11 The enzyme aspartate carbomoyltransferase (ACTase) is a key regulatory enzyme in nucleotide metabolism
in bacteria.The activity of this enzyme was studied in the bacterium Helicobacter pylori, an important human
pathogen.ACTase activity and the growth of H. pylori were measured at different concentrations of carbomoyl
aspartate (CAA), the end product of the reaction catalysed by ACTase.
@Zn
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a i State the growth of H. pylori at a CAA concentration of 30 mmol dm–3. (1)
ii Calculate the change in ACTase activity between CAA concentrations of 20 and 40 mmol dm–3. (1)
b Compare the effect of increasing CAA concentration on the growth of H. pylori and ACTase activity. (2)
c Explain the effect of CAA on ACTase activity. (2)
d Suggest a direct medical application of this information. (1)
(total 7 marks)
© IB Organization 2009
, CJ8A:>8 68>9H 6C9 EGDI:>CH &.(
- 8Zaa gZhe^gVi^dc VcY e]didhnci]Zh^h
Notation in biochemical >cigdYjXi^dc
pathways
Respiration and photosynthesis are two key biochemical
Photosynthesis and respiration pathways in ecosystems. Light energy from the Sun is trapped
involve large organic molecules. as chemical energy in photosynthesis and then the energy
For simplicity, these are often is transferred through food chains and released back to
identified by the number of the environment as heat energy from respiration.The two
carbon atoms they contain.Thus pathways can be simply written as:
glucose, C6H12O6, is simplified to
C6.A biochemical pathway may photosynthesis
be written as C3 n C3 so that
nothing appears to have happened 6CO2 + 6H2O + energy C6H12O6 + 6O2
but the number of oxygen and/or
hydrogen atoms in the second C3 respiration
molecule will have changed. Both
photosynthesis and respiration There are a number of similarities between the two pathways,
have linear and cyclic components which will be examined in this chapter.The basics of
in their pathways. Many of photosynthesis and respiration are covered in Chapter 3, and it
the compounds involved are would be useful to review this chapter before proceeding.
abbreviated to their initials.
-#& 8Zaa gZhe^gVi^dc
6hhZhhbZci hiViZbZcih
r State that oxidation involves the loss of electrons from an element, whereas reduction involves a gain of electrons; and
that oxidation frequently involves gaining oxygen or losing hydrogen, whereas reduction frequently involves losing
oxygen or gaining hydrogen.
r Outline the process of glycolysis, including phosphorylation, lysis, oxidation and ATP formation.
r Draw and label a diagram showing the structure of a mitochondrion as seen in electron micrographs.
r Explain aerobic respiration, including the link reaction, the Krebs cycle, the role of NADH + H+, the electron
transport chain and the role of oxygen.
r Explain oxidative phosphorylation in terms of chemiosmosis.
r Explain the relationship between the structure of the mitochondrion and its function.
gZYjXZY dm^Y^hZY Dm^YVi^dc VcY gZYjXi^dc
bdaZXjaZ & bdaZXjaZ '
Cell respiration involves several oxidation and reduction reactions. Such
dm^Y^hZY gZYjXZY reactions are common in biochemical pathways.When two molecules react,
bdaZXjaZ & bdaZXjaZ ' one of them starts in the oxidised state and becomes reduced, and the other
starts in the reduced state and becomes oxidised, as shown in Figure 8.1.
;^\jgZ -#& Dm^YVi^dc VcY gZYjXi^dc VgZ
a^c`ZY egdXZhhZh Ä Vh dcZ bdaZXjaZ ^h There are three different ways in which a molecule can be oxidised
gZYjXZY Vcdi]Zg ^h dm^Y^hZY ^c V gZYdm or reduced, as outlined in Table 8.1. In biological oxidation reactions,
gZVXi^dc# addition of oxygen atoms is an alternative to removal of hydrogen atoms.
Since a hydrogen atom consists of an electron and a proton, losing
hydrogen atoms (oxidation) involves losing one or more electrons.
&.)
Oxidation and reduction occur together in biochemical reactions.As Dm^YVi^dc GZYjXi^dc
one compound loses electrons, for example, another gains. In the simple
equation for respiration, glucose is oxidised as hydrogen atoms, and adhh d[ ZaZXigdch \V^c d[ ZaZXigdch
therefore electrons, are gradually removed from it and added to hydrogen adhh d[ ]nYgd\Zc \V^c d[ ]nYgd\Zc
acceptors (the oxygen atoms on the left side of the equation), which \V^c d[ dmn\Zc adhh d[ dmn\Zc
become reduced.
IVWaZ -#& 8]Vc\Zh ^ckdakZY ^c dm^YVi^dc VcY
C6H12O6 + 6O2 n 6CO2 + 6H2O + energy gZYjXi^dc#
Chemical reactions like this are referred to as redox reactions. In redox An easy way to remember
reactions, the reduced molecule always has more potential energy than the oxidation and reduction is to think
oxidised form of the molecule. Electrons passing from one molecule to of the words OIL RIG:
another carry energy with them.
OIL = Oxidation Is Loss (of
GZhe^gVi^dc electrons)
Cell respiration is the controlled breakdown of food molecules such RIG = Reduction Is Gain (of
as glucose or fat to release energy, which can be stored for later use.The electrons)
energy is most commonly stored in the molecule adenosine triphosphate,
or ATP. The respiration pathway can be divided into four parts: Bisphosphate and diphosphate
r glycolysis Although both these molecules
r link reaction contain two phosphate groups,
r Krebs cycle the phosphates are joined in
r electron transfer chain and chemiosmosis. different ways. In a diphosphate
molecule such as ADP, the two
<anXdanh^h phosphates are joined to each
other; in a bisphosphate molecule
Glycolysis is the first stage in the series of reactions that make up such as hexose bisphosphate, each
respiration. It literally means ‘breaking apart glucose’.The glycolysis phosphate is joined to a different
pathway occurs in the cytoplasm of the cell. It is anaerobic (that is, it can part of the hexose molecule.
proceed in the absence of oxygen) and produces pyruvate and a small
amount of ATP. One molecule of the hexose sugar glucose is converted to NAD+ is a hydrogen carrier that
two molecules of the three-carbon molecule called pyruvate with the net accepts hydrogen atoms removed
gain of two molecules of ATP and two molecules of NADH + H+.The during the reactions of respiration.
process is shown in detail in Figure 8.2 (overleaf ). During glycolysis, two hydrogen
1 The first steps are to add two phosphate groups from ATP, in a process atoms are removed and NAD+
accepts the protons from one of
called phosphorylation.A hexose bisphosphate molecule is produced. them and the electrons from both
(This appears contrary to the purpose of respiration, which is to make of them.
ATP, but the two lost ATPs are recovered later.)
2 The hexose bisphosphate is now split into two triose phosphates in a NAD++ 2H n NADH + H+
reaction called lysis. Note that NADH + H+ must be
3 Now, another phosphorylation takes place but this time an inorganic written in this way and should not
phosphate ion, Pi, is used and not ATP.Two triose bisphosphates are be simplified to NADH2.
formed.The energy to add the Pi comes from an oxidation reaction.
The triose bisphosphate is oxidised and at the same time NAD+ is
reduced to NADH + H+.
4 There now follows a series of reactions in which the two phosphate
groups from each triose bisphosphate are transferred onto two
molecules of ADP, to form two molecules of ATP – this is ATP
formation.A pyruvate molecule is also produced.
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' 6IE
' Anh^h e]dhe]dgnaViZY +"XVgWdc hj\Vg
]ZmdhZ W^he]dhe]ViZ
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hj\Vg hea^ih id [dgb ild ("
XVgWdc hj\Vg e]dhe]ViZh
' ("XVgWdc hj\Vg e]dhe]ViZ
' ig^dhZ e]dhe]ViZ
888 888
E E
( Dm^YVi^dc E^ E^ ' C69
) 6IE [dgbVi^dc ' C69= =
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igVch[ZggZY id
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VXXZeidg VcY
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6IE bdaZXjaZh#
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e]dhe]ViZ bdaZXjaZh VgZ
888 888 XdckZgiZY id engjkViZ
;^\jgZ -#' I]Z hiV\Zh d[ \anXdanh^h# CdiZ i]Vi [dg ZVX] bdaZXjaZ d[ \ajXdhZ! ild
bdaZXjaZh d[ 6IE VgZ jhZY VcY [djg VgZ [dgbZY! hd i]ZgZ ^h V cZi \V^c d[ ild 6IEh#
Four molecules of ATP are formed by converting one molecule of
glucose to two molecules of pyruvate. However, two molecules of ATP
were required to start the pathway and so there is a net gain of two
molecules of ATP per glucose. In addition two NADH + H+ are formed.
To summarise, the net products of glycolysis per glucose molecule are:
r 2 ATP
r 2 NADH + H+
r 2 molecules of pyruvate.
& A^hi i]gZZ lVnh ^c l]^X] V hjWhiVcXZ XVc WZ gZYjXZY#
' L]Vi bdaZXjaZ ^h jhZY id e]dhe]dgnaViZ \ajXdhZ Vi i]Z hiVgi d[ \anXdanh^h4
( HiViZ i]Z cVbZ d[ i]Z egdXZhh i]Vi hea^ih i]Z ]ZmdhZ W^he]dhe]ViZ
bdaZXjaZ ^cid ild ig^dhZ e]dhe]ViZ bdaZXjaZh#
) L]Vi ^h jhZY id e]dhe]dgnaViZ ZVX] ig^dhZ e]dhe]ViZ bdaZXjaZ [daadl^c\
i]Z VWdkZ gZVXi^dc4
* >c i]Z \anXdanh^h eVi]lVn! l]^X] bdaZXjaZ ^h dm^Y^hZY Yjg^c\ Vc
dm^YVi^dc$gZYjXi^dc gZVXi^dc4
+ L]Vi ^h i]Z cZi \V^c d[ 6IE [gdb \anXdanh^h eZg \ajXdhZ bdaZXjaZ4
&.+
I]Z a^c` gZVXi^dc VcY @gZWh XnXaZ
If oxygen is present, pyruvate formed during glycolysis moves into
the mitochondrial matrix by facilitated diffusion.The structure of a
mitochondrion is shown in Figures 8.3 and 8.4.
djiZg ^ciZg"bZbWgVcZ bVig^m Xg^hiV ^ccZg
bZbWgVcZ heVXZ g^WdhdbZ bZbWgVcZ
;^\jgZ -#( :aZXigdc b^Xgd\gVe] d[ V b^idX]dcYg^dc ,' %%% #
I]Z [aj^Y bVig^m XdciV^ch i]Z I]Z ^ccZg bZbWgVcZ ^h [daYZY id Increasing area
ZconbZh gZfj^gZY [dg i]Z a^c` [dgb Xg^hiVZ! l]^X] ^cXgZVhZ i]Z
gZVXi^dc VcY @gZWh XnXaZ# hjg[VXZ VgZV [dg gZVXi^dch# I]^h Just as the inner lining of the small
bZbWgVcZ XdciV^ch i]Z egdiZ^ch intestine is folded to increase its
cZZYZY [dg i]Z ZaZXigdc igVch[Zg surface area to absorb food, so the
X]V^c VcY Vahd 6IE hnci]VhZ# inner mitochondrial membrane is
folded into cristae to increase its
Xg^hiVZ g^WdhdbZ surface area.The cristae provide
a large area for the enzymes and
6IEVhZ molecules used in the electron
transport chain (see page 199).
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ZcXadhZh i]Z b^idX]dcYg^dc `cdlc Vh i]Z ^ciZg"bZbWgVcZ heVXZ! ^h ^bedgiVci ^c
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;^\jgZ -#) 9^V\gVb d[ V b^idX]dcYg^dc ^c adc\^ijY^cVa hZXi^dc#
The link reaction and the Krebs cycle pathways occur in the
mitochondrial matrix, shown in Figure 8.5 (overleaf ).
1 The link reaction converts pyruvate to acetyl CoA using
coenzyme A, and a carbon atom is removed as carbon dioxide.This is
called a decarboxylation reaction.At the same time as the carbon
dioxide is removed, pyruvate is oxidised by the removal of hydrogen.The
hydrogen atoms are removed by NAD+ to form NADH + H+.
- 8:AA G:HE>G6I>DC 6C9 E=DIDHNCI=:H>H &.,
[VX^a^iViZY Y^[[jh^dc
[gdb i]Z XnideaVhb
i]Z a^c` gZVXi^dc engjkViZ C69 & 9ZXVgWdmnaVi^dc
8D' 888 C69= = VcY dm^YVi^dc
gZVXi^dch
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88
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V\V^c gZXnXaZY
)"XVgWdc VX^Y
8888
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888888
C69= =
+ Dm^YVi^dc C69 @gZWh
gZVXi^dch XnXaZ
Vahd `cdlc Vh i]Z X^ig^X VX^Y XnXaZ
;69=' C69
* 6IE ;69 )"XVgWdc VX^Y C69= = ( 9ZXVgWdmnaVi^dc
[dgbVi^dc 6IE 8888 8D' VcY dm^YVi^dc
gZVXi^dch
69E E^ 8D'
*"XVgWdc VX^Y
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) 9ZXVgWdmnaVi^dc C69= =
VcY dm^YVi^dc C69
gZVXi^dch
;^\jgZ -#* I]Z a^c` gZVXi^dc VcY @gZWh XnXaZ#
2 Acetyl CoA now enters the Krebs cycle to continue the processes
of aerobic respiration. Immediately, the coenzyme A is removed to be
recycled.
3 The two carbons that enter with acetyl CoA also leave as carbon
dioxide from two decarboxylation reactions.
4 One molecule of ATP is formed.
5 Hydrogen is removed during oxidation reactions to the two hydrogen
carriers NAD+ and FAD+.
6 Since the Krebs cycle is a cyclic process, what enters must eventually
leave so that the cycle begins and ends with the same substances.
Because each molecule of glucose forms two molecules of pyruvate
during glycolysis, each glucose molecule requires two link reactions and
two rotations of the Krebs cycle.Thus, when working out the products
&.-
of the cycle we must consider two sets of products. So, to summarise, the Note that the correct method to
products of the link reaction and Krebs cycle, per glucose molecule, are: show reduced FAD is FADH2.
r 8 molecules of NADH + H+
r 2 molecules of FADH2
r 2 molecules of ATP
r 6 molecules of CO2.
I]Z ZaZXigdc igVchedgi X]V^c! dm^YVi^kZ e]dhe]dgnaVi^dc VcY
X]Zb^dhbdh^h
Most of the ATP produced from glucose breakdown occurs in the
last phase of respiration at the end of the electron transport chain.
Reactions take place on the inner mitochondrial membrane of the
cristae and in the inter-membrane space between the inner and outer
membranes.The inner membrane holds molecules called electron
carriers, which pick up electrons and pass them from one to another in
a series of oxidations and reductions.The pathway is called the electron
transport chain (ETC) because electrons from hydrogen are moved along
it. Several protein molecules are electron carriers and the three key ones
are shown in Figure 8.6.
Electrons from NADH + H+ are transferred onto the first electron
carrier.As they pass through the carrier, they lose energy and this is used
to pump a proton (H+) from the matrix to the inter-membrane space,
lowering the pH of the space.The electrons are then transferred to two
further carriers and the process is repeated.As the electrons from one
NADH + H+ pass along the chain, a total of nine protons are pumped
Xnidhda d[ XZaa egdidc XnidX]gdbZ
ejbeh dm^YVhZ
djiZg ]nYgd\Zc ^dch
b^idX]dcYg^Va egdidch VXXjbjaViZ
bZbWgVcZ = = = = = ==== = ]ZgZ XgZVi^c\ V
^ciZg"bZbWgVcZ = = ediZci^Va Y^[[ZgZcXZ
heVXZ = = = = == = = VXgdhh i]Z bZbWgVcZ
^ccZg = ==
b^idX]dcYg^Va
bZbWgVcZ 'ZÄ 'ZÄ 'ZÄ
bVig^m d[
b^idX]dcYg^dc 'ZÄ 'ZÄ egdidc X]VccZa
= = 6IE hnci]VhZ
ZaZXigdc XVgg^Zgh d[
i]Z ^ccZg C69 '= &' D'
b^idX]dcYg^Va C69= =
bZbWgVcZh ejbe
]nYgd\Zc ^dch ='D 69E E^ 6IE
egdidch [gdb i]Z
bVig^m id i]Z ^ciZg" =
bZbWgVcZ heVXZ
Vh egdidch Y^[[jhZ Ydlc i]Z
XdcXZcigVi^dc \gVY^Zci WVX` id i]Z
bVig^m k^V 6IE hnci]VhZ! ZcZg\n
^h ]VgcZhhZY [dg 6IE hnci]Zh^h
;^\jgZ -#+ I]Z ZaZXigdc igVchedgi X]V^c h]dl^c\ dm^YVi^kZ e]dhe]dgnaVi^dc VcY X]Zb^dhbdh^h#
- 8:AA G:HE>G6I>DC 6C9 E=DIDHNCI=:H>H &..
Chemiosmosis into the inter-membrane space.At the end of the chain, the electrons are
Osmosis is the passive flow combined with protons and oxygen atoms to make water, in the oxidative
of water molecules down a part of oxidative phosphorylation.
concentration gradient through
a partially permeable membrane. The space between the membranes is very narrow and allows for a
Chemiosmosis is similar but instead rapid increase in the concentration of the protons that are pumped into it
of water moving, it is protons during the electron transfer reactions.The protons in the inter-membrane
that pass down a concentration space create a concentration gradient between the space and the matrix.
gradient. These protons can now flow passively down this concentration gradient
back into the matrix, through a very large integral protein.This is called
As Table 8.2 shows, the net chemiosmosis.The large protein contains the enzyme ATP synthase,
production of ATP from one which joins ADP and Pi to form ATP. Three protons flowing through
molecule of glucose is, in theory, this enzyme results in one ATP being formed. Since the electrons from
36. Biochemists have discovered one NADH + H+ pump nine protons into the inter-membrane space,
that the actual production is closer each NADH + H+ results in the formation of three ATP. This is the
to 30 ATPs and propose that this phosphorylation part of oxidative phosphorylation.
discrepancy occurs because some
protons are used to transfer ATP FADH2 also supplies electrons to the electron transport chain but
from the matrix to the cytoplasm. further down the chain than NADH + H+, missing the first protein
Only about 30% of the energy in a pump. FADH2 allows the production of just two ATPs.
glucose molecule generates ATP.
DkZgVaa 6IE egdYjXi^dc Yjg^c\ VZgdW^X gZhe^gVi^dc
'%%
Together, glycolysis, the link reaction and the Krebs cycle yield 36
ATP molecules for each molecule of glucose broken down by aerobic
respiration, as summarised in Table 8.2.
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6IE [dgbVi^dc &- 6IE
cZi ZcZg\n n^ZaY + C69= = ) 6IE
' ;69=' (+ 6IE
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, L]ZgZ egZX^hZan Yd i]Z a^c` gZVXi^dc VcY i]Z gZVXi^dch d[ @gZWh XnXaZ
iV`Z eaVXZ4
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eaVXZ4
. >c i]Z a^c` gZVXi^dc! ^h engjkViZ dm^Y^hZY dg gZYjXZY4
&% CVbZ i]Z bdaZXjaZ i]Vi ZciZgh i]Z @gZWh XnXaZ#
&& 9jg^c\ dcZ gdiVi^dc d[ i]Z @gZWh XnXaZ! ]dl bVcn bdaZXjaZh d[ XVgWdc
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&* L]Vi ]VeeZch id i]Z e= d[ i]Z ^ciZg"bZbWgVcZ heVXZ Vh ZaZXigdch
bdkZ Vadc\ i]Z :I84
&+ =dl bVcn bdaZXjaZh d[ 6IE VgZ egdYjXZY [gdb dcZ C69= = 4
&, CVbZ i]Z bdaZXjaZ i]Vi i]Z egdidch eVhh i]gdj\] \d^c\ [gdb i]Z ^ciZg"
bZbWgVcZ heVXZ id i]Z bVig^m#
-#' E]didhnci]Zh^h
6hhZhhbZci hiViZbZcih
r Draw and label a diagram showing the structure of a chloroplast as seen in electron micrographs.
r State that photosynthesis consists of light-dependent and light-independent reaction.
r Explain the light-dependent reactions.
r Explain photophosphorylation in terms of chemiosmosis.
r Explain the light-independent reactions.
r Explain the relationship between the structure of the chloroplast and its function.
r Explain the relationship between the action spectrum and the absorption spectrum of photosynthetic pigments in
green plants.
r Explain the concept of limiting factors in photosynthesis with reference to light intensity, temperature and
concentration of carbon dioxide.
I]Z gZVXi^dch d[ e]didhnci]Zh^h The light-dependent and light-
independent reactions
Photosynthesis is the process by which light energy is harvested and stored
as chemical energy, primarily in sugars but also in other organic molecules Both of these reactions are part of
such as lipids. It occurs in green plants, algae and some bacteria.All these photosynthesis and can only occur
organisms are known as autotrophs, which means they can make their when there is sufficient light.The
own food. light-independent reactions do not
have to take place during darkness.
Photosynthesis can be divided into two parts:
r the light-dependent reaction
r the light-independent reaction.
The light-dependent reaction produces compounds that are used in the
light-independent reaction.
Both the light-dependent and the light-independent reactions take
place in the chloroplasts of plant cells (Figures 8.7 and 8.8, overleaf ).
The stroma contains the enzymes required for the light-independent
reaction and the stacks of thylakoid membranes increase the surface area
for the light-dependent reaction.
- 8:AA G:HE>G6I>DC 6C9 E=DIDHNCI=:H>H '%&
\gVcjb hiVgX]
higdbV \gV^c
aVbZaaV
X]adgdeaVhi
ZckZadeZ
;^\jgZ -#, :aZXigdc b^Xgd\gVe] d[ V X]adgdeaVhi '% %%% #
djiZg bZbWgVcZ X]adgdeaVhi
^ccZg bZbWgVcZ ZckZadeZ
g^WdhdbZh a^e^Y YgdeaZi
hiVgX] \gV^c
higdbV
aVbZaaV
i]naV`d^Y
\gVcjb hiVX` d[ i]naV`d^Yh
;^\jgZ -#- 9^V\gVb d[ V X]adgdeaVhi#
I]Z a^\]i"YZeZcYZci gZVXi^dc
The light-dependent reaction occurs on the thylakoid membranes
of the chloroplast and is powered by light energy from the Sun. Each
thylakoid is a flattened sac so the space in the middle is narrow.The
thylakoid membranes form stacks called grana, which may be joined
together by intergranal membranes. Light is absorbed by photosynthetic
pigments such as chlorophyll, which are found on the granal membranes.
There are several pigments found in plants and each one absorbs light of
a slightly different wavelength.The pigments are associated with proteins
that are involved in electron transport, proton pumping and chemiosmosis.
The photosynthetic pigments are combined into two complex groups
called photosystems I and II, which absorb the light energy and use
this to boost electrons to a higher energy level so that they become
‘excited’, as shown in Figure 8.9.
'%'
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ZaZXigdc
]^\]"ZcZg\n
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ZaZXigdc XVgg^Zgh
ZÄ 69E E^
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e]didhnhiZb >> a^\]i ZÄ C69E =
VWhdgWZY 'ZÄ
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='D C69E=
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& D' '= 'ZÄ ZÄ
'
8nXa^X e]dide]dhe]dgnaVi^dc
69E E^ ]^\]"ZcZg\n
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ZÄ
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WZilZZc ZaZXigdc XVgg^Zgh e]didhnhiZb >ZaZXigdc
X]Vc\Z ^c ZcZg\n XVgg^Zgh a^\]i
d[ ZaZXigdch VWhdgWZY
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1 The first step in the light-dependent reaction is the photoactivation
of photosystem II. Pigment molecules in the photosystem absorb light
energy and boost electrons in a molecule of chlorophyll to a higher
energy level.The electrons are accepted by a carrier protein molecule at
the start of the electron transport chain.
2 Photosystem II has to replace these lost electrons and it does this by
taking them from water.Water is split into electrons, protons (hydrogen
ions) and an oxygen atom. Since the splitting is brought about by light
energy, it is called photolysis.The oxygen is released as an excretory
product.
3 Excited electrons travel along the electron transport chain into
photosystem I.As they do this, they lose energy but this is used to
pump protons into the thylakoid interior (in a similar way as occurs
in the electron transport chain in the mitochondrion).The thylakoid
interior is small and so a proton concentration gradient builds up
quickly.The protons then flow out through a large channel protein,
- 8:AA G:HE>G6I>DC 6C9 E=DIDHNCI=:H>H '%(
NADP+ is very similar to NAD+ almost identical to the one in mitochondria, which contains the
– it simply has a phosphate group enzyme ATP synthase.This time though, the formation of ATP is called
attached.An easy way to remember photophosphorylation and it occurs between photosystems II and I
that photosynthesis uses NADP+ (Figure 8.10).
is to note that they both have a 4 Absorption of light energy causes photoactivation in photosystem I,
letter ‘P’. boosting more electrons to an even higher energy level.The electrons
that arrive from photosystem II replace those that are displaced.The
electrons at the higher energy level are combined with protons in the
hydrogen carrier NADP+ to form NADPH + H+.
The two products of the light-dependent reaction,ATP and NADPH +
H+,are used to drive the light-independent reaction.
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When ATP is produced using energy from excited electrons flowing from
photosystem II through photosynthesis I and on to NADP+, the process is
called non-cyclic photophosphorylation.
When light is not a limiting factor, the light-independent reactions
may proceed more slowly than the light-dependent reaction, so that the
supply of NADP+ runs out.This means the electrons boosted up from
photosystem I have no acceptor available to take them.They rejoin the
electron transport chain near the start and generate more ATP for the
light-independent reaction.This alternative pathway is called cyclic
photophosphorylation (Figure 8.9).
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The light-independent reaction occurs in the stroma of the chloroplast
and is a cyclic pathway called the Calvin cycle.The pathway is shown
in Figure 8.11. (Large organic molecules have been simplified to show
just the number of carbon atoms they contain.) ATP and NADPH + H+
formed during the light-dependent stage supply energy and reducing
power for the Calvin cycle.The final product of the cycle is carbohydrate.
During each turn of the Calvin cycle one molecule of carbon dioxide is
used so Figure 8.11 shows three cycles combined together.As this is a cycle,
what goes in must leave, so three carbons enter in three molecules of carbon
dioxide and three carbons leave in one molecule of triose phosphate, which
can be used to form glucose or other organic compounds.
1 At the start of the cycle, the acceptor molecule ribulose bisphosphate
(RuBP) combines with incoming carbon dioxide from the air to form
glycerate 3-phosphate (GP).This reaction is called carbon fixation. It
is catalysed by RuBP carboxylase, an enzyme that is sometimes called
rubisco.
2 The ATP and NADPH + H+ from the light-dependent reaction
convert the glycerate 3-phosphate into triose phosphate (TP). Glycerate
3-phosphate therefore becomes reduced to triose phosphate. No more
phosphate is added so the only input from ATP is energy.
3 Six molecules of triose phosphate are produced but only five are
needed to reform the ribulose bisphosphate to keep the cycle going.
The extra triose phosphate leaves the cycle and since it takes a
phosphate with it, this is replaced in the cycle from ATP.
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Six ‘turns’ of the Calvin cycle produces two triose phosphate molecules,
which can be combined to form the final product, glucose. Some triose
phosphate molecules will follow other pathways to make other organic
carbohydrate molecules, such as sucrose or cellulose, or other molecules
that the plant needs, such as amino acids, fatty acids or vitamins.
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Occasionally, the answer to a
question about an unknown biochemical
pathway is discovered as a result of
designing an investigation that is simple and
elegant.To find the steps involved in the
light-independent reaction, a team led by
Melvin Calvin (1911–1997) designed what
he called the ‘lollipop’ apparatus.
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To what extent could an elegant scientific
protocol be considered a work of art?
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I]Z VXi^dc heZXigjb VcY i]Z VWhdgei^dc heZXigjb Chlorophyll is the most important
and abundant plant pigment used
The spectrum of colours that humans can perceive is just part of the to capture light for photosynthesis.
electromagnetic spectrum.The range of wavelengths in visible light is from There are several forms of
400 nm to about 700 nm. Light provides the energy for photosynthesis but chlorophyll and each selectively
not all wavelengths are absorbed equally by the chloroplasts. If white light absorbs certain wavelengths of
is shone onto chloroplasts, the wavelengths they absorb depend on the light at the red and blue ends of
pigments present in them. Figure 8.12 shows an investigation in which the spectrum, while reflecting
the pigments from chloroplasts have been extracted and form a solution. green light.Terrestrial plants and
They are illuminated by light that has passed through a prism, so that the green algae contain two forms of
whole spectrum is visible.As the spectrum of wavelengths passes through the pigment, chlorophyll a and b,
the solution, the red and blue colours are lost, because they have been but diatoms contain a third type
absorbed by the pigments.The green part of the spectrum is not affected, known as chlorophyll c instead of
as chlorophyll does not absorb green light. chlorophyll b.
The investigation in Figure 8.12 can be made more sophisticated by Plants also contain several other
filtering white light so that only a precise wavelength is shone onto the pigments, including carotenoids,
chlorophyll solution.The proportion of each wavelength that is absorbed which are orange in colour, and
by the solution can be measured and an absorption spectrum, which anthocyanins, which are red.These
shows the relative amounts of each wavelength that is absorbed, can be pigments also selectively absorb
built up. Each pigment has a characteristic absorption spectrum, as shown certain wavelengths and reflect
in Figure 8.13 (overleaf ). others.Absorbed light may be
used in chemical reactions, and
The rate of photosynthesis can be measured in several ways, one the reflected light determines the
of which is to measure the volume of oxygen released. Rapid oxygen colour of the plant and can be
production indicates a high rate of photosynthesis. If the rate is measured important in attracting pollinators
for a range of wavelengths, a graph known as an action spectrum can to flowers.
be built up. Chlorophyll is more sensitive to some wavelengths of light
than others and produces excited electrons at the highest rate at these
wavelengths.The more excited electrons are produced, the faster the rate
of photosynthesis.A typical action spectrum shows that blue and red light
are used most efficiently.
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Figure 8.14 shows action and absorption spectra plotted on one graph.
The degree of correlation between the light energy absorbed at different
wavelengths and the rate of photosynthesis indicates that absorbed light is
used in the photosynthetic pathways.
Absorption and action spectra vary for different species of plant. Some
plants contain different pigments such as carotene and xanthophylls, which
absorb wavelengths that chlorophyll cannot.These pigments, known as
accessory pigments, absorb some yellow and green light and account for
the photosynthesis that occurs in this range.
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Like all metabolic processes, the photosynthetic pathway requires a %% 6
number of components to make it work. If any of these components is in A^\]i ^ciZch^in
short supply, it limits the rate at which photosynthesis works.
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factor and change the rate of photosynthesis.
When one step in photosynthesis is slowed down, the whole process
slows down. If light intensity is increased, the rate of photosynthesis
increases until a certain point when increasing light has no further effect,
as shown in Figure 8.15.
At low light intensities, there may be a shortage of the products of the
light-dependent reaction so photosynthesis is slow.At point A, the plant is
saturated with light and cannot photosynthesise at a faster rate even with
more light.This indicates that some other factor is limiting the reaction.
Temperature affects enzymes that catalyse the reactions of
photosynthesis so that if the temperature is too low the reactions
may proceed very slowly and a graph of temperature versus rate of
photosynthesis would look similar to Figure 8.16.At low concentrations
of carbon dioxide there may be insufficient carbon dioxide to be fixed in
the Calvin cycle.At higher carbon dioxide concentrations, another factor
may limit the reaction.
r In Figure 8.16, experiment 1 shows that as light intensity increases so
does the rate of photosynthesis between the points A and B on the
graph.At these light intensities, light is the limiting factor. Between
points B and C another factor has become limiting.
r In experiment 2, where the temperature has been increased to 20 °C,
the line has not changed, showing that it is the carbon dioxide
concentration that is the limiting factor – a change in temperature has
had no effect.
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Water is also essential for r In experiment 3, raising the carbon dioxide concentration causes the
photosynthesis but it is seldom rate of photosynthesis to increase to point D, but then another limiting
likely to be a limiting factor since factor comes in to play from D to E.
all the cells of a plant must contain
it to remain alive. r In experiment 4 we see that, at the higher carbon dioxide
concentration, raising the temperature causes the line to rise to F but
then again another limiting factor has become limiting from F to G.
The level of carbon dioxide in the atmosphere is relatively low and carbon
dioxide is frequently a limiting factor for photosynthesis. Horticulturalists
increase the yield of their crops by maximising the rate of photosynthesis
in their glasshouses.They do this by keeping the air inside warm with
heaters, increasing the intensity of light using lamps and, in some cases,
increasing the concentration of carbon dioxide.
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:cY"d["X]VeiZg fjZhi^dch (1)
(1)
1 Which of the following statements is correct? (1)
A Oxidation can involve the removal of oxygen from a compound.
B The solution inside a mitochondrion is called the matrix and the solution inside
a chloroplast is called the stroma.
C The folds of the inner membrane of a mitochondrion are called grana.
D The photosynthetic pigments in a chloroplast are found on the cristae.
2 Which of the following statements about glycolysis is correct?
A It is anaerobic, occurs in the cytoplasm, and includes at least one phosphorylation
reaction.
B It is aerobic and includes a lysis reaction.
C In the final stages, two molecules of ATP are used in the formation of pyruvate.
D It is aerobic and does not include a lysis reaction.
3 Which of the following statements about the link reaction and Krebs cycle is correct?
A Pyruvate in the mitochondrion matrix is oxidised to acetyl CoA.
B At the end of the link reaction, coenzyme A is recycled back into the cytoplasm
to combine with another pyruvate molecule.
C During one rotation of the Krebs cycle there are three decarboxylation reactions.
D The link reaction occurs in the mitochondrial matrix and Krebs cycle occurs on the
mitochondrial cristae.
'&%
4 Which of the following statements about the electron transport chain is correct? (1)
(1)
A As electrons flow along the chain, protons are pumped into the mitochondrial matrix.
B ATP is formed as electrons flow through the enzyme ATP synthase. (1)
C The flow of electrons along the chain causes the pH of the inter-membrane space (1)
to increase.
D When protons diffuse through ATP synthase into the matrix,ATP is formed.
5 Which of the following statements about the light-dependent reaction is correct?
A Photoactivation of photosystem I causes photolysis.
B Cyclic photophosphorylation involves both photosystems I and II.
C Electrons from the photolysis of water are transferred to NADP+ from photosystem I.
D NADP+ becomes oxidised when it combines with electrons and protons.
6 Which of the following statements about the light-independent reaction is correct?
A The enzyme RuBP carboxylase is used to convert ribulose bisphosphate into triose
phosphate.
B The conversion of glycerate 3-phosphate to triose phosphate requires ATP and
NADP+ from the light-dependent reaction.
C At the start of the Calvin cycle, carbon dioxide combines with glycerate 3-phosphate
to form ribulose bisphosphate.
D The formation of ribulose bisphosphate from triose phosphate requires a
phosphorylation reaction.
7 Which of the following statements is correct?
A A limiting factor is one that determines what the end-product of a reaction is.
B A limiting factor is one that determines the rate of a reaction.
C Limiting factors for photosynthesis include light intensity, carbon dioxide
concentration and glucose concentration.
D An absorption spectrum can be obtained by measuring the release of oxygen gas
from pondweed at different wavelengths of light.
8 Explain the reasons for: (2)
a many grana in the chloroplast (2)
b poor growth of plants growing beneath trees (2)
c large amounts of RuBP carboxylase in the chloroplast (total 6 marks)
9 Explain the process of aerobic respiration in a cell starting at the end of glycolysis and including oxidative (8)
phosphorylation.
10 Explain how the light-independent reaction of photosynthesis relies on the light-dependent reaction. (5)
- 8:AA G:HE>G6I>DC 6C9 E=DIDHNCI=:H>H '&&
:conbZ VXi^k^in11 At the start of glycolysis, glucose is phosphorylated to produce glucose 6-phosphate, which is converted into
fructose 6-phosphate.A second phosphorylation reaction is then carried out, in which fructose 6-phosphate
is converted into fructose 1,6-bisphosphate.This reaction is catalysed by the enzyme phosphofructokinase.
Biochemists measured the enzyme activity of phosphofructokinase (the rate at which it catalysed the reaction) at
different concentrations of fructose 6-phosphate.The enzyme activity was measured with a low concentration of
ATP and a high concentration of ATP in the reaction mixture.The graph below shows the results.
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a i Using only the data in the above graph, outline the effect of increasing fructose 6-phosphate (2)
concentration on the activity of phosphofructokinase, at a low ATP concentration. (2)
ii Explain how increases in fructose 6-phosphate concentration affect the activity of the enzyme.
b i Outline the effect of increasing the ATP concentration on the activity of phosphofructokinase. (2)
ii Suggest an advantage to living organisms of the effect of ATP on phosphofructokinase. (1)
(total 7 marks)
© IB Organization 2009
12 There are many abiotic factors that affect the rate of photosynthesis in terrestrial plants.Wheat is an important
cereal crop in many parts of the world.Wheat seedlings were grown at three different concentrations of carbon
dioxide (in parts per million) and the rate of photosynthesis was measured at various light intensities.
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a Describe the relationship between the rate of photosynthesis and light intensity for wheat seedlings (2)
grown at a CO2 concentration of 500 ppm. (3)
b Outline the effect of CO2 concentration on the rate of photosynthesis of the wheat seedlings. (2)
c The normal atmospheric concentration of CO2 is 370 ppm. Deduce the effect of doubling the CO2
concentration to 740 ppm on the growth of wheat plants.
Leaf area and chlorophyll levels were measured in sun leaves and shade leaves of Hedera helix (English ivy)
and Prunus laurocerasus (cherry laurel). Sun leaves developed under maximal sunlight conditions while
shade leaves developed at reduced sunlight levels in the shadow of other leaves.
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d Calculate the percentage increase in the amount of chlorophyll in shade leaves of ivy compared to (1)
sun leaves of ivy.
e Suggest a reason for the differences in chlorophyll concentration and leaf area in sun and shade leaves (2)
in these two species.
(total 10 marks)
© IB Organization 2009
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