Maths Zone book 4 2077

g. Weeks Days h. Days Hors i. Weeks Days Hours

12 4 7 18 4 3 15

+4 5 + 3 12 + 7 6 20

2. Subtract the following.

a. Min. Sec. b. Hrs. Min. c. Hrs Min Sec

22 25 15 32 7 45 37
– 10 15 – 9 17 – 2 32 42

d. Months Days e. Year Months f. Year Months Days

7 25 8 10 9 8 25

– 5 15 – 5 11 – 7 10 16

g. Weeks Days h. Days Hours i. Weeks Days Hours

15 28 8 23 4 3 20

– 9 15 – 2 17 – 2 1 22

Maths Zone – Grade 4 101

Word Problems

1. Sita started a work in the field at 7 : 35 am and finished
the work at 10 : 15 am. How long did she work?

2. Laxmi travelled 5 hours 28 minutes 42 seconds by a car
and 2 hours 15 minutes 13 sec by an auto-rickshaw. How
much time did she travel in total?

3. How old are you? Find out subtracting your date of birth
from todays date?

4. Your math periods starts at 9 : 30 am and ends at 10:15
am. How long is the period?

5. Puspa went to USA for a tour on March 27, 2016 and
returned home on July 30, 2016. How long did she stay in
USA?

102 Maths Zone – Grade 4

Money

Every country has their own currency. Nepali currency is rupees and
paisa. 100 paisa make one rupee.

1 Rupee = 100 Paisa

Example 1

Convert rupees into paisa.

a. Convert Rs 5 and 30 paisa into paisa

Solution: (5 × 100) paisa + 30 paisa

= 500 paisa + 30 paisa

= 530 paisa Alternatively
b. Convert 356 paisa into rupees 3 Rupees

Solution: 356 paisa = Rs 356 100 356
100
– 300
= 3.56
56 Paisa

= Rs 3 and 56 paisa. = 3 Rupees 56 paisa

Also, 356 paisa 1 paisa = 0.01 Rupees
= 300 paisa + 56 paisa 15 paisa = 0.15 Rupees
= (3 × 100) paisa + 56 paisa 25 paisa = 0.25 Rupees
= Rs 3 + Rs 0.56 56 paisa = 0.56 Rupees
= Rs 3.56

Exercise 4.5

1. Change following into paisa.
a. Rs 8 b. Rs 3 and 25 paisa c. Rs 10 and 20 paisa

d. Rs 212 e. Rs 914 f. Rs 9.25 g. Rs 0.75
2. Change into Rupee.

a. 400 paisa b. 2500 paisa c. 50 paisa

d. 35 paisa e. 346 paisa f. 675 paisa

Maths Zone – Grade 4 103

3. Express into Rupees and paisa.
Rs 20.56 = ...R...s....2..0...a..n...d...5..6...p..a..i..s.a.......

a. Rs 30.05 = ...............................

b. Rs 15.75 = ...............................

c. Rs 45.87 = ...............................

d. Rs 0.25 = ...............................

e. Rs 38.15 = ...............................
Addition and Subtraction of Money

Let's take few examples of addition and subtraction of money.

Example 1

Add Rs 15 and 73 paisa and Rs 65 and 45 paisa.

Rs Paisa Alternatively
Rs 15 and 73 paisa = Rs 151 .73
1

15 73

+ 65 45 Rs 65 and 45 paisa = + Rs 65.45

81 1 18 Rs. 81.18
∴ Rs 81 and 18 paisa. It is similar to addition of decimal.

Example 2

Subtract Rs 12 and 65 paisa from Rs 19 and 27 paisa.

Rs P Rs P Alternatively
19 27 18 +100 127
65 – 12 65 8 12
– 12 ?
6 62 Rs 1 9 . 2 7

– Rs 1 2 . 6 5

Rs 6 . 6 2

Easy! Exactly like
subtraction of decimal.

104 Maths Zone – Grade 4

Exercise 4.6

1. Add the following.

a. Rs P b. Rs P c. Rs P
37 54 45 38 84 36

+ 45 58 + 47 76 + 46 45

d. Rs P e. Rs P f. Rs P
32 60 272 63 570 72

+ 15 55 + 46 66 + 49 64

2. Add the following.

a. Rs 23.46 b. Rs 84.36 c. Rs 96.47
+ Rs 47.92 + Rs 39.83 + Rs 49.32

d. Rs 258.38 e. Rs 728.35 f. Rs 653.65
+ Rs 463.47 + Rs 443.87 + Rs 425.56

3. Subtract the following.

a. Rs P b. Rs P c. Rs P
75 55 80 24 85 29

– 50 64 – 47 57 – 39 55

d. Rs P e. Rs P f. Rs P
200 15 345 42 542 82

– 83 68 – 167 95 – 184 26

Maths Zone – Grade 4 105

4. Subtract the following.

a. Rs 470.30 b. Rs 250.50 c. Rs 1270.80
– Rs 225.95 – Rs 112.80 – Rs 980.95

d. Rs 120.80 e. Rs 557.23 f. Rs 178.65
– Rs 67.35 – Rs 269.68 – Rs 115.80

Word Problems

1. Aakriti has Rs 195.65 in her pocket. Her mother gave her
Rs 185.75. How much money does she have now?

2. Puspa bought a book for Rs 305 and 40 paisa. She bought
a pen for Rs 47.85 paisa. How much did she spend?

3. Parbati had Rs 200. She spent Rs 176.25 paisa. How much
does she have now?

4. Radha bought a ring for Rs 41,000. She sold it at
Rs.38000.24. What is her profit or loss?

5. Sunil had Rs 676.20. He gave her sister Rs 289.86. Then,
how much did he have?

106 Maths Zone – Grade 4

Multiplication of Money

Example 1

Radha has to buy 4 pens. If the cost of a pen is Rs 17.40,
how much does she have to pay?

Solution: Rs 17.40 Multiply normally, neglating decimal.

× 4 Total no of digits after decimals are
Rs 69.60 '2' in multiplier and multiplicands
so put decimal after 2 digits from
right in the product.

Example 2

Multiply.

Solution: Rs 273.343 There are 3 digits after
decimals so in product
× 12 also, decimal (dot .) sign
546686 must be placed after of 3
+ 2733430 digits from right.
3280.116

The product is 3280.116

Example 2

Multiply.

22 3

Solution: Rs 23 and 35 paisa

× 7
Rs 163 and 45 paisa

The product is Rs. 163 and 45 paisa.

Maths Zone – Grade 4 107

Exercise 4.7

1. Multiply the following.

a. Rs P b. Rs P c. Rs P
65 54 75 34 38 82
×8
×4 ×7
f. Rs P
d. Rs P e. Rs P 73 24
27 45 53 33 × 15

× 10 × 12

2. Multiply the following.

a. Rs 4.70 b. Rs 5.85 c. Rs 432.20
× 3 × 8 × 4

d. Rs 123.70 e. Rs 750.60 f. Rs 128.43
× 9 × 6 × 7

3. Word problems.
a. A book costs Rs 247.50. Find the cost of 10 such books.
b. The cost of a kg apple is Rs 154.20 find the cost of
such 5 kg apples.
c. Shamjana bought 9 books. If the cost of a book is Rs
170.85. How much does she pay for books?
d. Sarala visits a restaurant with family. She orders 5
plates of momo. The cost of a plate momo is Rs 127.75.
How much she has to pay?
e. The cost of a mobile phone is Rs 12475.66. Find the
cost of such 5 mobiles.

108 Maths Zone – Grade 4

Division of Money

Example 1

The cost of 7 pens is Rs 105.49. Find the cost of a pen?

Solution:

Here, we divide rupees and paisa by 7.

15 7

7 Rs 105 49 paisa

– 7 – 49

35 ×

– 35

×

∴ Rs 15 and 7 paisa.
Alternatively

15.70 Oh! There are two
7 4105.49 digits after decimal
in dividend and
– 7 there are two digits
35 after decimal in
Quotient also.
– 35
× 49

– 49 It is no more different than
× the division of decimal.

Exercise 4.8

1. Divide the following.

a. 4 Rs P b. 12 Rs P c. 10 Rs P

24 112 144 168 200 180

d. 6 Rs P e. 5 Rs P f. 2 Rs P

90 120 40 25 68 46

Maths Zone – Grade 4 109

2. Divide the following.

a. Rs 17.00 ÷ 4 b. Rs 32.75 ÷ 5 c. Rs 34.00 ÷ 2

d. Rs 65.20 ÷ 4 e. Rs 652.20 ÷ 7 f. Rs 716.15 ÷ 5

g. Rs 651.40 ÷ 4 h. Rs 785.25 ÷ 5 i. Rs 854.85÷8

j. Rs 425.25 ÷ 10 k. Rs. 124.50 ÷6 l. Rs. 278.46÷ 9

3. Divide the following.

a. 28.20 by 4 b. 256.40 by 8 c. 245.45 by 9

d. 325.75 by 5 e. 666.60 by 6 f. 844.88 by 4

Word Problems

1. The cost of 3 kg sugar is Rs. 142.50. How much will 1 kg
sugar cost?

2. A dozen pens cost Rs. 144.36. What is the cost of a pen.
3. Divide the Rs. 325.75 among 5 students.
4. Sarita paid Rs. 495.90 for 9 plates Mo:Mo:. What is the

cost of one plate?
5. The cost of 6 meter ribbon is Rs. 625.50. Find the cost of

a metre ribbon.
6. The cost at 4 ticket in cinema hall is Rs. 360.80. What is

the cost of a ticket?

110 Maths Zone – Grade 4

Maths Fun

Time of SAARC Countries
Teachers are requested to show or display the time difference of SAARC
countries and Discuss in the class.

SAARC countries are :- Afghanistan, Pakistan, India, Nepal, Bhutan,
Maldives and Shri-lanka and Bangladesh

Students are requested to show the time which is equal to the Nepalese

time.

Its 7 pm in Nepal What time is it now What time is it now

in India? in Pakistan?

What time is it now What time is it now What time is it now

in Afghanistan? in Bhutan? in Maldives?

Maths Zone – Grade 4 111

Practice Zone

Group 'A'

Circle the correct option.

1. 45 months is equal to

a. 3 years 9 months b. 4 years c. 3 years 7 months

2. Minute hand at a clock is at 7 and hour hand is between 2 & 3
then the time is

a. 2:40 b. 2:35 c. 3:20

3. The short form of date 10th Falgun 2038 is

a. 2038/11/10 b. 2038/10/11 c. 11/10/2038

4. The time between 2PM to 5AM is

a. 3 hours b. 7 hours c. 15 hours

5. The number of the days in a leap year is

a. 364 days b. 366 days c. 365 days

6. Rs. 45.37P is equal to

a. Rs. 45 and 37 paisa b. Rs. 45.37 c. Rs. 4537

7. To convert rupees into paisa, rupee must be multiplied by

a. 10 b. 100 c. 1000

8. 365P + Rs. 23.25P + Rs. 15.10P is equal to

a. Rs. 41 b. Rs. 42 c. Rs. 41 30 paisa

Group 'B'

1. Saugat bought a book for Rs. 65 and 45P, and a pen for Rs. 25 and
75 paisa. He gave a note of Rs. 100 to the shopkeeper. How much
money did he get back?

112 Maths Zone – Grade 4

2. The cost of a kg sugar is Rs. 85.60P. The cost of a packet Tea is Rs.
102.45P. What is the total cost?

3. The cost of a bag of Aata is Rs. 235.60P. What is the cost of such 6
bags?

4. Prabesh has Rs. 346.50P. He has to divide it among 5 children.
How much does each get?

5. What time will it be 2 hours 25 minutes after 4:45 am?

6. Puspa is 14 years 6 months 12 days and Sunil is 12 years 8 months
and 20 days old respectively. By how many years is Puspa older
than Sunil?

7. See the calendar for this year and write the date of the following.

a. Republic day ________ b. Tamu Lhosar ________

c. Viajaya Dashami ________ d. Indra Jatra ________

e. Martyr's day ________ f. Udauli Parba ________

g . EId ________ h. Christmas ________

i. Children day ________ j. Women's day ________

Maths Zone – Grade 4 113

Answers of Unit 4

Exercise 4.1

1. a. 1 : 15 : 20 b. 3 : 30 : 50 c. 8 : 35 : 25

d. 7 : 25 : 30 e. 4 : 45 : 15 f. 12 : 55 : 45

2. c. 5 minutes to 7'O clock d. 20 minutes to 5' O clock

e. 15 minutes past 8' O clock f. 20 minutes past 9' O clock

3. c. Quarter to 4' O clock d. Quarter past 3 ' O clock

e. Quarter past 4 ' clock f. Half past 5 ' O'clock

Exercise 4.2

1. a. 720 minutes b. 1200 minutes c. 285 minutes

d. 810 minutes e. 568 minutes f. 682 minutes

2. a. 12 hrs. b. 8 hrs c. 22 hrs.

d. 12 hrs. 58 minutes e. 4 hrs. 5 min f. 10 hrs 25 min.

3. a. 360 sec. b. 1020 sec. c. 1380 sec.

d. 872 sec. e. 447 min. f. 5700 sec.

4. a. 11 min. b. 16 min. c. 24 min. 18 sec.

d. 7 min. 25 sec. e. 398 min. f. 66 min.

Exercise 4.3

1. a. 36 months b. 144 months c. 252 months
2. a.
d. 6 years b. 90 years c. 78 years 10 months
f.
3. a. 32 years 2 months e. 129 years
d.
4. a. 177 months
c.
e. 210 days b. 730 days c. 750 days

140 days e. 375 days f. 1660 days

8 months 10 days b. 1 year 2 months 25 days

1 year 9 months 20 days d. 3 years 5 months 16 days

2 years 8 months 10 days f. 1 year 11 months 26 days

114 Maths Zone – Grade 4

Exercise 4.4: Addition and Subtraction of Time

1. a. 52 minutes 33 second b. 22 hours 57 minutes
c. 8 hours 54 minutes 42 seond d. 8 months 28 days
e. 14 year 3 months f. 9 year 8 months 10 days
g. 17 weeks 2 days h. 11 days 6 hours
i. 12 weeks 3 days 11 hours
2. a. 12 minute 10 second b. 6 hours 15 minute
c. 5 hours 12 minute 55 seond d. 2 months 10 days
e. 2 year 11 months f. 1 year 10 months 9 days
g. 6 weeks 13 days h. 6 days 6 hours
i. 2 weeks 1 days 22 hours

Word Problems

1. 2 hours 40 minutes
2. 7 hours 43 minutes 55 seconds
3. (Do yourself)
4. 45 minutes
5. 4 months 3 days

Exercise 4.5

1. a. 800 paisa b. 325 paisa c. 1020 paisa
d. f. 925 paisa
g. 925 paisa e. 925 paisa
2. a. c. Rs. 0.50
d. 75 paisa f. Rs. 6.75
3. a. b. Rs. 15 and 75 paisa
c. Rs. 4 b. Rs. 25 d. 25 paisa

Rs. 0.35 e. Rs. 3.46

Rs. 30 and 5 paisa

Rs. 45 and 87 paisa

Exercise4.6

1. a. Rs. 83 P12 b. Rs. 93 P14 c. Rs. 130 P81
Rs. 620 P35
d. Rs. 48 P15 e. Rs. 319 P29 f. Rs. 145.79
Rs. 1079.21
2. a. Rs. 71.38 b. Rs. 124.19 c.
R. 45 P 74
d. Rs. 721.85 e. Rs. 1172.22 f. Rs. 358 P 56

Subtracting the Money

1. a. Rs. 24 P 91 b. Rs. 32 P 67 c.
Rs. 177 P47 f.
d. Rs. 116 P 47 e.

Maths Zone – Grade 4 115

2. a. Rs. 244.35 b. Rs. 137.70 c. 289.85
d. f. Rs. 62.85
3. a. Rs. 53.45 e. Rs. 287. 55 c. Rs. 23 75 paisa
d. e. Rs. 386.34
Rs. 381.40 b. Rs. 353 25 paisa
c. Rs. 310 P 56
Rs. 2999 76 paisa f. Rs. 1098 P 60
c. Rs. 1728.80
Exercise 4.7 f. Rs. 899.01
c. Rs. 1537.65
1. a. Rs. 262 P 16 b. Rs. 527 P 45
Rs. 639 P 96
d. Rs. 270 P 50 e. Rs. 46.80
Rs. 4503.60
2. a. Rs. 14.10 b. Rs. 771
Rs. 62,378.30
d. Rs. 1113. 30 e.

3. a. Rs. 2475 b.

d. Rs. 638.75 e.

Exercise 4.8

Show to your teacher.


116 Maths Zone – Grade 4

5 Measurement

Specific Objective Prescribed by CDC

 To measure the distance/length in centimeter or in meter by the help of a ruler or
meter tape.

 To tell the relation between centimeter and meter and convert meters into centimeters.
 To add and subtract two distance without converting one unit into another.
 To recognize, distinguish and compare the standardized capacity measuring vessels

of 25 ml to 1liter.
 To guess the capacity of vessels (not more than of 1 litre) to the nearest hundred

milliliters.
 To add and subtract two capacities without converting from one unit to another.
 To find out the weight of the given objects by using the standardized weight

measuring devices (DHAKS) of 50 gm to 1 kg.
 To guess the weight of the given objects (not more than 1 kg) to the nearest hundred

g.
 To convert kg into g.

Maths Zone – Grade 4 117

Length

Class Discussion

Centimetre (cm), metre(m) and kilometre (km) are the
standard units of length. Metre and centimetre are
used to measure the length of objects. Metre is divided
into 100 equal parts. Such parts are called centimetres.

1 metre = 100 centimetre

Centimetre = cm, meter = m
millimetre = mm kilometre = km

A ruler is divided into 15 equal parts, each part is 1 centimetre (cm).
Therefore, the length of a ruler is 15 cm. There are 10 small division in
one centimetre. Each such division is called millimetre.

1 centimetre = 10 millimetre
1 cm = 10 mm

÷ 10 cm
mm

× 10

Example 1 Multiply cm by
10 to change into
Convert the following into millimetre (mm)
mm.
a. 7 cm b. 12 cm 8 mm

Solution: 7 cm Solution: 12 cm 8 mm

= (7 × 10) mm = (12 × 10)mm + 8 mm

= 70 mm = 120 mm + 8 mm

= 128 mm

118 Maths Zone – Grade 4

Example 2

Change into 'cm'

Solution: b. 85 mm
a. 60 mm

60 mm 85 mm
= 6100 cm = 6 cm = 8105 cm = 8.5 cm

Example 3

Change into 'm'

Solution: b. 750 cm
a. 700 cm

700 cm 750 cm
= 710000 m = 7 m = 715000 m = 7.50 m

Exercise 5.1

1. Convert into 'mm'
a. 16 cm b. 31 cm c. 25 cm
d. 8 cm 7 mm e. 4 cm 9 mm f. 14 cm 8 mm
2. Convert into 'cm'
a. 50 mm b. 60 mm c. 90 mm
d. 110 mm e. 180 mm f. 200 mm
3. Convert into 'cm'
a. 3 m b. 8 m c. 15 m
d. 25 m e. 4 m 70 cm f. 12 m 60 cm
4. Convert into 'm'
c. 1200 cm
a. 300 cm b. 700 cm f. 4000 cm

d. 1800 cm e. 2500 cm

Maths Zone – Grade 4 119

Measure of Distance

Class Discussion

Kilometre is used to measure the distance from one place to another.
We write 'km' for kilometre.

1000 m = 1 km

Do you know?
‰‰ How far is Kathmandu from Pokhara?............. km
‰‰ What is the length of Mahendra highway?............ km

We measure the distance between two cities in kilometre.

m ÷ 1000 km
× 1000
Example 1
b. 7 km 225 m
Convert into metres

a. 5 km

Soln: 5 km Soln: 7 km 225 m
= 5 × 1000 m = (7 × 1000)m + 225 m
= 5000 m = 7000 m + 225 m
= 7225 m

Example 2 b. 2343 m Put decimal
after 3 digits
Convert into Km from right while
dividing the
a. 5000 m number by 1000

Soln: 5000 m Soln: 2343 m

= 51000000 km = 12030403
= 5 km = 2.343 km

120 Maths Zone – Grade 4

Exercise 5.2

1. Convert the following into metres.

a. 3 km b. 25 km c. 5 km 225 m

d. 81 km 60 m e. 17 km 405 m f. 47 km 320 m

g. 246 km 350 m h. 885 km 705 m i. 24 km 758 m

2. Convert the following into 'km'

a. 3000 m b. 5000 m c. 9000 m

d. 20,000 m e. 40,000 m f. 80000 m

3. Convert the following into km and m.

a. 4250 m b. 17365 m

Soln: 4250 m Soln: 17365 m

= 4000 m + 250 m = 17000 m + 365 m

= 4 km + 250 m = 17 km + 365 m

= 4 km 250 m = 17 km 365 m

c. 8250 m d. 8572 m e. 7045 m

f. 9676 m g. 3690 m h. 2650 m

i. 76625 m j. 73690 m k. 25365 m

Maths Zone – Grade 4 121

Addition of length

Class Discussion

Adding the length is also like as the addition of time, money etc.
We must add.

mm and mm, cm and cm
m and m, km and km

Example 1

Add 35 cm and 8 mm with 16 cm and 9 mm.

Solution: cm mm We have,

11 10 mm = 1 cm

35 8 17 mm = 10 mm + 7 mm
+ 16 9
= 1 cm + 7 mm
52 1 7

 52 cm 7 mm

11 Directly we can add carryover of
35.8 mm to cm column also.
Or + 16.9

52.7 = 52 cm 7 mm

Example 2

Add 7 m 25 cm with 9 m 86 cm

Solution: m cm 100 cm = 1 m
7 25
86 So, 111 cm = 100 cm + 11 cm
+9 111
16 –100 = 1 m + 11 cm
+1 11
17 i.e 1 m 11 cm

So, 1 m must be added with 16 m, in

the column of metre.

7.25

Or + 9.86

17.11 = 17 m 11 cm

122 Maths Zone – Grade 4

Exercise 5.3

1. Add the following. cm mm c. m cm
a. cm mm b. 35
47
16 9 28 9 73

+ 15 6 + 73 8 + 23

d. m cm e. km m f. km m

76 54 64 105 222 346
+ 35 77 + 85 112 + 42 584

2. Add the following.
a. 15 cm 8 mm and 4 cm 5 mm
b. 15 m 45 cm and 65 m 78 cm
c. 23 km 631 m and 42 km 792 m
d. 72 km 459 m and 93 km 657 m
e. 22m 85 cm 8 mm and 24 m 75 cm 9 mm
f. 5 m 27 cm 4 mm and 9 m 29 cm 3 mm
g. 29 km 650 m 80 cm and 22 km 540 m 60 cm
h. 12 km 875 m 35 cm and 19 km 550 m 85 cm

word Problems

3. A room is 7 m 49 cm long and 3 m 80 cm wide. How much
is the room longer than it's width?

4. Sanu needs 1 m 96 cm clothes for skirt and 2 m 35 cm for
shirt. How much cloths does she need altogether to make
a set of dress?

5. Samita measured schoovl's play ground and found that it
was 245 m 76 cm long and 120 m 47 cm wide. How much
total distance did she measure?

6. Saurav walked 1 km 747 m in Sunday and 2 km 648 m on
Monday. What distance did he travel on both days?
Maths Zone – Grade 4 123

Subtraction of Length

Class Discussion

Subtracting the length is also like as the subtraction of time, money
etc. We must subtract;

mm and mm, cm and cm
m and m, km and km

Example 1

Subtract 35 cm 9 mm from 44 cm 5 mm.

Solution:cm mm cm mm cm mm
44 5
44 5 3 13 – 35 9
– 35 9 4 3 15 86
? 44 + 1 cm
+10 mm 5 Alternatively

– 35 9 3 13 15

86 4 4 . 5 cm

= 8 cm 6 m

Example 2 – 3 5 . 9 cm
8 . 6 cm = 8 cm 6 mm

Subtract 26 m 64 cm from 52 m 23 cm.

Solution:: after rearranging, we get
m cm m cm
Borrowing 1 m from 52
52 23 51 m and adding 1 m = 100
– 26 64 cm to 23 cm it become
52+100 123 123 cm. Now subtract
– 26 64 64 from 123.

25 59

Alternatively = 25 m 59 cm

4 11 11 13 Exactly, same
as subtraction
52.23 m

– 2 6 . 6 4 m

25.59 m of decimal !
= 23 m 59 cm

124 Maths Zone – Grade 4

Example 3

Subtract 31 km 339 m from 56 km 145 m.

Solution: km m km m Here, 1 km = 1000 m.
56 145 1 km So, while borrowing
55 +1000 1145 1 km, we must add
– 31 339 1000 m to 145 m.
– 31 339

24 806

= 24 km 806 m

Alternatively

5 11 3 15

5 6 . 1 4 5 km

– 3 1 . 3 3 9 km

2 4 . 8 0 6 km = 24 km 806 m

Example 4

Subtract 12m 80 cm 9 mm from 19 m 32 cm 4 mm.

Solution: After rearranging

m cm mm m cm mm m cm mm
19 32 4 19 31 +10 14 18 +100 131 14
– 12 80 9 – 12 80 9
– 12 80 9

?? ?5 6 51 5

‰‰ We can't subtract 9 mm from 4 mm. Borrow 1 cm from 32 cm and add
it equivalent 10 mm to 4 and it becomes 14 mm.

‰‰ We can't subtract 80 cm from 31 cm. Borrow 1 m from 19 m and add
it equivalent 100 cm to 31 cm and it becomes 131 cm.

‰‰ Now subtract mm with mm, cm with cm and m with m.

Example 5

Subtract 21 km 650 m 75 cm from 29 km 370 m 30 cm.

Solution:

km m cm km m cm km m cm
29 370 30 29 369 +100 30 28 +1000 1369 130
– 21 650 75 – 21 650 75 – 21 650 75
7 719 55
?? ?5

Maths Zone – Grade 4 125

Exercise 5.4

1. Subtract the following.

a. cm mm b. cm mm c. m cm
5 36 129
13 6 25 6 – 18 728

–8 4 – 22

d. km m e. km m cm
87 345 18 500 80
221
– 62 – 12 275 35

2. Subtract the following.
a. 71 cm 3 mm from 82 cm 4 mm
b. 36 m 37 cm from 51 m 42 cm
c. 21 m 74 cm from 66 m 53 cm
d. 18 km 128 m from 36 km 229 m
e. 24 m 35 cm 7 mm form 37 m 49 cm 8 mm
f. 17 m 27 cm 5 mm from 32 m 38 cm 3 mm
g. 4 km 360 m 22 cm from 9 km 245 m 25 cm

126 Maths Zone – Grade 4

5 m 60 cm word Problems
12 mm 75 cn
3. From Pokhara, Muglin is 99 km 125 m far and Kathmandu
is 200 km 345 m far. How far is Kathmandu from Muglin?

4. Shova has 56 m 78 cm ribbon in her shop. She sold 29 m
38 cm. How much ribbon is left in here shop?

5. Length of a pole is 12 m 75 cm. It
is 5 m 60 cm under the water in a
pond. Find the length of the pole
which is above the pond.

Maths Zone – Grade 4 127

Capacity

Class Discussion
Look at the given objects and learn the capacity that they contains.
After learning this, also find out the capacity of your water bottle.

60 ml 500 ml 1.5 l

1 l 20 l 500 l

The amount of liquid that an object holds into it is called capacity of
the object.
Some standard vessels are used to measure the liquid.

We use these vessels to measure the

liquid.

‰‰ Ask your grandfather/

grandmother and How did they

measure liquid on their time? Pathi Mana

128 Maths Zone – Grade 4

Let's Discuss

+

500 ml 500 ml 1l

+ ++ 

100 ml 200 ml 500 ml 200 ml 1l
1000 ml is called 1 Litre

1000 ml = 1 l

Example 1 Oh! Multiply
l by 1000 to
a. 3l = 1l + 1l + 1l convert into ml.

= 1000 ml + 1000 ml + 1000 ml

= 3000 ml

We can say 3l = 3 × 1000 ml = 3000 ml

Example 2 b. 5l 200 ml
= (5 × 1000)ml + 200 ml
Convert into ml. = (5000 + 200)ml
a. 8 l = 5200 ml
= 8 × 1000 ml
= 8000 ml

Convert only litre
into milliliter &
add millitre.

Maths Zone – Grade 4 129

Example 3

Convert ml into l.

a. 7000 ml b. 7725 ml

= 7000 l = 7725 l
1000 1000
= 7 l = 7.725 l

= 7 l 725 ml

Divide ml by Put decimal infront of
1000 to convert 3 digits from last after
into litre. dividing by 1000. Express
7.725 into 7 l and 725 ml.
Exercise 5.5

1. Express into ml. b. 23 l c. 1 l 252 ml
a. 15 l e. 6 l 296 ml f. 9 l 576 ml
d. 12 l 366 ml h. 18 l 27 ml
g. 7 l 745 ml

2. Convert into litres. b. 8000 ml c. 13000 ml
a. 6000 ml f. 5700 ml

d. 15000 ml e. 2200 ml

3. Convert into inters and milliters. c. 4004 ml
a. 9380 ml b. 3446 ml

d. 6065 ml e. 1667 ml f. 11360 ml

4. Collect the water bottle from your class and guess how
much water do they hold?

5. In your home, there may be water tank, pot or water jar.
Ask your parents and write their capacity [at least 10
pots].

Eg. 1. Water tank = 1000 l

2. Jug = 2l etc.

128 Maths Zone – Grade 4

Addition and Subtraction of Capacity

We arrange litres and milliliters separately and add or subtract as
given. Be sure that milliliters must be expressed in 3 digits.

Example 1

Add 16 l 484 ml and 51 l 654 ml

Solution:

l ml 16 l 484 ml  16.484
51 l 654 ml  + 51.654
1
68.130
16 484
+ 51 654 ∴ Sum is 68 l 130 ml

68 l 1 138 l

1000 ml = 1l So,
1138 ml = 1000 ml + 138 ml
For 1000 ml we add 1l to the liter column

Example 2

Add 19 l 17 ml and 25 l 355 ml

Solution: 19 l 17 ml  1

19.017

25 l 355 ml  + 25.355

44.372

∴ Sum is 44 l 372 ml

Example 3

Subtract 48 l 484 ml from 61 l 743 ml.
Solution: l ml

5 11 6 13 13

61 743

– 48 484
1 3 l 2 5 9 ml ∴ Difference = 13 l 259 ml

Maths Zone – Grade 4 129

Exercise 5.6

1. Add the following.

a. l ml b. l ml c. l ml

78 193 57 297 346 969

+ 45 635 + 49 497 + 58 695

d. l ml e. l ml f. l ml

37 446 65 465 117 987

46 245 + 95 278 + 66 47

+ 18 008

2. Add the following.
a. 172 l 497 ml and 46 l 37 ml
b. 346 l 245 ml and 237 l 47 ml
c. 37 l 384 ml and 82 l 920 ml

3. Subtract the following.

a. l ml b. l ml c. l ml

80 445 418 146 23 570

– 40 225 – 258 140 – 20 320

d. l ml e. l ml f. l ml

21 515 32 875 27 654

– 15 325 – 21 758 – 12 785

128 Maths Zone – Grade 4

4. Simplify the following.
a. 18 l 284 ml + 26 l 481 ml – 11 l 244 ml
b. 49 l 228 ml – 52 l 446 ml + 10 l 248 ml

Word Problems

5. There are three cows in Laxmi's house. Mali cow gives 4l 345 ml
milk, Kali gives 6l 200 ml milk and chamri cow gives 5 l 645 ml
milk. What is the total milk at Laxmi's house?

6. In Jeban's house, there are 3 vehicles, motorbike consume, 15 l 447
ml petrol. Car consumes 47 l 850 ml petrol and scooty consumes
9 l 350 ml petrol in a month. What is the total consumptions of
petrol in a month in his house?

7. Sami was carrying 12 l 350 ml milk. She slipped in the store and
spoiled some milk and only 7 l 200 ml is left in the pot. How
much milk did she spoil?

Maths Zone – Grade 4 129

Weights

Class Discussion

What is your weight?
Is your book heavier than pen?
How can you measure your weight?
Let's take the weight of students in class.

50 g 500 g 1 kg 35 kg 50 kg

We use gram to measure the wight of lighter object like book, pen

eraser, pencil. etc. We use kilogram to measure the weight of heavier

object like, rice, sugar, your weight, etc.

The symbols use for gram is 'g' and kilogram is 'kg'.

1000 grams = 1 kilogram

Example 1 1000 g = 1 kg

Convert into grams.

a. 3kg b. 15 kg 325 g

= 3 × 1000 g = 15 × 1000 g + 325 g
= 3000g = 15000 g + 325 g

= 15325 g
128 Maths Zone – Grade 4

Example 2

Convert into kg and gram

a. 12000 g b. 3435 g

= 12000 kg = 3435 kg
1000 1000

= 12 kg = 3.435 kg

= 3 kg 435 g

÷1000 Multiply by 1000 to
change 'kg to gram'.
g
kg

×1000 Divide by 1000 to
change gram to kg.

Exercise 5.7

1. Change into gram 'g'.

a. 9 kg b. 15 kg c. 56 kg d. 14 kg

e. 102 kg f. 3 kg 245 g g. 7 kg 584g

h. 17 kg 250 g

2. Convert into kg.

a. 7000 g b. 8000 g c. 15000 g
f. 25000 g
d. 17000 g e. 12000 g

3. Convert into kg and gram c. 2455 g d. 12130 g
a. 18300 g b. 5632 g

e. 9780 g f. 8450 g g. 7600 g h. 15560 g

Maths Zone – Grade 4 129

Addition and Subtraction of Weight

1. Add 35kg 50 g to 49 kg 9 gram.

kg g 1 kg = 1000 grams so,
35 050 Write grams in 3 digits.
+ 49 009 50 g as 050 g and 9 grams as 009 grams.
84 kg 059 g Add grams to gram and kg to kg.

2. Add 16 kg 99 grams and 38 kg 89 grams.

kg g We need three
16 099 digits on the
+ 38 089 column of grams.
54 kg 188 g

3. Add 215 kg 447 g and 283 kg 848 gram.

kg g 1000 g = 1 kg
So, 1295 gram = 1 kg 295 gram
1 So, 1 goes as carry over in kg column.

215 447
+ 283 848

499 1 295

= 499 kg 295 gram

4. Subtract 23 kg 78 gram from 47 kg 145 g.

kg g

0 13 15

47 1 4 5
– 23 0 7 8

24 67
= 24 kg 67 gm

128 Maths Zone – Grade 4

5. Subtract 49 kg 445 g from 68 kg 30 gram.

kg g Or – 68.030 Or kg +100 g
49.445 67 1030
5 17 9 12 10 18.585
– 49 445
68 030
– 49 445 18 kg 585 g

18 585 = 18 kg 585 g

= 18 kg 585 g

Exercise 5.8

1. Add the following.

a. kg g b. kg g c. kg g

47 445 18 754 39 142

+ 35 368 + 15 125 + 27 345

d. kg g e. kg g f. kg g

38 425 46 680 97 489

+ 35 458 + 78 546 + 78 559

2. Add the following.
a. 25 kg 320 g and 57 kg 450 g
b. 17 kg 85 g and 4 kg 357 g
c. 73 kg 243 g and 22 kg 67 g
d. 13 kg 68 g and 71 kg 667 g
e. 32 kg 8 grams and 18 kg 946 g

Maths Zone – Grade 4 129

3. Subtract the following.

a. kg g b. kg g c. kg g

14 759 27 225 15 865

– 10 564 – 18 175 – 12 725

d. kg g e. kg g f. kg g

23 781 87 524 842 268

– 18 215 – 69 911 – 527 732

4. Subtract the following.
a. 28 kg 450 g from 45 kg 650 g

b. 16 kg 525 g from 30 kg 825 g

c. 75 kg 200 g from 90 kg 90 g

d. 39 kg 346 g from 58 kg 17 g
5. Sumana bought 25 kg aata from market. She used 13 kg 250

gram of it. How much aata is left?
6. Sunaina bought 14 kg 350 g potato, 12 kg 850 gram tomatoes and

7 kg 50 grams onion from the vegetable shop for a party. How
much total vegetable did she carry home?
7. Saajan's weight is 47 kg 250 g. Sulaman weight is 35 kg 160 g.
What is the difference of their weight?
8. Samira loose 8 kg 760 g weight. She is now 42 kg 350 g. What was
her earlier weight?

128 Maths Zone – Grade 4

Maths Fun

Do the following class activity
a. What is the length of your
classroom?
b. Which is longer, your
classroom or your bedroom?
c. Let's guess, what is the
length of your playground?
d. How far is your home from
your school?
e. What is your height?
f. Who is the tallest boy of your class? What is his height?
g. Who is the tallest girl of your class? What is her height?
h. What is the height of your math teacher?
i. Measure the length of your desk.
j. Can you measure the thickness of your book?

Maths Zone – Grade 4 129

Practice Zone

Group A

Circle the correct option.

1. 7 km is equal to ...................

a. 7000m b. 700m c. 70m

2. 8cm 4mm is equal to

a. 84mm b. 804mm c. 12mm

3. Suman has 2 kg 500 gram Laddu. Samita has 800 grams. What is
the total weight.

a. 2 kg b. 3 kg 300 g c, 1500 grams

4. A drum has capacity of 50l water. If Sagun take 20l 500ml water.
How much water remain their?

a. 30 l b. 29l 500ml c. 30 l 500 ml

5. The weight of Motu is 50kg & Patlu is 20kg. How much weight is
required to make 1 quintal?

a. 20 kg b. 50 kg c. 30 kg

6. Conversion of 10l 460ml into ml is

a. 10460 ml b. 1460 ml c. 10046 ml

7. The sum of 2 kg 54 g and 3 kg 97 g is

a. 6 kg 151 gram b. 7 kg 61 kg c. 6 kg 51gram

8. The difference of 9 kg 27 g and 2 kg 350 g is

a. 7 kg 77 g b. 6 kg 677 g c. 6 kg 322 g

128 Maths Zone – Grade 4

Group B
1. Add the following.

a. 10 cm 2 mm and 23 cm 9 mm
b. 83 cm 5 mm and 18 cm 9 mm
c. 35 m 92 cm and 82 m 42 cm
d. 58 m 81 cm and 61 m 36 cm
e. 31 m 72 cm and 83 m 49 cm
f. 65 km 348 m and 27 km 885 m
g. 13 m 60 cm 6 mm and 32 m 63 cm 8 mm
h. 35 m 80 cm 6 mm and 52 m 60 cm 5 mm
i. 14 km 752 m 41 cm and 51 km 716 m 53 cm
j. 24 km 636 m 66 cm and 54 km 437 m 45 cm
2. Subtract the following.
a. 84 cm 4 mm from 89 cm 1 mm
b. 56 cm 9 mm from 60 cm 6 mm
c. 79 m 65 cm from 82 m 54 cm
d. 18 m 42 cm from 37 m 57 cm
e. 26 km 319 m from 51 km 306 m
f. 42 km 472 m from 66 km 351 m
g. 35 m 80 cm 6 mm from 52 m 60 cm 5 mm
h. 26 m 57 cm 4 mm from 67 m 28 cm 7 mm
i. 31 km 345 m 63 cm from 72 km 147 m 40 cm
j. 21 km 650 m 75 cm form 29 km 370 m 30 cm

Maths Zone – Grade 4 129

Answers of Unit 5

Exercise 5.1

1. a. 160mm b. 310mm c. 250mm d. 87mm

e. 49mm f. 148mm

2. a. 5cm b. 6 cm c. 9cm d. 11cm

e. 18 cm f. 200 cm

3. a. 300cm b. 800m c. 1500cm d. 2500m

e. 470cm f. 1260cm

4. a. 3m b. 7 m c. 12 m d. 18 m

e. 25 m f. 40 m

Exercise 5.2

1. a. 300m b. 25000m c. 225m d. 8060m

e. 17405m f. 47320m g. 246350m h. 885705m

i. 24758m

2. a. 3km b. 5km c. 91km d. 20km

e. 40 km f. 80 km

3. a. 8km 250m b. 8km 572m c. 7km 45m f. 9km 676m

g. 3km 690m h. 2km 650m i. 70km 625m j. 73km 690m

k. 25km 365m

Exercise 5.3

1. a. 32 cm 5 mm b. 102 cm 7 mm c. 96 m 82 cm

d. 112 m 31 cm e. 149 km 217m f. 269 km 930 m

2. a. 20 cm 3 mm b. 81 m 23 cm c. 66 km 423 m

d. 166 km 116 m e. 47 m 61 cm 7 mm f. 14m 56 cm 7 mm

g. 51 km 19m 40 cm h. 32 km 426 m 20 cm

3. 11m 29 cm 4. 4 m 31 cm 5. 366 m 23 cm

6. 4 km 395 m

Exercise 5.4

1. a. 5cm 2mm b. 2cm 9mm c. 14 m 1 cm

d. 25 km 124 m e. 6m 225 m 45 cm

2. a. 11 cm 1mm b. 15 m 5 cm c. 42 m 79 cm

d. 18 km 101 m e. 13 m 14 cm 1 mm f. 15m 10 m 8 mm

g. 4 km 835 m 3 cm

128 Maths Zone – Grade 4

Word Problems 4. 27m 40 cm 5. 7 m 15 cm

3. 101 km 220 m

Exercise 5.5

1. a. 15000ml b. 23000ml c. 1252ml d. 12366ml

e. 6296ml f. 9576ml g. 7745ml h. 18027ml

2. a. 6l b. 8l c. 13l d. 15l

e. 2l f. 5l

3. a. 9l 380ml b. 3l 446ml c. 4l 4ml d. 6l 65ml

e. 1l 667ml f. 11l 360ml

4 & 5 (Do yourself)

Exercise 5.6

1. a. 123 l 828 ml b. 106l 794ml c. 405 l 664ml
d. 101l 699ml e. 160 l 743 ml f. 184l 034ml
2. a. 218l 534 ml b. 583l 292 ml c. 120 l 304 ml
3. a. 40l 220ml b. 160l 6ml c. 3l 250ml
d. 6l 190ml e. 11l 113ml f. 14l 869ml
4. a. 33l 521ml b. 7l 30ml
5. 16l 190ml 6. 72l 647ml 7. 5l 150ml

Exercise 5.7

1. a. 9000g b. 15000g c. 14000g d. 102000g
f. 3245g g. 7584g h. 17250g
2. a. 7kg b. 8kg c. 15kg d. 17kg
e. 12kg f. 25kg
3. a. 18kg 300g b. 5kg 632g c. 2kg 455 g d. 12kg 130g
e. 9kg 780g f. 8kg 450g g. 7kg 600g h. 15kg 560g

Exercise 5.8

1. a. 82kg 813g b. 33kg 879g c. 66kg 487g d. 73kg 883g

e. 125kg 226g f. 175kg 48g 95kg 310g d. 84kg 735g

2. a. 82kg 770g b. 21kg 442g c. 3kg 140g d. 5kg 566g

e. 50kg 954g 14kg 890g d. 18kg 670g
12kg 90g 8 . 51kg 110g
3. a. 4kg 195g b. 9kg 50g c.

e. 17kg 613g f. 314kg 536g

4. a. 17kg 200g b. 14kg 300g c.

5. 11kg 750 6. 34 kg 250g 7.

Maths Zone – Grade 4 129

6 Mensuration

Specific Objective Prescribed by CDC

 To tell and write the area of the given figures by counting the number of
unit squares.

 To find the volume of the given solid objects by counting the number of
unit cubes.

128 Maths Zone – Grade 4

Perimeter

Activity I

Take your math book. It's faces are in rectangular shape.

Measure the length and breadth.
What is the length = ................ cm
What is the breadth = ................ cm
Let's measure, all sides of front face.
What do you get?
Find the sum of all sides.

Activity II S 10 cm R
Q
This is a rectangle.

Length of rectangle = 10 cm 8 cm
8 cm
Breadth of rectangle = 8 cm

Here, PQ and SR are length.

PS and QR are breadth P 10 cm

Sum of length and breadth = PQ + QR + SR + SD

= 10 cm + 8 cm + 10 cm + 8 cm

= 36 cm

The total length of boundary of a plane figure is called
perimetre (P)

‰‰ Can you find the perimeter of upper part of your desk?
‰‰ Try to find the perimeter of T.T board of your school?
‰‰ Find the rectangularly shapped objects at home and find their

perimetre.

Maths Zone – Grade 4 129

Example 1

Solution:

Lengh of the sides of a triangle are given. P
8 cm
PQ = 6 cm, QR = 8 cm, PR = 7 cm 6 cm

Sum of the length of sides 7 cm

PQ + QR + PR Q R
= 6 cm + 8 cm + 7 cm = 21 cm

Sum of all sides of triangle is called perimeter of triangle.

Example 2

Solution: D 5 cm
6 cm C
ABCD is a quadrilateral
4 cm
It has four sides. A
7 cm B
Its perimeter is the sum of length of all four sides.

So, Perimeter (p) = Sum of lenght of all sides

= AB + BC + CD + AD

= 7 cm + 4 cm + 5 cm + 6 cm = 22 cm

Perimeter of Rectangle D l C
The figure alongside is a rectangle ABCD. l b

The opposite sides of rectangles are equal. b B

The length of rectangle are AB = CD = l A

The breadth of rectangle are , AD = BC = b

Perimeter of rectangle (P) = AB + CD + AD + BC

= l + l + b + b

= 2l + 2b = 2(l + b)

∴ Perimeter of a rectangle is P = 2 (l + b)

So we can find the perimetre of rectangle by using formula
Perimeter (P) = 2(l + b).
128 Maths Zone – Grade 4

Perimeter of Square D l C
l l l
All sides of a square are equal. A B

∴ Perimeter of square (P) = Sum of all sides R

= AB + BC + CD + DA Q

= l + l + l + l

= 4 l

∴ Perimeter of square (P) = 4 l

Example 3

Find the perimetre of square. S
P 4 cm
Solution:

Side (l) = 4 cm

Perimetre (P) = 4 l

= 4 × 4

= 16 cm

Perimeter of triangle = Sum of length of all sides
Perimeter of rectangle = 2(l + b)
Perimetre of square = 4l

Perimetre of Quadrilateral = Sum of length of all sides.

Example 4 T
5 cm
Find the perimetre. 3 cm
4 cm
Solution:
4 cm
Perimetre (P) = Sum of length of all sides U S
= PQ + QR + RS + ST + TU + UP
3 cm 2 cm
Q
R
P

= 3 cm + 2 cm + 4 cm + 5 cm + 4 cm + 3 cm

= 21 cm

Maths Zone – Grade 4 129

Exercise 6.1

1. Find the perimeter of following plane figures.

a. P b. C

8 cm 3 cm5 cm 4 cm 13 cm 5 cm
6 cm 3 cm 12 cm
Q B
10 cm
A
R

c. D 5 cm F d. P

7 cm 6 cm 3 cm

C Q 5 cm R
2. Find the perimeter of the following polygons.

a. A 4 cm D b. 6 cm S
C P
Q 3 cm R
B 6 cm 3 cm
6 cm

c. F 2 cm E 4 cm d. A 4 cm D
I
2 cm E F 2 cm
B cm 1 C
1 cm
4 cm
5 cm 5 cm

G 3 cm H G 2 cm H

128 Maths Zone – Grade 4

3. Find the perimeter of following rectangles.

a. P D b. S R

5 cm 6 cm
C
P 10 cm P 4 cm Q G
c. H G d. H

4 cm 5 cm

E 8 cm F E 9 cm F
(Use P = 2(l+ b)) R

4. Find the perimeter of following squares.

a. D C b. S

A l = 3 cm B P l = 5 cm Q
d. L K
c. H G

E l = 4 cm F I l = 10 cm J
(Use P = 4l) Maths Zone – Grade 4 129

5. Find the perimeter of triangles whose sides are as follows.
a. 6 cm, 8 cm and 10 cm
b. 4 cm, 6 cm and 7 cm
c. 7 cm, 24 cm and 25 cm
d. 10 cm , 15 cm and 12 cm

6. Find the perimeter of Quadrilaterals, whose sides are as
follows.
a. 4 cm, 6 cm, 8 cm and 7 cm

b. 5 cm, 4 cm, 7 cm and 9 cm

c. 8 cm, 9 cm , 7 cm and 10 cm

d. 7 cm, 3 cm, 5 cm and 10 cm

7. Find the perimeter of rectangles having following
dimensions.
a. length (l) = 8 cm, breadth (b) = 6 cm
b. length (l) = 10 cm, breadth (b) = 7 cm
c. length (l) = 12 cm, breadth (b) = 6 cm
d. length (l) = 5.5 cm, breadth (b) = 4.5 cm

8. Find the perimetre of square having the following
dimensions.
a. length (l) = 5 cm
b. side (l) = 7 cm
c. side (l) = 9 cm
d. side (l) = 6.5 cm

9. The length and breadth of a room is 15 m and 10 m
respectively. Find its perimeter.

10. Find the perimeter of your math book and your note
copy. Find their sum.

128 Maths Zone – Grade 4