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Published by Cambridge Paperbacks, 2018-11-05 02:45:04

Even more Algebra

Even More Intermediate



Algebra



Problems and Solutions


with your fx-991ES or fx-



115ES Calculator












Dr Allen Brown







Cambridge 
Paperbacks

Cambridge Paperbacks


www.CambridgePaperbacks.com

First published by Cambridge Paperbacks 2018



© Allen Brown 2018

All rights reserved. No part of this publication may be reproduced or
transmitted in any form or by any means, electronic or mechanical, including
photocopy, recording, or any information storage and retrieval system without
permission in writing from the author.


Disclaimer

Although the author and publisher have made every effort to ensure that the
information in this book was correct during preparation and printing, the
author and publisher hereby disclaim any liability to any party for any errors
or omissions.

Read this First


Continuing the theme from the previous two ebooks

on Intermediate Algebra Problems and Solutions, this
ebook has more examples showing you how to make

effective use of your fx-991ES or fx-115ES calculator.

The emphasis has been made on re-arranging

expressions in order to perform calculations to

determine the value of x. Once x has been
determined, the SOLVE feature in the fx calculator has

been used to confirm the answer.


This is very powerful technique for you to acquire in
order to ensure the correctness of your result. You are

encouraged to use it when solving algebraic problems
on your course of study whether it’s at GCSE level or

higher.


As you progress working through this ebook your
understanding of maths will increase and as stated

previously, it’s therefore important you perform all

the keystrokes yourself to maximise the learning
experience.


Dr Allen Brown

Cambridgeshire

Contents

1 Equations with Reciprocals ................................................................. 3

Example 1-1: ....................................................................................... 3
Example 1-2: ....................................................................................... 6

Example 1-3: ....................................................................................... 6
Example 1-4: ....................................................................................... 7

Example 1-5: ....................................................................................... 8
Example 1-6: ....................................................................................... 9

Example 1-7: ..................................................................................... 10

2 Quadratic Expressions ....................................................................... 12
Example 2-1: ..................................................................................... 12

Example 2-2: ..................................................................................... 13

Example 2-3: ..................................................................................... 14
Example 2-4: ..................................................................................... 15

Example 2-5: ..................................................................................... 16
Example 2-6: ..................................................................................... 17

3 Cubic Expressions .............................................................................. 19
Example 3-1: ..................................................................................... 19

Example 3-2: ..................................................................................... 21

Example 3-3: ..................................................................................... 23
4 Trigonometric Expressions ................................................................ 25

Example 4-1: ..................................................................................... 25

Example 4-2: ..................................................................................... 27

1

Example 4-3: ..................................................................................... 29
Example 4-4: ..................................................................................... 30

Example 4-5: ..................................................................................... 31

Example 4-6: ..................................................................................... 33
5 Logarithmic and Exponential Expressions ........................................ 35

Example 5-1: ..................................................................................... 35
Example 5-2: ..................................................................................... 37

Example 5-3: ..................................................................................... 39

Example 5-4: ..................................................................................... 40
6 Indices ................................................................................................ 43

Example 6-1: ..................................................................................... 43
Example 6-2: ..................................................................................... 45

Example 6-3: ..................................................................................... 46

Example 6-4: ..................................................................................... 47
Example 6-5: ..................................................................................... 49

Example 6-6: ..................................................................................... 50
7 Changing the Subject of an Equation................................................ 52

Example 7-1: ..................................................................................... 52

Example 7-2: ..................................................................................... 55
Example 7-3: ..................................................................................... 56

Example 7-4: ..................................................................................... 58






2

1 Equations with Reciprocals

Very often you will come across equations which have

fractional components and you are asked to get all the

x values onto the left hand side of the equation.
Following the golden rule, whatever you do on one

side of the equation you need to do the equivalent on
the other side. Your fx-991ES calculator is really useful

for indicating whether you have the right answer

using the SOLVE feature. In the following examples,
the keystrokes will be given for each equation.





Example 1-1:

Solve the equation,

− 5
+ = 10
4 3

With the 4 and 3, the common value is 12, need to

multiple both sides by 12,

− 5
12 × + 12 × ( ) = 12 × 10
4 3

This becomes,


3 + 4( − 5) = 120
3

Expand the bracket,

3 + 4 − 20 = 120


Add 20 to both sides of the equation,


3 + 4 − 20 + 20 = 120 + 20

Leaving

7 = 140
Divide both sides by 7,

7 140
=
7 7

Giving the result = 20. This result can be confirmed
using the SOLVE feature on your fx calculator. Here is

the original equation,

− 5
+ = 10
4 3

Enter the following keystrokes, (X)


CQ(X)a4$+aJ(X)p5R3
$Q(=)10











4

Notice we use the Q= not the = in the bottom

right corner on your calculator. Now enter,
q(SOLVE) and you see in the display,










You are now expected to enter a guess value for X, this
is how the algorithm in the calculator works – it needs

a seed value (a good guess). Enter 1=,









You will see the correct value for X = 20 which is what

we previously derived. The L-R, indicates whether
there was any difference between the left hand side

and the right hand side of the equation. Sometimes

(SOLVE) only gets an approximation for X and this
what L-R shows.


In the remaining examples you can solve the

equations yourself and we shall use SOLVE to show
whether your answer is correct.



5

Example 1-2:

Solve for x,

− 5 + 5
+ = 5
10 5

The keystrokes for solving this equation are.


CaQ(X)p5R10$+aJ(X)
+5R5$Q(=)5










q(SOLVE) 1=









x = 15.





Example 1-3:
Solve for x,


− 2 + 10
+ = 5
2 9
6

The keystrokes are,

CaQ(X)p2R2$+aJ(X)+

10R9$Q(=)5










q(SOLVE) 1=









x = 8.





Example 1-4:

Solve for x,

+ 19
= 3 +
5 4

The keystrokes are,

CaQ(X)+19R5$Q(=)3+

J(X)a4



7

q(SOLVE) 1=








x = 16.





Example 1-5:

Solve for x,

− 4 − 10
=
7 5

The keystrokes are,


CaQ(X)p4R7$Q(=)aJ(X)
p10R5










q(SOLVE) 1=

8

x = 25.




Example 1-6:

Solve for x,


+ 5 + 1 + 3
− =
6 9 4

The keystrokes are,

CaQ(X)+5R6$paJ(X)+

1R9$Q(=)aJ(X)+3R4









q(SOLVE) 1=








1
= −0.1426. . = −
7

9

Example 1-7:

Solve for x,

+
=


1 When A =9.716, B = 2.328, C = 7.95 and D = 1.693


2 When A = 58.97, B =39.93, C = 4.33 and D = -123.84

1 The keystrokes are,


CaQ(A)+Q(B)RQ(C)pQ(D)$
Q(=)Q(X)










q(SOLVE)

A? 9.716=
B? 2.328=

C? 7.95=

D? 1.693=







=

10

= 1.92488




2 Enter the keystrokes


q(SOLVE)
A? 58.97=

B? 39.93=

C? 4.33=

D? z123.84=








=









= 0.7716






11

2 Quadratic Expressions

When solving quadratic equations, you are already

familiar with the well expression,


2
− ± √ − 4

2
2
You will have real solutions provided ≥ 4 . To

perform this calculation, use the multi-stage features
2
of your fx calculator, let = √ − 4 first. The
keystrokes are,


CQ(F)Q(=)sQ(B)dp4Q(A)
Q(C)$Q(:)


azJ(B)+J(F)R2J(A)$Q(:)

azJ(B)pJ(F)R2J(A)









After entering all these keystrokes, this is what you
will see in the display.


Example 2-1:

1 Solve the following quadratic expression,

12

2
5 + 14 − 55
Enter the keystrokes,


r

B? 14=

A? 5=
C? z55=


= =






The expression becomes,


2
5 + 14 − 55 = (5 − 11)( + 5)



Example 2-2:

2 Solve the following quadratic expression,

2
3 − 44 + 121

Enter the keystrokes,


r

B? z44=


13

A? 3=

C? 121=

= =






The expression becomes,

2
3 − 44 + 121 = ( − 11)(3 − 11)




Example 2-3:

3 Solve the following quadratic expression,

2
6 − 25 + 21

Enter the keystrokes,

r

B? z25=

A? 6=

C? 21=
= =







14

The expression becomes,

2
6 − 25 + 21 = ( − 3)(6 − 7)


Example 2-4:

4 Solve the following quadratic expression,

2
50 − 15 − 27

Enter the keystrokes,

r

B? z15=

A? 50=

C? z27=

= =







The expression becomes,

2
50 − 15 − 27 = (10 − 9)(5 + 3)

You can of course use the EQN option from the MODE

to solve quadratic equations; these examples show

the versatility of the fx-991ES calculator.

15

Example 2-5:

5 Solve the following quadratic expression,

5 4 3
− =
− 2 + 6

After you have re-arranged this expression to look like

a quadratic you should be able to find the solutions.

We shall use the SOLVE feature on your fx-991ES
calculator. The keystrokes are,

C5aQ(X)p2$p4aJ(X)$

Q(=)3aJ(X)+6









There are two solutions, we shall use two seed values,

-3 and +3,


q(SOLVE)


Solve for X z3=










16

q(SOLVE)


Solve for X 3=








The expression can be factorised to give,


( + 2)( − 12)

This should confirm the result you got from re-

arranging the original expression.




Example 2-6:

6 Solve the following quadratic expression,

3 − 2 5
= − 2
2 − 3 + 4

More re-arranging to get it into a recognisable

quadratic form. It can be solved directly similar to the
previous example. The keystrokes for your fx

calculator are,

Ca3Q(X)p2R2J(X)p3$

Q(=)5J(X)aJ(X)+4$p2


17

q(SOLVE)


Solve for X 3=









q(SOLVE)


Solve for X z3=









You will recognise that 10.666.. = 10⅔ , the factorised

quadratic is therefore,

(3 − 32)( − 1)










18

3 Cubic Expressions

3
You will encounter equations which have x and here
are some examples of how they are solved, that is

bring all the x values onto the left hand side.




Example 3-1:

Solve for x in the following equation,

3 3
3
+ 7 = + 2
4 5

Subtract ¾ from both sides,


3 3 3 3
3
+ 7 − = + 2 −
4 4 5 4

Which leaves,

3 5
3
7 = +
5 4

3
Subtract from both sides,
5

3 5
3
7 − =
5 4

Which becomes,

19

1 34 3 5
3
(7 − ) = =
5 5 4

5
Multiply both sides by to give,
34
5 5 25
3
= × = = 0.1838
4 34 136

Therefore,


3
= √0.1838

The keystrokes for this calculation are,

CqS0.1838=









To confirm this is correct, consider the original

expression,


3 3
3
+ 7 = + 2
4 5

The keystrokes to solve this expression are,

C3a4$+7Q(X)q(x )Q(=)J
3
q(x )a5$+2
3

20

q(SOLVE)









(Note your calculator may have a difference number
in the display from a previous calculation).

=










Which confirms the answer.





Example 3-2:
Solve for x in the following equation,


+
3
=
− 2

Where A = 7.169, B = 6.43, C = 8.46 and D = 1.59

21

The expression can be written as,



3 +
= √
− 2


The keystrokes for your fx calculator to perform this

calculation are,

CqSaQ(A)+Q(B)RQ(C)p

Q(D)d

r

A? 7.169=

B? 6.43=

C? 8.48=
D? 1.59=











The value of x is therefore 1.31857








22

Example 3-3:

Solve for x in the following equation,

2
3
= √2.2 −
7

After rearranging you should arrive at,



3 2 2
= √ 2.2 − ( )
7


The keystrokes for this calculation are,

CqS2.2p(2a7$)

d=









To confirm this result, the keystrokes for finding x
using SOLVE are,


C2a7$Q(=)s2.2pQ(X)
q(x )
3








23

q(SOLVE)
1=












The value of x = 1.284, this confirms the result you

should have obtained by re-arranging the expression.























Available from


www.CambridgePaperbacks.com


24

4 Trigonometric Expressions

In this chapter you will encounter trigonometric

functions are their inverse values which you should be

able to derive. Here are two fully worked examples.




Example 4-1:

Solve for x in the following equation,



2
√1 − = sin(27.7 )
Square both sides of the expression,

2

2
1 − = sin (27.7 )
Add -1 to both sides,

2

2
1 − − 1 = sin (27.7 ) − 1
Leaving

2
2

= 1 − sin (27.7 )
Take the square root of both sides,


2

= √1 − sin (27.7 )
The keystrokes for the calculation are,




25

Cs1pj27.7q(Deg)1)

d=










Leaving x = 0.8854. The (Deg) keystroke is found

above the M key; it’s useful to use this should the

calculator be in it’s radian mode. This result can be
confirmed using SOLVE with the following keystrokes,



2
√1 − = sin(27.7 )
Cs1pQ(X)d$Q(=)j27.

7q(Deg)1)









q(SOLVE) 1=









Which confirms the result.


26

Example 4-2:

Solve for x in the following equation for x in the range
o
o
[15 , 25 ]
7
= cos(2 − 1)
9

Take the inverse cosine of both sides,

7
cos −1 ( ) = cos −1 (cos(2 − 1))
9

7
2 − 1 = cos −1 ( )
9

Add 1 to both sides,

7
2 − 1 + 1 = cos −1 ( ) + 1
9

7
2 = cos −1 ( ) + 1
9

Divide both sides by 2,

1 7
= [cos −1 ( ) + 1]
2 9

The keystrokes for this calculation are,






27

C1a2$(q>7a9$)

+1)=


x







o
Therefore x = 19 , 58 minutes and 16.39 seconds. You
will have notice we used the x key to convert an
angle into minutes and seconds. To confirm this result

using SOLVE, enter the following keystrokes,

7
= cos(2 − 1)
9

C7a9$Q(=)k2Q(X)p1)









o
o
We are looking for a solution in the range [15 , 25 ]
q(SOLVE) 15=








Which confirms the result.

28

In the following examples, re-arrange the expressions

yourself to get x on the left hand side and perform the
calculation.





Example 4-3:
Solve for x by re-arranging the following equation


1 − 3

= tan(54.3 )
3.2

After re-arranging you should arrive at the result,


3
= √1 − 3.2 tan(54.3 )

The keystrokes for this calculation are,

CqS1p3.2l54.3

)=








To confirm this result, the keystrokes for finding x

using SOLVE are,

Ca1pQ(X)q(x )R3.2$
3
Q(=)l54.3q(Deg)1)

29

q(SOLVE) 1=








x = -1.5115 which should confirm your result from re-

arranging the expression.



Example 4-4:

Solve for x by re-arranging the following equation

16.8
2
3 − = 0

sin(65.2 )
After re-arranging you should arrive with,



3 16.8
= √
3 sin(65.3)


The keystrokes for this calculation are,

CqS16.8a3j65.

3)=


30

To confirm this result, the keystrokes to solve this

expression are,

C3Q(X)dp16.8aJ(X)j

65.2q(Deg)1)$Q(=)0









q(SOLVE) 1=








The value of x = 1.834





Example 4-5:
Find the value of x in the expression,


1 +
= |cos ( )|
2 2

When

31

1 A = 85.3, B = 102.8 and C = 5.7

2 A = 55.2, B = 15.8 and C = 2.5

After re-arranging your should arrive with,

1
=
+
√2 |cos ( )|



The keystrokes for this calculation are,

C1as2q(Abs)kaQ(A)+

Q(B)RQ(C)$)r


The keystrokes for the original expression are,

C1a2Q(X)d$Q(=)q(Abs)k

aQ(A)+Q(B)RQ(C)$)









You will see the expression in the display of your fx

calculator,

1 q(SOLVE)

A? 85.3=

B? 102.8=

32

C? 5.7=

Solve for X 1=








The value of x is 0.772.

2 q(SOLVE)


A? 55.2=
B? 15.8=

C? 2.5=

Solve for X 1=








The value of x is 0.7109




Example 4-6:

Re-arrange the following expression to find x.

2
+ tan(3 − 1) = 2.6
11.5




33

After re-arranging this expression you should arrive

with,

1 2
= [1 + tan −1 (2.6 − )]
3 11.5

The keystrokes for this calculation are,

C1a3$(1+q?2.6

p2a11.5$))=








To confirm this result, enter the following keystrokes,

C2a11.5$+l3Q(X)p

1)Q(=)2.6q(SOLVE)


Solve for X 1=








Leaving x = 22.866.










34

5 Logarithmic and Exponential Expressions

In this chapter we shall be looking at mix of
logarithmic and exponential expressions as they are

both closely linked.




Example 5-1:

Find the value of x in the following expression.


5.4
= log (3.2 + 2)
3
3

Express this as,

5.4
log (3) = log (3.2 + 2)
3
3
3
This can written as,


5.4
log (3 3 ) = log (3.2 + 2)
3
3
Remove the logs,


5.4
3 3 = 3.2 + 2


Add -2 to both sides,

5.4
3.2 = 3 3 − 2

35

Divide both sides by 3.2

5.4
3 3 − 2
=
3.2


The keystrokes for performing this calculation are,

Ca3^5.4P3$p2R3

.2=









The value of x is 1.6327, to confirm this result use
SOLVE on your fx-991ES calculator with the following

keystrokes,

5.4
= log (3.2 + 2)
3
3
C5.4a3$Q(=)i3$3.

2Q(X)+2










q(SOLVE)

36

Solve for X 1=








Which confirms the result.





Example 5-2:
Re-arrange the following expression to find the value

of x. when A = 5.87, B = 8.419 and C = 2.097


1.7 =


Take logs on both sides,



ln( 1.7 ) = ln ( )


This becomes,


1.7 = ln ( )


Divide both sides by 1.7


1
= ln ( )
1.7 −

37

The keystrokes for this expression are,

C1a1.7$hQ(A)aQ(B)p

Q(C)$)








r
A? 5.87=


B? 8.419=
C? 2.097=







The value of x = -0.0436. To confirm this result, use

SOLVE on the original expression; the keystrokes are,


1.7 =


CqH1.72Q(X)$Q(=)

Q(A)aQ(B)pQ(C)









38

q(SOLVE) ===1=








which confirms the result is correct. You should now
be able to calculate the values of x in the following

examples.



Example 5-3:

Find the value of x in the following expression by re-

arranging the expression to make x the subject,

log ( + 2) = 1.2
7

After re-arranging you should arrive with,

= 7 1.2 − 2


The keystrokes for this calculation are,

C7^1.2$p2=









To confirm this solution, enter the following
keystrokes into the fx calculator,

39

Ci7$Q(X)+2$Q(=)1.2









q(SOLVE)

Solve for X 1=









The value of x is 8.3304 which should correspond with
the result you obtained.





Example 5-4:

Find the value of x in the following expression when

1. A = 7.169, B = 5.82 and C = 3.382

2. A = 8.46, B =8.97 and C = 7.17

+
10 1.4 =


After re-arranging you should arrive with,






40

1 +
= log ( )
1.4

The keystrokes for this calculation are,

C1a1.4$gaQ(A)+Q(B)

RQ(C)$)r


To confirm this result, enter the following keystrokes,

CqG1.4Q(X)$Q(=)a

Q(A)+Q(B)RQ(C)









1 q(SOLVE)

A? 7.169=

B? 5.82=

C? 3.382=
Solve for X 1=








The value of x is 0.4174 which should correspond with

the first result you obtained.

41

2 q(SOLVE)
A? 8.46=

B? 8.97=

C? 7.17=

Solve for X 1=









The value of x is 0.2755 which should correspond with

the second result you obtained.




















Available from


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42

6 Indices

Although you have been using some indices, in this

chapter we shall look at specific examples involving

indices.




Example 6-1:

Find the value of x which satisfies the expression,

1
= 0.488
2 + 2.3

Invert both side of the expression,
1
2 + 2.3 =
0.488
Add -2 to both sides,

1
2 + 2.3 − 2 = − 2
0.488

leaving
1
2.3 = − 2
0.488


2.3 1
= √ − 2
0.488



43

The keystrokes for performing this calculation are,

CF2.3$1a0.488$

p2=









The value of x is 0.2699. To confirm this result, enter

the following keystrokes using the SOLVE feature on
your fx calculator,


1
= 0.488
2 + 2.3

C1a2+Q(X)^2.3$$

Q(=)0.488










q(SOLVE) Solve for X 1=








Which confirms the result.

44

Example 6-2:

Find the value of x which satisfies the expression,


1 − 1.9
= 0.377
1 + 1.9


After re-arranging you should arrive with,



1.9 1 − 0.377
= √
1 + 0.377



The keystrokes for this calculation are (using M),

0.377=

qF1.9$a1pMR1+

M=









Confirm this result with the following keystrokes for

the original expression,

Ca1pQ(X)^1.9R1+
J(X)^1.9$$Q(=)0.377






45

q(SOLVE) Solve for X 1=









Which should confirm the result you obtained.




Example 6-3:

Find the value of x which satisfies the expression,



1
√ = 1.8665
1 − −1.6



After re-arranging you should arrive with,

1 1
= − ln (1 − )
1.6 1.8665 2

The keystrokes for this calculation are,

Cz1a1.6$h1p1a1

.8665d$)=



46


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