F4 ADD MATH MODULE 2021

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

47 The diagram shows the positions of L, M and N along a river.
M 85 m N

current flow

L
The width of the river is 50 m, M is due north of L and the velocity of the downstream river flow is
2.5 m/s. Nathaniel wanted to row his boat from L across the river to M, but the boat was swept by the
current flow and stopped at N in 15 seconds. Calculate the speed, in m/s, of Nathaniel’s boat. (Ans :
6.08)

[3 marks] [clon textbook form 4]

Answer :

 solve problems 2

→→ →

48 Given the position vector for three toy cars are OP = x + 3y, OQ = 2x + 5y and OR = kx + 4y, where

k is a constant. These toy cars are placed in a straight line, find the value of k . (Ans : 3 )
2

[3 marks] [clon textbook form 4]

Answer :

→→ →

49 Given that O, P, Q, and R are four points such that OP = p , OQ = q and OR = 4 p . M is the

midpoint of PQ, and the line OM is extended to a point S such that → = 8 → .

OS 5 OM

(a) Express in terms of p and q :

→ [ Ans : 4 ( p +q) ]
5
(i) OS .
(Ans : 4 p − q )
→

(ii) QR .

[4 marks]

(b) Hence, show that point S lies on QR and state the ratio of QS : SR.
(Ans : 1 : 4) [3 marks] [Forecast]
Answer :

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 solve problems 3

→→

50 In the diagram, P is the midpoint of OA, and Q is a point on AB such that AQ = 3QB .
A

P
GQ

OB

→→
(a) Given that OA = 5 a and OB = 10 b . Express in terms of a and b :
~~ ~~

(i) → . (Ans : 5 a − 10 b )
2 ~
BP ~

→ (Ans : 5 a + 15 b)
4 2
(ii) OQ , ~ ~

[4 marks]

→→ →→
(b) Given that BG =  BP and OG =  OQ , find

(i) the values of  and , (Ans : = 2 , .= 4 )
5 5

(ii) the ratio of area of triangle OGP : area of triangle QGB.
(Ans : 6 : 1)

[6 marks]

[Forecast]

Answer :

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

→→ →

51 The diagram shows a triangle, ACE. It is given that AE = k x , BD = 3 x and ED = (h −1) y ,
~~
~

where k and h are constants.

C

BD

AE

→

If AB = 2 x + 6 y , find
~~

(a) the values of h and k, (Ans : h = 7, k = 5) [4 marks]

(b) the area of triangle BCE, if the area of triangle ABE is 18 unit2.

(Ans : 27) [2 marks]

(c) the area of triangle BCD, if the area of triangle ABE is 15 unit2.

(Ans : 13.5) [2 marks]

(d) the area of triangle BCD, if the area of triangle ACE is 30 unit2.

(Ans : 10.8) [2 marks]

[Forecast]

Answer :

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

==========================================================================================================================================

8.3 Vectors in a cartesian plane

8.3.1 Represent vectors and determine the magnitude of the vectors in the Cartesian
plane.

==========================================================================================================================================

 vectors in the Cartesian plane ~ 1

52 The diagram shows five points, P, Q, R, S and T on a grid.

PT

R

Q
S

Express

(a) → → , → → → and → in the form  x  ,
y
PR , QR TR , SR , PQ PT

(b) → → , → → → and → in the form x i + y j.

RP , RQ RT , RS , QP TP

Answer :

→ → = →

(a) PR = QR TR =

→ → = →

SR = PQ PT =

→ → = →

(b) RP = RQ RT =

→ → = →

RS = QP TP =

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 vectors in the Cartesian plane ~ 2

→→

53 The diagram shows two vectors, OP and QO .

Q (−8, 4) y
P (5, 3)

x

O

Express

(a) → in the form  x  ,
y
OP

→

(b) OQ in the form x i + y j.

[2 marks] [2003, No.12]

Answer : (b)
(a)

54 The diagram shows a parallelogram OABC, drawn on a Cartesian plane.
y

B

C (−5, 3)

O A (2, 1)
x

Express

(a) → in the form  x  ,
y
CB

(b) → in the form x i + y j.

BA

[2 marks]
[Forecast]

Answer : (b)
(a)

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)
MIND think :

in the form of compenent i and j → →

~~ OA =  AO =

A (−3, 2) in the form column vector → →

OA =    AO =  
   
   

 magnitude of a vector

→→

55 Given that OAB is a right-angled triangle with AOB = 90, OA = 4 i + 2 j and OB = −3 i + 6 j . Find
~~ ~~

the area of triangle AOB. (Ans : 15)

[2 marks] [Forecast]

Answer :

MIND think :

r = x i +y j = x  magnitude r , r=
 
~ ~~  y  ~ ~

56 Given that a = −2 i + h j. Find the values of h such that  a = 20 . (Ans : 4)
[2 marks] [Forecast]
Answer :

→→

57 Given that OP = 3 i + k j and OQ = 4 j . If OP and OQ are the two sides of a rhombus, find the value
~~
~

of k. (Ans :  7 )

[2 marks] [Forecast]

Answer :

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

==========================================================================================================================================

8.3.2 Describe and determine the unit vector in the direction of a vector.

==========================================================================================================================================

 unit vector in the direction of a vector

→

58 The diagram shows vector OA drawn on a Cartesian plane.

y
6A
4
2

x
O 2 4 6 8 10 12

(a) → in the form  x  .
y
Express OA

→

(b) Find the unit vector in the direction of OA .

[2 marks]
[2005, No.15]

Answer :

(a) (b)

→

59 The diagram shows the vector OR .

y

R (3, 4)

O x [3 marks] [2010, No.15]
Express in the form x i + y j :
(b)
→

(a) OR ,

→

(b) the unit vector in the direction of OR .

Answer :

(a)

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

60 The length of vector u is 13 units and the direction is opposite with vector −3i + 2j.

~

Find the vector of u . [ Ans : 3 13 i − 2 13 j ]
[2 marks] [clon textbook form 4]
~

Answer :

61 Given that p = 3 i + k j and  = 1 (3 i + k j) , find the possible values of k. (Ans :  4)

p
~ 5~
~ ~~ ~

[2 marks] [forecast]

Answer :

MIND think :

• r = x i +y j = x  unit vector in the direction r ,  =
 
~ ~~  y  ~ r

~

• if r is a unit vector   r  =  

~~ Note : r = 2r = 3r . . .

~~ ~

62 Given that 5i + k j is a unit vector, find the possible values of k. (Ans : 7)

74

[2 marks] [clon textbook form 4]

Answer :

63 Given that ^ = (1− h) i −3 j, find the possible values of h. (Ans : 1 , 9 )

v 55
~5
[2 marks] [clon textbook form 4]

Answer :

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

64 Given that x =  h  and y =  −k  . If the unit vector in the direction of 2x is 2  h  .
k h 3 k

Find the value of  3 y . (Ans : 9 )

2

[2 marks] [Forecast]

Answer :

==========================================================================================================================================

8.3.3 Perform arithmetic operations onto two or more vectors.

==========================================================================================================================================

 arithmetic operations / vectors in the Cartesian plane 1

65 The diagram shows a parallelogram, OPQR, drawn on a Cartesian plane.

y Q
R
P
O x

It is given that → → → .

OP = 6i + 4j and PQ = −4i + 5j. Find PR

(Ans : −10i + j)

[3 marks]
[2005, No.16]

Answer :

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)
66 The diagram shows a parallelogram ODEF drawn on a Cartesian plane.

y
E

F
D
x

O

→→ →

It is given that OD = 3 i + 2 j and DE = −5 i + 3 j . Find DF . (Ans : −8 i + j )
−− −−
−−

[3 marks] [2011, No.16]

Answer :

 arithmetic operations / vectors in the Cartesian plane 2

→→

67 The diagram shows two vectors, OA and AB .

y
A (4, 3)

O x
−5 B

Express

(a) → in the form  x  , (b) → in the form x i + y j.
y
OA AB

[2 marks] [2006, No.13]

Answer :

(a) (b)

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

→→

68 The diagram shows two vectors, PQ and RS .

y

S (−4, 4)

P (4, 2)

R (−2, 1) Q (1, 2)
O
x

Express

(a) → in the form  x  , →
y
PQ (b) SR in the form x i + y j.
[2 marks] [Forecast]

Answer :

(a) (b)

→→ Q (3, 5)

69 The diagram shows two vectors, OP and OQ .
y

P (−3, 2)

x
O

If point N lies on PQ such that → = 1 → . Find the → in the form x i + y j.

PN 2 NQ ON

[ Ans : : −i + 3j ]

[2 marks] [Forecast]

Answer :

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 arithmetic operations / magnitude of a vector

→→

70 Given that AB = −2 i + 3 j , BC = 3 i − 4 j , and B (−1, 5). Find
~~ ~~

(a) the coordinates of point A, [ Ans : (1, 2) ]

(b) the length of AC. (Ans : 2 )
[4 marks] [Forecast]

Answer :

(a) (b)

71 Given that a = 13 i + j and b = 7 i − k j, find [ Ans : 6 i + ( 1 + k ) j ]
(a) a − b , in the form x i + y j,
(b) the values of k if  a − b  = 10. (Ans : −9, 7)

Answer : [4 marks] [2009, No.13]
(a)
(b)

72 It is given that vector r =  −82 and vector s =  h  , where h is a constant.
7

(a) Express the vector r + s , in terms of h.

(b) Given that  r + s  = 13 units, find the positive value of h. (Ans : 4)
Answer :
[4 marks] [2011, No.17]

(a) (b)

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 arithmetic operations / unit vector in the direction of a vector 1

73 Given that O (0, 0), A (−3, 4), and B (2, 16), find in terms of the unit vectors, i and j,

(a) → ,

AB

(b) the unit vector in the direction of → . [ Ans : 1 (5 i + 12j)
13
AB

]

[4 marks] [2004, No.16]

Answer :

(a) (b)

74 The following information refers to the vectors a and b .

a =  2  , b =  −41
8

Find [ Ans : 152 ]

(a) the vector 2 a − b ,

(b) the unit vector in the direction of 2 a − b . [ Ans : 1 152 ]
13

[4 marks] [2007, No.16]

Answer : (b)
(a)

→→

75 Given STUV is a parallelogram, TV = 2 i + 3 j and UV = −2 i − 2 j . Find the unit vector in the direction
~~ ~~

→ [ Ans : 1 (4i + 5j) ]

of TU in terms of i and j . 41

~~

[3 marks] [Forecast]

Answer :

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

76 Given that a = 2i − j and b = 3i + j. Find the vector in the same direction and parallel 2b − 4a and has a

magnitude of 5 10 . [ Ans : 5 (− i + 3j) ]
Answer : [3 marks] [Forecast]

 arithmetic operations / unit vector in the direction of a vector 2

77 The diagram shows a regular hexagon with centre O.

ED

FO C

AB

→ →→ →

(a) Express AC + CE + CB as a single vector. (Ans : AF )

(b) Given → a, → b , and the length of each side of the hexagon is 3 units, find the unit

OA = OB =

vector in the direction of → a and b . (Ans : −a + b )
3
AB in terms of

[3 marks] [2016, No.10]

Answer :

(a) (b)

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 arithmetic operations / unit vector in the direction of a vector 3

78 Given that → =  q q 1 and → =  2  . →
− 2
AB OA If OB is a unit vector, find the possible values

of q. (Ans : −2, −1)

[4 marks] [Forecast]

Answer :

 arithmetic operations

79 r = 3a + 4b,
s = 4a − 2b,
t = pa + (p + q)b, where p and q are constants.

Use the above information to find the values of p and q when t = 2r − 3s.
(Ans : p = −6, q = 20)

[3 marks] [2003, No.13]
Answer :

→→

80 Given that A (−2, 6), B (4, 2), and C (m, p), find the value of m and of p such that AB + 2 BC =

10 i −12 j . (Ans : m = 6, p = −2)

~~

[4 marks] [2004, No.17]

Answer :

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

→ →→

81 A (2, 3) and B (−2, 5) lie on a Cartesian plane. It is given that 3 OA = 2 OB + OC . Find

(a) the coordinates of C, [ Ans : (10, −1) ]

→ (Ans : 4 5 )
[4 marks] [2018, No.9]
(b) | AC | .

Answer :

(a) (b)

82 It is given that P (2, m), Q (h, 6), v = 2i − j , w = 9i + 3 j and → = 2v + kw , such that m, h

PQ

and k are constants. Express h in terms of m. (Ans : h = 30 −3m)

[3 markah] [2019, No.16]

Answer :

 parallel vectors / collinear ~ 1

83 The following information refers to the vector a and b .

a =  6 4 , b =  2 
 m−  5 

It is given that a = k b , where a is parallel to b and k is a constant. Find the value of

(a) k, (Ans : 3)

(b) m. (Ans : 19)

Answer : [3 marks] [2012, No.16]

(a) (b)

84 Given u=  34  and v=  k 6 1 , find
  −

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

(a) the unit vector in the direction of u , [ Ans : 1  34  ]
(b) the value of k such that u and v are parallel. 5 

(Ans : 9)

[4 marks] [2013, No.15]

Answer : (b)
(a)

85 The diagram shows a trapezium ABCD.

D C
q

A
p

B

Given p =  3  and q =  k − 1 , where k is a constant, find the value of k.
4 2

(Ans : 5 )

2

[3 marks] [2017, No.4]

Answer :

86 Given that p =  2  , q =  −9  and r =  m  . If 2 p + q is parallel to r , find the value
2 6 4
~ ~ ~ ~~ ~

of m. (Ans : −2)

[4 marks] [Forecast]

Answer :

87 Vector ba has a magnitude of 5 unit, and parallel to  −4  . If a > b, find the value of a and
2

of b. (Ans : a = 2, b = −1)

[4 marks] [Forecast]

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

Answer :

 parallel vectors / collinear ~ 2

→→

88 The points P, Q, and R are collinear. It is given that PQ = 4 a − 2 b and QR = 3 a + (1+ k) b , where
~~ ~~

k is a constant. Find

(a) the value of k. (Ans : −2.5)

(b) the ratio of PQ : QR. (Ans : 4 : 3)
Answer : [4 marks] [2006, No.14]

(a) (b)

→→ →

89 Given that AB = (2k −1) p + 3q . If AB is extended to point C such that BC = k p + 6h q , express k

~~ ~~

in terms of h. (Ans : k = 2h )

4h−1

[2 marks] [clon textbook form 4]

Answer :

90 It is given → =  k  , → = 13 and → =  h  , where h and k are constants. Express h in
4 −2
OP OQ OR

terms of k, if points P, Q and R lie on a straight line. (Ans : h = 6 − 5k)

[3 marks] [2015, No.15]

Answer :

→→ →
91 Given OA = i + j , OC = 5 i + 3 j and OD = 3 i +  j . If point D lies on AC, find the value
~~ ~~ ~~

of . (Ans : 2)

[3 marks] [Forecast]

Answer :

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 parallel vectors / collinear ~ 3

→→ →

92 Given that OP = − i +10 j , OQ = 3 i + 2 j , and OR = 4 i . Show that P, Q, and R are collinear.
~~ ~~ ~

[3 marks] [Forecast]

Answer :

93 Given that → → = 10 i + j , → Determine whether S, K, and R are in a straight

OS = 2 j , OK and OR = 6 i .
~ 3~ ~
~

line. Prove your answer mathematically. (Answer : no)

[3 marks] [Forecast]

Answer :

 parallel vectors / collinear ~ 4

94 Given p=  −34  and q=  2  , find
  k 

(a) p , (Ans : 5)

(b) the value of k such that p + q is parallel to the x-axis. (Ans : −3)

[3 marks] [2014, No.16]

Answer : (b)
(a)

95 Given that a =  −31 , and b =  −2  . If 2p a + 5 b is parallel to y-axis, find the value
5
~ ~ ~~

of p. (Ans : 5 )
3

[3 marks] [Forecast]

Answer :

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

96 Given that p =  m1−1 and q =  9  , where m is a constant. Find the value of m if p is
8
~ ~ ~

perpendicular / orthogonal to q . (Ans : 1 )
9
~

[3 marks] [Forecast]

Answer :

MIND think : a perpendicular to b

• a is parallel to x-axis  the constant of j = ~~

~ 

• a is parallel to y-axis  the constant of i = ( ma ) ( mb ) = −1 @ a. b=0

~ ~~ ~~

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

==========================================================================================================================================

8.3.4 Solve problems involving vectors.

==========================================================================================================================================

97 A motoboat cross a river with the enjine that can move with a speed of 7 j . The speed for the current

~

of the river and the wind blows against the motorboat are 2 i − 3 j and −4 i + 6 j respectively. Find
~~ ~~

the resultant vector cause to the motoboat. (Ans : −2 i + 10 j )

~~

[2 marks] [Forecast]

Answer :

98 A ball is throw horizontally with an acceleration of 2 ms−2 from the top of a tower. The ball will drop
freely with an acceleration due to the gravity force, g ms−2. By using i as the unit vector in the direction

~

of horizontal acceleration, and j as the unit vector in the drop direction due to the gravity force.

~

(a) Find the resultant vector of the ball in terms of i and j . [1 mark]

~~

(b) Hence, by using g = 10, calculate the magnitude of the resultant vector of

the ball. (Ans : 10.20) [2 marks]

Answer : [Forecast]
(a) (b)

99 A particle moves with the velocity vector, v = ( 2 i − 3 j ) ms−1. If it started from the position i + 4
~ ~~ ~

j . Find

~

(a) the speed, in ms−1, of the particle, (Ans : 13 )

(b) the position of the particle after 3 seconds, (Ans : 7 i − 5 j )

~~

(c) the duration, in second, for the particle to reach the position 11( i − j ). (Ans : 5)

~~

[4 marks] [Forecast]

Answer :

(a) (c)

(b)

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

MIND think :

speed = of velocity vector

100 Car P left town P (0, 0) with velocity of vP = ( 6 i + 8 j ) kmh−1. At the same time, car Q left

~~

town Q (100, 40) with velocity of vQ = ( − 4 i + 4 j ) kmh−1. Find the time when the car P will cross

~~

car Q. (Ans : 10)

[2 marks] [clon textbook form 4]

Answer :

101 A particle is moving from the point P (7, 15) with the velocity vector of (3 i − 2 j ) ms−1. After t

~~

seconds leaving P, the paticle is on point S.

(a) Find

(i) the speed of the particle, (Ans : 13 )

(ii) the position of the particle from O after 4 seconds. [ Ans : (19, 7) ]
(b) When will the particle reside on the right side of the origin ?
(Ans : 7.5)
Answer : [4 marks] [clon textbook form 4]

(a) (i) (b)

(ii)

102 The diagram shows the location of Pay’house, the school and the public library at point O, point A and
point B respectively on the Cartesian plane. The shortest distance between Pay’house and the school is
7.5 km while the shortest distance between the school and the public library is 19.5 km.

y

B
16

A

x
O

Given the vector from Vivi’s house to the school is 3 i + 4 j , express the vector from Pay’s house to

the public library in the form of x i + y j . (Ans : 8 i + 16 j )

[3 marks] [Forecast]

Answer :

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MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

PAPER 2
 Part A ~ parallel 1 → 6 – 8 marks

103 Given that AB =  5  , OB =  2  and CD =  k  , find
7 3 5

(a) the coordinates of A, [ Ans : (–3, –4) ] [2 marks]

(b) the unit vector in the direction OA , (Ans : − 3 i − )4j [2 marks]
5
5

(c) the value of k, if CD is parallel to AB . (Ans : )25 [2 marks]
7
[2003, No.6]

Answer :

→→ (Ans : −4i + 3 j )

104 It is given that AB = −3i + 2 j and AC = −7i + 5 j (Ans : −4i+3 j )
5
(a) Find [4 marks]

→

(i) BC ,

→

(ii) the unit vector in the direction BC .

→ →→

(b) Given AD = pi − 15 j , where p is a constant and AD is parallel to BC , find the

value of p. (Ans : 20) [3 marks]
[2012, No.5]

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 Part A ~ parallel 2

105 The diagram shows the position and the direction of boats A, B and C in a solar boat competition.

C
B
A

Starting line

Both boat A and boat B move in the direction of the water current. The velocity of

the water current is given by w = i + 1 j  ms−1. Given the velocity of boat A is a =

 2

( 2i + j ) ms−1 and the velocity of boat B is b = ( 6i )+ 3 j ms−1.

(a) Determine how many times the resultant velocity of boat B compare to the

resultant velocity of boat A. (Ans : 7 ) [4 marks]
3

(b) On the way to the finishing line, boat C is facing a technical problem and off track.

The velocity of boat C is c = 2i − 3 j  ms−1. Find

 2

(i) the resultant velocity of boat C, (Ans : 3 i − j )

(ii) the unit vector in the direction of boat C, [ Ans : 1 (3 i − j ) ]
[3 marks] 10
[2016, No.5]
Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 Part A ~ parallel 3

106 In the diagram, ABCD is a quadrilateral. AED and EFC are straight lines.

D

F
EC

AB

It is given that → = 20 x , → =8y, → 1 AD and EF = 3 EC.

AB AE DC = 25 x − 24 y , AE = 45
~~ ~~

(a) Express in term of x and y :
~~

(i) → , (Ans : −20 x + 32 y )
~~
BD

→ (Ans : 25 x )
~
(ii) EC , [3 marks]

(b) Show that the points B, F and D are collinear.
[3 marks]

(c) If x = 2, and  y  = 3, find  → . (Ans : 104) [2 marks]
~~ [2005, No.6]
BD

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472) C
107 The diagram shows a trapezium ABCD.

B

F

A ED

It is given that → =2y, → = 6x, → = 2→ and → 5→

AB AD AE AD BC = AD
~~3 6

→ (Ans : 5 x + 2 y ) [2 marks]
~~
(a) Express AC in term of x and y .
~~

(b) Point F lies inside the trapezium ABCD such that 2 → = m → , m is a constant.

EF AB

(i) Express → in term of m, x and y. (Ans : 4 x + m y )
~~ ~~
AF

(ii) Hence, if the point A, F and C are collinear, find the value of m.
(Ans : 8 )

5

[5 marks]
[2006, No.5]
Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)
108 The diagram shows a quadrilateral PQRS. The straight line PR intersects the straight line QS at point
T.

S

R
T

PQ

→→ →
It is given that QT : TS = 2 : 3, PQ = 10u , PS = 25v and QR = −u + 15v

(a) Express in terms of u and v ,

(i) → , (Ans : −10u + 25v )

QS

→ (Ans : 6u + 10 v )
[3 marks]
(ii) PT ,

(b) Find the ratio PT : TR. (Ans : 2 : 1)
[5 marks]

[2013, No.3]

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)
109 The diagram shows a trapezium OPQR and point T lies on PR.
PQ

T

OR

→→ →→

It is given that OR = 18b , OP = 6a and OR = 2 PQ .

(a) Express in terms of a and b ,

→ (Ans : −6a + 18b )

(i) PR ,

(ii) → , (Ans : 6a + 9b )
[3 marks]
OQ

→→

(b) It is given that PT = k PR , where k is a constant. Find the value of k if the point

O, T and Q are collinear. (Ans : 1 ) [5 marks]
3

(c) If the area of triangle QTR = 45 unit2, and the perpendicular distance from P to

OR is 4 units, find b . (Ans : 3.75) [2 marks]

[2014, No.5]

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

110 Solution by scale drawing is not accepted.
The diagram shows the positions of jetty O and kelongs, K, L, R, S and T in the sea.

Land L R
Sea
K
S

T

Kelong L is situated 400 m from jetty O and kelong R is situated 600 m from jetty O
in the direction of OL. Kelong S is situated 300 m from jetty O and kelong T is situated
600 m from kelong S in the direction of OS. Kelongs L, K and T are situated on a
straight line such that the distance of kelong K from kelong T is 5 times its distance
from kelong L.

(a) By using p to reperesent 100 m in the direction of OR and q to represent 150

m in the direction of OT, express in terms of p and q

→ (Ans : 10 p + q )
3
(i) OK

(ii) → (Ans : − 8 p + q)
3
RK

[3 marks]

(b) If Joe uses a binocular to observe kelong R from kelong S, determine whether

kelong R can be seen without being blocked by kelong K or otherwise.

Prove your answer mathematically.

(Ans : → = p+q; can be seen) [5 marks]

KS − 10
3

[2019, No.6]

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 Part A ~ triangle law 1

111 In the diagram, ABCD is a quadrilateral. The diagonals BD and AC intersect at point R. Point P lies
on AD.
D

C

PR

AB

It is given that AP = 1 AD, BR = 1 BD, → = x and → = y.
33
AB AP

(a) Express in terms of x and y :

(i) → , (Ans : x − 3 y )

DB

(ii) → . (Ans : 2 x + y)
3
AR

[3 marks]

(b) → → → where h and k are constants, find

Given that DC = k x − y and AR = h AC ,

the value of h and of k. (Ans : h = 1 , k = 4 ) [4 marks]
23
[2008, No.6]

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 Part A ~ triangle law 2

112 The diagram shows triangle ABC. The straight line AQ intersect the straight line BR at P.
C

RQ
P

AB

It is given that AR = 3RC, BQ = 2 BC, → = 3x and →
3
AB AC = 4 y .

(a) Express in terms of x and y :

→ (Ans : −3x + 4y )

(i) BC ,

→ (Ans : x + )8y

(ii) AQ . 3

[3 marks]

(b) It is given that → = → and → = → → where h and k are constants,

AP h AQ AP AR + k RB ,

find the value of h and of k. (Ans : h = 9 , k = 3 ) [5 marks]
11 11
[2009, No.5]

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 Part B ~~ parallel 3 → 10 marks

113 The diagram shows a parallelogram ABCD. Point P lies on the straight line AB and point Q lies on the
straight line DC. The straight line AQ is extended to the point R such that AQ = 2QR.

R
DQ

C

A PB

→→

It is given that AP : PB = 3 : 1, DQ : QC = 3 : 1, AP = 6u and AD = v .

(a) Express, in terms of u and v :

(i) → , (Ans : v + 6u )

AQ

→ (Ans : 2u + v )

(ii) PC .

Hence, show that the points, P, C and R are collinea [6 marks]

(b) It is given that u = 3i and v = 2i + 5 j . ( Ans : 8i + 5 j )

→ 8i+5 j

(i) Express PC in terms of i and j , (Ans : − − )

→ 89

(ii) Find the unit vector in the direction of PC . [4 marks]
[2011, No.10]
Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 Part B ~~ triangle law 1

114 The diagram shows triangle OAB. The straight line AP intersects the straight line OQ at R. It is given

that 1 AQ = 1 AB, → = 6 x , and → = 2y.
OP = OB,
34 OP ~ OA

~

A

Q

R

OP B

(a) Express in terms of x and / or y
~~

(i) → , (Ans : −2 y + 6 x )
~~
AP

→ (Ans : 3 y + 9 x )
2 2~
(ii) OQ . ~

[4 marks]

(b) (i) Given that → = h → , state → in terms of h, x and y.
~~
AR AP AR

[ Ans : h (−2 y + 6 x ) ]
~~

→→ →
(ii) Given that RQ = k OQ , state RQ in terms of k, x and y .
~~

[ Ans : k ( 3 y + 9 x ) ]
2 2~
~

[2 marks]

(c) Using → and → from (b), find the value of h and of k.

AR RQ

(Ans : h = 1 , k = 1 ) [4 marks]
23

[2004, No.8]

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)
115 The diagram shows triangle AOB. The point P lies on OA and the point Q lies on AB. The straight line
BP intersects the straight line OQ at the point S.

B

Q

S A
OP

→→

It is given that OA : OP = 4 : 1, AB : AQ = 2 : 1, OA = 8 x and OB = 6 y .

(a) Express in terms of x and / or y .

(i) → , (Ans : 2 x − 6 y )

BP

→ (Ans : 4 x + 3 y )
[3 marks]
(ii) OQ .

(b) →→ → = k → , where h and k are constants, find the value

Using OS = h OQ and BS BP

of h and of k. (Ans : h = 2 , k = 4 )
[5 marks] 55

(c) Given that │ x │ = 2 units, →
(Ans : 580 ) [2 marks]
│ y │ = 3 units and AOB = 90, find │ AB │.

[2007, No.8]

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

116 The diagram shows a triangle ABC. R
C

QB

P (Ans : −3y + 2x )
A
(Ans : − y + 2x )
→→ [3 marks]

It is given AP : PB = 1 : 2, BR : RC = 2 : 1, AP = 2x , and AC = 3y . (Ans : 41 ) [2 marks]

(a) Express in terms of x and y ,

→

(i) CP ,

→

(ii) CR ,

→

(b) Given x = 2i and y = −i + 4 j , find CR .

(c) Given → = → and → = → where m and n are constants, find the

CQ m CP QR n AR ,

value of m and of n. (Ans : m = 3 , n = 2 ) [5 marks]
55
[2015, No.9]

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 Part B ~~ triangle law 1 / parallel

117 The diagram shows a triangle PQR. The straight line PT intersects with the straight line QR at point S.
Point V lies on the straight line PT.

Q T
S

V R
P

It is given that → = 1 → , → = 6x and → = 9y .

QS 3 QR PR PQ

(a) Express in terms of x and / or y :

(i) →

QR

→ (Ans : 6y + 2x )
[3 marks]
(ii) PS .

(b) It is given that → = m → and → = n(x − 9y ), where m and n are constants.

PV PS QV

Find the value of m and of n. (Ans : m = 3 , n = 3 ) [5 marks]
84

(c) Given → = hx + 9y , where h is a constant, find the value of h.

PT

(Ans : 3) [2 marks]

[2017, No.8]

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 Part B ~~ triangle law 2 → 10 marks

118 The diagram shows triangle OAB. The point C lies on OA and the point D lies on AB. The straight line
OD intersects the straight line BC at the point E.
O CA

ED

B

It is given that → → → 2→ and →→
OA
OA = x , OB = y , OC = 3 AB = 2 AD .

(a) Express in terms of x and y :

→ (Ans : −y + 2 x )
3
(i) BC ,
(Ans : 1 y + 1 x )
→ 2 2

(ii) OD .

[4 marks]

→→ →→
(b) It is given that OE = h OD and BE = k BC , where h and k are constants. Express

→

OE

(i) in terms of h, x and y , [ Ans : h(1 y + 1 x ) ]
2 2

(ii) in terms of k, x and y . (Ans : y −k y + 2 k x )
(c) Hence, find the value of h and of k. 3
Answer :
[3 marks]

(Ans : h = 4 , k = 3 ) [3 marks]
55
[2010, No.9]

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

119 The diagram shows triangles OAQ and OPB where point P lies on OA and point Q lies on OB. The
straight lines AQ and PB intersect at point R.
A

P

R
O

QB

It is given that → 18x , → 16y , OP : PA = 1 : 2, OQ : QB = 3 : 1, → = m → , →

OA = OB = PR PB QR

= n → , where m and n are constants.

QA

(a) Express → in terms of :

OR

(i) m, x dan y , (Ans : 6x − 6mx + 16m y )

(ii) n, x dan y . (Ans : 12y −12n y + 18nx )
[4 marks]

(b) Hence, find the value of m and of n. (Ans : m = 2 , n = 1 ) [4 marks]
39

(c) Given | x | = 2 unit, | y | = 1 unit and OA is perpendicular to OB,

calculate | → | . (Ans : 40 ) [2 marks]
3
PR [2018, No.8]

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

FORECAST

 Part A ~ 6 – 8 marks

120 A boat is set on a course of N 30 E with a speed of 12 knots. However, the water current is
flowing at 5 knots towards the east.

(a) Sketch the digram which shows the movement of the boat and the water current.

[1 mark]

(b) Find :

(i) the magnitude, (Ans : 15.13) [2 marks]

(ii) the direction, (Ans : 046.63) [2 marks]

of the resultant velocity of the boat.

(c) If the boat intends to move northward, show that the direction at which must be steered

in order to do so is N 24.62 W. [2 marks]

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

121 The diagram shows a right-angled triangle ABC. M is the midpoint of AB. MN is parallel to BC and P

→→

is a point on CN such that CP = 2PN. Given BM = a and BC = 2 b .

~~

C
P
N

A

M
B

(a) Express in terms of a and / or b :

→

(i) MN ,

→ (Ans : −2 b + 2 a )

(ii) CA ,

(iii) → . (Ans : 4 b + 2 a )
33
BP [4 marks]

(b) (i) If │ a │ = 12 units, │ b │ = 9 units, find the area of triangle ABC. (Ans : 216 )

(ii) Find the shortest distance for P to BC. (Ans : 12)
[3 marks]

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 Part A ~ parallel 3

122 The diagram shows a triangle OAB and OAC. The straight lines OB and AC intersect at point K such

→→

that AK : AC = 1 : 3. Given OA = 3 a and OC = h c , where h is a constant.
B

C

K

A

O

Find

(a) → in terms of h, a and c, [ Ans : 1 (−3 a + h c ) ] [2 marks]
3
AK (Ans : 2 a + h c ) [1 mark]
3
→ (Ans : 3) [4 marks]

(b) OK in terms of h, a and c ,

Hence, if → = 10 a + 5c , find the value of h.`

KB

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

123 The diagram shows a map of part of Telipok District, with the condition that all roads are straight. The
mosque is equidistance from the school and the Community Hall, while the fountain is equidistance from
the bus station and the mosque.

Bus Station

Library

Fountain

School Mosque Community Hall

The Telipok District Council has decided to build a straight road from the school to the library through the
fountain. The distance from the school to the library is k times the distance from the school to the
fountain. The distance from the Community Hall to the library is twice the distance from the library to the

bus station. Given that the displacement of bus stations and mosques from the school is u and v

~~

respectively.

(a) Find the value of k. (Ans : 4 ) [5 marks]
3

(b) Given that the cost of road construction from school to fountain is RM600000. Find the cost, in
RM, of the construction of the same type of road from the fountain to the library. (Ans : 200000)
[2 marks]

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 Part A ~ triangle law 1

124 The diagram shows a triangle OPR and QSP is a straight line.
R

QT

S

O P

It is given that → p, → = q and → = 4 → .

OP = OQ OR OQ

(a) Express in terms of p and q .

(i) → , (Ans : − p + q ) [1 mark]

PQ

→ (Ans : − p + 4 q ) [1 mark]

(ii) PR .

(b) It is given that → = m → and →→

PS PQ PT = k PR .

→→

By using OT = 2 OS , find the value of m and of k.

(Ans : k = 1 , m = 2 ) [5 marks]
33

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

 Part A ~~ triangle law 2

125 The diagram shows a parallelogram PQRS, where L is the midpoint of RS. QR is produced to N such
that QR = RN and QL is produced to meets SN at M.

MS
NP

L

R

Q

→→

It is given that PQ = 3 a and QR = 2 b .

(a) Express in terms of a and / or b :

→ (Ans : 2 b − 3 a )
2
(i) QL ,
(Ans : 3 a + 2 b )
→ [2 marks]

(ii) SN ,

→→ →→ →
(b) Given that QM = h QL and NM = k NS , find QM in terms of

(i) h, a and b , ( Ans : 2h b − 3 h a )
2

(ii) k, a and b . (Ans : 4 b −3k a −2k b )
Hence, find the value of h and of k. (Ans : h = 4 , k = 2 ) [5 marks]

Answer : 33

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

→→

126 The diagram shows a trapezium PQRS. U is the midpoint of PQ and PU = 2 SV . PV and TU are two
straight lines intersecting at W where TW : WU = 1 : 3 and PW = WV.
S VR

T
W

PU Q

→→ →
It is given that PQ = 12 a , PS = 18 b and QR = 18b − 5 a
~~ ~~

(a) Express in terms of a and / or b (Ans : 7 a )
~~ ~
→
(i) SR , (Ans : 3 a + 18 b )
→ ~~
(ii) PV ,
→ (Ans : 3 a + 9 b )
(iii) PW . 2~ ~
[4 marks]

→

(b) Using PT : TS = h : 1, where h is a constant, express PW in terms of h, a
~

and / or b . [ Ans : 3 a + 27h b]
~ 2 2 (h + 1)
~ ~

Hence, find the value of h. (Ans : 2)

[4 marks]

Answer :

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

CONTINUOUS EXERCISES

127 The diagram shows a rectangle OABC and the point D lies on the straight line OB.

CB

5y D

O 9x A

→ [ Ans : k ( 5 y +9x)]
k +1
It is given that OD = kDB. Express OD in terms of k, x and y .
[3 marks] [clon 2007, No.15]
Answer :

128 The diagram shows the point A on the Cartesian plane.
y
A (4, 3)

x
O

(a) → x .
State OA in the form of  
 y 

→

(b) Point A is reflected about the y-axis to point A. It is given OB = i + m j and unit vector of

→ is n  10  , where m and n are constants. Find the value of m and n.
 
A'B  24 

(Ans : m = 15, n = 1 ) [4 marks] [2020, No.14]
26

Answer :

(a)

(b)

JABATAN PENDIDIKAN NEGERI SABAH

MODULE FORM 4 ADDITIONAL. MATHEMATICS (3472)

SOLUTION OF
TRIANGLES

- ONE PAGE NOTE (OPN)
- WORKSHEET

Encik Mohd Salleh Ambo

JABATAN PENDIDIKAN NEGERI SABAH





WORKSHEET
TOPIC 9 : SOLUTION OF TRIANGLES

[ Part C → 10 marks ]

==========================================================================================================================================

9.1 Sine Rule
9.1.1 Make and verify conjectures on the relationship between the ratio of length of sides of a triangle
with the sine of the opposite angles, and hence define the sine rule.

[ the use of digital technology is encouraged ]

9.1.2 Solve triangles involving sine rule.
9.1.3 Determine the existence of ambiguous case of a triangle, and hence identify the conditions for such

cases.
9.1.4 Solve triangles involving ambiguous cases.
9.1.5 Solve problems related to triangles using the sine rule.

9.2 Cosine rule
9.2.1 Verify the cosine rule.
9.2.2 Solve triangles involving the cosine rule.
9.2.3 Solve problems involving the cosine rule.

9.3 Area of a triangle
9.3.1 Derive the formula for area of triangles, and hence determine the area of a triangle.
9.3.2 Determine the area of a triangle using the Heron’s formula.
9.3.3 Solve problems involving areas of triangles .

9.4 Application of sine rule, cosine rule and area of a triangle
9.4.1 Solve problems involving triangles.

==========================================================================================================================================