Kimia kertas 1 SPM 2019

Bil. Mol CO2= Isipadu
isipadu molar

= 0.96
24

= 0.04 mol

Daripada persamaan,
1 mol C2H5OH menghasilkan 2 mol CO2
0.02 mol C2H5OH menghasilkan 0.04 mol CO2
Jisim C2H5OH = bil.mol x Jisim molar

= 0.02 x 46
= 0.92g

1.0 mol dm-3 H2SO4 = 98g dm-3

2.0 mol dm-3 H2SO4 = 2 x 98g dm-3
= 196 g dm-3

Dari persamaan,
2 mol HCl menghasilkan 1 mol MgCl2
0.04 mol HCI menghasilkan 0.02 mol MgCl2
Bil mol = MV

1000
Kemolaran = 0.04 x 1000

20.0
= 2.0 mol dm-3

CO2 = 12+2(16)
= 44

C4H10 = 4(12) + 10(1)
= 58

O2 = 2(16)
= 32

N2 = 2(14)
= 28

NH4+ PO43-

% Nitrogen = 3(14) x 100% (NH4)3PO4
149 Jisim molar = 3[14+4(1)] + 31+4(16)

= 28.19% = 149
% Fosforus = 31 x 100%

149
= 20.80%

% Nitrogen + % Fosforus = 28.19 + 20.80
= 48.99%