‡j cv¤úwUi ÿgZv KZ? [DU. 16-17] A. 1.67 H.P. B. 3.34 H.P. C. 6.68 H.P. D. 26.72 H.P. cvwb DVv‡bvi Kvh©Ki ev Mo D”PZv, h = 0 + 12 2 = 6m Ges e¨vmva©, r = 1.8 2 = 0.9m P = W t = Fh t = mgh t = Vgh t = r 2 lgh t = 3.14 0.92 12 1000 9.8 6 24 60 = 1246.90W = 1246.90 746 H.P. = 1.67 H.P. 02. cÖwZ †m‡K‡Û 10litre cvwb 10m Dc‡i †Zvjvi Rb¨ AšÍZ KZ ÿgZvi cv¤ú `iKvi? [DU. 00-01] A. 980J B. 100W C. 980W D. 980KW P = W t = mgh t = 10 9.8 10 1 = 980W STEP 02 ANALYSIS OF JU QUESTION 01. 50m Mfxi GKwU Kzqv †_‡K Bwćbi mvnv‡h¨ 30sec G 1000kg cvwb DVv‡bv nq| hw` BwÄbwUi ¶gZv 40% bó nq Zvn‡j Gi Ak¦¶gZv- [JU. 10-11] A.80.00H.P B. 36.49H.P C.37.75 H.P D. 50.12H.P p = mgh t 746 H.P ev, P = 1000 9.8 50 30 746 0.60 = 36.49 02. 100 m Mfxi GKwU Kzqv †_‡K Bwćbi mvnv‡h¨ cÖwZ wgwb‡U 1000 kg cvwb DVv‡bv nq| hw` BwÄbwUi ¶gZv 42% bó nq, Zvn‡j Gi Ak¦¶gZv- [JU. 10-11] A. 80.00 HP B. 73.75 HP C. 75.37 HP D. 37.75 HP Kvh©Ki ¶gZv = (100 – 42)% = 58%; 0.58 P = mgh t P = 1000 9.8 100 60 0.58 746 = 37.75 H.P. STEP 03 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. GKwU cvwbc–Y© Kzqvi MfxiZv 20m Ges e¨vm 2m| GKwU cv¤ú 24 wgwb‡U KzqvwU‡K cvwbk~b¨ Ki‡Z cv‡i| cv¤úwUi Ak¦¶gZv KZ? [JnU. 12-13] A. 6.53 H.P. B. 5.73 H.P. C. 4.63 H.P. D. 1.67 H.P. KzqvwU‡K cvwb k~b¨ Ki‡Z K…ZKvR, W = mg h 2 = Vg h 2 = Ahg h 2 = r 2 hg h 2 W = 1 2 20 103 9.8 20 2 = 6.16 106 J ¶gZv, P = W t = 6.16 106 24 60 746 = 5.73H.P. KU 01. GKwU Kzqv †_‡K cv‡¤úi mvnv‡h¨ cÖwZ wgwb‡U 1200 kg cvwb 10 m Mo D”PZvq D‡Ëvjb Kiv nq| cv¤úwUi Ak¦¶gZv KZ? [KU. 14-15] A. 2.63 H.P B. 1960 H.P C. 117600 H.P D. 120 H.P ¶gZv, P = mgh t = 1200 9.8 10 1 60 = 1960 Watt = 1960 746 = 2.63 H.P. 02. 3430W ¶gZv m¤úbœ GKwU †gvUi PvwjZ cv¤ú Øviv GKwU K~c n‡Z M‡o 7.20m D”PZvq cvwb DVv‡bv nq| †gvU‡ii `¶Zv 90% n‡j cÖwZ wgwb‡U KZ wK‡jvMÖvg cvwb DV‡e? [KU. 10-11] A. 2324 kg B. 2625kg C. 2356 kg D. 1000 kg p = mgh t m = pt gh = 0.90 3430 60 9.8 7.2 = 2625kg 03. GKwU cvwbc~Y© Kzqvi MfxiZv 10 m Ges e¨vm 40 m GKwU cv¤ú 20 wgwb‡U KzqvwU‡K cvwbk~b¨ Ki‡Z cv‡i| cv‡¤úi Ak¦ ¶gZv wbY©q Ki| [KU. 06-07] A. 687.48HP B. 748HP C. 847.45HP D. 847.45HP ¶gZv, P = r 2 h 2 g 2t 746 H.P. = 3.14 202 102 1000 9.8 2 20 60 746 = 687.48 HP 04. GKwU cv¤ú 4.9 wgwb‡U Kzqv †_‡K 1000 Kg cvwb 6 m Mo D”PZvq Zzj‡Z cv‡i| cv‡¤úi ¶gZvi 75% Kvh©Ki n‡j Gi ¶gZv wbY©q Ki| [KU. 05-06] A. 266.67W B. 2667.68W C. 257.35W D. 295.52W p = mgh t ev, P = mgh t = 1000 9.8 6 4.9 60 0.75 = 266.67W BU 01. GKwU †gvUi 100m Mfxi GKwU Kzqv †_‡K cÖwZ wgwb‡U 1200kg cvwb Zzj‡Z cv‡i| †gvU‡ii ¶gZv- [BU: 11-12] A. 10000watt B. 19.6kwatt C. 1200watt D. None P = mgh t = 1200 9.8 100 60 1000 = 19.6kW PART B Analysis of Science & Technology Question NSTU 01. GKwU cvwbc~Y© K~‡ci MfxiZv I e¨vm h_vµ‡g 10m I 4m| GKwU cv¤ú 20 wgwb‡U K~cwU‡K cvwb k~b¨ Ki‡Z cv‡i| cv¤ú Gi Ak¦ ¶gZv wbY©q Ki| [NSTU: 14-15] A. 5.1 HP B. 51.28 HP C. 6.87 HP D. None W = r 2 h 2 g 2 = (2) 2 (10) 2 1000 9.8 2 = 6157521.60 P = w t = 6157521.60 20 60 746 , P = 6.878HP
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 217 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES PSTU 01. GKwU cvwbc~Y© Kzqvi MfxiZv 10m Ges e¨vm 1.5m| GKwU cv¤ú 25 wgwb‡U KyqvwU‡K cvwbk~b¨ Ki‡Z cv‡i| cv¤úwUi ¶gZv KZ? [PSTU. 15-16] A. 0.773HP B. 1.543HP C. 3.095HP D. 6.190HP P = r 2 lgh 2t = (0.75) 2 10 1000 9.8 × 10 2 746 25 60 = 0.7738HP STEP 04 ANALYSIS OF ENGINEERING & BUTex QUESTION KUET 01. GKwU BwÄb 5 wgwb‡U Kzqv †_‡K 10,000 wjUvi cvwb 10m Mo D”PZvq Zzj‡Z cv‡i| BwÄbwUi ÿgZv 70% Kvh©Ki n‡j Gi Ak¦ ÿgZv †KvbwU? [KUET:18-19] A. 3.35hp B. 3.07hp C. 3.65hp D. 4.38hp E. 6.25hp Pin = 100 70 10000 9.8 10 5 60 746 hp = 6.25hp 02. GKwU cv¤ú N›Uvq 25 106 kg cvwb 50 m Mfxi Kzqv ‡_‡K Zzj‡Z cv‡i| cv‡¤úi ¶gZv 70% Kvh©Ki n‡j cÖK…Z ¶gZv KZ? [KUET:09-10] A. 4.06 MW B. 4.86 MW C. 2.38 MW D. 420 MW E. 238 MW mgh t = p 70 100 , P = 4.86 MW 03. GKwU Kzc †_‡K 20m Dc‡i cvwb †Zvjvi Rb¨ 3K.W Gi GKwU cv‡¤ú e¨envi Kiv nq| cv‡¤úi `¶Zv 87.7% n‡j cÖwZ wgwb‡U KZ wjUvi cvwb †Zvjv hv‡e? [KUET: 09-10] A. 1610Li B. 805L C. 402L D. 201L E. 100L p = mgh t m = pt gh = .877 3 1000 60 9.8 20 = 805.4L 04. 100m Mfxi GKwU Kzc †_‡K Bwćbi mvnv‡h¨ cÖwZ wgwb‡U 100kg cvwb DVv‡bv nq| hw` BwÄbwUi ¶gZvi 20% bó nq; Z‡e Gi Ak¦¶gZv KZ? [KUET: 07-08] A. 2.73H.P B. 27.37H.P C. 273 H.P D. 027HP E. 273.68HP p = mgh t 746 H.P ev, P = 100 9.8 100 60 0.80 746 = 2.736H.P RUET 01. GKwU cvwb c~Y© Kzqvi e¨vm 4m GK MfxiZv 12m. GKwU cv¤ú 20minute G GUv‡K cvwbk~b¨ Ki‡Z cv‡i| cv¤úwUi ¶gZv wbY©q Ki? [RUET: 09-10] A. 7.396kW B. 7.693kW C. 7.5kW D. 8.39kW E. 8.693kW P = r 2 h 2 g 2t 1000 = (2) 2 (12) 2 1000 9.8 2 20 60 1000 = 7.389 kW STEP 05 ANALYSIS OF HSC BOARD QUESTION wb‡Pi DÏxcKwU co Ges 01 I 02 bs cÖ‡kœi DËi `vI : [h. †ev. 2015] GKwU cvwbc~Y© Kzqvi MfxiZv 10m Ges e¨vm 1.5m GKwU cv¤ú 25 wgwb‡U KzqvwU‡K cvwbk~b¨ Ki‡Z cv‡i| 01. cv¤úwUi ÿgZv KZ? A. 0.773 HP B. 1.543 HP C. 3.095 HP D. 6.190 HP S A info P = r 2 lgh t = 3.14 × (0.75) 2 ×10 × 9.8 × 103 × 5 25 × 60 = 0.773 H.P 02. 0.4 HP ÿgZvi AviI GKwU cv¤ú hy³ Ki‡j wK cwigvY mgq mvkÖq n‡e? A. 24.36 wgwbU B. 16.48 wgwbU C. 8.52 wgwbU D. 0.63 wgwbU S C info p + p = w t t = w p + p = 3.14 × (0.75) 2 × 10 × 9.8 × 103 × 5 (0.77 + 0.4) × 746 = 8.52 wgwbU 03. GKwU Kzqvi MfxiZv 10m Ges e¨vm 6m| GKUv cv‡¤úi mvnv‡h¨ KzqvwU‡K 20 wgwb‡U m¤ú~Y© cvwb k~b¨ Kiv n‡j cv‡¤úi ÿgZv KZ? [e. †ev. 2015] A. 15.5 HP B. 2.15 HP C. 3.12 HP D. 3.53 HP S A info P = W t = Fh t = mgh t = Vgh t = 3.14 × 32 × 10 × 1000 × 9.8 × 5 20 × 60 = 11563 W = 15.5 H.P. SAQ Short Answer Questions WRITTEN PART BAQ Broad Answer Questions 01. †Kv‡bv Kzqv †_‡K 30m Dc‡i cvwb †Zvjvi Rb¨ 5 kW Gi GKwU cv¤ú e¨envi Kiv nq| cv‡¤úi Kg©`ÿZv 90% n‡j cÖwZ wgwb‡U KZ wjUvi cvwb †Zvjv hv‡e? [g = 9.8m/sec2 ] Solve P = 5 103 0.9 = 4500 W,h = 30m, t = 1min = 60s P = mgh t m = Pt gh m = 918.367 kg ∵ w = m v = 1 kg L V = 918 L 02. GKwU `vjv‡bi Qv‡` jvMvb 5m j¤^v GKwU gB Abyf~wg‡Ki mv‡_ 30 †KvY K‡i Av‡Q| 60kg f‡ii GK e¨w³ 20kg f‡ii †evSv wb‡q 10sec G Qv‡` I‡Vb| Zvi Ak¦ÿgZv †ei Ki| Solve W = mgh = 80 9.8 5sin30J = 1960J P = W t = 1960 10 = 196W. e¨w³i Ak¦ ÿgZv = 196 746h.p. = 0.2627 h.p. 03. 144kg f‡ii GK e¨w³ 65kg f‡ii GKwU †evSv wb‡q 2m `xN© GKwU wmwo †e‡q 2min G Dc‡i D‡V| hw` wmwowU Abyf‚wg‡Ki mv‡_ 30 †Kv‡Y AvbZ _v‡K Zvn‡j m¤úbœ Kv‡Ri cwigvY wbY©q Ki? Solve GLv‡b, m = (144 + 65) = 209kg g = 9.8 ms–2 x = 2m = 30 W = mgh = mgx sin = 209 9.8 2 sin30 = 2048.2 J 04. 30m D”PZv †_‡K GKwU e¯‘‡K webv evavq co‡Z w`‡j †Kv_vq Dnvi MwZkw³ wefekw³i wظY n‡e? Solve cÖkœg‡Z, v 2 = v0 2 + 2g (30 – h) v 2 = 2g (30 – h) [v0 = 0 ms–1 ] Avevi, Ek = 1 2 mv2 Ek = 1 2 m.2g (30 – h) Ek = 30mg – mgh Avevi, Ep mgh kZ©g‡Z, Ek = 2Ep 30mg – mgh = 2mgh 30g = 3gh h = 10m 05. GKwU e¯‘i fi‡eM 200% e„w× Ki‡j Gi MwZkw³ KZ¸Y cwiewZ©Z nq? Solve e¯‘i fi‡eM e„w× P1 = 200% P = 200 100P = 2P e¯‘i MwZkw³ Ek1 = ? Avgiv Rvwb, Ek1 Ek2 = P1 2 P 2 Ek1 Ek2 = (2P) 2 P 2 Ek1 = 4Ek myZivs, MwZkw³ 4 ¸Y e„w× cvq| 06. 3430W ÿgZv m¤úbœ GKwU †gvUi PvwjZ cv¤ú Øviv GKwU K‚c n‡Z M‡o 7.20m D”PZvq cvwb DVv‡bv nq| †gvU‡ii `ÿZv 90% n‡j cÖwZ wgwb‡U KZ wK‡jvMÖvg cvwb D‡V| Solve P = P = m t gh m = Pt gh = 0.90 3430 60 9.8 7.2 = 2625kg
218 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 07. 3kg f‡ii e¯‘i Dci GKwU ej wµqvkxj Av‡Q| e¯‘wUi Ae¯’vb mgxKiY x = 3t – 4t2 + t3 , ‡hLv‡b x Gi gvb wgUv‡i Ges t Gi gvb †m‡K‡Û| t = 0 n‡Z t = 4 †m‡KÛ mg‡q ejwU w`‡q e¯‘i Dci K…ZKv‡Ri cwigvY wbY©q Ki| Solve x = 3t – 4t2 + t3 v = 3 – 8t + 3t2 t = 0s G †eM = 3ms–1 , t = 4s G †eM = 3 – 8 4 + 3 4 2 = 19 K…ZKvR = MwZkw³i cwieZ©b = 1 2 m (v4 2 – v0 2 ) = 1 2 3 (192 – 3 2 ) = 528J 08. GKwU cvwb c~Y© Kzqvi MfxiZv 7.2 wgUvi I e¨vm 4 wgUvi| 31.4 wgwb‡U KzqvwU‡K cvwb k~b¨ Ki‡Z cv‡i Giƒc GKwU •e`y¨wZK cv‡¤úi ÿgZv wbY©q Ki| Solve Kzqvi fi‡K›`ª = D”PZv 2 = 7.2 2 = 3.6m Kzqvi AvqZb = r 2 h = (2)2 7.2 = 90.47 103Litre Kzqvi cvwbi fi = 90.47 103 kg [∵ 1 litre cvwbi fi = 1kg] P = W t = mgh t = 90.47103 9.83.6 31.460 = 1.69kW GLv‡b, A = 2rh, r = d 2 = 4 2 = 2m v = r 2 h A h r 2 09. GKwU e¯‘‡K wbw`©ó D”PZv †_‡K †d‡j †`qv nj| f~wg n‡Z 10 wgUvi D”PZvq MwZkw³ w¯’wZkw³i wظY n‡j KZ D”PZv †_‡K e¯‘wU‡K †djv n‡qwQj? Solve g‡b Kwi, h D”PZv n‡Z e¯‘wU †d‡j †`Iqv n‡qwQj| f~wg n‡Z 10m D”PZvq; wefekw³, Ep = mg 10 = 10mg MwZkw³, Ek = 1 2 mv2 = 1 2 m (v0 2 + 2gh) = 1 2 m {0 + 2g (h – 10)} = mg(h – 10) kZ©g‡Z, mg(h – 10) = 2 10mg h h–10m 10m h = 30m 10. c„w_exi c„ô †_‡K 1.5km Dc‡i wKQz cwigvY †gN Av‡Q| H †gN e„wóiƒ‡c †b‡g G‡m f~-c„‡ô 1106m 2 ¯’v‡b 1cm MfxiZvq cvwb m„wó Ki‡Z cv‡i| D³ cvwb‡K †g‡N cwiYZ Ki‡Z KZ KvR Ki‡Z n‡qwQj- [BUTex:00-01] Solve v = 106 10–2m 3 = 104m 3 ; h = 1.5km = 1.5 103m; m = v = (103 104 ) = 107 kg K…ZKvR, W = mgh = 107 9.81.5103 = 14.7 1010J 11. Abyf‚wgK Kv‡Vi Dci GKwU †c‡iK Djø¤^fv‡e ivLv Av‡Q| 1 kg f‡ii GKwU nvZzwo Øviv †c‡iKwU‡K Lvov wb‡Pi w`‡K 4 ms1 ‡e‡M AvNvZ Kiv n‡jv| †c‡iKwU Kv‡Vi g‡a¨ 0.015 m Xz‡K †M‡j Mo evav`vbKvix ej wbY©q Ki| Solve Avgiv Rvwb, nvZzwoi wefekw³ + MwZkw³ = Kv‡Vi cÖwZ‡iva e‡ji weiæ‡× KvR ev, mgx + 1 2 mv2 = Fx F = mg + mv2 2x GLv‡b, nvZzwoi fi, m = 1kg nvZzwoi †eM, v = 4ms1 †c‡i‡Ki miY, x = 0.015m AwfKl©R Z¡iY, g = 9.8ms2 Mo evav`vbKvix ej, F = ? = 1 kg 9.8 ms2 + 1 kg + (4ms1 ) 2 2 0.015 m = 543.13 N 543.13 N 12. GKwU KYvi Dci F = ( 2 ) ^ i + 3^ j + 4^ k N ej cÖ‡qv‡Mi d‡j Q (3, 4, 2) we›`y †_‡K P ( 2, 3, 5) we›`y‡Z ¯’vbvšÍwiZ nq| ej KZ©„K m¤úvw`Z Kv‡Ri cwigvY wbY©q Ki| Solve GLv‡b, Q we›`yi Ae¯’vb †f±i r1 = (3 ) ^ i + 4^ j + 2^ k Ges P we›`yi Ae¯’vb †f±i r2 = ( 2 ) ^ i + 3^ j + 5^ k miY, r = r2 r1 = ( 2 3)^ i + (3 + 4)^ j + (5 + 2) ^ k = ( 5 ) ^ i + 7^ j + 7^ k Avgiv Rvwb, KvR, w = F. r = ( 2 ) ^ i + 3^ j + 4^ k N. ( 5 ) ^ i + 7^ j + 7^ k m = (10 + 21 + 28) J = 59 J 59 J 13. GKwU e›`y‡Ki w¯úªs‡K 4cm msKzwPZ K‡i 10gm f‡ii GKwU ¸wo †Quvov n‡jv| w¯úªswU hLb mvg¨ve¯’vq †cu․‡Q ZLY m`¨gy³ ¸wji †eM KZ? Solve msKzwPZ w¯úªq Gi w¯’wZkw³ = 1 2 kx2 G w¯’wZkw³ ¸wji MwZïw³‡Z iƒcvšÍwiZ nq| 1 2 kx2 = 1 2 mv2 ev, kx2 = mv2 ev, v 2 = kx 2 m = (200 N/m)(4 102 m) 2 (102 kg) = 32 ev, v = 5.67 m/s v = 5.67 m/s GLv‡b, k = w¯úªs aªæeK = 200 N/m x = •`N©¨ ms‡KvPb = 4cm = 4 102 m m = ¸wji fi = 10 gm =10 2 kg v = ¸wji †eM = ? 14. 28 cm •`N©¨ I 0.012 kg f‡ii GKwU mylg †PB‡bi GK PZz_©vsk †Kv‡bv Abyf‚wgK †Uwe‡ji GK cÖvšÍ n‡Z Szj‡Q| SzjšÍ Ask †Uwe‡ji Dci Zzj‡Z K…ZKvR KZ? Solve hw` †PB‡bi †gvU fi M Ges m¤ú~Y© •`N©¨ L nq, Z‡e, SzjšÍ As‡ki fi M 4 Ges †Uwe‡ji cÖvß n‡Z SzjšÍ As‡ki fvi‡K‡›`ªi `~iZ¡ L 8 | myZivs SzjšÍ Ask‡K, L 8 D”PZvq Zzj‡Z K…ZKvR, W = M 4 g L 8 = 1 32 MgL = 1 32 (0.012 kg) (9.8 m/s2 (28 102 m) = 0.0010 J 15. cvwb cwic~Y© cyKz‡ii MfxiZv 10 wgUvi, •`N©¨ 10 wgUvi Ges cÖ¯’ 5 wgUvi| 30 wgwb‡U cyKziwU‡K cvwb k~b¨ Ki‡Z KZ Ak¦ÿgZvi cv¤ú e¨envi Ki‡Z n‡e?[KUET; 19-20] Solve cyKz‡ii cvwbi AvqZb, V = (10 5 10) = 500 m3 cvwbi fi, m = v = 1000 500 kg cyKz‡ii fvi‡K‡›`ªi MfxiZv, h = 10 2 = 5m h 2 h 2 P = mgh t watt = 1000 500 9.8 5 30 60 746 H.P = 18.245 H.P 16. †Kv‡bv Kzqv †_‡K 30m Dc‡i cvwb †Zvjvi Rb¨ 5kW Gi GKwU cv¤ú e¨envi Kiv nq| cv‡¤úi Kg©`ÿZv 90% n‡j cÖwZ wgwb‡U KZ wjUvi cvwb †Zvjv hv‡e? [g = 9.8 m/sec2 ] [BUET: 18-19] Solve P = 5 103 0.9 = 4500W, h = 30m, t = 1 min = 60s P = mgh t m = Pt gh m = 918.367kg ∵w = m v = 1 kg L V = 918L 17. GKwU cvwb c~Y© Kzqvi MfxiZv 7.2 wgUvi I e¨vm 4 wgUvi| 31.4 wgwb‡U KzqvwU‡K cvwb k~b¨ Ki‡Z cv‡i Giƒc GKwU •e`y¨wZK cv‡¤úi ÿgZv wbY©q Ki| [BUTex: 03-04] Solve Kzqvi fi‡K›`ª= D”PZv 2 = 7.2 2 = 3.6m Kzqvi AvqZb r 2 h = (2)2 7.2 = 90.47 103 Litre Kzqvi cvwbi fi = 90.47 103 kg [ 1 litre cvwbi fi = 1 kg] P = W t = mgh t = 90.47 × 103 × 9.8 3.6 31.4 60 = 1.69kW
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 219 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 18. GKwU ivB‡d‡ji ¸wj GKwU Z³v †f` K‡i| hw` ¸wji †eM wظY Kiv nq Zv n‡j GKB cyiæ‡Z¡i KZwU Z³v †f` Ki‡e? [RU-C, Set-3. 19-20] Solve g‡b Kwi, ¸wji fi = m Ges †eM = v 1g †ÿ‡Î : MwZkw³, Ek1 = 1 2 mv2 2q †ÿ‡Î : MwZkw³, Ek2 = 1 2 m(2v)2 = 2mv2 †f`K…Z Z³vi msL¨v, n = Ek2 Ek1 = 2mv2 1 2 mv2 = 4 ASPECT SPECIAL: †f`K…Z Z³vi msL¨v, n = v2 = 22 = 4wU| 19. cÖwZwU 2 1030kg f‡ii `ywU Zviv gy‡LvgywL msN‡l©i Rb¨ GK Ac‡ii w`‡K avegvb| wbKUeZ©x nIqvi c~‡e© `ywUi ga¨eZ©x `~iZ¡ wQj 109 km Ges Zv‡`i MwZ wQj bMY¨| msN‡l©i mg‡q Zv‡`i †eM KZ n‡e? cÖwZwU Zvivi e¨vmva© 104 km| a‡i bvI †h, msNl© bv nIqv ch©šÍ Zviv `ywU AweK…Z _vK‡e| [G = 6.67 10–11NM2 kg–2 ] [BUET; 19-20] Solve ZviKv‡`i †gvU kw³ msiwÿZ _vK‡e| – GM M 109 103 = – GM M (104 + 104 ) 103 + 2 1 2 Mv2 v 2 = GM 1 2107 – 1 1012 = 6.67 1012 v = 2.58 106 ms–1 20. 0.5m D”PZv n‡Z 2.5kg f‡ii GKwU e¯‘ GKwU w¯úªs Gi Dci cwZZ n‡jv| w¯úªs Gi ej aªæeK 1950 N/m n‡j w¯úªswU me©vwaK KZUzKz msKzwPZ n‡e wbY©q Ki| [BUTEX; 19-20] Solve GLv‡b, mg(h + x) = 1 2 kx2 2.5 9.8(0.5 + x) = 1 2 1950x2 975x2 – 24.5x – 12.25 = 0 x = 0.1253557m = 12.535577 cm 21. GKwU ej 60m DuPz n‡Z gvwU‡Z cwZZ n‡j GwU 75% kw³ nvwi‡q †dj‡j GwU cÖwZdwjZ n‡q KZ D”PZvq DV‡e? [BUTEX; 19-20] Solve mgh = 0.25 mgh [Aewkó kw³ = 25%] h = 0.25h = 15m 22. 2 kg f‡ii GKwU e¯‘ 500 m Dc‡i Aew¯’Z GKwU wegvb †_‡K †d‡j †`Iqv n‡jv| f~wg ¯úk© Kivi c~e© gyû‡Z© Gi MwZkw³ KZ?[RU-C, Set-1. 19-20] Solve f‚wg ¯úk© Kivi gyn~‡Z© MwZkw³ = †gvU wefekw³ wefekw³ Ep = mgh m = 2kg g = 9.8 ms2 ; h = 500 m Ep = (2 9.8 500) J. = 9800 J 23. GKwU `vjv‡bi Qv‡`i mv‡_ jvMv‡bv 5m j¤^v GKwU gB Abyf~wg‡Ki mv‡_ 30 †KvY K‡i Av‡Q| 60 kg f‡ii GK e¨w³ 25 kg f‡ii IRbmn 10 sec G Qv‡` DV‡j Zvi Ak^ÿgZv †ei Ki| [RUET: 19-20] Solve h ; h = 5 sin 30˚ = 2.5 m †jvKwUi Ak^ÿgZv, P = mgh t = (60 + 25) × 9.8 × 2.5 10 × 746 HP = 0.279 HP 30˚ 5m 24. 10 KW kw³ m¤úbœ GKwU Bwćbi 200kg f‡ii GKwU e¯‘‡K 40m D”PZvq Zzj‡Z KZ mgq jvM‡e? (g = 10m/s2 )? [BUTex: 03-04] Solve P = mgh t t = mgh P = 200 10 40 10 1000 = 8s 25. 90 dzU D”PZv n‡Z GKwU e¯‘‡K cwZZ n‡Z †`qv nj| †Kv_vq Gi MwZkw³ w¯’wZ kw³i A‡a©K n‡e? Solve awi, x D”PZvq 1 2 P.E = K.E n‡e| x D”PZvq P.E = mgx Ges K.E = 1 2 m.2g (h – x) = mg(h –x), [v2 = u 2 + 2g(h – x) v 2 = 2g(h – x)] V V1 (h – x) h = 90 U = 0 x GLb, 1 2 mgx = mg (h – x) 1 2 x = (h – x) 3 2 x = h x = 2 3 h = 60 ft STEP 3 mKj cvV¨eB‡qi NCTB QUESTIONS ANALYSIS cÖkœ e¨vLvmn mgvavb 01 cÖkœ . [Bm&nvK, Avwgi] mg F wPÎ : wP‡Î F e‡ji cÖfv‡e eøKwU AvbZ Zj †e‡q Dc‡ii w`‡K DV‡Q| GLv‡b †Kvb e‡ji weiæ‡× KvR n‡q‡Q? A. F B. mg C. mg sin D. mg cos F = mg cos(90 – ) = mg sin 02. Gi gv‡bi †ÿ‡Î- [Bm&nvK, Avwgi] i. 0 0 0 90 n‡j e‡ji Øviv KvR m¤úbœ n‡e ii. 0 0 90 135 n‡j e‡ji weiæ‡× KvR m¤úbœ n‡e iii. 1350 1800 n‡j FYvZ¥K KvR m¤úbœ n‡e wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans C 03. kw³i GKK- [Bm&nvK, Avwgi] i. Ryj ii. kgm2 s –2 iii. B‡jKUªb †fvë wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans D 04. GKwU nvév I GKwU fvix e¯‘i fi‡eM GKB, †KvbwUi MwZkw³ †ewk? [Bm&nvK, Avwgi] (i) nvév e¯‘wUi (ii) fvix e¯‘wUi (iii) Df‡qi mgvb wb‡Pi †KvbwU mwVK? A. i B. ii C. iii D. i,ii I iii S A info Ek = P 2 2m Ek 1 m [∵ aªæeK] fi hvi Kg MwZkw³ Zvi †ewk| 05. wP‡Î 100 kg f‡ii eøKwU AB Zj eivei wb‡P coj| K…Z Kv‡Ri cwigvY KZ? [Bm&nvK, Avwgi] 2m A C B 60° A. 100 J B. 200 J C. 980 J D. 1960 J S C info W = mgscos = 100 × 9.8 × 2 × cos60° = 980 J
220 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES wb‡Pi †jLwPÎwU‡Z GKwU w¯úªs-G cÖhy³ e‡ji mv‡_ •`N©¨ e„w×i cwieZ©b †`Lv‡bv n‡q‡Q| 06 I 07 bs cÖ‡kœi DËi `vI: A B 1 2 3 4 5 6 ej (N) 5 4 3 2 1 0 •`N©¨ e„w× (cm) 06. Nm–1 GK‡K w¯úªs aªæeK KZ? [Bm&nvK, Avwgi] A. 200 B. 150 C. 100 D. 50 S B info K = F x = 3 2 × 10–2 = 150 Nm–1 07. w¯úªswUi •`N©¨ e„w× 3 cm n‡j w¯úªs-G mwÂZ kw³i cwigvY KZ? [Bm&nvK, Avwgi] A. 0.0675 J B. 0.0576 J C. 0.0375 J D. 0.0275 J S A info U = 1 2 Kx2 = 1 2 × 150 × (3 × 10–2 ) 2 = 0.0675 J 08. wb‡Pi †Kvb Z_¨wU mwVK? [Bm&nvK, Avwgi] A. Ek h B. Ek h C. Ek h D. Ek h Ans A 09. GKwU e¯‘KYv w¯’ive¯’v †_‡K AwfK‡l©i cÖfv‡e co‡Z _v‡K| f~-c„‡ôi mv‡c‡ÿi KYvwUi w¯’wZkw³ (PL) I MwZkw³ (KE) Ges mgq (t) Gi †jLwPÎ AvuKv n‡jv| mwVK †jL †KvbwU? [Bm&nvK, Avwgi] A. PE KE t B. PE KE t C. PE KE t D. PE KE t Ans B 10. GKwU w¯úªs‡K cÖmvwiZ Kiv n‡jv- [Bm&nvK, Avwgi] i. GwU wefe kw³ AR©b K‡i ii. GwU cÖZ¨vqbx ej jvf K‡i iii. cÖZ¨vqbx e‡ji Øviv K…Z KvRB Gi wefe kw³ wb‡Pi †KvbwU mwVK? A. i I iii B. i I ii C. ii I iii D. i, ii I iii Ans B 11. GKwU w¯úªs Gi GK cÖvšÍ `„p Aej¤^‡b AvUwK‡q Aci cÖv‡šÍ fi Szwj‡q w¯úªswU Dc‡i wb‡P `yj‡Z †`Iqv n‡jv| [Bm&nvK, Avwgi] A. †gvU kw³ mgq B. †gvU kw³ mgq C. †gvU kw³ mgq D. †gvU kw³ mgq Ans C 12. f~wg‡Z cZ‡bi gyn~‡Z© e„wói †dvUvi Z¡iY KZ n‡e? [Bm&nvK, Avwgi] A. k~b¨ B. g C. g 2 D. g Ans A 13. †Kv‡bv MwZkxj e¯‘i MwZkw³ Ek Ges fi‡eM P n‡j P ebvg E †jLwPÎwU n‡e- [Bm&nvK, Avwgi] A. Awae„Ë B. AvqZvKvi cive„Ë C. Dce„Ë D. mij‡iLv Ans D 14. GKwU e¯‘i MwZkw³ wظY Kiv n‡jv| Zvi fi‡eM- [Bm&nvK, Avwgi] A. AcwiewZ©Z _vK‡e B. 4 ¸Y n‡e C. 1 2 ¸Y n‡e D. 2 ¸Y n‡e S D info Ek = P 2 2m P Ek [m constant] P2 = n × P1 = 2P 15. •iwLK fi‡eM 50% evo‡j MwZkw³ e„w× cvqÑ [Bm&nvK, Avwgi] A. 25% B. 50% C. 100% D. 125% S D info 1.5 100 50 1 P2 1 1 2 1 2 1 2 2 E (1.5) E 2.25E P P E E = 2.25E1 – E1 = 1.25E1 = 125% 16. †Kv‡bv w¯úªs Gi gy³ cÖv‡šÍi GKK miY NUv‡j w¯úªswU mi‡Yi wecixZ w`‡K †h ej cÖ‡qvM K‡i Zv‡K Kx ejv nq? [Zcb, AvwRR] A. evwn¨K ej B. cÖhy³ ej C. w¯úªs aªæeK D. †Kv‡bvwUB bq Ans C 17. 2Nm1 w¯úªs aªæe‡Ki GKwU Av`k© w¯úªs Gi •`N©¨ mvg¨ve¯’v †_‡K 0.1m e„w× Ki‡j w¯úªs Gi wefekw³ KZ e„w× cv‡e? [Zcb, AvwRR] A. 0.1 J B. 0.001J C. 1 J D. 0.01J w = 1 2 kx2 = 1 2 2 (0.1)2 = 0.01 J 18. GK e¨w³ GKwU e¯‘‡K 30 s-G 1m D”PZvq IVvq| Aci GK e¨w³ GKB e¯‘‡K 60 s-G GKB D”PZvq Zzj‡Z cv‡i| Zv‡`i Kv‡Ri AbycvZ n‡e- [Zcb, AvwRR] A. 1 : 2 B. 1 : 1 C. 2 : 1 D. 4 : 1 S B info W = mgs A_©vr KvR mg‡qi Dci wbf©ikxj bq| W1 : W2 = 1 : 1 19. GKwU e¯‘ hw` mg`ªæwZ‡Z e„ËvKvi c‡_ Ny‡i- [Zcb, AvwRR] i. Gi Dci †Kv‡bv KvR nq bv ii. Gi Dci †Kv‡bv ej wµqv K‡i bv iii. Gi †eM AcwiewZ©Z _v‡K bv wb‡Pi †KvbwU mwVK? A. i I iii B. i I ii C. ii I iii D. i, ii I iii Ans A 20. 1kg f‡ii GKwU e¯‘ gm„Y Avbyf~wgK mgZ‡ji Dci w`‡q 2ms-1 †e‡M 1m c_ AwZµg Kij| AwfKl© e‡ji Øviv Kv‡Ri cwigvY KZ? [Zdv¾j, gwnDwÏb] A. k~b¨ B. 2J C. 1J D. 0.5J Ans A 21. Avbyf~wg‡Ki mv‡_ †Kv‡Y AvbZ GKwU Nl©Ywenxb iv¯Ívq v ‡e‡M PjšÍ m f‡ii GKwU e¯‘i DaŸ©gyLx Z¡iY a m„wó Ki‡Z KZ ¶gZv cÖ‡qvM Ki‡Z n‡e? [Mwb, mykvšÍ] A. ma v sin B. ma v cos C. ma v + mg v sin D. ma v sin F – mgsin = ma F = ma + mgsin P = FV = (ma + mgsin)V = mav + mgvsin 22. m f‡ii GKwU e¯‘ v aªæe †e‡M Ges aªæe ej F Gi weiæ‡× P‡j S `~iZ¡ AwZµg K‡i| GB MwZ‡K a‡i ivL‡Z KZ ¶gZvi cÖ‡qvRb? [Mwb, mykvšÍ] A. mv B. 1 2 mv2 C. 1 2 Fs D. Fv Ans D 23. 100 gm f‡ii GKwU evjwZ Djø¤^ Z‡j 10m e¨vmv‡a©i e„Ëc‡_ Nyi‡Z Nyi‡Z A Ae¯’vb †_‡K B Ae¯’v‡b Avmj (g = 10ms–2 )| kw³ cwieZ©b KZ? [Mwb, mykvšÍ] 10m A B A. 10 Ryj B. 20 Ryj C. 40 Ryj D. 60 Ryj E = mgh = 0.1 10 (10 2) = 20J 24. 10 gm f‡ii GKwU gv‡e©j‡K 5cm myZvq †eu‡a 1 ms–1 mg `ªæwZ‡Z e„ËvKvi c‡_ †Nviv‡Z _vK‡j myZvi Uvb Z_v †K›`ªgyLx ej Øviv KvR n‡e- [‡gvK‡Q` m¨vi] A.0.1 J B.0.98 J C. 0.005 J D. 0 J Ans D
ASPECT PHYSICS cÖ_g cÎ KvR, kw³ I ÿgZv 221 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 25. 50kg f‡ii †evSv gv_vq wb‡q 50 kg f‡ii GK e¨w³ Lvov †`qv‡ji mv‡_ 60° ‡Kv‡Y AvbZ 2m `xN© gB †e‡q wb‡P bvg‡Q| Kv‡Ri cwigvY n‡e- [‡gvK‡Q` m¨vi] A.100 J B.200 J C. 1960 J D.980 J W = mghcos = (50 + 50) 9.8 2 cos60° = 980J 26. GKwU w¯úªs Gi Dci ej cÖ‡qv‡M cÖmvwiZ K‡i †Q‡o w`‡j w¯úªswU Zvi c~e©ve¯’vq wd‡i Avmvi KviY n‡jv- [‡gvK‡Q` m¨vi] A. RoZv B. •iwLK fi‡eM C. MwZkw³ D. w¯’wZkw³ Ans D 27. wbw`©ó ‡e‡M GKwU e¯‘‡K (evZv‡mi evav‡K AMÖvn¨) Lvov Dc‡ii w`‡K wb‡¶c Kiv n‡jv| wb‡Pi ‡Kvb Dw³wU mZ¨ wbY©q K‡iv| [AvRMi m¨vi] A. m‡e©v”P D”PZvq MwZkw³ me©vwaK nq B. w¯’wZkw³ mg‡qi mv‡_ mylgfv‡e e„w× cvq C. mgMÖ MwZc‡_ fi‡eM aªæeK _v‡K D. mgMÖ MwZc‡_ ‡gvU kw³ aªæeK _v‡K Ans D 28. †Kvb `ywU †f±i ivwki WU ¸Ydj wn‡m‡e KvR‡K cÖKvk Kiv nq? [BKivg m¨vi] A. UK© I e¨vmva© †f±i B. ej I Z¡iY C. UK© I †K․wYK †eM D. ej I miY Ans D 29. GKwU PjšÍ e¯‘i †eM wظY n‡j Zvi MwZkw³ cÖv_wgK MwZkw³i KZ¸Y? [BKivg m¨vi] A. 4 ¸Y B. wظY C. AvU ¸Y D. 1 2 ¸Y Ans A 30. f~-c„ô n‡Z GKwU e¯‘‡K Dc‡i †Zvjv n‡j e¯‘i g‡a¨ †Kvbkw³ e„w× cvq- [BKivg m¨vi] A. wefe kw³ B.MwZkw³ C.Zvcxqkw³ D.ivmvqwbK kw³ f~c„ô ‡_‡K GKwU e¯‘‡K Dc‡i †Zvjv n‡j e¯‘i wefe kw³ e„w× cvq Ges MwZkw³ n«vm cvq| STEP 4 MCQ CONCEPT TEST WRITTEN cÖkœ 01. F = (3i ˆ + 2j ˆ – 6k ˆ )N ej cÖ‡qv‡Mi d‡j e‡ji wµqv‡iLv eivei e¯‘i miY 4m n‡j K…ZKvR n‡eA. 4 J B. 8 J C. 12 J D. 28 J 02. 1 m `xN© 1 kg f‡ii GKwU miæ iW‡K †kvqv‡bv †_‡K Lvov Kiv n‡jv| wefe kw³ KZ? A. 4.9 J B. 9.8 J C. 19.6 J D. 20 J 03. 6 kg fi wewkó GKwU w¯’i e¯‘i Dci 30 N ej cÖ‡qvM Kivi 10s ci e¯‘wUi MwZkw³ KZ n‡e? A. 5000 J B. 7500 J C. 8000 J D. 6000 J 04. 1 kg I 3 kg f‡ii `ywU e¯‘i fi‡eM mgvb| e¯‘ `ywUi MwZkw³i AbycvZ n‡eA. 1 : 1 B. 1 : 2 C. 3 : 1 D. 9 : 1 05. 1 cm cyiæ‡Z¡i I 200 gm f‡ii wgUvi †¯‥j‡K Abyf~wgK Ae¯’v †_‡K Lvov Ki‡j wefekw³- A. 19.60 J B. 1.960 J C. 1.940 J D. 0.970 J 06. GKwU wjd‡Ui ¶gZv 25kW, wjdUwU 0.5ms-1 †e‡M DV‡Z _vK‡j Gi †Kej Uvb KZ? A. 1.25 105N B. 5 104N C. 1 104N D. 5 105N 07. 200N ej †Kvb wbw`©ó f‡ii e¯‘i Dci wµqv Kivq e¯‘wU e‡ji w`‡Ki mv‡_ 60 †KvY Drcbœ K‡i 30m `y‡i m‡i †Mj| Kv‡Ri cwigvY KZ? A. 3000W B. 3000J C. 6000J D. 9000J 08. 5kg f‡ii GKwU nvZzwo Øviv †`qv‡j GKwU †c‡iK‡K 2ms–1 ‡e‡M AvNvZ Kivq GwU 10cm Xy‡K †Mj| †`qv‡ji Mo evav n‡eA.125N B. 150N C. 100N D. 250N 09. 16kg Gi GKwU †evgv we‡ùvwiZ n‡q 4kg I 12kg Gi `ywU LÛ nj| 12kg f‡ii †eM 4ms-1 n‡j Ab¨ UzKivwUi MwZ kw³ KZ? A. 96j B. 144j C. 288j D. 192j 10. GKwU Mvwo 10ms–1 MwZ‡Z Pj‡Q| KZ †e‡M Pj‡j MvwowUi MwZkw³ wظY n‡e? A.10m/s B. 40m/s C. 100m/s D. 14.1m/s 11. 40 km/hr †e‡M PjšÍ GKwU Mvwoi MwZkw³ 2105 J| MvwowU 20 km/hr †e‡M Pj‡j Zvi MwZkw³ KZ J n‡e? A. 4 105 B. 6 105 C. 3 105 D. 8 105E. 0.5 105 12. GKwU PjšÍ e¯‘ mgvb f‡ii Aci GwU w¯’i e¯‘‡K AvNvZ K‡i †_‡g ‡Mj| MwZkw³i †h Ask ¯’vbvšÍwiZ n‡eA. 100% B. 50% C. 0% D. 1% 13. 40 m D”PZv †_‡K GKwU e¯‘‡K webv evavq co‡Z w`‡j †Kvb D”PZvq MwZkw³ w¯’wZkw³i wZb¸Y n‡e? A. 10 m B. 13.33 m C. 20 m D. 26.66 m 14. GKwU ivB‡d‡ji ¸wji †eM hw` wظY Kiv nq Zvn‡j Gi MwZkw³ KZ¸Y n‡e? A. 2 ¸Y B. 8 ¸Y C. 4 ¸Y D. 16 ¸Y 15. 5 kg f‡ii GKwU e¯‘i Z¡iY 3 ms–2 n‡j 4s ci e¯‘wUi MwZkw³- A. 3 J B. 5 J C. 15 J D. 36 J E. 360 J 16. GKwU hš¿ 5 †m‡K‡Û 20 Ryj KvR Ki‡Z cv‡i| hš¿wUi ¶gZv KZ? A. 4 IqvU B. 4 wbDUb/ †m‡KÛ C. 4 IqvU/ †m‡KÛ D. 4 wbDUb/wgUvi 17. 60 kg f‡ii R‣bK e¨w³ 20 min G 180 m D”PZvq Av‡ivnY K‡ib| Zvi wefe kw³ KZ Ryj? A. 9.58 104 B. 10.58 104 C. 12.58 104 D. 15.58 104 18. •iwLK fi‡eM 60% evo‡j MwZkw³ e„w× cvqA. 60% B. 125% C. 156% D. 160% 19. 1m DuPz †Uwe‡ji Dci Aew¯’Z 100g f‡ii GKwU eB‡K 10 cm `~‡i miv‡bv n‡j, eBwUi w¯’wZ kw³i cwieZ©b n‡eA. 9.8 J B. 98 J C. 0 J D. †KvbwUB bq 20. GKwU 5 wK‡jvMÖvg mPj e¯‘i mi‡Yi j¤^w`‡K 10 wbDUb I 5 wbDUb gv‡bi `ywU ej e¯‘wUi Dci wecixZ w`‡K wµqv K‡i| ej `ywU Øviv K…Z Kv‡Ri gvb KZ n‡e? A. 50 Ryj B. 25 Ryj C. 0 Ryj D. 15 Ryj OMR SHEET 07. A B C D 14. A B C D 01. A B C D 08. A B C D 15. A B C D 02. A B C D 09. A B C D 16. A B C D 03. A B C D 10. A B C D 17. A B C D 04. A B C D 11. A B C D 18. A B C D 05. A B C D 12. A B C D 19. A B C D 06. A B C D 13. A B C D 20. A B C D WRITTEN PART 21. GKwU B‡j±ª‡bi †eM 106m/sec| Gi MwZkw³ B‡j±ªb- †fvë GK‡K †ei Ki22. 10 †KwR f‡ii GKwU e¯‘ 50 wg. D”PZv n‡Z cwZZ n‡j Gi MwZ kw³ n‡e23. GKwU nvjKv I GKwU fvix e¯‘i fi‡eM mgvb n‡j †KvbwUi MwZkw³ †ewk n‡eÑ e¨vL¨v K‡iv| 24. 4 wU NbvK…wZ cv_i L‡Ûi cÖwZwUi fi 250 kg Ges Gi D”PZv 0.5m| GKwUi Dci GKwU †i‡L ¯Íi cÖ¯‘Z Ki‡Z K…Z Kv‡Ri cwigvY n‡e25. 100m Mfxi Kzqv †_‡K Bwćbi mvnv‡h¨ cÖwZ wgwb‡U 1200kg cvwb D‡Ëvjb Kiv nq| Bwćbi `¶Zv 70% n‡j Gi Ak¦ ¶gZv KZ? 26. hw` GKwU Mvwoi MwZ 2ms–1 e„w× cvq Ges MwZkw³ wظY nq Z‡e Mvwoi cÖK…Z †eM KZ n‡e? 27. †Kv‡bv Kzc †_‡K 20m Dc‡i cvwb †Zvjvi Rb¨ 6kW Gi GKwU cv¤ú e¨envi Kiv n‡”Q| cv‡¤úi `¶Zv 88.2% n‡j cÖwZ wgwb‡U KZ wjUvi cvwb †Zvjv hv‡e? 28. 0.2 Kg IR‡bi GKwU ej 20m D”PZv n‡Z cwZZ nj| Bnv gvwU‡Z covi `iæb 30J kw³ ¶q nj| gvwU‡Z cÖwZNv‡Zi ci Bnv KZ D”PZvq DV‡e? †hLv‡b g = 10m/sec2 | 29. 0.2 kg IR‡bi GKwU ej 20 wgUvi D”PZv n‡Z cwZZ nj| Bnv gvwU‡Z covi `iæY 30J kw³ ¶q nj| gvwU‡Z cÖwZNv‡Zi ci Bnv KZ D”PZvq DV‡e (†hLv‡b g = 10 m/Sec2 ) 30. GKwU •e`y¨wZK gUi 1 wgwbU 40 †m‡KÛ mg‡q 10 wgUvi D”PZvq GKwU fe‡bi Qv‡` 1000 †KwR cvwb DËjb Ki‡Z cv‡i| gUiwUi ÿgZv KZ IqvU? MCQ ANSWER ANALYSIS WRITTEN cÖkœ bs DËi e¨vL¨v 01 D F = 3i ˆ + 2j ˆ – 6k ˆ F = 3 2 + 22 (–6) 2 = 7 W = Fx = (7 × 4) J = 28 J 02 A miæ iW‡K †kvqv‡bv †_‡K Lvov Ki‡j Gi fi‡K›`ª l 2 = 1m 2 = 0.5 m D”PZvq DbœxZ nq| wefekw³, Ep = mgh = 1 × 9.8 × 0.5 = 4.9 J
222 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES cÖkœ bs DËi e¨vL¨v 03 B E = 1 2 mv2 = 1 2 m (0 + at)2 = 1 2 m × F m × t 2 = 1 2 × 6 × 30 6 × 10 2 = 7500 J 04 C P1 = P 2 m1v1 = m1v2 1 × v1 = 3 × v2 v1 = 3v2 ; E1 : E2 = 1 2 m1v 2 1 : 1 2 m2v 2 2 = 1 × (3v2) 2 : 3 × v2 2 = 9v2 2 : 3v2 2 = 3 : 1 05 D fi‡K‡›`ªi cwieZ©b, h = 1m 2 = 0.5 m Ep = mgh = 200 1000 × 9.8 × 0.5 = 0.98 J 06 B P = Fv ev, F = P v = 251000 0.5 = 5104N 07 B w = FS cos = 200×30 cos60° = 3000 J 08 C FS = 1 2 mv 2 ev, F = 1 5 (2) 2 2 (0.10) = 100N 09 C m1v1 = m2v2 ev, v1 = m2 v2 m1 = 12 4 4 Ek1 = 1 2 m1v 2 1 = 1 2 4 (12)2 = 288J 10 D v2 = nv1 ev, v2 = 2 10 = 14.1m/s 11 E MwZkw³, Ek = 1 2 mv2 ; Ek αv2 E2 = V2 V1 2 E1 = 20 40 2 2 105 = 0.5 105 12 A fi‡e‡Mi msi¶Ym~Î Abyhvqx, m1u1 + m2u2 = m1v1+ m2 v2 mu1 + m×0 = m × 0 + mv2 u1 = v2 MwZkw³, Ek = 1 2 mv2 ; Ek αv2 ¯’vbvšÍwiZ MwZkw³ 100% 13 A x = h n + 1 = 40 3 + 1 = 10m 14 C MwZkw³, Ek = 1 2 mv2 ; Ek αv2 E2 = V2 V1 2 E1 = (2)2 E1 = 4 E1 15 E 4s ci e¯‘wUi ‡eM, v = at = 3 × 4 = 12 ms–1 ; 4s ci e¯‘wUi MwZkw³, E = 1 2 mv2 = 1 2 5 (12)2 = 360 J 16 A ¶gZv, P = w t = 20 5 = 4 Watt 17 B wefe kw³, U = mgh = 60 9.8 180 = 10.58 104 J 18 C E = P 2 2m [GKwU KYv nIqvi Kvi‡Y Zvi fi w¯’i] E P 2 E2 = P2 P1 2 E1 = 1.62 E1 = 2.56E1 MwZkw³ e„w×, ΔE = 2.56–1=1.56 × 100% = 156% 19 C w¯’wZkw³, U = mgh w¯’wZkw³i cwieZ©b, U = mg(h2 – h1) = mg 0 = 0 20 C ej Øviv KvR, W = F. s = Fs cos; = 90˚ n‡j cos = 0 W = 0 21 2 k mv 2 1 E = 9.1 10 (10 ) eV 2.845eV 2 1.6 10 1 31 6 2 19 22 e¯‘ f~wg ¯úk© Kivi wVK c~e© g~û‡Z© e¯‘i mg¯Í wefe kw³B MwZkw³‡Z iƒcvšÍwiZ nq| E mgh 10 9.8 50J k =4900×107 erg 4.9 10 erg 10 ;1J=107 erg 23 g‡b Kwi, `ywU e¯‘i fi m1 I m2 (m2 > m1) Ges MwZ‡eM v1 I v2| G‡`i fi‡eM mgvb n‡j, m1v1 = m2v2 ev, v2 v1 = m1 m2 G‡`i MwZkw³i AbycvZ = Ek1 Ek2 = 1 2 m1v1 2 1 2 m2v2 2 = m1 m2 m2 m1 2 = m2 m1 m2 > m1 Ek1 > Ek2 A_©vr nvjKv e¯‘i MwZkw³ †ewk| 24 W = mg (0 + .5 + 1 + 1.5) = 7350J 25 ASPECT SPECIAL: P = t x% mgh /746 26 E2 E1 = v2 2 v1 2 E1 E2 = v1 2 v2 2 E1 2E1 = 2 2 v2 2 v2 = 4 2 = 2 2 cÖK…Z †eM, v = 2 + 2 2 = 2( 2 + 1) ms1 27 t x% mgh P gh P t x% m 9 8 20 6000 60 0 882 . . . L 3 1 6210 28 m~Îvbymv‡i, (mgh – 30) = mgh h = 0.2 × 10 × 20 – 30 0.2 × 10 = 5m 29 E = mgh = 0.21020 = 40J GLv‡b, 40 – 30 = 10 J Now, 10 = mgh h = 10 0.210 = 5m 30 p = mgh t = 1000 9.8 10 100 = 980
ASPECT PHYSICS cÖ_g cÎ gnvKl© I AwfKl© 223 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES SURVEY TABLE Kx coe? †Kb coe? †Kv_v n‡Z coe? KZUzKz coe? TOPICS MAGNETIC DECISION [hv co‡e] MAKING DECISION [†h Kvi‡Y co‡e] VVI For This Year DU JU RU CU GST Engr. HSC Written MCQ THEORY CONCEPT-01 D‡jøL‡hvM¨ weÁvbxMY I Zv‡`i Avwe®‹vimg~n 10% 05% 10% 05% 30% - 10% - CONCEPT-02 ¸iæZ¡c~Y© m~Îvejx 35% 10% 15% 10% 10% - 40% - CONCEPT-03 G msµvšÍ Z_¨vejx 45% 15% 10% 15% 15% - 45% - CONCEPT-04 g msµvšÍ Z_¨vejx 15% 30% 20% 15% 30% 40% 25% - CONCEPT-05 gnvKl©xq †ÿÎ msµvšÍ 20% 10% 15% 10% 15% 30% 65% - CONCEPT-06 gyw³‡eM msµvšÍ Z_¨vejx 65% 20% 15% 20% 35% 35% 65% CONCEPT-07 K…wÎg DcMÖn msµvšÍ Z_¨vejx 55% 30% 30% 40% 45% 60% 60% - - MvwYwZK cÖ‡qvM CONCEPT-01 gnvKl©xq ej msµvšÍ MvwYwZK cÖ‡qvM 65% 55% 60% 65% 55% 70% 75% CONCEPT-02 g Gi gvb msµvšÍ MvwYwZK cÖ‡qvM 50% 65% 50% 55% 65% 30% 80% CONCEPT-03 f~-c„ô n‡Z h D”PZv msµvšÍ MvwYwZK cÖ‡qvM 55% 70% 75% 80% 75% 75% 85% CONCEPT-04 f~-c„ô n‡Z d MfxiZv msµvšÍ MvwYwZK cÖ‡qvM 65% 65% 70% 75% 70% 30% 40% - CONCEPT-05 wewfbœ MÖ‡n g Gi gv‡bi Zzjbv msµvšÍ MvwYwZK cÖ‡qvM 70% 75% 70% 75% 80% 65% 45% - CONCEPT-06 wewfbœ MÖ‡n IR‡bi Zyjbv msµvšÍ MvwYwZK cÖ‡qvM 60% 63% 60% 65% 65% 75% 40% - CONCEPT-07 mylg NbZ¡ msµvšÍ MvwYwZK cÖ‡qvM 55% 60% 65% 70% 60% 65% 50% - CONCEPT-08 gnvKl©xq cÖvej¨, gnvKl©xq wefe msµvšÍ 60% 55% 70% 65% 75% 35% 60% - CONCEPT-09 gyw³‡eM msµvšÍ MvwYwZK cÖ‡qvM 75% 70% 80% 70% 65% 45% 80% - CONCEPT-10 K…wÎg DcMÖ‡ni †eM I Zv‡`i ch©vqKvj msµvšÍ MvwYwZK cÖ‡qvM 60% 65% 60% 55% 70% 45% 70% CONCEPT-11 †Kcjv‡ii m~Î msµvšÍ MvwYwZK cÖ‡qvM 70% 60% 55% 60% 55% 40% 75% - - CONCEPT-12 Acm~i I Abym~i msµvšÍ MvwYwZK cÖ‡qvM 40% 30% 35% 20% 30% 20% 30% DU. = Dhaka University, JU. = Jahangirnagar University, RU. = Rajshahi University, CU = Chittagong University, GST = General, Science & Technology, Engr. = Engineering. STEP 1 mvRv‡bv me Z_¨ THEORY fwZ© †ivMxi c_¨ Concept 1 D‡jøL‡hvM¨ weÁvbxMY I Zv‡`i Avwe®‹vimg~n bvg mvj Avwe®‹vi AvBR¨vK wbDUb 1687 (BmnvK); 1685 - (wMqvm DwÏb) gnvKl© m~Î ‡Rvnvb †Kcjvi (†WbgvK©) 1618 (BmnvK); 1609 - (cÖvgvwbK) ‡Kcjv‡ii m~Î ivwkqvb weÁvbxiv 1957 gnvKv‡k cÖ_g ¯úyUwbK-1 †cÖiY K‡ib K¨v‡fwÛm 1798 ‘G’ Gi gvb wbY©q UvB‡Kv eªv‡n g½j MÖ‡ni MwZ wewa j¶ K‡i MÖn b¶Î m¤ú‡K© Z_¨ msMÖn Kiv Av‡gwiKvb weÁvbxiv 1958 gnvKv‡k G·‡cøvivi-1 †cÖiY K‡ib gnvKl© ej Zwor ej Zwor †PŠ¤^Kxq ej F = Gm1m2 d 2 F = 1 40k q1q2 d 2 - `ywU e¯‘i g‡a¨ wµqv K‡i `ywU Pv‡R©i g‡a¨ wµqv K‡i MwZkxj Pv‡R©i g‡a¨ wµqv K‡i gva¨‡g cÖK…wZi Dci wbf©ikxj bq gva¨‡g cÖK…wZi Dci wbf©ikxj gva¨‡g cÖK…wZi Dci wbf©ikxj me©`v AvKl©Yag©x AvKl©Yag©x/ weKl©Yag©x AvKl©Yag©x/ weKl©Yag©x gnvKl© I AwfKl© GRAVITATION AND GRAVITY cÖ_g cÎ 06 Aa¨vq c„ôv 223
224 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ✅ wewfbœ ¸iæZ¡c~Y© aªæe ivwki gvb, GKK I gvÎv: bvg cÖKvk gvb GKK gvÎv gnvKl©xq aªæeK G 6.6710-11 Nm2 kg-2 M–1T –2L 3 AwfKl©R Z¡iY (Av`k©) g 9.80665 ms-2 LT–2 c„w_exi fi M 5.981024 kg M c„w_exi e¨vmva© R 6.36106 m L gnvKl©xq †¶Î cÖvej¨ E Nkg-1 LT–2 gnvKl©xq wefe V Jkg-1 L 2T –2 c„w_exi NbZ¡ 5.5103 kgm-3 ML–3 gyw³‡eM Veev VE 11.2 7 25000 kms-1 miles-1 mileh-1 LT–1 REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. r `~i‡Z¡ ivLv `ywU ¶z`ª KYvi g‡a¨ ci¯úi ga¨vKlx©q AvKl©Y ej F, KYv `yBwUi gvSLv‡b GKwU fvix †jvnvi cvZ ivLv n‡j GLb Zv‡`i g‡a¨ ci¯úi AvKl©Y ej KZ? [DU. 13-14] A. 0 B. F C. F/2 D. F/4 gnvwe‡k¦i †h †Kvb `ywU e¯‘KYv ci¯úi‡K AvKl©Y K‡i| AvKl©Y ej, F = G 2 1 2 r m m | gnvKlx©q aªæeK gva¨‡gi Dci wbf©i K‡i bv| AvKl©Y ej cwiewZ©Z nq bv| 02. ‡KvbwU me©v‡c¶v `ye©j ej? [DU. 03-04; BRU. 12-13, 14-15] A. gravitational force B. electromagnetic force C. strong nuclear force D. weak nuclear force Ans A 03. Mv‡Qi GKwU Av‡cj c„w_ex‡K f e‡j AvKl©Y Ki‡Q| c„w_ex Av‡cj‡K F e‡j AvKl©Y K‡i| myZivs- [DU. 02-03; JnU. 14-15, BRU. 13-14] A.F >>f B. F> f C. F = f D. f < F Ans C STEP 02 ANALYSIS OF JU QUESTION 01. ‡Kvb ejwUi cvjøv Amxg bq? [JU. 14-15] A. ZvwoZ †PŠ¤^Kej B. mej wbDK¬xq ej C. gnvKl© ej D. †KvbwUB bq Ans B 02. evB‡ii Drm Øviv gnvKl©xq e‡ji wecix‡Z KvR- [JU. 12-13] A. Positive B. Negative C. Infinity D. Zero Ans B STEP 03 ANALYSIS OF RU QUESTION 01. cÖwZwU MÖ‡ni AveZ©bKv‡ji eM© m~h© †_‡K Zvi Mo `~i‡Z¡i Nbd‡ji mgvbycvwZK- GwU †Kvb m~Î: [RU. 17-18; HSTU. 17-18] A. wbDU‡bi 1g m~Î B. Av‡cwÿKZvi 1Ôg ¯^xKvh© C. †Kcjv‡ii 3q m~Î D. †Kcjv‡ii 1g m~Î Ans C STEP 04 ANALYSIS OF CU QUESTION 01. wbDUbx ev wPivqZ ejwe`¨vi ‡gŠwjK ivwk bq ‡KvbwU? [CU. 15-16] A. ¯’vb B. mgq ev Kvj C. ‡eM ev `ªæwZ D. fi Ans C 02. c„w_exi Mo e¨vmva© cÖvq- [CU. 14-15, RU. 13-14] A. 3.67106 m B. 6.37106 m C. 7.36106 m D. 3.0108 m E. 9.1108 m Ans B STEP 05 ANALYSIS OF GST QUESTION PART A Analysis of General University Question IU 01. e¯‘i fi aªæe nq hLb e¯‘i †eM- [IU. 13-14] A. k~b¨ B. Av‡jvi †e‡Mi KvQvKwQ C. MwZkxj D. †KvbwUB bq Ans A PART B Analysis of Science & Technology Question SUST 01. M f‡ii GKwU wjdU mg‡e‡M h D”PZv AwZµg Ki‡Q, wjdwUi Dci †gvU †h KvR Kiv n‡q‡Q Zv- [SUST. 02-03] A. abvZ¥K B. FYvZ¥K C. mgh D. k~b¨ ej cÖ‡qv‡Mi w`‡Ki wecixZ w`‡K miY n‡j FYvZ¥K KvR nq| GLv‡b wjd‡Ui Dc‡i miY nq Ges AwfKl©R ej wb‡Pi w`‡K wµqv K‡i| ZvB KvR FYvZ¥K| MBSTU 01. bÿ‡Îi †ÿ‡Î M¨vm I †gNcyÄ RgvU euva‡Z ïiæ K‡i Kxfv‡e? [MBSTU. 16-17] A. AvšÍ:AvYweK AvK©l‡Yi Uv‡b B. AvYweK AvKl©‡Yi Uv‡b C. gnvK‡l©i Uv‡b D. AwfK‡l©i Uv‡b cigvYyi g‡a¨ †Kv‡bv •e`y¨wZK AvKl©Y ev weKl©Y †bB| G‡`i g‡a¨ GKgvÎ wµqvkxj ej nj gnvKl© ej| GB gnvKl© e‡ji cÖfv‡e M¨vm I †gNcyÄ RgvU euva‡Z ïiæ K‡i| 02. `ywU e¯‘i g‡a¨ †h `~iZ¡ Av‡Q Zv A‡a©‡K †b‡g Avm‡j gnvKl© ej- [MBSTU. 15-16] A. wظY K‡g B. wظY ev‡o C. Pvi¸Y ev‡o D. Pvi¸Y K‡g F 1 d 2 BSMRMU 01. GKK f‡ii `ywU e¯‘KYv GKK `~iZ¡ †_‡K †h ej ci¯ú‡ii AvKl©Y K‡i Zv‡K Kx ejv nq? [BSMRMU. 2020-21] A. Unit force B. One Newton Force C. Gravitational force D. Gravitational acceleration S A info F = GMm R 2 ; M= m = 1 GKK; R = 1 GKK n‡j, F = G, hv GKK ej (unit force)| BSMRSTU 01. w¯’i Zwor ej Ges gnvKl© e‡ji Zzjbvi †ÿ‡Î wb‡Pi †KvbwU wg_¨v? [BSMRSTU-H, 19-20] A. `ywU ejB e¯‘ `ywUi ga¨eZ©x `~i‡Z¡i e‡M©i mgvbycvwZK B. `ywU ejB msiÿYkxj ej C. `ywU ejB k~b¨¯’v‡b KvR K‡i D. `ywU ejB †K›`ªxq ej F 1 r 2 A_©vr ej e¯‘؇qi ga¨eZx© `~i‡Z¡i e‡M©i e¨v¯ÍvbycvwZK| 02. GKwU DcMÖn c„w_ex‡K †K›`ª K‡i e„ËvKvi c‡_ Nyi‡Q Zvn‡j Gi Dci ejwµqv- [BSMRSTU: 14-15] A. k~b¨ B. DcMÖ‡ni Zvr¶wYK †e‡Mi mgvšÍivj C. DcMÖ‡ni Zvr¶wYK †e‡Mi j¤^ eivei D. ‡KvbwUB bq Ans A
ASPECT PHYSICS cÖ_g cÎ gnvKl© I AwfKl© 225 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES HSTU 01. wb‡Pi ‡Kvb ejwU wecixZ eM©xq ej? [HSTU. 14-15] A. wbEwK¬q ej B. `~e©j ej C. gnvKl© ej D. j‡iÄ ej Ans C PSTU 01. gnvKl© m~Î e¨envi K‡i wb‡gœi †Kvb KvRwU m¤¢e bq? [PSTU. 15-16] A. K…wÎg DcMÖ‡ni gva¨‡g †hvMv‡hvM B. cÖvK…wZK M¨vm D‡Ëvjb C. Kqjv D‡Ëvjb D. cvigvYweK †evgv •Zwi Ans D STEP 06 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. MÖn ¸wji MwZc_ Dce„ËvKvi ZË¡wU †K Avwe®‹vi K‡ib? [MAT; 19-20] A. †Kcjvi B. U‡jwg C. wc_v‡Mvivm D. M¨vwjwjI S A info weÁvbx Ae`vb U‡jwg me©cÖ_g f~-‡Kw›`ªK ZË¡ Dc¯’vcb K‡ib| wc_v‡Mvivm R¨vwgwZK Dccv‡`¨i m~Î cÖ`vb| M¨vwjwjI cošÍ e¯‘i m~Î, †hŠwMK AYyexÿY hš¿, `~iexÿY hš¿, cvwb D‡Ëvj‡bi hš¿, evqy _v‡g©v‡¯‹vc cÖf…wZ| 02. `yBwU e¯‘i g‡a¨ `~iZ¡ Pvi¸Y e„w× †c‡j AwfKl© ej n‡e- [MAT. 15-16] A. Pvifv‡Mi GK fvM B. †lvj¸Y C. Pvi¸Y D. ‡lvjfv‡Mi GK fvM Ans D 03. `ywU mvwe©Kfv‡e GKB iƒc gnvk~b¨ hvb A I B gy³fv‡e c„w_exi w`‡K bvg‡Q| B Gi †P‡q A c„w_exi Kv‡Q n‡j †Kvb Z_¨wU mwVK bq- [MAT. 08-09] A. A Gi IRb > B Gi IRb B. A Gi fi =B Gi fi C. A Gi Z¡iY = B Gi Z¡iY D. Dfq gnvk~b¨hv‡bi b‡fvPvixMY IRbnxbZv Abyfe K‡i Ans C 04. wb‡Pi D‡jøwLZ †Kvb ej B‡jKUªb‡K wbDwK¬qv‡mi m‡½ Ave× K‡i cigvYy •Zix K‡i? [MAT. 07-08] A. gnvKl© ej B. †PŠ¤^K ej C. mej wbDwK¬q ej D. `~e©j wbDwK¬q ej Ans C 05. gnvKl© (Gravitation) ej wbf©i K‡i- [MAT. 05-06] A. e¯‘؇qi gva¨‡gi cÖK„wZ B. e¯‘i ؇qi f‡ii Dci C. e¯‘؇qi AwfgyL D. e¯‘؇qi AvK…wZ Ans B Concept 2 ¸iæZ¡c~Y© m~Îvejx ✅ cošÍ e¯‘i †¶‡Î M¨vwjwjI m~Î: 1589 mv‡j weÁvbx M¨vwjwjI GB m~Î cÖ`vb K‡ib| 1650 mv‡j weÁvbx wbDUb m~θ‡jvi cix¶vg~jK cÖgvY †`b| weÁvbx wbDUb wMwb I cvjK cix¶vi gva¨‡g 1g m~Î cÖgvY K‡ib| ✅ cošÍ e¯‘i m~Îmg~n: cÖ_g m~Î: evqyk~b¨ ¯’v‡b w¯’i Ae¯’vb †_‡K mKj cošÍ e¯‘ mgvb mg‡q mgvb `~iZ¡ AwZµg Ki‡e| wØZxq m~Î : w¯’i Ae¯’v †_‡K gy³fv‡e/webv euvavq cošÍ e¯‘ wbw`©ó mg‡q †h †eM cÖvß nq Zv D³ mg‡qi mgvbycvwZK| A_©vr t †m‡K‡Û v †eM cÖvß n‡j v t v1 t1 = v2 t2 = ......... = k Z…Zxq m~Î: gy³fv‡e cošÍ e¯‘i wbw`©ó mg‡q AwZµvšÍ `~iZ¡ D³ mg‡qi e‡M©i mgvbycvwZK| A_©vr t †m‡K‡Û h `~iZ¡ AwZµg Ki‡j h t 2 h1 h2 = t1 2 t2 2 = ......... = k Note: gy³fv‡e (i) cošÍ e¯‘ n‡Z n‡j Aek¨B Avw`‡eM k~b¨ n‡Z n‡e| (ii) evqy k~b¨ gva¨g n‡Z n‡e| wbDU‡bi gnvKl© m~Î m¤úwK©Z K‡qKwU ¸iæZ¡c~Y© Z_¨: ✅ 1687 mv‡j wbDUb m~ÎwU cÖgvb K‡ib| ✅ m~‡Îi MvwYwZK iƒc F = Gm1m2 d 2 ✅ GB ej AvKl©Y ag©x| ✅ G ej wecixZ eM©xq m~Î †g‡b P‡j (welg eM©xq)| ✅ e¨_©Zv: GB ej AvšÍ: AvYweK ej wbiƒcY Ki‡Z cv‡i bv| ✅ wbf©iZv: gnvKl© ej wbf©i K‡i e¯‘؇qi fi I ga¨eZ©x `~i‡Z¡i Dci| wbf©i K‡i bv e¯‘؇qi ga¨eZ©x gva¨‡gi Dci| ✅ gnvKl© e‡ji gvb c`v‡_©i AvK…wZ, cÖK…wZ, AwfgyL ev G‡`i ga¨eZ©x gva¨‡gi Dci wbf©i K‡i bv| ✅ gnvKl© m~‡Îi e¨envi: cÖvK…wZK m¤ú‡`i AbymÜvb Kqjv D‡Ëvjb gvwUi A‡bK Mfxi ‡_‡K cvwb DVv‡bv cÖvK…wZK M¨vm D‡Ëvjb wewfbœ iKg LwbR c`v_© D‡Ëvjb f~-Mf©¯’ Zvc NwUZ kw³ D‡Ëvjb ✅ e¯‘ M‡elYv weÁv‡bi bvbv M‡elYvq gnvKl© m~Î e¨envi Kiv nq gnv‡`kxq Zi½ M‡elYv wewfbœ MÖ‡ni MwZ m¤úwK©Z M‡elYv K…ò MnŸi M‡elYv †iwWI eY©vjx M‡elYv gnvKvk M‡elYv AvKvk ‡_‡K bx‡P bvg‡Z c¨vivmyU e¨envi K…wÎg DcMÖn ¯’vc‡b ✅ fvix e¯‘i †P‡q nvjKv e¯‘‡Z cøeZv ev DaŸ©gyLx ej †ekx nIqvq Zv †`wi‡Z gvwU‡Z †cŠQvq| ✅ cÖ‡qvRbxq Z_¨vejx: ◈ weÁvbx U‡jwgi g‡Z, c„w_ex †mŠiRM‡Zi ‡K›`ª Ges m~h©, Mªn, DcMÖn mK‡jB c„w_ex‡K †K›`ª K‡i wewfbœ RwUj K¶c‡_ AveZ©b Ki‡Q| ◈ weÁvbx †Kvcvwb©Kvm m~h©‡K w¯’i a‡i c„w_ex Zvi Pviw`‡K AveZ©b K‡i GK_v e‡jb| ◈ †R¨vwZwe©` UvB‡Kveªv‡n g½j M«‡ni MwZwewa j¶¨ K‡i wKQz Z_¨ msMÖn K‡ib| ◈ UvB‡Kveªv‡ni M‡elYvjä djvd‡ji mnvqZvq Ges Ab¨vb¨ ch©‡e¶‡Yi mvnv‡h¨ 1609 mv‡j †Wbgv‡K©i †R¨vwZwe©` †Kcjvi wZbwU m~Î cÖ`vb K‡ib| ◈ ‡Kcjv‡ii m~Î mg~n: Rvg©vb ‡R¨vwZwe©` †Rvnvbm †Kcjvi (1571 – 1630) m~‡h©i Pvwi w`‡K MÖnvbycy‡Äi MwZ welqK wZbwU m~Î wjwce× K‡ib| ◈ Dce„ËvKvi m~Î ev K‡ÿi m~Î (cÖ_g m~Î): m~h©‡K GKwU ‡dvKv‡m ‡i‡L cÖ‡Z¨KwU MÖn Dce„ËvKvi c‡_ Nyi‡Q| ◈ ‡¶Îd‡ji m~Î (wØZxq m~Î): cÖ‡Z¨KwU MÖn Ggb fv‡e Nyi‡Q ‡h, m~h© I MÖ‡ni †K‡›`ªi ms‡hvRK KvíwbK †iLv mgvb mg‡q mgvb †¶Îdj AwZµg K‡i|
226 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ◈ mg‡qi m~Î (Z…Zxq m~Î): m~‡h©i Pviw`‡K cÖwZwU MÖ‡ni AveZ©b Kv‡ji eM© Zv‡`i Mo `~i‡Z¡i Nb d‡ji mgvbycvwZK| T 2 a 3 or, T2 (2a)3 [2a = civÿ] T 2 8a3 ◈ †Kcjv‡ii m~Î g‡b ivLvi †KŠkj: EAT E A T Ellipse law (Dce„‡Ëi m~Î) Area Law (‡ÿÎd‡ji m~Î) Time Law (mg‡qi m~Î) ✅ †Kcjv‡ii m~Î we‡køl‡Y wbgœwjwLZ welq¸wj j¶Yxq- MÖ‡ni AveZ©bKvj Gi f‡ii Dci wbf©i K‡i bv| m~h© †_‡K MÖ‡ni Mo `~iZ¡ hZ Kg nq A_©vr MÖn m~‡h©i hZ wbK‡U _v‡K Gi AveZ©bKvj ZZ Kg nq| ✅ wbDU‡bi m~Î n‡Z †Kcjv‡ii m~Î cÖwZcv`b Kiv hvq| REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. gnvKl© aªæeK G Gi gvÎv- [DU. 17-18; 05-06, RU. 13-14] A. M -1L 3T –2 B. ML2T 2 C. ML2T -3 D. M -1L 3T 2 Ans A STEP 02 ANALYSIS OF JU QUESTION 01. †Kcjv‡ii AveZ©bKv‡ji m~ÎwU wb¤œiƒc- [JU. 12-13; OI: 16-17; MBSTU. 17-18; 16-17; RU. 17-18; JnU. 12-13] A. T R B. T R 3/2 C.T 3 R 2 D.†KvbwUB bq †Kcjv‡ii MÖn m¤úwK©Z wZbwU MwZ m~Î wb‡¤œ Av‡jvPbv Kiv n‡jv1. Dce„Ë m~Î (Law of ellipse): cÖwZwU MÖn m~h©‡K Dce„‡Ëi bvwf‡Z ev †dvKv‡m †i‡L GKwU Dce„ËvKvi c‡_ cÖ`wÿY Ki‡Q| 2. †ÿÎd‡ji m~Î (Law of area) : MÖn Ges m~‡h©i ms‡hvMKvix e¨vmva© †iLv mgvb mg‡q mgvb †ÿÎdj AwZµg K‡i| 3. mg‡qi m~Î (Law of time): cÖwZwU MÖ‡ni ch©vqKv‡ji eM© m~h© n‡Z Zvi Mo `~i‡Z¡i Nbd‡ji mgvbycvwZK| T 2 R 3 ev, T R 3/2 STEP 03 ANALYSIS OF RU QUESTION 01. DcMÖn gnvk~‡b¨ †Kvb bxwZ †g‡b P‡j? [RU. 10-11] A. wbDU‡bi Z…Zxq m~Î B. AwfKl© m~Î C. ‡Kcjv‡ii m~Î D. ‡KvbwUB bq Ans C STEP 04 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. gnvKl©xq aªæeK (Gravitational constant) ‘G’ Gi S.I GKK- [JnU. 14-15; MBSTU. 14-15] A. Nm2Kg-2 B. m-3Kg-1 S -1 C. m-3Kg S-2 D. Nm2Kg-1 Ans A KU 01. c„w_exi NbZ¡Ñ [KU. 14-15; JU. 17-18] A. 5.5 × 103 kg m -3 B. 5.96 × 1024 kg m-3 C. 6.673 × 10-11 kg m-3 D. ‡KvbwUB bq Ans A 02. †Kcjv‡ii m~θwj wb‡Pi †KvbwUi e¨vL¨v| [KU. 01-12] A. MÖn m¤úwK©Z MwZm~Î B. Av‡jvi †eM C. gnvKl©xq wefe D. gyw³‡eM Ans A IU 01. cÖwZwU MÖnB m~h©‡K GKwU †dvKvm †i‡L Dce„ËvKvi c‡_ Ny‡i GwU- [IU. 12-13] A. wbDU‡bi m~Î B. Wcjv‡ii m~Î C. M¨vwjwjIi m~Î D. †Kcjv‡ii m~Î Ans D JKKNIU 01. †Kcjv‡ii mg‡qi m~Î wb‡Pi †KvbwU? [JKKNIU-B, Set-3, 19-20] A. T r 3 B. T r 2 C. T2 r 3 D. T3 r 2 †Kcjv‡ii Z…Zxq m~Î ev mg‡qi m~ÎwU n‡jv- m~‡h©i Pviw`‡K cÖwZwU MÖ‡ni AveZ©b Kv‡ji eM© Zv‡`i Mo `~i‡Z¡i Nbd‡ji mgvbycvwZK| T 2 R 3 PART B Analysis of Science & Technology Question SUST 01. †Kcjv‡ii wØZxq m~Î †Kvb †fŠZ ivwki wbZ¨Zv m~Î †_‡K cÖgvY Kiv hvq? [SUST. 18-19] A. •iwLK fi‡eM B. kw³ C. †KŠwYK fi‡eM D. MwZkw³ E. hvwš¿Kkw³ Ans C PUST 01. m~‡h©i Pviw`‡K AveZ©biZ g½jMÖ‡ni Kÿc‡_i e¨vmva© c„w_exi Kÿc‡_i e¨vmv‡a©i 1.53 ¸Y| c„w_ex‡Z 365 w`‡b GK eQi n‡j g½jMÖ‡n KZ w`‡b GK eQi n‡e? [PUST-A, 19-20] A. 365 B. 665 C. 391 D. 691 †Kcjv‡ii Z…Zxq m~Îvbymv‡i, Tm Te 2 = Rm Re 3 Tm Te = 1.53 1 3 2 ev, Tm = (1.53) 3 2 365 = 690.76 691 day STEP 05 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. cÖwZwU MÖ‡ni chv©qKv‡ji eM© m~h© n‡Z Mo `~i‡Z¡i Nbd‡ji mgvbycvwZK| wb‡Pi †Kvb weÁvbx m~ÎwUi cÖe³v? [MAT. 13-14] A. U‡jgx B. ‡Kvcvwb©Kvm C. UvB‡Kv eªv‡n D. †Kcjvi Ans D DAT 01. hw` m~h© †_‡K c„w_exi Mo `~iZ¡ n«vm cvq Z‡e eQ‡ii •`N©¨? [DAT. 2020-21; JKKNIU-B, Set-3, 19-20] A. n«vm cv‡e B. Amxg n‡e C. e„w× cv‡e D. w¯’i _vK‡e S A info cÖwZwU MÖ‡ni ch©vqKv‡ji eM© m~h© †_‡K Gi `~i‡Z¡i Nbd‡ji mgvbycvwZK| T 2 r 3 ZvB `~iZ¡ Kg‡j eQ‡ii •`N©¨ n«vm cv‡e| 02. ÒcÖwZwU MÖnB m~h©‡K GKwU †dvKv‡m (Focus) †i‡L Dce„ËvKvi c‡_ Ny‡iÓGB m~ÎwU †KvbwU weÁvbxi? [DAT. 2020-21] A. RR© †jgvBUvi B. †Rvnvb †Kcjvi C. GWDBb nvej D. M¨vwjwjI S B info cÖwZwU MÖnB m~h©‡K GKwU †dvKv‡m †i‡L Dce„ËKvi Kÿc‡_ Ny‡i GB m~ÎwU weÁvbx †Rvnvb †Kcjvi Gi| 03. †Kvb e¯‘‡K ‡hfv‡eB ivLv †nvK bv †Kb Zvi IRb GKwU we›`yi ga¨ w`‡q e¯‘i Dci me©`v wµqv K‡i| GB we›`y‡K e‡j- [DAT. 16-17] A. Awf‡K›`ª B. fi‡K›`ª C. gnvKlx©q aªæeK D. AwfKl©R Z¡iY Ans B STEP 06 ANALYSIS OF HSC BOARD QUESTION 01. c„w_exi AvKvi nVvr †QvU n‡q Gi e¨vmva© c~‡e©i A‡a©K n‡j AwfKl©R Z¡i‡Yi gv‡bi cwieZ©b n‡e| cwiewZ©Z gvb c~e©gv‡bi KZ¸b n‡e? [iv.‡ev. 2019] A. 2 ¸b B. 4 ¸b C. 6 ¸b D. 8 ¸b S B info g = Gm R 2 g 1 R 2 g1 g2 = R 2 2 R 2 1 g2 = R1 R2 2 × g1 = R R 2 2 × g1 = 4 × g1
ASPECT PHYSICS cÖ_g cÎ gnvKl© I AwfKl© 227 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 3 G-msµvšÍ Z_¨vejx ✅ G-Gi cÖ‡qvM: (i) c„w_exi fi wbY©‡q; (ii) m~‡h©i fi wbY©‡q; (iii) c„w_exi Dcv`v‡bi Mo NbZ¡ wbY©q ; (v) MÖ‡ni ch©vqKvj I P‡µi e¨vmv‡a©i g‡a¨ m¤úK© ¯’vc‡b ✅ gnvKlx©q aªæeK wbY©‡qi c×wZ: (i) cvnvo I Lwb c×wZ (ii) cix¶vMvi c×wZ (iii) K¨v‡fwÛ‡mi c×wZ| ✅ G wbY©q c×wZ g‡b ivLvi welq: C-GPA CG P A K¨v‡fwÛ‡mi c×wZ cvnvo I Lwb c×wZ, cixÿvMv‡ii c×wZ ✅ msL¨vMZ gvb: c„w_exi fi 61024kg c„w_exi e¨vmva© 6.4106m c„w_exi NbZ¡ 5.5103 kg/m3 m~‡h©i fi 21030kg c„w_exi ‡K›`ª ‡_‡K m~‡h©i `~iZ¡ ev K¶c‡_i e¨vmva© = 1.5×1011m or 15 Crore km ✅ gnvKlx©q wefe: Amxg `~iZ¡ n‡Z GKK f‡ii †Kvb e¯‘‡K gnvKlx©q †¶‡Îi †Kvb we›`y‡Z Avb‡Z †h wbw`©ó KvR mvwaZ nq Zv‡K H we›`yi gnvKlx©q wefe e‡j| G‡K FYvZ¥K ivwk Øviv cÖKvk Kiv nq|GwU GKwU †¯‹jvi ivwk, Gi m‡e©v”P gvb n‡e Amx‡g Ges GB gvb n‡e (k~b¨)|c„w_ex ev P‡›`ªi Pviw`‡K AveZ©b Kv‡j cÖwZwµqv ej k~b¨ nIqvq gnvKvk hvÎx †Kvb IRb Abyfe K‡ib bv| ✅ GKwU fvix e¯‘ n‡Z Amxg `~i‡Z¡ Aew¯’Z †Kvb we›`y‡Z gnvKlx©q wefe Ges gnvKlx©q cÖvej¨ Df‡qi gvb k~b¨| ✅ gnvKlx©q aªæeK wbf©i K‡i bv- (i) cÖ‡ek¨Zv (ii) cÖeYZv (iii) w`K `wk©Zv (iv) †fŠZ Ae¯’v (v) gva¨g| ✅ †MvjvKvi †Kvb †Lvj‡Ki wfZ‡i gnvKl© ej k~b¨| REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF JU QUESTION 01. wb‡Pi †KvbwU mZ¨ bq? [JU-H, Set-A. 20-21] A. G Gi gvb e¯‘i f‡ii Dci wbf©i K‡i bv B. G Gi gvb f‚‡K›`ª †_‡K e¯‘i `~i‡Z¡i Dci wbf©i K‡i bv C. G Gi gvb 6.657×10–13 Nm2 kg–2 D. meKwU mZ¨ S C info G Gi gvb 6.657×10–11Nm2 kg–2 Ges gvÎv : L 3M –1T –2 STEP 02 ANALYSIS OF CU QUESTION 01. wb‡Pi †KvbwU mwVK? [CU. 15-16] A. g GKwU †¯‹jvi ivwk B. G GKwU †f±i ivwk C. G Ges g Df‡qi gvb mgvb D. G Gi gvb e¯‘i f‡ii Dci wbf©i K‡i bv E. G Ges g Df‡qB mve©Rbxb aªæeK Ans D STEP 03 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. GKK f‡ii `ywU e¯‘ KYv GKK `~i‡Z¡ †h ej Øviv ci¯úi‡K AvKl©Y K‡i †mwU n‡jv- [MAT. 16-17] A. AwfKl©R Z¡iY B. gnvKl©xq aªæeK C. GKK ej D. cøv‡¼i aªæeK Ans B 02. gnvKl©xq aªæeK G Gi gvb †KvbwU? [MAT. 05-06; DAT. 17-18; Kz. †ev. 2017; mKj †evW© 2018] A. 6.7610-11Nm2 kg-2 B. 6.6710-9Nm2 kg-2 C. 6.6710-11Nm2 kg-2 D. 6.7610-11Nm2 kg-2 Ans C STEP 04 ANALYSIS OF HSC BOARD QUESTION 01. gnvKlx©q aªæeK G-Gi †ÿ‡Î cÖ‡hvR¨- [Xv. †ev. 2015] A. Bnv gva¨‡gi cÖK…wZi Dci wbf©i K‡i B. G-Gi gvb e¯‘i f‡ii Ici wbf©i K‡i bv C. G-GKwU †¯‹jvi ivwk D. B I C DfqB Ans D 02. gnvKlx©q aªyeK ÔGÕ Gi †ÿ‡Î cÖ‡hvR¨Ñ [Xv. †ev. 2015] i. Bnv gva¨‡gi cÖK…wZi Dci wbf©i K‡i ii. G GKwU †¯‹jvi ivwk iii. G-Gi gvb e¯Íyi f‡ii Dci wbf©i K‡i wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans Blank 03. gnvKlx©q aªæe‡Ki gvÎv †KvbwU? [iv.‡ev. 2019; Kz. †ev. 2017; mKj †evW© 2014] A. M–1L 3T –2 B. M–1L 3T –1 C. M–1L 2T –2 D. M–1L 2T –1 Ans A 04. wek^Rbxb gnvKlx©q aªæe‡Ki- [wm. †ev. 2016] A. gvÎv [L3M –1T –2 ] B. gvb g Øviv cÖfvweZ nq C. GKK Nm2 kg–2 D. A I C DfqB Ans D 05. `ywU e¯‘i wµqvkxj gnvKl© e‡ji †ÿ‡Î gnvKlx©q aªæeK- [gv. †ev. 2017] A. ¯’vb‡f‡` cwieZ©bkxj B. fiwbi‡cÿ C. `~i‡Z¡i Dci wbf©ikxj D. GwU GKwU †f±i ivwk Ans B Concept 4 g-msµvšÍ Z_¨vejx ✅ mgxKiY : g = GM R 2 ◈ mgxKiY n‡Z eySv hvq, MÖ‡ni AwfKl©R Z¡iY wbf©i K‡i H MÖ‡ni fi I e¨vmv‡a©i Dci| ◈ •ewkó¨: ÔgÕ AvKwl©Z e¯‘i cÖK…wZi Dci wbf©i K‡i bv| ¯’vb †f‡` Gi gvb cwiewZ©Z nq| A_©vr e¯‘ wbi‡c¶ n‡jI ¯’vb wbi‡c¶ bq| Ô g Õ Gi GKK I gvÎv mvaviY Z¡i‡Yi Abyiƒc| gvÎv [LT-2 ] GKK ms-2 AwfKl©R Z¡ib AwfKl©xq cÖve‡j¨i mgvb welyexq AÂj R †ewk, g Kg †giæ AÂj R Kg, g †ewk
228 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ✅ g Gi ZviZg¨ : ◈ wb‡¤§v³ wZbwU Kvi‡Y g Gi gv‡bi cwieZ©b N‡U| D”PZvi wµqv A¶vsk wµqv ev c„w_exi AvK…wZi Rb¨ c„w_exi N~Y©b wµqv ev AvwýK MwZi Rb¨ ◈ g Gi ZviZg¨ ev cwieZ©‡bi KviY g‡b ivLvi †KŠkj: AuvwL GKUv D”P gv‡bi cvMjx| AuvwL GKUv D”Pgv‡bi cvMjx Aÿvsk wµqv D”PZvi wµqv c„w_exi MwZ ✅ c„w_exi wewfbœ A‡j g Gi gvb: AÂj gvb AÂj gvb †giæ AÂj 9.83217 ms-2 45 Aÿvs‡k 9.80665 ms–2 / 9.81 ms–2 welyexq AÂj 9.78039 ms-2 g½j MÖ‡n 3.8ms–2 µvšÍxq AÂj 9.78918 ms-2 e„n¯úwZ MÖ‡n 25.92ms–2 XvKvq 9.7835 ms-2 Puv‡` 1.95ms–2 ivRkvnx‡Z 9.790 ms–2 ✅ g Gi Zvrch©: (i) g Gi gvb 9.81 ms–2 Øviv gy³fv‡e cošÍ e¯‘i †eM cÖwZ †m‡K‡Û 9.81 ms–1 nv‡i ev‡o eySvq| (ii) 1kg f‡ii e¯‘i IRb 9.81 N| ✅ g Gi gvb m¤úwK©Z Av‡iv ¸iæZ¡c~Y© Z_¨: f~-c„‡ô g Gi gvb me‡P‡q †ekx Ges f~‡K‡›`ª g Gi gvb k~b¨| ‡giæ A‡j g Gi gvb †ekx e‡j e¯‘i IRbI †ekx| welye A‡j g Gi gvb Kg e‡j e¯‘i IRbI Kg| f~c„ô n‡Z Dc‡ii w`‡K †M‡j g Gi gvb Kg‡Z _v‡K Ges f~Af¨šÍi w`‡K AMÖmi n‡jI g Gi gvb Kg‡Z _v‡K| A¶vsk e„w× †c‡j g Gi gvb e„w× cvq A¶vsk n«vm †c‡j g Gi gvb n«vm cvq| ◈ P‡›`ª g Gi gvb f~c„‡ôi g Gi gv‡bi 1 6 Ask| m~‡h© 27 ¸Y| ✅ ¸iæZ¡cyY© Z_¨vejx: c„w_exi N~Y©b wµqvq m„ó †K›`ªgyLx ej cÖkwgZ Kivq †giæ A‡j g Gi gvb Aí K‡g (†giæ‡Z N~Y©b wµqv †bB) Ges welyexq A‡j †ekx K‡g| mgy`ª c„‡ô Ges 45° A¶vs‡k g Gi gvb‡K Av`k© aiv nq| Av`k© gvb 9.81ms-2 . ÕgÔ Gi gvb †_‡K c„w_exi Mo Nb‡Z¡i avibv cvIqv hvq| c„w_exi †K‡›`ª hw` †Kvb e¯‘ wb‡q hvIqv nq Zvn‡j e¯‘i Dci c„w_exi †Kvb AvKl©b _v‡K bv| g½j MÖ‡ni AwfKl©R Z¡i‡bi gvb 3.8ms-2 . gnvKlx©q aªæeK (G) AwfKlx©q Z¡iY (g) gvÎv [L 3M –1T –2 ] gvÎv [LT–2 ] ‡¯‹jvi ivwk ‡f±i ivwk Gi gvb e¯‘i f‡ii Dci/f~‡K›`ª n‡Z e¯‘i `~i‡Z¡i Dci wbf©i K‡i bv e¯‘i f‡ii Dci wbf©i K‡i bv wKš‘ f~‡K›`ª n‡Z e¯‘i `~i‡Z¡i Dci wbf©i K‡i ✅ AwfKl©R †K›`ª ev fvi‡K›`ª: †h we›`y‡Z e¯‘i mg¯Í fi †K›`ªxf~Z g‡b Kiv nq| fi‡K‡›`ª ej cÖ‡qv‡M e¯‘ ïaygvÎ •iwLK MwZ cÖvß nq| †Kvb cÖKvi e„Ëxq ev †KŠwYK MwZ cÖvß nq bv| mvaviYZ fi‡K›`ª I fvi‡K›`ª Awfbœ| †¶Î we‡k‡l AwfKl© †K›`ª e¯‘i evB‡iI _vK‡Z cv‡i| ✅ cÖ‡qvRbxq e¯‘i fvi‡K›`ª: cÖ‡qvRbxq e¯‘ fvi‡K‡›`ªi Ae¯’vb mylg e„Ë, AvswU, dvcv ev wb‡iU †MvjK R¨vwgwZK †K›`ª mylg mvgvšÍwiK ev AvqZ †¶Î KY©Ø‡qi †Q`we›`y mylg wÎfyRvK…wZi cvZ ga¨gv·qi †Q`we›`y mylg `Û ga¨we›`y mylg wmwjÛvi ev †ejbvK„wZi `Û ev †PvO A‡¶i ga¨we›`y bgbxq KwVb c`v_© wbw`©ó †Kvb fvi †K›`ª †bB ✅ IRbnxbZv, c„w_ex cÖ`w¶Y Kv‡j b‡fvPvix IRbnxbZv Abyfe K‡i; cvwbfwZ© evjwZi Djø¤^ Z‡j N~Y©biZ Ae¯’vq cvwbi †Kvb IRb _v‡K bv Ges cvwb c‡o hvq bv|
ASPECT PHYSICS cÖ_g cÎ gnvKl© I AwfKl© 229 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. AwfKl©xq Z¡iY g ebvg c„w_ex c„ô n‡Z MfxiZv h Gi †jLwPÎ †KvbwU? [DU. 20-21] A. g h B. g h C. g h D. g h S A info c„w_exi c„ô n‡Z hZ Mfx‡i hvIqv hvq g Gi gvb µgk K‡g Ges c„w_exi c„ô n‡Z hZ Dc‡i hvIqv hvq g Gi gvb µgk K‡g, Z‡e Dc‡i Kgvi nvi †ewk| f‚c„ô †_‡K h MfxiZvq AwfKl©R Z¡iY, g = g 1 – h R = g – gh R g = – g R h + g y m x c 02. c„w_exi N~Y©b nVvr †_‡g †M‡j †giæwe›`y‡Z e¯‘mg~‡ni fi n‡e- [DU. 05-06; KU. 11-12] A. less B. greater C. the same as before D. vary with latitude Ans C 03. evqy‡Z GK ev· Zyjvi IRb Ges 4wU †jvnvi e‡ji IRb cÖwZ †¶‡Î wVK 1Kg- †`Lv †M‡j- [DU. 03-04; KU. 10-11] A. Zzjvi fi I †jvnvi ej¸‡jvi fi mgvb B. Zzjvi fi †ekx C. Zzjvi fi Kg D. f‡ii Zzjbv e‡ji msL¨vi Dci wbf©i Ki‡e Ans A 04. Kg †_‡K †ewk AwfKl©xq Z¡iY g Abymv‡i mvRvI| (XvKv = D, ‡ivg = R DËi †giæ = N, welye‡iLv‡Z GKwU RvnvR E) [DU. 00-01] A. DENR B. EDRN C. RNED D. DREN welyexq A‡j g Gi gvb me‡P‡q Kg| welye †iLv n‡Z hZ †giæ A‡ji w`‡K hvIqv hvq g Gi gvb ZZ evo‡Z _v‡K| g Gi gvb Kg †_‡K †ekx EDRN| STEP 02 ANALYSIS OF JU QUESTION 01. welyexq AÂj n‡Z †giy A‡ji w`‡K AwfKl©xq Z¡iY- [JU. 18-19] A. n«vmcvq B. e„w× cvq C. GKB n‡e D. 45 Aÿvs‡k m‡e©v”P Ans B 02. ‡giæ‡Z g Gi gvb 9.83ms-2 n‡j welyexq A‡j n‡e- [JU. 13-14] A. 9.78 ms-2 B. 9.88 ms-2 C. 9.98 ms-2 D. 9.89 ms-2 Ans A STEP 03 ANALYSIS OF RU QUESTION 01. †gvU fi AcwiewZ©Z †i‡L c„w_exi e¨vmva© eZ©gvb e¨mv‡a©i GK-Z…Zxqvsk n‡q †M‡j f~-c„‡ôi AwfKl©R Z¡i‡Yi gvbÑ [RU. Astrazeneca, Set-1. 20-21] A. cwieZ©b n‡e bv B. eZ©gvb AwfKl©R Z¡i‡Yi GK-Z…Zxqvsk n‡e C. eZ©gvb AwfKl©R Z¡i‡Yi wZb¸b n‡e D. eZ©gvb AwfKl©R Z¡i‡Yi bq¸b n‡e S D info g2 g1 = GM R2 2 R1 2 GM = R1 2 R1 3 2 = 9 g2 = 9g1 [cÖkœg‡Z cwiewZ©Z e¨vmva© = eZ©gvb e¨vmv‡a©i GKZ…Zxqvsk] 02. †Kvb MÖvdwU f~-c„ô †_‡K c„w_exi †K‡›`ªi w`‡K wewfbœ MfxiZv d Gi Rb¨ AwfKl©R Z¡iY g Gi gvb wb‡`©k K‡i? [RU. Sinovac, Set-1. 20-21] A. g d B. g d C. g d D. g d S C info f‚c„ô †_‡K hZB c„w_exi †K‡›`ªi w`‡K hvIqv hvq ZZB AwfKl©R Z¡i‡Yi gvb n«vm †c‡Z _v‡K| A_©vr MfxiZv hZ e„w× cvq ZZB g Gi gvb Kg‡Z _v‡K| 03. KZ Aÿvsk g-Gi gvb me©v‡cÿv †ewk? [RU-C, Set-3. 19-20] A. 0 B. 45 C. 90 D. 180 c„w_exi AvwýK MwZi Rb¨, g = g – 2R cos2 ; = Aÿvsk| myZivs, Aÿvsk = 90 n‡j, g = g, hv m‡e©v”P| 04. GKwU K…wÎg DcMÖn c„w_exi c„ô †_‡K c„w_exi e¨vmv‡a©i wظY D”PZvq Ny‡i| H D”PZvq Gi MwZ‡eM KZ? [RU-C, Set-1. 19-20] A. gR B. 2 gR C. gR 3 D. gR 5 Avgiv Rvwb K…wÎg DcMÖ‡ni †eM, V = gR2 R + h = gR2 R + 2R = gR 3 05. AwfKl©R Z¡iY g-Gi mgxKiY nj- [RU. 17-18 ; SUST. 06-07] A. g = GM R B. g = GM R 2 C. g = GM R 3 D. g = GM2 R 2 Ans B 06. c„w_exi AvwýK MwZi Rb¨ AwfKl©R Z¡iY welyexq AÂj †_‡K †giæ A‡ji w`‡K- [RU. 13-14] A. n«vm cvq B. e„w× cvq C. mgvb _v‡K D. †KvbwUB bq Ans B 07. AwfKl©R Z¡iY g Gi †¶‡Î wb‡Pi †KvbwU mwVK? [RU. 13-14] A. D”PZvi Dci wbf©ikxj B. A¶vs‡ki Dci wbf©ikxj bq C. c„w_exi N~Y©b MwZi Dci wbf©ikxj bq D. mve©Rbxb aªæeK E. me¸‡jvB mwVK Ans A 08. c„w_exi †K‡›`ª †Kvb e¯‘i IRb –––| [RU. 13-14; CU. 13-14] A. k~b¨ B. Amxg C. c„w_ex c„‡ô e¯‘wUi IR‡bi mgvb D. c„w_ex c„‡ô e¯‘wUi IR‡bi †P‡q †ewk E. Dc‡ii me¸‡jvB fyj Ans A 09. ‡`vjK Lwbi wfZi wb‡j ev cvnv‡oi Dci wb‡j- [RU. 11-12] A. ‡`vjK `ªæZ Pj‡e B. ‡Kvb cwieZ©b n‡e bv C. ax‡i Pj‡e D. ‡KvbwUB bq Ans C 10. f‚-c„‡ô g-Gi gvb P›`ª c„‡ôi g-Gi gv‡bi KZ ¸Y? [RU. 06-07] A. GK B. wZb C. cuvP D. ‡KvbwUB bv Ans D STEP 04 ANALYSIS OF CU QUESTION 01. c„w_exc„‡ô †Kvb e¯‘i fi 1kg n‡j c„w_exi †K‡›`ª Gi fi KZ? [CU-A, Set-3. 20-21] A. 0kg B. 1 kg C. 9.81kg D. S B info gnvwe‡k¦i †h‡Kv‡bv RvqMvq fi cwieZ©b nq bv| me RvqMvq fi GKB _v‡K Z‡e AwfKl©R Z¡i‡Yi ZviZ‡g¨i Rb¨ IRb wfbœ nq| 02. wb‡¤œi †KvbwU c„w_exi f‡ii mwVK m~Î? [CU. 15-16;MBSTU. 19-20] A. 2 2 G gR M B. g GR M 2 C. G gR M 2 D. G g R M 2 E. 2 g GR M 2 R GM g ev, G gR M 2 03. ‘g’ Gi gvb me©vwaK †Kv_vq? [CU. 13-14] A. †giæ A‡j B. welyexq A‡j C. P›`ªc„‡ô D. f~-‡K‡›`ª E. f~-c„ô n‡Z Dc‡i Ans A STEP 05 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. c„w_ex c„ô n‡Z h Mfx‡i g Gi gvb- [JnU. 11-12] A. gh = g ( ) 1 2h R B. gh = g ( ) 1 + 2h R C. gh = g ( ) 1 h R D. gh = g ( ) 1 + h R Ans C
230 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 02. g Gi gvb me©vwaK †Kvb GjvKvq? [JnU. 12-13] A. f~-†K‡›`ª B. welye GjvKvq C. †giæ A‡j D. f~-c„‡ô n‡Z A‡bK Dc‡i Ans C 03. ‡Kvb fi‡K GKwU wbw`©ó D”PZv †_‡K †Q‡o w`‡j †Kvb ivwkwU aªæe _vK‡e?[JnU. 04-05] A. †eM B. Z¡iY C. miY D. fi‡eM Ans B KU 01. c„w_ex cÖ`w¶Y Kivi mgq GKRb b‡fvPvix IRbnxbZv Abyfe K‡ib KviY- [KU. 12-13] A. G‡¶‡Î †K›`ªgyLx ej k~b¨ B. G‡¶‡Î †K›`ªwegyLx ej k~b¨ C. G‡¶‡Î †K›`ªgyLx Ges †K›`ª wegyLx ej mgvb D. G‡¶‡Î †K›`ªgyLx e‡ji †P‡q †K›`ªwegyLx ej eo Ans C CoU 01. wb‡Pi †KvbwU mZ¨ bq- [CoU. 16-17] A. c„w_exi evwl©K MwZi Rb¨ g-Gi gv‡bi cwieZ©b nq B. c„w_exi AvwýK MwZi Rb¨ g-Gi gv‡bi cwieZ©b nq C. Aÿvsk cwieZ©‡b g-Gi gv‡bi cwieZ©b nq D. D”PZvi Kvi‡Y g-Gi gv‡bi cwieZ©b nq g-Gi gv‡bi ZviZg¨: g aªæe msL¨v bq| wb‡¤œv³ 3wU Kvi‡Y g-Gi gv‡bi cwieZ©b N‡U| (i) D”PZvi wµqv; (ii) Aÿvsk wµqv ev c„w_exi AvK…wZi Rb¨; (iii) c„w_exi N~Y©b ev AvwýK MwZi Rb¨ IU 01. AwfKl©R Z¡iY ‘g’ Gi gvb me‡P‡q Kg- [IU. 15-16] A. f~-c„‡ó B. †giæ‡Z C. f~-‡K‡›`ª D. welyex‡q Ans C 02. g-Gi gvb‡K cÖvgvb¨ wn‡m‡e aiv nq- [IU. 14 -15] A. welyexq A‡ji g- Gi gvb‡K B. †giæ A‡ji g- Gi gvb‡K C. 45 A¶vs‡k mgy`ªc„‡ó g- Gi gvb‡K D. 90 A¶vs‡k mgy`ªc„‡ô g- Gi gvb‡K Ans C 03. N~Y©‡bi Rb¨ welye GjvKvq AwfKl©xq Z¡iY KZ Kg n‡eÑ [IU. 14-15] A. 0.033 ms-2 B. 0.034 ms-2 C. 0.035 ms-2 D. 0.036 ms-2 Ans B BRUR 01. c„w_ex c„‡ôi GKwU †m‡KÛ †`vjK‡K c„w_exi Pviw`‡K cwiågYiZ GKwU gnvKvkhv‡b †bqv n‡j, Gi ch©vqKvj n‡e- [BRU. 12-13] A. 2s B. 4s C. 1s D. Amxg Ans D BU 01. c„w_exi AwfKl©R Z¡i‡Yi gvb wb‡Pi †KvbwUi Dci wbf©ikxj bq? [BU. 14-15] A. c„w_exi AvwýK MwZ B. c„w_exi evwl©K MwZ C. D”PZv D. AvKvi Ans B 02. wb‡Pi †Kvb A‡j AwfKl©R Z¡i‡Yi gvb me‡P‡q Kg? [BU. 13-14] A. welyexq AÂj B. f~-c„ô †_‡K 5km wfZ‡i C. f~-c„ô †_‡K 5km Dc‡i D. mgy`ª c„ôZ‡j Ans A PART B Analysis of Science & Technology Question SUST 01. f~-c„‡ô †Kvb e¯‘i fi 1 kg c„w_exi †K‡›`ª Bnvi fi KZ? [SUST. 14-15; IU. 15-16] A. 0 kg B. 9.87 kg C. 1 kg D. †KvbwU bq c„w_exi †K‡›`ª fi 1 †KwR n‡e| KviY fi AcwieZ©bkxj| 02. c„w_exi †K‡›`ª gnvKlx©q Z¡iY KZ? [SUST. 05-06, CU. 14-15] A. k~b¨ B. Amxg C. c„w_ex c„‡ôi mgvb D. †KvbwU bq Ans A JUST 01. wb‡Pi †Kvb †`‡k AwfKl©R Z¡i‡Yi gvb A‡c¶vK…Z ‡ewk? [JUST. 14-15] A. KvbvWv B. evsjv‡`k C. BKz‡qWi D. †Kwbqv E. eªvwRj Ans A BSMRSTU 01. c„w_exi fi P‡›`ªi f‡ii 80 ¸Y Ges Zv‡`i e¨vmva© h_vµ‡g 12800 km I 3200 km| P›`ªc„‡ôi AwfKl©R Z¡i‡Yi gvb KZ? [BSMRSTU-H, 19-20] A. 163 cm/s2 B. 1.7 m/s 2 C. 197 cm/s2 D. 168 m/s2 g = (e¨vmv‡a©i ¸Y) 2 f‡ii ¸Y g = 4 2 80 g = 197 cm/s2 c„w_exi wewfbœ A‡j g Gi gvb: AÂj gvb AÂj gvb †giæ AÂj 9.83217 ms-2 45 Aÿvs‡k 9.80665 ms–2 / 9.81 ms–2 welyexq AÂj 9.78039 ms-2 g½j MÖ‡n 3.8ms–2 µvšÍxq AÂj 9.78918 ms-2 e„n¯úwZ MÖ‡n 25.92ms–2 XvKvq 9.7835 ms-2 Puv‡` 1.95ms–2 ivRkvnx‡Z 9.790 ms–2 HSTU 01. welye A‡j GKwU e¯‘i IRb wKiƒc n‡e? [HSTU. 14-15] A. evo‡e B. Kg‡e C. AcwiewZ©Z _vK‡e D. DËi ‡bB Ans B DU Technology 01. c„w_exi e¨vmva© nVvr GK-Z…Zxqvsk n‡q †M‡jv, wKš‘ f‡ii †Kvb cwieZ©b n‡jv bv| AwfKl©R Z¡iY KZ ¸Y n‡e? [DU-Tech.19-20] A. wظY B. Pvi¸Y C. cuvP¸Y D. bq¸Y g = Gm R 2 g 1 R 2 g2 = 1 1 3 2 g1 = 9g1 STEP 06 ANALYSIS OF ENGINEERING & BUTex QUESTION BUET 01. Puv‡`i evqyk~b¨ ¯’v‡b w¯’ive¯’v †_‡K GKwU cvjK I GKwU mxmvi ej †djv nj| cvj‡Ki Z¡iY n‡e- [BUET: 12-13] A. mxmvi e‡ji †P‡q †ekx B. mxmvi e‡ji mgvb C. mxmvi e‡ji †P‡q Kg D. 9.8ms-2 Ans B STEP 07 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. c„w_exi †Kvb Aÿvs‡ki AwfKl©R Z¡i‡Yi gvb‡K Av`k©gvb aiv nq? [MAT. 17-18 ] A. 55 Aÿvs‡k B. 23 Aÿvs‡k C. 90 Aÿvs‡k D. 45 Aÿvs‡k Ans D 02. AwfKlR Z¡iY ‘g’ Gi †ejvq mwVK bv †KvbwU? [MAT. 13-14] A. c„w_exi †K‡›`ª ‘g’ Gi gvb k~b¨ B. welyexq A‡j ‘g’ Gi gvb 9.78ms–2 C. A¶vsk evov‡j‘g’ ev‡o D. †giæ A‡j ‘g’ Gi gvb me‡P‡q Kg Ans D 03. wb‡Pi †Kvb RvqMvq 1kg wPwb µq Kiv jvfRbK- [MAT. 96-97] A. welye †iLvq B. 450N A¶vs‡k C. †giæ‡Z D. 450 S A¶vs‡k Ans A DAT 01. †Kvb Aÿvs‡k ÔwRÕ (g) Gi gvb me©vwaK? [DAT. 2020-21] A. 90 B. 180 C. 0 D. 45 S A info c„w_exi evB‡i AwfKl©R Z¡iY c„w_exi †K›`ª †_‡K `~i‡Z¡i e‡M©i e¨¯ÍvbycvwZK| AwfKl©R Z¡iY c„w_ex Avi c„w_exi †fZ‡i †K›`ª †_‡K `~i‡Z¡i mgvbycvwZK 90 Aÿvsk g Gi gvb m‡e©v”P| AÂj gvb †giæ AÂj 9.83217 ms-2 welyexq AÂj 9.78039 ms-2 µvšÍxq AÂj 9.78918 ms-2 XvKvq 9.7835 ms-2 ivRkvnx‡Z 9.790 ms–2 45 Aÿvs‡k 9.80665 ms–2 / 9.81 ms–2 g½j MÖ‡n 3.8ms–2 e„n¯úwZ MÖ‡n 25.92ms–2 Puv‡` 1.95ms–2 f~-†K‡›`ª 0 ms–2
ASPECT PHYSICS cÖ_g cÎ gnvKl© I AwfKl© 231 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 02. wb‡Pi †Kvb Z_¨wU mwVK? [DAT. 18-19] A. wbi¶xq A‡j g Gi gvb me©vwaK B. †giæ A‡j g Gi gvb me©wb¤œ C. wbi¶xq A‡j g Gi gvb me©wb¤œ D. c„w_exi Af¨šÍ‡i bvg‡j g Gi gvb ev‡o Ans C 03. ‡Kvb e¯‘i fi f~-c„‡ô 75 kg n‡j Puv‡` Gi fi KZ? [DAT. 18-19] A. 75 kg B. 70 kg C. 280 kg D. 14 kg Ans A STEP 08 ANALYSIS OF HSC BOARD QUESTION 01. c„w_exi fi M Ges e¨vmva© R n‡j c„w_exc„‡ô g G Gi AbycvZ n‡eÑ [Xv.†ev. 2019] A. MR2 B. R M C. M R 2 D. M 2 R S C info g = GM R 2 g G = M R 2 02. AwfKl©R Z¡iY g ebvg c„w_ex c„ô n‡Z MfxiZv h Gi †jLwPÎ †KvbwU? [Xv. †ev. 2017; P. †ev. 2015] A. g R B. g R C. g R D. g R Ans A 03. AwfKl©R Z¡iY-g Gi cwieZ©b KvibÑ [iv.‡ev. 2019] i. c„w_exi AvKvi ii. AvwýK MwZ iii. evwl©K MwZ wb‡Pi †KvbwU mwVKÑ A. i I ii B. ii I iii C. i I iii D. i,iiIiii Ans A 04. c„w_exi e¨vmva© n«vm †c‡j g-Gi gvbÑ [iv. †ev. 2019; w`. †ev. 2015] A. n«vm cv‡e B. e„w× cv‡e C. AcwiewZ©Z _vK‡e D. k~b¨ n‡e Ans B 05. c„w_exi N~Y©b bv _vK‡j c„w_ex c„‡ôi †Kv‡bv ¯’v‡b e¯‘i IRbÑ [P. †ev. 2017] A. e„w× cv‡e B. k~b¨ n‡e C. Amxg n‡e D. AcwiewZ©Z _vK‡e Ans A 06. †`vjK Nwo‡K cvnv‡oi P~ovq wb‡q †M‡j hv N‡U Zv n‡jv, NwowU [P. †ev. 2016] i. mgq jvf Ki‡e ii. mgq nviv‡e iii. ax‡i Pj‡e wb‡Pi †KvbwU mwVK? A. ii B. iii C. ii I iii D. i, ii I iii Ans C 07. c„w_exi N~Y©b eÜ n‡j welye †iLvi g Gi gvbÑ [w`. †ev. 2017] A. e„w× cv‡e B. n«vm cv‡e C. GKB _vK‡e D. k~b¨ n‡e Ans A 08. g-Gi gvb me©vwaK †Kv_vq? [w`. †ev. 2015] A. †giæ B. welye C. f~-‡K‡›`ª D. cvnv‡oi P~ovq Ans A 09. AwfKl©R Z¡i‡Yi gv‡bi cwieZ©b N‡U- [h.‡ev. 2017] A. D”PZvi Rb¨ B. c„w_exi Kÿc‡_ N~Y©‡bi Rb¨ C. c„w_exi wbR A‡ÿ N~Y©‡bi Rb¨ D. me¸‡jvB Ans D 10. KZ Aÿvs‡k g Gi gvb me©v‡cÿv †ewk? [h. †ev. 2015] A. 0 B. 45 C. 90 D. 180 Ans C 11. c„w_exi AveZ©b eÜ n‡q †M‡j †giæ A‡j ‘g’ Gi wKiƒc cwieZ©b n‡e? [gv. †ev. 2008] A. e„w× cv‡e B. k~b¨ n‡e C. AcwiewZ©Z _vK‡e D. K‡g hv‡e Ans C 12. Abyf~wgK eivei AwfKl©R Z¡i‡Yi gvb KZ? [gv. †ev. 2018] A. k~b¨ B. 9.8 ms –2 C. –9.8 ms–2 D. Amxg Ans A 13. c„w_exi †K›`ª n‡Z †Kv‡bv we›`yi `~iZ¡ r n‡j (r < R) AwfKl©R Z¡iY (g) - Gi gvb wb‡Pi †Kvb m¤úK©wU mwVK? (R = c„w_exi e¨vmva©) [mKj †evW© 2014] A. g 1 r B. g 1 r 2 C. g r D. g r 2 Ans A Concept 5 gnvKl©xq †ÿÎ msµvšÍ ✅ gnvKlx©q †ÿÎ : †Kv‡bv e¯‘i Av‡kcv‡k †h AÂje¨vcx Gi gnvKlx©q cÖfve eRvq _v‡K, A_©vr Ab¨ †Kv‡bv e¯‘ ivLv n‡j †mwU AvKl©Y ej jvf K‡i, Zv‡K H e¯‘i gnvKlx©q †ÿÎ e‡j| ◈ •ewkó¨: gnvKlx©q †ÿÎ gnvKlx©q ej mÂvjb cÖwµqvq ga¨¯’Zvi f~wgKv cvjb K‡i| ZvwË¡Kfv‡e GKwU e¯‘i gnvKlx©q †ÿÎ Amxg ch©šÍ we¯Í…Z| cÖK…Zc‡ÿ gnvKlx©q †ÿÎ Amxg ch©šÍ we¯Í…Z| †Kv‡bv e¯‘i gnvKlx©q †ÿ‡Îi me©Î Gi cÖfve mgvb _v‡K bv| ✅ gnvKlx©q †ÿÎ cÖvej¨ ev gnvKlx©q ZxeªZv : gnvKlx©q †ÿ‡Îi †Kv‡bv we›`y‡Z GKK f‡ii GKwU e¯‘ ¯’vcb Ki‡j Zvi Dci †h gnvKlx©q ej cÖhy³ nq Zv‡K H we›`yi gnvKlx©q †ÿÎ cÖvej¨ e‡j| mgxKiY : EG = F m F = mEG GKK : N kg–1 gvÎv : [EG] = MLT–2 M = LT–2 ivwk : †f±i ivwk| AwfKl©R Z¡i‡Yi mv‡_ m¤úK© : c„w_exi †ÿ‡Î †Kvb we›`yi gnvKlx©q †ÿÎ cÖve‡j¨i gvb Avi H we›`yi AwfKl©R Z¡iY g-Gi gvb GKB| we›`y f‡ii Rb¨ cÖvej¨ : we›`y f‡ii cÖvej¨, E = GM r 2 | ✅ gnvKlx©q wefe : Amxg `~iZ¡ †_‡K GKK f‡ii †Kv‡bv e¯‘‡K gnvKlx©q †ÿ‡Îi †Kv‡bv we›`y‡Z Avb‡Z m¤úbœ Kv‡Ri cwigvY‡K H we›`yi gnvKlx©q wefe e‡j| mgxKiY : V = W m GKK : Jkg–1 gvÎv : [V] = L2T –2 ivwk : †¯‹jvi •ewkó¨ : K…ZKvR FYvZ¥K e‡j gnvKlx©q wefe me©`v FYvZ¥K| `ywU e¯‘i g‡a¨ AvKl©Y ej KvR K‡i _v‡K| evB‡ii †Kv‡bv ej ev kw³i cÖ‡qvRb nq bv| Amx‡g gnvKlx©q wefe k~b¨ aiv nq| Amx‡g Gi m‡e©v”P gvb k~b¨| `~iZ¡ e„w× ‡c‡j gnvKl© wefe e„w× cvq| gnvKlx©q cÖvej¨ n‡”Q gnvKlx©q wef‡ei FYvZ¥K †MÖwW‡q›U, E = V.
232 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ◈ †Mvj‡Ki †fZ‡i cÖvej¨ k~b¨| wKš‘ †Mvj‡Ki †fZ‡i wefe w¯’i| ◈ we›`y f‡ii gnvKlx©q wefe : mgxKiY, V = – GM r FYwPý GB A_© cÖKvk K‡i †h, evwn¨K †Kvb ej ev kw³ Øviv KvR m¤úbœ nqwb| gnvKlx©q ejB KvR m¤úbœ K‡i‡Q| cÖ‡qvRbxq Z_¨: (1) `~iZ¡ e„w× †c‡j gnvKl© wefe e„w× cvq| (2) Amx‡g †Kv‡bv e¯‘i gnvKlx©q wefe m‡e©v”P nq Ges Amx‡g Gi m‡e©v”P gvb n‡”Q k~b¨| ✅ wefe cv_©K¨ : GKK f‡ii †Kv‡bv e¯‘i gnvKlx©q †ÿ‡Îi GK we›`y n‡Z Ab¨ we›`y‡Z Avb‡Z †h cwigvY KvR mvwaZ nq| ◈ gvb : AvKl©Y e‡ji Awfgy‡L miY n‡j wefe cv_©K¨ FYvZ¥K n‡e| AvKl©Y e‡ji weiæ‡× miY n‡j wefe cv_©K¨ abvZ¥K n‡e| gnvKlx©q wefe gva¨‡gi cÖK…wZi Dci wbf©i K‡i bv| wKš‘ Ab¨ wefe¸‡jv gva¨‡gi cÖK…wZi Dci wbf©i K‡i| gnvKl©xq cÖvej¨ Zwor cÖvej¨ gnvKlx©q †ÿ‡Îi †Kv‡bv we›`y‡Z GKK f‡ii GKwU e¯‘ ¯’vcb Ki‡j Zvi Dci †h gnvKlx©q ej cÖhy³ nq Zv‡K H we›`yi gnvKlx©q †ÿÎ cÖvej¨ e‡j| Zwor †ÿ‡Îi †Kv‡bv we›`y‡Z GKK Avavb ¯’vcb Ki‡j Zvi Dci †h ej cÖhy³ nq Zv‡K H we›`yi Zwor cÖvej¨ e‡j| gnvKl©xq cÖvej¨, E = F m Zwor cÖvej¨, E = F q0 GwU GKwU †f±i ivwk GwU GKwU †f±i ivwk GKK: Nkg–1 GKK: NC–1 REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF JU QUESTION 01. c„w_ex‡Z gnvKl© e‡ji Aw¯ÍZ¡ cixÿvMv‡i- [JU-A, Set-D. 19-20] A. Dcw¯’wZ aiv c‡o‡Q B. aiv cov cÖvq wbKUeZx© C. gnvKl© e‡ji Aw¯ÍZ¡ cÖgvY m¤¢ bq D. †KvbwUB bq Dcw¯’wZ aiv c‡o‡Q Ges MÖvwfUb KYvi wewbg‡q Zv m¤úbœ nq| 02. gnvKl©xq wefe- [JU. 16-17] A. GKwU †¯‹jvi ivwk B. GKwU †f±i ivwk C. Gi GKK Ryj/wK‡jvMÖvg2 D. †KvbwUB bq mKj cªKvi wefe †¯‹jvi ivwk| STEP 02 ANALYSIS OF CU QUESTION 01. gnvKl©xq †ÿÎ cÖve‡j¨i gvÎv †KvbwU? [CU-A, Set-1. 20-21] A. MLT–2 B. LT–2 C. MLT–1 D. LT–1 S B info gnvKlx©q †ÿÎ cÖve‡j¨i gvÎv LT–2 | 02. †K ZË¡xqfv‡e gnvKl© Zi‡½i avibv cÖ¯Íve K‡ib? [CU-A, Set-2. 19-20] A. wKc _b© B. wbDUb C. AvBb÷vBb D. G‡jb ¸_ KYv ZË¡ cÖ`vb K‡ib wbDUb, Zi½ZË¡ cÖ`vb K‡ib nvB‡Mbm Ges gnvKl© Zi‡½i aviYv cÖ¯Íve K‡ib AvBb÷vBb| 03. we›`y f‡ii Rb¨ gnvKl©xq wefe †KvbwU? [CU. 14-15; MBSTU. 14-15] A. 2 r GM B. r GM C. 2 r GM D. r GM E. 3 r GM Ans B 04. GKwU e¯‘‡K †h †Kvb fv‡eB ivLv †nvK bv †Kb e¯‘i †fZ‡i Aew¯’Z †h we›`yi ga¨ w`‡q †gvU IRb wµqv K‡i †mB we›`y‡K H we¯‘i wK e‡j? [CU. 13-14] A. AwfKl© †K›`ª B. gnvKl©xq †¶Î C. AwfKl©R Z¡iY D. gnvKl©xq †¶Î cÖvej¨ E. †KvbwU bq Ans A STEP 03 ANALYSIS OF GST QUESTION PART A Analysis of General University Question BRUR 01. Amxg `~i‡Z¡ gnvKl©xq ZxeªZvi gvb- [BRU. 12-13] A. Amxg B. mmxg C. k~b¨ D. wbw`©ó Ans C STEP 04 ANALYSIS OF MEDICAL & DENTAL QUESTION DAT 01. m~h© †_‡K c„w_exi Mo `~iZ¡ K‡g †M‡j eQ‡ii •`N©¨- [DAT; 19-20] A. w¯’i _vK‡e B. K‡g hv‡e C. Amxg n‡e D. †e‡o hv‡e MÖ‡ni MwZ m¤úwK©Z †Kcjv‡ii 3q m~Îvbymv‡i T 2 R 3 R Kg‡j T I Kg‡e| AFMC 01. c„w_exi wbU wefe KZ? [AFMC. 2020-21] A. 1 B. †bB C. 0 D. Amxg S C info wewfbœ e¯‘i †ÿ‡Î wef‡ei gvb : welq •e`y¨wZK wefe abvZ¥K Pv‡R©i wbK‡U abvZ¥K FYvZ¥K Pv‡R©i wbK‡U FYvZ¥K c„w_exi k~b¨ †Mvj‡Ki Af¨šÍ‡i k~b¨ STEP 05 ANALYSIS OF HSC BOARD QUESTION 01. gnvKlx©q †ÿ‡Îi evB‡i gnvKlx©q wefe- [iv.‡ev. 2015] A. m‡e©v”P B. k~b¨ C. FYvZ¥K D. A I B DfqB Ans D 02. gnvKlx©q wef‡ei †ÿ‡Î [P. †ev. 2016] i. Gi gvb m‡e©v”P n‡e Amx‡g ii. Gi m‡e©v”P gvb k~b¨ iii. GwU KL‡bv FYvZ¥K n‡Z cv‡i bv wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans A 03. wb‡Pi †KvbwU gnvKlx©q †ÿ‡Îi cÖve‡j¨i GKK? [w`. †ev. 2016] A. Nm–1 B. Nm C. ms–2 D. ms–1 Ans C 04. me‡P‡q `ye©j ej †KvbwU? [h. †ev. 2015] A. gnvKl© ej B. ZvwoZ‡PŠ¤^K ej C. mej wbDwK¬q ej D. `ye©j wbDwK¬q ej Ans A 05. g -Gi gvbÑ [wm.‡ev. 2019] i. c„w_exc„‡ô †ewk ii. c„w_exi †K›`ª k~b¨ nq iii. c„w_exc„‡ô I Pvu‡`i c„‡ôi AbycvZ 16:81 wb‡Pi †KvbwU mwVKÑ A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans A 06. f~c„‡ô †Kv‡bv e¯‘i fi 50 kg n‡j Puv‡` fi KZ? [wm. †ev. 2019; w`. †ev. 15] A. 400 kg B. 980 kg C. 50 kg D. k~Y¨ Ans C 07. gnvKlx©q cÖve‡j¨i w`K †Kvb w`‡K nq? [e.‡ev. 2019] A. c„w_exi †K›`ª eivei B. gnvKl© e‡ji w`‡K C. gnvKl© e‡ji wecixZ w`‡K D. c„w_exi †K›`ª †_‡K evwn‡ii w`‡K Ans B
ASPECT PHYSICS cÖ_g cÎ gnvKl© I AwfKl© 233 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 08. wb‡Pi †KvbwUi c„‡ôi gnvKl© cÖvej¨ me‡P‡q †ewk? [e. †ev. 2016] A. P›`ª B. eya C. c„w_ex D. e„n¯úwZ Ans D 09. gnvKlx©q wef‡ei †ÿ‡Î- [mKj †evW© 2018] A. GwU †¯‹jvi ivwk B. Gi gvÎv mgxKiY L 2T –2 C. gnvKlx©q †ÿ‡Îi †Kv‡bv we›`y‡Z GwU FYvZ¥K D. me¸‡jvB Ans D 10. gnvKlx©q wef‡ei †ÿ‡Î- [mKj †evW© 2018] i. GwU †¯‹jvi ivwk ii. gnvKlx©q †ÿ‡Îi †Kv‡bv we›`y‡Z GwU FYvZ¥K iii. Gi gvÎvi mgxKiY L 2 T –2 wb‡Pi †KvbwU mwVK? A. i I ii B. ii I iii C. i I iii D. i, ii I iii Ans D Concept 6 gyw³‡eM msµvšÍ Z_¨vejx ✅ gyw³‡eM/cjvqb †eM/wb®Œgb †eM: †Kvb e¯‘‡K b~b¨Zg †h †e‡M D‡aŸ© wb‡¶c Ki‡j Zv Avi c„w_ex c„‡ô wd‡i Av‡m bv Zv‡K gyw³‡eM ev cjvqb †eM ev wb®ŒgY †eM e‡j| mgxKiY : Ve 2gR R 2GM ✅ wbf©ikxjZv: mgxKiY n‡Z †`Lv hvq gyw³‡e‡Mi gvb e¯‘i f‡ii Dci wbf©i K‡i bv, eis wbf©i K‡i- GKwU MÖn ev DcMÖ‡ni 1. AwfKl©R Z¡iY, 2. fi, 3. e¨vmv‡a©i Dci| MÖ‡ni bvg gyw³ †e‡Mi gvb MÖ‡ni bvg gyw³ †e‡Mi gvb c„w_ex 11.2kms–1 /7miles-1 /25000mileh-1 eya 4.3kms-1 g½j MÖn 5.1kms-1 [Zcb m¨vi] /4.77kms-1 [Avgxi m¨vi] e„n¯úwZ 6.02 104ms-1 ✅ we‡kl Z_¨: ◈ c„w_exi c„ô n‡Z †Kvb e¯‘‡K v †e‡M Dc‡ii w`‡K wb‡¶c Ki‡j c„w_exi AvKl©Y ej Øviv e¯‘wUi wewfbœ cwiYwZ n‡Z cv‡i| hw` v 2 < v 2 e 2 nq A_©vr v < 7.88 kms-1 n‡j e¯‘wU Dce„ËvKv‡i c„w_ex cÖ`w¶Y Ki‡e Ges c„w_ex‡Z wd‡i Avm‡e| v 2 = v 2 e 2 A_©vr v = 7.88 kms-1 nq Zvn‡j e¯‘wU e„ËvKvi c‡_ cÖ`w¶Y Ki‡e Ges Puv‡`i gZ DcMÖ‡n cwiYZ n‡e| v 2 > v 2 e 2 wKš‘ <ve 2 A_©vr v = 7.88 kms-1 n‡Z 11.2kms-1 nq Zvn‡j GwU c„w_ex‡K GKwU †dvKv‡m †i‡L Zv Dce„ËvKvi c‡_ c„w_ex‡K cÖ`w¶Y Ki‡Z _vK‡e| v = ve A_©vr v = 11.2 kms-1 nq Zvn‡j e¯‘wU Awae„Ë c‡_ c„w_ex †Q‡o P‡j hv‡e| v > ve n‡j A_©vr Dr†¶cb †eM (ve ) gyw³‡eM A‡c¶v †ekx nq Zvn‡j e¯‘ cive„Ë c‡_ c„w_ex †Q‡o P‡j hv‡e| gyw³‡e‡Mi 0.707 ¸Y †e‡M Abyf~wgKfv‡e †Kv‡bv e¯‘‡K wb‡ÿc Ki‡j Zv K…wÎg DcMÖ‡n cwiYZ n‡e| A_©vr, Kÿxq 0.707 × 11.2 = 7.9 kms–1 REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF JU QUESTION 01. hw` v 2 = V 2 E 2 nq A_©vr Dr‡ÿcY †eM 7.88km/s nq, n‡e, e¯‘wU- [JU. 13-14] A. e„ËvKvi c‡_ c„w_ex‡K cÖ`wÿY K‡i B. Dce„ËvKvi c‡_ c„w_ex‡K cÖ`wÿY K‡i C. Awae„Ëc‡_ c„w_ex †Q‡o hvq D. †KvbwUB bq Ans A 02. c„w_exi mv‡c‡¶ gyw³‡eM VE Pv‡`i mv‡c‡¶ gyw³‡eM VM n‡j bx‡Pi †Kvb m¤úK©wU mwVK| [DU. 11-12, IU. 12-13] A. VE>VM B. VE<VM C. VE=VM D. VEVM c„w_exi gyw³‡eM = VE, Pvu‡` gyw³‡eM = VM c„w_exi AwfKl©R Z¡iY Pv‡`i AwfKl©R Z¡i‡Yi †P‡q †ekx A_©vr gE>gM VE>VM STEP 02 ANALYSIS OF RU QUESTION 01. †Kvb e¯‘i Dr‡ÿcY †eM Zvi gyw³ †e‡Mi mgvb n‡j e¯‘wU- [RU. 16-17] A. DcMÖ‡n cwiYZ n‡e B. c„w_ex‡Z wd‡i Avm‡e C. cive„ËvKvi c‡_ c„w_ex †Q‡o hv‡e D. Awae„ËvKvi c‡_ c„w_ex †Q‡o hv‡e Ans C 02. †Kvb GK gyw³ †eM H e¯‘i f‡ii- [RU. 16-17] A. mgvbycvwZK B. e‡M©i mgvbycvwZK C. f‡ii Dci wbf©ikxj D. ‡KvbwUB bq Ve = 2gR gyw³ †eM e¯‘i f‡ii Dci wbf©ikxj bq| 03. c„w_ex n‡Z †Kvb e¯‘‡K KZ †e‡M Lvov Dc‡ii wb‡¶c Ki‡j Zv c„w_exi AvKl©Y KvwU‡q gnvk~‡b¨ P‡j hv‡e? [RU. 13-14] A. 1 11.2 kms B. 1 11.3 kms C. 1 11.4 kms D. 1 11.1 kms Ans A STEP 03 ANALYSIS OF CU QUESTION 01. gyw³‡eM †KvbwU? [CU-A, Set-3. 20-21, 18-19, 14-15, RUET. 11-12] A. Ve = 2gR B. Ve = 2gR C. Ve = 2g2R D. Ve = 2g R 2 S A info ve = 2gR = 2GM R 02. c„w_exi c„‡ô †_‡K GKwU e¯‘i gyw³‡eM KZ? [CU-A, Set-2. 20-21] A. 11.2 ms–1 B. 1120 ms–1 C. 11.2 kms–1 D. 112 kms–1 S C info c„w_ex †_‡K 11.2 kms–1 †e‡M †Kvb e¯‘‡K gnvKv‡ki w`‡K wb‡ÿc Ki‡j Zv Avi c„w_ex‡Z †diZ Avm‡e bv| 03. b~¨bZg KZ †e‡M Zzwg AvKv‡ki w`‡K GKwU cÖ¯Íi LÛ Qyo‡j GwU Avi c„w_ex‡Z wd‡i Avm‡e bv? [CU. 12-13] A. 10,000 mile/sec B. 34.67 mile/sec C. 6.95 mile/sec D. 9.80 mile/sec E. 13.90 mile/sec Ans C 04. GKwU K…wÎg DcMÖn‡K c„w_exi Uv‡bi evwn‡i gnvk~‡b¨ †cÖiY Ki‡Z gyw³‡eM KZ n‡e- [CU. 07-08, RUET. 12-13; CoU. 12-13, 14-15; RU. 17-18] A. 2 2 R GM v B. R h GM v C. R GM v D. v 2gR E. v – R 2g Ans D
234 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES STEP 04 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. g½j MÖ‡n gyw³‡e‡Mi gvb n‡jvÑ [KU. 18-19,14-15; CU. 14-15; RUET. 11-12] A. 5.1 km s-1 B. 5.1 m s-1 C. 11.2 km s-1 D. 11.2 m s-1 Ans A IU 01. Dr‡¶cY †e‡Mi gvb KZ n‡j GKwU e¯‘ c„w_ex‡Z wd‡i Av‡m bv| [IU. 11-12] A. 11.2 wK.wg./†m. B. 9.8 wK.wg./†m. C. 7.88 wK.wg./†m. D. †KvbwUB bq Ans A PART B Analysis of Science & Technology Question MBSTU 01. c„w_ex c„‡ô †Kvb GKwU M f‡ii e¯‘i gyw³‡eM 11.2 Km/s| fi wظY Kiv n‡j e¯‘wUi gyw³‡eM KZ n‡e? [MBSTU-A, Set-2 19-20; Xv. †ev. 2015; Kz. †ev. 2015; w`. †ev. 2015] A. 22.4 Km/s B. 5.6 Km/s C. 8.12 Km/s D. 11.2 Km/s gyw³‡eM MÖ‡ni f‡ii Dci wbf©ikxj wKš‘ e¯‘i f‡ii Dci wbf©i K‡i bv| STEP 05 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. wb‡Pi †Kvb Dw³wU mZ¨ bq? [MAT. 01-02] A. gyw³ †eM m~‡h©i Mo NbZ¡ I e¨vmv‡a©i Dci wbf©i Ki‡e B. w¯’i Zwor we`¨vi GKwU AšÍixZ AvwnZ cwievn‡Ki c„ôB n‡jv wefe c„ô C. I‡qi‡÷‡Wi cix¶v †_‡K cÖgvwYZ nq †h, Zwor cÖev‡ni d‡j Gi Pvicv‡k †PŠ¤^K †¶Î m„wó nq D. nj †fv‡ëR cÖwZ GKK AvqZ‡b Avavb evn‡Ki mgvbycvwZK Ans A AFMC 01. c„w_ex c„ô †_‡K †Kv‡bv eš‘i gyw³ †eM KZ? [AFMC. 2020-21] A. 11.7 kms–1 B. 13 kms–1 C. 10 kms–1 D. †Kv‡bvwUB bq S D info MÖ‡ni bvg gyw³ †e‡Mi gvb c„w_ex 11.2kms–1 /7miles–1 /25000mileh–1 g½j MÖn 5.1kms–1 [Zcb m¨vi] /4.77kms–1 [Avgxi m¨vi] eya 7.1kms–1 e„n¯úwZ 6.02104ms–1 gyw³ †eM/cjvqb †eM/wb®Œgb †eM: me©v‡cÿv Kg †h †e‡M †Kv‡bv e¯‘‡K Lvov Dc‡ii w`‡K wb‡ÿc Ki‡j Zv Avi c„w_ex‡Z wd‡i Av‡m bv †mB †eM‡K gyw³ †eM e‡j| wbf©ikxjZv: mgxKiY n‡Z †`Lv hvq gyw³‡e‡Mi gvb e¯‘i f‡ii Dci wbf©i K‡i bv, eis wbf©i K‡i- GKwU MÖn ev DcMÖ‡ni AwfKl©R Z¡iY, MÖn ev DcMÖ‡ni fi, MÖn ev DcMÖ‡ni e¨vmv‡a©i Dci| STEP 06 ANALYSIS OF HSC BOARD QUESTION 01. †Kv‡bv e¯‘i gyw³ †eM wbf©i K‡i- [Xv. †ev. 2019; Kz.‡ev. 2017] A. MÖ‡ni e¨vmv‡a©i Ici B. AwfKl©R Z¡i‡Yi Ici C. e¯‘i f‡ii Ici D. A I B DfqB Ans D 02. AwfKlx©q Z¡iY aªæeK n‡j, †Kv‡bv e¯‘i gyw³‡e‡Mi mv‡_ H MÖ‡ni e¨vmv‡a©i m¤úK© n‡”QÑ [P.‡ev. 2019] A. mgvbycvwZK B. e¨¯ÍbycvwZK C. eM©g~‡ji mgvbycvwZK D. eM©g~‡ji e¨¯ÍvbycvwZK S C info V = 2gR V R 03. †Kv‡bv GKwU KvíwbK MÖ‡ni fi Ges e¨vmva© e„w× Ki‡j D³ MÖ‡ni c„ô n‡Z gyw³‡eM- [P. †ev. 2017] A. evo‡Z cv‡i B. Kg‡Z cv‡i C. AcwiewZ©Z _vK‡Z cv‡i D. me¸‡jv mwVK S D info Ve = 2GM R = 2gR 04. gyw³‡e‡Mi mgxKiY n‡”Q- [w`. †ev. 2019; h. †ev. 2015] A. ve = GM R B. ve = 2GM R 2 C. ve = gR D. ve = 2gR Ans D 05. gyw³‡e‡Mi ivwkgvjvq †KvbwU Abycw¯’Z? [h. †ev. 2016] A. MÖ‡ni e¨vmva© B. AwfKl©R Z¡iY C. MÖ‡ni fi D. e¯‘i NbZ¡ Ans D 06. †Kv‡bv e¯‘i gyw³‡eM IB e¯‘i Nb‡Z¡iÑ [h. †ev. 2016] A. e‡M©i mgvbycvwZK B. mgvbycvwZK C. e¨¯ÍvbycvwZK D. Ici wbf©ikxj bq Ans D 07. †Kv‡bv e¯Íyi Dr‡ÿcY †eM v Ges gyw³‡eM vE nq, Z‡eÑ [h. †ev. 2015] i. v > vE n‡j, e¯ÍywU cive„Ë c‡_ c„w_exi c„ô Q‡o hv‡e ii. v 2 = v 2 E 2 n‡j, e¯ÍywU e„ËvKvi c‡_ c„w_ex‡K cÖ`wÿY Ki‡e iii. v = vE n‡j, e¯ÍywU Puv‡`i gZ c„w_ex‡K cÖ`wÿY Ki‡e wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans A 08. †Kv‡bv e¯‘i gyw³‡eM wbf©i K‡i [Kz. †ev. 2017] i. MÖ‡ni e¨vmv‡a©i Dci ii. AwfKl©R Z¡i‡Yi Dci iii. e¯‘i f‡ii Dci wb‡Pi †KvbwU mwVK? A. i B. i I ii C. ii I iii D. i, ii I iii Ans B 09. c„w_ex‡Z †Kv‡bv e¯‘i gyw³‡eM wbf©i K‡iÑ [e. †ev. 2015] A. e¯‘i f‡ii Ici B. c„w_exi e¨vmv‡a©i Ici C. e¯‘i e¨vmv‡a©i Ici D. c„w_exc„ô I e¯‘i `~i‡Z¡i Ici Ans B Concept 7 K…wÎg DcMÖn msµvšÍ Z_¨vejx ✅ ¯^vfvweK DcMÖn: cÖvK…wZK Kvi‡Y N‡U| †hgb- Puv`| ✅ K…wÎg DcMÖn: gvbe m„ó| †hgb- ¯úyUwbK-1, ¯úyUwbK-2, fóK-1, G·‡cøvivi-1 cÖf„wZ| ✅ f~-w¯’i DcMÖn: †Kv‡bv K…wÎg DcMÖ‡ni AveZ©bKvj wbR A‡¶i Pviw`‡K N~Y©vqgvb c„w_exi AveZ©b-Kv‡ji mgvb n‡j c„w_exi mv‡c‡¶ GwU w¯’i _vK‡e G ai‡bi DcMÖn‡K f~-w¯’i DcMÖn e‡j| Gi AveZ©b Kvj 24 N›Uv Ges †eM c~e© AwfgyLx| Puv` c„w_exi GKwU DcMÖn hv cÖvq 30 w`‡b c„w_ex‡K GKevi cÖ`w¶Y K‡i| ✅ ¸iæZ¡c~Y© Z_¨vejx: 1957 mv‡ji 4 A‡±vei ivwkqvi weÁvbxiv me©cÖ_g ¯úyUwbK-1 bv‡g K…wÎg DcMÖn gnvk~‡b¨ cvVvb| Av‡gwiKvi weÁvbxiv 1958 mv‡j G·‡cøvivi-1 bv‡g GKwU K…wÎg DcMÖn Dr†¶cb K‡ib| ivwkqvi weÁvbx BDwi M¨vMvwib 1961 mv‡j fóK-1 K…wÎg DcMÖ‡ni mvnv‡h¨ me©cÖ_g gnvk~‡b¨ wePiY K‡ib| evsjv‡`‡k XvKvi Zvwjevev` Ges PÆMÖv‡gi †eZeywbqvq f~-w¯’i DcMª‡ni †em †÷kb i‡q‡Q| †Uj÷vi (Telstor) n‡jv cÖ_g †hvMv‡hvM DcMªn †hwU Av‡gwiKv 1962 mv‡j Dr†¶cb K‡i‡Q| f~-w¯’i DcMÖn Gi K¶c_‡K cvwK©s K¶c_ e‡j|
ASPECT PHYSICS cÖ_g cÎ gnvKl© I AwfKl© 235 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ✅ K„wÎg DcMª‡ni e¨envi: c„w_exi AvKvi I AvK„wZ m¤úwK©Z f~-Rwic K…wÎg DcMÖ‡ni mvnv‡h¨ mgy‡`ªi MfxiZv wbY©q Kiv hvq f~-c„‡ôi GjvKv m¤ú‡K© †eZvi I †Uwjwfk‡bi gva¨‡g Z_¨ cÖ`vb DaŸ©vKv‡ki wewfbœ wewKib I Zvi cÖfve m¤ú‡K© wewfbœ Z_¨ AbymÜv‡b e¨eüZ nq| AvenvIqvi c~ev©fvm m¤ú‡K© Rvbv| MÖn b¶‡Îi MVb m¤ú‡K© M‡elYvi Kv‡R e¨eüZ nq| †R¨vwZwe©Áv‡bi M‡elYv Pvjv‡bv gnvRvMwZK iwk¥mn wewfbœ iwk¥i Drmmn bvbvwea M‡elYvq e¨eüZ nq| cÖwZi¶vg~jK cvnviv I wewfbœ mvgwiK e¨e¯’vcbvq GwU e¨eüZ nq ewn©we‡k¦ ib‡Rb iwk¥, Mvgv iwk¥, BZ¨vw` Drm msµvšÍ I †RvwZwe©Áv‡bi M‡elYv Pvjv‡Z| AvšÍtgnv‡`kxq †hvMv‡hv‡M GwU e¨eüZ nq DaŸ©vKv‡ki Avqb gÛj, KmwgK weKiY, PvwR©Z KYvi f¨vb A¨v‡mj †e÷bx, †mŠi wewKi‡Yi cÖfve BZ¨vw` m¤ú‡K© Z_¨ msMÖn Kiv hvq| c„w_exi †h †Kvb †`‡k AbywôZ †Ljvayjv ev †h †Kvb Abyôvb avivevwnKfv‡e †Uwjwfk‡bi gva¨‡g †`Lv‡bv D”P evqy gÛ‡ji Pvc, ZvcgvÎv I MVb wbY©q Kiv hvq| REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF CU QUESTION 01. GKwU f~w¯’i DcMÖ‡ni ch©vqKvj KZ? [CU-A, Set-4. 20-21, 17-18; JKKNIU-B, Set-3, 19-20; IU. 12-13] A. 0 hr B. 24 hr C. 12 hr D. 365 hr S B info GKwU f‚w¯’i DcMÖn Gi ch©vqKvj 24hr| †Kv‡bv DcMÖn‡K c„w_ex mv‡c‡ÿ w¯’i _vK‡Z n‡j A_©vr f~w¯’i _vK‡Z n‡j Gi ch©vqKvj c„w_exi AvwýK MwZi ch©vqKv‡ji mgvb n‡Z n‡e| c„w_exi AvwýK MwZi ch©vhKvj n‡jv 24 hr| 02. hLb `ywU DcMÖn GKB e„ËvKvi Kÿc‡Z AveZ©biZ nq, ZLb Zv‡`i –––| [CU-A, Set-4. 20-21] A. fi mgvb B. †KŠwYK fi‡eM mgvb C. MwZ kw³ mgvb D. `ªæwZ mgvb S D info `ywU wfbœ DcMÖn hLb GKB e„ËvKvi Kÿc‡_ AveZ©biZ nq ZLb a‡i †bIqv nq †h, Zviv c„w_ex †_‡K GKB D”PZvq Ae¯’vbiZ _v‡K| †m‡ÿ‡Î Zv‡`i `ªæwZ GKB n‡e| 03. c„w_exi fi M Ges e¨vmva© R n‡j, c„w_ex c„ô n‡Z h D”PZvq K…wÎg DcMÖ‡ni AveZ©b Kv‡ji gvb KZ? [CU. 12-13] A. GM (R h) 2 B. GM (R h) C. (R h) GM 2 D. GM (R h) 2 3 E. GM (R h) 3 Ans D 04. c„w_exi fi M Ges e¨vmva© R n‡j, h D”PZvq K…wÎg DcMÖ‡ni K¶xq †eM- [CU. 11-12; JU. 09-10; CU. 12-13] A. GM R+h B. R+h GM C. GM R+h D. R+h GM E. (R+h) 2 GM Ans A STEP 02 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. cvwKs Kÿc_ †KvbwU? [KU-A, Set-Ka. 19-20; Xv. †ev. 2017] A. †h c‡_ wegvb PjvPj K‡i B. †cvjvi DcMÖ‡ni Kÿc_ C. f~-w¯’i DcMÖ‡ni Kÿc_ D. c„w_exi Kÿc_ f~Ñw¯’i DcMÖ‡ni Kÿc_‡K cvwK©s Kÿc_ e‡j| PART B Analysis of Science & Technology Question MBSTU 01. `ywU DcMÖn GKB Kÿc‡_ N~Y©vqgvb| Zv‡`i Aek¨BÑ[MBSTU-A, Set-2 19-20] A. fi mgvb B. †KŠwYK fi‡eM mgvb C. MwZkw³ mgvb D. `ªæwZ mgvb GKwU wbw`©ó Kÿc‡_i †KŠwYK fi‡eM wbw`©ó| STEP 03 ANALYSIS OF MEDICAL & DENTAL QUESTION AFMC 01. Puv` c„w_ex‡K KZw`‡b GKevi cÖ`wÿY K‡i? [AFMC. 2020-21] A. 27 B. 29 C. 30 D. 28 Ans A STEP 04 ANALYSIS OF HSC BOARD QUESTION 01. †Kv‡bv e¯‘‡K KZ †e‡M wb‡ÿc Ki‡j GwU K…wÎg DcMÖ‡n cwiYZ n‡e?[Xv. †ev. 2016] A. 7.9 kms–1 B. 11.2 kms–1 C. 7.9 ms–1 D. 11.2 ms–1 Ans A 02. f~-w¯’i DcMÖ‡ni Kÿc_ m¤ú‡K© wb‡Pi †KvbwU mwVK bq? [Xv. †ev. 2015] A. f~-w¯’i DcMÖ‡ni Kÿc_ welye‡iLvi mivmwi Ic‡i _vK‡e B. f~-w¯’i DcMÖ‡ni Kÿc‡_ mg¯Í DcMÖ‡ni fi GKB n‡e C. f~-w¯’i DcMÖ‡ni Kÿc‡_i AveZ©bKvj 24 NÈv D. f~-w¯’i DcMÖ‡ni Kÿc‡_i m¤¢ve¨ e¨vmva© GKwU Ans C 03. GKwU f~-w¯’i DcMÖ‡ni AveZ©bKvj KZ?[Kz.†ev.2019; P.‡ev.2015; wm.‡ev.2016] A. 12 NÈv B. 24 NÈv C. 1 NÈv D. 12 NÈv Ans B 04. f~-w¯’i DcMÖ‡ni ch©vqKvjÑ [wm. †ev. 2016] A. 1 eQi B. 1 gvm C. 1 w`b D. 1 N›Uv Ans C
236 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES STEP 2 mg„× †ewmK MvwYwZK cÖ Ö‡qvM (MATH) kU©KvU †UKwbK Concept 1 gnvKl©xq ej msµvšÍ MvwYwZK cÖ‡qvM FORMULA 01. gnvKl© ej, Fm1m2, F 1 d 2 ; 2 1 2 2 1 F F d d ; F m1m2 d 2 ; 2 d Mm F G e„Ëxq MwZ: e„Ë c‡_i MwZ; (†K›`ªgyLx ej = gnvKl© ej) 02. 2 d GMm = d mv 2 v = d GM = d gR2 ( g = 2 R GM or, GM = gR2 ) Model Example01 `yBwU KYvi g‡a¨ gnvKl© e‡ji gvb †Kgb cwieZ©Y n‡e hw` GKwU KYvi fi c~‡e©i wظY, Ab¨ KYvi fi wZb¸Y Kiv nq Ges GKB mv‡_ Zv‡`i gv‡Si `~iZ¡ wØMY Kiv nq? General Rules [Written] 3 in 1 Shortcut Tricks & Tips [MCQ] F1 = Gm1m2 d1 2 ............(1) F2 = Gm1m2 d2 2 ............(2) 2 2 1 1 2 1 2 1 2 d d m m m m F F 1.5times 2 2 2 3 2 1 1 1 2 3 2 F m1m2 d 2 = 2 3 (2) 2 = 1.5 CONCEPTUAL MATH MEx 01 evqy‡Z GK Kzj‡¤^i `ywU Avavb ci¯úi †_‡K 1 km e¨eav‡b Aew¯’Z n‡j, G‡`i ga¨Kvi ej KZ n‡e? 9000N 9KN (1000) 1 1 F 9 10 2 9 NOW START PRACTICE 01. `ywU e¯‘i ga¨eZ©x `~iZ¡ c~‡e©i A‡a©K n‡j µxqviZ ej c~‡e©i KZ¸b n‡e? 02. `ywU mg‡giæ 10 cm `~‡i ci¯úi‡K 10 dyne ejØviv weKl©Y K‡i| hw` `~iZ¡ 5 cm nq| Z‡e weKl©Y e‡ji gvb KZ dyne? NOW PRACTICE SOLVE : 01. F 2 d 1 `~iZ¡ A‡a©K n‡j ej 4 ¸b n‡e| `~iZ¡ wظb n‡j ej 1 4 ¸b n‡e| 02. 1 2 F F = d1 d2 2 , F2 = 2 5 10 F1 = 40 dyne REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. k~b¨ gva¨‡g `yBwU B‡jKUª‡bi ga¨Kvi Kzj¤^ ej FE Ges gnvKl© ej FG Gi AbycvZ n‡e? [DU. 16-17] A. 4.21062 B. 4.21052 C. 4.21042 D. 4.21032 FE FG = K q1q2 d 2 G m1m2 d 2 = 9 109 (1.6 10–19) 2 6.673 10-11(9.1 10–31) 2 = 4.2 1042 02. `yBwU KYvi g‡a¨ gnvKl© e‡ji gvb †Kgb cwieZ©Y n‡e hw` GKwU KYvi fi c~‡e©i wظY, Ab¨ KYvi fi wZb¸Y Kiv nq Ges GKB mv‡_ Zv‡`i gv‡Si `~iZ¡ wØMY Kiv nq? [DU. 15-16] A. c~‡ei mgvb _vK‡e B. c~‡e©i wZb¸Y n‡e C. c~‡e©i wظY n‡e D. c~‡e©i ‡`o¸Y n‡e 2 2 1 1 2 1 2 1 2 d d m m m m F F 1.5times 2 2 2 3 2 1 1 1 2 3 2 03. m~h© c„w_exi Dci 3.61020 N AvKl©Yx ej cÖ‡qvM K‡i, c„w_ex m~h© †_‡K 1.51012 m `~‡i _v‡K, c„w_exi fi hw` 5.981024 kg nq Zvn‡j m~‡h©i fi KZ? (G = 6.6710–11 N-m 2 /kg2 ) [DU. 97-98] A. 2.031035 kg B. 2.031022 kg C. 2.031036 kg D. 2.031030 kg gnvKl© ej, F = G 2 1 2 d m m m2 = 1 2 Gm Fd = 11 24 20 12 2 6.67 10 5.89 10 3.6 10 (1.5 10 ) = 2.031030 kg STEP 02 ANALYSIS OF JU QUESTION 01. M f‡ii e¯‘‡K †K‡U m I (M-m) f‡ii e¯‘‡Z iƒcvšÍwiZ Kiv n‡jv| M/m KZ n‡j G‡`i g‡a¨ gnvKl© ej m‡e©v”P n‡e? [JU-A, Set-A. 19-20] A. 2 B. 4 C. 3 D. 5 F = Gm(M m) d 2 ; dF dm = M 2m = 0 M m = 2
ASPECT PHYSICS cÖ_g cÎ gnvKl© I AwfKl© 237 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 02. 1Kg f‡ii `ywU e¯‘‡K 1m `~‡i ¯’vcb Ki‡j G‡`i ga¨eZx© AvKl©Y ej n‡e- [JU-A, Set-A. 19-20] A. 6.673 10–11N B. 6.673 10–30N C. 6.673 10–15N D. 6.673 10–22N Avgiv Rvwb gnvKl© ej, F = G m1m2 d 2 = 6.673 1011 1 1 1 2 = 6.673 1011 N 03. GKwU e¯‘i fi 20 gm c„w_exi †K‡›`ªi w`‡K e¯‘wU KZ e‡j AvKwl©Z n‡e? [JU. 09-10] A. 196.00N B. 0.196 10-3N C. 0.16 10-6N D. 196 10-3 N AwfKl© ej, F = mg = 0.02 9.8 = 196 10–3 N STEP 03 ANALYSIS OF RU QUESTION 01. `ywU e¯‘i ga¨Kvi gnvKl© ej F| hw` Zv‡`i ga¨‡Kvi `~iZ¡ mgvb †i‡L fi A‡a©K Kiv nq, Z‡e e‡ji gvb KZ n‡e? [RU. Moderna, Set-2. 20-21] A. F/2 B. F/4 C. 2F D. F S B info F F = Gm1m2 (d) 2 d 2 Gm1m2 = m1 2 m2 2 m1m2 F = F 1 4 [gnvKl© ej F = Gm1m2 d 2 ; m1= m1 2 ; m2= m2 2 ] 02. 1 N ej 2 kg f‡ii Dci cÖ‡qvM Kiv n‡jv| Avevi 2 N ej 4 kg f‡ii Dci cÖ‡qvM Kiv n‡jv| 1g I 2q †ÿ‡Îi Z¡i‡Yi AbycvZ KZ n‡e? [RU. Astrazeneca, Set-1. 20-21] A. 1:1 B. 2:1 C. 4:1 D. 1:2 S A info F1 F2 = m1a1 m2a2 1 2 = 2 a1 4 a2 a1 a2 = 1[Avgiv Rvwb, F = ma] 03. 0.1 kg Ges 0.2 kg f‡ii `ywU e¯‘ 1 m `~‡i Aew¯’Z| e¯‘ `ywU G‡K Aci‡K KZ e‡j AvKl©Y Ki‡e? [RU. 12-13] A. 11.32 10-13 N B. 13.32 10-13 N C. 15.13 10-10 N D. 20.32 10-11 N gnvKl© ej, F = G 2 1 2 d m m = 2 11 (1) 6.6710 0.1 0.2 = 13.32 10-13 N STEP 04 ANALYSIS OF CU QUESTION 01. 12mg f‡ii GKwU e¯‘ c„w_exi †K‡›`ªi w`‡K KZ e‡j AvK…ó n‡e? [CU-A, Set-1. 20-21] A. 117.6×10–6 N B. 117.6×10–3 N C. 11.76N D. 1.76N S B info c„w_exi †K‡›`ªi w`‡K AvK…ó nIqvi Rb¨ Abyf‚Z ej = e¯‘i IRb = 12 10–3 9.8N = 117.6×10–3 N| 02. 10 kg f‡ii `ywU e¯‘i ga¨eZ©x AwfKl©R e‡ji gvb KZ? [CU-A, Set-2. 20-21] A. 6.67 × 10–7 N B. 6.67 × 10–10 N C. 6.67 × 10–9 N D. 6.67 × 10 –5 N E. Blank S Blank info cÖkœwUi mwVK †Kvb mgvavb †bB| KviY e¯‘ `ywUi ga¨eZ©x `~iZ¡ cÖ‡kœ †`Iqv †bB| 03. Mv‡Qi GKwU Av‡cj c„w_ex‡K F1 e‡j AvKl©Y Ki‡Q| c„w_ex Av‡cj‡K F2 e‡j AvKl©Y K‡i‡Q| myZivs- [CU-A, 19-20; w`. †ev. 2016] A. F2 >> F1 B. F2 > F1 C. F2 = F1 D. F2 < F1 Df‡qi AvKl©Y ej mgvb n‡e| 04. f‚wg n‡Z 'm' f‡ii †Kvb e¯‘KYv‡K 2R (c„w_exi e¨vmv‡a©i wظY) D”PZvq D‡Ëvjb Ki‡Z K…Z KvR| [CU. 18-19] A. 2mgR B. mgR 2 C. 2mgR D. 2mgR 3 W =GMm 1 R – 1 3R = GMm 2 3R = 2 3 m GM R 2 R = 2 3 mgR 05. `ywU †Mvj‡Ki fi h_vµ‡g 40 kg Ges 15 kg G‡`i †K›`ª ؇qi ga¨eZ©x `~iZ¡ 0.1m n‡j cvi¯úwiK AvKl©b ej KZ? [CU. 10-11] A. 39.96N B. 38.39N C. 37.50N D. 40.37N E. 41.25N S Blank info 2 1 2 . d M M F G 2 11 0.1 6.6710 4015 N 6 4.002 10 STEP 05 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. GKwU e¯‘i fi 10 †WwmMÖvg| g =10 ms2 n‡j e¯‘wU c„w_exi †K‡›`ªi w`‡K KZ e‡j AvKwl©Z n‡e? [JnU. 12-13] A. 102N B.103N C. 104N D. 105N AwfKl© ej, F = mg = 1010-4 10 = 10–2 N KU 01. †Kvb nvB‡Wªv‡Rb cigvYy‡Z B‡jKUªb I †cÖvUb Gi ga¨Kvi gnvKl© e‡ji gvb n‡jv- [KU. 07-08] A. 3.6 x 10-46N B. 3.6 x 10-47N C. 1.8 x 10-47N D. 1.7 10-48N 48 2 11 19 2 1 2 1.7 10 1 6.67 10 1.6 10 d m m F G IU 01. `ywU e¯‘i g‡a¨ †h `yiZ¡ Av‡Q Zv A‡a©‡K †b‡g Avm‡j gnvKl© e‡j- [IU. 15-16, MBSTU. 19-20, 15-16; w`. †ev. 2015] A. wظb ev‡o B. A‡a©K ev‡o C. A‡a©K K‡g D. Pvi¸b ev‡o F 1 d 2 F 1 d 2 2 F = 4F PART B Analysis of Science & Technology Question JUST 01. GK kg f‡ii 2 wU e¯‘i ga¨eZ©x `~iZ¡ lm n‡j, G‡`i g‡a¨ AvKl©Y ej KZ? [JSTU: 15-16; BSMRSTU-H, 19-20; iv. †ev. 2017] A. 6.67 10-5 N B. 6.67 10-6 N C. 6.67 10-11 N D. 6.67 10-12 N F = Gm1m2 d 2 = 6.6710–1111 (1) 2 = 6.67 10–11N STEP 06 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. GKwU e¯‘i fi c„w_ex‡Z 75 †KwR| Puv‡` e¯‘wUi fi wK n‡e? [MAT. 2020-21] A. 14 kg B. 280 kg C. 75 kg D. 70 kg S C info e¯‘i fi me©Î GKB _v‡K| ZvB e¯‘i fi c„w_ex‡Z 75 kg n‡j Puv‡`I 75 kg n‡e| DAT 01. `ywU e¯‘i ga¨Kvi `~iZ¡ A‡a©K Ki‡j gnvKl© e‡ji gvb- [DAT; 19-20] A. wظY ev‡o B. Pvi¸Y ev‡o C. wظY K‡g D. Pvi¸Y K‡g F 1 r 2 F2 = 1 1 2 2 F1 = 4F1 STEP 07 ANALYSIS OF HSC BOARD QUESTION 01. GKwU cv_i LÛ‡K f~-c„‡ô †_‡K Lvov Dc‡ii w`‡K Zzj‡Z _vK‡j Gi Dci KqwU ej wµqv K‡i? [wm. †ev. 2015] A. 1 B. 2 C. 3 D. 4 Ans B 02. GKwU e¯Íyi fi 12mg| c„w_exi †K‡›`ªi w`‡K e¯ÍywU KZ e‡j AvKwl©Z n‡e? [wm. †ev. 2015] A. 1.1810-4 N B. 1178 N C. 117.610-6 N D. 1.1810-4 N S C info F = mg = 12 × 103 × 9.8 =117.610-6 N
238 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 2 g-Gi gvb msµvšÍ MvwYwZK cÖ‡qvM FORMULA 01. AwfKl©R Z¡iY (†h †Kvb MÖn, DcMÖn I b¶‡Îi Rb¨) g = GM R 2 02. AwfKl©R Z¡i‡Yi mv‡_ Nb‡Z¡i m¤úK©, g = 4 3 RG [g = GM R 2 = G. 4 3 R 3 R 2 = 4 3 R G] 03. AvwýK MwZi Rb¨: (i) g = g 1 – 2 R cos2 g [ = Aÿvsk] (ii) wbiÿ‡iLvq, g = g 1 – 2 R g [me©wb¤œ, = 0] (iii) †giæ‡Z, g = g [m‡e©v”P, = 90] CONCEPTUAL MATH MEx 01 c„w_exi e¨vmva© 6.4106m Ges AwfKl©R Z¡iY 9.8ms-2 c„w_ex c„ô n‡Z 6.4106m D”PZvq AwfKl©R Z¡iY n‡eg = GM R 2 IRb, w = mg ;l DaŸ©Mvgx wjd‡Ui †ÿ‡Î, g = g + a; wb¤œMvgx wjd‡Ui †ÿ‡Î g = g – a 2 R h R g g e e h ev, 2 9.8 R R gh R = 2 2 1 or 4 1 9.8 gh ev, 4 9.8 gh =2.45ms-2 NOW START PRACTICE 01. c„w_exi e¨vmva© 6.4 106 m Ges c„‡ô AwfKl©R Z¡ib 9.8ms–2 | f~-c„ô n‡Z 6.4105m D”PZvq AwfKl©R Z¡i‡bi gvb †ei Ki? NOW PRACTICE SOLVE : 01. gh ge = R R + h 2 ev gh = 6.4 × 106 6.4 × 106 + 0.64 × 106 2 × 9.8 ev, gh = 6.4 6.4 + 0.64 2 × 9.8 = 8.10ms2 REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. c„w_ex c„ô n‡Z KZ D”PZvq AwfKlx©q Z¡i‡bi gvb c„w_ex c„‡ôi Z¡i‡bi gv‡bi kZKiv GK fvM n‡e? [DU. 10-11] A. 5.4 107m B 6.38 107m C. 7.5 107m D. 8.1 106m D”PZv, h= 1 g g h R = 1 1 100 6.38 106 = 5.4107 m STEP 02 ANALYSIS OF JU QUESTION 01. c„w_exi e¨vmva© R n‡j f‚-c„ô n‡Z KZ D”PZvq g-Gi gvb g/4 n‡e? [JU. 12-13] A. R B. 2R C. R/2 D. 4R D”PZv, h = 1 g g h R = 1 g / 4 g R = R STEP 03 ANALYSIS OF RU QUESTION 01. c„w_exi e¨vmva© R n‡j f~-c„‡ô n‡Z KZ D”PZvq g Gi gvb k~b¨ n‡e| [RU. 12-13] A. R B. 2R C. R 2 D. 4R R h g g e h 2 1 ev, R 2h 0 1 ev, 1 2 R h ev, 2 R h 02. hw` c„w_exi e¨vmva© 6.37106m Ges Bnvi DcwiZ‡j AwfKl©R Z¡i‡Yi gvb 9.8 ms2 nq, Z‡e c„w_exi fi KZ? [RU. 09-10] A. 59.621023 kg B. 601022 kg C. 69.521023 kg D. 95.621023 kg c„w_exi fi, M = G gR2 = 11 6 2 6.67 10 9.8 (6.37 10 ) = 6.67 9.8 40.5769 1023 = 59.621023 kg 03. c„w_ex n‡Z KZ D”PZvq AwfKl©R Z¡i‡bi gvb 4.9ms-2 n‡e- [RU. 13-14, KUET. 07-08] A. 2.56109 m B. 2.561010 m C. 2.65106 m D. 2.561011 m Here gh ge = 4.9 9.8 = 1 2 h=( 2–1) R=0.416.4106 = 2.65106m or, h = ge gh 1 R = 9.8 4.9 1 R = ( 2 1)R = 2.65 × 106 m STEP 04 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. c„w_exi e¨vmva© eZ©gvb gv‡bi A‡a©K n‡q †M‡j AwfKl©R Z¡iY 'g'-Gi gvb KZ n‡e? [KU. 12-13] A. 6g B. 2g C. 4g D. g/4 AwfKlx©q Z¡iY, g = 2 R GM MÖn `ywUi fi mgvb| g 2 R 1 g 2 g 4g R R g 2 1 2 2 1 2 CoU 01. †Kv‡bv ¯’v‡b g Gi gvb 9.832ms–2 n‡j, wb‡Pi †Kvb Dw³wU mwVK? [CoU. 18-19] A. ¯’vbwU †giæ A‡j Aew¯’Z B. ¯’vbwU 45 Aÿvs‡k Aew¯’Z C. ¯’vbwU welyexq A‡j Aew¯’Z D. ¯’vbwU mgy`ª c„‡ô Aew¯’Z Ans A