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## Cambridge Secondary checkpoint Mathematics April Paper 1 2019 Details Solution or Answers

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# Cambridge Secondary checkpoint Mathematics April Paper 1 2019 Details Solution

### Keywords: secondary checkpoint Mathematics April Paper 2 2019 Question Paper

CHECKPOINT MATHEMATICS/1112/01 2019

SOLUTION TO APRIL 2019 – PAPER 1

The solution to a particular question can be accessed instantly by
clicking on the desired question number in the QUICK ACCESS GRID.

12345
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25
26 27 28 29 30

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EDUCATE. EXCELERATE.

DISCLAIMER
The solution to the said examination paper has been drafted by teachers who are duly

accredited and experienced with the CHECKPOINT MATHEMATICS curriculum.
It has been developed independently of the CAIE and is in no way endorsed by the CAIE.

CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S1 6 × 3 + = 23 1

18 + = 23

= 23 – 18

= 5

S2 Let the number be . Back to QUICK ACCESS GRID
1
3 × – 6 = 15
3 – 6 = 15
3 = 15 + 6
3 = 21

21
= 3
= 7

S3 Back to QUICK ACCESS GRID
1 1 bottle → 500 ml
3 × 500 ml = 1500 ml

1500 ml = 1500 ÷ 1000 = 1.5 3 bottles → 3 × 500 ml
1 litre = 1000 ml

To convert ml to → divide by 1000

Back to QUICK ACCESS GRID

CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S4 12 biscuits → 125 g butter 1

125
1 biscuit → 12 g butter

125
36 biscuits → 12 × 36 g butter

125
12 × 36 = 125 × 3 = 375

36 biscuits → 375 g butter

S5 3 2 3 Back to QUICK ACCESS GRID
8 × 5 = 20 1

34
8×5

32 Back to QUICK ACCESS GRID
=8 ×5 ×2

3
= 20 × 2

=

S6

1 Test for divisibility by 9

If the sum of all the digits in a number is
exactly divisible by 9, then the number is
exactly divisible by 9.

54 → 5 + 4 = 9
297 → 2 + 9 + 7 = 18

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CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S7

1 Multiply by 4
× 4 = 4

then subtract 2
4 – 2

S8 12.7 × 0.3 Back to QUICK ACCESS GRID
1 127 × 3 = 381
127 3
= 10 × 10

381
= 100

= 3.81

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S9 Number of days it rains in November 2 ALTERNATIVE ANSWER

3 Number of days it does not rain in
= 5 × 30
=3×6 November
2

= 5 × 30

= 18 = 2 × 6

Number of days it does not rain in = 12
November = 30 – 18 = 12

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CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S10

Area of cross-section of prism 2 Area of a rectangle = length × width
=3×7×4
= 12 × 7 Volume of the prism
= 84 cm2 = area of cross-section × 10
Volume of the prism
= 84 × 10
= 840 cm3

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CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S11

Rice A Rice B ✔ 2

Free rice in bag A
= 25% of 500 g

25
= 100 × 500
= 25 × 5
= 125 g
Free rice in bag B

1
= 5 of 750 g

1
= 5 × 750
= 150 g
150 g > 125 g
∴ Bag B gives more free rice than bag A.

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CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S12 Lily ✔ 1

Mia

√121 = 11
√100 = 10
120 is closer to 121 than to 100.
∴ √120 is closer to √121 than to √100,
that is, √120 is closer to 11 than to 10.

Back to QUICK ACCESS GRID

S13 Primes between 60 and 70: 1

61 and 67

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S14

1 For a fair coin, both head and tail are
equally likely outcomes.
Accordingly, if a fair coin is tossed 200
times, the probability of obtaining heads is
50%, that is, 100 times.
Hence, coin C is most likely to be a fair coin.

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CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S15 1. 14 ÷ 0.2 = 70 2 1 2
2. 16 × 1.25 = 20
3. 20 × 0.5 = 10 14 ÷ 0.2 16 × 1.25
4. 36 ÷ 0.75 = 48 125
2
= 14 ÷ 10 = 16 × 100
125
10
= 14 × 2 = 4 × 25
=4×5
= 7 × 10 = 20

= 70

3 4

20 × 0.5 36 ÷ 0.75
5 75

= 20 × 10 =36 ÷ 100
= 10 100

= 36 × 75
4

= 36 × 3
= 12 × 4
= 48

Back to QUICK ACCESS GRID

S16 Size of exterior angle of a regular 2 Size of exterior angle of a regular n-sided
10-sided polygon
polygon
360
= 10
=

= 36°

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CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S17
(a)

1

13 24
– 11 06
18
02

Oliver’s journey will take 02 hours 18
minutes.

(b)

As per the train time-table on Saturday, 2
to be at Hankberg before 18:15, Yuri
needs to take the 15:30 train from
Flaghaven.

To be able to take the 15:30 train from
Flaghaven, he must be at the station
before 15:30.
The latest train from Dibside that can
reach him before 15:30 is the one at
12:36

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CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S18 539 11 × 7 × 7 1
(a) 847 = 7 × 11 × 11 =

(b) 55 11 × 5 1
539 = 11 × 7 × 7 =

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S19
(a)

2

(b) Rajiv is not correct ✔ 1 The median length for 40 birds
= (length of 20th bird + length of 21st bird) ÷
As per the given data, the lengths of 20th
as well as 21st birds lie in the interval 2
17 ≤ < 18.

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CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S20 2 + 8(40 – 5) 1 Alternative answer
= 2 + 8 × 40 – 8 × 5
= 2 + 320 – 40 2 + 8(35) = 2 + 280 = 282
= 2 + 280
= 282

S21 Back to QUICK ACCESS GRID Secondary
Primary

Ask the parents of his friends ✔

Look for survey results on the internet ✔

Go to the library to look up the results of the ✔
last election

1

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S22 20% of \$30 = 40% of \$ 15 1 20% of \$30 =40% of \$
20 40
100 × 30 = 100 ×
20
40 × 30 =
1
2 × 30 =
15 =

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CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S23 1 – 7 × – 5 = + 35
35

(a)

(b) 13 1 6 – (– 7) = 6 + 7 = 13

S24 ( – 1) × 5 = ( + 8) × 2 Back to QUICK ACCESS GRID
(a) 1 3 = 21
= 21 ÷ 3
5 – 5 = 2 + 16 = 7
5 – 2 = 16 + 5
3 = 21
OR
= 7

(b) 3 = 21 2

= 21 ÷ 3
= 7

Length of one line
= ( + 8) × 2
= (7 + 8) × 2
= 15 × 2
= 30 cm

Back to QUICK ACCESS GRID

CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S25 A → (7, 2) 2

B → ( , )
M → (5, 6)

7 +
2 =5

7 + = 10
= 10 – 7
= 3
2 +

2 =6
2 + = 12
= 12 – 2
= 10
co-ordinates of B = (3, 10)

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CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S26

+124668
1235779
2 3 4 6 8 8 10

4 5 6 8 10 10 12
6 7 8 10 12 12 14
6 7 8 10 12 12 14

8 9 10 12 14 14 16

Total number of scores = 36 3

Number of total scores that are 10 or
more
= 17

probability that the total score is 10 or

more =

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CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S27

= 4 + 1 = –1 = – 6

= 3 – 5 + = 11

2 Equation of a straight line: = m + c

for = –1, m = 0

+ = 11
= – + 11
m = –1

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CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S28
(a)

° + 62° + 62° = 180° 1 ° + 62° + 62° = 180° → sum of all angles
° + 124° = 180°
° = 180° – 124° of a triangle

↓ ° = 56° 1 ° + 132° + 90° + 118° = 360° → sum of all
° + 132° + 90° + 118° = 360°
° + 340° = 360°
° = 360° – 340°
° = 40°

CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

(b) Not correct ✔
The diagonals of a Kite are
REASON: perpendicular to each other which is not
true for BCDE.
One pair of opposite angles of a Kite are
equal.
Both the pairs of opposite angles of

Back to QUICK ACCESS GRID

S29
(a)

↓ 2

CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S29
(b)

1
Back to QUICK ACCESS GRID

CHECKPOINT MATHEMATICS/1112/01 2019

Solution Marks Notes

S30

(1 + 1 1) ÷ 2

3 2

= (1 + 1 × 2 + 1) ÷ 2
2
3

= (31 + 32) ÷ 2

= (31××22 + 32××33) ÷ 2
= (26 + 69) ÷ 2

11
= 6 ÷2

11 1
= 6 ×2

11
= 12

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