UNIT 5 : CIRCULAR MEASURE
5.1 Degrees and Radians
LEARNING OUTCOMES Angle in circle can be measured in either in degree (o) or radian (rad).
1 radian is obtained when the value of arc length is equal to the length of
After completing the unit, students radius in a circle.
should be able to:
Relationship between degree and radian
1. Convert angles from
degree to radian and 3600 = 2 rad Central angle
vice versa. 1800 = rad
2. Determine circular 10 = 6π0’ radius, r
Measurement as
arc length, area of 10 =
sector and area of
segment of circle. 180
1rad = 180
π
Figure 5.2
Example 5.1:
Convert each angle given to radian:
a) 600
b) 58.30
Solution: b) 58.30 π
1800
a) 600 π
1800 = 1.02 rad
= 1.047 rad
PRESS MODE RAD 2 Unit 5: Circular Measures
60 SHIFT DRG 1
= 1.047
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UNIT 5 : CIRCULAR MEASURE
Example 5.2 :
Convert each angle given to degree:
a) 0.84 rad
b) 3 rad
2
Solution:
a) 0.84 1800
= 48.130
PRESS MODE RAD 1
0.84 SHIFT DRG 2 = 48.13
b) 3 1800
2
= 85.940
Practice 5.1:
1. Change the following angles in terms of radians:
a. 48o b. 8.50
c. 520 21’ d. 620 9’
e. 123.40 f. 4500 Unit 5: Circular Measures
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UNIT 5 : CIRCULAR MEASURE
2. Change the following angles into degrees
a. 0.8 radian b. 4 π radian
c. 1.24 radian 3
π
e. 1 1 π radian
3 d. radian
2
f. 2 1 radian
4
g. 2.56 radian h. 1 radian
5.2 Arc Length
Consider a circle of radius r with centre O as shown in Figure 5.2. Given θ is the angle
subtended at the centre by the minor arc length.
Minor arc length, s
Major arc length
radius, r
Figure 5.2 Unit 5: Circular Measures
Arc length, s = rθ
where;
r = radius, θ = angle in radian
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UNIT 5 : CIRCULAR MEASURE
Example 5.3 :
5 cm s
1.2 rad
O
Figure 5.3
Figure 5.3 shows a circle with center O, and radius 5 cm. Given angle θ = 1.2 rad. Find the
value of arc length, s.
Solution :
s = rθ
= 51.2
= 6cm
Example 5.4 :
10 cm A
O
720
s
B
Figure 5.4 Unit 5: Circular Measures
Figure 5.4 shows a circle with center O. Given radius = 10 cm and angle AOB = 720. Find
the value of arc length, s.
Solution :
Convert angle in degree to radian,
θ = 720 π
1800
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UNIT 5 : CIRCULAR MEASURE
= 1.26 rad
Then,
s=rθ
= 10 × 1.26 rad
= 12.6 cm
Example 5.5 :
A
r
O 2.6 rad 18.2 cm
B
Figure 5.5
Figure 5.5 shows a circle with center O. Given angle AOB = 2.6 rad and arc length,
s of AB = 18.2 cm. Find the value, r.
Solution:
s=rθ
r = s
θ
= 18.2
2.6
= 7 cm
Unit 5: Circular Measures
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UNIT 5 : CIRCULAR MEASURE
Practice 5.1:
1. Figure 5.3 shows a circle with center O. Evaluate
the value of the arc length of the minor sector
O A AOB if angle AOB = 2 rad and radius OA = OB =
7 cm 2 rad 7cm.
B Figure 5.4 shows a circle with center O,
radius = 5cm and an angle of NOM = 1000. Find
Figure 5.3 the arc length of the minor sector NOM.
2.
N
M
1000
5 cm
O
Figure 5.4
3. Figure 5.5 shows a circle with a center O. Find
the radius of OB if given the arc length of minor
A sector AOB = AOB = 28 cm and the angle of
O 0.7rad AOB = 0.7 radian.
28 cm
B Unit 5: Circular Measures
B
Figure 5.5
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UNIT 5 : CIRCULAR MEASURE Unit 5: Circular Measures
4.
a) Find arc of length, s if r = 7 cm and = 30o .
b) Find arc of length, s if r = 20 cm and = rad.
3
c) Find radius, r if s = 5cm and = 0.6 rad.
d) Find radius, r if s = 8cm and = 2.5 rad.
e) Find angle of if r =9 cm and s = 20 cm.
f) Find angle of if r =5 cm and s = .
82
UNIT 5 : CIRCULAR MEASURE Figure 5.6 shows a sector STU formed from a
piece of a wire with a centre T. If the length of
5. S the wire is 50 m, and the radius of TS = TU = 7
m, find the angle, θ of the sector STU in:
7m a) radian
Tθ
b) degree.
U
Figure 5.6
6. A The figure 5.7 shows a sector OAB of a circle,
5cm Q centre O, formed from a piece of wire of length
19 cm. Given that OA = OB = 5cm, find the angle
θ , in radians.
θ
O
5cm
B
Figure 5.7
Unit 5: Circular Measures
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UNIT 5 : CIRCULAR MEASURE
5.3 Area of Sector
Minor sector 1
Area of sector, A = 2 r2 θ
Major sector
radius, r Where ;
r = radius, θ = angle in
radian
Figure 5.8 r = radius, θ = angle in
Figure 5.7 radian
Example 5.7 :
P
10 cm
O 720
R
Figure 5.8 Unit 5: Circular Measures
Figure 5.8 shows a circle with center O, and radius = 10 cm. Given an angle
POR = 720. Find the area of the shaded region.
Solution:
θ = 720 π
1800
= 1.26 rad
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UNIT 5 : CIRCULAR MEASURE
A = 1 r2θ
2
= 1 102 1.26
2
= 63 cm 2
Example 5.8 :
a. b. S
4.8rad T
7 cm X
Y 00.5.5raradd
6 cm U
Z
Figure 5.9
Calculate the area of the shaded region above.
Solution :
a. Area of the shaded region b. Area of the shaded region
= 1 r2θ = 1 r2θ
2 2
= 1 (7)2 (0.5) = 1 (6)2 (4.8)
2 2
= 12.25 cm2 = 86.4 cm2
Note:Minor sector Note:Major sector
Unit 5: Circular Measures
85
UNIT 5 : CIRCULAR MEASURE Figure 5.9 shows a circle with center O, and radius =
8 cm. Given the angle of a minor sector is 0.4
Practice 5.3 : radian, find the value of the shaded region.
1.
8 cm
O 0.4 rad
Figure 5.9 Find the area of sector that 20o subtended at the
center of the circle of radius 5 cm. Give your answer
2. correct to two decimal places. (Take = 3142)
5 cm
20o
Figure 5.10
Figure 5.11 shows a circle POQ with a center O,
3. radius OP = OQ = 4.5 cm and an angle of
Q
POQ = 1100. Evaluate:
P 110 0 M
4.5 cm O a) the value of an angle in radian
Figure 5.11 b) the area of minor sector POQ
c) the area of major sector POQ
Unit 5: Circular Measures
86
UNIT 5 : CIRCULAR MEASURE The Figure 5.12 shows a sector OAB of a circle,
centre O and radius 7 cm. given that the area of
4. A
sector OAB is 12.83 cm2. find AOB in degree.
7 cm
O
B The Figure 5.13 shows two arcs, AB and CD, of two
concentric circles, center O, with radius OA and OC
Figure 5.12 respectively. Given that the length of arc AB = 6 cm
, the length of arc CD = 2 cm and the length of OA
B = 12 cm. find
5. C Q
a) the angle in radians,
b) area of the shaded region, ABCD.
O
D
A
Figure 5.13
6. . Figure 5.14 show a part of the circle with centre O.
R a) Calculate the values of r,
b) Find the angle QOP in degree.
Q
r 12cm
1.2rad P
O
Unit 5: Circular Measures
Figure 5.14
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UNIT 5 : CIRCULAR MEASURE
7. Figure 5.15 shows two circle with centre O. Given OB
= 4 cm, BD = 8 cm and CD = 8.376 cm
C D a) Find the angle OAB in degree and radian,
A B
O b) Calculate the perimeter of the shaded portion
ABCD,
c) Calculate the area of the shaded portion
ABCD.
Figure 5.15
8. Figure 5.16 shows two sector with centre O. Given
OB = 5 cm, PB = 4 cm and the area of the sector
P POQ is 15cm2.
B
O a) Find the angle AOB in radian,
AQ b) Calculate the area of the shaded region,
Figure 5.16
c) Calculate the perimeter of the shaded region.
Unit 5: Circular Measures
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UNIT 5 : CIRCULAR MEASURE
5.4 Area of Segment
A
Oθ Segment Area of segment = area of sector AOB – area
of triangle AOB
= 1 r 2θ − 1 r 2 sinθ
22
( )B = 1 r 2 − sin
2
Figure 5.15 1 – angle in radian
Example 5.10 : 2 – angle in degree
Figure 5.12 shows a roundabout with center O, and radius 10 cm. Given an angle AOB of
the roundabout = 720. Find the area of segment AOB.
Solution:
A
10 cm
= O 72o
1800
x720
= 1.26 rad B
Figure 5.12
Area of segment of AOB 1 r2 ( θ1 – sin θ2 )
=
2
= 1 X 102 X (1.26 – sin 720) Unit 5: Circular Measures
2
= 15.45 cm2
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UNIT 5 : CIRCULAR MEASURE A
Practice 5.4 : 10 cm
1. The Figure 5.17 shows a circle with radius 10 cm and AOC = 1.4 rad. O 1.4 rad
a) Convert AOC in degree.
Figure 5.17
b)Find the area of the segment AOC C
2. Figure 2 shows a sector with radius 8 cm and angle 60.2o. B
Find the area of the segment. A
8 cm
60.2o
O
3. Figure 5.18 shows the sector AOB with radius 6 cm B
and centre O. Given the length of arc AB = 4.2 cm.
a. Find the angle AOB in degree and radian, O
A
b. Calculate the area of the shaded region.
Figure 5.18
Unit 5: Circular Measures
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UNIT 5 : CIRCULAR MEASURE
4 cm P 4) Figure 5.19 shows a sector with center O, and radius 4 cm.
O 24 cm Given arc length of PQ = 24 cm.
a) Find the angle POQ in radian and degree,
Q b) Find the area of the shaded region.
Figure 5.19
O 5) Given the value of radius is 11 cm and θ = 1250, find
11 cm θ
Q a) angle in radian
P b) the area of segment POQ.
Unit 5: Circular Measures
91