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Published by A, 2021-06-22 07:54:31

Tahun 4 ( Tolak Pecahan Sama Penyebut)

Tahun 4 ( Tolak Pecahan Sama Penyebut)

TAHUN 4

TOLAK PECAHAN

Contoh 1

5 - 1 = 5−1 = 4 = 2
6 6 6 6 3#

Contoh 2

27 - 3 = 2( 7 − 3 ) = 2 4 = 2 1 #
8 8 2
8 8

Contoh 3

54 - 353 = 2( 4 − 3 ) = 2 1 #
5 5
5

Contoh 4

3- 2 = 27 - 2 = 2 (7−2 ) = 2 5 #
7 7 7
7 7

8 2 - 7 = (7 9 + 29) - 7
9 9 9 9

= (7 9+2 ) - 7
9 9

= (7 11 ) - 7
9 9

= 7(119−7 ) = 7 4 #
9

CARA PENYELESAIAN

TOLAK PECAHAN SAMA
PENYEBUT

Selesaikan semua soalan.

1. 7 - 4 = 7−4 = 3 = 1
9 9 9 9 3#

2. 12 - 3 = 12 − 3 = 9 #
17 17 17 17

3. 45 - 1 = 4( 5 − 1 )
6
6 6

= 4 4 = 4 2 #
6 3

4. 63 - 2 = 6( 3 − 2) = 6 1 #
10 10
10 10

5. 5 1 - 3 = (4 8 + 18) - 3
8 8 8 8

= (4 8+1 ) - 3
8 8

= (4 9 ) - 3
8 8

= 4(9−83 ) = 4 6 = 4 3 #
8 4

6. 3 1 - 3 = (2 4 + 1) - 3
44 444

= (2 4+1 ) - 3
4 4

= (2 5 ) - 3

44

= 2(5−43 ) = 2 2 = 2 1 #
4 2

7. 8 3 - 581 = 3( 3 − 1 )
8 8

= 32 = 3 1 #
4
8

8. 7 4 - 335 = 4( 4 − 3 ) = 4 1 #
5 5 5

9. 2- 5 = 17 - 5
7 7
7

= 1 (7−5 )

7

= 1 2 #
7

10. 9 - 1 = 83 - 1
3 3
3

= 8 (3−1 )

3

= 8 2 #
3


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