CHECKPOINT MATHEMATICS/1112/02 2019
SOLUTION TO APRIL 2019 – PAPER 2
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CHECKPOINT MATHEMATICS/1112/02 2019
Solution Marks Notes
S1 25 × 1.8 + 32 1
(a)
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= 45 + 32
= 77 °F
(b)
S2 142 + 29 1
3×22 + 7 Back to QUICK ACCESS GRID
256 + 29
= 3×4 + 7 1 Note:
285
= 12 + 7 The answer can be worked out in a single
285 step using the calculator.
= 19
= 15 Back to QUICK ACCESS GRID
S3
1 P (Mike arrives late to school)
15 3
= 20 = 4
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CHECKPOINT MATHEMATICS/1112/02 2019
Solution Marks Notes
S4 248 675 1
(a) = 249 000 to the nearest thousand
(b) 52.747 square kilometres 1 number in the second decimal place (4) < 5
= 52.7 square kilometres
∴ number in the first decimal place remains
S5 unchanged.
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2
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CHECKPOINT MATHEMATICS/1112/02 2019
Solution Marks Notes
S6 1
(a)
(b)
Line = 2 shown on the grid in red 1
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CHECKPOINT MATHEMATICS/1112/02 2019
Solution Marks Notes
S7 Diameter of the pond in the scale 1 1 cm → 2 m
(a) drawing = 3.1 cm
3.1 cm → 3.1 × 2 m = 6.2 m
Diameter of the pond in real life
= 6.2 metres
(b)
Length of the shed in the scale drawing 1 2 m → 1 cm
= 1.5 cm 3 m → 3 ÷ 2 cm = 1.5 cm
4 m → 4 ÷ 2 cm = 2 cm
Width of the shed in the scale drawing
= 2 cm
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CHECKPOINT MATHEMATICS/1112/02 2019
Solution Marks Notes
S8 Total distance Carlos swims 2 1000 m = 1 km
(a) To convert m to km → divide by 1000
= 90 × 25 m
= 2250 m 2250 m = 2250 ÷ 1000 km = 2.250 km
= 2.250 km
(b) number of lengths Carlos swims on his 2
front
4
= 4 + 1 × 90
4
= 5 × 90
= 72
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S9
(a)
1
(b)
= –2 1 solution to the simultaneous equations
= –3 = co-ordinates of point of intersection of
the two lines
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Solution Marks Notes
S10 S = a × b × ÷ 2 2
(a)
S =
(b) × 7.6 × 9.22 2 2
V = 8 = 252.6 cm3 V= 8
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S11
(a)
(b) = 5.7 1
1 56 – 55.29 = 0.71
56.84 – 56 = 0.84
∴ 55.29 is closer to 56 than 56.84
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CHECKPOINT MATHEMATICS/1112/02 2019
Solution Marks Notes
S12
(a)
(b) 1 Blessy is older than Manjit.
< ∴ Blessy’s age > Manjit’s age
1 Anastasia is less than half the age of Blessy.
Anastasia’s age < ½ of Blessy’s age
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S13 Number of runners that take less than 1 2 1 hour = 60 minutes
hour = 20 + 15 + 10 = 45
Percentage of runners that take less than
1 hour
45
= 85 × 100
= 52.9%
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Solution Marks Notes
S14
2
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S15
(a)
Data shown by red cross on graph 1
(b) 8.75 seconds (approximately) 1 time deduced from the line of best fit;
values in the range of 8 – 9 seconds will be
acceptable
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Solution Marks Notes
S16
0.075 km 7.6 m 77 cm 780 mm
75 m 7.6 m 0.77 m 0.78 m
0.77 m 0.78 m 7.6 m 75 m
77 cm 780 mm 7.6 m 0.075 km
smallest largest
2 To compare the lengths, it is essential to
express them using the same units.
To convert:
km to m → multiply by 1000
cm to m → divide by 100
mm to m → divide by 1000
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S17 Chen earned a bonus ✔ 2 total distance
Average speed = total time
Total distance covered by Chen on his Total distance = average speed × total time
last journey
= 61 × 4.5
= 274.5 km
Distance covered per litre of fuel
274.5
= 96
= 2.859375 km/
2.859375 km/ > 2.8 km/
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Solution Marks Notes
S18
1 2.3 kilograms = 2.3 × 1000 g = 2300 g
0.3 litres = 0.3 × 1000 ml = 300 ml
150 ml < 300 ml
150 ml < 0.3
5 metres = 5 × 1000 mm = 5000 mm
5000 millimetres = 5 metres
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S19 1 2 Area of a trapezium
Area of the trapezium = 2 × (a + b) × 6 1
1
2 × (a + b) × 6 = 30 = 2 × (sum of parallel sides) × height
Other possible values of a and b in cm:
(a + b) × 3 = 30 ab
30 19
28
(a + b) = 3 37
a + b = 10 cm
a = 4 cm
b = 6 cm
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S20 Solution Marks Notes
% of children in film A audience 2 To convert a fraction to percentage
11 ↓
= 11+19 × 100 Multiply the fraction by 100
11
= 30 × 100
= 36.7
% of children in film B audience
5
= 5+7 × 100
5
= 12 × 100
= 41.7
∴ Film B has the greater proportion of
children in the audience.
Film B ✔
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Solution Marks Notes
S21 3
Area of the square = 82 = 64 cm2
Area of the square covered by the star
= 40% of 64 cm2
40
= 100 × 64
= 25.6 cm2
Width of the rectangle = 8 cm
60
60% of 8 cm = 100 × 8 = 4.8 cm
Length of the rectangle
= 8 + 4.8 = 12.8 cm
Area of the rectangle
= 12.8 × 8
= 102.4 cm2
% of the rectangle that the star covers
25.6
= 102.4 × 100
= 25%
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CHECKPOINT MATHEMATICS/1112/02 2019
Solution Marks Notes
S22 4200 cm3 54 000 mm3 45 litres 52 000 m
4200 cm3 54 cm3 45 000 cm3 52 000 cm3
52 000 cm3 → largest measurement
1 To compare the measurements, it is
essential to express them using the same
units.
To convert:
mm3 to cm3 → divide by 1000
litres to cm3 → multiply by 1000
1 cm3 = 1m
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CHECKPOINT MATHEMATICS/1112/02 2019
Solution Marks Notes
S23
Age Number of Can Cannot % of people
remember that can
11 to 20 people tested remember remember
21 to 30 4 80
31 to 40 20 16 6 70
20 14 14 65
40 26
Yes No ✔ 2
Reason:
As age increases, the percentage of
people that can remember decreases.
This indicates that younger people can
remember better than older people.
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Solution Marks Notes
S24 Volume of the cube = 33 = 27 cm3 3 Volume of a cube = side3
Volume of the cuboid Volume of a cuboid
= 1.2 × 100 × 30 × 50 = length × width × height
= 180 000 cm3
Number of cubes that fit inside the box Length of the cuboid = 1.2 m = 1.2 × 100 cm
180 000 180 000
= 27 27 = 6666.7
= 6666
∴ number of cubes that fit completely
inside the box = 6666
S25 Back to QUICK ACCESS GRID
√ . = +3.5 and –3.5 1
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