GROUP MEMBERS: 1.LIVITHA NAARAYANASREE (22010838) 2. IEAN AQISH BIN ABDUL AZIZ (22010911) 3. ANIS YASMIN SAFI BT SAIFUL AKMAL (22011195) 4. AKMALL FAIZ BIN ADAM KAMAL (22010864) 5. TAN YENCY (22010927 6. NUR DANIELLA AMANI BT MOHD ELLMIEZAN (22011303) 7. MUHAMMAD KHAIRULLAH BIN ISMAIL (22011353) 8. SYED ARIF ISYRAF BIN SYED AHMAD REZAL (22010848) 9. YUVANESWARI A/P KARUNAGARAN (22011289) 10. MUHAMAD HANIF BIN BAHARUDDIN (22011133) FBM0025 QUANTITATIIVE ANALYSIS I APPLICATION OF TRIGONOMETRY IN REAL LIFE BY:GROUP 5
Photo and position Project Manager A. Project Manager Content Contributer 1 Content Contributer 2 Editor Layout Design 1 Layout Design 2 Writer Illustrator 1 Illustrator 2
AA TTRRIIGGOOMMAAZZEE [Alex pulls out a map of the maze, while Maya examines the angles of the corners.] Alex, Maya, and Liam stand at the entrance of the mysterious octagonal maze, surrounded by towering trees Wow, look at this maze! It's like something out of a fairy tale! I can't believe we found this hidden gem in our own backyard. Alright, team, time to put our heads together and figure out how to conquer this maze Let's see if we can plot our course using this map. And I'll use my compass to keep track of our directions as we go. Hmm, maybe we can use some math to solve this puzzle more efficiently. [Liam takes out a notebook and starts scribbling calculations.] I've got an idea! We can use trigonometry to calculate the angles and distances between each corner of the maze. Trigonometry? Sounds complicated. But if it helps us find our way out faster, I'm all for it!
[Alex, Maya, and Liam work together, measuring angles and distances, and making calculations.] According to our calculations, each angle in the maze is 60 degrees. And if we cut the octagonal shape into smaller triangles, we can use trigonometric ratios to find the shortest route. So, this is how my method works: we use sin(30°) = opposite/hypotenuse, where the opposite side is 30, and we want to find the hypotenuse, 'x'. Solving for 'x', we get 'x' = 30/sin(30°), which gives us 60m. Then, we add 60m for each section, totaling 180m. I've got another way too! How about we use tan(30°) = opposite/adjacent, and if the opposite side is 30, we solve for the adjacent side 'A'. So, 'A' = 30/tan(30°), which gives us approximately 51.96m. Adding that to 60m, we get 111.96m That sounds good, Alex and Liam. With both 'H' (hypotenuse) and 'A' (adjacent) calculated, we can determine the shortest path. So, adding 60m plus 60m gives us 120m. [They implement their plan, navigating through the maze using the calculated shortest route.] Left turn here, right turn there... we're making progress! I can see the exit up ahead! Thanks to trigonometry, we've cracked the code of this maze!
[As they near the exit, they encounter a tricky section of the maze.] Let's recheck our calculations and see if we missed anything. Don't worry, we'll figure this out. We did it! We conquered the maze! [They emerge from the maze and bask in the sunlight, feeling accomplished.] I guess there's more to solving puzzles than just brains; it's about working together too. Agreed! Now, who's up for our next adventure? What an adventure! Who knew math could be so thrilling? Uh-oh, looks like we've hit a dead end.. [After some recalculations and brainstorming, they find a solution to navigate through the tricky section.] I think we need to backtrack a bit and take a different path. And according to my calculations, we're almost there! Good call, Alex! That should lead us back on track. [They finally reach the exit, triumphant and relieved.] Teamwork and math for the win! And all thanks to Liam's brilliant idea to use trigonometry .