Modul Kimia A

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

(i) A student repeat this experiment using copper block, but she dropped the weight from
400 cm height. Predict the value of diameter of dents produce.
Seorang pelajar telah mengulangi eksperimen ini dengan menggunakan bongkah kuprum,
tetapi dia telah menjatuhkan pemberat pada ketinggian 400cm. Ramalkan nilai diameter
lekuk yang terhasil.

……………………………………………………………………………………………………………

……………………………………………………………………………………………………………
[3
marks]

(j) Classify all the substances below into alloy and pure metals.
Kelaskan semua bahan-bahan di bawah kepada aloi dan logam
tulen.

Duralumin Magnesium Pewter Tin Manganese Gold
Duralumin Magnesium Piuter Timah Mangan Emas

Alloy Pure Metal
Aloi Logam Tulen

[3 marks]

Panitia Kimia 51

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

2 Fresh milk stored in the refrigerator lasts longer than that placed in the cabinet.
Susu segar yang disimpan di dalam peti sejuk didapati tahan lebih lama
berbanding diletakkan di dalam kabinet.

Referring to the above situation, plan a laboratory experiment to investigate the effect of
temperature on the rate of reaction between sodium thiosulphate solution and
hydrochloric acid.

Merujuk kepada maklumat di atas, rancang satu eksperimen dalam makmal untuk
menyiasat kesan suhu keatas kadar tindak balas antara larutan natrium tiosulfat dengan
asid hidroklorik.

Your planning must include the following aspects:
Perancangan anda hendaklah mengandungi aspek-aspek berikut :

(a) Problem statement
Pernyataan masalah

(b) All the variables
Semua pembolehubah

(c) Hypothesis
Hipotesis

(d) List of materials and apparatus
Senarai bahan dan radas

(e) Procedure
Prosedur

(f) Tabulation of data
Penjadualan data

[17 marks]

END OF QUESTION PAPER
KERTAS SOALAN TAMAT

Panitia Kimia 52

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

INFORMATION FOR CANDIDATES MAKLUMAT UNTUK CALON

1. This question paper consists of two questions: Question 1 and Question 2
Kertas soalan ini mengandungi dua soalan: Soalan 1 dan Soalan 2.

2. Answer all questions. Write your answers for Question 1 in the spaces provided in
this question paper.
Jawab semua soalan. Tulis jawapan anda bagi Soalan 1 pada ruang yang disediakan
dalam kertas soalan ini.

3. Write your answers for Question 2 on the 'helaian tambahan' provided by the invigilators.
You may use equations, diagrams, tables, graphs and other suitable methods to explain
your answers.
Tulis jawapan anda bagi Soalan 2 dalam helaian tambahan yang dibekalkan oleh pengawas
peperiksaan. Anda boleh menggunakan persamaan, rajah, jadual, graf dan cara lain yang
sesuai untuk menjelaskan jawapan anda.

4. Show your working, it may help you to get marks.
Tunjukkan kerja mengira, ini membantu anda mendapatkan markah.

5. The diagrams in the questions are not drawn to scale unless stated.
Rajah dalam soalan tidak dilukis mengikut skala kecuali dinyatakan.

6. The marks allocated for each question or sub-part of a question are shown in brackets.
Markah yang diperuntukkan bagi setiap soalan atau ceraian soalan ditunjukkan dalam
kurungan.

7. If you wish to change your answer, cross out the answer that you have done. Then write
down the new answer.
Jika anda hendak menukar jawapan, batalkan jawapan yang telah dibuat. Kemudian tulis
jawapan yang baru.

8. You may use a scientific calculator.
Anda dibenarkan menggunakan kalkulator saintijik.

9. You are advised to spend 45 minutes to answer Question 1 and 45 minutes for Question 2.
Anda dinasihati supaya mengambil masa 45 minit untuk menjawab Soalan 1 dan 45 minit
untuk Soalan 2.

10. Detach Question 2 from this question paper. Tie the 'helaian tambahan' together with
this question paper and hand in to the invigilator at the end of the examination.
Ceraikan Soalan 2 daripada kertas soalan ini. Ikat helaian tambahan bersama-sama
kertas soalan ini dan serahkan kepada pengawas peperiksaan pada akhir peperiksaan.

Panitia Kimia 53

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

Cadangan Jawaban

Panitia Kimia 54

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

Modul Kimia A K1 SPM 2020 (cadangan Jawaban) Jawaban
D
Nombor Soalan Jawaban Nombor Soalan B
1 A 26 A
2 A 27 D
3 B 28 C
4 B 29 B
5 C 30 B
6 A 31 C
7 B 32 C
8 C 33 D
9 D 34 C
10 B 35 C
11 D 36 A
12 D 37 D
13 A 38 B
14 A 39 B
15 D 40 B
16 D 41 C
17 B 42 C
18 A 43 B
19 A 44 C
20 D 45 B
21 B 46 D
22 A 47 D
23 D 48 A
24 A 49
25 B 50

Panitia Kimia 55

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

ANSWER SCHEME
MODUL KIMIA A PAPER 2

No (i) Sample answer Mark
1 (a) (ii) The number of protons in the nucleus of an atom. 1
17 1
(b) (i) 1
2.8.1 // 2, 8, 1 1
(ii)
Reacts with water to produce hydrogen and metal hydroxide// 1
(c) Reacts with oxygen to form metal oxide.//
Reacts with chlorine gas to produce metal chloride. 1
(d) (i) Q and R 1
because they have the same proton number but different nucleon 1
number// same number of proton but different number of neutrons

Correct no of shells
Correct e arrangement

XX

X X X
X X
S

X

XX

(ii) To fill advertising light bulb 1
9m
Total

2 (a) Base to ascending order of proton number 1
(b) C and E 1
(c) Group 2 and Period 3 1
1 ...2
(d) Have 2 valence electron and 3 shells occupied with electron
1
(e) C more reactive than E. 1
(f) 1 …3
Nuclei attraction toward electrons in C is stronger than E.
1
It is easier for atom C to attract/gain electron. 1
D,E,A,B,C
D 9

TOTAL

Panitia Kimia 56

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

3 (a) (i) Ethanoic acid// Methanoic acid //Oxalic acid 1 1
(ii) 1. Acid X is weak acid while hydrochloric acid is 1
2
strong acid// 1 2
The concentration of H+ ions in ethanoic acid is lower// 1 1
The concentration of H+ ions in hydrochloric acid is 1 1
1 1
higher 1
2. The higher the concentration of H+ ion, the lower 1 2
10
the pH value. 1
1
(iii) 1. pH increases

2. The concentration of hydrogen ion is decreases

(b) (i) A solution in which its concentration is accurately known.

(ii) Dilution

(iii) A volumetric flask measure volume more accurate

than a beaker
(iv) 2.0 mol dm-3 x V1 = 1.0 mol dm-3 x 100 cm3

V1 = 1.0 mol dm-3 x 100 cm3

2.0 mol dm-3

V1 = 50 cm3
TOTAL

4 (a)(i) I 11

(ii) Hidrogen 11

(iii) Mg + 2HCl MgCl2 + H2

- Formula bahan tbls dan hasil tbls betul 1 2
- Persamaan seimbang 1

(iv) Bil mol H2 = 1.2 dm3/24 dm3 = 0.05 mol 1

from the equation 1 mol Mg : 1 mol H2 1
if 0.05 mol Mg : 0.05 mol H2 13

Mass for Mg = 0.05 x 24 = 1.2g

(b) - Kadar tindak balas eksperimen I lebih tinggi 1

- Kecerunan graf Eksperimen I lebih tinggi// graf 12

eksperimen I lebih tegak // masa utk eksperimen I lebih singkat

(c) - Kehadiran mangkin//

- Suhu asid//

- Kepekatan asid// 1+1 2
- Saiz magnesium

TOTAL 11

Panitia Kimia 57

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

(a) Reaction that involves oxidation and reduction occur 1 1

simultaneously. 1 2

5 (b)(i) Cl2 + 2e → 2Cl- 1 2
1
(ii) 2I- → I2 + 2e 1 2
1
(c) Show the arrow direction of electron transfer from electrode Q to P 1 11
in Diagram 5 1
1
(d) P: Pale yellow solution turns colourless
Q: Colourless solution turns to brown 1
1
(e) Potassium iodide solution // Iodide ion 1

(f) Add several drops of starch solution
The solution turns dark blue

(g) Bromine water

TOTAL

(a)(i) CnH2n+1OH 1
6 (ii) Hydroxyl // -OH 12
11
b(i) Butene 1

(c)(i) Potassium dichromate(VI) solution // 12
Potassium manganate(VII) solution 1
12
(ii) Orange to gree // Purple to colourless
1
(d)(i) Butyl propanoate
(ii) C2H5COOH + C4H9OH → + H2O 1
(e) Number of mole of butene = 11.2 /56
13
= 0.2 mol
1.0 mole of butene burnt to produce 4.0 mole of CO2
0.2 mole of butene burnt to produce 0.8 mole CO2

Number of CO2 molecules = 0.8 mol x 6.02 x 1023
= 4.816 x 1023 molecules

TOTAL 10

Panitia Kimia 58

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

No Mark Scheme Mark
8 (a) (i) Sub Total

Type of food Function
additive

Thickener To thicken food

To make food last longer //

Preservative To slow down / prevent the growth of

microorganism

Antioxidant To prevent oxidation of food

Flavouring Agent To improve the taste of food //
To restore taste loss

Any two correct type of food additive 1+1

and its function 1+1 4

(ii) P1. Advantage

Make food stay fresh longer 1
Make food look nicer
Make food taste better

Any one answer

P2. Disadvantage

Able to cause serious diseases like cancer and asthma//

Able to cause allergy

Any one answer 12

(iii) Type of medicine 1
1
P1. Antibiotic
P2. Analgesic

Correct usage :

P1. Take full course / finish all the antibiotic 1

P2. Analgesic (aspirin/paracetamol) has to be taken after food 14

(b)(i) P1. Carbon dioxide / CO2 1

P2. Bubble / flow / channel / pass the gas through lime water 1

P3. Lime water turns milky / chalky / cloudy 13
(ii) P1. Add 2 cm3 dilute sulphuric acid followed by 2 cm3

iron(II) sulphate solution into test tube containing

solution S and shake. 1

P2. Add concentrated sulphuric acid slowly/carefully. 1

P3. A brown ring is formed. 13

(c)(i) P1. Barium chloride / Barium nitrate 1
12
P2. Sodium sulphate / Potassium sulphate / Ammonium
sulphate

(ii) P1. Filter the mixture and rinse 1

P2. Dry between two filter papers / using oven 12
Total 20

Panitia Kimia 59

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020 4
1 6
8 (a)(i) SO2 + H2O → H2SO3 1
(ii) Corrodes building 1 10
Corrodes metal structures 1
pH of the soil decreases
Lakes and rivers become acidic 1
[Able to state any three item correctly]
1
(b) (i) Oleum 1
(ii) 2SO2 + O2 → 2SO3 1
Correct chemical formula 1
Balance equation 1
(iii) Mole of sulphur = 48/32 = 1.5
Mole of SO2 = mole of sulphur = 1.5 1
Volume od SO2 = 1.5 x 24 dm3 = 36 dm3 1
1
(c) Ionic bond
Electron arrangement of sodium atom is 2.8.1 1
To obtain stable octet electron
1
Sodium atom release 1e // Na→Na+ + e 1
1
Electron arrangement of Chlorine atom is 2.8.7
To obtain the stable octet electron arrangement 1

Chlorine atom receive 1 e// Cl + e → Cl
Sodium ion and chlroine ion attract each other by strong
electrostatic bond
Diagram

High melting point // High boiling point // can conduct 1+1
electricity in molten and aqueous 1

JUMLAH 20

Panitia Kimia 60

Modul Peningkatan Prestasi Kota Belud 3.7 Kimia SPM 2020

9 (a)(i) 1
P1. Number of mole of butanol = 4(12)+9(1)+16+1 // 0.05 mol

P2. Heat released = mcθ 1
= 500 x 4.2 x 60 // 126000 J // 126 kJ 1

P3. 0.05 mol of butanol burnt completely to release 126000 J

1 mol of butanol released 126000J

P4. [value is correct] 1 5
2520 kJ 1
2
P5. [Negative sign with correct unit] 3
∆H = - 2520 kJ mol-1

ecf: P3 & P5 1
(ii) P1. Some heat is lost to the surrounding//heat is absorbed by the
1
apparatus/ tripod stand/ windshield/copper can 1
1
P2. Butanol undergoes incomplete combustion // does not 1
undergo complete combustion

(iii) P1. Butanol//Propanol
P2. Correct structural formula of any isomers
P3. Name based on isomer in P2
Sample answer :

Structural formula Name

Propan-1-ol

Propan-2-ol
Butan-1-ol
Butan-2-ol

2-methylpropan-1-ol
2-methylpropan-2-ol

Panitia Kimia 61

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

9 (b) P1. Named metal V 1

P2. Measure [25.0 – 50.0] cm3 of [0.1-1.0]mol dm-3 copper(II) 1
sulphate solution

P3. Pour the solution into a plastic/ polystyrene cup 1

P4. Record the initial temperature of the solution 1
P5. Add quickly excess/ 1 spatula of metal V powder into
1
copper(II) sulphate solution 1
1
P6. Stir the mixture

P7. Record the highest/maximum temperature reached

P8. Data 1
Initial temperature of copper (II) sulphate solution = T10C 1
Highest temperature = T2 0C 1

P9. Heat given out = 25 x 4.2 (T2 – T1) = X J 1

P10. Number of mole of copper(II) sulphate = = Y mol
P11. ∆H = - X/Y
1000
= - Z kJmol-1
11
Total
Max
10

20

Panitia Kimia 62

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

10 (a) Anode 1
Product : Oxygen gas 1
Half Equation : 4OH- → O2 + 2H2O + 4e

Cathode

Product : Hydrogen gas 1

Half equation: 2H+ + 2e → H2 14

(b) Cell X Cell Y

Energy Change Chemical energy to Electrical energy to 1+1

electrical energy chemical energy

Terminal Positive : Copper Positive : Copper 1+1
Negative : Zink Negative Cuprum

Half equation at positive Cu2+ + 2e → Cu Cu → Cu2+ + 2e 1+1
terminal

Half equation at negative Zn → Zn2+ + 2e Cu2+ + 2e → Cu 1+1
terminal

Observation at the Brown solid deposited// Copper plate become 1+1

positive terminal copper plate become thinner

thicker

Observation at the Zinc plate become Brown solid deposited// 1+1 Max
negative terminal thinner copper plate become 6
thicker

(c) [Name of a more electropositive metal and name of a less electropotitive metal] 1+1 2

[Name of one suitable salt solution] 11

Procedure:

1. Clean [named metal] with sandpaper 1

2. Pour about 5 cm3 [named salt solution] into a test tube 1

3. Place [named metal] into the solution 1

4. Record the observation in a table 1 Max

5. Repeat the experiment by using [another named metal] 14

Expected result Observation 1 3
Metal Deposit formed 1 20
No changes 1
More electropositive metal
Less electropositive metal
Balance equation

Total

Panitia Kimia 63

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

MODULE A PAPER 3 MARKING SCHEME

No PP Score
1 (a) [able to measure diameter of dents accurately and correctly] 3x2

Copper : 2.0, 2.1, 2.1 2x2
Brass : 1.9, 1.8, 1.9 1x2
[able to measure diameter of dents without two decimal place] 0
[able to state four diameter of dents correctly]
No response or wrong response

No PP Score
3
(b) [able to construct table with correct label and unit]
2
Diameter of dents 1
0
Type of blocks (cm) Average diameter of dents

l ll lll (cm)

Copper 2.00 2.10 2.10 2.06

Brass 1.90 1.80 1.90 1.87

[able to construct the table without correct label or unit]

[able to construct idea of table]

No response or wrong response

No PP Score
(c) [able to state hypothesis correctly] 3

When brass is used, the diameter of dent is smaller // 2
When copper is used, the diameter of dent is bigger 1
0
[able to state hypothesis less correctly]
[able to state idea of hypothesis]
No response or wrong response

No PP Score
(d) [able to state all the variables] 3

Manipulated variable : type of materials / blocks// copper and brass 2
Responding variable : diameter / size of dents 1
0
Fixed variable : size / diameter and mass of steel ball bearing// height of the weight //
mass of the weigh

[able to state any two variables correctly]
[able to state any one variable correctly]
No response or wrong response

No PP Score
(e) [able to state operational definition correctly] 3

Smaller dent is produced when 1kg of weight is dropped on the block. 2
[able to state operation definition less correctly]
Smaller dent is produced when weight is dropped on the block 1

[able to state operation definition] 0
The harder block has a smaller dent
No response or wrong response

Panitia Kimia 64

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

No PP Score
(f) [able to state observation correctly] 3

The average diameter of dent become smaller 2

[able to state observation less correctly] 1

The dent become smaller 0

[able to state idea of observation] Score
Small dent 3

No response or wrong response 2

No PP 1
(g) [able to state inference correctly]
0
Brass is the harder than copper
Score
[able to state inference less correctly] 3
Brass is the harder
2
[able to state idea of inference]
Brass is the hard // copper is soft 1
0
No response or wrong response
Score
No PP 3
(h) [able to state situation correctly] 2
1
Iron bar rust , steel bar do not rust 0
[able to state situation less correctly]
Only 1 bar stated Score
3
[able to state idea of situation]

No response or wrong response

No PP
(i) 1.65 cm

Between 1.55 until 1.75 cm
Between 1.45 until 1.55cm // 1.75 until 1.85 cm
No response or wrong response

No PP
(j) [able to classify all correctly]
Pure metal
Alloy Tin
Duralumin Gold
Pewter Manganese
Magnesium
[able to classify 5 correctly]
[able to classify 4 correctly] 2
No response or wrong response 1
0

Panitia Kimia 65

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

Question Rubric Score
3
Able to give the statement of the problem correctly
2
Sample answer :
How does the temperature of sodium thiosulphate solution affect the rate 1
of reaction? 0
Able to give the statement of the problem incorrectly Score

2(a) Sample answer : 3
How does the temperature of solution affect the rate of reaction?
Able to give an idea of statement of the problem 2
1
Sample answer : 0
To determine the rate of reaction by the temperature of solution Score
No response or wrong response 3

Question Rubric 2

Able to state all variables correctly 1
0
Sample answer :

Manipulated variable :The temperature of sodium thiosulphate solution

Responding variable : Rate of reaction//The time taken for the ‘X’ mark to

2(b) Constant variable disappear
: Volume and concentration (sodium thiosulphate) /

(hydrochloric acid) // sodium thiosulphate // acid//

size of conical flask

Able to state any two variables correctly

Able to state any one variable correctly

No response or wrong response

Question Rubric

Able to state the relationship between the manipulated variable and the

responding variable correctly

Sample answer :
The higher the temperature of sodium thiosulphate solution , the higher the
rate of reaction
Able to state the relationship between the manipulated variable and the
2(c) responding variable incorrectly

Sample answer :
The rate of reaction increases when the temperature of solution increase
Able to state an idea of hypothesis

Sample answer :
The temperature of reactant affect the rate of reaction
No response or wrong response

Panitia Kimia 66

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

Question Rubric Score

Able to give the list of the apparatus and materials correctly and

completely

2 (d) Apparatus: 3
conical flask, measuring cylinder, thermometer, stopwatch, white paper, 2
wire gauze, tripod stand, Bunsen bunner

Material:
[0.1 – 1.0] mol dm-3 sodium thiosulphate solution,
[ 0.1-1.0] mol dm-3 hydrochloric acid
Able to give the list of the apparatus and materials correctly but not
completely

Apparatus:
conical flask, thermometer, stopwatch, white paper, Bunsen bunner

Material:
Sodium thiosulphate solution, hydrochloric acid
Able to give two materials and at least one apparatus

Material: 1
Sodium thiosulphate solution, hydrochloric acid 0

Apparatus:
[container]
No response or wrong response

Question Rubric Score
3
Able to state all procedures correctly

1. Draw an X on a white paper.
2. Pour [20-100] cm3 of [0.1 – 1.0] mol dm-3 sodium thiosulphate

solution into a conical flask.

3. Record the temperature of solution.

4. Place the conical flask on the X.
2(e) 5. Pour [5 – 10] cm3 of [0.1 – 1.0] mol dm-3 hydrochloric acid

solution.

6. Swirl the conical flask and start the stopwatch immediately.

7. Stop the stopwatch when the X is no longer visible. Record the

time taken.
8. Repeat steps 2 to 7 using 35oC, 40oC, 45oC and 50oC temperature

of sodium thiosulphate solution.

Able to state four steps of procedures correctly 2

Steps 2, 4, 5, 8 1
Able to state two steps of procedures correctly 0

Steps 2, 5
No response or wrong response

Panitia Kimia 67

Modul Peningkatan Prestasi Kota Belud Kimia SPM 2020

Question Rubric Score
2
Able to exhibit the tabulation of data that includes the following
1
information.

1. Headings
2. With unit

Sample answer :

Temperature/ oC Time/s

30

35

2(f) 40
45

50

Able to tabulate the data incompletely

1. Titles without unit

Sample answer :

Temperature Time

No response given / wrong response 0
END OF MARKING SCHEME

Panitia Kimia 68