Maths Sem 1 Revision Book

Chapter 10

a x83 b t 62 c p  11 3
x5 t 8 p8

4x  7 5 3y  22  4 2t  130  5
a 4x  12 b 3y  18 c 2t  135

x3 y6 t  135
2

x  3  8*(2) y  4  5*(3) t2 7
2 * (2) 3 * (3) 5 * (5)
a x  3  16 b y  4  15 c t27

x  13 y  11 t9

2x  6  14 12x  8  32 20t  5  30
a 2x  20 b 12x  24 c 20t  35

x  10 x2 t7
4

3x 1 2x  5 6t  5  4t  3 2 y 11  y  5
a 5 1 2x  3x b  3  5  4t  6t c 5 11  y  2 y

x  6  2t  8 y6
t4

3x  2  2x  5 4w  5  2w  2 10x  2  2x  3
a 5  2  2x  3x
 2  5  2w  4w  3  2  2x 10x
x  7 b  2w  7 c  8x  5

w 7 x5
2 8

a x23 x5
b x35 x2
c 2x 14  38

2x  52  x  26

4x  6  15
d 4x  21  x  21

4
e 2x  3  25

2x  22  x  11

9  4x 1 4x 1  13 2 x3
a 19  4x 4x  12  x  3

4x  8
x2

2  3x 1 3x 1  11 1 x  4
b 1 2  3x 3x  12  x  4

x 1

3  4x 5 4x  5  21  2  x  4
c 53  4x 4x  16  x  4

4x  8  x  2

2  3x  4 10  2x  3 5  4x 7
4  2  3x  3 10  2x 7 5  4x
3x  6  x  2 2x  7  x  7 4x  2  x  1
a 3x  4  15
3x  19  x  19 2 2
b 2x  3  18 c 4x 7  8
3
 2  x  19 2x  15  x  15 4x  15  x  15
2 4
3
 7  x  15  1  x  15
22 24

3  5x  7 8  2x 3 7  5x  3
7  3  5x 38  2x 3 7  5x
d 5x  10  x  2 2x  5  x  5 5x  4  x  4
5x  7  13 e2
5x  20  x  4 2x  3  19 5
2 x4 2x  16  x  8 f 5x  3  24
 5 x8
5x  21  x  21
2 5

 4  x  21
55

a x59 x4 b x  4  2  x  2 c x23 x5
d x  5  2  x  3 f 5x  4  16
g 2x 1  13 4x 3  9
e 4x  6  x  3 5x  20  x  4
2x  14  x  7
2
h 3x  6  3

3x  3  x  1

Chapter 11

a 20 x 4 ÷ 1= 80 kg
b 20 x 1 ÷ 4= 5 kg

60 x 1 ÷ 2 = 30 female spectators
30 + 60 = 90 spectators

a 6:5 = 6  $2000  $2400
5

b 400 x100  20%
2000

a (I) 3  $900  $540 (ii) 3  280  $168
5 5

b 3 100  60%
5

a 7 x 0.05m2 =0.35m2
b 4.8 x1  96 days

0.05

a Car A ; Car B ;
500 11.3  56.5 litres 500 13.4  67 litres
100 100

b Car A ; Car B ;
200 x100  1769.91km 200 100  1492.54 km
11.3 13.4

c Car A ; Car B ;
25000 11.3  2825 litres 25000 13.4  3350 litres
100 100

3350  2825  525 litres

a 6 flapjacks ; 2 tablespoons golden syrup 40g granulated sugar 100g rolled oats
50g margerine

b 24 flapjacks ; 8 tablespoons golden syrup 160g granulated sugar 400 rolled oats
200g margerine

c 30 flapjacks ;
250g margerine 10 tablespoons golden syrup 200g granulated syrup 500g rolled oats

Greg ; Dom ;
6 x $5= 30 packs $3.19 = 24 packs

Can buy from greg 6 packs more tham from Dom.

12  30  45 boxes
8

a 100  40  80 days
50

b 100 x40  16 days
250

c 100 x40  11days
350

BASIC INEQUALITY RULES The rules for solving inequal

o If A>B o If A>B WITH ONE
o Then A+/-C>B+/-C o Then A*/÷C>B*/÷C
✓ IFYOU DIVIDE BY A
▪ EXAMPLE ; ▪ EXAMPLE
▪ 8>7 so 8+2>7+2 ▪ 8>7 so 8*2>7*2 Ex:

o If A<B o If A<B
o Then A+/-C<B+/-C o Then A*/÷C<B*/÷C

▪ EXAMPLE ; ▪ EXAMPLE
▪ 5<7 so 5-2<7-2 ▪ 6<8 so 6÷2<8÷2

❑ Solution 1 ; ❑ EXAMPLES 1 ; ❑ EXAMPLE
4 − 6 ≥ −15 + 1 1. 2 < 3
o Original problem 4 − 6 ≥ −14
✓ Simplfy (-15+1=-14 4 − 4 − 6 ≥ −14 − 4 4+2
✓ Substract 4 from BOTH sides by -6.You MUST −−66 ≥−−168 3 > 6
3 − 4
REVERSE the SIGN sice you divided by a negative ≤ 3
number Check ; 2. 3 < 19
✓ Substitute a number less than or equal to 3. I choose
3. Both sides equal -14 so my answer is absolutely 4 − 6 ≥ −15 + 1 = 2 <
correct 4 − 6 3 ≥ −15 + 1
4 − 18 ≥ −14 Absolute
❑ Solution 2 ; −14 ≥ −14

o Original problem Absolutely correct
✓ Separate & simplify first & second
✓ Then change the sign and combine it

lities are the same as solving equations,

E EXCEPTION;

A NEGATIVE,THE INEQUALITY
FLIPS

−−44 >−124
F
L
I
P

< −

2;
− 4
< 3
6 = > 2
4 < 15

9 = < 19
3
19
< < 3

ely correct

RATIOS,RATES & PROPORTIONS

RATIO RATES PROPORT

o Comparison of two o A special ratio o A statement
quantities in the same comparing two are equal.
unit. quantities with different
units. o Given the pr
o The ratio of a to b can : = :
be written as a : b or o For example, a typing then by cross m
. speed of 35 words per
minute compares the ad =
o Given the ratios a : b number of words typed
and b:c, we can state with the time taken.
the ratio a : b : c.

❑ EXAMPLES a:b:c ❑ EXAMPLES equivalent ❑ Example Proportions ;
4km to 3km to 5 km ratios ;
= 4:3:5 o Fine the value of x,
4 : 7 12 : 21
❑ EXAMPLE Rate : 8: 5 = : 48
o Shankar was paid RM 32 4 :7=4 x3 :7 x3
= 12 : 21 48 × 8 = × 48
for 8 hours of work. 5 48
o Rate of payment ; ❑ Example a:b:c 5 = 30
8 3 2 = RM 4 per hour o Find the ratio a:b:c
= 6
: = 2: 3
: = 4: 5
4 × 2: 4 × 3: 5 × 3
: : = 8: 12: 15

RTIONS

t that two ratios

roportion
,
=

multiplication,

= b c.

MURDE
MAT

EROUS
THS

STRIVE FOR MATHEMATICS A+

ALL THINGS ARE
DIFFICULT

BEFORE THEY ARE

EASY

THE END