NOTES ADDMATH F4 KSSM✨

NOTA MEMAHAMI KONSEP FUNGSI
PETA MINDA UNDERSTAND THE CONCEPT OF FUNCTIONS

VISUAL™

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Understand And Use The Concept Of
MathTshr3o5uo gh Quadratic Inequalities
OVERHEAD
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Example Sketch the graph of function g(x) = x2 - 9 .

g(x)

Solution

When g(x) = 0, -3 0 3x
x2 - 9 = 0
x2 = 9 g(x)
x =+3

When x = 0, -
g(x) = (-09)2 9
g(X) =

-9 9

Reflect the negative part of the graph -3 0 x
3
to get g(x) = x2 - 9 .

(x - 2)(x + 3)
Example Find the ranges of the value of x of (2x + 1) (x - 3) < 0.

(x - 2) < 0 (x + 3) < 0 Solution
x<2 x < -3
Attention: (2x + 1) and (x - 3) cannot be equal to 0
(x - 3) < 0 (x - 2)(x + 3)
(2x + 1) < -01 because expression (2x + 1) (x - 3) is undefined
x < x<3
2 when denominator becomes zero.

+ ++ + -

x<3

+ ++ - -

x<2 +- - -
-- - -
x < -1 +
2 +

x < -3

+ -3 - - 1 + 2 - 3+
2

∴ The ranges of value of x in order to (x - 2)(x + 3) < 0 is the part that sign -
(2x + 1) (x - 3)
is -3 < x < -1 and 2 < x < 3.
2

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PERSAMAAN SERENTAK / SIMULTANEOUS EQUATIONSDWIDWINObeTrAtentangan – opposite taburan – distribution diskrit – discrete berat – weight ketinggian – height lekuk pipi – dimples ibu jari – thumb menggulung lidah – roll tongue
PETA MINDA DWIDWI
VISUAL™

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NOTA JANJANG ARITMETIK/ARITHMETIC PROGRESSION
PETA MINDA

VISUAL™

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NOTA JANJANG ARITMETIK / ARITHMETIC PROGRESSION
PETA MINDA

VISUAL™

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NOTA PENUKARAN HUBUNGAN TAK LINEAR KEPADA BENTUK LINEAR
PETA MINDA REDUCE NON-LINEAR RELATIONS TO LINEAR FORMS

VISUAL™

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NOTA GEOMETRI KOORDINAT : PEMBAHAGIAN TEMBERENG GARIS
PETA MINDA COORDINATE GEOMETRY : DIVISION OF A LINE SEGMENT

VISUAL™

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NOTA GEOMETRI KOORDINAT : LUAS POLIGON
PETA MINDA COORDINATE GEOMETRY : AREA OF POLYGON

VISUAL™

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NOTA KONSEP GARIS SELARI DAN GARIS SERENJANG
PETA MINDA CONCEPT OF PARALLEL AND PERPENDICULAR LINES

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E

26OVNESRPHAPREEATDANOAMdTdAINitiDonAal Maths T3h5orough Diagrams FoCrmH4APPETRESRAM6 A: ACNOOLORDKUINSAMTEELGIEBOAMTKEATNRYJARAK © PNI Neuron
UndeErsQtaUnAdTALIOnodcNuUsOsIeFnvTLohOlveCinCUgoSnDcIiesNtpaVtnOOcLfeVEIqNuGatiDonISOTfANCE (M) Sdn. Bhd.
Hα F (554690-H)
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y Example 1 Given that the distances of moving
point V from point T(1, 2) is 2 units.
Find the equation of locus of point V.
V(c, d)

Solution

2 units Let point V is (c, d).
Given that distance of point V
from T (1, 2) is 2 units.

-- -- TV = 2

x x2 - (x 1)2 + (y 2)2 = 2
T(1, 2) (x (y 2) 2 = 22
2x + 1 -1+2)y2x2+-- 4y +4 = 4
x 2+ y2 4y +1 = 0

Equxa2t+iony2o-f 2loxc-us4yof+p1oi=nt0V. is

0x

Example 2 Find the equation of locus of moving point P so that its
y distances from A(1, 2) is the same with its distance from

B(5, 4).

Locus of point P I B(5, 4)

II

I III Solution
Let point P is (x, y). Given
II that distance of point P from
III A(1, 2) is the same with its
distance from B(5, 4).

A(1, 2) PA = PB

(x - 1)2+ (y - 2)2 = (x - 5)2 + (y - 4)2
+(x1-8+1x)y2+2+4-(yy4y-- (xx2-- (y -
x2 - 2x 2)2 = 5)2 + 4)2 - 8y + 16
2x + y +4 = 10x + 25 + y2
-369 =0
= 0-2x
y = + 9

0 x

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NOTA VEKTOR DAN SKALAR / VECTOR AND SCALAR
PETA MINDA

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NOTA VEKTOR DALAM KOORDINAT CARTESAN
PETA MINDA VECTORS IN THE CARTESIAN COORDINATES

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NOTA KONSEP PETUA SINUS / CONCEPT OF SINE RULE
PETA MINDA

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NOTA PENYELESAIAN SEGI TIGA MELIBATKAN OBJEK TIGA MATRA
PETA MINDA SOLUTION OF TRIANGLES INVOLVING THREE-DIMENSIONAL OBJECTS

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