BIO K3

★★ Modul Pintas Tingkatan 5
Peperiksaan Percubaan SPM 2018
Skema Jawapan Biologi
Kertas 3 4551/3

Question 1

No Mark Scheme Score
1 (a) KB0603 – Measuring Using Number 3

Able to record all 6 readings for the number of tortoises in the second captured
and the number of tortoises marked in the second capture.

Sample answer:

Area for tortoises Number of tortoises in Number of tortoises
captured the second capture / unit marked in the second

Kawasan kura-kura Bilangan kura-kura capture / unit
ditangkap dalam tangkapan kedua Bilangan kura-kura
yang bertanda dalam

tangkapan kedua

Riverside 20 15
Persisiran sungai

Mangrove swamp 18 17
side

Persisiran paya
bakau

Lakeside 19 16
Persisiran tasik

Able to list 5 - 3 readings correctly 2
Able to list 2 - 1 readings correctly 1
No response or incorrect response 0

1 (b) (i) KB0601 - Observation
Able to state two different observations based on the following criteria:
[Observation must have values / type for MV and RV from Table 2 or 3
comparison between two readings]
2
MV: Area for tortoise capture 1
Kawasan kura-kura ditangkap

RV: Number of tortoise in second capture / Number of
tortoises marked in the second captured
Bilangan kura-kura dalam tangkapan kedua / Bilangan kura-
kura yang bertanda dalam tangkapan kedua

Sample answers:

1. If the tortoise caught from riverside, the number of tortoise in the
second captured is 20 units / number of tortoises marked in the second
captured is 15 units.
Jika kura-kura ditangkap daripada persisiran sungai, bilangan kura-kura
dalam tangkapan kedua ialah 20 / bilangan kura-kura dalam tangkapan
kedua yang bertanda ialah 15

2. If the tortoise caught from lakeside, the number of tortoise in the
second captured is 19 units / number of tortoises marked in the second
captured is 16 units.
Jika kura-kura ditangkap daripada persisiran tasik, bilangan kura-kura
dalam tangkapan kedua ialah 19 / bilangan kura-kura dalam tangkapan
kedua yang bertanda ialah 16

Able to state one observation correctly and one-two inaccurate observations.

Sample answers:

1. If the tortoise caught from riverside, the number of tortoise marked in the
second captured higher // inversely.
Jika kura-kura ditangkap daripada persisiran sungai, bilangan kura
ditangkap adalah lebih tinggi

2. The number of tortoise captured in the second capture influenced by the
area for tortoise captured / catchment area.
Bilangan kura-kura ditangkap dalam tangkapan kedua dipengaruhi oleh
kawasan kura-kura ditangkap.

Able to state one correct observation
Or
Able to state two different observations at idea level.

Sample answers:

1. The number of tortoise captured in the second capture // marked in second
captured is different.
Bilangan kura-kura ditangkap dalam tangkapan kedua adalah berbeza

No response or wrong response 0

1(b)(ii) KB0604 - Making inference

Able to make two inferences correctly.
Note: Inference must match observation.
P1: Food source from catchment area // Temperature of catchment area //

Humidity
Sumber makanan daripada kawasan tangkapan / Suhu kawasan tangkapan
// Kelembapan
P2: Population size of tortoise.
Populasi saiz kura-kura

Sample answers: 3

1. More food source at riverside // Low temperature // high humidity, more 2
population size of tortoise. 1
Lebih banyak sumber makanan di persisiran sungai // suhu rendah // 0
kelembapan tinggi, lebih besar saiz populasi.

2. Less food source at lakeside, less population size of tortoise.
Kurang sumber makanan di persisiran tasik // suhu tinggi, lebih kecil saiz
populasi.

Able to make one correct inferences and one inaccurate inference inaccurately.

Sample answers:

1. More food source at river.
Lebih makanan di persisiran sungai

2. Less population of tortoise at lakeside.
Kurang populasi kura-kura di persisiran tasik.

Able to state one correct inference and one-two inference at idea level.

Sample answers:

1. Different population of tortoise.
Populasi kura-kura berbeza

2. Population of tortoise depends on catchment area.
Populasi kura-kura bergantung kepada kawasan tangkapan.

No response OR wrong response

Score Correct Scoring Idea Wrong
3
2 2 Inaccurate - -
1 - - -
1 - 1 - -
1 2 1 -
0 - - 2 -
- - 1 -
1 1 - 1
- - - 1
- 1 1 1
-

KB0610 - Controlling variables
1(c) Able to state all 3 variables and the methods to handle the variable correctly.

Sample answers:

Variables Method to handle the variable correctly
Manipulated variable:

Capture area for tortoise Use different area to catch tortoise //
Menggunkan kawasan tangkapan kura-kura yng
Kawasan tangkapan berbeza
Catch tortoise from riverside, mangrove swamp side
kura-kura and lakeside
Menangkap kura-kura daripada kawasan persisiran
sungai, persisiran paya bakau dan persisiran tasik

Responding variable:

1. Number of tortoise in Count and record the number of tortoise in second 3
second captured // captured // number of marked tortoise in second
Number of marked captured
tortoise in second Mengira dan merekod bilangan kura-kura dalam
captured tangkapan kedua // bilangan kura-kura yang
Bilangan kura-kura bertanda dalam tangkapan kedua
dalam tangkapan
pertama // Bilangan
kura-kura yang
bertanda dalam
tangkapan pertama

2. Population (size) of Calculate population size of tortoise using formula
tortoise =
Saiz populasi kura-
kura No.of tortoise in the 1st capture X No.of tortoise in the 2ndcapture
Number of marked tortoise in the second captured

Mengira saiz populasi kura-kura mengunakan formula =
Bil. Kura2 dlm tangkapan per1 X Bil. Kura2 dlm tangkapan ke2

Bilangan kura-kura yang bertanda dalam tangkapan kedua

Constant variable

1. Number of tortoise in 1. Same number of tortoise catch in the first
the first captured. captured is 25.
Bilangan kura-kura Bilangan kura-kura dalam tangkapan pertama
dalam tangkapan ialah 25.
pertama
2. Catch the same type of tortoise.
2. Type of tortoise. Menangkap jenis kura-kura yang sama iaitu
Jenis kura-kura kura-kura Dura

3. Day for recaptured. 3. The tortoise is recaptured after seven days
Hari untuk tangkap released.
semula Tangkap semula kura-kura selepas tujuh hari

6 ticks

4 - 5 ticks 2
1
1 - 3 ticks 0

0 tick

KB0611 - Making hypothesis 3
1 (d) Able to state hypothesis following all criteria. 2

P1: Manipulated variable (Catchment area)
Kawasan tangkapan

P2: Responding variable (Number of tortoise marked in second capture //
Population size of tortoise)
Bilangan kura-kura yang bertanda dalam tangkapan kedua // Saiz populasi
kura-kura

P3: Relationship

Sample answers:

1. The number of tortoise marked in the second captured from riverside is
higher than mangrove swamp side and lakeside / vice versa.
Bilangan kura-kura yang bertanda dalam tangkapan kedua daripada
persisiran sungai adalah lebih tinggi berbanding persisiran paya bakau dan
persisiran tasik / dan sebaliknya

2. The population size of tortoise at the riverside is higher than from mangrove
swamp side and lakeside / vice versa.
Saiz populasi kura-kura di persisiran sungai adalah lebih tinggi berbanding
persisiran paya bakau dan persisiran tasik / dan sebaliknya

Able to make a hypothesis relating the manipulated variable and the responding
variable inaccurately.

Sample answers:

1. Number of tortoises marked in the second capture depends on the catchment
area.
Bilangan kura-kura yang bertanda dalam tangkapan kedua bergantung
kepada kawasan tangkapan

Able to make a hypothesis at idea level. 1
0
Sample answers:

1. Different area causes different tortoises
Kawasan yang berbeza menyebabkan kura-kura yang berbeza

2. Area affects / influence number of tortoises.
Kawasan mempengaruhi bilangan kura-kura

No response or incorrect response
P3 is not given if there is no P1 or P2

KB0606 – Communication
1 (e)(i) Able to construct a table correctly based on the following aspects:

(T): The titles with units correctly.
(D): All the data

Number of tortoises in first, second and mark in the second captured.
Bilangan kura-kura dalam tangkapan pertama, kedua dan bertanda dalam
tangkapan kedua.
(C): Population size of the tortoises.
Saiz populasi kura-kura

Sample answer:

Number of Number of
tortoises in
Number of marked
the first
captured tortoises in tortoises in the Population
size of
Catchment (unit) the second second tortoises
area of the Bilangan (unit)
kura-kura capture (unit) capture (unit) Saiz
tortoise populasi
Kawasan dalam Bilangan Bilangan
tangkapan tangkapan kura-kura
kura-kura pertama kura-kura kura-kura (unit)

(unit) dalam yang bertanda 3

tangkapan dalam

kedua (unit) tangkapan

kedua (unit)

Riverside

Persisiran 25 20 15 33
sungai

Mangrove

swamp side

Persisiran 25 18 17 26

paya bakau

Lakeside

Persisiran 25 19 16 30
tasik

REJECT (C) if reading in decimals. 2
Any two correct 1
0
Any one correct

No response or incorrect response.

KB0607 – Relationship between space and time
1 (e)(ii) Able to draw the bar chart correctly with the following criteria:

Criteria:

P (paksi) : Uniform scales on both axis, label bar.
Y axis, Population size of tortoise
X axis, Area captured 3

T (titik) : All 3 points transferred correctly. 2
1
B (bentuk) : Same size for the bars and bars are separated. 0

Any two criteria correct

Any one criteria correct

No response or incorrect response

Population of Population size against the area of tortoise captured
tortoise,unit Saiz populasi kura-kura melawan kawasan tangkapan kura-kura
Saiz populasi
kura-kura,unit

3030

20
20

10
10

RRiviveersrisdiede MPaesnrMwgsirsaaosimnvridaegepnsrowpsvaaidyemaep PLeLarakseiksseiirdsaeinde AArreeaatotortrotioseise
Persisiran sungai bakau tasik Kccaaapwptuatruseardned
tangkapan

KB0608 – Interpreting data

1 (f) Able to explain the relationship between the catchment area and population size of
tortoises based on the bar chart and the following aspects:

R - able to state the relationship (Population size & area)
E1 - amount of food sources
E2 - temperature // humidity

Sample answers:

1. The population size of tortoises at riverside increase / higher than population 3
size of tortoises at mangrove swamp side and lakeside because more amount of
food sources and low temperature // more / high humidity / wet area.
Saiz populasi kura-kura di persisiran sungai meningkat / lebih tinggi saiz
populasi berbanding persisiran paya bakau dan persisiran tasik kerana lebih
banyak sumber makanan dan suhu rendah // kelembapan tinggi.

(1R + Any 2E)

Note: If R1 wrong, reject E1 & E2

Able to interpret the relationship incompletely

Sample answers:

1. The population of tortoises at riverside increase / higher than population of 2
tortoises at mangrove swamp side and lakeside because more amount of food
sources.
Populasi kura-kura di persisiran sungai meningkat / lebih tinggi berbanding
populasi kura-kura di persisiran paya bakau dan persisiran tasik kerana jumlah
makanan banyak.

Two aspects including R1
Example: R1 + E1 / R1 + E2

Note: Relationship at idea level is not accepted.
e.g: The population of tortoise influenced by the catchment area
BUT
Explanation can be accepted.

Able to interpret the relationship at idea level.

Sample answer:

1. The population size of tortoises at riverside increase / higher than population 1
size of tortoises at mangrove swamp side and lakeside.
Saiz populasi kura-kura di persisiran sungai meningkat / lebih tinggi
berbanding saiz populasi di persisiran paya bakau and persisiran tasik.

Only R1 stated

No response or incorrect response or wrong relationship. 0

KB0609 – Defining by operation

1 (g) Able to define operationally the population size of tortoise based on the result of
this experiment.

P1 : Number or tortoise in riverside, mangrove swamp side and lakeside
P2 : Number of tortoise marked in second captured
P3 : The population of tortoise depends on the catchment area //

hypothesis statement

Sample answer: 3
Population size of tortoise is number of tortoise in riverside, mangrove swamp
side and lakeside shown by the number of tortoise marked in second captured
depends on the catchment area.
Saiz populasi kura-kura ialah bilangan kura-kura di persisiran sungai, persisiran
paya bakau dan persisiran tasik ditunjukkan melalui bilangan kura-kura yang
bertanda dalam tangkapan kedua dipengaruhi oleh kawasan tangkap

Any two correct 2
1
Any one correct 0

No response or incorrect response
Theoretical explanation.

KB0605 - Predicting

1(h) Able to predict and explain the outcome of the experiment correctly with the 3
following aspects:

P : Population size of tortoise increase / any suitable value more than 33
E1: Increase humidity
E2: Low temperature

Sample answer:

1. The population size of tortoise will increase because more / increase of humidity
and low temperature after rain.
Saiz populasi kura-kura akan meningkat kerana kelembapan bertambah /
meningkat dan suhu rendah selepas hujan

Must Correct Prediction
P + 2E’s

P + Any 1 E 2
P only 1
No response or incorrect response 0

KB0602 – Classifying
1 (i) Able to classify all factors into two groups correctly in table:

Biotic factor Abiotic factor
Faktor biotik Faktor abiotik

Parasite Humidity 3
Parasit Kelembapan
2
Predator pH value 1
Pemangsa Nilai pH 0

Decomposer Topography
Pengurai Topografi

6 ticks
3-5 ticks
1-2 ticks
0 tick

Question 2 Score

KB061201 – (KB061203 – Statement of Identified Problem)
No Mark Scheme
2(i) Sample answers:

1. Does at different enzyme concentration has the highest rate of amylase 3
reaction on white tablecloths with porridge spill?
Adakah perbezaan kepekatan enzim mempunyai kadar tindakbalas amilase
paling tinggi ke atas kain alas meja berwarna putih yang terkena tumpahan
bubur?

2. Does at 2%, 4% and 5% concentration of amylase enzyme has the lowest rate
of amylase reaction on white tablecloths with porridge spill?
Adakah 2%, 4% dan 5% kepekatan enzim lipase mempunyai kadar tindakalas
lipase ke atas kain alas meja berwarna putih yang terkena tumpahan bubur?

3. What is the effect of different enzyme concentration on the rate of amylase
reaction on white tablecloths with porridge spill?
Apakah kesan perbezaan kepekatan enzim ke atas kadar tindakbalas lipase ke
atas kain alas meja berwarna putih yang terkena tumpahan bubur?

4. Do different enzyme concentration affect the rate of amylase reaction on white
tablecloths with porridge spill?
Adakah kepekatan enzim mempengaruhi kadar tindakbalas amilase ke atas
kain alas meja berwarna putih yang terkena tumpahan bubur?

Able to state the problem statement of the experiment with any 2 criteria

Sample answer 2
1. Does the enzyme concentration affect the enzyme activity?

Adakah kepekatan enzim mempengaruhi aktiviti enzim?

2. What is the effect of enzyme concentration on the rate of enzyme activity?
Apakah kesan kepekatan enzim ke atas kadar tindakbalas aktiviti enzim?

Able to state the problem statement of the experiment with any 1 criteria

Sample answer 1
1. What is the rate of reaction?

Apakah kadar tindakbalas?

2. Does enzyme concentration affect the enzyme?
Adakah kepekatan enzim mempengaruhi enzim?

No. KB061202 (KB061203 – Making Hypothesis) Score
2 (ii)
Mark Scheme

Able to state the hypothesis correctly based on 3 criteria:
P1 : Manipulated variable

(Enzyme concentration)
P2 : Responding variable

(Rate of enzyme activity)
P3 : Relationship of variable

Sample answers:

1. Rate of amylase reaction on white tablecloths with porridge spill at 5% of 3
amylase enzyme concentration is the highest.
Kadar tindakbalas amilase ke atas kain alas meja berwarna putih yang
terkena tumpahan bubur pada kepekatan 5% enzim amylase adalah paling
tinggi.

2. Rate of amylase reaction on white tablecloths with porridge spill at 2% of
amylase enzyme concentration is the highest.
Kadar tindakbalas amilase ke atas kain alas meja berwarna putih yang
terkena tumpahan bubur pada kepekatan 2% enzim amilase adalah paling
rendah.

3. The higher the amylase enzyme concentration, the higher rate of enzyme
activity.
Semakin tinggi kepekatan enzim amilase, semakin tinggi kadar aktiviti enzim

Able to state the hypothesis correctly based on 2 criteria:

Sample answers:

1. The rate of amylase activity depends on enzyme concentration. 2
Kadar aktiviti amilase bergantung kepada kepekatan enzim.

2. 2. The enzyme activity affected by enzyme concentration
3. Kadar aktiviti enzim dipengaruhi oleh kepekatan enzim.

Able to state the hypothesis correctly based on 1 criteria:

Sample answers: 1

1. The enzyme activity changes.
Perubahan ektiviti enzim

No. (KB061203-Controlling variable) Score
2 (iii) Mark Scheme 3

Able to state all three variables correctly.

Sample answers:

1. Manipulated variable:
Enzyme concentration
Kepekatan enzim

2. Responding variable:
Rate of enzyme reaction / time taken for iodine solution to remain yellow
Kadar tindakbalas enzim / masa yang diambil untuk larutan iodin kekal
kuning

3. Controlled variable:
Volume of saliva / volume of starch suspension / concentration of starch
suspension / pH value / temperature
Isipadu air liur / isipadu ampaian kanji / kepekatan ampaian kanji / nilai
pH / suhu

Able to state any two variables correctly 2
Able to state any one variables correctly 1
No response or incorrect response 0

No. KB061205 (KB061203 - Listing of Materials and Apparatus) Score
2 (iv) Mark Scheme 3

Sample answers:

Apparatus Materials
 Beakers (√)  2%, 3%, 4% and 5% of starch
 Test tube (√)
 Syringes (√) suspension / plain rice porridge
 Droppers (√) (√)
 Glass rods (√)  Saliva suspension (√)
 White tiles (with grooves)  Iodine solution (√)
 Thermometer (√)  Distilled water
 Test tube rack (√)
 Stopwatch (√) (√) compulsory for 4M
 *water bath (√)

(√) compulsory for 8A

*Bunsen burner + tripod stand + wire gauze + distilled water + beaker = 2
Water bath = 1 Apparatus + 1 Material 1
0
8A + 4M
Able to list 3 materials and any 7 - 5 apparatus related to the experiment

3M + 7 - 5A

Able to list 2-1 materials and any 4 - 1 apparatus related to the experiment

2-1 M + 4-1A

Wrong response or no response

No. KB061204 (KB061203 - Method / procedure of investigation) - 3m Score
2 (v) Mark Scheme

Notes:
K1: Preparation of materials and apparatus (all 3)
K2: Operating the constant variable (any 1)
K3: Operating the responding variable (any 1)
K4: Operating the manipulated variable (any 1)
K5: Steps to increase reliability of results accurately / precaution (any 1)

Able to describe all the 5’K’

Sample answer:

1. Mouth is rinsed with warm water. K5

Mulut dibilas dengan air suam

2. Saliva is collected by using a beaker. K1

Air liur dikumpul dengan menggnakan bikar

3. The saliva is diluted with an equal volume of distilled water. K1

Air liur dicairkan dengan jumlah air suling yang sama

4. 5 ml of 2% starch suspension is put into a test tube by using a K2/K1

syringe, labelled A1.

5ml ampaian kanji 2% diletakkan ke dalam tabung uji dengan

menggunakan picagari dan dilabelkan A1.

5. 2 ml of saliva is added into another test tube by using a second K2/K1

syringe, labelled A2.

2ml air liur ditambah ke dalam tabung uji dengan menggunakan

picagari dan dilabelkan A2 3

6. Test tube A1 and A2 are immersed into water bath at 370C. K1

Tabung uji A1 dan A2 direndam ke dalam kukus air pada 370C.

7. The test tubes are left for 5 minutes. K1/K2

Tabung uji dibiarkan selama 5 minit

8. A dry piece of white tile with groove tile is prepared. K1

Jubin putih lekuk disediakan

9. A drop of iodine solution is placed into each groove. K2/K1

Setitis larutan iodine diletakkan ke dalam setiap jubin lekuk

10. After 5 minutes, starch suspension from test tube A1 is poured K1

into the in test tube A2.

Selepas 5 minit, ampaian kanji daripada tabung uji A1 diisi ke

dalam tabung uji A2.

11. The mixture is stirred by using a glass rod. K1

Campuran dikacau menggunakan rod kaca

12. The stopwatch is started immediately. K1

Jam randik dimulakan serta-merta

13. A drop of mixture from test tube A2 is placed into first groove on K1

the tile contain iodine solution.

Sati titisan campuran daripada tabung uji A1 diisi ke dalam jubin K1

lekuk yang mengandungi larutan iodine.

14. The iodine test is repeated every minutes for 10 minutes.

Ujian iodine diulang setiap minit selama 10 minit.

15. Measure and record the time taken for iodine solution to remain K4

yellow by using a stopwatch

Masa untuk larutan iodin kekal kuning diukur dan direkodkan

dengan menggunakan jam randik. K4
16. Calculate and record the rate of enzyme reaction by using a

formula:

Rate of reaction =

________________1____________________
Time taken for iodine solution to remain yellow

Mengira dan merekod kadar tindakbalas enzim dengan
menggunakan formula :

Kadar tindakbalas = K3
1_____________________ K1
K5
Masa yang diambil untul larutan iodin kekal kuning
17. Steps 1 – 16 are repeated by using different concentration of

amylase at 3%, 4% and 5%.
18. Langkah 1-16 diulang dengan menggunakan kepekatan enzim

yang berbeza pada 3%, 4% dan 5%.
19. All the data is recorded in the table / tabulate data.

Semua data direkodkan di dalam jadual.
20. The experiment is repeated twice to get the average reading.

Eksperimen diulang dua kali untuk mendapatkan bacaan purata

Any 3-4 ‘K’ 2

Any 1-2 ‘K’ 1

No response or incorrect response 0

No. KB061203 – Planning Investigation (KB061203 - Data Presentation) - 2m Score
2 (vi) Mark Scheme

Sample answer:

Enzyme Time taken for iodine solution to Rate of enzyme
concentration remain yellow / time taken for the
reaction
(%) hydrolysis of starch to be (1 / min) / (min-1)
Kepekatan completed (min)
enzim (%) Kadar tindakbalas
Masa yang diambil untuk warna
2 kuning kekal kuning / masa untuk enzim (1/min) /
(min-1)
hidrolisis kanji lengkap (min)

2

3

4

5

Able to construct a table to record data based on one aspect only 1
No response or incorrect response 0

END OF SCHEME