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Published by mroberg, 2019-06-04 14:32:26

Final Product: Portfolio Martin Roberg

Final Product_ Portfolio - Google Docs

6/4/2019 Final Product: Portfolio - Google Docs

GPE = KE
mgh = .5mv2
72558=.5(50 kg)v2
72558/25=25v2/25
v2=2902.32
v=√2902.32
v=53.87 m/s
The roller coaster would be traveling at a rate of 53.9 m/s at the bottom of the tallest hill.
E. Sun
GPE = KE
mgh = .5mv2
1904300=.5(50 kg)v2
1904300/25=25v2/25
v2=76172
v=√76172
v=276 m/s
The roller coaster would be traveling at a rate of 276 m/s at the bottom of the tallest hill.
Moon
GPE=KE
mgh= .5mv2
11259=.5(50 kg)v2
11259/25=25v2/25
v2=450.36
v=√450.36
v=21.22 m/s
The roller coaster would be traveling at a rate of 21.2 m/s at the bottom of the tallest hill.

VY Canis Majoris
GPE=KE
mgh=.5mv2
17.4584=.5(50 kg)v2
17.4584/25=25v2/25
v2=0.698336
v=√0.698336
v=0.84 m/s
The roller coaster would be traveling at a rate of 0.84 m/s at the bottom of the tallest hill.

Star Wars Planet One
GPE=KE
mgh=.5mv2
81315=.5(50 kg)v2
81315/25=25v2/25
v2=3252.6

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v=√3252.6
v=57.03
The roller coaster would be travelling at a rate of 57 m/s at the bottom of the tallest hill.

Star Wars Planet Three
GPE=KE
mgh=.5mv2
126490=.5(50 kg)v2
126490/25=25v2/25
v2=5059.6
v=√5059.6
v=71.13 m/s
The roller coaster would be travelling at a rate of 71.1 m/s at the bottom of the tallest hill.

Data Table: Velocity
Planet 83.01
Jupiter 41.18
Star Wars Planet Two 53.87
Saturn 276
Sun 21.2
Moon 0.84
Vy Canis Majoris 57
Star Wars Planet One 71.1
Star Wars Planet Three

Graph:

X-axis: Planet
Y-axis: Velocity of Roller Coaster on the planets

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Critical Thinking Questions:
1. What factors affect Gravitational Potential Energy?
2. Why did the GPE change on the other planets?
3. How did the planet affect the velocity of the roller coaster? Explain using data.
4. How does GPE relate to Chemical Potential Energy?
5. How do Energy companies use GPE to generate Electrical Energy? Give an example
6. What happens to the GPE when the object falls to the ground? Describe the Energy
transformations along the way. Use a diagram. (Hint: Think about Mechanical Energy)
7. How is the coal from “October Sky” an example of potential energy?

5. GPE Calculations - Complete the following GPE Word Problems
Worksheet 1:
http://glencoe.mheducation.com/sites/0078600510/student_view0/unit1/chapter4/math_practice_2.html

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Worksheet 2:
http://go.hrw.com/resources/go_sc/ssp/HK1MSW65.PDF
https://web.kamihq.com/web/viewer.html?file=http%3A%2F%2Fgo.hrw.com%2Fresources%2Fgo_sc%2
Fssp%2FHK1MSW65.PDF&source=extension_open_button

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Coal Vs. Hydroelectrics

Notes:
Video 1:
Problem 1

● To find gravitational energy you need 257/310
○ Mass
○ Gravity
○ How high the object is raised (Height)

● Unknown variable
○ Potential energy due to gravity (PEg)

● Formula: PEg=MGH
● In this Problem

○ Mass= 20 kg
○ Gravity= 9.8
○ Height= 3 meters
○ Equation= PEg=(20 kg)(9.8 m/s2)(3 m)
○ Peg=588 Joules

Solution to problem 1:

https://docs.google.com/document/d/1HkEv9wIfqdA1ukjpObgog76L-WDG56qHqhEnq8YyUFY/edit

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Problem 2:

● In this problem 258/310
○ Potential Energy: 108486 Joules
○ Height 30 meters

● Unknown
○ Mass

● Equation:PEg=mgh

https://docs.google.com/document/d/1HkEv9wIfqdA1ukjpObgog76L-WDG56qHqhEnq8YyUFY/edit

6/4/2019 Final Product: Portfolio - Google Docs

● Steps
○ 108486=m(9.8 m/s2)(30 m)
○ 108486=294m
○ m=108486/294
○ m=369 kg

● Check
○ 108486=(369 kg)(9.8 m/s2)(30 m)
○ 108486=108486

● Solution to problem 2:

Video 2:

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● PE=mgh 260/310
● PE= (5 kg)(9.8 m/s2)(1.2 m)
● PE=58.8 Joules

https://docs.google.com/document/d/1HkEv9wIfqdA1ukjpObgog76L-WDG56qHqhEnq8YyUFY/edit

6/4/2019 Final Product: Portfolio - Google Docs

GPE Exit Tickets
4-1-19

Suppose you are on the Planet Hoth with a gravity 17% greater than Earth’s. You observe an
African Elephant with a Mass of 6000 kg on the top of a roller coaster with a height of 76 meters.
How fast would the Elephant be traveling at the bottom of the roller coaster?

Gravity of Planet Hoth= 17% greater than Earth
Gravity of Earth= 10 m/s2
10*1.17=11.6 m/s2
GPE= mgh
GPE=(6000 kg)(11.6 m/s2)(76 m)
GPE=5289600 Joules

4-2-19

Suppose you are on the Planet Hoth with a gravity 29% greater than Jupiter’s (24.7 m/s2). You
observe a Tiger with a Mass of 325 kg on the top of a roller coaster with a height of 35 meters.
How fast would the Tiger be traveling at the bottom of the roller coaster?

Gravity of Jupiter: 24.7 m/s2
Gravity of Planet Hoth: 24.7*1.29
Gravity of Panet Hoth:31.863 m/s2

GPE=mgh
GPE=(325 kg)(31.863 m/s2)(35 m)
GPE=362441.625 Joules

MGH=.5mV2
(325 kg)(31.863 m/s2)(35 m)=.5(325 kg)V2
362441.625=162.5V2

≅√2230.41=√V2

V 47 m/s
The tiger would be traveling at a rate of around 47 m/s

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GPE Quiz Review

QUIZ REVIEW2: GPE/KE

Vocabulary: Study the words from your GPE Project

Scenario: You are an engineer for a major engineering firm that will design the lift motor and
safety restraints for the next roller coaster on the planet Naboo in Star Wars. Naboo has a gravity
equal to 64% greater than Earth’s. The Star Wars Theme Park needs to provide you with the
velocity of the roller coaster on this planet to help you with your design. Your roller coaster will be
called the Millenium Falcon and will have a height of 83 m. Your roller coaster will “The Falcon”
will have a mass of 3,400 kg. You will need to compare the needs for safety on Earth to the
needs on Naboo. Explain your reasoning for the changes on Naboo.

Naboo:

Directions: Provide a data table showing the comparisons between the Millenium Falcon Roller
Coaster on Earth and Naboo. Describe the types of restraints that you would need on the faster
coaster.

Calculations: Naboo

Earth Gravity of Naboo= 1.64(Gravity of Earth)
Gravity of Earth= 10 m/s2 Gravity of Naboo=1.64*10 m/s2
Mass= 3400 kg Gravity of Naboo=16.4 m/s2
Height= 83 m
GPE=mgh Mass= 3400 kg
GPE=(3400 kg)(10 m/s2)(83 m)
GPE=2822000 Joules Height= 83 m
mgh=.5mv2 GPE=(3400 kg)(16.4 m/s2)(83 m)
(3400 kg)(10 m/s2)(83 m)=0.5(3400)v2
2822000=1700v2 GPE= 4628080 Joules
v2=2822000/1700 mgh=.5mv2
v2=1660 (3400 kg)(16.4 m/s2)(83 m)=0.5(3400)v2
4628080=1700v2
v2=4628080/1700

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v=40.75 m/s v2=2722.4
v=52 m/s

Extra Problem:

1. The Millenium Falcon Roller Coaster has a mass of 8500 kg on Planet Tatooine. The
height of the roller coaster is 125 m which results in a Potential Energy of 750,000 J.
What is the gravity on Planet Tatooine?

GPE=mgh
750000 = (8500 kg)(g)(125 m)
750000/1062500 =1062500g/1062500 g
g=0.7058823529

Check:
GPE=mgh
750000=(8500 kg)(0.7058823529 m/s2)(125)
750000 J =750000 J

2. The Tie Fighter Roller Coaster has a height of 115 m. on Planet Hoth. Hoth has a gravity
of 13.2 m/s2. This roller coaster has a Potential Energy of 450,000 J. What is the mass of
the Tie Fighter?

GPE=mgh
450,000=kg(13.2 m/s2)(115 m)
450000/1518=1518/1518 kg
kg=296.4426877

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Check:
GPE=mgh
450,000 J=(296.4426877 kg)(13.2 m/s2)(115 m)
450,000 J=450,000 J

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GPE/KE Notes

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Inclined Plane Project

Due: May 8th, 2019

1. Define the following vocabulary: Use pgs. 124 - 153

Simple Machine Mechanical Work Input Force
Advantage (MA)
Machine that does Transfer of energy The force applied to a
work with only one Ratio of the output
movement- lever, force exerted by a that occurs when a machine
pulley, wheel, and machine to the input
axle, inclined plane, force applied to the force makes an object
screw, and wedge machine
move; measured in

joules

Compound Machine Ideal Mechanical Power Output Distance (OD)
Advantage (IMA)
Two or more simple Amount of work done, The distance an
machines that The mechanical or the amount of output force acts
operate together advantage of a energy transferred, through in a machine
machine without divided by the time
friction required to do the
work or transfer the
energy; measured in
watts (W)

Efficiency Actual Mechanical Input Distance Output Force
Advantage
Ratio of the output The distance through The force exerted on
work done by the The mechanical which the input force an object by a
machine to the input advantage that a acts in a machine machine
work done on the machine provides in a

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machine, expressed real situation
as a percentage

First Class Lever Second Class Lever Third Class Lever Energy

A lever for which the the load is between The input force is The ability to do work
muscle force and the fulcrum and the between the output or cause change
resistive force act on input force; never force and the fulcrum
opposite sides of the changes the direction
fulcrum of the input force

Block and Tackle Fixed Pulley Movable Pulley Fulcrum
Pulley
A pulley that is Pulley moves along The fixed point
A system of pulleys attached to a the rope around which a lever
made of fixed and structure Wheel supports the pivots
moveable pulleys; load
can have large Effort is in the same
mechanical direction as
advantages movement
Reduces the forces
needed to move an
object

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QUIZLET: (Place link here)
https://quizlet.com/393696853/inclined-plane-project-vocab-flash-cards/

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3. Describe the difference between your Ideal Day and an Actual Day:
An ideal day would be a day where I can sleep in, go to school and not have homework carry over
from what was done in the day as well as the work done in class being easy and fun, and after
school being able to relax. While this can and has happened before, normally an actual day would
be wake up early, go to school, have at least one test and a class that isn’t enjoyable, and then

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going home and losing part of the afternoon on homework.
4. What is the difference between Ideal Mechanical Advantage and Actual Mechanical
Advantage? How is this similar to Question #3?

An ideal advantage in something is an advantage that a machine has while removing variables of
things such as friction. The actual mechanical advantage includes these variables, making it more
accurate and as stated in the name, the actual advantage that a machine has.

5. Why can’t you believe a salesman if they attempt you sell you a machine that is 125% efficient?

You can’t believe the salesman if they attempt to sell a machine that is 125% efficient. No item
can be more than 100% efficient, making this machine impossible. While a machine can increase
productivity by 125%, it can never be 125% efficient.

6. Experiment: How does the angle of an inclined plane affect:
Hypothesis: Angle vs. Mechanical Advantage or Angle vs. Efficiency (Use if...then…)
A. Ideal Mechanical Advantage
B. Actual Mechanical Advantage
C. Efficiency
*Think about the scientific Method
DATA TABLE - Use this table to record your lab data

Angle Ideal Mechanical Actual Mechanical Efficiency (%)
Advantage (Input Advantage (Work output/Work
12 degrees Distance/Output
22 degrees (Output Force/Input Input)
Distance) Force)

1.1 1.02 92%
1.16 95%
1.22

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32 degrees 1.3 1.27 98%

***Why is the Actual Mechanical Advantage always less than the Ideal Mechanical
The AMA is always less than the IMA because the IMA removes the factor of friction, while the
AMA keeps that factor.

Conclusion:

*Write your OWN CONCLUSION HERE! Use Data
The Purpose of this experiment was to find how to create a better ramp. My groups hypothesis
was that by increasing the angle of the ramp, the IMA AMA and Efficiency of the ramp would
increase. To do this we set up an experiment with a ramp, a 500 g weight, a spring scale, and a
chair. In this experiment we set the ramp to a 12 degree angle, a 22 degree angle, and a 32
degree angle. From our hypothesis, we expected that the greatest IMA, AMA, and Efficiency
would come from the 32 degree ramp. From the three trials we found that the amount of energy
exerted to move the 500 g weight dropped, lowering the input force. We also found that in return
for making the ramp use up less energy, that the distance walked (the input distance) increased.
From this we found that the 12 degree angle had an IMA of 1.1, an AMA of 1.02, and an efficiency
of 92%. For the 22 degree angle, we found that it had an IMA of 1.22, an AMA of 1.16 and an
efficiency of 95%. Lastly, with the 32 degree angle we found that it had an IMA of 1.3, an AMA of
1.27 and an efficiency of 98%. From this data, we were able to conclude that our hypothesis of an
increased angle would increase the IMA AMA and efficiency was correct.

7. Critical Thinking: Choose a famous skyscraper. This will be your Output Distance. Use
your knowledge of Inclined Planes, Mechanical Advantage, and Efficiency to draw and
label a sketch of all parts of the triangle formed.

Important Info:
A. Ideal Mechanical Advantage: 4.2
B. Actual Mechanical Advantage: 2.7
C. Output Force: 350 kg
Sketch (Use drawing)

8. Complete the Following Worksheet:

Worksheet 2
Effort Force = Input Force
Resistance Force = Output Force

Simple Machines, IMA, AMA, and Efficiency

Worksheet

Effort Force= Input Force

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Resistance Force= Output Force

Ideal Mechanical Advantage- IMA

1. A simple machine would be considered ideal if it had no friction.

IMA= Input Distance Output Force
--------------------- -----------------
Output Distance Input Force

In theory, this IMA should also equal

Actual Mechanical Advantage- AMA

2. Actual machines have friction. They do not have as high of a mechanical
advantage as an ideal machine because some of the efforts are lost in overcoming
friction.

AMA= Actual Measured Output Force
----------------------------------------
Actual Measured Input Force

Efficiency

Efficiency

3.
a. A machine multiplies force. How effective the machine is in that is called efficiency.
b. Efficiency is expressed as a percentage.
c. Effciency can be determined by the following equation:

Efficency= Actual Mechanical Advantage (AMA) *100 OR Work OUT *100
------------------------------------------------ ---------------
Ideal Mechanical Advantage (IMA) Work IN

Inclined Planes

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IMA= Input Distance/Output Distance 295/310
IMA= 24 m/5 m
IMA= 4.8
The IMA of the ramp is 4.8.

IMA= Input Distance/Output Distance
IMA= 18 m/4 m

https://docs.google.com/document/d/1HkEv9wIfqdA1ukjpObgog76L-WDG56qHqhEnq8YyUFY/edit

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IMA= 4.5
The IMA of the ramp is 4.5.

AMA= Output Force/Input Force 296/310
AMA= 325 N/20 N
AMA= 16.25
The AMA of the ramp is 16.25

https://docs.google.com/document/d/1HkEv9wIfqdA1ukjpObgog76L-WDG56qHqhEnq8YyUFY/edit

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6. The efficiency of a machine can be determined by the following equation

IMA= Input Distance/Output Distance 297/310
IMA= 12 m/2 m
IMA= 6

AMA= Output Force/Input Force
AMA= 783 N/150 N
AMA= 5.22
Efficiency= 100(AMA/IMA)
Efficiency=100(0.87)
Efficiency=87%
The ramp is 87% efficient.

https://docs.google.com/document/d/1HkEv9wIfqdA1ukjpObgog76L-WDG56qHqhEnq8YyUFY/edit

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IMA= Effort Distance From Fulcrum/Resistance Distance From
Fulcrum
IMA= 24 m/30 m
IMA= 0.8

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IMA= Effort Distance From Fulcrum/Resistance Distance From
Fulcrum
IMA= 15 m/7 m
IMA=2.14

https://docs.google.com/document/d/1HkEv9wIfqdA1ukjpObgog76L-WDG56qHqhEnq8YyUFY/edit 299/310

6/4/2019 Final Product: Portfolio - Google Docs

AMA=Resistance Force (Weight of Object)/Effort Force
AMA=597 N/75 N
AMA=7.96

AMA=Resistance Force (Weight of Object)/Effort Force 300/310
AMA= 128 N/55 N

https://docs.google.com/document/d/1HkEv9wIfqdA1ukjpObgog76L-WDG56qHqhEnq8YyUFY/edit


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