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Published by Class Notes BD, 2023-08-25 12:32:09

Aspect Physics 1

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Aspect Physics 1

ASPECT PHYSICS cÖ_g cÎ c`v‡_©i MvVwbK ag© 289 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 07. 3.0mm Ges 6.0mm e¨vm wewkó `ywU ‣KwkK bj‡K GKwU cvwbi cv‡Î Lvovfv‡e AvswkK Wzwe‡q ivL‡j bj `ywUi wfZi w`‡q cvwb Dc‡i D‡V †h `ywU Zij AeZj Z‡ji m„wó K‡i, †mB Zj `ywUi g‡a¨ D”PZvi cv_©K¨ KZ? [cixÿvKvjxb ZvcgvÎvq cvwbi c„ôUvb 7.3 10–2Nm–1 ] Solve T = r1gh1 2 = r2gh2 2 h1= 2T gr1 , h2 = 2T gr2 h1 – h2 = 2T g 1 r1 – 1 r2 = 2 7.3 10–2 1000 9.8 1 1.5 10–3 – 1 3 10–3 = 4.966 10–3m = 4.966mm 08. 4 10–4m e¨vmv‡a©i GKwU mxmvi †MvjK wMømvwi‡bi wfZi w`‡q 6.5 10–3m/s cÖvšÍ‡eM wb‡q co‡Q| mxmvi I wMømvwi‡bi NbZ¡ h_vµ‡g 11.37 103Kg/m3 1.26 103Kg/m3 n‡j wMømvwi‡bi mv›`ªZvsK wbY©q Ki| Solve v = 2 9 r 2 (s –l)g = 2 9 r 2 (s – l)g v = 2 9 (4 10–4 ) 2 (11.37 – 1.26) 103 9.8 6.5 10–3Nm–1 = 0.542Nsm–2 09. `ywU Zv‡ii •`N¨© mgvb wKš‘ e¨vm h_vµ‡g 3mm Ges 6mm| Zvi `yBwU‡K mgvb e‡j Uvb‡j cÖ_gwUi •`N¨©e„w× wØZxqwUi •`N¨©e„w×i wZb¸Y nq| Zvi `ywUi g‡a¨ †KvbwU †ewk w¯’wZ¯’vcK? MvwYwZK we‡køl‡Yi gva¨‡g †Zvgvi gZvgZ e¨³ Ki| [BUET. 18-19] Solve 1 = 3l2; r1 = 1.5 10–3m; r2 = 3 10-3m Y1 Y2 = FL A1l1 FL A2l2 = r 2 2 l2 r 2 1 11 = 4 3 ; Y1: Y2 = 4 : 3 cÖ_gwU †ewk w¯ wZ¯ vcK| 10. GKwU Zv‡ii •`N©¨ eivei ej cÖ‡qvM Kivq hw` •`N©¨ 5% e„w× cvq, Zvn‡j, e¨vm 3% n«vm cvIqv wK m¤¢e? Solve aiv hvK, Avw` •`N©¨ = L •`N©¨ e„w×, l = 5% of L = 5L 100 •`N©¨ weK…wZ, l L = 5L 100 L = 5 100 = 0.05 Avevi, aiv hvK, Avw` e¨vm = R e¨vm n«vm, r = 3% Gi R = 3R 100 cvk¦© weK…wZ, r R = 3R 100 R = 3 100 = 0.03 cqm‡bi AbycvZ, = cvk¦© weK…wZ •`N©¨ weK…wZ = 0.03 0.05 = 3 5 = 0.6 wKš‧ Gi gvb 0.5 Gi †ewk n‡Z cv‡i bv| Kv‡RB, ewY©Z NUbv m¤¢e bq| 11. 500 cc AvqZ‡bi †Kvb M¨vm 4 evqygÐjxq Pv‡c Av‡Q| 6 evqygÐjxq Pv‡c Gi AvqZb 70% K‡g hvq| M¨vmwUi AvqZb ¸YvsK KZ? [1 evqygÐjxq Pvc = 1.013 105 N/m2 ] Solve K = cÖhy³ AvqZb cxob AvqZb weK…wZ = cÖhy³ Pvc AvqZb weK…wZ = 2 1.013 105 0.7 = 2.894 105 N/m2 GLv‡b, cÖhy³ Pvc = Pv‡ci cwieZ©b = 2 evqygÐjxq Pvc = 2 N/m2 AvqZb weK…wZ = v V = 70% = 70 700 = 0.7 12. 5cm e¨vmv‡a©i eyèy` m„wó Ki‡Z K…ZKvR KZ? c„ôUvb, T = 3 1012 N/m1 | Solve Avgiv Rvwb, †ÿÎd‡ji cwieZ©b A n‡j W = A T wKš‧ eyèy‡ì `ywU c„ô _v‡K, myZivs †ÿÎd‡ji e„w× A = 2 [4 (r )] 2 2 r 2 1 = 8 [(0.05)2 0] = 0.0628 m2 GLv‡b, ewa©Z e¨vmva©, r2 = 5cm = 0.05 m Avw` e¨vmva©, r1 = 0 c„ôUvb, T = 3 102 N m1 K…ZKvR, W = ? AZGe, K…ZKvR, W = A T = 0.0628 m2 3 102 N m1 = 1.88 103 J 13. 2m •`N©¨ Ges 1mm2 cÖ¯’‡”Q‡ì †ÿÎdjwewkó Zvi‡K †U‡b 0.1 mm cÖmvwiZ Kiv n‡jv| hw` Zv‡ii Dcv`v‡bi Bqs ¸Yv¼ 2 1011 N m2 nq, Z‡e ZviwU cÖmvwiZ Ki‡Z Kv‡Ri cwigvY Kx n‡e? Solve Avgiv Rvwb, W = 1 2 YAl 2 L = 1 2 2 1011 N m2 106 m 2 (104 m) 2 2m = 5 104 J 14. Qq cv wewkó 3.0 103 g f‡ii GKwU †cvKv cvwbi DcwiZ‡j ùvwo‡q _vK‡Z cv‡i| QqwU cv mgvb fi enb Ki‡j Ges †cvKvi cv‡qi Zjv 2.0 105 m e¨vmv‡a©i †MvjK AvK…wZi n‡j, cvwbi mv‡_ †cvKvi cv‡qi ¯úk© †KvY KZ n‡e? Solve GLv‡b, †cvKvi fi, M = 3.0 103 g = 3.0 106 kg †cvKvi GK cv‡qi fi, m = M 6 = 3.0 106 kg 6 = 5 107 kg cv‡qi Zjvi eµZvi e¨vmva©, r = 2 105 m cvwbi c„ôUvb, T = 7.2 102 N m1 AwfKl©R Z¡iY, g = 9.8 ms2 ¯úk©‡KvY, = ? Avgiv Rvwb, mvg¨ve¯ vq T cos 2r = mg ev, cos = mg T r ev, cos = 5 107 kg 9.8 m s2 7.2 102 N m1 2 2 105 m ev, cos = 0.54157 = 57.2 15. GKwU mvev‡bi eyèy‡ì e¨mva© 1 †mwg n‡Z evwo‡q 10 †mwg Ki‡Z KZ KvR m¤úbœ Ki‡Z n‡e? (mvevb-cvwbi c„ôUvb = 2.6 102 wbDUb/ wgUvi)| [KUET; 19-20] Solve c„ôkw³ = K…ZKvR †ÿÎdj = c„ôUvb mvev‡bi eyèy‡ì 2wU c„ô _v‡K| ZvB, c„‡ôi †ÿÎd‡ji cwieZ©b, A = 2 (4R 2 – 4r 2 ) = 2 4 (0.12 – 0.012 ) = 0.2488m2 K…ZKvR, W = AT = 0.2488m2 2.6 10–2 N/m = 6.469 10–3 J 16. cvwb eënvi Kivi ci Kj eÜ Kiv n‡jv| ZviciI †duvUv †duvUv cvwb cowQj| cwigvc K‡i †`Lv †Mj cÖwZwU †duvUvi e¨vm 4 10–7 m| G iKg AvUwU cvwbi †duvUv GKwÎZ K‡i GKwU eo cvwbi †duvUv •Zwi Kiv n‡jv| cvwbi c„ôUvb 72 10–3 N/m n‡j (i) eo cvwbi †duvUvi e¨vm KZ? (ii) cvwbi ZvcgvÎv KZ e„w× cv‡e? [BUTEX; 19-20] Solve (i) 4 3 R 3 = 4 3 r 3 8 R 3 = 8r3 R = 2r D = 2d = 8 10–7 m (ii) W = ms T 4 (Nr2 – R 2 ) = ms 4T (Nr2 – R 2 ) = 4 3 R 3 s 3T(Nr2 – R 2 ) R 3 s = 37210–3 {8(210–7 ) 2 – (4– ) 2 } (410–7 ) 3 1000 4200 = 0.12857C

290 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES STEP 3 mKj cvVëB‡qi NCTB QUESTIONS ANALYSIS cÖkœ e¨vLvmn mgvavb cÖkœ 01. †Kv‡bv c`v‡_©i AYy¸‡jvi g‡a¨ wbU ej k~b¨ nq hLb- [Bm&nvK, Avwgi] A. r = r0 B. r r0 C. r r0 D. r r0 Ans A 02. wewfbœ c`v‡_©i AYy¸‡jvi g‡a¨ cvi¯úwiK AvKl©Y ej‡K Kx e‡j? [Bm&nvK, Avwgi] A. AvmÄb ej B. msmw³ ej C. c„ô Uvb D. c„ô kw³ Ans A 03. GKB Dcv`v‡bi •Zwi 2q Zv‡ii •`N©¨ 1g Zv‡ii •`‡N©ï wØ¸Y wKš‘ e¨vmva© 1g Zv‡ii A‡a©K n‡j I mgvb fvi cÖ‡qvM Ki‡j 2q Zvi I 1g Zv‡ii •`N©¨ cÖmvi‡Yi AbycvZ nq- [Bm&nvK, Avwgi] A. 1 2 B. 2 C. 8 D. 10 l2 l1 = l2 l1 r1 r2 2 = 2 1 1 2 2 04. mv›`ªZv ¸Yv‡¼i †¶‡Î- [Bm&nvK, Avwgi] i. = ej × `~iZ¡ †¶Îdj × ‡eM ii. GKK = wbDUb-‡m./wgUvi2 iii. []=[ML-2T -2 ] wb‡Pi †KvbwU mwVK? A. i B. i I ii C. ii I iii D. i, ii I iii Ans B 05. cZbkxj e„wó we›`y cÖvšÍxq †eM jvf K‡i- [Bm&nvK, Avwgi] A. evqyi EaŸ©Nv‡Zi Rb¨ B. evqyi mv›`ªZvRwbZ e‡ji Rb¨ C. c„ôUv‡bi Rb¨ D. evqygÛ‡j evqy cÖev‡ni Rb¨ Ans B 06. r e¨vmva©wewkó GKwU cvwbi †duvUvi c„ôkw³ mgvbycvwZK n‡e- [Bm&nvK, Avwgi] A. r2 Gi mv‡_ B. 1 r Gi mv‡_ C. r3 Gi mv‡_ D. r Gi mv‡_ Ans B 07. w¯’i nv‡i mv›`ªZvwenxb Amsbg¨ cÖev‡ni †ÿ‡Î ev‡b©․wji Dccv`¨ cÖKvk K‡i- [Bm&nvK, Avwgi] A. †K․wYK fi‡e‡Mi msiÿY B. Nb‡Z¡i msiÿY C. fi‡e‡Mi msiÿY D. kw³i msiÿY Ans D 08. mv›`ª gva¨‡gi ga¨ w`‡q cZbkxj r e¨vmv‡a©i GKwU e¯‘i cÖvšÍxq †eM n‡j- [Bm&nvK, Avwgi] A. r B. r –2 C. r –1 D. r 2 Ans D 09. GKwU Zi‡ji g‡a¨ wb‡iU †MvjvKvi e¯‘‡K †d‡j w`‡j mg‡qi mv‡_ †e‡Mi cwieZ©b n‡e- [Bm&nvK, Avwgi] A. B. C. D. Ans C 10. wb‡Pi †KvbwU mwVK bq? [Bm&nvK, Avwgi] A. c„ôUv‡bi Kvi‡Y e„wói †duvUv †MvjvKvi nq B. c„ôUv‡bi Kvi‡Y •KwkK b‡j cvwb Ic‡i C. c„ôUvb Zij c„‡ôi †ÿÎdj e„w× K‡i D. c„ôUvb Zij c„‡ôi †ÿÎdj msKzwPZ K‡i Ans C 11. c„ôUv‡bi †ÿ‡Î D‡jøL‡hvM¨ n‡jv- [Bm&nvK, Avwgi] i. c„ôUvb Zij c„ô‡K msKzwPZ K‡i ii. msKU ZvcgvÎvq c„ôUvb k~b¨ nq iii. Zi‡ji gy³ Z‡ji mv‡_ Ab¨ †Kv‡bv e¯‧i mshyw³ n‡j c„ôUvb e„w× cvq wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans A 12. GKwU c`v‡_©i Bqs-Gi ¸Yv¼ Gi `„pZvi ¸Yv‡¼i 2.6 ¸Y n‡j H c`v‡_©i cqmb Gi AbycvZ KZ? [Bm&nvK, Avwgi] A. 0.26 B. 1.3 C. 0.3 D. 0.6 S C info cqm‡bi AbycvZ, = 1 = 1 2.6 = 0.3 13. wb‡Pi †KvbwU cqm‡bi Abycv‡Zi gvb n‡Z cv‡i bv? [Bm&nvK, Avwgi] A. 0.2 B. 0.1 C. 0.8 D. 0.5 S C info cqm‡bi AbycvZ: – 1 < < 1 2 14. wb‡Pi †KvbwU w¯’wZ¯’vcK ¸Yv¼ bq? [Bm&nvK, Avwgi] A. Bqs-Gi ¸Yv¼ B. `„pZv ¸Yv¼ C. cqm‡bi AbycvZ D. AvqZb weK…wZ ¸Yv¼ Ans C 15. NbZ¡wewkó Ges mv›`ªZv¼wewkó GKwU Zij r e¨vmv‡a©i GKwU miæ b‡ji ga¨ w`‡q cÖevwnZ n‡”Q| †ibì msL¨v N n‡e- [Bm&nvK, Avwgi] A. N = r 2 B. N = r 2 C. N = r D. N = 2r 2 Ans C 16. †ibì msL¨vi gvÎv †KvbwU? [Bm&nvK, Avwgi] A. [M0L 1T –1 ] B. [M0L 0T 0 ] C. [M0L 0T –1 ] D. [M0L 2T –2 ] Ans B 17. Bqs ¸Yv¼ †KvbwU? [Zcb, AvwRR] A. w¯ wZ¯ vcK mxgvi g‡a¨ eëZ©b cxob I eëZ©b weK…wZi AbycvZ B. w¯ wZ¯ vcK mxgvi g‡a¨ AvqZb cxob I AvqZb weK…wZi AbycvZ C. GKK cÖ¯ ‡”Q‡ì †¶Îdjwewkó †Kv‡bv Zv‡ii •`N©¨ eivei †h ej cÖ‡qvM Ki‡j •`N©¨ weK…wZ GKK nq D. w¯ wZ¯ vcK mxgvi g‡a¨ cvk¦© weK…wZ I •`N©¨ weK…wZi AbycvZ Ans C 18. wb‡Pi †Kvb ivwkwUi †Kv‡bv gvÎv †bB| [Zcb, AvwRR] A. Bqs ¸Yv¼ B. AvqZb ¸Yv¼ C. `„pZvi ¸Yv¼ D.cqm‡bi AbycvZ Ans D 19. msmw³ ej n‡”QA. wewfbœ c`v‡_©i AYyi g‡a¨ cvi¯úwiK AvKl©Y ej B. GKB c`v‡_©i wewfbœ AYyi g‡a¨ cvi¯úwiK AvKl©Y ej C. GKB c`v‡_©i wewfbœ AYyi g‡a¨ cvi¯úwiK weKl©Y ej D. wewfbœ c`v‡_©i AYyi g‡a¨ cvi¯úwiK weKl©Y ej Ans B 20. AvmÄb ej n‡”Q [Zcb, AvwRR] A. GKB c`v‡_©i wewfbœ AYyi g‡a¨ cvi¯úwiK AvKl©Y ej B. wewfbœ c`v‡_©i AYyi g‡a¨ cvi¯úwiK AvKl©Y ej C. GKB c`v‡_©i wewfbœ AYyi g‡a¨ cvi¯úwiK weKl©Y ej D. wewfbœ c`v‡_©i AYyi †fZi cvi¯úwiK AvKl©Y ej Ans D 21. M¨v‡mi mv›`ªZv mnM-Gi †Kjwfb ev cig ZvcgvÎvi- [Zcb, AvwRR] A. mgvbycvwZK B. e¨¯ÍvbycvwZK C. eM©g~‡ji mgvbycvwZK D. eM©g~‡ji e¨¯ÍvbycvwZK S C info M¨v‡mi mv›`ªZv: T 22. A-†cvjvi AYy¸‡jvi ga¨Kvi eÜb‡K Kx e‡j? [Zcb, AvwRR] A. AvqwbK eÜb B. mg‡hvRx eÜb C. wØ‡cvj-wØ‡cvj eÜb D. avZe eÜb Ans C 23. wZbwU wee„wZ †Ìqv n‡jv wb‡Pi †KvbwU wg_¨v? [Zcb, AvwRR] i. mev©‡c¶v Kg †h e‡ji wµqvq e¯‧ wQ‡o hvq ev †f‡O hvq Zv‡K Amn ej e‡j ii. wewfbœ c`v‡_©i AYyi g‡a¨ cvi¯úwiK AvKl©Y e‡ji bvg msmw³ ej iii. Zi‡ji gy³Z‡ji GKK †¶Îd‡j mwÂZ wefe kw³‡K ejv nq Zi‡ji c„ôkw³ A. i I iii B. i I ii C. ii I iii D. i, ii I iii Ans C 24. GKRb QvÎ †Kv‡bv avZe Zv‡ii Bqs¸Yv¼ wbY©‡qi Rb¨ cvV wb‡q Dc‡ii †jLwPÎwU AvuKj| wKš‘ †m X I Y A‡¶ Kx _vK‡e Zv wjL‡Z fy‡j †Mj| X Ges Y A‡¶ h_vµ‡g Kx _vK‡j fyj ejv hv‡e bv? [Zcb, AvwRR] Y X i. Szjv‡bv IRb I •`N©¨ e„w× ii. cÖhy³ cxob I •`N©¨ e„w× iii. cÖhy³ cxob I Drcbœ weK…wZ A. i I iii B. ii I iii C. i, ii I iii D. i I iii Y = FL Al = mgL r 2 l wZbwU †¶‡Î, †jLwPÎwU mwVK, †Kbbv mg l Ges F A l L

ASPECT PHYSICS cÖ_g cÎ c`v‡_©i MvVwbK ag© 291 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 25. †Kv‡bv wbw`©ó ¯’v‡b •KwkK b‡j DwÌZ cvwbi D”PZv (h) I •KwkK b‡ji e¨vmva© (r) Gi g‡a¨ wb‡¤œi †Kvb †jLwPÎwU mwVK? [Zcb, AvwRR] A. h 1 r B. h r C. h r D. h 1 r Ans D 26. mv›`ªZv wK‡mi m‡½ Zzjbxq? [Zdv¾j, gwnDwÏb] A. ej B. KvR C. Z¡iY D. Nl©Y Ans D 27. PK I †ev‡W©i AYyi g‡a¨ AvKl©Y ej‡K ejv nq- [Zdv¾j, gwnDwÏb] (i) mskw³ ej (ii) AvmÄb ej (iii) c„ô Uvb wb‡Pi †KvbwU mwVK? A. i B. ii C. i I ii D. iii Ans B 28. ej cÖ‡qv‡Mi d‡j †K‡bv e¯‘i AvKvi cwieZ©b n‡j Zv‡K e‡j- [Zdv¾j, gwnDwÏb] (i) †gvPo weK…wZ (ii) AvqZb weK„wZ (iii) K…šÍb weK…wZ wb‡Pi †KvbwU mwVK? A. i I ii B. ii I iii C. i I iii D. ii Ans C 29. wb‡Pi †Kvb m¤úK©wU û‡Ki m~Î †g‡b P‡j? [Mwb, mykvšÍ] A. cxob weK…wZ = aªæeK B. F = kx C. F = mg D. cxob = F A û‡Ki myÎ: cxob weK…wZ cxob weK„wZ = aªæeK F x = k F = kx ● ● ● E B P fvi O cÖmviY T 30. w¯’wZ¯’vcKZv mxgv AwZµg Ki‡j GKwU Zv‡ii ¯’vqx cÖmviY †_‡K hvq| wP‡Î ¯’vqx cÖmviY †KvbwU? [Mwb, mykvšÍ] A. OP B. BE C. OT D. TE P we›`y ch©šÍ fvi e„w× †c‡j •`N©¨ cÖmviY e„w× cvq| P we›`y‡K w¯ wZ¯ vcK mxgv aiv nq| ZviwUi ¯ vqx weK…wZ nj OT| 31. †Kvb Zi‡ji wfZ‡i cošÍ GKwU e¯‘i †¶‡Î †eM ebvg mgq †jLwPÎ †`Lv‡bv n‡jv| †Kvb ‡jLwPÎwU cÖvšÍ‡eM wb‡`©k K‡i? [Mwb, mykvšÍ] A. V T B. V T C. V T D. V T Ans D 32. w¯’wZ¯’vcKZvq cÖZ¨qbx ej n‡jv- [†gvK‡Q` m¨vi] A. KLbI AvKwl©Z KLbI weKwl©Z B. AvKwl©Z C. weKwl©Z D. k~b¨ Ans A 33. AvšÍtAvYweK ej n‡jv- [†gvK‡Q` m¨vi] A. Kzj¤^xq ej B. gnvKl© ej C. mv›`ª ej D. w¯ wZ¯ vcK ej Ans D 34. msbg¨Zv me‡P‡q †ewk †Kvb c`v‡_©i? [†gvK‡Q` m¨vi] A. KwVb B. Zij C. M¨vmxq D. cøvRgv Ans C wb‡Pi wPÎwU ch©‡e¶Y Ki Ges 35 I 36 bs cÖ‡kœi DËi `vI: L = 1m } l = 2cm Zv‡ii Avw` e¨vm = 5mm fvi cÖ‡qv‡Mi ci e¨vm = 4.99 mm 35. ZviwUi •`N©¨ weK…wZ | [Mwb, mykvšÍ] A. 0.02cm B. 0.02m C. 210–2 D. 2cm •`N©¨ weK…wZ = 2 2 2 10 1m 2 10 m L 36. w¯’wZ¯’vcK mxgvi g‡a¨ †Kvb †jLwPÎwU n‡Z •`N©¨ cÖmvi‡Yi †¶‡Î K…Z Kv‡Ri gvb wbY©q Kiv m¤¢e| [Mwb, mykvšÍ] A. m¤úªmviY fvi B. m¤úªmviY fvi C. m¤úªmviY fvi D. m¤úªmviY fvi K…Z KvR, r l mg , Y A L F 2 1 W 2 ‣`N©¨ cÖmviY ebvg fvi †jLwPÎ A¼b Ki‡j †jLwU g~j we›`yMvgx mij‡iLv n‡e| 37. Pvc evo‡j mv›`ªZvsK- [†gvK‡Q` m¨vi] A. ev‡o B. K‡g C. w¯ i _v‡K D. †KvbwUB bq Ans A 38. cigvYyi †¶‡Î- [†gvK‡Q` m¨vi] i) Gi ¯^vaxb Aw¯ Z¡ Av‡Q ii) Giv ivmvqwbK wewµqvq AskMÖnY K‡i iii) Giv Zwor wbi‡c¶ wb‡Pi †KvbwU mwVK? A. i) I ii) B. i) I iii) C. ii) I iii) D. i), ii) I iii Ans C wb‡Pi Aby‡”Q`wU co Ges 39 I 40 bs cÖ‡kœi DËi `vI: KuvPbj‡K †fRvq Giƒc GKwU Zi‡ji ¯úk© †KvY 30°| Zij I KuvPb‡ji ms¯úk© e„‡Ëi 5cm Ges Zi‡ji c„ôUvb 5 Ncm–1 39. Djø¤^ †iLv eivei c„ôUv‡bi Dcvs‡ki gvb- [†gvK‡Q` m¨vi] A.15.65 N B. 25.65 N C. 21.65 N D. 24.65 N Fcos = TLcos30° = 55 3 2 = 21.65N 40. b‡j wK cwigvY Zij D‡ËvwjZ n‡e? [†gvK‡Q` m¨vi] A. 2.2 kg B. 3.2 kg C. 4.2 kg D. 5.2 kg F = mg 55cos30° = m9.8 m = 2.2kg

292 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 41. hw` ¯úk© †KvY 180° Gi Kg Ges 90° -Gi †ewk nq, Z‡e •KwkK b‡j Zi‡ji Ae¯’v †Kgb n‡e? [†gvK‡Q` m¨vi] A. wb‡P bvg‡e B. Dc‡i DV‡e C. DVv-bvgv Ki‡e D. w¯ i _vK‡e Ans A 42. c„ôUv‡bi •ewkó¨ n‡jv- [†gvK‡Q` m¨vi] i. gy³ Zij Zj‡K msKzwPZ Kiv ii. Zij Z‡ji †¶Îdj e„w×‡Z evav †`q iii. Zij Z‡ji †¶Îdj e„w×‡Z mnvqZv Kiv wb‡Pi †KvbwU mwVK? A. i I ii B. ii I iii C. iii I i D. i, ii I iii Ans A 43. AvšÍtAvYweK ¯’v‡bi gvb n‡”Q- [†gvK‡Q` m¨vi] A.10–9 cm–10–10 cm B.10–9m–10–10m C. 10 9 cm–1010 cm D.109m–1010m Ans B 44. fi‡e‡Mi gvÎv I ‡¶Îd‡ji gvÎvi AbycvZ wb‡Pi ‡KvbwUi gvÎvi mgvb? [igv m¨vi] A. kw³ B. cøeZv C. mv›`ªZv ¸Yv¼ D. ¶gZv mv›`ªZv ¸Yv¼, = fi‡eM ‡¶Îdj = 1 1 2 1 ML T L MLT 45. L ‡`N©¨ Ges r e¨vmv‡a©i GKwU Zv‡ii Dcv`v‡bi Bqs Gi w¯’wZ¯’vcK ¸Yv¼ Y| hw` Zv‡ii •`N©¨ L 2 Ges e¨vmva© y 2 Kiv nq Zvn‡j Gi Bqs ¸Yv¼ n‡e- [igv m¨vi] A. y 2 B. Y C. 2Y D. 4Y y 2 r L L / 2 r Y L r L r Y r L r L Y 2 2 2 1 2 2 2 1 1 2 1 1 2 2 2 2 Y2 = 2Y 46. GKwU Zv‡i Bqs-Gi ¸Yv¼ 21011Nm–2 Zv‡ii •`N©¨ 1% e„w× Ki‡Z cÖhy³ cxob KZ n‡e? [BKivg m¨vi] A. 11012Nm–2 B. 21011Nm–2 C. 21012Nm–2 D. 2109Nm–2 Ans D 47. AvšÍtAvYweK ¯’v‡bi cwieZ©‡bi Rb¨ KwVb e¯‘i- [BKivg m¨vi] i) AvKv‡ii cwieZ©b nq ii) c„ôUv‡bi cwieZ©b nq iii) AvqZ‡bi cwieZ©b nq wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans B 48. Zij c`v‡_©i Ab¨Zg ag© n‡”Q- [kvgmyi m¨vi] i. mv›`ªZv ii. `„pZv iii. c„ôUvb wb‡Pi ‡KvbwU mwVK? A. i I ii B. ii I iii C. i I iii D. i, ii I iii Ans C 49. c„ôUv‡bi Dci cÖfve we¯Ívi K‡i- [kvgmyi m¨vi] i) `ywlZKiY ii) ‡P․¤^KZ¡ iii) ZwoZvwnZKiY wb‡Pi ‡KvbwU mwVK? A. i I ii B. ii I iii C. i I iii D. i, ii I iii Ans C 50. Ab¨vb¨ ivwk aªæe _vK‡j cÖvšÍ‡eM mv›`ªZv ¸Yv‡¼i- [kvgmyi m¨vi] A. mgvbycvwZK B. e¨¯ÍvbycvwZK C. e‡M©i mgvbycvwZK D. e‡M©i e¨¯ÍvbycvwZK Ans B 51. ej cÖ‡qv‡Mi d‡j GKwU Zv‡ii •`N©¨ 1% cwieZ©b n‡j e¨vm kZKiv KZ cwieZ©b n‡e? (cqm‡bi AbycvZ = 0.2). [kvgmyi m¨vi] A. 0.2% B. 0.1% C. 0.01% D. 0.02% = 0.2, 0.01 100 1 L l 3 2 10 D d D 0.01 d 0.2 Dl dL = 0.2% 52. wb‡Pi †KvbwU gvÎvMZ fv‡e w¯’wZ¯’vcK ¸Yv‡¼i mgZzj¨? [kvgmyi m¨vi] A. cxob B. weK…wZ C. ZjUvb D. Z¡iY cxob I w¯ wZ¯ vcK ¸Yv‡¼i gvÎv GKB, [ML–1T –2 ] STEP 4 MCQ CONCEPT TEST WRITTEN cÖkœ 01. 1.0 poiseA. 1 N/s B. 1 Ns C. 0.1 N/s D. 0.1 Ns 02. GKwU Zv‡ii Dcv`v‡bi Bqs ¸Yv¼ 2 × 1011 Nm–2 | ZviwUi •`N©¨ 25% evov‡Z cÖhy³ cxob wbY©q Ki| A. 2.12 × 1011 Nm–2 B. 5 × 1010 Nm–2 C. 1.568 × 10–6 m 2 D. 5 × 1011 Nm–2 03. 108 Nm–2 cxo‡bi cÖ‡qv‡M 1m `xN© GKwU Zv‡ii •`N©¨ e„w× †cj 10–3 m| ZviwUi Bqs ¸Yv¼ KZ? A. 105 Nm–2 B. 10–11 Nm–2 C. 1011 Nm–2 D. 10–5 Nm–2 04. GKwU Zv‡ii e¨vm 5 mm Ges •`N©¨ 1m| Gi •`N©¨ eivei ej cÖ‡qvM Kivi d‡j •`N©¨ 1 cm e„w× cvq wKš‘ e¨vm 0.01 mm n«vm cvq| cqm‡bi AbycvZ †ei Ki| A. 0.2 B. 0.4 C. 0.5 D. 0.6 05. 3 × 10–3 m e¨vmv‡a©i GKwU †MvjK †Kv‡bv Zi‡ji †fZi w`‡q 3 × 10–2 ms–1 cÖvšÍ‡eM wb‡q co‡Q| Zi‡ji mv›`ªZv¼ 1.5 × 10–3 Nsm–2 n‡j mv›`ª ej wbY©q Ki| A. 2.54 × 10–6 N B. 2.45 × 10–5 N C. 2.46 × 10–5 N D. 2.54 × 10–5 N 06. GKwU Zv‡i 0.01m •`N¨© weK…wZ‡Z cvk¦© weK…wZ 0.0024m n‡j Zv‡ii Dcv`v‡bi cqm‡bi AbycvZA. 10m B. 0.24m C. 0.12m D. 0.8m 07. 1mm2 cÖ¯’‡”Q` ‡¶Îdj wewkó GKwU B¯úv‡Zi Zv‡ii •`N©¨ kZKiv GKfvM e„w× Ki‡Z KZ ej cÖ‡qvM Ki‡Z n‡eA. 2x1011N B. 2x106N C. 2103N D. 106N 08. GKwU 1m Zv‡ii e¨vmva© 0.5 m H Zv‡i ej cÖ‡qvM Ki‡j 0.02m e„w× cvq| wKš‘ e¨vmva© 0.05 m K‡g hvq cqm‡bi AbycvZ n‡eA. 0.2 B. 0.1 C. 0.01 D. 5 09. GKwU †K․wkK bj cvwb‡Z AvswkK †Wvev‡bv| Gi A‡a©K e¨vmv‡a©i Avi GKwU †K․wkK bj cvwb‡Z AvswkK †Wvev‡bv n‡j Zvi g‡a¨Kvi cvwbi ¯Í‡¤¢i D”PZv cÖ_gwUi g‡a¨Kvi cvwbi ¯Í‡¤¢i D”PZvi Zzjbvq KZ n‡e? A. GK PZz_©vsk (one quarter) B. A‡a©K (Half) C. wØ¸Y (Double) D. Pvi¸Y (quadruple) 10. Zi‡ji †¶‡Î mv›`ªZvi mn‡Mi m‡½ ZvcgvÎvi m¤úK© n‡”QA. T B. T C. 2 T D. None of this 11. 1mm2 cÖ¯’‡”Q` wewkó GKwU B¯úv‡Zi Zv‡ii •`N©¨ 5% e„w× Ki‡Z KZ ej cÖ‡qvM Ki‡Z n‡e? A. 105N B. 104N C. 106 D. 0.1104N 12. 1 10–4m 2 cÖ¯’‡”Q‡`i †ÿÎdj wewkó GKwU B¯úv‡Zi Zv‡i KZ ej cÖ‡qvM Ki‡j •`N©¨ wØ¸Y n‡e? [Y = 2 1011Pa] A. 2 107N B 2 1011N C. 2 106N D. 2 105N 13. 2 10–4m 2 cÖ¯’‡”Q‡`i †ÿÎdj wewkó GKwU B¯úv‡Zi Zvi KZ ej cÖ‡qvM Ki‡j Gi •`N©¨ wØ¸Y n‡e? [Y = 2 1011Pa] A. 1 107 N B 2 107 N C. 3 107 N D. 4 107 N 14. 2mm e¨v‡mi GKwU †MvjK‡K 106 ‡QvU †QvU we›`y‡Z †¯cÖ Kiv n‡j e¨wqZ kw³i cwigvb KZ? [c„ôUvb = 7210-3N/m ] A. 4.510-5 J B. 910-5 J C. 110-4 J D. 910-4 J

ASPECT PHYSICS cÖ_g cÎ c`v‡_©i MvVwbK ag© 293 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 15. wb‡Pi †Kvb&wU mwVK? A. Al L YAl U / 2 1 2 B. L YAl U 2 2 1 C. Yl L l U 2 1 D. A W U 16. GKwU e¯‘i fi evZv‡m 50g I A¨vj‡Kvn‡j 42g| A¨vj‡Kvn‡ji NbZ¡ 0.4g/cc n‡j AvqZb KZ? A. 22 cc B 18 cc C. 15.5 cc D.32 cc 17. GKB Dcv`v‡bi `yBwU Zv‡ii e¨vmv‡a©i AbycvZ 2:1, Zvi `yBwU‡Z mgcwigvY ej cÖ‡qvM Ki‡j m„ó cxo‡bi AbycvZ n‡eA. 1 : 2 B 1: 4 C. 2 : 1 D. 4 : 1 18. `ywU mgvb •`‡N©ï Zvi A I B Gi e¨vm h_vµ‡g 110-3m I 410-3m Dfq‡K mgvb e‡j Uvb‡j A Gi •`N©¨ e„w× B Gi •`N©¨ e„w×i 4 ¸Y nq| A I B Gi Dcv`v‡bi Bqs Gi w¯’wZ¯’vcK ¸Yvs‡Ki Zzjbv KiA. 1:1 B. 1:2 C. 2:1 D. 4:1 E. 1:4 19. GKwU cvwbi †dvUvi e¨vm 210–3m| G‡K †f‡½ 109 wU mgAvqZ‡bi cvwbi ÿz`ª †duvUv •Zwi Ki‡Z wK cwigvY kw³ cÖ‡qvRb n‡e? (7210–3Nm–1 ) A. 9.03810–4 J B. 9.038 10–6 J C. 9.038 10–3 J D. 9.038 10–3 J 20. GKwU ÿz`ª †MvjvKvi e¯‘ †Kvb Zi‡ji ga¨ w`‡q cÖvšÍ †e‡M co‡Q| e¯‘i IRb 0.03N| e¯‘i Dci wµqviZ cøeZv 0.01N| e¯‘i Dci wµqviZ mv›`ª ej KZ? A. 0.02N B. 0.2N C. 2N D. 0.1N OMR SHEET 07. A B C D 14. A B C D 01. A B C D 08. A B C D 15. A B C D 02. A B C D 09. A B C D 16. A B C D 03. A B C D 10. A B C D 17. A B C D 04. A B C D 11. A B C D 18. A B C D 05. A B C D 12. A B C D 19. A B C D 06. A B C D 13. A B C D 20. A B C D WRITTEN PART 21. 1 cm2 cÖ¯’‡”Q` wewkó GKwU B¯úv‡Zi Zv‡i KZ kg fi Szjv‡j Gi •`N©¨ wØ¸Y n‡e? (B¯úv‡Zi Bqs Gi ¸bvs¼ 2×1012 dynecm-2 ) 22. Zvgvi Zv‡ii Bqs Gi ¸Yv‡¼i gvb 21011Nm–2 | 1 cm2 cÖ¯’‡”Q` wewkó Zvgvi Zvi‡K †U‡b wØ¸Y j¤^v Ki‡Z KZ e‡ji cÖ‡qvRb n‡e? 23. 200 mm e¨vmv‡a©i GKwU †MvjK †Kvb Zi‡ji wfZi w`‡q 2.110–2ms–1 cÖvšÍ‡eM wb‡q co‡Q| H Zi‡ji mv›`ªZv¼ 0.003 N sm–2 n‡j mv›`ª e‡ji gvb KZ n‡e? 24. 2mm2 cÖ¯’‡”Q‡ì GKwU Zv‡ii mv‡_ 15 kg fi Sz‡j Av‡Q| fi Syjv‡bv Ae¯’vq ZviwUi •`N©¨ 4m| Zv‡ii Dcv`v‡bi Bqvs Gi ¸YvsK 1.31010 Nm–1 | fi mwi‡q wb‡j ZviwUi •`N©¨ wK cwigvb msKzwPZ n‡e? 25. GKwU Kcvi ej‡K 20C ZvcgvÎvi GKwU †Z‡ji U¨vs‡K †djv nj| ejwUi cÖvwšÍK †eM 6.5cms–1Ges e¨vmv_© 2.0mm| †Z‡ji NbZ¡ 1.5×103 kgm–3 Ges Kcv‡ii NbZ¡ 8.9×103 kgm–3 †Z‡ji mv›`ªZv ¸Yv¼ KZ? 26. 0.2mm e¨v‡mi GKwU †K․wkK b‡j cvwbi Av‡ivnb wbY©q Ki| (cvwbi c„ôUvb = 72×10-3Nm-1 ) 27. GKwU Zv‡ii Dcv`v‡bi Bqs Gi ¸YvsK 2×1011N/m2 | ZviwUi •`N¨© 15% e„w× Ki‡Z cÖhy³ cxob †ei Ki| 28. GKwU eo cvwbi †duvUv‡K 27 wU mgvb †QvU KYvq iƒcvšÍwiZ Kiv nj| cÖ‡Z¨KwU †QvU KYvi e¨vm 6mm. cÖ‡Z¨KwU †QvU cvwb KYvi PvR© 10C n‡j eo cvwbi KYvi e¨vmva© KZ? 29. GK wgwjwgUvi e¨vmv‡a©i GK †duvUv cvwb‡K `k j¶ mgvb e¨vmv‡a©i †duvUv‡Z cwiYZ Kiv n‡jv| c„ôkw³ e„w×i gvb KZ? 30. 2×1011 Nm-2 Bqs gvbvsK wewkó B¯úv‡Zi Zv‡ii •`N©¨ 1m Ges cÖ¯’‡”Q‡ì †ÿÎdj 1m2 | ZviwU †U‡b 1mm cÖmvwiZ Ki‡j KZ Ryj KvR m¤úbœ n‡e? MCQ ANSWER ANALYSIS WRITTEN cÖkœ bs DËi e¨vL¨v 01 D 02 B Y = cÖhy³ cxob weK…wZ cÖhy³ cxob = Y × weK…wZ = 2 × 1011 × 25 100 = 5 × 1010 Nm–2 03 C Y = •`N©¨ cxob •`N©¨ weK…wZ = 108 10–3 = 1011 Nm–2 04 A = dL Dℓ = 0.01 × 10–3 × 1 5 × 10–3 × 1 × 10–2 = 0.2 05 A F = 6rv = 6×× 1.5 × 10–3 × 3 × 10–3 × 3 × 10–2 = 2.54 × 10–6 N 06 B cvk¦© weK…wZ ‣`N©¨ weK…wZ = 0.0024 0.01 ev, 0.24 07 C Al FL Y ev, L YAl F 100 2 10 1 10 1 11 6 N 3 210 08 D cqm‡bi AbycvZ, cvk^© weK…wZ •`N©¨ weK…wZ = dL Dl = 0.05 1 0.5 0.02 = 5 ‣`N©¨ weK…wZ

294 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES cÖkœ bs DËi e¨vL¨v 09 C h1r1 = h2 r2 ev 2 1 1 2 r r h h ev 2 2 1 1 1 2 h h (wØ¸Y) 10 D Zij c`v‡_©i mv›`ªZv mnM ZvcgvÎv e„w×i mv‡_ `ªæZ n«vm cvq| 11 B Al FL Y ev, L YAl F N L Y l F 4 11 6 10 100 2 10 10 5 12 A F = (n – 1) YA = (2 – 1) 2 1011 1 10–4 = 2 107 (n = •`‡N©¨i ¸Y) 13 D F = YA = 2 1011 2 10–4 = 4 107 N 14 C 1 3 R nr ev, 3 3 6 1 1 10 10 1 r = 3 5 2 10 10 10 1 kw³ = 8(Nr2 – R 2 )T 8{106 (10-5 ) 2 –(10–3 ) 2 }7210–3 =110-4N 15 B 16 A e¯‧i evZv‡m IRb w = 50g; e¯‧i A¨vj‡Kvn‡j IRb wa / = 42g; nviv‡bv IRb = 50 – 42 = /8g AcmvwiZ A¨vj‡Kvn‡ji AvqZb 8 0.4 = 20cc e¯‧i AvqZb = 20cc 17 B 18 D 2 3 3 2 1 10 4 10 4 1 dA dB L L Y Y A B B A = 4:1 1 4 19 10–3 e¨vmv‡a©i GKwU cvwbi †duvUv 109 wU ÿz`ª n‡j e¨mva©, R = R 3 N = 10–3 3 109 = 10–6N E = 4 (Nr2 – R 2 ) T = 4 3.14 (109 10–12 –10–6 ) 72 10–3 = 9.038 10–4 J 20 A e¯‧i Dci wµqviZ mv›`ª ej = e¯‧i IRb – cøeZv = 0.03N – 0.01N = 0.02N 21 Al mgL Y gl YAL m 10 12 2 10 981 L 2 10 1 L 22 •`N©¨ n ¸Y evo‡j ej, F = YA(n 1) = 2 1011 104 (2 1) = 2 107N 23 F = 6rv = 6 0.003 200 103 2.1 102 = 2.374 10–4 N 24 Y = Fl1 A(l2l1) 1.3 1010 = 15 9.8 l1 2 10-6 (4 l1) = 26000 ( 4 l1) = 147l1 l1 = 3.977511m ms‡KvPb = l2 l1 = (4 3.977511) = 0.022489m 25 V = 9 2r ( ) 2 g ev, = 9V 2r ( ) 2 g; ev = 1.011 kgm3 s 1 26 T= hgr 2 h=2T gr = 0.1 10 10 9.8 2 72 10 3 3 3 = 0.1469m 27 Bqs ¸YvsK = cxob weK…wZ cxob = Bqs ¸YvsK × weK…wZ cxob = 2 × 1011 100 15 = 3×1010 Nm-2 28 3 r 3 3 4 R 27 3 4 R 3 = (3r)3 R = 3 3 = 9mm = 9 10-3m 29 v = v 4 3 r 3 = 4 3 r 3 × 106 R = r × 102 r = 1 × 10–3 102 r =10–5m w = A × T = 4 {106 × (10–5 ) 2 – (10–3 ) 2 } × 72 × 10–3 = 8.957 × 10–5 g = 895.75 erg 30 L YAl 2 1 W 2 10 J 1 2 10 (1 10 ) 2 1 5 11 3 2

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 295 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES SURVEY TABLE  Kx coe? †Kb coe? †Kv_v n‡Z coe? KZUzKz coe?  TOPICS MAGNETIC DECISION [hv co‡e] MAKING DECISION [†h Kvi‡Y co‡e] VVI For This Year DU JU RU CU GST Engr. HSC Written MCQ THEORY CONCEPT-01 ch©ve„wËK MwZi aviYv I cÖKvi‡f` 35% 40% 45% 40% 45% 05% 35% - CONCEPT-02 mij Qw›`Z ¯ú›`b/mij †`vjb MwZi Z_¨vejx 30% 35% 30% 35% 40% 10% 40% CONCEPT-03 †`vj‡Ki cÖKvi‡f` Ges e¨envi 40% 35% 40% 45% 50% 15% 60% CONCEPT-04 mij †`vj‡Ki m~Îvejx 20% 25% 30% 35% 30% - 20% - CONCEPT-05 †`vjbKvj hLb evo‡e ev Kg‡e 50% 45% 50% 55% 50% 20% 60% CONCEPT-06 mij Qw›`Z MwZmsµvšÍ †jLwPÎ 65% 60% 65% 60% 65% 40% 65% MvwYwZK cÖ‡qvM CONCEPT-01 mij Qw›`Z MwZi m~Îvejx msµvšÍ MvwYwZK cÖ‡qvM 80% 85% 80% 75% 85% 65% 70% CONCEPT-02 w¯úªs msµvšÍ MvwYwZK cÖ‡qvM 65% 60% 65% 70% 75% 45% 30% - CONCEPT-03 mij †`vjK msµvšÍ MvwYwZK cÖ‡qvM 70% 75% 70% 75% 70% 35% 50% CONCEPT-04 MÖn msµvšÍ MvwYwZK cÖ‡qvM 75% 70% 75% 80% 80% 65% 65% CONCEPT-05 ÎæwUc~Y© †`vj‡Ki †`vjbKvj 70% 75% 70% 75% 70% 60% 50% DU. = Dhaka University, JU. = Jahangirnagar University, RU. = Rajshahi University, CU = Chittagong University, GST = General, Science & Technology, Engr. = Engineering. STEP 1 mvRv‡bv me Z_¨ THEORY fwZ© †ivMxi c_¨ Concept 1 ch©ve„wËK MwZi aviYv I cÖKvi‡f` ✅ ch©ve„Ë MwZ: hw` †Kvb MwZkxj e¯‘ KYvi MwZ Ggb nq †h, GwU Gi MwZc‡_i †Kvb wbw`©ó we›`y‡K wbw`©ó mgq ci ci GKB w`K †_‡K AwZµg K‡i Z‡e Zv‡K ch©ve„Ë MwZ e‡j| D`vniY- mij †`vj‡Ki MwZ evqy gva¨‡g kã mÂvj‡bi mgq evqy KYvi MwZ KwVb e¯‘‡Z cigvYyi ¯ú›`b MwZ miæ h‡š¿i ev evqy gÛ‡ji MwZ Nwoi KvuUvi MwZ myZvq evav cv_‡ii MwZ (e„Ëxq) cv¤ú ev †c‡Uªvj BwÄ‡bi wmwjÛv‡i wc÷‡bi MwZ w¯cÖs G SzjšÍ e¯‘i MwZ m~‡h©i Pviw`‡K c„w_exi MwZ (Dce„Ëxq)| ✅ ch©ve„wËK MwZ `yB cÖKvi, h_v: ¯’vwbK ch©vqµg I KvwjK ch©vqµg ✅ ch©ve„Ë MwZ m¤úbœ †Kvb KYvi MwZ c_- (1) mij •iwLK, (2) e„ËvKvi (3) Dce„ËvKvi n‡Z cv‡i ◈ ¯ vwbK ch©vqµg: ‡Kvb e¯‘i MwZ hw` Ggbfv‡e cybive„wË nq †h wbw`©ó mgq ci ci †Kvb wbw`©ó we›`y‡K GKB w`K †_‡K AwZµg K‡i Z‡e, Zv‡K ¯’vwbK ch©vqµg e‡j| ¯’vwbK ch©vqµ‡gi †¶‡Î, y = sin (t, x)| D`vniY- Nwoi KvuUvi MwZ m~‡h©i Pviw`‡Ki MÖn‡`i MwZ GKwU Djø¤^ w¯cÖs Gi MwZ Zi‡½i Dcwiw¯’Z †Kvb KYvi MwZ ùwU‡Ki gvSLv‡b cigvYyi Kvh©µg FZz cwieZ©b †Rvqvi fvUv nvU© weU mij †`vj‡Ki MwZ avb †¶‡Z †XD‡qi MwZ B‡jKwUªK †cvj cÖf…wZ ◈ ¯ vwbK ch©vqµ‡gi D`vniY g‡b ivLvi †K․kj: Nvm †Zvj Nv m ‡Zv j Nwoi KuvUvi MwZ m~‡h©i Pvicv‡k MÖn¸‡jvi MwZ Zi‡½i Dcwiw¯’Z †Kvb KYvi MwZ Djø¤^ w¯úªs Gi MwZ ✅ KvwjK ch©vqµg: †Kvb ivwk ev dvsk‡bi gvb Ggb nq †h GwU wbw`©ó mgq ci ci GKB gvb MÖnY K‡i Z‡e Zv‡K KvwjK ch©vqµg e‡j| KvwjK ch©vqµ‡gi †¶‡Î, y = sin (t)| D`vniY- Zwor cÖevn / ch©ve„Ë Zwor cÖevn jvwU‡gi MwZ ürwc‡Ûi MwZ m~‡h©i Pviw`‡K c„w_exi MwZ Nwoi †m‡KÛ ev wgwb‡Ui KuvUvi MwZ ch©ve„wËK MwZ PERIODIC MOTION cÖ_g cÎ 08 Aa¨vq c„ôv 295

296 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF GST QUESTION PART A Analysis of Science & Technology Question HSTU 01. wmwjÛv‡ii g‡a¨ wc÷‡bi MwZ GKwU? [HSTU. 14-15] A. ‡`vjb MwZ B. N~Y©b MwZ C. ch©ve„Ë MwZ D. Dc‡ii me¸wj Ans C STEP 02 ANALYSIS OF ENGINEERING & BUTex QUESTION BUET 01. c„w_ex c„‡ôi Dc‡i †Kvb evqygÛj bv _vK‡j GKwU w`e‡mi mg‡qi e¨wß- [BUET. 14-15; KUET. 14-15] A. n«vm cv‡e B. e„w× cv‡e C. GKB _vK‡e D. AvenvIqvi Dci wbf©i K‡i Ans C STEP 03 ANALYSIS OF HSC BOARD QUESTION 01. K¤úv‡¼i GKK n‡jv- [Kz. †ev. 2015] A. Cycle s–1 B. Cycle C. Hertz D. A I C DfqB Ans D 02. KvwjK ch©vqµ‡gi D`vniY †KvbwU? [wm.‡ev 2021] A. ‡¯‥‡ji Dci `vM B. kv‡U©i †WvivKvUv `vM C. wMUv‡ii Zv‡ii MwZ D. KwVb c`v‡_©i †Kjv‡mi g‡a¨ AYy Ans C Concept 2 mij Qw›`Z ¯ú›`b/mij †`vjb MwZi Z_¨vejx ✅ mij Qw›`Z ¯ú›`b/ mij †`vjb MwZ: hw` †Kvb e¯‘i Z¡iY GKwU wbw`©ó we›`y †_‡K Gi mi‡Yi mgvbycvwZK Ges me©`v H we›`y AwfgyLx nq| Zvn‡j e¯‘i GB MwZ‡K mij †`vjb MwZ e‡j| D`vniY- Nwoi e¨vjvÝ Pµ wMUv‡ii K¤úgvb Zv‡ii MwZ w¯cÖs Gi Djø¤^ K¤úb K¤úgvb myi kjvKvi MwZ Kg we¯Ívi (4°) mij †`vj‡Ki MwZ cvwb‡Z m„ó Zi‡½i †¶‡Î cvwb KYvi MwZ| ◈ we:`ª: e¨eZ©bx †`vj‡Ki MwZ mij Qw›`Z †K․wYK ¯ú›`b a = 0 v = max a = max v = 0 mij‣iwLK MwZ Z¡iY mi‡Yi mgvbycvwZK I wecixZgyLx a = max mvg¨ve¯’vb mvg¨ve¯’vq m‡e©v”P we¯Ív‡i a = 0 a = maximum x = 0 x = maximum v = maximum v = 0 Ek = maximum Ek = 0 a(g) Ep = 0 Ep = maximum x we¯Ív‡ii cÖv‡šÍ †eM k~b¨ ga¨ve¯’v‡b Z¡iY k~b¨ ga¨ve¯’v‡b ‡eM me©vwaK wbw`©ó we¯Ív‡ii Rb¨ †gvU kw³ aªæe _v‡K m‡e©v”P MwZkw³ we¯Ív‡ii e‡M©i mgvbycvwZK we¯Ív‡ii cÖv‡šÍ Z¡iY me©vwaK KYvi †gvU kw³ we¯Ív‡ii e‡M©i mgvbycvwZK Ges mi‡Yi Dci wbf©i K‡i bv ✅ mij Qw›`Z ¯ú›`‡bi •ewkó¨: MwZ ch©ve„Ë MwZ GB ai‡bi MwZi e‡ji MwZc_ mij‣iwLK GwU GKwU ¯ú›`b MwZ Z¡iY mi‡Yi wecixZ gyLx Z¡iY mi‡Yi mgvbycvwZK wbw`©ó mgq AšÍi MwZ wecixZgyLx Z¡iY e¯‘ KYvi ga¨ Ae¯’vb AwfgyLx ga¨we›`y †_‡K cÖvšÍ we›`yØ‡qi `~iZ¡ mgvb miY‡K sin Ges cos Gi A‡c¶K Øviv cÖKvk Kiv hvq| ✅ ¯ú›`b MwZ/ †`vj MwZ: ch©ve„Ë MwZ m¤úbœ †Kvb e¯‘ hw` ch©vqKv‡ji A‡a©K mgq †Kvb wbw`©ó w`‡K Ges evwK A‡a©K mgq GKB c‡_ Zvi wecixZ w`‡K P‡j Zvi GB MwZ‡K ¯ú›`b MwZ e‡j| D`vniY- w¯cÖs Gi MwZ †Pv‡O Ave× M¨v‡mi K¤úb †`qvj Nwoi †`vj‡Ki MwZ KwVb e¯‘‡Z cigvYyi MwZ K¤úbkxj myi kjvKvi MwZ BwÄ‡bi wc÷‡bi MwZ wMUv‡ii Zv‡ii MwZ kã mÂvj‡bi mgq evqy KYvi MwZ U b‡ji g‡a¨ Zi‡ji ¯ú›`b ✅ ¯ú›`biZ †Kvb e¯‧i mvg¨ve¯ v‡b: miY k~b¨ Ñ Z¡iY k~b¨ Ñ †eM m‡e©v”P ◈ c~Y© †`vjb : †Kvb GKwU K¤úgvb e¯‘ GKwU we›`y n‡Z hvÎv ïiæ K‡i cybivq GKB w`K †_‡K H we›`y‡Z wd‡i Avm‡j †h K¤úb m„wó nq Zv‡K c~Y© †`vjb ev K¤úb e‡j| ◈ †`vjb ev ch©vq Kvj : †Kv‡bv GKwU mij †`vj‡Ki †`vjK wc‡Ûi GKwU c~Y© †`vjb w`‡Z †h cwigvY mgq jv‡M Zv‡K †`vjb Kvj e‡j| mgxKiY : T = 2 m k ; T = t N GLv‡b, T = ch©vqKvj/‡`vjbKvj ; t = mgq ; N = K¤úb msL¨v GKK : †m‡KÛ (s)

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 297 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ◈ K¤úv¼ : †Kv‡bv K¤úgvb e¯‘ ev ¯ú›`K GKK mg‡q hZ¸‡jv c~Y© †`vjb †`q Zv‡K K¤úv¼ e‡j| G‡K n Øviv m~wPZ Kiv nq| mgxKiY : n = 1 T = 2 = 1 2 K m GKK : K¤úv‡¼i GKK nvR© (Hz) ev cycle s–1 ev frequency s–1 ◈ we¯Ívi : `yjevi mgq †Kv‡bv GKwU mij †`vj‡Ki †`vjK wcÛ mvg¨ve¯’v n‡Z me©v‡cÿv hZUv †ewk `~‡i hvq Zv‡K Zvi we¯Ívi e‡j| cÖKvi‡f` : we¯Ívi `yB cÖKvi| h_v- (i) ‣iwLK we¯Ívi : G‡K A Øviv cÖKvk Kiv nq| (ii) †K․wYK we¯Ívi : G‡K Øviv cÖKvk Kiv nq| GKK : (i) •iwLK we¯Ívi : m ev cm (ii) †K․wYK we¯Ívi : radian (rad) ◈ †K․wYK K¤úv¼ : mij Qw›`Z ¯ú›`b m¤úbœ †Kv‡bv KYv GKK mg‡q †h †K․wYK `~iZ¡ AwZµg K‡i Zv‡K †K․wYK K¤úv¼ e‡j| G‡K Øviv m~wPZ Kiv nq| mgxKiY : = 2 T = 2n = 2 1 2 K m GKK : Gi GKK †iwWqvb/†m‡KÛ (rad s–1 ) ◈ `kv : mij Qw›`b ¯ú›`biZ †Kv‡bv e¯‘ ev KYvi †h‡Kv‡bv gyn~‡Z©i MwZi Ae¯’v‡K (miY, †eM, Z¡iY BZ¨vw`) Gi `kv e‡j| ◈ `kv cv_©K¨ : x = A sin (t + ) we¯Ívi (mgq wbi‡cÿ Ask) `kvi Ask (mgq wbf©i Ask) ◈ †K Avw` `kv ev cÖviw¤¢K `kv ev `kv aªæeK ejv nq| `yBwU Qw›`Z MwZi ¯ú›`b, xi = sin t Ges x2 = A sin (t + ). `kv cv_©K¨ ◈ `kv cv_©‡Kï †ÿ‡Î: `kv cv_©K¨ = 2 c_ cv_©K¨ i) `kv cv_©K¨ = ev 2 ev = 2n (n = 0, 1, 2, .......) nq Z‡e G‡ì MwZi Ae¯’v memgqB GKB _vK‡e| G ai‡bi MwZ mg`kvq i‡q‡Q| ii) = A_ev = (2n + 1), (n = 0, 1, 2, ..........) n‡j wecixZ `kvq Av‡Q| iii) = 2 A_©vr 90 nq, Z‡e G‡ì KYvi ¯ú›`bMwZ ci¯úi j¤^ eivei| hv‡ì g‡a¨ m¤úK© mgxKiY miY I we¯Ívi x = A sin (t + ) = A sin 2 nt †eM I we¯Ívi v = Acost = A 2 – x 2 Z¡iY I miY a = – 2 x = – 2A sint fi, ch©vqKvj I ej aªæeK T = 2 m k `kv cv_©K¨ I c_ cv_©K¨ `kv cv_©K¨ = 2 c_ cv_©K¨ / = 2 x REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. GKwU m f‡ii e¯‧ Nl©Ywenxb GKwU Z‡j v †e‡M Pjvi mgq GKwU w¯úªsGi mv‡_ av°v †j‡M w¯úªswU‡K msKzwPZ Kij| w¯úªswUi ej-aªæeK k n‡j w¯úªswU KZUzKz msKzwPZ n‡e? [DU. 20-21] A. m k v B. k m v C. kv D. mv S A info kw³i msiÿYkxjZvi bxwZ Abyhvqx, wm‡÷‡gi MwZkw³ = wm‡÷g Øviv AwR©Z w¯’wZkw³ ev wm‡÷‡g mwÂZ wefekw³ w¯úªs‡q av°v †Ìqv e¯‘i nviv‡bv MwZkw³ = ms‡KvP‡bi d‡j w¯úªs‡q mwÂZ wefekw³ 1 2 mv2 = 1 2 kx2 v 2 = k m x 2 AZGe, x = m k v 02. mij Qw›`Z MwZ‡Z ¯ú›`biZ `ywU KYvi miY- x1 = Asint x2 = Acost, †h †Kvb mg‡q G‡ì g‡a¨ `kv cv_©K¨ KZ n‡e? [DU.A 19-20] A. 2 B. C. /2 D. /4 S C info `ywU KYv x1 = Asin t I x2 = Acost ; t mgq cÖ_g KYvi `kv †KvY t; t mgq wØZxq KYvi `kv †KvY t 2 †h †Kvb mg‡q G‡ì g‡a¨ `kv cv_©K¨ = t + 2 t = 2 STEP 02 ANALYSIS OF JU QUESTION 01. ‡`vjb msL¨v N, mgq t Ges K¤úvsK n Gi g‡a¨ m¤úK© n‡jv [JU. 12-13] A. N = n t B. n = t N C. N = nT D. N = n t 2 Ans C 02. Ae¯ vb mv‡c‡¶ GK Pµ cwigv‡Y Mo MwZkw³ n‡e- [JU. 11-12; CoU. 10-11] A. 2 3 †gvU kw³ B. 3 2 †gvU kw³ C. 3 1 †gvU kw³ D. 2 1 †gvU kw³ Mo MwZkw³ = 2 1 m‡e©v”P MwZkw³ = 2 2 1 2 1 ka 2 2 2 1 2 1 m a Mo w¯’wZkw³ = 2 1 †gvU kw³ 03. mij Qw›`Z MwZ ev ¯ú›`b Gi †¶‡Î ‡K․wYK †eM- [JU. 10-11] A. = m k B. = k m C. = 2 m k D. = 2 k m Ans B 04. GKwU †m‡KÛ †`vjK‡K c„w_ex c„ô n‡Z wb‡q N~Y©vqgvb K…wÎg DcMÖ‡ni Af¨šÍ‡i ¯ vcb Ki‡j Zvi †`vjbKvj n‡e- [JU. 09-10] A. sec B. 0 sec C. 2 sec D. 4 sec K…wÎg DcMÖ‡ni Af¨šÍ‡i, g = 0 †`vjbKvj, T = 2 g L =2 0 L =

298 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES STEP 03 ANALYSIS OF RU QUESTION 01. f(x – vt) = constant mgxKiYwU †KvbwUi †ÿ‡Î cÖ‡hvR¨? [RU. 18-19] A. mg‡e‡M MwZkxj AMÖMvgx Zi‡½i B. w¯’i e¯‘KYvi C. PµvKvi c‡_ Pjgvb e¯‘i D. mij †`vj‡Ki Ans B 02. K¤úv¼ (f) I ch©vqKvj (T) Gi m¤úK© †KvbwU? [RU. 17-18] A. f = 1 T B. f = T C. T = 2f D. f = 2T Ans A 03. ‡dvU‡bi fi‡eM †KvbwU? [RU. 15-16] A. P = hc B. P = h C. P = h D. P = hc P = mc = hv c = h †dvU‡bi fi‡eM| 04. mij Qw›`Z ¯ú›`‡b we¯Ívi A n‡j ¯úw›`Z KYvi wefe kw³ m‡e©v”P n‡e hLb miY- [RU. 15-16] A. A B. A 2 C. A 2 D. 0 Ans A 05. mij Qw›`Z MwZi •ewkó¨ bq †KvbwU? [RU. 09-10] A. GwU ch©vq MwZ B. mij •iwLK MwZ C. †K․wYK MwZ D. †KvbwUB bq Ans C 06. mij †`vjbMwZ m¤úbœ GKwU e¯‧i we¯Ívi a, K¤úvsK n †`vjb Kvj t n‡j wb‡gœi †KvbwU Gi mgxKiY? [RU. 07-08] A. x = asinnt B. x = asin2nt C. t dx a t n x a cos 2 sin D. t dx a t n x a cos 2 sin Ans B STEP 04 ANALYSIS OF CU QUESTION 01. ch©vqKvj I ej aªæe‡Ki g‡a¨ wb‡Pi m¤úK© †KvbwU? [CU-A, Set-3. 20-21] A. T = 2 k m B. T = 2 k mg C. T = 2 m K D. T = 2 mg k S C info F = kx GLv‡b, k w¯úªswUi ej aªæeK| e¯‘‡K †Q‡o w`‡j F e‡ji ìæY †mwU a Z¡iY wb‡q P‡j| e¯‘wUi fi m n‡j Gi Z¡iY n‡e, a = F m = F m x a = kx †h‡nZz, k = k m = aªæeK| AZGe e¯‘i MwZ mij †`vjb MwZ n‡e| †h‡nZz GKK mi‡Y e¯‘i Z¡iY = k m | myZivs †`vjbiZ e¯‘i ch©vqKvj, T = 2 m k e¯‘i IRb mg-Gi wµqvi w¯úªswUi •`N©¨ l cwigvY †e‡owQj| 02. 2 `kv cv_©K¨‡Z T ch©vqKv‡ji GKwU c~Y© K¤ú‡bi †K․wYK K¤úv¼ KZ? [CU-A, Set-4. 20-21] A. = 2T B. =2/f C. =T/2 D. =2/T S D info Avgiv Rvwb, †Kv‡bv KYv e„ËvKvi MwZc‡_ T mgq 2 †iwWqvb AwZµg Ki‡j †K․wYK †eM = 2/T 03. mij Qw›`Z MwZm¤úbœ KYvi MwZc‡_i mvgë¯ v‡b.... [CU. 16-17] A. ‡eM me©vwaK, miY me©wb¤œ B. ‡eM me©wb¤œ, miY me©wb¤œ C. ‡eM me©vwaK, miY me©vwaK D. ‡eM me©wb¤œ, miY me©vwaK V = A 2 x 2 miY, x = 0 A_©vr KYvi MwZc‡_i mvgë¯’vb V = A 2 0 2 Vmax = A A_©vr †eM me©vwaK, miY me©wb¤œ| STEP 05 ANALYSIS OF DU-7 Clg QUESTION 01. mij †`vj MwZ‡Z wb‡¤œi †Kvb welqwU †`vj‡bi we¯Ív‡ii Dci wbf©ikxj bq? [DU-7Clg.A.19-20] A. Z¡iY B. †gvU kw³ C. K¤úvsK D. †eM mij †`vjb MwZ‡Z K¤úv¼, we¯Ívi I †K․wYK †e‡Mi †Kvb cwieZ©b nq bv| STEP 06 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. mij Qw›`Z ¯ú›`b Gi ‡¶‡Î ‡KvbwU mwVK mgxKiY? [JnU. 15-16] A. 0 2 2 2 x dy d x B. 0 2 2 2 x dt d x C. 0 2 2 2 t dt d x D. 0 2 2 2 y dy d x Ans B 02. mij Qw›`Z ¯ú›`b G ¯ú›`bkxj KYvi †eM k~b¨ nq- [JnU. 14-15] A. hLb Z¡iY m‡e©v”P nq B. hLb miY me©wbgœ nq C. hLb miY m‡e©v”P nq D. hLb Z¡iY me©wbgœ nq Ans C 03. GKwU mij Qw›`Z ¯ú›`‡bi MwZi mgxKi‡bi mgvavb- [JnU. 10-11] A. y = Asin(t + ) B. y = Acos (t + ) C. y = A expi (t + ) D. me¸‡jv Ans D KU 01. mij †`vj‡Ki †`vjbKvj wØ¸Y Kivi Rb¨- [KU. 15-16] A. ‣`N©¨ wØ¸Y Ki‡Z n‡e B. ‣`N©¨ Pvi¸Y Ki‡Z n‡e C. e‡ei fi wØ¸Y Ki‡Z n‡e D. e‡ei ei Pvi¸Y Ki‡Z n‡e L2 = (n2 ) L1(n = ‡`vjb Kv‡ji ¸Y) ev, L2 = 22 L = 4L 02. e¯‧ cÖwZ †m‡K‡Û hZ¸‡jv c~Y© N~Y©b m¤úbœ K‡i Zv‡K ejv nqÑ [KU. 13-14] A. ch©vq Kvj B. ‡K․wbK †eM C. K¤úv¼ D. •iwLK `ªæwZ Ans C CoU 01. mij Qw›`Z ¯ú›`‡b GK ch©vqKvj Mo w¯ wZ kw³ [CoU. 08-09, 07-08] A. 1 2 m 2A 2 B. 1 4 m 2A 2 C. m 2A 2 D. k~b¨ Ans A PART B Analysis of Science & Technology Question SUST 01. mij Qw›`Z MwZi mgxKiY †KvbwU? [SUST. 14-15] A. y = A sin(kx-t) B. y = A sin(vt-x) C. y = A cos(t-) D. y = A cos(kx-) E. y = A sin 2nx Ans C MBSTU 01. mij Qw›`Z ¯ú›`‡b ¯úw›`Z KYvi ‡¶‡Î 1 2 kA2 n‡”Q- [MBSTU. 15-16] A. m‡e©v”P MwZ kw³ B. m‡e©v”P wefe kw³ C. ‡gvU kw³ D. me¸‡jvB wVK Ans D 02. mij Qw›`Z ¯ú›`‡b ¯úw›`Z GKwU KYvi K¤úvsK wbf©i K‡i- [MBSTU. 14-15] A. ej aªæe‡Ki Dci B. cÖZ¨vqbx e‡ji Dci Ans D C. KYvwUi f‡ii Dci D. KYvwUi fi I ejaªæeK DfqwUi Dci 03. mij Qw›`Z ¯ú›`‡b GKwU KYvi we¯Ívi Xmax = A. ‡Kv_vq KYvwUi wefe kw³ me©wb¤œ n‡e? [MBSTU. 14-15] A. x = 0 †Z B. x = A †Z C. x = 1 2 A †Z D . x = A †Z Ans C

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 299 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES DU Technology 01. mij Qw›`Z ¯ú›`‡b ¯úw›`Z GKwU e¯‧i ¯ú›`‡bi we¯Ívi A n‡j, e¯‧wUi MwZkw³ m‡e©v”P n‡e hLb miY- [DU-Tech. 19-20] A. 2 A B. 2 A C. 0 D. A K.E = 1 2 k(A2 – x 2 ) x = 0 n‡j K.E = 1 2 KA2 hv m‡e©v”P STEP 07 ANALYSIS OF ENGINEERING & BUTex QUESTION BUET 01. †Kvb K¤úvs‡Ki mij †`vjMwZi Z¡iY a Ges miY x Gi m¤úK©wU a = 2 x mgxKi‡Yi mv‡_ m¤úwK©Z? [BUET. 12-13] A. B. 2 C. 2 D. 2 = 2f f = 2 STEP 08 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. ch©vqKvj I ej aªæe‡Ki g‡a¨ m¤úK© m~PK mgxKiY †KvbwU? [MAT. 18-19] A. T K B. T K 1 C. K T D. T K Ans B 02. GKwU mij †`vj‡Ki myZvi •`N©¨ 4 ¸Y evov‡j †`vjbKvj- [MAT. 15-16] A. 4 ¸Y evo‡e B. 4 ¸Y Kg‡e C. wØ¸Y n‡e D. `yB¸Y Kg‡e Ans C 03. wb‡gœi †KvbwU mij Qw›`Z MwZi •ewkó¨ bq? [MAT. 12-13] A. MwZ ch©vqe„Ë MwZ n‡e B. Z¡iY mi‡Yi e¨¯ÍvbycvwZK n‡e C. ej me©`v mvgë¯’vi w`‡K wµqv Ki‡e D. MwZ †`vjb MwZ n‡e Z¡iY mi‡Yi mgvbycvwZK I wecixZ g~Lx| a – x 04. wb‡Pi †KvbwU mij Qw›`Z ¯ú›`‡bi •ewkó¨? [MAT. 10-11] A. ‡Kvb ¯ú›`b MwZ bvB B. mij •iwLK MwZ †`Lv hvq bv C. †h †Kvb mg‡q Z¡i‡Yi gvb mvgë¯’vb †_‡K mi‡Yi gv‡bi mgvbycvwZK D. ch©vq e„Ë MwZ Ans CD 05. mij Qw›`Z ¯ú›`‡bi †e‡Mi mgxKiY- [MAT. 00-01] A. Asin (t+) B. – 2A sin (t+ ) C. Acos (t+) D. Asin (t+ ) x = A sin(t + ) v = dx dt = A cos (t + ) STEP 09 ANALYSIS OF HSC BOARD QUESTION 01. w¯úªs aªæe‡Ki GKK †KvbwU? [Xv. †ev. 2017] A. Nm2 B. Nm–1 C. Nm D. Nm–2 Ans B 02. mij Qw›`Z MwZm¤úbœ KYvi MwZc‡_i ga¨ Ae¯ v‡b [Xv. †ev. 2015] A. †eM me©wb¤œ, miY m‡e©v”P C. †eM me©wb¤œ, miY me©wb¤œ C. †eM me©vwaK, miY me©vwaK D. †eM me©vwaK, miY me©wb¤œ Ans D 03. nvZ Nwoi wgwb‡Ui KuvUvi K¤úvsK [Xv. †ev. 2015] A. 2.78 Hz B. 2.78101 Hz C. 2.78102 Hz D. 2.78104 Hz S D info = 2 = 2 = 2 3600 × 1 2 = 2.78×10–4 Hz 04. mij Qw›`Z ¯ú›`b m¤úbœ †Kv‡bv KYvi mi‡Yi m‡e©v”P Ae¯ vb n‡Z hvÎv ïiæ n‡j Avw` `kv KZ? [iv.‡ev. 2021] A. B. 2 C. 4 D. 0 Ans B 05. mij Qw›`Z MwZ‡Z MwZkxj †Kv‡bv KYvi mi‡Yi mgxKiY x = Acost, G‡ÿ‡Î KYvwU- [iv.‡ev. 2021] i. GK cÖvšÍ n‡Z hvÎv ïiæ K‡i‡Q ii. r = T 4 mg‡q mvg¨ve¯’v‡b _vK‡e iii. r = T 2 mg‡q KYvwUi hvÎv ïiæ we›`yi wecixZ cv‡k Ae¯’vb Ki‡e wb‡Pi †KvbwU mwVK? A. i I ii B. ii I iii C. i I iii D. i, ii I iii Ans B 06. mij Qw›`Z ¯ú›`‡bi •ewkó¨- [iv. †ev. 2019; mKj †evW© 2014] A. e¯‘i MwZ ch©vq MwZ B. Z¡iY e¯‘i mi‡Yi mgvbycvwZK C. Z¡iY e¯‘i miY AwfgyLx D. A I B DfqB Ans D wb‡¤œi DÏxcKwUi Av‡jv‡K 07bs cÖkœwUi DËi `vI: [iv. †ev. 2016] mij †`vj MwZm¤úbœ GKwU KYvi miY, x = 3 sin 2t wgUvi| 07. mvgë¯ vb †_‡K 1m `~‡i KYvwUi MwZkw³ I wefe kw³i AbycvZ A. 1 t 3 B. 3 t 1 C. 2 t 1 D. 1 t 2 S C info we¯Ívi, A = 3 m Ges x = 1m. Ek Ep = 1 2 k (A 2 – x 2 ) 1 2 kx2 = A 2 – x 2 x 2 = 3 – 1 1 = 2 : 1 08. mij Qw›`Z MwZm¤úbœ †Kv‡bv KYvi †ÿ‡ÎÑ [cÖPwjZ A_© enb K‡i][P. †ev. 2019] i. wefe kw³, Ep = 1 2 kA2 sin2 (t + ) ii. MwZkw³, Ek = 1 2 kA2 cos2 (t + ) iii. †gvU kw³ E A 2 wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans D 09. wP‡Îi m f‡ii e¯‧wU †U‡b †Q‡o w`‡j ¯ú›`‡bi K¤úv¼ n‡eÑ [P. †ev. 2017] A. B. C. D. Ans B 10. mij Qw›`Z ¯ú›`b MwZm¤úbœ †Kv‡bv KYvi †ÿ‡Î- [P.‡ev. 2016] A. KYvi †eM mvg¨ve¯’v‡b m‡e©v”P nq B. miY e„w×i mv‡_ mv‡_ †eM n«vm cvq C. we¯Ív‡ii cÖv‡šÍ †eM k~b¨ nq D. me¸‡jv mwVK Ans D 11. mij Qw›`Z ¯ú›`‡b ¯úw›`Z †Kv‡bv KYvi evievi ¯úw›`Z nevi KviY- [P. †ev. 2016] A. w¯’i RoZv B. MwZ RoZv C. cÖZ¨vqbx ej D. B I C DfqB Ans D 12. †Kv‡bv mij Qw›`Z ¯ú›`biZ e¯‧KYvi we¯Ívi A I miY x n‡j Z¡iY me©wb¤œ n‡eÑ [h. †ev. 2019] A. x = A Ae¯’v‡b B. x = A 2 Ae¯’v‡b C. x = A 4 Ae¯’v‡b D. x = 0 Ae¯’v‡b Ans D 13. wb‡Pi †KvbwU k~b¨ `kvi mgZyj¨ ? [h. †ev. 2016] A. 2 B. C. 3 2 D. 2 Ans D 14. mij †`vjb MwZm¤úbœ †Kv‡bv KYvi ch©vqKvj Gi ej aªæe‡Ki- [Kz.†ev.2016] A. mgvbycvwZK B. eM©g~‡ji mgvbycvwZK C. e¨¯ÍvbycvwZK D. eM©g~‡ji e¨¯ÍvbycvwZK Ans D

300 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 15. mij Qw›`Z ¯ú›`bkxj KYvi m‡e©v”P Ae¯ vb I mvg¨ve¯ vi g‡a¨ `kv cv_©K¨Ñ [Kz. †ev. 2016] A.x 4 B. x 2 C. D. 2 Ans B 16. mij †`vjb MwZ Ges e„ËvKvi MwZi m¤ú‡K©i †ÿ‡Î wb‡¤œv³ aviYv n‡jv- [Kz. †ev. 2015] A. mij †`vjb MwZi we¯Ívi e„‡Ëi e¨vmv‡a©i mgvb B. mylg e„ËvKv‡ii MwZi ch©vqKvj Ges mij †`vjb MwZ GKB nq C. mij †`vjb MwZi †K․wYK K¤úv¼ Ges mylg e„ËvKvi MwZi †K․wYK `ªæwZ Ges nq bv D. B I C DfqB Ans D 17. mij Qw›`Z Zi½ (SHW)- [Kz. †ev. 2015] A. AbycÖ¯’ Zi½ B. AMÖMvgx Zi½ C. Aby‣`N©¨ Zi½ D. me¸‡jv mwVK Ans D 18. mij †`vjb MwZi we‡kl I ¸iæZ¡c~Y© D`vniY n‡jv- [Kz. †ev. 2015] A. Djø¤^ w¯úªs-Gi MwZ B. ZvrÿwYK MwZ C. mij †`vj‡Ki MwZ D. A I C DfqB Ans D 19. mij Qw›`Z MwZ‡Z- [wm. †ev. 2017] A. e¯‘i Z¡iY e¯‘i mi‡Yi mgvbycvwZK B. Z¡iY GKwU wbw`©ó we›`y AwfgyLx nq C. wµqvkxj ej wecixZ e‡M©i m~Î †g‡b P‡j D. A I B DfqB Ans D 20. mij Qw›`Z ¯ú›`biZ KYvi †eMÑ [wm. †ev. 2016] i. ga¨we›`y‡Z m‡e©v”P ii. m‡e©v”P mi‡Y k~b¨ iii. mvg¨ve¯’vq me©wb¤œ wb‡Pi †KvbwU mwVK? A. i I ii B. ii I iii C. i I iii D. i, ii I iii Ans A 21. ‡Kv‡bv ¯ v‡b `ywU mij †`vj‡Ki †`vjbKv‡ji AbycvZ 1 : 2 n‡j, G‡ì Kvh©Ki •`‡N©ï AbycvZ KZ? [wm. †ev. 2015] A. 1 : 2 B. 1 : 2 C. 1 : 4 D. 2 : 1 Ans C wb‡Pi DÏxc‡Ki Av‡jv‡K 22bs cÖ‡kœi DËi `vI : [wm.‡ev 2021] C V A B V GLv‡b, T= 2sec g= 9.8ms–2 D 22. †Kvb we›`y‡Z KYvwUi †eM m‡e©v”P n‡e? V A. A B. B C. C D. D Ans A 23. mij Qw›`Z ¯ú›`‡bi •ewkó¨ bq †KvbwU? [e. †ev. 2017] A. KYvi miY mvB‡bi ev †KvmvB‡bi Av‡cÿK B. e‡ji w`K mvg¨we›`y AwfgyLx C. mvg¨we›`y‡Z MwZkw³ me‡P‡q Kg D. Z¡i‡Yi gvb mi‡Yi wecixZgyLx Ans C 24. mij Qw›`Z MwZm¤úbœ †Kv‡bv KYvi Z¡iY †Kvb ivwkwUi mgvbycvwZK? [e. †ev. 2016] A. ej B. ch©vqKvj C. miY D. †eM Ans C 25. mij Qw›`Z MwZi †ÿ‡Î Z¡i‡Yi mgxKiY- [e. †ev. 2015] A. a = A sin t B. a = A cos t C. a = – A 2 sin t D. a = – A 2 cos t Ans C Concept 3 †`vj‡Ki cÖKvi‡f` Ges eënvi ✅ ‡`vjK `yB cÖKvi (1) mij †`vjK (2) ‡h․wMK ev RwUj †`vjK ✅ mij †`vj‡Ki •ewkó¨mg~n myZv IRbnxb myZv, cvKnxb, bgbxq I AcÖmviYxq †`vjK wcÛ webv evavq `yj‡e (`„p Aej¤^b n‡Z `yj‡Z n‡e) †`vjK wcÛ (ee) ¶z`ª I fvix n‡e †`vj‡Ki MwZ n‡e mij Qw›`Z MwZ (†K․wYK we¯Ívi 4 Gi Kg n‡e) ◈ mij †`vj‡Ki •ewkó¨ g‡b ivLvi †K․kj: IRbnxb bgbxq AcÖmviYkxj myZvq ÿz`ª fvix ee Szjv‡j Zv webv evavq `yj‡e (Dc‡ii •ewk‡óï mv‡_ wgwj‡q bvI) ✅ mij †`vj‡Ki eënvi: cvnv‡oi D”PZv wbY©q mgq wbY©q AwfKl©R Z¡iY g Gi gvb wbY©q ◈ mij †`vj‡Ki eënvi g‡b ivLvi †K․kj: wR (g) fvB cvnv‡oi D”PZv wbY©q Ki‡Z A‡bK mgq jv‡M| wR (g) fvB cvnv‡oi D”PZv wbY©q Ki‡Z A‡bK mgq jv‡M g Gi gvb wbY©q cvnv‡oi D”PZv wbY©q mgq wbY©q ✅ †m‡KÛ †`vjK: †h mij †`vj‡Ki †`vjbKvj 2s A_©vr we¯Ív‡ii GK cÖvšÍ †_‡K Ab¨ cÖv‡šÍ †h‡Z 1 †m‡KÛ mgq jv‡M Zv‡K †m‡KÛ †`vjK e‡j| ✅ mij †`vj‡Ki •`N©¨ AwfKl©R Z¡i‡Yi mgvbycvwZK| ✅ †m‡KÛ †`vj‡Ki ¸iæZ¡c~Y© Z_¨mg~n: †`vjbKvj = 2s K¤úvsK = 0.5Hz GKwU Aa©‡`vjb Kvj = 1s. Kvh©Ki •`N©¨ = 0.993m. = 99.3 cm = 3.36ft ✅ mij Qw›`Z ¯ú›`‡bi mv‡_ mylg e„ËvKvi MwZi m¤úK©: 1. mylg †K․wYK `ªæwZ‡Z MwZkxj †Kvb KYvi †¶‡Î e„ËvKvi c‡_i e¨v‡mi Dci KYv Awf‡¶c mij Qw›`Z ¯ú›`b MwZ m¤úbœ nq; 2. mij Qw›`Z ¯ú›`‡bi †K․wYK K¤úvsK Avi mylg e„ËvKvi MwZi †K․wYK `ªæwZ GKB; 3. mij Qw›`Z ¯ú›`b Ges mylg e„ËvKvi MwZi ch©vqKvj GKB; 4. mij Qw›`Z ¯ú›`‡bi we¯Ívi e„ËvKvi MwZi e„‡Ëi e¨vmv‡a©i mgvb e„‡Ëi e¨vmv‡a©i mgvb| ✅ GK Pµ cwigv‡Y Mo MwZkw³ = Mo wefekw³ = 1 2 (†gvU kw³) †K․wYK K¤úv¼ g~jZ †K․wYK †eM| †K․wYK K¤úv‡¼i GKK: †iwWqvb/†m‡KÛ| Szjb we›`y †_‡K e‡ei fvi‡K›`ª ch©šÍ `~iZ¡ n‡”Q †`vj‡Ki Kvh©Kix •`N©¨| L = l + r = myZvi •`N©¨ + e‡ei e¨vmva© ‡Kvb GKwU K¤úgvb e¯‘i †h †Kvb gyû‡Z©i †`vj‡bi Ae¯’v A_©vr e¯‘wUi Ae¯’vb, †eM, Z¡iY Ges MwZi AwfgyL hv Øviv eySv hvq Zv‡K `kv e‡j| GKwU †`vjK‡K f~-†K‡›`ª wb‡q †M‡j †`vjbKvj Amxg n‡e A_©vr mij †`vjK Pj‡e bv|KviY f‚-†K‡›`ª g Gi gvb k~b¨ (0)| GKwU mij †`vjK cÖwZ †`vjbKv‡j `yB evi wUK K‡i| cÖZ¨qbx ej KYvi mi‡Yi mgvbycvwZK I wecixZgyLx| [F = –kx]

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 301 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF RU QUESTION 01. mij †`vjb MwZi †ÿ‡Î e‡ji •ewkó¨- [RU. 15-16] A. e‡ji gvb mvgë¯’vb †_‡K mi‡Yi gv‡bi e¨¯ÍvbycvwZK B. ej me©`v GKwU wbw`©ó we›`y AwfgyLx C. m`v N~Y©vqgvb D. ej n‡e mij •iwLK Ans B 02. ‡KvbwU‡Z mij †`vjK eëüZ nq bv? [RU. 06-07] A. AwfKl©R Z¡iY g Gi gvb wbY©q B. kw³ cwigvc C. cvnv‡oi D”PZv wbY©q D. mgq cwigvc Ans B STEP 02 ANALYSIS OF CU QUESTION 01. mij †`vj‡Ki we¯Ívi 4 Gi †ekx n‡j- [CU. 11-12] A. †`vjbKvj Amxg n‡e B. †`vjbKvj evo‡e C. †`vjbKvj Kg‡e D. †`vjK mij †`vj MwZ m¤úbœ n‡e bv E. †`vjbKvj w¯’i _vK‡e Ans D 02. GKwU mij †`vj‡Ki we¯Ívi wØ¸Y Kiv n‡j Gi ch©vqKvj c~‡e©i ch©vqKv‡ji [CU. 11-12] A. wØ¸Y n‡e B. A‡a©K n‡e C. mgvb n‡e D. Pvi¸Y n‡e E. GK PZz_©vsk n‡e Ans C STEP 03 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. Nwoi KuvUvi MwZ †Kvb MwZi D`vniY? [KU. 04-05] A. ch©ve„Ë MwZ B. ¯ú›`b MwZ C. mij‣iwLK MwZ D. N~Y©bMwZ Ans A CoU 01. wb‡Pi †KvbwU mij †`vjb MwZi •ewkó¨ bq? [CoU. 18-19] A. Z¡iY me©`v mi‡Yi mgvbycvwZK B. Z¡iY mi‡Yi wecixZgyLx C.Z¡iY I miY GKB w`‡K nq D. Z¡iY e¯‘ KYvwUi ga¨ Ae¯’vb AwfgyLx Ans C 02. mijQw›`Z ¯ú›`biZ GKwU KYv †Kvb Ae¯ vq _v‡K? [BRU. 13-14] A. Zij B. M¨vmxq C. cøvRgv D. ‡KvbwUB bq Ans D STEP 04 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. gnvKv‡k GKwU †m‡KÛ †`vj‡Ki K¤úv¼ KZ n‡e? [MAT. 17-18] A. 0 Hz B. 2 Hz C. 1 Hz D. Amxg Ans A 02. wb‡gœi †KvbwU †`vj‡Ki eënvi bq? [MAT. 03-04] A. AwfKl©R Z¡iY g Gi gvb wbY©q B. cvnv‡oi D”PZv wbY©q C. mgq wbY©q D. •`N©¨ wbY©q Ans D 03. †`vjK Nwoi †ejvq †Kvb Dw³wU mwVK? [MAT. 99-00] A. Mi‡gi w`‡b ax‡i Pj‡e B. welye †iLv n‡Z †giæ AÂ‡j Avb‡j NwowU ax‡i Pj‡e C. welye †iLv n‡Z †giæ AÂ‡j Avb‡j NwowU `ªæZ Pj‡e D. •`N©¨ evo‡j Nwo `ªæZ Pj‡e Ans A,C DAT 01. ‡`vjK Nwoi †ÿ‡Î MÖx®§Kv‡ji Rb¨ mwVK †KvbwU? [DAT: 16-17] A. Zv‡ii •`N©¨ K‡g hvq B. Nwo `ªæZ P‡j C. Nwo ax‡i P‡j D. ‡`vjbKvj AcwiewZ©Z _v‡K Ans C STEP 05 ANALYSIS OF HSC BOARD QUESTION 01. GKRb wkï wkïcv‡K©i GKwU †`vjbvq e‡m †`vj Lv‡”Q| nVvr Zvi gv‡K †`‡L †m ùvwo‡q †Mj| †`vjbwUi MwZ cÖK…wZ †Kgb n‡e? [iv. †ev. 2019] A. ax‡i Pj‡e B. `ªyZ Pj‡e C. †_‡g hv‡e D. cÖ_‡g aªyZ Ges c‡i ax‡i Pj‡e Ans D 02. ‡h †`vjK mvg¨ve¯ vb n‡Z me©vwaK mi‡Y †h‡Z 0.5 †m‡KÐ mgq †bq Zv‡K Kx e‡j? [w`.‡ev 2021] A. mij †`vjK B. RwUj †`vjK C. †m‡KÐ †`vjK D. †KUvi †`vjK Ans C wb‡Pi wPÎ †`‡L 03bs cÖ‡kœi DËi `vI: [w`. †ev. 2015] P Q R S U 03. †Kv‡bv ¯ v‡b `ywU mij †`vj‡Ki †`vjbKv‡ji AbycvZ 2 : 3 n‡j G‡ì Kvh©Ki •`‡N©ï AbycvZ n‡eA. 2 : 3 B. 3 : 2 C. 4 : 9 D. 9 : 4 Ans C 04. mij †`vj‡Ki mvnv‡h¨ wbY©q Kiv hvq- [w`. †ev. 2015] A. gyw³‡eM B. cvnv‡oi D”PZv C. gnvKlx©q aªæeK D. c„w_exi AveZ©b †eM Ans B 05. †`vjK NwoÑ [w`. †ev. 2019] i. cvnv‡oi Dci ax‡i P‡j ii. welye AÂj †_‡K †giy AÂ‡j wb‡j GwU ax‡i P‡j iii. MÖx®§Kv‡ji †P‡q kxZKv‡j `ªyZ P‡j wb‡Pi †KvbwU mwVK? A. i I ii B. ii I ii C. i I iii D. i, ii I iii Ans C Concept 4 mij †`vj‡Ki m~Îvejx ✅ mij †`vj‡Ki m~Îvejx : mij †`vjK `yjevi mgq PviwU m~Î †g‡b P‡j| 1582 mv‡j weÁvbx M¨vwjwjI GB m~Î Avwe®‥vi K‡ib| m~Î¸‡jv h_vµ‡g1g m~Î - (mgKvj m~Î) : †Kvb GK ¯’v‡b wbw`©ó •`N©¨ wewkó †Kvb GKwU mij †`vj‡Ki we¯Ívi 4˚ Gi g‡a¨ _vK‡j cÖwZwU †`vj‡Ki Rb¨ mgvb mgq jvM‡e| L, g w¯’i _vK‡j cÖwZwU †`vj‡Ki Rb¨ T GKB ev aªæeK| 2q m~Î- (•`‡N©ï m~Î) : we¯Ívi 4˚ Gi g‡a¨ _vK‡j †Kvb wbw`©ó ¯’v‡b mij †`vj‡Ki †`vjbKvj Zvi •`‡N©ï eM©g~‡ji mgvbycvwZK| T L 3q m~Î - (Z¡i‡Yi m~Î) : we¯Ívi 4˚ Gi g‡a¨ _vK‡j wbw`©ó •`N©¨ wewkó †Kvb mij †`vj‡Ki ‡`vjb Kvj H ¯’v‡bi AwfKl©R Z¡i‡Yi eM©g~‡ji e¨v¯ÍvbycvwZK| T 1 g 4_© m~Î - (f‡ii m~Î) : we¯Ívi 4˚ Gi g‡a¨ Ges Kvh©Ki •`N©¨ w¯’i _vK‡j †Kvb ¯’v‡b mij †`vj‡Ki †`vjbKvj †`vjK wc‡Ûi fi, AvK…wZ ev Dcv`v‡bi Dci wbf©i K‡i bv| ◈ †K․wYK we¯Ívi 4° Gi †ewk n‡j- T = 2 L g m~Î cÖ‡hvR¨ nq bv, KviY- e‡ei MwZ mij •iwLK n‡e bv Z¡iY mi‡Yi mgvbycvwZK nq bv mij †`vj‡Ki mij Qw›`Z MwZ m¤úbœ nq bv| ✅ mij †`vj‡Ki †`vjbKv‡ji m~Î : T = 2 L g †`vjbKvj evo‡e hw` g Gi gvb K‡g A_ev L Gi gvb ev‡o| †`vjbKvj Kg‡e hw` g Gi gvb ev‡o A_ev L Gi gvb K‡g|

302 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. GKwU mij †`vj‡Ki †`vjKwc‡Ûi m‡e©v”P Z¡iY nq †Kvb we›`y‡Z- [DU. 08-09] A. m‡e©v”P we¯Ívi we›`y‡Z B. gv‡Si me©wbgœ we›`y‡Z C. Dc‡ii A I B Gi gvSvgvwS †Kvb we›`y‡Z D. ‡`vjK wcÛwU mgZ¡i‡Y b‡o, ZvB m‡e©v”P Z¡i‡Yi we‡kl †Kvb we›`y bvB| gv‡Si me©wbgœ we›`y‡Z Z¡iY me©wbgœ, †eM m‡ev”P© m‡ev©”P we¯Ívi we›`y‡Z Z¡iY me©vwaK, †eM me©wbgœ (k~b¨) STEP 02 ANALYSIS OF JU QUESTION 01. GKwU †m‡KÛ †`vj‡Ki •`N©¨ KZ? [JU-A, Set-C. 20-21, CU. 17-18] A. L = g/ 2 B. L = g2 / 2 C. L = 2 g D. L = 2/g S A info T = 2 L g L = gT2 4 2 = g/ 2 [T = 2sec] 02. hw` GKwU †`vj‡Ki ch©vqKvj T Ges ‣`N©¨ L nq Zvn‡j- [JU. 11-12] A. L T 1 B. T L C. T L D. L T 1 Ans C STEP 03 ANALYSIS OF RU QUESTION 01. †K․wYK we¯Ívi 4 Gi †ewk bv n‡j Ges Kvh©Ki •`N¨© AcwiewZ©Z _vK‡j †`vjbKvj †`vj‡Ki e‡ei AvKvi, Dcv`vb I f‡ii Ici wbf©i K‡i bv GUv- [RU. Moderna, Set-2. 20-21] A. mgKvj m~Î B. f‡ii m~Î C. •`‡N©i m~Î D. †KvbwUB bq Ans D 02. mij †`vj‡Ki †ÿ‡Î mvg¨ Ae¯ v‡bÑ [RU-C, Set-1. 19-20] A. MwZkw³ k~b¨ B. w¯’wZkw³ k~b¨ C. DfqB k~b¨ D. †KvbwUB k~b¨ bq S B info mvgë¯’vq MwZkw³ m‡e©v”P I w¯’wZkw³ k~b¨ (0)| 03. GKRb QvÎ GKwU mij †`vj‡Ki †`vjbKvj (T) †`vj‡Ki wewfbœ •`‡N©ï (L) Rb¨ cwigvc Kij| bx‡Pi †Kvb Pj‡Ki gvb¸‡jv QK KvM‡R AuvK‡j g~j we›`yMvgx mij‡iLv n‡e? [RU. 16-17] A. L Ges T B. L Ges T C. L Ges T 2 D. L 2 Ges T T = 2 L g A_©vr T L L vs T2 MÖvd A¼b Ki‡j Zv gyjwe›`yMvgx mij‡iLv n‡e| 04. c„w_ex I Puv‡ì c„‡ô AwfKl©xq Z¡i‡Yi AbycvZ KZ? [RU. 15-16] A. 81 : 4 B. 81 : 6 C. 81 : 10 D. 81 : 16 Ans D STEP 04 ANALYSIS OF CU QUESTION 01. mij Qw›`Z GKwU e¯‧ KYvi MwZi mgxKib x = A sint, Dnvi Z¡iY KZ? [CU. 14-15, 13-14, 09-10] A. – 2 x B. 2 x C. x D. x 2 E. –x 2 Ans A 02. GKwU mij †`vj‡Ki Z¡i‡Yi mgxKiY †KvbwU? [CU. 12-13] A. a = Acos(t+) B. a = – Acos(t+) C. a = A sin(t+) D. a = – 2 Acos(t+) E. a = – 2A sin(t+) Ans E 03. GKwU †m‡KÛ †`vj‡Ki •`N¨© AwfKl©R Z¡i‡Yi- [CU. 09-10] A. e¨¯ÍvbycvwZK B. mgvbycvwZK C. e‡M©i mgvbycvwZK D. eM©g~‡ji mgvbycvwZK E. e‡M©i e¨¯ÍvbycvwZK Ans B STEP 05 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. mij †`vj‡Ki 4_© m~Î †KvbwU? [JNU. 10-11] A. •`‡N©ï m~Î B. Z¡i‡Yi m~Î C. mgKvj m~Î D. f‡ii m~Î Ans D KU 01. mij †`vj‡Ki m~Î †g‡b P‡j bv hLb †`vj‡Ki Ae¯ vb- [KU. 13-14] A. P›`ª c„‡ô B. mg‡e‡M PjšÍ wjd‡U C. c„w_exi †K‡›`ª D. ‡K․wYK we¯Ívi 4° Gi †ewk bv n‡j Ans C STEP 06 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. †KvbwU mvaviY my‡ijv †`vj‡bi Rb¨, †K․wYK ¯ vbPz¨wZ wb‡Pi †KvbwUi †P‡q †ewk n‡Z cv‡i bv? [MAT. 20-21; JUST. 14-15; w`.†ev. 2015] A. 5 B. 6 C. 3 D. 4 S D info mij †`vjb MwZi Rb¨ †K․wYK miY ev †K․wYK ¯’vbPz¨wZi gvb 4 Gi †P‡q †ewk n‡Z cv‡i bv| STEP 07 ANALYSIS OF HSC BOARD QUESTION 01. †Kv‡bv †m‡KÛ †`vj‡Ki Kvh©Kix •`N©¨ 1.96 ¸Y Ki‡j Gi †`vjbKvj KZ n‡e? [Xv. †ev. 2019] A. 3.92 s B. 2.8 s C. 3.44 s D. 1.4 s S B info T1 T2 = L1 L2 T2 = L2 L1 × T1 = 1.96 × 2 = 2.8 s 02. GKwU mij †`vj‡Ki duvcv ee‡K Zij Øviv c~Y© K‡i Zjvq †QvU wQ`ª K‡i w`‡j Ges Zij †duvUvq †duvUvq co‡Z _vK‡j †`vjKwU- [iv. †ev. 2017] A. cÖ_‡g ax‡i Ges c‡i `ªæZ Pj‡e B. cÖ_‡g `ªæZ Ges c‡i ax‡i Pj‡e C. jwä fvi‡K›`ª †K›`ª †_‡K wb‡P bvg‡Z _vK‡e D. B I C DfqB Ans D 03. GKwU mij †`vj‡Ki •`N©¨ L, fi M Ges K¤úv¼ | Gi K¤úv¼ 2 Ki‡Z n‡j- [iv. †ev. 2015] A. •`N©¨ e„w× K‡i 4L Ki‡Z n‡e B. •`N©¨ e„w× K‡i 2L Ki‡Z n‡e C. ‣`N©¨ n«vm K‡i L 2 Ki‡Z n‡e D. ‣`N©¨ n«vm K‡i L 4 Ki‡Z n‡e Ans D 04. †`vj‡Ki e‡ei fi †ewk n‡j †`vjbKvj Kx n‡e? [iv. †ev. 2015] A. evo‡e B. Kg‡e Ans C C. AcwiewZ©Z _vK‡e D. f‡ii eM©g~‡ji mgvbycvwZK n‡e 05. SI GK‡K cwigvcK…Z mij Qw›`Z ¯ú›`‡b ¯úw›`Z KYvi eëKjbxq mgxKiY 2 d 2 x dt2 + 32x = 0 n‡j, †K․wYK K¤úv¼ †KvbwU? [iv. †ev. 2015] A. 4 rads–1 B. 8 rads–1 C. 16 rads–1 D. 32 rads–1 S A info 2 d 2 x dt2 + 32x = 0 d 2 x dt2 + 16x = 0 d 2 x dt2 + 2 x = 0 ; Zzjbv K‡i cvB, 2 = 16 = 4 rads–1

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 303 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES wb‡Pi DÏxcKwU co 06 Ges 07bs cÖ‡kœi DËi `vI : [P. †ev. 2017] GKwU mij‡`vj‡Ki we¯Ívi A Ges †`vjbKvj T. †`vjKwU x = mi‡Yi mgqKvj t †m‡KÛ| 06. †`vjKwUi m‡e©v”P †eM [P. †ev. 2017] A. B. C. D. S B info vmax = A = 2 T A 07. DÏxc‡Ki mgqKvj t = KZ? [P. †ev. 2017] A. B. C. D. S D info x = A sin 2 T t = A 2 sin 2 T t = 1 2 2 T t = 6 t = T 12 08. †m‡KÛ †`vj‡Ki K¤úv¼- [P. †ev. 2015, e.†ev. 2015, wm.†ev. 2019] A. 0.5 Hz B. 1 Hz C. 2 Hz D. 4 Hz S A info = 1 T = 1 2 = 0.5 Hz 09. wPÎvbyhvqx A we›`y‡Z wb‡Pi †KvbwU mwVK? [w`.‡ev 2021] A V A. †eM Ges Z¡iY DfqB m‡e©v”P B. †eM me©wb¤œ, Z¡iY m‡e©v”P C. †eM m‡e©v”P, Z¡iY me©wb¤œ D. †eM I Z¡iY DfqB me©wb¤œ 10. GKwU c~Y© K¤ú‡b T mg‡q `kvi cwieZ©b 2 n‡j †K․wYK K¤úv¼ KZ n‡e? [h. †ev. 2016] A. = 2 /f B. = T/2 C. = 2f D. = 2T Ans C 11. mij Qw›`Z MwZm¤úbœ KYvi Z¡iY n‡”Q- [h. †ev. 2015] A. a = x 2 B. a = 2 x C. a = x D. a = – 2 x Ans D 12. mij‡`vj‡Ki MwZi †ÿ‡Î 1 2 KA2 wb‡`©k K‡i- [Kz.‡ev 2021] i. m‡e©v”P w¯’wZkw³ ii. m‡e©v”P MwZkw³ iii. †gvU kw³ wb‡Pi †KvbwU mwVK? A. i I ii B. ii I iii C. i I iii D. i, ii I iii Ans D 13. m f‡ii GKwU e¯‧ mij Qw›`Z ¯ú›`‡b MwZkxj Av‡Q| Gi ch©vqKvj n‡e [wm. †ev. 2017] A. T = 1 2 m k B. T = 2 2 m k 2 C. T = 2 m k D. T = 1 2 m k 2 Ans C Concept 5 †`vjbKvj hLb evo‡e ev Kg‡e ✅ mij †`vj‡Ki †`vjb Kvj: †`vjbKvj evo‡e †hLv‡b g Gi gvb Kg‡e : Kvh©Ki •`N©¨ evo‡j| ‡`vjK P›`ª c„‡ô wb‡j| mgZ¡i‡Y wjdU bx‡Pi w`‡K bvg‡j (Kvh©Ki Z¡iY (g–a)| ZvcgvÎv e„w× †c‡j (avZz wbwg©Z †MvjK) ‡`vjK wcÛ Lwb‡Z ev cvnv‡oi Dci wb‡j| †`vjK Nwo MÖx®§Kv‡j Av‡¯Í P‡j (Slow nq)| †`vjK wcÛ, cvi` Øviv Aa©c~Y© Kiv n‡j (e„w× cvq)| †`vjK Nwo‡K ‡giæ AÂj †_‡K welye AÂ‡j wb‡j| †`vjb Kvj Kg‡e A_©vr †`vjK `ªæZ Pj‡e : Kvh©Ki •`N©¨ Kgv‡j| ‡`vjK welye AÂj n‡Z †giæ AÂ‡j wb‡j| kxZKv‡j ev ZvcgvÎv Kg‡j Nwo `ªæZ P‡j| mgZ¡i‡Y Dc‡ii w`‡K PjšÍ wjd‡U †`vjK wb‡j (Kvh©Ki Z¡iY = g + a)| †`vjb Kvj Amxg n‡e : †`vjK‡K c„w_exi †K‡›`ª wb‡j| †`vjK‡K N~Y©vqgvb K…wÎg DcMÖ‡ni g‡a¨ wb‡j| †`vjbKvj AcwiewZ©Z _vK‡e : †`vjK dvcv bv n‡q wb‡iU n‡j| †`vjK‡K mg‡e‡M PjšÍ wjd‡U wb‡j| dvcv †`vjK wcÛ‡K cvi` Øviv c~Y© Kiv n‡j| mxmvi †`vjK wc‡Ûi cwie‡Z© wcZ‡ji †`vjK wcÛ n‡j (e‡ei c`v‡_©i cwieZ©b Ki‡j)| ◈ wjdU mg‡e‡M _vK‡j †`vjbKv‡ji †Kvb cwieZ©b nq bv| ✅ mij †`vjK m¤ú‡K© ÁvZe¨ welq : Zijc~Y© ee bx‡P wQ`ª Ki‡j 1g Kvh©Ki ‣`N©¨ e„w× cvq, †`vjbKvj e„w× cvq, Nwo †¯øv n‡e Ges c‡i Kvh©Ki •`N©¨ n«vm cv‡e, †`vjb Kvj n«vm cv‡e, Nwo `ªæZ (Fast) Pj‡e| P‡›`ª g Gi gvb Kg Ges T ‡ekx ZvB Nwo †¯øv Pj‡e| REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. GKwU mij †`vjK c„w_exi †K‡›`ª wb‡j Bnvi †`vjb Kvj n‡e- [DU. 09-10, CU. 16-17, w`.‡ev. 2016] A. Zero B. Infinity C. Less than that on the earth surface D. More than taht on the earth surface c„w_exi †K‡›`ª g = 0 AZGe g L T 2 02. wbw`©ó •`‡N©¨i GKwU mij †`vj‡Ki e‡ei fi 3 ¸Y Kgv‡j ch©vqKvj †Kgb n‡e? [DU. 17-18; JnU. 17-18] A. 3 ¸Y Kg‡e B.3 ¸Y evo‡e C. 9 ¸Y evo‡e D. AcwiewZ©Z _vK‡e ch©vqKvj e‡ei f‡ii Dci wbf©i K‡i bv|

304 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES STEP 02 ANALYSIS OF JU QUESTION 01. gnvKv‡k GKRb b‡fvPvixi wbKU GKwU mij †`vj‡Ki †`vjbKvj n‡eÑ [JU-A, Set-G. 20-21; SUST. 01-02] A. Amxg B. 1 Sec C. 2 sec D. 4 sec S A info Avgiv Rvwb, T = 2 L g T 1 g A_©vr gnvKv‡k g Gi gvb k~b¨| ZvB mij †`vj‡Ki †`vjbKvj Amxg| 02. c„w_ex c„‡ôi GKwU †m‡KÛ †`vj‡Ki c„w_ex Pviw`‡K cwiågYiZ GKwU gnvKvkhv‡b †bqv n‡j, Gi ch©vqKvj KZ n‡e? [JU-A, Set-B. 20-21, SUST. 01-02] A. 1 sec B. 2 sec C. 4 sec D. Amxg S D info Avgiv Rvwb, T = 2 L g T 1 g †h‡nZz gnvKvkhv‡b g = 0, ZvB ch©vqKvj Amxg n‡e| T = 2 L 0 = (Amxg) STEP 03 ANALYSIS OF RU QUESTION 01. GKwU mij †`vj‡Ki †`vjKwc‡Ûi m‡e©v”P Z¡iY nq †Kvb we›`y‡Z? [RU. 17-18] A. m‡e©v”P we¯Ívi we›`y‡Z B. ga¨ we›`y‡Z C. m‡e©v”P I me©wb¤œ we¯Ív‡ii gvSvgvwS Ae¯’v‡b D. ‡KvbwUB bv Ans A 02. †Kvb †`vjK Nwo‡K †Kvb Lwb‡Z wb‡q †M‡j wK NU‡e? [RU. 16-17] A. mgq nviv‡e B. mgq jvf Ki‡e C. mgq GKB _vK‡e D. NwowU eÜ n‡q hv‡e S A info Lwb‡Z wb‡q †M‡j g Gi gvb Kg‡e| T 1 g , ZvB g Gi gvb Kgv‡j T Gi gvb evo‡e A_©vr nviv‡e| 03. GKwU mij †`vj‡Ki f~-†K‡›`ª †`vjb Kvj KZ? [RU. 14-15] A. Amxg B. k~b¨ C. f~-c„‡ô †`vjb Kv‡ji mgvb D. ‡KvbwUB bq Ans A 04. †`vjK‡K Lwbi wfZi w`‡q cvnv‡oi Dci wb‡j- [RU. 11-12] A. ‡`vjK `ªæZ Pj‡e B. ‡Kvb cwieZ©b n‡e bv C. ax‡i Pj‡e D. ‡KvbwUB bq T = 2 L g g Gi gvb cvnv‡oi Dci ev Lwbi wfZi wb‡q †M‡j Kg‡Z _v‡K| myZivs T Gi gvb evo‡e A_©vr †`vjKwU ax‡i Pj‡e| 05. GKwU mij †`vjK‡K wjd‡U mgZ¡i‡Y Dc‡i DVv‡bv n‡j †`vjbKvj- [RU. 09-10] A. n«vm cvq B. e„w× cvq C. AcwiewZ©Z _v‡K D. †KvbwUB bq Ans A 06. mij Qw›`Z MwZ m¤úbœ †Kvb KYvi m‡e©v”P †eM 0.02ms-1 . KYvwUi we¯Ívi 0.004m n‡j ch©vq Kvj KZ? [RU. 09-10] A. 3.14s B. 0.004s C. 4.50s D. 1.26s Vmax = A = 2 T . A T= 2 Vmax A = 2 0.02 0.004 = 1.26 STEP 04 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. GKwU †`vjK‡K N~Y©vqgvb K…wÎg DcMÖ‡ni Af¨šÍ‡i †bqv n‡j †`vjbKvj [wm.‡ev. 15-16, KU. 01-02] A. e„w× cvq B. .n«vm cvq C. Amxg nq D. AcwiewZ©Z _v‡K K…wÎg DcMÖ‡n, g = 0; T = 2 L g = T = 2 L 0 = CoU 01. †Kvb mij †`vj‡Ki †`vjK wc‡Ûi fi µgvMZ evov‡bv n‡j Gi †`vjbKvj- [CoU. 15-16] A. evo‡e B. Kg‡e C. AcwiewZ©Z _vK‡e D. fi I ‡`vjbKv‡ji e„w× mgvbycvwZK n‡e Ans C PART B Analysis of Science & Technology Question BSFMSTU 01. †m‡KÛ †`vj‡Ki Aa© †`vj‡bi †`vjbKvj- [BSFMSTU-A, 19-20] A. 1 sec B. 2 sec C. 1 2 sec D. 4 sec †m‡KÛ †`vj‡Ki †`vjbKvj = 2 sec †m‡KÛ †`vj‡Ki Aa© †`vjbKvj = 2 2 = 1 sec. 02. mij‡`vj‡Ki Z…Zxq m~ÎwU wK‡mi mv‡_ m¤úwK©Z? [NSTU-A, 19-20] A. Z¡iY B. miY C. fi D. mgqKvj mij †`vj‡Ki 4wU m~Î i‡q‡Q| h_v1. mgKvj m~Î : g I L mgvb n‡j me †`vj‡Ki T mgvb 2. •`‡N©¨i m~Î : g GKB _vK‡j T L 3. Z¡i‡Yi m~Î : L GKB _vK‡j T 1 g 4. f‡ii m~Î : †`vjbKvj e‡ei f‡ii Dci wbf©i K‡i bv| STEP 05 ANALYSIS OF HSC BOARD QUESTION 01. †`vjK NwoÑ [w`.‡ev. 2019] i. cvnv‡oi Dci ax‡i P‡j ii. welye AÂj †_‡K †giæ AÂ‡j wb‡j GwU ax‡i P‡j iii. Mªx®§Kv‡ji †P‡q kxZKv‡j `ªæZ P‡j wb‡Pi †KvbwU mwVKÑ A. i I ii B. ii I iii C. i I iii D. i, ii I iii Ans C 02. †`vjK Nwo‡K cvnv‡oi P‚ovq wb‡q †M‡j NwowU- [e.†ev 2021, P.†ev 2016,X.†ev. 2017] i. mgq jvf Ki‡e ii. mgq nviv‡e iii. ax‡i Pj‡e wb‡Pi †KvbwU mwVK? A. i B. ii C. i I iii D. ii I iii Ans C

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 305 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 6 mij Qw›`Z MwZmsµvšÍ †jLwPÎ Y O miY, x T/4 T/2 3T/4 X T mgq, t Y O †eM, v T/4 T/2 3T/4 X T mgq, t welq †jLwP‡Îi aib welq †jLwP‡Îi aib miY-mgq †jLwPÎ sin m`„k L–T 2 †jLwPÎ g~jwe›`yMvgx GKwU mij‡iLv †eM-mgq †jLwPÎ cos m`„k g – T 2 †jLwPÎ AvqZvKvi Awae„Ë Z¡iY-mgq †jLwPÎ FYvZ¥K sin m`„k T 2 – 1 g †jLwPÎ g~jwe›`yMvgx GKwU mij‡iLv ✅ †jLwPÎ: g-T 2 †jLwPÎ Awae„Ë n‡e, L-T 2 †jLwPÎ mij‡iLv n‡e, T 2 – 1 g †jLwPÎ mij‡iLv n‡e| g T 2 L T 2 T 2 1 g REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF GST QUESTION PART A Analysis of Science & Technology Question HSTU 01. mij ‡`vj‡Ki L-T 2 ‡jLwPÎwU ‡Kgb n‡e? [HSTU. 14-15] A. mij ‡iLv B. c¨viv‡evwjK C. nvBcvi‡evwjK D. ‡KvbwUB bq Ans A DU Technology 01. Z = Zm sint GKwU e¯‧KYvi mi‡Yi mgxKiY n‡j, wb‡Pi †KvbwU Z¡iY I mg‡qi †jLwPÎ? [DU-Tech.19-20] A. a t B. a t C. a t D. a t Ans A STEP 02 ANALYSIS OF HSC BOARD QUESTION 01. mij †`vj‡Ki †ÿ‡Î †Kvb †jLwPÎwU mwVK? [P.‡ev 2021] A. B. C. D. g T 2 g T 2 g T 2 g T 2 Ans C 02. (g – T 2 ) †jLwPÎwUi cÖK…wZ Kxiƒc n‡e? [Xv.‡ev 2021; iv.†ev. 2019] A. B. C. D. T 2 O g T 2 O g T 2 O g T 2 O g Ans B 03. GKwU w¯úªs Gi cÖv‡šÍ m fi Szwj‡q †`vj‡Z w`‡j Gi †`vjbKv‡ji eM© (T 2 ) ebvg fi (m) Gi †jLwPÎ †Kgb n‡e? [iv.‡ev 2021] A. B. C. D. T 2 m m T 2 T 2 T 2 m m Ans A 04. †`vjbiZ GKwU w¯úªs Gi •`N©¨ e„w× ebvg fi †jLwPÎ †KvbwU? [P.†ev 2021] A. B. C. D. m(kg) l(m) m(kg) l(m) m(kg) l(m) m(kg) l(m) Ans B 05. AwfKl©R Z¡iY g, MfxiZv h-Gi †jLwPÎ †KvbwU? [P. †ev. 2015] A. g h B. g h C. g h D. g h Ans A 06. mijQw›`Z ¯ú›`b m¤úbœ †Kv‡bv KYvi mi‡Yi mgxKiY x = Asint n‡j †eMmgq †jLwPÎ n‡e [P. †ev. 2015] A. v 0 t B. v 0 t C. v 0 t D. v 0 t Ans A

306 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 07. mij †`vj‡Ki Rb¨ L ebvg T 2 †jLwP‡Îi cÖK…wZ wb‡Pi †KvbwU mwVK? [P.‡ev. 2019, w`. †ev. 2017, iv. †ev 2019] A. T 2 L B. T 2 L C. T 2 L D. T 2 L Ans B 08. T = 2 mgxKiY n‡Z wb‡Pi †KvbwU mwVK? [w`. †ev. 2017] A. T 2 g B. T 2 g C. T 2 1 g D. T 2 1 g Ans B 09. †Kvb †jLwPÎwU mij‡`vj‡Ki 2q m~Î‡K cÖKvk K‡i? [Kz. †ev. 2019] A. B. C. D. Ans B 10. T 2 1 g Gi †jLwPÎ †KvbwU? [Kz.‡ev. 2021] A. B. C. D. 1 g T 2 1 g T 2 1 g T 2 1 g T 2 Ans C 11. mij‡`vj‡Ki †ÿ‡Î †jLwPÎ n‡”Q [Kz. †ev. 2015] i. X Y L T2 O ii. O Y X L T2 iii. O Y X g T2 wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans A 12. mijQw›`Z MwZm¤úbœ KYvi Mo MwZkw³ cÖKv‡ki †ÿ‡Î †Kvb †jLwPÎwU mwVK? [g.‡ev 2021] A. B. C. D. K –A O +A K –A +A O –A +A K O –A +A K O Ans B STEP 2 mg„× †ewmK MvwYwZK cÖ Ö‡qvM (MATH) kU©KvU †UKwbK Concept 1 mij Qw›`Z MwZi m~Îvejx msµvšÍ MvwYwZK cÖ‡qvM FORMULA 01. mij Qw›`Z ¯ú›`‡bi e¨eKjbxq mgxKiY 2 2 dt d x + ω 2 x = 0 2 2 dt d x + m k x = 0 02. ω 2 = m k ω = m k ; f = 1 2 k m ; T = 1 f = 2 m k 03. mij Qw›`Z ¯ú›`b m¤úbœ KYvi: x = o x = A miY, x = a sint †eM, V = A 2 – x 2 A = KYvi we¯Ívi x = 0 n‡j, Vmax = A = 2A T = 2fA x = KYvi miY Z¡iY, a = – 2 x †K․wYK †eM, = 2 T = 2f amax = – 2A (x = A) |amax| = 2A 04. mij Qw›`Z ¯ú›`b m¤úbœ KYvi mgxKib, x = A sin (t + ) A = we¯Ívi hvnv KLbI FYvZ¥K n‡e bv; = Avw` `kv; (ωt + ) = `kv t = 0 mg‡q `kv = dx dt = V = ωA cosωt dt dv = a = – ω 2A sinωt = – 2 x

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 307 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES CONCEPTUAL MATH MEx 01 25x 0 dt d x 2 2 mgxKiYwU GKwU mij Qw›`Z ¯ú›`b eY©bv K‡i| GB ¯ú›`‡bi †K․wYK K¤úvsK KZ? 2 2 dt d x +25x = 0 2 2 dt d x + 25x= 0 By compare with 2 2 dt d x + 2 x = 0; 2 = 25 = 5 rad s1 MEx 02 mij †`vjb MwZ m¤úbœ GKwU KYvi we¯Ívi 0.02m Ges K¤úv¼ 2.5Hz n‡j Gi m‡e©v”P `ªæwZ KZ n‡e? m‡e©v”P †eM, vmax = A = 2f A = 2 2.5 0.02 = 0.314ms1 MEx 03 GKwU Zv‡ii wfZi w`‡q mvB‡bv‡mvBWvj Zi½ cÖevwnZ n‡j Zv‡ii KYvi m‡e©v”P `ªæwZ VS| Zv‡ii GKwU KYvi miY we¯Ív‡ii A‡a©K n‡j H KYvi `ªæwZ n‡jv? Vmax = A Avevi, v = A 2 – x 2 = A 2 – A 2 2 = A 2 – A 2 4 = A 3 2 = 3 2 Vmax MEx 04 mij Qw›`Z ¯ú›`‡b GKwU KYvi m‡e©v”P Z¡iY 8m/s2 Ges m‡e©v”P `ªæwZ 1.6m/s KYvwUi ch©vq Kvj wbY©q Ki? amax = 2A..... (i); Vmax = A.......(ii) ; (i ÷ ii) K‡i cvB, amax vmax = 8 1.6 = 2 T ev, T = 1.6 4 = 0.4 sec NOW START PRACTICE 01. †Kvb mij Qw›`Z MwZm¤úbœ KYvi we¯Ívi 3.0 cm Ges m‡e©v”P †eM 6.24 cms–1 n‡j KYvwUi ch©vqKvj KZ? 02. w¯úªs-G SzjšÍ m f‡ii GKwU e¯Íyi ch©vqKvj 2sec n‡j 4m f‡ii e¯Íyi Rb¨ ch©vq Kvj KZ †m‡KÛ? 03. mij Qw›`Z MwZm¤úbœ GKwU e¯‧i MwZi mgxKiY n‡”Q x = 4.0 cos(3t + 3 ) m, t = 2s mg‡qi e¯‧wUi miY n‡e04. GKwU e¯‧ m‡e©v”P we¯Ívi 5.0 m Ges 8.0 s†`vjbKv‡j mij Qw›`Z MwZ m¤úbœ| e¯‧wUi m‡ev©”P †eM KZ? 05. 400x 0 dt d x 4 2 2 n‡j, = KZ? NOW PRACTICE SOLVE : 01. m‡e©v”P †eM, vmax = A = 2 T A ch©vqKvj, T = 2 vmax A = 2 6.24 3 = 3.02 s 02. T2 T1 = 4m m T2 = 2 2 = 4sec 03. MwZi mgxKiY, x = 4.0 cos 3t + 3 = 4.0 cos 3 + 2 + 3 = 2.0 m 04. Vmax = A = 2 T .A, Vmax = 23.145 8 = 3.93m/s 05. 4 d 2 x dt2 + 400x = 0 d 2 x dt2 + 100x = 0; By compare with differential eqn , d 2 x dt2 + 2 x = 0 2 = 100 = 10 rads-1 REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. 3 d 2 x dt2 + 27x = 0 mgxKiYwU GKwU mij Qw›`Z ¯ú›`b eY©bv K‡i| GB ¯ú›`‡bi †K․wYK K¤úvsK KZ? [DU. 15-16; BSMRSTU. 19-20] A. 3 rad/s B. 3 rad/s C.27 rad/s D. 9 rad/s †K․wYK K¤úvsK = x Gi mnM d 2 x dt2 Gi mnM = 3 27 = 3 rad/s 02. d 2 x dt2 + 25x = 0 mgxKiYwU GKwU mij Qw›`Z ¯ú›`b eb©bv K‡i| GB ¯ú›`‡bi ‡K․wYK K¤úvsK KZ? [DU. 13-14] A. 100rads–1 B. 25rads–1 C. 10rads–1 D. 5rads–1 †K․wYK K¤úvsK, = x Gi mnM d 2 x dt2 Gi mnM = 25 1 = 5rads–1 03. mij Qw›`Z MwZ‡Z Pjgvb GKwU e¯‧i †gvU kw³ E. K¤úv¼ AcwiewZ©Z †i‡L we¯Ívi wØ¸Y Ki‡j Qw›`Z MwZ‡Z Pjgvb e¯‧wUi †gvU kw³ KZ n‡e? [DU. 12-13] A. E B. 2E C. E/2 D. 4E Ek = 1 2 kA2 , E2 Ea = A2 A1 2 ev, E2 E1 = 2 1 2 ev , E2 E1 = 4 ev, E2 = 4E1 kw³ c~‡e©i Zzjbvq 4 ¸Y n‡e| 04. GKwU e¯‧i m‡e©v”P we¯Ívi 5.0 m Ges 8.0s †`vjbKv‡j mij Qw›`Z MwZ m¤úbœ| e¯‧wUi m‡ev©”P †eM KZ? [DU. 09-10] A. 3.93 m/s B. 3.13 m/s C. 7.81 m/s D. 6.20 m/s Vmax = A = 2 T .A = 23.145 8 = 3.93m/s 05. 4 d 2 x dt2 + 100x = 0 mgxKiY Øviv ewY©Z mij Qw&›`Z MwZi †K․wYK K¤úvsK- [DU. 06-07; wm. †ev. 2016] A. 4 rads-1 B. 100 rads-1 C. 25 rads-1 D. 5 rads-1 = x Gi mnM d 2 x dt2 Gi mnM = 100 4 = 25 ev, = 5rads–1 STEP 02 ANALYSIS OF RU QUESTION 01. 4 d 2 x dt2 + 16x = 0 mgxKiYwU GKwU mij Qw›`Z ¯ú›`b eY©bv K‡i| GB ¯ú›`‡bi †K․wYK K¤úv¼ KZ? [RU. Astrazeneca, Set-1. 20-21] A. 4 rad s1 B. 16 rad s1 C. 2 rad s1 D. 1 2 rad s1 S C info cÖ`Ë mgxKiY, 4 d 2 x dt2 + 16x = 0 d 2 x dt2 + 4x = 0 ......(i) mij Qw›`Z ¯ú›`bMwZi mgxKiY d 2 x dt2 + 2 x = 0 Gi mv‡_ (i) Zzjbv K‡i, 2 = 4 = 2rads–1

308 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 02. Drm hw` w¯ i †kÖvZv †_‡K k‡ãi `ªæwZ‡Z `~‡i m‡i hvq, Z‡e kÖæZ k‡ãi AvcvZ K¤úvsK cÖK…Z K¤úvs‡Ki KZ n‡e? [RU. 17-18] A. A‡a©K B. mgvb C. wØ¸Y D. ‡KvbwUB bq Wcjv‡ii wµqv: f = f V + V0 V – Vs w¯’i †kÖvZvi Rb¨, V0 = 0, Dr‡mi †eM, Vs = –V f = f V V + V = 1 2 f = cÖK…Z K¤úv‡¼i A‡a©K| STEP 03 ANALYSIS OF CU QUESTION 01. GKwU mij Qw›`Z ‡`vj‡Ki ch©vqKv‡ji dg©~jv ‡KvbwU? [CU. 15-16] A. T = 2 k m B. T = 2 m k C. T = 4 k D. T = 2 k E.T = 4 m k Ans B 02. mij Qw›`Z MwZm¤úbœ GKwU KYvi MwZi mgxKiY y = 4sin [360t0.2)]; KYvwUi we¯Ívi KZ? [CU. 12-13] A. 0.2 B. 360 C. 2 D. 4 E. 2 y = Asin (t + Gi mv‡_ Zzjbv K‡i cvB, A = 4 03. mij Qw›`Z MwZ m¤úbœ GKwU e¯‧ MwZi mgxKiY n‡”Q x = 6cos 3t + 3 meters, t =2sec mg‡q e¯‧wU miY n‡e- [CU. 08-09] A. 1.0m B. 0.0m C. 6.0m D. 3.0m E. 2.0m x = 6cos 3 2 + 3 ev, x = 6cos (6 + 3 ) x = 6 1 2 = 3 STEP 04 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. 0.02 kg f‡ii e¯‧ 10cm we¯Ívi Ges 2sec ch©vq Kv‡ji mij Qw›`Z MwZ cÖvß n‡j e¯‧wU m‡e©v”P `ªæwZ wbY©q Ki| [JnU. 09-10] A. 0.628ms–1 B. 0.314ms–1 C. 0.55ms–1 D. 0.413ms–1 Vmax = A = 2 2 23.14 0.1 A T = 0.31ms–1 02. GKwU Zv‡ii wfZi w`‡q mvB‡bv‡mvBWvj Zi½ cÖevwnZ n‡j Zv‡ii KYvi m‡e©v”P `ªæwZ VS| Zv‡ii GKwU KYvi miY we¯Ív‡ii A‡a©K n‡j H KYvi `ªæwZ n‡jv? [JnU. 09-10] A. vs /2 B. 3vs /2 C. 2Vs D. 2vs /4 Vmax = A = Vs Avevi, v = A 2 – x 2 = A 2 – A 2 2 = A 2 – A 2 4 = A 3 2 = 3 2 Vs PART B Analysis of Science & Technology Question SUST 01. GKwU mij Qw›`Z MwZ m¤úbœ KYvi MwZi mgxKiY d 2 x dt2 + 16x = 0 n‡j KYvwUi ch©vqKvj (T) †m‡K‡Ð KZ n‡e? [SUST. 18-19] A. B. 2 C. 4 D. 8 E. 2 2 = 16 4 2 = 2 02. `ywU ¯ú›`biZ KYvi miY h_vµ‡g x = Asint Ges x = Acost n‡j G‡`i `kv cv_©K¨? [SUST. 07-08; Xv.†ev. 2021] A. 2 B. C. 3 D. 2 Ans D MBSTU 01. mij Qw›`Z MwZ‡Z Pjgvb GKwU e¯‧i †gvU kw³ E, K¤úv¼ AcwiewZ©Z †i‡L we¯Ívi wØ¸Y Ki‡j mij Qw›`Z MwZ‡Z Pjgvb e¯‧wUi †gvU MwZkw³ KZ n‡e? [MBSTU-C, Set-2 19-20] A. E B. 2E C. E/2 D. 4E E A 2 we¯Ívi wØ¸Y Ki‡j †gvU MwZkw³ 4 ¸Y n‡e| 02. GKwU mij Qw›`Z MwZ m¤úbœ KYvi m‡e©v”P ‡eM 0.03ms–1 I we¯Ívi 0.006m n‡j ch©vqKvj KZ? [MBSTU. 15-16] A. 5 s B. 2 s C. 4.5 s D. 18 s S Blank info vmax = A ev, vmax = 2 T A ev, T = 2A Vmax = 2 0.006 0.03 = 1.2566 DU Technology 01. GKwU Zi‡½i mgxKiY n‡jv, y = 10 sin(200t x) n‡j, Zi½wUi ch©vqKvj KZ? [DU-Tech.19-20] A. 1 s B. 0.5 s C. 0.1 s D. 0.01 s = 200 2 T = 200 T = 2 200 = 0.01 sec STEP 05 ANALYSIS OF ENGINEERING & BUTex QUESTION BUET 01. GKwU e¯‧ x 2cos(50t) Abymv‡i mij Qw›`Z MwZ‡Z `yj‡Q, †hLv‡b x Gi cwigvc wgUv‡i Ges t Gi cwigvc †m‡K‡Û| Bnvi m‡ev©”P †eM ms–1 GK‡K n‡e- [BUET. 12-13] A. 100sin(50t) B. 100cos(50t) C. 100 D. 200 x = 2 cos (50t), x = A cos (t) = 50, A = 2, Vmax = A = 50 2 = 100 CKRuet. Combind 01. mvg¨ve¯ vb †_‡K GKwU mij †`vjb MwZ m¤úbœ e¯‧ KYvi Kx cwigvY n‡j Gi †eM (v) m‡e©v”P †e‡Mi V max A‡a©K n‡e? [A = we¯Ívi] [CKRUET. 2020-21] A. ± A 2 – v 2 2 B. A 2 C. 1 2 A 2 sin2 ( + ) D. vmax A E. 3 2 A S E info v = 1 2 vmax A 2 – x 2 = 1 2 A A 2 – x 2 = A 2 4 4A2 – 4x2 = A2 x 2 = 3 4 A 2 x = 3 2 A 02. mij Qw›`Z ¯ú›`bœ GKwU e¯‧i †eM 3 m/sec miY ZLb 4 meter| Avevi, †eM hLb 4 m/sec miY ZLb 3 meter| †`vj‡bi we¯Ívi I ch©vqKvj wbY©q Ki| [CKRUET. 2020-21] A. 5m, 6.28 sec B. 5m, 628 sec C. 5.25 m, 6.28 sec D. 5.25 m, 6.28sec E. 5.5 m, 6.28 sec S A info v = A 2 – x 2 3 = A 2 – 4 2 ... .... ....(i); 4 = A 2 – 3 2 ... .... ... (ii); (i) 2 (ii) 2 9 16 = A 2 – 16 A 2 – 9 9A2 – 81 = 16A2 256 7A2 = 175 A 2 = 25 A= 5m = 3 5 2 – 4 2 = 3 3 = 3 3 = 1 rads–1 T = 2 = 2 s = 6.28s

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 309 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES KUET 01. mij Qw›`Z MwZ‡Z Pjgvb GKwU e¯‧i mgxKiY y = 10sin(12t/6) GLv‡b y Gi GKK wgUvi, t Gi GKK †m‡KÛ Ges `kv aªæe‡Ki GKK rad| e¯‧wUi m‡e©v”P `ªæwZ KZ? [KUET. 14-15] A. 10 m/s B. 12 m/s C. /6 m/s D.120 m/s E. 120 cm/s y = 10 sin 12t – 6 Compare with , y = A sin (t- ), = 12, A= 10 Vmax = A = 12 10 = 120ms–1 02. mij Qw›`Z ¯ú›`‡b GKwU KYvi m‡e©v”P Z¡iY 8m/s2 Ges m‡e©v”P `ªæwZ 1.6m/s KYvwUi ch©vq Kvj wbY©q Ki? [KUET. 07-08] A. sec B. 4sec C. 0.4sec D. 0.04sec E. 40sec amax= 2A......................(i. Vmax=A...................................(ii. (i ÷ ii) K‡i cvB, amax vmax = 8 1.6 = 2 T ev, T = 1.6 4 = 0.4 sec STEP 06 ANALYSIS OF HSC BOARD QUESTION 01. mij Qw›`Z ¯ú›`bkxj GKwU KYvi †`vjbKvj 10 †m‡KÛ| †Kvb mgxKiYwU Gi Z¡iY ‘a’ Ges miY ‘x’ Gi m¤úK© cÖKvk K‡i? [Xv. †ev. 2015; P. †ev. 2015] A. a = – 10x B. a = – (20)x C. a = – 2 10 2 x D. a = – (20) 2 x S C info a = – 2 x = – 2 10 2 x 02. †m‡KÛ †`vj‡Ki •`N©¨ AwfKl©R Z¡iY g Gi- [Xv. †ev. 2015] A. eM©g~‡ji mgvbycvwZK B. mgvbycvwZK C. eM©g~‡ji e¨¯ÍvbycvwZK D. e¨¯ÍvbycvwZK S B info T = 2 L g L g 03. 4 d 2 x dt2 + 64x = 0 mgxKiY Øviv ewY©Z MwZkxj †Kv‡bv KYvi K¤úvsK- [iv. †ev 2021] A. 1 Hz B. 2 Hz C. 8 Hz D. 16 Hz 4 d 2 x dt 2 + 64 x = 0 d 2 x dt2 + 16 x = 0 2 = 16 = 4 2 f = 4 f = 4 2 = 2 Hz 04. mij Qw›`Z MwZ‡Z Pjgvb GKwU e¯‧i we¯Ívi 0.01m I K¤úv¼ 12Hz, e¯‧wUi 0.005m mi‡Y †eM KZ? [iv. †ev. 2017] A. 0.03 ms1 B. 0.3968 ms1 C. 0.5328 ms1 D. 0.65264 ms1 Ans D wb‡Pi Aby‡”Q`wU c‡o 05bs cÖkœwUi DËi `vI: [iv. †ev. 2017] 0.01kg f‡ii GKwU e¯‘KYv mij‡iLv eivei mij †`vjbMwZ AR©b K‡i| Gi †`vjbKvj 2 sec, we¯Ívi 0.1m Ges miY 0.02m| 05. DÏxc‡K DwjøwLZ miYKv‡j MwZkw³ wefekw³i KZ ¸Y n‡e? A. 0.42 ¸Y B. 2.4 ¸Y C. 4.2 ¸Y D. 24 ¸Y S D info Ek Ep = a 2 – x 2 x 2 = 0.12 – 0.022 0.02 2 = 24 06. mij Qw›`Z MwZm¤úbœ †Kv‡bv KYvi Z¡iY †Kvb ivwkwUi mgvbycvwZK? [iv. †ev. 2016; e. †ev. 2016] A. ej B. miY C. ch©vhKvj D. †eM Ans B 07. 5 d 2 x dt2 +180x = 0 mgxKi‡Y †K․wYK K¤úv¼ KZ GKK? [P. †ev. 2016] A. 180 B. 36 C. 6 D. 5 S C info 5 d 2 x dt2 +180x = 0 d 2 x dt2 + 36x = 0 2 = 36 = 6 rad/s wb‡Pi DÏxc‡Ki Av‡jv‡K 08 I 09bs cÖ‡kœi DËi `vI : mij †`vjMwZm¤úbœ GKwwU KYvi miY x = 3sin2t. 08. KYvwUi ¯ú›`‡bi ch©vqKvj- [w`.‡ev 2021] A. 0.5 sec B. 1sec C. 2 sec D. 4sec Ans B 09. mvg¨ve¯ vb †_‡K 1m `~‡i KYvwUi MwZkw³ I wefekw³i AbycvZ- [w`.‡ev 2021] A. 1 : 3 B. 2 1 C. 2 : 1 D. 3 : 1 S C info Ek = 1 2 K (A2 – x 2 ) Ep = 1 2 Kx2 Ek EP = { 3 2 – 1} 1 2 Ek : Ep = 2 : 1 10. GKwU mij †`vjMwZ m¤úbœ e¯‧KYvi fi m Ges K¤úvsK n‡j ej aªæeKwU n‡e- [w`.‡ev 2021] A. m B. m C. m 2 D. m S C info = K m 2 = K m 2 = K m K = m 2 DÏxcKwU c‡o wb‡¤œi 11 Ges 12bs cÖkœ `yBwUi DËi `vI: [h. †ev. 2017] mij Qw›`Z MwZm¤úbœ KYvi mgxKiY y = 10 sin 2 T + 4 , hvi ch©vqKvj 5 sec| 11. 1.25 sec G KYvwUi miY KZ GKK n‡e? A. 707 GKK B. 10 GKK C. 12 GKK D. 18 GKK Ans A 12. KYvwUiÑ i. Avw` `kv x 4 ii. K¤úvsK 0.1Hz iii. we¯Ívi 7 GKK wb‡Pi †KvbwU mwVK? A. i B. ii I iii C. i I iii D. i, ii I iii Ans A 13. †Kv‡bv KYvi ¯ú›`b MwZi mgxKiY x = 10 sin (6t + 2)| KYvwUi K¤úv¼ KZ? [h. †ev. 2017] A. 1.5 Hz B. 6 Hz C. 3 Hz D. 10 Hz S C info = 6 2f = 6 f = 3 14. mij MwZm¤úbœ †Kv‡bv KYvi m‡e©v”P miY KZ n‡e? [h. †ev. 2016] A. xmax = 2A B. xmax = A C. xmax = A D. xmax = 2 x Ans C 15. GKwU mij Qw›`Z MwZm¤úbœ KYvi m‡e©v”P †eM 0.03ms–1 | KYvwUi we¯Ívi 0.006m n‡j †K․wYK K¤úvsK KZ? [Kz.‡ev 2021] A. 3 rad s–1 B. 10 rad s–1 C. 5 rad s–1 D. 7 rad s–1 S C info Vmax = A = Vmax A = 0.03 0.006 = 5 rad S–1 wb‡Pi DÏxc‡Ki Av‡jv‡K 16 Ges 17bs cÖkœ `yBwUi DËi `vI: [Kz. †ev. 2017] Ò0.3m •`‡N©¨i GKwU †`vjK GKwU Aa©e„‡Ë †`vj †`q| Gi e‡ei fi 0.01kg|Ó 16. me©wb¤œ Ae¯ v‡b MwZkw³ KZ? A. 2.425J B. 0.0294J C. 0.0194J D. 0J S B info mgL = 1 2 mv2 T = 1 2 mv2 = mgL = 0.01 × 9.8 × 0.3 = 0.0294 17. me©wb¤œ Ae¯’v‡b eewU wQ‡o †M‡j e‡ei MwZc_ cÖKvkKvix mgxKiY †KvbwU? A. y = mx B. y = c + mx C. y = bx cx D. y = cx2 S D info y = – 1 2 at2 = – 1 2 g x v 2 = – g 2v x 2 y = – g 2v x 2 y = – cx2

310 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 18. mijQw›`Z KYvi miY cybive„wË nq KLb? [g.‡ev 2021] A. 2 mgq ci B. mgq ci C. 2 mgq ci D. mgq ci S A info = 2 T T = 2 19. mij Qw›`Z ¯ú›`b m¤úbœ KYvi mgxKiY Y = A sin 2 (vt – x) KYvwUi m‡e©v”P miYÑ [e. †ev. 2019] A. 1 2 A B. A C. 1 2 D. Ans B wb‡Pi DÏxc‡Ki Av‡jv‡K 20 Ges 21bs cÖkœ `yBwUi DËi `vI : [e. †ev. 2019] mij †`vj MwZm¤úbœ GKwU KYvi miY x = 4 sin 4t wgUvi| 20. KYvwUi ¯ú›`‡bi ch©vqKvj KZ? A. 0.5 sec B. 1 sec C. 2 sec D. 4 sec S A info = 4 2 T = 4 T = 0.5 s 21. mvg¨ve¯ vb †_‡K 2 m `~‡i KYvwUiÑ i. MwZkw³ m‡e©v”P ii. wefekw³ m‡e©v” iii. †gvUkw³ = wefekw³ wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans C Concept 2 w¯úªs msµvšÍ MvwYwZK cÖ‡qvM FORMULA 01. ej, F = kx; k= ej aªæeK; mg = kx w¯úªs/ejaªæeK, k= mg x 02. †`vjbKvj, T = 2 g e [e = w¯úªs cÖmviY] 03. K…ZKvR ev w¯’wZkw³, w = 2 1 kx2 = 1 2 m 2 x 2 04. w¯úªs Gi MwZkw³, EK = 2 1 K (A2 – x 2 ) = 2 1 m 2 (A2 – x 2 ) 05. w¯úªs Gi †gvUkw³, E = 2 1 KA2 = 2 1 m 2A 2 06. K…ZKvR, w = 2 1 k 2 i 2 f x x [xi , xf `ywU Avw` Ae¯’vb n‡Z gvc‡Z n‡e] [xi= w¯úªs Gi Avw` Ae¯’vb; xf = w¯úªs Gi †kl Ae¯’vb] 07. GKwU w¯úªs‡K m:n Abycv‡Z KvU‡j, i. cÖ_g UzKivi w¯úªs aªæeK = m + n m k ii. wØZxq UzKivi w¯úªs aªæeK = m + n n k CONCEPTUAL MATH MEx 01 †Kvb SzjšÍ w¯cÖs G 50gm f‡ii e¯‧ Szjv‡j Zvi 20cm cÖmvib nq| Zvi ci †Q‡o w`‡j `yj‡Z _v‡K| w¯cÖs Gi †`vjb Kvj KZ n‡e? T = 2 g e = 2 9.8 .2 = 0.898s. Ans. [we.`ª: †`vjbKv‡ji Dci f‡ii †Kvb cÖfve †bB] MEx 02 k = 100 Nm–1 w¯cÖswU‡K 10cm cÖmvwiZ Ae¯ v n‡Z AviI 5cm cÖmvwiZ Ki‡Z K…ZKvR KZ? W = 1 2 k(xf 2 xi 2 ) 1 2 100{(.15)2 – (.1)2 } = .625J xi = 10cm, xf = 15cm MEx 03 k w¯úªs-aªæe‡Ki GKwU w¯úªs‡K †K‡U `yB As‡k Ggbfv‡e fvM Kiv n‡jv †h, GKwUi •`N¨© AciwUi wØ¸Y| AwaKZi j¤^v w¯úªswUi w¯úªs-aªæeK KZ? myZivs 1:2 Abycv‡Z KvU‡j eo UzKivi w¯úªs aªæeK = 1 + 2 2 k = 3 2 k NOW START PRACTICE 01. L ‣`N©¨ Ges K w¯cÖs aªæeK wewkó GKwU w¯cÖs‡K †K‡U mgvb Pvi UzKiv Kiv n‡j cÖwZ UzKiv w¯cÖs Gi w¯cÖs aªæeK n‡e02. †Kvb w¯úªs‡qi we¯Ívib 5cm| w¯úªswU‡K ej cÖ‡qv‡M †U‡b j¤^v Kivq Gi mnY 2cm n‡j, D³ †ÿ‡Î MwZkw³ wbY©q Ki? (k = 110Nm–2 ) 03. GKwU w¯úªs-G 3kg fi Szjv‡bv nj| G‡Z w¯úªswUi •`N©¨ 5cm e„w× †c‡j w¯úªs aªæeK KZ n‡e? 04. 25 N ej †Kvb w¯cÖs‡K †U‡b 10 cm e„w× K‡i| w¯cÖswU‡K 6 cm cÖmvwiZ Kiv n‡j K…Z Kv‡Ri cwigvYNOW PRACTICE SOLVE : 01. k = mg L = mg g g L 4 = mg L 4 = 4 K 03. K = mg x = 3 × × 102= 588 Nm1 02. Ek = 1 2 k (A2 – x 2 ) = 1 2 110 {(0.05)2 – (0.02)2 } = 0.115J 04. F = Kx ev, K = F x = 25 0.1 = 250 W = 1 2 Kx2 = 1 2 × 250 × (.06)2 = 0.45 J

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 311 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. GKwU Av`k© w¯cÖs Gi ‡kl cÖv‡šÍ Szjv‡bv GKwU fi T ch©vqKvj wb‡q Djø¤^fv‡e ¯úw›`Z nq| GLb ¯ú›`‡bi we¯Ívi wØ¸Y Kiv n‡j, bZzb †`vjbKvj n‡e- [DU. 15-16] A. T B. 2T C. T/2 D. 4T T = 2 L g GLv‡b we¯Ívi †`vjbKvj‡K cÖfvweZ K‡i bv| ZvB †`vjbKvj GKB _vK‡e| 02. 300 Nm–1 ej aªæeK m¤úbœ GKwU w¯úÖs‡K KZUzKz msKzwPZ Ki‡j 1.5 J KvR Kiv n‡e? [DU. 06-07] A. 0.1 m B. 1.5 m C. 3.0 m D. 1.0 m KvR, W = 2 1 kx2 x = 2W k = 2 × 15 300 = 0.1m 03. 2 Nm–1 w¯úÖs aªæeK m¤úbœ GKwU Av`k© w¯úÖs‡qi •`N©¨ mvg¨e¯ v †_‡K 0.1 m e„w× Ki‡j w¯úÖs‡qi w¯ wZkw³i e„w× n‡e- [DU. 04-05] A. 0.01 J B. 0.1 J C. 1 J D. 0.001 J w¯úÖs‡qi K…ZKvR/ w¯’wZkw³, W = 2 1 kx2 = 1 2 2 (0.1)2 = 0.01 J 04. GKwU w¯cÖs-G 5 kg fi Szjv‡bv nÕj| G‡Z •`N©¨ 2 cm e„w× †cj| w¯cÖs aªæe‡Ki gvb n‡”Q- [DU. 04-05] A. 24.5 N/ms B. 245 N/m C. 250 N/m D. 2450 N/m L mg k .02 59.8 2450 N / m STEP 02 ANALYSIS OF RU QUESTION 01. w¯úªs-G SzjšÍ m f‡ii GKwU e¯Íyi ch©vqKvj 2sec n‡j 4m f‡ii e¯Íyi Rb¨ ch©vq Kvj KZ †m‡KÛ? [RU. 18-19] A. 1 B. 4 C. 8 D. 16 T2 T1 = 4m m = 2 T2 = 2 2 = 4sec STEP 03 ANALYSIS OF CU QUESTION 01. 80 Nm–1 ej aªæeK m¤úbœ GKwU w¯úªs‡K †U‡b 300 cm j¤^v Kiv n‡jv| w¯úªs e‡ji wecix‡Z K…Z Kv‡Ri cwigvY KZ? [CU-A, 19-20] A. 3.6 10–2 J B. 3.6 J C. 72 J D. 360 J w = 1 2 kx2 = 1 2 × 80 × (3)2 = 360J 02. 25N ej Øviv †Kvb w¯cÖs‡K †U‡b 10cm e„w× Kiv n‡jv| Gi w¯cÖs aªæeK KZ? [CU. 14-15] A. 22:5cms-1 B. 250Ncm C. 2.5Nm D. 250Nm–1 F = kx ev, Nm x F k 250 0.10 25 Nm–1 STEP 04 ANALYSIS OF GST QUESTION 01. mij Qw›`Z MwZm¤úbœ e¯‧i mi‡Yi mgxKiY x = 2 sin 3t Ges w¯úªs aªæeK k = 30 Nm–1 n‡j, t = /9 mg‡q Gi wefe kw³ KZ GKK? [GST-A. 20-21] A. 40 B. 45 C. 80 D. 90 S B info U = 1 2 kx2 = 1 2 × 30×3 = 45J [x = 2 sin 3 = 3] PART A Analysis of General University Question JnU 01. GKwU finxb w¯cÖs Gi GK cÖv‡šÍ `„pfv‡e AvU‡K †i‡L AcicÖvšÍ 500gm fi Szwj‡q w`‡q GKUz †U‡b †Q‡o †`qv n‡jv| w¯cÖs aªæeK 200N/m n‡j Gi K¤úvsK KZ? [JnU. 14-15] A. 6.4Hz B. 4.8Hz C. 3.2Hz D. 1.6Hz f = 1 2 k m ev, f = 1 2 200 0.50 = 3.1830 =3.2Hz 02. GKwU w¯cÖs G 1kg fi Szjv‡bv n‡jv| G‡Z w¯cÖs wUi •`N©¨ 1m e„w× †c‡j w¯cÖs aªæeK n‡e? [JnU. 06-07] A. 9.8N/m B. 1N/m C. 0.50N/m D. 98N/m S A info x mg k = 1 19.8 =9.8N/m KU 01. †Kvb w¯cÖs Gi GK cÖv‡šÍ m f‡ii GKwU e¯‧ Szjv‡j GwU 6m cÖmvwiZ nq| e¯‧wU‡K Gi ci GKUz †U‡b †Qvo w`‡j Gi ch©vq Kvj KZ n‡e- [KU. 09-10] A. 4.9s B. 0.39s C. 0.29s D. 0.49s Z¡ ib mib T 2 ev, 9.8 6 T 2 = 4.9s PART B Analysis of Science & Technology Question SUST 01. GKUv w¯cÖs‡qi Dci 1 kg fi ivLv n‡j †mwU 10cm msKzwPZ nq| GKwU 5kg fi 1m Dci ‡_‡K w¯cÖswUi Dci †Q‡o w`‡j w¯cÖswUi KZ m msKzwPZ n‡e? [SUST. 13-14] A. 0.98 B. 1.00 C. 1.41 D. 4.43 E. 0.22 F = kx k= F x == mg x = 1 9.8 .1 = 98 again, W = 1 2 kx2 , So, mgh = 1 2 kx2 x 2 = 2mgh k = 2 5 9.8 1 98 = 1 x = 1 02. GKwU w¯cÖs Gi GK cÖv‡šÍ †Svjv‡bv GKwU fvi‡K wØ¸b Kiv n‡j Zvi K¤úvsK- [SUST. 09-10] A. †e‡o wØ¸b n‡e B. K‡g A‡a©K n‡e C. 4 ¸b evo‡e D.1.4 ¸Y n‡e n = 1 2 k m n2 n1 = m1 m2 ev, n2 n1 = 1 2 ev, n1 n2 = 2 ev, n1 = 2n2 = 1.4 n2 = 1.4 ¸Y 03. mij Qw›`Z MwZ‡Z ¯ú›`bkxj GKwU KYvi we¯Ívi A Ges ej aªæeK k n‡j, KYvwUi †gvU kw³- [SUST. 07-08] A. 2 2 1 KA B. 2 2 1 Kx C. K a 2 2 1 D. kx †gvU kw³ E = 1 2 KA2 04. K w¯cÖs aªæe‡Ki GKwU w¯cÖs †K †U‡b j¤^v Kiv n‡jv| wØZxq GKwU w¯cÖs‡K Gi A‡a©K cwigvY j¤^v Ki‡Z wØ¸Y KvR Ki‡Z nq| 2q w¯cÖs Gi w¯cÖs aªæeK KZ? [SUST. 06-07] A. K B. 2K C. 4K D. 8K E. 16K 2 1 2 1 2 1 2 x x k k w w ev, 2 2 2 1 1 2 k k ev, k2 = 8k

312 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 05. ‡Kvb w¯cÖs Gi GK cÖv‡šÍ GKwU e¯‧ Szjv‡j 10 cm cÖmvwiZ nq| e¯‧wU GKUz †U‡b †Q‡o w`‡j K¤úv¼ KZ n‡e? [g = 10ms–2 ] [SUST. 05-06] A. 1.11 Hz B. 1.57 Hz C. 3.0 Hz D. 4.0 Hz n = 1 2 ZiY miY = 1 2 10 0.1 = 1.57 Hz JUST 01. GKwU w¯úªs‡qi ej aªæeK 60 Nm–1 | w¯úªswU‡K ¯^vfvweK Ae¯ v n‡Z 0.5 m cÖmvwiZ Ki‡Z K…ZKvR KZ n‡e? [JUST-C, 19-20] A. 5.7 J B. 7.5 J C. 0.57 J D. 570 J W = 1 2 kx2 = 1 2 × 60 × (0.5)2 = 7.5 J STEP 05 ANALYSIS OF ENGINEERING & BUTex QUESTION BUET 01. L ‣`N©¨ Ges K w¯cÖs aªæeK wewkó GKwU w¯cÖs‡K †K‡U mgvb Pvi UzKiv Kiv n‡j cÖwZ UzKiv w¯cÖs Gi w¯cÖs aªæeK n‡e- [BUET. 10-11] A. k 4 B. k 2 C. 2k D. 4k k = mg L = m g g L 4 = mg L 4 = 4k 02. GKwU w¯cÖs (aªæeK ej, K) ‡K †K‡U `yB As‡k Ggb fv‡e fvM Kiv n‡jv †h GKwUi •`N©¨ AciwUi wØ¸Y| AwaKZi j¤^ w¯cÖswUi aªæeK e‡ji gvb KZ? [BUET. 09-10] A. 2 3 k B. 3 2 k C. 3K D. 2K K1x1=K2x 2 ev, K1x1=K2.2x1 ev, K1=2K2 K1+K2=K ev, 2K2+K2=K ev, K K 3 1 2 , Ges K K 3 2 1 STEP 06 ANALYSIS OF HSC BOARD QUESTION 01. GKwU w¯úªs‡K cÖmvwiZ Kiv nj [wm. †ev. 2017] i. GwU wefe kw³ AR©b K‡i ii. GwU cÖZ¨qwb ej jvf K‡i iii. cÖZ¨qwb e‡ji Øviv K…Z KvRB Gi wefe kw³ wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans D Concept 3 mij †`vjK msµvšÍ MvwYwZK cÖ‡qvM FORMULA 01. †`vjbKvj: T = 2 g L ; T = N t ; t → †gvU mgq , N → †gvU †`vjb msL¨v 02. R h R L L 2 1 2 T 1 T 03. 1 2 2 T 1 T g g ASPECT SPECIAL: Kvh©Kix •`N©¨ n ¸Y e„w× ‡c‡j †`vjb Kvj T2 = n 2; †`vjbKvj n ¸Y e„w× †c‡j •`N©¨, L2 = n 2L1 [Note: f~-†K›`ª, gnvKvk, K…wÎg DcMÖn GB wZb ¯ v‡b g = 0, T = , f = 0Hz] Model Example01 ch©vqKvj wØ¸Y Ki‡j †`vj‡Ki •`N©¨ KZ ¸Y e„w× cvq? General Rules [Written] 3 in 1 Shortcut Tricks & Tips [MCQ] GLv‡b, T2 T1 = 2; Avgiv Rvwb, T = 2 L g T2 T1 = L2 L1 2 = L2 L1 L2 L1 = 4 L2 = 4L1 L2 = n2L1 = (2)2 L = 4L Model Example02 GKwU †m‡KÛ †`vj‡Ki •`N©¨ Pvi¸Y e„w× Kiv n‡j, Gi †`vjbKvj KZ n‡e? General Rules [Written] 3 in 1 Shortcut Tricks & Tips [MCQ] T = 2 L g T2 T1 = L2 L1 T2 T1 = L2 L1 L2 L1 T1 = 4 T1 = 2 2 = 4 sec T2 = n T1 = 4 2 = 4 sec CONCEPTUAL MATH MEx 01 GKwU mij †`vj‡Ki †`vjbKvj 50% evov‡bv n‡j, Kvh©Kix •`N©¨ KZ n‡e? T2 T1 = L2 L1 150 100 = L2 L1 3 2 = L2 L1 9 4 = L2 L1 2.25L1 = L2 c~‡e©i 2.25 ¸Y| NOW START PRACTICE 01. GKB ¯ v‡b †Kvb GKwU mij †`vj‡Ki •`N©¨ wZb ¸Y e„w× Kiv n‡j, Zvi †`vjb Kvj KZ n‡e? 02. GKwU mij †`vj‡Ki •`N©¨ AciwUi wØ¸Y| wØZxq mij †`vj‡Ki †`vjbKvj 3s n‡j cÖ_gwUi †`vjbKvj KZ? 03. GKwU mij †`vj‡Ki †`vjbKvj T1 †`vjKwUi •`N©¨ wØ¸Y Kiv n‡j cwiewZ©Z †`vjbKvj n‡e? 04. ch©vqKvj wØ¸b Ki‡Z mij †`vj‡Ki •`N©¨ KZ¸b e„w× Ki‡Z n‡e? 05. awi `yBwU mij †`vjK A Ges B hw` A Gi •`N©¨ B Gi wØ¸Y Ges B Gi †`vjb Kvj 3S nq Z‡e A Gi †`vjb Kvj KZ? 06. †Kvb w¯cÖs Gi GK cÖv‡šÍ m f‡ii GKwU e¯‧ Szjv‡j GwU 6m cÖmvwiZ nq| e¯‧wU‡K Gi ci GKUz †U‡b †Q‡o w`‡j Gi ch©vq Kvj KZ n‡e07. †Kvb ¯ v‡b g = 981 cm/sec2 n‡j †mB ¯ v‡b †m‡KÛ †`vj‡Ki •`N©¨ KZ? 08. GKwU mij †`vj‡Ki ‡`vjbKvj 41% evov‡Z Gi Kvh©Ki •`N©¨ KZUzKz cwieZ©b Ki‡Z n‡e?

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 313 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES NOW PRACTICE SOLVE : 01. T2= 1 3.T =1.732 T1 = 1.73 ¸Y| 05. B A B A L L T T ev, 1 2 3 TA ev, TA= 3 2 =4.24S 02. 2 1 2 T 1 L T L ev, 1 2 3 1 T ev 3 2 1 T 4.24 s 06. T= 2 miY Z¡iY ev, 9.8 6 T 2 = 4.9s 03. 2 1 T n T (n = ¸b) ev 1 2 2 T T 07. T = 2 L g ev L = gT2 4 2 = 9.81 (2) 2 4 9.87 = 99.39cm 04. 1 2 1 2 L L T T ev 1 2 1 2 L L ev, 1 2 4 L L (eM© K‡i) L2 4L1 08. 41% evov‡j T2 = 1.41 T1 L2 = n2L1 L2 = ( 2) 2L1 ev, L2 = 2L1 REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. GKwU mij †`vj‡Ki †`vjbKvj 50% evov‡Z Gi Kvh©Ki •`‡N©ï cwieZ©b KZ n‡e? [DU. 20-21] A. 25% B. 100% C. 125% D. 67% S C info e„w×cÖvß †`vjbKvj, T2 = T1 + T1 Gi 50% = 1.5 T1; T2 T1 = 1.5 ; T = 2 L g n‡j, T L [g aªæeK n‡j] T 2 L T2 2 T1 2 = L2 L1 T2 T1 2 = L2 L1 L2 L1 = (1.5)2 L2 = 2.25L1 L = L2 – L1 = 2.25 L1 – L1 L = 125% L1 02. mij †`vj MwZ m¤úbœ GKwU KYvi we¯Ívi 0.02m Ges K¤úv¼ 2.5Hz n‡j Gi m‡e©v”P `ªæwZ KZ n‡e? [DU. 18-19] A. 0.05ms-1 B. 0.125 ms-1 C.0 .157 ms-1 D. 0.314 ms-1 m‡e©v”P †eM, Vmax = A = 2fA = 2 2.5 0.02 = 0.314ms1 03. c„w_ex c„‡ô (ge = 9.8 m/s2 ) GKwU †`vjK Nwo mwVK mgq †`q| NwowU P›`ªc„‡ô (gm=1.6 m/s2 ) †bIqv n‡j c„w_ex c„‡ôi 1h mgq P›`ªc„‡ô n‡e- [DU. 17-18] A. h 1.6 9.8 B. h 9.8 1.6 C. h 1.6 9.8 D. h 9.8 1.6 Tm = m e g g Te = 1.6 9.8 1= h 1.6 9.8 04. gy³fv‡e †Kvb cošÍ e¯‧i Z¡iY g wbY©q Ki‡Z wM‡q GKRb QvÎ GKwU mij †`vj‡Ki ‣`N©¨ l cwieZ©b K‡i wfbœ wfbœ l Gi Rb¨ †`vj‡Ki †`vjbKvj T cwigvc Kij| Gevi †m T 2 (y-axis) ebvg l (x-axis) †jLvwPÎ G‡K Xvj S †ei Kij g Gi gvb KZ? [DU. 14-15] A. 4 2 S B. 4 2 /S C. 2/S D. 2S g L T 2 2 4 ev, L g T 2 2 4 ev, g s 2 4 ev, s g 2 4 05. ch©vqKvj wØ¸b Ki‡Z mij †`vj‡Ki •`N©¨ KZ¸Y Ki‡Z n‡e? [DU. 10-11] A. 1 4 B. 1 2 C. 2 D. 4 L2 = n2L = 22L = 4L (n = ch©vq Kv‡ji ¸Y) 07. GKwU mij †`vj‡Ki •`N©¨ AciwUi wØ¸Y| wØZxq mij †`vj‡Ki †`vjbKvj 3s n‡j cÖ_gwUi †`vjbKvj KZ? [DU. 04-05, 13-14; NSTU. 12-13] A. 4.24 s B. 4.54 s C. 5.0 s D. 5.24 s 2 1 2 T 1 L L T ev, 1 2 3 1 T ev, 3 2 1 T 4.24 s 08. g½j MÖ‡ni e¨vmva© I fi h_vµ‡g c„w_exi e¨vmva© I f‡ii 0.532 ¸Y I 0.11 ¸Y| c„w_ex c„‡ô GKwU mij †`vj‡Ki †`vjbKvj 2 S n‡j g½j MÖ‡n †`vjb Kvj KZ ? [DU. 03-04] A. 4s B. 3.2s C. 1.25s D. 0.75s Tm Te = e¨vmv‡a©i ¸b f‡ii ¸b = 0.532 0.11 = 1.60×2 = 3.2s 09. 0.2 m •`N©¨ wewkó GKwU mij †`vj‡Ki †`vjbKvj 0.9 s cvIqv †Mj| †`vjbKvj 1.8s Ki‡Z n‡j †`vjKwUi •`N©¨ n‡e- [DU. 02-03; BU. 15-16] A. 0.1 m B. 0.28 m C. 0.4 m D. 0.8 m 2 1 2 T 1 L L T ev, 2 0.2 1.8 0.9 L ev, 2 0.2 2 1 L L 0.8m 2 10. hw` m fi wewkó GKwU mij Qw›`Z †`vj‡Ki ej aªæeK k †K wØ¸Y Kiv nq Z‡e †`vj‡Ki Avw` †`vjbKvj cwiewZ©Z nq wbgœiƒ‡c: [DU. 01-02] A. T 2 B. 2T C T 4 D. 2T T2 T1 = k1 k2 ev T2 T1 = 1 2 T2 = T1 2 11. GKwU †m‡KÛ †`vj‡Ki P›`ªc„‡ô †`vjbKvj KZ n‡e? (†Ìqv Av‡Q c„w_exi fi Pvu‡ì f‡ii 81 ¸Y Ges c„w_exi e¨vmva© Pvu‡ì e¨vmv‡a©i 4 ¸Y) [DU. 00-01] A. 4.5s B. 9s C. 8/9s D. 9/8s Tm = m e M M e m R R Te = 81 4 1 2 = 4.5s 12. GKwU mij †`vjMwZi we¯Ívi A Ges †`vjbKvj T, Gi m‡e©v”P †eM KZ? [DU. 00-01] A. T 2 A B. 2 T A C. T A D. AT m‡e©v”P †eM, vmax = A= T 2 A STEP 02 ANALYSIS OF JU QUESTION 01. hw` GKwU mij †`vj‡Ki we¯Ívi wØ¸Y Kiv nq, Zvn‡j mij †`vjKwUi ch©vqKvjÑ [JU-A, Set-B. 20-21] A. A‡a©K n‡e B. wØ¸Y n‡e C. Pvi¸Y n‡e D. AcwiewZ©Z _vK‡e S D info T = 2 L g | mij †`vj‡Ki †`vjbKvj ev ch©vqKvj e‡ei fi I we¯Ív‡ii Dci wbf©i K‡i bv| AZGe, ch©vqKvj AcwiewZ©Z _vK‡e|

314 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 02. GKwU †m‡KÛ †`vj‡Ki K¤úv¼Ñ [JU-A, Set-A. 19-20] A. 2.5 Hz B. 0.5 Hz C. 1.5 Hz D. 2 Hz K¤úv¼, f = 1 T = 1 2 = 0.5 Hz ASPECT SPECIAL: †m‡KÛ †`vj‡Ki †ÿ‡Î, †`vjbKvj, T = 2 sec; Aa© †`vjbKvj = 1 sec; K¤úv¼, f = 0.5 Hz; Kvh©Kix •`N©¨, L = g 2 = 0.993 m ev 99.3 cm ev 3.36 ft 03. `ywU mij †`vj‡Ki †`vjbKv‡ji AbycvZ 1:2 n‡j, Kvh©Ki •`‡N©ï AbycvZ KZ? [JU. 18-19] A. 1 : 2 B. 1 : 4 C. 1 : 2 D. 2 : 1 T = 2 L g LT 2 04. GKwU †m‡KÛ †`vj‡Ki •`N©¨ bq¸Y Kiv n‡j Gi †`vjbKvj KZ n‡e? [JU. 15-16] A. 4 sec B. 5 sec C. 6 sec D. 9 sec 9 2 6sec T2 n T1 05. GKwU mij †`vj‡Ki •`N©¨ 2.45| †Kvb ¯ v‡b AwfKl©R Z¡iY 9.81m/sec2 | G ¯ v‡b †`vjKwUi †`vjbKvj- [JU. 09-10] A. 4s B. 5.5s C. 3.54s D. 3.14s 9.8 2.45 T 2 = 3.14s 06. `ywU mij †`vj‡Ki †`vjbKv‡ji AbycvZ 4:5 n‡j, Kvh©Ki •`‡N©ï AbycvZ KZ? [JU. 06-07] A. 25:16 B. 16:25 C. 30:16 D. 40:32 T = 2 L g LT 2 L1 L2 = T1 2 T2 2 = 16 25 STEP 03 ANALYSIS OF RU QUESTION 01. 2 `kv cv_©K¨‡Z T ch©vqKv‡ji GKwU c~Y© K¤ú‡bi †K․wYK K¤úv¼ KZ? [CU-A, Set-4. 20-21; e. †ev. 2019] A. = 2T B. =2/f C. =T/2 D. =2/T S D info Avgiv Rvwb, †Kv‡bv KYv e„ËvKvi MwZc‡_ T mgq 2 †iwWqvb AwZµg Ki‡j †K․wYK †eM =2/T 02. GKwU mij †`vjK, x Gi •`N©¨ Aci GKwU †`vjK, y Gi •`‡N©ï 3 ¸Y| y †`vj‡Ki †`vjbKvj 1 3 sec n‡j, x-Gi †`vjbKvj KZ n‡e? [RU. Astrazeneca, Set-1. 20-21] A. 3sec B. 3 2 sec C. 3 sec D. 1 3 sec S D info †`vjbKvj T = 2 L g Zvn‡j T L; Tx Ty = Lx Ly = 3Ly Ly = 3 Tx = 1 3 3 = 1 3 sec [mij †`vjK x Gi •`N©¨ Lx = 3 Ly] 03. GKwU mij †`vj‡Ki †`vjbKvj 3S. n‡j Kvh©Ki •`N©¨ n‡e- [RU. 08-09, JUST. 15-16] A. 2.125m B. 2.234m C. 2.257m D. 2.158m 2 2 2 2 4 9.8 (3) 4 gT L = 2.234m 04. AwfKl©R Z¡iY g = 9.81ms-2 4s †`vjb Kvj wewkó GKwU mij †`vj‡Ki •`N©¨ = ? [RU. 09-10] A. 0.994m B. 1.988m C. 3.006m D. 3.976m 2 2 2 2 4 9.81 (4) 4 gT L =3.9758m 05. GKwU †m‡KÛ †`vj‡Ki •`N©¨ Zv‡ci d‡j Ggb fv‡e e„w× †cj ‡`vjbKvj cwiewZ©Z n‡q 2.05 ‡m‡KÛ n‡jv| cwiewZ©Z Ae¯ vq †`vjKwU NÈvq KZ wgwbU †ìx‡Z hv‡e? [RU. 12-13] A. 1 B. 1.5 C. 2 D.2.5 2s G Slow P‡j 0.05 Sec 3600s G Slow P‡j 0.05 3600 2 = 90 sec = 1.5 min STEP 04 ANALYSIS OF CU QUESTION 01. GKwU KYv a we¯Ívi I E †gvU kw³i mij Qw›`Z MwZ m¤úv`b ïiæ K‡i| GKwU Ae¯ v‡b Gi MwZkw³ 4 3E n‡j Gi miY KZ? [CU-A, Set-2. 19-20] A. 2 a y B. 2 a y C. 2 a 3 y D. y = a 3 4 × 1 2 ka2 = 1 2 k (a2 – y 2 ) 3a2 = 4a2 – 4y2 4y2 = a2 y 2 = a 2 4 y = a 2 02. 3 d 2 x dt2 + 48x = 0 mgxKiY Øviv ewY©Z mij †`vjb MwZi †K․wYK K¤úv¼ KZ? [CU-A, 19-20] A. 48 rads–1 B. 16 rads–1 C. 8 rads–1 D. 4 rads–1 3 d 2 x dt2 + 48x = 0 d 2 x dt2 + 16x = 0 2 = 16 = 4rads–1 03. GKwU mij †`vj‡Ki †`vjb Kvj T; †`vjKwUi •`N©¨ wØ¸Y n‡j cwiewZ©Z †`vjbKvj KZ n‡e? [CU. 20-21, 18-19, JU. 10-11,DU. 06-07,MBSTU. 14-15.BRUR. 13-14] A. T 2 B. 2T C 2T D. T 2 T L T2 = 2T 04. †Kvb GKwU †m‡KÛ †`vj‡Ki •`N©¨ hw` 2.25 ¸Y Kiv nq, Z‡e Gi †`vjbKvj n‡e- [CU. 15-16] A. 3 sec B. 7 sec C. 8 sec D. 10 sec E. 9 sec T2 nT1 2.252 3sec 05. GKB ¯ v‡b †Kvb GKwU mij †`vj‡Ki •`N©¨ wZb ¸Y Kiv n‡j, Zvi †`vjb Kvj KZ ¸Y n‡e? [CU. 11-12, 07-08] A. 1.70 B. 1.414 C. 1.71 D. 1.73 E. 1.50 T2 = n T1 = 3T1 = 1.73T1 STEP 05 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. mij †`vj MwZ m¤cbœ e¯‧i m‡e©v”P MwZkw³ Gi mgxKiY- [JnU. 17-18] A. E = 1 2 kA2 B. E = 1 2 m 2A 2 C. A I B DfqB D. †KvbwUB bq Ans C

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 315 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 02. GKwU mij †`vj‡Ki e‡ei fi 100g Ges Kvh©Ki •`N©¨ 1 wgUvi| Dj¤^ †iLv †_‡K GwU‡K 10 cm `~‡i †U‡b †Q‡o w`‡j MwZ c‡_i me©wbgœ we›`y AwZµgKv‡j e‡ei †eM wbY©q Ki [JnU. 08-09] A. 0.44 ms-1 B. 1.3ms–1 C. 0.22ms–1 D. 0.31ms–1 wP‡Î, x 1 (0.1) 0.995m 2 2 x = 1 2 – (0.1) 2 = 0.995m myZivs me©wbgœ we›`y‡Z †eM v = ? mv mgh 2 2 1 ev, v = 2gh = 2 9.8 5 10–3 O N A B x h 1 m 0.1m = 0.31ms–1 [h = 1–0.995 = 5 10–3 ] 03. GKwU mij †`vjK 27.5 s mg‡q 50wU †`vjb c~Y© Ki‡j †`vjKwUi •`N©¨ KZ? [JnU. 07-08] A. 7.51m B. 0.751m C. 23.6 cm D. 7.51 cm S A info g L T 2 ev, 9.8 2 50 27.5 L ev, L = 7.51 m 04. mij †`vjb MwZ m¤úbœ GKwU KYvi we¯Ívi 0.05m. Ges †`vjb Kvj 12.0s KYvwUi m‡e©v”P MwZ KZ? [JnU. 06-07] A. 0.026m/s B. 0.013m/s C. 0.52m/s D. 0.062m/s S A info T V 2 max 12.0 2 0.05 A =0.0261m/s KU 01. ch©vqKvj wØ¸Y Ki‡j mij †`vj‡Ki •`N©¨ KZ¸Y e„w× cv‡e? [KU-A, Set-Ka. 19-20; Kz. †ev. 2021] A. 1/4 B. 1/2 C. 2 D. 4 L T 2 L2 = n2L1 = (2)2L1 = 4L1 02. mij †`vjb MwZi ch©vqKv‡ji mgxKiY- [KU. 18-19] A. g = 4 2 L T 2 B. g = 4 L T 2 C. g = 4 2 L T D. g = 4 L T T = 2 L g g = 4 2L T 2 03. hw` †Kvb cvnv‡oi kx‡l© I Lwbi Mfx‡i mij †`vj‡Ki †`vjb Kvj GKB nq Zvn‡j cvnv‡oi D”PZv I Lwbi MfxiZvi AbycvZ n‡e [KU. 12-13] A. 1:2 B. 2:1 C. 4:3 D. 3:4 gh = gd ev, R d R h 1 2 1 ev, R d R h 2 ev, 2h=d ev, 2 1 d h ev, h:d =1:2 04. GKwU ‡m‡KÛ †`vj‡Ki •`N¨© Pvi¸b Kiv n‡j Gi †`vjb Kvj n‡e- [KU. 10-11, CU. 20-21,10-11] A. 4s B. 2S C. 6S D. 8S T nT 4 2 4s 2 1 05. ‡Kvb GKwU †m‡KÛ †`vj‡Ki •`N©¨ hw` 1.44 ¸Y e„w× Kiv nq Zvn‡j Gi †`vjbKvj KZ n‡e? [KU. 08-09] A. 2s B. 3s C. 2.4s D. 3.4s T2 nT1 = 1.44 2 2.4S s 06. ‡Kvb ¯ v‡b g = 981 cm/sec2 n‡j †mB ¯ v‡b †m‡KÛ †`vj‡Ki •`N©¨ KZ ? [KU. 03-04] A. 99.39 cm B. 90.39 cm C. 108 cm D. None T = 2 L g ev 2 4 2 gT L = 9.81 (2) 2 4 9.87 99.39 cm gvbwU gyL¯’ ivLv fvj| IU 01. GKwU mij †`vjK 0.9 sec G GKevi wUK Ki‡j Kvh©Ki ‣`N©¨Ñ [IU. 14-15, MBSTU. 15-16] A. 0.501 m B. 0.75 m C. 0.64 m D. 0.804 m g L T 2 ev, 20.9 = g L 2 ev, 0.81= g 2 L ev, L = 0.804 BRUR 01. GKwU mij Qw›`Z MwZm¤úbœ e¯‧i m‡e©v”P we¯Ívi 5.0 m I †`vjbKvj 5.0 s n‡j, e¯‧wUi m‡e©v”P †eM KZ? [BRUR-F, Set-2, 19-20] A. 3.93 m/s B. 3.13 m/s C. 7.1 m/s D. 6.20 m/s vmax = A = 2 T A = 2 5 × 5 = 6.20 ms–1 02. GKwU mij †`vj‡Ki †`vjb Kvj 8 †m. Gi K¤úvsK KZ? [BRU. 12-13] A. 1Hz B. 2Hz C. 0.125Hz D. 0.5Hz n = 1 T = 1 8 = 0.125Hz BU 01. ‡Kvb GKwU †m‡KÛ †`vj‡Ki •`N©¨ 25.6% evo‡j Gi †`vjb Kvj KZ n‡e? [BU. 12-13; MBSTU. 15-16] A. 2.24s B. 3.6s C. 25 D. 3.24s T2 1 0.256T = 1.256 2 =2.2414 PART B Analysis of Science & Technology Question SUST 01. 300 g f‡ii GKwU ej mij Qw›`Z MwZ‡Z MwZkxj| ga¨e¯ vb n‡Z e¯‧wU hLb 0.20 m miY nq ZLb Gi Dci wµqviZ cÖZ¨vqbx e‡ji gvb 0.24 N| ejwUi †`vjbKvj KZ s? [SUST-B, 19-20] A. 7.02 B. 5.25 C. 6.12 D. 3.14 E. 9.12 †`vjbKvj, T = 2 e a , a = F m = 0.24 0.3 = 0.8 ms2 T = 2 e a = 2 3.1416 0.2 0.8 = 2 3.1416 1 2 = 3.1416 s 02. c„w_exc„‡ô GKwU mij †`vj‡Ki †`vjbKvj 4.0s n‡j P›`ªc„‡ô Gi †`vjbKvj KZ †m‡KÛ (s) n‡e? [c„w_exi fi P‡›`ªi f‡ii 81 ¸Y Ges e¨vmva© P‡›`ªi e¨vmv‡a©i 4 ¸Y] [SUST. 15-16] A. 4 B. 5 C. 9 D. 16 E. 81 Tm = f‡ii ¸Y e¨vmv‡a©i ¸Y Te ev, 4 4 81 Tm 4 9sec 4 9 03. GKwU mij †`vj‡Ki MwZi mgxKiY y = -10 sin (6t) n‡j †`vjKwUi Z¡iY mg‡qi mv‡_ wKfv‡e cwiewZ©Z nq ? [SUST. 14-15] A. B. C. D. E. we¯Ívi – Ve nIqvq wb‡P †_‡K ïiæ n‡e| 04. 1m `xN© GKwU w¯cÖs‡q GKwU e¯‧ Szwj‡q †Q‡o †`Iqvi ci GwU †m‡K‡Û 1 evi c~Y© †`vjb †`q| †`vjb †_‡g hvIqvi w¯cÖswU KZ ‣`N¨© cÖmvwiZ n‡q _vK‡e? (g=10m/s2 ) [SUST. 11-12] A. 1.1m B. 1.2m C. 1.25m D. 1.5m E. 2m g L T 2 ev, 10 2 2 L ev, .L 10 1 2 ev, L 1.013m 10 2 (T = 1 evi c~b© †`vjb Gi mgq ×2 ev, T=1×2 = 2) a t a t a t a t a t

316 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 05. GKwU mij †`vj‡Ki ‡`vjbKvj 41% evov‡Z Gi Kvh©Ki •`N©¨ KZUzKz cwieZ©b Ki‡Z n‡e? [SUST. 07-08] A. 1.5 ¸Y B. 2 ¸Y C. 3 ¸Y D. 4 ¸Y L2= n2L1= (1.41)2 . L = 1.988 = A_©vr 2 ¸Y 06. GKwU mij †`vj‡Ki myZvi •`N©¨ 0.98 wg. Ges ‡`vjbKvj 2 †m. n‡j ‡`vjK wc‡Ûi e¨vmva© wbY©q Ki- [SUST. 05-06] A. 1.96 cm B. 3.0 cm C. 1.3 cm D. †KvbwU bq g L T 2 ev, g L T 2 4 2 2 4 2 gT L 2 4 ( ) 2 9.8 (2) L L 0.9929 m L l r 0.9929 0.98 r ev, r 0.01294 r 1.294 cm ev, r 1.3 cm 07. f~-c„‡ôi `yÕwU ¯ v‡b GKwU mij †`vj‡Ki †`vjbKvj h_vµ‡g 2 †m‡KÛ I 2.01 †m‡KÛ| cÖ_g ¯ v‡b AwfKl©R Z¡iY Gi gvb 9.8 ms-2 n‡j wØZxq ¯ v‡b Gi gvb KZ ? [SUST. 05-06] A. 9.5 ms-2 B. 9.7 ms-2 C. 9.2 ms-2 D. 9.9 ms-2 1 2 2 1 g g T T 2 2 1 1 2 T T g g 1 2 2.01 2 2 g g g2 = 9.7ms–2 JUST 01. mij Qw›`Z MwZm¤úbœ GKwU e¯‧i we¯Ívi 0.01 m Ges K¤úb 12 Hz n‡j, 0.005 m `~i‡Z¡ e¯‧wUi MwZ‡eM KZ ms–1 ? [JUST-A, Set-Ka 19-20] A. 0.55 B. 0.6 C. 0.7 D. 0.65 v = A 2 –x 2 = 2f (0.01) 2 – (0.005) 2 = 2 × 3.14016×12 (0.01) 2 – (0.005) 2 = 0.65 ms–1 02. GKwU mij †`vj‡Ki wc‡Ûi fi 2 kg Ges Kvh©Kix •`N©¨ 1.5 m| Dj¤^ †iLv n‡Z 6 ‡Kv‡Y †U‡b †Q‡o w`‡j †`vj‡Ki MwZc‡_i me©wb¤œ we›`y AwZµgKv‡j Zvi †eM KZ? [JUST. 15-16] A. 0.80 ms-1 B. 0.40 ms-1 C. 0.90 ms-1 D. 4.8 ms-1 E. 2.8 msvmax = 2 gl sin 2 = 2 9.8 1.5 sin 6 2 = 0.40 ms1 03. GKwU 10m ‣`‡N©¨i †¯‥j fvi‡K›`ª eivei Szwj‡q w`‡j †¯‥jwUi GKwU †`vjb m¤ú~Y© Ki‡Z KZ mgq jvM‡e? [JUST. 15-16] A. 8s B. 6.34 s C. Zero D. Infinite E. Is s g L T 6.34 9.8 10 2 2 MBSTU 01. 40 cm `xN© GKwU mij †`vjK GK wgwb‡U 40 evi †`vj †`q| hw` Gi •`N©¨ 160 cm nq Z‡e 60 evi `yj‡Z KZ mgq wb‡e? [MBSTU-C, Set-2 19-20] A. 30 s B. 60 s C. 160 s D. 180 s ‡`vjbKvj, T = 2 L g ; T1 = t N = 60 40 s = 1.5 s T L T2 = L2 L1 T1 = 160 40 1.5 = 3 s t = NT2 = 60 3 = 180s 02. GKwU †m‡KÛ †`vj‡Ki K¤úv¼Ñ [MBSTU-A, Set-2 19-20] A. 2.5 Hz B. 0.5 Hz C. 1.5 Hz D. 2 Hz K¤úv¼, f = 1 T = 1 2 = 0.5 Hz. 03. x = Asin(t + ) mgxKiY Abymv‡i x Gi †Kvb gv‡bi Rb¨ Z¡i‡Yi gvb me©wb¤œ n‡e? [MBSTU-B, Set-2 19-20] A. x = A 2 B. x = A C. x = 2A D. x = 0 a = – 2 x ; x = 0 n‡j amin = 0 04. gnvKv‡k GKwU †m‡KÛ †`vj‡Ki K¤úvsK KZ n‡e? [MBSTU-C, Set-2 19-20] A. 0 Hz B. 2 Hz C. 1 Hz D. Amxg f = 1 T = 1 = 0 [gnvKv‡k g = 0 ZvB T Amxg] 05. mij Qw›`Z ¯ú›`b m¤úbœ KYvi m‡e©v”P Z¡iY KZ? [MBSTU-C, Set-2 19-20] A. a = 2 x B. a = x 2 C. a = 2 x D. a = x 2 a = 2 x ; hLb miY m‡e©v”P nq ZLb Z¡iY m‡e©v”P| 06. 0.5Hz K¤úv¼ hy³ GKwU mij †`vj‡Ki Kvh©Ki ‣`N©¨ KZ? (g=9.8ms–1 ) [MBSTU. 14-15] A. 0.90m B. 0.9314m C. 0.98 m D. 0.993m n = 0.5Hz T = 2s T = 2 L g ev, 2 = 2 L g ev, L = 9.8 () 2 ev, L = 0.9929 = 0.993 BSMRSTU 01. hw` GKwU mij †`vj‡Ki we¯Ívi wØ¸Y Kiv nq Zvn‡j mij †`vjKwUi ch©vqKvjÑ [BSMRSTU-C, 19-20] A. wØ¸Y B. A‡a©K n‡e C. Pvi¸Y n‡e D. AcwiewZ©Z _vK‡e mij †`vj‡Ki †`vjb Kvj we¯Ív‡ii Dci wbf©i K‡i bv| 02. GKwU mij‡`vjK A Gi •`N©¨ Aci GKwU mij‡`vjK B Gi •`‡N©¨i 2 ¸Y| †`vjK B Gi †`vjbKvj 2sec n‡j †`vjK A Gi †`vjb Kvj KZ? [BSMRSTU: 14-15, KUET. 08-09] A. 2sec B. 4sec C. 2sec D. 22sec TA TB = LA LB ev, TA 2 = 2 1 ev, TA = 2 2 STEP 06 ANALYSIS OF ENGINEERING & BUTex QUESTION BUET 01. GKwU †m‡KÛ †`vj‡Ki •`N©¨ 25.6% e„w× Kiv n‡jv| Gi †`vjbKv‡ji e„w× n‡e- [BUET. 09-10] A. 12% B. 24% C. 5% D. 50% T2 = 1 + 0.256 T1ev, T2 = 1.256 2 = 2.24sec †`vjb Kv‡ji e„w× =2.24-2 =0.24 =24% KUET 01. †m‡KÐ †`vj‡Ki •`N©¨ 1% Kgv‡j, D³ †`vj‡Ki w`‡b KZ mgq cwiewZ©Z n‡e? [KUET. 18-19] A. 433s mgqe„w× cv‡e B. 433s mgq nviv‡e C. 216s mgqe„w× cv‡e D. 216s mgq mgq nviv‡e E. mgq AcwiewZ©Z _vK‡e T L; T 2 = 99 100 T = 99 100 2 2 86400 86400 + n = 99 100 2 = n 433 R = 6400km] H = 8.9km 02. GKwU †m‡K‡Û †`vj‡Ki •`N©¨ wZb¸Y e„w× Ki‡j †`vjbKvj KZ n‡e? [KUET. 12-13] A. 4s B. 5s C. 6s D. 16s E. 25s T2 13 T = 4 2 4S 03. GKwU †m‡KÛ †`vj‡Ki f~-c„‡ô mwVK mgq †`q| P‡›`ª wb‡q †M‡j Gi †`vjbKvj KZ n‡e? (c„w_exi e¨vmva© P‡›`ªi e¨vmv‡a©i 4 ¸Y Ges c„w_exi fi P‡›`ªi f‡ii 81 ¸Y) [KUET. 07-08] A. 5.4sec B. 4.5sec C. 2.25sec D.5sec E. 3.5sec Tm Te = f‡ii ¸Y e¨vmv‡a©i ¸Y = 81 4 ev, Tm = 4.5sec

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 317 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES CUET 01. ‡Kvb GKwU †m‡KÛ †`vj‡Ki •`N©¨ hw` 1.69 ¸Y e„w× Kiv nq, Zvn‡j Gi †`vjb Kvj KZ n‡e? [CUET: 12-13] A. 2.6sec B. 1.3sec C. 3.38sec D. None of them T2 = 1.69T=1.3 2 = 2.6 sec STEP 07 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. †Kvb mij Qw›`Z ¯ú›`b MwZ m¤úbœ KYvi we¯Ívi 3cm Ges m‡e©v”P †eM 6.24cms-1 n‡j, KYvwUi ch©vqKvj wb‡gœi KZ †m‡KÛ? [MAT. 10-11] A. 3.02 B. 2.03 C. 4.02 D. 0.02 Vmax = A ev, Vmax = 2 T A ev, T = max 2 V A 6.24 2 3 = 3.02 DAT 01. GKwU †m‡KÛ †`vj‡Ki Kvh©Ki •`N©¨ KZ? [DAT: 17-18] A. 0.993m B. 0.997m C. 0.799m D. 0.731m Ans A AFMC 01. ivRKxq †`vj‡Ki Kvh©Kix •`N©¨ KZ? [AFMC. 2020-21] A. 0.994m B. 2 sec C. 9.94m D. 1m S A info †m‡KÛ †`vj‡Ki Kvh©Ki •`N©¨, L = g 2 = 9.8 (3.14) 2 = 0.993 m = 99.3 cm = 3.36ft STEP 08 ANALYSIS OF HSC BOARD QUESTION 01. GKwU mij‡`vj‡Ki Kvh©Ki •`N©¨ A‡a©K K‡i c„w_exi †K‡›`ª wb‡q †M‡j Gi †`vjbKvjÑ [Xv.‡ev 2021] A. k~b¨ n‡e B. 1 2 ¸Y n‡e C. AcwieZ©xZ _vK‡e D. Amxg n‡e Ans D 02. †m‡KÛ †`vj‡Ki •`N©¨ AwfKl©R Z¡iY 'g' Gi [Xv. †ev. 2015] A. eM©g~‡ji mgvbycvwZK B. mgvbycvwZK C. eM©g~‡ji e¨v¯ÍvbycvwZK D. e¨v¯ÍvbycvwZK Ans B wb‡Pi Aby‡”Q`wU c‡o 03bs cÖkœwUi DËi `vI: [iv. †ev. 2017] 0.01kg f‡ii GKwU e¯‘KYv mij‡iLv eivei mij †`vjbMwZ AR©b K‡i| Gi †`vjbKvj 2 sec, we¯Ívi 0.1m Ges miY 0.02m| 03. ej aªye‡Ki gvb KZ? A. 0.0314Nm1 B. 0.09854Nm1 C. 0.02465Nm1 D. 0.3944Nm1 S B info = k m k = m 2 = m 2 T 2 K = 4 2m T 2 k = 4 2 × 0.01 2 2 = 0.0985 Nm–1 04. c„w_exi e¨vm eivei myo‡½i g‡a¨ e¯‧i MwZ- [iv.‡ev. 2016] A. ch©ve„Ë B. ¯ú›`b C. mij‣iwLK D. me¸‡jv mwVK Ans D 05. mij †`vjb MwZm¤úbœ †Kv‡bv KYvi m‡e©v”P †eM KZ n‡e? [iv.†ev.2016,2015] A. max = A B. max = A C. max = A D. max = 2A Ans C 06. †`vjK Nwo‡K cvnv‡oi P‚ovq wb‡q †M‡j NwowU- [P.‡ev 2021] i. mgq jvf Ki‡e ii. mgq nviv‡e iii. ax‡i Pj‡e wb‡Pi †KvbwU mwVK? A. i B. ii C. i I iii D. ii I iii Ans C 07. GKwU mij †`vjK f~-c„‡ô 0.75 sec-G GKevi wUK †`q| †`vjKwUi Kvh©Ki •`N©¨ KZ? [w`. †ev. 2016] A. 0.186 m B. 0.326 m C. 0.559 m D. 0.686m S C info T = 2 × L g L = gT2 4 2 = 9.8 × (2 × 0.75) 2 4 2 = 0.559 08. †Kv‡bv †`vjK Nwoi ch©vqKvj MÖx®§Kv‡j 2.002 sec nq| NwowU N›Uvq KZ †m‡KÛ †¯øv n‡e? [h. †ev. 2017] A. 2.5s B. 3.6s C. 4.5s D. 6.6s S B info cÖwZ 2s G †¯øv P‡j (2.002 – 2) s = 0.002s NÈvq †¯øv P‡j = 0.002 2 × 3600s = 3.6s 09. gnvKv‡k GKRb b‡fvPvixi wbKU GKwU †m‡KÛ †`vj‡Ki K¤úvsK KZ n‡e? [h. †ev. 2015] A. 0 Hz B. 1 Hz C. 2 Hz D. Amxg S A info gnvKv‡k †m‡KÛ †`vj‡Ki †`vjbKvj Amxg| wb‡Pi DÏxc‡Ki Av‡jv‡K 10bs cÖ‡kœi DËi `vI : [wm.‡ev 2021] C V A B V GLv‡b, T= 2sec g= 9.8ms–2 D V 10. †`vj‡Ki Kvh©Kix •`N©¨ KZ? A. 0.49m B. 0.99m C. 1.03m D. 1.56m S B info L = g 2 4 2 = 9.8 2 2 4 (3.14) 2 = 0.99m 11. wb‡Pi †Kvb Kvi‡Y †`vjK Nwo †¯øv Pj‡e? A. g †K w¯’i †i‡L L evov‡j T evo‡e e‡j B. g †K w¯’i †i‡L L Kgv‡j T Kg‡e e‡j? C. L †K w¯’i †i‡L g evov‡j T evo‡e e‡j? D. L †K w¯’i †i‡L L evov‡j T Kg‡e e‡j? 12. †Kv‡bv ¯ v‡b `ywU mij‡`vj‡Ki †`vjbKv‡ji AbycvZ 1 t 2 n‡j, G‡`i Kvh©Ki •`‡N©¨i AbycvZ KZ? [wm. †ev. 2015] A. 1 t 2 B. 1 t 2 C. 1 t 4 D. 2 t 1 Ans C 13. GKwU mij‡`vjK‡K 4g AwfKl©R Z¡i‡Yi GKwU MÖ‡n wb‡q †M‡j Gi †`vjbKvj KZ n‡e? [g.‡ev 2021] A. T 4 B. T 2 C. 2T D. 4T S B info T 1 g T1 T2 = g2 g1 T2 = g2 g1 × T1 = g 4g × T. T2 = T 2 14. 0.3 m •`N©¨wewkó GKwU mij †`vj‡Ki †`vjbKvj 0.8 sec cvIqv †Mj| †`vjbKvj 2.4 sec Ki‡Z n‡j †`vjbKwUi •`N©¨ KZ n‡e? [e. †ev. 2019] A. 1.8 m B. 2.4 m C. 2.7 m D. 3.6 m S C info L2 = T 2 2 T 2 1 × L1 2 = 2.4 0.8 × 0.3 = 2.7 m wb‡Pi DÏxc‡Ki Av‡jv‡K 15 Ges 16 cÖkœ `yBwUi DËi `vI : [e. †ev. 2017] GKwU mij †`vj‡Ki myZvi •`N©¨ 79.2cm Ges e‡ei e¨vmva© 0.8cm| (AwfKl©R Z¡iY 9.8ms-2 ) 15. D³ †`vjKwUi †`vjbKvj KZ? A. 0.5077 s B. 0.5129 s C. 0.8976 s D. 1.7952 s S D info T = 2 L g = 2 0.792 + 0.008 9.8 = 1.7952 s 16. D³ †`vjK‡K †m‡KÛ †`vj‡K cwiYZ Ki‡j i. †`vjKwU `ªyZ Pj‡e ii. †`vjbKvj 2sec n‡e iii. myZvi •`N©¨ 19.29 cm e„w× Ki‡Z n‡e wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii S C info T L L1 L = T1 T 2 = 2 1.7952 2 L1 L = 1.24 L1 – L L = 1.24 – 1 L = (1.24 – 1)L = 0.24 × 80 cm = 19.2 cm 17. GKwU †m‡KÐ †`vj‡Ki GK cÖvšÍ †_‡K Ab¨ cÖv‡šÍ †h‡Z mgq jv‡MÑ [e. †ev. 2015] A. 0.5 †m. B. 1 †m. C. 2 †m. D. 4 †m. Ans B

318 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 4 MÖn msµvšÍ MvwYwZK cÖ‡qvM FORMULA 01. m e e m M M R m R T e T 02. h e w w = h e g g 03. Tm = f‡ii ¸Y e¨vmv‡a©i ¸Y Te [GLv‡b, m = moon (Puv`); e = earth (c„w_ex)] Model Example01 GKwU †m‡KÛ †`vj‡Ki P›`ª c„‡ô †`vjbKvj KZ? †Ìqv Av‡Q, c„w_exi fi Puv‡ì f‡ii 81 ¸Y I e¨vmva© Puv‡ì e¨vmv‡`©i 4 ¸Y| General Rules [Written] 3 in 1 Shortcut Tricks & Tips [MCQ] Avgiv Rvwb, T = 2 L g Tm = 2 L g .............(i) Te = 2 L ge .........(ii) (i) I (ii) n‡Z Tm Te = ge gm ....................(iii) Avevi, g = GM R 2 Ge = GM Re 2 .................. (iv) gm = GMm R 2 m .......................... (v) (iv) I (v) n‡Z ge gm = GMe Re 2 Rm 2 GMm = Me Mm Rm 2 Re 2 ge gm = Me Mm Rm Re 2 ............. (vi) (iii) bs I (vi) bs n‡Z, Tm Te = Me Mm Rm Re 2 Tm Te = Me Mm Rm Re Tm Te = 81 1 4 Tm Te = 9 4 Tm = 9 4 2 Tm = 4.5sec. Tm = f‡ii ¸Y e¨vmv‡a©i ¸Y Te = 81 4 2 = 4.5 sec. GLv‡b, m = moon (Puv`); e = earth (c„w_ex) NOW START PRACTICE 01. GKwU KvíwbK MÖ‡ni fi Puv‡ì f‡ii 64 ¸Y I e¨vmva© Puv‡ì e¨vmv‡a©i 5 ¸Y n‡j, GKwU †m‡KÛ †`vj‡Ki KvíwbK MÖ‡ni c„‡ô †`vjbKvj KZ? NOW PRACTICE SOLVE : 01. T = f‡ii ¸Y e¨vmv‡a©i ¸Y T 64 5 2 = 8 5 2 = 16 5 Concept 5 ÎæwUc~Y© †`vj‡Ki †`vjbKvj FORMULA 01. w`‡b, T = 2 × 86400 86400 n Or, n = 86400 (T2 T1) T2 02. NÈvq, T = 2 × 3600 3600 n Or, n = 3600 (T2 T1) T2 03. wgwb‡U, T = 2 × 60 60 n Or, n = 60 (T2 T1) T2 04. cvnvwo D”PZv, h = T2 T1 – 1 × R [R = c„w_exi e¨vmva©] Note: i. †`vjK hw` ax‡i P‡j, n = (–) ii. †`vjK hw` `ªæZ P‡j, n = (+) CONCEPTUAL MATH MEx 01 GKwU †m‡KÛ †`vj‡Ki Kvh©Kix ‣`N¨© 1% e„w× Kiv n‡j, †`vjKwU •`wbK KZ †m‡KÛ ax‡i Pj‡e? t = 86400 101 100 –1 = 430 s NOW START PRACTICE 01. †m‡KÐ †`vj‡Ki •`N©¨ 1% Kgv‡j, D³ †`vj‡Ki w`‡b KZ mgq cwiewZ©Z n‡e? 02. GKwU †m‡KÐ †`vj‡Ki •`N©¨ Zv‡ci d‡j Ggbfv‡e e„w× †cj †h †`vjbKvj cwiewZ©Z n‡q 2.01 sec nj| cwiewZ©Z Ae¯ vq †`vjKwU NÈvq KZ †m‡KÐ †¯øv Pj‡e?

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 319 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES NOW PRACTICE SOLVE : 01. T L; T 2 = 99 100 T = 99 100 2 2 86400 86400 + n = 99 100 2 = n 433 02. †¯øv n‡j, T2 T1 = 3600 3600 – n 2.01 2 = 3600 3600 – n n = 18 sec REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF RU QUESTION 01. GKwU †m‡KÛ †`vj‡Ki •`N©¨ Zv‡ci d‡j Ggbfv‡e e„w× †cj †h †`vjbKvj cwiewZ©Z n‡q 2.05 †m‡KÛ n‡jv| cwiewZ©Z Ae¯ vq †`vjKwU NÈvq KZ wgwbU †ìx‡Z hv‡e? [RU. 12-13] A. 1 B. 1.5 C. 2 D. 2.5 S B info T2 T1 = 3600 3600 – n 2.05 2 = 3600 3600 – n n = 1.46 min 1.5 min SAQ Short Answer Questions WRITTEN PART BAQ Broad Answer Questions 01. mij †`vjb MwZ m¤úbœ 0.5 MÖvg f‡ii GKwU KYvi †`vjbKvj 2s Ges we¯Ívi 5cm| KYvwUi- (1) m‡ev©”P †eM (2) m‡ev©”P Z¡iY (3) mvgë¯ vb †_‡K 4cm `~i‡Z¡ †eM, Z¡iY I KYvwUi Dci wµqvkxj ej wbY©q Ki| Solve Avgiv Rvwb, (1) m‡ev©”P †eM, Vmax = A = 5 cm s–1 (2) m‡ev©”P Z¡iY, amax = 2A = 5 2 cm s–2 (3) mvgë¯’vb †_‡K miY, x = 4cm ‡eM, v = (A 2 –x 2 ) = 9.4cms–1 Z¡iY, a = – 2 x = – 39.4cms–2 wµqvkxj ej, F = ma = 19.72 10–5N (Ans.) GLv‡b, T = 2s A = 5cm m = 5 10–3 kg = 2 T = rads–1 02. 40cm `xN© GKwU mij †`vjK 1 wgwb‡U 40 evi †`vj †`q| hw` Gi •`N¨© 160cm Kiv nq Z‡e 60 evi `yj‡Z KZ mgq wb‡e? Solve GLv‡b, L1 = 40 cm T1 = 60/40 sec = 1.5 sec L2 = 160 cm T2 = ? Avgiv Rvwb, T1 = 2 L1 g g = 4 2L1 T1 2 = 7.018ms–2 Avevi, T2 = 2 L2 g = 3sec 1 evi `yj‡Z mgq jv‡M 3sec, 60 evi `yj‡Z mgq jv‡M (3 60) sec = 3 min 03. GKwU mij †`vjb MwZi mgxKiY, x = 10sin 3 t – 12 wgUvi| (1) we¯Ívi (2) ch©vqKvj (3) m‡ev©”P ‡eM (4) m‡ev©”P Z¡iY (5) cÖviw¤¢K `kv (6) hvÎv ïiæi 1 †m‡KÛ c‡ii miY I †eM wbY©q Ki| Solve Avgiv Rvwb, mij Qw›`Z MwZ m¤úbœ KYvi mgxKiY, x = A sin(t – ) GLv‡b, x = 10 sin 3 t – 12 mgxKiY `ywU Zzjbv K‡i cvBÑ (1) we¯Ívi, A = 10m (2) = 3 ev, 2 T = 3 T = 6s (3) m‡ev©”P †eM, Vmax = A = 10 3 ms–1 (4) m‡ev©”P Z¡iY, amax = 2A = 10 2 9 ms–2 (5) cÖviw¤¢K `kv, = 10rad = 15° (6) hvÎv ïiæi 1 †m‡KÛ c‡ii miY, x = 10sin 3 – 12 = 7.07m I †eM, v = 10 3 cos 3 – 12 = 7.41ms–1 (Ans.) 04. GKwU mij †`vjb MwZi ch©vqKvj 12 †m‡KÛ Ges we¯Ívi 10 †mw›UwgUvi| MwZc‡_i g‡a¨ Ae¯ vb AwZµg Kivi 14 †m‡KÛ ci miY I Avw` `kv wbY©q Ki| Solve Avgiv Rvwb, x = A sin(t) = 10sin 2 T t = 1.2759cm Avevi, x = A sin (t + ) ev, 1.2759 = 10 sin = 7.33 rad (Ans.) GLv‡b, T = 12s A = 10cm T = 14s x = ? = ? 05. ‡Kvb GKwU †m‡KÛ †`vj‡Ki •`N¨© 25.6% evov‡j Gi †`vjbKvj KZ n‡e? Solve Avgiv Rvwb, T1 = 2 L1 g Ges T2 = 2 L2 g myZivs, Avgiv wjL‡Z cvwi, T2 = T1 1.256L L = 2.24 sec (Ans) GLv‡b, L1 = L ‡`vj‡Ki ‣`N©¨ 25.6% evo‡j, L2 = L1 + L1 Gi 25.6% = 1.256L T1 = 2 sec T2 = ? 06. mij Qw›`Z ¯ú›`‡bi MwZkxj 0.1 kg f‡ii GKwU KYvi we¯Ívi 1 m Ges ch©vqKvj 0.2 s n‡j KYvwUi Dci cÖhy³ m‡e©v”P e‡ji gvb KZ? hw` eøKw¯úªs wm‡÷g Øviv ¯ú›`b nq, Z‡e w¯úªswUi w¯úªs-aªæeK KZ? Solve Z¡i‡Yi m‡e©v”P gvb, amax n‡j amax = 2A [ïay gvb we‡ePbv K‡i] = 2 T 2 A = 4 2 T 2 A = (4 2 ) (1 m) (0.2 s) 2 = 986.96 m/s2 cÖhy³ e‡ji m‡e©v”P gvb, Fmax n‡j, Fmax = mamax = (0.1 kg) (986.96) m/s2 ) = 98.69 N Avevi w¯úª-aªæeK, k n‡j, k = Fmax A = 90.69 N 1 m = 98.6 N/m 98.6 N/m

320 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 07. GKwU mij †`vjK 0.9 sec G GKevi wUK& kã K‡i| †`vjKwUi Kvh©Ki •`N©¨ KZ? Solve Kvh©Ki •`N©¨ L = T 2 g 4 2 L = (1.8) 2 9.8 4 9.87 = 0.804 m GLv‡b, Aa©‡`vjbKvj = wU‡Ki mgq ev, T 2 = 0.9 s ev, T = 1.8 s 08. †Kvb w¯úªs Gi GK cÖv‡šÍ m f‡ii GKwU e¯‧ Szjv‡j GwU 8 cm cÖmvwiZ nq| e¯‧wU Gi ci GKUz †U‡b †Q‡o w`‡j Gi ch©vqKvj KZ n‡e? Solve w¯úªs G e¯‘wU Syjv‡bvi ci, mg = kx ev, m k = x g ev, m k = 0.08 9.8 ev, m k = 0.09035 ev, T = 2 ev, T = 0.567 s 0.567 s 09. GKwU cvnv‡oi D”PZv 5km, Gi P‚ovq AwfKl©R Z¡iY wbY©q Ki| Solve cvnv‡oi cv`v‡`‡k Ges cvnv‡oi kx‡l© AwfKl©R Z¡iY h_vµ‡g g Ges gA n‡j, GLv‡b, c„w_exi e¨vmva©, R = 6.4 106 m f~-c„‡ô AwfKl©R Z¡iY, g = 9.8 ms2 cvnv‡oi D”PZv, h == 5 km = 5 103 m cvnv‡oi P‚ovq AwfKl©R Z¡iY, gA = ? cvnv‡oi cv`‡`‡k Ges cvnv‡oi kx‡l© AwfKl©R Z¡iY h_vµ‡g, g Ges gA n‡j, gA g = R 2 (R + h)2 gA = (6.4 106 m) 2 9.8 m s2 (6.4 106 m + 5 103 m) 2 9.78 ms2 10. GKwU †m‡KÛ †`vj‡Ki •`N¨© 2.25 ¸Y Kiv n‡j Gi †`vjbKvj KZ n‡e? Solve GLv‡b, T1 = 2 sec L1 = L ‡`vj‡Ki •`N¨© 2.25 ¸Y Kiv n‡j, L2 = 2.25L1 = 2.25L T2 = ? Avgiv Rvwb, T1 T2 = L1 L2 T2 = L2 L1 T1 = 3sec (Ans.) 11. GKwU †m‡KÛ †`vj‡Ki •`N¨© •k‡Zï d‡j n«vm †cj| Gi d‡j †`vjbKvj Ggb n‡jv †h, †`vjK wU w`‡b 10 †m‡KÛ `ªæZ hvq| cwiewZ©Z †`vjbKvj KZ? Solve GLv‡b, n = 10sec Avgiv Rvwb, w`‡b n †m‡KÛ `ªæZ Pj‡j †`vjbKvj, T1 = 86400 8640 + n 2sec = 86400 86400 + 10 2sec = 1.999768545 sec 12. mij Qw›`Z ¯ú›`biZ GKwU KYvi ch©vqKvj 4s Ges we¯Ívi 4 m| mg¨ve¯ vb AwZµg Kivi KZ mgq c‡i KYvwUi kw³i A‡a©K w¯ wZkw³ Ges evwK A‡a©K MwZkw³ n‡e? [BUTex. 2020-21] Solve cÖkœg‡Z, Ep =Ek 1 2 kx2 = 1 2 m 2 (A2 – x 2 ) x = A 2 = 4 2 m Avevi, x = A Sin t A 2 = A Sin 2 T .t = A Sin 2 4 .t Sin t 2 = 1 2 = Sin 4 t 2 = 4 t = 0.5c [mvgë¯’v †_‡K Wvbw`‡K 0.5s ci GB Ae¯’v •Zix n‡e GKBfv‡e evgw`‡K 0.5s ci MwZ I w¯’wZkw³ mgvb n‡e|] 13. 0.1 kg f‡ii GKwU KYv 0.1m we¯Ív‡ii mv‡_ mij †`vjb MwZ m¤úbœ Ki‡Q| hLb KYvwU mvg¨ve¯ vq _v‡K, ZLb Zvi MwZkw³ 8 10–3 J| KYvwUi K¤ú‡bi Avw` `kv 45o n‡j Gi MwZi mgxKiY †ei Ki| [BUET; 19-20] Solve Avgiv Rvwb, Ek = 1 2 m 2A 2 1 2 m 2A 2 = 8 10–3 = 4 rad/sec ; y = A sin (t + ) y = 0.1 sin 4t + 4 14. 1.00 10–20kg f‡ii GKwU KYvi mij Qw›`Z MwZi †`vjbKvj 1.00 10–5 s Ges Zvi m‡e©v”P MwZ‡eM 1.00 103m/s| KYvwUi A. †K․wYK K¤úv¼ Ges B. m‡e©v”P miY wbY©q Ki| [BUET. 18-19] Solve = 2 T = 2 110–5 = 200000rads–1 Vmax = A 1.00 103 = 200000A A = 1.5915 10–3 15. hLb mij Qw›`Z ¯ú›`b MwZ m¤úbœ GKwU KYvi Ae¯’vb (`~iZ¡) Gi we¯Ív‡ii A‡a©K, ZLb KYvwUi †gvU kw³i KZ Ask MwZkw³ I w¯’wZkw³ n‡e? [BUTEX; 19-20] Solve †gvU kw³ ET = 1 2 kA2 [K = ej aªæeK, A = we¯Ívi] x = A 2 w¯’wZkw³ EP = 1 2 kx2 = 1 2 k A 2 4 = 1 4 ET MwZkw³, EK = ET – EP = 3 4 ET †gvU kw³i GK PZz_©vsk w¯’wZkw³ I wZb PZz_©vsk MwZkw³‡Z iƒcvšÍi n‡e| 16. AwfKl©R Z¡iY g = 9.8 wgUvi/†m2 Gi Rb¨ GKwU †m‡KÛ †`vj‡Ki •`N©¨ wbY©q Ki| AwfKl©R Z¡iY 10% Kwg‡q D³ †`vj‡Ki †`vjbKvj wVK ivL‡Z n‡j •`‡N©ï wK cwieZ©b n‡e? [KUET; 19-20] Solve †m‡KÛ †`vj‡Ki •`N©¨, L = gT2 4 2 = 9.8 2 2 4 2 = 0.9929m = 99.29cm Avevi, T = 2 L g T w¯’i (GKB) _vK‡j L g g Gi gvb 10% Kg‡j L Gi gvb 10% Kg‡e •`‡N©ï cwieZ©b = L Gi 10% = 99.29cm 10 100 = 9.929 cm. 17. GKwU wjd‡Ui Qv` †_‡K mij †`vjK Szjv‡bv Av‡Q| wjdU Pjvi mgq GB †`vj‡Ki †`vjbKvj wjd‡Ui w¯ i Ae¯ vi Zzjbvq hw` A‡a©K nq, Z‡e wjd‡Ui Z¡i‡Yi w`K I gvb wbY©q Ki| [KUET. 05-06] Solve T2 T1 = g1 g2 = 1 2 g1 g2 = 1 4 ..................(i) g2 g1 wjdUwUi Z¡i‡Yi w`K DaŸ©gyLx Ges Z¡iY a n‡j, g2 = g + a g g + a = 1 4 4g = g + a a = 3g = 3 9.8 = 29.4ms2 18. GKwU cvnv‡oi cv`‡`‡k GKwU †m‡KÛ †`vjK mwVK mgq †`q| GwU‡K cvnv‡oi m‡e©v”P k„‡½ wb‡q †M‡j cÖwZw`b 2 wgwbU ax‡i P‡j| cvnv‡oi D”PZv wbY©q Ki| [c„w_exi e¨vmva© = 6400km] [KUET. 04-05] Solve 2min= 120 sec n = 120sec GLb, R R + H = 86400 86400 – n 1 R + H R = 86400 86400 n 1 + H R = 86400 86400 n H = 86400 86400 n 1 R = 8.9 km 19. hLb mij Qw›`Z ¯ú›`b MwZ m¤úbœ GKwU KYvi Ae¯’vb (`~iZ¡) Gi we¯Ív‡ii A‡a©K, ZLb KYvwUi †gvU kw³i KZ Ask MwZkw³ I w¯’wZkw³ n‡e Solve †gvU kw³ ET = 1 2 kA2 [k = ej aªæeK, A = we¯Ívi] w¯’wZkw³ EP = 1 2 kx2 = 1 2 k A 2 4 = 1 4 ET MwZkw³, Ek = ET – EP = 3 4 ET †gvU kw³i GK PZz_©vsk w¯’wZkw³ I wZb PZz_©vsk MwZkw³‡Z iƒcvšÍi n‡e|

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 321 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 20. GKwU †m‡KÛ †`vj‡Ki •`N¨© ivRkvnx‡Z 95cm Ges PÆMÖv‡g 100cm| †Kvb e¯‧i IRb ivRkvnx‡Z 95gm – wt n‡j, PÆMÖv‡g Dnvi IRb KZ? Solve WR WC = mgR mgC = gR gC GLb, 2 lR gR = 2 lC gC ev, lR gR = lC gC ev, gR gC = lR lC WR WC = lR lC = 95 100 ev, WC = WR 100 95 = 95 100 95 = 100 gm –wt 21. GKwU e¯‧ mij †`vj MwZ‡Z x = 6.0 cos(6t + ) m mgxKiY Abyhvqx `yj‡Q| e¯‧i MwZi K¤úv¼ KZ? t = 2s mg‡q e¯‧wUi †eM I Z¡i‡Yi gvb KZ? [DU.A 19-20] Solve x = 6 cos (6t + ) ...... (1) ; x = A cos( t + ) ; x = A cos(2ft + ) mgxKiY‡K (1) bs mgxKi‡Yi mv‡_ Zzjbv Ki‡j, 2f = 6 ; f = 6 2 = 3Hz K¤úv¼ = 3Hz ; x = 6 cos (6t + ) ; v = dx dt = d dt 6 cos (6t + ) = 6 sin (6t + ) 6 = 36 sin (6t + ) ................. (2) a = dv dt = d dt {36 sin(6t + )} = 36 cos (6t + ) 6 = 216 2 cos (6t + ) ............(3) t = 2s c‡i †eM, v = 36 sin (12 + ) ; v = 0 ms1 ; t = 2s c‡i Z¡iY ; a = 216 2 cos(13) = 216 2 ms2 STEP 3 mKj cvVëB‡qi NCTB QUESTIONS ANALYSIS cÖkœ e¨vLvmn mgvavb cÖkœ 01. mij Qw›`Z MwZ Z¡iY ev cÖZ¨vqbx ej mi‡Yi- [Bm&nvK, Avwgi] A. mgvbycvwZK I mggyLx B. e¨¯ÍvbycvwZK I wecixZgyLx C. e¨¯ÍvbycvwZK I mggyLx D. mgvbycvwZK I wecixZgyLx S D info F – x Or, a – x Z¡iY I cÖZ¨qbx ej mi‡Yi mgvbycvwZK I wecixZgywL| 02. `ywU ¯ú›`biZ KYvi miY h_vµ‡g x = Asint Ges x = Acost n‡j G‡ì ga¨Kvi `kv cv_©K¨- [Bm&nvK, Avwgi] A. 2 B. 2 C. D. 2 S B info `kv cv_©K¨ = t + 2 – t = 2 03. ‡KvbwU mij Qw›`Z ¯ú›`‡bi •ewkó¨ bq? [Bm&nvK, Avwgi] i. Gi MwZ GKwU mij‡iLvq N‡U ii. ej e¯‘i mi‡Yi mgvbycvwZK iii. Z¡iY e¯‘i mi‡Yi AwfgyLx wb‡Pi †KvbwU mwVK? A. i B. i I ii C. i, ii I iii D. i, ii I iii Ans B 04. mij Qw›`Z ¯ú›`b m¤úbœ KYv KZ mgq ci GKB `kv cÖvß n‡e? [Bm&nvK, Avwgi] A. 2 B. 2 C. 2 D. 1 g K m Ans C 05. †`vjbiZ GKwU w¯úªs Gi •`N©¨ e„w× ebvg fi †jLwPÎ †KvbwU? [Bm&nvK, Avwgi] A. ℓ(m) m(kg) B. ℓ(m) m(kg) C. ℓ(m) m(kg) D. ℓ(m) m(kg) S B info w¯úªs Gi †ÿ‡Î fi (m) e„w×i mv‡_ •`N©¨ (ℓ) mgvbycvwZK nv‡i e„w× cvq| 06. †jLwPÎwU mij †`vj‡Ki †Kvb m~‡Îi cÖKvk? [Bm&nvK, Avwgi] Y T 2 X g A. 1g B. 2q C. 3q D. 4_© S C info mij †`vj‡Ki m~Îmg~n: 1g m~Î: mgKvj m~Î 2q m~Î: •`‡N©ï m~Î T L 3q m~Î: Z¡i‡Yi m~Î T 1 g 4_© m~Î: f‡ii m~Î T = 2 L g g 1 T 2 wb‡Pi wPÎ I Z_¨ n‡Z 07 I 08 bs cÖ‡kœi DËi `vI : wP‡Î mij †`vjKwU A Ae¯’vb †_‡K `yj‡Z ïiæ K‡i cÖ_‡g B Gici C Ae¯’v‡b †c․Qvq| 07. ‡`vjKwUi A Ae¯ v‡bi Rb¨ cÖ‡hvR¨- [Bm&nvK, Avwgi] i. MwZkw³ m‡e©v”P ii. ‡eM m‡e©v”P iii. wefe kw³ me©wb¤œ wb‡Pi †KvbwU mwVK? A. i B. i I ii C. ii I iii D. i, ii I iii A we›`y‡Z x = 0, Vmax = A Ges 2 2 k m A 2 1 E A_v©r MwZkw³ m‡e©v”P| ga¨we›`y‡Z KYv w¯’i _v‡K e‡j Zvi Dci ej wµqv K‡i bv, ZLb Zvi w¯’wZ kw³ k~b¨| 08. ‡`vjKwUi C Ae¯ v‡bi Rb¨ wb‡Pi †KvbwU mwVK? [Bm&nvK, Avwgi] A. wefe kw³ k~b¨ B. Kvh©Kix ej k~b¨ C. †eM k~b¨ D. Z¡iY m‡e©v”P S CD info C Ae¯’v‡b x = A Z¡iY, a = – 2 x A_©vr Z¡iY m‡e©v”P | MwZkw³ me©wbgœ| 09. †K․wYK we¯Ívi 4°-Gi g‡a¨ n‡j mij †`vj‡Ki †`vjbKvj †`vj‡Ki Kvh©Kix •`‡N©ï- [Bm&nvK, Avwgi] A. e¨¯ÍvbycvwZK B. mgvbycvwZK C. e‡M©i e¨¯ÍvbycvwZK D. eM©g~‡ji mgvbycvwZK S D info T = 2 L g T L 10. mij Qw›`Z e¯‧KYvi mi‡Yi mgxKiY x = A cos t; G‡ÿ‡Î KYvwUi- [Bm&nvK, Avwgi] i. t = 0 mg‡q miY x = A ii. t = T 2 mg‡q miY x = – A iii. t = T 4 mg‡q miY x = 0 wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans D 11. GKwU †MvjK Nwo mij †`vjMwZ m¤úbœ Ki‡Q hvi K¤úv¼ | Gi MwZkw³i cwieZ©‡bi K¤úv¼- [Bm&nvK, Avwgi] A. 2 B. 3 C. 2 D. 4 Ans C 12. GKwU mij †`vj‡Ki †MvjvK…wZ duvcv wcÛ cvwb Øviv c~Y©| †`vjbiZ Ae¯ vq GKwU wQ`ª w`‡q †duvUvq †duvUvq cvwb †e‡iv‡Z _vK‡j †`vjKwUi †`vjbKvj- [Bm&nvK, Avwgi] A. µgvMZ n«vm cvq B. GKB _v‡K C. cÖ_‡g ev‡o I c‡i n«vm cvq D. µgvMZ e„w× cvq Ans C

322 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 13 GKwU mij †`vj‡Ki Kvh©Ki •`N©¨ I ch©vqKv‡ji e‡M©i †jLwPÎ Kxiƒc n‡e? [Bm&nvK, Avwgi] A. mij‣iwLK B. m~PKxq C. Awae„Ëxq D. Zi½agx© Ans C 14. GKwU mij †`vjMwZm¤úbœ e¯‧KYvi fi m Ges K¤úv¼ n‡j ej aªæeKwU n‡e- [Bm&nvK, Avwgi] A. m B. m C. m 2 D. m Ans C 15. GKwU mij †`vjm¤úbœ KYvi mgxKiY x = A sin t n‡j, KYvi cÖv_wgK Ae¯ vb †Kv_vq? [Bm&nvK, Avwgi] A. ga¨ we›`yi Wvbw`‡Ki †h †Kv‡bv we›`y‡Z B. ga¨ we›`yi evgw`‡Ki †h †Kv‡bv we›`y‡Z C. ga¨we›`y‡Z D. cÖvšÍ we›`y‡Z Ans C 16. mij †`vjb MwZm¤úbœ †Kv‡bv KYvi AšÍiK mgxKiY n‡”Q 5 d 2 x dt2 + 180x = 0| KYvwUi ch©vqKvj KZ n‡e? [Zcb, AvwRR] A. 0.95 s B. 1.05 s C. 37.68 s D. 0.52 s S B info 5 d 2 x dt2 + 180x = 0 d 2 x dt2 + 36x = 0 2 = 36 = 6 2 T = 6 T = 2 6 = 1.05 s 17. †m‡KÛ †`vjK n‡”Q †h mij †`vj‡Ki †`vjbKvj- [Zcb, AvwRR] A. GK †m‡KÛ B. `yB †m‡KÛ C. wZb †m‡KÛ D. Pvi †m‡KÛ S B info ‡m‡KÛ †`vj‡Ki †¶‡Î, T = 2 sec 18. mij Qw›`Z ¯ú›`‡b ¯úw›`Z GKwU KYvi ch©vqKvj 20 s n‡j Gi †K․wYK K¤úv¼ KZ? [Zcb, AvwRR] A. = 20 rad s–1 B. = 10 rad s–1 C. = 2 rad s–1 D. = 15 rad s–1 S B info = 2 T = 2 20 = 10 rads–1 19. GKwU mij †`vj‡Ki ch©vqKvj 2 s Gi K¤úv¼ KZ? [Zcb, AvwRR] A. 2 Hz B. 1 Hz C. 0.5 Hz D. 4 Hz S C info = 1 T = 1 2 = 0.5 Hz 20. GKwU †m‡KÛ †`vj‡Ki †`vjbKvj e„w× †c‡q‡Q| †`vjbKvj 2 s Ki‡Z n‡j Gi •`N©¨- [Zcb, AvwRR] A. evov‡Z n‡e B. Kgv‡Z n‡e C. wKQzB Ki‡Z n‡e bv D. me¸‡jvB mwVK S B info T L ; T Kgv‡Z n‡j L Kgv‡Z n‡e| 21. GKwU mij †`vj‡Ki †`vjbKvj T; †`vjKwUi •`N©¨ wØ¸Y n‡j cwiewZ©Z †`vjbKvj KZ n‡e? [Zcb, AvwRR] A. 2T B. 2T C. 1 2 T D. 1 2 T S A info T2 = x × T1 T2 = 2T 22. †Kv‡bv mij †`vj‡Ki †`vjbKvj A‡a©K Kivi Rb¨- [Zcb, AvwRR] A. •`N©¨ GK-PZz_©vsk Ki‡Z n‡e B. ‣`N©¨ wØ¸Y Ki‡Z n‡e C. e‡ii fi wØ¸Y Ki‡Z n‡e D. e‡ei fi A‡a©K Ki‡Z n‡e S A info T1 T2 = L1 L2 L2 = L1 × T2 2 T 2 1 = L × T 2 2 T 2 L2 = 1 4 L 23. mij †`vjb MwZm¤úbœ †Kv‡bv KYvi we¯Ívi A| Gi miY KZ n‡j kw³i A‡a©K MwZkw³ Ges A‡a©K wefekw³ n‡e? [Zcb, AvwRR] A. A 3 B. A 2 C. A 2 D. A 2 2 S C info 1 2 Ek = 1 2 Ep 1 2 . 1 2 k (x2 – A 2 ) = 1 2 . 1 2 kx2 x 2 – A 2 = x 2 2x2 = A2 x = A 2 24. GKRb evwjKv GKwU †`vjbvq e‡m †`vj Lv‡”Q| evwjKvwU I‡V ùvov‡j †`vjbKv‡ji Kx cwieZ©b n‡e? [Zcb, AvwRR] A. n«vm cv‡e B. e„w× cv‡e C. AcwiewZ©Z _vK‡e D. evwjKvwUi D”PZvi Dci wbf©i K‡i e„w× ev n«vm †c‡Z cv‡i Ans A 25. †Kv‡bv e¯‘i MwZ hw` Ggb nq †h wbw`©ó mgq cici †Kv‡bv wbw`©ó we›`y‡K GKB w`K †_‡K AwZµg K‡i hvq Zvn‡j Zv‡K †Kgb ch©ve„wË e‡j? [Zcb, AvwRR] A. KvwjK ch©ve„wË B. ¯’vwbK ch©ve„wË C. DfqB D. †Kv‡bvwUB bq Ans B 26. mij †`vjbMwZi D`vniY- [Zcb, AvwRR] i. †m‡KÛ †`vjK ii. Djø¤^ w¯úªs iii. nvZ cvLv wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans A 27. mij †`vjb MwZ Ges e„ËvKvi MwZi m¤ú‡K©i †ÿ‡Î| wb‡¤œv³ aviYv n‡jv- [Zcb, AvwRR] i. mij †`vjb MwZi we¯Ívi e„‡Ëi e¨vmv‡a©i mgvb nq ii. mylg e„ËvKvi MwZ Ges mij †`vjb MwZi ch©vqKvj GKB nq iii. mij †`vjb MwZi †K․wYK K¤úv¼ Ges mylg e„ËvKvi MwZi †K․wYK `ªæwZ GKB nq bv wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans A 28. GKwU e¯‧ x = 2 cos (50t) Abymv‡i mij Qw›`Z MwZ‡Z `yj‡Q, †hLv‡b xGi cwigvc wgUv‡i Ges t-Gi cwigvc †m‡K‡Û| Gi m‡e©v”P †eM ms–1 GK‡K n‡e- [Zcb, AvwRR] A. 100 sin (50t) B. 100 cos (50t) C. 100 D. 200 S C info Vmax = A = 50 × 2 = 100 29. wb‡¤œv³ †Kvb ivwki GK‡Ki muv‡_ ej aªæe‡Ki GK‡Ki mv`„k¨ Av‡Q? [Zdv¾j, gwnDwÏb] A. Pvc B. ej C. KvR D. Zj Uvb Ans D †Kv‡bv ¯ v‡b g Gi gvb 9.8ms-2 | D³ ¯ v‡b GKwU mij †`vj‡Ki •`N©¨ 0.7m| DcwiD³ Z‡_ï wfwË‡Z 30 I 31 bs cÖ‡kœi DËi `vI: 30. ‡`vj‡Ki •`N©¨ 4 ¸Y evov‡j T Kxfv‡e cwiewZ©Z n‡e? [Zdv¾j, gwnDwÏb] A. 4 ¸Y ev‡o B. 4 ¸Y ev‡o C. 2 ¸Y ev‡o D. 2 ¸Y ev‡o T2 = nT1 = 4T1 = 2T1 31. e‡ei fi 4 ¸Y evov‡j Gi †`vjbKvj- [Zdv¾j, gwnDwÏb] A. 4 ¸Y ev‡o B. 4 ¸Y ev‡o C. 2 ¸Y ev‡o D. AcwiewZ©Z _v‡K T=2 L g ; †`vjbKvj f‡ii Dci wbf©i K‡i bv| 32. mij Qw›`Z MwZ m¤úbœ KYvi †eM me©wb¤œ- [Zdv¾j, gwnDwÏb] i. cÖv‡šÍ ii. ga¨ Ae¯’v‡b iii. mvg¨ve¯’v‡b wb‡Pi †KvbwU mwVK? A. i B. ii C. iii D. ii I iii Ans A 33. mij Qw›`Z ¯ú›`‡b ¯úw›`Z GKwU e¯‧i mi‡Yi (x) mv‡_ Z¡i‡Yi (a) cwieZ©b †Kvb †jLwPÎ wb‡`©k K‡i? [Mwb, mykvšÍ] A. B. C. D. Ans B 34. mij ‡`vj‡Ki †`vjbKvj wbf©i K‡i- [Zdv¾j, gwnDwÏb] i. e‡ei Dci ii. AwfKl©R Z¡i‡Yi Dci iii. Kvh©Ki •`‡N©ï Dci wb‡Pi †KvbwU mwVK? A. i B. i I ii C. i I iii D. ii I iii T = 2 L g ; So, T Gi gvb L I g Gi Dci wbf©ikxj| a x a x a x a x

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 323 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 35. mij Qw›`Z ¯ú›`‡b ¯úw›`Z GKwU e¯‧i w¯ wZ kw³ Ep Ges miY r Gi m¤úK© †Kvb †jL wPÎwU wb‡`©k K‡i? [Mwb, mykvšÍ] A. B. C. D. 2 k kx 2 1 E , x = r n‡j, 2 p kr 2 1 E k 2 1 = aªæeK, A_©vr 2 p E r 36. mij †`vj MwZ‡Z MwZkxj GKwU e¯‧ GK †m‡K‡Û n msL¨K †`vjb m¤úbœ K‡i| Gi †K․wYK K¤úvsK KZ? [Mwb, mykvšÍ] A. n rads–1 B. 1 n rads–1 C. 2n rads–1 D. 2 n rads–1 2 n 1 2 n t 2 N rad s-1 37. GKwU KYv 0.02 m we¯Ívi I 2.5Hz K¤úvs‡Ki mij †`vj MwZ‡Z `yj‡Q| Gi m‡e©v”P `ªæwZ KZ? [Mwb, mykvšÍ] A. 0.008 ms–1 B. 0.05 ms–1 C. 0.12 ms–1 D. 0.314 ms–1 v = A = 2nA = 23.142.50.02 = 0.314rad s-1 38. mij †`vj‡Ki MwZ- [Mwb, mykvšÍ] i. mij Qw›`Z ¯ú›`b MwZ ii. Z¡iY mi‡Yi mgvbycvwZK I mggyLx iii. Kg we¯Ív‡i mij †`vj MwZ wb‡Pi †KvbwU mwVK? A. i B. ii I iii C. iii D. i I iii Ans D GKwU w¯úªs hvi ej aªæe‡Ki gvb k-Gi GKcÖv‡šÍ fi Szwj‡q Djø¤^fv‡e †U‡b †Q‡o w`‡j mijQw›`Z ¯ú›`‡b ¯úw›`Z nq| w¯úªswU‡K †K‡U `yBfvM Kiv n‡jv hvi GKwUi ‣`N©¨ Av‡iKwUi wØ¸Y| DÏxcKwU nv‡Z 39 I 40 bs cÖ‡kœi DËi `vI| 39. mijQw›`Z ¯ú›`‡bi †¶‡Î †KvbwUi cwieZ©b nq bv- [Mwb, mykvšÍ] A. cÖZ¨qbx ej B. MwZkw³ C. w¯’wZkw³ D. †`vjb Kvj Ans D 40. DÏxc‡Ki w¯úªswU KvUvi ci eo AskwUi w¯úªs aªæeK wK n‡e? [Mwb, mykvšÍ] A. k B. 2k C. 2 3 k D. 3 2 k 2 1 2 1 1 2 k 2 3 k 2 3 L L k k k 1 L 41. mij †`vj MwZi •ewkó¨ bq- [†gvK‡Q` m¨vi] A. e¯‘i MwZ mij‣iwLK B. e¯‘i Z¡iY mi‡Yi wecixZgyLx C. GwU †`vjb MwZ bv D.e¯‘i MwZ ch©vq MwZ Ans C 42. mij Qw›`Z Zi½ KZ cÖKvi? [†gvK‡Q` m¨vi] A. `yB B. wZb C. Pvi D.cuvP Ans A 43. ZvcgvÎv evo‡j Kvh©Kix •`N©¨- [†gvK‡Q` m¨vi] i. ev‡o ii. K‡g iii. w¯’i _v‡K A. i B. i I ii C. ii I iii D. i, ii I iii Ans A 44. mij †`vj‡Ki •ewkó¨- [†gvK‡Q` m¨vi] i. myZv IRbnxb I bgbxq n‡e ii. myZv Am¤úªmviYkxj n‡e iii. w¯’i _v‡K wb‡Pi †KvbwU mwVK? A. i. B. i I ii C. ii I iii D. i, ii I iii Ans B 45. wb‡Pi †Kvb †jLwU mij †`vj‡Ki Z…Zxq m~Î mg_©b K‡i? [†gvK‡Q` m¨vi] A. B. C. D. Ans B 46. GKwU mij †`vj‡Ki Kvh©Kix •`N¨© 1% e„w× Ki‡j Gi †`vjbKv‡ji cwieZ©b n‡e- [†gvK‡Q` m¨vi] A. 1% ‡e‡o hv‡e B. 0.5% e„w× cv‡e C. 0.5% K‡g hv‡e D. 2% ‡e‡o hv‡e T2 = 1.01 T1 = 1.005 T1 T = T2 - T1 = (1.005–1)T1 = 0.005T1= 0.5% e„w× cv‡e 47. mij †`vjbMwZ m¤úbœ †Kvb KYvi we¯Ívi A| Gi miY KZ n‡j kw³i A‡a©K MwZkw³ Ges A‡a©K wefe kw³ n‡e? [†gvK‡Q` m¨vi] A. A 3 B. A 2 C. A 2 D. A 3 2 A A 2 1 x E E x 1 1 2 2 48. gnvKv‡k GKRb gnvKvkPvixi wbKU GKwU mij †`vjK- [†gvK‡Q` m¨vi] A. `ªæZ Pj‡e B. w¯’i _vK‡e C. Kvh©Kix •`N©¨ †e‡o hv‡e D. Kvh©Kix •`N©¨ n«vm cv‡e Ans B 49. wb‡Pi ‡KvbwU mij Qw›`Z ¯ú›`‡bi •ewkó¨ bq- [†Mvjvg m¨vi] i. GwU GKwU ch©ve„Ë MwZ ii. GwU mij •iwLK MwZ iii. ‡h ‡Kvb mg‡q Z¡i‡Yi gvb mi‡Yi gv‡bi mgvbycvwZK bq wb‡Pi ‡KvbwU mwVK? A. i I iii B. iii C. i I ii D. i, ii I iii Ans B 50. gnvKv‡k GKRb b‡fvPvixi wbKU GKwU mij ‡`vj‡Ki ‡`vjbKvj n‡e- [†Mvjvg m¨vi] A. k~b¨ B. Amxg C.c„w_exi †`vjbKv‡ji A‡a©K D. 2 sec Ans B 51. mij Qw›`Z MwZ‡Z N~Y©biZ KYvi kw³i ‡¶‡Î- [cÖvgvwYK m¨vi] i. m‡e©v”P w¯’wZkw³ = 1 2 kA2 ii. m‡e©v”P MwZkw³ = 1 2 kA2 iii. ‡gvU hvwš¿K kw³ = 1 2 kA2 wb‡Pi ‡KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ep = 1 2 KA2 , Ek = 1 2 KA2 ‡gvU hvwš¿K kw³ = 1 2 KA2 cos2 (t + ) + 1 2 KA2 sin2 (t + )= 1 2 KA2 52. m~h©‡K cÖ`w¶YiZ c„w_exi ch©vq Kvj- [igv m¨vi] A. 365 w`b A‡c¶v 6 N›Uv ‡ewk B. 365 w`b A‡c¶v 6 N›Uv Kg C. 365 w`b A‡c¶v 4 N›Uv ‡ewk D. 366 w`b A‡c¶v 4 N›Uv Kg m~h©‡K cÖ`w¶YiZ c„w_exi ch©vqKvj 365.25 w`b | ch©vqKvj e„w× = 365.25 –365 =0.25 w`b = (0.2524)= 6 N›Uv 53. GKwU e¯‧ mij Qw›`Z MwZ‡Z i‡q‡Q| e¯‧wUi K¤ú‡bi we¯Ívi Ges ch©vqKvj DfqB wØ¸Y Kiv n‡j Gi m‡e©v”P ‡e‡M- [AvRMi m¨vi] A. GK PZz_©vsk nq B. A‡a©K nq C. AcwiewZ©Z _v‡K D. wØ¸Y nq 2 1 1 2 1 2 T T A A v v 2 v1 v1 2T T A 2A v T 2 O L L 2 O g T O g T 2 O L Ep r o o Ep r O O Ep r o o Ep r o o

324 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 54. †KvbwU ch©ve„Ë MwZi D`vniY bq? [BKivg m¨vi] A. Nwoi KvuUvi MwZ B. wc÷‡bi MwZ C. jvwU‡gi MwZ D. Mvwoi MwZ Ans D 55. m fiwewkó GKwU mij Qw›`Z ‡`vj‡Ki ejaªæeK (k) †K wØ¸Y Kiv n‡j, †`vj‡Ki Avw` †`vjbKvj T cwiewZ©Z n‡e Kxfv‡e? [kvgmyi m¨vi] A. 2T B. 2 T C. T 4 D. T 2 2 T T 2k k T k k T 1 2 1 2 56. GKwU w¯ i wjdU Gi g‡a¨ ivLv mij‡`vj‡Ki †`vjbKvj T| hw` wjdUwU Dc‡ii w`‡K g 3 Z¡iY wb‡q D‡V Z‡e †`vjKwUi †`vjbKvj KZ n‡e? [kvgmyi m¨vi] A. T 2 B. 3 2 T C. 2 T D. 4T 3 4g 3 g g2 g T 2 3 T 4 3 T 4g / 3 g T g g T 1 2 1 2 57. L •`N©¨ Ges k w¯cÖs aªæeK wewkó GKwU w¯cÖs‡K †K‡U mgvb Pvi UzKiv Kiv n‡j cÖwZ UzKiv w¯cÖs Gi w¯…s aªæeK KZ n‡e? [kvgmyi m¨vi] A. k 4 B. k 2 C. 2k D. 4k x F F kx k 4 x x n‡j, k x F x F k 4 4 / 4 1 = 4kx x = 4k 58. GKwU mij‡`vjK‡K c„w_exi e¨vmv‡a©i mgvb D”PZvq wb‡q ‡M‡j †`vjbKvj KZ ¸Y n‡e? [kvgmyi m¨vi] A. 1 4 B. 1 2 C. 2 D. 4 T2 = R2 R1 × T1 = R + R R × T = 2T 59. mijQw›`Z ¯ú›`‡b ¯úw›`Z GKwU KYvi m‡e©v”P Z¡iY 8 ms–2 Ges m‡e©v”P `ªæwZ 1.6 ms–1 | KYvwUi ch©vqKvj KZ? [kvgmyi m¨vi] A. 0.4s B. 0.2s C. 0.1s D. 0.05s amaxa A 8 A ii 2 2 Vmaxv A 1.6 A i 0.4sec 4 1.6 T 1.6 8 T 2 1.6 8 ii : i STEP 4 MCQ CONCEPT TEST WRITTEN cÖkœ 01. †Kv‡bv KYvi ¯ú›`b MwZi mgxKiY x = 10 sin (6 t + 2)| KYvwUi K¤úv¼ KZ? A. 1.5 Hz B. 6 Hz C. 3 Hz D. 10 Hz 02. cwiewZ©Z Ae¯ vq †`vjKwU NÈvq KZ wgwbU †`wi‡Z hv‡e? A. 1 B. 1.5 C. 2 D. 2.5 03. †Kv‡bv e¨w³ GKwU w¯ i wjd‡Ui †fZi GKwU mij †`vj‡Ki ch©vqKvj cvb T, hw` wjdwU g 3 Z¡i‡Y Dc‡i DV‡Z _v‡K Zvn‡j ch©vqKvj n‡eA. 3 T B. 3 2 T C. T 3 D. T 2 04. mij Qw›`Z MwZm¤úbœKvix †Kv‡bv KYvi m‡e©v”P †eM 0.02 ms–1 | KYvwUi we¯Ívi 0.004 m n‡j KYvwUi ch©vqKvj KZ? A. 1.526 sec B. 0.628 sec C. 1.256 sec D. 0.325 sec 05. 200 Nm–1 ej aªæeKwewkó †Kv‡bv w¯úªs‡K †U‡b 0.05 m cÖmvwiZ Kivi Rb¨ cÖ‡qvRbxq ejA. 10 N B. 1 N C. 100 N D. 5 N 06. GKwU mij †`vj Nwoi †`vjbKvj T. ‡`vjKwUi •`N©¨ wØ¸b Kiv n‡j cwiewZ©Z †`vjbKvj n‡eA. 2T B. 2T C. T 2 1 D. T 12 1 07. g½j MÖ‡ni e¨vmva© I fi h_vµ‡g c„w_exi e¨vmva© I f‡ii 0.532 ¸Y I 0.11 ¸Y| c„w_ex c„‡ô GKwU mij †`vj‡Ki †`vjbKvj 2 †m‡KÛ n‡j g½j MÖ‡n †`vjbKvj KZ? A. 3.2 S B. 3.5 S C. 1.25 S D. 0.75 S 08. 0.2 m •`N©¨ wewkó GKwU mij †`vj‡Ki †`vjbKvj 0.9 sec cvIqv †Mj| ‡`vjbKvj 1.8 S Ki‡Z n‡j †`vjKwUi •`N©¨ n‡eA. 40.1 m B.0 0.28 m C. 0.4 m D. 0.8 m 09. GKwU †m‡KÛ †`vj‡Ki P›`ª c„‡ô †`vjbKvj KZ ? †`qv Av‡Q c„w_exi fi Puv‡ì f‡ii 81 ¸Y Ges c„w_exi e¨vmva© Pvu‡ì e¨vmv‡a©i 4 ¸Y| A. 4.5 sec B. 9 sec C. sec 9 8 D. sec 8 9 10. GKwU ‡m‡KÛ †`vj‡Ki ‣`N©¨ hw` 2.25 ¸Y e„w× Kiv nq Z‡e Gi ‡`vjbKvj KZ n‡eA. 3 Sec. B. 2 Sec. C. 4.5 Sec. D. 4 Sec. 11. wbw`©ó •`‡N©ï GKwU mij †`vj‡Ki e‡ii fi 4 ¸Y evov‡j ch©vqKvj †Kgb n‡e? A. 4 ¸Y Kg‡e B AcwiewZ©Z _vK‡e C. 16 ¸Y evo‡e D. 4 ¸Y evo‡e 12. gnvKv‡k GKwU †m‡KÛ †`vjK Gi K¤úvsK KZ n‡e? A. 1Hz B. 0Hz C. 2 Hz D. Infinite 13. GKwU w¯úªs G 1kg fi Szjv‡bv n‡jv| G‡Z w¯úªs wUi •`N©¨ 1m e„w× †c‡j w¯úªs aªæeK n‡e? A. 9.8 N/m B. 1 N/m C. 0.50 N/m D.98 N/m 14. GKwU mij †`vj‡Ki ch©vqKvj 50% evov‡Z Gi Kvh©Ki •`N©¨ wKiƒc cwieZ©b Ki‡Z n‡e? A. 2 ¸Y B 2.50 ¸Y C. 2.75 ¸Y D. 2.25 ¸Y 15. mij †`vjbMwZ m¤úbœ GKwU e¯‧i we¯Ívi a, K¤úvsK n †`vjb Kvj t n‡j wb‡gœi †KvbwU Gi mgxKiY? A. x = asinnt B. x = asin2nt C. x = a sin 2n t D. x = a cos t

ASPECT PHYSICS cÖ_g cÎ ch©ve„wËK MwZ 325 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 16. mij‡`vjb MwZm¤úbœ †Kvb e¯‧KYvi MwZi mgxKiY x = 20sin (31t – /6) n‡j me©vwaK †eM KZ? m/s? A. 520 B. 640 C. 580 D. 620 17. Ae¯ vb mv‡c‡¶ GK Pµ cwigvY Mo MwZkw³ A. Ek = 3 2 †gvU kw³ B. Ek = 1 3 †gvU kw³ C. KE = 3 2 †gvU kw³ D. KE = 1 3 ‡gvU kw³ 18. 4 d 2 x dt2 + 400x = 0 n‡j = KZ? A. 1 rads–1 B. 10 rads–1 C. 100 rads–1 D. 50 rads–1 19. GKwU w¯úªs Gi ej aªæeK‡K Pvi ¸Y Ki‡j †`vjbKvj Kq¸Y n‡e? A. 1 2 T1 B. 2T1 C. 1 2 T2 D. 1 4 T1 20. †Kvb ¯ v‡b g = 981 cm/sec2 n‡j †mB ¯ v‡b †m‡KÛ †`vj‡Ki •`N©¨ KZ ? A. 99.39 cm B. 90.39 cm C. 108 cm D. None OMR SHEET 07. A B C D 14. A B C D 01. A B C D 08. A B C D 15. A B C D 02. A B C D 09. A B C D 16. A B C D 03. A B C D 10. A B C D 17. A B C D 04. A B C D 11. A B C D 18. A B C D 05. A B C D 12. A B C D 19. A B C D 06. A B C D 13. A B C D 20. A B C D WRITTEN PART 21. mij Qw›`Z ¯úw›`Z MwZ m¤úbœ †Kvb ¯ú›`‡Ki MwZi mgxKiY x=10 sin (250 t ) n‡j ¯ú›`KwUi K¤úv¼ KZ nvR©? 22. 15kg f‡ii GK wkï 4m •`‡N©¨i GKwU bvMi †`vjbvq `yj‡Q| †`vj‡bi we¯Ívi 0.5m n‡j †`vjb Kvj KZ? 23. GKwU e¯‧ m‡e©v”P we¯Ívi 5.0 m Ges 8.0 s†`vjbKv‡j mij Qw›`Z MwZ m¤úbœ| e¯‧wUi m‡ev©”P †eM KZ? 24. GKwU †m‡KÛ †`vj‡Ki Kvh©Kix ‣`N¨© 1% e„w× Kiv n‡j, †`vjKwU •`wbK KZ †m‡KÛ ax‡i Pj‡e? 25. 1 m Kvh©Kwi •`N©¨ wewkó GKwU mij †`vjK cÖwZ wgwb‡U 30wU †`vjb m¤úbœ K‡i| cix¶vi ¯ v‡b AwfKl©R Z¡i‡Yi gvb n‡jv26. ‡Kvb mij Qw›`Z ¯ú›`b MwZ m¤úbœ KYvi we¯Ívi 3cm Ges m‡ev©”P †eM 6.24 cms–1 n‡j KYvwUi ch©vqKvj KZ †m‡KÛ? 27. hw` c„w_exi fi I e¨vmva© P‡›`ªi fi I e¨vmv‡a©i h_µ‡g 81 ¸Y I 4 ¸Y nq Z‡e c„w_ex †_‡K GKwU †m‡KÛ †`vjK‡K P‡›`ª wb‡q †M‡j Gi †`vjbKvj KZ n‡e? 28. c„w_ex c„‡ô GKwU †m‡KÛ †`vj‡Ki •`N©¨ 100cm| †h †`vjK c„w_ex‡Z cÖwZ wgwb‡U 20 evi †`vj Lvq Zvi •`N©¨ n‡e29. nVvr msKzwPZ n‡q c„w_exi e¨vmva© A‡a©K nj, w`‡bi •`‡N©¨i wK cwieZ©b n‡e? 30. ‡Kvb GKwU †m‡KÛ †`vj‡Ki ‣`N¨© 25.6% evo‡j Gi †`vjbKvj KZ? MCQ ANSWER ANALYSIS WRITTEN cÖkœ bs DËi e¨vL¨v 01 C 2 = 6 = 3 Hz 02 B †m‡KÛ †`vjKwU NÈvq †`vjb w`Z = 3600 2 wU = 1800 wU GLb 1800 wU †`vjb w`‡Z mgq jvM‡e = (1800 × 2.05) s = 3690 s †`wi n‡e = (3690 – 3600) s = 90 s = 1.5 min 03 B 04 C = vmax A = 0.02 0.004 = 5 sec–1 T = 2 = 2 × 3.14 5 = 1.256 sec 05 A F = kx = 200 × 0.05 = 10 N 06 A 1 2 1 T 2 T L L ev, 1 2 T 2 T ev, 2 T 2 T 07 A Tm = c„w_exi e¨vmv‡a©i ¸Y c„w_exi f‡ii ¸Y Te (fMœvsk n‡j) ; 2 0.11 0.532 Tm = 3.2 sec. 08 D 2 1 2 T 1 T L L ev, 2 0.2 1.8 0.9 L ev, 2 0.2 4 1 L ev, L2=0.8m 09 A Tm = c„w_exi f‡ii ¸Y c„w_exi e¨vmv‡a©i ¸Y Te 2 4 81 = 4.5 sec.

326 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES cÖkœ bs DËi e¨vL¨v 10 A 1 2 1 2 L L T T ev, 1 2.25 2 2 T ev, 1.5 2 2 T ev, T2 = 3 sec. 11 B ch©vqKvj e‡ei f‡ii Dci wbf©i K‡i bv| 12 B T = 2 L g g = 0 T = = 1 0 f = 1 T = 1 1 0 = 0 Hz 13 A K = mg x = 1 9.8 1 = 9.8N/m 14 D T2 T1 = L2 L1 150 100 = L2 L1 = 9 4 L2 = 2.25L1 15 B x = asint = asin 2ft 16 D x = Asin(t + ) Gi mv‡_ Zzjbv K‡i, GLv‡b, A = 20m; = 31rad/s; Vm = A = 31 20 = 620m/s 17 C Ae¯’vb mv‡c‡ÿ GK Pµ cwigvY Mo kw³ = 3 2 †gvU kw³| 18 B 4 d 2 x dt2 + 400x = 0 d 2 x dt2 + 100x = 0 By compare withd 2 x dt2+ 2 x = 0; 2 = 100 = 10 rads–1 19 A ‡`vjbKvj, T = 2 m k ’ T 1 k ; T2 T1 = k1 k2 = 1 4 T2 = 1 2 T1 20 A T = 2 L g ev 2 4 2 gT L = 9.81 (2) 2 4 9.87 99.39 cm 21 x = A Sin [t ± ) = 2f = 250 f = 125 Hz 22 T = 2 m k 36.75 15 2 = 4.014 sec Avevi, L Mg K = 4 159.8 = 36.75 23 Vmax=A = 2 T . A, Vmax = 23.145 8 = 3.93m/s 24 t=86400 101 100 –1 =430s 25 g L T 2 , T = t N = 60 30 = 2sec g = 4 2 T 2 = 2 26 Vmax = A 100 6.24 = × 100 3 3 6.24 = T 2 T = 6.24 2 3 = 3.02 sec 27 2 4.5Sec 4 9 2 4 81 T r m Tm e 28 T1 T2 = T1 T2 = L1 L2 = 2 60 20 = 100 L2 2 3 = 100 L 2 L2 = 225cm 29 T2 = T1 T1 n 2 = 86400 86400 4 = 18 hr 30 T L = T2 T1 T2= 1 2 L L T = 100 125.6 2 = 2.24s

ASPECT PHYSICS cÖ_g cÎ Av`k© M¨vm I M¨v‡mi MwZZË¡ 367 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES SURVEY TABLE  Kx coe? †Kb coe? †Kv_v n‡Z coe? KZUzKz coe?  TOPICS MAGNETIC DECISION [hv co‡e] MAKING DECISION [†h Kvi‡Y co‡e] VVI For This Year DU JU RU CU GST Engr. HSC Written MCQ THEORY CONCEPT-01 Av`k© M¨vm Ges M¨v‡mi m~Îvejx 20% 30% 20% 30% 20% 10% 30% - CONCEPT-02 M¨v‡mi MwZZ‡Ë¡i †gŠwjK ¯^xKvh©mg~n 15% 35% 30% 20% 10% 05% 30% - CONCEPT-03 Av`k© M¨v‡mi MZxq mgxKiYmg~n 25% 40% 30% 20% 25% 15% 25% - CONCEPT-04 AvYweK †e‡Mi eÈb Ges Mo gy³ c‡_i Z_¨vejx 10% 45% 40% 30% 10% 10% 25% - CONCEPT-05 ¯^vaxbZvi gvÎvi ¸iæZ¡c~Y© Z_¨vejx 35% 35% 30% 20% 30% 15% 30% - CONCEPT-06 m¤ú„³ Ges Am¤ú„³ ev‡®úi Z_¨vejx 20% 25% 20% 20% 10% 20% 40% - CONCEPT-07 Av`ª©Zv Ges wkwkivsK msµvšÍ Z_¨vejx 25% 30% 30% 35% 30% 15% 30% - MvwYwZK cÖ‡qvM CONCEPT-01 e‡qj, Pvj©m I Pvcxq m~Î / Pvc, AvqZb I ZvcgvÎv msµvšÍ MvwYwZK cÖ‡qvM 60% 65% 70% 70% 75% 60% 70% - CONCEPT-02 n«‡`i ev cyKz‡ii MfxiZv wbY©q msµvšÍ MvwYwZK cÖ‡qvM 70% 75% 75% 75% 80% 45% 80% CONCEPT-03 Av`k© M¨vm msµvšÍ 55% 50% 60% 65% 70% 80% 75% CONCEPT-04 ZvcgvÎv I g~j MoeM© †eM msµvšÍ MvwYwZK cÖ‡qvM 80% 75% 80% 75% 80% 60% 80% CONCEPT-05 M¨v‡mi MwZkw³ msµvšÍ MvwYwZK cÖ‡qvM 60% 55% 60% 65% 60% 50% 60% CONCEPT-06 Mogy³ c_ msµvšÍ MvwYwZK cÖ‡qvM 65% 60% 65% 60% 65% 45% 50% CONCEPT-07 Av‡cwÿK Av`ª©Zv I wkwkiv¼ msµvšÍ MvwYwZK cÖ‡qvM 60% 50% 45% 50% 60% 40% 70% DU. = Dhaka University, JU. = Jahangirnagar University, RU. = Rajshahi University, CU = Chittagong University, GST = General, Science & Technology, Engr. = Engineering. STEP 1 mvRv‡bv me Z_¨ THEORY fwZ© †ivMxi c_¨ Concept 1 Av`k© M¨vm Ges M¨v‡mi m~Îvejx ✅ Av`k© M¨vm: †h mKj M¨vm M¨v‡mi MwZZ‡Ë¡i †gŠwjK ¯^xKvh© mg~n †g‡b P‡j Ges mKj ZvcgvÎvq I Pv‡c e‡q‡ji I Pvj©‡mi m~Î hyM¥fv‡e †g‡b P‡j Zv‡K Av`k© M¨vm e‡j| ev¯Í‡e Av`k© M¨v‡mi mgxKiY †Kvb M¨vmB mwVKfv‡e †g‡b P‡j bv| Av`k© M¨vm GKwU KvíwbK aviYv gvÎ| Z‡e D”P ZvcgvÎv I wbgœ Pv‡c ev¯Íe M¨vm mg~n Av`k© M¨v‡mi b¨vq AvPiY K‡i| ✅ Av`k© M¨v‡mi •ewkó¨m~PK gvb`Û: Av`k© M¨vm mKj ZvcgvÎv I Pv‡c PV = nRT mgxKiY †g‡b P‡j| w¯’i ZvcgvÎvq Av`k© M¨v‡mi Af¨šÍixY kw³ Gi AvqZ‡bi Dci wbf©ikxj bq| A_©vr, dU dV T = 0, U M¨v‡mi Af¨šÍixY kw³ V = M¨v‡mi AvqZb T = ZvcgvÎv Av`k© M¨v‡mi AYymg~‡ni g‡a¨ †Kvb AvKl©Y ev weKl©Y †bB| Av`k© M¨v‡mi AYymg~‡ni †gvU AvqZb M¨vm Øviv `LjK…Z AvqZ‡bi Zzjbvq bMb¨| ✅ M¨v‡mi Pjivwk: M¨v‡mi AvqZb, ZvcgvÎv I Pvc GB wZbwU‡K Pjivwk e‡j| ✅ M¨vm: mvaviY ZvcgvÎv I Pv‡c †h mKj c`v_© evqexq Ae¯’vq _v‡K Zv‡`i‡K M¨vm e‡j| †hgb- H2, O2 Ges N2 BZ¨vw`| ✅ eZ©gv‡b cÖPwjZ aviYv Abymv‡i msKU ZvcgvÎvi Dc‡i ‡Kvb c`v‡_©i evqexq Ae¯’v‡K M¨vm e‡j| ✅ M¨vmxq m~Î: M¨v‡mi 3 wU m~Î i‡q‡Q- 1. e‡q‡ji m~Î, 2. Pvj©‡mi m~Î, 3. †i‡bvi/ †M jy¨mv‡Ki Pvcxq m~Î m~Î Avwe®‹vi I mvj w¯’i ivwk m¤úK© †jLwPÎ e‡q‡ji m~Î 1662 wLª: Bs‡iR weÁvbx ievU© e‡qj ZvcgvÎv, fi P 1 V mgcive„Ë/ AvqZvKvi cive„Ë AvB‡mv_vg©/ m‡gvò ‡iLv Pvj©‡mi m~Î 1787 wLª: divmx weÁvbx Pvj©m Pvc, fi 273 V V V 0 0 , V T g~jwe›`yMvgx mij‡iLv AvB‡mvevi/ mgPvcxq †iLv Pvcxq m~Î/ †i‡bvi m~Î 1842 wLª: divmx weÁvbx †i‡bv AvqZb, fi 273 P P P 0 0 , P T g~jwe›`yMvgx mij‡iLv AvB‡mv‡Kvi/ mgAvqZb †iLv Av`k© M¨vm I M¨v‡mi MwZZË¡ THE IDEAL GAS & KINETIC THEORY OF GASES cÖ_g cÎ 10 Aa¨vq c„ôv 367

368 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES A¨v‡fvMv‡Wªvi m~Î GKB ZvcgvÎv I Pv‡c mgvb AvqZ‡bi mKj M¨v‡m mgvb msL¨K Aby _v‡K| M¨vm I ev‡®úi g‡a¨ cv_©K¨ GB †h, M¨vm‡K GKwU wbw`ó ZvcgvÎvq bx‡P †i‡L Pvc cÖ‡qvM Ki‡Z nq wKš‘ ev®ú‡K Pvc cÖ‡qvM Ki‡jB Zi‡j cwibZ Kiv hvq| †Kvb c`v_© Gi µvwšÍ ZvcgvÎv A‡c¶v AwaK ZvcgvÎvq _vK‡j Zv‡K ejv nq M¨vm cig k~Y¨ ZvcgvÎv 0 k ev -2730C (ev -459.4F) ✅ e‡q‡ji m~Î g‡b ivLvi †KŠkj- †Kvb wKQz e‡qj (Boil) Ki‡Z Zvc w`‡Z nq myZivs e‡q‡ji m~‡Î ZvcgvÎv w¯’i| ◈ e‡q‡ji m~Î: ÒZvcgvÎv w¯’i _vK‡j †Kv‡bv wbw`©ó f‡ii M¨v‡mi AvqZb Zvi Pv‡ci e¨v¯ÍvbycvwZKÓ| A_©vr, V 1 P | 1662 wLª÷v‡ã weÁvbx ievU© e‡qj GB m~Î Avwe®‹vi K‡ib| w¯’i ZvcgvÎvq wbw`©ó f‡ii M¨v‡mi AvqZb (V) I Pvc (P) Gi †jLwPÎ AvqZvKvi cive„Ë| Y O X V P 1 V P Y O X V 1 P Y X P 1 V Y X PV O V Y X PV O P ✅ Pvj©‡mi m~Î g‡b ivLvi †KŠkj- Pvj©‡mi m~Î Pvj©m Pvc w¯’i Y X V (m 3 ) O T (K) ✅ Nb‡Z¡i mv‡_ ZvcgvÎv I Pv‡ci m¤úK© P T 1 T ✅ cig k~b¨ ZvcgvÎvq M¨v‡mi- AvqZb k~b¨ Pvc k~b¨ nq MwZkw³ k~b¨ nq ✅ cig k~b¨ ZvcgvÎvi bx‡P M¨v‡mi AvqZb FYvZ¥K nq weavq ZvwË¡Kfv‡e gnvwe‡k¦ †Kvb wKQziB ZvcgvÎv -2730C Gi †P‡q Kg n‡Z cv‡i bv ev Gi bx‡P ZvcgvÎv _vK‡Z cv‡i bv| ✅ M¨vm m~‡Îi mgš^q: Av`k© M¨vm mgxKiY: e‡q‡ji I Pvj©‡mi m~‡Îi mgš^q mgxKiY: PV T = K ; K = aªæeK GK MÖvg AYy ev GK †gvj M¨v‡mi mgxKiY: PV = RT; R = mve©Rbxb M¨vm aªæeK ✅ n †gvj M¨v‡mi †¶‡Î mgxKiY: PV = nRT = m M RT; n = †gvj msL¨v = MÖv‡g cÖKvwkZ fi (m)/ MÖvg AvYweK fi (M). G‡K Av`k© M¨v‡mi mgxKiY ejv nq| ✅ Av`k© M¨v‡mi aªæeK mg~n: 1. cÖgvY ev ¯^vfvweK ZvcgvÎv 0C ev 273.16K 2. cÖgvY ev ¯^vfvweK Pvc mgy`ª c„‡ô 45 Aÿvs‡k 0C ev 273.16K ZvcgvÎvq Djø¤^fv‡e Aew¯’Z 760mm D”PZv wewkó ï®‹ ev weï× cvi` ¯Í¤¢ †h Pvc †`q Zv‡K cÖgvY ev ¯^vfvweK Pvc e‡j| cÖgvY Pvc = 760mm cvi` ¯Í¤¢| * 76cm Hg * 0.76m Hg * 1.013 105 Nm–2 * 1.013 105 Pa 3. cÖgvY ZvcgvÎv I Pv‡c GK †gvj M¨v‡mi AvqZb 22.4 Litre ev, 22.4 10–3m 3 4. STP †Z evqyi NbZ¡ 1.293kgm–3 5. me©Rbxb M¨vm aªæeK, R 8.314Jmol–1K –1 A_ev 0.0821 L atm mol–1 k –1 6. AbycÖwZ M¨vm aªæeK, K K = R NA ✅ m‡gvò cwieZ©b e‡q‡ji m~Î †g‡b P‡j|

ASPECT PHYSICS cÖ_g cÎ Av`k© M¨vm I M¨v‡mi MwZZË¡ 369 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF RU QUESTION 01. GKK Pv‡c †Kvb M¨v‡mi GK †gv‡ji AvqZb I M¨vmwUi cig ZvcgvÎvi AbycvZ wb‡Pi †KvbwU wb‡`©k K‡i? [RU. Moderna, Set-2. 20-21] A. AvYweK fi B. mve©Rbxb M¨vm aªæeK C. M¨vm aªæeK D. †KvbwUB bq S B info Av`k© M¨v‡mi m~Îvbyhvqx, PV = nRT 1.V = 1.RT V T = R [GKK Pv‡ci ìæb P = 1 Ges GKK †gv‡ji Rb¨ n = 1] 02. cig †¯‹‡j Pv‡ci m~Î n‡jv- [RU. 16-17; Xv.‡ev 2021] A. P T B. P T 2 C. P 1 T D. P T e‡q‡ji m~Î: P 1 v ; Pvj©‡mi m~Î: V T; Pvcxq m~Î: P T 03. A¨v‡fvMv‡Wªvi msL¨v-Gi gvb KZ? [RU. 15-16] A. 6.02 1022 B. 6.02 1023 C. 6.02 1029 D. 6.02 1025 Ans B 04. wb‡Pi ‡KvbwU wMÖb nvDm M¨vm bq? [RU. 15-16] A. CO2 B. H2O C. NO2 D. N2O Ans B 05. mKj M¨v‡mi Rb¨ AvqZb cÖmviY mn‡Mi gvb- [RU. 13-14] A. 1 272 / C B. 1 273 / C C. 1 275 / C D. 1 271 / C Ans B 06. w¯’i ZvcgvÎvq †Kvb M¨v‡mi AvqZb e„w× †c‡j- [RU. 13-14] A. Pvc ev‡o B. Pvc K‡g C. AYyi MwZkw³ K‡g D. †KvbwUB bq Ans B 07. M¨v‡mi AvqZb †Kvb ZvcgvÎvq k~b¨ nq? [RU. 11-12] A.273 K B. 0C C. 32F D. 0K Ans D 08. Av`k© M¨v‡mi m¤úªmviY †iLv (V ebvg T, ˚C †jLwPÎ) KZ wWwMÖ †mjwmqvm ZvcgvÎvq ZvcgvÎv A¶‡K †Q` K‡i? [RU. 11-12] A. 0˚C B. –273˚C C. 273 K D. 25˚C Ans B 09. ZvcgvÎv n«vm †c‡j †Kvb ¯’v‡bi Rjxq ev®ú aviY ¶gZv- [RU. 09-10] A. GKB _v‡K B. e„w× cvq C. n«vm cvq D. AcwiewZ©Z _v‡K Ans C STEP 02 ANALYSIS OF CU QUESTION 01. cig k~b¨ (absolute zero) ZvcgvÎv KZ? [CU. 15-16] A. 0C B. 0F C. 0R D. 0 K E. –273F Ans D 02. cvwbi wngv¼ KZ? [CU. 15-16] A. 0°F B. 32°F C. 80°F D. 100°F E. 212°F Ans B 03. PV T = aªæeK, GB m~ÎwU mZ¨ hLb- [CU. 13-14] A. ïay m‡gvò cwieZ©b nq B. ïay iæ×Zvc cwieZ©b nq C. m‡gvò I iæ×Zvc DfqwU cwieZ©b nq D. me¸wj E. †KvbwU bq| Ans C 04. 1 K¨vjwi Zvc‡K m¤ú~Y© Kv‡R iƒcvšÍwiZ Ki‡j KZ Ryj KvR m¤úbœ n‡e? [CU. 12-13] A. 1 J B. 2.4 J C. 4.2 J D. 4.8 J E. 9.6 J 1 cal = 4.2J 05. GKRb Wyeyix n«‡ì Zj‡`‡k KvR Kivi mgq 2cm3 AvqZ‡bi eyèy` Dc‡ii w`‡K cÖevwnZ n‡”Q| cvwbi DcwiZ‡j ey`ye‡ì AvqZb 4cm3 nq; wKš‘ ZvcgvÎv AcwiewZ©Z _v‡K| GwU †Kvb m~Î †g‡b P‡j? [CU. 11-12] A. Pvj©‡mi m~Î B. e‡q‡ji m~Î C. wbDU‡bi m~Î D. †KvbwUB bq Ans B 06. Pv‡ci GKK †Kvb&wU? [CU. 11-12] A. wbDUb B. Ryj C. IqvU D. c¨vm‡Kj E. †fvë Ans D 07. Ò†Kvb GKwU wbw`©ó f‡ii M¨v‡mi ZvcgvÎv w¯’i _vK‡j Dnvi AvqZb Pv‡ci e¨¯Ívbycv‡Z cwiewZ©Z nqÓ- m~ÎwU Kvi? [CU. 11-12] A. Pvj©‡mi B. e‡q‡ji C. MvD‡mi D. c¨vm‡K‡ji E. AvwK©wgwW‡mi Ans B 08. w¯’i ZvcgvÎvq †Kvb M¨v‡mi Pvc P I AvqZb V Gi g‡a¨ m¤úK© wK? [CU. 11-12] A. PV2 = w¯’i B. PV = w¯’i C. P V = w¯’i D. P V 2 = w¯’i E. V P = w¯’i Ans B STEP 03 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. wbw`©ó f‡ii †Kvb M¨v‡mi AvqZb D‡jøL Ki‡Z wK cÖ‡qvRb? [KU. 15-16] A. Pvc B. ZvcgvÎv C. Pvc I ZvcgvÎv D. cig k~b¨ ZvcgvÎv Ans C 02. Ôwbw`©ó Pv‡c wbw`©ó f‡ii †Kvb M¨v‡mi AvqZb Zvi cig ZvcgvÎvi mgvbycvwZKÕ| GwU......... bv‡g cwiwPZ| [KU. 09-10] A. †i‡bvi m~Î B. e‡q‡ji m~Î C.cig ZvcgvÎvi m~Î D. Pvj©‡mi m~Î Ans D 03. GKB ZvcgvÎv I Pv‡c mgvb AvqZ‡bi mKj M¨v‡m mgvb msL¨K AYy _v‡K| GwU nj- [KU. 05-06, 11-12] A. Pvj‡m©i m~Î B. i‡q‡ji m~Î C. ‡i‡bvi m~Î D. A¨v‡fvM¨v‡Wªvi m~Î Ans D CoU 01. mve©Rbxb M¨vm aªæeK- R = [CoU. 11-12; BSMRSTU. 11-12; kvgmyi m¨vi] A. PV nT B. PV nT2 C. PT nv D. Pn Tv PV = nRT R = PV nT IU 01. †Kvb ZvcgvÎvq M¨v‡mi MwZkw³ k~b¨ nq? [IU. 16-17, CoU. 16-17] [kvgmyi m¨vi] A.273C B.273C C. 0C D.303C cig k~b¨ ZvcgvÎvq †Kvb M¨v‡mi AvqZb ZvwË¡Kfv‡e k~b¨ n‡q hvq| cig k~b¨ ZvcgvÎvq M¨v‡mi †Kvb MwZkw³ _v‡K bv A_©vr AYy¸‡jv w¯’i _v‡K| †Kvb M¨v‡mi Af¨šÍixY kw³ ïay ZvcgvÎvi Dci wbf©i K‡i| 02. Zvc MwZwe`¨vi cÖ_g m~‡Îi †¶‡Î †KvbwU mZ¨ bq? [IU. 15-16] A. GwU Zvc I Kv‡Ri g‡a¨ m¤úK© ¯’vcb K‡i B. wbw`©ó cwigvY KvR †c‡Z n‡j wbw`©ó cwigvY Zv‡ci cÖ‡qvRb C. ‡Kvb wKQz e¨q bv K‡i KvR ev kw³ cvIqv m¤¢e D. KvR I Zvc G‡K Ac‡ii mgZzj¨ Ans C 03. †Kvb Av`k© M¨v‡mi w¯’wZkw³- [IU. 11-12] A. k~‡bï †P‡q †ekx B. k~b¨ C. k~‡bï †P‡q Kg D. †KvbwUB bq Ans B 04. cvwbi •Îa we›`y‡Z Pvc- [IU. 06-07] A. 3.58 mm HgP B. 5.58mm HgP C. 4.58 mm HgP D. ‡KvbwUB bq Ans C BRUR 01. hw` Pvc e„w× cvq, Zvn‡j ùzUbvsK ---- [BRU. 13-14] A. decreased B. increased C. remained constant D. none of them Ans B PART B Analysis of Science & Technology Question SUST 01. cvwbi •Îa we›`yiPvc (mm Hg) I ZvcgvÎv (K) h_vµ‡g: [SUST. 18-19] A. 4.58, 273.16 B. 4.58, 273.15 C. 5.58, 0 D. 4.58, 273.0 E. 5.58, 273.16 Ans A

370 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES BSMRSTU 01. wb‡Pi †Kvb kZ© mv‡c‡¶ ev¯Íe M¨vm mg~n Av`k© M¨v‡mi gZ AvPiY K‡i? [BSMRSTU. 14-15] A. Zvc I Pv‡ci mKj Ae¯’vq B. Lye D”P Pv‡c C. hLb M¨v‡mi ZvcgvÎv Nbxfe‡bi wbK‡U _v‡K D. Kg Nb‡Z¡ hLb M¨v‡mi KYv¸‡jv Zzjbvg~jK `~i‡Z¡ _v‡K Ans D 02. ‡Kvb k‡Z© ev¯Íe M¨vm mg~n Av`k© AvPiY K‡i? [BSMRSTU. 14-15, MBSTU. 19-20;Kz.†ev. 2016, e.†ev. 2015, w`.†ev. 2021] A. wbgœ ZvcgvÎvq I D”P Pv‡c B. wbgœ ZvcgvÎvq I wbgœ Pv‡c C. D”P ZvcgvÎvq I D”P Pv‡c D. wbgœ Pv‡c I D”P ZvcgvÎvq Ans D DU Technology 01. GKwU Av`k© M¨vm hLb cigk~b¨ ZvcgvÎvq †cuŠQvq ZLb M¨vmwUÑ [DU-Tech. 2020-21] A. mvaviY Zi‡j Nbxf‚Z nq B. AwZ Zi‡j Nbxf‚Z nq C. me©vwaK AvYweK wefekw³ jvf K‡i D. †Kv‡bv Pvc cÖ‡qvM K‡i bv S D info 273C ev 0 K ev –159.4F ZvcgvÎv‡K cig k~b¨ ZvcgvÎv e‡j| GB ZvcgvÎvq M¨v‡mi AvqZb, Pvc I MwZkw³ k~b¨ n‡q hvq e‡j M¨vmwU †Kv‡bv Pvc cÖ‡qvM K‡i bv| STEP 04 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. 100 wWwMÖ †mjwmqv‡m cvwb ev‡®úi Pvc nqÑ [MAT. 2020-21] A. 55 mm Hg B. 760 mm Hg C. 1489 mm HgD. 355 mm Hg 100C G cvwbi ev‡®úi Pvc 760.00 mmHg 02. wbw`©ó IR‡bi GKwU Av`k© M¨v‡mi ¶gZv †Kvb •ewk‡ó¨i Dci wbf©i K‡i? [MAT. 18-19, 14-15] A. NbZ¡ B. AvqZb C. Pvc D. ZvcgvÎv Ans D 03. †Kvb ZvcgvÎvq M¨v‡mi MwZkw³ k~b¨ n‡e? [MAT. 17-18] A.330C B. 273C C. –273C D. 0 C Ans C 04. w¯’i ZvcgvÎvq wbw`©ó f‡ii M¨v‡mi AvqZb I Pvc v–p †jL wPÎ †Kvb ai‡bi? [MAT. 16-17] A. AvqZvKvi Awae„Ë (Rectangular Hyperbola) B. mij •iwLK (Streaight line) C. e„ËvKvi (Circular) D. cive„Ë (Parabola) Ans A 05. mveR©bxb M¨vm aªæeK R Gi gvb KZ? [MAT. 05-06; MBSTU. 15-16; CoU. 12-13; RUET. 12-13;15-16;] A.8.13Jk-1mol-1 B. 8.83Jk-1mol-1 C. 8.34Jk-1mol-1 D. 8.31Jk-1mol-1 Ans D 06. Av`k© M¨vm I ev¯Íe M¨vm msµvšÍ bx‡Pi †Kvb Z_¨wU fyj? [MAT. 08-09] A. N2,O2 Av`k© M¨vm B. H2, CO2 ev¯Íe M¨vm C. PV=nRT mgxKiYwU Av`k© M¨vm cy‡ivcywi AbymiY K‡i D. PV=nRT mgxKiYwU ev¯Íe M¨v‡m cy‡ivcywi AbymiY K‡i bv Ans A 07. Pvc, Zvc I AvqZb msµvšÍ †Kvb m~ÎwU mwVK bq? [MAT. 08-09, D: 08-09] A. V = V0 1 + 273 B. P = Po 1 + 273 C. PV = M m RT D. PV = nRT Ans C 08. PV=k GB mgxKiYwU mvaviY fv‡e †Kvb m~‡Îi cÖKvk [MAT. 02-03] A. Pvj©‡mi m~Î B. e‡q‡ji m~Î C. Pv‡ci m~Î D. Av`k© M¨vm mgxKiY Ans B 09. ‡Kvb Dw³wU mwVK bq? [MAT. 00-01] A. ùzUbvs‡K Zi‡ji m¤ú„³ ev®ú Pvc Zij c„‡ôi Dci¯’ Pv‡ci †P‡q AwaK| B. wbw`©ó ZvcgvÎvq wewfbœ M¨v‡mi wgkª‡b †h Pvc cÖv‡qvM K‡i Zv H wgkª‡bi g‡a¨ M¨vm¸‡jvi Pv‡ci mgwói mgvb| C. m¤ú„³ ev®ú e‡q‡ji m~Î †g‡b P‡j bv| D. ZvcgvÎv n«v‡mi mv‡_ mv‡_ Am¤ú„³ ev‡®úi Pvc n«vm cvq Ans D AFMC 01. wb‡Pi †KvbwU cig ïb¨ ZvcgvÎv? [AFMC. 2020-21; P. †ev. 2019, 16; w`.‡ev. 2016; wm.‡ev. 2015] A. 33C B. –273C C. 40C D. 0C †h ZvcgvÎvq w¯’i Pv‡c †Kv‡bv wbw`©ó f‡ii M¨v‡mi AvqZb k~b¨ nq Ges MwZkw³ m¤ú~Y©iƒ‡c †jvc cvq Zv‡K cigk~b¨ ZvcgvÎv e‡j| 0 K ev –273C †K cigk~b¨ ZvcgvÎv aiv nq| STEP 05 ANALYSIS OF HSC BOARD QUESTION 01. STP †Z mKj M¨v‡mi †gvjvi AvqZbÑ [Xv.‡ev 2021] A. 22.4L B. 22.9L C. 28.4L D. 22.8L Ans A 02. g~jMo eM©‡eM C Ges Pvc P Gi g‡a¨ m¤úK© n‡jvÑ [Xv.†ev. 2019] A. C = 3P n B. C = 3P P C. C = P 3n D. C = n 3P Ans B 03. wb‡¤œi wP‡Î P-V wZbwU †jLwPÎ †`qv nj [Xv. †ev. 2016] wb‡Pi †KvbwU mwVK? A. ii I iii B. i I iii C. i I ii D. i, ii I iii Ans C 04. w¯’i ZvcgvÎvq wbw`©ó f‡ii M¨v‡mi Rb¨ †Kvb †jLwPÎwU cÖ‡hvR¨? [iv.‡ev. 2019; Xv.‡ev. 2017; P.‡ev. 2016] A. PV V B. PV V C. P V D. P V Ans B 05. ZvcgvÎv w¯’i _vK‡j AvqZb (V) I Pvc (P) Gi m¤úK© wb‡Pi †Kvb †jLwPÎ cÖgvY K‡i? [iv.‡ev. 2019; h.‡ev. 2019; w`.‡ev. 2016] A. Y V P X B. Y 1 P X V C. Y PV P X D. me¸‡jv mwVK Ans D 06. C.G.S GK‡K †evjRg¨vb aªæe‡Ki gvb S.I GK‡Ki gvb A‡cÿv KZ ¸b †ewk? [iv.‡ev. 2019] A. 10-7 B. 107 C. 10-5 D. 105 Ans B 07. wb‡Pi †Kvb †jLwPÎwU Ôe‡qjÕ -Gi m~‡Îi Rb¨ cÖ‡hvR¨? [iv.‡ev. 2019] A. B. C. D. Ans B

ASPECT PHYSICS cÖ_g cÎ Av`k© M¨vm I M¨v‡mi MwZZË¡ 371 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES 08. Av`k© M¨v‡mi †ÿ‡Î MwZkw³ (E) ebvg ZvcgvÎv (T) Gi †jLwPÎ †KvbwU? [P. †ev. 2017] A. B. C. D. Ans B 09. w¯’i AvqZ‡b 0C ZvcgvÎvq †Kv‡bv M¨v‡mi Pvc wØ¸Y Ki‡j Gi P‚ovšÍ ZvcgvÎv n‡e- [w`.‡ev 2021] A. 27C B. 273C C. 300C D. 546C Ans B 10. M¨v‡mi †ÿ‡Î ZvcMZxq Pjivwk Kx Kx? [w`.‡ev 2021] A. AvqZb, fi I NbZ¡ B. AvqZb, ZvcgvÎv I NbZ¡ C. AvqZb, fi I ZvcgvÎv D. AvqZb, ZvcgvÎv I Pvc Ans D 11. Av`k© M¨v‡mi †ÿ‡Î Pvc, AvqZb I ZvcgvÎvi g‡a¨ m¤úK© n‡”Q- [w`.‡ev. 2016] A. PV = RT B. PV = nRT C. PV = KT D. me¸‡jv mwVK Ans D 12. ¯^vfvweK ZvcgvÎv I Pv‡c Aw·‡Rb AYyi Mo eM©‡e‡Mi eM©g~j-[w`.†ev. 2016] A. 461 ms–1 B. 361 ms–1 C. 261 ms–1 D. 162 ms–1 C = 3RT m = 3 × 8.31 × 273 32 × 10–3 = 461 ms–1 13. ‘PV’ ivwkwUi M¨v‡mi †ÿ‡Î wb‡`©k K‡iÑ [h. †ev. 2017] A. kw³ B. ÿgZv C. fi‡eM D. RoZv Ans A 14. GKK AvqZ‡bi AYy¸‡jvi MwZkw³ E Ges M¨v‡mi Pv‡ci m¤úK© ¯’vcbKvix mgxKiY †KvbwU? [h. †ev. 2016] A. E = 3 2 P B. E = 2 3 P C. E = 1 2 3 2 P D. E = 1 2 2 3 P Ans A 15. Av`k© M¨v‡mi Rb¨ wb‡Pi †KvbwU mwVK? [Kz. †ev. 2017] A. B. C. D. Ans D 16. PV = 1 3 mNC2 mgxKi‡Y C [Kz. †ev. 2017] A. Mo †eM B. Mo eM© †eM C. g~j Mo eM©‡eM D. Av‡jvi †eM 17. M¨v‡mi cigk~b¨ ZvcgvÎvi gvb n‡”QÑ [Kz. †ev. 2016] i. 0C ii. 0K iii. 273C wb‡Pi †KvbwU mwVK? A. ii B. iii C. ii I iii D. i, ii I iii Ans C 18. e‡q‡ji m~Î wb‡Pi †Kvb cÖwµqv †g‡b P‡j? [wm. †ev. 2015] A. mgPvc B. m‡gvò C. iæ×Zvcxq D. mg AvqZb Ans B 19. me©Rbxb M¨vm aªæeK R GKK †KvbwU? [e.‡ev 2021] A. JK mol–1 B. JK-1 mol C. J mol D. J mol–1K –1 Ans D Concept 2 M¨v‡mi MwZZ‡Ë¡i †gŠwjK ¯^xKvh©mg~n ✅ M¨v‡mi MwZZË¡: 1730 mv‡j ev‡b©vwj me© cÖ_g MwZ Z‡Ë¡i mvnv‡h¨ M¨v‡mi m~Îvejx e¨vL¨v K‡ib| GRb¨ ev‡b©vwj‡K M¨v‡mi MwZ Z‡Ë¡i RbK ejv nq| ✅ 1860 Lªx÷v‡ã K¬wmqvm, g¨v·I‡qj, †evjRg¨vb, wRb, f¨vÛvi Iqvj&m MwZ Z‡Ë¡i cÖf~Z DbœwZ mvab K‡ib Ges Z‡Ë¡i mvnv‡h¨ M¨v‡mi bvbviƒc AvPi‡bi e¨vL¨v cÖ`vb K‡ib| ✅ M¨v‡mi MwZ Z‡Ë¡i †gŠwjK ¯^xKvh© mg~n: 1857 mv‡j K¬wmqvm cÖ_g GB ¯^xKvh© ¸‡jv eY©bv K‡ib| ¯^xKvh© ¸‡jv njÑ GKB M¨v‡mi AYy¸‡jv GKB iKg Ges wewfbœ M¨v‡mi AYy¸wj wewfbœ| AYy¸‡jv we›`y fi ev fi hvi AvqZb M¨vm cv‡Îi Zzjbvq Kg| M¨v‡mi AYy¸‡jv m¤ú~Y© `„p w¯’wZ¯’vcK †MvjK Ges ci¯ú‡ii mv‡_ †Kvb AvKl©Y ev weKl©Y bvB| AYy¸‡jv ci¯ú‡ii mv‡_ Ges cv‡Îi †`qv‡ji mv‡_ av°v Lvq| AYy¸‡jv mg‡e‡M P‡j| msNl©Kvj AwZ Aí| D³ mg‡q AwZµvšÍ `~iZ¡ gy³ c_| AYy¸‡jv m¤ú~Y© w¯’wZ¯’vcK †MvjK, ZvB msN‡l©i c~‡e© I c‡i G‡`i fi‡eM I MwZkw³ msiw¶Z _v‡K| AYy¸‡jv wewfbœ MwZ‡Z G‡jv‡g‡jvfv‡e BZ¯ÍZ †QvUvQywU K‡i Ges wbDU‡bi MwZ m~Î †g‡b P‡j| Av`k© M¨vm ¯^xKvh©mg~n m‡ev©Zfv‡e †g‡b P‡j wKš‘ ev¯Íe M¨vm mKj ¯^xKvh© †g‡b P‡j bv| M¨vm AYy¸‡jvi Dci AwfKl©R e‡ji cÖfve †bB| M¨v‡mi AYy ¸‡jv AbeiZ av°vq wjß _vK‡jI GKK Nb AvqZ‡b AYyi msL¨v w¯’i _v‡K| A_©vr Av`k© M¨v‡mi AvYweK NbZ¡ w¯’i _v‡K| GKwU msN‡l© †h mgq e¨q nq Zv `ywU msN‡l©i ga¨eZ©x mg‡qi Zyjbvq bMb¨ A_©vr av°v¸‡jv Zvr¶wYK| ✅ M¨v‡mi MwZZ‡Ë¡i cÖ‡qvM: M¨v‡mi MwZZË¡ cÖ‡qvM K‡i wb‡¤œv³ m~Î I mgxKiY cÖgvY/cÖwZcv`b Kiv hvq| 1. e‡q‡ji m~Î; 2. Av`k© M¨v‡mi mgxKiY; 3. Pvj©‡mi m~Î; 4. Pv‡ci m~Î; 5. A¨v‡fvMv‡Wªvi m~Î REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF JU QUESTION 01. ¯^vfvweK M¨v‡mi MwZZË¡ Abymv‡i M¨vm AYy¸‡jvi g‡a¨ †Kv‡bv AvšÍtAvYweK ej †bB| myZivs Aby¸‡jvi- [JU-A, Set-D. 19-20; Xv. †ev. 2019] A. •iwLK fi‡eM †bB B. MwZkw³ †bB C. wefekw³ †bB D. †KvbwUB bq Av`k© M¨v‡mi w¯’wZkw³ = 0 STEP 02 ANALYSIS OF RU QUESTION 01. †gvjvi AvqZb MYbvi mwVK mgxKiY †KvbwU? [RU. 17-18] A. V = nPT R B. V = nPR T C. V = rPT N D. V = nRT P Ans D

372 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES STEP 03 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. w¯’i ZvcgvÎvi †ÿ‡Î M¨v‡mi Aby¸wji Rb¨ †Kvb c¨vivwgUvi aªæe (Constant)? [MAT. 2020-21] A. MwZ‡eM B. fi C. MwZ‡eM kw³ D. AvqZb wbw`©ó ZvcgvÎvq (T), M¨v‡mi AYy¸‡jvi †gvU MwZkw³ (Ek) w¯’i _v‡K| AYy¸‡jv we›`y fi ev fi hvi AvqZb M¨vm cv‡Îi Zzjbvq Kg| M¨v‡mi AYy¸‡jv m¤ú~Y© `„p w¯’wZ¯’vcK †MvjK Ges ci¯ú‡ii mv‡_ †Kvb AvKl©Y ev weKl©Y bvB| Av`k© M¨vm ¯^xKvh©mg~n m‡ev©Zfv‡e †g‡b P‡j wKš‘ ev¯Íe M¨vm mKj ¯^xKvh© †g‡b P‡j bv| M¨vm AYy¸‡jvi Dci AwfKl©R e‡ji cÖfve †bB| M¨v‡mi AYy ¸‡jv AbeiZ av°vq wjß _vK‡jI GKK Nb AvqZ‡b AYyi msL¨v w¯’i _v‡K| A_©vr Av`k© M¨v‡mi AvYweK NbZ¡ w¯’i _v‡K| 02. wb‡Pi †KvbwU M¨v‡mi MwZZ‡Ë¡i Rb¨ mwVK [MAT. 11-12] A. wbDU‡bi MwZ m~Î mg~n †g‡b P‡j bv B. GKB M¨v‡mi AYy m`„k C. AYy¸‡jv Aeµg MwZ‡Z MwZkxj D. AYy¸‡jv wb‡Ri g‡a¨ AvKwl©Z nq mKj M¨vm AYyi m¤^š^‡q MwVZ| GKwU M¨v‡mi mKj AYy m`„k¨ Ges GKwU M¨v‡mi AYy Ab¨ M¨v‡mi AYy †_‡K Avjv`v| 03. M¨v‡mi MwZZË¡ Abyhvqx Ab¨Zg ¯^xKvh© n‡jv AYy¸‡jvi g‡a¨ msNl© My‡jv? [MAT. 00-01] A. w¯’wZ¯’vcK B. AvswkK w¯’wZ¯’vcK C. m¤ú~Y© w¯’wZ¯’vcK D. m¤ú~b© Aw¯’wZ¯’vcK Ans C STEP 04 ANALYSIS OF HSC BOARD QUESTION 01. M¨v‡mi MwZZË¡ Abymv‡i †KvbwU mwVK? [Xv.†ev. 2019] A. AYy¸‡jvi msNl© Aw¯’wZ¯’vcK B. AYy¸‡jvi w¯’wZkw³ †bB C. AYy¸‡jvi MwZkw³ †bB D. AYy¸‡jvi fi‡eM †bB Ans B 02. M¨v‡mi MwZZ‡Ë¡i †gŠwjK ¯^xKvh© Abymv‡i [Xv. †ev. 2017] i. ZvcgvÎv e„w×i mv‡_ AYyi †eM e„w× cvq ii. AYy¸‡jvi ga¨eZ©x `~i‡Z¡i Zzjbvq AYy¸‡jvi AvqZb D‡cÿYxq iii. `ywU av°vi ga¨eZx© mg‡q AYyMy‡jv mg‡e‡M mij‡iLvq P‡j bv wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans A 03. M¨v‡mi mv›`ªZv ¸YvsK ZvcgvÎvi [P. †ev. 2016] A. mgvbycvwZK B. e¨¯ÍvbycvwZK C. eM©g~‡ji mgvbycvwZK D. eM©g~‡ji e¨¯ÍvbycvwZK Ans C 04. M¨v‡mi AYyi Mogy³ c_ Zvi Nb‡Z¡i [P. †ev. 2016] A. e‡M©i mgvbycvwZK B. mgvbycvwZK C. e¨¯ÍvbycvwZK D. eM©g~‡ji e¨¯ÍvbycvwZK Ans C 05. wbw`©ó ZvcgvÎvq mKj M¨vm AYyi Rb¨ †Kvb ivwkwU aªæeK? [w`. †ev. 2017] A. fi B. fi‡eM C. MwZkw³ D. AvqZb Ans C 06. †Kv‡bv M¨v‡mi g~j Mo eM©‡eM Ges cig ZvcgvÎvi m¤úK©- [w`. †ev. 2015] A. mgvbycvwZK B. e¨¯ÍvbycvwZK C. eM©g~‡ji mgvbycvwZK D. e‡M©i e¨¯ÍvbycvwZK Ans C 07. †Kv‡bv cv‡Î Ave× M¨vm AYy¸wji me©vwaK msL¨K AYyi †eM‡K e‡j- [g.‡ev 2021] A. Mo †eM B. g~j Mo eM©‡eM C. Mo eM©‡eM D. me©vwaK m¤¢ve¨ †eM Ans D 08. ev¯Íe M¨vm e‡q‡ji m~Î †g‡b P‡j- [g.‡ev 2021] A. D”P ZvcgvÎv B. Kÿ ZvcgvÎv C. wb¤œ ZvcgvÎv D. 0C ZvcgvÎv Ans A 09. PV = aªæeK, mgxKiYwU wb‡Pi †Kvb cÖwµqv‡K mg_©b Ki‡e? [e.‡ev 2021; P.‡ev 2021] A. m‡gvò B. mg AvqZb C. mg Pvc D. iæ×Zvcxq Ans A 10. M¨v‡mi MwZZË¡ Abymv‡i wb‡Pi †Kvb wee„wZwU Am½wZc~Y©? [e.‡ev. 2019] A. Aby¸‡jv wbDU‡bi m~Î †g‡b P‡j B. Aby¸‡jv mew`‡K mg‡e‡M MwZkxj C. Aby¸‡jv AwZ ÿz`ª D. ev®úvq‡bi nvi n«vm cvq Ans A 11. M¨v‡mi †gŠwjK ¯^xKvh© Abymv‡i- [e. †ev. 2015] A. GKwU M¨v‡mi mKj AYy m`„k B. ZvcgvÎvi mv‡_ AYy¸‡jvi †eM ev‡o C. M¨v‡mi kw³ wefe kw³ D. A I B DfqB Ans D 12. M¨v‡mi †gŠwjK ¯^xKvh© Abymv‡iÑ [e. †ev. 2015] i. GKwU M¨v‡mi mKj AYy m`„k ii. M¨v‡mi kw³ wefe kw³ iii. ZvcgvÎvi mv‡_ AYyMy‡jvi †eM ev‡o wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans B Concept 3 Av`k© M¨v‡mi MZxq mgxKiYmg~n welq mgxKiY M¨v‡mi MwZZË¡ I kw³i mgxKiY P = 1 3 c 2 = 1 3 mnc2 V = mn V = 1 3 mc2 V = (M = mn) = 2 3 1 2 Mc2 = 2 3 E E = 1 2 Mc2 M¨v‡mi Pvc Gi GKK AvqZ‡bi AYy¸‡jvi MwZkw³i `yB-Z…Zxqvsk| Av`k© M¨v‡mi ms‡kvwaZ mgxKiY (1 †gvj M¨v‡mi Rb¨) P + a v 2 (V – b) = RT f¨vbWvi Iqvjm mgxKiY (n †gvj M¨v‡mi Rb¨) P + n 2 a v 2 (V – nb) = nRT a = f¨vbWvi Iqvj‡mi Pvc ms‡kvab aªæeK b = f¨vbWvi Iqvj‡mi AvqZb ms‡kvab aªæeK g~j Mo eM©‡e‡Mi mv‡_ Pv‡ci m¤úK© C= 3P (P = M¨v‡mi Pvc, = M¨v‡mi NbZ¡) g~j Mo eM©‡e‡Mi mv‡_ ZvcgvÎvi m¤úK© C = 3RT M C T ( †hLv‡b R I M aªæeK) M¨vm AYyi MwZkw³ I ZvcgvÎvi mv‡_ m¤úK© 1 2 mc2 = 2 3 KT ev, C = 3RT M M¨v‡mi AYyi Mo MwZkw³ Gi cig ZvcgvÎvi mgvbycvwZK| GKwU AYyi MwZkw³ = 2 3 †evjRg¨vb aªæeK cig ZvcgvÎv †evjRg¨vb aªæeK K = 1.38 10–23JK–1 A¨v‡fvMv‡Wªvi msL¨v NA = 6.0222 1026 AYy/wK‡jv‡gvj A_ev NA = 6.022 1023 AYy/‡gvj

ASPECT PHYSICS cÖ_g cÎ Av`k© M¨vm I M¨v‡mi MwZZË¡ 373 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF JU QUESTION 01. M¨vm AYyi Mo eM©‡eM M¨v‡mi cig ZvcgvÎvi- [JU. 10-11] A. e¨¯ÍvbycvwZK B. mgvbycvwZK C. e‡M©i mgvbycvwZK D. ‡KvbwUB bq Ans D STEP 02 ANALYSIS OF RU QUESTION 01. ZvcgvÎv e„w× †c‡j AYy¸‡jvi Mo eM© †eM- [RU. 09-10] A. n«vm cvq B. e„w× cvq C. AcwiewZ©Z _v‡K D. k~b¨ nq Ans B STEP 03 ANALYSIS OF CU QUESTION 01. T ZvcgvÎvq Av`k© M¨v‡mi †¶‡Î GKwU AYyi Mo MwZkw³ KZ? [CU. 15-16, 11-12; JU. 18-19; IU. 12-13] A. 2 3 KT B. 1 3 KT2 C. 1 2 KT 2 D. 3 2 KT3 E. 3 2 KT Ans E 02. M¨v‡mi AYyi Mo MwZkw³ Dnvi- [CU. 06-07] A. ZvcgvÎvi e¨¯ÍvbycvwZK B. Pv‡ci mgvbycvwZK C. ZvcgvÎvi mgvbycvwZK D. Pv‡ci e¨¯ÍvbycvwZK Ans C STEP 04 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. GKwU wbw`©ó Pv‡c †h ZvcgvÎvq †Kvb c`v_© KwVb, Zij I evqexq iƒ‡c mvg¨ve¯’vq _v‡K, Zv‡K e‡j H c`v‡_©i- [KU. 14-15] A. w¯’i we›`y B. •Îa we›`y C. w÷g we›`y D. eid we›`y Ans B IU 01. AYyi g~j Mo eM© †e‡Mi mv‡_ Pv‡ci m¤úK© n‡”Q, P =? [IU. 13-14] A. 1 3 c 2 B. 2 3 E C. Nmc2 2l 2 D. GwU mve©Rwbb Ans A BRUR 01. Which is the correct one? [BRUR. 12-13] A. Crms : Cm : Cav = 1.22:1.2:1 B. Crms : Cav : Cm = 1.22:1.12:1 C. Cm : Crms : Cav = 1:1.12:1.22 D. Crms : Cav : Cm = 1.12:1:0.22 Ans B PART B Analysis of Science & Technology Question SUST 01. ‡KvbwU wVK? [SUST. 05-06] A. †Kvb e¯‘‡K Mig Ki‡j Bnvi Kbvmg~‡ni MwZkw³i †Kvb cwieZ©b nq bv| B. †Kvb e¯‘‡K Mig Ki‡j Bnvi KYvmg~‡ni MwZkw³ e„w× cvq C. †Kvb e¯‘‡K VvÛv Ki‡j Bnvi KYvmg~‡ni MwZkw³ e„w× cvq| D. †Kvb e¯‘‡K Mig Ki‡j Bnvi KYvmg~‡ni w¯’wZkw³ e„w× cvq EK T ZvcgvÎv e„w× †c‡j MwZkw³ e„w× cvq| JUST 01. MwZ kw³ we¯Ív‡ii mv‡_- [JUST. 15-16] A. e„w× cvq B. n«vm cvq C. mgvb _v†K D. e‡M©i mgvbycv‡Z ev‡o E. k~b¨ nq Ans D MBSTU 01. g~j Mo eM©‡e‡Mi mv‡_ Pv‡ci m¤úK© n‡jv- [MBSTU. 14-15; CoU.15-16] A. c = 3 P B. c = 3P C. c = 3P D. c = 2P Ans C BSMRSTU 01. wb‡Pi †KvbwU Av`k© M¨v‡mi MZxq mgxKiY? [BSMRSTU-H, 19-20] A. PV = nRT B. PV = 1 3 mNc2 C. PV = RT D. PV = P1V1 PV = 1 3 mNC2 M¨v‡mi MZxq mgxKiY PV = nRT Av`k© M¨v‡mi mgxKiY P1V1 = P2V2 e‡qj Pvj©‡mi mgš^q m~Î PV = RT 1 †gvj M¨v‡mi mgxKiY| HSTU 01. wb‡Pi †Kvb m¤úK©wU mwVK bq? [HSTU. 14-15] A. P1V1 T1 = P2V2 T2 B. PV = nRT C. P1 T1 = P2 T2 D. P1 V1 = P2 V2 Ans D STEP 05 ANALYSIS OF ENGINEERING & BUTex QUESTION BUET 01. `ywU wfbœ Av`k© M¨vm GKB Pv‡c wfbœ wfbœ cv‡Î Ave× Av‡Q| hw` 1 I 2 G¸‡jvi NbZ¡ Ges C1 I C2 h_vµ‡g G¸‡jvi g~jMo eM©‡eM nq, Zvn‡j C1 C2 Gi mgvb n‡e- [BUET. 05-06] A. 2 1 2 2 B. 2 2 2 1 C. 1 2 D. 2 1 Ans D KUET 01. m‡gvò cÖwµqvq GKwU M¨v‡mi Pvc I AvqZ‡bi mgxKiY n‡”Q [KUET. 05-06] A. PV = k B. P v = K C. v P = K D. PV = k Ans A STEP 06 ANALYSIS OF HSC BOARD QUESTION 01. cig †¯‹‡j Pv‡ci m~Î n‡jv- [Kz.‡ev 2021] A. P T B. P T 2 C. P 1 T D. P T Ans A 02. T ZvcgvÎvi Av`k© M¨v‡mi †ÿ‡Î AYyi Mo MwZkw³Ñ [wm.†ev.2015,P.†ev.2015] A. 2 3 KT B. 3 2 KT2 C. 3 2 KT4 D. 3 2 KT Ans D 03. ‡Kvb M¨v‡mi g~j Mo eM©‡eM Ges cig ZvcgvÎvi m¤úK©Ñ [wm. †ev. 2015] A. mgvbycvwZK B. e¨¯ÍvbycvwZK C. eM©g~‡ji mgvbycvwZK D. e‡M©i e¨¯ÍvbycvwZK Ans C 04. GKK AvqZ‡bi AYyMy‡jvi MwZkw³ E Ges M¨v‡mi Pv‡ci m¤úK© ¯’vcbKvix mgxKiY †KvbwU? [e. †ev. 2016] A. E = 3 2 P B. E = 2 3 P C. E = 1 2 3 2 P D. E = 1 2 2 3 P Ans A

374 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 4 AvYweK †e‡Mi eÈb Ges Mo gy³ c‡_i Z_¨vejx ✅ MwZ Z‡Ë¡ Mo †e‡Mi †Kvb eënvi ‡bB| ïaygvÎ g~j Mo eM©‡eM AYyi wewfbœ ‡e‡Mi cÖwZwbwaZ¡Kvix Mo wn‡m‡e eëüZ nq| ✅ M¨v‡mi AYy¸‡jvi †gvU MwZkw³ cig ZvcgvÎvi mgvbycvwZK| ✅ M¨v‡mi RMS †eM cig ZvcgvÎvi eM©g~‡ji mgvbycvwZK| ✅ Mo gy³ c_: cÖgvY ZvcgvÎv I Pv‡c cÖwZ NbwgUvi M¨v‡m 2.91025 wU AYy _v‡K| GB AYy¸‡jv ci¯ú‡ii mv‡_ msN‡l© wjß _v‡K| wnmve K‡i †`Lv †M‡Q cÖwZ †m‡K‡Û msN‡l©i msL¨v cÖvq 109 wU| msÁv: †Kvb AYyi cici `ywU msN‡l©i gaëZ©x `~iZ¡¸‡jvi Mo wb‡q †h `~iZ¡ cvIqv hvq Zv‡K Mo gy³ c_ e‡j| hw` N msL¨K av°vi g‡a¨ AYy †gvU S `~iZ¡ AwZµg K‡i Z‡e Mo gy³ c_ = S N ✅ cÖwZwU AYyi Mo gy³ c_ mgvb ✅ K¬wmqvm me©cÖ_g Mo gy³ c‡_i ivwkgvjv †ei K‡ib ✅ Mo gy³c‡_i mgxKiY: K. K¬wmqv‡mi mgxKiY: = 1 a 2 n L. g¨v·I‡q‡ji mgxKiY: = 1 2a 2 n ✅ GB m~Î¸‡jvi g‡a¨ g¨v·I‡q‡ji m~ÎwU mvaviYZ Mo gy³ c‡_i ivwkgvjv wbY©‡q eënvi Kiv nq| wZwb AvYweK †eM e›Ub m~Î Aej¤^‡b G ivwkgvjv wbY©q K‡ib| ✅ Mo gy³ c‡_i wbf©ikxjZv: 1 n (n = AYyi msL¨v) 1 a 2 (a = AYyi e¨vm) 1 (NbZ¡ GKK AvqZ‡b AYyi msL¨vi (n) mgvbycvwZK) 1 P (NbZ¡ Pv‡ci mgvbycvwZK) T (NbZ¡ ZvcgvÎvi e¨¯ÍvbycvwZK) REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF RU QUESTION 01. †Kvb cv‡Î Ave× M¨v‡m AYy¸wji me©vwaK msL¨K M¨vm AYyi †eM‡K ejv nq? [RU. 12-13, F. 15-16] A. Mo †eM B. g~j Mo eM© †eM C. me©vwaK m¤¢ve¨ †eM D. Mo eM© †eM Ans C STEP 02 ANALYSIS OF GST QUESTION PART A Analysis of Science & Technology Question JUST 01. Av`k© K…òe¯‘ (Black Body) Gi †kvlY ¶gZv- [JUST. 15-16] A. 0% B. 1% C. 50% D. 75% E. 100% Ans E STEP 03 ANALYSIS OF HSC BOARD QUESTION 01. bvB‡Uªv‡Rb M¨v‡mi †ÿ‡Î Mvgv () Gi gvb KZ? [Xv. †ev. 2015] A. 1.67 B. 1.4 C. 1.33 D. 1.28 Ans B GK-cvigvYweK M¨v‡mi Rb¨, = 1.67 (He, Ar) wØ-cvigvYweK M¨v‡mi Rb¨, = 1.41 (Cl2, O2) eûcvigvYweK M¨v‡mi Rb¨, = 1.33 (CO2, H3) 02. GKwU Av`k© M¨v‡mi ZvcgvÎv T n‡Z e„w× K‡i 2T Kiv nj| †Kvb ivwkwU wØMyY n‡e? [Xv. †ev. 2015; P. †ev. 2015] A. AYyMywji Mo eM©‡e‡Mi eM©g~j B. AYyMywji Mo †e‡Mi eM© C. AYyMywji Mo‡eM D. AYyMywji Mo eM©‡eM Ans D 03. M¨v‡mi Aby¸‡jvi g~j Mo eM© †eM Crms Ges cig ZvcgvÎv T n‡j wb‡Pi †KvbwU mwVK? [w`.‡ev. 2019] A. Crms T B. Crms T C. Crms 1 T D. Crms 1 T Ans B 04. wb‡Pi †KvbwU jw¤^K Zi½? [w`.‡ev. 2019] A. ‡eZvi Zi½ B. w¯úªs Gi Zi½ C. kã Zi½ D. Uvbv Zv‡ii Zi½ Ans C 05. ZvcgvÎv KZ¸Y n‡j Aw·‡Rb M¨v‡mi AYyi †eM wØ¸Y n‡e? [wm. †ev. 2016] A. 2 B. 4 C. 8 D. 16 Ans B Concept 5 ¯^vaxbZvi gvÎvi ¸iæZ¡c~Y© Z_¨vejx ✅ msÁv: †Kvb MwZkxj wm‡÷‡gi Ae¯’vb m¤ú~Y©iƒ‡c †evSv‡Z †gvU †h msL¨K ¯^vaxb ivwki cÖ‡qvRb nq ev MwZkxj wm‡÷‡gi †gvU MwZkw³i ivwkgvjvq †h KqwU ¯^vaxb eM©ivwk cvIqv hvq| ✅ e¨vL¨v: †Kvb MwZkxj wm‡÷‡gi Ae¯’vb m¤ú~Y© cÖKvk Ki‡Z hZ¸‡jv ¯’vbv‡¼i cÖ‡qvRb nq Zvi msL¨vB n‡”Q ¯^vaxbZvi gvÎv| ‡Kvb e¯‘ Aev‡a ev ¯^vaxbfv‡e hZ¸‡jv MwZi AwaKvix n‡Z cv‡i †mB msL¨v‡K H e¯‘i ¯^vaxbZvi gvÎv e‡j| ✅ mgxKiY: †Kvb wm‡÷‡gi ¯^vaxb GK cigvYyK AYyi msL¨v n n‡j ¯^vaxbZvi gvÎv n‡e 3n wKš‘ AYy¸‡jvi cvi¯úwiK Ae¯’vb r msL¨K mgxKiY w`‡q m¤úK©hy³ n‡j gvÎv msL¨v, n = 3n – r ✅ D`vniY: GK cvigvYweK M¨vm AYyi ¯^vaxbZvi gvÎv 3 •iwLK MwZi ¯^vaxbZvi gvÎv 3 Av`k© M¨v‡mi cÖwZwU AYyi ¯^vaxbZvi gvÎv 3 AveZ©biZ KYvi ¯^vaxbZvi gvÎv 5 wØ-cvigvYweK M¨vm (O2,N2, H2) AYyi ¯^vaxbZvi gvÎv 5 (3wU •iwLK MwZi Rb¨ Ges `ywU N~Y©b MwZi Rb¨) T na2 P

ASPECT PHYSICS cÖ_g cÎ Av`k© M¨vm I M¨v‡mi MwZZË¡ 375 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ✅ we‡kl Z_¨: M¨vm ¯^vaxbZvi gvÎv (Cp I Cv Gi AbycvZ) Mokw³ mgxKiY GK-cigvYyK M¨vm (He, Ne, Ar) 3 1.67 Mokw³ = 3 2 KT wØ- cigvYyK M¨vm (O2, N2, Cl2) 5 1.40 Mokw³ =5 2 KT wÎ- cigvYyK M¨vm (CO2, O3, CH4) 6 1.33 Mokw³ =6 2 KT ✅ kw³i mgwefvRb bxwZ: Zvcxq mvg¨ve¯’vq Av‡Q Ggb MZxq wm‡÷‡gi †gvU kw³ wewfbœ ¯^vaxbZvi gvÎvi wfZi w`‡q mgfv‡e ew›UZ nq Ges cÖ‡Z¨K ¯^vaxbZvi gvÎvwcQz kw³i cwigvY nq 1 2 KT ✅ cÖeZ©K: g¨v·I‡qj (1859) cÖ‡Z¨K AYyi Mo MwZkw³ = 3 2 KT cÖ‡Z¨K AYyi ¯^vaxbZvi gvÎvi †gvU kw³i cwigvY = 1 2 KT GK cigvYyK M¨v‡mi †¶‡Î kw³ = 3 2 KT wØ-cigvYyK M¨v‡mi †¶‡Î kw³ = 5 2 KT REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF JU QUESTION 01. wØ-cigvYyK M¨v‡mi MwZkw³i cwigvY KZ? [JU-A, Set-C. 20-21] A. 3/4 kT B. 3/2 kT C. 5/2kT D. 7/2 kT Avgiv Rvwb, f ¯^vaxbZv gvÎv wewkó cigvYyi MwZkw³= f 2 kT wØ-cigvYy M¨v‡mi ¯^vaxbZvi gvÎv, f = 2 3 – 1 = 5; wØ-cigvYyK M¨v‡mi MwZkw³ = 5 2 kT STEP 02 ANALYSIS OF CU QUESTION 01. GKwU wØcvigvYweK M¨v‡mi Rb¨ ¯^vaxbZvi gvÎv –––| [CU. 16-17] A. 3 B. 8 C. 5 D. 2 E. 4 Ans C 02. = 1.41 ‡Kvb M¨v‡mi †¶‡Î cÖ‡hvR¨? [CU. 06-07] A. O2 B. H2 C. N2 D. Cl2 E. me¸‡jv wØ-cigvYyK M¨v‡mi †¶‡Î = 1.41| 03. 27C ZvcgvÎvq GK †gvj wnwjqvg M¨v‡mi MwZkw³i cwigvb–[CU. 16-17] A. 3500 J B. 3741 J C. 3650 J D. 3845 J E. 3835 J M¨v‡mi MwZkw³, E = 3 2 m M RT = 3 2 1 8.314 300 = 3741J STEP 03 ANALYSIS OF DU-7 Clg QUESTION 01. GKwU AYyi ¯^vaxbZvi gvÎv f n‡j H AYy Øviv MwVZ Av`k© M¨v‡mi †gvU Af¨šÍixY kw³ KZ n‡e? [DU. 7Clg-A: 20-21] A. f 2 nRT B. 3f 2 nRT C. f 2 RT D. 3f 2 RT f ¯^vaxbZv gvÎvwewkó †Kv‡bv M¨v‡mi GKwU AYyi MwZkw³ = f 2 kT f ¯^vaxbZv gvÎvwewkó †Kv‡bv M¨v‡mi n †gvj msL¨K AYyi MwZkw³ = f 2 nNAkT = f 2 nRT [ †gv‡ji M¨vm aªæeK, R = NAk; †hLv‡b, NA = A¨v‡fv‡M‡Wªv msL¨v; k = †evëRg¨vb aªæeK] STEP 04 ANALYSIS OF GST QUESTION PART A Analysis of General University Question JnU 01. PV = aªæeK mgxKi‡Y wØcigvYyK M¨v‡mi ‡¶‡Î Gi gvb- [JnU. 15-16] A. 1.20 B. 1.40 C. 1.33 D. †KvbwUB bq GK cigvbyK M¨v‡mi ‡¶‡Î = 1.66 wØ-cigvbyK M¨v‡mi ‡¶‡Î = 1.40; wÎ-cigvbyK M¨v‡mi ‡¶‡Î = 1.33 IU 01. GKwU AveZ©YiZ KYvi ¯^vaxbZvi gvÎv- [IU-D, 19-20] A. 2 B. 3 C. 4 D. 5 AveZ©biZ I wØcvigvYweK KYvi ¯^vaxbZvi gvÎv 5 •iwLK MwZ‡Z I GKcvigvYweK KYvi ¯^vaxbZvi gvÎv 3 PART B Analysis of Science & Technology Question SUST 01. M¨v‡mi GKwU AYyi ¯^vaxbZvi gvÎv 6 n‡j kw³i mgwefvRb bxwZ Abymv‡i cÖwZ AYyi Mo kw³ KZ? [SUST. 18-19] A. 6 kT B. 3 kT C. 2 kT D. 3 2 kT E. 1 2 kT Ans B PSTU 01. eûcvigvYweK M¨v‡mi †¶‡Î ÔÕ Gi gvb KZ? [PSTU. 14-15] A. 1.33 B. 1.41 C. 1.67 D. 2.33 GK cigvbyK M¨v‡mi †¶‡Î = 1.66 wØ-cigvbyK M¨v‡mi †¶‡Î = 1.44; eûcigvbyK M¨v‡mi †¶‡Î = 1.33 STEP 05 ANALYSIS OF HSC BOARD QUESTION 01. Aw·‡Rb (O2) M¨v‡mi cÖwZ AYyi Mo MwZkw³ KZ? [iv.‡ev 2021] A. 3 2 RT B. 3 2 Kt C. 5 2 R D. 5 2 KT O2 M¨vm wØ-cvigvbweK M¨vm| myZivs Mo MwZkw³, = 5 2 KT 02. cÖwZwU Aw·‡Rb AYyi †gvU kw³- [iv. †ev. 2016] A. E = 3 2 KT B. E = 5 2 KT C. E = 2 3 KT D. E = 7 2 KT Ans A 03. †Kv‡bv M¨v‡mi AYy¸‡jvi Mo MwZkw³- [iv.†ev.2015; P.†ev. 2015; w`.†ev.2015] A. E¯ = 3 2 RT B. E¯ = 3 2 KT C. E¯ = 2 3 RT D. E¯ = 2 3 KT Ans B 04. CO2 M¨v‡mi Rb¨ Gi gvb KZ? [Kz. †ev. 2017] A. 1.66 B. 1.41 C. 1.33 D. 1.2 Ans C 05. hw` nvB‡MÖvwgUv‡ii wm³ I ï®‹ evj‡ei ZvcgvÎvi cv_©K¨ Kg cÖ`k©b K‡i Zvn‡j- [g.‡ev 2021] A. Av‡cÿwK Av`ª©Zv Kg B. Av‡cwÿK Av`ª©Zv †ewk C. wb¤œ wkwkiv¼ D. kix‡i Avivg AYyfe n‡e Ans B

376 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES Concept 6 m¤ú„³ Ges Am¤ú„³ ev‡®úi Z_¨vejx ✅ m¤ú„³ I Am¤ú„³ ev‡®úi g‡a¨ cv_©K¨: m¤ú„³ ev®ú Am¤ú„³ ev®ú 1. m¤ú„³ ev®ú Ave× ¯’v‡b •Zix Kiv hvq 2. m¤ú„³ ev®ú e‡qj I Pvj©‡mi m~Î †g‡b P‡j bv 3. ZvcgvÎv e„w× K‡i GKwU wbw`©ó cwigvY m¤ú„³ ev®ú‡K Am¤ú„³ ev‡®ú cwiYZ Kiv hvq 4. m¤ú„³ ev®ú Zi‡ji ms¯ú‡k© mvg¨ve¯’vq _vK‡Z cv‡i| 5. me©vwaK Pvc cÖ‡qvM K‡i| 1. Am¤ú„³ ev®ú Ave× ev †Lvjv †h †Kvb ¯’v‡b •Zix n‡Z cv‡i 2. Am¤ú„³ ev®ú e‡qj I Pvj©‡mi m~Î ‡g‡b P‡j 3. ZvcgvÎv Kwg‡q GKwU wbw`©ó cwigvb Am¤ú„³ ev®ú‡K m¤ú„³ ev‡®ú cwiYZ Kiv hvq 4. Am¤ú„³ ev®ú KL‡bv Zi‡ji ms¯ú‡k© mvg¨ve¯’vq _vK‡Z cv‡i bv 5. Am¤ú„³ ev®úPvc < m¤ú„³ ev®úPvc ◈ m¤ú„³ ev‡®úi •ewkó¨ g‡b ivLvi †KŠkj- k¤úv em‡K †g‡b P‡j bv k¤úv m¤ú„³ ev®ú em‡K e‡q‡ji m~Î †g‡b P‡j bv †g‡b P‡j bv ◈ †Kvb ev®ú e‡q‡ji m~Î gv‡b bv G e¨vcv‡i Avi Confused nIqv jvM‡e bv| ✅ m¤ú„³ ev®ú Pv‡ci Dci ZvcgvÎv, AvqZb I Zi‡ji cÖK…wZi cÖfve: ZvcgvÎv: ZvcgvÎv e„w× †c‡j m¤ú„³ ev®ú Pvc e„w× cvq Zi‡ji cÖK…wZ: Zi‡ji cÖK…wZi Dci m¤ú„³ ev®ú Pvc wbf©i K‡i| wewfbœ Zi‡ji Rb¨ m¤ú„³ ev®ú Pvc wfbœ wfbœ nq| AvqZ‡bi cÖfve: m¤ú„³ ev®úPvc AvqZ‡bi Dci wbf©i K‡i bv| ✅ µvwšÍ ZvcgvÎv: †h ZvcgvÎvi Dc‡i †Kvb M¨vm‡K †Kej gvÎ Pvc cÖ‡qv‡M Zi‡j cwiYZ Kiv hvq bv Zv‡K µvwšÍ ZvcgvÎv e‡j| ✅ ¯’vqx M¨vm: mvaviY ZvcgvÎvi †h mKj M¨vm‡K †Kej Pvc cÖ‡qv‡M Zi‡j cwiYZ Kiv hvq bv Zv‡K ¯’vqx M¨vm e‡j| ‡hgb: Aw·‡Rb, nvB‡Wªv‡Rb wnwjqvg BZ¨vw`| ✅ Av‡cw¶K Av`ª©Zv wbY©‡qi ¸iæZ¡: gvby‡li †gRvR, ¯^v¯’¨ Kg© D`¨g A‡bKvs‡k Av‡cw¶K Av`ª©Zvi Dci wbf©ikxj| wbivc` wegvb Pvjbvi †¶‡Î ✅ ev®ú I M¨v‡mi g‡a¨ cv_©K¨ ev®ú M¨vm 1. †Kvb M¨vmxq c`v‡_©i ZvcgvÎv µvwšÍ ZvcgvÎv A‡c¶v Kg n‡j Zv‡K ev®ú e‡j| 2. ev®ú‡K Pvc cÖ‡qvM Ki‡j Zi‡j cwiYZ Kiv hvq| 1. †Kvb c`v_© Gi µvwšÍ ZvcgvÎv A‡c¶v AwaK ZvcgvÎvq _vK‡j Zv‡K M¨vm e‡j| 2. M¨vm †K ïaygvÎ Pvc cÖ‡qv‡M Zi‡j cwiYZ Kiv hvq bv| ✅ M¨v‡mi AYy¸‡jv wbDU‡bi m~Î †g‡b P‡j ✅ f¨vbWviIqvj&m Gi g‡Z AwZwi³ Pvc M¨v‡mi Nb‡Z¡i e‡M©i mgvbycvwZK ev M¨v‡mi AvqZ‡bi e‡M©i e¨v¯ÍvbycvwZK| ✅ Zi‡ji mv›`ªZv hZ Kg nq KYv¸‡jvi MwZ ZZ e„w× cvq| ✅ ZvcgvÎv hZ †ekx KYv¸‡jvi MwZI ZZ e„w× cvq| ✅ ZvcgvÎv e„w×i mv‡_ mv‡_ †Møwmqv‡ii Drcv`K (G) Gi gvb K‡g| REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF DU QUESTION 01. cvwb, eid I Rjxq ev®ú †h ZvcgvÎvq GK m‡½ _vK‡Z cv‡i Zv n‡jv- [DU. 03-04; CoU. 13-14; RU. 18-19] A. 0K B. 273.16K C. 100K D. 4K •Îa we›`y‡Z cvwb, eid I Rjxq ev®ú GK m‡½ _vK‡Z cv‡i| •Îa we›`y n‡jv 0C ev 273.16K| 02. ‡Kvb e¨w³ ce©‡Zi P‚ovq cvwb dzUv‡Z PvB‡j cvwbi cvÎ‡K †h ZvcgvÎvq DËß Ki‡Z n‡e Zv- [DU. 09-10] A. higher than 100C B. lower than 100C C. to 100C D. cannot be determined Ans B STEP 02 ANALYSIS OF JU QUESTION 01. Aw·‡R‡bi msKU Pvc I ZvcgvÎv KZ? [JU. 12-13] A. 50 and 304.1K B. 50 and 254 K C. 73 and 249 K D. 13 and 304.1 K Ans B STEP 03 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. M¨vm I ev‡®úi g‡a¨ cv_©K¨ GB †h, [KU. 09-10] A. M¨vm‡K ïay Pvc cÖ‡qv‡M Zi‡j cwibZ Kiv hvq wKš‘ ev®ú‡K Kiv hvq bv| B. M¨v‡mi Zvc n«vm Ki‡j Zi‡j cwiYZ nq wKš‘ ev®ú Zi‡j cwiYZ nq bv| C. M¨vm‡K GKwU wbw`ó ZvcgvÎvi wb‡P †i‡L Pvc cÖ‡qvM Ki‡Z nq| D. ‡Kvb M¨vmxq c`v_© Gi µvwšÍ ZvcgvÎv A‡c¶v AwaK ZvcgvÎvq _vK‡j Zv‡K ev®ú e‡j| Ans C IU 01. †Kvb c`v_© Gi µvwšÍ ZvcgvÎv A‡c¶v AwaK ZvcgvÎvq _vK‡j Zv‡K ejv nq- [IU. 10-11] A. ev®ú B. Zij C. M¨vm D. ‡KvbwUB bq Ans C STEP 04 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. †h wU m¤ú„³ ev‡®úi ag© bq [MAT. 01-02] A. ZvcgvÎv e„w× Ki‡j wbw`©ó cwigvb m¤ú„³ ev®ú Am¤ú„³ ev‡®ú cwibZ nq| B. m¤ú„³ ev®ú †Lvjv I Ave× Dfq ¯’v‡b •Zwi Kiv nq| C. m¤ú„³ ev®ú Pvj©‡mi I e‡qj Gi m~Î †g‡b P‡j bv| D. m¤ú„³ ev®ú ¯^xq Zi‡ji mv‡_ mvg¨ve¯’vq Ae¯’vb K‡i| Ans B 02. ‡Kvb Dw³wU mwVK bq? [MAT. 01-02] A. N‡ii ZvcgvÎv e„w× Ki‡j N‡ii Av‡cw¶K Av`ª©Zv n«vm cv‡e| B. wkwkiv¼ 0 0C Gi bx‡P bvg‡Z cv‡i| C. evZv‡mi ZvcgvÎv 300C n‡Z K‡g 200C n‡j Av‡cw¶K Av`ª©Zv †e‡o hv‡e D. AvenvIqv c~e©vfv‡mi †ejvq Av‡cw¶K Av`ª©Zv AwaK ¸iæZ¡c~Y© | Ans B 03. wbw`©ó ZvcgvÎvq †Kvb Ave× ¯’v‡b me©vwaK †h cwigvb ev®ú avib Ki‡Z cv‡i Zv A‡c¶v Kg ev®ú _vK‡j G‡K e‡j? [MAT. 00-01] A. m¤ú„³ ev®ú Pvc B. Am¤ú„³ ev®ú C. Am¤ú„³ ev®ú Pvc D. m¤ú„³ ev®ú Ans B

ASPECT PHYSICS cÖ_g cÎ Av`k© M¨vm I M¨v‡mi MwZZË¡ 377 ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES STEP 05 ANALYSIS OF HSC BOARD QUESTION 01. m¤ú„³ ev‡®úi †ÿ‡Î †KvbwU mwVK? [Xv.‡ev 2021] A. e‡qj Gi m~Î †g‡b P‡j B. Pvj©‡mi m~Î †g‡b P‡j C. e‡qj Ges Pvj©‡mi m~Î gv‡b bv D. GKwU e× ¯’v‡b •Zwi Kiv hvq bv Ans C 02. Am¤ú„³ ev®ú †g‡b P‡j- [Xv. †ev. 2016] A. e‡q‡ji m~Î B. Pvj©‡mi m~Î C. Pv‡ci m~Î D. e‡qj I Pvj©‡mi m~Î Ans D 03. †Kv‡bv ¯’v‡bi Am¤ú„³ ev®úPvc f Ges m¤ú„³ ev®úPvc F n‡j †KvbwU mwVK? [iv.‡ev 2021] A. f F B. f F C. f F D. f F R = f F × 100% myZivs f < F 04. †Kv‡bv ¯’v‡bi Rjxq ev®úPvc m¤ú‡K© ejv hvq- [iv.‡ev 2021] i. m¤ú„³ Rjxq ev®ú me©vwaK Pvc †`q ii. Am¤ú„³ Rjxq ev®ú e‡q‡ji m~Î †g‡b P‡j iii. evqy‡Z Rjxq ev®ú Kg‡j evqyi NbZ¡ e„w× cvq wb‡Pi †KvbwU mwVK? A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans D 05. evqy‡Z Rjxq ev‡®úi cwigvY K‡g †M‡j- [w`.‡ev 2021] A. evqyi NbZ¡ K‡g B. evqyi NbZ¡ ev‡o C. Rjxq ev®úPvc ev‡o D. Av‡cwÿK Av`ª©Zv ev‡o Ans B 06. m¤ú„³ ev‡®úi †ÿ‡ÎÑ [w`.‡ev. 2019] i. P1 n1T2 = P2 n2T2 ii. n P = aªæeK, hLb T w¯’i _v‡K iii. GwU e‡qj I Pvj©‡mi m~Î †g‡b P‡j wb‡Pi †KvbwU mwVKÑ A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans A 07. Rjxq ev®ú m¤ú‡K© ejv hvq- [w`.‡ev. 2016] A. m¤ú„³ Rjxq ev®ú me©vwaK Pvc †`q B. m¤ú„³ Rjxq ev®ú Pvj©‡mi m~Î †g‡b P‡j C. †KvbwUB bq D. me¸‡jv mwVK Ans A 08. evqygÛ‡ji Rjxq ev®ú Nbxfe‡bi Rb¨ wb‡Pi †KvbwU msNwUZ nq bv? [h. †ev. 2015] A. wkwki B. Kzqvkv C. So D. e„wó Ans C 09. evqyi Av‡cwÿK Av`ª©Zv Kg n‡j ev®úvqb n‡eÑ [wm. †ev. 2015] A. axi MwZ‡Z B. `ªyZ MwZ‡Z C. Av‡Mi gZB D. AwZaxi MwZ‡Z Ans B 10. †gNgy³ w`‡b `ycy‡ii Av‡MB wkwki wZ‡ivwnZ nq †Kb? [e.‡ev. 2019] A. w`‡bi Av‡jvi ZxeªZv e„w× cvq B. Av‡cwÿK Av`©ªZv e„w× cvq C. ZvcgvÎv e„w×‡Z evqy Am¤ú„³ nq D. ev®úvq‡bi nvi n«vm cvq Ans C 11. w¯’wZ¯’vcKZv m¤ú‡K© ejv nq, BnvÑ [e.‡ev. 2019] i. ZvcgvÎvi mv‡_ cwieZ©b nq ii. ‡fRv‡ji Dcw¯’wZ‡Z cwieZ©b nq iii. c`v‡_©i AvK…wZi Dci wbf©i K‡i wb‡Pi †KvbwU mwVKÑ A. i I ii B. ii I iii C. i I iii D. i, ii I iii Ans A 12. Am¤ú„³ ev‡®úi †ÿ‡Î- [mKj †evW© 2018] A. Ave× ev †Lvjv †h †Kv‡bv ¯’v‡b GwU •Zwi Kiv hvq B. GwU e‡qj Ges Pvj©‡mi m~Î †g‡b P‡j C. ZvcgvÎv evwo‡q GwU‡K m¤ú„³ ev‡®ú cwiYZ Kiv hvq D. A I B DfqB Ans D Concept 7 Av`ª©Zv Ges wkwkivsK msµvšÍ Z_¨vejx ✅ c`v_© weÁv‡bi †h kvLvq Rjxq ev‡®úi Pv‡ci cwigvc Kiv nq Zv‡K Av`ª©ZvwgwZ ev nvB‡MÖvwgwUª e‡j| ✅ Av`©ªZv: †Kvb ¯’v‡bi evZv‡mi Av`ª©Zv wbf©i K‡i H ¯’v‡biÑ K. cvwbi Dr‡mi Dcw¯’wZ L. A¶vsk M. mgy`ª c„ô †_‡K D”PZvi Dci ✅ wkwkivsK: †h ZvcgvÎvq GKwU wbw`©ó ¯’v‡bi evqy Zvi wfZ‡ii Rjxq ev®ú Øviv m¤ú„³ nq A_ev †h ZvcgvÎvq wkwki Rg‡Z ev A`„k¨ n‡Z ïiæ K‡i Zv‡K H evqyi wkwkivsK e‡j| ✅ wkwkivsK I Av‡cw¶K Av`ª©Zv wbY©q: Av‡cw¶K Av`©ªZv wbY©q: evqyi Av`ª©Zv wbY©‡qi Rb¨ †h hš¿ e¨eüZ nq Zv‡K Av`©ªZv gvb hš¿ ev nvB‡MÖvwgUvi e‡j| Av`©ªZvgvb hš¿¸‡jv‡K Pvi †kªYx‡Z fvM Kiv n‡q‡Q| wkwkivsK nvB‡MÖvwgUvi (Dew point Hygrometer) wm³ I ï®‹ evj¦ nvB‡MÖvwgUvi (Wet & dry Hygrometer) ivmvqwbK nvB‡MÖvwgUvi (Chemical Hygrometer) †Kk nvB‡MÖvwgUvi (Hair Hygrometer) ✅ Hygrometer †kÖYxwefvM g‡b ivLvi †KŠkj- †Kki †K †Kk nvB‡MÖvwgUvi k wkwkivsK nvB‡MÖvwgUvi/ wm³ I ï®‹ evj¦ nvB‡MÖvwgUvi i ivmvqwbK nvB‡MÖvwgUvi wkwkivsK wbY©q: †Møwmqv‡ii mgxKi‡Yi mvnv‡h¨ evqyi wkwkivsK Rvbv hvq- = 1 – G(1 - 2) GLv‡b, G = ï®‹ ev‡j¦i ZvcgvÎvq †Møwmqv‡ii ivwk; 0C = evqyi wkwkivsK; 1 0C = ï®‹ ev‡j¦i ZvcgvÎv; 2 0C = Av`©ª ev‡j¦i ZvcgvÎv ✅ AvenvIqvi c~e©vfvm: wm³ I ï®‹ evj¦ nvB‡MÖvwgUvi cvV †_‡K AvenvIqvi c~e©vfvm m¤ú‡K© Rvbv hvq : _v‡g©vwgUviØ‡qi cv‡Vi e¨eavb: †ekx n‡j eyS‡Z n‡e evqy Z_v AvenvIqv ï®‹| Kg n‡j eyS‡Z n‡e evqy Av`ª© A_©vr AvenvIqv wm³ ax‡i ax‡i Kg‡Z _vK‡j eyS‡Z n‡e e„wói m¤¢vebv Av‡Q nVvr K‡g †M‡j eyS‡Z n‡e So n‡Z cv‡i| ✅ Av`ª©Zv wgwZ msµvšÍ K‡qKwU NUbv : el©vKvj A‡c¶v kxZKv‡j †fRv Kvco `ªæZ ïKvq| kxZKv‡j †Vuv‡U wMømvwib jvMv‡bv nq, KviY Zv bv n‡j †VuvU †d‡U hvq GKB ZvcgvÎvq XvKv n‡Z K·evRv‡i A¯^w¯Í †eva nq| AvKvk †gNjv _vK‡j wkwki c‡o bv| `ycy‡ii Av‡MB wkwki wZ‡ivwnZ nq| wfRv Kvc‡o evj¦ Rov‡j Gi ZvcgvÎv K‡g hvq| Mi‡gi w`‡b KzKzi wRnŸv †ei K‡i †`Šovq| Ng©v³ †`‡n cvLvi evZvm jvM‡j Avivg Abyf~Z nq| wkwki Kzqvkv ‡gN e„wó wkjv

378 An Exclusive Parallel Text Book of Physics ASPECT PHYSICS ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ASPECT SERIES ✅ evqygÛ‡j ev®ú Nbxf~Z nIqvi dj: wkwki (Dew) Kzqvkv (fog): evqy cÖevn bv _vK‡j †gNnxb iv‡Z Kyqvkv †ekx c‡o| Kzqvkv `yB cÖKvi nvjKv Kzqvkv (moist) I Nb Kzqvkv (Dense fog) †gN: DaŸ©vKv‡ki KzqvkvB †gN e„wó wkjv (Sleet): †gN hLb Dc‡i DV‡Z _v‡K ZLb ZvcgvÎv `ªæZ Kg‡Z _v‡K Ges cvwbi wngvsK 0 0C/ -20 0C Gi wb‡P †b‡g hvq| Rjxq ev®ú `ªæZ Nbxf~Z n‡q wkjvq cwiYZ nq e‡j Gi wfZi wKQz evqy Ave× _vK‡Z cv‡i| REAL TEST ANALYSIS OF PREVIOUS YEAR QUESTIONS STEP 01 ANALYSIS OF JU QUESTION 01. GK NbwgUvi AvqZ‡bi evqy‡Z †h cwigvY Rjxq ev®ú _v‡K, Zv evqyi [JU. 10-11] A. Av`ª©Zv B. Av‡cw¶K Av`ª©Zv C. cig Av`ª©Zv D. ‡KvbwUB bq Ans C STEP 02 ANALYSIS OF RU QUESTION 01. †KvbwU wg_¨v? [RU. Astrazeneca, Set-1. 20-21] A. Av`ª©ZvgvcK h‡š¿ `yB _v‡gv©wgUv‡ii cv‡Vi cv_©K¨ n«vm †c‡j So n‡Z cv‡i B. ce©‡Zi P~ovi evqyi Pvc Kg, cvwbi ùzUbv¼ Kg, ZvB ivbœv Kiv mnR C. el©vi w`b A‡cÿv kxjKv‡j †fRv Kvco ZvovZvwo ïKvq D. evqyi cig Av`ª©Zv 102 kg m3 Øviv eySv hvq †h, GK NbwgUvi AvqZ‡bi evqy‡Z 10 g Rjxq ev®ú we`¨gvb ce©‡Zi P‚ovq evqyi Pvc Kg _vKvq cvwbi ùzUbv¼ Kg nq| A_©vr KgZvcgvÎvq cvwb dzU‡Z Avi¤¢ K‡i| hv ivbœv Kivi Rb¨ Dchy³ ZvcgvÎv bv| d‡j ce©‡Zi P‚ovq ivbœv Kiv KwVb| 02. ‡h ZvcgvÎvq evqygÛ‡ji †Kvb wbw`©ó AvqZ‡bi evqy Gi g‡a¨ Aew¯’Z Rjxq ev®ú Øviv m¤ú„³ nq Zv‡K e‡j- [RU. 06-07] A. wkwkiv¼ B. cig Av`©ªZv C. Av‡cw¶K Av`ª©Zv D. Av`ª©ZvwgwZ Ans A STEP 03 ANALYSIS OF CU QUESTION 01. wkwkiv¼ ej‡Z Avgiv Kx eywS? [CU-A, 19-20; wm.‡ev. 2021, 19, iv.‡ev. 2017] A. Zvc B. ZvcgvÎv C. Av`ª©Zv D. Av‡cwÿK Av`ª©Zv †h ZvcgvÎvq wkwki Rg‡Z ïiæ K‡i Zv‡K wkwkiv¼ e‡j| 02. ‡Kvb wbw`©ó AvqZ‡bi evqy‡Z Dcw¯’Z Rjxq ev‡®úi cwigvY‡K wK eySvq? [CU. 09-10] A. Av`ª©Zv B. cig Av`ª©Zv C. Av‡cw¶K Av`ª©Zv D. wkwkivsK Ans B STEP 04 ANALYSIS OF GST QUESTION PART A Analysis of General University Question KU 01. nvB‡MÖvwgUv‡ii _v‡g©vwgUvi Ø‡qi cv‡Vi e¨eavb ax‡i ax‡i Kg‡Z _vK‡j eyS‡Z n‡e- [KU. 08-09] A. e„wói m¤¢vebv Av‡Q B. AvenvIqv ï¯‹ C. AvenvIqv Av`ª© D. So n‡Z cv‡i Ans A IU 01. wm³ I ï®‹ evj¦ _v‡gv©wgUv‡ii cv‡Vi e¨eavb nVvr K‡g hvIqvi A_©- [IU. 12-13] A.So n‡Z cv‡i B.e„wó n‡Z cv‡i C.AvenvIqv ï®‹ D.evqy Av`ª© Ans A BRUR 01. wkwkiv‡¼ †Kv‡bv ¯’v‡bi m¤ú„³ Rjxqev‡®úi Pvc, †Kv‡bv wbw`©ó ZvcgvÎvq H ¯’v‡bi Am¤ú„³ Rjxq ev‡®úi Pv‡ci- [BRUR-F, Set-2, 19-20] A. †ewk B. mgvb C. Kg D. mgvb ev †ewk wkwkiv‡¼ †Kv‡bv ¯’v‡bi m¤ú„³ Rjxqev‡®úi Pvc, †Kv‡bv wbw`©ó ZvcgvÎvq H ¯’v‡bi Am¤ú„³ Rjxq ev‡®úi Pv‡ci mgvb| 02. Av‡cw¶K Av`ª©Zv n‡jv- [BRU. 13-14] A. R=F/f B. R= f/F100% C. R=t/f D. R=f/t Ans B PART B Analysis of Science & Technology Question PSTU 01. Av‡cw¶K Av`ª©Zv 100% n‡j wkwkiv¼ evqyi ZvcgvÎv- [PSTU. 15-16] A. A‡a©K n‡e B. wØ¸b n‡e C. mgvb n‡e D. Kg n‡e Ans C STEP 05 ANALYSIS OF MEDICAL & DENTAL QUESTION MAT 01. wkwkiv¼ ej‡Z wK eySvq? [MAT. 2020-21] A. Av`©ªZv B. Av‡cwÿK Av`©ªZv C. Zvc D. ZvcgvÎv ZvcgvÎv: wkwkiv¼ ej‡Z ZvcgvÎv eySvq| mwVK Ackb ev‡` evwK Ackb¸‡jvi we‡kølY: Av`©ªZv: †Kvb ¯’v‡bi evZv‡mi Av`ª©Zv wbf©i K‡i H ¯’v‡biÑ cvwbi Dr‡mi Dcw¯’wZ A¶vsk mgy`ª c„ô †_‡K D”PZvi Dci| cig Av`ª©Zv: GKK AvqZ‡bi evqy‡Z †h cwigvY Rjxq ev®ú Dcw¯’Z _v‡K Zv‡K H ¯’v‡bi cig Av`ª©Zv e‡j| Gi GKK : Kgm2 DAT 01. kir Kv‡j †Kvb mg‡q wkwki c‡o? [DAT. 18-19] A. †gNjv iv‡Z B. Agvem¨vi iv‡Z C. †gNgy³ iv‡Z D. cywY©gvi iv‡Z Ans C STEP 06 ANALYSIS OF HSC BOARD QUESTION 01. Av`ª©ZvgvcK h‡š¿ `yB _v‡g©vwgUv‡ii cv‡Îi cv_©K¨Ñ [iv.‡ev. 2019] i. nVvr n«vm †c‡j So n‡Z cv‡i ii. ax‡i ax‡i Kg‡j e„wó n‡Z cv‡i iii. Lye Kg n‡j AvenvIqv ï®‹ nq wb‡Pi †KvbwU mwVKÑ A. i I ii B. i I iii C. ii I iii D. i, ii I iii Ans A 02. evqy‡Z Rjxq ev‡®úi cwigvY †e‡o †M‡j- [iv. †ev. 2016] A. evqyi NbZ¡ K‡g B. evqyi Pvc K‡g C. Rjxq ev®úPvc K‡g D. A I B DfqB Ans D 03. evqyi Av‡cwÿK Av`ª©Zv Kg n‡j ev®úvqb n‡e- [w`. †ev. 2015] A. axi MwZ‡Z B. `ªæZMwZ‡Z C. Av‡Mi g‡ZvB D. AwZ axi MwZ‡Z Ans B 04. wkwki n‡”Q [h. †ev. 2017] A. cvwbi †duvUv B. ZvcgvÎv C. Zvc D. Av`ª©Zv Ans A 05. wm³ I ï®‹ evj¦ Av`ª©ZvgvcK h‡š¿i `yB _v‡g©vwgUv‡ii ZvcgvÎvi cv_©K¨ nVvr †e‡o †M‡j eySv hvq H ¯’v‡bÑ [h. †ev. 2015] i. Av‡cwÿK Av`ª©Zv e„w× †c‡q‡Q ii. Av‡cwÿK Av`ª©Zv n«vm †c‡q‡Q iii. wfRv Kvco ZvovZvwo kyKv‡e wb‡Pi †KvbwU mwVK? A. i B. i I ii C. ii I iii D. i, ii I iii Ans C

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