30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

43
1. !!" # $
%&






+ ก 0 V & $ /7 -( * +ก ( I & $ $ ก/7

b e ′
c
V b e ′ = I r ก (1.10) -(
b b e ′
I = g I r
C m b b e ′
β
r b e ′ = o ' ก I = g I r -(
m b b e ′
C
g m
g I β
m b o
I c = = I β (1.13)
b o
g
m
I (1.14)
- ก ก (1.12) = (1.13) I c = g V = β o b
m b e ′

* + 0, $9 ก +'/ ก ( g V + ก - ,, $ $!&! '(
m b e ′

'&'tก&! -( +' ก / $ $!&! ! ,,&, -( +' ก / '&'tก&!

1.4.4.5 3
Nก
(C b c ′ ′′ ′ )


-&, '&'tก&! & . - ))2 (+ / &, ก0,/ '&'tก-



&! + - ก 8 / ' %$ &! " C ก' & ก0,C

b c ′
ob

1.4.4.6 3


(C b e ′ ′′ ′ )



-&, $ $!&! & . - ))2 (+ / &, ก0,/ $ $!&! %7
( - ก/ ' 2 / ' 0
1.4.4.6.1 , F '(C ( - ก ก
β
ob

g m
C b e ′ + C b c ′ = ; C b c ′ ≅ C (1.15)
ob
π
2 F β o
β
1.4.4.6.2 , F '(C ( - ก ก
T ob
g m
C b e ′ + C b c ′ = ;C b c ′ ≅ C
ob
π
2 F
T
g m
C b e ′ = − C (1.16)
ob
π
2 F T



1.9 %$ &! !0 + 7 C ob = 0.65 pF,F = 6.5 GHz,T = 25 C,I C (dc ) = 2 mA;
T
A
- ( C
b e ′
I C ( ) I C ( )
c
c
d
d
9 + - ก ก (1.9) g m = =
V T ( B ) q
k T
" I C (dc ) = 2 mA
ก

ก
ก

44
1. !!" # $
%&







×
I C (dc ) 2 10 − 3
g = = = 77.821 mS
m
×
×
25.7 10 − 3 25.7 10 − 3
g m
- ก ก (1.16) C b e ′ = − C
ob
π
2 F
T
×
77.821 10 − 3 − 12 1.256 pF
×
C b e ′ = 9 − 0.65 10 =
×
×
2×3.14 6.5 10

C b e ′ ′′ ′ = == = 1.256 pF

1.4.4.7
/
Nก
(r
)
b c ′ ′′ ′

! &, '&'tก&! & . ! W (+ / &,


$
ก0,/ '&'tก&! " ก! %$ &! $ %$'$ ! ก & - กก (
I CBO ก '( $ " &X ( ก0, ก ! % / C -( ! * ก
b c ′

r &
- ก 0 ! / ก0 '( $ r
b c ′
b c ′

1.4.4.8
/ Nก


(r

ce )
$

! '&'tก&! $!&! & . ! W (+





/ '&'tก&! ก0,/ $ $!&! " ก!$ ก & - ก ก ( I CEO ก " &X (!
ก0,"+' 50 Ω +
75 Ω -7 '( $ r
ce

-


ก %$ &! ! * 7 7 0 , $ก0 ก ก ก* + 0

$!&! '( $
$
V ! &ก$ 0 V CBO &, '( &ก$ 0 V CEO
CC
ก ( I ! * ก 0.5I C (MAX)
C
ก ! , -(! &'
ก %$ &! F 6 &
+

T

H + β -(! 8''0 j ก ! ก '(&'
ก C ! *
FE F ob
$
ก ( $&! / ,,-* ' 3, - / %$ &! -* & . -(!

, F H '(C
,
ob
FE
T

1.5 )




%$ &! ))2 +
& ก :&)!; &)! * 0

ก &-&)! (JFET) '( ' 0 &)! (Depletion MOSFET) 0 0 * :&)!; + 7 &-&)!
ก

ก
ก

45
1. !!" # $
%&






'( ' 0 &)! &)!กt& & ก0 ก0, %$ &! -(! , '0ก1 ( ))2 '(

$&! ก ก


1.5.1
! ก %
!
%'

0 , $ก0 & . &)! " &ก$ & +

+W $" , 25 C 0 ! 1.13


! 1.13 0 , $ก0 / &)!


0 , $ก0 +W $" , 25 C

$&! 05'0ก1 +
0 &, ก &ก!% (Gate-Source Breakdown Voltage) BV − 30 V
GSS
ก ( &ก! + (Forward Gate Current) I 10 mA
GF
ก 5& ก* '0 & . 0 + P 300 mW
D
+W $ ! / ( * T −65 7 +160 C
j
$ 0 +W $ ( T −65 7 +160 C
stg
+ &+! !0 &'/ ! & . ก!0 ก j$,

)
1.5.1.1 % ก% ก
)
(BV GSS
0

&, ก &ก!% & . 0 ก'0, (+ / &ก! (G)
ก0,/ % (S) / ( / & (D) '0 - ก0,/ % 0 1.36





Q 1 Q 2
I GSS I GSS







1.36 0 BV GSS / &)!


- ก! 1.13 BV = 30 V− - ก 1.36 ก. 0 V /0 ',!
GSS GG

8 R &/ / &ก! '(/0 , ก! / % / ( / & '0 - ก0,/ % & . ก , ก'0,
G
ก ( I +' - ก 1.36 /. 0 V -( /0 ! ก0 /
GG
GSS
ก &)! $ ก* + 0 V < BV
DD GSS
ก

ก
ก

46
1. !!" # $
%&






)
1.5.1.2 ก
ก
-. / (I GF
ก ( &ก! + & . ก ( +' (+ / &ก!ก0,/ % &
0,

, + '(/ & ' 0 1.37


- ก! 1.13 I GF = 10 mA - ก 1.37 ก. 0 V /0 , ก!
GG
8 R &/ / &ก! '(/0 ',! &/ / % / ( / & ' ก ( I +' -
G
GF
1.37 /. 0 V -( /0 ! ก0 /
GG


Q 1 Q 2






1.37 ก ( I / &)!
GF

ก " ก! &)! -( , ก'0, (+ / &ก! ก0,/ % !
$

! ก , + + ก ( I GF ≤ 10 mA
1.5.1.3 ก
!:
ก+ - / . %
;
*
ก 5& ก* '0 & . 0 + & . ก* '0 5& / &)!


& & ก0,/ %$ &! - ก! 1.13 P = 350 mW ( - ก ก
D

P = I V (1.17)
D
D DS

=
=

1.10 &)! P = 350 mW,T = 25 C, BV GSS = − 25 V,V − 3 V, I DSS 30 mA;!

D
P
A
; '(" & +
ก W ! P D = 250 mW,V DD = 20 V,V DS = 0.5V DD
9 + - ก ก (1.17) P = I V
D
D DS
V = 0.5V
DS DD
=
×
V = 0.5 20 10 V
DS
×
P 250 10 − 3
I = D = = 25 mA
D
V 10
DS
20 V;
=

W ! P D = 250 mW ! I == = 25 mA,V DS = = = = 10 V,V DD = = = =
D
1.5.1.4 .6!
' +
+W $ ! / ( * &
- ก" / &)! (+ / & ก0,
0

/ % ! 0 T = T - ก! 1.13 T = − 65 C 7 160 C
+


j stg J
ก

ก
ก

47
1. !!" # $
%&






1.5.1.5
.6!



& & ก0 ก0, %$ &! - ก! 1.13 T stg = − 65 C 7 160 C +
/
1.5.2 ก4 '
1.5.2.1
/ /
5


- ก! 1.14 R θ JC = 125 C W
1.5.2.2
/ /
5 .6! &%



& & ก0 ก0, %$ &! - ก! 1.14 R θ JA = 357 C W
! 1.14 '0ก1 ( / &)!



'0ก1 ( +W $" , 25 C

$&! 05'0ก1 +
7
! ! !0 0 R 125 C W
θ
JC
! ! +W $" , R 357 C W
7
θ
JA
+ &+! !0 &'/ ! & . ก!0 ก j$,
1.5.3 ก4 '

1.5.3.1 % ก% ก
)
& & ก0,/ 1.5.1.1


! 1.15 '0ก1 ( ))2 / &)!


'0ก1 ( ))2 +W $" , 25 C

'0ก1 ( &
/ , 05'0ก1 ! * !0 +


0 &, ก &ก!%
I = − 1 V, V 0; BV − 30 − 36 - V
=
(Gate-Source Breakdown Voltage) G DS GSS
−
V = 20 V, V = 0, -
DS
GS
ก ( &ก!ก'0, T = 25 C; − 2 − 100 pA

A
(Gate Reverse Current) V = 0 V, V = 0, I GSS - 4 100
−
GS
DS

T =150 C; − − nA
A
0 &ก!% 0! ) =15 V, I =1 nA; - 3 6 V
(Gate-Source Cutoff Voltage) V DS D V GS (off ) − −
ก ( $ !0 & % =15 V, V = 0; 5 10 15
(D-S Saturation Current) V DS GS I DSS mA
ก ( &ก!/ ( * =10 V, I =1 mA; I - -
(Gate Operating Current) V DS D G 20− pA
ก

ก
ก

48
1. !!" # $
%&






! 1.15 (! )


'0ก1 ( &
/ , 05'0ก1 ! * !0 +

ก ( & 0! ) = 6 V; - -
(Drain Cutoff Current) V DS = 10 V, V GS − I D (off ) 2 pA
! & % = 0, I =1 mA; - 150 - Ω

(Drain-Source On-Resistance) V GS D r DS (ON)
- &/ V DS =10 V, V GS = 0, C 2.2 3.8
(Input Capacitance) f = 1 MHz; iss - pF
- " ก'0, V DS =10 V, V GS = 0, C - 1 2.1
(Reverse Transfer Capacitance) f = 1 MHz; rss pF
0ก ! %

(Trans conductance) V DS =10 V, V GS = 0, g , g 4.5 6 7.5 mS
f = 1 kHz; m fs
( PW ≤300 µs duty cycle ≤3%)
0ก ! % V DS =15 V, V GS = 0, , g - 4 -

(Trans conductance) f = 400 MHz; g m fs mS

)}ก&ก (Noise Figure) NF - 1.7 -
% & & &ก V DS =15 V, I = 5 mA, dB
D
Ω
R =1 k , f = 400 MHz; G - - 10
G
Common Source Power Gain PS
+ &+! !0 &'/ ! & . ก!0 ก j$,

1.5.3.2 ก
ก
ก (I )
GSS
ก ( &ก!ก'0, & . ก ( ))2 +'8 / &ก!ก0,/ % ,,
0
, ก'0, '(/ & '0 - ก0,/ % 1.38

- ก! 1.15 I = − 2 pA- ก 1.38 ก. 0 V /0 ',! 8
GSS GG
R &/ / &ก! '(/0 , ก! / % / ( / & '0 - ก0,/ % & . ก , ก'0, -(
G

ก ( I +' - ก 1.38 /. 0 V -( /0 ! ก0 /
GG
GSS
ก & & ก0,/ 1.5.1.1





Q 1 Q 2







1.38 ก ( I / &)!
GSS
ก

ก
ก

49
1. !!" # $
%&







1.5.3.3 % ก
)

(V GS (off ) ,V P )

0
&ก!% 0! ) & . ก'0, 2 +/ &ก! ก0,/ %
0


* +ก ( & & . 9 + & ก ก : 0 $ ); (Pinch off Voltage;V
)
P
t 0 & . ', &-&)! ,,
&-&)! ,, & (N-CH) -( V GS (off )
& . , ก 0 1.39
(P-CH) -( 0 V
GS (off )
3 V & - ก& . &)! ,, &
t

- ก! 1.15 V −
GS (off )
0 1 nA
- ก 1.39 ก. 0, V + V = − 3 V -( * + I =
GG GS D
0 3 V (
- ก 1.39 /. & & ก0, 1.39 ก. ! V GS (off )
& . , ก)

ก &)! 0 V GS (off ) -(! ! * ก 0 BV GSS $X( 0


-( * +&)! * & +

R D R D
I D= 1 nA I D= 1 nA
N-CH D P-CH D
R G R G
G G
Q Q
1 2
S V = 15 V S V DS = − 15 V
V = − 3 V DS V DD V = 3 V V DD
P
P
V GG
V GG

0

1.39 0 V + V / &)!
GS (off ) P
1.5.3.4 ก

% )
(I D SS )
ก ( $ !0 & % & . ก ( & ก +'8 / & ก0,

/ % / ( / &ก!'0 - ก0,/ % 0 1.40

R D R D

N-CH D I DSS =10 mA P-CH D I DSS =10 mA
G G Q
Q 1 2
S V DS = 15 V V DD S V DS = 15 V V DD





1.40 ก ( I / &)!
DSS


- ก! 1.15 I D SS = 10 mA

ก

ก
ก

50
1. !!" # $
%&






- ก 1.40 ก. 0 V ! ,, , ก'0, + ก / & ก0,
DD
/ % / &ก!'0 - ก0,/ % -( * + ก ( +'8 / & ก0,/ % $ ก

; 1.40 /. & & ก0 ก0, 1.40 ก. ! 0 V /0 ! ก0

-7 & ก :ก ( I D SS DD
/
$
ก ก ก ,, ก* + + I = 0.5I DSS
D
1.5.3.5 ก
ก
' + (I
)
G
ก ( &ก!/ ( * & . ก ( +'8 / &ก!ก0,/ % / ( &)!
* ก!$ ก ( I ก -( ก ( I ก ( R ! (+ / &ก!
G G GG
ก0,/ %

- ก! 1.15 I = − 20 pA ก &)! '( $
G
1.5.3.6 ก
%
(I D (off ) )
ก ( & 0! ) & . ก ( +'8 / & ก0,/ % / ( /

0 ก
&ก! '(/ % 0, V " ก!$ก ( I
GS (off ) D (off )
- ก! 1.15 I = 2 pA ก &)! '( $
D (off )
15.3.7
/ % )
(r DS (ON) )
! & % & . ! (+ / & ก0,/ %

( - ก ก
/ ( / &ก!'0 - ก0,/ % ! r
DS (ON)
V DS
r DS (ON) =
I D
- ก! 1.15 r DS (ON) = 150 Ω

ก &)!& . $! ! , $ ก ( I + !' & '
D
1.5.3.8 3 %/ '/ (C
)
iss


- &/ & . - ))2 (+ / &ก! ก0,/ % / ( / &
ก0,/ % 0, 0 0 V +
10 V 0 1.41




R S
1 MΩ
Q 1
C V DS (0,10 V)
V GS iss
V GG
−
0-( 20 V)

1.41 C / &)!
iss

ก

ก
ก

51
1. !!" # $
%&







- ก! 1.15 C iss = 2.2 pF,V DS = 10 V,V GS = 0;
- ก 1.42 '(& 0 :-

− & ก ) A C / ( / & ก0,/ % 0, 0 0 V
iss
" 3.8 pF '(! * 1.3 pF " C -( 8ก80 ก0, 0 V
iss GS
− & ก ) B C / ( / & ก0,/ % 0, 0 10 V
iss
" 2.2 pF '(! * 0.8 pF " C -( 8ก80 ก0, 0 V ก ก ,, -
GS
iss
&'
ก C ! ก0, V / &)! -
0
iss GS
5
F = 1 MHz = 2.2 pF,V GS = 0,V DS = 10 V;

4
-Input Capacitance (pF) (pF) 3 2 V DS = 0
C
iss





C iss C iss - 1 V DS = 10 V



0
−
−
0 − 4 − 8 − 12 16 20
V GS -Gate-SourceVoltage (V)
0
1.42 0 0 j (+ C ก0, V (2N4416A, 2006: 5)
iss GS

1.5.3.9 3 & ก (C )
rss
- " ก'0, & . - ))2 (+ / & ก0,/ &ก!/ (


/ & ก0,/ % 0, 0 0 V + 10 V 0 1.43


D
R S JFET
1 MΩ C rss
G
Q 1
V DS (0,10 V)
V GS
V GG S
−
0-( 20 V)

1.43 C / &)!
rss

- ก! 1.15 C rss = 0.56 pF " , V DS = 10 V (%7 & . ก
'0 - / & ก0,/ % )



ก

ก
ก

52
1. !!" # $
%&







C rss ≈ 2.1 pF,V GS = 0,V DS = 0;
2.4
F = 1 MHz
C ≈ 1.0 pF,V = 0,V = 10 V;
1.8 rss GS DS
V DS = 0
1.2


0.6 V DS = 10 V

0
−
0 − 4 − 8 − 12 16 − 20
V GS -Gate-SourceVoltage (V)
1.44 0 0 j (+ C ก0, V
0
GS
rss
- ก 1.44 '(& 0 :-

− & ก ) V DS = 0 + 7 / & ก0,/ % 0, 0 0 V


C rss ≈ 2.1 pF,V GS = 0,V DS = 0;
− & ก ) = 10 V + 7 / & ก0,/ % 0, 0
V
DS
10 V;
10 V C rss ≈ 1 pF,V GS = 0,V DS =

ก &)! ก ก ,, V = 0.5V &
V = 20 V -(
DS DD DD
V DS = 10 V 0 0 -7 - กก )& C ( 0.75-1 pF
rss
1.5.3.10
% ก
) (g
)
m
0ก ! % & . 0! (+ ก ( & !
0
V & . g - * / &)! ( g ก ( ! ) ก' & ก0, g 1 kHz
GS m m m
ก- ก 0 g ก ( '0, 0 &ก! - ก&
/ก , -(
m
ก , ก ก , ( ก 1 kHz )


8 V GS (off ) = − 3 V T = − 55 C
-Transfer Conductance (mS) 6 4 T = 125 C T = 25 C

A


A

A
D
m
m 2 g = 4.9 mS, I = 5 mA,V GS (off ) = − 3 V;
g
0
0.1 1 5 10
I D -Drain Current (mA)
1.45 0 0 j (+ g ก0,ก ( I
D
m
ก

ก
ก

53
1. !!" # $
%&







- ก! 1.15 g 6 mS " , F = 1 kHz + ก ,
m

F = 400 MHz -( g = 4 mS
m
- ก 1.45 0 0 j (+ g ก0,ก ( I " g m
m
D
80 ! ก0,ก ( I '(& 0 :-
D
− & ก ) T = 25 C g = 6 mS, I = 10 mA; '( ! *

m
D
A
g = 0.6 mS, I = 0.1 mA;
m
D
− & ก ) T = 125 C g = 5.4 mS, I = 10 mA; '(

A m D
! * g = 0.4 mS, I = 0.1 mA;
m
D
− & ก )T = − 55 C g = 7 mS,I = 10 mA; '(

D
A
m
! * g = 1 mS,I = 0.1 mA;
m
D
ก $& (+ '( ก ,,-( g - * / &)! (
m
- ก ก

2I DSS
g m 0 = (1.18)
V P
 V 
g = g 1− GS  (1.19)
m m 0 
 V P 
0 0
" g
ก ! % / ( V =
m 0 GS
- ก 1.46 0 0 j (+ ก ( I ก0, V &
0
D GS
ก* + I = 5 mA -( - * '(& 0 :-
D
10
V DS = 10 V,V GS (off ) = − 3 V;
8 T = − 55 C
-Drain Current (mA) 6 4 T = D 25 C GS = − 1.05 V;

A

A
I =
5 mA,V

A
D T = 125 C
I
2
− 1.05
0
0 − 0.6 − 1.2 − 1.8 − 2.4 − 3
V GS -Gate-SourceVoltage (V)

1.46 0 0 j (+ ก ( I ก0, 0 V
D GS
ก

ก
ก

54
1. !!" # $
%&







− T = 25 C, I = 5 mA,V GS = − 1.05 V;

D
A
− T = − 55 C, I = 5 mA,V GS = − 1.2 V;

A
D
-( 0 &ก!&+t +W $& ' ' ก ! 0 V & '
GS
' ( 0.15 V & 0 -( - * & W ก
1.5.3.11
Qก ก (NF

)


)}ก&ก !0 &'/ 055 ,ก &)! NF ! * ก' &
1 dB- ก! 1.15 NF = 1.7 dB
)
1.5.3.12 )
ก (G PS
% & & &ก & . 0! / ก* '0 / &)! - %


- ก! 1.15 G = 10 dB
PS
ก &)! ก ก ,, - / &)! /

ก* '0 10 dB " -0 - ,,%

1.5.4 3+ R %- '
$&! 5 $&! '( '(& 0 1.47

1.5.4.1
% ก
) (g
m )
0 ก' ' +0 / 1.5.3.10


1.5.4.2 % ก

ก
)
( )V
ก ( '0,&ก!% & . 0 ก ( '0, (+ / &ก! ก0,
0
/ % " ! (+ / &ก! ก0,/ % ก -7
- & }











C = C iss + C rss m out
g R
T











1.47 05'0ก1 '( ,,-* ' 3, $ - / &)! %


ก

ก
ก

55
1. !!" # $
%&






1.5.4.3 . ก+ %ก
% (g V
)
m
+' ก* & $ ก ( & & . +' ก* & $ ก ( ก , " 0

V ก & $ +
' / 0 V -( * + $ ก ( I +' ก- ก g V & ' ' !

m
d
& 0 V & $ /7 -( * +ก ( I +'& $ ก/7 " $9 ! +0 ' ก9

d
g ( - ก ก
m

2I DSS  V GS 
g =  1−  (1.20)
m
V P  V P 
0
0
" I DSS
ก ( $ ! & % '(V
&ก!% 0! )
P
V
0 (+ / &ก!ก0,/ % &
ก* + - * / &)!
GS

1.5.4.4 3 & ก (C )
rss
1.5.4.5 3 %/ '/ (C )
iss


0 ก' / ! / C '(C + - ก 8 / '/
iss rss
&)! - ก 1.47 . ,,-* ' 3, $ - / &)! % ,, C " & ' C +
T
rss

& . (C g R ) ! / ก0,C -( ก
iss
rss m out
C = C + C g R (1.21)
T iss rss m out
$

1.11 - &/ ,,-* ' 3, - / &)! % - ก C rss = 1.5 pF, C iss = 5 pF,

I DSS = 15 mA,V = − 5 V,V GS = − 1.5 V;
P

2I  V 
9 + - ก ก (1.20) g = DSS  1− GS 
m
V P  V P 
)
−
×
×
2 15 10 − 3  ( 1.5 
g =  1−  = 4.2 mS
m
−
− 5   ( ) 5  

g = == = 4.2 mS,C rss = = = = 1.5 pF,C iss = = = = 5 pF;
m







1.48 ,,-* ' 3, $ - / &)!


ก

ก
ก

56
1. !!" # $
%&







-


$&! -* & . ก ( " ,,-* ' 3, $ - / &)! ก I DSS ,
,C '(C
V GS (off ) rss iss
ก &)! ! * 7 7 0 , $ก0 &
2 ก0 ก & + / &)! "

ก ! , -(! &'
ก&)! C ก 1 pF

$ ก ( I & ก0, 0.5I DSS rss
D




______________________________

























































ก

ก
ก

2







ก
ก


ก !
"

#$
ก !
%
&'
%
& ( ก !






ก ! ) * (ก+!, ('- % (! %
& (
)
%

' $
(
! ! 360

(
-$ . ! ) ก ( . //0 ก , //0 ก !, ก ก-
&
-


!! % '"%
& ( (/ &( +ก%
&ก % '"%
& ( . (/
ก *

3-$
4
% .
" % (,5

//0 ( -
&( . ก !!
-

"
"
+

ก+
(
!%(
-
6 (

"

2.1






!

β = β = 100,V BE = 0.6 V;
o
F
F = 6 GHz,C ob = 1 pF,r bb′ = 2 ;
Ω
T
Q 1
V
o
E
E g i

15 MHz
,% 2.1




ก ,% 2.1

* '"%
& ( (
$ :-
− Q %
& ( % .
" %
% !( " ."
#$
Q
1
1

"



" * F (% ก ! 6 GHz C (% ก ! 1 pF
T
ob
) %

' $
( ก ( +ก( . (
− R B 1 , R R ก
! ." ก %
& ( ." " ) %
% (
; 3

2
B
E
) .; &
ก" ก <& 3 β "
F
, C C % .
" % ('- ก !<

( ." //0
− C
B C E
ก . <
" .
" % ! )
"
− E . ก (
& ,
"
%
"
ก 75 Ω ( -
ก (,5
g
ก

ก
ก

58
2.




!! & & ( (/ "
ก (V ก
" ก ! "
( " 180

)
o
2.1.1 ก


#$!
%&&'
ก
#(
"

(3- , ) %
%
& ( ก ก I , I
V
B C CE
-


)
)
ก ,% 2.2 (ก (.+
(ก+!,
(
ก (ก+!,

." //0 ก . <

V CC = 12 V
I R B 1 R C I C
R B1
C
I
B β F B
I B Q 1
* ) &
V BE = 0.6 V
E
R B2 R E
I
R B 2 I = I + I C
B
E

,% 2.2 //0 ก ,% 2.1


//0 ก %
& ( (
$ :-
I * , & ก ( +ก( (I (,
,
− . ก (
& ก β F B C )
ก (,
, ก (! (I
B )
− *
) & (,5
ก? ! ก ."% ! (! (,5
ก#
'
& 3

− V (% ก ! 0.6 V
BE
− %&@% ก I
. <
ก% (! "
C
I
− ก I
. <
. ก (
& ก β F B "
B
2.1.1.1 ก
)
#
*
I
B
ก , ก I $


,% 2.3, 2.4 ,% 2.5
B
ก ,% 2.3 " ก
V CC = IR B 1 + IR B 2 = ( I R B 1 + R B 2 )

I = V CC
( R B 1 + R B 2 )

V = IR
TH B 2
V CC B 2 (2.1)
R

$
V =
TH
( R B 1 + R B 2 )
ก

ก
ก

59
2.



ก ,% 2.4 " ก



R R 2 (2.2)
B
1 B
R = ( R R ) =
TH B 1 B 2 )
( R B 1 + R B 2




β F B I β F B
I
I
Q 1 Q 1

V BE = 0.6 V V BE = 0.6 V
V TH






,% 2.3 ก (! ก ก ก , V
TH







R TH
R TH


,% 2.4 ก , R
TH

V CC =12 V
I V
R C C R C
C
R TH
I
B β F B
I B V CE

V BE = 0.6 V
E
R E I C V R E
I + I = I E
C
B

&
,% 2.5 ก , ก I ก . ก (

V
TH
B
ก ,% 2.5 ก , ก I ก . ก (
&
V "
B TH
ก


ก

ก
ก

60
2.




V = I R + V + I R (2.2a)
TH B TH BE E E

(
- ก I = I + I C , I = β F B , I = (β + ) 1 I
I
;
C
B
E
E
B
F
V TH = I R + V BE + ( β + ) 1 I R
B E
F
B TH
) }
V − V = I R + ( β + 1 R
TH BE B { TH F E
V − V )

$
I = ( TH BE (2.3)
B
R TH + (β + ) 1 R E
F
2.1.1.2 ก
)
#
*
I (+#V
CE
C
ก , ก I
V ก ,% 2.5 " ก
C CE

I = β I (2.4)
C F B
V CC = I R + V CE + (β + ) 1 I R
C C
F
B E
}
I R +

$
V CE = V CC − { C C ( β + ) 1 I R (2.5)
B E
F
, I V
,
2.1 ก ,% 2.1 , V TH , R TH , I B C CE
×
×
R
V CC B 2 12 10 10 3
- .
ก ก (2.1) V = = = 3 V
TH ) 3 3
×
×
( R B 1 + R B 2 ( 30 10 + 10 10 )
3
×
×
R R 2 30 10 × 10 10 3
B
1 B
ก ก (2.2) R = = = 7,500 Ω
TH ) 3 3
×
×
( R B 1 + R B 2 ( 30 10 + 10 10 )
(V − V ) (3 0.6− )
ก ก (2.3) I = TH BE =
B
3
×
R TH + (β + ) 1 R E 7.5 10 + (100 1 470+ )
F
I = 43.66 µA
B
I =
ก ก (2.4) I = β F B 100 43.66 10 − 6 = 4.366 mA
×
×
C
}
I R +
ก ก (2.5) V CE = V CC − { C C ( β + ) 1 I R
B E
F
×
V CE = 12 − ( { 4.366 10× − 3 × 1 10 3 ) ( 101 43.66 10+ × × − 6 × 470 )}
V = 5.561 V
CE
Ω Ω
V TH = = = = 3 V, R TH = = = = 7.5 k , I = =Ω Ω B = = 43.66 µA, I = == = 4.366 mA,V CE = = = = 5.561 V;
C
ก

ก
ก

61
2.




2.1.2 ก


#$!
%&&'
ก
#( +,
ก+


C b c ′
r bb′ b′

m b e ′
C b e ′ r b e ′ V b e ′ g V
E g



,% 2.6 //0 ก !
ก ,% 2.1


) (,5

.
"
ก ! "
*

ก (F M id
"
ก % . X C B , X X (% ก ! 0 Ω X C b e ′ X C b c ′ ก
C
C
C
E
"
%&$
,% 2.6 2.7
r bb′ b′
r b e ′ V b e ′ g V
m b e ′
E g


Z in Z i Z o Z out
,% 2.7 //0 ก !
ก %&$ C C
b c ′
b e ′
2.1.2.1 ก
)
#
*
g (+# r
m b e ′ ′′ ′
,V β %
& (
(,5
" % ! I C (dc ) T F

I C (dc ) I C (dc )
ก ก (1.9) g = =
m
V T (k T q )
B
β
ก ก (1.10) r b e ′ = o
g m
2.1.2.2 ก
)
#
*
Z (+# Z
i in
2.1.2.2.1 Z - & 3
"
( " . (! ก !ก * %&$
i
"
%
;
ก% $ . % . (! ก !ก
,% 2.7

Z = r + r (2.6)
i bb′ b e ′

2.1.2.2.2 Z - & 3
"
( " . (! ก !ก
in

,% 2.7

ก

ก
ก

62
2.




R R 2
1 B
B
R =
BB )
( R B 1 + R B 2
R BB i R BB (r bb′ + r b e ′ )
Z

$
Z = ( R BB Z i ) = = (2.7)
in
( R BB + Z i ) ( R BB + r bb′ + r b e ′ )
2.1.2.3 ก
)
#
*
Z (+# Z
o
out
"


2.1.2.3.1 Z - & 3

ก . ( +ก( ก !ก
o

*
- . ก (
& ก g V "
%
ก .


%
"
-
m b e ′
(,G
,% 2.7
Z = ∞ (2.8)
o
2.1.2.3.2 Z - & 3
"
ก . ( +ก( ก !ก
out
* "
%
% . ( +ก( ก !ก
,% 2.7



Z out = Z ( C R L )
R
o
R R
(
- ก Z = ∞ , R = C L ;
o out R + )
( C R L
R R (2.9)
C L

$
Z = R = R R ) =
out out ( C L R + )
( C R L

,
,
2.2 ก ,% 2.1 E
15 MHz , g m , r b e ′ , Z Z in , Z Z * %
o
i
out
g

T = 25 C
A
I C (dc ) I C (dc )
- .
ก ก (1.9) g = =
m
V (k T q )
T B
T = (273 25+ ) = 298 K
×
k T 1.38 10 − 23 × 298
V = B = = 25.7 mV
T
×
q 1.60 10 − 19
×
I C (dc ) 4.366 10 − 3
g m = = − = 169.883 mS
×
V T 25.7 10 3
β o 100
ก ก (1.10) r b e ′ = = − = 588.64 Ω
×
g m 169.883 10 3
3
×
R R 1 10 × 75 69.767 Ω
C L
R = = =
out
( R + R L ) ( 1 10 + 75 )
×
3
C
ก ก (2.6) Z = r + r
i bb′ b e ′
ก

ก
ก

63
2.




+
=
Z = 2 588.64 590.64 Ω
i
R Z R BB (r bb′ + r b e ′ )
ก ก (2.7) Z = ( R BB Z i ) = BB i =
in
( R BB + Z i ) ( R BB + r bb′ + r b e ′ )
3
×
×
R R 2 30 10 × 10 10 3 7,500 Ω
B
1 B
(
- ก R BB = = =
3
×
( R B 1 + R B 2 ) ( 30 10 + 10 10 3 )
×
×
R Z 7,500 590.64
Z = BB i = = 547.521 Ω
in )
( R BB + Z i ) (7,500 590.64+
ก ก (2.8) Z = ∞
o
×
3
1 10 × 75
ก ก (2.9) Z out = R out = = 69.767 Ω
( 1 10 + 75 )
3
×
g = == = 169.883 mS, r b e ′ ′′ ′ = = = = 588.64 , Z = =Ω Ω i = = 590.64 , Z in = = = = 547.521 , Z = ∞ ∞Ω Ω o == = , ∞ ∞
Ω
Ω Ω
Ω Ω Ω
Ω Ω
m
Ω
Ω Ω Ω
Z = = = = 69.767 ;
out
2.1.2.4 ก
)
#
*
A (+# A
V (F Mid ) ( i F Mid )



2.1.2.4.1 A -

ก .
V
V (F Mid ) o
E ก ,% 2.7
(
ก "
( " "
i

E = I b (r bb′ + r b e ′ )
i
E
I = i
b
r
( bb′ + r b e ′ )
E r E r
i b e ′
i b e ′
V b e ′ = I r = =
b b e ′
r
( bb′ + r b e ′ ) Z i
ก "
ก V = I Z
o c out
(
- ก I = g V
c m b e ′
V = g V Z
′
o m b e out
E r
i b e ′
(
- ก V b e ′ =
Z
i
g E r Z
′
V =
m i b e out
o
Z i
V o g r Z g r R R (2.10)
′
′
m b e out
m b e C L

$
A V (F Mid ) = − = − = − )
R +
E
r
i Z i ( bb′ + r b e ′ )( C R L
ก

ก
ก

64
2.




E = I R + I Z = I ( R + Z )
g i g i in i g in
E g
I =
i
( R + Z in )
g
E = I Z
i
i in
E Z
E = g in
i
( R + Z in )
g
V o V o E i V o E Z
g in
A = − = − × = − ×
V (F Mid ) E g E i E g E i E g ( R + Z in )
g
V o V o Z in g r Z Z in
′
m b e out

$
A V (F Mid ) = − E g = − E i × ( R + Z in ) = − Z i × ( R + Z in ) (2.11)
g
g
(
- ก
V (/ ก
" ก ! E 180 # (,5

o g
"

$
-
−
) ! & !! & & (

A # ( . ! ( )
.
" (/
V (F Mid )
-
"
ก ( . ! ก
,

- ก
ก . ก I
2.1.2.4.2 A ( i F Mid ) R L
'" E . - E " ก (. -
ก
ก I
,% 2.7 ก A ( i F Mid ) g i
b
I R
A ( i F Mid ) = I L
E = I b b ( bb′ + r b e ′ )
r
i
E
I = i
b )
(r bb′ + r b e ′
E r
i b e ′
V b e ′ = I r = + )
b b e ′
r
( bb′ r b e ′
g V R g E r R
′
′
=
m i b e C
m b e C
I R L = ( R + R L ) (r bb′ + r b e ′ )( R + R L )
C
C
I R g E r R (r bb′ + r b e ′ )
′
A ( i F ) = L = m i b e C ×
Mid
I b (r bb′ + r b e ′ )( R + R L ) E i
C
I R g r R
′

$
A = L = m b e C (2.12)
( i F Mid ) R + )
I
b ( C R L
V o V o
,
2.3 ก ,% 2.1 , A V (F Mid ) = − , A V (F Mid ) = − A ( i F Mid )
E
i E g
V o g r Z g r R R
′
′
m b e out
m b e C L
- .
ก ก (2.10) A V (F Mid ) = − E i = − Z i = − ( bb′ + r b e ′ )( C R L )
R +
r
ก

ก
ก

65
2.




×
×
169.883 10 − 3 × 588.64 69.767
A V (F ) = − = − 11.812
Mid 590.64
V o
A V (F ) = − = − 11.812
Mid
E i
V o V o Z in
ก ก (2.11) A V (F ) = − = − ×
Mid E g E i ( R + Z in )
g
V o 547.521
A V (F Mid ) = − = − 11.812× )
E g (75 547.521+
V o
×
A = − = − 11.812 0.879 = − 10.382
V (F Mid ) E g
I R g r R
′
ก ก (2.12) A = L = m b e C
( i F Mid ) I b ( R + R L )
C
×
×
169.883 10 − 3 × 588.64 1, 000
=
A ( i F Mid ) (1, 000 75 )
+
A ( i F Mid ) = 93.023
V o V o I R L
= − −− −
= − −− −
== =
== =
A V (F ) == = = − −− − 11.812, A V (F ) = − −− − == = 10.382, A ( i F ) = = = = = = = = 93.023;
Mid E i Mid E g Mid I b
2.1.2.5 ก
)
#
*
,


ก.
+, (Power Gain; P )
G
ก (,5

. ก "
ก (P ก
)
out
-

"
( " (P . < .

ก ก ! ก
ก
)
in

& % ."
,( &(! ก , P %
ก (,5
" % ก '
G
"
( " "
ก (
- ก ก
. (. -
V o V o Z in
ก ก (2.11) A V (F Mid ) = − = − ×
E
g E i ( R + Z in )
g
I R g r R
′
ก ก (2.12) A = L = m b e C
( i F Mid ) I b ( R + R L )
C
V I R
P = o × L
G E I
g b
V I R V Z g r R
′
P = o × L = o × in × m b e C
G
E g I b E i ( R + Z in ) ( R + R L )
C
g
V I R g r R R Z g r R
′
′
P = o × L = m b e C L × in × m b e C
G
E g I b (r bb′ + r b e ′ )( R + R L ) ( R + Z in ) ( R + R L )
C
C
g
ก (2.12a) '"ก ! E ก (2.12b) '"ก ! E
i
g
ก

ก
ก

66
2.




2
V I R ( g r R ) R L Z
′
m b e C
P = o × L = × in (2.12a)
G 2
E I ) ( R + )
g b Z i ( R + R L g Z in
C
2
g r R
V I R ( m b e C ) R L
′
P = o × L = (2.12b)
G
E I R + ) 2
i b Z i ( C R L
,
2.4 ก ,% 2.1 , P (dB) ( - '"ก ! E E
G i g
2
V I R ( g r R ) R L
′
m b e C
- .
ก ก (2.12b) P = o × L =
G
E I R + ) 2
i b Z i ( C R L
V I R
=
P = o × L = 11.812 93.023 1, 098.787
×
G E i I b
P = 10 log 1, 098.787 = 30.409 dB
10
G
2
V I R ( g r R ) R L Z
′
m b e C
ก ก (2.12a) P = o × L = × in
G 2
E g I b Z i ( R + R L ) ( R + Z in )
g
C
V I R 547.521
P = o × L = 11.812 93.023× )
×
G
+
E g I b (75 547.521
V I R
P = o × L = 11.812 93.023 0.879
×
×
G
E I
g b
V I R
P = o × L = 965.834
G E g I b
P = 10 log 965.834 = 29.849 dB
G 10
"
"
( - '" E P = == = 30.409 dB ( - '" E P = == = 29.849 dB
i G g G
2.1.3 ก


#$!
%&&'
ก
#( +,
,
.

"
(F ( - E
X C B , X X
)
L
C
C
g
C
E
#$
# (!
ก ! )
* C & & (
ก ! ) * C C ! )
B
C
E
"
"
( +ก( ก ก !!


& ก !! * ก .
. C
B

! )
"
# ! ก &( . ก(,5
3

$
2.1.3.1 ก
)
#
*
F ( L C B )
ก ,% 2.8 ( - E
(% ก !
"
# % ." X
g
C
B
# (,5
(% ก ! "
%
% (

(
ก
กก .
."(,5
F ( L C B )

$
( - E
"
% C ! ) % (! "
%
% (
X ก+ - R
B C B FLCB g
ก

ก
ก

67
2.



"
"

(% ก ! F ( L C B ) % . X (% ก ! R FLCB
, F ( L C B ) ก ก
C
B
R FLCB r bb′ b′

r b e ′ V b e ′ g V
m b e ′
R
E out
g


,% 2.8 , F ( L C B )


X C B = R FLCB

1
(
- ก X =
C B
π
C
2 F ( L C B ) B
1 = R
π
C
2 F ( L C B ) B FLCB
1 (2.13)

$
F ( L C B ) =
π
C
2 R
FLCB B
R FLCB r bb′ b′

r b e ′ V b e ′ g V
m b e ′
R
E out
g



r
R ( bb′ + r b e ′ )
r
R = R + R ( bb′ + r )} = R + BB
FLCB g { BB b e ′ g + )
R
( BB r bb′ + r b e ′
r bb′ b′
r b e ′ R FLCB



R FLCB

,% 2.9 , R FLCB

# (,5
"
%
% (
C

ก , R
FLCB B
,% 2.9

R BB (r bb′ + r b e ′ )
R FLCB = R + { BB ( bb′ + r b e ′ )} = R +
R
r
g
g
( R BB + r bb′ + r b e ′ )
ก

ก
ก

68
2.




R BB (r bb′ + r b e ′ )

$
R FLCB = R +
g
( R BB + r bb′ + r b e ′ )

,
2.5 ก ,% 2.1 , F ( L C B )
1
- .
ก ก (2.13) F ( L C ) =
π
B 2 R FLCB B
C
R BB (r bb′ + r b e ′ ) 7,500 ( 2 588.64+ )
* % R = R + = 75 + = 622.521 Ω
FLCB g )
( R BB + r bb′ + r b e ′ (7,500 2 588.64+ + )
1 = 1
=
F ( L C B ) 2 R FLCB B 2 3.14 622.521 240 10 − 12
π
×
×
×
×
C
F = 1.065 MHz
( L C B )
F ( L C B ) = == = 1.065 MHz
2.1.3.2 ก
)
#
*
F ( L C )
E
ก ,% 2.10 ( - E
(% ก ! F ( L C E ) # (,5

"
%
g
C ! ) % & & ( % ." X (% ก ! R FLCE
, F ( L C E ) " ก ก
C
E
E
X C E = R FLCE
1
(
- ก X C E = 2 F ( L CE ) E
π
C
1 = R
"
π
2 F C FLCE
( L CE ) E
1 (2.14)

$
F ( L C E ) =
π
2 R
FLCE C E
r bb′
B b′ C
I b I c
r V g V
R g b e ′ b e ′ m b e ′
R BB
E g R OUT
E
R E
C E
R FLCE

,% 2.10 , F
( L C E )
"
# (,5
"
%
% (
C (3- .

ก , R
FLCE E
, R R ."

& & ( ก (,5
r bb′ r b e ′ R g
# " r bb′ , r b e ′ g BB , ,
(β + 1 ) (β + ) 1 (β + ) 1
o
o
o
ก

ก
ก

69
2.




R BB
,% 2.11
(β o +1 )



(r bb′ + r b e ′ )  R g R 
R = +  BB 
EE
( β + ) 1   ( β + 1 ) (β + ) 1  
o
o
o
r
= ( bb′ + r b e ′ ) + R R
g BB
R
EE
( β + ) 1 (β + 1 )( R + R BB )
o
g
o
R R
E EE
R FLCE = ( R R EE ) =
E
( R + R EE )
E
r bb′ b′
r b e ′
E
g
( bb′ + r b e ′ )
r
β + ) 1

( o ( bb′ + r b e ′ )   R g R BB 
r
R = +  
EE β + β + β +
( o ) 1   ( o 1 ) ( o ) 1  
R g R BB ( bb′ + r )   R R 

r
β + ) 1 β + ) 1 R EE = b e ′ +  g BB 
( o ( o β + β + 1 R +

( o ) 1   ( o )( g R BB )
R R
R = R R ) = E EE
FLCE ( E EE R + )
( E R EE
R R
EE FLCE

,% 2.11 , R
FLCE

,
2.6 ก ,% 2.1 , F ( L C E )
1
- .
ก ก (2.14) F ( L C ) =
π
E
2 R FLCE C E
R R
E EE
* % R FLCE = ( R R EE ) =
E
( R + R EE )
E
+
×


(2 588.64 )  75 7,500 
=
+
R EE = ) +  )(  = 5.847 0.735 6.582 Ω
(100 1+   (100 1 75 7,500+ + )  
×
R R 470 6.582
E EE
R FLCE = = = 6.491 Ω
( R + R EE ) (470 6.582 )
+
E
1 1
F = = = 2.453 kHz
( L C E ) − 6
π
×
×
×
×
2 R FLCE C E 2 3.14 6.491 10 10
F ( L C E ) = == = 2.453 kHz
ก

ก
ก

70
2.




2.1.3.3 ก
)
#
*
F ( L C C )
# (,5

"
%
ก ,% 2.12 ( - E
(% ก ! F ( L C C )
g
" " ก ก
C ! ) % ( +ก( % . X (% ก ! R FLCC
, F ( L C C )
C
C
C

X C C = R FLCC
1
(
- ก X =
C C
π
C
2 F ( L C C ) C
" 1 = R
2 Fπ ( L C C ) C FLCC
C
1 (2.15)

$
F ( L C C ) =
π
C
2 R
FLCC C
C C
r R
B bb′ b′ C FLCC
R g
m b e ′
r b e ′ V g V
R BB b e ′ R L
R C
E g
E


,% 2.12 , F ( L C C )

# (,5
"
%
% (
C
ก , R
FLCC C
,% 2.13

R +
R FLCC = ( C R L )

g V
m b e ′
R = R + R )
FLCC ( C L



R FLCC

,% 2.13 , R
FLCC
2.1.3.4 ก
)
#
*
F
L
* F -
"
#
ก( - ก ก F ( L C B ) ,
L
F ( L C E ) F ( L C C ) %
) (,5

F
L


ก

ก
ก

71
2.



F
,
2.7 ก ,% 2.1 , F ( L C C ) L

1
- .
ก ก (2.15) F ( L C ) =
π
C
C
2 R FLCC C
)
3
=
×
* % R FLCC = ( R + R L ) ( 1 10 + 75 = 1,075 Ω
C
1
F ( L C C ) =
π
C
2 R
FLCC C
1
F ( L C ) =
C × × × × − 12
2 3.14 1, 075 820 10
F ( L C C ) = 180.641 kHz
(
- ก F ( L C B ) = 1.065 MHz, F ( L C E ) = 2.453 kHz, F ( L C C ) = 180.641 kHz;

$
F = F = 1.065 MHz
L ( L C B )


F ( L C C ) = == = 180.641 kHz
F - F ( L C B ) = == = 1.065 MHz
L

2.1.3.5 ก
)
#
*
A V (F L )

A V (F L ) -

"
.
V E g
o
% E " !
"
&( . (H3 ก ! ) * C
ก ! ) * C

g B E
C
$
< ('
( ก ! C . ก (
& % '"
& "
%
"
ก 50 Ω
C B
(ก ก !
"
# '" E R
"
. - 75 Ω
$
ก , A V (F L ) g g

r bb′ b′

I I I
i b r b e ′ V b e ′ g V c
m b e ′
E g



,% 2.14 , A %
ก ! ) * C
V (F L ) B

ก ,% 2.14 R ('
( ก ! ,% 2.9 " ก
FLCB
R BB (r bb′ + r b e ′ )
R FLCB = R +
g
( R BB + r bb′ + r b e ′ )
R BB (r bb′ + r b e ′ )
ก .
." Z BB =
( R BB + r bb′ + r b e ′ )


ก

ก
ก

72
2.




R FLCB = R + Z
BB
g
E = I i ( R + X C B ) + I Z
g
i BB
g
 1 
E = I R + + I Z
g i  g  i BB
ω
 J C B 
ω
+
 1  { 1 J C B ( R + Z BB )}
g
E = I i  R + Z BB +  = I i
g
g
ω
ω
 J C B  J C B
ω
E J C B
g
I = { 1 J C B ( R + Z BB )}
i
ω
+
g
I R
I =
i BB
b
( R BB + r bb′ + r b e ′ )
ω
E J C B R
g
I = × BB
{ 1 J C+ ω B ( R + Z BB )} ( R BB + r bb′ + r b e ′ )
b
g
V = g V Z
′
o
m b e out
ω
E g Z J C r R
′
B b e BB
g m out
V =
{ 1 J C B ( R + Z BB )}( R BB + r bb′ + r b e ′ )
o
+
ω
g
ω
V o g Z J C r R
′
B b e BB
m out
A = − = −
V (F L )
ω
+
E g { 1 J C B ( R + Z BB )}( R BB + r bb′ + r b e ′ )
g
X C B = R FLCB = R + Z
g
BB
1 1
-
(
- ก X C = . = ( R + Z BB )
g
B ω C B ω C B
1
Cω B =
( R + Z BB )
g
1
ω
%
Cω B =
J C
B
( R + Z BB )
g
V o J ( g r Z R ) 1
′
m b e out BB
A = − = − ×
V (F L ) )

E g  ( R + Z BB )  ( R + Z BB

g
g
+
 1 J  ( R BB + r bb′ + r b e ′ )
 ( R + Z BB ) 


g
V o J g r Z R )
′
( m b e out BB
A V (F ) = − = −
+
L
E g {1 J 1 }( R BB + r bb′ + r b e ′ )( R + Z BB )
g
( g r Z out R BB ) 90
m b e ′
A V (F ) = −
1
L  2 2 − 1 
( R BB + r bb′ + r b e ′ )( R + Z BB )  ( ) 1 + ( ) 1 tan 
g
 1 
V o ( g r Z R BB ) 90
′
m b e out
A V (F L ) = − = −
E g ( R BB + r bb′ + r b e ′ )( R + Z BB ) 2
45
g
ก

ก
ก

73
2.






90 −
V o (0.707 )( g r Z R BB )
45
′
m b e out
A V (F L ) = − E g = − ( R BB + r bb′ + r b e ′ )( R + Z BB )
g

7
45
V o ( 0.70 )( g r Z R BB )
′
m b e out
A V (F ) = − = −
L E g ( R BB + r bb′ + r b e ′ )( R + Z BB )
g
)

V o (0.707 g r Z R BB
45
′
m b e out
A V (F ) = − = − ×
L E ( R + Z ) ( R + r bb′ + r b e ′ )
g g BB BB
R BB (r bb′ + r b e ′ )
r
(
- ก Z = Z = , Z = ( bb′ + r );
BB in ) i b e ′
( R BB + r bb′ + r b e ′
Z in = R BB (r bb′ + r b e ′ ) = R BB
Z ( R + r + r )(r + r ) ( R + r + r )
i BB bb′ b e ′ bb′ b e ′ BB bb′ b e ′
)
V o (0.707 g r Z Z in 45
′
m b e out
A = − = − ×
V (F L ) )
E
g ( R + Z in Z i
g
V o V o Z in g r Z Z in
′
m b e out
(
- ก A = − = − × = − ×
V (F Mid ) E g E i ( R + Z in ) Z i ( R + Z in )
g
g
V o (2.16)

$
A V (F L ) = − E g = 0.707A V (F Mid )

,
2.8 ก ,% 2.1 , A V (F L )
V o
)
- .
ก ก (2.16) A = − = (0.707 A
V (F L ) E g V (F Mid )
V o
A V (F L ) = − = (0.707 )( 10.382− ) = − 7.34 45
E
g
V o
= − −− −
== =
A V (F L ) == = E g = − −− − 7.34 45
2.1.4 ก


#$!
%&&'
ก
#( +,
,
( - E
ก
ก ( "
"
(F C #
)
g
T
H

ก ! r X # < % .
V " # < % ."
V
"
b e ′
b e ′
C
o
T

, " ก &( . //0 ก !
"
(3- , F , A B
H V (F H ) W
2.1.4.1 ก
)
#
*
F
H
F -
"

ก ! ) * C ก ,% 2.15 ( - E
g
T
H

(% ก ! F % . X (% ก ! R # R (,5
"
%
% (
C ( -

"
T
H
C
FH
FH
T
ก

ก
ก

74
2.




X (% ก ! R
, F " ก ก
C T FH H
X = R
C T FH
1
(
- ก X C T = 2 F Cπ H T

" 1 = R
FH
π
2 F C
H T
1

$
F = (2.17)
H
2 Rπ FH C T
r bb′ b′ C = C b e ′ + C b c ′ (1 g R+ m out )
T

m b e ′
C T r b e ′ V b e ′ g V
E g


Z out

,% 2.15 , F A
H V (F H )

C = C b e ′ + C b c ′ (1 g R+ m out )
T
r bb′ R FH 1 R FH
B b′ C r bb′
R g r g V
C T b e ′ m b e ′
R g R BB r b e ′ C
E R BB T
g
E

 R R   r R

′
r
R =  g BB + r bb′ ,R = ( b e ′ R ) = b e FH 1 ;
FH 1 ) FH FH 1 + )
R +
r
 ( g R BB   ( b e ′ R FH 1

,% 2.16 ก , R
FH
ก , R # (,5
"
%
% (
C
FH T

,% 2.16
 R R  R r + R r + R R


R FH 1 = r  bb′ + g BB  = g bb′ BB bb′ g BB
 ( R + R BB )  ( R + R BB )


g
g
r R 1
′
b e FH
R = (r R ) =
FH b e ′ FH 1 )
r
( b e ′ + R FH 1
r b e ′ ( R r + R r + R R )
BB bb′
g bb′
g BB
R FH =
R r + R r + R r + R r + R R
g b e ′
g bb′
BB bb′
BB b e ′
g BB
ก

ก
ก

75
2.



,
2.9 ก ,% 2.1 , F
H
1
- .
ก ก (2.17) F =
H
π
2 R FH T
C
 R R   75 7,500 
×


g BB

* % R FH 1 =  ) + r bb′  =  + ) + 2 = 76.257 Ω
  ( R + R BB    (75 7,500 
g
×
r R 1 588.64 76.257 69.767 ;
′
b e FH
Ω
R FH = = = 67.511 , R out = Ω
r
( b e ′ + R FH 1 ) (588.64 76.257+ )
C b c ′ = C ob = 1 pF
×
g m 169.883 10 − 3 − 12
×
C b e ′ = − C ob = − 1 10 = 3.508 pF
2 F T 2 3.14 6 10 9
π
×
×
×
×
×
C = C b e ′ + C b c ′ (1 g R ) 3.508 10 − 12 + × − 12 { 1+ ( 169.883 10 − 3 × 69.767 )}
=
+
1 10
T
m out
C = 16.360 pF
T
1 1
F = =
H 2 Rπ FH T 2 3.14 67.511 16.360 10 − 12
×
×
×
×
C
F = 144.172 MHz
H
F == = 144.172 MHz
=
H
2.1.4.2 ก
)
#
*
A V (F H )

-

"
.
V E
A V (F H ) o g
"
ก ,% 2.15 2.16 ( - E
(% ก ! F % . X (% ก ! R " ก
g H C T FH
  r   

E = I R + I R r + b e ′  
g i g i  BB  bb′
ω
+
b e T  
   1 J r C
′
   r    

E = I i  R +  R BB  r bb′ + b e ′   

g
g
+
ω
     1 J r C 
b e T  
′
 R g ( bb′ + r b e ′ + R BB ) R+ BB ( bb′ + r b e ′ )
r
r


a =  
+ J r C ( R R + R r + r R ) 
ω
′
 b e T g BB g bb′ bb′ BB 
a
E = I
g i )
ω
r
′
( bb′ + r b e ′ + R BB ) + J r C ( R BB + r bb′
b e T
ω
+
E g ( { r bb′ + r b e ′ + R BB ) J r C ( R BB + r bb′ )}
′
b e T
I =
i
a )
′
i BB
I = I R (1 J r C+ ω b e T
b )}
( { R BB + r bb′ + r b e ′ ) J r C+ ω b e T ( R BB + r bb′
′
E R (1 J r C+ ω ′ )
I = g BB b e T
b
a
ก

ก
ก

76
2.



 r  E r R


′
V b e ′ = I b  b e ′  = g b e BB
  (1 J r Cω+ b e T )   a
′
V =
′
m b e out
o g V Z
V o g Z r R
′
m out b e BB
A V (F ) = − = −
H E g a
1 r b e ′ ( R r + R r + R R BB )
g bb′
BB bb′
g
(
- ก Cω T = , R FH = ;
R FH R r + R r + R r + R r + R R
g bb′
g b e ′
BB b e ′
BB bb′
g BB
1 R r + R r + R r + R r + R R
g b e ′
BB bb′
g bb′
BB b e ′
g BB
C = =
ω
T
R FH r b e ′ ( R r + R r + R R )
BB bb′
g bb′
g BB
%
C
a
ω
T
g Z r R
′
m out b e BB
A V (F ) = −
H
a
g Z r R
′
m out b e BB
A V (F H ) = − }
+
+
r
r
R
BB bb′
g b e ′
g bb′
BB b e ′
g BB
{ g ( bb′ + r b e ′ + R BB ) R BB ( bb′ + r b e ′ ) JR r + R r + R r + R r + R R
g Z r R
′
= − m out b e BB
R g (r bb′ + r b e ′ + R BB ) R+ BB (r bb′ + r b e ′ ) JR+ g (r bb′ + r b e ′ + R BB ) R+ BB (r bb′ + r b e ′ )
g Z r R BB
m out b e ′
A V (F H ) = −
r
R
r
{ g ( bb′ + r b e ′ + R BB ) R+ BB ( bb′ + r b e ′ )}(1 J+ ) 1
g Z r R
′
m out b e BB
A = −
V (F H ) 1
R (r + r + R ) R+ (r + r )} ( ) 1 2 + ( ) 1 2 tan − 1
{ g bb′ b e ′ BB BB bb′ b e ′
1
g Z r R
′
m out b e BB
A V (F H ) = −
45
r
r
R
{ g ( bb′ + r b e ′ + R BB ) R+ BB ( bb′ + r b e ′ )} 2
)
(0.707 g Z r R − 45
′
m out b e BB
A V (F H ) = − )
r
r
R g ( bb′ + r b e ′ + R BB ) R+ BB ( bb′ + r b e ′
(
- ก Z in = R BB
Z R + Z in ) { g ( bb′ + r b e ′ + R BB ) R+ BB ( bb′ + r b e ′ )}
r
r
R
( g
i
−
V o (0.707 g Z r Z in
45
) m out b e ′
A V (F H ) = − = − × R +
E g Z i g Z in
V o g Z r Z in
m out b e ′
(
- ก A V (F ) = − = − ×
Mid
E g Z i R + Z in
g
V o −
A V (F ) = − = (0.707 A (F ) 45
) V

$
H E g Mid (2.18)
ก

ก
ก

77
2.




,
2.10 ก ,% 2.1 , A V (F H )

V o
)
- .
ก ก (2.18) A V (F H ) = − E g = (0.707 A V (F Mid ) − 45

V o −
−
A V (F H ) = − E g = (0.707 )( 10.382 ) 45


V o −
A V (F H ) = − = − 7.34 45
E
g
= − −= − −
A = = 7.34 − −− − 45
V (F H )
2.1.4.3 ก
)
#
*
B
W
B - ก "
!
* , " ก<
W

"
ก !
"


B = F − F (2.19)
W H L

% A V ." ,dB( ! )
A
V (F Mid )

A V ( dB = 20 log 10 A V
)
A V (F Mid ) A V (F Mid )


* % A -

6
V
-

ก

A V (F Mid )
%
ก (F Mid )

A V (F Mid ) ( dB = 20 log A V (F Mid ) = 20 log 1 = 0 dB
)
A V (F Mid ) 10 A V (F Mid ) 10 1


%
"
(F
L )

A V (F L ) ( dB = 20 log A V (F L ) = 20 log 0.707 = 20 ( 0.15− ) = − 3 dB
)
A 10 A 10 1
V (F Mid ) V (F Mid )
%
"
(F
)
H
A V (F H ) ( dB = 20 log A V (F H ) = 20 log 0.707 = 20 − ) 3 dB
)
( 0.15 = −
A V (F Mid ) 10 A V (F Mid ) 10 1

ก

ก
ก

78
2.




,
2.11 ก ,% 2.1 , B (
ก / 3
K . A V
W
A V (F Mid ) dB
ก !
( )
F
- .
ก ก (2.19) B = F −
F
W H L
* % F = 144.172 MHz, F = 1.065 MHz;
H L
×
6
×
6
B = 144.172 10 − 1.065 10 = 143.107 MHz
W
B = == = 143.107 MHz
W
F
,
L
A V (F L ) ( dB = 20 log A V (F L ) = 20 log − 7.340 = 20 − ) 3 dB
)
( 0.15 = −
A 10 A 10 − 10.382
V (F Mid ) V (F Mid )
F
,
H

A V (F H ) ( dB = 20 log 10 A V (F H ) = 20 log 10 − 7.340 = 20 − ) 3 dB
)
( 0.15 = −
A V (F Mid ) A V (F Mid ) − 10.382

" (
ก /
,% 2.17



A V
A V F )
( Mid
dB
B W = 143.107 MHz


(F Mid )


F (log scale)
F = 1.065 MHz F = 144.107 MHz
H
L
,% 2.17 3
K . A V ก ! F ,% 2.1
A V (F Mid ) dB


2.1.5 ก
ก(






!
ก.
$ ก
ก(


Ω
Ω

V = 12 V, R = 75 , R = 75 , F ≤ 1 MHz, F ≥ 250 MHz,T = 25 C;
CC g L L H A
* ( - ก F = 1 MHz, F = 250 MHz;
H
L
ก

ก
ก

79
2.




Q 1 2SC3355 V CBO = 20 V,V CEO = 12 V,
Ω
V EBO = 3 V, I C (MAX) = 100 mA, r bb′ = 2 ,
P = 600 mW, β = β = 120,V BE = 0.6 V,
F
o
D
Q 1 F = =
V T 6.5 GHz, C ob 0.65 pF;
o
E
E i
g

,% 2.18

% '" ก !!

,C ก
ก(

1
ก ก (2.17) F =
H
π
2 R C
FH T
1
C =
T
π
2 R F
FH H
1
C b e ′ + C b c ′ {1 g+ m ( R out )} =
π
F
2 R FH H
1
C b e ′ + C b c ′ + C g R =
′
b c m out
π
F
2 R FH H
1
C g R = − (C b e ′ + C b c ′ )
′
b c m out
π
F
2 R FH H
g m
(
- ก (C b e ′ + C b c ′ ) = %

ก
π
2 F T
1 g m
C g R = 2 Rπ FH H − 2 Fπ T
′
b c m out
F
π
π
2 F − 2 g R F
C g R = T m FH H
′
b c m out
4π 2 R FH H T
F F
2π F − g R F F − g R F )
=
C g R = ( T m FH H ) ( T m FH H
′
b c m out
π
4π 2 R FH H T 2 R FH H T
F F
F F
( F − g R F )
g = T m FH H
m
π
F F C R
2 R FH H T b c out
′
2 g Rπ m FH H T b c out = ( T g R F )
F −
F F C R
′
m FH H
π
F = 2 g R F F C R + g R F
′
b c out
T
m FH H T
m FH H
F = g R F (2 F C Rπ T b c out + ) 1
′
T
m FH H
F T
g =
m
π
R FH F H (2 F C R + ) 1
′
T
b c out
I
(
- ก g = C (dc )
m
(k T q )
B
I C (dc ) = F T
π
F
(k T q ) R FH H (2 F C R + ) 1
′
T
B
b c out
ก

ก
ก

80
2.




F T ( B ) q
k T

$
I C (dc ) = (2.20)
π
R FH H (2 F C R + ) 1
F
′
b c out
T
2.1.5.1 ก
ก.
$
I
C
" ( - ก กก I C (dc ) % , ก ก (2.20) #

I C (dc ) " ก&
0.5I C (MAX) (3- , ; %
& (

F T ( B ) q
k T
ก ก (2.20) I C (dc ) =
π
F
R FH H (2 F C R + ) 1
′
b c out
T
ก .
." F = 250 MHz, R FH = R g , R out = R L , C b c ′ = C ob ;
H
,
2.12 , I
C
F T ( B ) q
k T
- .
ก ก (2.20) I C (dc ) =
R F (2 F C Rπ + ) 1
′
FH H T b c out

Ω
* % F = 250 MHz, R FH = R = 75 , R out = R = 75 , C b c ′ = C ob = 0.65 pF,T = 25 C;
Ω
H
g
L
A
k T
F T ( B ) q
I C (dc ) =
R F (2 F C Rπ + ) 1
′
FH H T b c out
×
6.5 10 × 25.7 10 − 3
9
×
I C (dc ) =
) }
9
×
×
×
×
×
×
75 250 10 6 ( { 2 3.14 6.5 10 × 0.65 10 − 12 × 75 + 1
I C (dc ) = 2.979 mA
* ( - ก I = == = 2.5 mA
C
2.1.5.2 ก
ก.
$
R C , R E , R (+# R
B
B
2
1
"


$ %
.
' $
( ก
)
"
"
( +ก( , 2.5 mA ก .

//0 ก ,
$


ก .
V CE = 0.5V CC (2.21)
V RC = 0.35V CC (2.22)
V RE = 0.15V (2.23)
CC
0.35V CC
R = (2.24)
C
I
C
0.15V CC
R = (2.25)
E
( β + ) 1 I B
F
ก

ก
ก

81
2.




( - ก .
R TH = 15R (2.26)
E
ก ก (2.2a) V = I R + V + I R
TH B TH BE E E
V TH = I R + V BE + ( β + ) 1 I R (2.27)
B E
B TH
F
R
V CC TH V CC TH ; (2.28)
R
R B 1 = , R B 2 =
V V − V )
TH ( CC TH
,
2.13 ก .
R C , R E , R R
B
2
1
B
- .
ก ก (2.21), (2.22) (2.23)
×
=
V = 0.5 12 6 V
CE
×
V RC = 0.35 12 = 4.2 V
=
×
V = 0.15 12 1.8 V
RE
×
I 2.5 10 − 3
I = C = = 20.833 µA
B
β 120
F
×
0.35V 0.35 12
ก ก (2.24) R = CC = = 1,680 Ω
C − 3
×
I C 2.5 10
×
0.15V 0.15 12
ก ก (2.25) R = CC = = 714.061 Ω
E − 6
( β + ) 1 I B 20.833 10 (120 1+ )
×
F
×
=
ก ก (2.26) R TH = 15R = 15 714.061 10.710 kΩ
E
ก ก (2.27) V = I R + V + ( β + ) 1 I R
TH B TH BE F B E
×
×
V TH = ( 20.833 10 − 6 × 10.710 10 3 ) + 0.6

×
×
+ ( 121 20.833 10 − 6 × 714.061 )
V TH = 2.623 V
×
×
R
V CC TH 12 10.710 10 3 48.997 kΩ
ก ก (2.28) R = = =
B 1
V TH 2.623
×
×
V CC TH 12 10.710 10 3
R
R = = = 13.705 kΩ
B 2 − ) )
V
( CC V TH (12 2.623−
Ω Ω
Ω Ω Ω
R = == = 1.68 k , R = =Ω Ω E = = 714.061 , R B 1 = = = = 48.997 k , R B 2 = = = = 13.705 k ;
Ω
Ω
Ω
Ω Ω Ω
Ω Ω Ω
C
2.1.5.3 ก
)+



$ )D


E
(
- ก! % " กก ก !! .
# (,5
" (,
. "
(,5
4
% .

%" * '" A-1
; <
ก ก.

ก

ก
ก

82
2.




R = 1.68 kΩ (,5
4
R = 1.6 kΩ
C
C
R = 714.061 Ω (,5
4
R = 680 Ω
E E
R B 1 = 48.997 kΩ (,5
4
R B 1 = 47 kΩ
R = 13.705 kΩ (,5
4
R = 13 kΩ
B 2 B 2
2.1.5.4 ก

F .
!
% ก ! ( - '" "
%
4


V − V )
( TH
ก ก (2.3) I = BE
B
R TH + ( β + ) 1 R E
F
I
ก ก (2.4) I = β F B
C
}
ก ก (2.5) V = V − I R + ( β + ) 1 I R
CE CC { C C F B E
-
"
∗. (. V " < 3 (ก&
0.5 V
" . ก(ก&
. .(,
, R .
)
&
-
±
CE B 1
R .
2
B
,
2.14 ! %
%
& (

)
×
×
V CC B 2 12 13 10 3 2.6 V
R
- .
ก ก (2.1) V = = =
TH
×
×
3
( R B 1 + R B 2 ) ( 47 10 + 13 10 3 )
3
×
×
R R 2 47 10 × 13 10 3 10.183 kΩ
1 B
B
ก ก (2.2) R = = =
TH
×
3
×
( R B 1 + R B 2 ) ( 47 10 + 13 10 3 )
(V − V ) (2.60 0.6− )
ก ก (2.3) I = TH BE = = 21.630 µA
B
3
×
×
R TH + (β + ) 1 R E 10.183 10 + (121 680 )
F
I =
×
ก ก (2.4) I = β F B 120 21.630 10 − 6 = 2.595 mA
×
C
}
I R +
ก ก (2.5) V CE = V CC − { C C ( β + ) 1 I R
F
B E
×
×
+
×
×
V CE = 12 − ( { 2.595 10 − 3 × 1.6 10 3 ) ( 121 21.630 10 − 6 × 680 )}
V CE = 6.068 V
I = == = 21.630 µA, I = == = 2.595 mA,V = = = = 6.068 V;
B C CE
2.1.5.5 ก
ก.
$
C , C (+# C
B C E
(3- ก
ก ก !! # ก .
C ! ) ก "
B

('- ( " (!
ก

ก
ก

83
2.



C % .
" % ! 3 ก ! ก % ." & & (
E
; 3(,5
ก % //0 ก !

C % .
" % ('- //0 ก ! , R
C
L
1
ก ก (2.13) F ( L C B ) =
π
C
2 R
FLCB B
1
C = (2.29)
B
π
2 R FLCB F ( L C B )
* % F -
"
L
R BB ( r bb′ + r b e ′ ) R R
R FLCB = R + , F ( L C ) = F R BB = B 1 B 2
g
L
( R BB + r bb′ + r b e ′ ) B ( R B 1 + R B 2 )
1
ก ก (2.14) F =
( L C E ) 2 R FLCE C E
π
1
C = (2.30)
E
2 Rπ FLCE F ( L C E )
* % F -
"
L
Ω
R FLCE = X C E = 0.5 , F ( L C E ) = F L ;
1
ก ก (2.15) F =
( L C C )
π
2 R FLCC C
C
1
C = (2.31)
C
2 Rπ FLCC F ( L C C )
Ω
* % R = X = 0.5 , F = F ;
FLCE C E ( L C E ) L
F -
"
L
,
2.15 ก .
C C C
B , E C
1
- .
ก ก (2.29) C =
B
π
2 R FLCB F ( L C B )
10.183 kΩ
* % R BB =
×
2.595 10 − 3
g = = 100.972 mS
m
×
25.7 10 − 3
β 120
r b e ′ = o = = 1.188 kΩ
×
g m 100.972 10 − 3
ก

ก
ก

84
2.




+
×
×
r
R BB ( bb′ + r b e ′ ) 10.183 10 3 ( 2 1.188 10 3 ) 1.14 kΩ
R = R + = 75 + =
FLCB g ) 3 3
×
+
×
( R BB + r bb′ + r b e ′ ( 10.183 10 + 2 1.188 10 )
F ( L C B ) = F = 1 MHz
L
1 = 1
C =
B 2 Rπ FLCB F ( L C B ) 2 3.14 1.14 10 × 1 10
×
×
6
×
×
3
C = 139.680 pF
B
1
ก ก (2.30) C =
E
π
2 R FLCE F ( L C E )
Ω
* % R FLCE = X C E = 0.5 , F ( L C E ) = F = 1 MHz;
L
1 1
C = = = 0.3184 µF
E
π
×
×
×
×
2 R FLCE F ( L C E ) 2 3.14 0.5 1 10 6
1
ก ก (2.31) C =
C
π
2 R FLCC F ( L C C )
Ω
* % R FLCC = 0.5 , F ( L C E ) = F = 1 MHz;
L
1 1
C = = = 0.3184 µF
C
π
×
×
×
×
2 R FLCC F ( L C C ) 2 3.14 0.5 1 10 6
C = == = 139.680 pF,C E = 0.3184 µF, C = == = 0.3184 µF;
B
C
2.1.5.6 ก
)+
, กG )
# F $ )D


E
('
( ก
ก ! "
%
* '" A-4
; <
ก ก.
C = 139.680 pF (,5
4
C = 150 pF ( &ก
B
B
C = 0.3184 µF (,5
4
C = 0.33 µF %
%
E E
C = 0.3184 µF (,5
4
C = 0.33 µF %
%
C
C
2.1.5.7 ก

F
L
C % .
" % ! )
"
ก !ก % ( -
B
" '" (ก+!, ) 4
1
ก ก (2.13) F = F =
L ( L C B )
π
C
2 R FLCB B
,
2.16 ! F ( - '" 4
L
1
- .
ก ก (2.13) F = F ( L C ) =
L
π
B
C
2 R
FLCB B
Ω
* % R BB = 10.183 k , C = 150 pF;
B
ก

ก
ก

85
2.




+
×
×
R BB ( bb′ + r b e ′ ) 10.183 10 3 ( 2 1.188 10 3 )
r
R FLCB = R + = 75 + = 1.14 kΩ
g
3
×
×
+
( R BB + r bb′ + r b e ′ ) ( 10.183 10 + 2 1.188 10 3 )
1 = 1
=
F =
L F ( L C B ) 2 R FLCB B 2 3.14 1.14 10 × 150 10 − 12
π
3
×
×
×
×
C
F = 931.202 kHz
L
F - 931.202 kHz # ก 1 MHz
- '" "
L
2.1.5.8 ก

F
H
C R ! )
"
R (,5
"
%
% (

FH
T
FH
C ก ! ก % ( - '" 4
T
1
ก ก (2.17) F =
H
2 Rπ C
FH T
,
2.17 ก ! F
H
1
- .
ก ก (2.17) F =
H
π
C
2 R FH T
×
2.595 10 − 3
=
Ω
* % R BB 10.183 k , g = − = 100.972 mS;
m
×
25.7 10 3
β 120
r b e ′ = o = = 1.188 kΩ
g × − 3
m 100.972 10
 R R  ( 75 10.183 10 3 )
×
×


R FH 1 = r  bb′ + g BB  = 2 + = 76.451 Ω
×
+
 ( R + R BB )  ( 75 10.183 10 3 )


g
3
×
r R 1 1.188 10 × 76.451
′
b e FH
R FH = = = 71.828 Ω
×
3
r
( b e ′ + R FH 1 ) ( 1.188 10 + 76.451 )

×
3
R R 1.6 10 × 75
C L
R = = = 71.641 Ω
out )
( R + R L ( 1.6 10 + 75 )
×
3
C
C b c ′ = C ob = 0.65 pF
×
100.972 10 − 3 − 12
×
C b e ′ = 9 − ( 0.65 10 ) = 1.823 pF
×
×
×
2 3.14 6.5 10
C = 1.823 10 − 12 + 0.65 10 − 12 { 1+ ( 100.972 10 − 3 × 71.641 )} = 7.174 pF
×
×
×
T
1 1
F = =
H
2 Rπ FH T 2 3.14 71.828 7.174 10 − 12
×
×
×
×
C
F = 309.019 MHz
H
=
F == = 309.019 MHz # ก 250 MHz
- '" "
H
ก

ก
ก

86
2.




2.1.5.9 ก

A V (F Mid ) , A V (F L ) (+# A V (F H )


V o g r Z g r Z
′
′
m b e out
m b e out
ก ก (2.10) A V (F Mid ) = − = − ) = −
r
E
i ( bb′ + r b e ′ Z i
V o g r Z Z in
′
m b e out
ก ก (2.11) A V (F Mid ) = − = − ×
E
g Z i R + Z in
g
V o
ก ก (2.16) A V (F L ) = − E g = 0.707A V (F Mid ) 45
V o
ก ก (2.18) A V (F ) = − = 0.707A V (F ) − 45
H
E g Mid
V o V o V o V o
,
2.18 ! A V (F Mid ) = − E i , A V (F Mid ) = − E g , A V (F L ) = − E g , A V (F H ) = − E g ;
V o g r Z
′
m b e out
- .
ก ก (2.10) A = − = −
V (F Mid )
E
i Z i
×
2.595 10 − 3
* % g = = 100.972 mS
m
×
25.7 10 − 3
β o 120 3
×
Ω
+
Ω
r b e ′ = = − = 1.188 k , Z = r bb′ + r b e ′ = ( 2 1.188 10 ) = 1.190 k ;
i
×
g m 100.972 10 3
+
×
Z = r bb′ + r b e ′ = ( 2 1.188 10 3 ) = 1.190 kΩ
i
×
3
×
R Z 10.183 10 × 1.190 10 3
Z = BB i ) = 3 3 = 1.065 kΩ
in
+
×
×
( R BB Z i ( 10.183 10 + 1.190 10 )
3
×
R R 1.6 10 × 75 71.641 Ω
C L
Z = R = = =
out out ( R + ) ( 3 )
×
C R L 1.6 10 + 75
×
3
×
V o 100.972 10 − 3 × 1.1833 10 × 71.641 7.193
A V (F Mid ) = − = − = −
×
E
i ( 1.190 10 3 )
×
V o 1.065 10 3
)
ก ก (2.11) A = − = − ( 7.193 ×
V (F Mid ) 3
×
+
E g ( 75 1.065 10 )
A V (F Mid ) = − ( 7.193 0.934× ) = − 6.718
V o
ก ก (2.16) A V (F ) = − = 0.707A V (F ) 45
L E g Mid
V o
A V (F ) = − = − (0.707 6.718× ) = − 4.749 45
L
E g
V o
ก ก (2.18) A V (F H ) = − E g = 0.707A V (F Mid ) − 45
ก

ก
ก

87
2.





A V (F H ) = − (0.707 6.718× ) = − 4.749 − 45


= =
== =
= − −− −
A V (F ) == = 6.718, A V (F ) = − −− − 4.749 45 , A V (F ) = − −= − − 4.749 − −− − 45 ;
Mid L H
2.1.5.10 ก

F*+,กH*#
%&&'
!
(3- , ; %
& ( %
# (,5
" % ก


! ) ก? % //0 %
& ( * '" ก
V CC ≤ V CEO (2.32)


I < (2.33)
C 0.5I C (MAX)

I <
V CE C P (2.34)
D
,
2.19 ! ) ก? % //0 %
& (
- .
ก ก (2.32), (2.33) (2.34)


V CC ≤ V CEO
≤
12 V 12 V
-
V∴ CC
" ก . (% ก ! V CEO &

I < 0.5I C (MAX)
C
−
3
×
×
2.595 mA < (0.5 100 10 )
<
2.595 mA 50 mA
∴
I
" ก 0.5I &
C C (MAX)
I <
V CE C P D
×
×
6.068 2.595 10 − 3 < 600 mW
15.746 mW < 600 mW
∴ V I
" ก P &
CE C D
%
& ( ( .



2.1.5.11 ก

F*+,กH*#
%&&'
,
(3- , ; "
%
%
# (,5
" ( - ก '"

"
%
% %
ก //0 % (. * , ก ก //0 % (ก& #$
& 2 (%

1 1 1
%
ก //0 "
%
" ก , , ,1, 2,3, 5,10,12 20 W <& 3 1%,5%,
8 4 2

ก

ก
ก

88
2.



10% 20%

) , " ก ก
2.1.5.11.1 %
ก //0 R . - (P
C R C
( 2 0.35V CC ) 2
P = (2.35)
R C
R
C
) , " ก ก
2.1.5.11.2 %
ก //0 R . - (P R E
E


( 2 0.15V CC ) 2
P R = (2.36)
E
R E

2.1.5.11.3 %
ก //0 R . - (P ) , " ก ก
B 1 R B 1

V
2 V ) 2 2 V − ( BE + V R )} 2
{ CC
( R
P = B 1 = E (2.37)
R B 1 R B 1 R B 1
2.1.5.11.4 %
ก //0 R . - (P ) , " ก ก
B 2 R B 2


2 V ) 2 ( 2 V BE + V R ) 2
( R
P R = B 2 = E (2.38)
B
2
R B 2 R B 2
,
2.20 ! ) ก? % //0 "
%


( 2 0.35V CC ) 2 ( 2 0.35 12× ) 2
- .
ก ก (2.35) P R C = R C = 1.6 10 3 = 22.05 mW
×

R = 1.6 kΩ ± 5% ( - ก '"
1 W (125 mW)
C
8
×
( 2 0.15V CC ) 2 ( 2 0.15 12 ) 2
ก ก (2.36) P R = = = 9.529 mW
E R E 680
R = 680 Ω ± 5% ( - ก '"
1 W (125 mW)
E
8
V
2 V − ( BE + V R )} 2 2 {12 − (0.6 1.8+ )} 2
{ CC
ก ก (2.37) P = E = = 3.921 mW
R B 1 3
×
R
B 1 47 10
R B 1 = 47 kΩ ± 5% ( - ก '"
1 W (125 mW)
8
2 V ) 2 2 V + V R ) 2 ( 2 0.6 1.8+ ) 2
( R
( BE
ก ก (2.38) P = B 2 = E = = 0.886 mW
R B 2 3
×
R
B 2 R B 2 13 10
ก

ก
ก

89
2.





R = 13 kΩ ± 5% ( - ก '"
1 W (125 mW)
B 2
8
" "
%

$

R = 1.6 kΩ ± 5% 1 8 W
C
R = 680 Ω ± 5% 1 8 W
E
R B 1 = 47 kΩ ± 5% 1 8 W

R = 13 kΩ ± 5% 1 8 W
B 2
2.1.5.12 ก

F*+,กH*#
%&&'
, กG )
# F

(3- , ;
ก %
# (,5
( - ก '" (ก+!, %
"
)


%

ก ก
% ก & 2 (%
2.1.5.12.1 %

ก C , " ก ก
C
V C C = ( 2 0.5V CC + 0.15V CC ) = ( 2 0.65V CC ) (2.39)

2.1.5.12.2 %

ก C , " ก ก
E

V C E = ( 2 0.15V CC ) (2.40)
2.1.5.12.3 %

ก C , " ก ก
B
V = 2 (0.15V + 0.6 V ) (2.41)
C B CC
)
2.1.5.12.4 (ก+!, % (. ก !ก '"



" ก

1) '
& ก (Mica) ( &ก (Ceramic) $ 1.8 pF

# 820 pF 0.001 µF
# 0.22 µF %

ก 50 V,100 V, 300 V, 500 V, 600 V
1000 V


2) '
& %
% (Tantalum) $ 0.10 µF
# 330 µF
%

ก 6.3 V,10 V,16 V, 20 V 50 V


,
2.21 ก ! ) ก? % //0 (ก+!, )

- .
ก ก (2.39) V C C = ( 2 0.5V CC + 0.15V CC ) = ( 2 0.65V CC ) = ( 2 0.65 12× ) 15.6 V=

C = 0.33 µF '
& %
% %

ก 16 V
C
ก ก (2.40) V C E = ( 2 0.15V CC ) 2 0.15 12= ( × ) 3.6 V=
C = 0.33 µF '
& %
% %

ก 16 V
E
ก ก (2.41) V = 2 (0.15V + 0.6V ) = 2 ( { 0.15 12× ) 0.6+ } = 4.8 V
C B CC
ก

ก
ก

90
2.




C = 150 pF '
& ( &ก %

ก 50 V
B
" (ก+!, )
$


C = 150 pF 50 V ( &ก
B
C = 0.33 µF 16 V %
%
E
C = 0.33 µF 16 V %
%
C



2.2



&


V DD = 20 V
V = − 5 V,BV = − 25 V;
R G1 R D P GSS
C D 0.047 F
590 kΩ 1.8 kΩ C iss = 4 pF,C rss = 1 pF;
N-CH D
C G 100 pF
G
Q 1
R g R L V o
75 Ω S 2 kΩ
E i
R G2
R S
E g 47 kΩ 750 Ω C S
0.1 F

,% 2.19

* '"( (/
2.2.1 ก


#$!
%&&'
ก
#(

"
(3- , ) %
(/ # , ก ! I ,V
V ก ,
D DS GS
"
% 2.20
(
ก
V = V GS + V (2.42)
RS
G
 I 
V GS = V P   1− D  (2.43)

 I DSS 

R
V DD G 2 (2.44)
V = V =
R G 2 G + )
R
( G 1 R G 2
I D
V
R D
V = − 5 V
Q 1 V DS P
BV GSS = − 25 V
V GS
V G
V R S


,% 2.20 //0 ก ,% 2.19

ก

ก
ก

91
2.




V = I R + V + I R (2.45)
DD D D DS D S

V DD (2.45a)
I DSS =
R +
D R S

 V  2
I = I DSS  1− GS  (2.46)
D
 V P 

* % I - ก (
. <
R ( " (
ก <
R ก
S
D
D
- ก (
) % (ก ก
I
DSS
V -
//0 . (ก ก !
GS
V -
//0 % % ."ก (
(,5
@
P
ก ก (2.42) V = V + V
G GS RS
(
- ก V RS = I R
D S
V = V + I R
G GS D S
 V  2
%
I = I DSS  1− GS 
ก V = V GS + I R "
D
G
D S
 V P 
 V  2  V  2
V = V + I R 1− GS = V + I R 1− GS
G GS DSS S   GS DSS S  
 V P   V P 
 2V V 2 
V = V + I R 1  − GS + GS 
GS
DSS
S
G
 V ) 2 
V
 P ( P 
 2 
R V
V = V + I  R − 2I DSS S GS + I DSS R V GS 
S
G GS  DSS S V ) 2 
V
 P ( P 
2I R V I R V 2
R −
V = V GS + I DSS S DSS S GS + DSS S 2 GS
G
V
V P ( P )
2
I R V 2I R V
R −
0 = DSS S GS + V GS − DSS S GS + I DSS S V G
(V P ) 2 V P
2 
R 
R −
I DSS R V GS 2I DSS S
0 = +  1−  V GS + I DSS S V G
S
V ) 2  V P 
( P
I R V 2  2I R 
R −

$
0 = DSS S GS +  1− DSS S  V GS + I DSS S V (2.47)
G
(V P ) 2  V P 
I R  2I R 
* % a = DSS S , b =  1− DSS S  , c = I DSS S V G ;
R −
V ) 2  V P 
( P
ก

ก
ก

92
2.




2
− b ± b − 4ac
V GS = (2.48)
2a
∗. (. ) V * ( - ก % ก V (,5
%
ก "
P
GS
,
2.22 ก ,% 2.20 , V I
GS D
×
×
R
V DD ( G 2 ) 20 47 10 3 1.475 V
- .
ก ก (2.44) V = V = = =
R G 2 G ( R G 1 + R G 2 ) ( 590 10 + 47 10 3 )
×
×
3
V DD 20 7.843 mA
ก ก (2.45a) I DSS = = =
R + R ( 1.8 10× 3 + )
D S 750
2
− b ± b − 4ac
ก ก (2.48) V GS =
2a
×
I R 7.843 10 − 3 × 750
* % a = DSS S = = 0.235
V ) 2 ( ) 5− 2
( P
 2I R   2 7.843 10 − 3 × 750 
×
×
b =  1− DSS S  =  1−  = 3.352
 V P    − 5  
)
=
×
R −
c = I DSS S V = ( 7.843 10 − 3 × 750 − 1.475 4.407
G
)
2
− (3.352 + (3.352 ) − (4 0.235 4.407× × )
V =
GS 1 )
×
(2 0.235
− (3.352 ) 2.663+
V = = − 1.465 V
GS 1
0.47
)
2
− (3.352 − (3.352 ) − (4 0.235 4.407× × )
V =
GS 2 )
(2 0.235×
− (3.352 ) 2.663−
V GS 2 =
0.47
V = − 12.797 V
GS 2
 V  2
ก ก (2.46) I = I DSS  1− GS 
D
 V P 
* % I = 7.843 mA,V = − 5 V,V = − 1.465 V;
DSS P GS
I = 7.843 10 − 3   1− − 1.465   2 = 3.92 mA
×
D
 − 5 
=
== =
V GS = = = = V GS 1 = − −− − 1.465 V, I == = 3.92 mA;
D
ก

ก
ก