Ncert Solutions For Class 10 Maths

If you are looking NCERT Solutions for Class 10 Maths error free and prepared by experienced mentors. Don’t
WORRY!! Here we are providing Free PDF you can get easy with a single click.

SUMMARY

tan = 1 ⇒ cot = 1
cot ⇒ tan
⇒
cos = 1 sec = 1
sec cos

sin = 1 cosec = 1
cosec sin

We also observe that

tan = and cot = cos

cos sin

Trigonometric table:

Trigonometric Identities:
(i) sin2θ + cos2θ = 1
(ii) 1 + tan2θ = sec2θ
(iii) 1 + cot2θ = cosec2θ

Trigonometric ratios of complementary angles:
Sin (900- θ) = cos θ
cos (900- θ) = sin θ
Tan (900- θ) = cot θ
Cot (900- θ) = tan θ
Sec (900- θ) = cosec θ
Cosec (900- θ) = sec θ

OBJECTIVE

1. If 5tan θ = 4, then value of 5 sin θ−3 cosθ is :
5 θ+3 cosθ
a)1 ) 1 ) 4 ) 2
36
5 3

HURRY!! Visit our portal and get your NCERT Solutions UPDATED 2021-22. These all very essential for your exam
preparation

If you are looking NCERT Solutions for Class 10 Maths error free and prepared by experienced mentors. Don’t
WORRY!! Here we are providing Free PDF you can get easy with a single click.

2. Given 3sin β + 5cos β = 5, then the value of (3cos β- 5sin β)2 is equal to:

a) 9 ) 9 ) 1 ) 1

5 3 9

3. If tan θ= 4, then ( 3 +ta n θ ) is equal to: )√2 )1
a) 0 )2√2 d) increases, then decreases

4. As x increases from 0 to 2 , the value of cos x :

a) Increases b) decreases c) remains constant

5. Value of x from the equation
2 6 3 4
xsin 6 cos2 4 = 2 4 6 is :

a) 4 b) 6 c) -2 d) 0

6. The area of a triangle is 12 sq. cm. Two sides are 6 cm and 12 cm. The included angle is :

a) cos−1 (1) b) cos−1 (1) c) sin−1 (1) d) sin−1 (1)

3 6 6 3

7. If α + β = 900 and α = 2β, then cos2 + sin2β equals to:

a) 1 b) 0 c) 1 d) 2
2

SUBJECTIVE

1. If A + B = 900, prove that:

√ + − 2 = tan
2


Prove the following (Q 2 to Q5)

2. + = sec + 1

1− 1−

3. + + − = 2 = 2
2 − 2 1−2 2
− +

4. ( 8 − 8 ) = ( 2 − 2 )( 1 − 2 2 )

5. + −1 = 1+

− +1

6. If x = r sin θ cos φ, y = r sin θ sin φ, z = r cos θ, then prove that: x2+y2+z2=r2.

7. Prove that: 1 −1=1− 1

− +

8. Evaluate: tan 70 tan 230 tan 600 tan 670 tan 830 + cot 540 + sin 200 sec 700- 2
tan 360

HURRY!! Visit our portal and get your NCERT Solutions UPDATED 2021-22. These all very essential for your exam

preparation

If you are looking NCERT Solutions for Class 10 Maths error free and prepared by experienced mentors. Don’t
WORRY!! Here we are providing Free PDF you can get easy with a single click.

9. Evaluate: 32cosec2580 - 23cot 580tan 320 - 53tan 130 tan 370 tan 450 tan 530 tan 770.

10. If 5x = sec θ and 5 = tanθ, find the value of 5( 2 − 1 ).
2

11. Find the value of sec 600 geometrically.

12. Prove the following: sin A(1 + tan A) + cos A(1 + cot A) = sec A + cosec A.

Answers: 4) b 5) b 6) d 7) a
Objective:

1) b 2) a 3) d

Subjective: 9)-1 10) 1 11) 2
8)√3 5

HURRY!! Visit our portal and get your NCERT Solutions UPDATED 2021-22. These all very essential for your exam
preparation