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Tips Menjawab Soalan Kertas 2 Fizik SPM
Tajuk Fokus
Tingkatan 4 : Haba
Gelombang
Cahaya dan Optik
Tingkatan 5 : Tekanan
Elektrik
Elektromagnet

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Published by salmizam2h, 2024-02-18 02:58:34

WEBINAR PHYSICS PAPER 2 SPM 2023 10 NOV 2023

Tips Menjawab Soalan Kertas 2 Fizik SPM
Tajuk Fokus
Tingkatan 4 : Haba
Gelombang
Cahaya dan Optik
Tingkatan 5 : Tekanan
Elektrik
Elektromagnet

Keywords: Bengkel Menjawab Soalan Kertas 2 Fizik

KERTAS 1 KERTAS 2 KERTAS 3 Soalan Objektif [40 markah] 40 soalan Aneka Pilihan Aneka Gabungan Bahagian A Soalan Berstruktur [60 markah] 8 soalan Bahagian B Soalan Esei [20 markah] 2 soalan (Respon Terhad) (Pilih 1) Bahagian C Soalan Esei [20 markah] 1 soalan (Respon Terbuka) Ujian Amali Bersepadu [15 markah]


Bil Perkara Kertas 2 (4531/2) 1 Jenis Instrumen Ujian Subjektif 2 Jenis Item Bahagian A : Subjektif berstruktur (ST) Bahagian B : Subjektif respon terhad (RH) dan respon terbuka (RB) Bahagian C : Subektif respon terhad (RH) dan respon terbuka (RB) 3 Bilangan Soalan Bahagian A : 8 Item (Jawab semua) Bahagian B : 2 item (Pilih satu) Bahagian C : 1 Item (Wajib) 4 Jumlah Markah 100 markah 5 Cara Memberi Respons Bahagian A, Bahagian B dan Bahagian C • Ditulis pada ruang dalam kertas soalan 6 Tempoh Ujian 2 jam 30 minit 7 Wajaran Konstruk Mengingati : 10 - 15 Memahami : 15 - 20 Mengaplikasi : 24 Menganalisis : 15 Menilai : 15 Mencipta : 16 JUMLAH : 100 FORMAT INSTRUMEN PENTAKSIRAN BAGI MATA PELAJARAN FIZIK KERTAS 2 (4531/2)


CHAPTER/QUESTION NO PAPER 1 PAPER 2 2021 PAPER 2 2022 2021 2022 A B C A B C FORM 4 1. MEASUREMENT 1 1,2 - - - 1(a) - - 2. FORCE AND MOTION 1 2,3,4,5 3,4,6,7,8,15 - - - - - - 3. GRAVITATION 6,7,8,9,10 9,10 3 9(a),(c) - 4 - - 4. HEAT 11, 12 11,12,13,16 1 - - - - 11 5. WAVES 13,14,15 14,17 5 - - 5 - - 6. LIGHT AND OPTICS 16,17,18,19 18,19,20, 8 - - 7 - - FORM 5 1. FORCE AND MOTION II 20,21,22 5,21,22,23 - 9(b),(d) - - - - 2. PRESSURE 23,24,25,26 24,25,26,27 - - 11 1(b), 6 - - 3. ELECTRICITY 27,28,29,30 28,29,30,31 - 10 - - 10 - 4. ELECTROMAGNETISM 31,32,33 32,33,34 6 - - - 9 - 5. ELECTRONICS 34,35,36 35,36 4 - - 8 - - 6. NUCLEAR PHYSICS 37,38,39,40 37,38 7 - - 3 - - 7. QUANTUM PHYSICS - 39,40 2 - - 2 - - ANALISIS FIZIK KERTAS 2 (4531/2) SPM 2021 DAN 2022


FORM 4 • HEAT • WAVES • LIGHT AND OPTICS FORM 5 • PRESSURE • ELECTRIC • ELECTROMAGNETISME


F4 Chapter 4 - HEAT(HABA) 4.1 Thermal Equilibrium 4.2 Specific Heat Capacity 4.3 Specific Latent Heat 4.4 Gas Law a. Boyle’s Law b. Charles Law c. Gay Lussac Law


a) i. What is ? [1 mark] ii. State the characteristics of the particles at [1 mark] b) What is the value of temperature, when the pressure of the gas is zero? [1 mark] c) Define the law involved in this experiment [1marks] An experiment is carried out to investigate the relationship between the pressure and the temperature of a fixed mass of gas. The graph of pressure, P against temperature, T obtained is shown in Diagram 3. Example: Paper 2 Question 1


Graph of P against θ shows that gas pressure increases linearly when temperature of the gas rises. At 0°C, gas molecules are still moving and the gas has pressure. At –273°C (absolute zero), gas molecules no longer move and do not collide with the walls of the container. Hence, gas pressure becomes zero. Textbook Physics F4 pg 160


a) i. What is ? Absolute zero [1 mark] ii. State the characteristics of the particles at gas molecules no longer move//gas particles are not moving [1 mark] b) What is the value of temperature, when the pressure of the gas is zero. − C// 0 K [1 mark] c) Define the law involved in this experiment Pressure is directly propotional to absolute temperature of a fixed mass of gas at constant volume [1marks] An experiment is carried out to investigate the relationship between the pressure and the temperature of a fixed mass of gas. The graph of pressure, P against temperature, T obtained is shown in Diagram 3. Example: Paper 2 Question 1


2. Rajah 2 menunjukkan seperiuk besar mi yang dimasak dalam jumlah air panas yang banyak. Diagram 2 shows a large pot with noodles being cooked in a large amount of hot water. Rajah 2 (a) (i) Apakah yang dimaksudkan dengan haba? What is the meaning of heat? Tenaga // form of Energy [1 markah] (ii) Mengapakah mi dimasak dalam jumlah air panas yang banyak? Why is the noodle being cooked in a large amount of hot water? -large mass of hot water// large heat capacity -transfer large amount of heat to noodle [2 markah] (b) 2 kg air pada suhu 30◦C ditambah ke dalam air panas berjisim 9 kg pada suhu 95◦C. Berapakah suhu akhir air tersebut apabila mencapai keseimbangan terma? 2 kg of water at 30◦C is added to 9 kg of hot water at 95◦C. What is the final temperature of the mixture when thermal equilibrium is achieved? [2 markah] Example: Paper 2 Question 2


a) i. After the journey, what happens to the pressure of air in the tyre Increases [1 mark] ii. Give two reasons for your answer in (a) (i) -temperature of air increases due to friction -rate of change of momentum increases [2 mark] b) Name the gas law involved in (a). Gay Lussac’s Law [1 mark] c) Before the journey, the air pressure in the tyre is 200 kPa at a temperature of 30◦C. After the journey, the air pressure become 220 kPa. Calculate the temperature of the tyre after the journey. [2 marks] Diagram 3.1 shows a car tyre before travelling from Alor Star to Kuala Lumpur. Diagram 3.2 shows the same tyre after reaching the destination. Diagram 3.1 Diagram 3.2 Example: Paper 2 Question 3 = + = = 333.3 K


Diagram 1 shows a glass of ice changing into water. Diagram 2 shows a glass of water changing into ice. Based on Diagram 1 and 2, compare the changes in energy involved, phase of substances and the temperature. Based on your answer, deduce a relationship between energy, phase of substance and temperature. Name the physics concept involved. [5 marks] KF03: Menganalisis (membuat perbandingan persamaan dan perbezaan/hubungan pembolehubah) Diagram 1 Diagram 2 -Diagram 1, heat energy absorbed, Diagram 2 heat energy released -Diagram 1 phase changes solid to liquid, Diagram 2 phase changed liquid to solid -Temperature constant / unchanged both diagram -Energy absorbed or released to change the phase of substance at constant temperature. -Latent Heat


In the past, people placed an ice pack on the forehead to bring down a fever. This method is a bit messy because we need to collect the water droplets that formed as the ice melts. Nowadays, people use cooling pads to treat fever. Diagram shows a cooling pad for fever that is used nowadays. As a researcher, you are required to design a cooling pad that can help to bring down a fever fast and is convenient to use. Suggest and explain how you would produce a cooling pad from the aspects of the type of coolant, the type of cloth, and the type of protective film used, as well as additional features that can be added. ASPECTS REASON the type of coolant – High specific heat capacity Coolant made of hydrogel Low density of coolant Absorb large amount of heat Absorbs more heat Easy to carry//Portable type of cloth –High melting point Spun lace fabric Does not melt easily Easily follow shape of forehead type of protective film used – made of diamond film Anti stick to the gel additional features Size of gel pad that fits forehead Cover forehead//More heat can absorbed KF05: MENCIPTA – Penyelesaian Masalah


5.1 Fundamentals of Waves F4 Chapter 5 – WAVES (GELOMBANG) 5.2 Damping and Resonance 5.3 Reflection of Waves 5.4 Refraction of Waves 5.5 Diffraction of Waves 5.6 Interference of Waves 5.7 Electromagnetic Waves



Frekuensi semakin bertambah Frekuensi bertambah, tenaga bertambah Gelombang Mikro//Micowave Gelombang tidak dibelaukan// wave does not diffracted


-apabila gelombang tuju terkena satu halangan ia akan dipantulkan - masa gelombang dihantar dan dipantulkan direkodkan - jarak ditentukan menggunakan rumus d = Pantulan // Reflection


= 340.43 − 1600 = . d =


Light and Optics 6.1 Refraction of Light 6.2 Total Internal Reflection 6.3 Image Formation by Lenses 6.4 Thin Lenses Formula 6.5 Optical Instruments


Pantulan // Reflection


5.1 < 5.2 // vice versa // 5.1 shorter than 5.2 // 5.2 longer than 5.1 5.1 > 5.2 // vice versa // 5.1 longer than 5.2 // 5.2 shorter than 5.1 5.1 > 5.2 // vice versa // 5.1 bigger than 5.2 // 5.2 smaller than 5.1 shorter object distance, longer image distance // vice versa shorter object distance, bigger size image// vice versa


PRESSURE (TEKANAN) 2.1 Pressure in Liquids 2.2 Atmospheric Pressure 2.3 Gas Pressure 2.4 Pascal’s Principle 2.5 Archimedes’ Principle 2.6 Bernoulli’s Principle



P < Q // vice versa // P less / small weight than Q P < Q // vice versa // P less weight of water displaed than Q P < Q // vice versa // P less immersed than Q Volume of bottle immersed decrease, weight of water displaced decrease Weight of bottle decrease, weight of water displaced decrease Q banyak sedikit// lebih sedikit P lebih kurang Kurang banyak sederhana


F5 Chapter 3 - ELECTRIC 3.1 Current and Potential Difference 3.2 Resistance 3.3 Electromotive Force and Internal Resistance 3.4 Electrical Energy


i. P = IV 1450 W = I (240 V) I = 6.04 A ii. E = Pt = (1450 W) (35 x 60 s) = 3.05 X J iii. P = R = . . = 1 332 W


An air fryer is designed to fry food without oil. Table 10 shows the specifications of four types of air fryer, P, Q, R and S. Study the specification and justify each aspect. Choose the most suitable air fryer that used to fry food effectively. [10 marks] ASPECTS REASON Kuasa/Power - High Produce more electrical energy//Release more heat Bahan Pemanas/Material Heater-Nichrome High Resistance//High Resistivity//Produce More Heat Takat lebur pemanas/Melting point heater - High Withstand high temperature //Does not melt easily Komponen elektrik tambahan/Additional electrical component : Thermostat Control excessive heat/temperature Choose : S Has high power, heater made of nichrome with high melting point and Thermostat.


ELECTROMAGNETISME 4.1 Force on a Current carrying Conductor in a Magnetic Field Flemming’s Left Hand Rule Motor 4.2 Electromagnetic Induction Flemming’s Right Hand Rule AC and DC Generator, Dynamo 4.3 Transformer Transmission Electricity


Section B : Paper 2


a. Transformer b. Prinsip Kerja Transformer -arus ulang alik mengalir melalui gegelung primer transformer -Medan magnet yang berubah-ubah dihasilkan -Fluks magnet yang berubah-ubah dipautkan oleh teras besi lembut kepada gegelung sekunder -d.g.e aruhan terhasil pada gegelung sekunder //voltan output lebih kecil terhasil pada gegelung sekunder.


SECTION B SECTION C


Ulangkaji semua tajuk – buat nota ringkas (mind map) Jawab semua soalan Percubaan Negeri. Setkan masa untuk menjawab FORM 4 • MEASUREMENT • FORCE AND MOTION I • GRAVITATION • HEAT • WAVES • LIGHT AND OPTICS FORM 5 • FORCE AND MOTION II • PRESSURE • ELECTRIC • ELECTROMAGNETISME • ELECTRONICS • NUCLEAR PHYSICS • QUANTUM PHYSICS


MEET THE FUTURE


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