M DUL LENGKAP Year KSSR Semakan 6 Assessment Formative and Summative Digital Resources Mathematics Leow Yong Wei Mageswari Devan • Info • Simulation • Gamified Quiz Wordwall Let's Grasp! Formative Assessment PBD Module Idea Starter Mathematics Comics Booster Zone UASA Section B PAK-21 HOTS & i-THINK Summative Assessment Summative Practices Ujian Pertengahan Sesi Akademik (UPSA) Ujian Akhir Sesi Akademik (UASA) Answers PdPc- friendly Features
© Penerbitan Pelangi Sdn. Bhd. ii Info Quiz Summative Practice 2 Summative Practice 1 Summative Practice 3 Summative Practice 4 Summative Practice 5 Summative Practice 6 Summative Practice 7 Summative Practice 8 Let’s Grasp! Let’s Grasp! Let’s Grasp! Let’s Grasp! Let’s Grasp! Let’s Grasp! Let’s Grasp! Let’s Grasp! PBD Module PBD Module PBD Module PBD Module PBD Module PBD Module PBD Module PBD Module 1 UNIT Whole Numbers and Operations 1 Rekod Pentaksiran Murid iii – vi Ujian Pertengahan Sesi Akademik (UPSA) 68 Ujian Akhir Sesi Akademik (UASA) 140 Answers A1 - A8 CONTENTS Info Quiz 2 UNIT Fractions, Decimals and Percentages 26 Info 3 UNIT Money 47 Simulation Quiz Quiz 4 UNIT Time 76 Quiz 5 UNIT Measurement 88 Quiz 7 UNIT Coordinates, Ratio and Proportion 114 Quiz 8 UNIT Data Handling and Likelihood 129 Info 6 UNIT Space 99 Info Simulation Quiz
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages © Penerbitan Pelangi Sdn. Bhd. 26 Date: 1. Divide any fractions of two numbers involving proper fractions, whole numbers and mixed numbers. (a) 4 5 ÷ 2 = 4 5 ÷ 2 1 = 4 5 × 1 2 = 2 5 (b) 1 3 ÷ 2 5 = 1 3 × 5 2 = 5 6 (c) 1 4 5 ÷ 3 = 9 5 ÷ 3 1 convert mixed numbers to an improper fraction = 9 5 × 1 3 = 3 5 (d) 2 1 2 ÷ 4 5 = 5 2 × 5 4 = 25 8 = 3 1 8 (e) 2 1 3 ÷ 1 2 5 = 7 3 ÷ 7 5 = 7 3 × 5 7 = 5 3 = 1 2 3 (f) 4 ÷ 3 7 = 4 × 7 3 = 4 × 7 3 whole number × numerator = 28 3 = 9 1 3 2 1 3 1 1 1 change ÷ to × invert the divisor simplify the fraction Butterfly method 1 3 ÷ 2 5 = 1 × 5 3 × 2 = 5 6 Alternative 1 3 5 – 3 2 convert an improper fraction to mixed numbers 3 8 25 – 24 1 9 3 28 – 27 1 Let’s Grasp! Fractions, Decimals and Percentages 2 UNIT Learning area: Numbers and Operations In a proper fraction, which value is greater? The denominator or numerator?
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages 27 © Penerbitan Pelangi Sdn. Bhd. Date: 2. Convert any decimals to percentages more than 100% and vice versa. (a) Convert 3.1 to percentage. Method 1: 3.1 = (3.1 × 100)% = (3.10 × 100)% = 310% Method 2: 3.1 = 3 1 10 = 1 31 10 × 1002% = (31 × 10)% = 310% (b) Convert 245% to decimal. Method 1: 245% = 245 100 = 245 ÷ 100 = 2.45 Method 2: 245% = 100 100 + 100 100 + 45 100 = 2 + (45 ÷ 100) = 2.45 3. Determine the value of percentages within and more than 100% of a quantity in decimals and vice versa. (a) 70% × 2.4 = 70 100 × 2.4 = 0.7 × 2.4 = 1.68 2.4 × 0.7 1 6 8 + 0 0 0 1.6 8 1 decimal place 1 decimal place 2 decimal places (b) 365% × 8.7 = 365 100 × 8.7 = 3.65 × 8.7 = 31.755 3.6 5 × 8.7 2 5 5 5 + 2 9 2 0 0 3 1.7 5 5 2 decimal places 1 decimal place 3 decimal places (c) 0.5 0.8 × 100% = 5 8 × 100% = 62.5% (d) 2.55 0.5 × 100% = 25.5 5 × 100% = 5.1 × 100% = 510% 5.1 Move the decimal point. The number of movement of the upper number and the lower number is the same. Info Operations involving fractions, decimals and percentages
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages © Penerbitan Pelangi Sdn. Bhd. 28 Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 PBD MODULE Fractions Textbook: 61 – 67 LS 2.1.1 Divide fractions of two numbers involving proper fractions, whole numbers and mixed numbers. 2.1 1. Solve the following divisions. LS 2.1.1 PL 2 PL 3 (a) 1 2 ÷ 2 = 1 2 × 1 2 = 1 4 (b) 2 3 ÷ 4 = 2 3 × 1 4 = 2 12 = 1 6 (c) 3 4 ÷ 6 = 3 4 × 1 6 = 3 24 = 1 8 (d) 1 4 ÷ 2 5 = 1 4 × 5 2 = 5 8 (e) 1 9 ÷ 2 3 = 1 9 × 3 2 = 3 18 = 1 6 (f) 3 8 ÷ 1 4 = 3 8 × 4 1 = 12 8 = 1 1 2 (g) 1 2 3 ÷ 3 = 5 3 × 1 3 = 5 9 (h) 4 2 7 ÷ 5 = 30 7 × 1 5 = 30 35 = 6 7 (i) 9 1 3 ÷ 7 = 28 3 × 1 7 = 28 21 = 1 1 3
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages 29 © Penerbitan Pelangi Sdn. Bhd. Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 LS 2.1.1 Divide fractions of two numbers involving proper fractions, whole numbers and mixed numbers. 2. Solve the following divisions. LS 2.1.1 PL 2 PL 3 (a) 8 ÷ 3 4 = 8 × 4 3 = 32 3 = 10 2 3 (b) 9 ÷ 2 3 = 9 × 3 2 = 27 2 = 13 1 2 (c) 10 ÷ 1 3 5 = 10 ÷ 8 5 = 10 × 5 8 = 50 8 = 6 1 4 (d) 3 2 9 ÷ 2 3 = 29 9 ÷ 2 3 = 29 9 × 3 2 = 87 18 = 4 5 6 (e) 1 5 6 ÷ 5 9 = 11 6 ÷ 5 9 = 11 6 × 9 5 = 99 30 = 3 3 10 (f) 7 1 3 ÷ 1 6 = 22 3 ÷ 1 6 = 22 3 × 6 1 = 132 3 = 44 (g) 5 1 2 ÷ 1 1 4 = 11 2 ÷ 5 4 = 11 2 × 4 5 = 44 10 = 4 2 5 (h) 6 2 3 ÷ 1 5 6 = 20 3 ÷ 11 6 = 20 3 × 6 11 = 120 33 = 3 7 11 (i) 4 9 10 ÷ 2 4 5 = 49 10 ÷ 14 5 = 49 10 × 5 14 = 245 140 = 1 3 4
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages © Penerbitan Pelangi Sdn. Bhd. 30 Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 PBD MODULE Decimals Textbook: 68 – 72 LS 2.2.1 Multiply decimals with decimals, the product up to three decimal places. 2.2 3. Solve the following multiplications. LS 2.2.1 PL 2 PL 3 (a) 0.8 × 1.4 = 1.12 0 . 8 × 1 . 4 3 2 + 8 0 1 . 1 2 (b) 1.2 × 3.5 = 4.2 1 . 2 × 3 . 5 6 0 + 3 6 0 4 . 2 0 (c) 4.7 × 2.1 = 9.87 4 . 7 × 2 . 1 4 7 + 9 4 0 9 . 8 7 (d) 6.8 × 4.7 = 31.96 6 . 8 × 4 . 7 4 7 6 + 2 7 2 0 3 1 . 9 6 (e) 0.19 × 1.4 = 0.266 0 . 1 9 × 1 . 4 0 7 6 + 1 9 0 0 . 2 6 6 (f) 2.6 × 3.17 = 8.242 3 . 1 7 × 2 . 6 1 9 0 2 + 6 3 4 0 8 . 2 4 2 (g) 4.08 × 8.4 = 34.272 4 . 0 8 × 8 . 4 1 6 3 2 + 3 2 6 4 0 3 4 . 2 7 2 (h) 10.85 × 5.2 = 56.42 1 0 . 8 5 × 5 . 2 2 1 7 0 + 5 4 2 5 0 5 6 . 4 2 0 (i) 3.45 × 1.84 = 6.348 3 . 4 5 × 1 . 8 4 1 3 8 0 2 7 6 0 0 + 3 4 5 0 0 6 . 3 4 8 0
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages 31 © Penerbitan Pelangi Sdn. Bhd. Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 LS 2.2.2 Divide decimals by decimals, the quotient up to three decimal places. 4. Solve the following divisions. LS 2.2.2 PL 2 PL 3 (a) 2.7 ÷ 0.3 = 2.7 ÷ 0.3 = 27 ÷ 3 = 9 9 3 27 – 27 0 (b) 1.12 ÷ 0.8 = 1.12 ÷ 0.8 = 112 ÷ 80 = 1.4 (c) 1.674 ÷ 0.6 = 1.674 ÷ 0.6 = 16.74 ÷ 6 = 2.79 (d) 0.979 ÷ 1.1 = 0.979 ÷ 1.1 = 9.79 ÷ 11 = 0.89 (e) 1.815 ÷ 1.5 = 1.815 ÷ 1.5 = 18.15 ÷ 15 = 1.21 (f) 16 ÷ 2.5 = 16 ÷ 2.5 = 160 ÷ 25 = 6.4 (g) 0.084 ÷ 0.12 = 0.084 ÷ 0.12 = 8.4 ÷ 12 = 0.7 (h) 1.656 ÷ 0.36 = 1.656 ÷ 0.36 = 165.6 ÷ 36 = 4.6 (i) 4.41 ÷ 1.4 = 4.41 ÷ 1.4 = 44.1 ÷ 14 = 3.15 Tips To divide a decimal number by a decimal number, follow the following 2 steps: 1 Convert the divisor to a whole number by moving the decimal point to the right. 2 Move the decimal point in the dividend according to the number of movements in 1. 1.4 80 112.0 – 80 32.0 – 32.0 .0 2.79 6 16.74 – 12 4.7 – 4.2 .54 –.54 .00 0.89 11 9.79 – 0 9.7 – 8.8 .99 – .99 .00 1.21 15 18.15 – 15 3.1 – 3.0 .15 –.15 .10 6.4 25 160.0 – 150 10.0 – 10.0 .0 0.7 12 8.4 – 0 8.4 – 8.4 .0 4.6 36 165.6 – 144 21.6 – 21.6 .0 3.15 14 44.10 – 42 2.1 – 1.4 .70 –.70 .00
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages © Penerbitan Pelangi Sdn. Bhd. 32 Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 PBD MODULE Percentages Textbook: 73 – 79 LS 2.3.1 Convert decimals to percentages more than 100% and vice versa. 2.3 5. Convert the following decimals to percentages. LS 2.3.1 PL 2 (a) 0.07 = (0.07 × 100)% = 7% (b) 0.6 = (0.6 × 100)% = 60% (c) 0.12 = (0.12 × 100)% = 12% (d) 1.09 = (1.09 × 100)% = 109% (e) 3.4 = (3.4 × 100)% = 340% (f) 7.58 = (7.58 × 100)% = 758% 6. Complete these. LS 2.3.1 PL 2 i-THINK Bridge Map Decimals Percentages as as 5.3 (a) 530% 2.07 (c) 207% (b) 8.04 804% 7. Convert the following percentages to decimals. LS 2.3.1 PL 2 (a) 4% = 4% ÷ 100% = 0.04 (b) 90% = 90% ÷ 100% = 0.9 (c) 36% = 36% ÷ 100% = 0.36 (d) 208% = 208% ÷ 100% = 2.08 (e) 710% = 710% ÷ 100% = 7.1 (f) 542% = 542% ÷ 100% = 5.42 i-THINK Map
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages 33 © Penerbitan Pelangi Sdn. Bhd. Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 LS 2.3.2 Solve addition and subtraction number sentences involving percentages. 8. Solve the following addition of percentages. LS 2.3.2 PL 3 (a) 5% + 4% = 9% (b) 12% + 6% = 18% (c) 37% + 21% = 58% (d) 9% + 8% = 17% (e) 26% + 7% = 33% (f) 43% + 29% = 72% 9. Solve the following subtraction of percentages. LS 2.3.2 PL 3 (a) 9% − 2% = 7% (b) 17% − 3% = 14% (c) 48% − 14% = 34% (d) 10% − 6% = 4% (e) 60% – 29% = 31% (f) 91% – 35% = 56%
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages © Penerbitan Pelangi Sdn. Bhd. 34 Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 LS 2.3.3 Determine value of percentages within and more than 100% of a quantity in decimals and vice versa. 10. Determine the value of percentages of a quantity in decimals. LS 2.3.3 PL 3 (a) 10% × 1.6 = 10 100 × 1.6 = 0.1 × 1.6 = 0.16 (b) 25% × 7.6 = 25 100 × 7.6 = 0.25 × 7.6 = 1.9 (c) 110% × 0.3 = 110 100 × 0.3 = 1.1 × 0.3 = 0.33 (d) 230% × 7.6 = 230 100 × 7.6 = 2.3 × 7.6 = 17.48 (e) 40% of 18.5 = 40 100 × 18.5 = 0.4 × 18.5 = 7.4 (f) 500% of 18.5 = 500 100 × 18.5 = 5 × 18.5 = 92.5 11. Find the value of percentages for each of the following. LS 2.3.3 PL 3 (a) 0.2 0.5 × 100% = 2 5 × 100% = 40% (b) 1.2 1.6 × 100% = 12 16 × 100% = 75% (c) 1.2 0.4 × 100% = 12 4 × 100% = 300% (d) 3.6 1.5 × 100% = 36 15 × 100% = 240% (e) 0.9 compared to 1.5 = 0.9 1.5 × 100% = 9 15 × 100% = 60% (f) 6.75 compared to 4.5 = 6.75 4.5 × 100% = 675 450 × 100% = 150%
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages 35 © Penerbitan Pelangi Sdn. Bhd. Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 PBD MODULE Mixed operations Textbook: 80 – 91 LS 2.4.1 Solve mixed operations number sentences of any two basic operations, involving whole numbers, decimals and fractions, with and without brackets. 2.4 12. Solve the following. LS 2.4.1 PL 2 PL 3 (a) 3 1 2 + 1.8 − 2.47 = Lakukan operasi dari kiri ke kanan. 3 1 2 + 1.8 − 2.47 = 3.5 + 1.8 – 2.47 = 5.3 – 2.47 = 2.83 (b) 10 − 4 2 5 + 3.18 = Lakukan operasi dari kiri ke kanan. 10 – 4 2 5 + 3.18 = 10 – 4.4 + 3.18 = 5.6 + 3.18 = 8.78 (c) 9.1 − 5 + 2 3 4 = Lakukan operasi dari kiri ke kanan. 9.1 – 5 + 2 3 4 = 9.1 – 5 + 2.75 = 4.1 + 2.75 = 6.85 (d) 2 3 10 + 6.1 − 4.09 = Lakukan operasi dari kiri ke kanan. 2 3 10 + 6.1 − 4.09 = 2.3 + 6.1 – 4.09 = 8.4 – 4.09 = 4.31 (e) 4 1 8 + 8.79 − 1.06 = Lakukan operasi dari kiri ke kanan. 4 1 8 + 8.79 − 1.06 = 4.125 + 8.79 – 1.06 = 12.915 – 1.06 = 11.855 (f) 20 − 13 1 4 + 7.585 = Lakukan operasi dari kiri ke kanan. 20 – 13 1 4 + 7.585 = 20 – 13.25 + 7.585 = 6.75 + 7.585 = 14.335
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages © Penerbitan Pelangi Sdn. Bhd. 36 Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 LS 2.4.1 Solve mixed operations number sentences of any two basic operations, involving whole numbers, decimals and fractions, with and without brackets. 13. Solve the following. LS 2.4.1 PL 2 PL 3 (a) 4 1 2 × 0.7 ÷ 2 = Lakukan operasi dari kiri ke kanan. 4 1 2 × 0.7 ÷ 2 = 4.5 × 0.7 ÷ 2 = 3.15 ÷ 2 = 1.575 (b) 12 ÷ 3 3 4 × 1.35 = Lakukan operasi dari kiri ke kanan. 12 ÷ 3 3 4 × 1.35 = 12 ÷ 15 4 × 1.35 = 12 × 4 15 × 1.35 = 3.2 × 1.35 = 4.32 (c) 18 ÷ 1.6 × 2 7 10 = Lakukan operasi dari kiri ke kanan. 18 ÷ 1.6 × 2 7 10 = 18 ÷ 1.6 × 2.7 = 180 ÷ 16 × 2.7 = 11.25 × 2.7 = 30.375 (d) 4 3 5 × 2.68 ÷ 2.3 = Lakukan operasi dari kiri ke kanan. 4 3 5 × 2.68 ÷ 2.3 = 4.6 × 2.68 ÷ 2.3 = 12.328 ÷ 2.3 = 123.28 ÷ 23 = 5.36 (e) 2 1 4 × 3.5 ÷ 1.5 = Lakukan operasi dari kiri ke kanan. 2 1 4 × 3.5 ÷ 1.5 = 2.25 × 3.5 ÷ 1.5 = 7.875 ÷ 1.5 = 78.75 ÷ 15 = 5.25 (f) 36 ÷ 3 1 5 × 1.24 = Lakukan operasi dari kiri ke kanan. 36 ÷ 3 1 5 × 1.24 = 36 ÷ 3.2 × 1.24 = 360 ÷ 32 × 1.24 = 11.25 × 1.24 = 13.95
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages 37 © Penerbitan Pelangi Sdn. Bhd. Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 LS 2.4.1 Solve mixed operations number sentences of any two basic operations, involving whole numbers, decimals and fractions, with and without brackets. 14. Solve the following. LS 2.4.1 PL 2 PL 3 (a) 4 × 0.59 + 3 4 5 = Lakukan operasi darab terlebih dahulu diikuti operasi tambah. 4 × 0.59 + 3 4 5 = 4 × 0.59 + 3.8 = 2.36 + 3.8 = 6.16 (b) 2 9 10 – 18 × 0.054 = Lakukan operasi darab terlebih dahulu diikuti operasi tolak. 2 9 10 – 18 × 0.054 = 2.9 – 18 × 0.054 = 2.9 – 0.972 = 1.928 (c) 12 1 2 ÷ 5 + 71.29 = Lakukan operasi bahagi terlebih dahulu diikuti operasi tambah. 12 1 2 ÷ 5 + 71.29 = 12.5 ÷ 5 + 71.29 = 2.5 + 71.29 = 73.79 (d) 318.9 ÷ 3 − 17 3 4 = Lakukan operasi bahagi terlebih dahulu diikuti operasi tolak. 318.9 ÷ 3 – 17 3 4 = 318.9 ÷ 3 – 17.75 = 106.3 – 17.75 = 88.55 (e) 12 2 5 + 92 × 0.69 = Lakukan operasi di dalam kurungan dahulu. 12 2 5 + 92 × 0.69 = (2.4 + 9) × 0.69 = 11.4 × 0.69 = 7.866 (f) 115.497 − 5 5 8 2 ÷ 0.8 = Lakukan operasi di dalam kurungan dahulu. 115.497 – 5 5 8 2 ÷ 0.8 = (15.497 – 5.625) ÷ 0.8 = 9.872 ÷ 0.8 = 98.72 ÷ 8 = 12.34
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages © Penerbitan Pelangi Sdn. Bhd. 38 Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 PBD MODULE Problem solving Textbook: 93 – 98 LS 2.5.1 Solve daily problems involving whole numbers, fractions, decimals and percentages. 2.5 15. Solve each of the following problems. LS 2.5.1 Application Daily (a) Haikal wants to pour 1 2 l of water into a few containers which has the capacity of 1 8 l each. How many containers are needed by Haikal? PL 4 Bilangan bekas yang diperlukan = 1 2 l ÷ 1 8 l = 1 2 × 8 1 = 4 (b) The diagram below shows a handcraft which is made by Aqil. – m7 9 Given that the area of the handcraft is 1 3 4 m2 . Calculate the measure, in m, of length of the handcraft. PL 4 × 7 9 m = 1 3 4 m2 Panjang kraf tangan = 1 3 4 m2 ÷ 7 9 m = 2 1 4 m (c) The table below shows the mass of two parcels. Parcel P Q Mass 0.75 kg 1.6 times the mass of P Calculate the mass, in kg, of parcel Q. PL 4 Jisim bungkusan Q = 1.6 × 0.75 kg = 1.2 kg
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages 39 © Penerbitan Pelangi Sdn. Bhd. Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 LS 2.5.1 Solve daily problems involving whole numbers, fractions, decimals and percentages. 16. Solve each of the following problems. LS 2.5.1 Application Daily (a) The diagram shows a cake sliced by Chin into two equal parts. In each part, Chin cut the cake again into 5 equal small parts. Calculate the fraction of each small piece of cake from the whole cake. PL 5 1 2 ÷ 5 = 1 2 × 1 5 = 1 10 (b) The diagram below shows the conversation between Puan Hani and her daughter, Nadia, in their preparation for a dinner party. PL 5 (i) What is the total volume, in l, of the orange juice? Give the answer in decimal. Jumlah isi padu jus oren yang dibeli = (6 × 1.35) + 2 1 2 = 8.1 + 2.5 = 10.6 l (ii) Calculate the volume, in ml, of orange juice that can be filled into each glass? Isi padu jus oren dalam satu gelas = 10.6 l ÷ 53 = 0.2 l = 200 ml Mathematics Comic Mathematics Comic Pour all the orange juice into the water container in the kitchen. Then pour it back into 53 glasses with an equal amount each. Mom, this large bottle contains 2 1 2 l of orange juice while the small bottles contain 1.35 l of orange juice.
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages © Penerbitan Pelangi Sdn. Bhd. 40 Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 LS 2.5.1 Solve daily problems involving whole numbers, fractions, decimals and percentages. 17. Solve each of the following problems. LS 2.5.1 Application Daily (a) The diagram below shows the distance between a few locations. 72.3 km F G E Given that the distance of FG is 1.5 times the distance of EF. Calculate the distance, in km, of EG. PL 5 Jarak EG Jarak EF + Jarak FG = 48.2 km + 72.3 km = 120.5 km (b) The diagram below shows the conversation between two pupils. Iqbal Daim The total mass of both of us is 78.2 kg. My mass is 5 2 5 kg more than your mass. Prove the mass of Iqbal, in kg, is 36.4 kg. PL 6 HOTS Analysing Iqbal Daim 5 2 5 kg 78.2 kg = 72.8 kg ÷ 2 = 36.4 kg Maka, dibuktikan jisim Iqbal ialah 36.4 kg.
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages 41 © Penerbitan Pelangi Sdn. Bhd. Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 Booster Zone UASA Section B (a) The table below shows the percentage of Year 4 pupils at SK Jalan Pelangi based on their hobbies. The percentage for the hobby of drawing is not shown. Hobby Cooking Reading Swimming Drawing Percentages 45% 20% 20% Calculate the total percentage of pupils with hobbies of cooking and drawing. Peratus murid dengan hobi melukis = 100% − 45% − 20% − 20% = 15% Jumlah peratus murid dengan hobi memasak dan melukis = 45% + 15% = 60% (b) A recycling club at SK Jalan Pelangi has collected 42.6 kg of old newspapers from Level 1 pupils. The mass of old newspapers collected from Level 2 pupils is 325% of the mass of old newspapers collected from Level 1 pupils. Calculate the mass, in kg, of the old newspapers collected from Level 2 pupils. Jisim surat khabar lama = 325% × 42.6 kg = 3.25 × 42.6 kg = 138.45 kg Booster Zone
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages © Penerbitan Pelangi Sdn. Bhd. 42 Date: Teacher’s Signature: Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 (c) The diagram below shows the area of a flower garden at SK Jalan Pelangi. 6– 1 m2 4 Gardeners in SK Jalan Pelangi want to plant five types of flowers in the garden with the area of each type of flower being the same size. Calculate the area, in m2 , of each type of flower planted by the gardeners. 6 1 4 m2 ÷ 5 = 25 4 m2 ÷ 1 5 = 5 4 m2 = 1 1 4 m2 Encik Jason boleh menanam 5 jenis bunga dengan keluasan 1 1 4 m2 bagi setiap jenis bunga. Sebarang jawapan lain yang betul juga diterima. (d) The table below shows the distance between SK Jalan Pelangi and the houses of three teachers who teach at the school. Teacher Distance from house to school Mrs. Wong 21.5 km Puan Haniza 0.89 km Mr. Ramesh 0.7 times the total distance of Mrs. Wong and Puan Haniza Calculate the distance from Mr. Ramesh’s house to SK Jalan Pelangi. Booster Zone
43 © Penerbitan Pelangi Sdn. Bhd. Date: 1. The diagram below shows a mathematical sentence. (a) How many decimal places for the product? (b) Solve the mathematical sentence. [3 marks] 2. Convert 0.05 to a percentage. [1 mark] 3. Convert 80% to a decimal. [1 mark] 4. The diagram below shows a decimal number card. (a) Convert the decimal number to a percentage. (b) Calculate 3.06 divided by 1.2. [3 marks] 5. 6 3 8 ÷ 1 1 4 = [2 marks] 6. 20% × 5.4 kg = [2 marks] 7. 8.25 2.5 × 100% = [2 marks] 8. 4 2 5 – 1.68 + 2.5 = [3 marks] SUMMATIVE PRACTICE 2 A Section
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages © Penerbitan Pelangi Sdn. Bhd. 44 © Penerbitan Pelangi Sdn. Bhd. 9. 81 − 64.2 ÷ 1 1 2 = [3 marks] 10. 5.109 + 2 3 4 × 7 = [3 marks] 11. 15 1 10 + 70.82 ÷ 4 = [3 marks] 12. Calculate 6.4 × 12 3 8 + 62. State the answer in a mixed number. [3 marks] B Section 1. (a) The diagram below shows the volume of water that can be filled into a container and a cup at Puan Zulaikha’s house. A B 4.4 fi 0.32 fi How many cups can be filled completely using all the water in the container? [3 marks].
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages 45 © Penerbitan Pelangi Sdn. Bhd. (b) Puan Zulaikha wants to hang a picture frame in her house as shown in the diagram. Given that the area of the picture frame is 3 10 m2 . Calculate the length, in m, of the picture frame. [2 marks] (c) Puan Zulaikha’s son, Elhan, has a book M and a book N. The mass of book M is 0.95 kg, while the mass of book N is 2.6 times the mass of book M. Calculate the total mass, in kg, of Elhan’s books. [3 marks] (d) The table below shows the percentage discount for a few items at a supermarket. Item Percentage discount Handbag 32% Shoes 48% Fragrance set 68% Puan Zulaikha bought two items with a total percentage discount of 80%. State the two items bought by Puan Zulaikha. [4 marks] 3 4 – m Gamified Quiz 2
Mathematics Year 6 Unit 2 Fractions, Decimals and Percentages © Penerbitan Pelangi Sdn. Bhd. 46 Date: Think-Pair-Share Preparation phase: 1. Activity in pairs. 2. Teacher prepares question cards and competition sites as the following example. Example: Draw 9 squares (a) 5 1 2 ÷ 3 5 = (b) 4 ÷ 2 1 4 = (c) 6.7 × 1.23 = (d) 1.837 ÷ 1.1 = (e) 82% − 34% = (f) 43% + 29% = (g) 125% × 4.6 = (h) 7.1 − 4.935 ÷ 2 1 10 = (i) 11 3 8 + 2.472 × 0.2 = Instructions: 1. Each pair of pupils solve the questions starting from (a). 2. Whoever solves the fastest and the answer is correct, can mark a symbol in one of the 9 squares. 3. The pupil who is the fastest to connect the symbols in a row horizontally or vertically is the winner. Example of work result: PAK-21 ACTIVITY 2 UNIT Fractions, Decimals and Percentages PAK–21 Activity
Mathematics Year 6 Unit 3 Money 47 © Penerbitan Pelangi Sdn. Bhd. Date: 1. Financial terms which are commonly used in society. Term Definition Cost price The price of goods obtained by the dealer before being sold. Selling price The price of any goods sold to the buyers. Profit The money obtained after deducted with cost price. Loss This situation arises when the cost price is higher than the selling price. Bill A written statement about the purchase of any goods or services that has been received. Invoice A record of detailed information of goods or services supplied to customers and the total amount of price needs to be paid by the customers. Voucher Document which can be exchanged with certain goods or services. Example: gift voucher, discount voucher Receipt Document issued by a payee to the purchaser after completing the payment transaction. Discount The price reduction from the original price of any goods. Rebate The deduction of a certain amount of payment or the return of part of the money after buying goods. Asset Anything which is owned such as cash money and property. Example: car, house, cash money, jewelleries Depreciation Assets will experience depreciation due to several factors as follows: • Obsolescence factor is a deteriorating physical condition. • Technological changes that cause the assets to become outdated such as computers. Liability Financial commitment or debt. Example: overdue bills, credit card debts, house instalments, taxes Interest • A sum of money earned from the savings in the bank. • Excess fees charged on loans or credits. Dividend Distribution of some company’s (private limited) profit to the shareholders. Service tax Money that needs to be paid for services provided by certain businesses such as hotels and restaurants. Let’s Grasp! Money 3 UNIT Learning area: Numbers and Operations Info Finance, insurance and takaful terms Between the values of asset and liability, which one requires a higher value for better money management?
Mathematics Year 6 Unit 3 Money © Penerbitan Pelangi Sdn. Bhd. 48 Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 PBD MODULE Financial management Textbook: 103 – 120 LS 3.1.1 Recognise cost price, selling price, profit, loss, discount, rebate, voucher, bill, receipt, invoice, asset, liability, interest, dividend and service tax. 3.1 1. State the correct financial term. LS 3.1.1 PL 1 PL 2 (a) Document issued by a payee to the purchaser after completing the payment transaction. Resit (b) This situation arises when the cost price is higher than the selling price. Rugi (c) The price reduction from the original price of any goods. Diskaun (d) Financial commitment or debt such as credit card debt. Liabiliti (e) The price of any goods sold to the buyers. Harga jual (f) The return of part of the money after buying goods. Rebat (g) A sum of money earned from the savings in the bank. Faedah (h) Money that needs to be paid for the provided services. Cukai perkhidmatan (i) A written statement about the purchase of any goods that has been received. Bil ( j) The price of goods obtained by the dealer before being sold. Harga kos (Harga beli) (k) Anything which is owned such as cash money and property. Aset (l) Distribution of some company’s profit to the shareholders. Dividen (m) The money obtained after deducted with cost price. Untung (n) Document which can be exchanged with certain goods. Baucar (o) A record of detailed information of goods or services supplied to customers and the total amount of price needs to be paid by the customers. Invois (p) Assets will experience depreciation due to several factors such as obsolescence and technological changes. Susut nilai
Mathematics Year 6 Unit 3 Money 49 © Penerbitan Pelangi Sdn. Bhd. Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 LS 3.1.2 Determine cost price, selling price, profit, loss, discount, rebate, interest, dividend and service tax. 2. Solve each of the following. LS 3.1.2 (a) The table below shows the cost price, profit value or selling price for a few items sold in a sports shop. Complete the table below. PL 3 Item Cost price Profit value Selling price (i) Sports shoes RM100 RM40 RM100 + RM40 = RM140 (ii) Bag RM120 RM155 – RM120 = RM35 RM155 (iii) Badminton racket RM420 – RM70 = RM350 RM70 RM420 (iv) Soccer ball RM180 RM270 – RM180 = RM90 RM270 (b) Complete the table below. Determine whether the value is profit or loss. PL 3 Item Cost price Selling price Profit / Loss (i) Table fan RM150 RM110 Rugi = RM150 – RM110 = RM40 (ii) Mobile phone RM420 RM900 Untung = RM900 – RM420 = RM480 (iii) Shoes RM390 RM160 Rugi = RM390 – RM160 = RM230 (iv) Handbag RM540 RM600 Untung = RM600 – RM540 = RM60 Simulation Profit and loss
Mathematics Year 6 Unit 3 Money © Penerbitan Pelangi Sdn. Bhd. 50 Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 (c) Calculate the cost price or selling price. PL 3 (i) Selling price: RM33.80 Profit: RM7.80 (ii) Cost price: RM1 200 Loss: RM650 Cost price = Harga jual − Untung = RM33.80 − RM7.80 = RM26 Selling price = Harga kos − Rugi = RM1 200 − RM650 = RM550 (iii) Cost price: RM45 Profit: RM12 (iv) Selling price: RM24 Loss: RM86 Selling price = = RM45 + RM12 = RM57 Cost price = Harga jual + Rugi = RM24 + RM86 = RM110 (v) Cost price: RM3 790 Loss: RM2 500 (vi) Selling price: RM1 570 Profit: RM490 Selling price = H = RM3 790 − RM2 500 = RM1 290 Cost price = Harga jual − Untung = RM1 570 − RM490 = RM1 080
Mathematics Year 6 Unit 3 Money 51 © Penerbitan Pelangi Sdn. Bhd. Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 (d) Calculate the selling price after the percentage of profit is given. PL 3 (i) Cost price: RM100 Percentage of profit: 10% Nilai untung = 10 100 × RM100 = RM10 Harga jual selepas untung = RM100 + RM10 = RM110 (ii) Cost price: RM250 Percentage of profit: 15% Nilai untung = 15 100 × RM250 = RM37.50 Harga jual selepas untung = RM250 + RM37.50 = RM287.50 (e) Calculate the percentage of profit or percentage of loss for each of the following. PL 3 (i) Item Cost price Selling price Rice RM20 RM21 Untung = Harga jual − Harga kos = RM21 − RM20 = RM1 Peratus untung = RM1 RM20 × 100% = 5% (ii) Item Cost price Selling price Bicycle RM450 RM360 Rugi = Harga kos − Harga jual = RM450 − RM360 = RM90 Peratus rugi = RM90 RM450 × 100% = 20% (iii) Item Cost price Selling price Book RM120 RM102 Rugi = Harga kos − Harga jual = RM120 − RM102 = RM18 Peratus rugi = RM18 RM120 × 100% = 15% (iv) Item Cost price Selling price Shirt RM50 RM62.50 Untung = Harga jual − Harga kos = RM62.50 − RM50 = RM12.50 Peratus untung = RM12.50 RM50 × 100% = 25%
Mathematics Year 6 Unit 3 Money © Penerbitan Pelangi Sdn. Bhd. 52 Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 LS 3.1.2 Determine cost price, selling price, profit, loss, discount, rebate, interest, dividend and service tax. 3. Solve each of the following. LS 3.1.2 (a) Calculate the new price after the discount is given. PL 3 (i) Original price: RM50 Percentage of discount: 20% Nilai diskaun = 20 100 × RM50 = RM10 Harga baharu selepas diskaun = RM50 – RM10 = RM40 (ii) Original price: RM90 Percentage of discount: 5% Nilai diskaun = 5 100 × RM90 = RM4.50 Harga baharu selepas diskaun = RM90 – RM4.50 = RM85.50 (iii) Original price: RM200 Percentage of discount: 10% Nilai diskaun = 10 100 × RM200 = RM20 Harga baharu selepas diskaun = RM200 – RM20 = RM180 (iv) Original price: RM450 Percentage of discount: 15% Nilai diskaun = 15 100 × RM50 = RM67.50 Harga baharu selepas diskaun = RM450 – RM67.50 = RM382.50 (v) Original price: RM1 000 Percentage of discount: 25% Nilai diskaun = 25 100 × RM1 000 = RM250 Harga baharu selepas diskaun = RM1 000 – RM250 = RM750 (vi) Original price: RM3 500 Percentage of discount: 30% Nilai diskaun = 30 100 × RM3 500 = RM1 050 Harga baharu selepas diskaun = RM3 500 – RM1 050 = RM2 450
Mathematics Year 6 Unit 3 Money 53 © Penerbitan Pelangi Sdn. Bhd. Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 LS 3.1.2 Determine cost price, selling price, profit, loss, discount, rebate, interest, dividend and service tax. (b) Calculate the new price after the rebate is given. PL 3 (i) Original price: RM50 Rebate: RM5 Harga baharu selepas rebat diberi = RM50 − RM5 = RM45 (ii) Original price: RM120 Rebate: RM10 Harga baharu selepas rebat diberi = RM120 − RM10 = RM110 (iii) Original price: RM200 Rebate: RM15 Harga baharu selepas rebat diberi = RM200 − RM15 = RM185 (iv) Original price: RM450 Rebate: RM20 Harga baharu selepas rebat diberi = RM450 − RM20 = RM430 (v) Original price: RM810 Rebate: RM30 Harga baharu selepas rebat diberi = RM810 − RM30 = RM780 (vi) Original price: RM990 Rebate: RM75 Harga baharu selepas rebat diberi = RM990 − RM75 = RM915 (c) Complete the following tables. PL 3 (i) (ii) Quantity Item Unit price (RM) Total (RM) 20 Pen 1.20 24 10 Scarf 5.60 56 50 Book 3.40 170 Total 250 – 20% discount 50 Total payment 200 Quantity Item Unit price (RM) Total (RM) 25 Milk 2.60 65 30 Juice 5.00 150 50 Coffee 4.50 225 Total 440 – 15% discount 66 Total payment 374
Mathematics Year 6 Unit 3 Money © Penerbitan Pelangi Sdn. Bhd. 54 Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 LS 3.1.2 Determine cost price, selling price, profit, loss, discount, rebate, interest, dividend and service tax. 4. Solve the following problems. LS 3.1.2 PL 3 (a) Kumar and Ikram have saved RM3 000 and RM8 000 respectively in Bank Q and no withdrawal is made. The bank offers interest with an interest rate of 3% per annum. Complete the following table. Kumar Ikram Year Interest value First 3% × RM3 000 = 3 100 × RM3 000 = 3 × RM30 = RM90 Second 3% × RM3 090 = 3 100 × RM3 090 = 0.3 × RM309 = RM92.70 Third 3% × RM3 182.70 = 3 100 × RM3 182.70 = 0.03 × RM3 182.70 = RM95.48 Year Interest value First 3% × RM8 000 = 3 100 × RM8 000 = 3 × RM80 = RM240 Second 3% × RM8 240 = 3 100 × RM8 240 = 0.3 × RM824 = RM247.20 Third 3% × RM8 487.20 = 3 100 × RM8 487.20 = 0.03 × RM8 487.20 = RM254.62 (b) Intan received an education loan of RM21 000. The loan imposed an interest rate of 3% per annum. What is the value of interest that Intan needs to pay in 5 years? HOTS Applying Nilai faedah = RM21 000 × 3% × 5 = RM21 000 × 3 100 × 5 = RM210 × 3 × 9 = RM3 150 (c) Mr. Raj took out a personal loan of RM19 500 from a bank. The imposed interest rate is 6.88% per annum. Calculate the total amount of the loan that Mr. Raj needs to repay for 5 years. HOTS Applying Jumlah bayaran = (6.88% × RM19 500 × 5) + RM 19 500 = 1 6.88 100 × RM19 500 × 52 + RM19 500 = RM6 708 + RM19 500 = RM26 208
Mathematics Year 6 Unit 3 Money 55 © Penerbitan Pelangi Sdn. Bhd. Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 LS 3.1.2 Determine cost price, selling price, profit, loss, discount, rebate, interest, dividend and service tax. 5. Calculate each of the following. LS 3.1.2 PL 3 (a) The table below shows the amount of money invested by four investors in different companies. Calculate the value of dividend received by them. Name Amount of money Lim RM10 000 Fauzi RM12 000 Muthu RM15 000 Gabril RM20 000 (i) Lim Percentage of dividend received: 7% Nilai dividen = 7% × RM10 000 = 7 100 × RM10 000 = RM700 (ii) Fauzi Percentage of dividend received: 7.5% Nilai dividen = 7.5% × RM12 000 = 7.5 100 × RM12 000 = RM900 (iii) Muthu Percentage of dividend received: 8% Nilai dividen = 8% × RM15 000 = 8 100 × RM15 000 = RM1 200 (iv) Gabril Percentage of dividend received: 8.5% Nilai dividen = 8.5% × RM20 000 = 8.5 100 × RM20 000 = RM1 700 (b) Calculate the percentage of dividend given by a unit trust to the following investors. (i) Baihaqi Invested capital: RM10 000 Value of dividend: RM650 Peratus dividen = RM650 RM10 000 × 100% = 6.5% (ii) Liew Invested capital: RM18 000 Value of dividend: RM1 440 Peratus dividen = RM1 440 RM18 000 × 100% = 8%
Mathematics Year 6 Unit 3 Money © Penerbitan Pelangi Sdn. Bhd. 56 Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 LS 3.1.2 Determine cost price, selling price, profit, loss, discount, rebate, interest, dividend and service tax. 6. Fill in the blanks based on the given information. LS 3.1.2 PL 3 (i) Pak Hisham’s Restaurant No. 3 Receipt no.: A12 28/8/2021 2 Chicken rice 2 Fried rice 4 Syrup drink Total 6% service tax Total payment RM13 RM12 RM10 Service tax = 6% × RM35 = 6 100 × RM35 = RM2.10 Total payment = RM35 + RM2.10 = RM37.10 (ii) Mak Tipah’s Corner No. 4 Receipt no.: B008 29/8/2021 2 Briyani rice 4 Fried chicken 4 Watermelon juice Total 6% service tax Total payment RM24 RM18 RM18 Service tax = 6% × RM60 = 6 100 × RM60 = RM3.60 Total payment = RM60 + RM3.60 = RM63.60 RM13 + RM12 + RM10 = RM35 RM24 + RM18 + RM18 = RM60 RM35 RM2.10 RM37.10 RM60 RM3.60 RM63.60
Mathematics Year 6 Unit 3 Money 57 © Penerbitan Pelangi Sdn. Bhd. Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 PBD MODULE Insurance and takaful Textbook: 121 – 122 LS 3.2.1 Recognise insurance and takaful. LS 3.2.2 Explain purpose and importance of insurance and takaful protection. 3.2 7. Fill in the similarities and differences of insurance and takaful protection. LS 3.2.1 i-THINK Double Bubble Map Insurance Takaful Wajib patuh syariah Tidak perlu patuh syariah Risiko ditanggung syarikat insurans Jaminan perlindungan kepada pencarum Membayar pampasan kepada waris pencarum Risiko ditanggung peserta secara berkumpulan Premium Sumbangan 8. Explain the purposes and importance of insurance and takaful protection. LS 3.2.2 PL 2 (a) Melindungi aset dan harta pencarum akibat kemalangan seperti kebakaran. (b) Sebagai pampasan kepada waris pencarum akibat kematian. (c) Menanggung perbelanjaan perubatan akibat penyakit. (d) Menanggung ganti rugi dan kecederaan akibat kemalangan. i-THINK Map
Mathematics Year 6 Unit 3 Money © Penerbitan Pelangi Sdn. Bhd. 58 Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 PBD MODULE Problem solving Textbook: 123 – 132 LS 3.3.1 Solve daily problems involving cost price, selling price, profit, loss, discount, rebate, voucher, bill, receipt, invoice, asset, liability, interest, dividend and service tax, financial management and risks in daily situation. 3.3 9. Solve each of the following problems. LS 3.3.1 Application Daily (a) The diagram shows a motorcycle and the rebate given on the price of the motorcycle. Imran only paid RM3 290 to buy the motorcycle. What is the original price of the motorcycle? PL 4 (b) Mr. Muthu bought a car at a price of RM90 000. Ten years later, he sold the car for RM43 000. How much is the loss experienced by Mr. Muthu? PL 4 (c) The diagram below shows the selling price of a washing machine. Washing machine Selling price : RM4 500 Discount : 15% Puan Aisyah gets a discount of 15% when purchasing the washing machine. What is the price of the washing machine after the discount? PL 4 RM450
Mathematics Year 6 Unit 3 Money 59 © Penerbitan Pelangi Sdn. Bhd. Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 (d) The diagram below shows the selling price of two items in a bookstore. RM8 Rebate: RM1 RM80 RM64 (i) What is the percentage of discount offered for the dictionary? PL 5 (ii) Helmi has RM100. He bought a dictionary and a few pens. What is the maximum number of pens that can be bought by Helmi? PL 5 (e) The diagram on the side shows the original price of a pair of shoes. Suzana bought the shoes with a discount of 10%. Not long after, she sold the shoes to Alia and made a profit of 10% . Did Alia buy the shoes for RM300? Prove it. PL 6 RM300
Mathematics Year 6 Unit 3 Money © Penerbitan Pelangi Sdn. Bhd. 60 Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 LS 3.3.1 Solve daily problems involving cost price, selling price, profit, loss, discount, rebate, voucher, bill, receipt, invoice, asset, liability, interest, dividend and service tax, financial management and risks in daily situation. 10. Solve each of the following problems. LS 3.3.1 Mrs. Jenny plans to buy clothes for her daughter, Sasha, during a bargain sale at a shopping mall. Mathematics Comic I like both of them, mom. Sasha, which dress do you like? (a) Discounts of 30% and 20% are respectively given to the flowered and non-flowered dresses. Calculate the price of the flowered dress and the price of the non-flowered dress after the discount. PL 5 (b) Mrs. Jenny plans to buy both of the dresses that Sasha likes. What is the total price for both of the dresses? PL 4 Ju (c) Mrs. Jenny has a voucher worth RM30. Calculate the total price that Mrs. Jenny needs to pay for both of the dresses. PL 5 = Mathematics Comic
Mathematics Year 6 Unit 3 Money 61 © Penerbitan Pelangi Sdn. Bhd. Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 Booster Zone UASA Section B (a) The table below shows the assets and liabilities of Encik Daim. House RM285 600 Cash money RM8 000 Credit card debt RM1 200 Car loan RM110 000 Overdue bill RM1 450 Fixed deposits RM176 940 (i) Calculate the total assets of Encik Daim. (ii) How much is the total of liabilities of Encik Daim? (b) The diagram below shows three bills that need to be paid by Encik Daim. Phone bill RM167.90 Internet bill RM130.50 Electric bill RM249.85 Encik Daim makes the payment using 11 pieces of RM50 notes. How much is the balance of money he will receive? Booster Zone
Mathematics Year 6 Unit 3 Money © Penerbitan Pelangi Sdn. Bhd. 62 Date: Teacher’s Signature: Date: PERFORMANCE LEVEL () 1 2 3 4 5 6 (c) Encik Daim invested a certain amount of money in a mutual fund. The diagram below shows the value of the money invested by Encik Daim in the form of a check. Ceria Bank Paid to: Muhammad Daim bin Zainal Date: 2 Ringgit Malaysia: Five thousand only 7 0 8 2 1 RM5 000 Encik Daim will receive a dividend rate of 8.5% per annum from the investment. After exactly one year, Encik Daim received a dividend of RM452. Is the statement true? Prove it. (d) The table below shows the cost price and selling price of two electrical appliances in a supermarket. The selling price for the air conditioner is not shown. Item Cost price Selling price Television RM1 500 RM2 025 Air conditioner RM1 000 Encik Daim wants to buy an air conditioner. Given that the percentage of profit for selling the air conditioner is the same as the percentage of profit for selling the television. How much should Encik Daim pay for the air conditioner? Booster Zone
Mathematics Year 6 Unit 3 Money 63 © Penerbitan Pelangi Sdn. Bhd. Date: 1. The diagram below shows a document after a payment transaction. Economy Supermarket Cooking oil RM15.20 Rice RM29.70 Milk RM11.60 Stinky bean RM18.40 Total RM74.90 Cash RM80.00 Balance RM5.10 Thank you. Please come again. Sunday 29-08-2021 12:34 p.m. What is the name of the document? [1 mark] 2. The diagram below shows the definition of a financial term. State the financial term based on the statement above. [1 mark] 3. The diagram below shows a financial term. State the financial term based on the statement above. [1 mark] 4. Given the cost price of a watch is RM1 200, find the selling price with a profit of 40%. [2 marks] SUMMATIVE PRACTICE 3 A Section
Mathematics Year 6 Unit 3 Money © Penerbitan Pelangi Sdn. Bhd. 64 © Penerbitan Pelangi Sdn. Bhd. 5. The diagram below shows a statement made by Ikram. I have saved RM6 000 in a bank and the bank has offered an interest rate of 5% per annum. Calculate the balance of money in Ikram’s account after 1 year. [2 marks] 6. The price of a television after a 20% discount is RM4 608. Calculate the original price of the television. [2 marks] 7. The diagram below shows the selling price of a storybook collection. Selling price : RM140 Rebate : RM15 STORY ANIMAL’S Nazirul has bought the storybook collection. Calculate the total amount he has paid after the rebate is given. [2 marks] 8. The diagram below shows the cost price of a set of comic books. RM60 KOMIC KOMIC COMIC Given the selling price of a set of the comic books is RM129. How much is the profit gained from the sale of a set of the comic books? [2 marks] 9. The diagram below shows information about an electric bicycle. Selling price : RM7 900 Discount : 15% Helmy has RM6 700. State Helmy’s situation if he wants to buy the bicycle. [3 marks]
Mathematics Year 6 Unit 3 Money 65 © Penerbitan Pelangi Sdn. Bhd. B Section 1. (a) The diagram below shows the prices of two models of smartphones. Model P RM2 690 15% discount Model Q RM2 400 RM100 rebate Mr. Vincent wants to buy a cheaper smartphone. Which model of smartphone should he buy? Show your calculation steps. [3 marks] (b) Mr. Vincent paid a total of RM2 300 in cash to buy the smartphone in (a). (i) Will Mr. Vincent receive any balance? If yes, calculate the amount of the balance. (ii) Mr. Vincent will receive a document as proof of payment from the store. What is the name of the document? [3 marks]
Mathematics Year 6 Unit 3 Money © Penerbitan Pelangi Sdn. Bhd. 66 Date: (c) An insurance company is offering insurance to Mr. Vincent. The insurance representative explains the purposes and importance of insurance and takaful protection. State three of those purposes and importance. [3 marks] (d) The diagram below shows Mr. Vincent’s assets and liabilities. Does Mr. Vincent manage his finances well and wisely? State your reason. [3 marks] Gamified Quiz 3
Mathematics Year 6 Unit 3 Money 67 © Penerbitan Pelangi Sdn. Bhd. Date: Gallery Walk Preparation phase: 1. Teacher prepares 8 questions and places them at eight stations. 2. Examples of questions are as follows: Example: 1. Selling price : RM620.10 Cost price : RM455.90 Profit = 2. Savings : RM1 200 Interest rate : 4% Interest value = 3. Expense : RM170 Service tax : 6% Total payment = 4. Selling price : RM380 Loss : RM150 Cost price = 5. Asset : RM120 500 Liability : RM37 860 Net property = 6. Total : RM409 Rebate : RM15 Total payment = 7. Cost price : RM580 Profit : 20% Selling price = 8. Investment : RM20 000 Dividend rate : 7.5% Dividend value = Instructions: 1. All pupils are given a sheet of A4 paper which is divided into eight sections. 2. Each pupil takes turns to move to the eight stations. 3. Pupils rewrite the questions at each station onto the A4 paper. 4. Pupil who solves all the questions the fastest with correct answers is the winner. 3 UNIT Money PAK–21 Activity PAK-21 ACTIVITY
Mathematics Year 6 Ujian Akhir Sesi Akademik (UASA) © Penerbitan Pelangi Sdn. Bhd. 140 SECTION A [26 marks] Answer all questions. 1. The diagram shows a number card. (a) Convert the number to a whole number. (b) Write the number of the answer in 1(a) in words. [2 marks] 2. 4.7 million + 600 000 = State the answer in decimal of a million. [2 marks] 3. 4 1 3 ÷ 5 6 = [2 marks] 4. 1.2 × 7.38 = [2 marks] 5. 600% − 72% − 240% = [2 marks] 6. Daim would like to deposit RM30 000 into his son’s account for his education in the future. The interest rate for the savings is 2% per annum. Calculate the interest received after saving for one year. [3 marks] Ujian Akhir Sesi Akademik Score 50 (UASA)
Mathematics Year 6 Ujian Akhir Sesi Akademik (UASA) © Penerbitan Pelangi Sdn. Bhd. 142 11. The diagram shows a circle. m What is the name of line m? [1 mark] 12. The diagram shows the number of white cards and black cards. State the ratio of the number of black cards to the number of white cards. [1 mark] 13. The diagram shows the letter cards in a box owned by Zafriq. U B B B B U B B B U B B What is the likelihood of Zafriq picking a consonant letter card from the box? State your reason. [2 marks] SECTION B [24 marks] Answer all questions. 1. (a) The diagram shows the cost price and selling price for a short-sleeved jersey and a long-sleeved jersey. Jersey Cost price Selling price Short-sleeved RM12 RM30 Long-sleeved RM19 RM40 Which jersey sales will get a higher profit? Prove your answer. [3 marks]
Mathematics Year 6 Answers A1 © Penerbitan Pelangi Sdn. Bhd. 1 UNIT Whole Numbers and Operations 1. (a) 1 273 414 (b) 3 605 550 (c) 4 580 090 (d) 5 701 071 2. 3. (a) 3 534 219 (b) 5 610 012 (c) 9 400 800 4. (a) Two million six hundred forty-one thousand three hundred and eighty-five (b) Six million four hundred seven thousand and thirty-eight (c) Eight million one hundred thousand and ninety 5. (a) Ascending order by tens (b) Descending order by hundreds (c) Ascending order by hundred thousands (d) Descending order by millions 6. (a) Ascending order by ten thousands (b) P = 3 480 924 Q = 3 490 924 7. 8. (a) 0.72 million (b) 6.19 million (c) 7.368 million (d) 4.053 million 9. (a) Three over ten million (b) Zero point six nine million (c) 4 1 2 million (d) 5.087 million (e) One, seven over eight million (f) 2.901 million 10. (a) 0.4 million (b) 0.006 million (c) 0.072 million (d) 1.093 million (e) 5.05 million (f) 8.1 million 11. (a) 0.091 million; 91 000 (b) 2.003 million; 2 003 000 (c) 4.235 million; 4 235 000 (d) 9.2 million; 9 200 000 12. (a) 1 4 million (b) 2 5 million (c) 7 8 million (d) 1 1 10 million (e) 3 3 5 million (f) 4 1 2 million 13. (a) 200 000 (b) 300 000 (c) 625 000 (d) 1 750 000 (e) 9 500 000 (f) 3 800 000 14. (a) 0.08 million (b) 8 750 000 (c) 6.034 million (d) 750 000 (e) 7 4 5 million (f) 2 625 000 15. (a) 900 000 (b) 728 000 (c) 849 000 (d) 1 196 645 (e) 3 739 000 (f) 8 805 200 (g) 5 153 500 (h) 6 740 620 16. (a) 230 000 (b) 557 000 (c) 300 220 (d) 137 200 (e) 2 920 000 (f) 2 392 345 (g) 2 029 600 (h) 2 700 000 17. (a) 8 500 000 (b) 8 250 000 (c) 4 952 000 (d) 7 665 000 (e) 7 200 000 (f) 6 250 000 (g) 1 260 000 (h) 5 200 000 18. (a) 50 000 (b) 100 000 (c) 276 000 (d) 125 000 (e) 470 000 (f) 375 000 19. (a) 2 174 000 (b) 6 412 500 (c) 4 278 500 (d) 7 960 300 (e) 4 137 500 (f) 5 987 700 20. (a) 1 488 640 (b) 2 008 000 (c) 449 600 (d) 2 362 500 21. (a) 5 150 000 (b) 3 615 000 (c) 3 384 000 (d) 2 263 200 (e) 4 782 500 (f) 1 504 000 22. (a) 8 588 895 (b) 389 000 23. (a) 3 877 000 (b) 8 000 000 (c) 25 (d) 8 344 000 24. (a) ✓ (d) ✓ (e) ✓ 25. Orange: 11, 23, 61, 43, 59, 37 Blue: 57, 35, 49, 27, 69, 14 26. (a) 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28 (b) 44, 45, 46, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 60, 62, 63, 64, 65, 66 (c) 80, 81, 82, 84, 85, 86, 87, 88 27. (a) 670 000 boxes of chocolate milk (b) 1 400 520 tiles (c) 15 000 bookmarks (d) 600 000 cans of sardine (e) 0.225 million victims (f) 44 916 remainder 40 pillowcases ANSWERS
M DUL LENGKAP The M DUL LENGKAP series for Years 4, 5 and 6 is published specifically for Pentaksiran Bilik Darjah (PBD). Moreover, this series is formulated to fulfil the requirements of formative and summative assessments as outlined by the Malaysian Ministry of Education. The contents of this series are aligned with the Dokumen Standard Kurikulum dan Pentaksiran (DSKP) and textbook. All practices in this series are systematically arranged with extra features to assist pupils in mastering the lessons. Digital resources such as info, simulations and gamified quizzes are also included for a more effective learning experience. W.M: RM10.95 / E.M: RM11.65 PELANGI PelangiPublishing PelangiBooks PelangiBooks Subject / Year 4 5 6 Bahasa Melayu English Matematik Mathematics Sains Science Sejarah Pendidikan Islam Pelajaran Jawi Pendidikan Jasmani dan Pendidikan Kesihatan 4 5 6 MODUL LENGKAP PBD GENIUS PBD Year 6 KSSR Semakan Mathematics ISBN: 978-629-470-213-4 WRC496934