Balancing Redox Reac
Reactions
Rules for Writing Half-Reactions
1. Write an unbalanced ½ reaction showin
2. Balance all atoms except H and O
3. Balance O by adding H2O(l)
4. Balance H by adding H+(aq)
5. Balance the charge by adding e- and canc
For basic solutions only:
6. Add OH-(aq) to both sides to equal the numbe
7. Combine H+(aq) and OH-(aq) on the same side t
from both sides.
ctions using Half-
ng formulas for reactants and products
cel anything that is the same on both sides
er of H+(aq) present
to form H2O(l). Cancel equal amounts of H2O(l)
Balancing Redox Reac
Half-Re
SUMMARY
1. Use the information provided to start two h
2. Balance each half-reaction equation.
3. Multiply each half-reaction by simple whole
4. Add the two half-reaction equations, cancel
exactly the same on both sides of the equati
ctions by Constructing
eactions
half-reaction equations.
e numbers to balance electrons lost and gained.
lling the electrons and anything else that is
ion.
Balancing Redox Reactions by
• Example: A person suspected of being intoxic
person’s breath reacts with an acidic dichroma
acid) and aqueous chromium(III) ions. Predic
• Create a skeleton equation from the informatio
• Separate the entities into the start of two half-r
• Now use the steps you learned for balancing ha
• Now, balance the electrons lost and gained, an
anything else that is exactly the same on both s
y Constructing Half Reactions
cated blows into this device and the alcohol in the
ate ion solution to produce acetic acid (ethanoic
ct the balanced redox reaction equation.
on provided:
reaction equations
alf reactions
nd add the half reactions. Cancel the electrons and
sides of the equation.
Redox Terms
▫ Review: “LEO the lion says GER”
x Loss of electrons = entity being oxidized
x Gain of electrons = entity being reduced
x BUT…. Chemists don’t say “the reactant b
x Rather, they use the terms OXIDIZING A
x OXIDIZING AGENT: causes oxidation by
another substance in
x REDUCING AGENT: causes reduction by
substance in a redox
What does this mean? Let’s revisit our first exa
Which reactant was reduced?
So…. Which is the Oxidizing Agent (OA)
LEO = Oxidized Zn(s) Æ Zn 2+
GER = Reduced 2 H+(aq) + 2 e
being oxidized” or “the reactant being reduced”
AGENT (OA) and REDUCING AGENT (RA)
removing (gaining) electrons from
n a redox reaction
donating (losing) electrons to another
reaction
ample when zinc and hydrochloric acid reacted.
Which was oxidized?
)? Which is the Reducing Agent (RA)
(aq) + 2 e- Reducing Agent
e- Æ H2 (g) Oxidizing Agent
Redox Terms
▫ Silver ions were reduced to silver metal b
copper metal was oxidized to copper(II) i
▫ If Ag+(aq) is reduced it is the: OXIDIZING
▫ If Cu(s) is oxidized it is the:
REDUCIN
It is important to note that oxidation and redu
and oxidizing agents and reducing agents
by reaction with copper metal. Simultaneously,
ions by reaction with silver ions.
G AGENT (OA)
NG AGENT (RA)
uction are processes,
are substances.
REDOX React
Reduction
• Historically, the formation of a metal from
its “ore” (or oxide)
▫ I.e. nickel(II) oxide is reduced by
hydrogen gas to nickel metal
NiO(s) + H2(g) Æ Ni(s) + H2O(l)
Ni +2 Æ Nio
• A gain of electrons occurs (so the entity
becomes more negative)
• Electrons are shown as the reactant in the
half-reaction
• A species undergoing reduction will be
responsible for the oxidation of another
entity – and is therefore classified as an
oxidizing agent (OA)
tions … so far
Oxidation
• Historically, reactions with oxygen
▫ I.e. iron reacts with oxygen to
produce iron(III) oxide
4 Fe(s) + O2(g) Æ Fe2O3(s)
Fe 0 Æ Fe+3
• A loss of electrons occurs (so the entity
becomes more positive)
• Electrons are shown as the product in the
half-reaction
• A species undergoing oxidation will be
responsible for the reduction of another
entity – and is therefore classified as an
reducing agent (RA)
Redox Terms
• Summary so far:
▫ The substance that is reduced (
is also known as the oxidizing a
▫ The substance that is oxidized (
is also knows as the reducing a
• Question: If a substance is a
does this mean in
The substance has a very
• Question: If a substance is a
does this mean in
The substance has a weak attraction fo
(gains electrons)
agent
(loses electrons)
agent
very strong oxidizing agent, what
terms of electrons?
strong attraction for electrons.
very strong reducing agent, what
terms of electrons?
or its electrons, which are easily removed
Redox Table
• A reaction is considered spontan
• A reduction ½ reaction table is u
of a reaction
▫ Reduction Tables show reduction
therefore all the reactants will be
▫ If we list the OA’s from an experim
we create a reduction ½ reaction
SOA Ag+(aq) +
Cu2+(aq) +
Zn2+(aq) +
Mg2+(aq) +
neous if it occurs on its own
useful in predicting the spontaneity
n ½ reactions in the forward direction,
oxidizing agents
ment in decreasing order of strength,
table:
1 e- Æ Ag(s) SRA
2 e- Æ Cu(s)
2 e- Æ Zn(s)
2 e- Æ Mg(s)
Building Redox Tab
• Consider the following experimental
the redox table you have created
Hg2+(aq) Cu2+(a
Hg(s) ✗ ✗
Cu(s) ✓ ✗
Ag(s) ✓ ✗
Au(s) ✗ ✗
SOA Au3+(aq) +
Hg2+(aq) +
Ag+(aq) +
Cu2+(aq) +
Zn2+(aq) +
Mg2+(aq) +
bles #1
l information and add half-reactions to
aq) Ag+(aq) Au3+(aq)
✗✓
✓✓
✗✓
✗✗
3 e- Æ Au(s) SRA
2 e- Æ Hg(s)
1 e- Æ Ag(s)
2 e- Æ Cu(s)
2 e- Æ Zn(s)
2 e- Æ Mg(s)
Building Redox Tab
SOA Au3+(aq) + 3 e-
Hg2+(aq) + 2 e-
Ag+(aq) + 1 e-
Cu2+(aq) + 2 e-
Zn2+(aq) + 2 e-
Mg2+(aq) + 2 e-
▫ The spontaneity rule!
x A reaction will be spontaneous if
OA = Spontaneous
above Reaction
RA
bles #1
- Æ Au(s) SRA
- Æ Hg(s)
- Æ Ag(s)
Æ Cu(s)
Æ Zn(s)
Æ Mg(s)
f on a redox table:
RA = Non-spontaneous
below Reaction
OA
Building Redox Tab
• Example 2: Use the following information
OA RA
3 Co 2+ (aq) + 2 In(s) Æ 2 In 3+ (aq) + 3 C
OA RA
Cu 2+ (aq) + Co(s) Æ Co 2+ (aq) + Cu(s)
OA RA
Cu 2+ (aq) + Pd(s) Æ no reaction
SOA Pd2+(aq) + 2 e
Cu2+(aq) + 2 e-
Co2+(aq) + 2 e-
In3+(aq) + 3 e-
bles #2
n to create a table of reduction ½ reactions
Co(s) Pd(s)
Co(s)
Cu2+
Co2+
In(s)
e- Æ Pd(s) SRA
- Æ Cu(s)
- Æ Co(s)
Æ In(s)
Building Redox Tab
• Example 3: Use the following information
OA RA
2 A 3+ (aq) + 3 D(s) Æ 3 D2+ (aq) + 2 A(s)
OA RA
G + (aq) + D(s) Æ no reaction
OA RA
3 D 2+ (aq) + 2 E(s) Æ 3 D(s) + 2 E3+(aq)
OA RA
G + + E(s) Æ no reaction
(aq)
SOA A3+(aq) + 3 e-
2 e-
D2+(aq) + 3 e-
E3+(aq) + 1 e- Æ
G+(aq) +
bles #3
n to create a table of reduction ½ reactions
A3+
D2+(aq) D(s)
E(s)
G+
Æ A(s) SRA
Æ D(s)
Æ E(s)
Æ G(s)
Building Redox Tab
• So far we have been using examples wh
and the reducing agents are metal atom
▫ Non-metal atoms I.e. Cl2(g) + 2e- Æ 2 C
▫ Non-metal ions I.e. 2 Br- (aq) Æ Br2(l) +
• Redox Table Trend
▫ OA’s tend to be metal ions and non-m
▫ RA’s tend to be metal atoms and non-
• Also, are there any entities that could a
▫ Multivalent metals
bles
here the oxidizing agents are metal ions
ms. What else could gain or lose electrons?
Cl-(aq) (Cl2(g) could act as a Reducing Agent)
+ 2 e- (2Br-(aq) could act as an Oxidizing Agent)
metal atoms
-metal ions
act as both OA or RA?
• Example 4: Use the following information
RA OA
Ag(s) + Br2(l) Æ AgBr(s)
RA OA
Ag(s) + I2(s) Æ no evidence of rea
OA RA
Cu2+(aq) + I-(aq) Æ no redox reactio
OA RA
Br2(l) + Cl-(aq) Æ no evidence of re
SOA Cl2(g) + 2 e- Æ
Br2(l) + 2 e- Æ
Ag+(aq) + 1 e- Æ
I2(s) + 2 e- Æ
Cu2+(aq) + 2 e- Æ
n to create a table of reduction ½ reactions
action Br2(l) Cl-
on
eaction I2(s) Ag(s)
Cu2+(aq) I-(aq)
Æ 2Cl-(aq) SRA
Æ 2Br-(aq)
Æ Ag(s)
Æ 2I-(aq)
Æ Cu(s)
Predicting Redox Re
• Now that you know what redox reactions ar
if a reaction will occur (is spontaneous) a
reaction equation will be. How do we d
1. The first step is to determine all the entities
▫ Helpful reference: Table 5 pg. 680
▫ Remember: In solutions, molecules and ions
independently of each other.
▫ Example: When a solution of potassium
slowly poured through acidified iron(II)
▫ Does a redox reaction occur and what is th
eactions
re, you will be responsible for determining
and if so, what the
do this?
s that are present.
s behave
permanganate is
) sulfate solution.
he reaction equation?
Predicting Redox Re
2. The second step is to determine all poss
▫ This is a crucial step!! Things to watch out
x Combinations
x (i.e. MnO4-(aq) is an oxidizing agent only i
x To indicate this draw an arc between the
hydrogen ion
x Species that can act as both OA and RA
x Any lower charge multivalent metal i.e. F
x Water (H2O(l))
x Label both possibilities in your list
eactions
sible OA’s and RA’s
t for:
in an acidic solution)
e permanganate and
Fe2+, Cu+, Sn2+, Cr2+
• Before we move on, let’s pract
▫ Pg. 680 #23
tice Step 1 and 2
• Pg. 680 #23
• Pg. 680 #23
Predicting Redox Re
3. The third step is to identify the SOA a
SOA
3. The fourth step is to show the ½ reac
▫ SOA equation straight from table. SRA
▫ Are these equations balanced? Do the n
▫ If not, multiply one or both equations b
eactions
and SRA using Appendix C11 (page 805)
SRA
ctions (from the redox table) and balance
A equation read from right to left
number of electrons lost = electrons gained
by a number then add the balanced equations
Predicting Redox Re
3. The last step is to predict the spontan
ionic equation represent a spontaneo
redox reaction?
If the SOA
above Æ Spontaneo
SRA??
If the SRA
below Æ Nonspontan
SOA
eactions
neity. Does the net
ous or non-spontaneous
ous
neous
Predicting Redox Re
Could copper pipe be used to transport a hyd
1. List all entities
1. Identify all possible OA’s and RA’s
1. Identify the SOA and SRA
2. Show ½ reactions and balance
3. Predict spontaneity
Since the reaction is
nonspontaneous, it should be
possible to use a copper pipe to
carry hydrochloric acid
eactions #2
drochloric acid solution?
REDOX Reacti
Reduction
• Historically, the formation of a metal from
its “ore” (or oxide)
▫ I.e. nickel(II) oxide is reduced by
hydrogen gas to nickel metal
NiO(s) + H2(g) Æ Ni(s) + H2O(l)
Ni +2 Æ Nio
• A gain of electrons occurs (so the entity
becomes more negative)
• Electrons are shown as the reactant in the
half-reaction
• A species undergoing reduction will be
responsible for the oxidation of another
entity – and is therefore classified as an
oxidizing agent (OA)
• Decrease in oxidation number
ions … the end
Oxidation
• Historically, reactions with oxygen
▫ I.e. iron reacts with oxygen to
produce iron(III) oxide
4 Fe(s) + O2(g) Æ Fe2O3(s)
Fe 0 Æ Fe+3
• A loss of electrons occurs (so the entity
becomes more positive)
• Electrons are shown as the product in the
half-reaction
• A species undergoing oxidation will be
responsible for the reduction of another
entity – and is therefore classified as an
reducing agent (RA)
• Increase in oxidation number