151 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. Exercise 7 (p.9) 1. Area 4 x 4 = 16 m2 2. Perimeter 3 + 2 + 3 + 2 = 10 m 3. Area 12 x 9 = 108 cm2 4a. Length of rectangle 8 cm + 8 cm = 16 cm b. Area of rectangle 16 cm x 8 cm = 128 cm2 5. Perimeter of Rectangle F 15 + 5 + 15 + 5 = 40 cm Side of Square E 40 cm ÷ 4 = 10 cm
152 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. Boost! Math Primary 3 Lesson 45: Area and Perimeter [2] Answer Key Area Perimeter 1a) Area = (7 x 7) cm = 49 cm² 1a) Perimeter = 4 x 7 cm (or 7 cm + 7 cm + 7 cm + 7 cm) = 28 cm 1b) Area = (8 x 4) cm = 32 cm² 1b) Perimeter = (8 + 8 + 4 + 4) cm = 24 cm 1c) Area = (9 x 3) cm = 27 m² 1c) Perimeter = (9 + 9 + 3 + 3) m = 24 m 1d) Area = (12 x 12) m = 144 m² 1d) Perimeter = (4 x 12) m (or 4 m + 4 m + 4 m + 4 m) = 48 m 2a) 41 cm – 5 cm = 36 cm 4 x side = 36 cm Side = 36 cm ÷ 4 = 9 cm = (9 x 9) cm = 81 cm² Area 2b) Perimeter = (4 x 9) cm = 36 cm 3. 40 cm – 4 cm = 36 cm Perimeter = (2 + 2 + 1 + 1) units = 6 units 6 units = 36 cm 1 unit = 36 cm ÷ 6 = 6 cm Length = 2 x 6 cm = 12 cm Area = (12 x 6) cm = 72 cm² 4. Length of 1 side of square A = 6 + 3 = 9 Area of square A = 9 x 9 = 81 Area of square B = 6 x 6 = 36 Total area of A and B = 81 + 36 = 117 cm² 4 cm 2 units 1 unit 3 cm 6 cm A B
153 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. 5. The two red lines add up to 1 length i.e. 7 cm Perimeter = 7 + 7 + 3 + 3 + 7 + 3 + 3 + 7 (2 red lines) = 40 cm 6. Perimeter of A = (40 + 40 + 10 + 10) cm = 100 cm Perimeter of B = 100 cm Length of 1 side of B = 100 ÷ 4 = 25 cm 7. Use systematic Listing. Perimeter of Y = 4 + 4 + 16 + 16 = 40 cm 8. Using Logical Thinking: 1 Length + 1 Breadth = 15 cm Perimeter of 1 rectangle = 2 x 15 = 30 cm 9. 1 Length = 3 Breadth Let the breadth be 1 unit and 1 length be 3 units Perimeter of 1 rectangle = 3u + 3u + 1u + 1u = 8u 8 units = 16 cm 1 unit = 16 ÷ 8 = 2 cm Length (3u) = 3 x 2 = 6 Perimeter of square = 4 x 6 = 24 cm Breadth Length Area of Y 1 cm 4 cm 1 x 4 = 4 cm² 2 cm 8 cm 2 x 8 = 16 cm² 3 cm 12 cm 3 x 12 = 36 cm² 4 cm 16 cm 4 x 16 = 64 cm² 7 cm 3 cm Figure A 7 cm 3 cm 3 cm 3 cm 7 cm 7 cm 7 cm Length Breadth 15 cm 1 Length = 3 Breadths 3 Breadths
154 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. 10. 2 Lengths = 3 Breadths Let 1 breadth be 1 unit. Perimeter = 2 L + 1 B + 1 L + 3 B + 1 L + 1 B = 2 L + 2 L + 5 B = 3 B + 3 B + 5 B = 11 B 11B = 11 units 11 units = 44 1 unit = 44 ÷ 11 = 4 Length of figure = 3 x 4 = 12 cm 1 L = (3 x 4) ÷ 2 = 6 cm Breadth of figure = 6 + 4 = 10 cm Area = (12 x 10) cm = 120 cm² 11. Perimeter = 4 sides = 15 cm Figure is made up of 8 equal sides. Perimeter of rectangle = 2 x 15 cm = 30 cm 12. Perimeter = 24 cm Each side of big square = 6 cm Each side of small square = 6 ÷ 2 = 3 cm Perimeter of each small square = 4 x 3 cm = 12 cm 13. Each side of square = 48 cm ÷ 4 = 12 cm Length of half side of square = 12 cm ÷ 2 = 6 cm Perimeter of rectangle = (12 + 12 + 12 + 12 + 6 + 6) cm = 60 cm 2 Lengths 3 breadths 1 Length 1 Length 1 breadth 1 breadth
155 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. Boost! Math Primary 3 Lesson 46: Heuristics – Review 1 Answer Key 1. Difference in age does not change. 39 – 9 = 30 1 unit = 30 2 units = 2 x 30 (M1) = 60 60 – 39 = 21 years (M1, A1) Ans: 21 years 2. No of intervals 11 – 1 (M1) = 10 Distance between every pot of sunflower = 50 m ÷ 10 (M1) = 5 m (A1) 3. Using the Supposition Method: Assume all are girls. 29 x 5 = 145 stickers 145 – 113 = 32 stickers (M1) Difference 5 – 3 = 2 stickers 32 ÷ 2 = 16 boys (M1, A1) OR Use a Guess and Check Table Ans: 16 boys 4. Amount of money Sam had left = $3715 - $1435 (M1) = $2280 Amount of money Sam had at first = $2280 + $1999 + $760 (M1) = $5039 (A1) Ans: $5039 5. Number of game cards in 7 pages 7 x 22 = 154 Number of game cards Mark had at first 154 – 18 + 10 = 146 Ans: 146 game cards Mother Jimmy 30
156 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. 6. 2 units = 36 1 unit = 36 ÷ 2 = 18 (M1) 7. Number of circles in Figure 12 12 x 2 + 2 (2 at the ends) = 26 [M2 A1] Ans: 26 8. Pattern 1: 1 = 1 x 1 (M1) Pattern 2: 4 = 2 x 2 Pattern 3: 9 = 3 x 3 Therefore, Pattern 8: 8 x 8 = 64 (M1, A1) Ans: 64 squares 9. String A String B 525 cm String C 195 cm 4 units = 195 + 525 cm (M1) = 720 cm 1 unit = 720 ÷ 4 (M1) = 180 cm (A1) = 1 m 80 cm (A1) Ans: 1 m 80 cm 10. Each day Tessa spent more than Rachel $5 - $3 = $2 more [M1] At the end difference between Tessa and Rchel $10 Number of days they spent 10 ÷ 2 = 5 days [M1] Tessa at first $75 + 5 x $5 = $100 [M1 A1] Ans: $100 (M3, A1) 36 ? Mulan Each at first 18 x 3 = 54 ( M1 A1) Nina Ans: 54 stickers
157 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. 11. 10 units = $3500 (M1) 1 unit = $3500 ÷ 10 (M1) = $350 6 units = 6 x $350 (M1) = $2100 (A1) Ans: $2100 12. 5 units = 267 + 8 = 275 1 unit = 275 ÷ 5 = 55 More 2 x 55 + 8 = 118 Ans: $118 13. ÷2 -2 ÷2 -3 ? 12 x2 +2 x2 +3 64 32 30 15 12 Ans: 64 bottles of orange juice 14. Using the Supposition Method: Assume all answers were answered correctly. 40 x 4 = 160 marks (total) Marks Macy lost 160 – 124 (M1) = 36 marks Marks taken away for every wrong answer 4 + 2 = 6 marks 36 ÷ 6 = 6 wrong answers 40 – 6 = 34 correct answers (M1) (M1, A1) OR use Guess and Check Table Ans: 34 correct answers $267 Fendi 8 George Hilary ? Computer Dryer TV Set $3500
158 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. Boost! Math Primary 3 Lesson 47: Heuristics – Review 2 Answer Key 1. The difference in age remains the same. 5 years ago 2 units 26 years 1 unit 26 ÷ 2 (M1) = 13 years (A1) 13 + 5 = 18 years (M1, A1) Ans: 18 years 2. No of flights of stairs from 1st to 5th floor 5 – 1 (M1) = 4 No of flights of stairs from 2nd to 8th floor 8 – 2 = 6 1 flight of stairs = 8 ÷ 4 (M1) = 2 min 6 flights of stairs = 6 x 2 min (M1) = 12 min (A1) Cyril will take 12 min. 3. Draw Stacking Model More 19 x 5 = 95 8 units 287 – 95 = 192 1 unit 192 ÷ 8 = 24 (1 soccer ball) 1 tennis racket 24 + 19 = 43 Ans: $43 4. The total remains unchanged. In the end, 3 units = 150 + 120 = 270 1 unit = 270 ÷ 3 = 90 (Paul had left) Paul gave 150 – 90 = 60 (M1) (M1 A1) Ans: 60 figurines Mrs Lee Jack 26 8 th 7 th th 6 th 5 th rd nd 4 3 2 st 1 8 min ? min 5 tennis rackets 5 soccer balls $19 $19 $19 $19 $19 $287 After model Paul Jake 150 +120
159 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. 5. Total of red lines 8 lengths Total of blue lines 8 breaths Total perimeter (8 x 10 cm) + (8 x 7 cm) = 80 cm + 56 cm (M2) = 136 cm (A1) Ans: 136 cm (A1) 6. Distance snail crawls a day = 5 m – 4 m (M1) = 1 m The snail crawls up 5 m after 5 days. On the 6th day 5 + 5 = 10 m (M1, A1) Ans: 6 days 7. 31 + 32 + 29 = 92 (2A + 2B + 2C) A + B + C = 92 ÷ 2 (M1) = 46 C 46 – 31 = 15 B 46 – 32 = 14 A 46 – 29 = 17 Ans: Ann = 17, Ben = 14, Chris = 15 8. 2 units = 12 + 30 + 12 = 54 1 unit = 54 ÷ 2 = 27 Total (4 units ) = 27 x 4 = 108 Ans: 108 apples Add up to 4 lengths 4 lengths M1 A1 A B 1 unit 2 units 30 12 12 12 After model 1 unit
160 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. 9. 1 unit = 63 – 38 = 25 Tarts at first 25 + 63 = 88 Ans: 88 tarts 10. Harry 28 5 William 5 3 – 2 = 1 6 ÷ 1 = 6 20 + 6 = 26 (M1, A1) Ans: A = 26 OR 2A + 2B = 39 + 39 = 78 B = 91 – 78 = 13 A = 39 – 13 = 26 Ans: A = 26 ? Difference between Harry’s and William’s amounts = $28 – $5 – $5 = $18 Ans: $18 11.Make a Table (M2) 39 sold Tarts Pies Left 2 units 38 left 63 sold 91 A 2 x A B 3 x B A To Btal 20 40 19 57 40 + 57 = 97 26 52 13 39 A52 + 3B9= 91 97 – 91 = 6 to go B
161 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. 12. I unit 385 ÷ 5 (M1) = 77 (A1) Train A (at first) 77 x 4 + 18 (M1) = 326 (A1) Ans: 326 passengers 13. 5 units = 960 1 unit = 960 ÷ 5 = 192 3 units = 192 x 3 = 576 Poured from A to B 576 ÷ 2 = 288 Ans: 288 ml 14. 2 ducks 2 x 2 = 4 legs 1 goat 1 x 4 = 4 legs 1 group 2 ducks and 1goat 4 + 4 = 8 legs No of groups 184 ÷ 8 = 23 (M1) (M1) No of ducks 2 x 23 = 46 (M1 A1) Ans: 46 ducks 960 ml A B A 385 B
162 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. Boost! Math Primary 3 Lesson 48: Semester 2 Review 3 Answer Key Section A (2 marks each) 1) 3 2) 4 3) 2 Pattern: – 120 + 10 2430 – 120 2310 2310 + 10 2320 4) 3 5) 1 Fractions with common numerators, the smaller the denominatorthe greater the fraction 3 4 6) 2 - 180 = 50 tens (500) Time shown 12.50 pm is 500 + 180 = 680 15 minutes fast 12.35 pm 15 min12.50 pm 7) 3 8) 4 9) 4 2 m = 200 cm 7 x 6 = 42 tennis balls Option (1), (2) & (3) 1 200 ÷ 5 = 40 cm 42 + 3 = 45 tennis balls 4 Option (4) 2 or 1 4 2 10) 3 11) 2 12) 3 Tot. amt. of money $10 greatest poss. 3-digit no. 999 1x2 = 2 $10 = 1000 cents smallest poss. 4-digit no. 1000 4x2 8 1000 ÷ 50 = 20 (50ȼ coins) 900 + 1000 = 1999 13) 4 24 grps of 60 24 grps of 56 + 24 grps of 4 14) 4 duration15min+20 min = 35 min 5.20 a.m. 35 min 5.55 a.m. 15) 4 Area 7 cm x 7 cm = 49 cm2 16) 1 17) 1 18) 3 1 unit = 312 (more adults) 3 units = 3 x 312 = 936 Let S represents shelf & CT 4 x 36 = 144 strawberries represents coffeetable, 144 ÷ 6 = 24 strawberries 5S + 1 CT = 528 – Equation 1 3S + 1 CT = 348 – Equation 2 Equation 1 – Equation 2: 2S 528 – 348 = 180 1S 180 ÷ 2 = $90 19) 3 28 cm Perimeter = ? Breadth = 28 ÷ 4 = 7 cm Perimeter = 28 + 7 + 28 + 7 = 70 cm 20) 2
163 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. Section B (2 marks each) 21. (a) see right (b) 306 (a) Eight thousand and forty-seven (b) 300 + 6 = 306 22. ∠b, ∠c, ∠a 23. 580 96 x 6 = 576 576 + 4 = 580 24. 48 g Mass of apple = 6 x 8 g (M1) = 48 g (A1) 25. 3 km 838 m 1 way 829 m+ 1090 m= 1919 m Total distance 1919 m x 2 = 3838 m 26. $455 1600 – 899 – 246 = 455 27. Fraction of pizza eaten 1 + 1 = 3 + 5 5 3 15 15 = 8 15 28. Fraction of muffins left 20 - 12 = 8 20 20 20 = 29. A, C, B, D 30. 6 No of kites Carl has 4 x 5 = 20 No of kites Bill has 4 x 2 = 8 No of kites Carl must give Bill (20 – 8) ÷ 2 = 12 ÷ 2 = 6 31. 217 2 units = 378 – 56 ? 1 unit = 322 ÷ 2 Girls = 161 Boys Girls 161 + 56 = 217 56 378 + 56 32. 112 $21 $15 John 141 - 29 = 112 33. 1 = 2 4 8 1 = 4 2 8 Ans: 3 8 34. DB ⊥ BC
164 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. Section C: Question 21 to 24 carry 3 marks each. Questions 25 and 26 carry 4 marks each. 41. Total volume of paint = 5 x 900 ml (M1) = 4 500 ml Volume of paint used = 4 500 ml - 700 ml (M1) = 3 800 ml (A1) Ans: 3 800 ml 42. No of dolls Ariel had in the end 25 + 10 + 10 = 45 ( M2) (A1) Ans: 45 dolls Nina Ariel 25 10 10 ? 35. , , 36. $39 Alex at first $125 – $37 = $88 Ben in the end $88 - $49 = $39 37. $18 2 cakes 21 + 15 = 36 1 cake 36 ÷ 2 = 18 $21 $15 38. 1 h 40 min 40 min 1 h 4.45 pm 5.25 pm 1 h + 40 min = 1 h 40 min 15 min 6.25 pm 6.40 pm 39. 19 pails 120 – 44 = 76 76 ÷ 4 = 19 40. 128 cm² 6 units = 48 1 unit = 48 ÷ 6 = 8 (Breadth) 2 units = 8 x 2 = 16 (Length) Area 16 x 8 = 128 1u 2u 2u 1u
165 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. 43. Cost of pencil = $1.80 - $0.60 = $1.20 1 set = 1 pen + 1 pencil $1.80 + $1.20 = $3 (M1) No of sets Gillian bought = 24 ÷ 3 (M1) = 8 (A1) No of pencils Gillian bought = 8 Ans: 8 pencils 7 3 44. Fraction of posters given away 1 + 1 (M1) = 21 3 + 7 21 = 10 21 21 21 Fraction of posters left 21 - 10 (M1) 21 = 11 (A1) Ans: 11 21 45. 36 = 6 x 6 Length of square = 6 cm Perimeter of rectangle = (20 + 20 + 6 + 6) cm = 52 cm (M1) (A1) (M1) (A1) Ans: 52 cm 46. 5 safety cones = 4 gaps Distance between 1st and 2nd safety cone = 12 ÷ 4 = 3 m (M1) (A1) Distance between 1st and last safety cone = 19 x 3 m (M1) = 57 m (A1) Ans: 57 m
166 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. Boost! Math Primary 3 Lesson 49: Semester 2 Review 4 Answer Key Section A (2 marks each) 1) 2 2) 1 3) 3 4) 3 5) 3 6) 2 7) 3 8) 1 9) 2 10) 2 Section A Worked Solutions 1. 7 x 4 = 28 6 x 9 = 54 (digit 4 is in the ones place) 8 x 6 = 48 5 x 10 = 50 5 x 2 10 2. 1 x 2 = 2 (not equivalent fraction) 1 x 4 = 4 5 x 4 20 1 x 3 = 3 6. A = 1 8 = 5 , = 4 2 10 10 5 7. blouse 78.70 – 20 = 58.70 total 78.70 + 58.70 = 137.40 8. Perimeter of A 32 + 32 + 18 + 18 = 100 Length of one side of B 100 ÷ 4 = 25 9. 6h 15 min – 1 h = 5 h 15 min 10. Total 190 + 50 = 240 Patricia has in the end 240 ÷ 3 = 80 Patricia gives to Jack 190 – 80 = 110 5 x 3 15 1 x 6 = 6 5 x 6 30 4. 5413, 5416, 5421, 5428 , 5437 +3 +5 +7 +9 5. Mass shown on scale 5000 g Mass of 2 apples 80 x 2 = 160 g Mass of pineapple 5000 – 160 = 4840 g 6h 8.30 a.m. 15 min 2.30 p.m. 2.45 p.m.
167 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. Section B (2 marks each) Qn Answers Worked Solution 11. 230 3 h = 3 x 60 min = 180 min 180 min + 50 min = 230 min 12. 8312 1 + 8 = 6 + 8 (M1) 13. 7 3 18 18 18 = 14 = 7 18 9 14. 1 4 = 1 3 12 3 15. 6 = 54 ÷ 3 = 18 (M1) = 18 ÷ 3 = 6 16. $15 2 sports bags $99 - $69 = $30 1 sport bag $30 ÷ 2 = $15 {M1} 17. 36 3 units = 108 1 unit = 108 ÷ 3 {M1} = 36 Y = 288 – 64 18. Y = 224 X = 32 = 224 X = 224 ÷ 7 = 32 19. 5.55 p.m. 5h 10 min + 1 h 15 min = 3 h 25 min 2.30 p.m. --- 3 h --- > 5.30 p.m. - 25 min-> 5.55 p.m. ------ ---------- 20. Section C: Question 21 to 26 carry 3 marks each. Questions 27 to 29 carry 4 marks each. 21. 1 unit = 113 – 83 = 30 Brenda 83 – 30 = 53 (M1) (M1 A1) Ans: 53 kg B A A B C 113 kg 83 kg
168 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. 22. Difference in mass between first and second bag = 752 g + 167 g = 919 g Mass of sugar in second bag = 1 642 g – 919 g = 723 g (M1) (M1) (A1) Ans: 723 g 23. (a) Time taken to shop at the florist = 40 min + 35 min (M1) = 75 min = 1 h 15 min (A1) Ans: (a) 1 h 15 min (b) - 40 min - 35 min 1p.m. 1.40 p.m 2.15 p.m. (A1) Ans: (b) 1 p.m. 24. From Bakery A: No of groups of muffins 24 ÷ 4 = 6 Cost of 6 groups of muffins 6 x $11 = $66 (M1) From Bakery B: No of groups of muffins 24 ÷ 6 = 4 Cost of 4 groups of muffins 4 x $15 = $60 (M1) Ans: Bakery B (A1) 25. 15 + 15 + 45 = 75 3 units = 276 – 75 = 201 1 unit = 201 ÷ 3 = 67 Jaclyn 67 + 15 + 45 = $127 (M1) (M1 A1) Ans: $127 Leanne Kris Jaclyn 15 276 15 45
169 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. 26. 7 x 5 = 35 8 units = 131 – 35 = 96 1 unit = 96 ÷ 8 = 12 1 racket 12 + 7 = 19 2 rackets 19 x 2 = $38 (M1) (M1 A1) 27(a) 1 Breadth = 24 ÷ 3 = 8 cm (A1) Ans: (a) 8 cm 27(b) 7 breadths = 7 x 8 cm = 56 cm (M1) Perimeter = 56 cm + (3 x 24 cm) = 56 cm + 72 cm = 128 cm (M1) (A1) Ans: (b) 128 cm 28(a) No of gaps between 1st and 3rd paper flower = 2 Distance between each gap = 12 cm ÷ 2 = 6 cm No of gaps between 2nd and 15th paper flower = 13 (M1) 28(b) Total distance between 2nd and 15th paper flower = 13 x 6 cm = 78 cm (M2) (A1) Ans: 78 cm 29. Work backwards remaining half of muffins in afternoon 2 + 48 = 50 muffins left in the afternoon 50 x 2 = 100 (M1) half of muffins unsold in morning 100 + 3 = 103 (M1) total muffins at first 103 x 2 = 206 (M1 A1) Ans: 206 muffins rackets basketballs 7 131 7 7 7 7 Ans: $38 3 2 48 ?
170 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. Boost! Math Primary 3 Lesson 50: Semester 2 Review 5 Answer Key Section A (2 marks each) 1) 4 2) 2 3) 3 4) 4 5) 1 6) 1 7) 2 8) 3 9) 3 10) 3 Section B (2 marks each) Qn Answers Worked Solution 11. 1083 12. , , Convert to same denominator: 12 , 3 , 7 14 14 14 13. 252 min 240 min + 12 min = 252 min 14. 4 ÷2 = 8 ÷2 1 2 15. 30 Number of bags 25 ÷ 5 = 5 Number of chocolate bars 5 x 6 = 30 16. and 1 + 4 9 12 = 3 12 + 9 12 = 12 = 1 12 17. 125 ml Capacity of 4 bottles = 1 000 ml Capacity of 1 bottle = 1 000 ÷ 4 = 250 ml Capacity of 2 mugs = 250 ml Capacity of 1 mug = 250 ÷ 2 = 125 ml 18. 36 cm Perimeter = 6 x 6 cm = 36 cm 19. 10.5 h No of hours opened in the morning = 2.5 h No of hours opened in the afternoon = 4 h No of hours opened in the evening = 4 h Total no of hours opened in a day = 2.5 h + 4 h + 4 h = 10.5 h 20.
171 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. Section C: (*deduct ½ mark for missing unit) Question 21 to 24 carry 3 marks each. Questions 25 and 26 carry 4 marks each. 21. Mass of 2 packets of beans = 2 x 320 g = 640 g (M1) Mass of empty box = 1010 g – 640 g = 370 g (M1 A1) Ans: 370 g 22. 23. Volume of 4 cups of juice = 4 x 280 ml = 1120 ml (M1) Total volume of juice = 1250 ml + 1120 ml = 2370 ml (M1 A1) Ans: 2 370 ml or 2 ℓ 370 ml 24. Change = $15 - $4.96 = $10.04 1 vegan burger + 1 pkt of sweet potato fries (M1) = $6.99 + $3.05 (M1 A1) Ans: 1 vegan burger and 1 packet of sweet potato fries (A1) Fred Gigi Harry 15 ? Distance Harry drove = 2789 m + 56 m + 141 m = 2986 m (M2) = 2 km 986 m (A1) *(deduct ½ mark if answer is not in km & m) Ans: 2 km 986 m 141 2789
172 2021 Copyright of PAL Solutions. No furtherreproductionanddistribution is allowed. 25. Beatrice’s money for 3 more days = 3 x $7 = $21 (M1) Total amount spent by both girls for same number of days = $91 - $21 = $70 (M1) Total amount of money spent by both girls for each day = $70 ÷ $10 = 7 (M1) Total no of days 7 + 3 = 10 (days) Beatrice’s pocket money = 10 x $7 = $70 (A1) Ans: $70 26. No of squares = 7 No of sides = 20 Length of each side = 140 cm ÷ 20 = 7 cm (M½) Perimeter of each square = 4 x 7 cm = 28 cm (M½ A1) (a) Ans: 28 cm Area of one square = 7 cm x 7 cm = 49 cm2 (M½) Area of figure = 7 x 49 cm2 = 343 cm2 (M½ A1) (b) Ans: 343 cm2