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## NCERT Solutions Class 12 Mathematics Part III . 627 Pages (1343-1970). Free Flip-Book by Study Innovations

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# NCERT Solutions Class 12 Mathematics Part III . 627 Pages (1343-1970). Free Flip-Book by Study Innovations

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Class XII Chapter 8 – Application of Integrals Maths

The area of the region bounded by the lines is the area of ∆ABC. AL and CM are the
perpendiculars on x-axis.
Area (∆ABC) = Area (ALMCA) – Area (ALB) – Area (CMB)

Question 15: , is represented as

Find the area of the region

The area bounded by the curves,

Page 45 of 53

Class XII Chapter 8 – Application of Integrals Maths

The points of intersection of both the curves are .
The required area is given by OABCO.
It can be observed that area OABCO is symmetrical about x-axis.

∴ Area OABCO = 2 × Area OBC

Area OBCO = Area OMC + Area MBC

Question 16:
Area bounded by the curve y = x3, the x-axis and the ordinates x = –2 and x = 1 is
A. – 9
B.

Page 46 of 53

Class XII Chapter 8 – Application of Integrals Maths
C.
D.

Solve it yourself.
The correct option is D.

Question 17:

The area bounded by the curve , x-axis and the ordinates x = –1 and x = 1 is

given by

[Hint: y = x2 if x > 0 and y = –x2 if x < 0]

Page 47 of 53

Class XII Chapter 8 – Application of Integrals Maths
A. 0
B.
C.
D.

Thus, the correct answer is C.
Page 48 of 53

Class XII Chapter 8 – Application of Integrals Maths

Question 18:
The area of the circle x2 + y2 = 16 exterior to the parabola y2 = 6x is

A.

B.

C.

D.

The given equations are
x2 + y2 = 16 … (1)
y2 = 6x … (2)

Area bounded by the circle and parabola
Page 49 of 53

Class XII Chapter 8 – Application of Integrals Maths

Area of circle = π (r)2
= π (4)2
= 16π units

Thus, the correct answer is C.

Page 50 of 53

Class XII Chapter 8 – Application of Integrals Maths

Question 19:

The area bounded by the y-axis, y = cos x and y = sin x when
A.

B.

C.
D.
The given equations are
y = cos x … (1)
And, y = sin x … (2)

Required area = Area (ABLA) + area (OBLO)
Integrating by parts, we obtain

Page 51 of 53

Class XII Chapter 8 – Application of Integrals Maths

Thus, the correct answer is B.

Therefore, the required area is units
Page 52 of 53

Class XII Chapter 9 – Differential Equations Maths
Question 1: www.ncrtsolutions.blogspot.com
Exercise 9.1

Determine order and degree(if defined) of differential equation

The highest order derivative present in the differential equation is . Therefore, its
order is four.
The given differential equation is not a polynomial equation in its derivatives. Hence, its
degree is not defined.

Question 2:
Determine order and degree(if defined) of differential equation
The given differential equation is:

The highest order derivative present in the differential equation is . Therefore, its order
is one.
It is a polynomial equation in . The highest power raised to is 1. Hence, its degree is
one.

Question 3:

Determine order and degree(if defined) of differential equation

Page 1 of 120

Class XII Chapter 9 – Differential Equations Maths

The highest order derivative present in the given differential equation is . Therefore,
its order is two.

It is a polynomial equation in and . The power raised to is 1.
Hence, its degree is one.

Question 4:

Determine order and degree(if defined) of differential equation

The highest order derivative present in the given differential equation is . Therefore,
its order is 2.
The given differential equation is not a polynomial equation in its derivatives. Hence, its
degree is not defined.

Question 5:
Determine order and degree(if defined) of differential equation

The highest order derivative present in the differential equation is . Therefore, its
order is two.

Page 2 of 120

Class XII Chapter 9 – Differential Equations Maths

It is a polynomial equation in and the power raised to is 1.
Hence, its degree is one.

Question 6:
Determine order and degree(if defined) of differential equation

The highest order derivative present in the differential equation is . Therefore, its
order is three.

The given differential equation is a polynomial equation in .

The highest power raised to is 2. Hence, its degree is 2.

Question 7:
Determine order and degree(if defined) of differential equation

The highest order derivative present in the differential equation is . Therefore, its
order is three.

It is a polynomial equation in . The highest power raised to is 1. Hence, its
degree is 1.

Question 8:

Determine order and degree(if defined) of differential equation

Page 3 of 120

Class XII Chapter 9 – Differential Equations Maths

The highest order derivative present in the differential equation is . Therefore, its order
is one.
The given differential equation is a polynomial equation in and the highest power
raised to is one. Hence, its degree is one.

Question 9:
Determine order and degree(if defined) of differential equation

The highest order derivative present in the differential equation is . Therefore, its
order is two.
The given differential equation is a polynomial equation in and and the highest
power raised to is one.
Hence, its degree is one.

Question 10:
Determine order and degree(if defined) of differential equation

The highest order derivative present in the differential equation is . Therefore, its
order is two.
This is a polynomial equation in and and the highest power raised to is one.
Hence, its degree is one.

Question 11:
The degree of the differential equation

is

Page 4 of 120

Class XII Chapter 9 – Differential Equations Maths

(A) 3 (B) 2 (C) 1 (D) not defined

The given differential equation is not a polynomial equation in its derivatives. Therefore,
its degree is not defined.
Hence, the correct answer is D.

Question 12:
The order of the differential equation

is
(A) 2 (B) 1 (C) 0 (D) not defined

The highest order derivative present in the given differential equation is . Therefore,
its order is two.
Hence, the correct answer is A.

Page 5 of 120

Class XII Chapter 9 – Differential Equations Maths
Question 1: Exercise 9.2

Differentiating both sides of this equation with respect to x, we get:

Now, differentiating equation (1) with respect to x, we get:

Substituting the values of in the given differential equation, we get the L.H.S.
as:

Thus, the given function is the solution of the corresponding differential equation.
Question 2:

Differentiating both sides of this equation with respect to x, we get:

Substituting the value of in the given differential equation, we get:

L.H.S. = = R.H.S.

Hence, the given function is the solution of the corresponding differential equation.

Page 6 of 120

Class XII Chapter 9 – Differential Equations Maths

Question 3:
Differentiating both sides of this equation with respect to x, we get:

Substituting the value of in the given differential equation, we get:

L.H.S. = = R.H.S.

Hence, the given function is the solution of the corresponding differential equation.

Question 4:

Differentiating both sides of the equation with respect to x, we get:

Page 7 of 120

Class XII Chapter 9 – Differential Equations Maths

L.H.S. = R.H.S.
Hence, the given function is the solution of the corresponding differential equation.
Question 5:
Differentiating both sides with respect to x, we get:

Substituting the value of in the given differential equation, we get:
Hence, the given function is the solution of the corresponding differential equation.
Question 6:

Page 8 of 120

Class XII Chapter 9 – Differential Equations Maths

Differentiating both sides of this equation with respect to x, we get:

Substituting the value of in the given differential equation, we get:

Hence, the given function is the solution of the corresponding differential equation.
Question 7:

Differentiating both sides of this equation with respect to x, we get:

Page 9 of 120

Class XII Chapter 9 – Differential Equations Maths

L.H.S. = R.H.S.
Hence, the given function is the solution of the corresponding differential equation.
Question 8:
Differentiating both sides of the equation with respect to x, we get:

Substituting the value of in equation (1), we get:

Page 10 of 120

Class XII Chapter 9 – Differential Equations Maths

Hence, the given function is the solution of the corresponding differential equation.
Question 9:
Differentiating both sides of this equation with respect to x, we get:

Substituting the value of in the given differential equation, we get:
Page 11 of 120

Class XII Chapter 9 – Differential Equations Maths

Hence, the given function is the solution of the corresponding differential equation.
Question 10:

Differentiating both sides of this equation with respect to x, we get:

Substituting the value of in the given differential equation, we get:

Hence, the given function is the solution of the corresponding differential equation.
Page 12 of 120

Class XII Chapter 9 – Differential Equations Maths

Question 11:
The numbers of arbitrary constants in the general solution of a differential equation of
fourth order are:
(A) 0 (B) 2 (C) 3 (D) 4
We know that the number of constants in the general solution of a differential equation
of order n is equal to its order.
Therefore, the number of constants in the general equation of fourth order differential
equation is four.
Hence, the correct answer is D.

Question 12:
The numbers of arbitrary constants in the particular solution of a differential equation of
third order are:
(A) 3 (B) 2 (C) 1 (D) 0
In a particular solution of a differential equation, there are no arbitrary constants.
Hence, the correct answer is D.

Page 13 of 120

Class XII Chapter 9 – Differential Equations Maths
Question 1: Exercise 9.3

Differentiating both sides of the given equation with respect to x, we get:

Again, differentiating both sides with respect to x, we get:

Hence, the required differential equation of the given curve is
Question 2:
Differentiating both sides with respect to x, we get:

Again, differentiating both sides with respect to x, we get:
Page 14 of 120

Class XII Chapter 9 – Differential Equations Maths

Dividing equation (2) by equation (1), we get:

This is the required differential equation of the given curve.
Question 3:
Differentiating both sides with respect to x, we get:
Again, differentiating both sides with respect to x, we get:
Multiplying equation (1) with (2) and then adding it to equation (2), we get:

Now, multiplying equation (1) with equation (3) and subtracting equation (2) from it, we
get:

Substituting the values of in equation (3), we get:
Page 15 of 120

Class XII Chapter 9 – Differential Equations Maths

This is the required differential equation of the given curve.
Question 4:
Differentiating both sides with respect to x, we get:

Multiplying equation (1) with equation (2) and then subtracting it from equation (2), we
get:

Differentiating both sides with respect to x, we get:
Dividing equation (4) by equation (3), we get:

This is the required differential equation of the given curve.

Page 16 of 120

Class XII Chapter 9 – Differential Equations Maths
Question 5:

Differentiating both sides with respect to x, we get:

Again, differentiating with respect to x, we get:

Adding equations (1) and (3), we get:

This is the required differential equation of the given curve.

Question 6:
Form the differential equation of the family of circles touching the y-axis at the origin.
The centre of the circle touching the y-axis at origin lies on the x-axis.
Let (a, 0) be the centre of the circle.
Since it touches the y-axis at origin, its radius is a.
Now, the equation of the circle with centre (a, 0) and radius (a) is

Page 17 of 120

Class XII Chapter 9 – Differential Equations Maths

Differentiating equation (1) with respect to x, we get:
Now, on substituting the value of a in equation (1), we get:

This is the required differential equation.
Question 7:
Form the differential equation of the family of parabolas having vertex at origin and axis
along positive y-axis.
The equation of the parabola having the vertex at origin and the axis along the positive
y-axis is:

Page 18 of 120

Class XII Chapter 9 – Differential Equations Maths

Differentiating equation (1) with respect to x, we get:
Dividing equation (2) by equation (1), we get:

This is the required differential equation.
Question 8:
Form the differential equation of the family of ellipses having foci on y-axis and centre at
origin.
The equation of the family of ellipses having foci on the y-axis and the centre at origin is
as follows:

Page 19 of 120

Class XII Chapter 9 – Differential Equations Maths

Differentiating equation (1) with respect to x, we get:
Again, differentiating with respect to x, we get:
Substituting this value in equation (2), we get:
This is the required differential equation.

Page 20 of 120

Class XII Chapter 9 – Differential Equations Maths

Question 9:
Form the differential equation of the family of hyperbolas having foci on x-axis and
centre at origin.
The equation of the family of hyperbolas with the centre at origin and foci along the x-
axis is:

Differentiating both sides of equation (1) with respect to x, we get:
Again, differentiating both sides with respect to x, we get:
Substituting the value of in equation (2), we get:

Page 21 of 120

Class XII Chapter 9 – Differential Equations Maths

This is the required differential equation.

Question 10:
Form the differential equation of the family of circles having centre on y-axis and radius
3 units.
Let the centre of the circle on y-axis be (0, b).
The differential equation of the family of circles with centre at (0, b) and radius 3 is as
follows:

Differentiating equation (1) with respect to x, we get:
Substituting the value of (y – b) in equation (1), we get:

Page 22 of 120

Class XII Chapter 9 – Differential Equations Maths

This is the required differential equation. as the general solution?
Question 11:
Which of the following differential equations has
A.

B.
C.
D.
The given equation is:

Differentiating with respect to x, we get:

Again, differentiating with respect to x, we get:

Page 23 of 120

Class XII Chapter 9 – Differential Equations Maths

This is the required differential equation of the given equation of curve.
Hence, the correct answer is B.

Question 12: as one of its particular solution?
Which of the following differential equation has

A.

B.

C.

D.

The given equation of curve is y = x.
Differentiating with respect to x, we get:

Again, differentiating with respect to x, we get:

Now, on substituting the values of y, from equation (1) and (2) in each of

the given alternatives, we find that only the differential equation given in alternative C is
correct.

Page 24 of 120

Class XII Chapter 9 – Differential Equations Maths

Hence, the correct answer is C.

Page 25 of 120

Class XII Chapter 9 – Differential Equations Maths
Question 1: Exercise 9.4

The given differential equation is:

Now, integrating both sides of this equation, we get:

This is the required general solution of the given differential equation.
Question 2:
The given differential equation is:

Page 26 of 120

Class XII Chapter 9 – Differential Equations Maths

Now, integrating both sides of this equation, we get:

This is the required general solution of the given differential equation.
Question 3:

The given differential equation is:

Now, integrating both sides, we get:
Page 27 of 120

Class XII Chapter 9 – Differential Equations Maths

This is the required general solution of the given differential equation.
Question 4:
The given differential equation is:

Integrating both sides of this equation, we get:

Page 28 of 120

Class XII Chapter 9 – Differential Equations Maths

Substituting these values in equation (1), we get:

This is the required general solution of the given differential equation.
Question 5:
The given differential equation is:

Integrating both sides of this equation, we get:
Page 29 of 120

Class XII Chapter 9 – Differential Equations Maths

Let (ex + e–x) = t.
Differentiating both sides with respect to x, we get:

Substituting this value in equation (1), we get:

This is the required general solution of the given differential equation.
Question 6:
The given differential equation is:

Integrating both sides of this equation, we get:

Page 30 of 120

Class XII Chapter 9 – Differential Equations Maths

This is the required general solution of the given differential equation.
Question 7:
The given differential equation is:

Integrating both sides, we get:

Substituting this value in equation (1), we get:
Page 31 of 120

Class XII Chapter 9 – Differential Equations Maths

This is the required general solution of the given differential equation.
Question 8:
The given differential equation is:

Integrating both sides, we get:

This is the required general solution of the given differential equation.
Page 32 of 120

Class XII Chapter 9 – Differential Equations Maths
Question 9:

The given differential equation is:

Integrating both sides, we get:

Substituting this value in equation (1), we get:
Page 33 of 120

Class XII Chapter 9 – Differential Equations Maths

This is the required general solution of the given differential equation.
Question 10:
The given differential equation is:

Integrating both sides, we get:

Page 34 of 120

Class XII Chapter 9 – Differential Equations Maths

Substituting the values of in equation (1), we get:

This is the required general solution of the given differential equation.
Question 11:

The given differential equation is:

Integrating both sides, we get:
Page 35 of 120

Class XII Chapter 9 – Differential Equations Maths

Comparing the coefficients of x2 and x, we get:
A+B=2
B+C=1
A+C=0
Solving these equations, we get:

Substituting the values of A, B, and C in equation (2), we get:

Therefore, equation (1) becomes:

Page 36 of 120

Class XII Chapter 9 – Differential Equations Maths

Substituting C = 1 in equation (3), we get:
Question 12:

Integrating both sides, we get:
Page 37 of 120

Class XII Chapter 9 – Differential Equations Maths

Comparing the coefficients of x2, x, and constant, we get:

Solving these equations, we get
Substituting the values of A, B, and C in equation (2), we get:
Therefore, equation (1) becomes:

Page 38 of 120

Class XII Chapter 9 – Differential Equations Maths

Substituting the value of k2 in equation (3), we get:

Question 13:

Page 39 of 120

Class XII Chapter 9 – Differential Equations Maths

Integrating both sides, we get:

Substituting C = 1 in equation (1), we get:

Question 14:
Integrating both sides, we get:

Page 40 of 120

Class XII Chapter 9 – Differential Equations Maths

Substituting C = 1 in equation (1), we get:
y = sec x

Question 15:
Find the equation of a curve passing through the point (0, 0) and whose differential

equation is .

The differential equation of the curve is:

Integrating both sides, we get:

Page 41 of 120

Class XII Chapter 9 – Differential Equations Maths

Substituting this value in equation (1), we get:
Now, the curve passes through point (0, 0).

Substituting in equation (2), we get:

Hence, the required equation of the curve is
Question 16:

For the differential equation find the solution curve passing
through the point (1, –1).

Page 42 of 120

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