The final speed was 67 m/s.
10. A car starting from rest accelerates at a rate of 8.0 m/s/s. What is its final speed at the end of 4.0
seconds?
V2 = V1 + (a*t)
V2 = 0 + (8*4)
V2 = 32
After four seconds, the car is traveling at 33 m/s.
11. After traveling for 6.0 seconds, a runner reaches a speed of 10 m/s. What is the runner’s
acceleration?
A= V 2−V 1
T
A= 10−0
6
A= 1.67
12. A cyclist accelerates at a rate of 7.0 m/s2. How long will it take the cyclist to reach a speed of 18
m/s?
T= V 2−V 1
A
T= 18−0
7
T = 2.57
It will take the cyclist 2.57 seconds to reach a speed of 18m/s.
13. A skateboarder traveling at 7.0 meters per second rolls to a stop at the top of a ramp in 3.0
seconds. What is the skateboarder’s acceleration?
A= V 2−V 1
T
A= 7m/sec−0m/sec
3sec
A= 2.33m/sec
Potential Energy Project:
Define and make note cards for the following words:
Energy - The strength Joules - The system of Chemical Potential Law of Conservation of
Energy - A form of Energy: Energy can not
required for continuous physical units of work potential energy that is be destroyed or created
released during
activity or energy chemical reactions
Kinetic Energy: Energy Kilojoules: measure of Elastic Potential Gravity: the force that
that a body possesses ow much energy people Energy: Potential attracts an object
by virtue of being in get from consuming a energy stored as a result toward the center of the
motion food or drink of deformation of an earth
elastic object
Potential Energy: the Gravitational Potential Mechanical Energy:
energy possessed by a Energy: Energy an Mechanical energy is
body by virtue of its object possesses the sum of kinetic and
position relative to because of its position potential energy in an
others, stresses within in a gravitational object that is used to do
itself, electric charge, its work.
and other factors
Resource: h ttp://www.physicsclassroom.com/class/energy/Lesson-1/Potential-Energy
Gravitational Potential Energy
Determine the Gravitational Potential Energy (GPE) of 3 different masses (g) at 3 different h eights.
3 objects: You, gallon of milk, television (research the masses)
* 2.2 lbs = 1 kg
Earth:
Object Mass Gravity Height GPE
Lindy 8.16 kg 9.8
500 m GPE = m(g)(h)
9.8 = 8.16(9.8)(500)
= 39984 joules
9.8
Television 15.69 kg 500 m GPE = m(g)(h)
= 15.69(9.8)(500)
= 76881 joules
Potato 0.18 kg 500 m GPE = m(g)(h)
= 0.18(9.8)(500)
= 882 joules
Object Mass Gravity Height GPE
Lindy 8.16 kg 9.8
10 m GPE = m(g)(h)
9.8 = 8.16(9.8)(10)
= 799.68 joules
9.8
Television 15.69 kg 10 m GPE = m(g)(h)
= 15.69(9.8)(10)
= 1537.62 joules
Potato 0.18 kg 10 m GPE = m(g)(h)
= 0.18(9.8)(10)
= 17.64 joules
Object Mass Gravity Height GPE
Lindy 8.16 kg 9.8
20 m GPE = m(g)(h)
9.8 = 8.16(9.8)(20)
= 1599.36 joules
9.8
Television 15.69 kg 20 m GPE = m(g)(h)
= 15.69(9.8)(20)
= 3075.24 joules
Potato 0.18 kg 20 m GPE = m(g)(h)
= 0.18(9.8)(20)
= 35.28 joules
Data Table:
Your data table will need: Object, mass, gravity, height, GPE
Videos: h ttp://www.youtube.com/watch?v=x5JeLiSBqQY
*Video shows you how to use the GPE equation.
Determine the GPE of one of the masses on the following planets:
“Kotulskian” - 17% greater than Earth’s Gravity
Gravity: 9.8(1.17)
Gravity: 11.47
“Danuzzitopia” - 39% less than Earth’s Gravity
Gravity: 9.8(1.39)
Gravity: 5.98
“Carlucciville” - 82% greater than Earth’s Gravity
Gravity: 9.8(1.82)
Gravity: 17.84
“Cheshire” - 63% less than Earth’s Gravity
Gravity: 9.8(1.63)
Gravity: 3.63
Calculations:
Change the names below
A. Planet Kotulskian:
Potato Mass Gravity Height GPE
B. Planet Danuzzitopia: 11.47 20 m
0.18 kg GPE = m(g)(h)
Potato = 0.18(11.47)(20)
C. Planet Carlucciville: = 49.29 joules
Potato Mass Gravity Height GPE
5.98 20 m
0.18 kg GPE = m(g)(h)
= 0.18(5.98)(20)
= 21.53 joules
Mass Gravity Height GPE
17.84 20 m
0.18 kg GPE = m(g)(h)
= 0.18(17.84)(20)
= 64.22 joules
D. Planet Cheshire: Mass Gravity Height GPE
Potato 3.63 20 m
0.18 kg GPE = m(g)(h)
= 0.18(3.63)(20)
= 13.1 joules
Data Table:
Earth Gravity Object Mass Height GPE
9.8 Potato 0.18 kg 20 m
GPE = m(g)(h)
Kotulskian 11.47 Potato 0.18 kg 20 m = 0.18(9.8)(20)
Potato 0.18 kg 20 m = 35.28 joules
Danuzzitopia 5.98 Potato 0.18 kg 20 m
Potato 0.18 kg 20 m GPE = m(g)(h)
Carlucciville 17.84 = 0.18(11.47)(20)
= 49.29 joules
Cheshire 3.63
GPE = m(g)(h)
= 0.18(5.98)(20)
= 21.53 joules
GPE = m(g)(h)
= 0.18(17.84)(20)
= 64.22 joules
GPE = m(g)(h)
= 0.18(3.63)(20)
= 13.1 joules
Graph:
Critical Thinking Questions:
1. What factors affect Gravitational Potential Energy?
a. The mass of the object, gravity of the planet, and height from which you drop it affects
the Gravitational Potential Energy.
2. Why did the GPE change on the other planets?
a. Since, on the other planets, the gravity was different, the Gravitational Potential Energy
changed. Based on whether the gravity on the other planets was lower or higher, the GPE
corresponded.
3. Which planet would you be able to hit a golf ball further? Explain using data.
a. I’d be able to hit a golf ball the farthest on Planet Cheshire, since it would require the
least energy to hit it. On Planet Cheshire, the GPE is only 13.1 joules, while on the other
planets it’s considerably higher.
4. How does GPE relate to Chemical Potential Energy?
a. Both GPE and CPE are forms of potential energy, which means they have the ability to
generate energy, if you have a way to collect and harness it.
5. How do Energy companies use GPE to generate Electrical Energy? Give an example
a. Some energy companies use hydraulics to harness the power of GPE. When the water is
falling down, it generates GPE, however, when it hits the bottom, the GPE turns into
kinetic energy. The water can be directed to a generator that can harness the kinetic
energy and turn it into usable energy.
6. What happens to the GPE when the object falls to the ground? Describe the Energy
transformations along the way. Use a diagram.
a. As an object falls, the height from the ground decreases, which causes the Gravitational
Potential Energy to decrease. The height from which the object is dropped plays a large
part in the formula to find the GPE, so it makes sense that the closer the aforementioned
object gets to the ground, the less GPE it will have.
Kinetic Energy Project:
Kinetic Energy Project
Objective: 7.1.b. Energy can be stored in many forms and can be transformed
into the energy of motion.
Problem Statement:
1. Design an experiment to test how changing the angle of a ramp affects Kinetic Energy
2. What is the velocity of a roller coaster at the bottom of the hill?
Hypothesis:
If all three angles are tested, then the largest angle will produce the most kinetic energy at the bottom of
the hill.
If we find the actual velocity, it will be higher than the average velocity.
Independent Variable:
Angle of the ramp
Dependent Variable:
Kinetic energy
*Use the following angles: 8, 18, 28
Example: Suppose you want to make a ramp with a 23 degree angle. Look up 23 degrees on
the Angle Chart and find the sine (decimal).
Sin 23 = 0.39
Substitute Sin 23 with 0.39
0.39 = opposite
hypotenuse
0.39 = opposite (height of ramp)
180 cm
solve for opposite (height of ramp)
Degree Height of Ramp GPE = KE
8 degrees GPE = KE
mgh = 0.5(m)(v2 )
(0.035kg)(9.8m/s)(0.17m) = 0.5(0.17(v2)
0.058 joules = 0.5(0.17)(v2 )
0.058 joules = 0.085(v2 )
0.68 joules = v2
Sin 8 = 0.13917 0.82 = v
D
0.13917 = opposite V= T1.2
120 cm V= 1.85
0.13917(120) = 16.7 cm
V = 0.65
18 degrees GPE=m*g*h
Sin 18 = 0.30902 GPE=.035*9.8*.37
opposite
0.30902 = 120 cm GPE= .1269
0.30902(120) = 37 cm .1269=KE
.1269=.5*m*v2
.1269=.5*.035
.1269=.0175*v2
7.25 = v2
2.69 = v
V = D/T
V = 1.2/.96
V = 1.25
28 degrees. GPE=m*g*h
Sin 28 = 0.46947 GPE=.035kg*9.8m/s2*.44m
GPE=.15 joules
GPE=KE
.15 joules=.5*m*v2
.15 joules=.5*.035 kg*v2
.15 joules= .0175*v2
8.57 m/s = v2
2.93 = V
0.46947 = opposite
120 cm
0.46947(120) = 56 cm Average Velocity = D/T
Average Velocity = 1.2/.44
*Actually 47 cm as the pole was not tall Average Velocity = 2.7
enough to have 56 cm
*A ngle Chart
*Include diagrams of the 3 Angles
*Include math examples for determining the angles and KE.
Video Resources:
1. How to solve KE problems: https://www.youtube.com/watch?v=tryiwu4RhSM
2. PE/KE: https://www.youtube.com/watch?v=Je8nT93dxGg
3. PE/KE: https://www.youtube.com/watch?v=BSWl_Zj-CZs
4. PE/KE: h ttps://www.youtube.com/watch?v=7K4V0NvUxRg
Data Analysis - W rite your data analysis paragraph here
To conclude, the average velocity was continuously smaller than the actual
velocity at the end of the ramp. This was because, the average velocity took the
velocity from every point on the ramp and averaged it out, making it less
accurate than the actual velocity. Whereas, with the actual velocity, it didn’t
average anything out, and instead took the velocity when the ramp ended, which
is when the full kinetic energy could actually be found. To prove this, in our first
trial with the ramp at 8 degrees the actual velocity at the bottom of the ramp was
.82m/s. However, the average velocity(taking in time from the top of the ramp
when the car was slower) was .65m/s. That is a .17 difference in the speed due to
averaging the velocities at every point on the ramp, including the top when the
car was slower since the car was just starting. Plus, when doing the same test at
28 degrees and there was a .23 difference, with the ending velocity higher. The
ending velocity was 2.93m/s whereas the average velocity was 2.7m/s.
In order to find the ending velocity for 28 degrees, we found the GPE
first(.15 joules) then used the equation GPE=KE to solve for v. V2=8.57m/s so
when we square rooted it we ended up with 2.93m/s. When we were finding the
average velocity we used the equation D/T or in other words distance divided by
time. The D=1.2m and the T=.44 seconds leaving us with 2.7m/s. Therefore, this
shows how the two different velocities compare and how we went about to find
them.
Data Analysis Rubric (Self Evaluate) 3 4
Lab Rubric - Data Analysis Sections
12
Data/ ____Data is poorly ____Data is ____Data is _4__Data is clearly
Observation organized or missing represented in a represented in the and accurately
s altogether. table or graph, but it table or graph with represented in a
No mention of is incomplete or minor errors. More table or graph.
observations there are major complete discussion Observations
errors. Some of observations. include discussion
discussion of of both qualitative
observations and quantitative
observations.
Conclusion/ ____No conclusion is ____Somewhat ____Adequately __4__Clearly
Analysis written in this report or it explains whether or explains whether or explains whether or
is very brief. No data is not the hypothesis not the hypothesis not the hypothesis
cited. was supported. was supported. Data was supported. Data
____No analysis is ____ Possible is cited to support was cited to support
included or it is extremely sources of error are hypothesis. the hypothesis.
brief no sources of error somewhat ____Possible _4___Possible
are explained. explained. sources of error are sources of error are
____No discussion of ____ No discussion adequately clearly explained.
patterns or trends in the of patterns or trends explained.
data __3__Some ____Trends and
discussion of Patterns in the data
patterns or trend in are clearly
the data discussed.
Article: E veryday Energy
Read the article and answer the questions.
1. A
2. B
3. D
4. C
5. D
6. A
7. C
8. The Hoover Dam harnesses the power of a massive river, channeling the huge masses of water
into turbines, the kinetic energy of the water flowing through the makeshift waterfall within the
dam produces kinetic energy, which causes the turbines to spin. The spinning of the turbines
provides a way of harnessing this kinetic energy, which is then channeled into a generator and
turned into energy.
9. The amount of water housed in the dam, and the gravity determine how much energy will be
produced.
10. Since the amount of energy plays such a large role in how much energy can be produced by the
Hoover Dam, the fact that they have recently been experiencing droughts in that area would
greatly affect their ability to produce water. The energy is produced by the kinetic energy the
water forms when it’s coursing down through the dam, so, logically, if there was less water, less
water could be produced.
FINAL PART - Roller Coaster Physics
Objective:
1. When energy is transformed, the total amount of energy stays constant (is conserved).
2. Work is done to lift an object, giving it gravitational potential energy (weight x height). The gravitational
potential energy of an object moving down a hill is transformed into kinetic energy as it moves, reaching
maximum kinetic energy at the bottom of the hill.
Determine the velocity of a full roller coaster of riders at the bottom of the largest hill. You can use the
following roller coasters:
Watch these Videos for help:
http://www.youtube.com/watch?v=Je8nT93dxGg
http://www.youtube.com/watch?v=iYEWIuQBVyg
Use either:
GPEtop = KEb ottom
1. Cyclone - Coney Island
Height of largest hill - 2 6m
Mass of Coaster/number of riders - 735 kg (12 people)
Velocity at Bottom of Hill in m/s:
GPE = KE
Mgh = 0.5(m)(v2 )
755kg(9.8m/s)(26m) = 0.5(735)(v2 )
192374 = 367.5(v2)
192374.0 = v2
367.5
√523.5 = √v2
22.9 m/s = v
2. Pick your own coaster: The Voyage
Height of largest hill - 49.68 meters
Mass of Coaster/number of riders: 1470 kg (24 people)
Velocity at Bottom of Hill in m/s -
GPE = KE
mgh = 0.5(m)(v2)
1470kg(9.8m/s)(49.58m) = 0.5(1470kg)(v2 )
714249.48 = 735(v2)
714249.48 = v2
735
971.8 = v2
√971.8 = √v2
31.17 = v
*Write about your results in a paragraph.
I found that if you were to look for the velocity of two rollercoasters full of riders,
(averaging a human at 100 kg), and the first rollercoaster having six cars while the second
rollercoaster has twelve, you would find that the rollercoaster with the higher mass has a larger
velocity at the bottom of the hill (22.9 m/s vs. 31.17 m/s). Due to the higher mass of the second roller
coaster, the gravitational pull on it is stronger, not to mention the fact that the people and train of
the roller coaster is dropped from a larger height. Since the train is dropped from a larger height, it
has more time to gain speed, making the velocity stronger. So, the combination of a larger height
and a larger mass created a rather large difference in velocity.
Inclined Plane Project:
1. Define the following vocabulary: Use pgs. 124 - 153
Simple Machine- Any Mechanical Advantage- Work- t he transfer of Input Force- T he force
of the basic the ratio of the force energy that occurs that is applied to the
mechanical devices for produced by a when a force makes machine
applying force such as machine to the force an object move
an inclined plane, applied to it, used to
wedge, or lever find the performance
of the machine
Compound Machine- A Ideal Mechanical Power- the amount of Output Distance-
machine consisting of Advantage- a measure work done in one number of times that
two or more simple of the force second. It is a rate at a machine increases
machines that operate amplification achieved which work is done an input force
together by using a machine. It
is the desired
amplification in the
output force
Efficiency- a measure Actual Mechanical Input Distance- Output Force- T he
of how much of the Advantage- t he force
work put into a that a machine can distance the force acts force applied by the
machine is changed multiply while
into useful output subtracting losses through machine
work by the machine from the machine
having to overcome
friction
First Class Lever- the Second Class Lever- Third Class Lever- t he Energy- p ower derived
fulcrum is located in the person on the input force is between from the utilization of
the middle and force other end is the load, the output force and physical or chemical
is applied to one side. and the point at which the fulcrum. resources
Ie: seesaw, crowbar the plank pivots is the Ie:baseball bat,
fulcrum. Ie: human forearm
wheelbarrow
Block and Tackle Fixed Pulley- c hanges Movable Pulley- a
Pulley- a system of two the direction of the pulley that is attached
or more pulleys with a force on a rope or belt to a ceiling or other
rope or cable that moves along its object by two lengths
threaded between circumference of the same rope that
them, normally used is free to move up and
for heavy loads down
2. Experiment: How does the angle of an inclined plane affect:
A. Ideal Mechanical Advantage
B. Actual Mechanical Advantage
C. Efficiency
*Think about the scientific Method
DATA TABLE
***Why is the Actual Mechanical Advantage always less than the Ideal Mechanical
Output Output Input Input Dist. Input IMA AMA Efficiency
Trial Force Output Dist. Work Force 1.2 meters Work
#1 10 N 0.51 meters 5.1 Joules 6N .935 meters 7.2 Joules 2.35 1.67 E = 70.8%
#2 10 N 0.51 meters 5.1 Joules 8 N .64 meters 7.48 1.83 1.25 E = 53%
Joules
#3 10 N 0.51 meters 5.1 Joules 9 N 5.76 3.68 1.03 E = 88%
Joules
Conclusion:
*Write your OWN CONCLUSION HERE!
In the end, the evidence shows that the larger the angle of the inclined plane, the larger the
amount of force required to lift the object up it will be. If you were to look at the data, The IMA increases
from our first trial (the smallest angle) to our final trial (the largest angle). The trial in the middle appears
to have botched data, so we can only assume that that was an error on our part. The AMA is connected to
the IMA, the AMA is simply the mechanical advantage of the inclined plane while calculating for
variable such as friction. Since the AMA calculates for friction, it’s always going to be smaller than the
IMA, especially since you have to move the object over a longer distance than you do with the IMA.
Anyway, when you look at the AMA, it decreases from the first trial to the final trial, except, again, for
the middle trial. Finally, we have the efficiency. Logically, it should increase from the first trial to the last
trial, and the data shows it does. Looking at the numbers, the first trial had an efficiency of 70.8%,
whereas the final trial had an efficiency of 88%. Overall, the greater the angle, the greater the ideal
mechanical advantage, the less the actual mechanical advantage and the greater the efficiency.
3. Critical Thinking (Include in Presentation):
A. How much WORK would be done to lift a 350 kg Piano to the top of the Empire State Building using
a ramp with an angle of 35 degrees?
350kg*9.8m/s2=3430
2.5=3430 N/x
8575 N = x
Win= Di n* Forcein
Win=834 ft(8575 N)
Win=7,151,550J
1. What is the length of the ramp to the top of the Empire State Building?
35 degrees = 0.57358
Hyp = Opp/0.57358
Hyp = 443m/0.57358
Hyp = 772.34 meters
2. Suppose the Ideal Mechanical Advantage is 3.2
3. The Actual Mechanical Advantage (AMA) is 2.5.
4. What is the Efficiency of this Machine?
Worko ut = Do ut* Fout
Workout = 1454 ft(3430 N)
Workout = 4,987,220 J
E = Workout/ Worki n
E = 4,987,220/7,151,550
E = .697*100
E = 69.7%
5. Provide a diagram of this example.
4. Explain how the Ideal Mechanical Advantage and Actual Mechanical Advantage is determined
for the following simple machines:
A. Inclined Plane
a. IMA= Din/Do ut
i. To find the IMA of an inclined plane, you must find the Distance input and the Distance
output first. Then, you do Distance input divided by the Distance output.
b. AMA= Fo ut/Fin
i. To find the AMA of an inclined plane, you must find the Force output and Force input
first. Next, you divide the Force output by the Force input.
B. Lever
a. IMA = length of ef f ort arm
length of the resistance arm
i. The effort end of the lever is the lever is the side of the lever that effort is applied to,
while the resistance arm is the side of the lever which holds the load.
b. AMA = resistance f orce
ef f ort f orce
i. First you must find the resistance force and then divide it by the effort force.
C. Pulleys
a. In order to find the IMA and AMA for a pulley you have to count the amount of ropes you have
required to lift the object.
D. Wheel and Axle
a. IMA= radius of the wheel
radius of the axle
i. To find the IMA of a wheel and axis, you must divide the radius of the wheel by the
radius of the axle.
b. AMA= Resistance f orce
Actual Ef f ort f orce
i. To find the AMA of a wheel and axis, you must do the resistance force divided by the
actual effort force.
5. Complete the Following Worksheet:
Worksheet 2
Effort Force = Input Force
Resistance Force = Output Force
6. Group: Video 1 Trial of the Lab that demonstrates the experiment and the
calculations
* Attach link to video here
https://drive.google.com/file/d/0B2c0D-tJa6iZV1pWRTgwVzRLUEE/view
https://drive.google.com/drive/shared-with-me
Resources to Help:
Inclined Plane Quiz:
Directions: Analyze the Inclined Plane Data Table that is shared on Classroom and
determine which machine has the greatest Actual Mechanical Advantage (AMA).
Problem Statement:
How does the angle of an inclined plane affect the Mechanical Advantage?
Hypothesis: ( Use proper form!)
If you increase the angle of an inclined plane, then the Mechanical Advantage will decrease.
Diagrams of Inclined Planes: (Label Diagrams)
Angle Chart: h ttps://drive.google.com/open?id=0B4RmhXJlHvo1YXZhcDNMSDNSMXc
Angle: opp Work:
hyp Wo ut = Fo ut * Dout
Ang = Wo ut = 7N*30m
Wo ut = 210 Joules
Ang = 30
150 Wi n = Fi n * Din
Ang = 11.50 Win = 2N * 150m
Wi n = 300 Joules
Angle: opp Work:
hyp Wout = Fo ut * Dout
Ang = Wo ut = 7N * 30m
Wo ut = 210 Joules
Ang = 30
90 Wi n = Fi n * Di n
Ang = 19.50 Win = 3N * 90m
Win = 270 Joules
Angle: opp
hyp Work:
Ang = Wo ut = Fo ut * Dout
Wo ut = 7N * 30m
Ang = 30 Wout = 210 Joules
50
Ang = 0.6 Win = Fi n * Din
Wi n = 4N * 50m
Ang = 370 Win = 200 Joules
Calculations ( Examples):
IMA: AMA: Efficiency:
Din F out W out
IMA = Do1u5t0m AMA = 7FNin E= 2W10inJ * 100
IMA = AMA = 2N E= 300J * 100
30m
IMA = 5 AMA = 3.5 E = 0.7 * 100
E = 70%
IMA: Din AMA: F out Efficiency:
D90omut 7FNin W out
IMA = 30m AMA = 3N E= 2W10inJ * 100
IMA = AMA = E= 270 J * 100
IMA = 3 AMA = 2.3 E = 0.78 * 100
E = 78%
IMA; AMA: Efficiency:
Din F out W out
IMA = Dout AMA = F in E= W in * 100
IMA = 50m AMA = 7N E= 210J * 100
30m 4N 200J
IMA = 1.7 AMA = 1.75 E = 1.05 * 100
E = 105%
Graph: (Angle and Mechanical Advantage)
Conclusion:
Option #1 Write a Conclusion.
***Your conclusion must also address which machine would be impossible and
why?
The third machine would be impossible, as it has an efficiency of 105%, and it’s
impossible to have a machine with an efficiency of over 100%. Another issue is
the fact that the AMA is larger than the IMA, another impossible scenario.
Option #2 Building
Compare 2 famous buildings based on the following Inclined Plane Data.
A builder wanted to get a 6 0 kg bag of concrete to the top of the 2 buildings.
Eiffel Tower: 300 meters
Leaning Tower of Pisa: 56.6 meters
1. What would the length of the ramp be if the machine has:
Eiffel Tower:
IMA = Din
Dout
300m * 5.9 = x * 300m
300m
1,770 meters = x
Leaning Tower of Pisa:
IMA = Din
Dout
56.6m * 5.9 = x * 56.6m
56.6m
333.94 meters = x
IMA - 5.9
AMA - 3.7
2. What are the angles of the ramps?
Eiffel Tower:
Angle = opp
hyp
Angle = 300m
1770m
Angle = 0.1694
Angle = 9.50
Leaning Tower of Pisa:
Angle = opp
hyp
Angle = 56.6m
333.94m
Angle = 0.1694
Angle = 9.50
3. Using Work Input and Output, what is the efficiency of the machines?
Eiffel Tower:
Wo ut = Fout * Do ut
Wo ut = (9.8m/s2 * 60kg)(300m)
Wout = 588N * 300m
Wout = 176,400 Joules
3.7 = F out
F in
588N
x * 3.7 = x *x
3.7x/3.7 = 588N/3.7
X = 158.91N
Win = Fi n * Di n
Wi n = 158.91N * 1,770m
Wi n = 281270.7 Joules
Leaning Tower of Pisa:
Wo ut = Fout * Dout
Wout = (9.8m/s2 * 60kg)(56.6m)
Wo ut = 33280.8 Joules
3.7 = F out
F in
588N
x * 3.7 = x *x
3.7x/3.7 = 588N/3.7
X = 158.91N
Wi n = Fin * Di n
Wi n = 158.91N * 333.94m
Wi n = 53066.40 Joules
Efficiency:
E= W out * 100
W in
33280.8J
E= 53066.4J * 100
E = 0.63 * 100
E = 63%
Chemistry of a Star Presentation:
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