HEBAT! SPM 2019 Matematik Tg 5

Practice 1 Number Bases 1
Practice 2 5
Practice 3 Asas Nombor 10
Practice 4 19
Practice 5 Graphs of Functions II 27
Practice 6 33
Practice 7 Graf Fungsi II 40
Practice 8 50
Practice 9 Transformations III 57
Practice 10 66
Penjelmaan III 74
A1 – A12
Matrices

Matriks

Variations

Ubahan

Gradient and Area under a Graph

Kecerunan dan Luas di bawah Graf

Probability II

Kebarangkalian II

Bearing

Bearing

Earth as a Sphere

Bumi sebagai Sfera

Plans and Elevations

Pelan dan Dongakan

Forecast Paper
Answers

PRA 3CTICE Transformations III
Penjelmaan III

FORMULAE A SPMnalysis of PAPER ‘11 ‘12 ‘13 ‘14 ‘15 ‘16 ‘17 ‘18
1✓

Questions 2 ✓✓✓✓✓✓✓✓

 1. FSackatloerfsakcatloar,,kk= =PPPAPAA’A’ 2 . ALuraesaimofejim= akg2 e× =luaks2 o×bajerkea of object

Objective Questions PAPER 1 In the diagram given, triangle ABC is the image
of triangle DEF under an enlargement. Find the
3.1 Combination of Two Transformations centre of the enlargement and its scale factor.
Dalam rajah yang diberi, segi tiga ABC
Gabungan Dua Penjelmaan ialah imej bagi segi tiga DEF di bawah satu
pembesaran. Cari pusat pembesaran dan
1. y faktor skala.

3 A E, 3 B H, 3 C E, 2 D H, 2
D2
J 3. Determine the image of point G(–1, 2) under
1 12345
x a reflection in the line x = 0 followed by an
–3 –2 –1–10 A
–2 C enlargement of scale factor 2 with centre (1, 0).
–3
Tentukan imej bagi titik G(–1, 2) di bawah
B–4
–5 pantulan pada garis x = 0 diikuti oleh satu

pembesaran pada pusat (1, 0) dengan faktor

skala 2.

A (1, –2) C (–1, 2)

Determine the image of shape J under a B (1, 4) D (–3, 4)

1 2translation2 followed by a clockwise Questions 4 and 5 are based on the following
–3 statements.
Soalan 4 dan 5 adalah berdasarkan pernyataan yang
rotation of 90° about the origin. berikut.

Tentukan imej bagi bentuk J di bawah translasi
1 22
–3 diikuti oleh putaran 90° ikut arah jam 1 2G is a translation6 .
–3
pada asalan.
1 2G ialah translasi6
2. H –3 .

D H is an anticlockwise rotation of 90° at centre (0, 4).
H ialah putaran lawan arah jam melalui 90° pada
pusat (0, 4).

A 4. State the coordinates of the image of point
EF

K(3, 5) under the combined transformation GH.

Nyatakan imej bagi titik K(3, 5) di bawah

BC gabungan penjelmaan GH.

A (7, 2) C (1, 1)

B (5, 4) D (–4, 4)

© Penerbitan Pelangi Sdn. Bhd. 10

5. State the coordinates of the image of point Mathematics  Form 5 Practice 3 Transformations III 

L(–2, 3) under the combined transformation The diagram given shows two triangles.
Triangle II is the image of triangle I under the
HG. combined transformation of  HOTS
Rajah yang diberi menunjukkan dua segi
Nyatakan imej bagi titik L(–2, 3) di bawah tiga. Segi tiga II ialah imej bagi segi tiga I di
bawah gabungan penjelmaan
gabungan penjelmaan HG. A an enlargement followed by a translation.
pembesaran diikuti oleh translasi.
A (4, 0) C (4, 8) B a translation followed by an enlargement.
translasi diikuti oleh pembesaran.
B (–4, 0) D (7, –1) C a rotation followed by an enlargement.
putaran diikuti oleh pembesaran.
6. y D a reflection followed by an enlargement.
pantulan diikuti oleh pembesaran.
II
The diagram given shows triangles UVW,
I XYZ and ABC drawn on a Cartesian plane.
0x
Rajah yang diberi menunjukkan segi tiga
Subjective Questions PAPER 2 UVW, XYZ dan ABC dilukis pada satah
Cartes.
1. (a) Given S is a reflection in the line x = 1 (i) Given transformation D is a reflection
1 2and T is a translation in the line y = –x and transformation
4 . E is an anticlockwise rotation of 90°
–1 about the origin. ∆ABC is transformed
under combined transformation
Diberi S ialah pantulan pada garis x = 1 ED. Specify a single transformation
1 2dan T ialah translasi which is equivalent to the combined
4 . transformation ED.
–1 Diberi penjelmaan D ialah pantulan
pada garis y = –x dan penjelmaan
State the coordinates of images of E ialah putaran 90° lawan arah jam
pada asalan. ∆ABC diterjelmakan
point (–2, 1) under the following di bawah gabungan penjelmaan ED.
Huraikan satu penjelmaan tunggal
transformations. yang setara dengan gabungan
penjelmaan ED.
Nyatakan imej bagi titik (–2, 1) di bawah (ii) If ∆XYZ is the image of ∆UVW under
transformation F.
penjelmaan yang berikut. Jika ∆XYZ ialah imej bagi ∆UVW di
bawah penjelmaan F.
(i) T 2 (a) Describe in full transformation F.
Huraikan selengkapnya
(ii) S penjelmaan F.

(iii) TS

(b)

y

8B

6

4

W2 V A
C 46
–8 Z–6 –4 Y –2 0 2 x
–2

X
–4

U

11 © Penerbitan Pelangi Sdn. Bhd.

  Mathematics  Form 5 Practice 3 Transformations III The diagram given shows three rhombuses,
MNPQ, RSTU and VWXY, on a Cartesian
(b) Given the area of ∆UVW is 27 cm2, plane. RSTU is the image of MNPQ under
find the area of the shaded region. a transformation Z and VWXY is the image
of RSTU under a transformation A.
Diberi luas ∆UVW ialah 27 cm2,
cari luas kawasan berlorek. Rajah yang diberi menunjukkan tiga rombus,
MNPQ, RSTU dan VWXY, pada satah
2. (a) y Cartes. RSTU ialah imej bagi MNPQ di
4 bawah penjelmaan Z dan VWXY ialah imej
2J bagi RSTU di bawah penjelmaan A.

–8 –4 0 4 I (i) Describe in full, the transformation
–2 x
Huraikan selengkapnya, penjelmaan
8
H (a) Z,

–4 (b) A.
G
(ii) Given that rhombus VWXY represents
The diagram above shows two lines, a region of area 169 cm2, find the
area, in cm2, of the region represented
GH and IJ, on a Cartesian plane. Given by the shaded region.
1 2transformation K is a translation
–3 Diberi rombus VWXY mewakili suatu
3 kawasan yang luasnya 169 cm2,
cari luas, dalam cm2, kawasan yang
diwakili oleh kawasan berlorek.

and transformation L is a clockwise

rotation of 90° about (0, –1). Draw the
image of  HOTS

Rajah di atas menunjukkan dua garis lurus,

GH dan IJ, pada satah Cartes. Diberi
1 2penjelmaan K ialah translasi
–3 dan
3

penjelmaan L ialah putaran 90° ikut arah

jam pada (0, –1). Lukis imej bagi

(i) line GH under the transformation K 2,

garis GH di bawah penjelmaan K2,

(ii) line IJ under combined transformation

KL.

garis IJ di bawah gabungan 3.

penjelmaan KL. F y
6I
(b) B4

y

8 2
Y
G ED A C
X U 6 –8 –6 –4 –2 0 x
T Q 2468

P –2

4 HJ

S R 2 M N x The diagram above shows triangles ABC,
V 0 2 46 ABD, GFE and HIJ on a Cartesian plane.
–6 Rajah di atas menunjukkan segi tiga ABC,
W –4 –2 ABD, GFE dan HIJ pada satah Cartes.

© Penerbitan Pelangi Sdn. Bhd. 12

Mathematics  Form 5 Practice 3 Transformations III 

(a) Transformation K is a reflection in the line 1 2 Penjelmaan T ialah translasi4 dan
1 2 –3
y = 2. Transformation L is a translation –1 . penjelmaan P ialah putaran 90° lawan
3

State the coordinates of image of point D arah jam pada pusat (0, 1). Nyatakan
koordinat bagi imej titik (6, 2) di bawah
under the following transformations. setiap penjelmaan berikut.
(i) Translation T
Penjelmaan K ialah pantulan pada garis Translasi T
1 2y = 2. Penjelmaan L ialah translasi (ii) Rotation P
–1 . Putaran P
3 (iii) Combined transformation P2
Gabungan penjelmaan P2
Nyatakan imej bagi titik D di bawah (b) y

gabungan penjelmaan yang berikut.

(i) KL

(ii) LK

(b) ∆ABD is the image of ∆ABC under 10
transformation M and ∆GFE is the D
image of ∆ABD under transformation N.
8
Describe in full, E B H
∆ABD ialah imej ∆ABC di bawah C
6 G
penjelmaan M dan ∆GFE ialah imej bagi
∆ABD di bawah penjelmaan N. Huraikan A 4I
F
selengkapnya, 2

(i) transformation M,

penjelmaan M, – 10 – 8 – 6 – 4 – 2 0 x
246
(ii) a single transformation which is
The diagram above shows three triangles,
equivalent to the transformation NM.
ABC, FDE and IHG, drawn on a Cartesian
satu penjelmaan tunggal yang setara
plane.
dengan penjelmaan NM.
Rajah di atas menunjukkan tiga segi tiga,
(c) ∆HIJ is the image of ∆ABC under an
ABC, FDE dan IHG, yang dilukis pada
enlargement. suatu satah Cartes.

∆HIJ ialah imej bagi ∆ABC di bawah satu (i) FDE is the image of IHG under the
combined transformation VU. Describe
pembesaran. in full the transformation:

(i) State the coordinates of the centre of

enlargement. FDE ialah imej bagi IHG di bawah
gabungan penjelmaan VU. Huraikan
Nyatakan koordinat pusat pembesaran.

(ii) Given that area of ∆HIJ is 240 unit2, selengkapnya penjelmaan:

calculate the area of ∆ABC. (a) U (b) V

Diberi luas ∆HIJ ialah 240 unit2, (ii) Given triangle IHG represents a region
of area 24 m2, calculate the area, in m2,
hitung luas ∆ABC.

of the region represented by the shaded

region.

Diberi segi tiga IHG mewakili suatu
kawasan yang mempunyai luas 24 m2.
Hitung luas, dalam m2, kawasan yang
diwakili oleh rantau yang berlorek.

4

1 2 4. (a) Transformation T is a translation –3
and transformation P is an anticlockwise
rotation of 90° about the centre (0, 1). State
the coordinates of the image of point (6, 2)
under each of the following transformations.

13 © Penerbitan Pelangi Sdn. Bhd.

  Mathematics  Form 5 Practice 3 Transformations III

1Paper The diagram given shows three quadrilaterals,
ABCD, PQRS and TUVS, drawn on a Cartesian
1. The diagram below shows five trapeziums plane.
SPM Rajah yang diberi menunjukkan tiga buah sisi
drawn on a square grid. P is the object and Q, empat, ABCD, PQRS dan TUVS, yang dilukis
CLONE pada satah Cartes.

2017 R, S and T are the possible images of P under

a transformation.

Rajah di bawah menunjukkan lima buah 1 2 (a) Transformation T is a translation–2
4
trapezium yang dilukis pada grid segi empat .

sama. P adalah objek dan Q, R, S dan T Transformation R is a clockwise

merupakan imej yang mungkin bagi P di rotation of 90° about the centre (1, 1).

bawah satu transformasi. Transformation P is a reflection in the line

y = h.
1 2
R Penjelmaan T ialah translasi –2 .
Q 4

Penjelmaan R ialah putaran 90° ikut arah

S jam pada pusat (1, 1).

Penjelmaan P ialah pantulan pada garis

P T y = h.

Find the image of point (5, 3) under the

following combined transformations:

Which of the following is true? Cari imej bagi titik (5, 3) di bawah
Antara berikut, yang manakah adalah benar?
gabungan penjelmaan yang berikut:

Image Transformation (i) R2
Imej Transformasi
(ii) TR

AQ Reflection [5 marks]
Pantulan
[5 markah]

BR Enlargement (b) (i) TUVS is the image of ABCD under
Pembesaran
a combined transformation WX.

CS Translation Describe in full the transformation
Translasi
TUVS ialah imej bagi ABCD di

DT Rotation bawah gabungan penjelmaan WX.
Putaran
Huraikan selengkapnya penjelmaan

(a) X,

2Paper (b) W.

(ii) It is given that quadrilateral TUVS

1. y represents a region of area 38.5 m2.
12
SPM 10 D Calculate the area, in m2, of the

CLONE RVS C region represented by the shaded
2013 U
region.
SPM T

CLONE
2014

Q 8 B Diberi sisi empat TUVS mewakili

kawasan yang luasnya 38.5 m2.

6 Hitung luas, dalam m2, kawasan yang

4 diwakili oleh kawasan berlorek.
PA
[7 marks]
2
[7 markah]

_10 _8 _6 _4 _2 0 x
246

© Penerbitan Pelangi Sdn. Bhd. 14

Mathematics  Form 5 Practice 3 Transformations III 

(b) The diagram given shows two hexagons
ABCDEF and JKLMNP, drawn on a
Cartesian plane.

Rajah yang diberi menunjukkan dua buah
heksagon ABCDEF dan JKLMNP dilukis
pada suatu satah Cartes.

y
8P

6N J

4F AM

2E CB L K
x
–2 0 D2 4 6 8
10 12 14

2. (a) The diagram below shows point P(3, 0) (i) Hexagon KLMNPJ is the image
SPM of hexagon ABCDEF under the
drawn on a Cartesian plane. combined transformation XY.
CLONE Describe in full the transformation:

2017 Rajah di bawah menunjukkan titik P(3, 0) Heksagon KLMNPJ ialah imej
bagi heksagon ABCDEF di bawah
dilukis pada suatu satah Cartes. gabungan penjelmaan XY. Huraikan
selengkapnya penjelmaan:
y
(a) Y,
5
(b) X.
4
(ii) It is given that hexagon KLMNPJ
3 represents a region with an area of
180 m2. Calculate the area, in m2, of
2 hexagon ABCDEF.

1 P
2468
0 x Diberi bahawa heksagon KLMNPJ
–1 mewakili suatu kawasan yang
–2 mempunyai luas 180 m2. Hitung luas,
dalam m2, heksagon ABCDEF.
–2
[8 marks]

[8 markah]
1 2 Transformation M is a translation –2 .
2

Transformation N is a reflection in the line

y = x.

State the coordinates of the image

of P under each of the following

transformations:
1 2 Penjelmaan M ialah satu translasi
–2 .
2

Penjelmaan N ialah pantulan pada garis

y = x.

Nyatakan koordinat imej bagi titik P di

bawah setiap penjelmaan berikut:

(i) M2,

(ii) MN.

[4 marks]

[4 markah]

15 © Penerbitan Pelangi Sdn. Bhd.

  Mathematics  Form 5 Practice 3 Transformations III

3. (a) y Pentagon KLMNJ ialah imej
6 bagi pentagon ABCDE di bawah
SPM gabungan penjelmaan VU. Huraikan
selengkapnya penjelmaan
CLONE
2015 (a)  U, (b) V.

4 [5 marks]

2 [5 markah]

–4 –2 0 x (ii) Given pentagon ABCDE represents
R –2 24 a region of area 32 m2. Calculate the
area, in m2, represented by the shaded
The diagram above shows point R drawn region.

on a Cartesian plane. Diberi pentagon ABCDE mewakili
1 2 Transformation S is a translation suatu kawasan yang luasnya 32 m2.
–2 . Hitung luas, dalam m2, yang diwakili
4 oleh kawasan yang berlorek.

Transformation T is a clockwise rotation [3 marks]

of 90° about centre (1, 0). [3 markah]

State the coordinates of the image of point

R under the following transformations.

Rajah di atas menunjukkan titik R yang

dilukis pada satah Cartes.
1 2 Penjelmaan S ialah translasi
–2 .
4

Penjelmaan T ialah putaran 90° ikut arah

jam pada pusat (1, 0).

Nyatakan koordinat bagi imej titik R di

bawah setiap penjelmaan yang berikut.

(i) TS (ii) ST

[4 marks]

[4 markah]

(b)

y
8K

6 L M
N
CB A4 F GH

D E2 J I

–6 –4 –2 0 x 4. y
2 4 6 8 10 12 10
SPM
The diagram above shows three pentagons, 8
ABCDE, FGHIJ and KLMNJ, drawn on a CLONE
Cartesian plane. 2012 6

Rajah di atas menunjukkan tiga pentagon, 4 P x
ABCDE, FGHIJ dan KLMNJ, yang dilukis M
pada satah Cartes. 2
2 4 6 8 10
(i) Pentagon KLMNJ is the image of –4 –2 0 L
pentagon ABCDE under the combined –2
transformation VU. Describe in full, K
the transformation –4

© Penerbitan Pelangi Sdn. Bhd. 16

Mathematics  Form 5 Practice 3 Transformations III 

The diagram given shows three pentagons, K,
L and M, drawn on Cartesian plane.

Rajah yang diberi menunjukkan tiga buah
pentagon, K, L dan M, dilukis pada satah
Cartes.

(a) Transformation R is a rotation of 90°

anticlockwise about centre (2, 1).

Transformation S is a reflection in the

straight line y = 6.
1 2 Transformation T is a translation
–4 .
1

State the coordinates of the image of

point P under each of the following

transformations.

Penjelmaan R ialah putaran 90° lawan

arah jam pada pusat (2, 1).

Penjelmaan S ialah pantulan pada garis

lurus y = 6. 5. y
1 2 Penjelmaan T ialah translasi 10
–4 . SPM U
1
CLONE
2012

Nyatakan koordinat bagi imej titik P di 8Q

bawah setiap penjelmaan yang berikut. 6
SR
(i) T
4
(ii) TS

(iii) SR 2 P
T 68
[5 marks] –6 –4 –2 0 V x
24 10 12
[5 markah]

(b) (i) M is an image of K under combined The diagram above shows three triangles,
transformations WV. Describe in full
the transformation PQR, SQR and TUV, drawn on a Cartesian

M ialah imej bagi K di bawah plane.
gabungan penjelmaan WV. Hurai
selengkapknya penjelmaan Rajah di atas menunjukkan tiga segi tiga, PQR,

(a) V, (b) W. SQR dan TUV, yang dilukis pada satah Cartes.
(ii) Given that K represents a region of
(a) Given transformation M is a rotation of
area 36 m2. Find the area, in m2, of a
region represented by M. 90° anticlockwise about the centre O and
Diberi bahawa K mewakili rantau 1 2transformation N is a translation
yang mempunyai luas 36 m2. Cari 1 .
luas, dalam m2, bagi rantau yang 2
diwakili oleh M.
State the coordinates of the image of point
[7 marks]
R under each of the following combined
[7 markah]
transformations.

Diberi penjelmaan M ialah putaran 90°,

ikut lawan arah jam pada pusat O dan
1 2penjelmaan N ialah translasi
1 .
2

Nyatakan koordinat imej bagi titik R di
bawah setiap gabungan penjelmaan yang
berikut.
(i) N2
(ii) NM

[4 marks]

[4 markah]

17 © Penerbitan Pelangi Sdn. Bhd.

  Mathematics  Form 5 Practice 3 Transformations III

(b) (i) Triangle TUV is the image of triangle
PQR under the combined transformation
AB. Describe in full, the transformation

Segi tiga TUV ialah imej bagi
segi tiga PQR di bawah gabungan
penjelmaan AB. Huraikan
selengkapnya penjelmaan

(a) B,
(b) A.
(ii) Given triangle PQR represents a

region of an area 20 m2. Calculate the
area, in m2, represented by the shaded
region.
Diberi segi tiga PQR mewakili suatu
kawasan yang luasnya 20 m2. Hitung
luas, dalam m2, yang diwakili oleh
kawasan yang berlorek.
[8 marks]

[8 markah]

1. y
10 C
A
8
6B

4

2

0 x
2 4 6 8 10

(a) Given transformation K is a clockwise rotation of 90° about the origin and L is a reflection in the
line y = –x. Find the coordinates of the image of the point P(3, 1) under the following combined
transformations.

Diberi penjelmaan K ialah putaran 90° arah jam pada pusat asalan dan L ialah pantulan pada garis
y = –x. Cari koordinat bagi imej bagi titik P(3, 1) di bawah gabungan penjelmaan.
(i) KL
(ii) K2

(b) In the diagram above, ABC is a triangle. P is a reflection in the line y = 5 and Q is a reflection in the line
x = 5.

Dalam rajah di atas, ABC ialah sebuah segi tiga. P ialah pantulan pada garis y = 5 dan Q ialah
pantulan pada garis x = 5.
(i) Draw the image of ∆ABC under the combined transformation QP.
Lukis imej ∆ABC bagi di bawah gabungan penjelmaan QP.
(ii) Describe a single transformation which is equivalent to QP.
Huraikan selengkapnya satu penjelmaan tunggal yang setara dengan QP.

© Penerbitan Pelangi Sdn. Bhd. 18

1CTICE Number Bases 2. (a) –3 3
Asas Nombor
PRA

–4 4

Objective Questions PAPER 1 y
(b), (d) 

1. C 2. D 3. B 4. A 5. A 15 y =1–x2 y = 2x
6. A 7. B 8. B 9. D 10. C 10 x
11. D 12. B 13. B 14. A 15. B
16. D 17. D 18. B 19. B 20. A 5 4.5 4
21. A 22. B 23. B 24. A 25. D
26. C 27. D – 4 – 3 – 2 –1 0 1.2
y =1–x2
123

–5

Subjective Questions PAPER 2 –10

1. (a) 1510, 1610, 1710 (c) (i) 4.5
(b) 14410, 14510, 14610 (ii) 1.2
(d) –2.5, 2.5
2. (a) 4 × 53 + 2 × 52 + 3 × 51 + 1 × 50
(b) 56610 1Paper 2. D 3. D 4. D 5. A

3. (a) 4 1. D 6 9 12 15
4. (a) 40305 6. D –3 –2 –1.5 –1.2

(b) 10038 2Paper
5. (a) 2

(b) 100100112
6. 3215, 3225, 3235, 3245

1Paper 1. (a)

1. A x1 23 4 5
6. C
2. D 3. C 4. D 5. D y –18 –9 –6 – 4.5 –3.6
7. A 8. B
9. C 10. B (b) y

1.2 1.6 4 10.3 x

1. 156; 100111002 02 6 8 10 12 14 16
2. (a) k = 3 –2
y = – 18
(b) 14105 –2.2 x

PRA2CTICE Graphs of Functions II –4 y = x – 12
Graf Fungsi II
–6
Objective Questions PAPER 1
–8
1. A 2. A 3. B 4. A 5. B
6. C 7. B 8. D 9. A 10. D –10

Subjective Questions PAPER 2 –12

1. (a) m = –9, p = –3 –14
(b) y
–16
y = 2x – 8
–18
x
y = –x + 8 –20

x = –3 4

–3 0 (c) (i) y = –2.2
(ii) x = 1.2
8 (d) x = 1.6, 10.3



A1 © Penerbitan Pelangi Sdn. Bhd.

  Mathematics  Form 5 Answers

2. (a) 1 2 2.5 3 (d) (i) 62 cm2
x – 4 –3 –2 –1 0 2 –7 –15.625 –28 (ii) 53.2 cm2
y 77 38 17 8 5 (iii) 2.3 cm
PRA
(b) y 3CTICE Transformations III
Penjelmaan III

80 Objective Questions PAPER 1

70 1. B 2. D 3. B 4. B 5. C
6. C
60

50 Subjective Questions PAPER 2

40 1. (a) (i) (6, –1)

(ii) (4, 1)

30 (iii) (8, 0)

20 (b) (i) A reflection in the line y = 0.
Pantulan pada garis y = 0.
1.75 —31
–1.75 10 1.9 (ii) (a) F is an enlargement of scale factor with
centre (–5, –2).
123 x —31
–4 –3 –2 –1 0–1.4 4 F ialah pembesaran dengan faktor skala
–10 pada (–5, –2).

–20 y = –5x + 5 (b) 24 cm2

–30 2. (a) y
HЈ 4

(c) (i) –1.4 (ii) 1.9 GЈ JЈ 2 J

(d) x = –1.75, 1.75, 0 –8 –4 0 I x
IЈ –2 8
–4 4 H
G
1 2 1 2 1. (a) L = (8 × 10) –1 1
2 ×x×x – 2 × 4 × (10 – x)

= 80 – 1 x2 – 20 + 2x
2
1 x2 (b) (i) (a) Z is a reflection in the line x = –0.5.
= 60 + 2x – 2 Z ialah pantulan pada garis x = –0.5.

(b) x = 2; y = 62 (b) A is an enlargement of scale factor 2 with
x = 4; y = 60 centre (– 4, 3).
x = 7; y = 49.5
A ialah pembesaran dengan faktor skala 2
(c) y pada (– 4, 3).

(d)(i) (ii) 126.75 cm2
62
3. (a) (i) (–6, 0) (ii) (– 6, 6)

60 (b) (i) M is a reflection in line AB.
M ialah pantulan pada garis AB.
58
1 2 1 2 –6 –6
56 (d)(iii) (ii) Translation 0 . / Translasi 0.
(d)(ii)
54 (c) (i) (–5, 3)
53.2
(ii) 26 —23 unit2
52

50 4. (a) (i) (10, –1)
(ii) (–1, 7)
48 (iii) (–6, 0)

46 (b) (i) (a) A reflection in the line x = –1/ Pantulan pada
garis x = –1
44
(b) An enlargement of scale factor 2 with the
42 centre (– 4, 5). / Pembesaran dengan faktor
skala 2 pada (– 4, 5).
40 0 1 2 3 4 5 6 7 8 x

5.7

© Penerbitan Pelangi Sdn. Bhd. A2

Mathematics  Form 5 Answers 

(b) (i) y

1Paper 10 C A
8
1. C B
6
2Paper

1. (a) (i) (–3, –1) 4 B´
(ii) (1, 1)
2 A´
(b) (i) (a) X is a reflection in the line x = –2.5.
X ialah pantulan pada garis x = –2.5. C´
—21 0 x
(b) W is an enlargement of scale factor with
centre S(–6, 10). 2 4 6 8 10

W ialah pembesaran pada S(–6, 10) dengan (ii) Rotation of 180° about (5, 5).
faktor skala —21 . Putaran 180° pada (5, 5).

(ii) 115.5 m2 PRA 4CTICE Matrices
Matriks
2. (a) (i) (–1, 4)
Objective Questions PAPER 1
(ii) (–2, 5)
1. C 2. B 3. A 4. C 5. C
(b) (i) (a) Y is a clockwise rotation 90° about the centre 6. D 7. B 8. C 9. B 10. D
(6, 0). 11. C 12. A 13. C 14. D 15. A
16. D 17. A 18. A 19. C 20. A
Y ialah putaran 90° mengikut arah jam pada
pusat (6, 0). Subjective Questions PAPER 2

(b) X is an enlargement of scale factor 2 about
L.

X ialah pembesaran pada L dengan faktor
skala 2.

(ii) 45 m2

3. (a) (i) (4, 5) 1. (a) –1 (b) d = 3, e = –2

(ii) (–2, 7) 1 25 4 (b) f = –5, g = 1
(b) (i) (a) U is a reflection at the y-axis. –1
U ialah pantulan pada paksi-y. 2. (a) 3

(b) V is an enlargement of scale factor 3 with 1 3. (a) R = – —113 2—123
centre J. —256
—236
V ialah pembesaran dengan faktor skala 3
pada pusat J. (b) h = –1, k = 3

(ii) 256 m2

4. (a) (i) (–1, 4) 4. Red pen / Pen merah = RM0.85
(ii) (–1, 10) Blue pen / Pen biru = RM0.70
(iii) (0, 10)
1 2 1 2 5. (a)
(b) (i) (a) V is a reflection in the line x = 2. 1 (b) –—1—21313 ——113533
V ialah pantulan pada garis x = 2. –9

(b) W is an enlargement at centre (1, – 6) with 1 2 1 2x 2
scale factor 2.
6. y = 1.5
W ialah pembesaran pada (1, – 6) dengan
faktor skala 2. Price of a packet of nasi lemak at stall A, x = RM2.00
Hargar bagi sebungkus nasi lemak di gerai A, x = RM2.00
(ii) 144 m2
Price of a packet of nasi lemak at stall B, y = RM1.50
5. (a) (i) (9, 9) Harga bagi sebungkus nasi lemak di gerai B, y = RM1.50
(ii) (– 4, 9)
7. (a) p = –3, r = –8
(b) (i) (a) B is a reflection in the line UV. (b) x = –9, y = 11
B ialah pantulan pada garis UV.
(b) A is an enlargement of scale factor 3 with 1 21 0

centre (9, 7). 8. (a) U = 0 1
A ialah pembesaran pada (9, 7) dengan skala (b) q = –2, r = 4

3. 1 9. (a) – —97 2—78
(iii) 160 m2 —72
– —71


1. (a) (i) (–3, 1) 1 24 –1
(ii) (–3, –1)
(b) 1 2

A3 © Penerbitan Pelangi Sdn. Bhd.

  Mathematics  Form 5 Answers

1 212 Subjective Questions PAPER 2

10. (a) 10 1. (a) 135
(b) w = –3, x = –2 (b) 5

14 2 2 2. (a) 0.75
3
11. (a) 5 (b) 64

13 2 1 2 1 2–2 p = –8 ; p = 2, q = 7 3. (a) p = —2q1— 26
q 18 (b) 6
(b) –5 4

12. (a) k = – —118 , l = –7 (b) m = 2, n = 6 4. a = 15, x = 3 , y = 1
8 3
5. 225
6. (a) a = —6z4— 3y
1Paper (b) 1.25

1. A 2. C 3. D 4. D 5. C
6. A 7. C 8. A 9. C

2Paper 1Paper

1. (a) m = –5, n = 9 1. A 2. A 3. A 4. B 5. B
6. B 7. C 8. B 9. B 10. C
1 2 1 2 1 29 5 x = 1 ; x = 4, y = –7
y –2
(b) 3 2

2. (a) m = –13, n = –2

1 2 1 2 1 2(b) x 4 1. 15 days / 15 hari
5 –1 y = –14  ; x = 2, y = 6
2 –3 6CTICE Gradient and Area under a Graph
Kecerunan dan Luas di bawah Graf
1 2 3. (a) —148 –4 PRA
–5 3

(b) Price of a blue pen / Harga sebatang pen biru = RM2;
price of a black pen / Harga sebatang pen hitam =

RM1.50 Objective Questions PAPER 1

1 2 1 2 1 26 1 x = 69 ; x = 9.50, y = 12.00 1. D 2. A 3. A 4. D 5. B
y 62 6. D 7. C 8. A 9. D 10. B
4. 4 2 11. D

Price of a child ticket = RM9.50
Harga bagi sekeping tiket kanak-kanak = RM9.50

Price of an adult ticket = RM12.00 Subjective Questions PAPER 2
Harga bagi sekeping tiket dewasa = RM12.00
1. (a) 10 s (b) –3.5 m s–2
5. (a) x + y = 12; 40x + 38y = 470 (c) 14
(b) x = 7, y = 5
2. (a) 3.2 m s–1 (b) 131 m

3. (a) 46 (b) 532.5 m

1 2 1 3 –5 4. (a) 0.5 h / j
1. (a) M–1 = 2   –2 4 (b) 81 km h–1 / 81 km j–1

(b) Price of a piece of cupcake A = RM5 (c) (i) 44 km

(ii) 0.9 h / j

Price of a piece of cupcake B = RM1 5. (a) 20 (b) 34

Harga sebiji kek cawan A = RM5 6. (a) 30 km
Harga sebiji kek cawan B = RM1 (b) 80 km h–1 / 80 km j–1

(c) 45

PRA 5CTICE Variations
Ubahan
2Paper
Objective Questions PAPER 1
1. (a) 15 s
1. D 2. B 3. D 4. B 5. B (b) –1 —13 m s–2
6. B 7. C 8. C 9. B 10. C (c) v = 12
11. B 12. C 13. C 14. B 15. C
16. B 17. A 18. C 19. B 20. C 2. (a) 8 m s–1
21. B (b) 1—31 m s–2
(c) t = 24

© Penerbitan Pelangi Sdn. Bhd. A4

Mathematics  Form 5 Answers 

3. (a) Farah (b) 15 s
(c) 110 m (d) 40 s

4. (a) (i) h = 145 1Paper 2. B 3. D 4. C 5. C
k = 170
(ii) 1. D Outcome of card picked
Distance (km) 6. A Kesudahan kad terpilih
Jarak (km) D I ME
2Paper
320
1. (a)

PRA h= H (H, D) (H, I) (H, M) (H, E)
145
Outcome of coin tossed
Kesudahan duit syiling0 130Time (min)T (T, D)(T, I) (T, M) (T, E)
k = 170 250 Masa (min)
dilambung
(b) 76.8 km h–1 / 76.8 km j–1 M)}; —14
I), (H, M),
(b) (i) {(H, M), (T, (H, E), (T, E)}; —58
(ii) {(H, D), (H,

1. (a) The two vehicles meet at 62.5 km from town X at 0926. 2. (a) {(1, B), (2, B) , (3, B) , (4, B), (5, B), (6, B) ,
Kedua-dua kenderaan bertemu di 62.5 km dari bandar  (1, G) , (2, G), (3, G), (4, G) , (5, G) , (6, G),
X pada 0926.  (1, Y), (2, Y) , (3, Y), (4, Y) , (5, Y), (6, Y) }
(b) t = 1100
(c) 40 km h–1 / 40 km j–1 (b) (i) {(1, Y), (2, Y)}; —19
(ii) {(1, B), (2, B), (3, B), (4, B), (5, B), (6, B),
7CTICE Probability II
Kebarangkalian II (3, G), (4, G), (5, G), (6, G), (3, Y), (4, Y), (5, Y),
(6, Y)};—79

Objective Questions PAPER 1 3. (a) {(1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 3), (2, 4), (2, 5),
(3, 1), (3, 2), (3, 4), (3, 5) (4, 1), (4, 2) (4, 3), (4, 5)
1. D 2. A 3. B 4. A 5. D (5, 1), (5, 2) (5, 3), (5, 4)}
6. D 7. A 8. A 9. C 10. B
11. C 12. C 13. D 14. D 15. A (b) (i) {(2, 1), (2, 3), (2, 4), (2, 5), (4, 1), (4, 2) (4, 3),
16. A 17. D 18. A 19. D 20. B (4, 5)}; —25

Subjective Questions PAPER 2 (ii) {(1, 2), (1, 4), (3, 2),(3, 4), (5, 2), (5, 4)} ; 1—30

1. (a) —15 4. (a) First hit Second hit Outcomes
(b) (i) —3190 Pemanahan Pemanahan Kesudahan
pertama kedua
(ii) —23 AA
A

2. (a) 29 (b) 513425 (c) —92 AB AB
114
C AC
3. (a) —6203 (b) —2116 A BA

4. (a) {(Banana, Orange), (Durian, Orange), (Apple, BB BB
Orange)} /
{(Pisang, Oren), (Durian, Oren), (Epal, Oren)}, —15 C BC
A CA
(b) {(Banana, Coca Cola), (Banana, Mineral water),
(Durian, Coca Cola), (Durian, Mineral water), CB CB
(Orange juice, Orange), (Soya bean, Orange),
(Apple, Coca Cola), (Apple, Mineral water)} / C CC
{(Pisang, Coca Cola), (Pisang, Air mineral), (Durian,
Coca Cola), (Durian, Air mineral), (Jus oren, Oren), (Air (b) (i) —13 (ii) —59
soya, Oren), (Epal, Coca Cola), (Epal, Air mineral)}, —185

A5 © Penerbitan Pelangi Sdn. Bhd.

  Mathematics  Form 5 Answers

5. (a) (i) {(Ali, Muthu), (Ali, Chong), (Ali, Susan), RM200), (Tunai RM300, Baucer hadiah RM400),
(Ali, Nora), (Kavitha, Muthu), (Kavitha, (Tunai RM300, Baucer hadiah RM800), (Tunai
Chong), (Kavitha, Susan), (Kavitha, Nora), RM500, Baucer hadiah RM200), (Tunai RM500,
(Mary, Muthu), (Mary, Chong), (Mary, Susan), Baucer hadiah RM400), (Tunai RM500, Baucer
(Mary, Nora)} hadiah RM600), (Tunai RM500, Baucer hadiah
RM800)}; 11—12
(ii) —21

(b) (i) {(Ali, Kavitha), (Ali, Mary), (Ali, Susan),
(Ali, Nora), (Muthu, Kavitha), (Muthu, Mary),
(Muthu, Susan), (Muthu, Nora), (Chong, Kavitha),
(Chong, Mary), (Chong, Susan), (Chong, Nora)} 1. (a) 3
5
(ii) —31
(b) (i) 130 (ii) 5230

6. (a) {(Angela, Edward), (Angela, Farhan), (Angela, Gerry), PRA 8CTICE Bearing
(Bily, Edward), (Billy, Farhan), (Billy, Gerry),
Bearing
(Chong, Edward), (Chong, Farhan), (Chong, Gerry),
(Din, Edward), (Din, Farhan), (Din, Gerry)} Objective Questions PAPER 1

(b) —16 1. A 2. C 3. D 4. D 5. A
6. B 7. A 8. B 9. C 10. B
(c) The probability Billy and Din on duty together is 0 11. A 12. A 13. B 14. B 15. A
because both of them are from the same class. 16. B 17. D 18. B 19. C 20. D
21. B 22. B 23. D
Kebarangkalian Billy dan Din bertugas bersama ialah
0 kerana mereka berdua adalah dari kelas yang sama.

7. (a) {(Cash RM100, Gift voucher RM200), (Cash RM100, Subjective Questions PAPER 2
Gift voucher RM400), (Cash RM100, Gift voucher
RM600), (Cash RM100, Gift voucher RM800), (Cash 1. (a) 228° (b) 146° (c) 190°
RM300, Gift voucher RM200), (Cash RM300, Gift 2. (a) 080° (b) 260°
voucher RM400), (Cash RM300, Gift voucher RM600), 3. (a) 266° (b) 176°
(Cash RM300, Gift voucher RM800), (Cash RM500, 4. (a) 251° (b) 113°
Gift voucher RM200), (Cash RM500, Gift voucher 5. (a) (i) 275°
RM400), (Cash RM500, Gift voucher RM600), (Cash (ii) 125°
RM500, Gift voucher RM800) (b) 28 km

{(Tunai RM100, Baucer hadiah RM200), (Tunai RM100, 6. (a) 232°
Baucer hadiah RM400), (Tunai RM100, Baucer hadiah 7. (a) 245°
RM600), (Tunai RM100, Baucer hadiah RM800), (Tunai (b) 352° (c) 112°
RM300, Baucer hadiah RM200), (Tunai RM300, Baucer (b) 115°
hadiah RM400), (Tunai RM300, Baucer hadiah RM600),
(Tunai RM300, Baucer hadiah RM800), (Tunai RM500,
Baucer hadiah RM200), (Tunai RM500, Baucer hadiah
RM400), (Tunai RM500, Baucer hadiah RM600), (Tunai
RM500, Baucer hadiah RM800)}

(b) (i) {(Cash RM100, Gift voucher RM200), (Cash 1Paper

RM100, Gift voucher RM400), (Cash RM100, 1. D
6. B
Gift voucher RM600), (Cash RM100, Gift 2. A 3. D 4. A 5. D

voucher RM800), (Cash RM300, Gift voucher

RM400), (Cash RM500, Gift voucher RM400)} 1. (a) (i) 160° (ii) 200°
{(Tunai RM100, Baucer hadiah RM200), (b) 23.94 m

(Tunai RM100, Baucer hadiah RM400), (Tunai PRA 9CTICE Earth as a Sphere
RM100, Baucer hadiah RM600), (Tunai RM100, Bumi sebagai Sfera
Baucer hadiah RM800), (Tunai RM300, Baucer
hadiah RM400), (Tunai RM500, Baucer hadiah
RM400)}; —21

(ii) {(Cash RM100, Gift voucher RM200), (Cash Objective Questions PAPER 1
RM100, Gift voucher RM400), (Cash RM100,
Gift voucher RM600), (Cash RM100, Gift 1. B 2. B 3. A 4. C 5. B
voucher RM800), (Cash RM300, Gift voucher 6. D 7. D 8. B 9. C 10. C
RM200), (Cash RM300, Gift voucher RM400), 11. A 12. A 13. C 14. D 15. C
(Cash RM300, Gift voucher RM800), (Cash
RM500, Gift voucher RM200), (Cash RM500, Subjective Questions PAPER 2
Gift voucher RM400), (Cash RM500, Gift
voucher RM600), (Tunai RM500, Gift voucher 1. (a) 92°W / B
RM800)} (b) 7 680 nautical miles / batu nautika
(c) 3 127.80 nautical miles / batu nautika
{(Tunai RM100, Baucer hadiah RM200), (Tunai
RM100, Baucer hadiah RM400), (Tunai RM100,
Baucer hadiah RM600), (Tunai RM100, Baucer
hadiah RM800), (Tunai RM300, Baucer hadiah

© Penerbitan Pelangi Sdn. Bhd. A6

(d) 8 hours / jam CTICE Mathematics  Form 5 Answers 

2. (a) (i) 150°E / T PRA 10 Plans and Elevations
(ii) 2160 nautical miles Pelan dan Dongakan
2160 batu nautika
(b) 9°S Objective Questions PAPER 1
(c) (i) 1520.36 nautical miles
1520.36 batu nautika 1. A 2. C 3. C 4. C 5. A
(ii) 10.6 hours/10.6 jam 6. A

3. (a) 167°W / B L 53°N / U Subjective Questions PAPER 2
(b) N / U
(The following diagrams are not drawn to full-scale.)
M Rajah-rajah yang berikut tidak dilukis mengikut skala penuh.

Q

O 1. (a) T/B Q U C

P Equator / Khatulistiwa

S 13°E / T 14 cm

(53°S, 167°W) / (53°S, 167°B) R/A P S D
4 cm 4 cm 6 cm
(c) 8 580 nautical miles / batu nautika
(d) (i) 4 800 nautical miles / batu nautika
(ii) 119°56W / B

4. (a) T(40°N / U, 152°E / T) (b) P/Q
(b) (i) x = 12° (ii) y = 76°
(d) 10.1 hours / jam 5 cm 5 cm
R/T S/U
8 cm

8 cm 10 cm

1Paper A/B 14 cm D/C

1. A 2. C 3. D 4. B 5. A 2. (a) (b)
6. B 7. A
F/ E/P 4 cm R/Q F
2Paper 1 cm 5 cm R/ E 2 cm Q/ P
N
1. (a) (35°S, 150°W) / (35°S, 150°B) G/N G
(b) 85°W / B
(c) 3 195 nautical miles / batu nautika 6 cm 3 cm 4 cm 3 cm 6 cm
(d) 11.03 hours / jam H / M S K/ L L/S/M
K/H
2. (a) (80°S, 30°W)/(80°S, 30°B) 2 cm 2 cm C/ T/D U/ V
(b) 3 600 nautical miles / batu nautika B/A
(c) 1 667.02 nautical miles / batu nautika A/ D/V 4 cm T/ U 1 cmB/ C
(d) 82.5°N / U
3. (a) V

3. (a) 110°W / B 4 cm
(b) 78°W / B
(c) 4 800 nautical miles / batu nautika I/ J H/ G 3 cm E / F
(d) (i) 6 000 nautical miles / batu nautika
(ii) 11.67 hours / jam

4. (a) 150°W / B 3 cm
(b) 25°N / U
(c) 6 600 nautical miles / batu nautika A/B 6 cm D/ C
(d) (i) 3 932 nautical miles / batu nautika
(ii) 697.41 knot (b) (i) (ii)

5. (a) 155°E / T VK L
(b) 4 987 nautical miles / batu nautika
(c) 44°S I/A 4 cm J/ B
(d) 14.93 hours / jam
V
3 cm
H K/G/P L /N E/H/I F/Q/G/J 7 cm

1. (a) (i) 128°E / T (ii) q = 92° E/D 3 cm 3 cm 2 cm
(b) (i) 1 838.51 nautical miles / batu nautika F/C 2 cm M D/A 4 cm C/P/B M/N
(ii) 6 000 nautical miles / batu nautika
(c) 10.75 hours / jam

A7 © Penerbitan Pelangi Sdn. Bhd.

  Mathematics  Form 5 Answers

3. (a) D H G/L/C

2Paper 5 cm

1. (a) (i) H/A 2 cm G 2 cm F 2 cm E/D AE K/I

2 cm 6 cm F/J/B 6 cm



6 cm (b) (i) M/N

J /B K L M/C 4 cm P/R
E/H 6 cm F/G
(ii) F/E L /M 6 cm K
4 cm
4 cm J/L 3 cm
H /G I
A /D J /K A/D 8 cm B/C
2 cm
6 cm B /C (ii) N M
H/G/R
(b) L/F 2 cm M/E L 4 cm
D/C E/F/P
5 cm
4 cm
J/K
3 cm
A/B/I

J /Q P K /G 6 cm 4. (a) E / A D
2 cm 1 C /D
cm
B /A
6 cm 4 cm

2. (a) E/F B 4 cm C

5 cm D/J 3 cm C/I (b) (i) E
A/G 3 cm 2 cm
J/P/F
6 cm B/H H/G

(b) (i) F/G 3 cm J 3 cm I/H 3 cm

P/Q 2 cm N/R 8 cm N/M 4 cm B/A 4 cm C/D

4 cm (ii) E

E/A D/K M/L C/B 2 cm
P F/G
J/H

(ii) E 8 cm F 3 cm
2 cm
I/J

C/M/D N/P 3 cm C / B / N 4 cm D / A / M

L/K 4 cm 2 cm H/G
B/A R/Q

© Penerbitan Pelangi Sdn. Bhd. A8

Mathematics  Form 5 Answers 

3. (a) ∠RKJ (b) 25.6°

4. 3 168 cm3

1. (a) 1 cm 2 cm 1 cm 2 cm 5. Durian = RM12, Jackfruit = RM2
Durian= RM12, Cempedak= RM2
H/D L U G/Q R 6. (a) Not a statement / Bukan pernyataan

5 cm (b) Implication 1: If x = y, then x – y = 0.
Implikasi 1: Jika x = y, maka x – y = 0.
E/A K TF/P/B S Implication 2: If x – y = 0, then x = y.
Implikasi 2: Jika x – y = 0, maka x = y.
(c) (n – 2) × 180°

(b) (i) 1 cm 1 cm 7. 24
E/H K/L T/U F/G
8. (a) {(Miri, Kuching), (Miri, Sandakan), (Miri, Bintulu),
3 cm 2 cm (Miri, Tawau), (Kuching, Miri), (Kuching, Sandakan),
P/Q (Kuching, Bintulu), (Kuching, Tawau), (Sandakan,
Miri), (Sandakan, Kuching), (Sandakan, Bintulu),
A/D 4 cm B/C 2 cm S/R (Sandakan, Tawau), (Bintulu, Miri), (Bintulu, Kuching),
(Bintulu, Sandakan), (Bintulu, Tawau), (Tawau, Miri),
(ii) F/T/K/E 5 cm G/U/L/H (Tawau, Kuching), (Tawau, Sandakan), (Tawau, Bintulu)},

M N1 cm n(S) = 20
P Q1 cm (b) (i) {(Miri, Kuching), (Miri, Sandakan), (Miri, Bintulu),
1 cm
S/B/A R/C/D (Miri, Tawau), (Kuching, Miri), (Kuching,
Sandakan), (Kuching, Bintulu), (Kuching,
Tawau), (Bintulu, Miri), (Bintulu, Kuching),

1Paper 2. C 3. B 4. A 5. D (Bintulu, Sandakan), (Bintulu, Tawau)},
7. C 8. B 9. D 10. B —35
1. B 12. C 13. D 14. B 15. D (ii) {(Sandakan, Miri), (Sandakan, Kuching),
6. D 17. C 18. D 19. A 20. B
11. D 22. C 23. D 24. A 25. D (Sandakan, Bintulu), (Tawau, Miri), (Tawau,
16. A 27. C 28. A 29. D 30. C Kuching), (Tawau, Bintulu)},
21. A 32. D 33. D 34. A 35. B 1—30
26. D 37. D 38. A 39. D 40. C
31. A 9. (a) 68—47 cm (b) 169—57 cm2
36. B
10. (a) 300 s (b) 40 km h–1/ 40 km j–1
2Paper (c) 20 km

11. (a) 5j + 7k = RM285
12j + 8k = RM420

1. y 1 21 2 1 25 7 j 285 ; j = 15, k = 30
k 420
4 y=x–2 (b) 12 8 = 

2 12. (a) x –2 –1 0 1 2.2 2.5 3 4 5
y 17 9 5 5 10.3 12.5 17 29 45
O 2 468 x
–2 (b)  y
–4 y – 4 = – 2x
50

45

2. (a) 40
P
R 35

Q 30

25

20

(b) 15
P
R 10 6.5

Q 5 3.7 4.25 x
1 2345
–0.25

–3 –2 –1 0
–5

y = 6x + 7

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  Mathematics  Form 5 Answers

(c) (i) 6.5 15. (a) M/T 5 cm L /Z 3 cm Q
(ii) 3.70
(d) –0.25, 4.25

13. (a) (i) (2, 3)

(ii) (2, 0)
(iii) (6, 0)

6 10 cm

1 2(b) (i) Transformation X: A translation  1 .

1 2 Transformasi X: Translasi pada  6 .
1
Transformation Y: An enlargement of scale

factor 2 with centre (7, 2). J/P K/V R
Transformasi Y : Pembesaran dengan faktor 5 cm K/L/W

skala 2 pada (7, 2).

(ii) 25 m2 (b) (i) J/M/S

14. (a) Upper Cummulative
Frequency boundary frequency
Mass Kekerapan Sempadan Kekerapan 5 cm
Jisim longgokan
(kg) atas

28 – 37 2 37.5 2 8 cm

38 – 47 4 47.5 6

48 – 57 8 57.5 14 5 cm
V/Z/U
58 – 67 6 67.5 20
L/M 5 cm W/S
68 – 77 3 77.5 23 P/T/N
10 cm
78 – 87 2 87.5 25 (ii)
K/J

(b) 56.5 kg 4 cm
(c) R

CKeukmermapualnatliovneggfroekqaunency

28 Q 8 cm

24

20

16 V/P Z/T U/N

12 16. (a) (25°N, 123°E) / (25°U, 123°T)
(b) 4 785.31 nautical miles
8 4 785.31 batu nautika
(c) 64°S
4 (d) 12.95 hours / 12.95 jam

0 27.5 37.5 47.5 57.5 67.5 77.5 87.5 Mass (kg)
Jisim (kg)

(d) 48%

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Notes

A11

Notes

A12