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This e-book describes an Introduction to Statistics to helps students who taking Engineering Mathematics subjects especially in Malaysian Polytechnic. The concept of this e­book is interactive in the terms of infographic elements which included theory notes, clear examples with the guided answer and intensive practice. Hopefully, with this e-book students will gain a better understanding of theories, concepts and methods used in solving problems for statistic topics.

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Published by Penerbit PSIS, 2022-11-03 05:06:35

EBOOK STATISTICS

This e-book describes an Introduction to Statistics to helps students who taking Engineering Mathematics subjects especially in Malaysian Polytechnic. The concept of this e­book is interactive in the terms of infographic elements which included theory notes, clear examples with the guided answer and intensive practice. Hopefully, with this e-book students will gain a better understanding of theories, concepts and methods used in solving problems for statistic topics.

Keywords: EBOOK STATISTICS

EXAMPLE 9

Based on the following table, calculate
the median of the data.

Height (cm) Number of trees
15 – 19 3
20 – 24 10
25 – 29 26
30 – 34 24
35 – 39 20
40 – 44 12
45 – 49 5

44


SOLUTION

Height (cm) Number of trees Cumulative
frequency
15 – 19 3
20 – 24 10 3
25 – 29 26 13
30 – 34 24 39
35 – 39 20 63
40 – 44 12 83
45 – 49 5 95
100

Therefore, ෥ = + ൗ −


෤ = 29.5 + 100ൗ2 − 39 (5)
24

= .

45


LET'S TRY

QUESTION 1

The table shows the number of books read by
the students of a class in one year. Calculate
the median of the data.

Number of books Number of students
10 - 14 3
15 - 19 7
20 - 24 9
25 - 29 12
30 - 34 5

46


LET'S TRY

QUESTION 2

The table shows the time taken (in seconds)
by a group of 40 students to complete a race.
Calculate the median of the data.

Time (in seconds) Number of
students

41 - 45 3

46 - 50 7

51 - 55 9

56 - 60 5

47


ෝ = +
+

L = lower boundary mode class

d1 = difference between the
mode class and frequency
before it

d2 = difference between the
mode class and frequency
after it

c = size of class

48


EXAMPLE 10

The following table are the marks
obtained by 48 students of class 3A
in a Mathematics test. Find the
mode for the data.

Test marks Number of students
50 – 59 4
60 – 69 8
70 – 79 18
80 – 89 16
90 – 99 2

49


SOLUTION

Test marks Number of students
50 – 59 4
60 – 69 8
70 – 79
80 – 89 = − =
90 – 99
18
16 = − =
2

Therefore, ෝ = +
+

10
ො = 69.5 + 10 + 2 (10)

=

50


EXAMPLE 11

Calculate the mode for the
following grouped data.

Class Number of students

21 – 30 12
31 – 40 20
41 – 50 28
51 – 60 16
61 – 70 14
71 – 80 10

51


SOLUTION

Class Number of students
21 – 30 12
31 – 40 20 = − =
41 – 50 28
51 – 60 16 = − =
61 – 70 14
71 – 80 10

Therefore, ෝ = +
+

8
ො = 40.5 + 8 + 12 (10)

= .

52


LET'S TRY

QUESTION 1

The table shows the scores of 200 students
who participated in a Mathematics Quiz. Find
the mode of the score.

Score Number of participants
1 - 20 7
21 - 40 45
41 - 60 94
61 - 80 36
81 - 100 18

53


LET'S TRY

QUESTION 2

The table shows the weight of 16 students in
a class. Find the mode of the weight.

Weight Number of students

30 - 34 3

35 - 39 5

40 - 44 6

45 - 49 2

54


SUBTOPIC 1.4


WHAT IS
MEASURE OF
DISPERSION?

The measure of dispersion shows the
scatterings of the data. It tells the variation

of the data from one another and gives a
clear idea about the distribution of the data.

The types of measures of dispersion are
mean deviation, variance, standard deviation,

quartiles, deciles and percentiles.

56


MEASURES OF DISPERSION

= σ − ഥ


σ − ഥ

=

=
57


EXAMPLE 12

Find the mean, deviation
for the set data below:

2, 7, 6, 3, 4, 8

58


SOLUTION

Step 1: Calculate the mean
σ 2 + 7 + 6 + 3 + 4 + 8

ҧ = = 6 = 5

Step 2: Form a table

− ഥ
23
72
61
32
41
83

σ − ഥ = 12

Step 3: Substitute into the formula

= σ − ҧ 12
= 6 =

59


EXAMPLE 13

Find the variance and
standard deviation for the set
data below:

1, 4, 3, 2, 7, 8, 4, 8, 8

60


SOLUTION

Step 1: Calculate the mean
σ 1 + 4 + 3 + 2 + 7 + 8 + 4 + 8 + 8
ҧ = = 9 = 5

Step 2: Form a table − ഥ
16
− ഥ 1
14 4
41 9
32 4
23 9
72 1
83 9
41 9
83
83 σ − ഥ = 62

σ − ഥ = 22

61


Step 3: Substitute into the formula

σ − ҧ 2 62
9
Therefore, 2 = = = .

= = 6.89 = .

62


EXAMPLE 14

Find the mean deviation,
variance and standard deviation
for the set data below:

3, 4, 7, 8, 10

63


SOLUTION

Step 1: Calculate the mean
σ 3 + 4 + 7 + 8 + 10

ҧ = = 5 = 6.4

Step 2: Form a table − ഥ
11.56
− ഥ 5.76
3 3.4 0.36
4 2.4 2.56
7 0.6 12.96
8 1.6
10 3.6 σ − ഥ = 33.2

σ − ഥ = 11.6

64


Step 3: Substitute into the formula

Therefore, = σ − ҧ 11.6
= 5 = .

σ − ҧ 2 33.2
5
2 = = = .

= = 6.64 = .

65


LET'S TRY

QUESTION 1

Find the mean deviation, variance and
standard deviation for the following data:

a) 4, 5, 7, 10
b) 5, 3, 11, 9, 13, 8

66


MEASURES OF DISPERSION

σ − ഥ
= σ

= σ − ഥ
σ

=
67


EXAMPLE 15

The data below shows the age of
participants in a chess competition.
Find the mean deviation of the data.

Age (years) Number of participants
10 – 14 4
15 – 19 12
20 – 24 18
25 – 29 9
30 – 34 12
35 – 39 5

68


SOLUTION

Step 1: Calculate the mean

Age (years) Midpoint,

10 – 14 4 12 48
15 – 19 12 17 204
20 – 24 18 22 396
25 – 29 9 27 243
30 – 34 12 32 384
35 – 39 5 37 185
σ = 60 σ = 1460

σ 1460
Therefore, ҧ = σ = 60 = 24.3

69


Step 2: Add 1 column and calculate

Age (years) Midpoint, − ഥ

10 – 14 4 12 48 49.2
15 – 19 12 17 204 87.6
20 – 24 18 22 396 41.4
25 – 29 9 27 243 24.3
30 – 34 12 32 384 92.4
35 – 39 5 37 185 63.5

σ = 60 σ = 1460 σ − ҧ = 358.4

Step 3: σ − ҧ 358.4
Substitute into = σ = 60

the formula = .

70


EXAMPLE 16

The frequency distribution table below
show the marks of a pupils in a Quiz.
Find the variance of the data.

Mark Number of pupils
0–9 6
10 – 19 7
20 – 29 12
30 – 39 11
40 – 49 4

71


SOLUTION

Step 1: Calculate the mean

Age (years) Midpoint,

0–9 6 4.5 27
10 – 19 7 14.5 101.5
20 – 29 12 24.5 294
30 – 39 11 34.5 379.5
40 – 49 4 44.5 178
σ = 40 σ = 980

σ 980
Therefore, ҧ = σ = 40 = 24.5

72


Step 2: Add 1 column and calculate

Age (years) Midpoint, − ഥ

27 2400
0 – 9 6 4.5 700
0
10 – 19 7 14.5 101.5 1100
1600
20 – 29 12 24.5 294
379.5 σ − ҧ 2 = 5800
30 – 39 11 34.5

40 – 49 4 44.5 178

σ = 40 σ = 980

Step 3: 2 = σ − ഥ
Substitute into σ

the formula 5800
= 40

=

73


EXAMPLE 17

Find the standard deviation of the
data below:

Score Frequency
11 – 20 7
21 – 30 16
31 – 40 18
41 – 50 9

74


SOLUTION

Step 1: Calculate the mean

Age (years) Midpoint,

11 – 20 7 15.5 108.5
21 – 30 16 25.5 408
31 – 40 18 35.5 639
41 – 50 9 45.5 409.5
σ = 50 σ = 1565

σ 1565
Therefore, ҧ = σ = 50 = 31.3

75


Step 2: Add 1 column and calculate

Score Midpoint, − ഥ

11 – 20 1747.48
7 15.5 108.5

21 – 30 16 25.5 408 538.24

31 – 40 18 35.5 639 317.52

41 – 50 9 45.5 409.5 1814.76

σ = 50 σ = 1565 σ − ҧ 2 = 4418

Step 3: Calculate 2 = σ − ഥ = 4418
the variance σ 50

Step 4: = 88.36
Find the standard
= = 88.36
deviation = .

76


LET'S TRY

QUESTION 1

The table shows the height of a group
of students. Find the mean deviation
and variance for the data.

Height (cm) Number of students

100 - 109 3
110 - 119 5
120 - 129 7
130 - 139 6
140 - 149 4

77


LET'S TRY

QUESTION 2

The table shows the number of car sold by a
dealer in 100 days. Find the standard deviation
for the number of cars sold in a day.

Number of cars Number of days
50 - 59 2
60 - 69 10
70 - 79 18
80 - 89 26
90 - 99 20
100 - 109 19
110 - 119 5

78


Diterbitkan oleh
Politeknik Sultan Idris Shah

Sg.Lang, 45100 Sg. Ayer
Tawar

Selangor
No. Tel : 03 3280 6200
No. Fax : 03 3280 6400
Laman web : http://www.psis.edu.my


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