143
3.
g m
ก !ก (1.16) C b c ′ = C ob = C re ,C b e ′ = − C ob ;
π
2 F T
2 C N
2
ก !ก (3.11) C N S = P P
S
2
C N
C = S S
P 2
N P
, C = C , N = N , C = C , N = N ;
′
P b ep P 11 S b e ′ S 21
2
C N 21
b e ′
C b ep = (3.25)
′
N 2 11
1
ก !ก (3.1b) F =
R
2π LC
, F = F ( R L 11 ) , L = L 11 , C = C BT + C b ep ;
′
R
1
F R (L 11 ) =
2π L 11 ( C BT + C b ep )
′
1
( C BT + C b ep ) = 2
′
( )
π
L 11 ( 2 F R L 11 )
1
$
C BT = 2 − C b ep (3.26)
′
( )
π
L 11 ( 2 F R L 11 )
1
ก !ก (3.1b) F =
R
2π LC
, F = F ( R L 22 ) !8 ,.
.' L
R
22
L = L 22 , C = C CT ;
1
$
C = (3.27)
CT 2
L ( 2 Fπ )
22 R (L 22 )
"#
3.19 + %! 9 C % C
BT CT
g m ;
- ,
ก !ก (1.16) C b c ′ = C ob = C re ,C b e ′ = − C ob
π
2 F T
×
397.937 10 − 3 − 12 209.919 pF
×
C b e ′ = 6 − 1.3 10 =
×
×
×
2 3.14 300 10
×
C N 2 21 = 209.919 10 − 12 ( ) 1 2 209.919 pF
b e ′
ก !ก (3.25) C = = =
′
b ep 2 2
N 11 ( ) 1
ก
ก
ก
144
3.
1
ก !ก (3.26) C BT = 2 − C
′
b ep
π
L 11 ( 2 F ( R L 11 ) )
1 − 12
×
C BT = 2 − 209.919 10 = 53.171 nF
×
×
×
×
1.90 10 − 6 ( 2 3.14 500 10 3 )
1 1
ก !ก (3.27) C = =
CT 2 2
π
×
×
×
×
L 22 ( 2 F ( R L 22 ) ) 238 10 − 6 ( 2 3.14 500 10 3 )
C CT = 426.151 pF
" C = = = = 53.171 nF,C = = = = 426.151 pF;
BT CT
3.6.9 ก
$
"# ก1 $
&@.* $I
"
J
)
C BT = 53.171 nF +;
9 ! & D
C BT = (47 nF 5.6 nF ) . !(ก (52.6 nF
)
C CT = 426.151 pF +;
9 ! & D
C CT = (390 pF 39 pF ) . !(ก(429 pF
3.6.10 ก
$
'
B
W (L 11 )
B 9
' ( ' &
9 L & 9 r ,C % R ,
′
′
W (L 11 ) 11 b ep b ep g
r ก( กก r
&9 L
′
b e ′
11
b ep
r N 2 11
b e ′
r b ep =
′
N 2
21
C N 2 21
b e ′
ก !ก (3.25) C b ep = 2
′
N
11
1 (3.27a)
B W (L ) =
11 π + )
2 R ( C BT C b ep
′
R r ′
g b ep
, R =
R + r b ep
′
g
3.6.11 ก
$
'
B W (L 12 )
B W (L 12 ) 9
' ( ' &
9 L , & 9 R L (ab) % C CT (ab)
12
1
ก !ก (3.18) B W (L ) =
π
12
R
2 C CT (ab) L (ab)
C CT N 2 22
ก !ก (3.15) C CT (ab) = 2
N
12
2
R N 12
L
ก !ก (3.16) R =
L (ab) 2
N 32
ก
ก
ก
145
3.
"#
3.20 + %! 9 B W (L 11 ) % B W (L 12 )
β o 120
- ,
ก !ก (1.10) r b e ′ = = = 301.555 Ω
×
g m 397.937 10 − 3
2 2
r N 11 301.555 ( ) 1
b e ′
r b ep = 2 = 2 = 301.555 Ω
′
N ( ) 1
21
2 × − 12 2
C N 21 209.919 10 ( ) 1 209.919 pF
b e ′
ก !ก (3.25) C b ep = = =
′
N 2 ( ) 1 2
11
×
R r ′ 75 301.555
g b ep
ก !ก R = = = 60.061 Ω
R + r b ep (75 301.555+ )
′
g
1
ก !ก (3.27a) B =
W (L 11 ) )( − 9 − 12 )
×
×
×
×
( 2 3.14 60.061 52.6 10 + 209.919 10
B (L ) = 50.203 kHz
W 11
×
C CT N 2 22 429 10 − 12 ( ) 2 1.716 nF
10
ก !ก (3.15) C CT (ab) = 2 = 2 =
N ( ) 5
12
R N 2 12 75 ( ) 5 2
L
ก !ก (3.16) R L (ab) = 2 = 2 = 1.875 kΩ
N ( ) 1
32
1 1
ก !ก (3.18) B W (L ) = =
π
12
×
×
2 C CT (ab) L (ab) ( 2 3.14 1.716 10 − 9 × 1.875 10 3 )
×
×
R
B W (L 12 ) = 49.490 kHz
" B = = = = 50.203 kHz, B = = = = 49.490 kHz;
' ( ' + %! 50 kHz
W (L 11 ) W (L 12 )
3.6.12 ก
$
'
F R (L 11 ) F R (L 12 )
+;
9 !8 ,.
.' &
9 L % L & !
, F ( R L 11 ) % F ( R L 12 ) 11 12
C N 2 21
b e ′
ก !ก (3.25) C b ep =
′
N 2
11
2
C CT N 22
ก !ก (3.15) C CT (ab) =
N 2
12
1
ก !ก (3.13) F R (L ) =
21
2π L 21 (C BT + C b e ′ )
, F R (L 21 ) = F ( R L 11 ) , L = L 11 ( , C BT + C b e ′ ) ( C= BT + C b ep ) ;
′
21
1 (3.28)
$
F R (L 11 ) =
2π L 11 ( C BT + C b ep )
′
ก
ก
ก
146
3.
1
ก !ก (3.14) F =
R (L 12 ) 2π L C (ab)
12 CT
"#
3.21 + %! 9 F ( R L 11 ) % F ( R L 12 )
2
C N 21 209.919 pF
b e ′
- ,
ก !ก (3.25) C = =
′
b ep 2
N 11
1
ก !ก (3.28) F =
R (L 11 )
2π L (C + C )
′
11 BT b eP
1
F R (L ) =
11 (2 3.14× ) 1.90 10× − 6 ( 52.6 10 − 9 + 209.919 10 − 12 )
×
×
F = 502.696 kHz
R (L 11 )
2
C CT N 22
ก !ก (3.15) C = = 1.716 nF
CT (ab) 2
N 12
1
ก !ก (3.14) F =
R (L 12 ) 2π
L C
12 CT (ab)
1 498.337 kHz
F = =
( R L 12 ) (2 3.14× ) 59.50 10× − 6 × 1.716 10 − 9
×
" 9 !8 F % F "ก 500 kHz % ! 8+ &9 9 !8 ก 9 ,
R (L 11 ) R (L 12 )
ก + ก
T %T
1 2
*
3.7
@A
กCK "
±
C F 1 F R = 5.5 MHz,B W = 60 kHz;
V BE = 0.6 V,β = β = 100,
F
o
Ω
C = 0.5 pF,F = 7 GHz,r bb′ = 2 ;
ob T
C
F 1
Q 1
V o
E g E 1 i E 2 i
Z incf C = C = C = 0.056 µF/50 V
C
E
B
+ 3.17
, "- /(,. . !(ก01 &
'
$
ก + 3.17 ! %
:-
− C /(,. . !(ก01 & 5.5 MHz +;
)+ก '+ % 3 /(,. ?ก& (ก
ก
'
(
F 1
ก
ก
ก
147
3.
!8 5.5 MHz <9
9
$
/ "
' ( '+ %! 60 kHz ± %& ก
"
(R + R CF 1 ) + %! 600 Ω % Z incf + %! 600 Ω ! % /( ! &(!"
3 <
ก .
g
− Q
.( & '
00> "
#$
, )
- $
& ก '
1
! 9 H FE > 80, C ob < 1 pF % F > 800 MHz
T
3.7.1 ก
.
BCCD
ก
+"
ก + 3.17 ! 8 "
9"
+ 00> ก % & "
+ 3.18 , C
$
!9 !"
00> ก % &
<9
# 8 ก& ก
F 1
I I
R B 1 C
β F B
I
I Q 1
B
V BE = 0.6 V
I R B 2 I = I + I C
B
E
+ 3.18 00> ก % & + 3.17
ก ( %
' 00> ก % & + 3.18 / + %! 9 )
Q
1
, I % V .# ! 8
!ก &9 +
$"-
I B C CE
R
V CC B 2
ก !ก (2.1) V =
TH
( R B 1 + R B 2 )
R R 2
1 B
B
ก !ก (2.2) R =
TH
( R B 1 + R B 2 )
V − V BE )
( TH
ก !ก (2.3) I =
B
R + ( β + ) 1 R
TH F E
ก !ก (2.4) I = β I
C F B
}
ก !ก (2.5) V = V − I R + ( β + ) 1 I R
CE CC { C C F B E
3.7.2 ก
.
BCCD
ก
++ #
ก + 3.19 C % ,.
.' 5.5 MHz ! 9 !&
(Z )
F 1 icf
+ %! 215 Ω % !ก &9 +
$
ก
ก
ก
148
3.
C F 1
R CF1 R CF2 r bb′
B b′ Q 1 C
Z I b I c
R g icf I i
215Ω r b e ′ V b e ′ g V
m b e ′
E g E i E 1 i E 2 i R BB R C R L V O
E
Z in Z i Z incf Z out
+ 3.19 00> ก % !8 ,.
.' 5.5 MHz
I C (dc ) I C (dc )
ก !ก (1.9) g = =
m
V T (k T q )
B
β o
ก !ก (1.10) r b e ′ =
g m
Z = R + Z (3.29)
in CF 1 icf
, Z 9 (!/
.'
!8 ,.
.'
in
Z = R + R (r + r )}
incf CF 2 { BB bb′ b e ′
R BB (r bb′ + r b e ′ )
$
Z incf = R CF 2 + (3.30)
( R BB + r bb′ + r b e ′ )
9 (!/
.'
!8 ,.
.' Q
, Z incf 1
(
ก C ! 9
. -
+ %! 6 dB & ก + %! 9 E %
'
i
1
F
2
!ก
E i
20 log 1 = 6 dB
10 E
i 2
E i 6
log 1 = = 0.3
10
E i 2 20
0.3 1.995 2
10 = ≈
E i 1 = 2
E i 2
E
E = 1 i ≈ 0.5E
i 2 2 i 1
$
E = 0.5E
i
i
1
2
ก
ก
ก
149
3.
R R
C L
ก !ก (2.9) Z = R = ( R R ) =
out out C L R + )
( C R L
V = g V Z
′
m b e out
o
R ( bb′ + r )
r
E = I Z = I i R CF 2 + BB b e ′
i incf
i
2
( R BB + r bb′ + r b e ′ )
R ( R + r + r ) R ( bb′ + r )
+
r
E = I i CF 2 BB bb′ b e ′ BB b e ′
i
2
( R BB + r bb′ + r b e ′ )
E i ( R BB + r bb′ + r b e ′ )
I = 2
i
R ( R + r + r ) R+ (r + r )
CF 2 BB bb′ b e ′ BB bb′ b e ′
I R = E R BB
i
i BB
I =
2
b ( R BB + r bb′ + r b e ′ ) R CF 2 ( R BB + r bb′ + r b e ′ ) R BB (r bb′ + r b e ′ )
+
V b e ′ = I r
b b e ′
E R r
BB b e ′
i
V b e ′ = 2
r
R CF 2 ( R BB + r bb′ + r b e ′ ) R+ BB ( bb′ + r b e ′ )
ก E = 0.5E
i
i
1
2
)
(0.5 E R r
BB b e ′
i
V b e ′ = 1
R CF 2 ( R BB + r bb′ + r b e ′ ) R+ BB ( bb′ + r b e ′ )
r
)
V o (0.5 g Z r R (3.31)
′
m out b e BB
A = − = −
V (F R ) E i 1 R CF 2 ( R BB + r bb′ + r b e ′ ) R+ BB ( bb′ + r b e ′ )
r
, A &
!8 ,.
.'
V (F R )
3.7.3 ก
.
BCCD
ก
++ #
"# *
+
)
ก + %! 9 !8 &
(F , F 9 !8 &
"
X C T
H
H
9
! 9 9 ก 9 !&
& X %! < "
A ! 9 9 ก 0.707A +;
ก
C T V (F H ) V (F R )
& ! ! 8
.( & "
ก
"
9
!8 9
'
) !8 " & F %& ก 9 F ก ก % 9 +;
(
9
R
H
ก + 3.20 +;
ก ก
!ก R
&9 X
C
FH
T
R FH = ( { R CF 2 R BB ) r+ bb′ } r
b e ′
)
R R + r bb′ ( CF + R BB
R
R FH = CF 2 BB + 2 ) r b e ′
R
( CF 2 R BB
R 2 BB + r bb′ ( CF 2 + R BB )} b e ′
R
R
r
{ CF
R =
FH + + + +
R
r
R
R
R
{ CF 2 BB r bb′ ( CF 2 R BB )} ( CF 2 R BB ) b e ′
ก
ก
ก
150
3.
1
ก !ก (2.17) F =
H
π
C
2 R FH T
r bb′ b′ C = C b e ′ + C b c ′ (1 g R+ m out )
T
Q 1
r b e ′ C T
E
2 i
R FH
R
R
r
R
R FH = { CF 2 BB + r bb′ ( CF 2 + R BB )} b e ′
+
R
R
r
{ CF 2 BB + r bb′ ( R CF 2 + R BB )} ( R CF 2 + R BB ) b e ′
+ 3.20 ก + %! 9 R
FH
)
ก !ก (2.18) A = (0.707 A − 45
V (F H ) V (F Mid )
ก A = A
V (F Mid ) V (F R )
V o
)
−
A V (F H ) = − = (0.707 A V (F R ) (3.32)
45
E i 1
"#
3.22 ก + 3.17 + %! 9 I B , I C ,V CE , F B W , A V (F R ) , F %T = 25 C
,
H
R
A
×
×
V CC B 2 12 6.9 10 3
R
- ,
ก !ก (2.1) V TH = = = 2.679 V
3
×
×
( R B 1 + R B 2 ) ( 24 10 + 6.9 10 3 )
3
×
×
R R 2 24 10 × 6.9 10 3 5.359 kΩ
B
1 B
ก !ก (2.2) R = = =
TH )
×
3
( R B 1 + R B 2 ( 24 10 + 6.9 10 3 )
×
V − V ) ( 2.679 0.6− )
ก !ก (2.3) I = ( TH BE = = 49.833 µA
B 3
×
R TH + (β + ) 1 R E 5.359 10 + (101 360× )
F
ก !ก (2.4) I = β I = 100 49.833 10 − 6 = 4.983 mA
×
×
C F B
}
I R +
ก !ก (2.5) V CE = V CC − { C C ( β + ) 1 I R
B E
F
) (
×
×
×
V CE = 12 − ( { 4.983 10 − 3 × 840 + 101 49.833 10 − 6 × 360 )}
V CE = 6 V
×
×
I C (dc ) I C (dc ) 4.983 10 − 3 × 1.60 10 − 19
ก !ก (1.9) g = = = = 193.872 mS
m
×
V T (k T q ) 1.38 10 − 23 (273 25+ )
B
β 100
ก !ก (1.10) r b e ′ = o = = 515.804 Ω
×
g m 193.872 10 − 3
ก
ก
ก
151
3.
×
R R 840 75 68.852 Ω
C L
ก !ก (2.9) Z = R = ( R R ) = = =
out out C L R + ) +
( C R L 840 75
r
R BB ( bb′ + r b e ′ )
ก !ก (3.30) Z = R +
incf CF 2 )
( R BB + r bb′ + r b e ′
3
×
×
R R 2 24 10 × 6.9 10 3 5.359 kΩ
1 B
B
R = = =
BB )
( R B 1 + R B 2 ( 24 10 + 6.9 10 3 )
3
×
×
)
V o (0.5 g Z r R
′
m out b e BB
ก !ก (3.31) A = − = −
V (F R ) E i 1 R CF 2 ( R BB + r bb′ + r b e ′ ) R+ BB ( bb′ + r b e ′ )
r
, C b c ′ = C ob = 0.5 pF
×
g m 193.872 10 − 3 − 12 3.910 pF
×
C b e ′ = − C ob = − 0.5 10 =
π
×
×
×
2 F T 2 3.14 7 10 9
×
×
C = C b e ′ + C b c ′ (1 g R+ m out ) 3.910 10= × − 12 + 0.5 10 − 12 { 1+ ( 193.872 10 − 3 × 68.852 )}
T
C = 11.084 pF
T
R BB = 5.359 kΩ
)
V o (0.5 g Z r R
′
m out b e BB
A V (F R ) = − = − )
E
i 1 R CF 2 ( R BB + r bb′ + r b e ′ ) R+ BB (r bb′ + r b e ′
×
×
×
×
×
0.5 193.872 10 − 3 × 68.852 515.804 5.359 10 3
A = −
(
V (F R ) 3 3
)
+
75 5.359 10 + + ) 5.359 10 (2 515.804
×
2 515.804 +
×
A = − 5.737
V (F R )
1
ก !ก (3.32) F =
H
π
2 R C
FH T
r b e ′ { CF 2 BB + r bb′ ( CF 2 + R BB )}
R
R
R
, R =
FH + + + )
R
R
R
R
{ CF 2 BB r bb′ ( CF 2 R BB )} r+ b e ′ ( CF 2 R BB
( { 3 ) ( 3 )}
×
+
×
×
515.804 75 5.359 10 + 2 75 5.359 10
R FH = ( { 3 3 )} 3
(
×
+
×
×
+
2 75 5.359 10
75 5.359 10 ) ( + × + 515.804 75 5.359 10 )
×
212.920 10 6
R FH = = 66.231 Ω
( 412.793 10 + 2.802 10 6 )
3
×
×
C = 11.084 pF
T
1
F = = 216.911 MHz
H
×
×
×
×
2 3.14 66.231 11.084 10 − 12
±
−
F R = 5.5 MHz, B W = 60 kHz ( 3 dB);
" I = == = 49.833 µA, I = == = 4.983 mA,V CE = = = = 6 V, F R = 5.5 MHz, B W = 60 kHz ,
± ± ±
±
B
C
=
= − −− −
A == = 5.737, F == = 216.911 MHz;
V (F R ) H
ก
ก
ก
152
3.
3.7.4 ก
ก
@A*
กCK "
Ω
Ω
* ก,
. @ ก
ก V = 12 V, R = 75 , R = 75 ,T = 25 C;
CC g L A
C F 1
Q 1
V o
E E 1 i E 2 i
g
Ω
C F = 5.5 MHz, B = ± 60 kHz,V = 0.6 V, β = β = 85, C = 1 pF, F = 2 GHz, r bb′ = 2 ;
F 1 R W BE F o ob T
+ 3.21
, "- /(,. . !(ก01 & "- ก
'
3.7.4.1 ก
ก,
.
I
C
k T
F T ( B ) q
ก !ก (2.20) I C (dc ) =
F
R FH H ( 2 F C Rπ T b c out + ) 1
′
ก
"
F = 5.5 MHz, R FH = R CF 2 , R out = R L , C b c ′ = C ob ;
H
ก !ก (3.30) Z = R + R (r + r )}
incf CF 2 { BB bb′ b e ′
ก R ! 9 ! 8 % ($
BB
Z incf = ( R CF 2 + r bb′ + r b e ′ )
ก C & ก 9 !&
ก+ %! 600 Ω
$
Z incf %& ! 9 600 Ω
1
F
β
r b e ′ = o
g m
I
ก g = C (dc ) %
m
V T
β V
r b e ′ = o T
I
C (dc )
β V
9 r b e ′ = o T "
!ก Z incf %
I
C (dc )
β V
Z = R + r + o T
incf CF 2 bb′
I C (dc )
β V
o T = Z − ( R + r )
I C (dc ) incf CF 2 bb′
ก
ก
ก
153
3.
β V
$
I = o T (3.33)
C (dc ) )
Z
( incf − R CF 2 + r bb′
!ก (2.20)
9 ก !ก (3.33) %& ! 9 & ก 9 9 I C (dc )
3.7.4.2 ก
ก,
.
R C , R E , R R
B
1
2
B
ก !ก (2.21), (2.22) % (2.23)
V CE = 0.5V CC ,V RC = 0.35V CC ,V RE = 0.15V CC ;
0.35V
ก !ก (2.24) R = CC
C
I C
0.15V
ก !ก (2.25) R = CC
E
( β + ) 1 I B
F
ก !ก (2.26) R TH = 15R
E
ก !ก (2.27) V TH = I R + V BE + (β + ) 1 I R
F
B TH
B E
R
V CC TH
ก !ก (2.28) R =
B 1
V TH
R
V CC TH
R =
B 2 − )
V
( CC V TH
3.7.4.3 ก
"
+ & ,
+ "
ก %
ก +
+;
9 ! & D
R
V CC B 2
ก !ก (2.1) V =
TH
( R B 1 + R B 2 )
R R 2
1 B
B
ก !ก (2.2) R TH =
( R B 1 + R B 2 )
V − V )
ก !ก (2.3) I = ( TH BE
B
R TH + ( β + ) 1 R E
F
I
ก !ก (2.4) I = β F B
C
}
ก !ก (2.5) V = V − I R + ( β + ) 1 I R
CE CC { C C F B E
9 V %& <( / !9 ก(
± 0.5 V
CE
3.7.4.4 ก
ก,
.
C , C C
B E C
ก
"
X C B = X C E = X C C = 0.5 Ω % F ( L C B ) = F ( L C E ) = F ( L C C ) = 9 !8 C
1
F
1
ก !ก (2.29) C =
B
π
2 R F
FLCB ( L C B )
ก
ก
ก
154
3.
1
ก !ก (2.30) C =
E
π
2 R FLCE F ( L C E )
1
ก !ก (2.31) C =
C
π
2 R FLCC F ( L C C )
3.7.4.5 ก
"
+
F
H
I I
ก !ก (1.9) g = C (dc ) = C (dc )
m
V T (k T q )
B
β
ก !ก (1.10) r b e ′ = o
g
m
R R
C L
ก !ก (2.9) Z out = R out = )
R +
( C R L
R R 2
B
1 B
R =
BB )
( R B 1 + R B 2
R
r
R
R 2 BB + r bb′ ( CF 2 + R BB )} b e ′
{ CF
ก !ก (3.29) R =
FH + + + +
R
R
R
R
r
{ CF 2 BB r bb′ ( CF 2 R BB )} ( CF 2 R BB ) b e ′
1
ก !ก (2.17) F =
H
π
2 R FH T
C
3.7.4.6 ก
"
+ A
V (F R )
)
V o (0.5 g Z r R
′
m out b e BB
ก !ก (3.31) A = − = −
V (F R ) E i 1 R CF 2 ( R BB + r bb′ + r b e ′ ) R BB ( bb′ + r b e ′ )
+
r
"#
3.23 ก + 3.21 ก
, "- /(,. . !(ก01 & '
k T
F T ( B ) q
- ,
ก !ก (2.20) I =
C (dc )
π
R F ( 2 F C R + ) 1
′
FH H T b c out
Ω
ก
"
F = 5.5 MHz, R = R = 75 , R = R = 75 ;
Ω
H FH CF 2 out L
C b c ′ = C ob = 1 pF, F = 2 GHz,T = 25 ;
T
A
2 10 × 25.7 10 − 3
×
×
9
I C (dc ) =
) }
×
×
×
×
×
×
9
75 5.5 10 6 ( { 2 3.14 2 10 × 1 10 − 12 × 75 + 1
I C (dc ) = 64.163 mA
β o T
V
ก !ก (3.33) I C (dc ) =
Z − R + r )
( incf CF 2 bb′
Ω
Ω
Ω
ก
"
R CF 2 = 75 , Z incf = 600 , r bb′ = 2 ,V = 25.7 mV;
T
×
×
85 25.7 10 − 3 4.15 mA
I C (dc ) = =
(600 75 2− + )
ก
ก
ก
155
3.
9 ก !ก (3.33) %& ! 9 & ก 9 9 I C (dc ) !ก (2.20)
, ก I = 4 mA
C
×
0.35V 0.35 12
ก !ก (2.24) R = CC = = 1,050 Ω
C
I × − 3
C 4 10
×
I C 4 10 − 3
I = β = 85 = 47.058 µA
B
F
×
0.15V 0.15 12
ก !ก (2.25) R = CC = = 444.775 Ω
E
( β + ) 1 I B 47.058 10 − 6 (85 1+ )
×
F
×
=
ก !ก (2.26) R TH = 15R = 15 444.775 6.671 kΩ
E
ก !ก (2.27) V TH = I R + V BE + (β + ) 1 I R
B TH
F
B E
×
×
V TH = ( 47.058 10 − 6 × 6.671 10 3 ) + 0.6
+ ( 86 47.058 10 − 6 × 444.775 )
×
×
V = 2.692 V
TH
×
×
V CC TH 12 6.671 10 3 29.736 kΩ
R
ก !ก (2.28) R = = =
B 1
V TH 2.692
×
×
V CC TH 12 6.671 10 3 8.6 kΩ
R
R = = =
B 2 − ) (12 2.692− )
V
( CC V TH
1
ก !ก (2.29) C =
B
π
2 R F
FLCB ( L C B )
Ω
, R FLCB = X C B = X C E = X C C = 0.5 , F ( L C B ) = F ( L C E ) = F ( L C C ) = 5.5 MHz;
1
C = = 0.0579 µF
B 6
×
×
×
×
2 3.14 0.5 5.5 10
C = C = C = 0.0579 µF
E
C
B
" ก +
9 R % C +;
9 ! & D
! "
&
1
R = 1, 050 Ω +;
9 ! & D
R = 1 kΩ ± 5% W
C C
8
1
R = 444.775 Ω +;
9 ! & D
R = 430 Ω ± 5% W
E E
8
1 W
R = 29.736 kΩ +;
9 ! & D
R = 30 kΩ ± 5%
B 1 B 1
8
1 W
R = 8.6 kΩ +;
9 ! & D
R = 9.1 kΩ ± 5%
B 2 B 2
8
C = 0.0579 µF +;
9 ! & D
C = 0.056 µF 50 V
B B
C = 0.0579 µF +;
9 ! & D
C = 0.056 µF 50 V
E
E
C = 0.0579 µF +;
9 ! & D
C = 0.056 µF 50 V
C
C
ก
ก
ก
156
3.
ก
"
+ & ,
+ "
×
×
V CC B 2 12 9.1 10 3 2.792 V
R
ก !ก (2.1) V = = =
TH )
( R B 1 + R B 2 ( 30 10 + 9.1 10 3 )
3
×
×
×
3
×
R R 2 30 10 × 9.1 10 3 6.982 kΩ
B
1 B
ก !ก (2.2) R TH = = =
3
×
×
( R B 1 + R B 2 ) ( 30 10 + 9.1 10 3 )
V − V ) ( 2.792 0.6− )
( TH
ก !ก (2.3) I = BE = = 49.861 µA
B 3
×
×
R TH + ( β + ) 1 R E 6.982 10 + (86 430 )
F
×
ก !ก (2.4) I = β I = 85 49.861 10 − 6 = 4.238 mA
×
C F B
}
I R +
ก !ก (2.5) V CE = V CC − { C C ( β + ) 1 I R
B E
F
) (
×
×
×
V CE = 12 − ( { 4.238 10 − 3 × 1,000 + 86 49.861 10 − 6 × 430 )}
V = 5.918 V
CE
" & )
.( & ' I = == = 49.861 µA, I = == = 4.238 mA %V = == = 5.918 V
B C CE
ก
"
+
F
H
×
I C (dc ) I C (dc ) 4.238 10 − 3
ก !ก (1.9) g = = = = 164.902 mS
m
×
V (k ) q 25.7 10 − 3
T B
β o 85
ก !ก (1.10) r b e ′ = = − = 515.457 Ω
×
g m 164.902 10 3
×
R R 1,000 75 69.767 Ω
C L
ก !ก (2.9) Z = R = = =
out out R + ) (1,000 75+ )
( C R L
3
×
×
R R 2 30 10 × 9.1 10 3 6.982 kΩ
1 B
B
R BB = = =
×
3
×
( R B 1 + R B 2 ) ( 30 10 + 9.1 10 3 )
R
R
r
R 2 BB + r bb′ ( CF 2 + R BB )} b e ′
{ CF
ก !ก (3.29) R FH =
+
R
R
r
R
R
{ CF 2 BB + r bb′ ( CF 2 + R BB )} ( CF 2 + R BB ) b e ′
{ 75 6.982 10 + 2 75 6.982 10 3 )} 515.457
(
×
3
×
+
×
R =
{ 75 6.982 10 + 2 7.057 10 3 )} ( 7.057 10 3 ) 515.457
(
FH
3
+
×
×
×
×
3
537.764 10 × 515.457
×
R FH = = 66.397 Ω
( 537.764 10 + 3.637 10 6 )
3
×
×
1
ก !ก (2.17) F =
H
π
2 R FH T
C
×
g m 164.902 10 − 3 − 12
×
, C b c ′ = C ob = 1 pF, C b e ′ = − C ob = − 1 10 = 12.192 pF;
π
×
×
×
2 F T 2 3.14 2 10 9
×
×
C = C b e ′ + C b c ′ (1 g R+ m out ) 12.192 10= × − 12 + 1 10 − 12 { 1+ ( 164.902 10 − 3 × 69.767 )}
T
C = 24.696 pF
T
ก
ก
ก
157
3.
1
F = = 97.11 MHz
H
×
×
×
×
2 3.14 66.397 24.696 10 − 12
=
" F == = 97.11 MHz .# ! 9 ก 9 5.5 MHz 9
.( & ' ! 8 5.5 MHz
H
ก
"
+ A V (F R )
)
V o (0.5 g Z r R
′
m out b e BB
ก !ก (3.31) A = − = −
V (F R ) + + + + )
E
r
i 1 R CF 2 ( R BB r bb′ r b e ′ ) R BB ( bb′ r b e ′
×
×
×
×
×
0.5 164.902 10 − 3 × 69.767 515.457 6.982 10 3
A V (F R ) = − ( 3 ) 3 )
×
+
×
75 6.982 10 + 2 515.457 + 6.982 10 (2 515.457+
×
20.702 10 6
A V (F R ) = − ( 562.459 10 + 3.612 10 6 ) = − 4.959
×
×
3
V o
= − −− −
= − −− −
" A V (F R ) == = E i 1 == = 4.959
+
&$
'
, "-
.( &
0& % ก / !8
ก ก ! C %8 ก
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9
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5 กก 2
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4
0 >
. 5 1
ก , / 0 *
F 1 ก3 (0 -
4% 1 # &
T
4.1
2
+V V max T 3 500 kHz +V V max
0 π 2π 3π t
0
T π 2π 3π
− V T N 23 L 23 − V
L 13
N 13
N 33 L 33
E
g
500 kHz
1 MHz
D , D t = 0,V = 0.35 V, I = 5 mA,V = 20 V, PIV = 50 V;
1 2 rr F F R
T L = 1.40 µH, L = 170 µH, L = 170 µH, N = 7 T, N = 79 T, N = 79 T;
3 13 23 33 13 23 33
1 4.1 . %
2 $% , 4%$ %
ก
ก
ก
160
4.
ก 1 4.1
5( % % & :-
− T
. 5 1 500 kHz
% 5! ก
500 kHz$% L .5(
3 43
C (ก -ก 1 .--# $/. /* 500 kHz .5( .- 2 ,+% $%
CM
= 0 ก 180 D
.ก D .5( D
1 2
!
− ( )
. % =
- 0 .
& 1 (
= 0 ก
!
•
*
*
− D .5( D - 1N604%$ %% ก 0 *
1 .-- 0 . ก0
*
2
1
ก (. 4
5; 4% %
V 0 (
0.2-0.3 V
! , , 00*ก 4%$ %.
F
− R .5( R
ก %
# ก (. I .5( I
ก !
4%
2
1
D
D
2
1
, (0- ) .5( ( -2 )4
5; R ก
0+ 0 ก -.0 # R .5( R
π
π
π
2
1
L
!
! ก -# N .5( N 4
ก
V 4
ก -V FD 2
FD
22
32
1
− V
2 #
E
g
o
4.1.1 ก
!!" ก
#$$%& '
2
4.1.1.1 ก
(
) I #% I
D
D
2
1
T 3 500 kHz D 1
I
N L D
L 13 23 23 V FD 1 = 0.35 V 1
N
E g 13 N 33 L 33 I D 1
500 kHz
D 2
1 4.2 . % 4==D ก (. 5 -#
2
$% , 4%$ %, (0- )
π
ก 1 4.2 , (0- ) D ( ก (. .5( D 4
ก (. (4%
ก
π
2
1
ก
ก (3.8) E P = E S
N P N S
$% E = E , E = V , N = N , N = N ;
P i S 1 P 13 S 23
E i = V 1 , E N 23 = V 1 ;
i
N 13 N 23 N 13
ก
ก
ก
161
4.
E N
V = i 23 ,V = V 2 ; (4.1)
1
1
N 13
V = V FD 1 + I R + I R
1
D
L
D
1
1
1
R +
V − V FD 1 = I D 1 ( 1 R L )
1
V − V FD V V FD
1
−
=
1
I D 1 = ( R + R L 1 ) ( R + 1 R L ) ( R + R L )
1
1
1
E N
! ก V = i 23
1
N 13
E N 23 V FD
i
1
I D 1 = ( R + R L ) N 13 − ( R + R L ) (4.2)
1
1
E N 23 V FD
(
E
i
ก
ก (4.2) I = − 1
D 1 ( R + R L ) N 13 ( R + R L ) i
1
1
E N 23 − V FD N 13
i
I = 1
D 1 ( R + R L ) N 13
1
R +
I D 1 ( 1 R L ) N 13 = E N 23 − V FD 1 N 13
i
E N − V N = I R + R ) N
i 23 FD 1 13 D 1 ( 1 L 13
R +
E N 23 = I D 1 ( 1 R L ) N 13 + V FD 1 N
i
13
R +
I D ( 1 R L ) N 13 + V FD N 13
% & E = 1 1 (4.2a)
i
N 23
$% E ! . % 4==D D
.ก L # T
13
i
3
ก 1 4.3 , ( -2 ) D ( ก (. 4==D .5( D 4
ก (. 4==D
π
π
2 1
! กV = % & (4%
ก
V
2
1
T 3 500 kHz D 1
N L
L 13 23 23
N
E g 13 D I
N 33 L 33 2 I D D 2
500 kHz 2
V FD 2 = 0.35 V
)
1 4.3 . % 4==D ก (. 5 -#
2 , ( -2π π
ก
ก
ก
162
4.
V − V FD V V FD
2
−
=
I D 2 = ( R + R L 2 ) ( R + 2 R L ) ( R + 2 R L )
2
2
2
E N
! ก V = i 33
2
N 13
V
&
E N
FD
% I D 2 = ( R + i R L 33 ) N 13 − ( R + 2 R L ) (4.3)
2
2
*& 4.1 ก 1 4.2 (
E i (V peak )
! ก
% I D = 1 mA peak
1
R +
I D ( 1 R L ) N + V FD N 13
13
+ , ก
ก (4.2a) E = 1 1
i
N
23
$% E ! . % 4==D D
.ก L # T
i 13 3
Ω
Ω
R = 500 , R = 1 k , N = 7 T, N = 79 T,V = 0.35 V;
13
L
23
1
FD
1
{ 7 1 10 − 3 ( 500 1 10 3 )} (0.35 7+ × )
×
×
+
×
E = = 163.924 mV
i peak
79
* E = == = 163.924 mV peak
i
4.1.1.2 ก
(
) F
R (L 43 )
F !
$/. /* 0 .
L ก % ก (L C ).5(
R (L 43 ) 43 43 CM
0 - # L ! (
# C
43 CM
L 13 = N 2 13
L 43 ( N 23 + N 33 ) 2
L 13 ( N 23 + N 33 ) 2
L 43 = (4.4)
N 2
13
1
ก
ก (3.1b) F =
R
2π LC
$% F = F R (L 43 ) , L = L 43 , C = C CM ;
R
1 (4.5)
% & F R (L 43 ) =
2π
L C
43 CM
1
C CM = 2 (4.5a)
( )
π
L 43 ( 2 F R L 43 )
ก
ก
ก
163
4.
*& 4.2 ก 1 4.1 .5( 4.2 (
C
! E
500 kHz
CM
g
×
L 13 ( N 23 + N 33 ) 2 1.40 10 − 6 (79 79+ ) 2
+ , ก
ก (4.4) L = =
43 2 2
N 13 ( ) 7
L 43 = 713.257 µH
1
ก
ก (4.5a) C CM = 2
( )
π
L 43 ( 2 F R L 43 )
$% F R (L ) = 500 kHz, L 43 = 713.257 µH;
43
1
C CM = 2 = 142.198 pF
×
×
×
×
713.257 10 − 6 ( 2 3.14 500 10 3 )
* C = == = 142.198 pF
CM
4.1.1.3 ก
(
) B
W (L 43 )
ก 1 4.2 (0 - # R 0 C 4% .ก ก R 4
CM g
}
0 .
L ก5 R .5( R (r + R + R ) 4 0 .
L ก5 R
23 gL 23 ( { g L 23 ) d 1 1 L 43 BW
k T ) q
ก
ก (1.20) r = ( B
d
I
D
&
B
% r = r = (k T q ) (4.5b)
d 1 d
I D
$% r !
0 +% # 4%$ % D
d
1 1
ก
ก (3.10) Z P = Z S , Z = Z N 2 P ;
S
P
N 2 N 2 N 2
P S S
$% Z = R BW , Z = R g L ) ( d 1 R + R L ) , N = N 23 + N 33 , N = N 23 ;
r +
S
1
P
P
S
( 23
2
R N 23
g
R =
g L ) 2
( 23
N
13
r
R g L ) ( d + R + R L ) ( N + N ) 2
1
% & R = ( 23 1 × 23 33 (4.5c)
BW ) 2
R ( ( + r + R + R N 23
g L 23 ) d 1 1 L
$% R !
0 0 C 0 .
L
BW CM 43
R g L ) !
0 ก L 4 L 23
13
( 23
ก
ก
ก
164
4.
1
ก
ก (3.2) B =
W
π
2 CR
$% B = B W L ) , R = R BW ,C = C CM ;
W
( 43
1
% & B W (L ) = (4.5d)
π
43 2 C CM R BW
*& 4.3 ก 1 4.1 .5( 4.2 (
B
W (L 43 )
k T ) q k T
( B
+ , ก
ก (4.5b) r = r = = B
d 1 d I D qI D
×
×
$% I = (0.318 I = 0.318 1 10 − 3 = 0.318 mA,T = 25 C;
D ) D 1 A
×
r = 1.38 10 − 23 ( 273 25+ ) = 80.825 Ω
d 1 − 3 − 19
×
×
0.318 10 × 1.60 10
2 2
R N 23 75× ( )
79
g
R = = = 9.552 kΩ
g L ) 2 2
( 23
N 13 ( ) 7
r
R g L ) ( d + R + R L ) ( N + N ) 2
1
ก
ก (4.5c) R = ( 23 1 × 23 33
BW ) 2
R ( ( + r + R + R N 23
g L 23 ) d 1 1 L
×
9.522 10 3 (80.825 500 1, 000+ + ) (79 79+ ) 2 5.422 kΩ
R = × =
( 9.522 10 + 80.825 500 1, 000 ) ( )
BW 2
3
+
×
+
79
1 1
ก
ก (4.5d) B = =
W (L 43 ) − 12 3
π
×
×
×
×
2 C CM R BW 2 3.14 142.198 10 × 5.422 10
B W (L 43 ) = 206.532 kHz
* B = == = 206.532 kHz
W (L 43 )
4.1.1.4 ก
(
) V
o
V . % 4==D 0ก
R /
2 #
o L
D # ก (
V
.- ก4% 2 ,
o
4.1.1.4.1 V , (0- )π ก 1 4.2 D ก (. 4==D
1
o
E N 23 V FD
i
ก
ก (4.2) I = − 1
D 1 ( R + R L ) N 13 ( R + R L )
1
1
V = I R
o (0 π− ) D 1 L
E N V FD
% & V = I R = R L i 23 − 1 (4.6)
o (0 π− ) D 1 L
( R + R L ) N 13 ( R + R L )
1
1
! . % 4==D 0ก
R # ( = (0- )
$% V o (0- ) L π
π
ก
ก
ก
165
4.
4.1.1.4.2 V , ( -2 ) ก 1 4.3 D ก (. 4==D
π
π
2
o
E N 33 V FD 2
i
ก
ก (4.3) I = −
D 2 ( R + R L ) N 13 ( R + R L )
2
2
V o ( -2 ) = I D R
π
π
L
2
E N V FD
% & V o π = I D R = R L i 33 − 2 (4.7)
( -2 ) π
L
2
( R + R L ) N 13 ( R + R L )
2
2
π
π
$% V o ( -2 ) ! . % 4==D 0ก
R # ( = ( -2 )
π
π
L
(0
. % 4==D ก5 ก 4
ก5 ก
V o (0- ) .5(V o ( -2 )
π
π
π
! (0
(0 -5%
1
5%5 $% ก
# R
R , V o (0- ) 1 ก V o ( -2 )
π
π
π
1
2
(
4% ก
ก
-
R !
V ก -V
π
π
π
1 o (0- ) o ( -2 )
E N V FD
ก
ก (4.6) V = I R = R L i 23 − 1
π
o (0- ) D 1 L R + R +
( 1 R L ) N 13 ( 1 R L )
R L E N 23
i
V = − V FD
π
o (0- ) ) 1
( R + R L N 13
1
R E N
( R + R L ) = L i 23 − V FD
1
V (0- ) N 1
o π 13
R E N
R = L i 23 − V − R
1 FD L
V o (0- ) N 13 1
π
ก
%
R = R ,V = V ;
π
1 1x o (0- ) ox
R E N
% & R = L i 23 − V − R (4.8)
1x FD L
1
V ox N 13
$% R ! 0 0 R 1ก 5 . 5 0
ก 5 . 5 V
1x
1
ox
V ! . % 4==D 0ก
R 0
0 ก
ox
L
E N V FD
ก
ก (4.7) V = I R = R L i 33 − 2
π
π
o ( -2 ) D 2 L
( R + R L ) N 13 ( R + R L )
2
2
E N V FD
V o ( -2 ) = R L i 33 − 2
π
π
( R + R L ) N 13 ( R + R L )
2
2
R L E N 33
i
V o ( -2 ) = − V FD
π
π
)
( R + R L N 13 2
2
R E N
R + R = L i 33 − V
2 L FD
2
V o π π N 13
( -2 )
ก
ก
ก
166
4.
R E N
R = L i 33 − V FD − R
L
2
V o π ) N 13 2
( -2π
ก
%
R = R 2x ,V o ( -2 ) = V ox ;
π
π
2
R E N 33
i
L
% & R 2x = − V FD − R (4.9)
L
V ox N 13 2
$% R ! 0 0 R 1ก 5 . 5 0
ก 5 . 5 V
2x
ox
2
V ! . % 4==D 0ก
R 0
0 ก
ox L
*& 4.4 ก 1 4.1,4.2 .5(4.3
! E = 180 mV peak ,V FD 1 = 0.35 V .5(V FD 2 = 0.25 V
i
ก. (
V o (0- ) .5(V o ( -2 )
π
π
π
#.
-.0 R .5( R !
V = V
π
π
π
1 2 o (0- ) o ( -2 )
+ , ก. (
V o (0- ) .5(V o ( -2 )
π
π
π
E N V FD
ก
ก (4.6) V o (0- ) = I R = R L i 23 − 1
π
D
L
R +
R +
1
( 1 R L ) N 13 ( 1 R L )
− 3
×
3
V o (0- ) = 1 10 180 10 × 79 − 0.35
×
(
π
+
+
×
×
7 500 1 10 3 ) ( 500 1 10 3 )
(
3
×
×
×
V o (0- ) = 1 10 1.354 10 − 3 − 233.333 10 − 6 ) = 1.12 V peak
π
E N V FD
ก
ก (4.7) V o π π = I D R = R L i 33 − 2
L
( -2 )
2
N 13 ( R + R L ) ( R + R L )
2
2
− 3
×
3 180 10 × 79 0.25
×
V o ( -2 ) = 1 10 −
(
π
π
×
+
+
×
7 500 1 10 3 ) ( 500 1 10 3 )
(
×
3
×
×
V o ( -2 ) = 1 10 1.354 10 − 3 − 166.666 10 − 6 ) = 1.187 V peak
π
π
* V = = = = 1.12 V ,V = = = = 1.187 V ;
π π π
π
( -2 ) π π
π
o (0- ) peak o π ππ π π peak
#.
-.0 R .5( R
V ก -V $% 0 5%V
ก -V
π
π
π
π
π
π
1 2 o (0- ) o ( -2 ) o ( -2 ) o (0- )
R E N
ก
ก (4.9) R 2x = L i 33 − V FD − R
L
V ox N 13 2
$% V ox = V o (0- ) = 1.12 V,V FD = 0.25 V;
π
2
1 10 180 10 − 3 × 79
×
3
×
3
×
R 2x = − 0.25 − 1 10 = 590.561 Ω
1.12 7
* (0 5 R ก %
500 Ω ΩΩ Ω 5 590.561 Ω ≈ ≈Ω ≈ ≈ 600 Ω ΩΩ Ω
Ω Ω
2
ก
ก
ก
167
4.
4.1.2 ก
ก#
2
ก 1 4.4 ก.--
2 ก 750 kHz 1.5 MHz E
i
200 mV peak
4.1.2.1 ก
(
) C
CM
1
$% C .5( L (ก -ก .--# (4%
ก
CM 43
L 13 ( N 23 + N 33 ) 2
ก
ก (4.4) L =
43 2
N 13
1
ก
ก (4.5a) C =
CM 2
π
L ( 2 F ( )
43 R L 43 )
*& 4.5 (
C
CM
×
L 13 ( N 23 + N 33 ) 2 1.3 10 − 6 (89 70+ ) 2
+ , ก
ก (4.4) L 43 = =
N 2 ( ) 7 2
13
L = 670.72 µH
43
1
ก
ก (4.5a) C =
CM 2
π
L ( 2 F ( )
43 R L 43 )
$% F = 750 kHz, L = 670.72 µH;
R (L 43 ) 43
1 67.207 pF
C = =
CM 2
×
×
×
×
670.72 10 − 6 ( 2 3.14 750 10 3 )
67.207 pF 5
0 ' 68 pF
= == = 68 pF /
ก
* C CM
+V
V max +V V
T
3 750 kHz max
0 π 2π 3π t
0
T π 2π 3π
T N L
− V L 13 23 23 − V
N 13
N 33 L 33
E
g
750 kHz
1.5 MHz
L 23 , N 23
L 13 , N 13
L 33 , N 33 D 1 ,D 2 #1N60 t = 0,V = 0.35 V,I = 5 mA,V = 20 V,PIV = 50 V;
R
rr
F
F
T L = 1.3 µH,N = 7 T,L = 213 µH,N = 89 T,L = 130 µH,N = 70 T;
3 13 13 23 23 33 33
1 4.4 . %
2 $% , 4%$ % , ก ก.--
ก
ก
ก
168
4.
4.1.2.2 ก
(
) I #% I
D
D
1
2
E N 23 V FD 1
i
ก
ก (4.2) I D 1 = − )
N
1
1
13 ( R + R L ) ( R + R L
E N 33 V FD
i
ก
ก (4.3) I = − 2
D 2 N 13 ( R + R L ) ( R + R L )
2
2
*& 4.6 (
I .5( I
D 1 D 2
E N 23 V FD
i
+ , ก
ก (4.2) I D = − 1
1
N 13 ( R + R L ) ( R + R L )
1
1
×
200 10 − 3 × 89 0.35
I D = − = 1.461 mA peak
(
1
×
+
×
+
7 500 1 10 3 ) ( 500 1 10 3 )
E N 33 V FD
i
ก
ก (4.3) I D = − 2
2
N 13 ( R + R L ) ( R + R L )
2
2
×
200 10 − 3 × 70 0.35
I D = − = 1.10 mA peak
(
+
2
×
+
×
7 500 1 10 3 ) ( 500 1 10 3 )
* I = = = = 1.461 mA , I = = = = 1.10 mA ;
D 1 peak D 2 peak
4.1.2.3 ก
%0 ก T
3
( , IFT(.ก
5! ) # + 3
4.1.2.4 ก
(
) V #% V
π ππ
π
π
π ππ
π
o (0- ) o ππ π
( -2 )
E N V FD
ก
ก (4.6) V = I R = R L i 23 − 1
π
o (0- ) D 1 L
R +
R +
N 13 ( 1 R L ) ( 1 R L )
E N V FD
ก
ก (4.7) V o π π = I D R = R L i 33 − 2
( -2 )
L
2
N 13 ( R + R L ) ( R + R L )
2
2
*& 4.7 (
V o (0- ) .5(V o ( -2 )
π
π
π
E N V FD
+ , ก
ก (4.6) V o (0- ) = I R = R L i 23 − 1
π
L
D
R +
R +
1
N 13 ( 1 R L ) ( 1 R L )
×
×
3
V o (0- ) = I R = 1.461 10 − 3 × 1 10 = 1.461 V peak
π
D
L
1
E N V FD
ก
ก (4.7) V o π π = I D R = R L i 33 − 2
L
( -2 )
2
N 13 ( R + R L ) ( R + R L )
2
2
3
×
×
V o ( -2 ) = I D 2 R = 1.10 10 − 3 × 1 10 = 1.10 V peak
π
π
L
* V o (0- ) = = = = 1.461 V peak ,V o ππ π = = = = 1.10 V peak ;
π
π
π ππ
π
π π π
( -2 )
ก
ก
ก
169
4.
(
3 V o (0- ) ก - 1.461 V .5(V o ( -2 ) ก - 1.10 V peak (0
π
π
π
peak
5% V o (0- )
5! ก - 1.10 V peak
π
4.1.2.5 ก
(
) R #% R
1 2
ก (
R .5( R !
V ก - V
π
π
π
1 2 o (0- ) o ( -2 )
R E N
ก
ก (4.8) R = L i 23 − V FD − R
L
1x
V ox N 13 1
*& 4.8 (
R .5( R !
V o (0- ) ก - V o ( -2 )
π
π
π
1
2
R E N
+ , ก
ก (4.8) R = L i 23 − V FD − R
1x
L
V ox N 13 1
$% R ! 0 0 R 1ก 5 . 5 0
ก 5 . 5 V
1x
ox
1
V = 1.10 V
ox peak
1 10 200 10 − 3 × 89
3
×
×
3
×
R = − 0.35 − 1 10 = 993.506 Ω
1x
1.10 7
R = 993.506 Ω 5
0 ' R = 1 kΩ
1x
1x
* R (0 1ก 5 ก 500 Ω ΩΩ Ω ก5 1 kΩ ΩΩ Ω .
1
4.2
2
34 $ *
#%
+V
V max
0 π 2π 3π t +V
0 V max
T T π 2π 3π
− V − V
Q 1
E
g
500 kHz 1 MHz
D , D 1N4148 t = 4 ns,V = 0.6 V, I = 200 mA,V = 75 V,V = 100 V;
1 2 rr F F R RRM
Q 1 2SC930 V CBO = 30 V,V CEO = 20 V,V EBO = 5 V, I C (MAX) = 30 mA, P = 120-250 mW,
D
β = β = 100,V = 0.6 V, F = 300 MHz, C = C = 1.3 pF, r bb′ = 2 ;
Ω
F o BE T ob re
1 4.5 . %
2 $% , / 0 .5(4%$ %
*
ก
ก
ก
170
4.
*
2 $% , / 0 .5(4%$ % 4% J 0 ก
2
$% , 4%$ % ( 1 4.1 ) $% ก ก.--
Q
. T ก % = D
1 3
.ก D .5( D
0 -
4% ก ก 1 4.5
< - 4% % & :-
1
2
*
− Q / 0
# . % .5( % = #
.ก D .5( D $%
1 1 2
π
π
π
D ก (.
! 4% - , ( -2 ) D ก (.
! 4% - , (0- )
2
1
*
− C .5( C
$% C ,!
0 ก (. 5 - ก# 5 53ก 0 Q
.ก
C
E
C
1
D .5(C ,!
0 ก#
0 0 * Q
.ก D ก ก & C .5(C
D ก
E
C
2
1
1
E
*
4
4==D ก (. 0 # 5 53ก 0 * .5(#
0 0 Q D
.ก D .5( D
1 1 2
− R .5( R %4-. 4
ก - D ! 5%. % V ก 0.6 V 0 V $%
1
1
L
FD
1
ก (. 4
5; (
5 µA
ก 0.6 V 0 V $%
− R .5( R %4-. 4
ก - D ! 5%. % V
2 L 2 FD 2
ก (. 4
5; (
5 µA
4.2.1 ก
!!" ก
#$*
I C
I D V FD = 0.6 V
β F B 1 1
I
I B
I D + I D
Q 1 1 2
V BE = 0.6 V
I = I + I C I D 2 V FD = 0.6 V
B
E
2
1 4.6 . % 4==D ก (. 0 # 1 4.5
ก 1 4.5
5 4==D ก (. 0 4% % . % 1 4.6 ก
(
* 4==D ก (. 0
ก 0 4 &
, 4% 5
V CC B 2
R
ก
ก (2.1) V TH =
( R B 1 + R B 2 )
R R 2
B
1 B
ก
ก (2.2) R TH = ( R B 1 R B 2 ) =
( R B 1 + R B 2 )
V − V )
ก
ก (2.3) I = ( TH BE
B
R + (β + ) 1 R
TH F E
ก
ก
ก
171
4.
I
ก
ก (2.4) I = β F B
C
}
I R +
ก
ก (2.5) V CE = V CC − { C C ( β + ) 1 I R
F
B E
V CC = I R + V FD 1 + ( D 1 + I D 2 ) R
I
D
1
L
1
I + I = 2I )
D
D
! ก I (0 ก - I ! +% # 4%$ % & 2 0 ก (4% ( D 1 D 2 D 1
1
2
4
5; R
L
V CC = I R + V FD 1 + 2I R L
D
1
D
1
1
V − V = I ( R + 2R )
CC FD 1 D 1 1 L
V − V )
( CC FD 1 ; (4.10)
I = , I = I
D 1 ( R + 2R L ) D 1 D 2
1
, I .5( I
*& 4.9 ก 1 4.5, 4.6 (
I B , I C ,V CE D D
1 2
×
×
V CC B 2 12 13 10 3 4.216 V
R
+ , ก
ก (2.1) V TH = = =
3
×
×
( R B 1 + R B 2 ) ( 24 10 + 13 10 3 )
×
×
3
R R 2 13 10 × 24 10 3 8.432 kΩ
1 B
B
ก
ก (2.2) R TH = = =
3
( R B 1 + R B 2 ) ( 13 10 + 24 10 3 )
×
×
−
( 4.216 0.6 )
ก
ก (2.3) I = = 55.637 µA
B
3
×
8.432 10 + (101 560× )
×
I =
ก
ก (2.4) I = β F B 100 55.637 10 − 6 = 5.563 mA
×
C
I R +
ก
ก (2.5) V CE = V CC − { C C (β + ) 1 I R }
F
B E
) (
×
×
×
V CE = 12 − ( { 5.563 10 − 3 × 560 + 101 55.637 10 − 6 × 560 )}
V = 5.737 V
CE
−
V − V FD ) (12 0.6 )
( CC
ก
ก (4.10) I D 1 = 1 ) =
R +
6
×
×
×
( 1 2R L { 2 10 + ( 2 56 10 3 )}
I D 1 = 5.397 µA
I D 1 = I D 2 = 5.397 µA
* I = == = 55.637 µA, I = == = 5.563 mA, V CE = = = = 5.737 V .5( I D 1 = = = = I D 2 = = = = 5.397 µA
C
B
π ππ
π
4.2.2 ก
!!" ก
#$$%&
ก% (0- )
1
ก 4.7 D ก (. .0 D 4
ก (.
(
*ก 4%
1
2
%
&
!
0 (
# - ก -ก %$% 5( & R , (0- )
*
R i (0- ) BB π
π
ก
ก
ก
172
4.
R = R R r + R )
EP E 2 ( d 2 L
! ก R
1
ก
5( & 4%
! 0 # ก - R
0
2 E
r
R EP = R ( d 2 + R L )
E
R E ( d + R L )
r
R EP = 2
( R + r d + R L )
E
2
E = I r + I r + I (β + 1)R
i b bb′ b b e ′ b F EP
E
I = i
b
r bb′ + r b e ′ + (β + 1)R EP
F
E i E i {r bb′ + r b e ′ + (β + 1)R EP }
F
R i (0- ) = I b = E i
π
R i (0- ) = r bb′ + r b e ′ + (β + 1)R EP
π
F
% & R = r + r + (β + ) 1 R (4.11a)
π
i (0- ) bb′ b e ′ F EP
R in (0- ) R i (0- )
π
π
r bb′ D 1
B b′ C A K
I b I c
r V g V
R g b e ′ b e ′ m b e ′ R C R 1
E g E i R BB D 2
I E A K
e
R EP r d I d
π
R E R 2 2 2 R L V o (0- )
1 4.7 . % 4==D ก (. 5 -
ก5 , (0- ) # 1 4.5
π
!
0 (
# - ก -ก %* , (0- )
R in (0- ) π
π
R R 2
B
1 B
R =
BB
R B 1 + R B 2
R
R BB i (0- )
π
ก R in (0- ) = ( R BB R i (0- ) ) =
π
π
R BB + R i (0- )
π
R R (0- )
π
BB i
% & R = (4.11b)
π
in (0- )
R BB + R i (0- )
π
*& 4.10 ก 1 4.7 (
R i (0- ) .5( R in (0- )
π
π
+ , ก
ก (4.11a) R i (0- ) = r bb′ + r b e ′ + (β + ) 1 R
π
EP
F
ก
ก
ก
173
4.
×
(k T q ) 1.38 10 − 23 × (273 25+ )
B
$% r d = = = 4.762 kΩ
×
×
2
I D 2 1.60 10 − 19 × 5.397 10 − 6
I ( ) 5.563 10 − 3
×
g = C dc = = 216.459 mS
m
(k T q ) 25.7 10 − 3
×
B
β o 100
r b e ′ = = − = 461.981 Ω
×
g m 216.459 10 3
×
×
3
R R 2 13 10 × 24 10 3 8.432 kΩ
B
1 B
R BB = = =
×
( R B 1 + R B 2 ) ( 13 10 + 24 10 3 )
3
×
(
3
×
×
r
R E ( d + R L ) 560 4.762 10 + 56 10 3 )
R EP = 2 = = 554.886 Ω
( R + r d 2 + R L ) ( 560 4.762 10 + 56 10 3 )
3
+
×
×
E
R i (0- ) = r bb′ + r b e ′ + ( β + ) 1 R EP
π
F
+
R = 2 461.981+ (101 554.886× )
π
i (0- )
R = 56.507 kΩ
π
i (0- )
R R (0- )
π
BB i
ก
ก (4.11b) R =
π
in (0- )
( R BB + R i (0- ) )
π
$% R = 56.507 kΩ
π
i (0- )
3
×
×
R
R BB i (0- ) 8.432 10 × 56.507 10 3
π
R = = = 7.337 kΩ
π
in (0- ) 3 3 )
( R BB + R i (0- ) ) ( 8.432 10× + 56.507 10
×
π
Ω
Ω Ω Ω
Ω Ω Ω
Ω
* R i (0- ) = = = = 56.507 k , R in (0- ) = = = = 7.337 k ;
π ππ
π ππ
π
π
I ! ก (. 4==D 4
5; D , (0- )# D % # R
π
2
2
d
2
1
! 0 #
5( & 4%
I R
e E
I =
d 2 )
( R + r d 2 + R L
E
*
! ก / 0
β 1 .5( # . % # ก (. I
0
o
b
5( & 4% (4%
I =
e I c
I R
c E
I d =
2
( R + r d 2 + R L )
E
. g V 5 I
m b e ′
c
g V R
′
m b e E
I =
d 2 )
( R + r d 2 + R L
E
ก
ก
ก
174
4.
. E r 5 V (4%
i b e ′
b e ′
R i (0- )
π
E g r R (4.12)
′
i m b e E
% & I =
d 2 )
R ( R + r + R
π
i (0- ) E d 2 L
! . % 0ก
R , (0- )
(
4% ก
ก (4.12)
V o (0- ) L π
π
1 ก - R
L
% & V o (0- ) = I R (4.13)
π
L
d
2
*& 4.11 (
I .5(V o (0- )
! ก
% E = 25 mV peak
π
d
i
2
E g r R
′
i m b e E
+ , ก
ก (4.12) I =
d 2 )
R i (0- ) ( R + r d 2 + R L
π
E
Ω
$% r d 2 = 4.762 k , g = 216.459 mS;
m
Ω
Ω
r b e ′ = 461.981 , R i (0- ) = 56.507 k , E = 25 mV peak ;
π
i
( 25 10 − 3 × 216.459 10 − 3 × 461.981 560 )
×
×
×
I d = = 404.025 nA
×
×
2
+
3
×
56.507 10 3 ( 560 4.762 10 + 56 10 3 )
ก
ก (4.13) V o (0- ) = I R
π
L
d
2
Ω
$% I d = 404.025 nA, R = 56 k ;
L
2
×
×
V o (0- ) = 404.025 10 − 9 × 56 10 3
π
V = 22.625 mV
π
o (0- ) peak
* I d 2 = = = = 404.025 nA peak ,V o (0- ) = = = = 22.625 mV peak ;
π ππ
π
4.2.3 ก
!!" ก
#$$%&
ก% ( - π ππ π
π π
π
π
2 )
R in ( -2 ) R i ( -2 )
π
π
π
π
r bb′ b′ D 1
r 1 d I 1 d
r b e ′ V b e ′ g V
m b e ′
E g D 2
( -2π π ) I e
R EP 1 R E V o (0- )
π
1 4.8 . % 4==D ก (. 5 -
ก5 , ( - π ππ π # 1 4.5
π π
π
π
2 )
ก
ก
ก
175
4.
1
ก 4.8 D ก (. .0 D 4
ก (.
2
1
*
π
π
R i ( -2 ) !
0 (
# - ก -ก %$% 5( & R , ( -2 )
π
π
BB
R R 2
E
R = ( R R ) =
EP 1 E 2
( R + R 2 )
E
! ก R
1
ก
5( & 4%
! 0 # ก - R
0
2
E
% & R = r + r + (β + ) 1 R (4.14)
π
π
i ( -2 ) bb′ b e ′ F EP 1
R R ( -2 )
π
π
BB i
% & R in π π = (4.15)
( -2 )
R + R
π
π
BB i ( -2 )
*& 4.12 (
R i ( -2 ) .5( R in ( -2 )
π
π
π
π
+ , ก
ก (4.14) R i ( -2 ) = r bb′ + r b e ′ + (β + ) 1 R
π
π
EP
1
F
Ω
Ω
$% r b e ′ = 461.981 , R = 560 , E = 25 mV peak ;
E
i
×
×
R R 2 560 2 10 6 559.843 Ω
E
R EP 1 = = =
( R + R 2 ) ( 560 2 10 6 )
+
×
E
R i ( -2 ) = (r bb′ + r b e ′ ) ( β+ F + ) 1 R EP 1
π
π
R i π π = ( 2 461.981+ ) + (101 559.843× ) 57.008 k= Ω
( -2 )
R R ( -2 )
π
π
BB i
ก
ก (4.15) R in π π =
( -2 )
( R BB + R i π π )
( -2 )
Ω
Ω
$% R BB = 8.432 k , R i ( -2 ) = 57.008 k ;
π
π
3
×
×
8.432 10 × 57.008 10 3
R = = 7.345 kΩ
( 8.432 10 + 57.008 10 3 )
π
π
in ( -2 )
×
3
×
Ω
Ω
Ω Ω Ω
Ω Ω Ω
* R i π ππ π = = = = 57.023 k , R in π ππ π = = = = 7.345 k ;
π
π
π
π
π
π
π
π
( -2 )
( -2 )
I ! ก (. 4==D 4
5; D , ( -2 )# D % # R
π
π
d
1
1
1
1
! 0 #
5( & 4%
R C
I d 1 = g V
m b e ′
R +
d
C r + R L
1
E r
i b e ′
! ก V b e ′ =
R
π
π
i ( -2 )
E g r R (4.16)
′
i m b e C
% & I d 1 =
R +
R i ( -2 ) ( C r + R L )
π
π
d
1
ก
ก
ก
176
4.
π
π
V o ( -2 ) ! . % 0ก
R , ( -2 ) (
4% ก
ก (4.16)
π
π
L
1 ก - R
L
% & V o ( -2 ) = I R (4.17)
π
π
d
L
1
*& 4.13 (
I .5(V
! ก
% E = 25 mV
π
π
d 1 o ( -2 ) i peak
E g r R
′
i m b e C
+ , ก
ก (4.16) I =
d 1 )
R +
R i ( -2 ) ( C r + R L
π
π
d
1
×
(k T q ) 1.38 10 − 23 × (273 25+ )
$% r = B = = 4.762 kΩ
d
×
×
1 I D 1 1.60 10 − 19 × 5.397 10 − 6
Ω
Ω
r b e ′ = 461.981 , R = 560 ;
C
Ω
R i ( -2 ) = 57.008 k , E = 25 mV peak ;
π
π
i
( 25 10 − 3 × 216.459 10 − 3 × 461.981 560 )
×
×
×
)
I d 1 = 57.023 10 3 ( 560 4.762 10 + 56 10
×
3
×
×
+
3
I d 1 = 400.369 nA peak
ก
ก (4.17) V o ( -2 ) = I R
π
π
d
L
1
$% I d 1 = 400.369 nA peak
×
×
V o ( -2 ) = I R = 400.369 10 − 9 × 56 10 3
π
π
d
L
1
V o π π = 22.420 mV peak
( -2 )
* I d 1 = = = = 400.369 nA peak ,V o ππ π = = = = 22.420 mV peak ;
π
π ππ
π
( -2 )
4.2.4 ก
!!" ก
#$$%&
*& 3* ,
4.2.4.1 ก
(
) F
( L C B )
$% C ( - +
0 %% 0 $% ,
5 กก F (
X
B ( L C B ) C B
ก -
0 0 C /
0 % ก5 ! R ก 1 4.9 (4%
B FLCB
ก
R E ( d + R L )
r
R EP = 2
( R + r d 2 + R L )
E
R R 2
E
R EP 1 =
R + R 2
E
ก
ก
ก
177
4.
C B
R FLCB r bb′
r b e ′ R ≈ R EP ≈ R EP 1
E
E
g
β +
( o ) 1 R E
1 4.9 . % ก (
R
FLCB
! ก R ≈ R EP ≈ R
E
1
EP
) }
r
R FLCB = R + R BB { bb′ + r b e ′ + ( β + 1 R E
o
g
) }
R BB { bb′ + r b e ′ + (β + 1 R E
r
o
R FLCB = R + ) }
g
R
o
{ BB + r bb′ + r b e ′ + ( β + 1 R E
X C = R FLCB
B
1
! ก X =
C B
π
C
2 F ( L C B ) B
1
R =
FLCB
π
2 F ( L C B ) B
C
1 (4.18)
% & F =
( L C B ) 2 Rπ FLCB B
C
*& 4.14 ก 1 4.5 .5( 4.9 (
F
( L C B )
1
+ , ก
ก (4.18) F =
( L C B )
π
C
2 R FLCB B
) }
r
R BB { bb′ + r b e ′ + (β + 1 R E
o
$% R FLCB = R + ) }
g
R
{ BB + r bb′ + r b e ′ + ( β + 1 R E
o
×
8.432 10 3 {2 461.981+ + (101 560× )}
R FLCB = 75 + = 7.420 kΩ
{ 8.432 10 + 2 461.981+ (101 560× )}
3
+
×
C = 470 pF
B
1
=
F ( L C B ) 2 3.14 7.420 10 × 470 10 − 12
×
×
×
×
3
F = 45.660 kHz
( L C B )
* F = == = 45.660 kHz
( L C B )
ก
ก
ก
178
4.
4.2.4.2 ก
(
) F ( L C E )
X
$% C ( - +
0 %% 0 $% ,
5 กก F ( L C E ) C E
E
ก -
0 0 C /
0 % ก5 ! R
E FLCE
C
R E
r bb′ r b e ′ FLCE 2 R
β + ) 1 β + ) 1 FLCE D
( o ( o 2
R g r 2 d
β + ) 1
( o
R BB
β + ) 1 R E
E ( o
g
R R
FLCE 1 FLCE 3
1 4.10 . % ก (
R
FLCE
ก 1 4.10 (4%
ก
R = R + r + R )
FLCE FLCE 3 ( d 2 L
R R
g BB
R FLCE 1 =
(β + 1 )( R + R BB )
g
o
r bb′ + r b e ′
R = R +
FLCE 2 FLCE 1
(β + ) 1
o
R R 2
E FLCE
R = ( R R ) =
FLCE 3 E FLCE 2
( R + R FLCE 2 )
E
R FLCE = r d 2 + R + R FLCE 3
L
X C = R FLCE
E
1
! ก X =
C E
π
2 F C
L C ) E
( E
1
R FLCE =
π
2 F C
L C ) E
( E
1
% & F ( L C ) = (4.19)
π
E
2 R FLCE C E
*& 4.15 ก 1 4.5 .5( 1 4.10 (
F ( L C )
E
1
+ , ก
ก (4.19) F ( L C E ) = 2 R FLCE C E
π
ก
ก
ก
179
4.
×
×
75 8.432 10 3
$% R FLCE 1 = = 0.736 Ω
( 75 8.432 10 3 ) (100 1+ )
×
+
+
×
2 461.981 560 5.329
Ω
Ω
R FLCE 2 = 0.736 + = 5.329 , R FLCE 3 = = 5.278 ;
+
+
(100 1 ) (560 5.329 )
3
+
×
×
R FLCE = ( 5.278 4.762 10 + 56 10 3 ) = 60.767 k , CΩ E = 0.22 µF;
1
=
F ( L C E ) 2 3.14 60.767 10 × 0.22 10
−
6
×
×
3
×
×
F ( L C E ) = 11.911 kHz
* F ( L C ) = == = 11.911 kHz
E
4.2.4.3 ก
(
) F
( L C C )
X
$% C - +
0 %% 0 $% ,
5 กก F
C ( L C C ) C C
ก -
0 0 C /
0 % ก5 ! R ก 1 4.11 (4%
C FLCC
ก
C C
R FLCC
D 1
r
1 d
R L
R FLCC = R + r + R L
1 d
C
1 4.11 . % ก (
R FLCC
R
R FLCC = R + r +
C
L
d
1
X C C = R FLCC
1
! ก X C C = 2 F ( L C C ) C
π
C
1
R FLCC =
2 Fπ C
L C ) C
( C
1 (4.20)
% & F ( L C C ) = 2 R FLCC C
π
C
*& 4.16 ก 1 4.5 .5( 1 4.11 (
F ( L C C )
1
+ , ก
ก (4.20) F =
( L C C ) 2 Rπ
C
FLCC C
ก
ก
ก
180
4.
+
=
R +
×
3
×
$% R FLCC = ( C r + R L ) ( 560 4.762 10 + 56 10 3 ) = 61.322 kΩ
d
1
C = 0.22 µF
C
1 = 1
=
F ( L C C ) 2 R FLCC C 2 3.14 61.322 10 × 0.22 10 − 6
π
3
×
×
×
×
C
F ( L C C ) = 11.803 kHz
* F = == = 11.803 kHz
( L C C )
4.2.4.4 ก
(
) F '
L
$% F # !
0 %% 0 # ก
L
0 %% 0 # F , F .5( F
1 +%
F #
( L C B ) ( L C E ) ( L C C ) L
*& 4.17 (
F #
L
+ , 5! ก
1 +% F ( L C B ) = 45.660 kHz, F ( L C C ) = 11.803 kHz, F ( L C E ) = 11.911 kHz;
* F # ! F = == = 45.660 kHz
L ( L C B )
4.2.5 ก
!!" ก
#$$%&
*& 3$7
F !
0 %% 1
X
ก - R $% R !
0 -
FH
H
C
FH
T
0 X .5(;5% ก5 (
. % V
5%5
5! 0.707 # V
ก5
C
o
o
T
( , , ( -2 )π π # ก (
* % . % 1 4.12 .5( 4.13
ก 1 4.13
. %
ก 4% % &
g BB
g
R = ( { R R ) r+ } = R R + r bb′ ( R + R BB )
FH 1 g BB bb′ )
( R + R BB
g
R FH 2 = r b e ′ + ( β + ) 1 R
E
F
R FH 1 FH 2
R
R FH = ( R FH 1 R FH 2 ) =
( R FH 1 + R FH 2 )
! ก R
0 1
ก
! 0 # ก -0 0
0
5( & 4% (4%
1
r +
R = R r + R )} = R C ( d 1 R L )
out { C ( d 1 L )
R +
( C r + R L
d
1
1
ก
ก (2.17) F = (4.21)
H
π
2 R C
FH T
ก
ก
ก
181
4.
r bb′ C = C b e ′ + C b c ′ (1 g R+ m out ) R out
T
r b e ′ V b e ′ g V
m b e ′
I D 1
1 d r
1 d
C T D 2
E g
π
π
π
( -2 ) R E V ( o π − 2 )
1 4.12 . % 4==D ก (. 5 -
0 %% 1 # 1 4.5
r bb′ R FH 1 R FH
B
R FH 2
r b e ′
R g
R BB C
E T
g
β +
( F ) 1 R E
R ≈ R EP ≈ R EP 1
E
1 4.13 . % ก (
R
FH
*& 4.18 (
F # .5(
1 +%
2
H
1
+ , ก
ก (4.21) F =
H
2 Rπ FH C T
( 75 8.432 10 3 ) ( + × 3 )
+
×
×
2 75 8.432 10
$% R FH 1 = ( { R R BB ) r+ bb′ } = = 76.338 Ω
( 75 8.432 10 3 )
g
+
×
R = r + ( β + ) 1 R = 461.981+ (101 560× ) 57.021 k= Ω
FH 2 b e ′ F E
×
×
R FH 1 FH 2 76.338 57.021 10 3 76.235 Ω
R
R = = =
FH )
×
+
( R FH 1 + R FH 2 ( 76.338 57.021 10 3 )
(
×
×
3
r +
R C ( d R L ) 560 4.762 10 + 56 10 3 )
R = 1 = = 554.886 Ω
out ) ( 3 3 )
R +
×
×
+
d
( C r + R L 560 4.762 10 + 56 10
1
I C dc 5.563 10 − 3
×
( )
C b c ′ = C = C ob = 1.3 pF, g = = = 216.459 mS;
m
re
×
(k T q ) 25.7 10 − 3
B
×
g m 216.459 10 − 3 − 12
×
C b e ′ = − C b c ′ = − 1.3 10 = 113.593 pF
π
2 F × × × 6
T 2 3.14 300 10
C = C + C (1 g R+ )
T b e ′ b c ′ m out
C = 113.593 10 − 12 + 1.3 10 − 12 { 1+ ( 216.459 10 − 3 × 554.886 )} = 271.036 pF
×
×
×
T
ก
ก
ก
182
4.
1 1
F = = = 7.706 MHz
H
π
×
×
×
×
2 R FH C T 2 3.14 76.235 271.036 10 − 12
×
1 +% 2 2F= H = 2 7.076 10 = 14.152 MHz
6
×
* F H = == = 7.706 MHz .5(
1 +% 2 4% 14.152 MHz
4.2.6 ก
(
& #* V o (0- ) #% V o ππ π ก&3
π
π
π
π ππ
π ππ
( -2 )
$%
5 กก ก (. I (0 ก -
! ก5 I
! ก %ก ; % 5 %
ก (
D
D
1
2
0 ! ก V # 4%$ % 1ก , 4
1ก0
+
. % V o (0- ) 4
ก ก - V o ( -2 ) F
π
π
π
.5(4
ก
ก .ก 4#$% ก % 5! ก4%$ % กก %$% ,
0 R×1(250 mA) ก
ก5 L 0 4% ก (
0.6 V & 0
V
4.2.7 ก
ก#
2
34 $ *
#%
ก ก.--
2 ก 250 kHz 1 500 kHz $% ก
%
F = 30 kHz, I D 1 = I D 2 = 5 µA, R ≥ 100R C , R = 620 Ω, V CC = 12 V, R = 75 ,T = 25 C .5(
Ω
L
C
A
g
L
E = 25 mV peak ,;
i
V CC = 12 V
+V R C
V max R 1 +V
C C V max
t R B1
0 π 2π 3π
0
T NPN C T π 2π 3π
− V C B B Q 1 − V
R 2
E
R g
C E
E g E i R L V o
R B2
R E
250 kHz
500 kHz
D 1 , D 2 1N4148 t = 4 ns,V = 0.6 V, I = 200 mA,V = 75 V,V RRM = 100 V;
rr
R
F
F
Q 2SC930 V = 30 V,V = 20 V,V = 5 V, I = 30 mA, P = 120-250 mW,
1 CBO CEO EBO C (MAX) D
β = β = 88,V BE = 0.6 V, F = 300 MHz,C ob = C = 1.3 pF, r bb′ = 2 ; Ω
o
F
re
T
1 4.14 . %
2 $% , / 0 *.5(4%$ % , ก ก.--
4.2.7.1 ก
(
) I
C
ก (2.20)
, 4%
ก
ก
ก
183
4.
F T ( B ) q
k T
ก
ก (2.20) I C (dc ) =
π
F
R FH H (2 F C R + ) 1
′
b c out
T
$% ก
% F = 500 kHz, R FH = R g , C b c ′ = C ob = C .5( R out = R
H
C
re
ก 5! ก I (0 5! ก ก I 4% ก
ก (2.20) .5( I (
C C (dc ) C (dc )
*
(0 4
ก 0.5I C (MAX) !
5 %9 # / 0
$% ก
% V CE = 0.5V CC ,V RC = 0.25V CC ,V RE = 0.25V CC ; (4.22)
I
I = C
B
β F
0.25V CC
R = (4.23)
C
I
C
0.25V 0.25V
R = CC ≈ CC (4.24)
E β +
( F ) 1 I B I C
*& 4.19 ก
% I
C
F T ( B ) q
k T
+ , ก
ก (2.20) I C (dc ) =
R F ( 2 F C Rπ + ) 1
′
FH H T b c out
Ω
$% F = 500 kHz, R = 75 , C = C = C = 1.3 pF, R = R = 620 Ω;
H FH b c ′ ob re out C
F T ( B ) q
k T
I C (dc ) =
R FH H ( 2 F C Rπ T b c out + ) 1
F
′
300 10 × 25.7 10 − 3
×
6
×
I C (dc ) =
) }
6
×
×
×
×
×
×
75 500 10 3 ( { 2 3.14 300 10 × 1.3 10 − 12 × 620 + 1
I C (dc ) = 81.635 mA
)
(
−
3
×
×
! ก I C (MAX)
30 mA I 5! ก (0 0 ก 0.5 30 10 ก - 15 mA ก$ *
C
ก
%
R
620 Ω
C
0.25V
ก
ก (4.23) R = CC
C
I C
×
0.25V 0.25 12
I = CC = = 4.838 mA
C
R C 620
* 5! ก I = == = 4.838 mA
C
4.2.7.2 ก
(
) R C , R E , R B 1 , R B 2 , R R #% R
,
2
L
1
/ 0 (0 4% -ก 0 & % , &
ก (. 5 53ก 0 *
+
*
ก
ก
ก
184
4.
4
505 % 5
0.25V
ก
ก (4.23) R = CC
C
I
C
0.25V 0.25V
ก
ก (4.24) R = CC ≈ CC
E
β +
( F ) 1 I B I C
ก
ก (2.26) R TH = 15R
E
ก
ก (2.27) V TH = I R + V BE + ( β + ) 1 I R
F
B TH
B E
R
V CC TH V CC TH ;
R
ก
ก (2.28) R = , R =
B 1 B 2 )
V (V − V
TH CC TH
V − V FD )
( CC
ก
ก (4.10) I = 1 , I = I ;
D 1 ( R + 2R L ) D 1 D 2
1
V CC − V FD
I = 1
D 1 ( R + 2R L )
1
V CC − V FD
R + ) = 1
L
( 1 2R
I D 1
V CC − V FD
R = 1 − 2R L
1
I D 1
*& 4.20 ก (
R , R , R , R , R R .5( R
,
C E B 1 B 2 1 2 L
+ , ก
ก (4.22) V CE = 0.5V CC ,V RC = 0.25V CC ,V RE = 0.25V CC ;
×
=
=
=
×
×
V = 0.5 12 6 V,V = 0.25 12 3 V,V = 0.25 12 3 V;
CE RC RE
×
I 4.838 10 − 3
I = C = = 54.977 µA
B
β F 88
×
0.25V 0.25 12
ก
ก (4.23) R = CC = = 620 Ω
C
×
I C 4.838 10 − 3
×
0.25V CC 0.25 12
ก
ก (4.24) R = ≈ = 620 Ω
E
( β + ) 1 I B 4.838 10 − 3
×
F
×
ก
ก (2.26) R = 15R = 15 620 = 9.3 kΩ
TH E
ก
ก (2.27) V TH = I R + V BE + ( β + ) 1 I R
B TH
B E
F
)
×
×
×
×
V TH = ( 54.977 10 − 6 × 9.3 10 3 ) + 0.6 + ( 89 54.977 10 − 6 × 620
V TH = 4.144 V
×
×
R
V CC TH 12 9.3 10 3
ก
ก (2.28) R B 1 = = = 26.930 kΩ
V TH 4.144
ก
ก
ก
185
4.
×
×
V CC TH 12 9.3 10 3
R
R B 2 = = = 14.205 kΩ
(V CC − V TH ) (12 4.144− )
ก$ * R ≥ 100R
C
L
ก
% R = 100R = 100 620 = 62 kΩ
×
L C
V − V FD )
( CC
ก
ก (4.10) I D 1 = ( R + 2R L 1 ) , I D 1 = I D 2 ;
1
−
V CC − V FD 1 12 0.6 ( 3 )
×
×
R = I D 1 − 2R = 5 10 − 6 − 2 62 10
L
1
×
R = R = 2.156 ΜΩ
1
2
Ω
Ω
Μ
Ω
* R = == = 620 , R = =Ω Ω E = = 620 , R B 1 = = = = 26.930 k , R B 2 = = = = 14.205 k , R = =Ω Ω 1 = = R = == = 2.156 ΜΩ
Μ
ΜΩΩ
Ω Ω
Ω Ω
Ω Ω Ω
Ω Ω Ω
;
C
2
R = == = 62 kΩ ΩΩ Ω
L
4.2.7.3 ก
(% 3
* 3 3 (83
*
9 3
R = 620 Ω
0 ' R = 620 Ω
C
C
R = 620 Ω
0 ' R = 620 Ω
E E
R B 1 = 26.930 kΩ
0 ' R B 1 = 27 kΩ
R B 2 = 14.205 kΩ
0 ' R B 2 = 15 kΩ
R = R = 2.156 MΩ
0 ' R = R = 2.2 MΩ
1 2 1 2
R = 62 kΩ
0 ' R = 62 kΩ
L
L
4.2.7.4 ก
*
$ : , 3'
34 $ *
ก 0 - +% # / 0 (ก (
5 ก ,
*
0
0 '
V − V )
( TH
ก
ก (2.3) I = BE
B
R TH + (β + ) 1 R E
F
I
ก
ก (2.4) I = β F B
C
}
I R +
ก
ก (2.5) V CE = V CC − { C C (β + ) 1 I R
B E
F
V − V FD )
( CC
ก
ก (4.10) I D 1 = ( R + 2R L 1 ) , I D 1 = I D 2 ;
1
!
∗
0+ V 4
; % 5 % ก ± 0.5 V
ก ก
5 . 5 # R
R
B
2
B
1
CE
ก
ก
ก
186
4.
*
*& 4.21 0 - +% # / 0 .5(4%$ %
×
×
R
V CC B 2 12 15 10 3
+ , ก
ก (2.1) V TH = = = 4.285 V
3
×
( R B 1 + R B 2 ) ( 27 10 + 15 10 3 )
×
×
×
3
R R 2 27 10 × 15 10 3
1 B
B
ก
ก (2.2) R TH = = = 9.642 kΩ
3
( R B 1 + R B 2 ) ( 27 10 + 15 10 3 )
×
×
V − V ) (4.285 0.6− )
( TH
ก
ก (2.3) I = BE = = 56.847 µA
B
+
×
R TH + ( β + ) 1 R E ( 9.642 10 3 ) (89 620 )
×
F
ก
ก (2.4) I = β F B 88 56.847 10 − 6 = 5.003 mA
×
×
I =
C
}
ก
ก (2.5) V = V − I R + ( β + ) 1 I R
CE CC { C C F B E
) (
×
×
×
V CE = 12 − ( { 5.002 10 − 3 × 620 + 89 56.847 10 − 6 × 620 )}
V CE = 5.761 V
V − V )
−
( CC FD 1 12 0.6
ก
ก (4.10) I D = I D = = = 4.905 µA
1 2 R + ) 6 ( 3 )
×
×
×
( 1 2R L 2.2 10 + 2 62 10
* I = == = 56.847 µA, I = == = 5.003 mA, I D 1 = = = = I D 2 = = = = 4.905 µA .5(V CE = == = 5.761 V/ V
CE
C
B
ก5 6 V ! , 4%
4.2.7.5 ก
(
) C B , C #% C
E
C
$% ก
%
C - +
F #
B
L
1
ก
ก (4.18) F ( L C B ) = 2 Rπ FLCB B
C
1
% & C = (4.25)
B
2 Fπ R
L C ) FLCB
( B
1
ก
ก (4.19) F =
( L C E )
π
2 R FLCE C E
Ω
ก
%
R FLCE = 0.5 , F ( L C ) = F L ;
E
1
% & C = C = (4.26)
C
E
2 Fπ R
( L C
E ) FLCE
, C .5( C
*& 4.22 (
C B E C
1
+ , ก
ก (4.25) C =
B
π
R
2 F ( L C B ) FLCB
ก
ก
ก
187
4.
+
$% C ! 0 ก3- (
ก
%
0 %% 0 #
B
F ( L C ) = F = 30 kHz
L
B
×
I C (dc ) 5.003 10 − 3
g = = = 194.669 mS
m
k T q × − 3
B 25.7 10
β 88
r b e ′ = o = − 3 = 452.049 Ω
×
g m 194.669 10
3
×
×
R R 2 27 10 × 15 10 3
1 B
B
R BB = = = 9.642 kΩ
3
×
×
R B 1 + R B 2 27 10 + 15 10 3
) }
r
R BB { bb′ + r b e ′ + (β + 1 R E
o
R FLCB = R + + + + ( β + ) }
g
R
{ BB r bb′ r b e ′ o 1 R E
×
9.642 10 3 {2 452.049+ + (89 620× )}
R = 75 + = 8.292 kΩ
FLCB 3
2 452.049 +
×
×
9.642 10 + + (89 620 )
1 1
C = =
2 F ( L C B ) FLCB 2 3.14 30 10 × 8.292 10 3
B
π
3
×
×
×
×
R
C = 640.117 pF
B
1
ก
ก (4.26) C = C =
E
C
π
2 F R
( L C E ) FLCE
Ω
$% R FLCE = 0.5 , F ( L C E ) = F = 30 kHz;
L
1 1
C = C = = = 10.615 µF
E
C
π
3
×
×
×
2 F R 2 3.14 30 10 × 0.5
L C ) FLCE
( E
* C = == = 640.117 pF,C E = = = = C = == = 10.615 µF;
B
C
4.2.7.6 ก
(% 3 *& ก; (
: (83
*
9 3
C = 640.117 pF
0 ' C = 680 pF /
ก
B
B
C = C = 10.615 µF
0 ' C = C = 15 µF . 5
E C E C
4.2.7.7 ก
*
$ F '
H
1
ก
ก (4.21) F =
H
2 Rπ C
FH T
*& 4.23 ก 0 - F #
! ,
0 ' .5(
1 +% 2
H
1
+ , ก
ก (4.21) F =
H
π
2 R C
FH T
ก
ก
ก
188
4.
$% R BB = 9.642 kΩ
( 75 9.462 10 3 ) ( + × 3 )
×
×
+
2 75 9.462 10
R = ( { R R ) r+ } = = 76.410 Ω
( 75 9.462 10 3 )
FH 1 g BB bb′
×
+
R FH 2 = r b e ′ + ( β + ) 1 R = 452.049 + (89 620× ) = 55.632 kΩ
E
F
×
×
R
R FH 1 FH 2 76.410 55.632 10 3 76.305 Ω
R = = =
FH )
( R FH 1 + R FH 2 ( 76.410 55.632 10 3 )
+
×
×
( k T q ) 25.7 10 − 3
r = r d = B = = 5.239 kΩ
d
×
1
2
I D 4.905 10 − 6
1
(
3
×
×
r +
R C ( d R L ) 620 5.239 10 + 62 10 3 )
=
R out = 1 ) ( 3 3 ) = 614.335 Ω
×
+
R +
×
( C r + R L 620 5.239 10 + 62 10
d
1
Ω
C b c ′ = C = C ob = 1.3 pF, g = 194.669 mS, r b e ′ = 452.049 ;
re
m
×
g m 194.669 10 − 3 − 12
×
C b e ′ = − C b c ′ = − 1.3 10 = 102.027 pF
2 F T 2 3.14 300 10 6
π
×
×
×
C = 102.027 10 − 12 + 1.3 10 − 12 { 1+ ( 194.669 10 − 3 × 614.335 )} = 258.796 pF
×
×
×
T
1
F = = 8.063 MHz
H − 12
×
×
×
×
2 3.14 76.305 258.796 10
6
1 +% 2 2F = 2 8.063 10 =16.126 MHz
×
=
×
H
* F = == = 8.063 MHz 1 ก 500 kHz ! , 4% .5(
1 +% 2 4% 16.126 MHz
H
4.2.7.8 ก
*
$ :)%&ก<) !!" '
34 $ *
!
5 %9 # / 0 # ( ,
ก (2.32),
*
(2.33).5( (2.34)0 -
V CC ≤ V CEO
I < 0.5I
C C (MAX)
V I < P
CE C D
*& 4.24 ก 0 - + 5 กK ( 4==D # / 0 *
+ , ก
ก (2.32), (2.33).5( (2.34)
V CC ≤ V CEO
12 V ≤ 20 V
ก
ก
ก
189
4.
!
∴
V ก
ก - V CEO
CC
I < 0.5I C (MAX)
C
)
−
×
3
×
5.003 mA < ( 0.5 30 10
5.003 mA 15 mA<
I
∴ ก 0.5I C (MAX)
C
I <
V CE C P
D
5.761 5.003 10× × − 3 < 120 mW
28.822 mW 120 mW<
∴
V I ก P
CE C D
* / 0 *4
4.2.7.9 ก
*
$ :)%&ก<) !!" ' *& * 3 3
!
5 %9 # 0 0 5! ก , ก 5 4==D 2
#
4.2.7.9.1 ก 5 4==D # R
! P (
4% ก
C R C
( 2 0.25V CC ) 2
P R C = (4.27)
R
C
4.2.7.9.2 ก 5 4==D # R
! P (
4% ก
E R E
( 2 0.25V CC ) 2
P R = (4.28)
E
R E
4.2.7.9.3 ก 5 4==D # R
! P (
4% ก
1
B
R
B
1
V
( 2 V R ) 2 2 V − ( BE + V R )} 2
{ CC
P R = B 1 = E (4.29)
B
1
R B 1 R B 1
4.2.7.9.4 ก 5 4==D # R
! P (
4% ก
R
2
B
B
2
( 2 V R ) 2 ( 2 V BE + V R ) 2
P R = B 2 = E (4.30)
B 2 R B 2 R B 2
4.2.7.9.5 ก 5 4==D # R
! P (
4% ก
1
R
1
ก
ก
ก
190
4.
( )
V
2 V 2 2 V − ( FD + 2I R )} 2
D
{ CC
P = 1 R = 1 1 L (4.30a)
R
1
R
1 R 1
4.2.7.9.6 ก 5 4==D # R
! P (
4% ก
2 R 2
( )
V
2 V R 2 2 V − ( FD + 2I D R L )} 2
{ CC
P R 2 = 2 = 2 2 (4.30b)
R
2 R 2
*& 4.25 ก 0 - + 5 กK ( 4==D # 0 0
×
( 2 0.25V CC ) 2 ( 2 0.25 12 ) 2
+ , ก
ก (4.27) P R = P R = = = 29.032 mW
E
C
R C 620
1
R = 620 Ω ± 5% 5! ก , # % W (125 mW)
C
8
×
( 2 0.25V CC ) 2 ( 2 0.25 12 ) 2
ก
ก (4.28) P R E = R E = 620 = 29.032 mW
1
R = 620 Ω ± 5% 5! ก , # % W (125 mW)
E
8
V
+
( 2 V R ) 2 2 V − ( BE + V R )} 2 2 {12 − (0.6 3 )} 2
{ CC
ก
ก (4.29) P R B 1 = B 1 = E = 3
×
R
B 1 R B 1 27 10
P R = 5.226 mW
B 1
1
R B 1 = 27 kΩ ± 5% 5! ก , # % W (125 mW)
8
2 V ) 2 ( 2 V BE + V R ) 2 ( 2 0.6 3+ ) 2
( R
ก
ก (4.30) P R B 2 = B 2 = E = 3 = 1.728 mW
×
R
B 2 R B 2 15 10
1
R B 2 = 15 kΩ ± 5% 5! ก , # % W (125 mW)
8
( )
V
2 V 2 2 V − ( FD + 2I R )} 2
D
{ CC
ก
ก (4.30a) P = 1 R = 1 1 L
R 1
R
1 R 1
)}
× ×
2 12 − { 0.6 + ( 2 5 10 − 6 × 62 10 3 2
×
P = = 0.105 mW
1 R 6
×
2.2 10
P = P
R
R
1
2
1
R = 2.2 ΜΩ ± 5% 5! ก , # % W (125 mW)
1
8
1
R = 2.2 ΜΩ ± 5% 5! ก , # % W (125 mW)
2
8
* (4%
0 % &
ก
ก
ก
191
4.
1 1
R = 620 Ω ± 5% W, R B 1 = 22 kΩ ± 5% W;
C
8 8
1 1
R = 620 Ω ± 5% W, R B 2 = 11 kΩ ± 5% W;
E
8 8
1 1
R = 2.2 ΜΩ ± 5% W, R = 2.2 ΜΩ ± 5% W;
2
1
8 8
4.2.7.10 ก
*
$ :)%&ก<) !!" ' *& ก; (
:
+
+
!
5 %9 # 0 ก3- ( 0 5! ก , 0 ก3- (
. % 4==D ก (. 0 1 ก . % 4==D 0ก
2
4.2.7.10.1 . % ก (. 0 # C (
4% ก
C
V C C = ( 2 0.5V CC + 0.25V CC ) = ( 2 0.75V CC ) (4.31)
4.2.7.10.2 . % ก (. 0 # C (
4% ก
E
V C E = ( 2 0.25V CC ) (4.32)
4.2.7.10.3 . % ก (. 0 # C (
4% ก
B
V = ( 2 0.25V + 0.6 V ) (4.33)
C B CC
*& 4.26 ก 0 - + 5 กK ( 4==D # 0 ก3- ( +
+ , ก
ก (4.31) V C C = ( 2 0.75V CC ) = ( 2 0.75 12× ) 18 V=
C = 15 µF , %. 5
. % 16 V
C
ก
ก (4.32) V C E = ( 2 0.25V CC ) = ( 2 0.25 12× ) = 6 V
C = 15 µF , %. 5
. % 6.3 V
E
ก
ก (4.33) V = ( 2 0.25V + 0.6V ) = 2 ( { 0.25 12× ) 0.6+ } 7.2 V=
C B CC
C = 680 pF, % /
ก . % 50 V
B
* (4% 0 ก3- ( +% &
C = 680 pF 50 V /
ก
B
C = 15 µF 6.3 V. 5
E
C = 15 µF 16 V . 5
C
ก
ก
ก
192
4.
4.3
# 3
*
.-- * 0 ,
5 กก 2
ก % 5! ก
*
2 ( ;5- ก
< - 5( %4% % & :-
C F 1 5.5 MHz
Q 1 OSC Q MIXER
1 MHz 2
5.5 MHz
E
g
4.5 MHz
1 4.15 . %
.-- * 0 * ก 4.5 MHz 5.5 MHz
− Q OSC
/ 5 5 0 *.--. 5 L ก %
1 MHz
1
− L .5( C
- +
ก ก %
1 MHz
3
1
− C C C .5( L
D ก5 -.-- ,!
0 3 +%
,
,
1
1
2
3
MIXER
# . % 4.5 MHz .5( 1 MHz ก
− Q
2
*
/ 5 5 0 * ก # 5 53ก 0
4%;5- ก# , ;50 , 4.5 MHz
.5( 1 MHz
− C
,!
0 # # -
B
− C
,!
0 ก# Q ; R
.ก C F 1 5.5 MHz
2
C
3
2
C
5.5 MHz
ก
5.5 MHz ;
.ก R /
− C
F 1 L
5.5 MHz ก % ก;5- ก# 4.5 MHz ก - 1 MHz
.-- * 0 * ( 5
ก %
4.5 MHz ก5 5.5 MHz
OSC ,
ก # / 5 5 0 *.--. 5 L
ก (
# Q
1
$
:(
ก
2 ก
# % ก
1 2 $%
>
5 กก # ก ก (. 4==D .-- 03
5! $% 4
0 ก ก (. 4==D
- 4%$ %
, 4% .ก , 00*ก 4%$ %
ก
ก
ก
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