BASIC SURVEY COMPUTATION

CG 103 SURVEY COMPUTATION 1 CHAPTER 4: TRAVERSE
JKA, POLITEKNIK KUCHING SARAWAK

Example 5

Base on diagram given; calculate the coordinate for all station. Given coordinate for station 4 is S200
W 200

Answer DISTANCE LATIT DEPART COORDINATE

STN BEARING 46.753 -20.471 -42.033 N/S E/W
39.265 33.498 -20.484 -200 -200
4 44.103 36.689 24.475 -220.471 -242.033
5 244⁰ 01’ 57” 44.662 -8.242 43.895
1 328⁰ 33’ 15” 41.885 -41.474 -5.853 -186.973 -262.517
2 33⁰ 42’ 25”
3 100⁰ 38’ 02” -150.284 -238.042
4 188⁰ 01’ 56”
-158.526 -194.147

-200.000 -200.000

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CG 103 SURVEY COMPUTATION 1 CHAPTER 4: TRAVERSE
JKA, POLITEKNIK KUCHING SARAWAK

Example 6
Calculate bearing from 2 know coordinate
Answer
Bearing and distance for line 1 to 2

1. Latit = 233.137 – 200 = 33.137
2. Depart = 245.335 – 200 = 45.335
Distance 1 to 2

1-2 =�(33.137)2 + (45.335)2 = 56.154

Bearing 1 to 2

tan = ( )
( )

= 45.335
33.137

= −1 1.368108157

= 53° 50′08"

Bearing 1 to 2 is 53⁰ 50’ 08” because both latit and depart are positive.

Bearing and distance for line 2 to 3

1. Latit =204.680- 233.137 = -28.457
2. Depart = 304.534 - 245.335 = 59.199

Distance 2 to 3

2 – 3 =�(28.457)2 + (59.199)2 = 65.684

Bearing 2 to 3

= 59.199
28.457

= 64° 19′34"

Bearing 2 to 3 = 360⁰ - 64° 19′34" = 295⁰ 40’ 25”

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CG 103 SURVEY COMPUTATION 1 CHAPTER 4: TRAVERSE
JKA, POLITEKNIK KUCHING SARAWAK

EXAMPLE 7
Calculate bearing and distance for line 1 to 2 and line 2 to 3

Answer

Bearing and distance for line 1 to 2

3. Latit = -227.853 – (- 200) = - 27.853
4. Depart = 303.909 – 250 = 53.909

Distance 1 to 2

1-2 =�(27.853)2 + (53.909)2 = 60.679

Bearing 1 to 2

tan = ( )
( )

= 53.909
27.853

= 62° 40′34"

Bearing 1 to 2 is 180⁰- 62° 40′34"= 117⁰ 19’ 26”

Bearing and distance for line 2 to 3

3. Latit =-212.460 –(-227.853) =15.393
4. Depart = 361.485 – 303.909 = 57.576

Distance 2 to 3

2 – 3 =�(15.393)2 + (57.576)2 = 59.598

Bearing 2 to 3

= 57.576
15.393

= 75° 01′55"

Bearing 2 to 3 is 75° 01′55"

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CG 103 SURVEY COMPUTATION 1 CHAPTER 4: TRAVERSE
JKA, POLITEKNIK KUCHING SARAWAK

Example 8
Calculate coordinate for intersection point P

Answer

Calculate bearing for line AC and line BD

Bearing and distance for line B to D

1. Latit = 10.442-100 = -89.558
2. Depart = 325.651 – 200 = 125.651

Bearing 1 to 2

tan = ( )
( )

= 125.651
89.558

= 54° 31′14"

Bearing B to D is 180 − 54° 31′14" = 125⁰ 28′ 46"

Bearing and distance for line B to D

1. Latit = 91.945 – 28.922 = 63.023
2. Depart = 312.375 – 200.947 = 111.428

Bearing 1 to 2

= 111.428
63.023

= 60° 30′28"

Bearing B to D is 60° 30′28"

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CG 103 SURVEY COMPUTATION 1 CHAPTER 4: TRAVERSE
JKA, POLITEKNIK KUCHING SARAWAK

To calculate coordinate P, first calculate bearing and distance for line BA

Bearing and distance for line BA

1. Latit = 28.922-100 = -71.078
2. Depart = 200.947 -200 = 0.947

Distance 1 to 2

1-2 =�(71.078)2 + (0.947)2 = 71.084

Bearing 1 to 2

= 0.947
71.078

= 0° 45′48"

Bearing 1 to 2 is 360⁰ -0⁰ 45’ 48” = 359⁰ 14’ 12”

Calculate angle P angle B

Angle P = (125⁰ 28’ 46” + 180⁰ ) – ( 60⁰ 30’ 28” + 180⁰ ) =64⁰ 58’ 18”

Angle B = (359⁰ 14’ 12”-180⁰ ) - 125⁰ 28’ 46” = 53⁰ 45’ 26”

Distance AP

64⁰ 58’ 18” 53⁰ 45’ 26”
71.084 =


Distance AP = 63.272

Calculate latit and depart for line AP

STN BEARING DISTANCE LATIT DEPART COORDINATE
55.073
A N/S E/W
P 60⁰ 30’ 28”
28.922 200.947

63.272 31.149 60.071 256.020

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CG 103 SURVEY COMPUTATION 1 CHAPTER 4: TRAVERSE
JKA, POLITEKNIK KUCHING SARAWAK

Example 9
Calculate area using coordinate method. Given coordinate for station 1 N 100 E 150

STN BEARING DISTANCE LATIT DEPART COORDINATE AREA
N/S E/W

1 100 150

2 121⁰00’07” 39.014 -20.095 33.441 79.905 183.441 18344.1 11985.75

3 72⁰10’12” 40.936 12.534 38.970 92.439 222.411 17771.751 16957.103

4 181⁰09’49” 39.619 -39.611 -0.805 52.828 221.606 20485.037 11749.528

5 209⁰08’52” 29.602 -25.853 -14.418 26.975 207.188 10945.328 5977.822

6 295⁰23’45” 44.969 19.286 -40.623 46.261 166.565 4493.091 9584.724

1 342⁰52’05” 56.234 53.739 -16.565 100 150 6939.150 16656.5

TOTAL 78978.457 72911.427

Area = . − .


= 3033.515

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CG 103 SURVEY COMPUTATION 1 CHAPTER 4: TRAVERSE
JKA, POLITEKNIK KUCHING SARAWAK

Example 10
Calculate area using coordinate method. Given coordinate for station 1 is S 200 E 150

STN BEARING DISTANCE LATIT DEPART COORDINATE AREA
N/S E/W

1 -200 150

2 334⁰28’42” 52.006 46.931 -22.407 -153.069 127.593 25518.6 22960.4

3 309⁰40’46” 55.410 35.379 -42.645 -117.690 84.948 13002.9 15016.4

4 16⁰12’21” 69.926 67.148 19.516 -50.542 104.464 12294.4 4293.4

5 95⁰00’02” 99.401 -8.664 99.023 -59.206 203.487 10284.6 6184.9

1 200⁰48’ 06” 150.611 -140.794 -53.487 -200 150 8880.9 40697.4

TOTAL 69981.4 89152.5

Area = − .


= 9585.5

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CG 103 SURVEY COMPUTATION 1 CHAPTER 4: TRAVERSE
JKA, POLITEKNIK KUCHING SARAWAK

TUTORIAL

1. Calculate bearing and distance for line AB and coordinate for point C

2. Calculate coordinate for traverse and calculate area using coordinate method. Given coordinate for station
1 ia N 100 W 250.

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CG 103 SURVEY COMPUTATION 1 CHAPTER 4: TRAVERSE
JKA, POLITEKNIK KUCHING SARAWAK

3. Base on given diagram,calculate coordinate for point P.

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