2 Hasni’s father takes 7 hours 56 minutes
to stamp 7 pieces of batik cloth of the
same pattern. What is the time taken
to stamp one piece of batik cloth?
Given time taken to stamp 7 pieces of
Find batik cloth is 7 hours 56 minutes
Method
time taken to stamp one piece
of batik cloth
7 hours 56 minutes
???????
7 hours 56 minutes ÷ 7 =
1 hour 8 minutes
7 7 hours 5 6 minutes
–7 –56
00
7 hours 56 minutes ÷ 7 = 1 hour 8 minutes
The time taken to stamp one piece
of batik cloth is 1 hour 8 minutes.
Saiz sebenar How many pieces of batik cloth can
be completed in 204 minutes?
46
TEACHNOETRE’SS • Ask pupils to check their answers by multiplication or using a calculator. 5.9.2
3 The time taken to bake a fruit cake is 48 minutes.
How long does it take to bake 4 similar fruit cakes?
Give the answer in hours and minutes.
Method 4 × 48 minutes
= hours minutes
Multiply 48 minutes 3
by 4. Then convert
4 8 minutes
the answer to ×4
hours and minutes.
1 9 2 minutes
192 minutes = 180 minutes + 12 minutes
= 3 hours + 12 minutes
= 3 hours 12 minutes
4 × 48 minutes = 3 hours 12 minutes
The time taken to bake 4 similar fruit cakes
is 3 hours 12 minutes.
LET’S TRY 30 minutes
Solve the problems.
a Look at the picture. Calculate the
difference in time taken by Dashini to
read a storybook and watch television. 45 minutes
b The time taken for a car to travel non-stop from Johor Bahru
to Kuala Lumpur is 5 hours 30 minutes. If Mr Tan stops at
Pagoh for 20 minutes and at Ayer Keroh for 15 minutes, what
is his total travelling time?
c Haikal plays badminton 6 days a week and the total time is
720 minutes. How many minutes does he play badminton
every day? Saiz sebenar
A1B04 TEACHNOETRE’SS • Provide more problem solving exercises of various levels of difficulty. 5.9.2
47
FUN TIME
Let’s sing along.
OOLOnenntee’seyyayeelealaarrrer––mishheotomwwwbemlemvreaatnhmnyayotm,mntohonsnt.thhss??
OOLOneOnOLnteOe’neOsneOLnwteOwe’neasnweenmteelmel’aeesmeerhilekhinelkanhiokonrmu–luo–euluutitesurmerherhteermo–so––me–iweiwshmbshhvehoesooemsmobmwirwinwxwexabtattrhdymnymmenmatayrhmyastaaya,atendhnndisntncya,.ayyayouytymn,stmssesede?i?sincnsc.ou.ountnteeddsss?s???
Sunday Monday Tuesday
Wednesday
Thursday Friday
Saturday
1 hour 1 minute
= 60 minutes = 60 seconds
SCAN THIS
Saiz sebenar • Guide pupils to sing the song to the melody of “The Farmer in the Dell”. 5.2.1
• Divide pupils into two groups. Groups take turns to ask and answer 5.2.2
48 10A5B-106 TEACHNOETRE’SS questions until the last verse.
LENGTH, MASS, AND
VOLUME OF LIQUID
Come rhyme with me.
Ride along on my scooter
My Modenas Elegan I call her
From centimetre to metre
Divide one hundred for the answer.
Text a wish in telegram
Happy Mother’s Day, mother
From kilogram to gram
Multiply one thousand for the answer.
Every pupil must remember
The largest planet is Jupiter
From litre to millilitre
Multiply one thousand for the answer.
SCAN THIS
TEACHNOETRE’SS • Guide pupils through the rhyme above. Saiz sebenar
• Instil values such as appreciating mother’s deeds and love our country.
• Introduce other measuring tools. 6.1.1
6.2.1 49
6.3.1
CONVERT UNITS OF LENGTH
1
Finish
3m
9 m 20 cm
a How many centimetres before the tortoise reaches
the finishing line?
To convert m to cm, 1 m is equal
multiply by 100. to 100 cm.
3 m = cm Method 2 1 m = 100 cm
Method 1 100 cm
3 m = 3 × 100 cm 100 cm
+ 100 cm
= 300 cm 300 cm
3 m = 300 cm
It is 300 cm before the tortoise reaches the finishing line.
b Convert 9 m 20 cm to cm.
9 m 20 cm = cm
9 m 20 cm 9 m = 900 cm How do you convert
20 cm 9 m to 900 cm?
9 m 20 cm = 900 cm + 20 cm
= 920 cm
9 m 20 cm = 920 cm
Saiz sebenar
50 TEACHNOETRE’SS • Carry out simulation activities to convert units of metre to centimetre 6.1.1
using objects or flash cards.
• Emphasise to pupils to multiply by 100 when converting m to cm.
• Surf https://www.homeschoolmath.net/worksheets/measurements/PDFs/
To convert cm to m,
2 What is the length of this rope in m? divide by 100.
400 cm = m
400 cm = (400 ÷ 100) m 400 cm
=4m
400 cm = 4 m The length of the rope is 4 m.
3 Convert the height of the
orangutan to m and cm.
150 cm 150 cm = m cm
150 cm = 100 cm + 50 cm
= 1 m + 50 cm
= 1 m 50 cm
150 cm = 1 m 50 cm
4 What is the height and width of the
picture frame in m and cm?
210 cm = m cm
106 cm = m cm
LET’S TRY 200 cm
Convert the following units. c
ab
cm cm m
m cSmaiz sebenar
d 7 m 23 cm = cm e 808 cm =
6.1.1
A1B07 TEACHNOETRE’SS • Guide pupils to convert cm to m by dividing by 100.
• Surf http://www.metric-conversions.org 51
ADDITION OF LENGTH
1 Zebra
enclosure
390 m 453 m
Giraffe 372 m 560 m Horse
enclosure stable
Elephant enclosure
Find the distance from the horse stable to the giraffe
enclosure pass the zebra enclosure.
453 m + 390 m = m
1
453m
+390m
843m
453 m + 390 m = 843 m
The distance from the horse stable to the giraffe
enclosure pass the zebra enclosure is 843 m.
2 112 cm + 365 cm + 78 cm = cm
11
1 1 2 cm
3 6 5 cm
+ 7 8 cm
5 5 5 cm
Saiz sebe1n1a2r cm + 365 cm + 78 cm = 555 cm
52 TEACHNOETRE’SS • Train pupils to add units of length by providing situations involving length, 6.1.2
height, and distance.
• Provide various questions based on the diagram above.
3 What is the distance from to ? 54 cm 83 cm
Write your answer in m and cm.
54 cm + 97 cm + 83 cm 97 cm
= m cm
1 234 cm = 200 cm + 34 cm
= 2 m + 34 cm
5 4 cm = 2 m 34 cm
9 7 cm
+ 8 3 cm
2 3 4 cm
54 cm + 97 cm + 83 cm = 2 m 34 cm
The distance from to is 2 m 34 cm.
4 87 cm + 1 m 64 cm + 1 m 32 cm = m cm
1
8 7 cm
1 m 6 4 cm 183 cm
+ 1 m 3 2 cm
2 m 1 8 3 cm 100 cm 83 cm
+1 –100 100 cm = 1 m
3 m 8 3 cm
87 cm + 1 m 64 cm + 1 m 32 cm = 3 m 83 cm
LET’S TRY cm
1 Add.
a 45 m + 109 m = m b 38 cm + 62 cm =
c 84 cm + 79 cm + 105 cm = m cm
d 30 m 27 cm + 11 m 36 cm = m cm
2 Add 37 m 85 cm and 2 m 15 cm. Give the answer in cm.Saiz sebenar
A1B08 TEACHNOETRE’SS • Guide pupils to regroup from centimetre to metre. 6.1.2 53
• Emphasise that if the total units of centimetre exceeds 100, convert 100 cm
to 1 m.
SUBTRACTION OF LENGTH
1
Mount Murud, Sarawak Mount Ledang, Johor
2 423 m 1 276 m
What is the difference in height between Mount Murud
and Mount Ledang?
2 423 m – 1 276 m = m
11
3 1 13
2 423m
–1 276m
1 147m
2 423 m – 1 276 m = 1 147 m
The difference in height between Mount Murud
and Mount Ledang is 1 147 m.
2 How much longer is Perodua Bezza 364 cm
than Perodua Axia? Perodua Axia
415 cm – 364 cm = cm
3 11
4 1 5 cm
– 3 6 4 cm
5 1 cm
415 cm – 364 cm = 51 cm
Perodua Bezza is 51 cm longer 415 cm
Saiz sebentahran Perodua Axia. Perodua Bezza
54 TEACHNOETRE’SS • Use information about the height of buildings, distance of places, 6.1.3
depth of oceans or straits to find the differences.
3 Subtract 23 m 77 cm from 30 m 58 cm.
30 m 58 cm – 23 m 77 cm = m cm
2 9 15 8 58 cm cannot subtract 77 cm.
So, convert 1 m to 100 cm.
3 0 m 5 8 cm
– 2 3 m 7 7 cm 100 cm + 58 cm = 158 cm
6 m 8 1 cm
30 m 58 cm – 23 m 77 cm = 6 m 81 cm
4 6 m – 3 m 24 cm – 96 cm = cm
Convert 6 m to 600 cm.
Convert 3 m 24 cm to cm.
3 m 24 cm = 300 cm + 24 cm
= 324 cm
9 1 17 Discuss other methods
5 1010 to get the answer.
2 7 6 cm
6 0 0 cm – 9 6 cm
– 3 2 4 cm
1 8 0 cm
2 7 6 cm
6 m – 3 m 24 cm – 96 cm = 180 cm
LET’S TRY cm
1 Subtract.
a 421 m – 157 m = m b 930 cm – 485 cm =
c 13 m 78 cm – 6 m 90 cm = m cm
d 50 m – 24 m 70 cm – 89 cm = cm
2 Subtract 3 m 16 cm from 10 m. Give the answer in cm.
3 Find the difference between 90 m 5 cm and 72 m 80 cmS.aiz sebenar
A1B09 TEACHNOETRE’SS • Guide pupils to regroup from metre to centimetre. 6.1.3 55
• Carry out activities to compare the height or length between two objects
found in the classroom, and find the difference.
MULTIPLICATION OF LENGTH
1
A child's crash Malaysians are Keep your The seat belt in Red means
helmet is not an said to be polite. distance. the back seat is stop.
not a decoration.
accessory but Is it true?
a requirement. Use it.
15 m 15 m 15 m 15 m
What is the distance from the first pole to the fifth pole?
4 × 15 m = m
2
1 5m
×4
60m
4 × 15 m = 60 m
The distance from the first pole to the fifth pole is 60 m.
21 5 × 84 cm = cm Convert the answer
2 to m and cm. 4 m 20 cm.
8 4 cm 420 cm = 400 cm + 20 cm
×5 = (400 ÷ 100) m + 20 cm
4 2 0 cm = 4 m + 20 cm
= 4 m 20 cm
5 × 84 cm = 420 cm
Saiz sebenar TEACHNOETRE’SS • Do multiplication on units of length through simulation activities 6.1.4
or given pictures.
56
3
6 m 80 cm ?
a Find the length of a row of terrace houses.
6 × 6 m 80 cm = m cm
6 m 8 0 cm
×6
3 6 m 4 8 0 cm
+ 4 –400
4 0 m 8 0 cm
6 × 6 m 80 cm = 40 m 80 cm
The length of a row of terrace houses is 40 m 80 cm.
b 40 m 80 cm = cm
40 m 80 cm = 40 m + 80 cm
= (40 × 100 cm) + 80 cm
= 4 000 cm + 80 cm
= 4 080 cm
40 m 80 cm = 4 080 cm
LET’S TRY b 1 0 8 cm c 6 m 3 4 cm
×9 ×3
Multiply.
a 27m
×4
d 5 × 18 m = cm e 6 × 9 m 25 cm = m Scamiz sebenar
AB110 TEACHNOETRE’SS • Train pupils to multiply using repeated addition, number lines, 6.1.4
and times tables.
• Explain to pupils the method of regrouping centimetre to metre. 57
DIVISION OF LENGTH
1
The overall length of the coaches of a train is 14 m.
Find the length of one coach.
14 m ÷ 7 = m
2m Is the length of 2 m
7 14m the same as 200 cm?
–14
0
14 m ÷ 7 = 2 m
The length of one coach of a train is 2 m.
21 760 cm ÷ 4 = cm 3 Divide 1 040 cm by 5.
1 9 0 cm 1 040 cm ÷ 5 = cm
4 7 6 0 cm
–4 cm
5 1 0 4 0 cm
36
–36 What is the
answer?
00
–0
0
Saiz sebe7n6ar0 cm ÷ 4 = 190 cm
58 TEACHNOETRE’SS • Explain the concept of division involving length or distance through 6.1.5
simulation activities.
4 The length of a horse stable is
17 m 40 cm. What is the length
of each section of the stable?
17 m 40 cm ÷ 3 = m cm
5 m 8 0 cm 2 m is equal to 200 cm.
3 1 7 m 4 0 cm
17 m 40 cm ÷ 3 = 5 m 80 cm
–15 +200 The length of each section of the
2 240 horse stable is 5 m 80 cm.
–24
00
–0
0
5 960 cm ÷ 8 = m cm
1 2 0 cm 120 cm = 100 cm + 20 cm
8 9 6 0 cm = 1 m + 20 cm
–8 = 1 m 20 cm
16 960 cm ÷ 8 = 1 m 20 cm
–1 6
00
–0
0
LET’S TRY b 6 3 3 0 cm c 7 9 m 1 7 cm
1 Divide.
a 4 112m
d 31 m ÷ 5 = m cm e 864 cm ÷ 8 = m cm
2 Divide 2 m by 4. State the answer in cm. Saiz sebenar
AB111 TEACHNOETRE’SS • Remind pupils to convert the unit if the answer required is in a different unit 6.1.5
from the question.
59
• Use suitable situations in school to carry out simulation activities such as
multiplying and dividing length.
CONVERT UNITS OF MASS
1 This turnip is Please weigh two
and a half kilograms
4 kilograms.
of fish for me.
1 kg = 1 000 g
Half kg = 500 g
2 kg 500 g
4 kg
a Convert 4 kg to g.
4 kg = g To convert kg to g,
multiply by 1 000.
4 kg = 4 × 1 000 g
= 4 000 g
4 kg = 4 000 g
b State 2 kg 500 g in g.
2 kg 500 g = g
2 kg 500 g 2 kg = 2 000 g Convert 2 kg
to 2 000 g.
500 g
2 kg 500 g = 2 000 g + 500 g
= 2 500 g
Saiz sebena2r kg 500 g = 2 500 g
60 TEACHNOETRE’SS • State the relationship between kilogram and gram units through 6.2.1
simulation activities and using scales.
• Emphasise that pupils must convert kilogram to gram by multiplying
by 1 000.
2 What is the mass of a Rafflesia flower in kg? To convert g to kg,
divide by 1 000.
7 000 g = kg
7 000 g = (7 000 ÷ 1 000) kg
= 7 kg
7 000 g 7 000 g = 7 kg
The mass of a Rafflesia flower is 7 kg.
3 Convert the mass of an ostrich egg 4
to kg and g.
1 950 g
1 400 g = kg g What is the mass
1 400 g = 1 000 g + 400 g 1 400 g of this cake in
= 1 kg + 400 g kg and g?
= 1 kg 400 g
1 400 g = 1 kg 400 g
The mass of an ostrich egg
is 1 kg 400 g.
LET’S TRY
Convert the following units.
a b c
1 kg 1 kg SUGAR 2 000 g 1 325 g 1 325 g
kg kg g
2 000 g
g
d 6 kg 8 g = g e 9 010 g = kg gSaiz sebenar
AB112 TEACHNOETRE’SS • Emphasise to pupils that to convert gram to kilogram, divide by 1 000. 6.2.1
• Surf http://wwwhomeschoolmath.net/worksheets/measuring.php
61
ADDITION OF MASS
1 Calculate the total mass of the durians.
34 kg + 47 kg = kg
1
3 4 kg
+ 4 7 kg
8 1 kg
47 kg 34 kg + 47 kg = 81 kg
34 kg The total mass of the durians is 81 kg.
2 What is the total mass of the mangosteens?
28 kg + 19 kg + 7 kg = kg
2 28 kg
2 8 kg
1 9 kg
+ 7 kg
5 4 kg
28 kg + 19 kg + 7 kg = 54 kg 7 kg 19 kg
The total mass of the mangosteens is 54 kg.
Banana
Durian Chips
3 Calculate the total mass of Chips and .
685 g 975 g
685 g + 975 g = g Durian Banana
Chips Chips
11
685g
+ 975g 685 g 975 g
1 660g
State the answer
685 g + 975 g = 1 660 g in kg and g.
Durian Banana
Chips
The total mass of and is 1 660 g.Saiz sebenarChips
685 g 975 g
62 TEACHNOETRE’SS • Guide pupils to add units of mass based on situations and through 6.2.2
simulation activities.
• Explain that the addition of units of mass is the same as addition
of whole numbers.
4 Add 1 250 g, 786 g and 5 964 g. State the answer in kg.
1 250 g + 786 g + 5 964 g = kg 8 000 ÷ 1 000 = 8
2 21 8 000 g is
equal to 8 kg.
1 250g
786g
+5 964g
8 000g
1 250 g + 786 g + 5 964 g = 8 kg
5 2 kg 450 g + 1 kg 950 g + 2 kg 780 g = kg g
1 2 000 g is
equal to 2 kg.
2 kg 4 5 0 g
1 kg 9 5 0 g
+ 2 kg 7 8 0 g
5 kg 2 1 8 0 g
+2 –2 000
7 kg 1 8 0 g
2 kg 450 g + 1 kg 950 g + 2 kg 780 g = 7 kg 180 g
LET’S TRY
Add.
a 72 kg + 18 kg = kg b 435 g + 262 g = g
c 2 364 g + 75 g + 3 561 g = kg
d 30 kg 510 g + 920 g = kg g
e 6 kg 217 g + 1 kg 830 g + 2 kg 96 g = kg g Saiz sebenar
A1B13 TEACHNOETRE’SS • Guide pupils to regroup from gram to kilogram. 6.2.2
63
SUBTRACTION OF MASS
1
2 350 g
100 kg 66 kg
39 g
350 g
a Find the difference in b How much more is the
mass between mass of than the
and . mass of ?
100 kg – 66 kg = kg 2 350 g – 350 g = g
9 2 350g
0 1010 – 350g
1 0 0 kg 2 000g
– 6 6 kg
3 4 kg
100 kg – 66 kg = 34 kg 2 350 g – 350 g = 2 000 g
The difference in mass The mass of is 2 000 g
between and more than the mass of .
is 34 kg.
Saiz sebenar TEACHNOETRE’SS How much less is the mass 6.2.3
of than the mass of ?
64
• In groups, carry out activities of subtracting units of mass based on situations
given using question cards.
• Train pupils to compare mass between objects and find the difference.
2 7 kg 90 g – 5 kg 780 g = kg g
0 10
6 1 0 90
7 kg 9 0 g
– 5 kg 7 8 0 g
1 kg 3 1 0 g
7 kg 90 g – 5 kg 780 g = 1 kg 310 g
3 8 kg 62 g – 2 350 g = 2 350 g = 2 kg 350 g
8 kg 62 g = 8 000 g + 62 g 8 kg 6 2 g
= 8 062 g – 2 kg 3 5 0 g
7 10 6 kg 3 1 2 g
8 062g
–2 350g
5 712g
Which answer is correct? Why?
100g 20g
100g 50g
MMIINNDD The mass of may be g.
CCHHAALLLLEENNGGEE
LET’S TRY
1 Subtract.
a 102 kg – 47 kg = kg b 3 150 g – 765 g = g
c 15 kg 650 g – 9 kg 340 g = kg g
d 30 kg 8 g – 19 kg 632 g = g
2 Find the difference between 8 kg 100 g and 7 kg 550 g.
3 Subtract 4 201 g from 9 kg 60 g. Saiz sebenar
AB114 TEACHNOETRE’SS • Guide pupils to regroup from kilogram to gram. Explain how to subtract 6.2.3 65
according to the concept of kilogram and gram units, or according to place
value.
MULTIPLICATION OF MASS
1
RICE
OATS 15 kg STRAWBERRY
JAM
1 250 g
482 g
a Calculate the mass of b What is the mass of 7 jars
8 similar packets of rice. of strawberry jam?
8 × 15 kg = kg 7 × 482 g = g
4 51
1 5 kg 482g
×8 ×7
1 2 0 kg 3 374g
8 × 15 kg = 120 kg 7 × 482 g = 3 374 g
The mass of 8 similar The mass of 7 jars of
packets of rice is 120 kg. strawberry jam is 3 374 g.
c Calculate the mass of 4 packets of oats.
4 × 1 250 g = kg 5 000 g = ? kg
5 kg 5 000 ÷ 1 000 = 5
12
Convert 5 000 g
1 250g to kg.
×4
5 000g
4 × 1 250 g = 5 kg
Saiz sebenar The mass of 4 packets of oats is 5 kg.
66 TEACHNOETRE’SS • Multiply units of mass through simulation activities or based on 6.2.4
the situation given.
• Multiply using repeated addition, number lines, or times tables.
2 9 × 2 kg 300 g = kg g
2 kg 3 0 0 g Why do we subtract
×9 2 000 g and add 2 kg?
1 8 kg 2 7 0 0 g Explain.
+ 2 –2 000
2 0 kg 7 0 0 g
9 × 2 kg 300 g = 20 kg 700 g
3 3 × 3 kg 172 g = g 2
Convert 3 kg 172 g to g. 3 1 72 g
3 kg 172 g = (3 × 1 000 g) + 172 g ×3
= 3 000 g + 172 g 9 516 g
= 3 172 g
3 × 3 kg 172 g = 9 516 g
Which weights 350 g ?
are suitable to 350 g
MMIINNDD be placed on 350 g 1 kg 500 g 200g 100g 50 g
CCHHAALLLLEENNGGEE the scales?
LET’S TRY b 583g c 1 094g
×5 ×3
Multiply.
a 2 6 kg
×4
d 5 × 2 000 g = kg e 6 × 4 kg 129 g = kg g
f 9 × 1 kg 108 g = g g 7 × 1 050 g = kg Sgaiz sebenar
AB115 TEACHNOETRE’SS • Focus on how to regroup from gram to kilogram. 6.2.4
67
DIVISION OF MASS
1 Calculate the mass of a packet of green peas.
15 kg
15 kg ÷ 5 = kg
3 kg
5 1 5 kg
–15
0
15 kg ÷ 5 = 3 kg
The mass of a packet of green peas
is 3 kg.
2 What is the mass of anchovies 1 5 0 g
600 g
in each bowl? 4 600g
600 g ÷ 4 = g –4
20
600 g ÷ 4 = 150 g –20
00
The mass of anchovies in –0
each bowl is 150 g. 0
3 Calculate the mass of 625g
Saiz sebenar 5 kg a packet of mussels. 8 5 000g
5 kg ÷ 8 = g –4 8
68
20
–16
5 kg ÷ 8 = 625 g 40
The mass of a packet –40
of mussels is 625 g. 0
TEACHNOETRE’SS • Explain the concept of division involving mass by doing simulation 6.2.5
activities.
• Discuss nett mass, which means the mass of an item without the mass of
its container.
4 30 kg 612 g ÷ 3 = kg g
1 0 kg 2 0 4 g Try to divide 30 kg 612 g by 6.
3 3 0 kg 6 1 2 g What is the answer?
–30 –6 30 kg 612 g ÷ 3 = 10 kg 204 g
0 01
–0
12
–12
0
5 8 kg 400 g ÷ 7 = kg g
1 kg 2 0 0 g
7 8 kg 4 0 0 g Convert 1 kg to 1 000 g.
–7 +1 000 1 000 g + 400 g = 1 400 g
1 1 400
–1 4
00
–0
00
–0
0 8 kg 400 g ÷ 7 = 1 kg 200 g
8 400 g ÷ 7 = Does this question give
the same answer?
Discuss.
LET’S TRY b 6 780g c 3 9 kg 2 1 0 g
Divide.
a 4 3 2 kg
d 45 kg ÷ 5 = g e 25 kg 200 g ÷ 7 = kg Saiz sgebenar
AB116 TEACHNOETRE’SS • Remind pupils to convert the unit if the answer required is in a different 6.2.5 69
unit from the question.
• Provide more questions in various forms such as number sentences,
vertical forms, and situations.
CONVERT UNITS OF VOLUME OF LIQUID
1 This date milk
is 1 litre.
1ℓ 1ℓ
1 ℓ = 1 000 mℓ
1 litre equals
1 000 millilitres.
2 What is the volume of coconut water in mℓ?
2 ℓ = mℓ
2 ℓ = 2 × 1 000 mℓ To convert ℓ to mℓ,
= 2 000 mℓ multiply by 1 000.
2 ℓ = 2 000 mℓ
2 ℓ The volume of coconut water is 2 000 mℓ.
3 Convert 4 ℓ 360 mℓ to mℓ.
4 ℓ 360 mℓ = mℓ Try to convert
5 ℓ 93 mℓ to mℓ.
4 ℓ 360 mℓ = 4 ℓ + 360 mℓ
= 4 000 mℓ + 360 mℓ
= 4 360 mℓ
Saiz sebe4naℓr 360 mℓ = 4 360 mℓ
70 TEACHNOETRE’SS • State the relationship between the units of litre and millilitre by simulation 6.3.1
activities and using measuring tools.
• Make a scrapbook about the volume of liquid using sales brochures.
4 What is the volume of water in ℓ? To convert mℓ to ℓ,
8 000 mℓ = ℓ divide by 1 000.
8 000 mℓ = (8 000 ÷ 1 000) ℓ
=8ℓ
8 000 mℓ = 8 ℓ
The volume of water is 8 ℓ.
8 000 mℓ
5 Convert the volume of fabric softener to ℓ and mℓ.
2 350 mℓ = ℓ mℓ
2 350 mℓ 2 000 mℓ = 2 ℓ SFoaftbernicer
350 mℓ
2 350 mℓ = 2 ℓ + 350 mℓ 2 350 mℓ
= 2 ℓ 350 mℓ
2 350 mℓ = 2 ℓ 350 mℓ
The volume of fabric softener is 2 ℓ 350 mℓ.
LET’S TRY
Convert the following units.
a 3 ℓ = mℓ b 10 ℓ = mℓ
c 5 000 mℓ = ℓ d 9 000 mℓ = ℓ
e 1 ℓ 940 mℓ = mℓ f 7 ℓ 50 mℓ = mℓ
g 2 ℓ 3 mℓ = mℓ h 4 ℓ 68 mℓ = mℓ
i 6 150 mℓ = ℓ mℓ j 3 070 mℓ = ℓ Samizℓsebenar
AB117 TEACHNOETRE’SS • Emphasise that to convert litre to millilitre, multiply by 1 000, and to convert 6.3.1 71
millilitre to litre, divide by 1 000.
ADDITION OF VOLUME OF LIQUID
1 What is the total volume of water in the barrel?
35 ℓ + 9 ℓ = ℓ I pour another
9 ℓ of water.
1
35ℓ
+ 9ℓ
44ℓ
35 ℓ + 9 ℓ = 44 ℓ 35 ℓ
The total volume of water
in the barrel is 44 ℓ.
2 12 ℓ + 30 ℓ + 8 ℓ = ℓ 3 670 mℓ + 340 mℓ = mℓ
1 1
1 2ℓ 6 7 0 mℓ
30ℓ + 3 4 0 mℓ
+ 8ℓ
50ℓ 1 0 1 0 mℓ
12 ℓ + 30 ℓ + 8 ℓ = 50 ℓ 670 mℓ + 340 mℓ = 1 010 mℓ
State 1 010 mℓ
in ℓ and mℓ.
MMIINNDD How much water, in mℓ,
CCHHAALLLLEENNGGEE should be added to the
beaker to make it 2 ℓ?
Saiz sebenar TEACHNOETRE’SS • Guide pupils to add volume of liquids based on situations 6.3.2
and simulation activities.
72
4 Calculate the total volume of drinks. ℓ 3 850 mℓ 4 120 mℓ 2 030 mℓ
3 850 mℓ + 4 120 mℓ + 2 030 mℓ = Bandung Corn Sugarcane
drink drink juice
11
3 8 5 0 mℓ
4 1 2 0 mℓ
+ 2 0 3 0 mℓ
1 0 0 0 0 mℓ
(10 000 ÷ 1 000) ℓ = 10 ℓ
3 850 mℓ + 4 120 mℓ + 2 030 mℓ = 10 ℓ
The total volume of drinks is 10 ℓ.
5 5 ℓ 720 mℓ + 2 ℓ 80 mℓ + 980 mℓ = ℓ mℓ
1
5 ℓ 7 2 0 mℓ
2 ℓ 8 0 mℓ
+ 9 8 0 mℓ
7 ℓ 1 7 8 0 mℓ
+1 –1 000
8 ℓ 7 8 0 mℓ
5 ℓ 720 mℓ + 2 ℓ 80 mℓ + 980 mℓ = 8 ℓ 780 mℓ
LET’S TRY
1 Add.
a 67 ℓ + 25 ℓ = ℓ b 38 ℓ + 9 ℓ + 27 ℓ = ℓ
c 304 mℓ + 961 mℓ = mℓ
d 1 055 mℓ + 3 498 mℓ + 447 mℓ = ℓ
e 6 ℓ 730 mℓ + 9 ℓ 407 mℓ = ℓ mℓ
2 Total up 5 ℓ 50 mℓ and 2 750 mℓ. State the answer in mℓS.aiz sebenar
AB TEACHNOETRE’SS • Guide pupils to regroup from millilitre to litre in addition. 6.3.2 73
118 • Provide more of exercises in various forms, such as number sentences,
vertical forms, and situations.
SUBTRACTION OF VOLUME OF LIQUID
1 Find the difference between the two volumes of petrol below.
85 ℓ – 47 ℓ = ℓ
7 15 85 ℓ 47 ℓ
85ℓ
–47ℓ
38ℓ
85 ℓ – 47 ℓ = 38 ℓ
The difference between the two volumes of petrol is 38 ℓ.
2 How much more is the volume of sunflower oil than olive oil?
3 500 mℓ – 1 250 mℓ = mℓ
4 10 SUNOFLILOWER OLIVE
OIL
3 5 0 0 mℓ 3 500 mℓ
– 1 2 5 0 mℓ 1250 mℓ
2 2 5 0 mℓ
3 500 mℓ – 1 250 mℓ = 2 250 mℓ
The volume of sunflower oil is 2 250 mℓ more than olive oil.
3 9 ℓ 480 mℓ – 2 ℓ 760 mℓ = ℓ mℓ
0 14
8 1 480
9 ℓ 4 8 0 mℓ
– 2 ℓ 7 6 0 mℓ
6 ℓ 7 2 0 mℓ
Saiz sebe9naℓr 480 mℓ – 2 ℓ 760 mℓ = 6 ℓ 720 mℓ
74 TEACHNOETRE’SS • Train pupils with mechanical questions in simple form using vocabulary 6.3.3
that means subtract.
10 ℓ
4 What is the remaining volume of water in the
big bottle after the small bottle is filled?
10 ℓ – 4 095 mℓ = mℓ
9 99 4 095 mℓ
0 10 101010
1 0 0 0 0 mℓ
– 4 0 9 5 mℓ
5 9 0 5 mℓ
10 ℓ – 4 095 mℓ = 5 905 mℓ
The remaining volume of water in the big bottle is 5 905 mℓ.
5 5 ℓ 200 mℓ – 1 680 mℓ = ℓ mℓ
11 What is the balance if
0 1 10 3 ℓ 520 mℓ is subtracted
4 1200
from 5 ℓ 200 mℓ?
5 ℓ 2 0 0 mℓ
– 1 ℓ 6 8 0 mℓ
3 ℓ 5 2 0 mℓ
5 ℓ 200 mℓ – 1 680 mℓ = 3 ℓ 520 mℓ
LET’S TRY
Subtract. ℓ b 1 100 mℓ – 480 mℓ = mℓ
a 90 ℓ – 36 ℓ =
c 71 ℓ – 64 ℓ = mℓ d 8 ℓ – 3 ℓ 150 mℓ = mℓ
e 9 ℓ 750 mℓ – 4 ℓ 10 mℓ = ℓ mℓ
f 5 ℓ 620 mℓ – 2 ℓ 700 mℓ = ℓ mℓ
g 6 ℓ 30 mℓ – 5 640 mℓ = mℓ
h 10 ℓ – 8 920 mℓ = ℓ mℓ Saiz sebenar
AB119 TEACHNOETRE’SS • Remind pupils to convert the unit if the answer required is in a different 6.3.3 75
unit from the question.
MULTIPLICATION OF VOLUME OF LIQUID
1 What is the volume of 6 similar bottles
of fresh milk?
6×2ℓ= ℓ
2ℓ MILK
×6
2ℓ
12ℓ
6 × 2 ℓ = 12 ℓ
The volume of 6 similar bottles of fresh milk is 12 ℓ.
2 4 × 250 mℓ = mℓ
2 OJruaincgee OJruaincgee OJruaincgee OJruaincgee
2 5 0 mℓ 250 mℓ 250 mℓ 250 mℓ 250 mℓ
×4
1 0 0 0 mℓ
4 × 250 mℓ = 1 000 mℓ
3 3 × 3 ℓ 120 mℓ = ℓ mℓ
3 ℓ 1 2 0 mℓ What is 9 ℓ 360 mℓ in mℓ ?
×3
9 ℓ 3 6 0 mℓ
3 × 3 ℓ 120 mℓ = 9 ℓ 360 mℓ
Saiz sebenar TEACHNOETRE’SS • Train pupils to multiply volume of liquids by using repeated addition or 6.3.4
times tables.
76
4 Find the volume of 7 similar bottles of shampoo.
7 × 650 mℓ = ℓ mℓ SHAMPOO
3 4 550 mℓ = 4 000 mℓ + 550 mℓ 650 mℓ
= 4 ℓ + 550 mℓ
6 5 0 mℓ
×7 = 4 ℓ 550 mℓ
4 5 5 0 mℓ
7 × 650 mℓ = 4 ℓ 550 mℓ
The volume of 7 similar bottles of shampoo is 4 ℓ 550 mℓ.
5 8 × 2 ℓ 450 mℓ = ℓ mℓ
4 3 000 mℓ
equals 3 ℓ.
2 ℓ 4 5 0 mℓ
×8
1 6 ℓ 3 6 0 0 mℓ
+ 3 –3 000
1 9 ℓ 6 0 0 mℓ
8 × 2 ℓ 450 mℓ = 19 ℓ 600 mℓ
1 ℓ 200 mℓ SHAMPOO Try calculating the
1 ℓ 200 mℓ volume of these
5 bottles of shampoo.
Give the answer in ℓ.
LET’S TRY
Multiply.
a 4 × 12 ℓ = ℓ b 3 × 750 mℓ = mℓ
ℓ mℓ
c 2 × 4 ℓ 500 mℓ = ℓ d 6 × 925 mℓ =
e 7 × 1 ℓ 420 mℓ = ℓ mℓ
f 9 × 2 ℓ 400 mℓ = ℓ mℓ Saiz sebenar
A1B20 TEACHNOETRE’SS • Carry out multiplication of volume of liquid using pictures from sales 6.3.4 77
brochures to enhance pupils’ understanding.
DIVISION OF VOLUME OF LIQUID
1 What is the volume of 24 ℓ of water is
water in each pail? filled equally in
24 ℓ ÷ 3 = ℓ 3 pails.
24 ℓ
8ℓ
3 24ℓ
–24
0
24 ℓ ÷ 3 = 8 ℓ
The volume of water in each pail is 8 ℓ.
2 900 mℓ ÷ 2 = mℓ 3 1 ℓ 20 mℓ ÷ 6 = mℓ
4 5 0 mℓ 1 ℓ 20 mℓ = 1 000 mℓ + 20 mℓ
2 9 0 0 mℓ = 1 020 mℓ
–8
1 7 0 mℓ
10 6 1 0 2 0 mℓ
–1 0 –6
00 42
–0 –42
0 00
–0
900 mℓ ÷ 2 = 450 mℓ
0
If 900 mℓ of glue is filled
equally in 4 bottles, what 1 ℓ 20 mℓ ÷ 6 = 170 mℓ
is the volume of glue
in each bottle?
Saiz sebenar TEACHNOETRE’SS • Carry out simulation activities using graduated containers. 6.3.5
78
4 7 ℓ 500 mℓ ÷ 5 = ℓ mℓ 5 11 ℓ ÷ 8 = ℓ mℓ
1 ℓ 5 0 0 mℓ 1 ℓ 3 7 5 mℓ
5 7 ℓ 5 0 0 mℓ
8 11 ℓ 0 mℓ
–5 +2 000
2 2 500 – 8 +3 000
–2 5
00 3 3 000
–0
00 –2 4
–0
0 60
7 ℓ 500 mℓ ÷ 5 = 1 ℓ 500 mℓ –56
A watermelon with a 40
mass of 4 kg has an
estimated 3 600 mℓ –40
volume of water.
MMIINNDD What is the estimated 0
CCHHAALLLLEENNGGEE volume of water
in a watermelon 11 ℓ ÷ 8 = 1 ℓ 375 mℓ
with a mass of 1 kg?
Discuss other
methods to find
the answer.
LET’S TRY mℓ b 840 mℓ ÷ 3 = mℓ
ℓ mℓ d 9 ℓ 120 mℓ ÷ 6 = ℓ mℓ
1 Divide. f 6 ℓ ÷ 8 = mℓ
a 32 ℓ ÷ 4 = ℓ
c 1 ℓ 10 mℓ ÷ 5 =
e 9 ℓ 240 mℓ ÷ 7 =
2 Divide 9 873 mℓ by 9. State the answer in ℓ and mℓ. Saiz sebenar
AB121 TEACHNOETRE’SS • In groups, carry out quizzes orally or in writing. 6.3.5
79
CREATE STORIES
1 15 m + 28 m = 43 m
Aishah bought 15 m of white cloth and
28 m of printed cloth to make curtains.
The total length of cloth is 43 m.
21 3 × 250 g = 750 g
Mother uses 3 blocks of butter to make
biscuits. The mass of a block of butter is
250 g. The total mass of the butter used
is .
31 1 ℓ 200 mℓ ÷ 4 = 300 mℓ
1 ℓ 200 mℓ The volume of sugarcane juice in a jug
is ℓ mℓ. The sugarcane juice
is poured equally into glasses.
Each glass is filled with mℓ of
sugarcane juice.
LET’S TRY b 8 × 625 mℓ = 5 000 mℓ
Create stories.
a 2 m 70 cm – 1 m 65 cm = 1 m 5 cm
c 4 kg 750 g + 1 kg 250 g = 6 kg d 13 ℓ 500 mℓ ÷ 9 = 1 ℓ 500 mℓ
Saiz sebenar
80 12A2B-123 TEACHNOETRE’SS • Guide pupils to create stories based on the number sentences using daily 6.4.1
situations.
• Carry out a story creating competition. Interesting stories with appropriate
pictures will be presented to the class.
SOLVE THE PROBLEMS 235 cm
84 cm
1 The picture shows the length of blue ribbon
and red ribbon that Anis uses to make ribbon
flowers. Calculate the total length of ribbons
used, in m and cm.
Given 235 cm of red ribbon, 84 cm of blue ribbon
Find the total length of ribbons used in m and cm
Method 235 cm + 84 cm = m cm
1 319 cm 300 cm = 3 m
19 cm
2 3 5 cm
+ 8 4 cm 391 cm = 3 m 19 cm
3 1 9 cm
235 cm + 84 cm = 3 m 19 cm
The total length of ribbons used is 3 m 19 cm.
2 Lily’s mass is 32 kg. Her mass is 3 kg more than Akmal’s
mass. What is Akmal’s mass?
32 kg
Method Lily’s mass
Akmal’s mass 3 kg
?
32 kg – 3 kg = kg
2 12 Akmal’s mass is 29 kg. Saiz sebenar
3 2 kg
– 3 kg
2 9 kg
TEACHNOETRE’SS • Guide pupils to solve problems by drawing diagrams. 6.4.2
81
3 Tini prepared two different drinks as shown in the table below.
Drink Volume a Calculate the volume of the
bandung drink in ℓ.
Barley 3 ℓ 400 mℓ
b Tini poured the bandung drink
Bandung 5 times the volume into 8 jugs. What is the volume,
in ℓ and mℓ, of the bandung
drink of barley drink drink in ℓ jug?
a Method 5 × 3 ℓ 400 mℓ = ℓ
3ℓ 4 0 0 mℓ I check by
× 5 repeated addition.
1 5 ℓ 2 0 0 0 mℓ 5 × 3 ℓ 400 mℓ = 17 ℓ
+ 2 –2 000 The volume of bandung
drink is 17 ℓ.
1 7 ℓ 0 mℓ
b Method 17 ℓ ÷ 8 = ℓ mℓ
2 ℓ 1 2 5 mℓ
8 17 ℓ 0 mℓ
– 16 + 1 0 0 0
1 1 000
–8
20
–16
40
–40
0
17 ℓ ÷ 8 = 2 ℓ 125 mℓ
Saiz sebenar The volume of bandung drink in 1 jug is 2 ℓ 125 mℓ.
82 12A4B-126 TEACHNOETRE’SS • Train pupils to solve daily problems involving addition, subtraction, 6.4.2
multiplication, and division using various suitable strategies.
LET’S TRY Fruit Mass
Pineapple 983 g
Solve the problems. Jackfruit 4 kg 450 g
a i. Calculate the total mass of the
pineapple and jackfruit.
ii. How much more is the mass of
the jackfruit than pineapple?
b Lina made 2 ℓ 520 mℓ of cocoa drink. She poured the drink
equally into 8 cups. Calculate the volume, in mℓ, of the cocoa
drink in each cup.
c The length of The length of this
this yellow hose green hose is
is 1 m 35 cm. 4 times the length
of the yellow hose.
i. State the length of the yellow hose in cm.
ii. What is the length, in m and cm, of the green hose?
FUN PROJECT
Tools/Materials Method
pictures from sales 1 Paste pictures related to length,
brochures and the mass, and volume of liquids.
Internet, glue,
coloured paper, 2 Create questions involving
pen, scissors addition, subtraction,
multiplication, and division.
Participants 3 Decorate the scrapbook.
3 pupils per group 4 Present your group’s workS.aiz sebenar
TEACHNOETRE’SS • Provide exercises in worksheets and question cards. 6.4.2 83
• Guide pupils to form questions from pictures chosen in the Fun Project.
FUN TIME
Let’s sing together. Find the answers.
If you’re ready and you’re smart look at the board 2 m 5 cm
Let’s think carefully and try to work it out = 205 cm
Two hundred and five, I figure it out
Yes that’s the answer, say it loud.
If you’re ready and you’re smart let’s count together
It’s so easy come on let’s all remember 32 cm
Thirty-two, yes it’s true 8 256 cm
That’s the answer, yes it’s true
Now I need you to answer my questions, too.
Answer 1 125ℓ 2 4 × 70 g = g
my – 43ℓ
questions. ℓ
3 1 380 cm + 920 cm = m
Saiz sebenar SCAN THIS 6.1
6.2
84 1A27B-128 TEACHNOETRE’SS • Sing the song to the melody of “If You Are Happy and You Know It”. 6.3
• Guide pupils to answer the questions.
• Teachers are encouraged to add other questions.
SHAPES
RECOGNISE PRISMS AND NON-PRISMS
1 Ladies and gentlemen,
on this triangular prism
is Onyet!
Wow! The elephant is
dancing on a cube.
A cube is a square prism.
The clown is standing
on a cuboid.
TEACHNOETRE’SS • Guide pupils to relate real objects with 3-D shapes to learn more about Saiz sebenar
square prisms, rectangular prisms, and triangular prisms.
7.1.1
85
21 a I am a cube. You
can also call me
square prism. vertex SQUARE
flat PRISM
surface
✿ 6 flat surfaces
edge of equal size
✿ 8 vertices
✿ 12 edges
base
b I am a cuboid or
rectangular prism.
flat surface vertex RECTANGULAR
PRISM
edge ✿ 6 flat surfaces
✿ 8 vertices
✿ edges
SCAN THIS base
c I am a vertex TRIANGULAR
flat surface PRISM
triangular prism.
✿ flat surfaces
edge ✿ vertices
✿ 9 edges
base
Talk about the same characteristics in prisms.
Saiz sebenar
86 12A9B-130 TEACHNOETRE’SS • Ask pupils to name objects around them that have the characteristics of 7.1.1
prisms. 7.1.2
• Emphasise that a prism is named based on the same shape of the two
opposite surfaces.
3 When a prism is
cut, it still has the
same shape.
SCAN THIS
A PRISM:
✿ has 5 or more flat surfaces.
✿ has 2 opposite surfaces of the same shape and size,
each called the base.
✿ has no curved surfaces.
4 A pyramid has vertices, All of these
edges, and flat surfaces. shapes are
These sphere, non-prisms.
cone, and
cylinder shapes
have curved
surfaces.
Sphere Cylinder Pyramid Cone
Let’s see why these four shapes are non-prisms.
Characteristics 5 or 2 opposite no curved
of prism more flat surfaces of surfaces
surfaces the same
Shape shape (base)
Sphere ✗✗ ✗
Cone ✗✗ ✗
Pyramid ✓✗ ✓
Cylinder ✗✓ S✗aiz sebenar
A1B31 TEACHNOETRE’SS • Carry out activities of cutting objects like cuboid-shaped cakes, polystyrene 7.2.1
in the shape of triangular prisms, and cube-shaped sponges to look at two
opposite surfaces of equal shape (cross-section). 87
FUN PROJECT
Build a mind map or chart as given below:
triangular pyramid
prism non-prism
square prism SHAPE cone
prism cylinder
rectangular sphere
prism
Below are nets of three-dimensional shapes.
MMIINNDD Jeny joins the prism net together.
CCHHAALLLLEENNGGEE Liza joins the non-prism net together.
Name the shapes that Jeny and Liza form.
LET’S TRY c
Name the prisms below.
ab
Saiz sebenar
88 TEACHNOETRE’SS • Prepare suitable mind maps and pictures of prisms and non-prisms. 7.2.1
Ask pupils to paste prism and non-prism shapes on the mind map.
BA 2
RECOGNISE REGULAR POLYGONS
1 A regular polygon
is a two-dimensional
shape.
pentagon
5 straight sides
regular
polygon
hexagon octagon
6 straight sides 8 straight sides
heptagon
7 straight sides
REGULAR POLYGON
✿ has 3 or more straight sides of equal length.
✿ has 1 flat surface.
✿ has no curved sides.
AD Which diagram
is a regular
B
CE polygon? Why?
Saiz sebenar
TEACHNOETRE’SS • Explain that regular polygons must have straight sides of equal length. 7.3.1
Polygons with sides of unequal lengths are irregular polygons.
• Use geoboards and dotted paper to build regular polygons and then 89
name them.
2 a A pentagon has 5 corners. A hexagon has
6 corners and 6 sides.
It also has 5 sides.
pentagon corner hexagon
straight
side
flat surface
b heptagon c octagon If the base
corners corners of this prism
straight straight is traced out,
sides sides what shape is
formed?
Which regular polygon is formed
MMIINNDD when the six triangles above are
CCHHAALLLLEENNGGEE combined together?
LET’S TRY
Name the polygons that have the following characteristics.
a 6 corners b 8 corners c 7 straight sides
6 straight sides 8 straight sides 7 corners
Saiz sebenar
90 13A2B-133TEACHNOETRE’SS • Carry out activities to build polygon frames using matchsticks and straws. 7.3.1
• Carry out quizzes to identify polygons based on pictures of situations.
CREATE PATTERNS
1 I want to make patterns This is a flower pattern.
from these pentagons. I used 6 pentagons.
2 We made fish
and butterfly
We pasted
colourful polygons. patterns.
What is the LET’S TRY
shape used in
this pattern? Try and make your
favourite pattern.
Saiz sebenar
AB 155 TEACHNOETRE’SS • Carry out a contest to make patterns based on pupils’ creativity. 7.3.2
134,
91
AXIS OF SYMMETRY
1 If this picture is folded along This blue line is called
the axis of symmetry.
the blue line, both parts will
overlap each other exactly.
AXIS OF
SYMMETRY
A straight line
that divides
any shape or
diagram into
two equal parts
of the same
shape and size.
2 This picture
of a house
has 1 axis of
symmetry.
Regular pentagon has 5
axes of symmetry because
there are 5 straight sides.
Look at the picture.
Is the blue line an
axis of symmetry?
Saiz sebenar • Emphasise that the axis of symmetry occurs with three-dimensional and
two-dimensional shapes. Discuss the axes of symmetry of heptagon
A1B35 TEACHNOETRE’SS and octagon. 7.4.1
92 • Carry out activities to explore the axis of symmetry using various shapes
inside and outside the classroom.
FUN PROJECT
Tools/Materials paper shirt,
pen, ruler
Method
1 Fold the paper shirt until one part
overlaps exactly on the other part.
2
Unfold the paper shirt. Draw
a line along the fold.
3 Label the axis of symmetry.
Axis of symmetry
LET’S TRY
How many axes of symmetry do these shapes have?
ab cd
TEACHNOETRE’SS • Guide pupils to explore axes of symmetry by drawing lines of symmetry Saiz sebenar
on picture cards of various shapes, by folding and cutting paper, as well as
using MS Word. 7.4.1
• Modify and use various materials or objects to find axes of symmetry. 93
SOLVE THE PROBLEMS
1 Puan Salina sticks three pictures on the Which one is a prism?
whiteboard. She asks Azian to choose
a picture of a prism. Which picture
is chosen by Azian? Why?
Given pictures of a cone, cuboid, and sphere
Find picture of a prism
Method make a checklist table
Characteristics 5 or 2 opposite no curved
of prism more flat surfaces of the surfaces
surfaces same shape
Shape (base)
Cone ✗✗✗
Cuboid ✓✓✓
Sphere ✗✗✗
A cuboid is a rectangular prism.
Azian chooses because it has 6 flat surfaces,
its opposite surfaces are of the same shape,
and it has no curved surfaces.
2 Wong cuts a shape. It has 2 corners more than a
pentagon. What is the shape?
Method trial and error 1 trial and error 2
hexagon heptagon
6 corners, 1 corner more 7 corners, 2 corners
than a pentagon more than a pentagon
NO
YES
Saiz sebenar The name of the shape is heptagon.
94 TEACHNOETRE’SS • Give more problem-solving questions using checklist tables or trial and error 7.5.1
method to reinforce pupils’ understanding.
3 Chin has three picture cards.
He asks Zaki to select a picture card that has more
than one axis of symmetry. Which picture card does
Zaki take?
Method draw axis of symmetry
1 axis of symmetry 2 axes of symmetry
1 axis of symmetry
Zaki takes the picture card of a handkerchief.
LET’S TRY
Solve the problem.
Jaslina has three flash cards.
She chooses a regular polygon card.
Which card has she chosen?
Give your reasons.
A1B36 TEACHNOETRE’SS • Encourage pupils to explore other ways to determine axis of symmetry Saiz sebenar
such as folding picture cards.
• Emphasise that there are shapes that have more than one axis of symmetry. 7.5.1
95