Science Portfolio 2018

Specific Heat Math Example 1

Metal #1

A. Heat Gained (Water) = mass of water * Change in Temperature *
Specific Heat of Water
Heat Gained (Water) = 100 g * (25 C - 22 C) * 1 cal/gC
Heat Gained (Water) = ​300 calories

*Now use the Heat gained to be your Heat Lost by the metal
Heat Gained = Heat Lost

B.​ Heat Lost (Metal) = mass * Change in Temperature of Metal *
Specific Heat of Metal

300 calories = 65 g * (75 C -25 C) * X
300 = 65 g * 50 C * X
300 = 3250 X
300/3250 = X

0.092 cal/gC = Specific Heat of Metal

 
 
 
 

Specific Heat Data Table

Mass Mass Δ Temp Δ Temp Heat Heat Lost Real Specific
Metal Water H20 Metal Gain
Object H20 Metal SH Metal Heat
Example 65 75-27 =
27-21 = 48 Use

100 6 600 600 notes

Copper - 28.4 100 24.3-22.5 86-24.3 180 180 0.103
S4

Aluminu 19.6 100 25.5-22 97.8-25.5
m - S4

Copper - 24.8-23. 76.8-24.8=
S7 52
28.6 100 1=1.7 170 170 0.11

Aluminiu 19.5 100 25.5-22= 77.9-25.5=
m - S7

Copper 28.4 100 25-22.5=2. 78.1-25=
S2 5

Aluminiu 19.6 100 26-24=2 78-26= 200 200 0.196 0.215
m-S2 100 26-23.5 250 250 0.256 0.215
75.8-2
Aluminiu 19.6 6
m -S3

Zinc -S3 29.3 100 25.1-23.7 75-25. 140 140 0.0958 0.093

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