CONFIDENTIAL* Module ‘A’cceleration STPM Johor Bahru S3 2022/2023 SULIT* Goh San San, Nur Fathin Suhana bt Ayob, Wong Minh Chjiat Isabelle, Chew Chin Kuen, Mohamad Rashidi bin Anang & Noreza bt Salleh Hudin Q6 - 15 Hydrocarbon (a)
CONFIDENTIAL* Module ‘A’cceleration STPM Johor Bahru S3 2022/2023 SULIT* Goh San San, Nur Fathin Suhana bt Ayob, Wong Minh Chjiat Isabelle, Chew Chin Kuen, Mohamad Rashidi bin Anang & Noreza bt Salleh Hudin (b) - Benzene insoluble in water - Phenol moderately soluble in water at room temperature; due to its hydroxyl group which can form hydrogen bond in water - Phenol can form hydrogen bond with water molecules, but benzene cannot Total 15
CONFIDENTIAL* Module ‘A’cceleration STPM Johor Bahru S3 2022/2023 SULIT* Goh San San, Nur Fathin Suhana bt Ayob, Wong Minh Chjiat Isabelle, Chew Chin Kuen, Mohamad Rashidi bin Anang & Noreza bt Salleh Hudin Q7 - 17 Hydroxyl Compound (a) - S is more acidic than methanol - S is more acidic phenolic group compare to the hydroxyl group in methanol - S has two acidic OH groups compare to only one in methanol - S produces more H+ ions in solution (b) - Reagent: Bromine water - Observation: compound S – white precipitate Methanol – no precipitate OR - Reagent: aqueous iron (III) chloride - Observation: blue/purple solution (c) No balanced equations are required; structures of reactant and products as well the reagent and condition must be shown Or can be written in balanced equation:
CONFIDENTIAL* Module ‘A’cceleration STPM Johor Bahru S3 2022/2023 SULIT* Goh San San, Nur Fathin Suhana bt Ayob, Wong Minh Chjiat Isabelle, Chew Chin Kuen, Mohamad Rashidi bin Anang & Noreza bt Salleh Hudin Total 15
CONFIDENTIAL* Module ‘A’cceleration STPM Johor Bahru S3 2022/2023 SULIT* Goh San San, Nur Fathin Suhana bt Ayob, Wong Minh Chjiat Isabelle, Chew Chin Kuen, Mohamad Rashidi bin Anang & Noreza bt Salleh Hudin Q 8 - 19 Carboxylic Acids and their Derivatives (a) Structures of A is 1 B is 1 C is 1 D is 1 E is 1 F is 1 (b) 1 1 2 1 1 1 (c) - B is more reactive - the electron withdrawing effect at the C=O group causes the carbonyl atom to be more partially positive. 1 1 Total 15
CONFIDENTIAL* Module ‘A’cceleration STPM Johor Bahru S3 2022/2023 SULIT* Goh San San, Nur Fathin Suhana bt Ayob, Wong Minh Chjiat Isabelle, Chew Chin Kuen, Mohamad Rashidi bin Anang & Noreza bt Salleh Hudin Q9 - 16 Haloalkanes (a) - unimolecular nucleophilic substitution mechanism (SN1) - the haloalkane is a tertiary haloalkane - structure 2-methyl-2-iodopropane 1 1 1 - SN1 mechanism 2 (b) (i) repeating unit 1 Monomers are 1.4-benzenedimine and 1.4-benzenedicarboxylic acid 1 1 (ii) 3 3 1 Total 15
CONFIDENTIAL* Module ‘A’cceleration STPM Johor Bahru S3 2022/2023 SULIT* Goh San San, Nur Fathin Suhana bt Ayob, Wong Minh Chjiat Isabelle, Chew Chin Kuen, Mohamad Rashidi bin Anang & Noreza bt Salleh Hudin Q10 - 18 Carbonyl Compounds (a) (b) (i) Structure of glucose Reducing agent Product 1 1 1 (ii) Disaccharide means two monosaccharides joined together via glycoside link 1 (iii) - two glucose react via condensation reaction - and form water as side product 1 1 1+1 Total 15
CONFIDENTIAL* Module ‘A’cceleration STPM Johor Bahru S3 2022/2023 SULIT* Goh San San, Nur Fathin Suhana bt Ayob, Wong Minh Chjiat Isabelle, Chew Chin Kuen, Mohamad Rashidi bin Anang & Noreza bt Salleh Hudin Q 11 - 14 Introduction to Organic Chemistry (a) Mol of C and H is 7.14 and 14.3 Empirical formula: CH2 1 1 (b) - NaOH is used to absorb CO2; CaCl2 absorbed H2O - mol of H2O = 1.08 / [16.0 + 2(1.0)] = 0.06 mol - mol of CO2 = 2.64 / [12.0 + 2(16.0)] = 0.06 mol based on CxHy + m O2 → x CO2 + y/2 H2O - 0.02 CxHy = 0.06 CO2; therefore, x = 3 - 0.02 CxHy = 0.06 H2O; therefore, y/2 = 3; y = 6 - Molecular formula: C3H6 1 1 1 1 1 (c) - A: CH3CH=CH2 B: ∆ (cyclopropane) - propene will react with bromine via electrophilic additional reaction - CH3CH=CH2 + Br2 → CH3CHBrCH2Br - cyclopropane react with bromine via free radical substitution reaction. - - propene can oxidised by cold dilute MnO4 - /OHsince it has unsaturated carbon / C=C CH3CH=CH2 + MnO4 - /OH- → CH3CH(OH)CH2(OH) 2 1 1 1 1 1 1 Total 15
CONFIDENTIAL* Module ‘A’cceleration STPM Johor Bahru S3 2022/2023 SULIT* Goh San San, Nur Fathin Suhana bt Ayob, Wong Minh Chjiat Isabelle, Chew Chin Kuen, Mohamad Rashidi bin Anang & Noreza bt Salleh Hudin Q12 - 14 Introduction to Organic Chemistry (a) - Isomers of C4H9Cl (All 4= 3 m ; 3 = 2m ; 2 = 1m and 1 to 0 no mark 3 - J is CH3CH2CHClCH3 - CH3CH2CHClCH3 + OH-→CH3CH2CH(OH)CH3 +Cl- . - K is CH3CH2CH(OH)CH3 - CH3CH2CH(OH)CH3 CH3CH2COCH3 + H2O - L is CH3CH2COCH3 CH3CH2CHClCH3 + Mg → CH3CH2CH(MgCl)CH3 equation and M 1 1 1 1 1 1 2 b) Isomer of J can be the following answer CH3CH2CH2CH2Cl or (CH3)2CHCH2Cl CH3CH2CH2CH2Cl or (CH3)3CCl Since they are 10 alcohol Since it has similar surround group of atoms Equation [1] Product [1] Equation [1] Product [1] 4 Total 15
CONFIDENTIAL* Module ‘A’cceleration STPM Johor Bahru S3 2022/2023 SULIT* Goh San San, Nur Fathin Suhana bt Ayob, Wong Minh Chjiat Isabelle, Chew Chin Kuen, Mohamad Rashidi bin Anang & Noreza bt Salleh Hudin Q13 - 19 Carboxylic Acids and their Derivatives (a) Each reagents + condition / intermediate [1] x 7 7 (b) Each product [1] x 4 4 product formed 1 (c) Each reagent + condition / intermediate [1] x 3 3 Total 15