(b) Method 1: P Z > −μ σ = 0.1587; = 2, = 0.5 −2 0.5 = 0.9998 m = 2.4999 / 2.5 Command Screenshot Change ‘Menu’ as ‘Distribution’. Choose ‘Inverse Normal’. w73 Enter the value. 0.8413=1 =0== = 201
(b) Method 2: P Z > −μ σ = 0.1587; = 2, = 0.5 Answer: m = 2.5 Command Screenshot Change ‘Menu’ as ‘Distribution’. Choose ‘Inverse Normal’. w73 Enter the value. 0.8413=0 .5=2= Obtain the value of m. = 202
Let’s Try! Solve each of the following. The diameters of limes from a farm have a normal distribution with a mean of 3.2 cm and a standard deviation of 1.5 cm. Calculate (a) the probability that a lime is chosen at random from this farm has a diameter of more than 3.9 cm. (b) the value d if 33% of the limes have diameters less than d cm. Answer: (a) 0.3204 (b) d = 2.54 203
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