193
4.
*
ก , / 0 % = .5(# . % 4==D D
.ก 4%$ %
0 - ,
4% ก
*
.-- * 0 ,
5 กก 2
ก % 5! ก
2 (
;5- ก
______________________________
ก
ก
ก
194
4.
ก
ก
ก
5
ก ก ก !
" #$%
)
& "&' & % * ก
( +,
$- ,.) / *
(
. !
& ก & ( & # % !ก(
!""
0&
,
, !""2
, !"" 3 3 ) 4
ก, !""!&
$$5 !
!"" 3 ! & "&' &
ก &
!
ก!""
!"" ( 6 ก (
7 3 " ก 4# % $8 "
ก "ก
#
!
!""9ก " $- ก "
:
5.1
3 !"
'
!"" 3. ( 3 $- ก #$% $< ก
"
$ ก " Z Z !
Z
,
3
2
1
r b e ′ V b e ′ g V
m b e ′
Q 1
Q 1
I b I c
I z
r d
g Vr
V m d
Q 2 Q 2
I d
z I
'
(
#$ 5.1 !
!"" 3. 3
ก #$ 5.1 ก. !
*. !
!"" 3. 3 ' 0 3
(
ก
ก
ก
196
5.
!
%BB< ก !
"0 3 !""
%2" -%,
'
ก #$ 5.1 &. !
. !
!"" 3. ( 3 0 3 B !
%BB< ก !
"0 3 !""
%2" -%,
5.1.1 ก
$%
& '
ก #$ 5.1 *. ! ก %
#$ I 0 = I r + I Z − I Z
b b e ′
b
b
z
1
1
0 = I b ( b e ′ + Z 1 ) I Z− z 1 (5.1)
r
#$ I I = g V
m b e ′
c
c
#$ I 0 = I Z + I Z + I Z − I Z + I Z
z z 1 z 2 z 3 b 1 c 2
0 = I z ( Z + Z + Z 3 ) I Z− b 1 + I Z
1
2
2
c
. ก I = g V !
V = I r
c m b e ′ b e ′ b b e ′
0 = I ( Z + Z + Z ) I Z− + g I r Z
z 1 2 3 b 1 m b b e ′ 2
0 = I b ( m b e ′ 2 Z 1 ) I+ z ( 1 Z + Z 3 ) (5.2)
Z +
g r Z −
2
∆
b z
ก ก (5.1)!
(5.2)
!
* $ D E ( )* I !
I
( r b e ′ + Z 1 ) ( Z− 1 )
∆ =
( g r Z − Z 1 ) ( 1 Z + Z 3 )
Z +
m b e ′
2
2
∆ = (r b e ′ + Z 1 )( Z + Z + Z 3 ) ( g r Z− m b e ′ 2 − Z 1 )( Z− 1 )
2
1
∆ = (r b e ′ + Z 1 )( Z + Z + Z 3 ) ( g r Z+ m b e ′ 2 − Z 1 )( )
Z
1
1
2
. ก ก
∆ ( ก " 0
∆ = ( r b e ′ + Z 1 )( Z + Z + Z 3 ) ( g r Z+ m b e ′ 2 − Z 1 )( ) 0Z 1 =
2
1
+
g r Z −
Z +
0 = ( b e ′ + Z 1 )( 1 Z + Z 3 ) ( m b e ′ 2 Z 1 )( )
r
Z
2
1
=
0 r b e ′ ( Z + Z + Z 3 ) Z Z+ 1 1 + Z Z + Z Z + g r Z Z − Z Z
m b e ′
1 1
1 3
1 2
1 2
2
1
=
0 r b e ′ ( Z + Z + Z 3 ) Z Z+ 1 2 + Z Z + g r Z Z
m b e ′
1 2
1
1 3
2
0 = r b e ′ ( 1 Z + Z 3 ) Z+ 1 ( Z + Z + g r Z 2 ) (5.3)
Z +
m b e ′
3
2
2
ก
ก
ก
197
5.
. ก Z = JX 1 , Z = JX !
Z = JX
3
2
2
1
3
0 = r b e ′ ( JX + JX + JX 3 ) + JX 1 ( JX + JX + g r JX 2 )
m b e ′
2
3
2
1
2
0 = Jr b e ′ ( X + X + X 3 ) + J X 1 ( X + X + g r X 2 )
m b e ′
1
2
2
3
0 = Jr b e ′ ( X + X + X 3 ) − X 1 ( X + X + g r X 2 )
m b e ′
1
2
3
2
0 = Jr b e ′ ( X + X + X 3 ) − X 1 { X 2 (1 g r+ m b e ′ ) + X 3 } (5.4)
1
2
ก ก (5.4) G , 3 ก $ &( & 0 !
* . &( &
ก ก
0 = Jr b e ′ ( X + X + X 3 )
2
1
Jr
b e ′
0 = X + X + X (5.4a)
3
1
2
ก ก (5.4) 3 ก $ &( g r *
m b e ′
0 = − X 1 { X 2 (1 g r+ m b e ′ ) + X 3 }
X
−
1
0 = X 2 (1 g r+ m b e ′ ) + X 3 (5.4b)
X = − X 3 (5.5)
2
(1 g r+ m b e ′ )
.
ก ก (5.5) X ( 3 ก " X 0 ก &
" !
X 2 < −X
3
2
3
ก ก (5.5)! &( ก (5.4a)
X
0 = X − 3 + X 3
1
+
(1 g r )
m b e ′
X
X = 3 − X 3
1
(1 g r+ m b e ′ )
X − X (1 g r+ ) X − X − X g r
X = 3 3 m b e ′ = 3 3 3 m b e ′
1
+
+
(1 g r ) (1 g r )
m b e ′
m b e ′
g r
X ( m b e ′ )
X = − 3 (5.6)
1
(1 g r+ m b e ′ )
< −X
ก ก (5.6) X ( 3 ก " X !
X
1 3 1 3
ก
ก
ก
198
5.
ก (5.6) (5.5) % ก
÷
X X ( g r ) (1 g r+ )
1 = − 3 m b e ′ − m b e ′
X 2 (1 g r+ m b e ′ ) X 3
X 1 = g r
X 2 m b e ′
. ก g r = β = β F
m b e ′
o
β = X 1 (5.7)
o X 2
(
ก ก (5.7) β $- * ก ! I c * ก ก
!""
)
o
I
b
X
ก( ก ก
β > 1
o
X 2
ก ก (5.5), (5.6) !
(5.7) '$% ) :-
− X ( 3 ก " X !
X < − X
2 3 2 3
− X ( 3 ก " X !
X < − X
3
1
3
1
X X
− β = 1 ก ก!""&
. ก
&( β = β > 1
F
o
o
X X
2 2
− X > X
1 2
ก ( 3 * X X !
X ก
* ) 2 !"" )
1 , 2 3
5.1.1.1
(
!""2
(Hartley Oscillator) 0 Z Z $-
1 , 2
, #(" !ก ก !
! 7$ ก ( Z $- ก7"$ ' ! #$
3
5.2 % ก
Q 1 Q 1
L 1 L 2
C 3
#$ 5.2 ! ก $
Z Z !
Z $- L L !
C * !""2
1 , 2 3 1 , 2 3
ก ก (5.4a) 0 = X + X + X
3
2
1
1
. ก X = J L , X = J L !
X =
ω
ω
1 1 2 2 3
ω
J C 3
ก
ก
ก
199
5.
1
ω
0 = J L + J L +
ω
1 2
ω
J C 3
Jω
1
0 = L + L +
1 2 2 2
J ω C 3
1
0 = L + L −
1 2 2
ω C 3
1
= L + L 2
1
2
ω C 3
1
ω C =
2
3
L +
1 L 2
1
2
ω =
L +
( 1 L 2 ) C 3
1
ω =
( L + L 2 ) C 3
1
. ก ω = 2 F 0 F $- &( & *
π
o o
) F = 1 (5.7a)
o
2π ( 1 L 2 ) C 3
L +
. ก L !
L $- #(" !ก ก % ก ! 7$
1
2
ก
กY $- ก ( !"" 'ก !
Z ! (
7ก%BB< ก $ % ก
ก
L = ( L + L 2 ) 2 L L+ 1 2 (5.8)
1
T
! ก (5.8)
(L + L 2 ) * ก (5.7a) % ก (
1
F = 1 (5.9)
o
2π L C 3
T
) 5.1 ก #$ 5.3 $ &( & *
!""2
T 1 2 1 2
* + ก ก (5.8) L = ( L + L ) 2 L L+
0 L = 160 µH, L = 20 µH;
1
2
×
×
×
L = 180 10 − 6 + 2 160 10 − 6 × 20 10 − 6
T
L = 293.137 µH
T
ก
ก
ก
200
5.
ก ก (5.9) F = 1
o
2π L C 3
T
0 C = 100 pF, L = 293.137 µH;
3 T
1
F = = 930.047 kHz
o
(2 3.14× ) 293.137 10× − 6 × 100 10 − 12
×
&( & *
!""2
&. 930.047 kHz
C = 10C = 1000 pF
3
1
C = C = 100 pF,C = 0.015 µF,
Q 1 2 3 4
L = 160 µH, L = 20 µH;
1 2
L 1
C 3
L 2
#$ 5.3 ! 3 *
!""2
5.1.1.2
- .
!""0&
,
(Colpitts Oscillator) 0 Z Z $-
1 , 2
&( ! ก!
* ก7"$ !
Z $- &( ! ก!
* ! $ 5.4
'
#
3
Q
Q 1 1
C 1 C 2
L 3
#$ 5.4 ! ก $
Z Z !
Z $- C C !
L * !""0&
,
,
,
2
1
3
2
1
3
ก #$ 5.4 !
ก ก (5.4a)
0 = X + X +
X
1
3
2
1 1
ω
. ก X = , X = !
X = J L
1 2 3 3
ω
ω
J C J C
1 2
1 1
ω
0 = + + J L
3
ω
ω
J C J C 2
1
ก
ก
ก
201
5.
Jω &#
1 1
2
0 = + + J ω 2 L 3
C 1 C 2
1 1
0 = + − ω 2 L 3
C 1 C 2
1 1 C + C
ω 2 L = + = 1 2
3
C 1 C 2 C C
1 2
1 C + C
ω = × 1 2
2
L 3 C C
1 2
. ก C + C 1 = 1
2
C C C C
1 2 1 2
C + C
2 1
ω = 1 × 1 = 1
2
L 3 C C C C
1 2
1 2
C + C 1 L 3 C + C 1
2
2
C C
1 2
ก C = C + C (5.10a)
T
2
1
1
2
ω =
L C
3 T
1 1 1
ω = = =
C L 3 C L 3 C L 3
T
T
T
. ก ω = 2 F 0 F $- &( & *
!""0&
,
π
o
o
F = 1 (5.10b)
o
2π C L 3
T
C = C = 100 pF, L = 127 µH;
1
2
3
Q C = 1000 pF, C = 10 pF;
1
3 4
C 3
C 1 C
L 3 4
C 2
#$ 5.5 ! 3 *
!""0&
,
) 5.2 ก #$ 5.5 $ &( & *
!""0&
,
1
* + ก ก (5.10b) F =
o
2π C L 3
T
ก
ก
ก
202
5.
×
×
C C 100 10 − 12 × 100 10 − 12
0 C = 1 2 = = 50 pF
T
C + C × − 12 + × − 12
1 2 100 10 100 10
L = 127 µH
3
F = 1 = 1.998 MHz
o − −
(2 3.14× ) 50 10× 12 × 127 10 6
×
&( & *
!""0&
,
&. 2 MHz
5.1.2 ก
$%
& ' /
ก #$ 5.1 &. !
. % ก
#$ I g Vr = (Z + +
z
2
d m d I d 2 r d ) I Z
. ก V = I Z !
r &. &( & G ( * ก " * B
1
d
z
g I Z r = I (Z + r ) I Z
+
m z 1 d d 2 d z 2
0 = I d (Z + r d ) I Z − g I Z r
+
1 d
2
2
z
m z
0 = I d (Z + r d ) I z ( Z − g Z r ) (5.11)
+
2
2
m
1 d
#$ I 0 = I Z + I z ( 1 Z + Z 3 ) (5.12)
Z +
2
2
z
d
ก ก (5.11)!
(5.12) ! * $ D E* I !
I
d
z
∆ = ( Z + r d ) ( Z − g Z r )
2
m
1 d
2
Z 2 ( Z + Z + Z 3 )
2
1
∆ = ( Z + r d )( Z + Z + Z 3 ) ( Z 2 )( Z − g Z r )
−
1
2
2
m
1 d
2
Z +
+
∆ = r d ( 1 Z + Z 3 ) Z Z + Z Z + Z Z − Z Z + g Z Z r
2 3
2 2
1 2
m
2 2
2
1 2 d
+
∆ = r d ( 1 Z + Z 3 ) Z Z + Z Z + g Z Z r
Z +
1 2
2 3
2
m
1 2 d
Z +
Z +
∆ = r d ( 1 Z + Z 3 ) Z 2 ( 1 Z + g Z r )
+
1 d
3
2
m
+
+
+
∆ = r d ( 1 Z + Z 3 ) Z 2 { 1 (1 g r ) Z 3 }
Z +
Z
2
m d
. ก ก
( ( . &( ∆ ( ก " 0
0 = r d ( Z + Z + Z 3 ) Z+ 2 { 1 (1 g r+ m d ) Z+ 3 } (5.13)
Z
1
2
. Z = JX 1 , Z = JX !
Z = JX ! &(
ก (5.13)
2
1
2
3
3
ก
ก
ก
203
5.
0 = r d ( JX + JX + JX 3 ) JX+ 2 {JX 1 (1 g r+ m d ) JX+ 3 }
1
2
0 = Jr d ( X + X + X 3 ) J X+ 2 2 { X 1 (1 g r+ m d ) + X 3 }
2
1
0 = Jr d ( X + X + X 3 ) − X 2 { X 1 (1 g r+ m d ) + X 3 } (5.14)
2
1
.
ก ก (5.14) G , 3 ก $ &( & 0 !
* &
ก ก
0 = Jr d ( X + X + X 3 )
2
1
Jr
d
0 = X + X + X (5.15a)
1 2 3
ก ก (5.14) 3 ก $ &( ! %BB< *
0 = − X 2 { X 1 (1 g r+ m d ) + X 3 }
− X
2
0 = X 1 (1 g r+ m d ) + X (5.15b)
3
X = − X 3 (5.16)
1
(1 g r+ m d )
.
ก ก (5.16) X ( 3 ก " X 0 ก &
" !
X < − X
1 3 1 3
ก ก (5.16)! &( ก (5.15a)
X
0 = − 3 + X +
X
3
2
(1 g r+ m d )
X 3
X = (1 g r+ ) − X 3
2
m d
X − X (1 g r+ ) X − X − X g r
X = 3 3 m d = 3 3 3 m d
2
(1 g r+ m d ) (1 g r+ m d )
X = − X 3 ( g r ) (5.17)
m d
2
+
(1 g r )
m d
ก ก (5.17) X ( 3 ก " X !
X < − X
2 3 2 3
ก (5.17) (5.16) % ก
÷
X 2 = − X 3 ( g r ) (1 g r+ m d )
m d
× −
+
X 1 (1 g r ) X 3
m d
ก
ก
ก
204
5.
X 2 = g r (5.18)
m d
X 1
V∆ I ∆ ∆ V V
. ก g r = D × DS = DS . g r = ds ) g r &. * !
m d m d m d
∆ V GS I ∆ D ∆ V GS V gs
* B * ก ก
ก ก (5.16), (5.17)!
(5.18) '$% ) :-
− X ( 3 ก " X !
X < − X 3 ;
1
3
1
− X ( 3 ก " X !
X < − X ;
2 3 2 3
X X
− g r = 2 ก ก!""&
. ก B &( g > 2
m d m
X 1 X r
1 d
− X >
X
1
2
( , X !
X ก
0 3 B 2 !""
ก 3 * X 1 2 3
5.1.2.1
(
-" & ' /
0 L L $- , #(" !ก ก !
! 7$ ก
,
2
1
'
C $- ก7"$ ! #$ 5.6
3
Q
2
Q 2
L 1 L 2
C 3
#$ 5.6 ! ก $
Z Z !
Z $- L L !
C * !""2
0 3 B
,
,
2
2
3
1
1
3
ก #$ 5.6 !
ก ก (5.15a)
0 = X + X + X
1 2 3
1
ω
. ก JX = J L !
JX = J L $- &( ! ก!
* !
JX =
ω
1 1 2 2 3
ω
J C 3
$- &( ! ก!
* ก7"$ ! ก %
'
0 = J L + J L + 1
ω
ω
1 2 J C 3
ω
(
' * ก % 4
,D
3( ก " ก %$ )
ก ก (5.8) L = ( L + L ) 2 L L+
T 1 2 1 2
1
ก ก (5.9) F =
o
2π L C
T 3
ก
ก
ก
205
5.
V DD = 20 V
N-CH D
G
Q 2
S
C 1
100 pF
C 2
R S 10 pF
L 1 18 µH 750 Ω
C 3
R GG
47 kΩ 10 pF L 2 0.6 µH R L
1 kΩ
#$ 5.7 ! 3 *
!""2
0 3 B
) 5.3 ก #$ 5.7 $ &( & *
!""2
* + ก ก (5.8) L = ( L + L 2 ) 2 L L+ 1 2
T
1
×
×
×
×
L = ( 18 10 − 6 + 0.621 10 − 6 ) + 2 18 10 − 6 × 0.621 10 − 6
T
L = 25.307 µH
T
1
ก ก (5.9) F =
o
2π L C
T 3
0 L = 25.307 µH, C = 10 pF;
3
T
1
F = = 10 MHz
o
(2 3.14× ) 25.307 10× − 6 × 10 10 − 12
×
&( & *
!""2
&. 10 MHz
5.1.2.2
- . -" & ' /
'
0 Z !
Z $- &( ! ก!
* ก7"$ Z $- &( ! ก!
3
2
1
* ! #$ 5.8
Q 2 Q 2
C 1 C 2
L 3
#$ 5.8 ! ก $
Z Z !
Z $- C C !
L * !""0&
,
,
,
1
2
3
3
2
1
ก ก (5.15a) 0 = X + X +
X
1 2 3
1 1
. ก JX = , JX = !
JX = J L ! ก %
ω
1 2 3 3
ω
ω
J C 1 J C 2
ก
ก
ก
206
5.
1 1
ω
0 = + + J L
3
ω
ω
J C J C
1 2
' * ก % 4
,D
3( ก " ก (5.10a)!
(5.10b)
C C
1 2
ก ก (5.10a) C = C + C
T
2
1 1
o
ก ก (5.10b) F =
2π
C L
T 3
Q 2
C 80 pF
1
C 2 80 pF
#$ 5.9 !
!""0&
,
0 3 B
) 5.4 ก #$ 5.9 $ &( & *
!""0&
,
×
×
C C 80 10 − 12 × 80 10 − 12
* + ก ก (5.10a) C = 1 2 = = 40 pF
T
C + C ( − 12 − 12 )
×
×
2 1 80 10 + 80 10
1
ก ก (5.10b) F =
o
2π C L 3
T
0 C = 40 pF, L = 200 µH;
3
T
1
F = = 1.78 MHz
o
( 2 3.14 ) 40 10 − 12 × 200 10 − 6
×
×
×
&( & *
!""0&
,
&. 1.78 MHz
5.1.3 ก
! 1
& ' -L C &%'
3 -L C % !ก( !""2
, !""0&
,
!
!""!&
$$5 ก ก $
!$
* & 3 *
'
, C !
C !ก %*0 ก ก!""
5.1.3.1 ก $
!$
&( r b e ′ , C b e ′ , C b c ′ iss rss
' * G ,
ก
ก
ก
207
5.
5.1.3.2 ก $
!$
&( * -L C . ก ' G# !
ก . $_
)!ก %* ก ! (ก7 !ก %*0 ก 3 3 ) 4
ก!
.
5.1.3.3 ก $
!$
&( * 0
4
( & ก&( C ′ b c (1+ g R )
m out
% (& $
!$
&( * 0
!ก %*0 3 " B B (& % ( ก "0
4
'
5.2
& 2 3 ก
!"" 3 3 ) 4
ก Z ก * 3 ) 4
ก & &
% #$% G , & # ก
5.2.1
.
.
&
&
(Quartz Crystal) 4
ก&
ก4
ก &
(
3 " ก ( c * ) ' d $- !4( " 3 !4( 0
$ ก" ) !
*
ก 3 &( & * ) #(ก "& * 3 ) 4
ก $_ '" 3 ) 4
ก ก
& % # ' % ( ก 18 MHz . ก & " ก . ก ก * 0 !
3 ) 4
ก $- '$ก
$ G , 0
7ก ก . ! ก ( 3 ) 4
ก )
!
! ก ) ก 3 ) 4
ก !
4
%BB< ก & ( ก " &( &
&' " * 3 ) 4
ก (& * 3 ) 4
ก) ก
"ก . $< ! ก !
"
& ก " & &' " * 3 ) 4
ก 3 ) 4
ก ก ก 0 !
( ' !
ก ! %BB< %
4( 3 ) 4
ก ก 0 !
$- !"" 'ก #
! #$ 5.10
R S
C
C P S
L S
#$ 5.10 !
กY
!
#
* 3 ) 4
ก
ก #$ 5.10 % ก
ก
ก
ก
208
5.
1
F = (5.19)
OS
2π L C
S S
0 F &. &( & * ก ก 0 !
!"" 'ก
OS
L &. &( & 'ก #
* 3 ) 4
ก
S
'
C &. &( & 'ก #
* 3 ) 4
ก
S
C S
L
C P S
#$ 5.11 ! #
* 3 ) 4
ก* & # ก ( F 0
) R S
OS
ก #$ 5.11 ก ก 0 !
!""* % ก
1
F OP = (5.20)
2π L S C C P
S
C + C P
S
0 F &. &( & * ก ก 0 !
!""*
OP
L &. &( & 'ก #
* 3 ) 4
ก
S
'
C &. &( & 'ก #
* 3 ) 4
ก
S
'
(
C &. &( & * ก ก!4( 0
!4 * 3 ) 4
ก
P
Ω
) 5.5 ก #$ 5.10 !
5.11 R = 150 , C = 2.5 pF, L = 45.077 µH!
C = 100 pF
P
S
S
S
$ &( F !
F OP
OS
1
* + ก ก (5.19) F OS =
2π L C S
S
1 15 MHz
F = =
OS − 6 − 12
×
×
×
(2 3.14) 45.077 10 × 2.5 10
ก ก (5.20) F OP = 1
S
2π L S C C P
C S + C P
ก
ก
ก
209
5.
1
F OP = − −
×
×
(2 3.14 ) 45.007 10 − 6 2.5 10 12 × 100 10 12
×
×
12
×
×
2.5 10 − 12 + 100 10 −
F OP = 15.198 MHz
F = = = = 15 MHz, F = = = = 15.198 MHz;
OS OP
(
4
$ ก83 ก7"$ * ก "3 ) 4
ก 0 &( # ก ( C
(
'
S
(
! & $
!$
,
7ก
5.2.2
3 !"-" & ' 2 3 4ก
ก #$ 5.12 ก. !
*. % , e $- 3 2 ! #$ 5.13 ก.
!
*.
Q Q
1 2
X 1 X 2 X 1 X 2
X 3 (C ′ ) X 3
b c
#$ 5.12 !
!"" 3. 3 0 3 3 ) 4
ก
(
'
ก #$ 5.13 ก. $-
!""2
0 3 3 ) 4
ก 0 X $-
1
3 ) 4
ก X $- L !
X $- C ,. % & ก $- 3 # ( L C )
2 2 3 b c ′ 2 T
&
. ก
L (X 2 )
2
(X 3 ) C b c ′ Q 2
Q 1
#$ 5.13 ! 3 !"" 3. ( 3 ' 0 3 3 ) 4
ก
ก
ก
ก
210
5.
ก #$ 5.13 *.
!""0&
,
0 3 3 ) 4
ก 0 X $-
3
)
3 ) 4
ก, X $- C !
X $- C % ( 3 &( & *
1 1 2 2
#กก 0 3 ) 4
ก
5.3 ก
ก
(
-" & '
ก #$ 5.14 ก!""
!""2
ก & 500 kHz 0
Ω
Ω
ก I C = 5 mA, β F = β o = 100,V BE = 0.6 V,V CC = 12 V, F T = 300 MHz, r bb ′ = 2 , R L = 10 k ,
C ob = C = 1.3 pF;
re
L , N
1 1
L
T
Q 1 L 2 , N 2 L 3 , N 3
L 1
V
C 3 L o L = 256 µH, N = 80 T;
1
1
2
L = 9 µH, N = 15 T;
2 2
#$ 5.14 !
!""2
3 ก!""
X
ก ก (5.7) β o = 1
X
2
X
ก β = = 1
n
o
X 2
X = nX 2
1
ω L = n L
ω
1 2
L = nL (5.21)
2
1
n
0 = β &. * ก ! *
*
o
! &( ก (5.21)
ก (5.8)
L = nL + L + 2 nL L
T 2 2 2 2
L = nL + L + 2L 2 n
2
T
2
L = L 2 ( n + 1 2 n )
+
T
ก
ก
ก
211
5.
L T
L 2 = (5.22)
( +n ) 1 + 2 n
1
ก ก (5.9) F = ก $ &( L
o T
2π L C 3
T
L T = 1 (5.23)
C 3 ( 2 F o ) 2
π
5.3.1 ก
5
$ 6 L L $C
1 , 2 3
. ก & * ก
( ก " 500 kHz
T 1 2 1 2
ก ก (5.8) L = ( L + L ) 2+ L L
ก ก (5.23) L T = 1
C 3 (2 Fπ o ) 2
) 5.6 $ &( L L !
C
,
1 2 3
* + ก ก (5.8) L T = ( L 1 + L 2 ) 2+ L L
1 2
×
×
×
×
L = ( 256 10 − 6 + 9 10 − 6 ) + 2 256 10 − 6 × 9 10 − 6 = 361 µH
T
ก ก (5.23) L T = 1
C 3 (2 Fπ o ) 2
1 1
C = =
3
×
×
×
×
L T (2 Fπ o ) 2 ( 361 10 − 6 )( 2 3.14 500 10 3 ) 2
C = 280.952 pF
3
C = == = 280.952 pF !
L L 3 OSC AM (! / )
! #$ 5.14
,
3 1 2
5.3.2 ก
5
$ 6 R B 1 , R B 2 , R $ R
E
C
. ก I = 5 mA
C
ก ก (2.21-2.23) V = 0.5V ,V = 0.35V ,V = 0.15V ;
CE CC RC CC RE CC
0.35V
ก ก (2.24) R = CC
C
I
C
0.15V
ก ก (2.25) R = CC
E
( β + ) 1 I B
F
ก ก (2.26) R = 15R
TH E
ก ก (2.27) V TH = I R +V BE + ( β F + ) 1 I R
B TH
B E
ก
ก
ก
212
5.
R
R
V CC TH V CC TH
ก ก (2.28) R = , R = ;
B 1 B 2
V V − V )
TH ( CC TH
) 5.7 $ &( R , R , R !
R . ก I = 5 mA !
$ " $- &( /
B 1 B 2 E C C
* + V CE = 0.5V CC ,V RC = 0.35V CC ,V RE = 0.15V CC ;
×
V = 0.5 12 = 6 V
CE
×
V = 0.35 12 = 4.2 V
RC
=
×
V RE = 0.15 12 1.8 V
×
I C 5 10 − 3
I = β F = 100 = 50 µA
B
0.35V 4.2
ก ก (2.24) R = CC = = 840 Ω
C
×
I C 5 10 − 3
×
0.15V 0.15 12
ก ก (2.25) R = CC = = 356.435 Ω
E
( β + ) 1 I B 50 10 − 6 (100 1+ )
×
F
×
=
ก ก (2.26) R TH = 15R = 15 356.435 5.346 kΩ
E
ก ก (2.27) V TH = I R +V BE + ( β F + ) 1 I R
B TH
B E
)
×
×
×
×
V = ( 50 10 − 6 × 5.346 10 3 ) + 0.6 + ( 101 50 10 − 6 × 356.435
TH
V TH = 2.667 V
V CC TH
R
ก ก (2.28) R B 1 =
V TH
R
V CC TH
R B 2 =
(V CC − V TH )
×
×
12 5.346 10 3
R B 1 = = 24.053 kΩ
2.667
×
×
12 5.346 10 3
R = = 6.873 kΩ
B 2
(12 2.667− )
$
$- &( /
R = 840 Ω $- &( / R = 820 Ω
C C
R E = 356.435 Ω $- &( / R E = 360 Ω
R B 1 = 24.053 kΩ $- &( / R B 1 = 24 kΩ
R = 6.873 kΩ $- &( / R = 6.8 kΩ
B 2 B 2
Ω
Ω
Ω
R = == = 820 , R = =Ω Ω = = 360 , R = = = = 24 k , R = = = = 6.8 k ;
Ω Ω Ω
Ω Ω
Ω Ω Ω
Ω Ω Ω
C E B 1 B 2
ก
ก
ก
213
5.
5.3.3 ก
5
$ 6 C B , C $ C
E
C
0 C !
C 3. ( 500 kHz ก &( C ( ก " 10 (
B
E
B
* C !
C ( ก " C
3 E 3
C = 10C 3 , C = C 3 ;
B
E
C " ,
500 kHz
ก
ก &( X &( $
C
C
C
0.5-10 Ω
1
C = (5.24)
C
π
2 F X C C
o
) 5.8 $ &( C B , C !
C
E
C
1
* + ก ก (5.24) C =
C
π
2 F X
o C C
0 F = 500 kHz, X C C = 10 ;
Ω
o
1
C = = 0.0318 µF
C
2 3.14 500 10 × 10
×
3
×
×
×
C = 10C = 10 280.952 10 − 12 = 0.0028 µF
×
3
B
C = C = 280.952 pF
3
E
!
$
$- &( /
C = 0.0028 µF $- &( / C = 0.0033 µF ก
B
B
C = 0.0318 µF $- &( / C = 0.033 µF ก
C C
C = 280.952 pF $- &( / C = 270 pF ก
E
E
C = == = 0.0033 µF, C = == = 0.033 µF !
C = == = 270 pF
E
C
B
5.3.4 ก
5
$ 6 β ββ β 1
F
X
ก ก (5.7) β = 1
o
X 2
0 X = L = 256 µH, X = L = 9 µH;
1 1 2 2
×
L 256 10 − 6
β o = 1 = = 28.444
×
L 2 9 10 − 6
&( β % ก * ) *
! (ก( ก ก
o
β o > 28.444 0
. ก$ 80 100
) Q & β = $ 80 100
1 F β o
ก
ก
ก
214
5.
'
5.4 ก
ก
- . -" & /
Q 2
C
L 3 1
C 2
#$ 5.15 !
!""0&
,
3 ก!""
ก #$ 5.15 ก!"" !""0&
,
0 3 B ก & 500 kHz ก
I D = 5 mA, I DSS = 10 mA ,V P = − 2.5 V,V DD = 12 V, C iss = 3 pF, C rss = 0.035 pF !
R L = 10 kΩ
1)2 ก
ก
X 2
ก ก (5.18) g r =
m d
X 1
X 2
n
ก g r = =
m d
X
1
X = nX 1
2
1 = n
ω
ω
J C J C
2 1
1 = n
C 2 C 1
C = nC (5.25)
1 2
0 = g r &. * ! * B *
n
m d
C C
ก ก (5.10a) C = 1 2
T
C + C
1 2
! &( (5.25)
(5.10a)
nC C
C = 2 2
T
nC + C 2
2
nC
C = 2
T
n + 1
C T ( +n ) 1
) C 2 = (5.26)
n
ก
ก
ก
215
5.
1
ก ก (5.10b) F =
o
2π C L
T 3
1
C L =
T
3
(2 Fπ o )
1
) C = (5.27)
T 2
π
L ( 2 F )
3 o
,
5.4.1 ก
5
$ 6 C C , L $ RFC
1 2 3 1
ก ก (5.25) C = nC
1 2
C T ( +n ) 1
ก ก (5.26) C 2 =
n
1
ก ก (5.27) C =
T 2
L (2 Fπ )
3 o
ก RFC = 4L
1 3
) 5.9 ก #$ 5.15 $ &( C C L !
RFC . ก F = 500 kHz,
,
,
1 2 3 1 o
L = 360 µH !
n = 1
3
1
* + ก ก (5.27) C =
T 2
L 3 (2 Fπ o )
0 F = 500 kHz, L = 360 µH;
o 3
1
C = = 281.733 pF
T 2
×
×
×
×
360 10 − 6 ( 2 3.14 500 10 3 )
×
C ( n + ) 1 281.733 10 − 12 (1 1+ )
ก ก (5.26) C = T n = 1 = 563.466 pF
2
ก ก (5.25) C = nC = ( ) 1 563.466 10× − 12 = 563.466 pF
1 2
RFC = 4L = 4 360 10 − 6 = 1.44 mH
×
×
1
3
$
$- &( /
C 1 = C 2 = 563.466 pF $- &( / C 1 = C 2 = 560 pF ก
C = == = C = == = 560 pF ก , L = == = 360 µH, RFC = == = 1.44 mH;
2
1
1
3
5.4.2 ก
5
$ 6 R $ R
S D
0 ก ' * B Q 3 )
2
+V
ก ก (2.42) V G =V GS RS
. V = 0 V
G
ก
ก
ก
216
5.
V = −V
RS GS
ก ก (2.59) V = 0.293V . ( I = 0.5I )
GS P D DSS
V = − 0.293V
RS P
− 0.293V
) R = P (5.28)
S
0.5I DSS
ก ก (2.62) V DS = 0.5V DD
ก ก (2.63) V R D = V DD − V +V R S )
( DS
) R = V R D (5.29)
D 0.5I DSS
) 5.10 ก #$ 5.15 $ &( R !
R D
S
( 0.293− )V
* + ก ก (5.28) R = P
S
0.5I DSS
0 V = − 2.5 V, I = 10 mA;
P DSS
( 0.293− )( 2.5− )
R = = 146.5 Ω
S − 3
×
×
0.5 10 10
×
=
ก ก (2.62) V = 0.5V = 0.5 12 6 V
DS DD
ก ก (2.63) V = V − V +V ) 12= − (6 0.732+ ) = 5.268 V
R D DD ( DS R S
V R 5.268
ก ก (5.29) R = D = = 1.053 kΩ
D
0.5I DSS 0.5 10 10 − 3
×
×
$
$- &( /
R S = 146.5 Ω $- &( / R S = 150 Ω
R = 1.053 kΩ $- &( / R = 1 kΩ
D D
R = == = 150 Ω ΩΩ Ω !
R = == = 1 kΩ ΩΩ Ω
S D
'
) 5.11 ก #$ 5.15 " * B Q . 3 &( & /
2
V DD
* + ก ก (2.45a) I DSS =
R D + R S
V DD 12 10.434 mA
I = = =
DSS )
R + R S ( 1 10× 3 + 150
D
2
− b ± b − 4ac
ก ก (2.48) V =
GS
2a
ก
ก
ก
217
5.
×
I R 10.434 10 − 3 × 150
0 a = DSS S = 2 = 0.250
2
(V P ) ( 2.5− )
2I R 2 10.434 10 − 3 × 150
×
×
=b 1− DSS S = 1− = 2.252
V P − 2.5
)
×
=
c = I DSS S −V G = ( 10.434 10 − 3 × 150 − 0 1.565
R
− 2.252 ± ( 2.252 ) − (4 0.250 1.565× × )
2
V GS =
×
2 0.250
− 2.252 1.872
±
V GS =
0.5
− 2.252 1.872
+
V GS 1 = = − 0.76 V
0.5
−
− 2.252 1.872
V GS 2 = = − 8.248 V
0.5
V GS = V GS 1 = − 0.76 V
V 2 3 − 0.76 2
×
ก ก (2.46) I D = I DSS 1− GS = 10.434 10 − 1− = 5.054 mA
V P − 2.5
ก ก (2.45) V DD = ( I R + V DS − I R ) ,V DS = V DD − ( I R + I R ) ;
D S
D S
D D
D D
×
×
+
×
V = 12 − ( { 5.054 10 − 3 × 1 10 3 ) ( 5.054 10 − 3 × 150 )} = 6.187 V
DS
= − −− −
' B Q V GS == = 0.76 V, I = == = 5.053 mA!
V DS = == = 6.167 V
2
D
&( * I "% &. I ± 0.5 mA &( * V "% &. V DS ± 0.5 V
DS
D
D
5.4.3 ก
5
$ 6 C $ C
S
D
(
C 3. 500 kHz ก* %$ 0
0 ก
S
C
C = 2
S
10
C " ,
500 kHz
ก 0 X ( ก " 0.5-10 Ω
D CD
1
C = (5.30)
D
π
2 F X C D
o
) 5.12 $ &( C !
C
S D
×
C 2 560 10 − 12
* + C = = = 56 pF
S
10 10
ก ก (5.30) C = 1
D
2 F Xπ o C D
0 F = 500 kHz, X CD = 10 ;
Ω
o
ก
ก
ก
218
5.
1
C = = 0.0318 µF
D 3
×
×
2 3.14 500 10 × 10
×
$
$- &( /
C = 56 pF $- &( / C = 56 pF ก
S
S
C = 0.0318 µF $- &( / C = 0.033 µF ก
D D
C = == = 56 pF!
C = == = 0.033 µF ก
S
D
5.4.4 ก
5
$ 6 g 1 /
m
X
ก ก (5.18) g r = 2
m d
X 1
1 1
. ก X = , X = !
C = C
2 1 1 2
ω C ω C
2 1
1 ω C 1 C 1
g r = × = = 1
m d
ω C 1 C
2 2
= $- &( * ก ก
! (ก( ก ก
1
) g
m
r d
>
1
&( g
m
r
d
1
. B &( r = 1 kΩ g > > 1 mS 0 $ก B &( r > 1 kΩ
d m 3 d
×
1 10
) &
. ก 3 g m > 1 mS
'
5.5 ก
ก
- . -" & 2 3 4ก
ก #$ 5.16 ก!"" !""0&
,
0 3 3 ) 4
ก ก & 500 kHz
Ω
0 ก I = 5 mA, β = β = 100,V = 0.6 V,V = 12 V, F = 300 MHz, r = 2 ,
C F o BE CC T bb′
C ob = C re = 1.3 pF !
R L = 10 kΩ ก ก!"" 3( ก "!""0&
,
3 C C !
,
2
1
L ( ก ) 3 X -TAL & ( ก " 500 kHz (! L
3
3
3
V CC
R B1 C
NPN
B Q 3
E
C 1 C 3
R B2
C 2 R E
X-TAL 3 R L
#$ 5.16 !
!""0&
,
0 3 3 ) 4
ก
ก
ก
ก
219
5.
5.5.1 ก
5
$ 6 C C $ L
1 , 2 3
0 "&( F $- &( & *
!
&( L
3
o
ก ก (5.25) C = nC
1 2
C T ( +n ) 1
ก ก (5.26) C 2 =
n
1
ก ก (5.27) C =
T
L 3 (2 Fπ o ) 2
) 5.13 ก #$ 5.16 $ &( C C !
L ก F = 500 kHz, L = 360 µH
,
3
o
2
1
3
!
n = 1
1
* + ก ก (5.27) C =
T 2
π
L (2 F )
3 o
0 F = 500 kHz, L = 360 µH, n =
1;
o 3
1
C = 2 = 281.733 pF
T
×
×
×
×
360 10 − 6 ( 2 3.14 500 10 3 )
×
C T ( +n ) 1 281.733 10 − 12 (1 1+ )
ก ก (5.26) C 2 = = = 563.466 pF
n 1
ก ก (5.25) C = nC = ( ) 1 563.466 10× − 12 = 563.466 pF
1 2
$
$- &( /
C = C = 563.466 pF $- &( / C = C = 560 pF ก
1 2 1 2
C = == = C = == = 560 pF ก !
$
L = == = 360 µH $- X -TAL = == = 500 kHz
1 2 3 3
5.5.2 ก
5
$ 6 R B 1 , R $ R
B
E
2
. ก I = 5 mA
C
ก ก (3.23) V CE = 0.5V CC ,V RE = 0.5V CC ;
I C
I B =
β
F
0.5V
ก ก (3.24) R = CC
E
(β + ) 1 I B
F
ก ก (2.26) R = 15R
TH E
ก ก (2.27) V TH = I R + V BE + ( β + ) 1 I R
B TH
F
B E
ก
ก
ก
220
5.
R
V CC TH V CC TH
R
ก ก (2.28) R = , R = ;
B 1 B 2 )
V TH (V CC − V TH
) 5.14 $ &( R , R !
R . ก I = 5 mA
B 1 B 2 E C
* + ก ก (3.23) V CE = 0.5V CC ,V RE = 0.5V CC ;
V CE = (0.5 12× ) 6 V=
V RE = (0.5 12× ) 6 V=
×
I 5 10 − 3
I = C = = 50 µA
B
β F 100
0.5V CC 6
ก ก (3.24) R E = = = 1.188 kΩ
( β F + ) 1 I B 101 50 10 − 6
×
×
3
×
×
ก ก (2.26) R = 15R = 15 1.188 10 = 17.82 kΩ
TH E
ก ก (2.27) V = I R +V + ( β + ) 1 I R
TH B TH BE F B E
×
×
×
×
×
V TH = ( 50 10 − 6 × 17.82 10 3 ) + 0.6 + ( 101 50 10 − 6 × 1.188 10 3 )
V TH = 7.49 V
×
×
R
V CC TH 12 17.82 10 3
ก ก (2.28) R B 1 = = = 28.551 kΩ
V TH 7.49
×
×
V CC TH 12 17.82 10 3
R
R B 2 = = = 47.417 kΩ
(V CC −V TH ) (12 7.49− )
$
$- &( /
R E = 1.188 kΩ $- &( / R E = 1.1 kΩ
R = 28.55 kΩ $- &( / R = 27 kΩ
B 1 B 1
R B 2 = 47.417 kΩ $- &( / R B 2 = 47 kΩ
Ω Ω Ω
Ω
Ω
Ω Ω Ω
Ω Ω Ω
R = == = 1.1 k , R = = = = 27 k , R = = = = 47 k ;
Ω
E B 1 B 2
5.5.3 ก
5
$ 6 C
3
C 3. 500 kHz !ก(0
!
C &( $
(
3 3
C 2 ,. !"( ! * 500 kHz ก& ( 0
,
7ก
10
C
C = 2 (5.31)
3
10
) 5.15 $ &( C
3
C
* + ก ก (5.31) C = 2
3
10
ก
ก
ก
221
5.
0 C = 560 pF
2
×
560 10 − 12
C = = 56 pF
3
10
$
$- &( /
C = 56 pF $- &( / C = 56 pF ก
3
3
C = == = 56 pF
3
5.5.4 ก
5
$ 6 β ββ β 1
F
X C
ก ก (5.7) β = 1 = 2
o
X 2 C 1
$- &( *
! (ก( ก
&( β > C 2
o
C 1
ก C = C β > 1 0
. ก$ 80 100
1 2 o
) Q & β = $ 80 100
β
o
3
F
5.6
55<
!""!&
$$5 % , e ก
!""0&
,
0
!"" #
* 3 ) 4
ก* 0 !
!"" ก
'
V CC = 12 V
R B1
35 kΩ
NPN C
β = β = 100,
B F o
Q
L 1 1 V = 0.6 V;
C 1 BE
100
100 pF E
C E
R B2 R E1
C 3 R L
C 2 10 pF V o
2.5 pF 100 pF 60 kΩ 1.5 kΩ 1 kΩ
#$ 5.17 !
!""!&
$$5
ก & "&' & * * ) #(ก "&( * L !
C 0 C !
C &( กก ( C
1
2
3
1
3
$ 30-40 ( ) ก , &( & '* C !
C % ( 4
( &( C ( . ก C C !
1 2 3 1 , 2
' , C !
C % (
C ( 'ก ก &( & ( ก " C &( ' ) &( & '* C
3 3 b e ′ b c ′ ce
4
( &( & * C ,. & ก ก ก!"" ก C ( ก " C * ก %
'
2
3
1
ก
ก
ก
222
5.
1
F = (5.32)
o
2π L C
1 3
0 C = C ≥ 40C
3
1
2
(
. ก #ก !""&
7ก
( ก
$- !"" % (! ก ก
) ก 3. ( C ก &( X $ 10-20 ( * X . & $- &( & '
CE
E
2
C
$ C 2
10
C
C = 2 (5.33)
E
10
) 5.16 ก #$ 5.17 $ &( F *
o
1
* + ก ก (5.32) F =
o
2π L C
1 3
0 C = C = 100 pF, C = 2.5 pF, L = 100 µH;
1
3
1
2
1
F = = 10.07 MHz
o
( 2 3.14× ) 100 10× − 6 × 2.5 10 − 12
×
F = == = 10.07 MHz
o
'
5.7
&
") !
!"" 3 ! & "&' & $- ก $ 'ก
3 !&$% 0 ,.
& "&' & *
!""!&
$$5 . ! & "&' ( !ก( !&$% 0
ก $
!$
&( ! &( & '* !&$% 0 $
!$
%$
Z
C 5 D 1 R 1
1 F/16 V 5 V 3 kΩ
V CC = 12 V
VR 1
5 kΩ β = β = 100,V BE = 0.6 V;
o
F
R B1
35 kΩ C D 1 (1 V)
NPN C = 1.5
C D 1 (5 V)
=
B
C 4 Q 1 C D 1 (0 V) 12 pF,C= D 1 (1 V) 8.7 pF;
R 2 L 1 C B
1 F/16 V 35 kΩ C 1 0.0082 µF
10
750 pF
E
C 3 C 2 R B2 R E1 C E R L
V C D 1 C D1 10 pF 750 pF 60 kΩ 1.5 kΩ 75 pF 1 kΩ V o
#$ 5.18 !
!"" 3 ! & "&' &
ก
ก
ก
223
5.
ก #$ 5.18
) :-
(
− C $- !&$% 0 * ก " C ก C ( ก " (C
D 1 3 T D 1 C 3 ) . $ "VR 1
V $
!$
$- 4
C &( & ' $
!$
%$ ก $
!$
&(
C
D 1 T
* C $- ก $
!$
& *
T
− กV &( ! %BB< , * ) &( C
$- 4
&( C
C D 1 D 1 T
& * , # * )
− R !
Z $- ! 5 V&
1 D 1
− VR !
R $- ! & "&' (V C D 1 ) . $ " $
&( * VR
2
1
1
! V $
!$
0-5 V
C
D 1
− C !
C " ,
ก !
"
ก
) % ก !
4
5
"
ก $ &( & * ก ก
& * 0 3 ก
.
1
F = (5.34)
o
2π L C
1 T
' )
0 C &. &( & * (C C
T D 1 3
C = C ≥ 40C
1 2 T
) 5.17 ก #$ 5.18 $ &( & ก ก
* V C D 1 = 1 V
1
* + ก ก (5.34) F =
o
2π L C
1 T
0 (1 V) 8.7 pF, L = 12 µH;
=
C
1
C = (C C ) (C= + C ) = ( 8.7 10× − 12 + 10 10 − 12 ) 18.7 pF=
×
T D 1 3 D 1 3
1 =
F =
o ( 2 3.14× ) 12 10× − 6 × 18.7 10 − 12 10.629 MHz
×
F = 10.629 MHz
o
F = == = 10.629 MHz
o
!5
กก *
!"" ( 3. 3 ' * ก "
ก
ก
ก
224
5.
1) X ( 3 ก " X !
X 2 < −X
2
3
3
2) X ( 3 ก " X !
X < − X
1 3 1 3
3) β = X 1 ก ก!""&
. ก β > X 1
o o
X 2 X 2
4) X >
1 X 2
กก *
!"" ( 3. 3 ' * ก " B
1) X ( 3 ก " X !
X 1 < −X
1
3
3
( < −X
2) X 3 ก " X !
X
2 3 2 3
3) g r = X 2 ก ก!""&
. ก B &( g > 1 > 1 mS
m d m
X 1 r d
4) X
2 > X
1
3 ) 4
ก $- '$ก
$ G , 0
7ก ก . ! ก ( 3 ) 4
ก ) !
! ก ก ก3 ) 4
ก 3 ) 4
ก !
4
%BB< ก !
" ก 0 &
)
( ก "& &' " * 3 ) 4
ก ก
"ก . $< ! ก !
" &
ก "& &' " * 3 ) 4
ก ก ก 0 !
!
ก * 3 ) 4
ก ( !
ก ! %BB< %
4( 3 ) 4
ก ก 0 !
$- !"" 'ก
!"" 3 3 ) 4
ก G , & !
' G# # ก
%$ 3 ก ก & * & . " ( ' . ( 6
!""!&
$$5 % , e ก
!""0&
,
0
!"" #
* 3 ) 4
ก ก & "&' & * * ) #(ก "&( * L !
C ( *
3
1
!""!&
$$5 #( C b c ′ , C b e ′ , C !
C % ( 4
( & * 3 ก ก
2
1
!"" 3 ! & "&' & 0 3 !&$% 0 & "&' &
*
!""!&
$$5 #ก 3 ( ก "% 0 ก
(
______________________________
ก
ก
ก
6
ก
ก
ก ก
ก
!"# !$ % &
$ ก ! '( ก (Cascade)
!1'
2 ก 3! 4 ก 5 4 ก !
2 1$ 6
ก ก
7 ( ก 3889 3 # : % ก !
2 !'ก 1 ! 3
ก " ' ก
26
! 3 (
6.1 ก
ก ! ;2 (Matching)
! (7 ก 4 6
;$ ! ก !'ก 7 ( ก
3889 3 # : !'ก ก " ' ก
24 % (
6.1.1 ก
ก
!
I s
E S
# 4' 6.1 ก ! ;24' ก ( 4 ( '(
ก # 4' 6.1 !' ( '( '% :-
− 5 ก ! ;2
E ก ( (
S
− E 5
ก ก
S
− R " " ! 4 ก E
S
S
− R " " ! 4 ( (
in
− P " ก 4' E ( ก
in S
− P " ก ก 4' R 3
out
in
P
!$ R ' ( " 4 6
" P = out ' ( ( 3 !ก
in
G
P in
ก
ก
ก
226
6.
E = I R + I R
S s S s in
E
I = S
s
( R + R in )
S
( E ) 2
P = E I = S (6.1)
in
S s
( R + R in )
S
2
E ) R in
2
( S
I
P out = ( ) R = 2 (6.2)
in
s
R +
( S R in )
2
R +
P (E S ) R in ( S R in )
P = out = ×
G
R +
P in ( S R in ) 2 (E S ) 2
R
% P = in (6.3)
G
( R + R in )
S
! 6.1 ก # 4' 6.1 ! " P !$ ก
" ! !1 H2 R ก R
S
G
in
R
"# $ ก !ก (6.3) P = in
G
( R + R in )
S
(4' P "$ ( (ก
G
R "$ " " ! 4
in
R "$ " " ! 4 I (6 E
S S
1 R R R 1
6 I R = R P = in = S = S =
in S G
4 ( R + R in ) (4R + R S ) 5R S 5
S
S
1 R R R 1
6 I R = R P = in = S = S =
in S G
3 ( R + R in ) (3R + R S ) 4R S 4
S
S
1 R R R 1
6 I R = R P = in = S = S =
in S G )
2 ( R + R in ) (2R + R S 3R S 3
S
S
R R R 1
6 I R = P = in = S = S =
R
in S G
( R + R in ) ( R + R S ) 2R S 2
S
S
R 2R 2R 2
6 I R = 2R P = in = S = S =
in S G
( R + R in ) ( R + 2R S ) 3R S 3
S
S
R 3R 3R 3
6 I R = 3R P = in = S = S =
in S G
( R + R in ) ( R + 3R S ) 4R S 4
S
S
R 4R 4R 4
6 I R = 4R P = in = S = S =
in S G
( R + R in ) ( R + 4R S ) 5R S 5
S
S
ก
ก
ก
227
6.
!# P 6 I ! '( ก 8 6 # 4' 6.2
G
P
4 G
5 R = 3R P = 0.75;
,
3 in S G
4
2
3 R = R S , P = 0.5;
G
in
1
2
1
3
1
4
1
5
Ω
R ( )
0 in
1 1 1
S R S R S R S R 2 S R 3 S R 4 S R
4 3 2
# 4' 6.2 " ! !1 H2
P ก R
G
in
ก # 4' 6.2 !' ( '( '% :-
− !$ R !'" 4 ก R P !'" 0.5
in S G
− !$ R !'" 4 ก 3R P !'" 4 ก 0.75
in S G
− 'ก (
!$ R !'" # ก R 4 6
ก 7 ( ก 3889 6
ก R !'"
in S in
1 !! ก % !3 (
% ก ก ( ( 4 6
" " ! 4 !'"
# : 4 4' 4 3
m b e ′ =
g V I = I R out + I R L
c
I c
I R I R L
g V I c out I R L
m b e ′
# 4' 6.3 ก ! ;24' ก ( 4 ( '(
ก # 4' 6.3 !' ( '( '% :-
2
− 5 ก ! ;2
ก 4
ก 4
2
− g V 5
ก ก " Nก 4' 7#ก" ":! ( V
b e ′
m b e ′
− R " " ! 4 ก 4
2
out
− R " " ! 4
L
ก
ก
ก
228
6.
ก # 4' 6.3 3 !ก
V = g V ( R out R L )
m b e ′
o
$ ก g V = I
m b e ′
c
V = I c ( R out R L )
o
R
R out L
$ ก ( R R ) =
out L
( R out + R L )
I R R
V = c out L (6.4)
o
( R out + R L )
2
( ) R R
I
P = I V = c out L (6.5)
c o
in
( R out + R L )
( ) 2 I R R ) 2
V
P = o = ( c out L (6.6)
out 2
R +
R
L ( out R L ) R L
2 ) 2 )
R
I
R
R
P ( ) ( out L ( out + R L
c
ก !ก (6.5) (6.6) P = out = ×
G
P + 2 2
I
R
R
in ( out R L ) R L ( ) R out L
c
R out
% P = (6.7)
G
( R out + R L )
! 6.2 ก # 4' 6.3 ! " P !$ ก
" ! !1 H2 R ก R
G out L
R out
"# $ ก !ก (6.7) P =
G
( R out + R L )
1 R L R L 1
6 I R out = R P = = =
G
L
4 ( R + 4R L ) 5R L 5
L
1 R L 1
6 I R out = R P = =
L
G
3 ( R + 3R L ) 4
L
1 R L 1
6 I R out = R P = =
G
L
2 ( R + 2R L ) 3
L
R L =
1
6 I R out = R P =
G
L
( R + R L ) 2
L
2R L 2
6 I R out = 2R P = =
G
L
(2R + R L ) 3
L
3R L 3
6 I R out = 3R P = =
L
G
(3R + R L ) 4
L
4R L 4
6 I R out = 4R P = =
G
L
(4R + R L ) 5
L
ก
ก
ก
229
6.
!# P 6 I ! '( ก 8 6 # 4' 6.4
G
P G R = 4R P = 0.8;
,
4 out L G
5
3
4
2
R = R , P = 0.5;
3 out L G
1
2
1
3
1
4
1
5
Ω
R ( )
0 out
1 1 1
R
R R R R L 2 L 3 L 4 L
R
R
4 L 3 L 2 L
# 4' 6.4 " ! !1 H2
P ก R
G out
2
ก # 4' 6.4 !$ R
5 " " ! 4 ก 4
$ 8
out
!'" # ก R 4 6
ก 7 ( ก 3889 6
ก R 1 !! ก % % ก ก 4 6
L L
" " ! 4 ก 4
2
8 !'" # ! 3R % 3
$
L
6 " ! 5 " " ! 4 ก Nก4 ก 2(
#
" !7' # 3! 5 " " ! 4 ( '( ! ก (# 6 !1'
2
ก ("
" ! 4 " ' ก
2
ก 3889 4' ! 76; 3 5 ก 3889 4' ก ก
'
%
%
4 4 ก ! ;24' 5 ก " ' ก
2 ก
6
! %
$ 1'( " ! 4 4 %
6.1.2 ก
&' '
!1'
2 ก 4
2 8 ก ( " !
4 " ก
2 ก
! ! ก ก 6;
2 6 ก
'
! ;2
6.1.2.1 ก
" (
) ก
ก # 4' 6.5 ก. ! 7 '( !ก Z 3
in
Z = R BB { bb′ + ( b e ′ − JX C T )}
r
r
in
$ ก R !'" " ! 4 # !$ ก " " ! 4 ! 7 4 % R 3
BB BB
− JX r b e ′
Z = r bb′ + ( b e ′ − JX C ) = r bb′ + C T
r
in
T
r
( b e ′ − JX C T )
ก
ก
ก
230
6.
r
r bb′ ( b e ′ − JX C ) JX− C r b e ′ r r − JX C r bb′ − JX C r b e ′
′
bb b e ′
Z = T T = T T
in
r
r
( b e ′ − JX C T ) ( b e ′ − JX C T )
r r − JX C ( bb′ + r b e ′ )
r
′
bb b e ′
Z = T
in
r
( b e ′ − JX C T )
1
−
$ ก JX C =
ω
T
J C T
ω
ω
r
J C r r + ( bb′ + r b e ′ ) J C
′
T bb b e ′
Z = × T
in
ω
ω
J C T J C r + 1
T b e ′
ω
J C r r + ( bb′ + r b e ′ )
r
T bb b e ′
′
Z =
in
ω
J C r + 1
T b e ′
ω
r
′
( bb′ + r b e ′ ) + J C r r
T bb b e ′
% Z = (6.8)
in
ω
+
1 J C r
T b e ′
r bb′ b′
r
C T b e ′ V b e ′ g V C
Z m b e ′ ce
in Z out
Z in Z out
L L
E S mi R ip C ip C ce R out mo
# 4' 6.5 ก ! ;2 ก ( (( " !7' #
ก ' ( Z ก # ก !:!R ก6
5 ; %
in
Z = r θ
in
2
(r bb′ + r b e ′ ) + ( C r rω T bb b e ′ ) 2
′
r =
ω
2
1 + ( C r ) 2
T b e ′
( C r rω T bb b e ′ )
′
−
1
θ = tan − 1 − { tan ω C r }
T b e ′
r
( bb′ + r b e ′ )
ก
ก
ก
231
6.
#
ก 6
" " ! 4 ' ก
2 Z (# 6
in
$ :ก ! (6; !ก 3 '%
(
r r
R = , X ip = ; !$ − X ip = X C ) (6.9a)
ip
cosθ sinθ ip
(
θ
R = r cos , X = r sin ; !$ − X = X C is ) (6.9b)
θ
is
is
is
(4' R "$ " " ! 4
ip
'
X "$ " ก
2
ip
R "$ " " ! 4 :ก !
is
X "$ " ' ก
2 :ก !
is
2
( r bb′ + r b e ′ ) + ( C r rω T bb b e ′ ) 2
′
r =
2
1 + ( C r ) 2
ω
T b e ′
θ = − 1 ω C r r
′
T bb b e ′
1 tan
r bb′ + r b e ′
ω
θ = tan − 1 ( C r )
2 T b e ′
θ θ − θ
=
1 2
!ก Z Z = R ( − JX )}
in in { ip C ip
!ก Z :ก ! Z = R − JX
in in is C is
ก # 4' 6.5 ก. ! 7 '( !ก Z 3
out
1
Z = R − JX ) = R
out ( out C ce out
ω
J C ce
g V 7$ !'" ! 4 I (6 # ! ก ! 7 4 % 3
m b e ′
ก # 4' 6.5 . R1 ก ! ;2 Z ก ( R
in ip
C
!$ ก ก C 5 6; L ! !$ ก ก
2"
ip ip mi
' ก
2กN
ก ก
! Z
$ 1'( R ( '( ! 7 '( !ก 3
in ip
1
ω L mi =
ω C ip
ω 2 L C = 1
mi ip
1
2
ω =
L C
mi ip
1 1
ω = =
L C L C
mi ip mi ip
ก
ก
ก
232
6.
π
$ กω = 2 F
R
1
F = (6.10)
R
2π L C
mi ip
1 (6.11)
L mi =
2
(2 Fπ R ) C ip
ก # 4' 6.5 . R1 ก ! ;2 ก Z ก ( C
out ce
R ก !$ ก ก " C 6; L ! ก C !$ ก ก
L ce mo ce
2" ' ก
2 กN
ก ก
! Z
$ 1'( R ( '( '( !ก 3
out out
1
ω
L mo =
ω C
ce
ω 2 L C = 1
mo ce
1
2
ω =
L C
mo ce
1 1
ω = =
L C L C
mo ce
mo ce
$ ก ω = 2 F
π
R
1
F = (6.12)
R
2π L C
mo ce
1
L mo = (6.13)
2
(2 Fπ R ) C ce
6.1.2.2 ก
*(! B
W in
2
B "$ " 42 ก # 4' 6.6 ก ! " R
W in bwi
5 " ! 4 4' C ( 4 % L 3 !ก
ip
mi
R R
ip S
R bwi = ( ip R S ) = (6.14)
R
R +
( ip R S )
1
ก !ก (3.2) B =
W
π
2 CR
(4' R = R bwi , C = C ip ;
1
% B = (6.15)
W in
π
C
2 R bwi ip
ก
ก
ก
233
6.
R R
bwi bwi
E R
S L mi R ip C ip ip C ip
# 4' 6.6 ก ! " R 4' C ( 4 % L
bwi ip mi
6.1.2.3 ก
*(! B
W out
2
"$ " 42 ก ก # 4' 6.7 ก ! "
B W out
R
5 " ! 4 4' C ( 4 % L mo
bwo
ce
R bwo R bwo
C R out L mo R out
ce
C ce
# 4' 6.7 ก ! " R 4' C ( 4 % L
bwo ce mo
R
R out L (6.16)
R = ( R R ) =
bwo out L )
( R out + R L
1
ก !ก (3.2) B =
W
π
2 CR
$ ก R = R C = C ce
bwo
1
% B W out = (6.17)
π
2 R C
bwo ce
2 $
∗
! (
: 42 7#ก $ ก ก" B
B W out 4' !'" :
W in
r bb′ b′
r b e ′ V
C b e ′ g V C
E S L mi T m b e ′ ce L mo
R out
# 4' 6.8 ( '( ก ! ;2 ( ( ( " !7' #
ก
ก
ก
234
6.
Ω
Ω
! 6.3 !!# 4
2 ( ( !' ( '( r bb′ = 2 , r b e ′ = 1.5 k ,
Ω
C = 1.5 pF, C ce = 0.5 pF, R out = 1 k ;" !7'
2 700 MHz 6
4 ก ! ;2
T
! # 4' 6.8 ! " C , R , L , L , B , B B
ip ip mi mo W in W out W
r r
"# $ ก !ก (6.9a) R = , X = ;
ip ip
cosθ sinθ
2
( r bb′ + r b e ′ ) + ( C r rω T bb b e ′ ) 2
′
(4' r =
2
1 + ( C r ) 2
ω
T b e ′
( 2 1.5 10 3 ) ( 2 3.14 700 10 × 1.5 10 − 12 × 2 1.5 10 3 ) 2
2
6
×
×
×
+
×
×
+
×
×
r =
1 + ( 2 3.14 700 10 × 1.5 10 − 12 × 1.5 10 3 ) 2
6
2
×
×
×
×
×
2.256 10 + 391.327
×
6
r = = 151.098 Ω
+
1 97.831
2 1.5 10
6
×
×
ω C r r 6.28 700 10 × 1.5 10 − 12 × × × 3
×
′
θ = tan − 1 T bb b e ′ = tan − 1
1
+
×
r bb′ + r b e ′ 2 1.5 10 3
(
)
θ = tan − 1 0.01317
1
6
×
×
×
θ = tan − 1 ( C r ) = tan − 1 ( 6.28 700 10 × 1.5 10 − 12 × 1.5 10 3 )
×
ω
2 T b e ′
θ = ( tan − 1 9.891 )
2
) (
)
θ = θ − θ = ( tan − 1 0.01317 − tan − 1 9.891 = − 83.472
1
2
r 151.098
R = = = 1.329 kΩ
ip
cosθ cos ( 83.472− )
r 151.098 ( )
X = = = − 152.084 Ω − X = X
ip ip C
−
sinθ sin 83.472 ip
1 1
C = ω X C ip = ( 2 3.14 700 10 × 152.084 ) = 1.495 pF
ip
6
×
×
×
1 1
ก !ก (6.11) L mi = 2 = 2
(2 Fπ R ) C ip 1.495 10 − 12 ( 2 3.14 700 10 6 )
×
×
×
×
L mi = 34.613 nH
1 1
ก !ก (6.13) L mo = 2 = 2
(2 Fπ R ) C ce 0.5 10 − 12 ( 2 3.14 700 10 6 )
×
×
×
×
L = 103.493 nH
mo
3
×
R R 1.329 10 × 75
ip S
=
ก !ก (6.14) R bwi = ) ( 3 = 70.993 Ω
R +
×
( ip R S 1.329 10 + 75 )
ก
ก
ก
235
6.
1 1
ก !ก (6.15) B W in = = = 1.5 GHz
π
×
×
×
×
2 R bwi ip ( 2 3.14 70.993 1.495 10 − 12 )
C
3
×
R out L 1 10 × 75
R
ก !ก (6.16) R bwo = = = 69.767 Ω
×
3
R
( out + R L ) ( 1 10 + 75 )
1 1
ก !ก (6.17) B W out = = = 4.564 GHz
π
×
×
×
×
C
2 R bwo ce ( 2 3.14 69.767 0.5 10 − 12 )
R = == = 1.329 k , C =Ω Ω ip = = = 1.495 pF, L mi = = = = 34.613 nH, L mo = = = = 103.493 nH, B W in = = = = 1.5 GHz,
Ω Ω
ip
2
B W out = == = 4.564 GHz 42 !'" 4 ก B W in = == = 1.5 GHz
ก 6; L L ก ก ( (
mi mo
( " !7' # (S กN : ;$ !
6.1.2.4 ก
$ -) (! "
( C ก C ' ( " L 5 L′ 6 # 4' 6.9
ipp
ip
mi
mi
R R
ip S
ก !ก (6.14) R bwi = ( ip R S ) = )
R
R +
( ip R S
1
ก !ก (6.15) B W in =
2 Rπ bwi ip
C
$ ก C = C ipx
ip
1
B W in =
π
2 R bwi ipx
C
ก
" C ipx
1
% C ipx = (6.18)
π
2 R bwi (B W in )
% กN :4' ก C 7#ก ! " 6
!
ip
C = C − C (6.19)
ipp ipx ip
!$ ( C ipp C ip ) :
2 ' ( ! " L 6
!
mi
1
ก !ก (6.11) L mi = (4' C 7#ก ' ( 5 ( C ipp C ip )
ip
2
( 2 Fπ R ) C ip
1
% L′ = (6.20)
mi
2
π
( 2 F R ) ( C + C ipp )
ip
ก
ก
ก
236
6.
Z in Z out
E S L mi R ip C ip C ce R out L mo
Z Z
in out
L′ R C C R L
E S mi C ipp ip ip ce out mo
2
# 4' 6.9 ก " 42 (6; L′ C
mi
ipp
! 6.4 ก ( 4' 6.3 ก 42 B ก 1.5 GHz6
$ 1'(
2
W in
50 MHz (" !7'
2" !
2
"# $ ก 4 6
" 42 ( C ก C
ip
ipx
×
3
R R 1.329 10 × 75
ip S
=
ก !ก (6.14) R bwi = ) ( 3 = 70.993 Ω
R +
×
( ip R S 1.329 10 + 75 )
1
ก !ก (6.18) C ipx =
π
2 R bwi (B W in )
(4' C "$ " " ! I ( ก 6
! 4 4' C
:
ipx
ip
B = 50 MHz
W in
1 44.859 pF
C = =
ipx 6
×
×
×
×
2 3.14 70.993 50 10
:
% กN 4' ก C 7#ก ! " 6
!
ip
ก !ก (6.19) C ipp = C ipx − C
ip
:
(4' C "$ " " ! 4' ก C
ipp ip
C ipp = ( 44.859 10 − 12 − 1.495 10 − 12 ) = 43.364 pF
×
×
1
ก !ก (6.20) L′ =
mi
2
C +
π
(2 F R ) ( ip C ipp )
(4' L′ "$ " " !
' ( 6
! 4' ก C ipp
mi
ก
ก
ก
237
6.
1
L′ =
( 2 3.14 700 10 6 ) ( 1.495 10 − 12 + 43.364 10 − 12 )
mi
2
×
×
×
×
×
L′ = 1.153 nH
mi
! ;2 ก ( L′ ′′ ′ = == = 1.153 nH C ipp = == = 43.364 pF
mi
6.1.3 ก
& -
ก .!
N
!ก : ! (Lump Circuits) 5 # 4' !' !ก 6 ก ! "
2
, R L C ! 7ก
" " !7'
2 " 42 3 ( !ก : !!'
4
6.1.3.1
ก .! 1
L
m 2
R m 1 C m 3 R m 4
# 4' 6.10 !ก : ! 4' 1
R − R F
Q = m 4 m 1 ,Q = R ; (6.21a)
m
m
R m 1 B W
Q R 1
m m
L = (6.21b)
m 2
ω
L m 2 (6.21c)
C m 3 = 2
R 2 m 1 + ( Lω m 2 )
ก
R m 4 > R m 1
(4' Q "$ " ก ": I 1 !ก : !
m
ω "$ " " ! N ; !:! (2 F
π
R )
F "$ " " !7'
2 !ก : !
R
2
B "$ " 42 !ก : !
W
6.1.3.2
ก .! 2
ก
R > R
m 5 m 1
ก
ก
ก
238
6.
R − R
Q = a m 5 m 1 (6.22a)
m
R m 1
L m 2 C m 4
R m 1 C m 3 R m 5
# 4' 6.11 !ก : ! 4' 2
$ ก a >
1
Q R 1
m m
L m 2 = (6.22b)
ω
( 2 )
+
1 R m 1 1 Q m
C m 3 = Q − + 1 (6.22c)
m
ω R ( 1 Q 2 ) R m 5
+
1
m
m
R m 5
C = (6.22d)
m 4
+
ω R m 5 R m 1 ( 1 Q 2 m ) − R m 5
6.1.3.3
ก .! 3
ก
R > R
m 5 m 1
L m 2 C m 3
R C m 4 R m 5
m 1
# 4' 6.12 !ก : ! 4' 3
1 (6.23a)
C m 3 = ω Q R 1
m m
1 (6.23b)
C m 4 =
ω R R m 1
m 5 −
R m 5 R m 1
1 R R C (6.23c)
L m 2 = + m 1 m 5 m 4
ω 2 C m 3
ก
ก
ก
239
6.
6.1.3.4
ก .! 4
L m 2 C m 3 L m 5
R m 1 C m 4 R m 6
# 4' 6.13 !ก : ! 4' 4
ก
Q " !'" 4 ก Q m 2
1
m
R
Q m 2 m 6
L m 5 = ω (6.24a)
1
C = (6.24b)
m 3
ω Q R
m 1 m 1
Q m 2 R m 6 + R m 1
C = (6.24c)
m 4 2
ω ( 1 Q m 2 ) R R 1
+
m
6 m
1+ ( Cω R Q )
L m 2 = m 3 m 1 m 2 (6.24d)
ω 2 C
m 3
!ก : ! 4
4' ;$ ! (ก 1$ ก 7 ( ก -
3889 6
3 # : ก " ' ก
26
! 3 ก ! " L C ก 4 !$ "
m
m
!1'
2 ก 5 " " ! 4 ( '( 6; " !1'
2
ก !'" ' ก
2 (# 5 ก 4 % (ก ' ( " L
$ C 6
m m
!ก : !
!ก 4' 6; 6 ก ! " L C !ก : !
C
C C 3 C = C − (6.25a)
m x m (new ) m x
( ω 2 C L + 1 )
C L 3 C m (new ) = m x (6.25b)
x
m
ω 2 L
x
L
L :ก ! L 3 L m (new ) = L − (6.25c)
m
m
x
x
ω 2 L C + 1
m x
L :ก ! C 3 L m (new ) = (6.25d)
x
m
ω 2 C
x
C :ก ! C 3 C m (new ) = C − (6.25e)
C
m
x
x
m
ก
ก
ก
240
6.
C m
C :ก ! L 3 C m (new ) = (6.25f)
m
x
+
1 ω 2 C L
m x
:
(4' L , C "$ " " !
' ( , " " ! : ก 26 !ก : !
m m
"$ " " !
' ( , " " ! : ก 26 !ก : !6
! 4' ก
:
L m (new ) , C m (new )
" ' ก
2
C L "$ " " ! : " " !
' ( !1'
2 ก4' ก
,
x
x
!ก : !
6 " % 5 ' ( # !1'
2 4' ! ;$ ! ก
ก !ก : ! ก # ก ( 5 # :ก !
R S R S
R P C P R P L P
C S L S
# 4' 6.14 # !1'
2
R .ก
C R C
S S P P
R P 1+ ( C Rω P P ) 2
R = , C = ; (6.26a)
S
S
2
ω
ω
1+ ( C R ) 2 ( R P ) C P
P P
1+ ( C Rω ) 2 C
R = S S 2 , C = S 2 ; (6.26b)
P
P
ω
ω
R ( C ) 1+ ( C R )
S S S S
R .ก
L R L
S S P P
R ( Lω ) 2 R 2 L
R = P P , L = P P ; (6.27a)
S
S
ω
ω
R 2 + ( L ) 2 R 2 + ( L ) 2
P P P P
R 2 ( Lω ) 2 R 2 + ( Lω ) 2
R = S S , L = S S ; (6.27b)
P 2 P 2
R S ω L S
! 6.5 ' ( ก R :ก ! C 5 R C
" !1'
24 %
S
S
P
P
ก
ก
ก
241
6.
R S
100 Ω
Z S Z R
P P C P
C S
10 pF
F = 100 MHz
R
# 4' 6.15 # R :ก ! C 5 R C
S S P P
×
6
×
6
×
π
×
"# $ ω = 2 F = 2 3.14 100 10 = 628 10 Rad s
R
×
×
6
1+ ( C Rω ) 2 1+ ( 628 10 × 10 10 − 12 × 100 ) 2
ก !ก (6.26b) R = S S 2 = 2
P
(
ω
×
6
R ( C ) 100 628 10 × × − 12 )
S S 10 10
R = 353.559 Ω
P
×
C 10 10 − 12
C = S = = 7.171 pF
P
1+ ( C Rω S S ) 2 1+ ( 628 10 × 10 10 − 12 × 100 ) 2
×
6
×
R 353.559
Z = P =
P
+
1 J ω P P ) 1 J ( 628 10 × 7.171 10 − 12 × 353.559 )
( C R
6
×
+
×
Z = 188.043 − 57.868 Ω
P
1 1
Z = R + = 100 +
S
S
ω
×
×
6
J C S J ( 628 10 × 10 10 − 12 )
Z = 188..031 − 57.871 Ω
S
Ω
Ω Ω Ω
Ω Ω
R = == = 353.559 , C = =Ω Ω = = 7.171 pF, Z = == = 188.043 − − − − 57.868 ,
P P P
Ω Ω Ω
Ω
Z = == = 188.031 − − − − 57.871 ;
S
! 6.6 ! ;2
ก 4' !' !1'
2 ก 75 Ω ก
−
4
2
4' !'" !1'
2(3.18 J 3.10 ) Ω 4' " !7' 150 MHz !'
2
42 2 MHz (6; !ก : ! 4' 3
L
C m 2
m 3
R m 5
75 Ω
C m 4 R m 1
E 3.18 Ω
S
# 4' 6.16 ก 6; !ก : ! 4' 3
ก
ก
ก
242
6.
"# $ ก
R m 5 > R
1
m
Ω
Ω
ก
6
R m 5 = 75 , R m 1 = 3.18 ;
F
ก !ก Q = R
m
B W
(4' F = 150 MHz, B = 2 MHz;
R W
×
F 150 10 6
Q = R = = 75
m
×
B 2 10 6
W
1
ก !ก (6.23a) C m 3 =
ω
Q R
m m 1
6
×
×
×
6
(4' ω = 2 F = 2 3.14 150 10 = 942 10 Rad s
π
×
R
R m 1 = 3.18 Ω
1
C m 3 = = 4.451 pF
942 10 × 75 3.18
×
6
×
1
ก !ก (6.23b) C m 4 =
ω R m 5 R m 1
R m 5 − R m 1
Ω
Ω
(4' R m 1 = 3.18 , R m 5 = 75 ;
1
C m 4 = = 67.401 pF
( 942 10 × 75 ) 3.18
×
6
−
75 3.18
1
ก !ก (6.23c) L m 2 = + R R C
4
5 m
1 m
m
ω 2 C
m 3
1 − 12
×
×
×
L m 2 = + ( 3.18 75 67.401 10 )
4.451 10 − 12 ( 942 10 6 ) 2
×
×
L m 2 = 269.261 nH
67.401 pF,
Ω
3 R m 1 = 3.18 , L m 2 = 269.261 nH,C m 3 = 4.451 pF, C m 4 =
Ω
−
R = 75 ; $ ก !1'
2 !'" (3.18 J 3.10 ) Ω 5 ก ( J− 3.10 ) Ω 4 %
m 5
(ก
X C x = 3.10 Ω
1 1
C = = = 342.442 pF
x
ω X 942 10 ×
6
×
C x 3.10
ω 2 L C + 1
m x
ก !ก (6.25d) L :ก ! C 3 L m (new ) =
m
x
ω 2 C x
"$ " " !
' ( 6
! L !$ ก " C
(4' L m (new ) m 2 X
L = L m 2 = 269.261 nH, C = 342.442 pF;
m
X
ก
ก
ก
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