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PEPERIKSAAAN PERTENGAHAN TAHUN

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Published by Stemza Cemerlang, 2018-05-21 21:28:11

SKEMA MATEMATIK TING 4

PEPERIKSAAAN PERTENGAHAN TAHUN

SKEMAMATEMATIKTINGKATAN4
PEPERIKSAANPERTENGAHANTAHUN2018

BAHAGIANA

1. (b)
(a)

1(a):2m
1(b):2m

2. 4p²+5p–6=0 1m
(4p–3)(p+2)=0 1m
2m
p=43danp=-2
1m
3. 4p²+11p–108=0 1m
(4p+27)(p-4)=0 2m

p=-247danp=4

4. x=2-y 1m
4y–(2–y)=18 1m
4y–2+y=18
5y=20 1m
y=4 1m
x=2-4
x=-2 1m

5. 6 1m
3(a)MRS=MPQ=-( )=-2 1m

y=-2x+c 1m
10=-2(6)+c 1m
c=22
y=-2x+22

(b)pintasan-x;y=0
-2x+22=0
-2x=-22
x=11;pintasan-x=11

6. (a)atau 1m
(b)x²+5≠21 1m
(c)8n–17,n=1,2,3,4,…. 2m

7. (a)i)palsu 1m
ii)palsu 1m
1m
(b)Implikasi1:Jika(-T)3=-125,makaT=-5 1m
Implikasi2:JikaT=-5,maka(-T)3=-125 1m

(c)PQRSTmempunyai5sisi 1m

8. (a)OPR+PQR 1m
1m
(12x14x14)+(327600x272x142)
1m
98+462
560 1m
1m
(b)PO+ONR+PQR

180 22 270 22
14+(360x2x 7 X7)+ (360x2X 7 x14)

14+22+66
102

9. Isipadusilinder–isipadukon 2m

(272x72x27)- [13x272x72x(13x27)] 1m
1m
4158-462
3696 1m
1m
BAHAGIANB 1m
10. (a)38 1m
1m
-6 2m
-2 Beri1m
24 1m
(b)paksi-x;-5≤x≤3danpaksi-y;-6≤y≤64
Semuatitikdiplotdenganbetul 1m
7-8titikdiplotdenganbetul 1m
Grafdilukisdenganlancar 1m

(c)i)19(18≤y≤20) 1m
ii)2.2(2.0≤x≤2.3) 1m
-2.45(-2.5≤x≤ -2.3)

(d)y=20x+40
x=-1.85(-1.95≤x≤ -1.75)



11. (a)2m
(b)2m

(c)i)(-1,9) 2m
ii)(5,9) 2m

12 (a) 1m
1m
Selangkelas kekerapan Titik 1m
tengah
8-10 5
11-13 7 9
14–16 11 12
17–19 5 15
20–22 9 18
23-25 3 21
24

(b) 2m

(5x9)+(7x12)+(11x15)+(5x18)+(9x21)+(3x24)
40

16.125 1m

(c)paksi-xdanpaksi-ydilukisdenganskalayangbetul 1m
Semuatitikdiplotdenganbetul 2m
4-5titikdiplotdenganbetul Beri1m
Grafdilukisdenganlancar 1m

`13 (a) Jarak kekerapan Titik
tengah
4.0–4.4 3 1m
4.5–4.9 4 4.2 2m
5.0–5.4 6 4.7 1m
5.5–5.9 8 5.2
6.0–6.4 10 5.7
6.5–6.9 6 6.2
7.0–7.4 3 6.7
7.2

(b)i)6.0–6.4 1m

ii) 2m

(3x4.2)+(4x4.7)+(6x5.2)+(8x5.7)+(10x6.2)+(6x6.7)+(3x7.2)
40

5.8 1m

(c)paksi-xdanpaksi-ydilukisdenganskalayangbetul 1m
Semuatitikdiplotdenganbetul 2m
5-6titikdiplotdenganbetul Beri1m
Grafdilukisdenganlancar 1m


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