Chemistry
Lecture
Chapter 1
MATTER
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Today lecture
Introduction
⚫Matter
Anything that occupies space and has mass.
e.g; air, water, animals, trees, atoms, …..
⚫Matter may consists of atoms, molecules or ions.
Three States of Matter
matter 4
Chapter 1 : MATTER
1.1 Atoms and Molecules
1.2 Mole Concept
1.3 Stoichiometry (next lecture)
matter 5
1.1 Atoms and Molecules
Learning Outcome
At the end of this lecture, students should be able :
a) Write isotopic notation.
b) Interpret mass spectrum.
matter 6
1.1 Atoms and Molecules
Terms
Atom
⚫An atom is the smallest / basic unit of a chemical
element/compound.
Example: Na, Li ,Ne
Molecule
⚫ A unit consist of two or more atoms that are
chemically bonded together
⚫There are two types;
⚫ diatomic molecule : Cl2, F2, HCl, O2
⚫ polyatomic molecule : H2O, CO3
Element
⚫A substance that cannot be separated into
simpler substances by chemical means.
⚫Element consist of only one kind of atom.
⚫Element can exist as atom or molecule.
Example: Na, Li, F2, Ne, Cl2
matter 8
ACTIVITY – 1 9
Categorize the followings:
F2, NaSO4, O2, CO, Li, and CO2 as;
ATOM : Li
MOLECULE: F2, NaSO4, O2, CO, CO2
ELEMENT : Li, F2, O2
COMPOUNDS : NaSO4, CO, CO2
matter
Subatomic particles
An atom is made up,
Proton (p+) Packed in a small nucleus
Neutron (no)
Electron (e–) Move rapidly around the nucleus of
an atom
Atom is
e- electrically
neutral
8/2/2021 matter 10
1.1-15
Elements are arranged in the
order of proton number
in the periodic table
What is proton number?
PROTON NUMBER (Z)
Also known as atomic number
Number of protons in the nucleus of each atom.
In neutral atom,
number of protons = number of electrons
EXAMPLE:
11
88
11 11
18 18
NUCLEON NUMBER (A)
Nucleon number also known as mass number
Total number of protons and neutrons
present in the nucleus of an atom.
Nucleon number = Proton Number + Number of Neutrons
(A) (Z) (N)
A = 13 A = 90 A = 61
Isotopes
⚫Are atoms of the same element , having the
same number of protons but different number of
neutrons in their nucleus.
1 H 12H 3200 Hg
1 1 H80
U235 U238
92 92
⚫Are atoms of the same element , having the 14
same protons number but different nucleon
number.
matter
Isotope Notation,AZ X
• An atom can be represented by an isotope notation
( atomic symbol )
A = Nucleon element
Number of X symbol
= Z+n
Z = Proton Number 15
of X
=p
Note : X can be atom or ion
matter
EXAMPLE:
35 Cl
17
Number of protons = proton number (Z) = 17
Number of electrons = 17
Number of neutrons = 35 - 17 = 18
Nucleon number (A)
= number of protons + number of neutrons
= 17 + 18 = 35
EXAMPLE – 1
Indicate the number of protons, neutrons, and
electrons in each of the following species:
157N 1363S 2694Cu 3884Sr
15360Ba 17846W 28002Hg
Ans: EXAMPLE – 01
157N 5 17 – 5 = 12 5
1363S
16 33 – 16 = 17 16
2694Cu
3884Sr 29 64 – 29 = 35 29
20820 Hg
13506 Ba 38 64 – 29 = 35 38
18764 W
80 202 – 80 = 122 80
56 130 – 56 = 74 56
74 186 – 74 = 112 74
X A isotope notation
Z
Z=6 Z = 40 Z = 28
A=6+7
A = 40 + 50 A = 28 + 33
= 13 = 90 = 61
13 C 4900Zr 2681Ni
6
ION
⚫Atom or group of atoms that has positive or
negative charge.
Cation Anion
a positive charge ion a negative charge ion
formed when a neutral formed when a neutral
atom loses an electron(s). atom gains an electron(s).
Na Na+ Cl Cl-
11 protons 11 protons 17 protons 17 protons
11 electrons 10 electrons 17 electrons 18 electrons
8/2/2021 matter 20
EXAMPLE – 4
Give the number of protons and electrons in each
of the following common ions:
K+, Mg2+, Fe3+, Br–, Mn2+, C4–, Cu2+.
(Refer to the periodic table)
Ans: EXAMPLE-4
19 19 – 1 = 18 Write Nuclear symbol
12 12 – 2 = 10 For K+, given neutron
number for potassium
26 26 – 3 = 23 is 20
35 35 + 1 = 36 K39 +
25 25 – 2 = 23
19
6 6 + 4 = 10
29 29 – 2 = 27
Ans:EXERCISE – 6
“The chemical identity of an atom can be
determined solely from its atomic number (Z)”
It means if we want to identify what element
the atom is, we must refer to the
atomic number (Z) or number of protons.
Because the atomic number is unchanged
no matter the atoms are isotopes or become ions.
24 Mg
12
Ans: EXERCISE – 6
EXAMPLE:
12 24 – 12 = 12 12
12 25 – 12 = 13 12
12 26 – 12 = 14 12
12 24 – 12 = 12 10
MASS SPECTROMETRY
Technique used to determined relative
atomic mass and the relative abundance
of isotopes
Different atoms / isotopes / molecules can
be identified by their characteristic pattern of
lines (peak)
MASS SPECTROMETER
A device used to determined
Relative atomic mass and the
Relative Molecular mass
Relative Isotopic mass
Structural formula of compound
MASS SPECTROMETER 1.1-26
① vaporization chamber ④ magnetic field
⑤ ion detector
③ accelerating chamber
② ionization chamber
Mass Spectrum of Magnesium
⚫The line of mass
spectrum shows Mg
consists of three
63 isotopes:
8.1 9.1 24Mg, 25Mg and 26Mg.
⚫The height of each line
is proportional to the
24 25 26 m/e (amu) abundance of each
isotope.
⚫24Mg is the most
abundant of the three
isotopes
matter 28
Example: MASS SPECTRUM OF ISOTOPES
Intensity of peaks
1200Ne (90.2%)
22Ne (8.82%)
21Ne 10
10 (0.26%)
19 20 21 22
Atomic mass (amu)
Note: relative intensity = relative abundance
1.2 Mole Concept
Learning Outcome
At the end of this lecture, students should be able :
a) Define the term empirical and molecular formulae
b) Define term molarity, molality,mole fraction,
percentage by mass, percentage by volume.
matter 30
Definition of mole
Amount of substances that contains the
same number of particles (atoms, molecules,
formula units, ions) as there are atoms in
exactly in 12 g of C–12 Avogadro’s
1 mol contains 6.023 x 1023 particles number (NA)
EXAMPLE: 6.023 x 1023 C–12 atoms
1 mol of C–12 contains
1 mol of H2O contains 6.023 x 1023 H2O molecules
1 mol of NaCl contains 6.023 x 1023 NaCl formula units
EXAMPLE – 01
1 molecule of H2O :
1) ? hydrogen atom
1 molecule H2O consists 2 hydrogen atoms
2) ? oxygen atom
1 molecule H2O consists 1 oxygen atom
3) How many atoms in a H2O molecule?
Total atoms in 1 H2O molecule =
2 hydrogen atom + 1 oxygen atom
3 atomsMATTER= 32
In 1 mole of H2O :
1) How many water molecules?
1 mole water ~ 6.023 x 10 23 molecules
2) ? hydrogen atom
1 mole H2O molecule ~ 2 mole hydrogen atom
6.023 x 10 23 ~ 2 x 6.023 x 10 23
molecules hydrogen atoms
1 mol contains 6.02 x 1023 entities 33
MATTER
1 mole each of several elements:
copper, iron, carbon, sulfur and mercury
Each of them contain 6.023 x 1023 atoms
Molar Mass
⚫The mass of 1 mole of an element or 1 mole
of compound.
Unit : g mol-1
⚫Example: 24 g mol-1
- molar mass of Mg = (12 + 4) gmol-1
- molar mass of CH4 = 16 g mol-1
=
MATTER 35
MOLECULAR MASS
The sum of the atomic masses in a
molecule (unit : amu)
EXAMPLE:
1S 32.07 amu
2O + (2 x 16.00) amu
SO2 SO2 64.07 amu
MOLECULAR MASS Vs MOLAR MASS
For any compound
molecular mass (amu) =“nusmamereic”ally= molar mass (grams)
1 molecule / 1 mole (6.02 x 1023particles)
1 formula unit
H2O 18.02 amu 18.02 g
NaCl
58.44 amu 58.44 g
Micro World Macro World
atoms & molecules grams
EXAMPLE: H2O
Atomic Mass (1 atom)
Unit: amu
Ar or Mr Molecular Mass (1 molecule)
no unit Unit: amu 18 amu
18 Molar Mass (1 mol of
molecules)
Unit: g/mol 18 g/mol
For calculation of mole, use molar mass
CALCULATING MOLES
Number of mole
= Mass (g)
Molar Mass (g mol-1 )
Conversion factor:
EXAMPLE:
1 mol of Fe = 55.85 g of Fe
1 mol of Fe contains 6.023 x 1023 atoms Fe
MATTER 39
The mole concept provide the bridge
between mass and number of entities
GRAMS
use molar mass
MOLES
use Avogadro’s number
MOLECULES or ATOMS
1.2.1 Mole Concept of Gases
2 condition for molar volume of any gas,
⚫At s.t.p (standard temperature and pressure)
⚫At room temperature
MATTER 41
Calculate number of oxygen in in 56cm3 of C02
56 cm3 ≡ 0.056 dm3
a. 22.4 dm3 = 1 mole of CO2
0.056 dm3 = 0.0025 mole
b. Number of molecules CO2 = number of mol x NA
= 0.0025 x 6.023 x 1023
= 1.506 x 1021 molecules
a.1 molecule of CO2 = 2 O atoms
1.506 x 1021 molecule of CO2 = (1.506 x 1021 x 2 ) O atoms
= 3.011 x 1021 O atoms
MATTER 42
TYPES OF CHEMICAL FORMULA
Empirical Formula
Molecular Formula
Structural Formula
Formula Unit (for ionic compounds)
EXAMPLE: benzene 43
Empirical Formula = (CH)n
Molecular Formula = C6H6
Structural Formula =
MATTER
EMPIRICAL FORMULA:
Shows the simplest ratio of atoms of each
element in a compound.
MOLECULAR FORMULA:
Shows the actual number of atoms of each
element in a molecule of the compound.
EXAMPLE: Hydrogen peroxide 44
Empirical Formula = (HO)n
Molecular Formula = H2O2
MATTER
-The relationship between empirical formula and
molecular formula is :
Molecular formula = n (empirical formula)
Where ;
n = molecular mass @ molar mass
emprical formula mass
MATTER 45
MASS FROM CHEMICAL FORMULA
Ratio Composition by mass
CO2
What mass of C in CO2?
What mass of O in CO2?
Mass of element C =
Mass of CO2 molar mass of C (g/mol)
x
molar mass of compound (g/mol)
Concentrations of solutions in daily life
A SOLUTION
Homogenous mixture of two or more
substances
SOLUTE
Substance present in the smaller amount
SOLVENT
Substance present in the larger amount
use to dissolve solute
2 types of solvent,
i) non-polar (example; benzene)
ii) polar (common: water)
1.2-54
solvent water
CuSO4 solution
solution
solute
CuSO4
1.2.2 Concentration of Solution
Amount of solute present in a given quantity
of solvent or solution
Molarity (M)
Molality (m)
Mole fraction (X)
Percentage by mass (mass %)
Percentage by volume (volume%)
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