Smart PBD Mathematics Yr5_Anyflip

PENERBIT ILMU
BAKTI SDN. BHD.

Day: Day: DDataet:e:

PdPc Pembelajaran
Abad ke-21 Activities

Activity 1 Travelling File

UNIT 1 Whole Numbers and Operations

Instructions:
1 Group
Divide pupils into four groups.

2 Tasks
(a) Each group is given a file containing questions to find the magic number. Teacher prepares
the question on a piece of paper.

EXAMPLE
Find the magic number. Then, complete the blank squares below.
PENERBIT ILMU
BAKTI SDN. BHD.12 8 3 10 Note:
10 8 18 975 The magic
20 12 4 4 11 6 number is
6 16 14 the sum up
Magic number: 21 of all three
Magic number: 36 4 numbers either
3 horizontally,
10 20 18 vertically or
5 10 3 24 16 8 diagonally.
468 14 12 22
927 Magic number: 48
Magic number: 18

(b) All groups are given 10 minutes to answer the questions. They need to write down the
answers and then put them back into the file. The file is distributed to other groups.

3 Discuses in the group
Each group will get files from other groups. They are required to read the questions and check
the answers and edit them if necessary.

4 Discuses in the class
After all groups respond to two or three files, all questions and answers are discussed in the
class.

P6

Mathematics KSSR Year 5 Class:

Name:
School:

Content Content Standard Learning Standard Pages Performance
Performance ( )Achieved/

Level ( ) Not
Achieved
PENERBIT ILMU
LEARNING AREA: NUMBERS AND OPERATIONSBAKTI SDN. BHD.1.1.1 (i) – (iii) 4 –
5 –
Unit 1 Whole Numbers and 1.1 Number Value 1.1.2 (i) 6 –
Operations 7 –
1.1.2 (ii) 8 3
1.2 Prime Numbers 9 2
1.3 Estimation 1.1.2 (iii) 10 3
1.4 Rounding Off
1.1.2 (iv) – (v) 11 3
Numbers
1.5 Number Patterns 1.2.1 12 3

1.6 Basic Operations 1.3.1 13 4
14 4
1.7 Mixed Operations 1.4.1 15 4
1.8 Using Unknown 1.4.2 16 4
1.9 Problem Solving 17 4
1.5.1 18 4
Unit 2 Fractions, Decimals 2.1 Fractions 1.5.2 19 –
and Percentages 2.2 Decimals 20 –
1.6.1
21 – 24 5
1.6.2
28 3
1.6.3
29 2, 3
1.6.4
30 3
1.7.1 (i) – (ii) 31 3

17.1 (iii) – (iv)

1.8.1
1.8.2

1.9.1
1.9.2
1.9.3

2.1.1

2.2.1
2.2.2

2.2.3

2.2.4

P13

Contents

Unit Whole Numbers an Operations Quiz Extra
Practice
1 Express Notes
DSKP Practice 1
Summative Practice 1 4
25

Unit Fractions, Decimals and Percentages Tutorial Quiz Extra
Video Practice
2 Express Notes 27
PENERBIT ILMUDSKP Practice 28
BAKTI SDN. BHD.Summative Practice 2 40

Unit Money Quiz 42
43
3 Express Notes 54
DSKP Practice 56
Unit Summative Practice 3 57
62
4 Time Video Quiz Extra 64
Practice 65
82
Express Notes 85
DSKP Practice 86
Summative Practice 4 93
96
Unit Length, Mass and Volume of Liquid Website Video Quiz Extra 97
Practice 104
5 Express Notes
DSKP Practice
Summative Practice 5

Unit Space Website PIB Quiz

6 Express Notes
DSKP Practice
Summative Practice 6

Unit Coordinates, Ratio and Proportion Website Video PAK-21 Quiz Extra
Activity Practice
7 Express Notes
DSKP Practice
Summative Practice 7

Unit Data Handling Video Quiz 108
109
8 Express Notes 117
DSKP Practice 119
Summative Practice 8

Ujian Akhir Sesi Akademik

e-Questions Scan the
QR code to
Scan QR code to download download the

• Pupil's Performance Record Teacher’s
• Answers Resource

User Guide P1
Pembelajaran Abad ke-21 Activities P6
Pupil's Performance Record P13
Instrumen Penjaminan Kualiti (Pemantauan) P16

Unit Learning Area: Numbers and Operations Digital File
Unit 1
1 Whole Numbers and
Operations

Express Notes

1 Place value and digit value
Number: 643 028
PENERBIT ILMU
BAKTI SDN. BHD.Digit6 4 30 2 8
tens ones
Place hundred ten thousands hundreds 20
value thousands thousands 8

Digit value 600 000 40 000 3 000 0

2 Read, say and write numbers

643 028
Six hundred forty-three thousand and twenty-eight

3 Extended notation

Partition Place value 6 hundred thousands + 4 ten thousands +
643 028 3 thousands + 0 hundreds + 2 tens + 8 ones

Digit value 600 000 + 40 000 + 3 000 + 20 + 8

4 Compare the value of two numbers

Case 1: 78 410 5 digits
278 410 278 410 is larger than 78 410

6 digits

Case 2: 643 028 7 000 > 3 000 647 028 is larger than 643 028
647 028

5 Arrange numbers in order
(a) Ascending order: arrangement of numbers from the smallest value to the largest
value
EXAMPLE 3 580, 8 053, 15 380, 15 830, 50 138, 85 013, 258 130

(b) Descending order: arrangement of numbers from the largest value to the
smallest value
EXAMPLE 259 140, 95 014, 50 149, 15 940, 15 490, 9 054, 4 590

1

Name: Class: Date:

4 A factory produces 875 360 boxes of gloves to be sent to government hospitals and
private hospitals. The number of gloves sent to government hospitals is 104 290
boxes more than private hospitals. Calculate the number of boxes of gloves sent to
government hospitals.

Government 104 290
hospital

Private hospital

PdPc

Extra = (875 360 – 104 290) ÷ 2

Practice= 385 535 boxes [1 mark]

PENERBIT ILMUNumber of boxes of gloves sent to government hospitals
BAKTI SDN. BHD.
= 385 535 + 104 290 [1 mark]

= 489 825 boxes [1 mark]

[3 marks] PL4

5 Table 1 shows the number of visitors to a theme park in three months.

Month Number of visitors
January 135 000
February 89 650 more than in January
March twice more than in February

Table 1

(a) Calculate the number of visitors to the theme park in February.

135 000 + 89 650 = 224 650 visitors

[1 mark] [1 mark]

[2 marks] PL3

(b) The number of visitors to the theme park in March is 449 300. Prove it.

February 224 650 2 times more than
March February

Number of visitors in March = 3 u 224 650 [1 mark]

= 673 950 [1 mark]

Thus, the statement is incorrect. [1 mark]

[3 marks] PL5

Extra
Practice

26

DSKP Practice NNaammee:: CClalassss:: DDaattee::

2.1 Fractions Textbook Pages: 65 – 69
Multiply fractions of two numbers. L.S 2.1.1 PL3

1 1 u 4 = 4 2 2 u 3 = 2 3 4 u 5 = 2 1
5 5 9 3 8 2

2 u 3 1 41 u 5
9 82
3

= 2 = 5
3 2
Tutorial
Video = 2 1
2
PENERBIT ILMU
BAKTI SDN. BHD.442u5=22153u 2 1 = 6 1 6 2 u 3 = 3
3 3 6 2 5 4 10
PdPc

14 u 5 31 u 13 12 u 3
3 6 5 42
2

= 70 = 13 = 3
3 2 10

= 23 1 = 6 1
3 2

7 5 u 2 1 = 1 11 8 2 1 u 1 5 = 4 5 9 3 1 u 1 3 = 6 1
8 3 24 3 6 18 2 4 8

5 u 7 7 u 11 7 u 7
8 3 3 6 2 4

= 35 = 77 = 49
24 18 8

= 11241 = 4158 = 6 1
8

PdPc Tutorial Video PdPc Tutorial Video

Scan the QR code or visit https: Scan the QR code or visit https:
//www.youtube.com/watch?v= //www.youtube.com/watch?v=
alstJ37BoZo to watch a video about gMJBu8BXhU to watch a video about
multiplication of two fractions. multiplication of mixed numbers.

28

Name: Class: Date:

3.3 Savings and Investment Textbook Pages: 104 – 106
Fill in the blanks with the correct terms. L.S 3.3.1, L.S 3.3.2 PL1 PL2

Compound Simple Investment Bonus Savings Dividend
interest interest

1 Savings The extra money deposited in the bank which will provide
return according to the interest rate and savings period.

2 Simple interestPENERBIT ILMUA sum of money earned when someone saves money in
BAKTI SDN. BHD.the bank for a certain period.

3 Dividend A sum of money paid by a company to its shareholders out
of its profits based on the percentage of shares held.

4 Investment Another way to get future returns in the form of current
income and capital gains.

5 Compound interest The interest received from savings and interest accumulated
each year.

6 Bonus Extra distribution to shareholders after dividend distribution
to increase self-motivation.

Answer the following questions. L.S 3.3.2 PL4

7 Luqman and Lutfi deposited RM5 000 in the bank. The following are the interests
received by Luqman and Lutfi within three years.

Year Luqman Year Lutfi
1 Interest received 1 Interest received
2 RM250.00 2
3 RM250.00 3 RM250.00
RM250.00 RM262.50
RM275.63

(a) State the type of interest received by
(i) Luqman: Simple interest
(ii) Lutfi: Compound interest

(b) Calculate the total amount of interest received by Lutfi.

Compound interest = RM250 + RM262.50 + RM275.63
= RM788.13

50

Name: Class: Date:

3 Quiz
(Objective)
1 Mr Rifaie deposited RM116 500 in bank K and RM149 370 in bank L.

(a) Calculate the total amount of Mr Rifaie’s savings in the two banks.

RM116 500 + RM149 370 = RM265 870 [1 mark]
[1 mark]

Quiz [2 marks] PL3

PENERBIT ILMU(b) Mr Tan’s savings are twice of Mr Rifaie’s savings.
BAKTI SDN. BHD.
PdPc Mr Tan’s savings are RM531 470. Prove it. hoTS Analysing

2 u RM265 870 = RM531 740 [1 mark]
[1 mark]

[2 marks] PL4

2 Table 1 shows the price of two types of computers.

Computer E F
Price RM1 980 Twice the price of computer E

Table 1

(a) Calculate the price of a computer F.

2 u RM1 980 = RM3 960 [1 mark]
[1 mark]

[2 marks] PL3

(b) Company UTE will purchase 100 computers of type E and F respectively.
How much does company UTE have to pay?

(RM1 980 + RM3 960) u 100 = RM5 940 u 100 [1 mark]
= RM594 000 [1 mark]

[2 marks] PL4
54

DSKP Practice Name: Class: Date:

5.1 Length Textbook Pages: 177 – 180
Complete. L.S 5.1.1 PL1
1 3 cm 7 mm = 3.7 cm 2 6.25 m = 625 cm
EXAMPLE
3 cm 7 mm 6.25 m = (6.25 u 100) cm
5.3 cm = 53 mm = 3 cm + (7 ÷ 10) cm = 625 cm
= 3 cm + 0.7 cm
5.3 cm = (5.3 u 10) mm = 3.7 cm
= 53 mm

3 4 m 70 cm = 4.7 m 4 5.8 km = 5 800 mPENERBIT ILMU 5 8 250 m = 8.25 km
BAKTI SDN. BHD.
4 m 70 cm 5.8 km = (5.8 u 1 000) m 8 250 m
= 4 m + ( 70 ÷ 100) m = 5 800 m = (8 250 ÷ 1 000) km

= 4 m + 0.7 m = 8.25 km
= 4.7 m

Convert to the given units. L.S 5.1.2 PL1

6 3 cm = 6 mm 7 2 m = 40 cm 8 7 km = 700 m
5 5 10

( )3cm = 3 u 102 mm ( )2m= 2 u 20 cm ( )7km = 7 u 1 000 m
51 51 10
5 5 100 10

= 6 mm = 40 cm = 700 m

State the answers in fractions. L.S 5.1.2 PL1

9 2 cm 8 mm = 2 4 cm 10 7 m 50 cm = 7 1 m 11 2 km 90 m = 21900 km
5 2

2 cm 8 mm 7 m 50 cm 2 km 90 m

= 2 cm + 84 cm = 7 m + 501 m = 2 km + 90 km
105 1002 1000

= 2 4 cm = 7 1 m = 21900 km
5 2

65

Name: Class: Date:

5.2 Mass Textbook Pages: 189 – 190

Solve the following unit conversions to find the correct path. L.S 5.2.1 PL1

START 0.125 kg 1 250 g 6 1 kg 6 200 g 3 kg 600 g
5

PENERBIT ILMU125 g 5.2 kg 3.6 kg
BAKTI SDN. BHD.
6 kg 300 g 63 g 5 200 g 5 1 kg 400 g
7 300 g 2
7130 kg
6 300 g 7 001 g 2 kg
5

1 kg 250 g 7.03 kg 3 700 g PdPc
4 PdPc

140 g 3170 kg Website Video

7.25 kg 71100 kg 7 kg 100 g 8 kg 400 g 8 2 kg
735 g 5

7110 kg 8.25 kg

FINISH 250 g 0.25 kg 1.5 kg 1 kg 50 g

PdPc Website PdPc Video

Scan the QR code or visit http://teach. Scan the QR code or visit https://
files.bbci.co.uk/skillswise/ma24weig- www.youtube.com/watch?v=_
e3-f-grams-or-kilograms.pdf hjV2H9yQsQ to watch video about
about grams and kilograms. the conversion of units of mass.

For educational purpose only For educational purpose only

71

Name: Class: Date:

5.3 Volume of Liquid Textbook Pages: 199 – 200
Solve the unit conversions to find the correct path. L.S 5.3.1 PL1

START 3 ᐉ = 300 mᐉ 7 2 ᐉ = 7 400 mᐉ
10 5
EXAMPLE ( ) ( )30
3 ᐉ= 3 u 1 000 mᐉ 300 7 2 ᐉ
0.7 ᐉ = 700 mᐉ 10 10 5
0.7 ᐉ = 300 mᐉ 2
= (0.7 u 1 000) mᐉ =7ᐉ+ 5 u 1 000 mᐉ
= 700 mᐉ
PENERBIT ILMU = 7 000 mᐉ + 400 mᐉ
BAKTI SDN. BHD.
= 7 400 mᐉ

700 70 8 017 817 7 400

3.28 ᐉ = 3 280 mᐉ 8 ᐉ 17 mᐉ = 8 017 mᐉ 800 ᐉ = 0.8 ᐉ

3.28 ᐉ 8 ᐉ 17 mᐉ 800 mᐉ
= (3.28 u 1 000) mᐉ = (800 ÷ 1 000) ᐉ
= 3 280 mᐉ 328 = 8 ᐉ + 17 mᐉ 80 = 0.8 ᐉ
= 8 000 mᐉ + 17 mᐉ

= 8 017 mᐉ

3 280 4 300 8 170 1 0.8
10
4 ᐉ 300 mᐉ
= 4 300 mᐉ 5 ᐉ 90 mᐉ = 5.09 ᐉ 700 mᐉ = 7 ᐉ
10
4 ᐉ 300 mᐉ
= 4 ᐉ + 300 mᐉ 5 ᐉ 90 mᐉ 7 700 mᐉ = 700 ᐉ
= 4 000 mᐉ + 300 mᐉ 10 1 000
= 4 300 mᐉ 5.9 = 5 ᐉ + (90 ÷ 1 000) ᐉ
= 5 ᐉ + 0.09 ᐉ 7
= 10 ᐉ
= 5.09 ᐉ

4.3 3110 5.09 7 7
100
4 025 mᐉ = 4.025 ᐉ 3 500 mᐉ = 3 1 ᐉ
2 FINISH

4 025 mᐉ 3 1 3 500 mᐉ 3 1
= (4 025 ÷ 1 000) ᐉ 5 2
= 4.025 ᐉ = 3 000 mᐉ + 500 mᐉ

=3ᐉ+ 500 ᐉ
1 000
1
= 3 2 ᐉ

75

Name: Class: Date:

6.4 Volume of Solids Textbook Pages: 226 – 227

Calculate the volume of each of the following composite shapes. L.S 6.4.1 PL3

1 4 cm 2 2m
4 cm
3 cm 4 cm 5m 3m
3m
8 cm 2m+3m 3m
=5m
10 cm
6m
Volume of the cube
= 4 cm u 4 cm u 4 cm Volume of the cuboid
= 64 cm3 =6mu5mu5m
Volume of the cuboid = 150 m3
= 10 cm u 8 cm u 3 cm Volume of the cube
= 240 cm3 =3mu3mu3m
Total volume = 27 m3
= 64 cm3 + 240 cm3 Total volume
= 304 cm3 = 150 m3 + 27 m3
= 177 m3
PIB
3 4 cm 4 14 cm
PENERBIT ILMU
BAKTI SDN. BHD.5 cm – 2 cm = 3 cm7 cm4 cm
6 cm 4 cm
2 cm
5 cm 6 cm 4 cm
4 cm

4 cm + 6 cm = 10 cm

PdPc Volume of the top of cuboid Volume of the original cuboid
= 4 cm u 4 cm u 3 cm = 14 cm u 7 cm u 6 cm
= 48 cm3 = 588 cm3
Volume of the bottom of cuboid Volume of the cube moved out
= 10 cm u 4 cm u 2 cm = 4 cm u 4 cm u 4 cm
= 80 cm3 = 64 cm3
Total volume Total volume
= 48 cm3 + 80 cm3 = 588 cm3 – 64 cm3
= 128 cm3 = 524 cm3

PdPc Pelibatan Ibu Bapa (PIB) Activity

90

Name: Class: Date:

6 Quiz
(Objective)
1 Diagram 1 shows a composite shape of a square and an equilateral
triangle.

PENERBIT ILMU P
BAKTI SDN. BHD.
Diagram 1 PdPc

(a) Measure angle P. 60° [1 mark] PL3 Quiz
Angle P =

(b) It is given that the perimeter of the whole diagram is 30 cm.
Find the area, in cm2, of the square.

The given diagram has 5 outer sides.

Length of each side = 30 cm = 6 cm [2 marks]
5 [1 mark]
Therefore, the area of the square = 6 cm u 6 cm = 36 cm2

[3 marks] PL4

2 Diagram 2 shows a composite shape of a rectangle KLMN and a square MXYZ. NMX
is a straight line.

K 5 cm L Y
9 cm
3 cm
Z

NM X
Diagram 2

93

Name: Class: Date:

7.2 Ratio Textbook Pages: 238 – 240

The diagram below shows the mass of four items that Puan Nora buys. State the following
ratios. L.S 7.2.1 PL3

PENERBIT ILMUWheat flourRiceCastor sugar Cooking oil
BAKTI SDN. BHD.1 kg10 kg2 kg 3 kg

1 Ratio of the mass of the wheat flour to the mass of the rice = 1 : 10 PAK-21
=2:3
2 Ratio of the mass of the castor sugar to the mass of the = 3 : 10
cooking oil = 10 : 1
= 1 : 16
3 Ratio of the mass of the cooking oil to the mass of the rice = 8 : 5 PdPc
=4:1
4 Ratio of the mass of the rice to the mass of the wheat flour

5 Ratio of the mass of the wheat flour to the total mass of
the four items

6 Ratio of the total mass of the four items to the mass
of the rice

7 Puan Nora wants to buy a 500 g packet of salt.
Ratio of the mass of the castor sugar to the
mass of the salt. hoTS Analysing

PdPc PAK-21 Activity

101

Ujian Akhir Sesi Akademik Performance Marks
Level

Time: 1 hour 15 minutes [60 marks]

This question paper contains 15 questions. Answer all questions. Show your working.
This may help you to get marks.

1 Diagram 1 shows several number cards. For
Examiner’s

Use
PENERBIT ILMU402 135 451 320 435 012 405 123
BAKTI SDN. BHD.
Diagram 1 1(a)

(a) State the number that has the digit 5 in the ten thousands place. 1
[1 mark]

451 320 1(b)
1
(b) Rewrite the numbers on the cards in descending order.
[1 mark] PL2

451 320 435 012 405 123 402 135 Total
1

2

2 Puan Farah buys 12 pairs of scarfs. She divides the scarfs equally among 2(a)
her 4 children. Each child receives 3 pairs of scarfs. 1
(a) Write a number sentence to represent the statement. [1 mark] PL3
2(b)
12 ÷ 4 = 3 1

(b) 5 pairs of the scarfs that Puan Farah buys are white and the rest are Total
2
black. Write the ratio of the number of pairs of white scarfs to the total

number of pairs of scarfs. [1 mark] PL3

5 : 12

2

3 Diagram 2 consists of five similar squares that are each divided into

several equal parts. 3
4
(a) Shade Diagram 2 to show the mixed number 2 . [1 mark]

Diagram 2 3(a)
1
119