My Nilam Maths Year 5 (DLP)

SKILL-BASED ACTIVITIES

CONTENTS CS 1.1 Content i-THINK
Standard Concept
LS 1.1.1
LEVEL Learning HOTS
Standard Question

Performance Additional Info
Level from internet

SKILL-BASED ACTIVITIES

UNIT 1 UNIT 10

Numbers Up To 1 000 000 1 Money 35

UNIT 2 UNIT 11

Addition 5 Time 43

UNIT 3 UNIT 12

Subtraction 8 Length 49

UNIT 4 UNIT 13

Multiplication 12 Mass 55

UNIT 5 UNIT 14

Division 15 Volume of Liquid 61

UNIT 6 UNIT 15

Mixed Operations 18 Space 67

UNIT 7 UNIT 16

Fractions 22 Coordinates 71

UNIT 8 UNIT 17

Decimals 26 Ratio 74

UNIT 9 UNIT 18

Percentage 32 Data Handling 76

PRA-UPSR MODEL PAPER 79

CONTENTS TOPICAL DRILL
Question Difficuly Level
TOPICAL DRILL
HOTS Questions
PAPER 1
Cloned UPSR Questions
UNIT 1: Numbers Up To 1 000 000 95
‘17
UNIT 2: Addition 96
PAPER 2
UNIT 3: Subtraction 97 113
115
UNIT 4: Multiplication 98 117
119
UNIT 5: Division 99 121
123
UNIT 6: Mixed Operations 100 125
127
UNIT 7: Fractions 101 129
131
UNIT 8: Decimals 102 133
135
UNIT 9: Percentage 103 137
139
UNIT 10: Money 104 141
143
UNIT 11: Time 105 145
147
UNIT 12: Length 106 A1

UNIT 13: Mass 107

UNIT 14: Volume of Liquid 108

UNIT 15: Space 109

UNIT 16: Coordinates 110

UNIT 17: Ratio 111

UNIT 18: Data Handling 112

ANSWERS

ONLINE RESOURCES

• Suggested Teaching And Learning Recode Year 5
• Mid-Year Test
• End-of-Year Test
• Answers

SMART NOTES

1 Fraction 1 1 1 1
Decimal 2 4 5 10

Percentage 0.5 0.25 0.2 0.1

50% 25% 20% 10%

2 1 + 1 = 2×1+1 = 3
× 2 2 2

3 RM × 100 sen
÷ 100

4 Interest Value = Savings × Interest × Period

5 Century × 10 Decade × 10 Year × 12 Month
÷ 10 ÷ 10 ÷ 12

6 km × 1 000 m × 100 cm × 10 mm
÷ 1 000 ÷ 100 ÷ 10

7 kg × 1 000 g
÷ 1 000

8 l × 1 000 ml
÷ 1 000

9 Area of triangle = 1 × Base × Height Height Height
2

Base Base

10 Ratio = a : b Comparison of two quantities with the same unit

11 Range : Maximum value – Minimum value
Mode : Data with the highest frequency
Median : The middle data value of a set of data, either in increasing or decreasing order

Mean : Sum of the data value
Frequency

UNIT

1 NUMBERS UP TO 1 000 000

Skill-based Activities Textbook: pp. 1 – 16
Textbook: pp. 1–3
CS 1.1 Value of numbers

A Write number in numerals and words. LS 1.1 (i) LEVEL 1

12

hundred ten thousands hundreds tens ones hundred ten thousands hundreds tens ones
thousands thousands thousands thousands

3 4

hundred ten thousands hundreds tens ones hundred ten thousands hundreds tens ones
thousands thousands thousands thousands

B Write the place value and digit value for the underlined digit. LS 1.1 (ii) LEVEL 2 Textbook: pp. 4

Number Place value Digit value

1 538 625
2 382 719
3 637 801

4 251 394

5 940 726

© Nilam Publication Sdn. Bhd. 1 Mathematics • Year 5

C Partition the following numbers. LS 1.1 (iii) Textbook: pp. 5–6

Number In place value In digit value

1 263 418

2 375 649

3 804 321

4 659 763

5 307 426

6 714 380

7 194 965

D Complete with symbol > or <. LS 1.1 (iv) Textbook: pp. 7–8

1 58 609 785 960 2 240 110 204 011

3 804 121 804 112 4 674 523 647 532

E Arrange the following numbers according to the stated order. LS 1.1 (iv) Textbook: pp. 7–8

1 784 412 988 317 898 523 998 321

Ascending order: 854 209 843 126 845 920
2 834 612

Descending order:

3 482 369 284 963 824 396 428 936

Ascending order: 2 © Nilam Publication Sdn. Bhd.
Mathematics • Year 5

CS 1.2 Estimation of quantities CS 1.3 Numbers in pattern

A State reasonable estimated quantity. LS 1.2 (i) LEVEL 3 Textbook: pp. 9–10

Quantity of beads in container R:

Quantity of beads in container S:
R 2 500 S

B Classify the following number patterns according to even number pattern or odd number

pattern. LS 1.3 (i) LEVEL 4 Textbook: pp. 11–12

1 210 212 214 216 218

2 731 733 735 737 739

3 1 214 1 224 1 244 1 264 1 284

4 5 019 5 241 5 463 5 685 5 907

5 7 435 7 807 8 179 8 551 8 923

C Complete the following number patterns. LS 1.3 (ii) LEVEL 4 Textbook: pp. 11–12

1 76 265 76 815 77 365 79 015 79 565

2 9 846 11 700 12 627 13 554

3 199 1 249 5 449 6 499

4 9 296 10 796 12 296 13 796

© Nilam Publication Sdn. Bhd. 3 Mathematics • Year 5

CS 1.4 Application of any numbers

A Round off the following numbers to the stated place value. LS 1.4 (i) Textbook: pp. 13–15

Nearest hundred

Number Nearest hundred Nearest ten Nearest thousand
thousand thousand

1 243 726

2 398 689

3 649 945

4 152 432

5 831 748

6 584 261

7 604 165

8 934 776

B Write the number that will become 428 900 when rounded off to the nearest hundred at the

bubble map below. LS 1.4 (ii) Textbook: pp. 13–15

428 900

Mathematics • Year 5 4 © Nilam Publication Sdn. Bhd.

UNIT ADDITION

2

Textbook: pp. 17 – 24

Skill-based Activities

CS 2.1 Addition of any two up to five numbers Textbook: pp. 17–21

A Add. LS 2.1 (i) LEVEL 2 & 3

1 185 521 + 518 625 = 2 454 312 + 116 732 + 98 685 =

3 85 695 + 9 647 + 262 826 + 388 617 4 975 + 59 341 + 187 935 + 379 614
= =

5 8 472 + 988 + 9 765 + 68 942 + 594 722 6 138 762 + 86 713 + 7 421 + 485 911 + 796
= =

© Nilam Publication Sdn. Bhd. 5 Mathematics • Year 5

B Calculate. LS 2.1 (ii) LEVEL 3 Textbook: pp. 17–21

1 R + 81 508 = 800 thousands 2 710 184 + M = 90 ten thousands

3 179 thousands + H + 945 + 98 573 4 Q + 79 563 = 342 855
= 648 371

5 400 864 + L = 796 345 6 48 634 + T + 479 228 = 824 500

7 P + 217 831 + 396 846 = 900 000 8 89 668 + K + 328 621 + 3 592 = 698 674

Mathematics • Year 5 6 © Nilam Publication Sdn. Bhd.

CS 2.2 Problem solving involving addition Textbook: pp. 22–24

A Solve the following problems. LS 2.2 (i) LEVEL 4 & 5

1 Mr Arrian buys 57 674 eggs from shop X, 788 542 eggs
from shop Y and 74 965 eggs from shop Z.

Calculate the total number of eggs he owns.

2 Table below shows the number of stamps of 3 pupils.

Pupil Ratna Suraj Tini

Number 9 443 899 more than Ratna 2 408

Calculate the total number of stamps of the three pupils.

3 Rahmat and Nisa read 250 and 215 books. While Maria

reads 36 books more than the total books read by Rahmat

and Nisa. Jamil reads 35 books more than Maria.
Calculate the total number of books read by Maria and

Jamil.

© Nilam Publication Sdn. Bhd. 7 Mathematics • Year 5

UNIT SUBTRACTION

3

Textbook: pp. 25 – 34

Skill-based Activities

CS 3.1 Subtraction of any two numbers Textbook: pp. 25–28

A Subtract. LS 3.1 (i) LEVEL 1 & 2

1 32 792 – 5 697 = 2 475 369 – 132 694 =

3 593 847 – 62 631 = 4 190 946 – 95 387 =

5 1 000 000 – 645 287 = 6 860 000 – 594 000 =
7 390 thousands – 87 941 = 8 50 ten thousands – 958 hundreds =

Mathematics • Year 5 8 © Nilam Publication Sdn. Bhd.

B Calculate. LS 3.1 (ii) LEVEL 3 Textbook: pp. 25–28

1 400 thousands – J = 980 hundreds 2 1 million – K = 424 thousands

3 L – 95 thousands = 522 thousands 4 M – 105 843 = 294 674

5 N – 211 631 = 189 643 6 794 600 – R = 324 611

7 584 921 – S = 119 854 8 900 000 – T = 369 854

© Nilam Publication Sdn. Bhd. 9 Mathematics • Year 5

CS 3.2 Subtraction of two numbers consecutively from any numbers

A Subtract the following. LS 3.2 (i) LEVEL 2 & 3 Textbook: pp. 29–30

1 97 674 – 62 037 – 9 875 = 2 320 500 – 81 300 – 94 500 =

3 700 000 – 120 000 – 4 700 = 4 607 853 – 48 760 – 386 794 =

5 875 908 – 109 027 – 341 809 = 6 726 654 – 311 524 – 108 105 =

7 697 221 – 213 512 – 55 701 = 8 532 098 – 121 690 – 34 086 =

Mathematics • Year 5 10 © Nilam Publication Sdn. Bhd.

CS 3.3 Problem solving involving subtraction Textbook: pp. 31–34

A Solve the following problems. LS 3.3 (i) LEVEL 4

1 Total number of teachers at the state of Kelantan is half
a million. 207 864 from them are male teachers and the
rest are female teachers.

What is the difference between the number of male
teachers and female teachers at Kelantan?

2 There are 127 684 apples in a lorry. During the journey,

73 567 apples are spoiled. Then, it is found that 21 413

apples are rotten.
What is the number of apples that are still good?

3 Pak Kasim buys a box of nails to build a hut. A box of
nails contains 50 000 nails. Pak Kasim needs 37 500
nails. After the hut is complete, it is found that only 6 800
nails is left in the box.

How many nails are broken while in use?

© Nilam Publication Sdn. Bhd. 11 Mathematics • Year 5

UNIT MULTIPLICATION

4

Skill-based Activities Textbook: pp. 35 – 46

CS 4.1 Multiplication of two numbers Textbook: pp. 35–39

A Multiply. LS 4.1 (i) LEVEL 1 & 2 3
8 321
1 2
3 102 6 213 ×2

×4 ×3

4 5 6
5 724 4 957 9 856

×6 ×5 ×8

7 8 9
6 794 2 708 5 638

×7 ×9 ×6

10 11 12
20 102 34 230 30 412

×4 ×2 ×3

13 14 15
203 120 112 052 314 209

×3 ×4 ×2

Mathematics • Year 5 12 © Nilam Publication Sdn. Bhd.

B Multiply. LS 4.1 (i) LEVEL 3 Textbook: pp. 35–39

1 3 102 2 2 104 3 4 210 4 5 101
× 13 × 25 × 32 × 27

5 3 032 6 7 568 7 8 705 8 5 679
× 44 × 37 × 59 × 28

9 16 085 10 1 5 7 4 8 11 2 3 1 4 7 12 1 8 7 6 5
× 35 × 23 × 33 × 41

13 4 967 × 10 = 14 9 274 × 10 = 15 369 × 100 =
16 750 × 100 =
19 7 936 × 54 = 17 592 × 1 000 = 18 809 × 1 000 =

20 8 692 × 82 =

© Nilam Publication Sdn. Bhd. 13 Mathematics • Year 5

SK 4.2 Problem solving involving multiplication Textbook: pp. 40–42

A Solve the following problems. LS 4.2 (i) LEVEL 4

1 8 996 bricks are needed to build a house.
What is the number of bricks needed to build 65 similar

houses?

2 The number of stamp Sarah has is 8 945. The number

of stamps Aliya has is 3 times the number of Sarah’s

stamps. The number of Dewi’s stamps is 2 times the

number of Aliya’s stamps.
What is the number of Dewi’s stamp?

3 Table below shows the number of two types of fruit,
mangosteens and rambutans that are distributed to the
market in several trips.

Fruit Mangosteen Rambutan

Number 4 098 5 464

Aizat will send the mangosteens in every 4 days and
rambutans in every 3 days to the market.

State the first time mangosteens and rambutans will be
sent simultaneously to the market and state the total

number of rambutans sent until that day.

Mathematics • Year 5 14 © Nilam Publication Sdn. Bhd.

UNIT DIVISION

5

Skill-based Activities Textbook: pp. 47 – 58

CS 5.1 Division of two numbers 3 97 752 Textbook: pp. 47–51

A Divide. LS 5.1 (i) LEVEL 1, 2 & 3 3
8 549 792
12

5 9 660

4 5 6
7 51 379 6 453 962 8 912 635

© Nilam Publication Sdn. Bhd. 15 Mathematics • Year 5

B Divide. LS 5.1 (i) LEVEL 3 2 Textbook: pp. 47–51
75 3 5 9 4 0 0
1 3
68 2 5 2 1 4 4 47 4 3 5 5 9 6

4 5 6
39 7 4 8 9 3 5 25 8 4 4 2 4 6 63 6 9 4 7 5 3

C Divide. LS 5.1 (i) LEVEL 3 Divider Textbook: pp. 47–51
10
Number Quotient
1 512 280 100
2 479 450 1 000 4 794 remainder 50
3 3 247
4 864 927 16
5 765 000 765

Mathematics • Year 5 © Nilam Publication Sdn. Bhd.

CS 5.2 Problem solving involving division Textbook: pp. 52–54

A Solve the following problems. LS 5.2 (i) LEVEL 4

1 A factory produces 320 880 irons in 3 weeks. The number
of irons produced is the same every day.

What is the number of irons produced in a day?

2 401 232 bottles of chilli sauce are placed in several boxes
to be distributed. A box can fit 24 bottles of chilli sauce.

What is the number of boxes needed to fit all the chilli
sauce bottles?

3 Number of residents in Town Y is 346 980. The number
of residents in Town Y is 4 times the number of residents
in Town Z.

Find the number of residents in Town Z.

© Nilam Publication Sdn. Bhd. 17 Mathematics • Year 5

UNIT MIXED OPERATIONS

6

Skill-based Activities Textbook: pp. 59 – 74
Textbook: pp. 59–63
CS 6.1 Mixed operation
2 300 × 7 + 200 =
A Solve. LS 6.1 (i)(a), (b) LEVEL 2 & 3

1 108 + 9 × 4 =

3 500 + 54 × 9 805 = 4 96 804 + 9 784 × 8 =

5 700 – 28 × 6 = 6 4 × 520 – 640 =

7 527 256 – 5 973 × 32 = 8 25 837 × 17 – 214 508 =

Mathematics • Year 5 18 © Nilam Publication Sdn. Bhd.

B Solve. LS 6.2 (i)(c), (d) LEVEL 2 & 3 Textbook: pp. 64–67

1 5 006 + 280 ÷ 7 = 2 8 000 ÷ 80 + 1 200 =

3 89 630 + 643 692 ÷ 14 = 4 7 209 ÷ 9 – 510 =

5 160 000 – 16 240 ÷ 29 = 6 238 964 – 392 800 ÷ 25 =

© Nilam Publication Sdn. Bhd. 19 Mathematics • Year 5

CS 6.2 Problem solving involving mixed operations Textbook: pp. 68–70

A Solve the following problems. LS 6.2 (i) LEVEL 5

1 A fish seller put 15 fishes in a basket. The seller has
18 baskets. He sells 60 fishes.

How many fishes are left?

2 Diagram below shows the number of beads in a box
and a jar.

2 100 100 beads
beads

Beads in the box are divided equally into 100 smaller

boxes.
What is the total number of beads in one small box

and a jar?

3 James has 8 money boxes. He collected 350 coins

in each of his money box. He spends 30 coins from

the money.
What is the number of coins left?

Mathematics • Year 5 20 © Nilam Publication Sdn. Bhd.

CS 6.3 Mixed operation involving bracket Textbook: pp. 71–73

A Calculate. LS 6.3 (i) LEVEL 3 & 4

1 (670 + 206) ÷ 6 = 2 26 × (2 014 + 870) =

3 (402 × 5) – (19 × 24) = 4 (28 506 – 8 976) × (841 – 794) =

© Nilam Publication Sdn. Bhd. 21 Mathematics • Year 5

UNIT FRACTIONS

7

Textbook: pp. 75 – 90

Skill-based Activities

CS 7.1 Addition of fractions Textbook: pp. 75–79

A Add. LS 7.1 (i) LEVEL 2, 3 & 4

1 1 + 3 = 2 2 1 + 1 = 3 6 3 + 5 1 =
6 6 4 8 2

4 5 + 3 1 + 3 5 1 + 3 + 1 2 6 1 1 + 4 + 2 1
8 8 5 5 4 2

= = =

7 3 3 + 1 1 + 2 1 8 6 1 + 3 1 + 1 1 9 5 1 + 1 1 + 2 1
8 6 4 8 2 4 6 3 9

= = =

Mathematics • Year 5 22 © Nilam Publication Sdn. Bhd.

CS 7.2 Subtraction of fractions Textbook: pp. 80–83

A Subtract. LS 7.2 (i), (ii) LEVEL 2, 3 & 4

1 7 – 1 = 2 8 – 5 1 = 3 6 3 – 2 1 =
8 8 4 8 2

4 9 7 – 1 – 1 5 5 5 5 – 2 – 1 1 6 8 – 3 2 – 1 1
8 8 8 6 6 5 10

= = =

7 8 1 – 3 1 – 1 1 8 9 9 – 4 1 – 2 4 9 10 3 – 3 1 – 5 1
4 2 4 10 2 5 4 2 8

= = =

© Nilam Publication Sdn. Bhd. 23 Mathematics • Year 5

CS 7.3 Addition and subtraction of fractions Textbook: pp. 84–85

A Solve. LS 7.3 (i) LEVEL 2, 3 & 4

1 8 1 + 1 – 1 1 2 5 7 – 1 1 +2 3 6 9 – 3 + 1 1
2 4 8 2 10 10

= = =

4 9 – 1 1 + 2 1 5 5 + 4 3 – 2 7 6 8 – 3 7 + 1 1
4 6 5 10 10 5

= = =

7 7 3 + 3 1 – 4 1 8 8 1 – 3 2 + 1 1 9 8 3 – 4 1 + 2 1
8 4 2 10 5 2 4 6 3

= = =

Mathematics • Year 5 24 © Nilam Publication Sdn. Bhd.

CS 7.4 Concept ‘of’ in fractions Textbook: pp. 86–89

A Find the value of the following fractions. LS 7.4 (i) LEVEL 1, 3 & 4

1 1 of 12 marbles 2 1 of 32 buttons
4 8

= =

3 3 of 60 pieces 4 3 of 640 apples
4 8

= =

5 3 1 × 16 6 3 7 × RM500
4 10

= =

7 2 4 × 900 minutes 8 9 1 × 240 litres
5 6

= =

© Nilam Publication Sdn. Bhd. 25 Mathematics • Year 5

UNIT DECIMALS

8

Skill-based Activities Textbook: pp. 91 – 106

CS 8.1 Addition of decimals Textbook: pp. 91–92

A Add. LS 8.1 (i) LEVEL 1, 2 & 3 3 80.7 + 9.58 + 140
=
1 8 + 3.08 + 29.5 2 0.37 + 15 + 3.801
= =

4 9.283 + 41.5 + 500 5 8.203 + 19 + 2.059 6 908 + 4.021 + 51.082
= = =

7 280 + 96.1 + 5.307 8 2.09 + 68 + 107.106 9 73.08 + 9.702 + 820
= = =

10 48.35 + 9.845 + 62.3 11 302 + 108.65 + 89.54 12 79.806 + 194.96 + 95.685
= = =

Mathematics • Year 5 26 © Nilam Publication Sdn. Bhd.

CS 8.2 Subtraction of decimals Textbook: pp. 93–94

A Subtract. LS 8.2 (i) LEVEL 2 & 3 2 19 – 6.29 – 2.95 =

1 9 – 1.72 – 3.5 =

3 18.9 – 16 – 1.92 = 4 11.02 – 5.72 – 3 =

5 700 – 93.4 – 2.076 = 6 5 – 0.091 – 2.8 =

7 12.3 – 5.8 – 3.456 = 8 712 – 25.2 – 6.98 =

© Nilam Publication Sdn. Bhd. 27 Mathematics • Year 5

CS 8.3 Addition and subtraction of decimals Textbook: pp. 95–96

A Solve. LS 8.3 (i) LEVEL 2 & 3

1 3.45 + 8 – 3.20 = 2 8 – 1.20 + 5.318 =

3 28.3 + 1.32 – 6 = 4 53.678 – 13.65 + 27.5 =

5 48 + 23.7 – 47.609 = 6 488.2 – 5.09 + 15.763 =

7 139.67 + 155 – 25.98 = 8 25.327 – 8.2 + 200.15 =

Mathematics • Year 5 28 © Nilam Publication Sdn. Bhd.

CS 8.4 Multiplication of decimals Textbook: pp. 97–98

A Multiply. LS 8.4 (i) LEVEL 2 & 3 3 9 × 1.052 =

1 4 × 1.24 = 2 8 × 2.19 =

4 7 × 19.425 = 5 18 × 3.72 = 6 42 × 6.81 =

7 52 × 9.76 = 8 25 × 3.092 = 9 37 × 6.984 =

10 10 × 0.39 11 10 × 5.7 12 100 × 180.98
= = =
13 100 × 7.293 14 1 000 × 0.23 15 1 000 × 9.735
= = =

© Nilam Publication Sdn. Bhd. 29 Mathematics • Year 5

CS 8.5 Division of decimals Textbook: pp. 99–101

A Divide. LS 8.5 (i) LEVEL 1, 2 & 3 3 18.3 ÷ 6 =

1 20.1 ÷ 3 = 2 7.05 ÷ 5 =

4 1.69 ÷ 13 = 5 10.785 ÷ 15 = 6 316.5 ÷ 30 =

7 0.6 ÷ 10 8 5.7 ÷ 10 9 71.2 ÷ 100
= = =
10 901.7 ÷ 100 11 17 ÷ 1 000 12 950 ÷ 1 000
= = =

Mathematics • Year 5 30 © Nilam Publication Sdn. Bhd.

CS 8.6 Problem solving involving decimals Textbook: pp. 103–105

A Solve the following problems. LS 8.6 (i) LEVEL 4 & 5

1 Distance from Village J to Village K is 5.02 km. Distance
from Village K to school is 1.9 km farther than the distance
from Village J to Village K.

What is the distance from Village K to school?

2 Jamal jogs as far as 9.3 km every day.
What is the total distance, in km, he jogs in 2 weeks?

3 Kogila fills 18 kg of flour equally into 15 containers with

equal size.
Calculate the mass of flour, in kg, in one container.

© Nilam Publication Sdn. Bhd. 31 Mathematics • Year 5

UNIT PERCENTAGE

9

Textbook: pp. 107 – 114

Skill-based Activities

CS 9.1 Value of percentage Textbook: pp. 107–108

A Convert percentage to fraction and vice versa. LS 9.1 (i) LEVEL 1 & 2

1 45% = 2 80% = 3 68% =

4 55% = 5 75% = 6 92% =

7 3 = 8 2 = 9 1 =
10 5 4

10 21 = 11 47 = 12 13 =
25 50 20

Mathematics • Year 5 32 © Nilam Publication Sdn. Bhd.

B Convert mixed numbers to percentage and vice versa. LS 9.1 (ii) LEVEL 2

Textbook: pp. 109–110

1 2 1 = 2 3 2 = 3 5 9 =
2 5 10

4 4 17 = 5 7 4 = 6 3 19 =
50 25 100

7 120% = 8 225% = 9 475% =

10 380% = 11 155% = 12 750% =

© Nilam Publication Sdn. Bhd. 33 Mathematics • Year 5

C Solve. LS 9.1 (iii) LEVEL 2 & 3 Textbook: pp. 111

1 3% of RM400 2 19% of 600 ml
= =

3 40% of 50 kg 4 90% of 420 km
= =

5 180% of 90 m 6 225% of 72 candies
= =

7 30% of a number is 15. 8 75% of K is 27.
What is the number? What is the value of K?

Mathematics • Year 5 34 © Nilam Publication Sdn. Bhd.

UNIT MONEY

10

Textbook: pp. 119 – 142

Skill-based Activities

CS 10.1 Addition of money Textbook: pp. 119–120

A Add. LS 10.1 (i) LEVEL 1, 2 & 3

1 2 3 90.00
RM 5 8 0 . 9 0 RM 5 9 0 0 . 2 0 RM

+ RM 7 . 5 0 + RM 4 1 8 . 2 0 + RM 4 0 5 0 . 2 0

4 5 700.50 6
RM 3 0 0 4 2 0 . 0 0 RM RM 7 5 0 0 8 0 . 5 0
RM 6 2 8 2 0 . 5 0
RM 8 5 0 0 . 0 0 RM 9 0 0 8 . 2 0
+ RM 2 0 8 0 0 . 0 0
+ RM 9 0 0 0 0 0 . 1 0 + RM 990.00

7 RM608.20 + RM1 800.90 + 125 sen + 8 RM180 060 + RM700 500.30 + RM29.30 +
RM3 600.80 + RM204 000 RM760 + RM75 000.05
= =

© Nilam Publication Sdn. Bhd. 35 Mathematics • Year 5

CS 10.2 Subtraction of money Textbook: pp. 121–122

A Subtract. LS 10.2 (i) LEVEL 1, 2 & 3 3
RM 9 6 0 2 7 0 . 0 0
1 2
– RM 2 4 0 1 0 5 . 5 0
RM 7 8 5 0 . 1 0 RM 9 0 0 . 0 0
– RM 6 2 0 . 3 0 – RM 3 2 0 . 5 0

4 5 6

RM 6 0 0 2 0 0 . 7 0 RM 9 5 0 0 0 0 . 0 5 RM 1 4 2 8 6 0 . 0 0
– RM 4 9 5 9 0 . 1 0 – RM 5 6 0 9 0 . 6 0 – RM 9 8 2 8 0 . 9 5

7 RM900 012 – RM128 500.85 – RM908.50 8 RM700 000 – RM46 302.50 – RM200.60
= =

Mathematics • Year 5 36 © Nilam Publication Sdn. Bhd.

CS 10.3 Addition and subtraction of money Textbook: pp. 123–124

A Calculate. LS 10.3 (i) LEVEL 1, 2 & 3

1 RM185 060 + RM16 800 – RM53 700.80 2 RM402 600.60 + RM60 180 – RM9 085.45
= =

3 RM70 095.60 + 2 050 sen – RM35 800.90 4 RM505 000.90 – RM97 005.90 + RM170.50
= =

5 RM905 160.80 – RM225 433.95 + RM4 500 6 RM509 710 – RM109 500.30 + RM900.20
= =

© Nilam Publication Sdn. Bhd. 37 Mathematics • Year 5

CS 10.4 Multiplication of money Textbook: pp. 125–126

A Multiply. LS 10.4 (i) LEVEL 1, 2 & 3 3

1 2 RM 1 5 9 5 0
×6
RM 4 8 0 2 0 RM 5 3 4 8 7
×7 ×5

4 5 6

RM 3 6 4 0 1 . 5 0 RM 1 2 8 4 5 . 5 5 RM 3 7 6 4 1 . 5 0
×8 ×9 ×8

7 8 2 010.20 9
75
RM 1 7 2 0 0 RM RM 1 2 8 6 2 . 9 5
× 24 × × 33

10 10 × RM15 421.65 11 100 × RM3 478.45
= =

12 1 000 × RM230.50 13 1 000 × RM68.50
= =

Mathematics • Year 5 38 © Nilam Publication Sdn. Bhd.

CS 10.5 Division of money Textbook: pp. 127–128

A Divide. LS 10.5 (i) LEVEL 1, 2 & 3 3
5 RM 2 1 5 4 0 0 . 8 5
12

3 RM 8 0 1 3 0 0 4 RM 5 0 1 2 0 0

4 5 6
18 RM 5 4 5 2 2 0 36 RM 5 2 2 3 . 6 0 60 RM 6 1 2 9 3 0 . 0 0

7 RM80 070 ÷ 10 8 RM8 376.50 ÷ 100 9 RM920 150 ÷ 1 000
= = =

© Nilam Publication Sdn. Bhd. 39 Mathematics • Year 5

CS 10.6 Multiplication and division of money Textbook: pp. 129–130

A Calculate. LS 10.6 (i) LEVEL 1, 2 & 3

1 RM64 020 ÷ 5 × 2 = 2 RM800 350 ÷ 10 × 7 =

3 RM2 592.80 × 5 ÷ 8 = 4 RM86 460 × 15 ÷ 8 =

Mathematics • Year 5 40 © Nilam Publication Sdn. Bhd.

CS 10.7 Problem solving involving money Textbook: pp. 132–136

A Solve the following problems. LS 10.7 (i) LEVEL 4

1 A printing company has obtained a profit of RM23 500.60
in January. In February, the company has obtained a
profit of RM1 240.40 more than January.

Calculate the total profit in January and February.

2 A hotel buys 12 similar refrigerators with price of

RM28 800.
What is the price of one refrigerator?

3 Mrs Liyana’s savings is RM450 090.80. She makes a

transfer of 3 of her money into the account of her son
5

that studies abroad.

What is the total amount of money that is transferred to

her son?

© Nilam Publication Sdn. Bhd. 41 Mathematics • Year 5

CS 10.8 Interest Textbook: pp. 137–139

A Solve the following problems. LS 10.8 (i) LEVEL 4

1 Table below shows Rosli’s savings in a bank.

Year Balance at beginning Interest rate Interest value Balance at end of
of year year

2018 RM6 000 3% RM180 RM6 180

2019 RM6 180 3% RM185.40

2020 3%

Based on the table above,
(a) state the simple interest value in year 2018.
(b) state the compounded interest value in year 2019.
(c) calculate the balance of Rosli’s money at the end of year 2019.
(d) by using calculator, complete the information at the table for year 2020.

Mathematics • Year 5 42 © Nilam Publication Sdn. Bhd.

UNIT TIME

11

Textbook: pp. 143 – 160

Skill-based Activities

CS 11.1 Relationship in time

A Change the following into the units stated in the brackets. LS 11.1 (i) LEVEL 1

Textbook: pp. 143–144

1 2 decades [year] 2 7 centuries [year]
= =

3 900 years [century] 4 40 years [decade]
= =

5 7 decades 15 years [year] 6 8 centuries 5 years [year]
= =

7 89 years [decade and year] 8 124 years [decade and year]
= =

9 482 years [century and year] 10 648 years [century and year]
= =

© Nilam Publication Sdn. Bhd. 43 Mathematics • Year 5

CS 11.2 Addition of time

A Add and give answer in the units stated in the brackets. LS 11.2 (i) LEVEL 2 & 3

Textbook: pp. 145–147

1 2 decades 4 years + 6 decades 3 years 2 1 decade 8 years + 2 decades 5 years
[decade and year] [decade and year]
= =

3 8 years + 3 decades 8 years + 4 5 decades 6 years + 3 decades 5 years +

6 decades 9 years [decade and year] 4 decades 8 years [decade and year]
=
=

5 4 centuries 9 years + 2 centuries 20 years 6 2 centuries 36 years + 7 centuries 24 years
[century and year] [century and year]
= =

7 1 century 28 years + 2 centuries 32 years + 8 2 centuries 38 years + 3 centuries 50 years

3 centuries 84 years [century and year] + 1 century 21 years [century and year]
= =

Mathematics • Year 5 44 © Nilam Publication Sdn. Bhd.

CS 11.3 Subtraction of time

A Subtract and give answer in the units stated in the brackets. LS 11.3 (i) LEVEL 2 & 3

Textbook: pp. 148–150

1 3 decades 6 years – 1 decade 4 years 2 4 decades 5 years – 1 decade 9 years
[decade and year] [decade and year]
= =

3 6 decades – 1 decade 6 years – 4 9 decades 4 years – 1 decade 7 years –

2 decades 8 years [decade and year] 2 decades 8 years [decade and year]

= =

5 3 centuries 15 years – 1 century 30 years 6 4 centuries 3 years – 2 centuries 45 years
[century and year] [century and year]
= =

7 10 centuries – 4 centuries 8 years – 8 9 centuries 5 years – 1 century 3 years –

3 centuries 20 years [century and year] 2 centuries 25 years [century and year]

= =

© Nilam Publication Sdn. Bhd. 45 Mathematics • Year 5

CS 11.4 Multiplication of time

A Multiply and give answer in the units stated in the brackets. LS 11.4 (i) LEVEL 2 & 3

Textbook: pp. 151–152

1 5 × 8 years [decade] 2 7 × 14 years [decade and year]
= =

3 3 × 2 decades 4 years [decade and year] 4 12 × 4 decades 7 years [decade and year]

= =

5 8 × 26 decades [century and year] 6 11 × 2 centuries 15 years [century and year]
= =

7 14 × 4 centuries 20 years [century and year] 8 24 × 6 centuries 5 years [century and year]

= =

Mathematics • Year 5 46 © Nilam Publication Sdn. Bhd.

CS 11.5 Division of time

A Divide and give answer in the units stated in the brackets. LS 11.5 (i) LEVEL 2 & 3

Textbook: pp. 153–155

1 8 decades 4 years ÷ 4 [decade and year] 2 245 years ÷ 5 [decade and year]

= =

3 9 decades 6 years ÷ 6 [decade and year] 4 19 decades 8 years ÷ 11 [decade and year]

= =

5 20 centuries 32 years ÷ 4 [century and year] 6 1 215 years ÷ 9 [century and year]

= =

7 13 centuries 4 years ÷ 8 [century and year] 8 33 centuries ÷ 30 [century and year]

= =

© Nilam Publication Sdn. Bhd. 47 Mathematics • Year 5